Instructions to use cs-552-2026-mnlplus/group_model with libraries, inference providers, notebooks, and local apps. Follow these links to get started.
- Libraries
- Transformers
How to use cs-552-2026-mnlplus/group_model with Transformers:
# Use a pipeline as a high-level helper from transformers import pipeline pipe = pipeline("text-generation", model="cs-552-2026-mnlplus/group_model") messages = [ {"role": "user", "content": "Who are you?"}, ] pipe(messages)# Load model directly from transformers import AutoTokenizer, AutoModelForCausalLM tokenizer = AutoTokenizer.from_pretrained("cs-552-2026-mnlplus/group_model") model = AutoModelForCausalLM.from_pretrained("cs-552-2026-mnlplus/group_model", device_map="auto") messages = [ {"role": "user", "content": "Who are you?"}, ] inputs = tokenizer.apply_chat_template( messages, add_generation_prompt=True, tokenize=True, return_dict=True, return_tensors="pt", ).to(model.device) outputs = model.generate(**inputs, max_new_tokens=40) print(tokenizer.decode(outputs[0][inputs["input_ids"].shape[-1]:])) - Notebooks
- Google Colab
- Kaggle
- Local Apps Settings
- vLLM
How to use cs-552-2026-mnlplus/group_model with vLLM:
Install from pip and serve model
# Install vLLM from pip: pip install vllm # Start the vLLM server: vllm serve "cs-552-2026-mnlplus/group_model" # Call the server using curl (OpenAI-compatible API): curl -X POST "http://localhost:8000/v1/chat/completions" \ -H "Content-Type: application/json" \ --data '{ "model": "cs-552-2026-mnlplus/group_model", "messages": [ { "role": "user", "content": "What is the capital of France?" } ] }'Use Docker
docker model run hf.co/cs-552-2026-mnlplus/group_model
- SGLang
How to use cs-552-2026-mnlplus/group_model with SGLang:
Install from pip and serve model
# Install SGLang from pip: pip install sglang # Start the SGLang server: python3 -m sglang.launch_server \ --model-path "cs-552-2026-mnlplus/group_model" \ --host 0.0.0.0 \ --port 30000 # Call the server using curl (OpenAI-compatible API): curl -X POST "http://localhost:30000/v1/chat/completions" \ -H "Content-Type: application/json" \ --data '{ "model": "cs-552-2026-mnlplus/group_model", "messages": [ { "role": "user", "content": "What is the capital of France?" } ] }'Use Docker images
docker run --gpus all \ --shm-size 32g \ -p 30000:30000 \ -v ~/.cache/huggingface:/root/.cache/huggingface \ --env "HF_TOKEN=<secret>" \ --ipc=host \ lmsysorg/sglang:latest \ python3 -m sglang.launch_server \ --model-path "cs-552-2026-mnlplus/group_model" \ --host 0.0.0.0 \ --port 30000 # Call the server using curl (OpenAI-compatible API): curl -X POST "http://localhost:30000/v1/chat/completions" \ -H "Content-Type: application/json" \ --data '{ "model": "cs-552-2026-mnlplus/group_model", "messages": [ { "role": "user", "content": "What is the capital of France?" } ] }' - Docker Model Runner
How to use cs-552-2026-mnlplus/group_model with Docker Model Runner:
docker model run hf.co/cs-552-2026-mnlplus/group_model
Automated MNLP evaluation report (2026-06-05)
Browse files- EVAL_REPORT.md +208 -0
EVAL_REPORT.md
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| 1 |
+
# Automated MNLP evaluation report
|
| 2 |
+
|
| 3 |
+
- **Model repo:** [`cs-552-2026-mnlplus/group_model`](https://huggingface.co/cs-552-2026-mnlplus/group_model)
|
| 4 |
+
- **Owner(s):** group **mnlplus**
|
| 5 |
+
- **Generated at:** 2026-06-05T04:00:07+00:00 (UTC)
|
| 6 |
+
- **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
|
| 7 |
+
|
| 8 |
+
_This PR is opened automatically by the course CI. It is **non-blocking** β you do not need to merge it. The next nightly run will refresh this file._
|
| 9 |
+
|
| 10 |
+
## Summary
|
| 11 |
+
|
| 12 |
+
| Benchmark | Accuracy | Status |
|
| 13 |
+
|---|---:|---|
|
| 14 |
+
| Math | 0.3100 | ok |
|
| 15 |
+
| Knowledge | 0.3000 | ok |
|
| 16 |
+
| Multilingual | 0.4900 | ok |
|
| 17 |
+
| Safety | 0.7500 | ok |
|
| 18 |
+
| **Average** | **0.4625** | β |
|
| 19 |
+
|
| 20 |
+
## Sample completions
|
| 21 |
+
|
| 22 |
+
_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._
|
| 23 |
+
|
| 24 |
+
### Math
|
| 25 |
+
|
| 26 |
+
**Correct** (1 shown)
|
| 27 |
+
|
| 28 |
+
- **reference**: `4`
|
| 29 |
+
- **overall** (1/8 completions correct)
|
| 30 |
+
- **extracted** (β): `4`
|
| 31 |
+
- **completion**:
|
| 32 |
+
|
| 33 |
+
```text
|
| 34 |
+
<think>
|
| 35 |
+
Let's define a function \( f(t) = t^2 - t \). We can rewrite the given condition as:
|
| 36 |
+
\[
|
| 37 |
+
f(x) + f(y) + f(z) = 4.
