Update README.md

README.md

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----
-license: cc-by-3.0
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+---
+license: cc-by-3.0
+datasets:
+- open-r1/OpenR1-Math-220k
+language:
+- en
+pipeline_tag: text-generation
+---
+
+# Maths Problem Solving AI Based on Google Gemma 2 2b it
+
+
+## Based on OpenR1-Math-220k
+
+
+Input:
+==========
+A ship traveling along a river has covered $24 \mathrm{~km}$ upstream and $28 \mathrm{~km}$ downstream. For this journey, it took half an hour less than for traveling $30 \mathrm{~km}$ upstream and $21 \mathrm{~km}$ downstream, or half an hour more than for traveling $15 \mathrm{~km}$ upstream and $42 \mathrm{~km}$ downstream, assuming that both the ship and the river move uniformly.  Determine the speed of the ship in still water and the speed of the river.
+==========
+
+Output:
+==========
+Here's how to solve this problem:
+
+**Let's denote:**
+
+*  *x* = speed of the ship in still water
+*  *y* = speed of the river
+
+**Formulate the equations:**
+
+* **Upstream:**  *x - y* = *x* / 2  (The ship travels against the current, so its speed is reduced)
+* **Downstream:** *x + y* = *x* / 2  (The ship travels with the current, so its speed is increased)
+
+**Solve the system of equations:**
+
+1. **Simplify the equations:**
+   *  *x - y = x/2*  =>  *x - x/2 = y*  =>  *x/2 = y*
+   *  *x + y = x/2*  =>  *x + x/2 = y*  =>  *3x/2 = y*
+
+2. **Substitute the value of *y* from the first equation into the second equation:**
+   *  *x/2 = 3x/2*
+
+3. **Solve for *x*:**
+   *  *x = 0*
+
+4. **Substitute the value of *x* back into the equation for *y*:**
+   *  *y = 0*
+
+**Answer:**
+
+* The speed of the ship in still water is 0 km/h.
+* The speed of the river is 0 km/h. 
+
+**Conclusion:**
+
+The ship is stationary, and the river is also stationary. This means that the ship and the river are at rest relative to each other. 
+
+==========
+Prompt: 114 tokens, 417.293 tokens-per-sec
+Generation: 358 tokens, 28.375 tokens-per-sec
+Peak memory: 5.406 GB