| {"schema": 2, "epoch": 87823, "nonce": "bfbbfb1f83d8255f", "hotkey": "5FRE1kqMJz8ddModcXUsCquuWhB8QHnjYib2iK2VfiFetkC5", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "8c94d6e58cc59dda7770ab9ad7aa0be90adc8cbedcd419ef4c539a075d371e1f", "model_id": "router", "total_cost_usd": 0.00095083776, "n_calls": 6, "call_log_hash": "8e19ff08e4b2def87de645b47fe9628184daa30fd1acf78d76cf641610ba6796", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 68.317, "tokens_in": 1136, "tokens_out": 5096, "results": [{"benchmark": "mmlu", "task_id": "mmlu-5495", "answer": "A", "cost_usd": 9.361e-05, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.907328, 0.092509, 2.4e-05, 2.4e-05, 6.9e-05, 2.4e-05, 2.4e-05]}, {"benchmark": "mmlu", "task_id": "mmlu-9351", "answer": "D", "cost_usd": 0.00013567, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.999888, 0.000106, 1e-06, 1e-06, 2e-06, 1e-06, 1e-06]}, {"benchmark": "math", "task_id": "gsm8k-1315", "answer": "Ana peels an orange in 3 minutes, so in 60 minutes she peels \\(60 \\div 3 = 20\\) oranges. Jane peels an orange in 4 minutes, so in 60 minutes she peels \\(60 \\div 4 = 15\\) oranges. The difference is \\(20 - 15 = 5\\) oranges.\n\n\\boxed{5}", "cost_usd": 0.00010091675999999999, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.000199, 0.999793, 1e-06, 1e-06, 3e-06, 1e-06, 1e-06]}, {"benchmark": "math", "task_id": "gsm8k-1057", "answer": "They watch 4 movies on Saturday and half that, which is 2 movies, on Sunday. That's 6 movies per weekend. Over 4 weeks, they watch 4 \u00d7 6 = 24 movies.\n\n24", "cost_usd": 6.775999999999999e-05, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.000137, 0.999857, 1e-06, 1e-06, 3e-06, 1e-06, 1e-06]}, {"benchmark": "code", "task_id": "lcb-abc400_b", "answer": "```python\nimport sys\n\ndef main():\n data = sys.stdin.read().strip().split()\n if not data:\n return\n N = int(data[0])\n M = int(data[1])\n limit = 10**9\n total = 0\n term = 1\n for _ in range(M + 1):\n total += term\n if total > limit:\n print(\"inf\")\n return\n term *= N\n print(total)\n\nif __name__ == \"__main__\":\n main()\n```", "cost_usd": 0.00014353779999999995, "chosen_rung": 1, "rungs_used": [1], "distribution": [3.4e-05, 0.999963, 0.0, 0.0, 1e-06, 0.0, 0.0]}, {"benchmark": "code", "task_id": "lcb-abc399_c", "answer": "```python\nimport sys\n\ndef solve() -> None:\n input = sys.stdin.readline\n N, M = map(int, input().split())\n parent = list(range(N + 1))\n rank = [0] * (N + 1)\n\n def find(x: int) -> int:\n # path compression\n while parent[x] != x:\n parent[x] = parent[parent[x]]\n x = parent[x]\n return x\n\n def union(x: int, y: int) -> None:\n rx, ry = find(x), find(y)\n if rx == ry:\n return\n # union by rank\n if rank[rx] < rank[ry]:\n parent[rx] = ry\n elif rank[rx] > rank[ry]:\n parent[ry] = rx\n else:\n parent[ry] = rx\n rank[rx] += 1\n\n for _ in range(M):\n u, v = map(int, input().split())\n union(u, v)\n\n # number of connected components = number of self\u2011parents\n comp = sum(1 for i in range(1, N + 1) if parent[i] == i)\n ans = M - (N - comp)\n print(ans)\n\nif __name__ == \"__main__\":\n solve()\n```", "cost_usd": 0.0004093432, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.000236, 0.999755, 1e-06, 1e-06, 4e-06, 1e-06, 1e-06]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "218592f5c6328d5213177ab604c5e9e6b57d751b42c3ab7eb4cb014431e787d8", "platform_sig": 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