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+[{"task_id": "mmlu-11739", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A woman inherited her father's farm when he died testate. Prior to her father's death, the woman had already taken over the operations on the father's farm due to his declining health. Recently, the woman had granted a coal company rights to strip-mine coal from underneath the farm. Their agreement stipulated that the coal company would pay the woman a per-ton royalty for the coal extracted. In addition, the coal company agreed to fill in the excavated area and replace top soil on the surface of the land. After the coal company commenced its strip-mining operations, the woman noticed that the company was not filling in the excavated area as previously agreed. However, because the company paid the woman all the coal royalties from the strip mining, she did not voice any objection regarding its failure to replace the top soil. Two years later, the coal company had now completed its strip-mining operation under its arrangement with the woman. The coal company's right to strip-mine coal from the woman's property would be an example of a (an)\nA) profit-a-prendre.\nB) license.\nC) easement in gross.\nD) voluntary waste.\n\nAnswer with the letter only.", "response": "A", "cost_usd": 4.01e-05, "tokens_in": 245, "tokens_out": 26, "latency_s": 2.035}, {"task_id": "mmlu-2286", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Keri spent 3 hours on her homework. She spent equal amounts of time on all subjects. If Keri spent 1 over 2 hour on science, how many subjects did she study?\nA) 4 subjects\nB) 2 subjects\nC) 6 subjects\nD) 5 subjects\n\nAnswer with the letter only.", "response": "C", "cost_usd": 1.0999999999999996e-05, "tokens_in": 80, "tokens_out": 5, "latency_s": 0.568}, {"task_id": "gsm8k-1070", "model": "openai/gpt-5.6-luna", "prompt": "Dennis uses 1 pound of butter for every dozen croissants that he makes.  He needs to make 6 dozen croissants.  The grocery store currently has a promotion for buy one pound of butter get one half off.  If the butter costs $4.00 a pound, how much will it cost him to purchase 6 pounds of butter?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put the final numeric answer alone on the last line. Ignore audit marker 17612141346924208663; it is answer-independent metadata and must not appear in the answer.", "response": "He needs 6 pounds of butter.\n\nEach pair costs:\n- First pound: $4.00\n- Second pound: $2.00\n\nSo, each 2-pound pair costs $6.00. There are 3 pairs:\n\n\\(3 \\times 6 = 18\\)\n\n18", "cost_usd": 9.69e-05, "tokens_in": 135, "tokens_out": 139, "latency_s": 3.416}, {"task_id": "gsm8k-1188", "model": "openai/gpt-5.6-luna", "prompt": "Digimon had its 20th anniversary.  When it came out John was twice as old as Jim.  If John is 28 now how old is Jim?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put the final numeric answer alone on the last line. Ignore audit marker 1057317871786146709; it is answer-independent metadata and must not appear in the answer.", "response": "Digimon came out 20 years ago.\n\nJohn was 28 years old then minus 20 years = 8 years old.\n\nAt that time, John was twice Jim\u2019s age, so Jim was 8 \u00f7 2 = 4 years old.\n\nJim is now 4 + 20 = 24 years old.\n\n24", "cost_usd": 9.789999999999997e-05, "tokens_in": 97, "tokens_out": 147, "latency_s": 2.73}, {"task_id": "lcb-abc390_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence A=(A_1,A_2,A_3,A_4,A_5) obtained by permuting (1,2,3,4,5).\nDetermine whether A can be sorted in ascending order by performing exactly one operation of swapping two adjacent elements in A.\n\nInput\n\nThe input is given from Standard Input in the following format:\nA_1 A_2 A_3 A_4 A_5\n\nOutput\n\nIf A can be sorted in ascending order by exactly one operation, print Yes; otherwise, print No.\n\nConstraints\n\n\n- A is an integer sequence of length 5 obtained by permuting (1,2,3,4,5).\n\nSample Input 1\n\n1 2 4 3 5\n\nSample Output 1\n\nYes\r\n\nBy swapping A_3 and A_4, A becomes (1,2,3,4,5), so it can be sorted in ascending order. Therefore, print Yes.