Update Automated MNLP evaluation report (2026-05-27)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-baseline/math_model`](https://huggingface.co/cs-552-2026-baseline/math_model)
 - **Owner(s):** group **baseline**
-- **Generated at:** 2026-05-24T16:13:44+00:00 (UTC)
+- **Generated at:** 2026-05-27T13:02:22+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -11,7 +11,7 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 
 | Benchmark | Accuracy | Status |
 |---|---:|---|
-| Math | 0.1500 | ok |
+| Math | 0.1600 | ok |
 | Knowledge | — | not run |
 | Multilingual | — | not run |
 | Safety | — | not run |
@@ -24,99 +24,95 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `70`
-- **overall** (5/8 completions correct)
-- **extracted** (✓): `70`
+- **reference**: `4`
+- **overall** (8/8 completions correct)
+- **extracted** (✓): `4`
 - **completion**:
 
     ```text
     <think>
-    Okay, so I need to figure out the sum of all integer values of the base b greater than 9 for which the base-b number 17 divides the base-b number 97. Hmm, let me start by understanding what the problem is asking.
+    Okay, so I need to solve the equation 10^x minus 10 equals 9990. Let me write that down first: 10^x - 10 = 9990. Hmm, let me think about how to approach this. 
     
-    First, base-b numbers. In base b, the number 17 would be equal to 1*b + 7, right? And the number 97 in base b would be 9*b + 7. The problem says that 17 divides 97 in base b. So,
+    First, maybe I should isolate the term with the exponent. That means I need to get 10^x by itself on one side of the equation. So, if I add 10 to both sides, that should cancel out the -10 on the left. Let me try that:
+    
+    10^x - 10 +
     
     ... [truncated 823 chars] ...
     
-    n \mathbb{Z}
-    $$
+    t the original problem is written as 10^x − 10 = 9990. The way it's written, it's 10^x minus 10, not 10^(x - 10). So unless there's some parentheses I'm missing, but the standard order of operations would make it 10^x - 10. 
     
-    ---
+    So, yeah, I think that's correct. 
+    
+    Another thought: sometimes when dealing with exponents, people might confuse the order of operations. But in this case, since there's no parentheses, it's definitely 10^x minus 10. 
     
-    ### Step 2: Simplify the division
+    So, conclusion: x = 4. 
     
-    We perform the division:
+    **Final Answer**
+    The solution is \boxed{4}.
+    </think>
+    
+    To solve the equation:
     
     $$
-    \frac{9b + 7}{b + 7} = 9 - \frac{56}{b + 7}
+    10^x - 10 = 9990
     $$
     
-    This shows that for the expression to be an integer, $ \frac{56}{b + 7} $ must also be an integer. Therefore, $ b + 7 $ must be a **divisor** of 56.
-    
     ---
     
-    ### Step 3: Find all divisors of 56 greater than 16
-    
-    We factorize 56:
+    ### Step 1: Isolate the Exponential Term
     
-    $$
-    56 = 2^3 \cdot 7
-    $$
-    
-    The positive divisors of 56 are:
+    We start by isolating the term with the exponent $10^x$:
     
     $$
-    1, 2, 4, 7, 8, 14, 28, 56
+    10^x - 10 = 9990
     $$
     
-    We are only interested in those divisors **greater than 16**, so we take:
+    Add 10 to both sides:
     
     $$
-    28, 56
+    10^x = 9990 + 10 = 10000
     $$
     
-    Now, compute $ b $ from $ b + 7 = d $:
+    ---
     
-    - If $ b + 7 = 28 \Rightarrow b = 21 $
-    - If $ b + 7 = 56 \Rightarrow b = 49 $
+    ### Step 2: Solve for $x$
     
-    ---
+    Now, we need to find the value of $x$ such that:
     
-    ### Step 4: Verify the results
+    $$
+    10^x = 10000
+    $$
     
-    Check if both bases satisfy the original condition:
+    We recognize that:
     
-    - For $ b = 21 $:  
-      $$
-      17_{21} = 1 \cdot 21 + 7 = 28,\quad 97_{21} = 9 \cdot 21 + 7 = 196
-      $$
-      $$
-      196 \div 28 = 7 \quad \text{(integer)}
-      $$
+    $$
+    10^4 = 10000
+    $$
     
-    - For $ b = 49 $:  
-      $$
-      17_{49} = 1 \cdot 49 + 7 = 56,\quad 97_{49} = 9 \cdot 49 + 7 = 448
-      $$
-      $$
-      448 \div 56 = 8 \quad \text{(integer)}
-      $$
+    So, the exponent $x$ must be:
     
-    Both values of $ b $ are valid and greater than 9.
+    $$
+    x = 4
+    $$
     
