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---
license: mit
language:
- fr
- en
---
Sudoku_i=[i,j]
i,j integer 
for i in range (0,9,1):
  for j in range (9,0,-1):
    if Sudoku_i[j]= Sudoku_i[9-j+1]
      return redundancy.
    else: return row_i
for i in range(0,9,3):
  for j in range (9,0,-3):
    if Sudoko_i[i]= Sudoku_i[j]:
      i= i+1-i.div(9)×i
      j= j-1-j.div(9)×j
      return One call per line.