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+[{"task_id": "mmlu-8564", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] For which of these two scenarios does the main character (who uses I/me/my) do something clearly morally wrong, according to ordinary moral standards in the US as of 2020? Scenario 1 | The excitement of the car crash made me cheer. Scenario 2 | My friend asked me to draw her doing something cool, so I drew her skydiving.\nA) Wrong, Wrong\nB) Wrong, Not wrong\nC) Not wrong, Wrong\nD) Not wrong, Not wrong\n\nAnswer with the letter only.", "response": "B", "cost_usd": 1.48e-05, "tokens_in": 118, "tokens_out": 5, "latency_s": 4.954}, {"task_id": "mmlu-8238", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU]  Corvino considers the following argument: Homosexuals are \"born that way\"; therefore, homosexual activity is good and natural. Corvino claims that this argument is unsound. Why?\nA) It ignores the possibility that homosexuality is a lifestyle choice.\nB) It assumes that all innate desires are good ones.\nC) It is equivalent to recognizing that homosexuality is unusual.\nD) None of the above\n\nAnswer with the letter only.", "response": "B", "cost_usd": 3.98e-05, "tokens_in": 98, "tokens_out": 50, "latency_s": 2.126}, {"task_id": "gsm8k-515", "model": "openai/gpt-5.6-luna", "prompt": "Tara bought 8 packs of 5 canvas bags for $4 each. She painted them and sold them at a craft fair for $8 each. How much profit did she earn on her bags?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put only the final numeric result on the last line. Audit marker 188412511236150659 is answer-independent metadata; do not reproduce it.", "response": "She bought \\(8 \\times 5 = 40\\) bags.\n\nHer total cost was \\(40 \\times \\$4 = \\$160\\).\n\nHer total sales were \\(40 \\times \\$8 = \\$320\\).\n\nProfit \\(= \\$320 - \\$160 = \\$160\\).\n\n160", "cost_usd": 0.00010759999999999999, "tokens_in": 98, "tokens_out": 163, "latency_s": 3.469}, {"task_id": "gsm8k-650", "model": "openai/gpt-5.6-luna", "prompt": "On Tuesday, Clara bought 20 pomegranates at $20 each. At the till she got $2 off because she had a voucher. The next day, the price shot to $30 per fruit, but the store also offered a 10% discount on the total cost. Sheila took advantage of the discount and bought 20 pomegranates. What is the difference between the final prices paid for the pomegranates on the two days?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put only the final numeric result on the last line. Audit marker 6762046148670721331 is answer-independent metadata; do not reproduce it.", "response": "Tuesday: \\(20 \\times \\$20 = \\$400\\), then subtract the \\$2 voucher: \\(\\$400 - \\$2 = \\$398\\).\n\nWednesday: \\(20 \\times \\$30 = \\$600\\), then apply the 10% discount: \\(\\$600 \\times 0.90 = \\$540\\).\n\nDifference: \\(\\$540 - \\$398 = \\$142\\).\n\n142", "cost_usd": 0.00010839999999999998, "tokens_in": 148, "tokens_out": 156, "latency_s": 3.159}, {"task_id": "lcb-abc398_a", "model": "openai/gpt-5.6-luna", "prompt": "Find a length-N string that satisfies all of the following conditions:\n\n- Each character is - or =.\n- It is a palindrome.\n- It contains exactly one or exactly two =s. If it contains two =s, they are adjacent.\n\nSuch a string is unique.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 100\n- N is an integer.\n\nSample Input 1\n\n4\n\nSample Output 1\n\n-==-\n\nSample Input 2\n\n7\n\nSample Output 2\n\n---=---\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive a complete solution from the full statement and constraints. Privately create a small-state specification and use it to challenge your algorithm. Check boundaries, ordering, multiplicity, repeated values, overflow, and complexity. Trace every published example and return only complete raw Python 3 source with no Markdown or prose.", "response": "import sys\n\nn = int(sys.stdin.readline())\nequals = \"=\" * (1 if n % 2 else 2)\ndashes = \"-\" * ((n - len(equals)) // 2)\nprint(dashes + equals + dashes)\n", "cost_usd": 0.00016629999999999998, "tokens_in": 229, "tokens_out": 239, "latency_s": 3.05}, {"task_id": "lcb-abc390_d", "model": "openai/gpt-5.6-luna", "prompt": "There are N bags, labeled bag 1, bag 2, \\ldots, bag N.