     ---
     
-    ### Final Step: Compute the sum
+    ### Step 3: Verify the Solution
+    
+    Substitute $x = 4$ back into the original equation:
     
     $$
-    21 + 49 = 70
+    10^4 - 10 = 10000 - 10 = 9990
     $$
     
+    This matches the right-hand side of the equation, confirming that the solution is correct.
+    
     ---
     
     ### Final Answer
     
     $$
-    \boxed{70}
+    \boxed{4}
     $$
     ```
 
@@ -129,23 +125,37 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
     ```text
     <think>
-    Okay, so I need to find the measure of angle BAC in this figure where there's a square and a regular heptagon sharing the side AD. Let me try to visualize the Asymptote figure first. The Asymptote code draws a regular heptagon and a square. The square shares the side AD with the heptagon. Points A, B, C, D are labeled, with A at the bottom, B on the left, C at the southeast, and D at the b
+    Okay, so I need to find the measure of angle BAC in this figure where there's a square and a regular heptagon sharing the side AD. Let me try to visualize the Asymptote figure first. 
+    
+    From the Asymptote code, it seems that there's a regular heptagon and a square sharing the side AD. The square is probably attached to the heptagon along side AD. The points are labeled A, B, C, D, and other
+    
+    ... [truncated 823 chars] ...
+    
+    le 360/7°. Therefore, coordinates of B are (-sin(360/7°), -cos(360/7°)).
+    
+    Wait, because cos(180° + α) = -cos(α), sin(180° + α) = -sin(α). So, if α = 360/7°, then coordinates are (-cos(α), -sin(α)).
+    
+    So, coordinates of B: (-cos(360/7°), -sin(360/7°)).
+    
+    So, now we have coordinates for points A, B, C.
+    
+    Point A: (-sin(3θ), cos(4θ)) where θ = 360/7°.
     
-    ... [truncated 822 chars] ...
+    Point B: (-cos(α), -sin(α)) where α = 360/7°.
     
-    as C + F - A. Let me check that.
+    Point C: (-sin(3θ), cos(4θ)).
     
-    D is defined as C + (F - A). So if C is (x_A, y_F), then F - A is (x_F - x_A, y_F - y_A). Then adding that to C gives (x_A + (x_F - x_A), y_F + (y_F - y_A)) = (x_F, y_F + y_F - y_A) = (x_F, 2y_F - y_A). So coordinates of D are (x_F, 2y_F - y_A). Then the square is A-C-D-F. So from A to C to D to F and back to A? So A is (x_A, y_A), C is (x_A, y_F), D is (x_F, 2y_F - y_A), and F is (x_F, y_F). So connecting A to C to D to F to A. Let me check if this is a square.
+    Wait, hold on. Wait, point C is at (-sin(3θ), cos(4θ)), and point A is at (-sin(3θ), cos(4θ))? Wait, no. Wait, earlier I said point C is at (-sin(3θ), cos(4θ)), but point A is at (-sin(3θ), cos(3θ))? Wait, no. Wait, let me check again.
     
-    For it to be a square, all sides must be equal and adjacent sides must be perpendicular. Let's check the lengths.
+    Earlier, coordinates of A: (-sin(3θ), cos(3θ)) where θ = 360/7°, right? Because angle of A is 90° + 3θ, which is 90° + 3*(360/7°). Then, coordinates of A are (cos(90° + 3θ), sin(90° + 3θ)) which is (-sin(3θ), cos(3θ)).
     
-    Length AC: distance between A and C. Since C is (x_A, y_F) and A is (x_A, y_A), so AC is vertical line, length |y_F - y_A|.
+    Similarly, coordinates of point C: (-sin(3θ), cos(4θ)).
     
-    Length CD: distance between C (x_A, y_F) and D (x_F, 2y_F - y_A). So sqrt[(x_F - x_A)^2 + (2y_F - y_A - y_F)^2] = sqrt[(x_F - x_A)^2 + (y_F - y_A)^2].
+    So, point A and point C have the same x-coordinate: -sin(3θ), but different y-coordinates: cos(3θ) and cos(4θ). 
     
-    Length DF: distance between D (x_F, 2y_F - y_A) and F (x_F, y_F). That's sqrt[(x_F - x_F)^2 + (y_F - (2y_F - y_A))^2] = sqrt[0 + (-y_F + y_A)^2] = |y_A - y_F|.
+    Point B is at (-cos(α), -sin(α)) where α = 360/7°.
     
-    Length FA: distance between F (x_F, y_F) and A (x_A, y_A): sqrt[(x_F - x_A)^2 + (y_F - y_A)^2].
+    So, to find angle BAC, which is the angle at point A between points B, A, and C.
     
-    So for it to be a square, AC = CD = DF = FA. So
+    So, angle B
     ```