Update Automated MNLP evaluation report (2026-05-26)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-mnlplus/general_knowledge_model`](https://huggingface.co/cs-552-2026-mnlplus/general_knowledge_model)
 - **Owner(s):** group **mnlplus**
-- **Generated at:** 2026-05-25T02:20:01+00:00 (UTC)
+- **Generated at:** 2026-05-26T12:29:10+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -12,7 +12,7 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 | Benchmark | Accuracy | Status |
 |---|---:|---|
 | Math | — | not run |
-| Knowledge | 0.2600 | ok |
+| Knowledge | 0.4100 | ok |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
@@ -24,74 +24,37 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `G`
+- **reference**: `I`
 - **overall** (1/1 completions correct)
-- **extracted** (✓): `G`
+- **extracted** (✓): `I`
 - **completion**:
 
     ```text
     <think>
+    To determine the probability of the event $\{M \geq 5\}$, we need to calculate the probability that $S_0 = 0$, $S_1 = 0$, $S_2 = 0$, $S_3 = 0$, $S_4 = 0$, and $S_5 = 0$.
+    We can calculate the probability of each of these events as follows:
+    - $P(S_0 = 0) = 1$
+    - $P(S_1 = 0) = P(S_0 + 1 = 0) + P(S_0 - 1 = 0) = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$
+    - $P(S_2 = 0) = P(S_1 + 1 = 0) + P(S_1 - 1 = 0) = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$
+    - $P(S_3 = 0) = P(S_2 + 1 = 0) + P(S_2 - 1 = 0) = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$
+    - $P(S_4 = 0) = P(S_3 + 1 = 0) + P(S_3 - 1 = 0) = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$
+    - $P(S_5 = 0) = P(S_4 + 1 = 0) + P(S_4 - 1 = 0) = \frac{1}{4} + \frac{1}{4} = \frac{1}{2}$
     </think>
     
-    \boxed{G}
+    \boxed{I}
     ```
 
 **Incorrect** (1 shown)
 
 - **reference**: `B`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `C`
+- **extracted** (✗): `D`
 - **completion**:
 
     ```text
     <think>
-    The user is asking about the volume integral of the divergence of a vector field over the interior of a sphere. The vector field is directed purely along the radial direction, and its magnitude decreases as 1/r². The answer choices are given, and the task is to choose the most appropriate value for the integral.
-    
-    First, I need to recall the divergence theorem, which relates the volume inte
-    
-    ... [truncated 823 chars] ...
-    
-    ield $\vec{f}(r)$ is directed purely along the radial direction, meaning it points outward from the origin, and its magnitude decreases as $f(r) = \frac{1}{r^2}$. In spherical coordinates, this corresponds to a radial vector field.
-    
-    ---
-    
-    ### Step 2: Use the Divergence Theorem
-    
-    The divergence theorem relates the volume integral of the divergence of a vector field to the flux of the field through the surface of the region. It states:
-    
-    $$
-    \iiint_V (\nabla \cdot \vec{f}) \, dV = \iint_S \vec{f} \cdot d\vec{S}
-    $$
-    
-    where $V$ is the region enclosed by the surface $S$.
-    
-    ---
-    
-    ### Step 3: Compute the Divergence
-    
-    For a radial vector field in spherical coordinates, the divergence is:
-    
-    $$
-    \nabla \cdot \vec{f} = \frac{1}{r^2} \frac{d}{dr}(r^2 f(r)) = \frac{1}{r^2} \frac{d}{dr}(r^2 \cdot \frac{1}{r^2}) = \frac{1}{r^2} \frac{d}{dr}(1) = 0
-    $$
-    
-    Thus, the divergence of the vector field is **zero** everywhere except at the origin, where the field is undefined.
-    
-    ---
-    
-    ### Step 4: Evaluate the Volume Integral
-    
-    Since the divergence is zero everywhere, the volume integral of the divergence over any region is also zero:
-    
-    $$
-    \iiint_V (\nabla \cdot \vec{f}) \, dV = 0
-    $$
-    
-    ---
-    
-    ### Final Answer
+    The correct answer is D.
+    </think>
     
-    $$
-    \boxed{C}
-    $$
+    \boxed{D}
     ```