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+[{"task_id": "mmlu-11079", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] A merchant's irrevocable written offer (firm offer) to sell goods\nA) Must be separately signed if the offeree supplies a form contract containing the offer.\nB) Is valid for three months.\nC) Is nonassignable.\nD) Can not exceed a three-month duration even if consideration is given.\n\nAnswer with the letter only.", "response": "A", "cost_usd": 0.00012448, "tokens_in": 89, "tokens_out": 937, "latency_s": 8.043}, {"task_id": "mmlu-11396", "model": "qwen/qwen3.7-flash", "prompt": "[MMLU] The defendant and her co-felon decided to rob a bank. They agreed to use unloaded guns in the robbery. As planned, the co-felon entered the bank while the defendant stationed herself outside as a lookout. The co-felon approached the bank teller, pointed her unloaded gun at him, and demanded themoney. While the teller was handing the money to the co-felon, the defendant got scared and fled. The teller, who had a weak heart started to feel faint. He handed over the money to the co-felon, and then clutched his chest and died. The co-felon was found not guilty by a jury in her trial, which preceded the defendant's trial. The defendant is subsequently prosecuted for conspiracy and acquitted. Her acquittal most likely resulted because\nA) the defendant abandoned her participation in the crime.\nB) the teller's death was accidental.\nC) the co-felon was acquitted.\nD) the teller was not placed in apprehension of bodily harm.\n\nAnswer with the letter only.", "response": "C", "cost_usd": 0.00027886, "tokens_in": 230, "tokens_out": 2092, "latency_s": 13.875}, {"task_id": "gsm8k-1011", "model": "deepseek/deepseek-v4-flash", "prompt": "A tank has a capacity of 18000 gallons. Wanda and Ms. B decided to pump water from a pond to fill the tank in two days. On the first day, working in shifts, Wanda filled 1/4 of the tank's capacity with water, and Ms. B pumped 3/4 as much water as Wanda pumped into the tank that day. On the second day, Wanda pumped 2/3 of the amount of water she pumped on the previous day, while Ms. B only pumped 1/3 of the number of gallons she pumped on the first day. How many gallons of water are remaining for the tank to be full?\n\nReason step by step, then give the final answer as a single number.", "response": "We are given: A tank capacity = 18000 gallons. Two days of pumping. First day: Wanda filled 1/4 of tank's capacity. So Wanda pumped (1/4)*18000 = 4500 gallons. Ms. B pumped 3/4 as much water as Wanda pumped that day. So Ms. B pumped (3/4)*4500 = 3375 gallons. So total first day = 4500+3375 = 7875 gallons.\n\nSecond day: Wanda pumped 2/3 of the amount she pumped on previous day. So Wanda second day = (2/3)*4500 = 3000 gallons. Ms. B pumped 1/3 of the number of gallons she pumped on first day. So Ms. B second day = (1/3)*3375 = 1125 gallons. Total second day = 3000+1125 = 4125 gallons.\n\nTotal pumped over two days = 7875+4125 = 12000 gallons. Tank capacity = 18000, so remaining = 18000-12000 = 6000 gallons.\n\nThus answer: 6000.The tank's capacity is 18,000 gallons. On the first day, Wanda pumped \\(\\frac{1}{4}\\) of the capacity, which is \\(18,000 \\times \\frac{1}{4} = 4,500\\) gallons. Ms. B pumped \\(\\frac{3}{4}\\) of Wanda's amount, so \\(4,500 \\times \\frac{3}{4} = 3,375\\) gallons. Total for the first day: \\(4,500 + 3,375 = 7,875\\) gallons.\n\nOn the second day, Wanda pumped \\(\\frac{2}{3}\\) of her first-day amount: \\(4,500 \\times \\frac{2}{3} = 3,000\\) gallons. Ms. B pumped \\(\\frac{1}{3}\\) of her first-day amount: \\(3,375 \\times \\frac{1}{3} = 1,125\\) gallons. Total for the second day: \\(3,000 + 1,125 = 4,125\\) gallons.\n\nOverall, the total water pumped is \\(7,875 + 4,125 = 12,000\\) gallons. The remaining capacity is \\(18,000 - 12,000 = 6,000\\) gallons.\n\n\\boxed{6000}", "cost_usd": 0.00016617999999999998, "tokens_in": 157, "tokens_out": 515, "latency_s": 23.595}, {"task_id": "gsm8k-1028", "model": "deepseek/deepseek-v4-flash", "prompt": "Tom buys a bedroom set for $3000.  