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+[{"task_id": "mmlu-3886", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Which of the following insures the value of the U.S. dollar?\nA) The euro and other foreign currencies held by the Federal Reserve\nB) Gold bars in secure locations like Fort Knox\nC) The promise of the U.S. government to maintain its value\nD) The value of the actual paper on which it is printed.\n\nAnswer with the letter only.", "response": "C", "cost_usd": 1.15e-05, "tokens_in": 85, "tokens_out": 5, "latency_s": 1.761}, {"task_id": "mmlu-11904", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A father conveyed a parcel of real estate to his three daughters by a warranty deed. The deed recited that the title was conveyed to the three siblings \"as joint tenants with the right of survivorship, and not as tenants in common.\" One of the sisters, during the lifetime of all three, conveyed an \"undivided one-third interest\" to a third party. The third party died, leaving a will that bequeathed her one-third interest to her son. Is the son's ownership interest enforceable in the face of the claim by the two non-selling sisters that they own 100% of the property pursuant to the law regarding joint tenancies?\nA) No, because each joint tenant owns an equal and undivided interest in the whole of the property, making invalid the sister's attempted conveyance of a one-third interest.\nB) Yes, only a will can create a joint tenancy; the deed was invalid for that purpose and resulted in a tenancy in common by operation of law.\nC) Yes, because the conveyance severed the joint tenancy, and the third party took a one-third interest that she could pass by will to her son.\nD) No, because the selling sister did not take steps to get a court order to sever the joint tenancy prior to conveying a deed to a third party.\n\nAnswer with the letter only.", "response": "C", "cost_usd": 3.12e-05, "tokens_in": 282, "tokens_out": 5, "latency_s": 0.938}, {"task_id": "gsm8k-436", "model": "openai/gpt-5.6-luna", "prompt": "Rory makes a cake that weighs 20 ounces. She cuts into 8 pieces. Rory and her mom each have a piece. How much does the remaining cake weigh?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and privately verify arithmetic, signs, rounding, and boundary assumptions. Put only the final numeric result on the last line.", "response": "The cake is divided into 8 equal pieces.\n\nEach piece weighs \\(20 \\div 8 = 2.5\\) ounces.\n\nRory and her mom take 2 pieces, leaving \\(8 - 2 = 6\\) pieces.\n\nThe remaining cake weighs \\(6 \\times 2.5 = 15\\) ounces.\n\n15", "cost_usd": 9.13e-05, "tokens_in": 85, "tokens_out": 138, "latency_s": 2.988}, {"task_id": "gsm8k-199", "model": "openai/gpt-5.6-luna", "prompt": "Mark is a copy-editor. He edits an equal number of sentences each week for two different publishers, who each pay him a different rate per sentence. Publisher B pays Mark twice what Publisher A pays. Mark edits a total number of 1000 sentences each week, and Publisher A pays him 5 cents per sentence. How much does Mark make in a week, in cents?\n\nReason step by step, then give the final answer as a single number.\n\nSolve in the requested units and privately verify arithmetic, signs, rounding, and boundary assumptions. Put only the final numeric result on the last line.", "response": "Mark edits 1000 sentences total, split equally between the publishers:\n\n- Publisher A: 500 sentences at 5 cents each = 2500 cents\n- Publisher B: 500 sentences at 10 cents each = 5000 cents\n\nTotal weekly earnings: 2500 + 5000 =\n\n7500", "cost_usd": 8.58e-05, "tokens_in": 126, "tokens_out": 122, "latency_s": 2.86}, {"task_id": "lcb-abc388_b", "model": "openai/gpt-5.6-luna", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive the algorithm from the complete specification and maximum constraints. Privately construct a small direct specification and try to falsify the proposed algorithm. Check ordering, multiplicity, repeated values, boundaries, state changes, and complexity. Trace every published example. The execution harness compares output tokens exactly even when the problem prose grants mathematical tolerance. Match the required canonical representation, precision, rounding, ordering, and separators shown by the statement and examples. Do not print extra precision merely because it is available. Return only one complete raw Python 3 program without Markdown, fences, or explanation.