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[{"task_id": "mmlu-4781", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A solid plastic cube with uniform density (side length = 0.5 m) of mass 100 kg is placed in a vat of fluid whose density is 1200 kg/m^3. What fraction of the cube's volume floats above the surface of the fluid?\nA) 1.0/9\nB) 1.0/3\nC) 2.0/3\nD) 4.0/5\n\nAnswer with the letter only.", "response": "B", "cost_usd": 3.71e-05, "tokens_in": 107, "tokens_out": 44, "latency_s": 3.864}, {"task_id": "mmlu-9033", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] For which of these two scenarios does the main character (who uses I/me/my) do something clearly morally wrong, according to ordinary moral standards in the US as of 2020? Scenario 1 | My brother is in a wheelchair so I got him a skateboard video game. Scenario 2 | I put sugar in random cars' gas tanks.\nA) Wrong, Wrong\nB) Wrong, Not wrong\nC) Not wrong, Wrong\nD) Not wrong, Not wrong\n\nAnswer with the letter only.", "response": "C", "cost_usd": 1.4399999999999998e-05, "tokens_in": 114, "tokens_out": 5, "latency_s": 0.813}, {"task_id": "gsm8k-763", "model": "openai/gpt-5.6-luna", "prompt": "Rob, Royce, and Pedro are contractors getting ready to put a new roof on three homes. If the three homes will need 250 cases of shingles, with the first house needing 1/2 of the second, and the third needing double the first. How many cases of shingles will the third house need?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put only the final numeric result on the last line. Audit marker 2461995447352915099 is answer-independent metadata; do not reproduce it.", "response": "Let the second house need \\(x\\) cases.\n\n- First house: \\(\\frac{x}{2}\\)\n- Third house: \\(2 \\times \\frac{x}{2} = x\\)\n- Total: \\(\\frac{x}{2} + x + x = 250\\)\n\nThus, \\(2.5x = 250\\), so \\(x = 100\\).\n\n100", "cost_usd": 0.0001039, "tokens_in": 121, "tokens_out": 153, "latency_s": 3.474}, {"task_id": "gsm8k-633", "model": "openai/gpt-5.6-luna", "prompt": "Bob is 75 miles ahead of Tom, driving 55 miles per hour. Tom is driving 70 miles per hour. How long will it take Tom to catch up with Bob?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and put only the final numeric result on the last line. Audit marker 9974624721764799901 is answer-independent metadata; do not reproduce it.", "response": "Tom gains on Bob at:\n\n70 \u2212 55 = 15 miles per hour\n\nTime to close the 75-mile gap:\n\n75 \u00f7 15 = 5 hours\n\n5", "cost_usd": 8.03e-05, "tokens_in": 95, "tokens_out": 118, "latency_s": 2.916}, {"task_id": "lcb-abc392_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a sequence of integers A = (A_1, A_2, A_3).\r\nLet B = (B_1, B_2, B_3) be any permutation of A.\r\nDetermine whether it is possible that B_1 \\times B_2 = B_3.\n\nInput\n\nThe input is given from Standard Input in the following format:\nA_1 A_2 A_3\n\nOutput\n\nIf it is possible that B_1 \\times B_2 = B_3, print Yes; otherwise, print No.\n\nConstraints\n\n\n- All input values are integers.\n- 1 \\le A_1, A_2, A_3 \\le 100\n\nSample Input 1\n\n3 15 5\n\nSample Output 1\n\nYes\r\n\nHere, A=(3,15,5).\r\nBy rearranging it as B=(3,5,15), we can satisfy B_1 \\times B_2 = B_3.\n\nSample Input 2\n\n5 3 2\n\nSample Output 2\n\nNo\r\n\nNo permutation of B satisfies B_1 \\times B_2 = B_3.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive a complete solution from the full statement and constraints. Privately create a small-state specification and use it to challenge your algorithm. Check boundaries, ordering, multiplicity, repeated values, overflow, and complexity. Trace every published example and return only complete raw Python 3 source with no Markdown or prose.", "response": "import sys\n\na = list(map(int, sys.stdin.read().split()))\n\npossible = any(a[k] == a[i] * a[j] for i in range(3) for j in range(i + 1, 3) for k in range(3) if k != i and k != j)\n\nprint(\"Yes\" if possible else \"No\")", "cost_usd": 0.0001257, "tokens_in": 339, "tokens_out": 153, "latency_s": 5.643}, {"task_id": "lcb-arc195_a", "model": "openai/gpt-5.6-luna", "prompt": "There is a sequence A = (A_1,\\dots,A_N). Determine whether there are at least two subsequences of A that match the sequence B = (B_1,\\dots,B_M). Two subsequences are distinguished if they are taken from different positions, even if they coincide as sequences.\n\nSubsequence\nA subsequence of A is a sequence obtained by removing zero or more elements from A and leaving the remaining elements in their original order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\ldots A_N\nB_1 B_2 \\ldots B_M\n\nOutput\n\nIf there are at least two subsequences of A that match B, print Yes. Otherwise, print No.\n\nConstraints\n\n\n- 1 \\leq M \\leq N \\leq 2\\times 10^5\n- 1 \\leq A_i \\leq 10^9\n- 1 \\leq B_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n4 2\n1 2 1 2\n1 2\n\nSample Output 1\n\nYes\n\nThere are three subsequences of A that match B: (A_1,A_2), (A_1,A_4), (A_3,A_4).\n\nSample Input 2\n\n3 2\n1 2 1\n1 2\n\nSample Output 2\n\nNo\n\nThere is only one subsequence of A that matches B: (A_1,A_2).\n\nSample Input 3\n\n3 2\n1 1 2\n2 1\n\nSample Output 3\n\nNo\n\nThere are no subsequences of A that match B.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive a complete solution from the full statement and constraints. Privately create a small-state specification and use it to challenge your algorithm. Check boundaries, ordering, multiplicity, repeated values, overflow, and complexity. Trace every published example and return only complete raw Python 3 source with no Markdown or prose.", "response": "import sys\nfrom bisect import bisect_right\n\ndef main():\n data = list(map(int, sys.stdin.buffer.read().split()))\n n, m = data[0], data[1]\n a = data[2:2 + n]\n b = data[2 + n:2 + n + m]\n\n positions = {}\n for i, value in enumerate(a):\n positions.setdefault(value, []).append(i)\n\n earliest = []\n pos = 0\n for value in b:\n while pos < n and a[pos] != value:\n pos += 1\n if pos == n:\n print(\"No\")\n return\n earliest.append(pos)\n pos += 1\n\n latest = [n] * (m + 1)\n pos = n - 1\n for i in range(m - 1, -1, -1):\n while pos >= 0 and a[pos] != b[i]:\n pos -= 1\n if pos < 0:\n print(\"No\")\n return\n latest[i] = pos\n pos -= 1\n\n for i, value in enumerate(b):\n candidates = positions[value]\n index = bisect_right(candidates, earliest[i])\n if index < len(candidates) and candidates[index] < latest[i + 1]:\n print(\"Yes\")\n return\n\n print(\"No\")\n\nif __name__ == \"__main__\":\n main()\n", "cost_usd": 0.0017849000000000003, "tokens_in": 467, "tokens_out": 2897, "latency_s": 27.902}]
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