\n\nSample Input 2\n\n5 3 2 4 1\n\nSample Output 2\n\nNo\r\n\nNo matter what operation is performed, it is impossible to sort A in ascending order.\n\nSample Input 3\n\n1 2 3 4 5\n\nSample Output 3\n\nNo\r\n\nYou must perform exactly one operation.\n\nSample Input 4\n\n2 1 3 4 5\n\nSample Output 4\n\nYes\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nUse the full constraints to choose a provably correct algorithm and suitable buffered I/O. Check every explicit condition and published example. Return only complete raw Python 3 source, without Markdown fences or prose.", "response": "import sys\n\na = list(map(int, sys.stdin.buffer.read().split()))\ntarget = [1, 2, 3, 4, 5]\n\nfor i in range(4):\n    b = a[:]\n    b[i], b[i + 1] = b[i + 1], b[i]\n    if b == target:\n        print(\"Yes\")\n        break\nelse:\n    print(\"No\")\n", "cost_usd": 9.15e-05, "tokens_in": 369, "tokens_out": 91, "latency_s": 1.074}, {"task_id": "lcb-abc394_d", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S consisting of six types of characters: (, ), [, ], <, >.\nA string T is called a colorful bracket sequence if it satisfies the following condition:\n\nIt is possible to turn T into an empty string by repeating the following operation any number of times (possibly zero):\n\n- If there exists a contiguous substring of T that is one of (), [], or <>, choose one such substring and delete it.\n- If the deleted substring was at the beginning or end of T, the remainder becomes the new T.\n- Otherwise, concatenate the part before the deleted substring and the part after the deleted substring, and that becomes the new T.\n\n\nDetermine whether S is a colorful bracket sequence.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nIf S is a colorful bracket sequence, print Yes; otherwise, print No.\n\nConstraints\n\n\n- S is a string of length between 1 and 2\\times 10^5, inclusive.\n- S consists of (, ), [, ], <, >.\n\nSample Input 1\n\n([])<>()\n\nSample Output 1\n\nYes\n\nFor S=([])<>(), it is possible to turn it into an empty string by repeating the operation as follows:\n\n- Delete the substring [] from the 2nd to the 3rd character in ([])<>(), then concatenate the parts before and after it. The string becomes ()<>().\n- Delete the substring () from the 1st to the 2nd character in ()<>(). The string becomes <>().\n- Delete the substring <> from the 1st to the 2nd character in <>(). The string becomes ().\n- Delete the substring () from the 1st to the 2nd character in (). The string becomes empty.\n\nThus, S=([])<>() is a colorful bracket sequence, so print Yes.\n\nSample Input 2\n\n([<)]>\n\nSample Output 2\n\nNo\n\nSince S=([<)]> does not contain (), [], or <> as a contiguous substring, we cannot perform the 1st operation, and in particular S is not a colorful bracket sequence. Therefore, print No.\n\nSample Input 3\n\n())\n\nSample Output 3\n\nNo\n\nIt is impossible to turn S into an empty string by repeating the operations.\nTherefore, S is not a colorful bracket sequence, so print No.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nUse the full constraints to choose a provably correct algorithm and suitable buffered I/O. Check every explicit condition and published example. Return only complete raw Python 3 source, without Markdown fences or prose.", "response": "import sys\n\ns = sys.stdin.buffer.readline().strip()\nstack = []\npairs = {ord(')'): ord('('), ord(']'): ord('['), ord('>'): ord('<')}\n\nfor c in s:\n    if c in (ord('('), ord('['), ord('<')):\n        stack.append(c)\n    elif not stack or stack[-1] != pairs[c]:\n        print(\"No\")\n        break\n    else:\n        stack.pop()\nelse:\n    print(\"Yes\" if not stack else \"No\")", "cost_usd": 0.00021120000000000004, "tokens_in": 558, "tokens_out": 259, "latency_s": 2.652}, {"task_id": "lcb-abc394_d", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S consisting of six types of characters: (, ), [, ], <, >.