File size: 7,446 Bytes
1fd0050 | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 | #include <iostream>
#include <vector>
#include <algorithm>
#include <queue>
using namespace std;
// Structure to store edge details
struct Edge {
int u, v, id;
};
int n;
vector<int> p;
vector<vector<pair<int, int>>> adj; // Adjacency list: u -> {v, edge_index}
vector<Edge> edge_list;
vector<vector<int>> dists; // All-pairs distances
// DP result structure
struct DP_Res {
long long val0;
long long val1;
int child_for_1;
};
vector<DP_Res> memo;
vector<int> weights; // Current weights for edges
// BFS to compute distances from a start node
void bfs(int start, vector<int>& d) {
fill(d.begin(), d.end(), -1);
d[start] = 0;
queue<int> q;
q.push(start);
while (!q.empty()) {
int u = q.front();
q.pop();
for (auto& edge : adj[u]) {
int v = edge.first;
if (d[v] == -1) {
d[v] = d[u] + 1;
q.push(v);
}
}
}
}
// DP to find Maximum Weight Matching on the tree
void dfs_dp(int u, int parent) {
long long sum_max = 0;
// First pass: Calculate sum of max(val0, val1) for all children
for (auto& edge : adj[u]) {
int v = edge.first;
if (v == parent) continue;
dfs_dp(v, u);
sum_max += max(memo[v].val0, memo[v].val1);
}
// val0: u is not matched with any child
memo[u].val0 = sum_max;
// val1: u is matched with exactly one child
long long best_val1 = -1e18; // Initialize with a very small number
int best_child = -1;
bool has_child = false;
for (auto& edge : adj[u]) {
int v = edge.first;
int idx = edge.second;
if (v == parent) continue;
has_child = true;
// If we match u with v, the value is:
// weight(u,v) + val0(v) [v not matched with its children] + sum_{other k} max(val0(k), val1(k))
// This simplifies to: weight(u,v) + val0(v) + (sum_max - max(val0(v), val1(v)))
long long current_val = weights[idx] + memo[v].val0 + (sum_max - max(memo[v].val0, memo[v].val1));
if (current_val > best_val1) {
best_val1 = current_val;
best_child = v;
}
}
if (has_child) {
memo[u].val1 = best_val1;
memo[u].child_for_1 = best_child;
} else {
memo[u].val1 = -1e18; // Leaf cannot be matched with a child
}
}
// Reconstruct the matching based on DP decisions
void get_matching(int u, int parent, bool matched_with_parent, vector<int>& matching_edges) {
if (matched_with_parent) {
// u is matched with parent, so u cannot match with any child
for (auto& edge : adj[u]) {
int v = edge.first;
if (v == parent) continue;
// Children treat u as not available (equivalent to not matched)
get_matching(v, u, false, matching_edges);
}
} else {
// u is not matched with parent, can choose to match with a child or not
if (memo[u].val1 > memo[u].val0) {
// Match u with best_child
int v_match = memo[u].child_for_1;
for (auto& edge : adj[u]) {
if (edge.first == v_match) {
matching_edges.push_back(edge.second);
break;
}
}
// Recurse
for (auto& edge : adj[u]) {
int v = edge.first;
if (v == parent) continue;
if (v == v_match) {
// v is matched with u (its parent)
get_matching(v, u, true, matching_edges);
} else {
// other children are not matched with u
get_matching(v, u, false, matching_edges);
}
}
} else {
// u matches with nobody
for (auto& edge : adj[u]) {
int v = edge.first;
if (v == parent) continue;
get_matching(v, u, false, matching_edges);
}
}
}
}
void solve() {
cin >> n;
p.resize(n + 1);
for (int i = 1; i <= n; ++i) cin >> p[i];
adj.assign(n + 1, vector<pair<int, int>>());
edge_list.clear();
edge_list.resize(n);
for (int i = 1; i < n; ++i) {
int u, v;
cin >> u >> v;
adj[u].push_back({v, i});
adj[v].push_back({u, i});
edge_list[i] = {u, v, i};
}
// Precompute all-pairs distances
dists.assign(n + 1, vector<int>(n + 1));
for (int i = 1; i <= n; ++i) bfs(i, dists[i]);
vector<vector<int>> operations;
while (true) {
// Check if sorted
bool sorted = true;
for (int i = 1; i <= n; ++i) {
if (p[i] != i) {
sorted = false;
break;
}
}
if (sorted) break;
weights.assign(n, 0);
// Assign weights to edges based on potential improvement
for (int i = 1; i < n; ++i) {
int u = edge_list[i].u;
int v = edge_list[i].v;
int pu = p[u];
int pv = p[v];
int d_old = dists[u][pu] + dists[v][pv];
int d_new = dists[v][pu] + dists[u][pv];
int gain = d_old - d_new;
if (gain == 2) {
weights[i] = 100; // Priority 1: Both move closer
} else if (gain == 0) {
// Priority 2: One moves closer.
// Prefer cases where we move a misplaced item closer, even if we disrupt a correctly placed item.
bool useful = false;
bool disrupts_target = false;
// Check if p[u] moves closer by going to v
if (dists[v][pu] < dists[u][pu]) {
useful = true;
if (pv == v) disrupts_target = true;
}
// Check if p[v] moves closer by going to u
if (dists[u][pv] < dists[v][pv]) {
useful = true;
if (pu == u) disrupts_target = true;
}
if (useful) {
if (disrupts_target) weights[i] = 5; // Good swap: disturbs a sorted node to help an unsorted one
else weights[i] = 1; // Okay swap: both unsorted, one helps one hurts
} else {
weights[i] = 0;
}
} else {
weights[i] = 0; // Gain < 0, bad move
}
}
// Find max weight matching
memo.assign(n + 1, {0, 0, 0});
dfs_dp(1, 0);
vector<int> matching;
get_matching(1, 0, false, matching);
if (matching.empty()) break; // Should not happen if not sorted
operations.push_back(matching);
// Apply swaps
for (int idx : matching) {
int u = edge_list[idx].u;
int v = edge_list[idx].v;
swap(p[u], p[v]);
}
}
cout << operations.size() << "\n";
for (auto& op : operations) {
cout << op.size();
for (int idx : op) cout << " " << idx;
cout << "\n";
}
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
if (cin >> t) {
while (t--) {
solve();
}
}
return 0;
} |