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ray init kwargs: {'num_cpus': None, 'runtime_env': {'env_vars': {'TOKENIZERS_PARALLELISM': 'true', 'NCCL_DEBUG': 'WARN', 'VLLM_LOGGING_LEVEL': 'WARN', 'VLLM_ALLOW_RUNTIME_LORA_UPDATING': 'true', 'VLLM_ALLREDUCE_USE_SYMM_MEM': '0', 'CUDA_DEVICE_MAX_CONNECTIONS': '1', 'NCCL_CUMEM_ENABLE': '0'}}}
2025-11-10 22:23:34,329 INFO worker.py:1606 -- Using address 10.24.1.115:6379 set in the environment variable RAY_ADDRESS
2025-11-10 22:23:34,342 INFO worker.py:1747 -- Connecting to existing Ray cluster at address: 10.24.1.115:6379...
2025-11-10 22:23:34,355 INFO worker.py:1918 -- Connected to Ray cluster. View the dashboard at 10.24.1.115:8265 
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(TaskRunner pid=3309296) 'trace_alloc_max_entries': 100000}}},
(TaskRunner pid=3309296) 'rollout_n': 8,
(TaskRunner pid=3309296) 'shuffle': False,
(TaskRunner pid=3309296) 'strategy': 'fsdp',
(TaskRunner pid=3309296) 'ulysses_sequence_parallel_size': 1,
(TaskRunner pid=3309296) 'use_dynamic_bsz': False},
(TaskRunner pid=3309296) 'custom_reward_function': {'name': 'compute_score', 'path': None},
(TaskRunner pid=3309296) 'data': {'apply_chat_template_kwargs': {},
(TaskRunner pid=3309296) 'custom_cls': {'name': None, 'path': None},
(TaskRunner pid=3309296) 'datagen': {'name': None, 'path': None},
(TaskRunner pid=3309296) 'dataloader_num_workers': 8,
(TaskRunner pid=3309296) 'filter_overlong_prompts': True,
(TaskRunner pid=3309296) 'filter_overlong_prompts_workers': 1,
(TaskRunner pid=3309296) 'image_key': 'images',
(TaskRunner pid=3309296) 'image_patch_size': 14,
(TaskRunner pid=3309296) 'max_prompt_length': 1024,
(TaskRunner pid=3309296) 'max_response_length': 2048,
(TaskRunner pid=3309296) 'prompt_key': 'prompt',
(TaskRunner pid=3309296) 'return_full_prompt': False,
(TaskRunner pid=3309296) 'return_multi_modal_inputs': True,
(TaskRunner pid=3309296) 'return_raw_chat': False,
(TaskRunner pid=3309296) 'return_raw_input_ids': False,
(TaskRunner pid=3309296) 'reward_fn_key': 'data_source',
(TaskRunner pid=3309296) 'sampler': {'class_name': None, 'class_path': None},
(TaskRunner pid=3309296) 'seed': None,
(TaskRunner pid=3309296) 'shuffle': True,
(TaskRunner pid=3309296) 'tokenizer': None,
(TaskRunner pid=3309296) 'tool_config_path': None,
(TaskRunner pid=3309296) 'train_batch_size': 256,
(TaskRunner pid=3309296) 'train_files': '/mnt/weka/home/xuezhe.ma/projects/yewendy/cur_working_dir/data/geo3k/train.parquet',
(TaskRunner pid=3309296) 'train_max_samples': -1,
(TaskRunner pid=3309296) 'truncation': 'error',
(TaskRunner pid=3309296) 'trust_remote_code': False,
(TaskRunner pid=3309296) 'use_shm': False,
(TaskRunner pid=3309296) 'val_batch_size': None,
(TaskRunner pid=3309296) 'val_files': '/mnt/weka/home/xuezhe.ma/projects/yewendy/cur_working_dir/data/geo3k/test.parquet',
(TaskRunner pid=3309296) 'val_max_samples': -1,
(TaskRunner pid=3309296) 'validation_shuffle': False,
(TaskRunner pid=3309296) 'video_key': 'videos'},
(TaskRunner pid=3309296) 'global_profiler': {'_target_': 'verl.utils.profiler.ProfilerConfig',
(TaskRunner pid=3309296) 'global_tool_config': {'nsys': {'_target_': 'verl.utils.profiler.config.NsightToolConfig',
(TaskRunner pid=3309296) 'controller_nsight_options': {'cuda-graph-trace': 'graph',
(TaskRunner pid=3309296) 'cuda-memory-usage': 'true',
(TaskRunner pid=3309296) 'trace': 'cuda,nvtx,cublas,ucx'},
(TaskRunner pid=3309296) 'discrete': False,
(TaskRunner pid=3309296) 'worker_nsight_options': {'capture-range': 'cudaProfilerApi',
(TaskRunner pid=3309296) 'capture-range-end': None,
(TaskRunner pid=3309296) 'cuda-graph-trace': 'graph',
(TaskRunner pid=3309296) 'cuda-memory-usage': 'true',
(TaskRunner pid=3309296) 'kill': 'none',
(TaskRunner pid=3309296) 'trace': 'cuda,nvtx,cublas,ucx'}},
(TaskRunner pid=3309296) 'torch_memory': {'context': 'all',
(TaskRunner pid=3309296) 'kw_args': {},
(TaskRunner pid=3309296) 'stack_depth': 32,
(TaskRunner pid=3309296) 'stacks': 'all',
(TaskRunner pid=3309296) 'trace_alloc_max_entries': 100000}},
(TaskRunner pid=3309296) 'profile_continuous_steps': False,
(TaskRunner pid=3309296) 'save_path': 'outputs/profile',
(TaskRunner pid=3309296) 'steps': None,
(TaskRunner pid=3309296) 'tool': None},
(TaskRunner pid=3309296) 'ray_kwargs': {'ray_init': {'num_cpus': None}, 'timeline_json_file': None},
(TaskRunner pid=3309296) 'reward_model': {'enable': False,
(TaskRunner pid=3309296) 'enable_resource_pool': False,
(TaskRunner pid=3309296) 'forward_max_token_len_per_gpu': 32768,
(TaskRunner pid=3309296) 'launch_reward_fn_async': False,
(TaskRunner pid=3309296) 'max_length': None,
(TaskRunner pid=3309296) 'micro_batch_size': None,
(TaskRunner pid=3309296) 'micro_batch_size_per_gpu': None,
(TaskRunner pid=3309296) 'model': {'external_lib': None,
(TaskRunner pid=3309296) 'fsdp_config': {'_target_': 'verl.workers.config.FSDPEngineConfig',
(TaskRunner pid=3309296) 'forward_prefetch': False,
(TaskRunner pid=3309296) 'fsdp_size': -1,
(TaskRunner pid=3309296) 'param_offload': False,
(TaskRunner pid=3309296) 'reshard_after_forward': True,
(TaskRunner pid=3309296) 'wrap_policy': {'min_num_params': 0}},
(TaskRunner pid=3309296) 'input_tokenizer': 'Qwen/Qwen3-VL-8B-Instruct',
(TaskRunner pid=3309296) 'path': '~/models/FsfairX-LLaMA3-RM-v0.1',
(TaskRunner pid=3309296) 'trust_remote_code': False,
(TaskRunner pid=3309296) 'use_fused_kernels': True,
(TaskRunner pid=3309296) 'use_remove_padding': False,
(TaskRunner pid=3309296) 'use_shm': False},
(TaskRunner pid=3309296) 'n_gpus_per_node': 0,
(TaskRunner pid=3309296) 'nnodes': 0,
(TaskRunner pid=3309296) 'profiler': {'_target_': 'verl.utils.profiler.ProfilerConfig',
(TaskRunner pid=3309296) 'all_ranks': False,
(TaskRunner pid=3309296) 'enable': False,
(TaskRunner pid=3309296) 'ranks': [],
(TaskRunner pid=3309296) 'save_path': 'outputs/profile',
(TaskRunner pid=3309296) 'tool': None,
(TaskRunner pid=3309296) 'tool_config': {'npu': {'_target_': 'verl.utils.profiler.config.NPUToolConfig',
(TaskRunner pid=3309296) 'analysis': True,
(TaskRunner pid=3309296) 'contents': [],
(TaskRunner pid=3309296) 'discrete': False,
(TaskRunner pid=3309296) 'level': 'level1'},
(TaskRunner pid=3309296) 'nsys': {'_target_': 'verl.utils.profiler.config.NsightToolConfig',
(TaskRunner pid=3309296) 'discrete': False},
(TaskRunner pid=3309296) 'torch': {'_target_': 'verl.utils.profiler.config.TorchProfilerToolConfig',
(TaskRunner pid=3309296) 'step_end': None,
(TaskRunner pid=3309296) 'step_start': 0},
(TaskRunner pid=3309296) 'torch_memory': {'_target_': 'verl.utils.profiler.config.TorchMemoryToolConfig',
(TaskRunner pid=3309296) 'stack_depth': 32,
(TaskRunner pid=3309296) 'trace_alloc_max_entries': 100000}}},
(TaskRunner pid=3309296) 'reward_manager': 'naive',
(TaskRunner pid=3309296) 'sandbox_fusion': {'max_concurrent': 64,
(TaskRunner pid=3309296) 'memory_limit_mb': 1024,
(TaskRunner pid=3309296) 'url': None},
(TaskRunner pid=3309296) 'strategy': 'fsdp',
(TaskRunner pid=3309296) 'ulysses_sequence_parallel_size': 1,
(TaskRunner pid=3309296) 'use_dynamic_bsz': False},
(TaskRunner pid=3309296) 'trainer': {'balance_batch': True,
(TaskRunner pid=3309296) 'critic_warmup': 0,
(TaskRunner pid=3309296) 'default_hdfs_dir': None,
(TaskRunner pid=3309296) 'default_local_dir': '/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new',
(TaskRunner pid=3309296) 'del_local_ckpt_after_load': False,
(TaskRunner pid=3309296) 'device': 'cuda',
(TaskRunner pid=3309296) 'esi_redundant_time': 0,
(TaskRunner pid=3309296) 'experiment_name': 'qwen3_vl_8b_geo3k',
(TaskRunner pid=3309296) 'log_val_generations': 0,
(TaskRunner pid=3309296) 'logger': 'wandb',
(TaskRunner pid=3309296) 'max_actor_ckpt_to_keep': None,
(TaskRunner pid=3309296) 'max_critic_ckpt_to_keep': None,
(TaskRunner pid=3309296) 'n_gpus_per_node': 8,
(TaskRunner pid=3309296) 'nnodes': 2,
(TaskRunner pid=3309296) 'project_name': 'verl_grpo_w',
(TaskRunner pid=3309296) 'ray_wait_register_center_timeout': 300,
(TaskRunner pid=3309296) 'resume_from_path': None,
(TaskRunner pid=3309296) 'resume_mode': 'auto',
(TaskRunner pid=3309296) 'rollout_data_dir': None,
(TaskRunner pid=3309296) 'save_freq': 20,
(TaskRunner pid=3309296) 'test_freq': 5,
(TaskRunner pid=3309296) 'total_epochs': 100,
(TaskRunner pid=3309296) 'total_training_steps': None,
(TaskRunner pid=3309296) 'use_legacy_worker_impl': 'auto',
(TaskRunner pid=3309296) 'val_before_train': True,
(TaskRunner pid=3309296) 'val_only': False,
(TaskRunner pid=3309296) 'validation_data_dir': None},
(TaskRunner pid=3309296) 'transfer_queue': {'enable': False}}
(TaskRunner pid=3309296) /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/trainer/main_ppo.py:274: UserWarning: Disabled critic as algorithm.adv_estimator != gae. If it is not intended, please set critic.enable=True
(TaskRunner pid=3309296) use_critic=need_critic(config),
(TaskRunner pid=3309296) /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/profiler/config.py:49: UserWarning: Torch profiler tool config is not fully supported now.
(TaskRunner pid=3309296) warnings.warn("Torch profiler tool config is not fully supported now.", stacklevel=1)
(TaskRunner pid=3309296) [validate_config] All configuration checks passed successfully!
(TaskRunner pid=3309296) Using dataset class: RLHFDataset
(TaskRunner pid=3309296) dataset len: 2101
(TaskRunner pid=3309296) Setting TOKENIZERS_PARALLELISM=false for forked processes.
(TaskRunner pid=3309296) WARNING:2025-11-10 22:23:51,055:Setting TOKENIZERS_PARALLELISM=false for forked processes.
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 0%| | 0/2101 [00:00<?, ? examples/s]
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 48%|β–ˆβ–ˆβ–ˆβ–ˆβ–Š | 1000/2101 [00:10<00:11, 95.66 examples/s]
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 95%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ| 2000/2101 [00:17<00:00, 115.93 examples/s]
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 2101/2101 [00:18<00:00, 117.64 examples/s]
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 2101/2101 [00:18<00:00, 112.45 examples/s]
(TaskRunner pid=3309296) filter dataset len: 2101
(TaskRunner pid=3309296) Using dataset class: RLHFDataset
(TaskRunner pid=3309296) dataset len: 601
(TaskRunner pid=3309296) Setting TOKENIZERS_PARALLELISM=false for forked processes.
(TaskRunner pid=3309296) WARNING:2025-11-10 22:24:10,452:Setting TOKENIZERS_PARALLELISM=false for forked processes.
