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+ [{"task_id": "mmlu-4111", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Imagine an economy that produces only two goods cheese and crackers. Calculate GDP for this economy if cheese retails for $3 a pound and 10 pounds are produced while crackers sell for $2 a pound and 20 pounds are produced.\nA) $35 \nB) $1,200 \nC) $70 \nD) $150 \n\nAnswer with the letter only.", "response": "C", "cost_usd": 2.53e-05, "tokens_in": 85, "tokens_out": 28, "latency_s": 3.124}, {"task_id": "mmlu-13211", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] How might the recent global economic crisis be viewed as a challenge to the liberalist perspective?\nA) Governmental cyberspace restrictions, in the form of censorship and monitoring, are increasing.\nB) The crisis has revealed the failure of international cooperation to prevent a global catastrophe, in the form of massive economic collapse and contagion.\nC) All of these options.\nD) Increasing state involvement in key industrial and financial sectors, including nationalisation and state-funded development.\n\nAnswer with the letter only.", "response": "C", "cost_usd": 6.420000000000002e-05, "tokens_in": 108, "tokens_out": 89, "latency_s": 3.629}, {"task_id": "gsm8k-561", "model": "openai/gpt-5.6-luna", "prompt": "If Mark weighs 150 pounds and Susan weighs 20 pounds less than Mark. And their friend Bob weighs twice as much as Susan. What is the average weight of the 3 friends?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put only the final numeric result on the last line. Audit marker 5179556546862238326 is answer-independent metadata; do not reproduce it.", "response": "Mark weighs 150 pounds.\n\nSusan weighs 150 \u2212 20 = 130 pounds.\n\nBob weighs 2 \u00d7 130 = 260 pounds.\n\nTheir total weight is 150 + 130 + 260 = 540 pounds.\n\nAverage weight = 540 \u00f7 3 = 180 pounds.\n\n180", "cost_usd": 7.759999999999999e-05, "tokens_in": 98, "tokens_out": 113, "latency_s": 2.867}, {"task_id": "gsm8k-489", "model": "openai/gpt-5.6-luna", "prompt": "The highest temperature ever recorded in Southlandia is -48 degrees Fahrenheit. The highest temperature ever recorded in Northlandia is 21 degrees Fahrenheit. The highest temperature recorded in Midlandia is -3 degrees Fahrenheit. What is the average highest temperature of these 3 countries?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put only the final numeric result on the last line. Audit marker 15812151835472309861 is answer-independent metadata; do not reproduce it.", "response": "Add the three temperatures:\n\n-48 + 21 + (-3) = -30\n\nDivide by 3:\n\n-30 \u00f7 3 = -10\n\n-10", "cost_usd": 6.83e-05, "tokens_in": 113, "tokens_out": 95, "latency_s": 2.797}, {"task_id": "lcb-abc395_b", "model": "openai/gpt-5.6-luna", "prompt": "Overview: Create an N \\times N pattern as follows.\n\n###########\n#.........#\n#.#######.#\n#.#.....#.#\n#.#.###.#.#\n#.#.#.#.#.#\n#.#.###.#.#\n#.#.....#.#\n#.#######.#\n#.........#\n###########\n\n\nYou are given a positive integer N.\nConsider an N \\times N grid. Let (i,j) denote the cell at the i-th row from the top and the j-th column from the left. Initially, no cell is colored.\nThen, for i = 1,2,\\dots,N in order, perform the following operation:\n\n- Let j = N + 1 - i.\n- If i \\leq j, fill the rectangular region whose top-left cell is (i,i) and bottom-right cell is (j,j) with black if i is odd, or white if i is even. If some cells are already colored, overwrite their colors. \n- If i > j, do nothing.\n\nAfter all these operations, it can be proved that there are no uncolored cells. Determine the final color of each cell.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\n\nOutput\n\nPrint N lines. The i-th line should contain a length-N string S_i representing the colors of the i-th row of the grid after all operations, as follows:\n\n- If cell (i,j) is finally colored black, the j-th character of S_i should be #.