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    n, d = data[0], data[1]\n    snakes = [(data[i], data[i + 1]) for i in range(2, 2 + 2 * n, 2)]\n\n    ans = []\n    for k in range(1, d + 1):\n        ans.append(str(max(t * (l + k) for t, l in snakes)))\n\n    sys.stdout.write(\"\\n\".join(ans))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.00012659999999999996, "tokens_in": 516, "tokens_out": 125, "latency_s": 1.762}, {"task_id": "lcb-abc388_b", "model": "openai/gpt-5.6-luna", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nWork independently from the statement and do not assume any candidate implementation. Write a correctness-first oracle for small legal inputs using direct simulation or exhaustive search. Also write a generator accepting seed and size arguments, seeding Python random, and printing one varied legal input. Systematically include legal ties and equalities, repeated values, minimum counts, endpoints, mandatory final transitions, and choices where an equal local action changes a later opportunity. Vary these boundary families from the seed instead of emitting a fixed example. The oracle must not reuse the efficient algorithm requested by the statement. The execution harness compares output tokens exactly even when the prose permits numerical tolerance. Reproduce every published output token exactly and infer one canonical representation for unseen outputs from the statement and examples without inventing extra precision. Return exactly two fenced blocks named oracle and generator, with no other text.", "response": "```oracle\nimport sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    if not data:\n        return\n\n    n, d = data[0], data[1]\n    snakes = [(data[i], data[i + 1]) for i in range(2, 2 + 2 * n)]\n\n    answers = []\n    for k in range(1, d + 1):\n        best = 0\n        for thickness, length in snakes:\n            weight = thickness * (length + k)\n            if weight > best:\n                best = weight\n        answers.append(str(best))\n\n    sys.stdout.write(\"\\n\".join(answers))\n\nif __name__ == \"__main__\":\n    main()\n```\n\n```generator\nimport random\nimport sys\n\ndef main():\n    if len(sys.argv) != 3:\n        raise SystemExit(\"usage: generator.py SEED SIZE\")\n\n    seed = int(sys.argv[1])\n    size = max(1, int(sys.argv[2]))\n    random.seed(seed)\n\n    n = 1 + random.randrange(size)\n    d = 1 + random.randrange(size)\n\n    mode = seed % 8\n    snakes = []\n\n    for i in range(n):\n        if mode == 0:\n            t = 1 if i % 2 == 0 else 100\n            l = 1 if i % 3 else 100\n        elif mode == 1:\n            t = random.choice([1, 2, 50, 99, 100])\n            l = random.choice([1, 2, 50, 99, 100])\n        elif mode == 2:\n            t = random.randint(1, min(100, max(1, size)))\n            l = random.randint(1, min(100, max(1, size)))\n        elif mode == 3:\n            t = min(100, 1 + i)\n            l = min(100, 100 - i)\n        elif mode == 4:\n            t = random.randint(1, 100)\n            l = max(1, min(100, 101 - t))\n        elif mode == 5:\n            t = random.choice([25, 50, 75])\n            l = random.choice([25, 50, 75])\n        elif mode == 6:\n            t = 100 if i == 0 else random.randint(1, 100)\n            l = 1 if i == 0 else random.randint(1, 100)\n        else:\n            if i == 0:\n                t, l = 1, 100\n            elif i == 1:\n                t, l = 100, 1\n            else:\n                t = random.randint(1, 100)\n                l = random.randint(1, 100)\n\n        