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 0%| | 0/601 [00:00<?, ? examples/s]
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 601/601 [00:06<00:00, 96.42 examples/s]
(TaskRunner pid=3309296) Filtering prompts longer than 1024 tokens (num_proc=1): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 601/601 [00:06<00:00, 94.28 examples/s]
(TaskRunner pid=3309296) /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/trainer/ppo/ray_trainer.py:325: UserWarning: Disabled critic as algorithm.adv_estimator != gae. If it is not intended, please set critic.enable=True
(TaskRunner pid=3309296) self.use_critic = need_critic(self.config)
(TaskRunner pid=3309296) filter dataset len: 601
(TaskRunner pid=3309296) Size of train dataloader: 8, Size of val dataloader: 1
(TaskRunner pid=3309296) Total training steps: 800
(TaskRunner pid=3309296) colocated worker base class <class 'verl.single_controller.base.worker.Worker'>
(WorkerDict pid=3309793) [Gloo] Rank 12 is connected to 15 peer ranks. Expected number of connected peer ranks is : 15
(WorkerDict pid=3309790) [W1110 22:24:36.591639467 ProcessGroupNCCL.cpp:981] Warning: TORCH_NCCL_AVOID_RECORD_STREAMS is the default now, this environment variable is thus deprecated. (function operator())
(WorkerDict pid=1869082, ip=10.24.0.201) reference model: Qwen/Qwen3-VL-8B-Instruct
(WorkerDict pid=3309790) `torch_dtype` is deprecated! Use `dtype` instead!
(WorkerDict pid=3309790) Flash Attention 2 only supports torch.float16 and torch.bfloat16 dtypes, but the current dype in Qwen3VLForConditionalGeneration is torch.float32. You should run training or inference using Automatic Mixed-Precision via the `with torch.autocast(device_type='torch_device'):` decorator, or load the model with the `dtype` argument. Example: `model = AutoModel.from_pretrained("openai/whisper-tiny", attn_implementation="flash_attention_2", dtype=torch.float16)`
(WorkerDict pid=1869083, ip=10.24.0.201) [W1110 22:24:36.598787525 ProcessGroupNCCL.cpp:981] Warning: TORCH_NCCL_AVOID_RECORD_STREAMS is the default now, this environment variable is thus deprecated. (function operator()) [repeated 15x across cluster] (Ray deduplicates logs by default. Set RAY_DEDUP_LOGS=0 to disable log deduplication, or see https://docs.ray.io/en/master/ray-observability/user-guides/configure-logging.html#log-deduplication for more options.)
(WorkerDict pid=3309790) Loading checkpoint shards: 0%| | 0/4 [00:00<?, ?it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Model config after override: Qwen3VLConfig {
(WorkerDict pid=1869082, ip=10.24.0.201) "architectures": [
(WorkerDict pid=1869082, ip=10.24.0.201) "Qwen3VLForConditionalGeneration"
(WorkerDict pid=1869082, ip=10.24.0.201) ],
(WorkerDict pid=1869082, ip=10.24.0.201) "eos_token_id": 151645,
(WorkerDict pid=1869082, ip=10.24.0.201) "image_token_id": 151655,
(WorkerDict pid=1869082, ip=10.24.0.201) "model_type": "qwen3_vl",
(WorkerDict pid=1869082, ip=10.24.0.201) "pad_token_id": 151643,
(WorkerDict pid=1869082, ip=10.24.0.201) "text_config": {
(WorkerDict pid=1869082, ip=10.24.0.201) "attention_bias": false,
(WorkerDict pid=1869082, ip=10.24.0.201) "attention_dropout": 0.0,
(WorkerDict pid=1869082, ip=10.24.0.201) "bos_token_id": 151643,
(WorkerDict pid=1869082, ip=10.24.0.201) "dtype": "bfloat16",
(WorkerDict pid=1869082, ip=10.24.0.201) "eos_token_id": 151645,
(WorkerDict pid=1869082, ip=10.24.0.201) "head_dim": 128,
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_act": "silu",
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_size": 4096,
(WorkerDict pid=1869082, ip=10.24.0.201) "initializer_range": 0.02,
(WorkerDict pid=1869082, ip=10.24.0.201) "intermediate_size": 12288,
(WorkerDict pid=1869082, ip=10.24.0.201) "max_position_embeddings": 262144,
(WorkerDict pid=1869082, ip=10.24.0.201) "model_type": "qwen3_vl_text",
(WorkerDict pid=1869082, ip=10.24.0.201) "num_attention_heads": 32,
(WorkerDict pid=1869082, ip=10.24.0.201) "num_hidden_layers": 36,
(WorkerDict pid=1869082, ip=10.24.0.201) "num_key_value_heads": 8,
(WorkerDict pid=1869082, ip=10.24.0.201) "rms_norm_eps": 1e-06,
(WorkerDict pid=1869082, ip=10.24.0.201) "rope_scaling": {
(WorkerDict pid=1869082, ip=10.24.0.201) "mrope_interleaved": true,
(WorkerDict pid=1869082, ip=10.24.0.201) "mrope_section": [
(WorkerDict pid=1869082, ip=10.24.0.201) 24,
(WorkerDict pid=1869082, ip=10.24.0.201) 20,
(WorkerDict pid=1869082, ip=10.24.0.201) 20
(WorkerDict pid=1869082, ip=10.24.0.201) ],
(WorkerDict pid=1869082, ip=10.24.0.201) "rope_type": "default"
(WorkerDict pid=1869082, ip=10.24.0.201) },
(WorkerDict pid=1869082, ip=10.24.0.201) "rope_theta": 5000000,
(WorkerDict pid=1869082, ip=10.24.0.201) "use_cache": true,
(WorkerDict pid=1869082, ip=10.24.0.201) "vocab_size": 151936
(WorkerDict pid=1869082, ip=10.24.0.201) },
(WorkerDict pid=1869082, ip=10.24.0.201) "tie_word_embeddings": false,
(WorkerDict pid=1869082, ip=10.24.0.201) "transformers_version": "4.57.1",
(WorkerDict pid=1869082, ip=10.24.0.201) "video_token_id": 151656,
(WorkerDict pid=1869082, ip=10.24.0.201) "vision_config": {
(WorkerDict pid=1869082, ip=10.24.0.201) "deepstack_visual_indexes": [
(WorkerDict pid=1869082, ip=10.24.0.201) 8,
(WorkerDict pid=1869082, ip=10.24.0.201) 16,
(WorkerDict pid=1869082, ip=10.24.0.201) 24
(WorkerDict pid=1869082, ip=10.24.0.201) ],
(WorkerDict pid=1869082, ip=10.24.0.201) "depth": 27,
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_act": "gelu_pytorch_tanh",
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_size": 1152,
(WorkerDict pid=1869082, ip=10.24.0.201) "in_channels": 3,
(WorkerDict pid=1869082, ip=10.24.0.201) "initializer_range": 0.02,
(WorkerDict pid=1869082, ip=10.24.0.201) "intermediate_size": 4304,
(WorkerDict pid=1869082, ip=10.24.0.201) "model_type": "qwen3_vl",
(WorkerDict pid=1869082, ip=10.24.0.201) "num_heads": 16,
(WorkerDict pid=1869082, ip=10.24.0.201) "num_position_embeddings": 2304,
(WorkerDict pid=1869082, ip=10.24.0.201) "out_hidden_size": 4096,
(WorkerDict pid=1869082, ip=10.24.0.201) "patch_size": 16,
(WorkerDict pid=1869082, ip=10.24.0.201) "spatial_merge_size": 2,
(WorkerDict pid=1869082, ip=10.24.0.201) "temporal_patch_size": 2
(WorkerDict pid=1869082, ip=10.24.0.201) },
(WorkerDict pid=1869082, ip=10.24.0.201) "vision_end_token_id": 151653,
(WorkerDict pid=1869082, ip=10.24.0.201) "vision_start_token_id": 151652
(WorkerDict pid=1869082, ip=10.24.0.201) }
(WorkerDict pid=1869082, ip=10.24.0.201)
(WorkerDict pid=1869083, ip=10.24.0.201) [Gloo] Rank 1 is connected to 15 peer ranks. Expected number of connected peer ranks is : 15 [repeated 15x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) Loading checkpoint shards: 25%|β–ˆβ–ˆβ–Œ | 1/4 [00:07<00:21, 7.11s/it]
(WorkerDict pid=3309795) `torch_dtype` is deprecated! Use `dtype` instead! [repeated 15x across cluster]
(WorkerDict pid=3309795) Flash Attention 2 only supports torch.float16 and torch.bfloat16 dtypes, but the current dype in Qwen3VLTextModel is torch.float32. You should run training or inference using Automatic Mixed-Precision via the `with torch.autocast(device_type='torch_device'):` decorator, or load the model with the `dtype` argument. Example: `model = AutoModel.from_pretrained("openai/whisper-tiny", attn_implementation="flash_attention_2", dtype=torch.float16)` [repeated 63x across cluster]
(WorkerDict pid=3309795) Loading checkpoint shards: 0%| | 0/4 [00:00<?, ?it/s] [repeated 15x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) Loading checkpoint shards: 50%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 2/4 [00:13<00:13, 6.51s/it] [repeated 7x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:19<00:06, 6.30s/it] [repeated 15x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:22<00:00, 5.02s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:22<00:00, 5.58s/it]
(WorkerDict pid=1869086, ip=10.24.0.201) Monkey patch Qwen3VLForConditionalGeneration model forward
(WorkerDict pid=1869086, ip=10.24.0.201) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention
(WorkerDict pid=1869086, ip=10.24.0.201) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration
(WorkerDict pid=3309795) Loading checkpoint shards: 50%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 2/4 [00:22<00:20, 10.43s/it] [repeated 15x across cluster]
(WorkerDict pid=3309792) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:25<00:00, 5.74s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:25<00:00, 6.39s/it] [repeated 6x across cluster]
(WorkerDict pid=3309795) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:29<00:08, 8.80s/it] [repeated 9x across cluster]
(WorkerDict pid=3309793) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:32<00:00, 6.71s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:32<00:00, 8.05s/it] [repeated 3x across cluster]
(WorkerDict pid=1869087, ip=10.24.0.201) Monkey patch Qwen3VLForConditionalGeneration model forward [repeated 7x across cluster]
(WorkerDict pid=1869087, ip=10.24.0.201) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention [repeated 7x across cluster]
(WorkerDict pid=1869087, ip=10.24.0.201) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration [repeated 7x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) Qwen3VLForConditionalGeneration contains 8.77B parameters
(WorkerDict pid=1869082, ip=10.24.0.201) wrap_policy: functools.partial(<function _or_policy at 0x149b68741360>, policies=[functools.partial(<function transformer_auto_wrap_policy at 0x149b68741240>, transformer_layer_cls={<class 'transformers.models.qwen3_vl.modeling_qwen3_vl.Qwen3VLVisionBlock'>, <class 'transformers.models.qwen3_vl.modeling_qwen3_vl.Qwen3VLTextDecoderLayer'>})])
(WorkerDict pid=1869082, ip=10.24.0.201) Ref use_remove_padding=True
(WorkerDict pid=1869082, ip=10.24.0.201) Ref use_fused_kernels=True
(WorkerDict pid=1869088, ip=10.24.0.201) Monkey patch Qwen3VLForConditionalGeneration model forward [repeated 8x across cluster]
(WorkerDict pid=1869088, ip=10.24.0.201) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention [repeated 8x across cluster]
(WorkerDict pid=1869088, ip=10.24.0.201) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration [repeated 8x across cluster]
(WorkerDict pid=1869089, ip=10.24.0.201) Loading checkpoint shards: 0%| | 0/4 [00:00<?, ?it/s]
(WorkerDict pid=1869088, ip=10.24.0.201) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:33<00:09, 9.76s/it]
(WorkerDict pid=1869088, ip=10.24.0.201) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:36<00:00, 7.03s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:36<00:00, 9.18s/it] [repeated 6x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) Model config after override: Qwen3VLConfig {
(WorkerDict pid=1869082, ip=10.24.0.201) "architectures": [
(WorkerDict pid=1869082, ip=10.24.0.201) "Qwen3VLForConditionalGeneration"
(WorkerDict pid=1869082, ip=10.24.0.201) ],
(WorkerDict pid=1869082, ip=10.24.0.201) "eos_token_id": 151645,
(WorkerDict pid=1869082, ip=10.24.0.201) "image_token_id": 151655,
(WorkerDict pid=1869082, ip=10.24.0.201) "model_type": "qwen3_vl",
(WorkerDict pid=1869082, ip=10.24.0.201) "pad_token_id": 151643,
(WorkerDict pid=1869082, ip=10.24.0.201) "text_config": {
(WorkerDict pid=1869082, ip=10.24.0.201) "attention_bias": false,
(WorkerDict pid=1869082, ip=10.24.0.201) "attention_dropout": 0.0,
(WorkerDict pid=1869082, ip=10.24.0.201) "bos_token_id": 151643,
(WorkerDict pid=1869082, ip=10.24.0.201) "dtype": "bfloat16",
(WorkerDict pid=1869082, ip=10.24.0.201) "eos_token_id": 151645,
(WorkerDict pid=1869082, ip=10.24.0.201) "head_dim": 128,
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_act": "silu",
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_size": 4096,
(WorkerDict pid=1869082, ip=10.24.0.201) "initializer_range": 0.02,
(WorkerDict pid=1869082, ip=10.24.0.201) "intermediate_size": 12288,
(WorkerDict pid=1869082, ip=10.24.0.201) "max_position_embeddings": 262144,
(WorkerDict pid=1869082, ip=10.24.0.201) "model_type": "qwen3_vl_text",
(WorkerDict pid=1869082, ip=10.24.0.201) "num_attention_heads": 32,
(WorkerDict pid=1869082, ip=10.24.0.201) "num_hidden_layers": 36,
(WorkerDict pid=1869082, ip=10.24.0.201) "num_key_value_heads": 8,
(WorkerDict pid=1869082, ip=10.24.0.201) "rms_norm_eps": 1e-06,
(WorkerDict pid=1869082, ip=10.24.0.201) "rope_scaling": {
(WorkerDict pid=1869082, ip=10.24.0.201) "mrope_interleaved": true,
(WorkerDict pid=1869082, ip=10.24.0.201) "mrope_section": [
(WorkerDict pid=1869082, ip=10.24.0.201) 24,
(WorkerDict pid=1869082, ip=10.24.0.201) 20,
(WorkerDict pid=1869082, ip=10.24.0.201) 20
(WorkerDict pid=1869082, ip=10.24.0.201) ],
(WorkerDict pid=1869082, ip=10.24.0.201) "rope_type": "default"
(WorkerDict pid=1869082, ip=10.24.0.201) },
(WorkerDict pid=1869082, ip=10.24.0.201) "rope_theta": 5000000,
(WorkerDict pid=1869082, ip=10.24.0.201) "use_cache": true,
(WorkerDict pid=1869082, ip=10.24.0.201) "vocab_size": 151936
(WorkerDict pid=1869082, ip=10.24.0.201) },
(WorkerDict pid=1869082, ip=10.24.0.201) "tie_word_embeddings": false,
(WorkerDict pid=1869082, ip=10.24.0.201) "transformers_version": "4.57.1",
(WorkerDict pid=1869082, ip=10.24.0.201) "video_token_id": 151656,
(WorkerDict pid=1869082, ip=10.24.0.201) "vision_config": {
(WorkerDict pid=1869082, ip=10.24.0.201) "deepstack_visual_indexes": [
(WorkerDict pid=1869082, ip=10.24.0.201) 8,
(WorkerDict pid=1869082, ip=10.24.0.201) 16,
(WorkerDict pid=1869082, ip=10.24.0.201) 24
(WorkerDict pid=1869082, ip=10.24.0.201) ],
(WorkerDict pid=1869082, ip=10.24.0.201) "depth": 27,
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_act": "gelu_pytorch_tanh",
(WorkerDict pid=1869082, ip=10.24.0.201) "hidden_size": 1152,
(WorkerDict pid=1869082, ip=10.24.0.201) "in_channels": 3,
(WorkerDict pid=1869082, ip=10.24.0.201) "initializer_range": 0.02,
(WorkerDict pid=1869082, ip=10.24.0.201) "intermediate_size": 4304,
(WorkerDict pid=1869082, ip=10.24.0.201) "model_type": "qwen3_vl",
(WorkerDict pid=1869082, ip=10.24.0.201) "num_heads": 16,
(WorkerDict pid=1869082, ip=10.24.0.201) "num_position_embeddings": 2304,
(WorkerDict pid=1869082, ip=10.24.0.201) "out_hidden_size": 4096,
(WorkerDict pid=1869082, ip=10.24.0.201) "patch_size": 16,
(WorkerDict pid=1869082, ip=10.24.0.201) "spatial_merge_size": 2,
(WorkerDict pid=1869082, ip=10.24.0.201) "temporal_patch_size": 2
(WorkerDict pid=1869082, ip=10.24.0.201) },
(WorkerDict pid=1869082, ip=10.24.0.201) "vision_end_token_id": 151653,
(WorkerDict pid=1869082, ip=10.24.0.201) "vision_start_token_id": 151652
(WorkerDict pid=1869082, ip=10.24.0.201) }
(WorkerDict pid=1869082, ip=10.24.0.201)
(WorkerDict pid=1869087, ip=10.24.0.201) Loading checkpoint shards: 25%|β–ˆβ–ˆβ–Œ | 1/4 [00:04<00:13, 4.43s/it]
(WorkerDict pid=3309793) Loading checkpoint shards: 0%| | 0/4 [00:00<?, ?it/s] [repeated 15x across cluster]
(WorkerDict pid=1869089, ip=10.24.0.201) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:13<00:04, 4.21s/it] [repeated 18x across cluster]
