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+ {"schema": 2, "epoch": 87861, "nonce": "67d77e32275222ec", "hotkey": "5FRE1kqMJz8ddModcXUsCquuWhB8QHnjYib2iK2VfiFetkC5", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "2e4d6a88063177a0a7a564f24e10b347ef48e87c9595a209162369a4fa4d4477", "model_id": "router", "total_cost_usd": 0.0012126840000000001, "n_calls": 6, "call_log_hash": "ad38234ac01204118eb1ff34024cad78117fc49f2a52b551de1533c9e0014cf1", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 249.111, "tokens_in": 1056, "tokens_out": 4384, "results": [{"benchmark": "mmlu", "task_id": "mmlu-1143", "answer": "B", "cost_usd": 9.813e-05, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.999879, 7e-05, 0.0, 0.0, 3.9e-05, 1.2e-05, 0.0]}, {"benchmark": "mmlu", "task_id": "mmlu-361", "answer": "D", "cost_usd": 0.00013659000000000002, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.998469, 0.000207, 0.0, 0.0, 0.001324, 1e-06, 0.0]}, {"benchmark": "math", "task_id": "gsm8k-157", "answer": "Blake runs back and forth 15 times on a 100-yard field, so each round trip is 200 yards, totaling \\(15 \\times 200 = 3000\\) yards.\n\nKelly runs back and forth once, which is 200 yards, then runs to the 40-yard line and back 34 times. Each trip to the 40-yard line and back is \\(40 \\times 2 = 80\\) yards, totaling \\(34 \\times 80 = 2720\\) yards. Her total distance is \\(200 + 2720 = 2920\\) yards.\n\nBlake runs farther by \\(3000 - 2920 = 80\\) yards.\n\n\\boxed{80}", "cost_usd": 0.000535346, "chosen_rung": 1, "rungs_used": [1], "distribution": [0.000435, 0.996899, 0.0, 0.0, 0.000153, 0.002512, 0.0]}, {"benchmark": "math", "task_id": "gsm8k-704", "answer": "Gerald's initial share from the $100 in the ratio 3:2 is \\( \\frac{3}{5} \\times 100 = 60 \\) dollars. After spending $10, he has \\( 60 - 10 = 50 \\) dollars left.\n\n\\boxed{50}", "cost_usd": 3.421800000000003e-05, "chosen_rung": 1, "rungs_used": [1], "distribution": [9.4e-05, 0.999881, 0.0, 0.0, 1.7e-05, 7e-06, 0.0]}, {"benchmark": "code", "task_id": "lcb-abc392_a", "answer": "import sys\nfrom itertools import permutations\n\na = list(map(int, sys.stdin.read().split()))\n\nfor b1, b2, b3 in permutations(a):\n if b1 * b2 == b3:\n print(\"Yes\")\n break\nelse:\n print(\"No\")", "cost_usd": 6.550000000000002e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [5.8e-05, 0.000207, 0.0, 0.0, 0.997718, 0.002017, 0.0]}, {"benchmark": "code", "task_id": "lcb-arc195_a", "answer": "import sys\n\ndef main():\n data = list(map(int, sys.stdin.buffer.read().split()))\n n, m = data[0], data[1]\n a = data[2:2 + n]\n b = data[2 + n:2 + n + m]\n\n earliest = [-1] * m\n j = 0\n for i, x in enumerate(a):\n if j < m and x == b[j]:\n earliest[j] = i\n j += 1\n\n if j < m:\n print(\"No\")\n return\n\n latest = [-1] * m\n j = m - 1\n for i in range(n - 1, -1, -1):\n if j >= 0 and a[i] == b[j]:\n latest[j] = i\n j -= 1\n\n print(\"Yes\" if earliest != latest else \"No\")\n\nif __name__ == \"__main__\":\n main()\n", "cost_usd": 0.00034290000000000004, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.000333, 6.9e-05, 0.0, 0.0, 0.996113, 0.003485, 0.0]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "4019e91a22ef3cbb99e1874d061ee8c32a2e8e996eb93570e83cbf8fca15bec6", "platform_sig": 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