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# Copyright (c) Meta Platforms, Inc. and affiliates.
# This source code is licensed under the MIT license found in the
# LICENSE file in the root directory of this source tree.
import re
import numpy as np
def extract_solution(solution_str):
answer_pattern = r"<answer>(.*?)</answer>"
matches = re.findall(answer_pattern, solution_str, re.DOTALL)
if matches:
final_answer = matches[-1].strip()
else:
final_answer = None
return final_answer
def validate_equation(equation_str, available_numbers):
"""Validate that equation only uses available numbers and each number once."""
try:
# Extract all numbers from the equation
numbers_in_eq = [int(n) for n in re.findall(r"\d+", equation_str)]
# Check if all numbers in equation are available
available_numbers = sorted(available_numbers)
numbers_in_eq = sorted(numbers_in_eq)
# Each number should be used exactly once
return numbers_in_eq == available_numbers
except:
return False
def evaluate_equation(equation_str):
"""Safely evaluate the arithmetic equation using eval() with precautions."""
try:
# Define a regex pattern that only allows numbers, operators, parentheses, and whitespace
allowed_pattern = r"^[\d+\-*/().\s]+$"
if not re.match(allowed_pattern, equation_str):
raise ValueError("Invalid characters in equation.")
# Evaluate the equation with restricted globals and locals
result = eval(equation_str, {"__builtins__": None}, {})
return result
except Exception as e:
return None
def compute_score(solution_str, ground_truth, method="strict", format_score=0.1, score=1.0):
"""The scoring function for countdown task.
Args:
solution_str: the solution text
ground_truth: dictionary containing target number and available numbers
method: the method to extract the solution
format_score: the score for correct format but wrong answer
score: the score for the correct answer
"""
target = ground_truth["target"]
numbers = ground_truth["numbers"]
equation = extract_solution(solution_str=solution_str)
if "wait" in solution_str:
do_print = True
do_print = np.random.rand() < 0.4
if do_print:
print(f"--------------------------------")
print(f"Target: {target} | Numbers: {numbers}")
print(f"Extracted equation: {equation}")
print(f"Solution string: {solution_str}")
if equation is None:
if do_print:
print(f"No equation found")
return 0
# Validate equation uses correct numbers
if not validate_equation(equation, numbers):
if do_print:
print(f"Invalid equation")
return format_score
# Evaluate equation
try:
result = evaluate_equation(equation)
if result is None:
if do_print:
print(f"Could not evaluate equation")
return format_score
if abs(result - target) < 1e-5: # Account for floating point precision
if do_print:
print(f"Correct equation: {equation} = {result}")
return score
else:
if do_print:
print(f"Wrong result: equation = {result}, target = {target}")
return format_score
except:
if do_print:
print(f"Error evaluating equation")
return format_score
class Parser:
@classmethod
def extract_answer_gsm8k(cls, generated_text):
"""Extract the first numerical answer following '####' in the generated text."""
try:
# Use regex to find the first occurrence of #### followed by a number
# Handle formats like: #### 18, #### $18, #### 18.0
match = re.search(r"####\s*\$?([\d,]+(?:\.\d+)?)", generated_text)
if match:
return float(match.group(1).replace(",", ""))
except Exception as e:
print(f"Error extracting answer: {e}, Text: {generated_text[:100]}")
return None
@classmethod
def extract_answer_boxed(cls, generated_text):
"""Extract the first numerical answer following '####' in the generated text."""
try:
pred = remove_boxed(last_boxed_only_string(generated_text))
except:
pred = generated_text
return pred
@classmethod
def extract_answer_boxed_ctd(cls, generated_text):
"""Extract the first numerical answer following '####' in the generated text."""
pred = Parser.extract_answer_boxed(generated_text)
pred = pred.replace(r"\div", "/").replace("\times", "*").replace(r"\cdot", "*")
return pred
@classmethod
def extract_answer_grpo_ctd(cls, generated_text):
"""Extract the first numerical answer following '####' in the generated text."""
pred = extract_solution(generated_text)
print(generated_text)
print(pred)
if pred is not None:
pred = pred.replace(r"\div", "/").replace("\times", "*").replace(r"\cdot", "*")
return pred
@classmethod
def extract_answer_sudoku(cls, solution_str):
"""Extract the Sudoku solution from the generated text."""