(WorkerDict pid=1869089, ip=10.24.0.201) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:15<00:00, 3.68s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:15<00:00, 3.99s/it]
(WorkerDict pid=1869089, ip=10.24.0.201) Monkey patch Qwen3VLForConditionalGeneration model forward
(WorkerDict pid=1869089, ip=10.24.0.201) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention
(WorkerDict pid=1869089, ip=10.24.0.201) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration
(WorkerDict pid=1869083, ip=10.24.0.201) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:20<00:06, 6.72s/it] [repeated 15x across cluster]
(WorkerDict pid=1869087, ip=10.24.0.201) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:15<00:00, 3.66s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:15<00:00, 3.92s/it]
(WorkerDict pid=1869088, ip=10.24.0.201) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:23<00:00, 5.18s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:23<00:00, 5.83s/it]
(WorkerDict pid=1869088, ip=10.24.0.201) Monkey patch Qwen3VLForConditionalGeneration model forward [repeated 2x across cluster]
(WorkerDict pid=1869088, ip=10.24.0.201) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention [repeated 2x across cluster]
(WorkerDict pid=1869088, ip=10.24.0.201) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration [repeated 2x across cluster]
(WorkerDict pid=3309794) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:21<00:07, 7.15s/it] [repeated 9x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:25<00:00, 6.33s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:25<00:00, 6.49s/it] [repeated 8x across cluster]
(WorkerDict pid=3309793) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:29<00:10, 10.99s/it] [repeated 3x across cluster]
(WorkerDict pid=3309789) Monkey patch Qwen3VLForConditionalGeneration model forward [repeated 9x across cluster]
(WorkerDict pid=3309789) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention [repeated 9x across cluster]
(WorkerDict pid=3309789) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration [repeated 9x across cluster]
(WorkerDict pid=3309793) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:32<00:00, 7.86s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:32<00:00, 8.20s/it] [repeated 3x across cluster]
(WorkerDict pid=3309795) Loading checkpoint shards: 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 3/4 [00:35<00:13, 13.72s/it] [repeated 2x across cluster]
(WorkerDict pid=3309795) Monkey patch Qwen3VLForConditionalGeneration model forward [repeated 3x across cluster]
(WorkerDict pid=3309795) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention [repeated 3x across cluster]
(WorkerDict pid=3309795) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration [repeated 3x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) Qwen3VLForConditionalGeneration contains 8.77B parameters
(WorkerDict pid=1869082, ip=10.24.0.201) wrap_policy: functools.partial(<function _or_policy at 0x149b68741360>, policies=[functools.partial(<function transformer_auto_wrap_policy at 0x149b68741240>, transformer_layer_cls={<class 'transformers.models.qwen3_vl.modeling_qwen3_vl.Qwen3VLVisionBlock'>, <class 'transformers.models.qwen3_vl.modeling_qwen3_vl.Qwen3VLTextDecoderLayer'>})])
(WorkerDict pid=1869086, ip=10.24.0.201) /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/profiler/config.py:49: UserWarning: Torch profiler tool config is not fully supported now.
(WorkerDict pid=1869086, ip=10.24.0.201) warnings.warn("Torch profiler tool config is not fully supported now.", stacklevel=1)
(WorkerDict pid=3309796) Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:39<00:00, 9.01s/it] Loading checkpoint shards: 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 4/4 [00:39<00:00, 9.83s/it] [repeated 2x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) Total steps: 800, num_warmup_steps: 0
(WorkerDict pid=1869082, ip=10.24.0.201) Actor use_remove_padding=True
(WorkerDict pid=1869082, ip=10.24.0.201) Actor use_fused_kernels=True
(WorkerDict pid=3309796) Monkey patch Qwen3VLForConditionalGeneration model forward
(WorkerDict pid=3309796) Monkey patch _flash_attention_forward in transformers.integrations.flash_attention
(WorkerDict pid=3309796) Using Torch backend for fused kernels in Qwen3VLForConditionalGeneration
(WorkerDict pid=3309796) [Gloo] Rank 7 is connected to 7 peer ranks. Expected number of connected peer ranks is : 7
(WorkerDict pid=1869082, ip=10.24.0.201) NCCL version 2.27.3+cuda12.9
(WorkerDict pid=1869082, ip=10.24.0.201) WARNING 11-10 22:26:47 [arg_utils.py:970] `--disable-mm-preprocessor-cache` is deprecated and will be removed in v0.13. Please use `--mm-processor-cache-gb 0` instead.
(WorkerDict pid=3309795) [Gloo] Rank 0 is connected to 0 peer ranks. Expected number of connected peer ranks is : 0 [repeated 47x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) `torch_dtype` is deprecated! Use `dtype` instead!
(WorkerDict pid=1869082, ip=10.24.0.201) /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/profiler/config.py:49: UserWarning: Torch profiler tool config is not fully supported now. [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) warnings.warn("Torch profiler tool config is not fully supported now.", stacklevel=1) [repeated 15x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) NCCL version 2.27.3+cuda12.9
(WorkerDict pid=1869088, ip=10.24.0.201) WARNING 11-10 22:26:52 [topk_topp_sampler.py:66] FlashInfer is not available. Falling back to the PyTorch-native implementation of top-p & top-k sampling. For the best performance, please install FlashInfer.
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 0%| | 0/67 [00:00<?, ?it/s]
(WorkerDict pid=3309791) `torch_dtype` is deprecated! Use `dtype` instead! [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 3%|β–Ž | 2/67 [00:00<00:04, 15.78it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 6%|β–Œ | 4/67 [00:00<00:03, 16.80it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 9%|β–‰ | 6/67 [00:00<00:03, 16.95it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 12%|β–ˆβ– | 8/67 [00:00<00:03, 16.71it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 15%|β–ˆβ– | 10/67 [00:00<00:03, 16.32it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 18%|β–ˆβ–Š | 12/67 [00:00<00:03, 16.37it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 21%|β–ˆβ–ˆ | 14/67 [00:00<00:03, 15.89it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 24%|β–ˆβ–ˆβ– | 16/67 [00:00<00:03, 15.94it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 27%|β–ˆβ–ˆβ–‹ | 18/67 [00:01<00:03, 15.84it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 30%|β–ˆβ–ˆβ–‰ | 20/67 [00:01<00:02, 15.78it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 33%|β–ˆβ–ˆβ–ˆβ–Ž | 22/67 [00:01<00:03, 13.06it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 36%|β–ˆβ–ˆβ–ˆβ–Œ | 24/67 [00:01<00:03, 13.55it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 39%|β–ˆβ–ˆβ–ˆβ–‰ | 26/67 [00:01<00:03, 13.67it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 42%|β–ˆβ–ˆβ–ˆβ–ˆβ– | 28/67 [00:01<00:03, 12.08it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 45%|β–ˆβ–ˆβ–ˆβ–ˆβ– | 30/67 [00:02<00:03, 12.12it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 48%|β–ˆβ–ˆβ–ˆβ–ˆβ–Š | 32/67 [00:02<00:02, 12.21it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 51%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 34/67 [00:02<00:02, 11.68it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 54%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Ž | 36/67 [00:02<00:02, 12.08it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 57%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‹ | 38/67 [00:02<00:02, 11.87it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 60%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‰ | 40/67 [00:02<00:02, 11.76it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 63%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Ž | 42/67 [00:03<00:02, 8.83it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 64%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ– | 43/67 [00:03<00:03, 7.97it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 66%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 44/67 [00:03<00:03, 7.48it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 67%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‹ | 45/67 [00:03<00:02, 7.72it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 69%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Š | 46/67 [00:03<00:02, 7.32it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 70%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 47/67 [00:04<00:02, 7.81it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 72%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ– | 48/67 [00:04<00:02, 7.68it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 75%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ– | 50/67 [00:04<00:01, 8.81it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 78%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Š | 52/67 [00:04<00:01, 9.65it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 81%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 54/67 [00:04<00:01, 10.33it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 84%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Ž | 56/67 [00:04<00:01, 10.61it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 87%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‹ | 58/67 [00:05<00:00, 10.95it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 90%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‰ | 60/67 [00:05<00:00, 11.01it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 93%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Ž| 62/67 [00:05<00:00, 10.99it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 96%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ| 64/67 [00:05<00:00, 11.04it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 99%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Š| 66/67 [00:05<00:00, 11.13it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (mixed prefill-decode, PIECEWISE): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 67/67 [00:05<00:00, 11.42it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 0%| | 0/67 [00:00<?, ?it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 3%|β–Ž | 2/67 [00:00<00:04, 16.20it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 6%|β–Œ | 4/67 [00:00<00:03, 17.99it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 10%|β–ˆ | 7/67 [00:00<00:03, 18.97it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 15%|β–ˆβ– | 10/67 [00:00<00:02, 19.13it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 18%|β–ˆβ–Š | 12/67 [00:00<00:02, 19.11it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 21%|β–ˆβ–ˆ | 14/67 [00:00<00:02, 18.84it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 24%|β–ˆβ–ˆβ– | 16/67 [00:00<00:02, 18.40it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 27%|β–ˆβ–ˆβ–‹ | 18/67 [00:00<00:02, 18.83it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 30%|β–ˆβ–ˆβ–‰ | 20/67 [00:01<00:02, 18.59it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 34%|β–ˆβ–ˆβ–ˆβ– | 23/67 [00:01<00:02, 19.11it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 37%|β–ˆβ–ˆβ–ˆβ–‹ | 25/67 [00:01<00:02, 19.32it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 40%|β–ˆβ–ˆβ–ˆβ–ˆ | 27/67 [00:01<00:02, 19.41it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 43%|β–ˆβ–ˆβ–ˆβ–ˆβ–Ž | 29/67 [00:01<00:01, 19.51it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 46%|β–ˆβ–ˆβ–ˆβ–ˆβ–‹ | 31/67 [00:01<00:01, 19.43it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 49%|β–ˆβ–ˆβ–ˆβ–ˆβ–‰ | 33/67 [00:01<00:01, 19.44it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 52%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ– | 35/67 [00:01<00:01, 19.24it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 55%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 37/67 [00:01<00:01, 19.10it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 58%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Š | 39/67 [00:02<00:01, 19.16it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 61%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 41/67 [00:02<00:01, 19.22it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 64%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ– | 43/67 [00:02<00:01, 19.35it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 67%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‹ | 45/67 [00:02<00:01, 19.32it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 70%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 47/67 [00:02<00:01, 19.02it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 73%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Ž | 49/67 [00:02<00:00, 18.63it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 76%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 51/67 [00:02<00:00, 18.36it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 79%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‰ | 53/67 [00:02<00:00, 18.25it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 82%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ– | 55/67 [00:02<00:00, 17.60it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 85%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Œ | 57/67 [00:03<00:00, 17.07it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 88%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–Š | 59/67 [00:03<00:00, 16.81it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 91%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ | 61/67 [00:03<00:00, 17.58it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 94%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–| 63/67 [00:03<00:00, 17.98it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 97%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–‹| 65/67 [00:03<00:00, 17.27it/s]
(WorkerDict pid=1869082, ip=10.24.0.201) Capturing CUDA graphs (decode, FULL): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 67/67 [00:03<00:00, 17.77it/s] Capturing CUDA graphs (decode, FULL): 100%|β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ| 67/67 [00:03<00:00, 18.54it/s]
(WorkerDict pid=1869088, ip=10.24.0.201) /mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/distributed/fsdp/fully_sharded_data_parallel.py:678: FutureWarning: FSDP.state_dict_type() and FSDP.set_state_dict_type() are being deprecated. Please use APIs, get_state_dict() and set_state_dict(), which can support different parallelisms, FSDP1, FSDP2, DDP. API doc: https://pytorch.org/docs/stable/distributed.checkpoint.html#torch.distributed.checkpoint.state_dict.get_state_dict .Tutorial: https://pytorch.org/tutorials/recipes/distributed_checkpoint_recipe.html .