He sells his old bedroom for $1000 and uses that to pay for part of the bedroom set.  He then has to pay 10% a month for the bedroom set.  How much does he have to pay per month?\n\nReason step by step, then give the final answer as a single number.", "response": "Tom buys a bedroom set for $3000. He sells his old bedroom set for $1000, which he uses as a partial payment, so the remaining amount owed is $3000 - $1000 = $2000. He then has to pay 10% a month for the bedroom set, meaning he pays 10% of the remaining balance each month. Therefore, the monthly payment is 10% of $2000, which is $200.\n\n200", "cost_usd": 0.001210824, "tokens_in": 78, "tokens_out": 4479, "latency_s": 50.804}, {"task_id": "lcb-abc391_a", "model": "google/gemini-3.6-flash", "prompt": "You are given a string D representing one of the eight directions (north, east, west, south, northeast, northwest, southeast, southwest). The correspondence between the directions and their representing strings is as follows.\n\n- North: N\n- East: E\n- West: W\n- South: S\n- Northeast: NE\n- Northwest: NW\n- Southeast: SE\n- Southwest: SW\n\nPrint the string representing the direction opposite to the direction denoted by D.\n\nInput\n\nThe input is given from Standard Input in the following format:\nD\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- D is one of N, E, W, S, NE, NW, SE, SW.\n\nSample Input 1\n\nN\n\nSample Output 1\n\nS\r\n\nPrint S, which represents south, the direction opposite to north.\n\nSample Input 2\n\nSE\n\nSample Output 2\n\nNW\r\n\nPrint NW, which represents northwest, the direction opposite to southeast.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n    d = sys.stdin.read().strip()\n    opposite = {\n        'N': 'S',\n        'S': 'N',\n        'E': 'W',\n        'W': 'E',\n        'NE': 'SW',\n        'SW': 'NE',\n        'NW': 'SE',\n        'SE': 'NW'\n    }\n    print(opposite[d])\n\nif __name__ == '__main__':\n    main()", "cost_usd": 0.0011895, "tokens_in": 238, "tokens_out": 111, "latency_s": 1.152}, {"task_id": "lcb-abc399_c", "model": "openai/gpt-5.6-luna", "prompt": "You are given a simple undirected graph with N vertices and M edges, where the vertices are labeled 1 to N. The i-th edge connects vertices u_i and v_i.\r\nWhat is the minimum number of edges that need to be deleted from this graph so that the graph becomes a forest?\n\nWhat is a forest?\r\n\r\nA simple undirected graph F is called a forest if and only if F does not contain any cycle.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\r\nu_1 v_1\r\nu_2 v_2\r\n\\vdots\r\nu_M v_M\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 0 \\leq M \\leq \\min \\left( \\frac{N(N-1)}{2}, 2 \\times 10^5\\right)\n- 1 \\leq u_i < v_i \\leq N\n- The given graph is simple.\n- All input values are integers.\n\nSample Input 1\n\n4 4\r\n1 2\r\n1 3\r\n2 4\r\n3 4\n\nSample Output 1\n\n1\r\n\nFor example, if you delete the first edge, the graph becomes a forest.\n\nSample Input 2\n\n5 0\n\nSample Output 2\n\n0\n\nSample Input 3\n\n10 10\r\n7 9\r\n4 6\r\n6 10\r\n2 5\r\n5 6\r\n5 9\r\n6 8\r\n4 8\r\n1 5\r\n1 4\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    if not data:\n        return\n\n    n, m = data[0], data[1]\n    parent = list(range(n + 1))\n    size = [1] * (n + 1)\n\n    def find(x):\n        while parent[x] != x:\n            parent[x] = parent[parent[x]]\n            x = parent[x]\n        return x\n\n    deleted = 0\n    idx = 2\n\n    for _ in range(m):\n        u, v = data[idx], data[idx + 1]\n        idx += 2\n\n        ru, rv = find(u), find(v)\n        if ru == rv:\n            deleted += 1\n        else:\n            if size[ru] < size[rv]:\n                ru, rv = rv, ru\n            parent[rv] = ru\n            size[ru] += size[rv]\n\n    print(deleted)\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.00020479999999999977, "tokens_in": 380, "tokens_out": 278, "latency_s": 2.273}]