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* SPDX-License-Identifier: BSD-2-Clause
*
* Copyright (c) 2020 NKI/AVL, Netherlands Cancer Institute
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions are met:
*
* 1. Redistributions of source code must retain the above copyright notice, this
* list of conditions and the following disclaimer
* 2. Redistributions in binary form must reproduce the above copyright notice,
* this list of conditions and the following disclaimer in the documentation
* and/or other materials provided with the distribution.
*
* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND
* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
* WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
* DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLE FOR
* ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES
* (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
* LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
* ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
* SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
#include "cif++/point.hpp"
#include "cif++/matrix.hpp"
#include <cassert>
#include <random>
namespace cif
{
// --------------------------------------------------------------------
template<typename T>
quaternion_type<T> normalize(quaternion_type<T> q)
{
std::valarray<double> t(4);
t[0] = q.get_a();
t[1] = q.get_b();
t[2] = q.get_c();
t[3] = q.get_d();
t *= t;
double length = std::sqrt(t.sum());
if (length > 0.001)
q /= static_cast<quaternion::value_type>(length);
else
q = quaternion(1, 0, 0, 0);
return q;
}
// --------------------------------------------------------------------
quaternion construct_from_angle_axis(float angle, point axis)
{
angle = static_cast<float>((angle * kPI / 180) / 2);
auto s = std::sin(angle);
auto c = std::cos(angle);
axis.normalize();
return normalize(quaternion{
static_cast<float>(c),
static_cast<float>(s * axis.m_x),
static_cast<float>(s * axis.m_y),
static_cast<float>(s * axis.m_z) });
}
std::tuple<double, point> quaternion_to_angle_axis(quaternion q)
{
if (q.get_a() > 1)
q = normalize(q);
// angle:
double angle = 2 * std::acos(q.get_a());
angle = angle * 180 / kPI;
// axis:
float s = std::sqrt(1 - q.get_a() * q.get_a());
if (s < 0.001)
s = 1;
point axis(q.get_b() / s, q.get_c() / s, q.get_d() / s);
return { angle, axis };
}
point center_points(std::vector<point> &Points)
{
point t;
for (point &pt : Points)
{
t.m_x += pt.m_x;
t.m_y += pt.m_y;
t.m_z += pt.m_z;
}
t.m_x /= Points.size();
t.m_y /= Points.size();
t.m_z /= Points.size();
for (point &pt : Points)
{
pt.m_x -= t.m_x;
pt.m_y -= t.m_y;
pt.m_z -= t.m_z;
}
return t;
}
quaternion construct_for_dihedral_angle(point p1, point p2, point p3, point p4,
float angle, float /*esd*/)
{
p1 -= p3;
p2 -= p3;
p4 -= p3;
p3 -= p3;
quaternion q;
auto axis = -p2;
float dh = dihedral_angle(p1, p2, p3, p4);
return construct_from_angle_axis(angle - dh, axis);
}
point centroid(const std::vector<point> &pts)
{
point result;
for (auto &pt : pts)
result += pt;
result /= static_cast<float>(pts.size());
return result;
}
double RMSd(const std::vector<point> &a, const std::vector<point> &b)
{
double sum = 0;
for (uint32_t i = 0; i < a.size(); ++i)
{
std::valarray<double> d(3);
d[0] = b[i].m_x - a[i].m_x;
d[1] = b[i].m_y - a[i].m_y;
d[2] = b[i].m_z - a[i].m_z;
d *= d;
sum += d.sum();
}
return std::sqrt(sum / a.size());
}
// The next function returns the largest solution for a quartic equation
// based on Ferrari's algorithm.
// A depressed quartic is of the form:
//
// x^4 + ax^2 + bx + c = 0
//
// (since I'm too lazy to find out a better way, I've implemented the
// routine using complex values to avoid nan's as a result of taking
// sqrt of a negative number)
double LargestDepressedQuarticSolution(double a, double b, double c)
{
std::complex<double> P = -(a * a) / 12 - c;
std::complex<double> Q = -(a * a * a) / 108 + (a * c) / 3 - (b * b) / 8;
std::complex<double> R = -Q / 2.0 + std::sqrt((Q * Q) / 4.0 + (P * P * P) / 27.0);