(WorkerDict pid=1869088, ip=10.24.0.201) warnings.warn(
(WorkerDict pid=1869088, ip=10.24.0.201) kwargs: {'n': 1, 'logprobs': 0, 'max_tokens': 2048, 'repetition_penalty': 1.0, 'detokenize': False, 'temperature': 1.0, 'top_k': -1, 'top_p': 1, 'ignore_eos': False}
(WorkerDict pid=3309791) WARNING 11-10 22:26:48 [arg_utils.py:970] `--disable-mm-preprocessor-cache` is deprecated and will be removed in v0.13. Please use `--mm-processor-cache-gb 0` instead. [repeated 15x across cluster]
(WorkerDict pid=3309794) [Gloo] Rank 1 is connected to 1 peer ranks. Expected number of connected peer ranks is : 1 [repeated 96x across cluster]
(WorkerDict pid=3309789) NCCL version 2.27.3+cuda12.9 [repeated 6x across cluster]
(WorkerDict pid=3309795) WARNING 11-10 22:26:52 [topk_topp_sampler.py:66] FlashInfer is not available. Falling back to the PyTorch-native implementation of top-p & top-k sampling. For the best performance, please install FlashInfer. [repeated 15x across cluster]
(TaskRunner pid=3309296) wandb: Currently logged in as: xuezhe-ma (mbzuai-llm) to https://api.wandb.ai. Use `wandb login --relogin` to force relogin
(WorkerDict pid=3309795) /mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/distributed/fsdp/fully_sharded_data_parallel.py:678: FutureWarning: FSDP.state_dict_type() and FSDP.set_state_dict_type() are being deprecated. Please use APIs, get_state_dict() and set_state_dict(), which can support different parallelisms, FSDP1, FSDP2, DDP. API doc: https://pytorch.org/docs/stable/distributed.checkpoint.html#torch.distributed.checkpoint.state_dict.get_state_dict .Tutorial: https://pytorch.org/tutorials/recipes/distributed_checkpoint_recipe.html . [repeated 15x across cluster]
(WorkerDict pid=3309795) warnings.warn( [repeated 15x across cluster]
(TaskRunner pid=3309296) wandb: setting up run keyf6t0u
(TaskRunner pid=3309296) wandb: Tracking run with wandb version 0.22.3
(TaskRunner pid=3309296) wandb: Run data is saved locally in /tmp/ray/session_2025-11-10_22-22-25_436333_3301430/runtime_resources/working_dir_files/_ray_pkg_279bf434c475ae18/wandb/run-20251110_222752-keyf6t0u
(TaskRunner pid=3309296) wandb: Run `wandb offline` to turn off syncing.
(TaskRunner pid=3309296) wandb: Syncing run qwen3_vl_8b_geo3k
(TaskRunner pid=3309296) wandb: ⭐️ View project at https://wandb.ai/mbzuai-llm/verl_grpo_w
(TaskRunner pid=3309296) wandb: πŸš€ View run at https://wandb.ai/mbzuai-llm/verl_grpo_w/runs/keyf6t0u
(TaskRunner pid=3309296) Checkpoint tracker file does not exist: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/latest_checkpointed_iteration.txt
(TaskRunner pid=3309296) Training from scratch
(WorkerDict pid=3309795) kwargs: {'n': 1, 'logprobs': 0, 'max_tokens': 2048, 'repetition_penalty': 1.0, 'detokenize': False, 'temperature': 1.0, 'top_k': -1, 'top_p': 1, 'ignore_eos': False} [repeated 15x across cluster]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 0}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle G, given that the radius is 26 and that chords AC and DF are equidistant from the center G. I also see that there are two segments labeled 10, which appear to be the distances from the center G to the chords AC and DF. Since the chords are equidistant from the center, and both distances are labeled 10, that makes sense. So, the perpendicular distance from the center G to chord AC is 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall that in a circle, if you draw a perpendicular from the center to a chord, it bisects the chord. So, if I drop a perpendicular from G to chord AC, it will hit AC at its midpoint, let's call that point M. Then, triangle GMA is a right triangle, with GM = 10 (the distance from center to chord), GA = 26 (the radius), and AM is half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem, in right triangle GMA:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) GAΒ² = GMΒ² + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, 26Β² = 10Β² + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 676 = 100 + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AM is half of AC, then AC = 2 * AM = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I should verify that the diagram supports this. The diagram shows a perpendicular from G to AC, and it's labeled 10, which matches the given distance. Also, the radius GA is drawn and is 26, which matches the given radius. So, the setup is consistent.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 0%| | 0/800 [00:00<?, ?it/s]
(TaskRunner pid=3309296) ("Initial validation metrics: {'val-core/hiyouga/geometry3k/reward/mean@1': "
(TaskRunner pid=3309296) 'np.float64(0.45074874013910277)}')
(TaskRunner pid=3309296) Training Progress: 0%| | 1/800 [02:52<38:16:31, 172.45s/it]
(TaskRunner pid=3309296) Training Progress: 0%| | 2/800 [05:25<35:38:29, 160.79s/it]
(TaskRunner pid=3309296) Training Progress: 0%| | 3/800 [07:52<34:12:30, 154.52s/it]
(TaskRunner pid=3309296) Training Progress: 0%| | 4/800 [10:22<33:47:48, 152.85s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 5}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle G, given that the radius is 26 and that chords AC and DF are equidistant from the center G. I also see that there are two segments labeled 10, which appear to be the distances from the center G to the chords AC and DF. Since the chords are equidistant from the center, and both distances are labeled 10, that makes sense. So, the perpendicular distance from the center G to chord AC is 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall that in a circle, if you draw a perpendicular from the center to a chord, it bisects the chord. So, if I drop a perpendicular from G to chord AC, it will hit AC at its midpoint, let's call that point M. Then, triangle GMA is a right triangle, with GM = 10 (the distance from center to chord), GA = 26 (the radius), and AM is half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem, in right triangle GMA:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) GAΒ² = GMΒ² + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, 26Β² = 10Β² + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 676 = 100 + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AM is half of AC, then AC = 2 * AM = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I should verify that the distance to DF is also 10, which is given, and since both chords are equidistant from the center, they are equal in length, but I don't need DF to find AC. The problem gives me the radius and the distance to AC, so I can directly compute AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 1%| | 5/800 [13:51<38:14:21, 173.16s/it]
(TaskRunner pid=3309296) Training Progress: 1%| | 6/800 [16:05<35:16:11, 159.91s/it]
(TaskRunner pid=3309296) Training Progress: 1%| | 7/800 [18:34<34:23:00, 156.09s/it]
(TaskRunner pid=3309296) Training Progress: 1%| | 8/800 [20:56<33:22:44, 151.72s/it]
(TaskRunner pid=3309296) Training Progress: 1%| | 9/800 [23:28<33:23:18, 151.96s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 10}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle G, given that the radius is 26 and that chords AC and DF are equidistant from the center G. The diagram shows that both chords are 10 units from the center, as indicated by the dashed lines from G to the chords.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the chords are equidistant from the center, they must be congruent. That is, AC = DF. But I need to find AC, so I can focus on one of them.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall that in a circle, the perpendicular distance from the center to a chord bisects the chord. So, if I drop a perpendicular from G to chord AC, it will hit AC at its midpoint, let's call that point M. Then, GM = 10, and GA is the radius, which is 26.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, triangle GMA is a right triangle, with right angle at M. GA is the hypotenuse (26), GM is one leg (10), and AM is the other leg, which is half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = GAΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AM is half of AC, then AC = 2 * AM = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 1%|▏ | 10/800 [26:51<36:47:23, 167.65s/it]
(TaskRunner pid=3309296) Training Progress: 1%|▏ | 11/800 [29:05<34:28:54, 157.33s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 12/800 [31:31<33:39:09, 153.74s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 13/800 [33:54<32:54:08, 150.51s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 14/800 [36:04<31:33:18, 144.53s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 15}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle G, given that the radius is 26 and that chords AC and DF are equidistant from the center G. The diagram shows that both chords are 10 units from the center, as indicated by the dashed lines from G to the chords.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the chords are equidistant from the center, they must be congruent. That is, AC = DF. But I need to find AC, so I can focus on one of them.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall that in a circle, the perpendicular distance from the center to a chord bisects the chord. So, if I drop a perpendicular from G to chord AC, it will hit AC at its midpoint, say point M. Then, triangle GMA is a right triangle, with GM = 10 (the distance from center to chord), GA = 26 (the radius), and AM is half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = GAΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AM is half of AC, then AC = 2 * AM = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, the length of chord AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 15/800 [39:27<35:19:05, 161.97s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 16/800 [41:30<32:42:45, 150.21s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 17/800 [43:49<31:56:38, 146.87s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 18/800 [45:58<30:44:57, 141.56s/it]
(TaskRunner pid=3309296) Training Progress: 2%|▏ | 19/800 [48:13<30:18:01, 139.67s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 20}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt]
(TaskRunner pid=3309296) user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] We are given a circle with center $G$, radius 26, and two chords $\overline{AC}$ and $\overline{DF}$ that are equidistant from the center. We are to find the length of chord $AC$.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, recall a key theorem in circle geometry: **Chords that are equidistant from the center of a circle are congruent.** Since $AC$ and $DF$ are equidistant from $G$, they must be congruent. But we are not given the length of $DF$, so this fact alone doesn’t help us directly unless we can find another way.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) However, we are also given that the distance from the center $G$ to chord $AC$ is 10. This is shown in the diagram: a perpendicular from $G$ to chord $AC$ (which we can assume is drawn to the midpoint of $AC$, since the perpendicular from the center to a chord bisects the chord).