snakes.append((t, l))\n\n    if n >= 2 and seed % 3 == 0:\n        t = random.randint(1, 100)\n        l = random.randint(1, 100)\n        snakes[0] = (t, l)\n        snakes[1] = (t, l)\n\n    if n >= 3 and seed % 5 == 0:\n        snakes[0] = (1, 100)\n        snakes[1] = (2, 99)\n        snakes[2] = (3, 98)\n\n    print(n, d)\n    for t, l in snakes:\n        print(t, l)\n\nif __name__ == \"__main__\":\n    main()\n```", "cost_usd": 0.0006929, "tokens_in": 569, "tokens_out": 1060, "latency_s": 8.627}, {"task_id": "lcb-abc388_b", "model": "google/gemini-3.6-flash", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nWork independently from the statement and do not assume any candidate implementation. Write a correctness-first oracle for small legal inputs using direct simulation or exhaustive search. Also write a generator accepting seed and size arguments, seeding Python random, and printing one varied legal input. Systematically include legal ties and equalities, repeated values, minimum counts, endpoints, mandatory final transitions, and choices where an equal local action changes a later opportunity. Vary these boundary families from the seed instead of emitting a fixed example. The oracle must not reuse the efficient algorithm requested by the statement. The execution harness compares output tokens exactly even when the prose permits numerical tolerance. Reproduce every published output token exactly and infer one canonical representation for unseen outputs from the statement and examples without inventing extra precision. Return exactly two fenced blocks named oracle and generator, with no other text.", "response": "```oracle\nimport sys\n\ndef main():\n    input_data = sys.stdin.read().split()\n    if not input_data:\n        return\n    \n    N = int(input_data[0])\n    D = int(input_data[1])\n    \n    snakes = []\n    idx = 2\n    for _ in range(N):\n        t = int(input_data[idx])\n        l = int(input_data[idx+1])\n        snakes.append((t, l))\n        idx += 2\n\n    for k in range(1, D + 1):\n        max_weight = None\n        for t, l in snakes:\n            current_length = l + k\n            weight = t * current_length\n            if max_weight is None or weight > max_weight:\n                max_weight = weight\n        print(max_weight)\n\nif __name__ == '__main__':\n    main()\n```\n\n```generator\nimport random\nimport sys\n\ndef main():\n    seed = int(sys.argv[1]) if len(sys.argv) > 1 else 42\n    size = int(sys.argv[2]) if len(sys.argv) > 2 else 100\n    random.seed(seed)\n\n    # Vary N and D based on size parameter\n    max_n = max(1, min(100, size))\n    max_d = max(1, min(100, size))\n\n    if seed % 5 == 0:\n        N = 1\n    else:\n        N = random.randint(1, max_n)\n    \n    D = random.randint(1, max_d)\n\n    print(f\"{N} {D}\")\n    \n    # Generate snakes with intentional ties and edge cases\n    for i in range(N):\n        if seed % 3 == 0 and i > 0:\n            # Include duplicate/tie values\n            t = random.choice([1, 100, 50])\n            l = random.choice([1, 100, 50])\n        else:\n            t = random.randint(1, 100)\n            l = random.randint(1, 100)\n        print(f\"{t} {l}\")\n\nif __name__ == '__main__':\n    main()\n```", "cost_usd": 0.006960000000000001, "tokens_in": 630, "tokens_out": 1730, "latency_s": 9.008}, {"task_id": "lcb-abc392_d", "model": "openai/gpt-5.6-luna", "prompt": "There are N dice.\r\nThe i-th die has K_i faces, with the numbers A_{i,1}, A_{i,2}, \\ldots, A_{i,K_i} written on them.\r\nWhen you roll this die, each face appears with probability \\frac{1}{K_i}.\nYou choose two dice from the N dice and roll them.\r\nDetermine the maximum probability that the two dice show the same number, when the dice are chosen optimally.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nK_1 A_{1,1} A_{1,2} \\dots A_{1,K_1}\r\n\\vdots\r\nK_N A_{N,1} A_{N,2} \\dots A_{N,K_N}\n\nOutput\n\nPrint the answer.\r\nYour answer is considered correct if the absolute or relative error from the true solution does not exceed 10^{-8}.