answer_pattern = r"<answer>(.*?)</answer>"
matches = re.findall(answer_pattern, solution_str, re.DOTALL)
if matches:
# Get the last answer tag content, strip whitespace and newlines
final_answer = re.sub(r"\s", "", matches[-1].strip())
return final_answer
return None
def is_equiv(str1, str2, verbose=False):
if type(str1) == float or type(str2) == float:
try:
return abs(float(str1) - float(str2)) < 1e-6
except:
return False
if str1 is None and str2 is None:
print("WARNING: Both None")
return True
if str1 is None or str2 is None:
return False
try:
ss1 = strip_string(str1)
ss2 = strip_string(str2)
if verbose:
print(ss1, ss2)
return ss1 == ss2
except Exception:
return str1 == str2
def remove_boxed(s):
if "\\boxed " in s:
left = "\\boxed "
assert s[: len(left)] == left
return s[len(left) :]
left = "\\boxed{"
try:
assert s[: len(left)] == left
assert s[-1] == "}"
return s[len(left) : -1]
except:
return s
def last_boxed_only_string(string):
idx = string.rfind("\\boxed")
if "\\boxed " in string:
return "\\boxed " + string.split("\\boxed ")[-1].split("$")[0]
if idx < 0:
idx = string.rfind("\\fbox")
if idx < 0:
return string
i = idx
right_brace_idx = None
num_left_braces_open = 0
while i < len(string):
if string[i] == "{":
num_left_braces_open += 1
if string[i] == "}":
num_left_braces_open -= 1
if num_left_braces_open == 0:
right_brace_idx = i
break
i += 1
if right_brace_idx is None:
retval = None
else:
retval = string[idx : right_brace_idx + 1]
return retval
def fix_fracs(string):
substrs = string.split("\\frac")
new_str = substrs[0]
if len(substrs) > 1:
substrs = substrs[1:]
for substr in substrs:
new_str += "\\frac"
if substr[0] == "{":
new_str += substr
else:
try:
assert len(substr) >= 2
except AssertionError:
return string
a = substr[0]
b = substr[1]
if b != "{":
if len(substr) > 2:
post_substr = substr[2:]
new_str += "{" + a + "}{" + b + "}" + post_substr
else:
new_str += "{" + a + "}{" + b + "}"
else:
if len(substr) > 2:
post_substr = substr[2:]
new_str += "{" + a + "}" + b + post_substr
else:
new_str += "{" + a + "}" + b
string = new_str
return string
def fix_a_slash_b(string):
if len(string.split("/")) != 2:
return string
a = string.split("/")[0]
b = string.split("/")[1]
try:
a = int(a)
b = int(b)
assert string == "{}/{}".format(a, b)
new_string = "\\frac{" + str(a) + "}{" + str(b) + "}"
return new_string
except AssertionError:
return string
def remove_right_units(string):
# "\\text{ " only ever occurs (at least in the val set) when describing units
if "\\text{ " in string:
splits = string.split("\\text{ ")
assert len(splits) == 2
return splits[0]
else:
return string
def fix_sqrt(string):
if "\\sqrt" not in string:
return string
splits = string.split("\\sqrt")
new_string = splits[0]
for split in splits[1:]:
if split[0] != "{":
a = split[0]
new_substr = "\\sqrt{" + a + "}" + split[1:]
else:
new_substr = "\\sqrt" + split
new_string += new_substr
return new_string
def strip_string(string):
# linebreaks
string = string.replace("\n", "")
# remove inverse spaces
string = string.replace("\\!", "")
# replace \\ with \
string = string.replace("\\\\", "\\")
# replace tfrac and dfrac with frac
string = string.replace("tfrac", "frac")
string = string.replace("dfrac", "frac")
# remove \left and \right
string = string.replace("\\left", "")
string = string.replace("\\right", "")
# Remove circ (degrees)
string = string.replace("^{\\circ}", "")
string = string.replace("^\\circ", "")
# remove dollar signs
string = string.replace("\\$", "")
# remove units (on the right)
string = remove_right_units(string)
# remove percentage
string = string.replace("\\%", "")
string = string.replace("\%", "") # noqa: W605
# " 0." equivalent to " ." and "{0." equivalent to "{." Alternatively, add "0" if "." is the start of the string
string = string.replace(" .", " 0.")
string = string.replace("{.", "{0.")
# if empty, return empty string
if len(string) == 0:
return string
if string[0] == ".":
string = "0" + string
# to consider: get rid of e.g. "k = " or "q = " at beginning
if len(string.split("=")) == 2:
if len(string.split("=")[0]) <= 2:
string = string.split("=")[1]
# fix sqrt3 --> sqrt{3}
string = fix_sqrt(string)
# remove spaces
string = string.replace(" ", "")
# \frac1b or \frac12 --> \frac{1}{b} and \frac{1}{2}, etc. Even works with \frac1{72} (but not \frac{72}1). Also does a/b --> \\frac{a}{b}
string = fix_fracs(string)
# manually change 0.5 --> \frac{1}{2}
if string == "0.5":
string = "\\frac{1}{2}"
# NOTE: X/Y changed to \frac{X}{Y} in dataset, but in simple cases fix in case the model output is X/Y
string = fix_a_slash_b(string)
return string
def validate_equation(equation_str, available_numbers):
"""Validate that equation only uses available numbers and each number once."""
try:
# Extract all numbers from the equation
numbers_in_eq = [int(n) for n in re.findall(r"\d+", equation_str)]
# Check if all numbers in equation are available
available_numbers = sorted(available_numbers)
numbers_in_eq = sorted(numbers_in_eq)
# Each number should be used exactly once
return numbers_in_eq == available_numbers
except:
return False
def evaluate_equation(equation_str):
"""Safely evaluate the arithmetic equation using eval() with precautions."""
try:
# Define a regex pattern that only allows numbers, operators, parentheses, and whitespace
allowed_pattern = r"^[\d+\-*/().\s]+$"
if not re.match(allowed_pattern, equation_str):
raise ValueError("Invalid characters in equation.")
# Evaluate the equation with restricted globals and locals
result = eval(equation_str.strip(), {"__builtins__": None}, {})
return result
except Exception as e:
return float("Inf")