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, let’s denote the foot of the perpendicular from $G$ to chord $AC$ as point $M$. Then $GM = 10$, and $M$ is the midpoint of $AC$. So, $AM = MC = \frac{1}{2} AC$.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, consider triangle $AGM$. This is a right triangle, with:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - Hypotenuse $AG$ = radius = 26
(TaskRunner pid=3309296) - One leg $GM$ = 10
(TaskRunner pid=3309296) - The other leg $AM$ = half of $AC$, which we’ll call $x$
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) AG^2 = AM^2 + GM^2
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) 26^2 = x^2 + 10^2
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) 676 = x^2 + 100
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) x^2 = 676 - 100 = 576
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296) x = \sqrt{576} = 24
(TaskRunner pid=3309296) $$
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, $AM = 24$, so the full length of chord $AC = 2 \times 24 = 48$.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We don’t even need the information about chord $DF$ β€” it’s redundant for this calculation, since we were given the distance from the center to chord $AC$, and the radius.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final Answer: $\boxed{48}$
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) local_global_step_folder: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20
(WorkerDict pid=3309790) INFO:2025-11-10 23:20:24,856:[Rank 9] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/model_world_size_16_rank_9.pt
(WorkerDict pid=1869083, ip=10.24.0.201) INFO:2025-11-10 23:20:35,068:[Rank 1] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/optim_world_size_16_rank_1.pt
(WorkerDict pid=1869083, ip=10.24.0.201) INFO:2025-11-10 23:20:35,075:[Rank 1] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/extra_state_world_size_16_rank_1.pt
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-10 23:20:25,894:[Rank 4] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/model_world_size_16_rank_4.pt [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-10 23:20:36,416:[Rank 0] Saved model config and tokenizer class to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/huggingface
(TaskRunner pid=3309296) Training Progress: 2%|β–Ž | 20/800 [51:48<35:07:56, 162.15s/it]
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 21/800 [53:58<33:01:02, 152.58s/it]
(WorkerDict pid=3309794) INFO:2025-11-10 23:20:37,736:[Rank 13] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/optim_world_size_16_rank_13.pt [repeated 15x across cluster]
(WorkerDict pid=3309794) INFO:2025-11-10 23:20:37,741:[Rank 13] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_20/actor/extra_state_world_size_16_rank_13.pt [repeated 15x across cluster]
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 22/800 [56:13<31:51:43, 147.43s/it]
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 23/800 [58:29<31:01:18, 143.73s/it]
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 24/800 [1:00:42<30:17:08, 140.50s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 25}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle G, given that chords AC and DF are equidistant from the center G, and the radius is 26. I also see that from the diagram, there are two segments labeled 10 β€” one from G to B (on AC) and one from G to E (on DF). Since the chords are equidistant from the center, and the perpendicular from the center to a chord bisects the chord, I can use the Pythagorean theorem.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let me think step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, since the perpendicular from the center to a chord bisects the chord, the segment from G to B (which is perpendicular to AC) bisects AC. So, if I let the length of AC be x, then AB = BC = x/2.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Similarly, the perpendicular from G to DF (which goes to point E) bisects DF, so DE = EF = DF/2.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, I’m told that chords AC and DF are equidistant from the center. That means the distance from G to chord AC (which is GB) is equal to the distance from G to chord DF (which is GE). From the diagram, both are labeled as 10. So, GB = GE = 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Also, the radius is 26, so GA = GC = GD = GF = 26.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, consider triangle GAB. It’s a right triangle, with right angle at B, since GB is perpendicular to AC. So, by the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) GAΒ² = GBΒ² + ABΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Substituting the known values:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 26Β² = 10Β² + ABΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 676 = 100 + ABΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AB is half of AC, then AC = 2 * AB = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I don’t even need to use DF β€” since the chords are equidistant and I have the radius, I can find AC directly from triangle GAB.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 25/800 [1:03:59<33:53:58, 157.47s/it]
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 26/800 [1:06:06<31:55:52, 148.52s/it]
(TaskRunner pid=3309296) Training Progress: 3%|β–Ž | 27/800 [1:08:16<30:40:01, 142.82s/it]
(TaskRunner pid=3309296) Training Progress: 4%|β–Ž | 28/800 [1:10:24<29:41:23, 138.45s/it]
(TaskRunner pid=3309296) Training Progress: 4%|β–Ž | 29/800 [1:12:30<28:49:30, 134.59s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 30}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. Also, from the diagram, I see that the perpendicular distance from G to chord AC is labeled as 10. Since the chords are equidistant from the center, the perpendicular distance from G to chord DF is also 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall that in a circle, if a perpendicular is drawn from the center to a chord, it bisects the chord. So, if I drop a perpendicular from G to chord AC, it will hit AC at its midpoint, say point M. Then, triangle GMA is a right triangle, with GM = 10 (the distance from center to chord), GA = 26 (the radius), and AM is half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = GAΒ²
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AM is half of AC, then AC = 2 Γ— AM = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of chord AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 30/800 [1:15:49<32:55:33, 153.94s/it]
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 31/800 [1:17:57<31:15:38, 146.34s/it]
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 32/800 [1:20:14<30:34:11, 143.30s/it]
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 33/800 [1:22:27<29:53:15, 140.28s/it]
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 34/800 [1:24:36<29:07:00, 136.84s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 35}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think about this step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. Also, the radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, recall a key theorem: In a circle, if two chords are equidistant from the center, then they are congruent. So, since AC and DF are equidistant from G, we know that AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given the length of DF, so that doesn’t directly help us find AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) However, we are given that the radius is 26, and we see that from the center G to chord AC, there is a perpendicular segment drawn (indicated by the dashed line from G to AC, meeting at point B, which is labeled as 10). So, the distance from the center G to chord AC is 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) This is crucial. The perpendicular from the center of a circle to a chord bisects the chord. So, if we drop a perpendicular from G to chord AC, it hits AC at its midpoint, say point B. So, AB = BC = (1/2) * AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, we can form a right triangle: triangle GBA, where:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - GA is the radius = 26
(TaskRunner pid=3309296) - GB is the distance from center to chord = 10
(TaskRunner pid=3309296) - AB is half the chord AC, which we’ll call x.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, by the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) GAΒ² = GBΒ² + ABΒ²
(TaskRunner pid=3309296) 26Β² = 10Β² + xΒ²
(TaskRunner pid=3309296) 676 = 100 + xΒ²
(TaskRunner pid=3309296) xΒ² = 676 - 100 = 576
(TaskRunner pid=3309296) x = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AB = 24, so AC = 2 * AB = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of chord AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 35/800 [1:27:43<32:18:53, 152.07s/it]
(TaskRunner pid=3309296) Training Progress: 4%|▍ | 36/800 [1:29:45<30:19:35, 142.90s/it]
(TaskRunner pid=3309296) Training Progress: 5%|▍ | 37/800 [1:31:53<29:23:08, 138.65s/it]
(TaskRunner pid=3309296) Training Progress: 5%|▍ | 38/800 [1:33:54<28:12:09, 133.24s/it]
(TaskRunner pid=3309296) Training Progress: 5%|▍ | 39/800 [1:35:55<27:23:07, 129.55s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 40}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think about this step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. Also, the radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, I recall a key theorem: In a circle, if two chords are equidistant from the center, then they are congruent. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that the distance from the center G to chord AC is 10. The diagram shows a perpendicular from G to chord AC, and it’s labeled 10. Since the chords are equidistant from the center, the distance from G to DF is also 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, to find the length of chord AC, I can use the Pythagorean Theorem. If I draw a perpendicular from the center G to chord AC, it bisects AC (this is a standard theorem: the perpendicular from the center to a chord bisects the chord). So, if I let M be the midpoint of AC, then GM = 10, and GA is the radius = 26.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, triangle GMA is a right triangle, with right angle at M. So:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) GAΒ² = GMΒ² + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Substitute the known values:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 26Β² = 10Β² + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 676 = 100 + AMΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AM is half of AC, then AC = 2 Γ— AM = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) local_global_step_folder: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40
(WorkerDict pid=1869083, ip=10.24.0.201) INFO:2025-11-11 00:07:52,686:[Rank 1] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/model_world_size_16_rank_1.pt
(WorkerDict pid=1869083, ip=10.24.0.201) INFO:2025-11-11 00:08:03,388:[Rank 1] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/optim_world_size_16_rank_1.pt
(WorkerDict pid=1869083, ip=10.24.0.201) INFO:2025-11-11 00:08:03,395:[Rank 1] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/extra_state_world_size_16_rank_1.pt
(WorkerDict pid=3309793) INFO:2025-11-11 00:07:54,151:[Rank 12] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/model_world_size_16_rank_12.pt [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-11 00:08:04,774:[Rank 0] Saved model config and tokenizer class to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/huggingface
(TaskRunner pid=3309296) Training Progress: 5%|β–Œ | 40/800 [1:39:16<31:50:52, 150.86s/it]
(TaskRunner pid=3309296) Training Progress: 5%|β–Œ | 41/800 [1:41:31<30:49:43, 146.22s/it]
(WorkerDict pid=3309793) INFO:2025-11-11 00:08:05,476:[Rank 12] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/optim_world_size_16_rank_12.pt [repeated 15x across cluster]
(WorkerDict pid=3309793) INFO:2025-11-11 00:08:05,481:[Rank 12] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_40/actor/extra_state_world_size_16_rank_12.pt [repeated 15x across cluster]
(TaskRunner pid=3309296) Training Progress: 5%|β–Œ | 42/800 [1:43:42<29:51:34, 141.81s/it]
(TaskRunner pid=3309296) Training Progress: 5%|β–Œ | 43/800 [1:45:55<29:12:12, 138.88s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–Œ | 44/800 [1:47:54<27:57:56, 133.17s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 45}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. Also, the diagram shows that from G to chord AC, the perpendicular distance is 10 (since a segment labeled 10 goes from G to AC). Since the chords are equidistant from the center, the perpendicular distance from G to DF is also 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall the chord length formula: if a chord is at distance d from the center in a circle of radius r, then the half-length of the chord is √(r² - d²), so the full chord length is 2√(r² - d²).
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Here, r = 26, d = 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, half of AC = √(26² - 10²) = √(676 - 100) = √(576) = 24.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, full length AC = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I should double-check: the diagram shows a perpendicular from G to AC, labeled 10, and since the chords are equidistant, DF is also 10 away β€” but I don’t need DF for this problem. The key is that AC is 10 units from center, radius 26, so chord length is 2√(26Β² - 10Β²) = 2√(576) = 2Γ—24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) That makes sense.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 6%|β–Œ | 45/800 [1:50:57<31:03:12, 148.07s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–Œ | 46/800 [1:53:06<29:49:05, 142.37s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–Œ | 47/800 [1:55:13<28:47:27, 137.65s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–Œ | 48/800 [1:57:21<28:09:55, 134.83s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–Œ | 49/800 [1:59:43<28:32:54, 136.85s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 50}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle G, given that chords AC and DF are equidistant from the center G, and the radius is 26. The diagram shows that from G, perpendiculars are drawn to both chords, and both perpendicular segments are labeled as 10. That’s a key clue.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, if two chords are equidistant from the center, they must be congruent. That’s a theorem: in a circle, if two chords are equidistant from the center, then they are equal in length. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But I don’t know DF’s length yet. However, I can use the perpendicular from the center to a chord to find half the chord length using the Pythagorean theorem.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In circle G, radius = 26. The perpendicular from G to chord AC (or DF) is 10 units long. That perpendicular bisects the chord, so if I let half of AC be x, then in the right triangle formed by G, the midpoint of AC, and point A, I have:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) radiusΒ² = (perpendicular)Β² + (half-chord)Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So,
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 26Β² = 10Β² + (AC/2)Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 676 = 100 + (AC/2)Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Subtract 100:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) 576 = (AC/2)Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Take square root:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AC/2 = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So AC = 2 Γ— 24 = 48
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) That’s it. The reasoning is solid: equidistant chords are congruent, but I don’t need that to find AC β€” I can directly use the right triangle formed by the radius, the perpendicular to the chord, and half the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer: \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 6%|β–‹ | 50/800 [2:02:51<31:45:02, 152.40s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–‹ | 51/800 [2:04:44<29:13:55, 140.50s/it]
(TaskRunner pid=3309296) Training Progress: 6%|β–‹ | 52/800 [2:06:57<28:44:18, 138.31s/it]
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 53/800 [2:09:09<28:18:17, 136.41s/it]
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 54/800 [2:11:20<27:55:22, 134.75s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 55}
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. Also, the diagram shows that from G to chord AC, the perpendicular distance is 10 (since a segment labeled 10 goes from G to AC, and similarly to DF).
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, I recall that in a circle, if two chords are equidistant from the center, then they are congruent. So AC β‰… DF. But I don’t know DF’s length yet. However, I can use the perpendicular from the center to a chord to find the chord’s length.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) The key idea: the perpendicular from the center to a chord bisects the chord. So if I drop a perpendicular from G to chord AC, it hits AC at its midpoint, say point M. Then triangle GMA is a right triangle, with GM = 10 (given), GA = radius = 26, and AM = half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, by the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = GAΒ²
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296) AMΒ² = 576
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AC = 2 Γ— AM = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I don’t even need DF for this β€” since the distance to AC is given, and radius is given, I can directly compute AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer: \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 55/800 [2:14:49<32:29:04, 156.97s/it]
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 56/800 [2:16:55<30:30:21, 147.61s/it]
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 57/800 [2:19:28<30:49:14, 149.33s/it]
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 58/800 [2:21:44<29:55:23, 145.18s/it]
(TaskRunner pid=3309296) Training Progress: 7%|β–‹ | 59/800 [2:23:54<28:56:53, 140.64s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 60}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. Also, the diagram shows that from G to chord AC, the perpendicular distance is 10 (since a segment labeled 10 is drawn from G to AC, meeting it at point B, which is the foot of the perpendicular). Since AC and DF are equidistant from the center, the perpendicular distance from G to DF is also 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, I can use the chord length formula: for a chord at distance d from the center in a circle of radius r, the half-length of the chord is √(r² - d²), so the full chord length is 2√(r² - d²).