\n\nConstraints\n\n\n- 2 \\leq N \\leq 100\n- 1 \\leq K_i\n- K_1 + K_2 + \\dots + K_N \\leq 10^5\n- 1 \\leq A_{i,j} \\leq 10^5\n- All input values are integers.\n\nSample Input 1\n\n3\r\n3 1 2 3\r\n4 1 2 2 1\r\n6 1 2 3 4 5 6\n\nSample Output 1\n\n0.333333333333333\r\n\n\n- When choosing the 1st and 2nd dice, the probability that the outcomes are the same is \\frac{1}{3}.\n- When choosing the 1st and 3rd dice, the probability is \\frac{1}{6}.\n- When choosing the 2nd and 3rd dice, the probability is \\frac{1}{6}.\n\nTherefore, the maximum probability is \\frac{1}{3} = 0.3333333333\\ldots.\n\nSample Input 2\n\n3\r\n5 1 1 1 1 1\r\n4 2 2 2 2\r\n3 1 1 2\n\nSample Output 2\n\n0.666666666666667\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nDerive the algorithm from the complete specification and maximum constraints. Privately construct a small direct specification and try to falsify the proposed algorithm. Check ordering, multiplicity, repeated values, boundaries, state changes, and complexity. Trace every published example. The execution harness compares output tokens exactly even when the problem prose grants mathematical tolerance. Match the required canonical representation, precision, rounding, ordering, and separators shown by the statement and examples. Do not print extra precision merely because it is available. Return only one complete raw Python 3 program without Markdown, fences, or explanation.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    it = iter(data)\n    n = next(it)\n\n    ks = [0] * n\n    by_value = [[] for _ in range(100001)]\n\n    for i in range(n):\n        k = next(it)\n        ks[i] = k\n        counts = {}\n        for _ in range(k):\n            x = next(it)\n            counts[x] = counts.get(x, 0) + 1\n        for x, c in counts.items():\n            by_value[x].append((i, c))\n\n    sums = [0] * (n * n)\n\n    for entries in by_value:\n        m = len(entries)\n        for a in range(m):\n            i, ci = entries[a]\n            for b in range(a + 1, m):\n                j, cj = entries[b]\n                sums[i * n + j] += ci * cj\n\n    answer = 0.0\n    for i in range(n):\n        for j in range(i + 1, n):\n            probability = sums[i * n + j] / (ks[i] * ks[j])\n            if probability > answer:\n                answer = probability\n\n    print(f\"{answer:.15f}\")\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.0007839000000000006, "tokens_in": 621, "tokens_out": 1203, "latency_s": 21.657}, {"task_id": "lcb-abc392_d", "model": "openai/gpt-5.6-luna", "prompt": "There are N dice.\r\nThe i-th die has K_i faces, with the numbers A_{i,1}, A_{i,2}, \\ldots, A_{i,K_i} written on them.\r\nWhen you roll this die, each face appears with probability \\frac{1}{K_i}.\nYou choose two dice from the N dice and roll them.\r\nDetermine the maximum probability that the two dice show the same number, when the dice are chosen optimally.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nK_1 A_{1,1} A_{1,2} \\dots A_{1,K_1}\r\n\\vdots\r\nK_N A_{N,1} A_{N,2} \\dots A_{N,K_N}\n\nOutput\n\nPrint the answer.\r\nYour answer is considered correct if the absolute or relative error from the true solution does not exceed 10^{-8}.\n\nConstraints\n\n\n- 2 \\leq N \\leq 100\n- 1 \\leq K_i\n- K_1 + K_2 + \\dots + K_N \\leq 10^5\n- 1 \\leq A_{i,j} \\leq 10^5\n- All input values are integers.\n\nSample Input 1\n\n3\r\n3 1 2 3\r\n4 1 2 2 1\r\n6 1 2 3 4 5 6\n\nSample Output 1\n\n0.333333333333333\r\n\n\n- When choosing the 1st and 2nd dice, the probability that the outcomes are the same is \\frac{1}{3}.\n- When choosing the 1st and 3rd dice, the probability is \\frac{1}{6}.\n- When choosing the 2nd and 3rd dice, the probability is \\frac{1}{6}.\n\nTherefore, the maximum probability is \\frac{1}{3} = 0.3333333333\\ldots.