std::complex<double> U = std::pow(R, 1 / 3.0);
std::complex<double> y;
if (U == 0.0)
y = -5.0 * a / 6.0 + U - std::pow(Q, 1.0 / 3.0);
else
y = -5.0 * a / 6.0 + U - P / (3.0 * U);
std::complex<double> W = std::sqrt(a + 2.0 * y);
// And to get the final result:
// result = (卤W + std::sqrt(-(3 * alpha + 2 * y 卤 2 * beta / W))) / 2;
// We want the largest result, so:
std::valarray<double> t(4);
t[0] = ((W + std::sqrt(-(3.0 * a + 2.0 * y + 2.0 * b / W))) / 2.0).real();
t[1] = ((W + std::sqrt(-(3.0 * a + 2.0 * y - 2.0 * b / W))) / 2.0).real();
t[2] = ((-W + std::sqrt(-(3.0 * a + 2.0 * y + 2.0 * b / W))) / 2.0).real();
t[3] = ((-W + std::sqrt(-(3.0 * a + 2.0 * y - 2.0 * b / W))) / 2.0).real();
return t.max();
}
quaternion align_points(const std::vector<point> &pa, const std::vector<point> &pb)
{
// First calculate M, a 3x3 matrix containing the sums of products of the coordinates of A and B
matrix3x3<double> M;
for (uint32_t i = 0; i < pa.size(); ++i)
{
const point &a = pa[i];
const point &b = pb[i];
M(0, 0) += a.m_x * b.m_x;
M(0, 1) += a.m_x * b.m_y;
M(0, 2) += a.m_x * b.m_z;
M(1, 0) += a.m_y * b.m_x;
M(1, 1) += a.m_y * b.m_y;
M(1, 2) += a.m_y * b.m_z;
M(2, 0) += a.m_z * b.m_x;
M(2, 1) += a.m_z * b.m_y;
M(2, 2) += a.m_z * b.m_z;
}
// Now calculate N, a symmetric 4x4 matrix
symmetric_matrix4x4<double> N(4);
N(0, 0) = M(0, 0) + M(1, 1) + M(2, 2);
N(0, 1) = M(1, 2) - M(2, 1);
N(0, 2) = M(2, 0) - M(0, 2);
N(0, 3) = M(0, 1) - M(1, 0);
N(1, 1) = M(0, 0) - M(1, 1) - M(2, 2);
N(1, 2) = M(0, 1) + M(1, 0);
N(1, 3) = M(0, 2) + M(2, 0);
N(2, 2) = -M(0, 0) + M(1, 1) - M(2, 2);
N(2, 3) = M(1, 2) + M(2, 1);
N(3, 3) = -M(0, 0) - M(1, 1) + M(2, 2);
// det(N - 位I) = 0
// find the largest 位 (位m)
//
// A位4 + B位3 + C位2 + D位 + E = 0
// A = 1
// B = 0
// and so this is a so-called depressed quartic
// solve it using Ferrari's algorithm
double C = -2 * (M(0, 0) * M(0, 0) + M(0, 1) * M(0, 1) + M(0, 2) * M(0, 2) +
M(1, 0) * M(1, 0) + M(1, 1) * M(1, 1) + M(1, 2) * M(1, 2) +
M(2, 0) * M(2, 0) + M(2, 1) * M(2, 1) + M(2, 2) * M(2, 2));
double D = 8 * (M(0, 0) * M(1, 2) * M(2, 1) +
M(1, 1) * M(2, 0) * M(0, 2) +
M(2, 2) * M(0, 1) * M(1, 0)) -
8 * (M(0, 0) * M(1, 1) * M(2, 2) +
M(1, 2) * M(2, 0) * M(0, 1) +
M(2, 1) * M(1, 0) * M(0, 2));
// E is the determinant of N:
double E =
(N(0, 0) * N(1, 1) - N(0, 1) * N(0, 1)) * (N(2, 2) * N(3, 3) - N(2, 3) * N(2, 3)) +
(N(0, 1) * N(0, 2) - N(0, 0) * N(2, 1)) * (N(2, 1) * N(3, 3) - N(2, 3) * N(1, 3)) +
(N(0, 0) * N(1, 3) - N(0, 1) * N(0, 3)) * (N(2, 1) * N(2, 3) - N(2, 2) * N(1, 3)) +
(N(0, 1) * N(2, 1) - N(1, 1) * N(0, 2)) * (N(0, 2) * N(3, 3) - N(2, 3) * N(0, 3)) +
(N(1, 1) * N(0, 3) - N(0, 1) * N(1, 3)) * (N(0, 2) * N(2, 3) - N(2, 2) * N(0, 3)) +
(N(0, 2) * N(1, 3) - N(2, 1) * N(0, 3)) * (N(0, 2) * N(1, 3) - N(2, 1) * N(0, 3));
// solve quartic
double lambda = LargestDepressedQuarticSolution(C, D, E);
// calculate t = (N - 位I)
matrix<double> t(N - identity_matrix(4) * lambda);
// calculate a matrix of cofactors for t
auto cf = matrix_cofactors(t);
int maxR = 0;
double maxCF = std::abs(cf(0, 0));
for (int r = 1; r < 4; ++r)
{
auto cfr = std::abs(cf(r, 0));
if (maxCF < cfr)
{
maxCF = cfr;
maxR = r;
}
}
quaternion q(
static_cast<float>(cf(maxR, 0)),
static_cast<float>(cf(maxR, 1)),
static_cast<float>(cf(maxR, 2)),
static_cast<float>(cf(maxR, 3)));
q = normalize(q);
return q;
}
// --------------------------------------------------------------------
point nudge(point p, float offset)
{
static const float kPI_f = static_cast<float>(kPI);
static std::random_device rd;
static std::mt19937_64 rng(rd());
std::uniform_real_distribution<float> randomAngle(0, 2 * kPI_f);
std::normal_distribution<float> randomOffset(0, offset);
float theta = randomAngle(rng);
float phi1 = randomAngle(rng) - kPI_f;
float phi2 = randomAngle(rng) - kPI_f;
quaternion q = spherical(1.0f, theta, phi1, phi2);
point r{ 0, 0, 1 };
r.rotate(q);
r *= randomOffset(rng);
return p + r;
}
} // namespace cif
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