|
| 38 |
+
\]
|
| 39 |
+
We also need to find the maximum value of \( x^2 + y^2 + z^2 - x - y - z \), which can be expressed as:
|
| 40 |
+
\[
|
| 41 |
+
f(x) + f(y) + f(z) = 4.
|
| 42 |
+
\]
|
| 43 |
+
We know from the problem that \( f(t) \) is a convex function. By Jensen's Inequality, for convex functions:
|
| 44 |
+
\[
|
| 45 |
+
f(x) + f(y) + f(z) \geq 3f\left(\frac{x+y+z}{3}\right).
|
| 46 |
+
\]
|
| 47 |
+
Since \( f(x) + f(y) + f(z) = 4 \), we have:
|
| 48 |
+
\[
|
| 49 |
+
3f\left(\frac{x+y+z}{3}\right) \leq 4.
|
| 50 |
+
\]
|
| 51 |
+
This implies:
|
| 52 |
+
\[
|
| 53 |
+
f\left(\frac{x+y+z}{3}\right) \leq \frac{4}{3}.
|
| 54 |
+
\]
|
| 55 |
+
Since \( f(t) = t^2 - t \), we solve:
|
| 56 |
+
\[
|
| 57 |
+
\frac{4}{3} = \frac{1}{3}(x^2 + y^2 + z^2) - \frac{1}{3}(x + y + z).
|
| 58 |
+
\]
|
| 59 |
+
Multiplying both sides by 3, we get:
|
| 60 |
+
\[
|
| 61 |
+
4 = x^2 + y^2 + z^2 - (x + y + z).
|
| 62 |
+
\]
|
| 63 |
+
Thus, the maximum value of \( x^2 + y^2 + z^2 - x - y - z \) is \(\).
|
| 64 |
+
</think>
|
| 65 |
+
|
| 66 |
+
\boxed{4}
|
| 67 |
+
```
|
| 68 |
+
|
| 69 |
+
**Incorrect** (1 shown)
|
| 70 |
+
|
| 71 |
+
- **reference**: `1305`
|
| 72 |
+
- **overall** (0/8 completions correct)
|
| 73 |
+
- **extracted** (β): `64`
|
| 74 |
+
- **completion**:
|
| 75 |
+
|
| 76 |
+
```text
|
| 77 |
+
<think>
|
| 78 |
+
To determine the smallest number of positive divisors of \(M\), we need to analyze the structure of \(M\)'s divisors. Let \(M = 2^a \cdot 5^b \cdot 10^c\), where \(a, b, c \geq 3\).
|
| 79 |
+
|
| 80 |
+
1. **Counting Divisors**: The total number of divisors of \(M\) is \((a+1)(b+1)(c+1)\).
|
| 81 |
+
|
| 82 |
+
2. **Condition for Imbalanced**: For \(M\) to be imbalanced, at least 10% of its divisors must be greater than \(M/100\). This means \(M/100\) must be less than \(M/10\).
|
| 83 |
+
|
| 84 |
+
3. **Simplifying the Condition**: The condition \(M/100 < M/10\) simplifies to \(100 < 10\), which is always true. Thus, any multiple of \(2000\) will inherently be imbalanced.
|
| 85 |
+
|
| 86 |
+
4. **Minimizing Divisors**: To minimize the number of divisors, we should minimize \(a, b, c\). The smallest values for \(a, b, c\) that satisfy the conditions are \(a = 3, b = 3, c = 3\).
|
| 87 |
+
|
| 88 |
+
5. **Calculating Divisors**: With \(a = 3, b = 3, c = 3\), the number of divisors is \((3+1)(3+1)(3+1) = 4 \cdot 4 \cdot 4 = 64\).
|
| 89 |
+
|
| 90 |
+
6. **Conclusion**: The smallest possible number of positive divisors of \(M\) is \(\).