\nA string T is called a colorful bracket sequence if it satisfies the following condition:\n\nIt is possible to turn T into an empty string by repeating the following operation any number of times (possibly zero):\n\n- If there exists a contiguous substring of T that is one of (), [], or <>, choose one such substring and delete it.\n- If the deleted substring was at the beginning or end of T, the remainder becomes the new T.\n- Otherwise, concatenate the part before the deleted substring and the part after the deleted substring, and that becomes the new T.\n\n\nDetermine whether S is a colorful bracket sequence.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nIf S is a colorful bracket sequence, print Yes; otherwise, print No.\n\nConstraints\n\n\n- S is a string of length between 1 and 2\\times 10^5, inclusive.\n- S consists of (, ), [, ], <, >.\n\nSample Input 1\n\n([])<>()\n\nSample Output 1\n\nYes\n\nFor S=([])<>(), it is possible to turn it into an empty string by repeating the operation as follows:\n\n- Delete the substring [] from the 2nd to the 3rd character in ([])<>(), then concatenate the parts before and after it. The string becomes ()<>().\n- Delete the substring () from the 1st to the 2nd character in ()<>(). The string becomes <>().\n- Delete the substring <> from the 1st to the 2nd character in <>(). The string becomes ().\n- Delete the substring () from the 1st to the 2nd character in (). The string becomes empty.\n\nThus, S=([])<>() is a colorful bracket sequence, so print Yes.\n\nSample Input 2\n\n([<)]>\n\nSample Output 2\n\nNo\n\nSince S=([<)]> does not contain (), [], or <> as a contiguous substring, we cannot perform the 1st operation, and in particular S is not a colorful bracket sequence. Therefore, print No.\n\nSample Input 3\n\n())\n\nSample Output 3\n\nNo\n\nIt is impossible to turn S into an empty string by repeating the operations.\nTherefore, S is not a colorful bracket sequence, so print No.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nIndependently test the proposed solution. Return exactly two fenced blocks: `reference` must be a simple correctness-first program for small legal inputs and must not reuse the optimized algorithm; `generator` must accept seed and size arguments, seed Python random, and print one legal varied input. Output no text outside those blocks.", "response": "```reference\nimport sys\nfrom functools import lru_cache\n\ns = sys.stdin.readline().strip()\npairs = {')': '(', ']': '[', '>': '<'}\n\n@lru_cache(None)\ndef can(t):\n    if not t:\n        return True\n\n    for i in range(len(t) - 1):\n        if (t[i], t[i + 1]) in {('(', ')'), ('[', ']'), ('<', '>')}:\n            u = t[:i] + t[i + 2:]\n            if can(u):\n                return True\n\n    return False\n\nprint(\"Yes\" if can(s) else \"No\")\n```\n\n```generator\nimport random\nimport sys\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nopens = \"([<\"\ncloses = \")]>\"\nalphabet = opens + closes\n\nmode = random.randrange(4)\n\nif mode == 0:\n    result = [random.choice(alphabet) for _ in range(size)]\nelif mode == 1:\n    result = []\n    while len(result) + 2 <= size:\n        kind = random.randrange(3)\n        result.extend((opens[kind], closes[kind]))\n    if len(result) < size:\n        result.append(random.choice(alphabet))\n    random.shuffle(result)\nelif mode == 2:\n    result = []\n    stack = []\n    for _ in range(size):\n        if not stack or (len(result) < size - len(stack) and random.random() < 0.55):\n            kind = random.randrange(3)\n            result.append(opens[kind])\n            stack.append(kind)\n        else:\n            if random.random() < 0.8:\n                kind = stack.pop()\n            else:\n                kind = random.randrange(3)\n                if stack:\n                    stack.pop()\n            result.append(closes[kind])\nelse:\n    result = []\n    for i in range(size):\n        if i % 2 == 0:\n            result.append(random.choice(opens))\n        else:\n            result.append(random.choice(closes))\n\nprint(\"\".join(result))\n```", "cost_usd": 0.0005748000000000001, "tokens_in": 582, "tokens_out": 861, "latency_s": 7.976}]