Update Automated MNLP evaluation report (2026-05-28)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-OAAA/math_model`](https://huggingface.co/cs-552-2026-OAAA/math_model)
 - **Owner(s):** group **OAAA**
-- **Generated at:** 2026-05-27T13:02:22+00:00 (UTC)
+- **Generated at:** 2026-05-28T08:03:33+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -11,7 +11,7 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 
 | Benchmark | Accuracy | Status |
 |---|---:|---|
-| Math | 0.1700 | ok |
+| Math | 0.1500 | ok |
 | Knowledge | — | not run |
 | Multilingual | — | not run |
 | Safety | — | not run |
@@ -24,111 +24,96 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `3`
-- **overall** (8/8 completions correct)
-- **extracted** (✓): `3`
+- **reference**: `70`
+- **overall** (5/8 completions correct)
+- **extracted** (✓): `70`
 - **completion**:
 
     ```text
     <think>
-    Okay, so I need to figure out how many treeks equal one squig. Let me start by writing down the given information.
+    Okay, so I need to figure out the sum of all integer values of the base b greater than 9 for which the base-b number 17 divides the base-b number 97. Hmm, let me start by understanding what the problem is asking.
     
-    First, the problem says that 10 treeks have the same weight as 3 squigs plus 1 goolee. So, mathematically, that would be:
+    First, base-b numbers. In base b, the number 17 would be 1*b + 7, right? And 97 in base b would be 9*b + 7. The problem says that 17 (in base b) divides 97 (in base b). Wait, but
     
-    10 treeks = 3 squigs + 1 goolee
+    ... [truncated 821 chars] ...
     
-    Then, it also says that 2 treeks plus 1 goolee weigh as much as 1 squig. So:
-    
-    2 treeks + 1 goolee = 1 squig
-    
-    And the que
-    
-    ... [truncated 822 chars] ...
-    
-    3 treeks.
-    
-    Therefore, the answer is 3. So, the number of treeks equal to 1 squig is 3. Therefore, \boxed{3}
-    
-    **Final Answer**
-    \boxed{3}
-    </think>
-    
-    To determine how many treeks have a combined weight equal to that of 1 squig, we begin by defining the weights of the three units:
-    
-    - Let $ T $ represent the weight of one treek.
-    - Let $ S $ represent the weight of one squig.
-    - Let $ G $ represent the weight of one goolee.
-    
-    ---
-    
-    ### Step 1: Translate the given information into equations
-    
-    From the problem, we are told:
-    
-    1. **10 treeks weigh as much as 3 squigs plus 1 goolee:**
+    rewrite $ 9b + 7 $ in terms of $ b + 7 $:
     
     $$
-    10T = 3S + G \tag{1}
+    9b + 7 = 9(b + 7) - 56
     $$
     
-    2. **2 treeks and 1 goolee weigh as much as 1 squig:**
+    So the congruence becomes:
     
     $$
-    2T + G = S \tag{2}
+    9(b + 7) - 56 \equiv 0 \pmod{b + 7}
     $$
     
-    ---
-    
-    ### Step 2: Solve the system of equations
-    
-    From equation (2), solve for $ G $:
+    This implies:
     
     $$
-    G = S - 2T \tag{3}
+    -56 \equiv 0 \pmod{b + 7}
     $$
     
-    Now substitute this expression for $ G $ into equation (1):
+    So:
     
     $$
-    10T = 3S + (S - 2T)
+    b + 7 \mid 56
     $$
     
-    Simplify the right-hand side:
+    ---
     
-    $$
-    10T = 4S - 2T
-    $$
+    ### Step 3: Find All Positive Divisors of 56
     
-    Now, add $ 2T $ to both sides:
+    The positive divisors of 56 are:
     
     $$
-    12T = 4S
+    1, 2, 4, 7, 8, 14, 28, 56
     $$
     
-    Divide both sides by 4:
+    We are only interested in divisors of 56 that are **greater than** $ b > 9 $, so $ b + 7 $ must be greater than 16. From the list, the valid divisors are:
     
     $$
-    3T = S
+    28, 56
     $$
     
+    So:
+    
+    - $ b + 7 = 28 \Rightarrow b = 21 $
+    - $ b + 7 = 56 \Rightarrow b = 49 $
+    
     ---
     
-    ### Step 3: Interpret the result
+    ### Step 4: Verify the Values of $ b $
     
-    From the above, we find:
+    We check both values to ensure they satisfy the original condition:
     
-    $$
-    S = 3T
-    $$
+    - For $ b = 21 $:  
+      $$
+      17_{21} = 1 \cdot 21 + 7 = 28,\quad 97_{21} = 9 \cdot 21 + 7 = 196
+      $$
+      $$
+      \frac{196}{28} = 7 \Rightarrow \text{Divisible}
+      $$
+    
+    - For $ b = 49 $:  
+      $$
+      17_{49} = 1 \cdot 49 + 7 = 56,\quad 97_{49} = 9 \cdot 49 + 7 = 448
+      $$
+      $$
+      \frac{448}{56} = 8 \Rightarrow \text{Divisible}
+      $$
     
-    This means that **1 squig weighs as much as 3 treeks**.
+    Both values of $ b $ satisfy the condition.
     