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Here, r = 26, d = 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, half of AC = √(26² - 10²) = √(676 - 100) = √576 = 24.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, full length AC = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I should double-check: the diagram shows a perpendicular from G to AC, labeled 10, and since the center is G, and the perpendicular to a chord bisects it, then yes, triangle GBA is a right triangle with legs 10 and 24, hypotenuse 26 β€” that checks out.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, AC = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) local_global_step_folder: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-11 00:55:52,351:[Rank 4] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/model_world_size_16_rank_4.pt
(WorkerDict pid=1869085, ip=10.24.0.201) INFO:2025-11-11 00:56:02,121:[Rank 3] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/optim_world_size_16_rank_3.pt
(WorkerDict pid=1869085, ip=10.24.0.201) INFO:2025-11-11 00:56:02,130:[Rank 3] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/extra_state_world_size_16_rank_3.pt
(WorkerDict pid=3309795) INFO:2025-11-11 00:55:53,423:[Rank 14] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/model_world_size_16_rank_14.pt [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-11 00:56:03,336:[Rank 0] Saved model config and tokenizer class to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/huggingface
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 60/800 [2:27:15<32:38:44, 158.82s/it]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 61/800 [2:29:27<30:58:37, 150.90s/it]
(WorkerDict pid=3309795) INFO:2025-11-11 00:56:04,865:[Rank 14] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/optim_world_size_16_rank_14.pt [repeated 15x across cluster]
(WorkerDict pid=3309795) INFO:2025-11-11 00:56:04,869:[Rank 14] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_60/actor/extra_state_world_size_16_rank_14.pt [repeated 15x across cluster]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 62/800 [2:31:45<30:06:40, 146.88s/it]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 63/800 [2:33:59<29:17:58, 143.12s/it]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 64/800 [2:36:16<28:51:17, 141.14s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 65}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. The diagram shows point G as the center, with segments from G to points on the circle (like to A, C, D, F) labeled as 26 β€” but wait, the diagram also shows some segments labeled 10 β€” those are from G to points on the chords, like to B and E, which are midpoints? That’s a key clue.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let me think: if chords are equidistant from the center, then they are congruent. That’s a theorem: In a circle, if two chords are equidistant from the center, then they are congruent. So AC β‰… DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But I need to find AC. The diagram shows a perpendicular from G to chord AC, meeting it at point B, and GB is labeled 10. Similarly, from G to chord DF, it meets at E, and GE is labeled 10. So both chords are at distance 10 from the center.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, in right triangle GAB, where G is the center, A is on the circle, and B is the midpoint of chord AC (since the perpendicular from center to a chord bisects the chord), then GA is the radius = 26, GB = 10, and AB is half of AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So by the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296) ABΒ² = 576
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AC = 2 Γ— AB = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) That’s it.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 65/800 [2:39:27<31:54:27, 156.28s/it]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 66/800 [2:41:36<30:12:06, 148.13s/it]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 67/800 [2:43:55<29:33:44, 145.19s/it]
(TaskRunner pid=3309296) Training Progress: 8%|β–Š | 68/800 [2:46:09<28:50:32, 141.85s/it]
(TaskRunner pid=3309296) Training Progress: 9%|β–Š | 69/800 [2:48:26<28:32:18, 140.54s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 70}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. The diagram shows G as the center, with segments from G to points on the circle (like to A, C, D, F) labeled as 26, and also some segments from G to points on the chords labeled as 10 β€” likely indicating the perpendicular distance from the center to the chords.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Wait β€” the diagram shows two segments from G to the chords: one to chord AC (at point B) and one to chord DF (at point E), both labeled 10. So, the perpendicular distance from center G to chord AC is 10, and to chord DF is also 10. Since they are equidistant from the center, that matches.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, to find the length of chord AC, I can use the formula for the length of a chord given the radius and the perpendicular distance from the center to the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) The formula is:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Chord length = 2 Γ— √(rΒ² - dΒ²)
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) where r is the radius and d is the perpendicular distance from the center to the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Here, r = 26, d = 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So,
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AC = 2 Γ— √(26Β² - 10Β²) = 2 Γ— √(676 - 100) = 2 Γ— √(576) = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) That’s straightforward.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I should double-check: the perpendicular from the center to a chord bisects the chord, so if I draw a perpendicular from G to AC, hitting at B, then AB = BC, and triangle AGB is a right triangle with hypotenuse GA = 26, leg GB = 10, so AB = √(26Β² - 10Β²) = √(576) = 24, so AC = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Yes, that’s solid.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 9%|β–‰ | 70/800 [2:51:39<31:39:14, 156.10s/it]
(TaskRunner pid=3309296) Training Progress: 9%|β–‰ | 71/800 [2:53:48<29:57:52, 147.97s/it]
(TaskRunner pid=3309296) Training Progress: 9%|β–‰ | 72/800 [2:55:59<28:54:56, 142.99s/it]
(TaskRunner pid=3309296) Training Progress: 9%|β–‰ | 73/800 [2:58:25<29:04:51, 144.00s/it]
(TaskRunner pid=3309296) Training Progress: 9%|β–‰ | 74/800 [3:00:43<28:39:14, 142.09s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 75}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] In my head, I’m thinking: Okay, we’re told that chords AC and DF are equidistant from the center G. That’s a key geometric fact. In a circle, if two chords are equidistant from the center, then they are congruent. So, AC β‰… DF. But we’re asked to find AC, and we’re given the radius is 26. Hmm, but we don’t have direct measurements of AC or DF. Wait β€” look at the diagram. There are two segments labeled 10 β€” one from G to B on AC, and one from G to E on DF. Since those are perpendicular distances from the center to the chords, and they’re both labeled 10, that confirms they’re equidistant. So, the perpendicular from the center to chord AC is 10 units long, and since the radius is 26, we can use the Pythagorean theorem to find half the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let me draw a mental picture: from center G, drop a perpendicular to chord AC, hitting it at point B. So, GB = 10, and GA is the radius = 26. Triangle GBA is a right triangle, with right angle at B. So, AB is half of AC, and by Pythagoras:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296) ABΒ² = 576
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, AB = 24, and since AB is half of AC, then AC = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) That makes sense. The key insight is that the perpendicular from the center to a chord bisects the chord, so we can use the right triangle formed by the radius, the perpendicular distance, and half the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer: \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 9%|β–‰ | 75/800 [3:03:58<31:47:14, 157.84s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–‰ | 76/800 [3:06:14<30:26:46, 151.39s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–‰ | 77/800 [3:08:31<29:31:35, 147.02s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–‰ | 78/800 [3:10:45<28:42:08, 143.11s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–‰ | 79/800 [3:12:59<28:08:52, 140.54s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 80}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] I need to find the length of chord AC in circle βŠ™G, given that chords AC and DF are equidistant from the center G, and the radius is 26. The diagram shows G as the center, with segments from G to points on the circle (like to A, C, D, F) and also to points B and E on the chords, with lengths labeled as 10. The dashed lines from G to A and to F are drawn, and the segments GB and GE are labeled 10 β€” suggesting that B and E are the feet of perpendiculars from G to chords AC and DF respectively.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since chords AC and DF are equidistant from the center, and the circle is symmetric, they must be congruent. So if I can find the length of one, I get the other. The key idea is to use the perpendicular from the center to a chord β€” it bisects the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, if I drop a perpendicular from G to chord AC, it hits at point B (as shown), and GB = 10. Since G is the center, and GB is perpendicular to AC, then B is the midpoint of AC. So triangle GBA is a right triangle with right angle at B.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We know:
(TaskRunner pid=3309296) - GA is the radius = 26
(TaskRunner pid=3309296) - GB = 10
(TaskRunner pid=3309296) - AB is half of AC, so if I find AB, then AC = 2 * AB.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem in triangle GBA:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296) ABΒ² = 576
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AC = 2 * AB = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer: \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) local_global_step_folder: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-11 01:45:14,908:[Rank 4] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/model_world_size_16_rank_4.pt
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-11 01:45:25,698:[Rank 4] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/optim_world_size_16_rank_4.pt
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-11 01:45:25,722:[Rank 4] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/extra_state_world_size_16_rank_4.pt
(WorkerDict pid=3309796) INFO:2025-11-11 01:45:15,691:[Rank 15] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/model_world_size_16_rank_15.pt [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-11 01:45:26,813:[Rank 0] Saved model config and tokenizer class to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/huggingface
(TaskRunner pid=3309296) Training Progress: 10%|β–ˆ | 80/800 [3:16:37<32:44:52, 163.74s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–ˆ | 81/800 [3:19:03<31:37:35, 158.35s/it]
(WorkerDict pid=3309793) INFO:2025-11-11 01:45:27,189:[Rank 12] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/optim_world_size_16_rank_12.pt [repeated 15x across cluster]
(WorkerDict pid=3309793) INFO:2025-11-11 01:45:27,194:[Rank 12] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_80/actor/extra_state_world_size_16_rank_12.pt [repeated 15x across cluster]
(TaskRunner pid=3309296) Training Progress: 10%|β–ˆ | 82/800 [3:21:18<30:12:27, 151.46s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–ˆ | 83/800 [3:23:31<29:02:59, 145.86s/it]
(TaskRunner pid=3309296) Training Progress: 10%|β–ˆ | 84/800 [3:25:49<28:32:51, 143.54s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 85}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Looking at this problem, I need to find the length of chord AC in circle centered at G, given that chords AC and DF are equidistant from the center, and the radius is 26. The diagram shows a circle with center G, and two chords AC and DF. The distances from G to these chords are marked as 10 units β€” this is key.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the chords are equidistant from the center, and the circle is symmetric, they must be congruent. That is, if two chords are equidistant from the center of a circle, they are equal in length. So, AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, to find the length of AC, I can use the Pythagorean theorem. If I draw a perpendicular from the center G to chord AC, it will bisect AC (a standard theorem: the perpendicular from the center to a chord bisects the chord). So, if I let M be the midpoint of AC, then GM = 10, and GA is the radius = 26.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, triangle GMA is a right triangle with right angle at M. Then:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = GAΒ²
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296) AMΒ² = 576
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since M is the midpoint of AC, then AC = 2 Γ— AM = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆ | 85/800 [3:28:59<31:16:45, 157.49s/it]
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆ | 86/800 [3:31:14<29:53:18, 150.70s/it]
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆ | 87/800 [3:33:34<29:13:35, 147.57s/it]
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆ | 88/800 [3:35:49<28:25:25, 143.72s/it]
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆ | 89/800 [3:38:30<29:22:42, 148.75s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 90}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Looking at this problem, I need to find the length of chord AC in circle centered at G, given that chords AC and DF are equidistant from the center, and the radius is 26. The diagram shows a circle with center G, and two chords AC and DF. The distances from G to these chords are marked as 10 units β€” this is key.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the chords are equidistant from the center, and the circle is symmetric, they must be congruent. So, if I can find the length of one, I get the other. The problem asks for AC, so I can focus on that.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I recall the formula for the length of a chord given the radius and the perpendicular distance from the center to the chord:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Chord length = 2 * sqrt(rΒ² - dΒ²)
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Where r is the radius, and d is the perpendicular distance from the center to the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Here, r = 26, and d = 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, plug in:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AC = 2 * sqrt(26Β² - 10Β²) = 2 * sqrt(676 - 100) = 2 * sqrt(576) = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) That’s straightforward. The diagram confirms the distance from G to chord AC is 10, and since the radius is 26, this formula applies.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I should double-check: the perpendicular from the center to a chord bisects the chord, so the right triangle formed has hypotenuse 26 and leg 10, so half the chord is sqrt(26Β² - 10Β²) = 24, so full chord is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Yes, that checks out.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆβ– | 90/800 [3:41:52<32:29:22, 164.74s/it]
(TaskRunner pid=3309296) Training Progress: 11%|β–ˆβ– | 91/800 [3:43:58<30:10:38, 153.23s/it]
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 92/800 [3:46:15<29:09:24, 148.25s/it]
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 93/800 [3:48:29<28:18:30, 144.14s/it]
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 94/800 [3:50:47<27:54:59, 142.35s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 95}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Looking at this problem, I need to find the length of chord AC in circle centered at G, given that chords AC and DF are equidistant from the center, and the radius is 26. The diagram shows a circle with center G, and two chords AC and DF intersecting the circle. The distances from G to both chords are marked as 10 units β€” this is key.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the chords are equidistant from the center, and the circle is symmetric, they must be congruent. So, if I can find the length of DF, I can use that to find AC. But wait β€” the problem doesn’t give me DF’s length directly. However, the diagram shows a right triangle formed by the radius GA, the perpendicular from G to chord AC, and half of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let me focus on chord AC. The perpendicular from the center G to chord AC meets it at point B (as shown in the diagram), and GB = 10. Since the perpendicular from the center to a chord bisects the chord, AB = BC = (1/2)AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In triangle AGB, GA is the radius = 26, GB = 10, and angle at B is 90 degrees. So triangle AGB is a right triangle.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296) ABΒ² = 576
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So half of chord AC is 24, meaning AC = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) I don’t even need DF for this β€” since the problem gives me the perpendicular distance and the radius, and I know the perpendicular bisects the chord, I can directly compute AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 95/800 [3:53:59<30:47:47, 157.26s/it]
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 96/800 [3:56:14<29:24:02, 150.34s/it]
(TaskRunner pid=3309296) WARNING:2025-11-11 02:26:04,288:WARNING: Error in configuration: macro '\frac' failed its substitution!
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 97/800 [3:58:39<29:04:36, 148.90s/it]
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 98/800 [4:00:52<28:04:21, 143.96s/it]
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ– | 99/800 [4:03:00<27:07:32, 139.30s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 100}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Looking at this problem, I need to find the length of chord AC in circle centered at G, given that chords AC and DF are equidistant from the center, and the radius is 26. The diagram shows a circle with center G, and two chords AC and DF intersecting the circle. The distances from G to both chords are marked as 10 units β€” this is key.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the chords are equidistant from the center, and the circle is symmetric, they must be congruent. So, if I can find the length of DF, I can use that to find AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But wait β€” the problem doesn’t give me DF’s length directly. However, the diagram shows a right triangle formed by the radius GA, the perpendicular from G to chord AC (which is 10 units), and half of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let me sketch this mentally: from center G, drop a perpendicular to chord AC β€” let’s call the foot of the perpendicular point M (though not labeled). Since the perpendicular from the center to a chord bisects the chord, AM = MC = (1/2)AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In right triangle GMA, we have:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - GA = radius = 26
(TaskRunner pid=3309296) - GM = 10 (distance from center to chord)
(TaskRunner pid=3309296) - AM = ?
