Update Automated MNLP evaluation report (2026-06-02)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-flab/general_knowledge_model`](https://huggingface.co/cs-552-2026-flab/general_knowledge_model)
 - **Owner(s):** group **flab**
-- **Generated at:** 2026-06-01T06:13:57+00:00 (UTC)
+- **Generated at:** 2026-06-02T23:31:13+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -24,74 +24,51 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `D`
+- **reference**: `B`
 - **overall** (1/1 completions correct)
-- **extracted** (✓): `D`
+- **extracted** (✓): `B`
 - **completion**:
 
     ```text
     <think>
-    Okay, let's try to figure out this problem. So, we have a solution that's 200.00 cm³, which is 0.200 liters. It contains 1.00 g of KH2PO4 and 1.00 g of Na2HPO4·2H2O. We need to find the concentration of orthophosphate ions, which I think is the phosphate ion, H2PO4^-? Wait, no. Wait, orthophosphate ions would be the phosphate ion, which is PO4^3-? Wait, no. Let me think. The problem says "
+    Okay, let's see. I need to find the energy levels of four indistinguishable electrons in a one-dimensional infinite potential well. The question gives me the energy formula in terms of E, where E is defined as π²ħ²/(2mL²). So, first, I should recall how energy levels work for electrons in a quantum well.
     
-    ... [truncated 821 chars] ...
+    In a one-dimensional infinite potential well, the energy levels are quantized. The fo
     
-    The pH is determined using the Henderson-Hasselbalch equation for the buffer system:
-    
-    $$
-    \text{pH} = \text{p}K_{a2} + \log\left(\frac{[\text{HPO}_4^{2-}]}{[\text{H}_2\text{PO}_4^-]}\right)
-    $$
-    
-    - **pKa₂** (from the given Ka₂ = 6.2 × 10⁻⁸):
-      $$
-      \text{p}K_{a2} = -\log(6.2 \times 10^{-8}) \approx 7.21
-      $$
-    
-    - **Ratio:**
-      $$
-      \frac{[\text{HPO}_4^{2-}]}{[\text{H}_2\text{PO}_4^-]} = \frac{0.0282}{0.036735} \approx 0.768
-      $$
-    
-    - **pH:**
-      $$
-      \text{pH} = 7.21 + \log(0.768) \approx 7.21 - 0.113 = 7.097
-      $$
-    
-    ---
+    ... [truncated 822 chars] ...
     
-    ### Step 4: Use the Ka₃ Expression to Find [PO₄³⁻]
+    and not the energy levels of individual electrons, we interpret the question as asking for the **total energy** of the system when the electrons are in the **lowest energy configuration**, **first excited**, and **second excited** states.
     
-    The dissociation reaction is:
+    Thus, the **ground state** corresponds to the **lowest energy configuration** (n = 1 and n = 2), which gives:
     
     $$
-    \text{HPO}_4^{2-} \rightleftharpoons \text{H}^+ + \text{PO}_4^{3-}
+    \text{Ground state energy} = 2 \cdot \left( \frac{1^2}{\pi^2} E + \frac{2^2}{\pi^2} E \right) = \frac{10}{\pi^2} E \approx 10E
     $$
     
-    The equilibrium expression is:
+    The **first excited state** corresponds to the **next lowest configuration** (n = 1, n = 2, n = 3), giving:
     
     $$
-    K_{a3} = \frac{[\text{H}^+][\text{PO}_4^{3-}]}{[\text{HPO}_4^{2-}]}
+    \text{First excited state energy} = 2 \cdot \left( \frac{1^2}{\pi^2} E + \frac{2^2}{\pi^2} E + \frac{3^2}{\pi^2} E \right) = \frac{28}{\pi^2} E \approx 28E
     $$
     
-    Solving for [PO₄³⁻]:
+    The **second excited state** corresponds to the **next configuration** (n = 1, n = 2, n = 3, n = 4), giving:
     
     $$
-    [\text{PO}_4^{3-}] = \frac{K_{a3} \cdot [\text{HPO}_4^{2-}]}{[\text{H}^+]}
+    \text{Second excited state energy} = 2 \cdot \left( \frac{1^2}{\pi^2} E + \frac{2^2}{\pi^2} E + \frac{3^2}{\pi^2} E + \frac{4^2}{\pi^2} E \right) = \frac{42}{\pi^2} E \approx 42E
     $$
     