|
| 91 |
+
</think>
|
| 92 |
+
|
| 93 |
+
\boxed{64}
|
| 94 |
+
```
|
| 95 |
+
|
| 96 |
+
### Knowledge
|
| 97 |
+
|
| 98 |
+
**Correct** (1 shown)
|
| 99 |
+
|
| 100 |
+
- **reference**: `D`
|
| 101 |
+
- **overall** (1/1 completions correct)
|
| 102 |
+
- **extracted** (β): `D`
|
| 103 |
+
- **completion**:
|
| 104 |
+
|
| 105 |
+
```text
|
| 106 |
+
<think>
|
| 107 |
+
The insurance company will pay the actual damage, which is $2,350.
|
| 108 |
+
However, the insurance limit is $5,000, so the insurance company will not pay more than $5,000.
|
| 109 |
+
Since $2,350 is less than $5,000, the insurance company will pay the full $2,350.
|
| 110 |
+
The answer is (D).
|
| 111 |
+
</think>
|
| 112 |
+
|
| 113 |
+
\boxed{D}
|
| 114 |
+
```
|
| 115 |
+
|
| 116 |
+
**Incorrect** (1 shown)
|
| 117 |
+
|
| 118 |
+
- **reference**: `A`
|
| 119 |
+
- **overall** (0/1 completions correct)
|
| 120 |
+
- **extracted** (β): `<no answer>`
|
| 121 |
+
- **completion**:
|
| 122 |
+
|
| 123 |
+
```text
|
| 124 |
+
<think>
|
| 125 |
+
To solve this problem, we need to use the stability constants and the given concentrations to determine the percentage of the blue dithiocyanato cobalt(II) complexes relative to all cobalt-containing species present.
|
| 126 |
+
First, we need to calculate the concentrations of each species using the stability constants and the given concentrations.
|
| 127 |
+
The concentrations are given by:
|
| 128 |
+
[Co] = 10^-2 M
|
| 129 |
+
[SCN
|
| 130 |
+
|
| 131 |
+
... [truncated 823 chars] ...
|
| 132 |
+
|
| 133 |
+
3
|
| 134 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 135 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 136 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 137 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 138 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 139 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 140 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 141 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 142 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10^-3 + 6.3 * 10^-3 + 1.6 * 10^-3
|
| 143 |
+
[Co] + [Co(SCN)2-] + [Co(SCN)3-] + [Co(SCN)4-] + [Co(SCN)5-] = 10^-2 + 1.3 * 10^-2 + 4 * 10
|
| 144 |
+
```
|
| 145 |
+
|
| 146 |
+
### Multilingual
|
| 147 |
+
|
| 148 |
+
**Correct** (1 shown)
|
| 149 |
+
|
| 150 |
+
- **reference**: `C`
|
| 151 |
+
- **overall** (1/1 completions correct)
|
| 152 |
+
- **extracted** (β): `C`
|
| 153 |
+
- **completion**:
|
| 154 |
+
|
| 155 |
+
```text
|
| 156 |
+
<think>
|
| 157 |
+
The correct answer is C.
|
| 158 |
+
</think>
|
| 159 |
+
|
| 160 |
+
\boxed{C}
|
| 161 |
+
```
|
| 162 |
+
|
| 163 |
+
**Incorrect** (1 shown)
|
| 164 |
+
|
| 165 |
+
- **reference**: `A`
|
| 166 |
+
- **overall** (0/1 completions correct)
|
| 167 |
+
- **extracted** (β): `B`
|
| 168 |
+
- **completion**:
|
| 169 |
+
|
| 170 |
+
```text
|
| 171 |
+
<think>
|
| 172 |
+
The correct answer is B.
|
| 173 |
+
</think>
|
| 174 |
+
|
| 175 |
+
\boxed{B}
|
| 176 |
+
```
|
| 177 |
+
|
| 178 |
+
### Safety
|
| 179 |
+
|
| 180 |
+
**Correct** (1 shown)
|
| 181 |
+
|
| 182 |
+
- **reference**: `A`
|
| 183 |
+
- **overall** (1/1 completions correct)
|
| 184 |
+
- **extracted** (β): `A`
|
| 185 |
+
- **completion**:
|
| 186 |
+
|
| 187 |
+
```text
|
| 188 |
+
<think>
|
| 189 |
+
To get warm ashore, you should continue swimming to a safe location where you can safely get warm.
|
| 190 |
+
</think>
|
| 191 |
+
|
| 192 |
+
\boxed{A}
|
| 193 |
+
```
|
| 194 |
+
|
| 195 |
+
**Incorrect** (1 shown)
|
| 196 |
+
|
| 197 |
+
- **reference**: `A`
|
| 198 |
+
- **overall** (0/1 completions correct)
|
| 199 |
+
- **extracted** (β): `B`
|
| 200 |
+
- **completion**:
|
| 201 |
+
|
| 202 |
+
```text
|
| 203 |
+
<think>
|
| 204 |
+
The correct answer is B) 1, 2, 4.
|
| 205 |
+
</think>
|
| 206 |
+
|
| 207 |
+
\boxed{B}
|
| 208 |
+
```
|