\n\nSample Input 2\n\n3\r\n5 1 1 1 1 1\r\n4 2 2 2 2\r\n3 1 1 2\n\nSample Output 2\n\n0.666666666666667\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nWork independently from the statement and do not assume any candidate implementation. Write a correctness-first oracle for small legal inputs using direct simulation or exhaustive search. Also write a generator accepting seed and size arguments, seeding Python random, and printing one varied legal input. Systematically include legal ties and equalities, repeated values, minimum counts, endpoints, mandatory final transitions, and choices where an equal local action changes a later opportunity. Vary these boundary families from the seed instead of emitting a fixed example. The oracle must not reuse the efficient algorithm requested by the statement. The execution harness compares output tokens exactly even when the prose permits numerical tolerance. Reproduce every published output token exactly and infer one canonical representation for unseen outputs from the statement and examples without inventing extra precision. Return exactly two fenced blocks named oracle and generator, with no other text.", "response": "```oracle\nimport sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    if not data:\n        return\n\n    n = data[0]\n    pos = 1\n    dice = []\n\n    for _ in range(n):\n        k = data[pos]\n        pos += 1\n        faces = data[pos:pos + k]\n        pos += k\n        dice.append(faces)\n\n    best = 0.0\n\n    for i in range(n):\n        for j in range(i + 1, n):\n            same = 0\n            for x in dice[i]:\n                for y in dice[j]:\n                    if x == y:\n                        same += 1\n            probability = same / (len(dice[i]) * len(dice[j]))\n            if probability > best:\n                best = probability\n\n    print(f\"{best:.15f}\")\n\nif __name__ == \"__main__\":\n    main()\n```\n\n```generator\nimport random\nimport sys\n\ndef main():\n    if len(sys.argv) < 3:\n        raise SystemExit(\"usage: generator SEED SIZE\")\n\n    seed = int(sys.argv[1])\n    size = int(sys.argv[2])\n    random.seed(seed)\n\n    n = max(2, min(100, size))\n    dice = []\n    total_faces = 0\n\n    for i in range(n):\n        remaining_dice = n - i - 1\n        max_k = min(30, 100000 - total_faces - remaining_dice)\n        max_k = max(1, max_k)\n\n        family = (seed + i) % 8\n\n        if family == 0:\n            k = 1\n            faces = [1]\n        elif family == 1:\n            k = min(max_k, 2 + random.randrange(max(1, min(8, max_k - 1))))\n            faces = [random.randint(1, 3) for _ in range(k)]\n        elif family == 2:\n            k = min(max_k, 1 + random.randrange(max(1, min(12, max_k))))\n            value = random.choice([1, 2, 99999, 100000])\n            faces = [value] * k\n        elif family == 3:\n            k = min(max_k, 1 + random.randrange(max(1, min(15, max_k))))\n            start = random.choice([1, 2, 99990, 100000])\n            faces = [min(100000, max(1, start + random.randint(-2, 2)))\n                     for _ in range(k)]\n        elif family == 4:\n            k = min(max_k, 1 + random.randrange(max(1, min(20, max_k))))\n            faces = [random.randint(1, 100000) for _ in range(k)]\n        elif family == 5:\n            k = min(max_k, 1 + random.randrange(max(1, min(20, max_k))))\n            base = random.randint(1, 100000)\n            faces = [min(100000, max(1, base + random.choice([-1, 0, 0, 0, 1])))\n                     for _ in range(k)]\n        elif family == 6:\n            k = min(max_k, 1 + random.randrange(max(1, min(10, max_k))))\n            faces = [1 if j % 2 == 0 else 100000 for j in range(k)]\n        else:\n            k = min(max_k, 1 + random.randrange(max(1, min(25, max_k))))\n            pool = [1, 2, 3, 50000, 99999, 100000]\n            faces = [random.choice(pool) for _ in range(k)]\n\n        dice.append(faces)\n        total_faces += k\n\n    print(n)\n    for faces in dice:\n        print(len(faces), *faces)\n\nif __name__ == \"__main__\":\n    main()\n```", "cost_usd": 0.0008821999999999997, "tokens_in": 674, "tokens_out": 1358, "latency_s": 13.105}]