# adapted from ai2d/utils.py import re from lmms_eval.filters.extraction import ExtendedRegexFilter def illusionvqa_doc_to_text(doc, lmms_eval_specific_kwargs=None): question, choices = doc["question"], doc["options"] len_choices = len(choices) post_prompt = lmms_eval_specific_kwargs["post_prompt"] pre_prompt = lmms_eval_specific_kwargs["pre_prompt"] options = [chr(ord("A") + i) for i in range(len_choices)] choices_str = "\n".join([f"{option}. {choice}" for option, choice in zip(options, choices)]) return f"{pre_prompt}{question}\n{choices_str}{post_prompt}" def illusionvqa_doc_to_target(doc): len_choices = len(doc["options"]) options = [chr(ord("A") + i) for i in range(len_choices)] return options[doc["options"].index(doc["answer"])] class MultiChoiceRegexFilter(ExtendedRegexFilter): def __init__(self, *args, **kwargs): """ regex_pattern: The basic regex pattern to use. If fails to match, we will use the customized match procedure - step 1 : We parse the choices between ([A-Z])s then try to find these choices in the response. - step 2 : We parse the choice with regex :[\s]*([A-?]), where ? varies by number of choices. group_select: Selects the (group_select)th match from the findall result. ignore_case: Ignores the case during step 1 matching ignore_punctuation: Remove the punctuation during step 1 matching regexes_to_ignore: Remove these regexes during step 1 matching """ super().__init__(*args, **kwargs) def apply(self, resps, docs): # here, we assume we have a list, in which each element is # a list of model responses for some particular input/target pair. # so we process each of these (same input/target response sets) # independently (and keep them a list.) filtered_resps = [] for r, doc in zip(resps, docs): # Regex to directly extract the option letter from the model response option_letter_regex = re.compile(r"^\s*([A-Z])\.") # Process each response filtered = [] for resp in r: # Try to match the option letter at the start of the response match = option_letter_regex.match(resp) if match: # If a match is found, append the matched letter filtered.append(match.group(1)) else: # If no match, return the original response filtered.append(resp) # Assuming we need the first response that matches or the original response filtered_resps.append(filtered[0]) return filtered_resps