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+[{"task_id": "mmlu-7732", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] Which of these measurements is equal to one square foot?\nA) 50 square inches\nB) 77 square inches\nC) 100 square inches\nD) 144 square inches\n\nAnswer with the letter only.", "response": "D", "cost_usd": 2.096e-05, "tokens_in": 66, "tokens_out": 146, "latency_s": 2.153}, {"task_id": "mmlu-3501", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] Which country faces a serious trade disadvantage due to its location?\nA) Singapore\nB) Italy\nC) Spain\nD) Mongolia\n\nAnswer with the letter only.", "response": "D", "cost_usd": 3.748e-05, "tokens_in": 49, "tokens_out": 277, "latency_s": 2.447}, {"task_id": "gsm8k-1045", "model": "deepseek/deepseek-v4-flash", "prompt": "Three people divided an amount of $1920. The second took $80 more than the first and the third took twice what the second took. Calculate the share of the first one.\n\nReason step by step, then give the final answer as a single number.", "response": "The first person's share is $420.\n\nLet the first person's share be \\(x\\). Then the second person's share is \\(x + 80\\), and the third person's share is \\(2(x + 80) = 2x + 160\\). The total sum is:\n\\[\nx + (x + 80) + (2x + 160) = 4x + 240 = 1920.\n\\]\nSolving for \\(x\\):\n\\[\n4x = 1920 - 240 = 1680 \\implies x = \\frac{1680}{4} = 420.\n\\]\n\n\\boxed{420}", "cost_usd": 8.5553e-05, "tokens_in": 56, "tokens_out": 283, "latency_s": 3.816}, {"task_id": "gsm8k-547", "model": "deepseek/deepseek-v4-flash", "prompt": "A phone tree is used to contact families and relatives of Ali's deceased coworker. Ali decided to call 3 families. Then each family calls 3 other families, and so on. How many families will be notified during the fourth round of calls?\n\nReason step by step, then give the final answer as a single number.", "response": "The phone tree starts with Ali calling 3 families in the first round. In each subsequent round, every family that was notified in the previous round calls 3 new families. Therefore, the number of families notified in each round follows a geometric progression: round 1: 3, round 2: 3 \u00d7 3 = 9, round 3: 9 \u00d7 3 = 27, round 4: 27 \u00d7 3 = 81.\n\nThus, 81 families are notified during the fourth round.\n\n\\boxed{81}", "cost_usd": 0.00012852, "tokens_in": 70, "tokens_out": 424, "latency_s": 5.602}, {"task_id": "lcb-abc392_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given a sequence of M integers A = (A_1, A_2, \\dots, A_M).\nEach element of A is an integer between 1 and N, inclusive, and all elements are distinct.\nList all integers between 1 and N that do not appear in A in ascending order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\dots A_M\n\nOutput\n\nLet (X_1, X_2, \\dots, X_C) be the sequence of all integers between 1 and N, inclusive, that do not appear in A, listed in ascending order.\nThe output should be in the following format:\nC\nX_1 X_2 \\dots X_C\n\nConstraints\n\n\n- All input values are integers.\n- 1 \\le M \\le N \\le 1000\n- 1 \\le A_i \\le N\n- The elements of A are distinct.\n\nSample Input 1\n\n10 3\n3 9 2\n\nSample Output 1\n\n7\n1 4 5 6 7 8 10\n\nHere, A=(3,9,2).\nThe integers between 1 and 10 that do not appear in A, listed in ascending order, are 1,4,5,6,7,8,10.\n\nSample Input 2\n\n6 6\n1 3 5 2 4 6\n\nSample Output 2\n\n0\n\n\nNo integer between 1 and 6 is missing from A.\nIn this case, print 0 on the first line and leave the second line empty.\n\nSample Input 3\n\n9 1\n9\n\nSample Output 3\n\n8\n1 2 3 4 5 6 7 8\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    n, m = data[0], data[1]\n    present = set(data[2:2 + m])\n    missing = [i for i in range(1, n + 1) if i not in present]\n\n    print(len(missing))\n    print(*missing)\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 9.79e-05, "tokens_in": 415, "tokens_out": 94, "latency_s": 5.569}, {"task_id": "lcb-abc388_c", "model": "openai/gpt-5.6-luna", "prompt": "There are N mochi (rice cakes) arranged in ascending order of size.\r\nThe size of the i-th mochi (1 \\leq i \\leq N) is A_i.\nGiven two mochi A and B, with sizes a and b respectively, you can make one kagamimochi (a stacked rice cake) by placing mochi A on top of mochi B if and only if a is at most half of b.\nYou choose two mochi out of the N mochi, and place one on top of the other to form one kagamimochi.\nFind how many different kinds of kagamimochi can be made.\nTwo kagamimochi are distinguished if at least one of the mochi is different, even if the sizes of the mochi are the same.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\cdots A_N\n\nOutput\n\nPrint the number of different kinds of kagamimochi that can be made.\n\nConstraints\n\n\n- 2 \\leq N \\leq 5 \\times 10^5\n- 1 \\leq A_i \\leq 10^9 \\ (1 \\leq i \\leq N)\n- A_i \\leq A_{i+1} \\ (1 \\leq i < N)\n- All input values are integers.\n\nSample Input 1\n\n6\r\n2 3 4 4 7 10\n\nSample Output 1\n\n8\r\n\nThe sizes of the given mochi are as follows:\n\nIn this case, you can make the following eight kinds of kagamimochi:\n\nNote that there are two kinds of kagamimochi where a mochi of size 4 is topped by a mochi of size 2, and two kinds where a mochi of size 10 is topped by a mochi of size 4.\n\nSample Input 2\n\n3\r\n387 388 389\n\nSample Output 2\n\n0\r\n\nIt is possible that you cannot make any kagamimochi.\n\nSample Input 3\n\n32\r\n1 2 4 5 8 10 12 16 19 25 33 40 50 64 87 101 149 175 202 211 278 314 355 405 412 420 442 481 512 582 600 641\n\nSample Output 3\n\n388\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    n = data[0]\n    a = data[1:]\n\n    ans = 0\n    k = 0\n\n    for j in range(n):\n        while k < j and 2 * a[k] <= a[j]:\n            k += 1\n        ans += k\n\n    print(ans)\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.0002911999999999999, "tokens_in": 542, "tokens_out": 395, "latency_s": 6.182}]