\n- If cell (i,j) is finally colored white, the j-th character of S_i should be ..\n\nConstraints\n\n\n- 1 \\leq N \\leq 50\n- All input values are integers.\n\nSample Input 1\n\n11\n\nSample Output 1\n\n###########\n#.........#\n#.#######.#\n#.#.....#.#\n#.#.###.#.#\n#.#.#.#.#.#\n#.#.###.#.#\n#.#.....#.#\n#.#######.#\n#.........#\n###########\n\nThis matches the pattern shown in the Overview.\n\nSample Input 2\n\n5\n\nSample Output 2\n\n#####\n#...#\n#.#.#\n#...#\n#####\n\nColors are applied as follows, where ? denotes a cell not yet colored:\n i=1 i=2 i=3 i=4 i=5\n????? ##### ##### ##### ##### #####\n????? ##### #...# #...# #...# #...#\n????? -> ##### -> #...# -> #.#.# -> #.#.# -> #.#.#\n????? ##### #...# #...# #...# #...#\n????? ##### ##### ##### ##### #####\n\nSample Input 3\n\n8\n\nSample Output 3\n\n########\n#......#\n#.####.#\n#.#..#.#\n#.#..#.#\n#.####.#\n#......#\n########\n\nSample Input 4\n\n2\n\nSample Output 4\n\n##\n##\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive a complete solution from the full statement and constraints. Privately create a small-state specification and use it to challenge your algorithm. Check boundaries, ordering, multiplicity, repeated values, overflow, and complexity. Trace every published example and return only complete raw Python 3 source with no Markdown or prose.", "response": "import sys\n\nn = int(sys.stdin.readline())\ngrid = [['?'] * n for _ in range(n)]\n\nfor i in range(n):\n j = n - 1 - i\n if i <= j:\n color = '#' if i % 2 == 0 else '.'\n for r in range(i, j + 1):\n for c in range(i, j + 1):\n grid[r][c] = color\n\nfor row in grid:\n print(''.join(row))", "cost_usd": 0.000254, "tokens_in": 728, "tokens_out": 302, "latency_s": 3.702}, {"task_id": "lcb-abc395_b", "model": "google/gemini-3.6-flash", "prompt": "Overview: Create an N \\times N pattern as follows.\n\n###########\n#.........#\n#.#######.#\n#.#.....#.#\n#.#.###.#.#\n#.#.#.#.#.#\n#.#.###.#.#\n#.#.....#.#\n#.#######.#\n#.........#\n###########\n\n\nYou are given a positive integer N.\nConsider an N \\times N grid. Let (i,j) denote the cell at the i-th row from the top and the j-th column from the left. Initially, no cell is colored.\nThen, for i = 1,2,\\dots,N in order, perform the following operation:\n\n- Let j = N + 1 - i.\n- If i \\leq j, fill the rectangular region whose top-left cell is (i,i) and bottom-right cell is (j,j) with black if i is odd, or white if i is even. If some cells are already colored, overwrite their colors. \n- If i > j, do nothing.\n\nAfter all these operations, it can be proved that there are no uncolored cells. Determine the final color of each cell.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\n\nOutput\n\nPrint N lines. The i-th line should contain a length-N string S_i representing the colors of the i-th row of the grid after all operations, as follows:\n\n- If cell (i,j) is finally colored black, the j-th character of S_i should be #.\n- If cell (i,j) is finally colored white, the j-th character of S_i should be ..\n\nConstraints\n\n\n- 1 \\leq N \\leq 50\n- All input values are integers.\n\nSample Input 1\n\n11\n\nSample Output 1\n\n###########\n#.........#\n#.#######.#\n#.#.....#.#\n#.#.###.#.#\n#.#.#.#.#.#\n#.#.###.#.#\n#.#.....#.#\n#.#######.#\n#.........#\n###########\n\nThis matches the pattern shown in the Overview.\n\nSample Input 2\n\n5\n\nSample Output 2\n\n#####\n#...#\n#.#.#\n#...#\n#####\n\nColors are applied as follows, where ? denotes a cell not yet colored:\n i=1 i=2 i=3 i=4 i=5\n????? ##### ##### ##### ##### #####\n????? ##### #...# #...# #...# #...#\n????? -> ##### -> #...# -> #.#.# -> #.#.# -> #.#.#\n????? ##### #...# #...# #...# #...#\n????? ##### ##### ##### ##### #####\n\nSample Input 3\n\n8\n\nSample Output 3\n\n########\n#......#\n#.####.#\n#.#..#.#\n#.#..#.#\n#.####.#\n#......