Update Automated MNLP evaluation report (2026-05-03)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-taadmin/general_knowledge_model`](https://huggingface.co/cs-552-2026-taadmin/general_knowledge_model)
 - **Owner(s):** group **taadmin**
-- **Generated at:** 2026-05-03T01:50:19+00:00 (UTC)
+- **Generated at:** 2026-05-03T02:10:11+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -16,4 +16,107 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 | Multilingual | `pass@1` | — | — | not run |
 | Safety | `pass@1` | — | — | not run |
 
+## Per-source breakdown
+
+### Knowledge
+
+| Source | Metric | Accuracy | # problems |
+|---|---|---:|---:|
+| `Idavidrein/gpqa/gpqa_diamond` | `pass@1` | 0.1500 | 20 |
+
 ## Sample completions
+
+### Knowledge
+
+**Correct** (2 shown)
+
+- **prompt** (truncated): `Suppose a spin-half particle is prepared in the state \(0.5|\uparrow\rangle+\frac{\sqrt{3}}{2}|\downarrow\rangle\). Given that \(|\uparrow\rangle\) and \(|\downarrow\rangle\) are eigenstates of \(\sigma_z\), determine the expectation value, rounded to one decimal place, of \(10\sigma_z+5\sigma_x\). Here, the symbols have their usual meanings.
+
+Choices:
+A. 1.65
+B. -0.7
+C. 0.85
+D. -1.4`
+- **reference**: `B`
+- **extracted answers** (1/1 correct, ✓):
+  - `B`
+- **raw completions**:
+  - completion 1:
+    ```text
+    <think>
+    Okay, so I need to find the expectation value of the operator $10\sigma_z + 5\sigma_x$ for a spin-half particle in the state $0.5|\uparrow\rangle + \frac{\sqrt{3}}{2}|\downarrow\rangle$. Let me start by recalling some basic concepts about quantum mechanics and spin operators.
+    
+    First, the Pauli matrices $\sigma_z$ and $\sigma_x$ are the matrices for the spin operators in the z and x directions, respectively. For a spin-1/2 particle, the eigenstates of $\sigma_z$ are $|\uparrow\rangle$ and $|\downarrow\rangle$, which are the basis states. The expectation value of an operator is calculated by taking the inner product of the state with the operator multiplied by the state, right?
+    
+    So, th...
+    ```
+
+- **prompt** (truncated): `Which one of the following statements regarding the molecular biology of Severe Acute Respiratory Syndrome Coronavirus 2 (SARS‑CoV‑2) is not correct?
+
+Choices:
+A. Programmed ribosomal frameshifting creates two polyproteins near to 5` end of the genome by moving back by 1 nucleotide with the help of slippery nucleotides, and pseudoknot. The SARS-CoV-2 programmed ribosomal frameshifting mostly has t...`
+- **reference**: `C`
+- **extracted answers** (1/1 correct, ✓):
+  - `C`
+- **raw completions**:
+  - completion 1:
+    ```text
+    <think>
+    Okay, let's tackle this question. So, the task is to find which statement about the molecular biology of SARS-CoV-2 is not correct. The options are A, B, C, D. Let me go through each one step by step.
+    
+    Starting with option A: It talks about programmed ribosomal frameshifting in SARS-CoV-2. The statement says that it creates two polyproteins near the 5' end by moving back by 1 nucleotide with slippery nucleotides and pseudoknots. Also, it mentions that the SARS-CoV-2 frameshifting is similar to SARS-CoV. I remember that both SARS-CoV and SARS-CoV-2 use similar mechanisms for frameshifting, like the -1 frameshift signals. So this seems correct. So A might be correct.
+    
+    Option B: It says...
+    ```
+
+**Incorrect** (2 shown)
+
+- **prompt** (truncated): `An unknown organic compound has been synthesized, and its 1H NMR spectrum gave the following data:
+1H NMR: chemical reference (ppm): 7.0 (1H, d, J = 16.0 Hz), 5.5 (1H, dq), 2.1 (3H, s), 1.6 (3H, d)
+Determine which of the following compounds it is: Cis-propenyl acetate, Trans-propenyl acetate, Cis-butenyl acetate, or Trans-butenyl acetate.
+
+Choices:
+A. Cis-propenyl acetate
+B. Cis-butenyl acetate
+C....`
+- **reference**: `D`
+- **extracted answers** (0/1 correct, ✗):
+  - `<no answer>`
+- **raw completions**:
+  - completion 1:
+    ```text
+    <think>
+    Okay, let's try to figure out which compound this is. The NMR data given is for an unknown organic compound with the following peaks:
+    
+    - 7.0 (1H, d, J=16.0 Hz)
+    - 5.5 (1H, dq)
+    - 2.1 (3H, s)
+    - 1.6 (3H, d)
+    
+    First, I need to recall what each of these NMR peaks represents. The 2.1 ppm peak is a singlet at 2.1, which is probably a methyl group (since it's a singlet and the rest of the molecule is probably not splitting it). The 1.6 ppm peak is a doublet, but wait, the third peak is 1.6 (3H, d). Wait, the 1.6 is a doublet? Wait, no. Wait, the data is:
+    
+    Wait, the user wrote:
+    
+    "1H NMR: chemical reference (ppm): 7.0 (1H, d, J = 16.0 Hz), 5.5 (1H, dq), 2.1 (3H, s), 1.6 (3H, d)"
+    
+    So the peaks ar...
+    ```
+
+- **prompt** (truncated): `Which of the following starting material(s) would be used to prepare methyl 2-propyl-1,2,4a,5,6,7,8,8a-octahydronaphthalene-1-carboxylate?
+
+Choices:
+A. methyl (2E,4E,10Z)-tetradeca-2,4,10-trienoate
+B. methyl (2E,8E,10E)-tetradeca-2,8,10-trienoate
+C. Cyclohexene and methyl 2,3-dimethylenehexanoate
+D. 1-vinylcyclohex-1-ene and methyl hex-2-ynoate`
+- **reference**: `B`
+- **extracted answers** (0/1 correct, ✗):
+  - `<no answer>`
+- **raw completions**:
+  - completion 1:
+    ```text
+    <think>
+    Okay, let's try to figure out which starting material is used to prepare methyl 2-propyl-1,2,4a,5,6,7,8,8a-octahydronaphthalene-1-carboxylate. Hmm, first, I need to understand the structure of the compound in question. 
+    
+    The name given is methyl 2-propyl-1,2,4a,5,6,7,8,8a-octahydronaphthalene-1-carboxylate. Let me break that down. The parent ring is naphthalene, which has two fused benzene rings. The numbering is 1,2,4a,5,6,7,8,8a. So, the structure is a naphthalene ring with eight hydrogen atoms, but here it's substituted with certain groups. The carboxylate group is at position 1, and there are methyl and propyl groups on positions 2 and 3. Wait, the name mentions "2-propyl" so may...
+    ```