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+[{"task_id": "mmlu-2286", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] Keri spent 3 hours on her homework. She spent equal amounts of time on all subjects. If Keri spent 1 over 2 hour on science, how many subjects did she study?\nA) 4 subjects\nB) 2 subjects\nC) 6 subjects\nD) 5 subjects\n\nAnswer with the letter only.", "response": "C", "cost_usd": 4.259e-05, "tokens_in": 85, "tokens_out": 308, "latency_s": 2.908}, {"task_id": "mmlu-10155", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] By 1900 B.P., the central elements of Mayan culture were in place. These did NOT include:\nA) stratified societies ruled by kings.\nB) ritual ball games and a reverence for precious jade.\nC) a sophisticated bronze producing industry.\nD) a hieroglyphic written language and calendar.\n\nAnswer with the letter only.", "response": "C", "cost_usd": 7.995e-05, "tokens_in": 91, "tokens_out": 594, "latency_s": 5.591}, {"task_id": "gsm8k-1060", "model": "deepseek/deepseek-v4-flash", "prompt": "Becky, Jake, and Silvia shared 4 pizzas. Each pizza had 8 slices. Becky ate 3 more slices than Jake did. Silvia ate twice as many slices than Jake did. If Becky ate 10 slices, how many total slices did they eat?\n\nReason step by step, then give the final answer as a single number.", "response": "Becky ate 10 slices. Since she ate 3 more than Jake, Jake ate 10 - 3 = 7 slices. Silvia ate twice as many as Jake, so she ate 2 \u00d7 7 = 14 slices. The total slices eaten is 10 + 7 + 14 = 31.\n\n31", "cost_usd": 9.323720000000002e-05, "tokens_in": 76, "tokens_out": 459, "latency_s": 7.651}, {"task_id": "gsm8k-272", "model": "deepseek/deepseek-v4-flash", "prompt": "A mother goes shopping. She buys cocoa at $4.20, laundry at $9.45 and a package of pasta at $1.35. She pays $20. How much change does the cashier give back?\n\nReason step by step, then give the final answer as a single number.", "response": "The total cost is $4.20 + $9.45 + $1.35 = $15.00. The change from $20 is $20.00 - $15.00 = $5.00.\n\n5", "cost_usd": 7.060999999999998e-05, "tokens_in": 65, "tokens_out": 222, "latency_s": 3.14}, {"task_id": "lcb-abc388_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ns = sys.stdin.readline().strip()\nprint(s[0] + \"UPC\")", "cost_usd": 3.6300000000000015e-05, "tokens_in": 219, "tokens_out": 24, "latency_s": 0.952}, {"task_id": "lcb-arc194_a", "model": "google/gemini-3.6-flash", "prompt": "You are given an integer sequence of length N: (A_1, A_2, \\ldots, A_N). There is also a sequence S, which is initially empty.\nFor each i = 1, 2, \\ldots, N in this order, you perform exactly one of the following two operations:\n\n- Append A_i as an element to the end of S.\n- Delete the last element of S. You cannot choose this operation if S is empty.\n\nPrint the maximum possible value of the sum of the elements of S after all operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- -10^9 \\leq A_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n6\r\n3 -1 -4 5 -9 2\n\nSample Output 1\n\n8\r\n\nStarting from the initial state where S is an empty sequence, consider the following operations:\n\n- For i = 1, append A_1 = 3 to the end of S. Now, S = (3).\n- For i = 2, append A_2 = -1 to the end of S. Now, S = (3, -1).\n- For i = 3, delete the last element of S. Now, S = (3).\n- For i = 4, append A_4 = 5 to the end of S. Now, S = (3, 5).\n- For i = 5, append A_5 = -9 to the end of S. Now, S = (3, 5, -9).\n- For i = 6, delete the last element of S. Now, S = (3, 5).\n\nHere, the sum of the elements of S after all operations is 3 + 5 = 8, which is the maximum possible value.\n\nSample Input 2\n\n1\r\n-1\n\nSample Output 2\n\n-1\r\n\nNote that if S is empty, you must choose to append an element.\n\nSample Input 3\n\n20\r\n-14 74 -48 38 -51 43 5 37 -39 -29 80 -44 -55 59 17 89 -37 -68 38 -16\n\nSample Output 3\n\n369\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "An optimal choice of operations corresponds to partitioning the array $A$ into:\n1. **Kept elements**: $A_i$ is appended and never deleted, contributing $A_i$ to the total sum.\n2. **Eliminated blocks**: Contiguous subarrays of **even length**. Any even-length contiguous subarray can be completely eliminated (contributing $0$ to the sum) by alternating between append and delete operations (i.e., append, delete, append, delete, ...), which never attempts to delete from an empty stack.\n\nThus, we can use dynamic programming:\nLet `dp[i]` be the maximum possible sum for the prefix of length `i`.\n- We can extend from `dp[i-1]` by keeping $A_i$: `dp[i] = dp[i-1] + A_i`\n- We can eliminate an even-length block ending at index `i`, which transitions from `dp[j]` where `j < i` has the same parity as `i`.\n\nWe can maintain the maximum `dp` values for even and odd indices to transition in $O(1)$ time per element.\n\n### Python 3 Source Code\n\n```python\nimport sys\n\ndef main():\n    input = sys.stdin.read\n    data = input().split()\n    if not data:\n        return\n    \n    N = int(data[0])\n    A = [int(x) for x in data[1:]]\n    \n    dp = 0\n    max_even = 0\n    max_odd = -float('inf')\n    \n    for i in range(1, N + 1):\n        val = A[i - 1]\n        if i % 2 == 1:\n            dp = max(dp + val, max_odd)\n            max_odd = max(max_odd, dp)\n        else:\n            dp = max(dp + val, max_even)\n            max_even = max(max_even, dp)\n            \n    print(dp)\n\nif __name__ == '__main__':\n    main()\n```", "cost_usd": 0.0315555, "tokens_in": 592, "tokens_out": 4089, "latency_s": 20.37}]