File size: 2,170 Bytes
14c9c2b | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 | #include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int n;
cin >> n;
if (n == 1) {
cout << "1 1\n";
return 0;
}
vector<int> pos_of_val(n + 1, 0);
vector<int> val_at_pos(n + 1, 0);
// Find positions of 1 and 2
for (int i = 1; i <= n; ++i) {
cout << "0";
for (int j = 1; j <= n; ++j) {
if (j == i) cout << " 2";
else cout << " 1";
}
cout << endl;
cout.flush();
int a;
cin >> a;
if (a == 0) {
pos_of_val[1] = i;
val_at_pos[i] = 1;
} else if (a == 2) {
pos_of_val[2] = i;
val_at_pos[i] = 2;
}
}
vector<int> unknown;
for (int i = 1; i <= n; ++i) {
if (val_at_pos[i] == 0) {
unknown.push_back(i);
}
}
// Determine the remaining values 3..n
for (int v = 3; v <= n; ++v) {
int k = v - 1; // number of known values
vector<int> U = unknown;
while (U.size() > 1) {
int mid = U.size() / 2;
vector<int> L(U.begin(), U.begin() + mid);
vector<int> R(U.begin() + mid, U.end());
vector<int> q(n + 1, 1); // filler = 1
for (int val = 1; val < v; ++val) {
q[pos_of_val[val]] = val;
}
for (int p : L) {
q[p] = v;
}
cout << "0";
for (int i = 1; i <= n; ++i) {
cout << " " << q[i];
}
cout << endl;
cout.flush();
int a;
cin >> a;
if (a == k + 1) {
U = L;
} else {
U = R;
}
}
int p = U[0];
pos_of_val[v] = p;
val_at_pos[p] = v;
unknown.erase(find(unknown.begin(), unknown.end(), p));
}
cout << "1";
for (int i = 1; i <= n; ++i) {
cout << " " << val_at_pos[i];
}
cout << endl;
cout.flush();
return 0;
} |