| {"schema": 2, "epoch": 87866, "nonce": "884fd0bb081a40f3", "hotkey": "5FRE1kqMJz8ddModcXUsCquuWhB8QHnjYib2iK2VfiFetkC5", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "2e4d6a88063177a0a7a564f24e10b347ef48e87c9595a209162369a4fa4d4477", "model_id": "router", "total_cost_usd": 0.07702587388, "n_calls": 6, "call_log_hash": "9f452a0a39b84f6b183c4cca131ea31c7f6a575ddcf756555c09812d57756a3e", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 82.778, "tokens_in": 986, "tokens_out": 12948, "results": [{"benchmark": "mmlu", "task_id": "mmlu-8163", "answer": "B", "cost_usd": 0.00016772, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.996569, 0.000766, 0.0, 0.0, 0.002664, 1e-06, 0.0]}, {"benchmark": "mmlu", "task_id": "mmlu-4490", "answer": "A", "cost_usd": 5.853e-05, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.989967, 0.004096, 0.0, 0.0, 0.005928, 9e-06, 0.0]}, {"benchmark": "math", "task_id": "gsm8k-627", "answer": "The tow truck towed 10 cars each day for the first three days, totaling 30 cars. For the remaining four days, it towed 4 fewer cars each day, meaning 6 cars per day, totaling 24 cars. The overall total is 30 + 24 = 54 cars.\n\n\\boxed{54}", "cost_usd": 8.5716e-05, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.00067, 0.997067, 0.0, 0.0, 7.5e-05, 0.002188, 0.0]}, {"benchmark": "math", "task_id": "gsm8k-505", "answer": "Frederick can buy 2x8 pieces for $6 each, which yield 400 sticks per piece, at a cost of $0.015 per stick. With $24, he can buy exactly 4 pieces, giving 4 \u00d7 400 = 1600 sticks. This is the maximum because the 2x8 is cheaper per stick than the 2x4.\n\n1600", "cost_usd": 0.00012310787999999997, "chosen_rung": 1, "rungs_used": [1], "distribution": [9.7e-05, 0.999674, 0.0, 0.0, 0.000128, 0.000101, 0.0]}, {"benchmark": "code", "task_id": "lcb-abc400_a", "answer": "a = int(input())\nprint(400 // a if 400 % a == 0 else -1)\n", "cost_usd": 3.680000000000003e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [5.3e-05, 0.000608, 0.0, 0.0, 0.998938, 0.000401, 0.0]}, {"benchmark": "code", "task_id": "lcb-arc191_a", "answer": "import sys\n\ndef main():\n input = sys.stdin.read\n data = input().split()\n if not data:\n return\n \n N = int(data[0])\n M = int(data[1])\n S = data[2]\n T = data[3]\n \n d_must = T[-1]\n \n # Count frequencies of digits 1-9 in T[:-1]\n counts = [0] * 10\n for ch in T[:-1]:\n counts[int(ch)] += 1\n \n # Pick up to N-1 largest digits from T[:-1]\n opt_digits = []\n needed = N - 1\n for d in range(9, 0, -1):\n take = min(counts[d], needed)\n opt_digits.extend([str(d)] * take)\n needed -= take\n if needed == 0:\n break\n \n # Combine opt_digits and d_must, sorted descending\n # We tag d_must to know if it gets used.\n all_digits = []\n must_placed = False\n must_val = int(d_must)\n \n for d_str in opt_digits:\n d = int(d_str)\n if not must_placed and must_val >= d:\n all_digits.append((d_must, True))\n must_placed = True\n all_digits.append((d_str, False))\n \n if not must_placed:\n all_digits.append((d_must, True))\n \n ans = list(S)\n used_must = False\n ptr = 0\n L = len(all_digits)\n \n for i in range(N):\n if ptr < L and all_digits[ptr][0] > ans[i]:\n ans[i] = all_digits[ptr][0]\n if all_digits[ptr][1]:\n used_must = True\n ptr += 1\n\n if used_must or (d_must in ans):\n print(\"\".join(ans))\n else:\n ans[-1] = d_must\n print(\"\".join(ans))\n\nif __name__ == '__main__':\n main()", "cost_usd": 0.076554, "chosen_rung": 5, "rungs_used": [5], "distribution": [8e-06, 2.1e-05, 0.0, 0.0, 0.000994, 0.998976, 0.0]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "0cf7571a9a3fda8060e9c60826a74fb3597209dbec273757222014fa67627786", "platform_sig": 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