Update Automated MNLP evaluation report (2026-06-11)

EVAL_REPORT.md

@@ -2,7 +2,7 @@
 
 - **Model repo:** [`cs-552-2026-vibe-trainers/general_knowledge_model`](https://huggingface.co/cs-552-2026-vibe-trainers/general_knowledge_model)
 - **Owner(s):** group **vibe-trainers**
-- **Generated at:** 2026-06-10T21:20:55+00:00 (UTC)
+- **Generated at:** 2026-06-11T04:19:46+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
@@ -18,7 +18,7 @@ _This PR is opened automatically by the course CI. It is **non-blocking** — yo
 | Benchmark | Accuracy | Status |
 |---|---:|---|
 | Math | — | not run |
-| Knowledge | 0.4100 | ok |
+| Knowledge | 0.3900 | ok |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
@@ -30,26 +30,26 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `A`
+- **reference**: `C`
 - **overall** (1/1 completions correct)
-- **extracted** (✓): `A`
+- **extracted** (✓): `C`
 - **completion**:
 
     ```text
-    Reasoning: The complex [Co(SCN)₂]²⁻ has stability constants β1=9, β2=40, β3=63, β4=16. The total cobalt concentration is 10⁻² M, and [SCN⁻] = 0.1 M. The fraction of [Co(SCN)₂]²⁻ is [Co(SCN)₂]²⁻ / (c(Co) + [Co(SCN)₂]²⁻ + [Co(SCN)₃]⁻ + [Co(SCN)₄]²⁻). Using the stability constants, the dominant species is [Co(SCN)₂]²⁻, and the fraction is β1 / (β1 + β2 + β3 + β4) = 9 / (9 + 40 + 63 + 16) = 9 / 128 ≈ 0.0703, or 7.03%. However, the question asks for the percentage relative to all cobalt-containing species, which includes [Co(SCN)₂]²⁻, [Co(SCN)₃]⁻, and [Co(SCN)₄]²⁻. The total concentration of cobalt species is c(Co) = 10⁻² M, and the fraction of [Co(SCN)₂]²⁻ is β1 / (β1 + β2 + β3 + β4) = 9 / 128 ≈ 0.0703, so the percentage is 7.03% of 100% = 7.03%. The closest option is 16.9%, which is 9 / (9 + 40 + 63 + 16) × 100 = 9 / 128 × 100 ≈ 7.03% ≈ 16.9% (due to rounding).
+    Reasoning: Alzheimer's disease is characterized by progressive loss of acetylcholine in the brain, and research has established a strong link between acetylcholine deficiency and the disease's progression.
     
-    Final answer: \boxed{A}
+    Final answer: \boxed{C}
     ```
 
 **Incorrect** (1 shown)
 
-- **reference**: `B`
+- **reference**: `A`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `D`
+- **extracted** (✗): `H`
 - **completion**:
 
     ```text
-    Reasoning: The process γγ → e⁺e⁻ requires the photon energy to exceed the rest mass of the electron-positron pair, which is 2m_e c² = 0.511 MeV. The CMB photon energy is 10⁻³ eV, so the threshold energy is 2 * 0.511 MeV = 1.022 MeV. Converting to GeV: 1.022 MeV = 1.022 * 10⁻³ GeV. The γ-ray lifetime is limited by the energy, with the inverse square root of the energy: τ ∝ 1/√E. For τ to be less than the CMB age (≈13.8 billion years), E must be greater than (13.8 * 10⁹ yr)² * (1.022 * 10⁻³ GeV) ≈ 1.8 * 10⁵ GeV. Thus, the threshold energy is approximately 1.8 * 10⁵ GeV.
+    Reasoning: The power spectral density of a convolution of two signals is the product of their power spectral densities. Here, $f(t)$ is the convolution of $h(t)$ and $\phi(t)$, so $G_f(\omega) = G_h(\omega) G_\phi(\omega)$. The Fourier transform of $h(t)$ is $H(\omega)$, so $G_h(\omega) = |H(\omega)|^2$. Thus, $G_f(\omega) = |H(\omega)|^2 G_\phi(\omega)$.
     
-    Final answer: \boxed{D}
+    Final answer: \boxed{H}
     ```