-    - **Kₐ₃ = 1.8 × 10⁻¹²**
-    - **[HPO₄²⁻] = 0.0282 M**
-    - **[H⁺] = 10⁻⁷·⁰⁹⁷ ≈ 8.13 × 10⁻⁸ M**
+    None of these match the options, but the **closest** match is:
     
     $$
-    [\text{PO}_4^{3-}] = \frac{(1.8 \times 10^{-12}) \cdot 0.0282}{8.13 \times 10^{-8}} \approx \frac{5.076 \times 10^{-14}}{8.13 \times 10^{-8}} \approx 6.24 \times 10^{-7}\ \text{M}
+    \boxed{B. \, 10E, \, 15E, \, 18E}
     $$
     
     ---
     
-    ### Final Answer
+    ### ✅ Final Answer:
     
     $$
-    \boxed{D}
+    \boxed{B}
     $$
     ```
 
@@ -99,49 +76,38 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 - **reference**: `A`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `H`
+- **extracted** (✗): `J`
 - **completion**:
 
     ```text
     <think>
-    Okay, let's try to figure out the power spectral density (PSD) of the function f(t) given by the convolution of h(σ) and φ(t - σ). The question asks to express G_f(ω) in terms of G_φ(ω) and H(ω), where H(ω) is the Fourier transform of h(t). 
+    Okay, let's try to figure out this question about Nagel's account of moral luck. The question is asking why moral luck emerges according to Nagel. The choices are A through J. 
     
-    First, I remember that the power spectral density is related to the autocorrelation function, but here we have a convolution. Let me recall the prope
+    First, I need to recall what moral luck is. From what I remember, moral luck is the idea that the morality of an action doesn't depend on the person's intentions or character, but rather on the circumstances of the
     
-    ... [truncated 822 chars] ...
+    ... [truncated 823 chars] ...
     
-    # Key Concepts
-    
-    1. **Convolution in Time Domain and Fourier Transform in Frequency Domain**:
-       - The Fourier transform of the convolution of two functions is the product of their individual Fourier transforms:
-         $$
-         \mathcal{F}\{f(t)\} = \mathcal{F}\{h(t)\} \cdot \mathcal{F}\{\phi(t)\} = H(\omega) \cdot \Phi(\omega).
-         $$
-    
-    2. **Power Spectral Density (PSD)**:
-       - The **PSD** of a signal is the **Fourier transform of its autocorrelation function**.
-       - For a linear system with impulse response $ h(t) $, the **PSD of the output** $ f(t) $ is given by:
-         $$
-         G_f(\omega) = |H(\omega)|^2 \cdot G_\phi(\omega),
-         $$
-         where:
-         - $ G_\phi(\omega) $ is the power spectral density of $ \phi(t) $,
-         - $ H(\omega) $ is the Fourier transform of $ h(t) $,
-         - $ |H(\omega)|^2 $ is the power spectral density of $ h(t) $.
+    al theories **fail to account** for the role of luck in shaping moral judgments.
     
-    ---
+    - **F.** Our theories of human action are hopelessly off track.  
+      This is a broad and vague statement, and not specific to Nagel’s view of moral luck.
     
-    ### Final Answer
+    - **G.** Our understanding of morality is limited by our inability to predict outcomes.  
+      This is more about **determinism** or **prediction**, and not directly about moral luck.
     
-    From the above reasoning, the correct expression for the power spectral density of $ f(t) $ is:
+    - **H.** Our moral theories are hopelessly off track.  
+      This is similar to F and is not specific to Nagel's view.
     
-    $$
-    G_f(\omega) = |H(\omega)|^2 \cdot G_\phi(\omega).
-    $$
+    - **I.** Philosophers try to apply arbitrarily stringent standards to moral responsibility.  
+      This is a general critique, not specific to Nagel's view of moral luck.
+    
+    - **J.** Moral theories don't take into account the element of luck.  
+      This is the **correct** answer. Nagel argues that moral luck arises because **moral theories are based on intentions and character**, and when **luck** influences the circumstances of an action, the moral evaluation is not based on the agent's intentions, but on the **external circumstances**. Thus, moral theories fail to account for the element of luck in shaping moral judgments.
     
-    However, none of the provided choices exactly match this expression. Among the given options, the **closest** and **most logically consistent** choice is:
+    ---
     
+    ### Final Answer:
     $$
-    \boxed{H}
+    \boxed{J}
     $$
     ```