\r\nBag i (1 \\leq i \\leq N) contains A_i stones.\nTakahashi can perform the following operation any number of times, possibly zero:\n\nChoose two bags A and B, and move all stones from bag A into bag B.\n\nFind the number of different possible values for the following after repeating the operation.\n\n- B_1 \\oplus B_2 \\oplus \\cdots \\oplus B_N, where B_i is the final number of stones in bag i.\r\nHere, \\oplus denotes bitwise XOR.\n\n\nAbout bitwise XOR\r\nFor non-negative integers a and b, the bitwise XOR a \\oplus b is defined as follows:\r\n\r\n\r\nIn the binary representation of a \\oplus b, the digit in the 2^k place (k \\ge 0) is 1 if and only if exactly one of the digits in the 2^k place of a and b is 1; otherwise, it is 0.\r\n\r\n\r\nFor example, 3 \\oplus 5 = 6 (in binary, 011 \\oplus 101 = 110).\r\nIn general, for k non-negative integers x_1, x_2, \\ldots, x_k, their bitwise XOR x_1 \\oplus x_2 \\oplus \\cdots \\oplus x_k is defined as (\\cdots((x_1 \\oplus x_2) \\oplus x_3) \\oplus \\cdots) \\oplus x_k, which does not depend on the order of x_1, x_2, \\ldots, x_k.\r\n\nIt can be proved that under the constraints of this problem, the number of possible values is finite.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the number of different possible values for B_1 \\oplus B_2 \\oplus \\cdots \\oplus B_N after repeating the operation.\n\nConstraints\n\n\n- 2 \\leq N \\leq 12\n- 1 \\leq A_i \\leq 10^{17}\n- All input values are integers.\n\nSample Input 1\n\n3\r\n2 5 7\n\nSample Output 1\n\n3\r\n\nFor example, if Takahashi chooses bags 1 and 3 for the operation, then the numbers of stones in bags 1, 2, 3 become 0, 5, 9.\r\nIf he stops at this point, the XOR is 0 \\oplus 5 \\oplus 9 = 12.\nThe other possible XOR values after repeating the operation are 0 and 14.\r\nTherefore, the possible values are 0, 12, 14; there are three values, so the output is 3.\n\nSample Input 2\n\n2\r\n100000000000000000 100000000000000000\n\nSample Output 2\n\n2\n\nSample Input 3\n\n6\r\n71 74 45 34 31 60\n\nSample Output 3\n\n84\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive a complete solution from the full statement and constraints. Privately create a small-state specification and use it to challenge your algorithm. Check boundaries, ordering, multiplicity, repeated values, overflow, and complexity. Trace every published example and return only complete raw Python 3 source with no Markdown or prose.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    n = data[0]\n    values = data[1:]\n\n    block_sums = [0] * n\n    results = set()\n    add_result = results.add\n\n    def dfs(i, block_count, current_xor):\n        if i == n:\n            add_result(current_xor)\n            return\n\n        value = values[i]\n        next_i = i + 1\n\n        for j in range(block_count):\n            old_sum = block_sums[j]\n            new_sum = old_sum + value\n            block_sums[j] = new_sum\n            dfs(next_i, block_count, current_xor ^ old_sum ^ new_sum)\n            block_sums[j] = old_sum\n\n        block_sums[block_count] = value\n        dfs(next_i, block_count + 1, current_xor ^ value)\n\n    dfs(0, 0, 0)\n    print(len(results))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.0051832, "tokens_in": 766, "tokens_out": 8511, "latency_s": 84.305}, {"task_id": "lcb-abc390_d", "model": "google/gemini-3.6-flash", "prompt": "There are N bags, labeled bag 1, bag 2, \\ldots, bag N.\r\nBag i (1 \\leq i \\leq N) contains A_i stones.\nTakahashi can perform the following operation any number of times, possibly zero:\n\nChoose two bags A and B, and move all stones from bag A into bag B.\n\nFind the number of different possible values for the following after repeating the operation.\n\n- B_1 \\oplus B_2 \\oplus \\cdots \\oplus B_N, where B_i is the final number of stones in bag i.\r\nHere, \\oplus denotes bitwise XOR.\n\n\nAbout bitwise XOR\r\nFor non-negative integers a and b, the bitwise XOR a \\oplus b is defined as follows:\r\n\r\n\r\nIn the binary representation of a \\oplus b, the digit in the 2^k place (k \\ge 0) is 1 if and only if exactly one of the digits in the 2^k place of a and b is 1; otherwise, it is 0.