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = GAΒ²
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296) AMΒ² = 576
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So half of chord AC is 24 β†’ AC = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since the problem says chords AC and DF are equidistant from the center, and we’ve used that to confirm symmetry, we don’t need DF’s length β€” we can directly compute AC using the perpendicular distance and radius.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) local_global_step_folder: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100
(WorkerDict pid=1869089, ip=10.24.0.201) INFO:2025-11-11 02:35:11,136:[Rank 7] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/model_world_size_16_rank_7.pt
(WorkerDict pid=1869084, ip=10.24.0.201) INFO:2025-11-11 02:35:21,458:[Rank 2] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/optim_world_size_16_rank_2.pt
(WorkerDict pid=1869084, ip=10.24.0.201) INFO:2025-11-11 02:35:21,492:[Rank 2] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/extra_state_world_size_16_rank_2.pt
(WorkerDict pid=3309795) INFO:2025-11-11 02:35:12,223:[Rank 14] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/model_world_size_16_rank_14.pt [repeated 15x across cluster]
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-11 02:35:22,545:[Rank 0] Saved model config and tokenizer class to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/huggingface
(TaskRunner pid=3309296) Training Progress: 12%|β–ˆβ–Ž | 100/800 [4:06:34<31:25:46, 161.64s/it]
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 101/800 [4:08:43<29:30:41, 151.99s/it]
(WorkerDict pid=3309795) INFO:2025-11-11 02:35:23,818:[Rank 14] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/optim_world_size_16_rank_14.pt [repeated 15x across cluster]
(WorkerDict pid=3309795) INFO:2025-11-11 02:35:23,822:[Rank 14] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_100/actor/extra_state_world_size_16_rank_14.pt [repeated 15x across cluster]
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 102/800 [4:10:54<28:14:30, 145.66s/it]
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 103/800 [4:12:56<26:48:05, 138.43s/it]
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 104/800 [4:15:05<26:12:17, 135.54s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 105}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. The radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, recall a key theorem: In a circle, if two chords are equidistant from the center, then they are congruent. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that the radius is 26, and we see two segments from the center G to the chords: both labeled 10. These are perpendicular distances from the center to the chords.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Wait β€” the diagram shows two perpendiculars from G to chords AC and DF, each of length 10. So, the perpendicular distance from the center to chord AC is 10, and similarly to chord DF is 10. So, yes, they are equidistant.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, to find the length of chord AC, we can use the right triangle formed by the radius, the perpendicular from the center to the chord, and half the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let’s consider triangle AGH, where H is the midpoint of chord AC (since the perpendicular from the center to a chord bisects the chord).
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, in right triangle AGH:
(TaskRunner pid=3309296) - AG is the radius = 26
(TaskRunner pid=3309296) - GH = 10 (distance from center to chord)
(TaskRunner pid=3309296) - AH = half of AC
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AHΒ² + GHΒ² = AGΒ²
(TaskRunner pid=3309296) => AHΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) => AHΒ² + 100 = 676
(TaskRunner pid=3309296) => AHΒ² = 576
(TaskRunner pid=3309296) => AH = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, half of AC is 24 β†’ AC = 2 Γ— 24 = 48
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 105/800 [4:18:28<30:04:42, 155.80s/it]
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 106/800 [4:20:38<28:35:06, 148.28s/it]
(TaskRunner pid=3309296) Training Progress: 13%|β–ˆβ–Ž | 107/800 [4:22:46<27:21:57, 142.16s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ–Ž | 108/800 [4:24:57<26:40:53, 138.81s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ–Ž | 109/800 [4:27:14<26:30:55, 138.14s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 110}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. The radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, recall a key theorem from circle geometry: In a circle, if two chords are equidistant from the center, then they are congruent. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that from the center G, perpendiculars to the chords are drawn, and those perpendiculars are labeled as 10 units long. The diagram shows that from G, a perpendicular is drawn to chord AC, meeting it at point B, and similarly to chord DF, meeting it at point E. The lengths of these perpendiculars are both labeled 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the distance from the center G to chord AC is 10 units, and the distance from G to chord DF is also 10 units β€” confirming they are equidistant.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, to find the length of chord AC, we can use the right triangle formed by the radius, the perpendicular from the center to the chord, and half the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In triangle AGC, we can consider triangle AGB, where G is the center, B is the midpoint of AC (since the perpendicular from the center to a chord bisects the chord), and AG is the radius = 26.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, triangle AGB is a right triangle with:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - Hypotenuse AG = 26
(TaskRunner pid=3309296) - Leg GB = 10 (distance from center to chord)
(TaskRunner pid=3309296) - Leg AB = half of AC
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) By the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = AGΒ²
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296) ABΒ² = 576
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AB = 24, so AC = 2 Γ— AB = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer: \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 110/800 [4:30:28<29:41:34, 154.92s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 111/800 [4:32:39<28:15:21, 147.64s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 112/800 [4:34:57<27:42:53, 145.02s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 113/800 [4:37:27<27:57:00, 146.46s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 114/800 [4:39:43<27:16:37, 143.15s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 115}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. The radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, I recall a key theorem from circle geometry: If two chords are equidistant from the center of a circle, then they are congruent. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that the radius is 26, and we see from the diagram that the perpendicular distance from G to chord AC is 10. The same distance is shown to chord DF β€” so the perpendicular from G to DF is also 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, we can use the right triangle formed by the radius, the perpendicular from center to chord, and half the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let’s focus on chord AC. The perpendicular from center G to chord AC meets it at point B (as shown in the diagram). So, GB = 10, and GA is the radius = 26.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Triangle GBA is a right triangle, right-angled at B.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, by the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Since AB is half of chord AC (because the perpendicular from the center to a chord bisects the chord), then:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AC = 2 Γ— AB = 2 Γ— 24 = 48
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 115/800 [4:42:56<30:05:02, 158.11s/it]
(TaskRunner pid=3309296) Training Progress: 14%|β–ˆβ– | 116/800 [4:44:59<28:03:43, 147.69s/it]
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ– | 117/800 [4:47:14<27:16:37, 143.77s/it]
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ– | 118/800 [4:49:31<26:50:19, 141.67s/it]
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ– | 119/800 [4:51:47<26:31:28, 140.22s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 120}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. The radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, I recall a key theorem from circle geometry: If two chords are equidistant from the center of a circle, then they are congruent. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that the radius is 26, and we see from the diagram that from the center G to the chords, there are perpendiculars drawn (as implied by the right-angle markings at G to the chords). The length of these perpendiculars is labeled as 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, if we drop a perpendicular from the center G to chord AC, it will bisect AC (by the perpendicular bisector theorem for chords). Let’s call the foot of the perpendicular from G to AC as point M. So, GM = 10, and AM = MC = (1/2)AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In triangle AGM, we have:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - AG is the radius = 26
(TaskRunner pid=3309296) - GM = 10
(TaskRunner pid=3309296) - AM is half of AC, which we want to find.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Triangle AGM is a right triangle, right-angled at M.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, by the Pythagorean Theorem:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + GMΒ² = AGΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² + 100 = 676
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AMΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AM = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AC = 2 Γ— AM = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) local_global_step_folder: /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120
(WorkerDict pid=3309792) INFO:2025-11-11 03:23:54,615:[Rank 11] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/model_world_size_16_rank_11.pt
(WorkerDict pid=3309796) INFO:2025-11-11 03:24:05,524:[Rank 15] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/optim_world_size_16_rank_15.pt
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-11 03:23:55,776:[Rank 0] Saved model to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/model_world_size_16_rank_0.pt [repeated 15x across cluster]
(WorkerDict pid=3309796) INFO:2025-11-11 03:24:05,535:[Rank 15] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/extra_state_world_size_16_rank_15.pt
(WorkerDict pid=1869082, ip=10.24.0.201) INFO:2025-11-11 03:24:07,730:[Rank 0] Saved model config and tokenizer class to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/huggingface
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ–Œ | 120/800 [4:55:18<30:27:47, 161.28s/it]
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ–Œ | 121/800 [4:57:47<29:45:39, 157.79s/it]
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-11 03:24:06,973:[Rank 4] Saved optim to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/optim_world_size_16_rank_4.pt [repeated 15x across cluster]
(WorkerDict pid=1869086, ip=10.24.0.201) INFO:2025-11-11 03:24:06,978:[Rank 4] Saved extra_state to /mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new/global_step_120/actor/extra_state_world_size_16_rank_4.pt [repeated 15x across cluster]
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ–Œ | 122/800 [4:59:58<28:10:37, 149.61s/it]
(TaskRunner pid=3309296) Training Progress: 15%|β–ˆβ–Œ | 123/800 [5:02:14<27:21:10, 145.45s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–Œ | 124/800 [5:04:30<26:46:36, 142.60s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 125}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. Also, the radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, recall a key theorem from circle geometry: If two chords are equidistant from the center of a circle, then they are congruent. So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that the radius is 26, and we see in the diagram that from center G to points A and C, there are segments labeled 10. Wait β€” those 10s are not radii. They are distances from G to the chords? Let me look again.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In the diagram, we see that from G to chord AC, there is a perpendicular segment labeled 10 β€” that is, the distance from center G to chord AC is 10. Similarly, from G to chord DF, there is also a perpendicular segment labeled 10 β€” so yes, they are equidistant from the center.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, we can use the formula for the length of a chord given its distance from the center.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) The formula is:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Chord length = 2 * √(r² - d²)
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) where r is the radius, and d is the perpendicular distance from the center to the chord.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Here, r = 26, d = 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So,
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AC = 2 * √(26² - 10²) = 2 * √(676 - 100) = 2 * √(576) = 2 * 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Let me double-check.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Yes, the perpendicular from the center to a chord bisects the chord. So, if we drop a perpendicular from G to AC, it hits AC at its midpoint, say M. Then triangle GMA is a right triangle with GM = 10, GA = 26 (radius), so AM = √(26² - 10²) = 24. Then AC = 2 * AM = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Perfect.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–Œ | 125/800 [5:07:53<30:08:12, 160.73s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–Œ | 126/800 [5:09:59<28:09:32, 150.40s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–Œ | 127/800 [5:12:16<27:20:23, 146.25s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–Œ | 128/800 [5:14:32<26:45:32, 143.35s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–Œ | 129/800 [5:17:03<27:08:59, 145.66s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 130}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. The radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, recall a key theorem from circle geometry:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) > If two chords are equidistant from the center of a circle, then they are congruent.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, since AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are not given DF’s length directly. However, we are given that the radius is 26, and we see in the diagram that from center G to points A and C, there are segments labeled 10 β€” but wait, those 10s are not radii. They are distances from G to points on the chords β€” probably perpendicular distances from the center to the chords.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Looking at the diagram:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - There is a perpendicular from G to chord AC, meeting it at point B, and GB is labeled 10.
(TaskRunner pid=3309296) - Similarly, from G to chord DF, meeting it at point E, GE is labeled 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the perpendicular distances from the center to both chords are equal (both 10 units). Therefore, by the theorem, chords AC and DF are congruent.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we still need to find AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We can use the Pythagorean Theorem.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Consider triangle GBA (or GBC β€” since G is center, and GB is perpendicular to AC, so it bisects AC).
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, triangle GBA is a right triangle with:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) - Hypotenuse GA = radius = 26
(TaskRunner pid=3309296) - Leg GB = 10
(TaskRunner pid=3309296) - Leg AB = half of AC (since perpendicular from center to chord bisects the chord)
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So,
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, AC = 2 Γ— AB = 2 Γ— 24 = 48
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–‹ | 130/800 [5:20:24<30:10:01, 162.09s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–‹ | 131/800 [5:22:38<28:33:40, 153.69s/it]
(TaskRunner pid=3309296) Training Progress: 16%|β–ˆβ–‹ | 132/800 [5:25:03<28:04:01, 151.26s/it]
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 133/800 [5:27:30<27:46:55, 149.95s/it]
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 134/800 [5:29:49<27:07:38, 146.63s/it]
(TaskRunner pid=3309296) test_gen_batch meta info: {'eos_token_id': 151645, 'pad_token_id': 151643, 'recompute_log_prob': False, 'do_sample': False, 'validate': True, 'global_steps': 135}
(TaskRunner pid=3309296) validation generation end
(TaskRunner pid=3309296) [prompt] user
(TaskRunner pid=3309296) Chords $\overline{A C}$ and $\overline{D F}$ are equidistant from the center. If the radius of $\odot G$ is 26 find $A C$ You FIRST think about the reasoning process as an internal monologue and then provide the final answer. The reasoning process MUST BE enclosed within <think> </think> tags. The final answer MUST BE put in \boxed{}.
