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[{"task_id": "mmlu-8163", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] Which two planets are most similar in size diameter wise?\nA) Mars and Mercury\nB) Venus and Earth\nC) Uranus and Neptune\nD) Jupiter and Saturn\n\nAnswer with the letter only.", "response": "B", "cost_usd": 0.00016772, "tokens_in": 57, "tokens_out": 1277, "latency_s": 9.033}, {"task_id": "mmlu-4490", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] Two numbers added together are 19. Their product is 70. What are the two numbers?\nA) 5, 14\nB) 7, 10\nC) 4, 15\nD) 3, 16\n\nAnswer with the letter only.", "response": "A", "cost_usd": 5.853e-05, "tokens_in": 79, "tokens_out": 432, "latency_s": 3.381}, {"task_id": "gsm8k-627", "model": "deepseek/deepseek-v4-flash", "prompt": "On a particular week, a tow truck pulled ten cars for each of the first three days and then four fewer cars on each of the remaining days of the week. Calculate the total number of cars it towed that week.\n\nReason step by step, then give the final answer as a single number.", "response": "The tow truck towed 10 cars each day for the first three days, totaling 30 cars. For the remaining four days, it towed 4 fewer cars each day, meaning 6 cars per day, totaling 24 cars. The overall total is 30 + 24 = 54 cars.\n\n\\boxed{54}", "cost_usd": 8.5716e-05, "tokens_in": 64, "tokens_out": 457, "latency_s": 8.935}, {"task_id": "gsm8k-505", "model": "deepseek/deepseek-v4-flash", "prompt": "Frederick is making popsicles to sell and to save money he is making his own popsicle sticks. He can get 200 sticks from a 2 x 4 piece of wood and 400 sticks from a 2 x 8 piece of wood. He has $24 to buy wood for sticks. A 2 x 4 costs $4. A 2 x 8 costs $6. What is the most popsicle sticks he can make if he buys the cheapest lumber?\n\nReason step by step, then give the final answer as a single number.", "response": "Frederick can buy 2x8 pieces for $6 each, which yield 400 sticks per piece, at a cost of $0.015 per stick. With $24, he can buy exactly 4 pieces, giving 4 \u00d7 400 = 1600 sticks. This is the maximum because the 2x8 is cheaper per stick than the 2x4.\n\n1600", "cost_usd": 0.00012310787999999997, "tokens_in": 118, "tokens_out": 640, "latency_s": 11.749}, {"task_id": "lcb-abc400_a", "model": "openai/gpt-5.6-luna", "prompt": "In the ceremony commemorating ABC400, we want to arrange 400 people in a rectangular formation of A rows and B columns without any gaps.\nYou are given a positive integer A. Print the value of a positive integer B for which such an arrangement is possible. If there is no such positive integer B, print -1.\n\nInput\n\nThe input is given from Standard Input in the following format:\nA\n\nOutput\n\nPrint the value of B or -1 as specified by the problem statement.\n\nConstraints\n\n\n- A is an integer between 1 and 400, inclusive.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n40\r\n\nWe can arrange 400 people in 10 rows and 40 columns.\n\nSample Input 2\n\n11\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n400\n\nSample Output 3\n\n1\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "a = int(input())\nprint(400 // a if 400 % a == 0 else -1)\n", "cost_usd": 3.680000000000003e-05, "tokens_in": 212, "tokens_out": 26, "latency_s": 1.495}, {"task_id": "lcb-arc191_a", "model": "google/gemini-3.6-flash", "prompt": "You are given a string S of length N and a string T of length M, both consisting of digits from 1 to 9.\nYou will perform the following operation for k=1,2,\\ldots,M in order:\n\n- Choose an integer i such that 1 \\le i \\le N. Then, replace the i-th character of S with the k-th character of T.\n\nFind the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nS\nT\n\nOutput\n\nPrint the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nConstraints\n\n\n- 1 \\le N,M \\le 10^6\n- N and M are integers.\n- S is a string of length N consisting of digits from 1 through 9.\n- T is a string of length M consisting of digits from 1 through 9.\n\nSample Input 1\n\n3 3\n191\n325\n\nSample Output 1\n\n593\n\nThe following sequence of operations is optimal:\n\n- For k=1: Choose i=3. Then, S = 193.\n- For k=2: Choose i=1. Then, S = 293.\n- For k=3: Choose i=1. Then, S = 593.\n\nIn this case, the value of S interpreted as an integer is 593, which is the maximum.\n\nSample Input 2\n\n3 9\n191\n998244353\n\nSample Output 2\n\n993\n\nSample Input 3\n\n11 13\n31415926535\n2718281828459\n\nSample Output 3\n\n98888976555\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n input = sys.stdin.read\n data = input().split()\n if not data:\n return\n \n N = int(data[0])\n M = int(data[1])\n S = data[2]\n T = data[3]\n \n d_must = T[-1]\n \n # Count frequencies of digits 1-9 in T[:-1]\n counts = [0] * 10\n for ch in T[:-1]:\n counts[int(ch)] += 1\n \n # Pick up to N-1 largest digits from T[:-1]\n opt_digits = []\n needed = N - 1\n for d in range(9, 0, -1):\n take = min(counts[d], needed)\n opt_digits.extend([str(d)] * take)\n needed -= take\n if needed == 0:\n break\n \n # Combine opt_digits and d_must, sorted descending\n # We tag d_must to know if it gets used.\n all_digits = []\n must_placed = False\n must_val = int(d_must)\n \n for d_str in opt_digits:\n d = int(d_str)\n if not must_placed and must_val >= d:\n all_digits.append((d_must, True))\n must_placed = True\n all_digits.append((d_str, False))\n \n if not must_placed:\n all_digits.append((d_must, True))\n \n ans = list(S)\n used_must = False\n ptr = 0\n L = len(all_digits)\n \n for i in range(N):\n if ptr < L and all_digits[ptr][0] > ans[i]:\n ans[i] = all_digits[ptr][0]\n if all_digits[ptr][1]:\n used_must = True\n ptr += 1\n\n if used_must or (d_must in ans):\n print(\"\".join(ans))\n else:\n ans[-1] = d_must\n print(\"\".join(ans))\n\nif __name__ == '__main__':\n main()", "cost_usd": 0.076554, "tokens_in": 456, "tokens_out": 10116, "latency_s": 48.185}]
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