| {"schema": 2, "epoch": 87829, "nonce": "56fad5336b2ae9c6", "hotkey": "5FRE1kqMJz8ddModcXUsCquuWhB8QHnjYib2iK2VfiFetkC5", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "8c94d6e58cc59dda7770ab9ad7aa0be90adc8cbedcd419ef4c539a075d371e1f", "model_id": "router", "total_cost_usd": 0.002929408, "n_calls": 6, "call_log_hash": "966d507dfc97324d3693f098a2c1f349b4195c9d08ba54a4ead19ed13f8c17e6", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 255.054, "tokens_in": 847, "tokens_out": 14413, "results": [{"benchmark": "mmlu", "task_id": "mmlu-13113", "answer": "B", "cost_usd": 0.00012556, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.999688, 0.000302, 1e-06, 1e-06, 4e-06, 1e-06, 1e-06]}, {"benchmark": "mmlu", "task_id": "mmlu-10279", "answer": "C", "cost_usd": 6.377e-05, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.998281, 0.001695, 3e-06, 3e-06, 1e-05, 3e-06, 3e-06]}, {"benchmark": "math", "task_id": "gsm8k-72", "answer": "Tommy sells 43 brownies at $3 each, which is 43 \u00d7 3 = $129. He sells 23 slices of cheesecake at $4 each, which is 23 \u00d7 4 = $92. The total amount raised is $129 + $92 = $221.\n\n221", "cost_usd": 3.3156000000000006e-05, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.001809, 0.998167, 3e-06, 3e-06, 1e-05, 3e-06, 3e-06]}, {"benchmark": "math", "task_id": "gsm8k-1223", "answer": "8", "cost_usd": 6.412e-05, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.001269, 0.998711, 3e-06, 3e-06, 8e-06, 3e-06, 3e-06]}, {"benchmark": "code", "task_id": "lcb-abc398_a", "answer": "```python\nimport sys\n\ndef main():\n data = sys.stdin.read().strip()\n if not data:\n return\n N = int(data)\n if N % 2 == 1:\n half = N // 2\n result = '-' * half + '=' + '-' * half\n else:\n half = N // 2 - 1\n result = '-' * half + '==' + '-' * half\n print(result)\n\nif __name__ == \"__main__\":\n main()\n```", "cost_usd": 0.00051, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.001049, 0.998933, 3e-06, 3e-06, 8e-06, 3e-06, 3e-06]}, {"benchmark": "code", "task_id": "lcb-arc195_a", "answer": "```python\nimport sys\nimport bisect\nfrom collections import defaultdict\n\ndef solve() -> None:\n data = sys.stdin.buffer.read().split()\n it = iter(data)\n N = int(next(it))\n M = int(next(it))\n A = [int(next(it)) for _ in range(N)]\n B = [int(next(it)) for _ in range(M)]\n\n # positions of each value in A (0-indexed, sorted)\n pos = defaultdict(list)\n for idx, val in enumerate(A):\n pos[val].append(idx)\n\n # leftmost match: L[i] = smallest index where B[0..i-1] can be matched\n L = [-1] * (M + 1) # L[0] = -1\n j = 0\n for i in range(N):\n if j < M and A[i] == B[j]:\n L[j + 1] = i\n j += 1\n if j < M: # no subsequence at all\n print(\"No\")\n return\n\n # rightmost match: R[i] = largest index where B[i-1..M-1] can be matched\n R = [N] * (M + 2) # R[M+1] = N\n j = M - 1\n for i in range(N - 1, -1, -1):\n if j >= 0 and A[i] == B[j]:\n R[j + 1] = i\n j -= 1\n\n # check each position of B for at least two possible indices\n for i in range(1, M + 1):\n val = B[i - 1]\n left = L[i - 1]\n right = R[i + 1]\n lst = pos[val]\n lo = bisect.bisect_right(lst, left) # first index > left\n hi = bisect.bisect_left(lst, right) # first index >= right\n if hi - lo >= 2:\n print(\"Yes\")\n return\n\n print(\"No\")\n\nif __name__ == \"__main__\":\n solve()\n```", "cost_usd": 0.002132802, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.001011, 0.998971, 3e-06, 3e-06, 7e-06, 3e-06, 3e-06]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "6e335283eee010da148e81c8fc0da82275c1586c7b7fce1bf346a9b771480a23", "platform_sig": 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