(TaskRunner pid=3309296) assistant
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) [response] Let me think this through step by step.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are told that chords AC and DF are equidistant from the center G of the circle. The radius of the circle is 26. We are to find the length of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) First, I note that the center of the circle is labeled G, and we are told that the radius is 26. So, GA = GC = GD = GF = 26 β€” all radii.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) We are also told that chords AC and DF are equidistant from the center. That means the perpendicular distance from G to chord AC is equal to the perpendicular distance from G to chord DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In a circle, if two chords are equidistant from the center, then they are congruent. That’s a key theorem.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, if AC and DF are equidistant from G, then AC = DF.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) But we are asked to find AC. So if we can find DF, we’re done.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Looking at the diagram, we see that from point G, there are two segments drawn to the chords: one to AC (perpendicular to AC at point B, since it’s labeled with a right angle at B), and one to DF (perpendicular to DF at point E). Both GB and GE are labeled as 10.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, the perpendicular distance from center G to chord AC is GB = 10, and to chord DF is GE = 10 β€” so indeed, they are equidistant.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Now, to find the length of chord AC, we can use the right triangle formed by radius GA, perpendicular GB, and half of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) In triangle AGB, GA is the hypotenuse (radius = 26), GB is the leg (distance from center to chord = 10), and AB is half of chord AC.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, by Pythagoras:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + GBΒ² = GAΒ²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + 10Β² = 26Β²
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² + 100 = 676
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) ABΒ² = 676 - 100 = 576
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) AB = √576 = 24
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) So, AB = 24, and since AB is half of AC, then AC = 2 Γ— AB = 2 Γ— 24 = 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Therefore, the length of AC is 48.
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) Final answer:
(TaskRunner pid=3309296)
(TaskRunner pid=3309296) \boxed{48}
(TaskRunner pid=3309296) [ground_truth] 48
(TaskRunner pid=3309296) [score] 0.9
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 135/800 [5:33:06<29:53:36, 161.83s/it]
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 136/800 [5:35:17<28:08:26, 152.57s/it]
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 137/800 [5:37:49<28:03:48, 152.38s/it]
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 138/800 [5:40:02<26:57:18, 146.58s/it]
(TaskRunner pid=3309296) wandb: updating run metadata
(TaskRunner pid=3309296) wandb: uploading history steps 138-138, summary; uploading output.log; uploading wandb-summary.json; uploading config.yaml
(TaskRunner pid=3309296) wandb: uploading wandb-summary.json; uploading config.yaml
(TaskRunner pid=3309296) wandb:
(TaskRunner pid=3309296) wandb: Run history:
(TaskRunner pid=3309296) wandb: actor/entropy β–β–β–β–β–β–β–β–β–β–‚β–‚β–‚β–‚β–‚β–ƒβ–ƒβ–ƒβ–ƒβ–„β–„β–…β–…β–…β–†β–†β–…β–†β–†β–†β–†β–‡β–‡β–‡β–‡β–‡β–‡β–ˆβ–ˆβ–ˆβ–ˆ
(TaskRunner pid=3309296) wandb: actor/grad_norm β–β–‚β–β–β–‚β–‚β–‚β–β–β–‚β–‚β–‚β–β–β–β–β–β–β–β–‚β–β–‚β–β–β–β–β–β–β–β–β–β–β–β–‚β–β–‚β–β–‚β–β–ˆ
(TaskRunner pid=3309296) wandb: actor/kl_coef ▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
(TaskRunner pid=3309296) wandb: actor/kl_loss β–β–β–β–β–β–β–‚β–‚β–‚β–‚β–‚β–‚β–ƒβ–ƒβ–ƒβ–ƒβ–„β–„β–„β–„β–…β–…β–…β–…β–†β–‡β–‡β–‡β–‡β–‡β–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆβ–ˆ
(TaskRunner pid=3309296) wandb: actor/lr ▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
(TaskRunner pid=3309296) wandb: actor/pg_clipfrac β–†β–‡β–ˆβ–†β–‡β–‡β–†β–†β–„β–„β–ƒβ–„β–„β–„β–ƒβ–ƒβ–„β–ƒβ–‚β–‚β–‚β–‚β–β–‚β–β–β–‚β–β–‚β–β–‚β–β–β–β–β–β–β–‚β–ƒβ–
(TaskRunner pid=3309296) wandb: actor/pg_clipfrac_lower β–β–ƒβ–β–ƒβ–β–β–β–‚β–ˆβ–‚β–β–β–ƒβ–β–β–β–β–β–„β–β–‚β–β–‚β–β–β–β–β–β–β–β–β–β–β–β–‚β–β–β–‚β–β–
(TaskRunner pid=3309296) wandb: actor/pg_loss β–β–‚β–‚β–…β–ƒβ–ƒβ–„β–‡β–ƒβ–…β–†β–ƒβ–‡β–†β–ˆβ–†β–„β–…β–ˆβ–†β–‡β–†β–…β–…β–†β–‡β–…β–…β–†β–„β–„β–ƒβ–„β–†β–„β–†β–…β–…β–„β–†
(TaskRunner pid=3309296) wandb: actor/ppo_kl β–ƒβ–ƒβ–„β–ƒβ–ƒβ–ƒβ–‚β–„β–„β–„β–„β–„β–„β–„β–„β–„β–†β–…β–†β–ˆβ–‡β–ˆβ–†β–†β–‚β–„β–„β–‚β–„β–ˆβ–β–‚β–„β–ƒβ–ƒβ–ˆβ–‡β–‚β–…β–‚
(TaskRunner pid=3309296) wandb: critic/advantages/max ▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
(TaskRunner pid=3309296) wandb: +59 ...
(TaskRunner pid=3309296) wandb:
(TaskRunner pid=3309296) wandb: Run summary:
(TaskRunner pid=3309296) wandb: actor/entropy 3.0163
(TaskRunner pid=3309296) wandb: actor/grad_norm 0.1468
(TaskRunner pid=3309296) wandb: actor/kl_coef 0.001
(TaskRunner pid=3309296) wandb: actor/kl_loss 0.03767
(TaskRunner pid=3309296) wandb: actor/lr 0.0
(TaskRunner pid=3309296) wandb: actor/pg_clipfrac 0.00018
(TaskRunner pid=3309296) wandb: actor/pg_clipfrac_lower 0
(TaskRunner pid=3309296) wandb: actor/pg_loss 0.0028
(TaskRunner pid=3309296) wandb: actor/ppo_kl -5e-05
(TaskRunner pid=3309296) wandb: critic/advantages/max 2.47487
(TaskRunner pid=3309296) wandb: +59 ...
(TaskRunner pid=3309296) wandb:
(TaskRunner pid=3309296) wandb: πŸš€ View run qwen3_vl_8b_geo3k at: https://wandb.ai/mbzuai-llm/verl_grpo_w/runs/keyf6t0u
(TaskRunner pid=3309296) wandb: ⭐️ View project at: https://wandb.ai/mbzuai-llm/verl_grpo_w
(TaskRunner pid=3309296) wandb: Synced 5 W&B file(s), 0 media file(s), 0 artifact file(s) and 0 other file(s)
(TaskRunner pid=3309296) wandb: Find logs at: ./wandb/run-20251110_222752-keyf6t0u/logs
(TaskRunner pid=3309296) Training Progress: 17%|β–ˆβ–‹ | 138/800 [5:41:20<27:17:25, 148.41s/it]
Error executing job with overrides: ['algorithm.adv_estimator=grpo', 'data.train_files=/mnt/weka/home/xuezhe.ma/projects/yewendy/cur_working_dir/data/geo3k/train.parquet', 'data.val_files=/mnt/weka/home/xuezhe.ma/projects/yewendy/cur_working_dir/data/geo3k/test.parquet', 'data.train_batch_size=256', 'data.max_prompt_length=1024', 'data.max_response_length=2048', 'data.filter_overlong_prompts=True', 'data.truncation=error', 'data.image_key=images', 'actor_rollout_ref.model.path=Qwen/Qwen3-VL-8B-Instruct', 'actor_rollout_ref.actor.clip_ratio_low=0.2', 'actor_rollout_ref.actor.clip_ratio_high=0.28', 'actor_rollout_ref.actor.optim.lr=1e-6', 'actor_rollout_ref.model.use_remove_padding=True', 'actor_rollout_ref.model.use_fused_kernels=True', 'actor_rollout_ref.actor.ppo_mini_batch_size=128', 'actor_rollout_ref.actor.ppo_micro_batch_size_per_gpu=8', 'actor_rollout_ref.actor.use_kl_loss=True', 'actor_rollout_ref.actor.kl_loss_coef=0.001', 'actor_rollout_ref.actor.kl_loss_type=low_var_kl', 'actor_rollout_ref.actor.entropy_coeff=0.001', 'actor_rollout_ref.model.enable_gradient_checkpointing=True', 'actor_rollout_ref.actor.fsdp_config.param_offload=False', 'actor_rollout_ref.actor.fsdp_config.optimizer_offload=False', 'actor_rollout_ref.rollout.log_prob_micro_batch_size_per_gpu=20', 'actor_rollout_ref.rollout.tensor_model_parallel_size=2', 'actor_rollout_ref.rollout.name=vllm', '+actor_rollout_ref.rollout.engine_kwargs.vllm.disable_mm_preprocessor_cache=True', 'actor_rollout_ref.rollout.gpu_memory_utilization=0.85', 'actor_rollout_ref.rollout.enable_chunked_prefill=False', 'actor_rollout_ref.rollout.enforce_eager=False', 'actor_rollout_ref.rollout.free_cache_engine=True', 'actor_rollout_ref.rollout.n=8', 'actor_rollout_ref.ref.log_prob_micro_batch_size_per_gpu=20', 'actor_rollout_ref.ref.fsdp_config.param_offload=True', 'algorithm.use_kl_in_reward=False', 'trainer.critic_warmup=0', 'trainer.logger=wandb', 'trainer.project_name=verl_grpo_w', 'trainer.experiment_name=qwen3_vl_8b_geo3k', 'trainer.n_gpus_per_node=8', 'trainer.nnodes=2', 'trainer.save_freq=20', 'trainer.test_freq=5', 'trainer.total_epochs=100', 'trainer.default_local_dir=/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/saves/saved_model_qwen3vl-8b-new']
Traceback (most recent call last):
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/trainer/main_ppo.py", line 42, in main
run_ppo(config)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/trainer/main_ppo.py", line 96, in run_ppo
ray.get(runner.run.remote(config))
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/ray/_private/auto_init_hook.py", line 22, in auto_init_wrapper
return fn(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/ray/_private/client_mode_hook.py", line 104, in wrapper
return func(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/ray/_private/worker.py", line 2858, in get
values, debugger_breakpoint = worker.get_objects(object_refs, timeout=timeout)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/ray/_private/worker.py", line 958, in get_objects
raise value.as_instanceof_cause()
ray.exceptions.RayTaskError(ValueError): ray::TaskRunner.run() (pid=3309296, ip=10.24.1.115, actor_id=f92def9c14e2fbc9815b632402000000, repr=<main_ppo.TaskRunner object at 0x14af01235cc0>)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/trainer/main_ppo.py", line 341, in run
trainer.fit()
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/trainer/ppo/ray_trainer.py", line 1118, in fit
old_log_prob = self.actor_rollout_wg.compute_log_prob(batch)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/single_controller/ray/base.py", line 48, in __call__
output = ray.get(output)
ray.exceptions.RayTaskError(ValueError): ray::WorkerDict.actor_rollout_compute_log_prob() (pid=3309795, ip=10.24.1.115, actor_id=bfa0242ac7d4ef5d4da2ec2102000000, repr=<verl.single_controller.ray.base.WorkerDict object at 0x149e19100400>)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/single_controller/ray/base.py", line 700, in func
return getattr(self.worker_dict[key], name)(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/single_controller/base/decorator.py", line 442, in inner
return func(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/transferqueue_utils.py", line 199, in dummy_inner
return func(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/profiler/profile.py", line 256, in wrapper
return func(self_instance, *args, **kwargs_inner)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/workers/fsdp_workers.py", line 978, in compute_log_prob
output, entropys = self.actor.compute_log_prob(data=data, calculate_entropy=True)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/profiler/performance.py", line 105, in f
return self.log(decorated_function, *args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/utils/profiler/performance.py", line 118, in log
output = func(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/workers/actor/dp_actor.py", line 339, in compute_log_prob
entropy, log_probs = self._forward_micro_batch(
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/workers/actor/dp_actor.py", line 170, in _forward_micro_batch
output = self.actor_module(
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/nn/modules/module.py", line 1773, in _wrapped_call_impl
return self._call_impl(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/nn/modules/module.py", line 1784, in _call_impl
return forward_call(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/distributed/fsdp/fully_sharded_data_parallel.py", line 854, in forward
output = self._fsdp_wrapped_module(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/nn/modules/module.py", line 1773, in _wrapped_call_impl
return self._call_impl(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/nn/modules/module.py", line 1784, in _call_impl
return forward_call(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/models/transformers/qwen3_vl.py", line 280, in forward_with_torch_backend
outputs = self.model(input_ids, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/nn/modules/module.py", line 1773, in _wrapped_call_impl
return self._call_impl(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/miniconda3/envs/w-new-verl/lib/python3.10/site-packages/torch/nn/modules/module.py", line 1784, in _call_impl
return forward_call(*args, **kwargs)
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/models/transformers/qwen3_vl.py", line 244, in qwen3_vl_base_forward
input_kwargs = _get_input_embeds(
File "/mnt/weka/home/xuezhe.ma/projects/yewendy/verl/verl/models/transformers/qwen3_vl.py", line 153, in _get_input_embeds
raise ValueError(
ValueError: Image features and image tokens do not match: tokens: 3060, features 3059
Set the environment variable HYDRA_FULL_ERROR=1 for a complete stack trace.