Update Automated MNLP evaluation report (2026-06-02)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-kth/general_knowledge_model`](https://huggingface.co/cs-552-2026-kth/general_knowledge_model)
 - **Owner(s):** group **kth**
-- **Generated at:** 2026-06-01T06:13:57+00:00 (UTC)
+- **Generated at:** 2026-06-02T23:31:13+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -12,7 +12,7 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 | Benchmark | Accuracy | Status |
 |---|---:|---|
 | Math | — | not run |
-| Knowledge | 0.4100 | ok |
+| Knowledge | 0.2700 | ok |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
@@ -30,16 +30,35 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 - **completion**:
 
     ```text
+    We are given a qPCR calibration curve. The positive control has known copy numbers. The qPCR efficiency is 100%, R2 = 1, slope = -3.3. This means the relationship between Ct and log10 copy number is linear with slope -3.3. So for every 1 cycle increase, the log10 copy number decreases by 3.3. The slope is -3.3, so the log10 copy number = -3.3 * Ct + intercept. Since R2 = 1, the line fits perfectly
+    
+    ... [truncated 823 chars] ...
+    
+    f target nucleic acid. Option B: "Ten-fold dilution is more than 3.3 cycles" - the slope is -3.3, so a ten-fold dilution corresponds to a 3.3 cycle difference. That's not the issue; the inconsistency is in the Ct values, not the dilution factor. Option C: "qPCR cannot be used for the quantification of nucleic acid in samples" - that's too broad and not the reason for the inconsistency. Option D: "The deviation is more than 0.3 between technical replicates" - the technical replicates are consistent within each dilution, so that's not the issue. The inconsistency is between the positive control's Ct values and the calibration curve. So A is the correct answer.
+    
+    Thus, the answer is A.
+    </think>
+    
+    The inconsistencies in the qPCR results arise because the positive control's Ct values do not align with the expected values based on the calibration curve. The calibration curve is derived from the positive control's known copy numbers, and the observed Ct values for the positive control are inconsistent with the slope of -3.3. This indicates that the calibration curve is not accurate, meaning the Ct values for the samples are not in agreement with the amount of target nucleic acid.
+    
     \boxed{A}
     ```
 
 **Incorrect** (1 shown)
 
-- **reference**: `F`
+- **reference**: `C`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `C`
+- **extracted** (✗): `<no answer>`
 - **completion**:
 
     ```text
-    \boxed{C}
+    We are given two compounds A and B. They are treated with sodium nitrite, hydrochloric acid, and water. The products are the two diketones shown: 4-isopropylcyclohexane-1,2-dione and 5-methylhexane-2,3-dione.
+    
+    We need to identify the correct starting materials A and B.
+    
+    The reaction is nitroso addition (nitroso addition to aldehydes/ketones). The product is a diketone. The reaction is: RCHO + NaNO
+    
+    ... [truncated 823 chars] ...
+    
+    an aldehyde/ketone that, when treated with nitroso addition, gives a diketone. The reaction is: RCHO + NaNO2 + HCl + H2O -> RCOO-NO2 + RCOOH + H2O? Actually, the product is a diketone. The reaction is nitroso addition to an aldehyde/ketone. The product is a diketone. So the starting material must be an aldehyde/ketone that, when treated with nitroso addition, gives a diketone. The reaction is: RCHO + NaNO2 + HCl + H2O -> RCOO-NO2 + RCOOH + H2O? Actually, the product is a diketone. The reaction is nitroso addition to an aldehyde/ketone. The product is a diketone. So the starting material must be an aldehyde/ketone that, when treated with nitroso addition, gives a diketone. The reaction is: RCHO + NaNO2 + HCl + H2O -> RCOO-NO2 + RCOOH + H2O? Actually, the product is a diketone. The reaction is nitroso addition to an aldehyde/ketone. The product is a diketone. So the starting material must be an aldehyde/ketone that, when treated with nitroso addition, gives a diketone. The reaction is: RCHO + NaNO2 + HCl + H2O -> RCOO-NO2 + RCOOH + H2O? Actually, the product is a diketone. The reaction is nitroso addition to an aldehyde/ketone. The product is a diketone. So the starting material must
     ```