\r\n\r\n\r\nFor example, 3 \\oplus 5 = 6 (in binary, 011 \\oplus 101 = 110).\r\nIn general, for k non-negative integers x_1, x_2, \\ldots, x_k, their bitwise XOR x_1 \\oplus x_2 \\oplus \\cdots \\oplus x_k is defined as (\\cdots((x_1 \\oplus x_2) \\oplus x_3) \\oplus \\cdots) \\oplus x_k, which does not depend on the order of x_1, x_2, \\ldots, x_k.\r\n\nIt can be proved that under the constraints of this problem, the number of possible values is finite.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the number of different possible values for B_1 \\oplus B_2 \\oplus \\cdots \\oplus B_N after repeating the operation.\n\nConstraints\n\n\n- 2 \\leq N \\leq 12\n- 1 \\leq A_i \\leq 10^{17}\n- All input values are integers.\n\nSample Input 1\n\n3\r\n2 5 7\n\nSample Output 1\n\n3\r\n\nFor example, if Takahashi chooses bags 1 and 3 for the operation, then the numbers of stones in bags 1, 2, 3 become 0, 5, 9.\r\nIf he stops at this point, the XOR is 0 \\oplus 5 \\oplus 9 = 12.\nThe other possible XOR values after repeating the operation are 0 and 14.\r\nTherefore, the possible values are 0, 12, 14; there are three values, so the output is 3.\n\nSample Input 2\n\n2\r\n100000000000000000 100000000000000000\n\nSample Output 2\n\n2\n\nSample Input 3\n\n6\r\n71 74 45 34 31 60\n\nSample Output 3\n\n84\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nWork independently without seeing another solution. Return one raw executable Python program derived by a structurally different route. Oracle must be a simple correctness-first program for small legal inputs and must not reuse the candidate algorithm. Generator must accept seed and size arguments, seed Python random, and print one varied legal input. Append oracle lines between comments `# ORACLE-BEGIN` and `# ORACLE-END`, prefixing every line with `#|`. Append generator lines the same way between `# GENERATOR-BEGIN` and `# GENERATOR-END`. Those comment sections must be inert when the complete response is executed as the candidate.", "response": "import sys\n\n\ndef solve():\n    input_data = sys.stdin.read().split()\n    if not input_data:\n        return\n    N = int(input_data[0])\n    A = [int(x) for x in input_data[1:]]\n\n    sum_A = [0] * (1 << N)\n    for i in range(N):\n        sum_A[1 << i] = A[i]\n    for mask in range(1, 1 << N):\n        lsb = mask & -mask\n        sum_A[mask] = sum_A[mask ^ lsb] + sum_A[lsb]\n\n    seen = set()\n\n    def dfs(mask, current_xor):\n        if not mask:\n            seen.add(current_xor)\n            return\n        first_bit = mask & -mask\n        rest = mask ^ first_bit\n        sub = rest\n        while True:\n            T = sub | first_bit\n            dfs(mask ^ T, current_xor ^ sum_A[T])\n            if not sub:\n                break\n            sub = (sub - 1) & rest\n\n    dfs((1 << N) - 1, 0)\n    print(len(seen))\n\n\nif __name__ == \"__main__\":\n    solve()\n\n# ORACLE-BEGIN\n#|import sys\n#|\n#|def get_partitions(lst):\n#|    if not lst:\n#|        yield []\n#|        return\n#|    first = lst[0]\n#|    for p in get_partitions(lst[1:]):\n#|        for i in range(len(p)):\n#|            yield p[:i] + [p[i] + [first]] + p[i+1:]\n#|        yield p + [[first]]\n#|\n#|def oracle_solve():\n#|    input_data = sys.stdin.read().split()\n#|    if not input_data:\n#|        return\n#|    N = int(input_data[0])\n#|    A = [int(x) for x in input_data[1:]]\n#|    \n#|    seen = set()\n#|    for part in get_partitions(A):\n#|        xor_val = 0\n#|        for block in part:\n#|            xor_val ^= sum(block)\n#|        seen.add(xor_val)\n#|    print(len(seen))\n#|\n#|if __name__ == '__main__':\n#|    oracle_solve()\n# ORACLE-END\n\n# GENERATOR-BEGIN\n#|import sys\n#|import random\n#|\n#|def main():\n#|    seed = int(sys.argv[1]) if len(sys.argv) > 1 else 42\n#|    size = int(sys.argv[2]) if len(sys.argv) > 2 else 6\n#|    random.seed(seed)\n#|    \n#|    N = min(12, max(2, size))\n#|    A = [random.randint(1, 10**17) for _ in range(N)]\n#|    \n#|    print(N)\n#|    print(*A)\n#|\n#|if __name__ == '__main__':\n#|    main()\n# GENERATOR-END", "cost_usd": 0.039087, "tokens_in": 881, "tokens_out": 10247, "latency_s": 46.822}]