Update Automated MNLP evaluation report (2026-05-17)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-kth/math_model`](https://huggingface.co/cs-552-2026-kth/math_model)
 - **Owner(s):** group **kth**
-- **Generated at:** 2026-05-16T04:57:46+00:00 (UTC)
+- **Generated at:** 2026-05-17T04:52:19+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -11,17 +11,79 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 
 | Benchmark | Accuracy | Status |
 |---|---:|---|
-| Math | — | error (generation_config) |
+| Math | 0.3100 | ok |
 | Knowledge | — | not run |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
-## Errors
+## Sample completions
 
-### math — `generation_config`
+_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._
 
-```
-generation_config.json not found: 404 Client Error. (Request ID: Root=1-6a07f219-31df42fa24af8d9830de3e10;1281fcc3-f3c3-4f28-8c3d-eaa5f9a55145)
+### Math
 
-Entry Not Found for url: https://huggingface.co/cs-552-2026-kth/math_model/resolve/main/generation_config.json.
-```
+**Correct** (1 shown)
+
+- **reference**: `4`
+- **overall** (8/8 completions correct)
+- **extracted** (✓): `4`
+- **completion**:
+
+    ```text
+    <think>
+    We can rewrite the equation as:
+    \[ 10^x = 10 + 9990 \Rightarrow 10^x = 10000 \Rightarrow 10^x = 10^4 \]
+    
+    Since the bases are the same, we can equate the exponents:
+    \[ x = 4 \]
+    
+    The answer is:
+    \[
+    </think>
+    
+    Therefore, the answer is \boxed{4}.
+    ```
+
+**Incorrect** (1 shown)
+
+- **reference**: `2 - \frac{\pi}{2}`
+- **overall** (0/8 completions correct)
+- **extracted** (✗): `\frac{1}{2}`
+- **completion**:
+
+    ```text
+    <think>
+    Let $P$ be the probability that Derek eventually becomes debt-free. We can derive a recursive equation for $P$.
+    
+    When Derek tosses the coin, there are two possible outcomes:
+    
+    1. Heads: He reduces his debt by 1 MIT. This means his debt becomes $\pi - 1$ MITs.
+    2. Tails: He reduces his debt by 2 MITs. This means his debt becomes $\pi - 2$ MITs.
+    
+    However, if his debt becomes nonpositive, he is
+    
+    ... [truncated 540 chars] ...
+    
+    ly becomes debt-free given a debt of $\pi - 1$ MITs, and $P_{\pi - 2}$ is the probability that Derek eventually becomes debt-free given a debt of $\pi - 2$ MITs.
+    
+    We can continue this process recursively, but we notice a pattern. The recursive equation can be rewritten as:
+    
+    \[ P = \frac{1}{2} \left( P_{\pi - 1} + P_{\pi - 2} \right) \]
+    
+    Using the same logic, we can derive the following recursive equation:
+    
+    \[ P = \frac{1}{2} \left( \frac{1}{2} \left( P_{\pi - 2} + P_{\pi - 3} \right) + \frac{1}{2} \left( P_{\pi - 3} + P_{\pi - 4} \right) \right) \]
+    
+    And so on.
+    
+    Notice that the recursive equation can be simplified to:
+    
+    \[ P = \frac{1}{2} \left( \frac{1}{2} \left( \frac{1}{2} \left( \cdots \right) + \frac{1}{2} \left( \frac{1}{2} \left( \cdots \right) \right) \right) + \frac{1}{2} \left( \frac{1}{2} \left( \cdots \right) + \frac{1}{2} \left( \frac{1}{2} \left( \cdots \right) \right) \right) \right) + \cdots \right) \]
+    
+    This is a geometric series with first term $\frac{1}{2}$ and common ratio $\frac{1}{2}$. The sum of the series is:
+    
+    \[ P = \frac{\frac{1}{2}}{1 - \frac{1}{2}} = \frac{1}{2} \div \frac{1}{2} = \frac{1}{2} \cdot 2 =
+    </think>
+    
+    Therefore, the answer is \boxed{\frac{1}{2}}.
+    ```