     ---
     
-    ### Final Answer
+    ### Step 5: Compute the Final Answer
+    
+    The valid values of $ b $ are $ 21 $ and $ 49 $, so their sum is:
     
     $$
-    \boxed{3}
+    21 + 49 = \boxed{70}
     $$
     ```
 
@@ -143,33 +128,29 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
     <think>
     Okay, so I need to find the measure of angle BAC in this figure where there's a square and a regular heptagon sharing the side AD. Let me try to visualize the Asymptote figure first. 
     
-    From the Asymptote code, it seems that there are seven lines drawn from the unit circle, each separated by 360/7 degrees, which is approximately 51.43 degrees. Then, points A, B, C, D are defined with specif
+    From the Asymptote code, it seems that there's a regular heptagon and a square sharing the side AD. The square is probably attached to the heptagon along side AD. The points are labeled A, B, C, D, and other
     
     ... [truncated 823 chars] ...
     
-    that, maybe I need to find coordinates of points A, B, C, and then compute angle BAC. 
-    
-    So perhaps I need to compute coordinates of points A, B, C, then compute the angle. 
-    
-    Given that, let me proceed. 
+    h is the length of vector AF. Since AF is (2 sin(180°/7), 0), the length is 2 sin(180°/7). Therefore, adding (0,1) times that vector, which is (0, 2 sin(180°/7)), to point A. Therefore, coordinates of C are:
     
-    First, let me note that point A is at angle theta_A = 360*3/7 + 90 degrees. 
+    C_x = A_x + 0 = -sin(180°/7)
     
-    Similarly, point B is at 360*2/7 + 90 degrees. 
+    C_y = A_y + 2 sin(180°/7) = -cos(180°/7) + 2 sin(180°/7)
     
-    Let me compute coordinates of points A, B, C, D. 
+    Similarly, D is C + F - A. Let's compute F - A:
     
-    First, let me convert all angles to radians for calculation, but maybe I can use exact expressions. 
+    F - A = [sin(180°/7) - (-sin(180°/7)), -cos(180°/7) - (-cos(180°/7))] = [2 sin(180°/7), 0], same as before.
     
-    Alternatively, use complex numbers. Let me denote points as complex numbers on the unit circle. 
+    So, D = C + [2 sin(180°/7), 0] = [ -sin(180°/7) + 2 sin(180°/7), -cos(180°/7) + 2 sin(180°/7) ] = [ sin(180°/7), -cos(180°/7) + 2 sin(180°/7) ]
     
-    Let me denote A as a complex number: A = e^{i(theta_A)}, where theta_A = 360*3/7 + 90° = (3*360 + 630)/7 = (1080 + 630)/7 = 1710/7 degrees? Wait, no. Wait, theta_A is 360*3/7 + 90 degrees. 
+    So, coordinates of D are (sin(180°/7), -cos(180°/7) + 2 sin(180°/7)).
     
-    Wait, 360*3/7 is 1080/7 ≈ 154.2857°, then adding 90° gives 244.2857°, which is 244°17'. 
+    Now, point B is dir(360*2/7 + 90°). Let me compute that angle: 360*2/7 + 90 = 720/7 + 630/7 = 1350/7 ≈ 192.857°, which is the third vertex of the heptagon. So, point B is at angle 192.857°, which is 90° + 2*(360/7) = same as the third vertex.
     
-    Similarly, theta_F is 360*4/7 + 90° = 1440/7 + 90° = 205.714° + 90° = 295.714°, which is 295°43'. 
+    Therefore, coordinates of B: (cos(192.857°), sin(192.857°)).
     
-    But maybe working with exact expressions is difficult. Alternatively, use complex numbers with angles in radians. 
+    Similarly, cos(192.857°) = cos(90° + 102.857°) = -sin(102.857°). Wait, 192.857° is 90° + 102.857°, and 102.857° is 360/7* (something). Let me check:
     
-    Alternatively, note that the regular heptagon has central angles of 360/7 degrees. So the angle between adjacent vertices
+    102.857° is approximately 360/7 * 2.857... Wait, 360/7 ≈ 51.428°, so 2.85
     ```