#\n########\n\nSample Input 4\n\n2\n\nSample Output 4\n\n##\n##\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nWork independently without seeing another solution. Return one raw executable Python program derived by a structurally different route. Oracle must be a simple correctness-first program for small legal inputs and must not reuse the candidate algorithm. Generator must accept seed and size arguments, seed Python random, and print one varied legal input. Append oracle lines between comments `# ORACLE-BEGIN` and `# ORACLE-END`, prefixing every line with `#|`. Append generator lines the same way between `# GENERATOR-BEGIN` and `# GENERATOR-END`. Those comment sections must be inert when the complete response is executed as the candidate.", "response": "import sys\n\n\ndef main():\n input_data = sys.stdin.read().split()\n if not input_data:\n return\n n = int(input_data[0])\n lines = []\n for r in range(1, n + 1):\n row = []\n for c in range(1, n + 1):\n d = min(r, n + 1 - r, c, n + 1 - c)\n row.append(\"#\" if d % 2 == 1 else \".\")\n lines.append(\"\".join(row))\n print(\"\\n\".join(lines))\n\n\nif __name__ == \"__main__\":\n main()\n\n# ORACLE-BEGIN\n#|import sys\n#|\n#|def oracle_solve(input_str):\n#| n = int(input_str.strip())\n#| grid = [['?'] * n for _ in range(n)]\n#| for i in range(1, n + 1):\n#| j = n + 1 - i\n#| if i <= j:\n#| color = '#' if i % 2 == 1 else '.'\n#| for r in range(i - 1, j):\n#| for c in range(i - 1, j):\n#| grid[r][c] = color\n#| return '\\n'.join(''.join(row) for row in grid)\n#|\n#|if __name__ == '__main__':\n#| print(oracle_solve(sys.stdin.read()))\n# ORACLE-END\n\n# GENERATOR-BEGIN\n#|import sys\n#|import random\n#|\n#|def main():\n#| seed = int(sys.argv[1]) if len(sys.argv) > 1 else 0\n#| size = int(sys.argv[2]) if len(sys.argv) > 2 else 50\n#| random.seed(seed)\n#| n = random.randint(1, max(1, min(size, 50)))\n#| print(n)\n#|\n#|if __name__ == '__main__':\n#| main()\n# GENERATOR-END", "cost_usd": 0.00977925, "tokens_in": 824, "tokens_out": 2443, "latency_s": 10.775}, {"task_id": "lcb-abc399_c", "model": "openai/gpt-5.6-luna", "prompt": "You are given a simple undirected graph with N vertices and M edges, where the vertices are labeled 1 to N. The i-th edge connects vertices u_i and v_i.\r\nWhat is the minimum number of edges that need to be deleted from this graph so that the graph becomes a forest?\n\nWhat is a forest?\r\n\r\nA simple undirected graph F is called a forest if and only if F does not contain any cycle.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\r\nu_1 v_1\r\nu_2 v_2\r\n\\vdots\r\nu_M v_M\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 0 \\leq M \\leq \\min \\left( \\frac{N(N-1)}{2}, 2 \\times 10^5\\right)\n- 1 \\leq u_i < v_i \\leq N\n- The given graph is simple.\n- All input values are integers.\n\nSample Input 1\n\n4 4\r\n1 2\r\n1 3\r\n2 4\r\n3 4\n\nSample Output 1\n\n1\r\n\nFor example, if you delete the first edge, the graph becomes a forest.\n\nSample Input 2\n\n5 0\n\nSample Output 2\n\n0\n\nSample Input 3\n\n10 10\r\n7 9\r\n4 6\r\n6 10\r\n2 5\r\n5 6\r\n5 9\r\n6 8\r\n4 8\r\n1 5\r\n1 4\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive a complete solution from the full statement and constraints. Privately create a small-state specification and use it to challenge your algorithm. Check boundaries, ordering, multiplicity, repeated values, overflow, and complexity. Trace every published example and return only complete raw Python 3 source with no Markdown or prose.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nif not data:\n sys.exit()\n\nn, m = data[0], data[1]\nparent = list(range(n))\nsize = [1] * n\ndeleted = 0\n\ndef find(x):\n while parent[x] != x:\n parent[x] = parent[parent[x]]\n x = parent[x]\n return x\n\nidx = 2\nfor _ in range(m):\n u = data[idx] - 1\n v = data[idx + 1] - 1\n idx += 2\n\n ru = find(u)\n rv = find(v)\n\n if ru == rv:\n deleted += 1\n else:\n if size[ru] < size[rv]:\n ru, rv = rv, ru\n parent[rv] = ru\n size[ru] += size[rv]\n\nprint(deleted)\n", "cost_usd": 0.00027699999999999947, "tokens_in": 442, "tokens_out": 388, "latency_s": 4.365}]