Buckets:
| from numpy import * | |
| def solver(I, a, T, dt, theta): | |
| """Solve u'=-a*u, u(0)=I, for t in (0,T] with steps of dt.""" | |
| Nt = int(T/dt) # no of time intervals | |
| T = Nt*dt # adjust T to fit time step dt | |
| u = zeros(Nt+1) # array of u[n] values | |
| t = linspace(0, T, Nt+1) # time mesh | |
| u[0] = I # assign initial condition | |
| for n in range(0, Nt): # n=0,1,...,Nt-1 | |
| u[n+1] = (1 - (1-theta)*a*dt)/(1 + theta*dt*a)*u[n] | |
| return u, t | |
| u, t = solver(I=1, a=2, T=8, dt=0.8, theta=1) | |
| # Write out a table of t and u values: | |
| for i in range(len(t)): | |
| print 't=%6.3f u=%g' % (t[i], u[i]) | |
| # or print 't={t:6.3f} u={u:g}'.format(t=t[i], u=u[i]) | |
| # Plot the solution only | |
| from matplotlib.pyplot import plot | |
| plot(t, u) | |
| show() | |
Xet Storage Details
- Size:
- 798 Bytes
- Xet hash:
- e839424f744bc4ca38b001eebc808aef838a36570c137564643a0de86b87e8ac
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