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| """ | |
| Algorithms for computing the skeleton of a binary image | |
| """ | |
| import numpy as np | |
| from scipy import ndimage as ndi | |
| from .._shared.utils import check_nD | |
| from ..util import crop | |
| from ._skeletonize_lee_cy import _compute_thin_image | |
| from ._skeletonize_various_cy import ( | |
| _fast_skeletonize, | |
| _skeletonize_loop, | |
| _table_lookup_index, | |
| ) | |
| def skeletonize(image, *, method=None): | |
| """Compute the skeleton of the input image via thinning. | |
| Parameters | |
| ---------- | |
| image : (M, N[, P]) ndarray of bool or int | |
| The image containing the objects to be skeletonized. Each connected component | |
| in the image is reduced to a single-pixel wide skeleton. The image is binarized | |
| prior to thinning; thus, adjacent objects of different intensities are | |
| considered as one. Zero or ``False`` values represent the background, nonzero | |
| or ``True`` values -- foreground. | |
| method : {'zhang', 'lee'}, optional | |
| Which algorithm to use. Zhang's algorithm [Zha84]_ only works for | |
| 2D images, and is the default for 2D. Lee's algorithm [Lee94]_ | |
| works for 2D or 3D images and is the default for 3D. | |
| Returns | |
| ------- | |
| skeleton : (M, N[, P]) ndarray of bool | |
| The thinned image. | |
| See Also | |
| -------- | |
| medial_axis | |
| References | |
| ---------- | |
| .. [Lee94] T.-C. Lee, R.L. Kashyap and C.-N. Chu, Building skeleton models | |
| via 3-D medial surface/axis thinning algorithms. | |
| Computer Vision, Graphics, and Image Processing, 56(6):462-478, 1994. | |
| .. [Zha84] A fast parallel algorithm for thinning digital patterns, | |
| T. Y. Zhang and C. Y. Suen, Communications of the ACM, | |
| March 1984, Volume 27, Number 3. | |
| Examples | |
| -------- | |
| >>> X, Y = np.ogrid[0:9, 0:9] | |
| >>> ellipse = (1./3 * (X - 4)**2 + (Y - 4)**2 < 3**2).astype(bool) | |
| >>> ellipse.view(np.uint8) | |
| array([[0, 0, 0, 1, 1, 1, 0, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 0, 1, 1, 1, 0, 0, 0]], dtype=uint8) | |
| >>> skel = skeletonize(ellipse) | |
| >>> skel.view(np.uint8) | |
| array([[0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0]], dtype=uint8) | |
| """ | |
| image = image.astype(bool, order="C", copy=False) | |
| if method not in {'zhang', 'lee', None}: | |
| raise ValueError( | |
| f'skeletonize method should be either "lee" or "zhang", ' f'got {method}.' | |
| ) | |
| if image.ndim == 2 and (method is None or method == 'zhang'): | |
| skeleton = _skeletonize_zhang(image) | |
| elif image.ndim == 3 and method == 'zhang': | |
| raise ValueError('skeletonize method "zhang" only works for 2D ' 'images.') | |
| elif image.ndim == 3 or (image.ndim == 2 and method == 'lee'): | |
| skeleton = _skeletonize_lee(image) | |
| else: | |
| raise ValueError( | |
| f'skeletonize requires a 2D or 3D image as input, ' f'got {image.ndim}D.' | |
| ) | |
| return skeleton | |
| def _skeletonize_zhang(image): | |
| """Return the skeleton of a 2D binary image. | |
| Thinning is used to reduce each connected component in a binary image | |
| to a single-pixel wide skeleton. | |
| Parameters | |
| ---------- | |
| image : numpy.ndarray | |
| An image containing the objects to be skeletonized. Zeros or ``False`` | |
| represent background, nonzero values or ``True`` are foreground. | |
| Returns | |
| ------- | |
| skeleton : ndarray | |
| A matrix containing the thinned image. | |
| See Also | |
| -------- | |
| medial_axis, skeletonize, thin | |
| Notes | |
| ----- | |
| The algorithm [Zha84]_ works by making successive passes of the image, | |
| removing pixels on object borders. This continues until no | |
| more pixels can be removed. The image is correlated with a | |
| mask that assigns each pixel a number in the range [0...255] | |
| corresponding to each possible pattern of its 8 neighboring | |
| pixels. A look up table is then used to assign the pixels a | |
| value of 0, 1, 2 or 3, which are selectively removed during | |
| the iterations. | |
| Note that this algorithm will give different results than a | |
| medial axis transform, which is also often referred to as | |
| "skeletonization". | |
| References | |
| ---------- | |
| .. [Zha84] A fast parallel algorithm for thinning digital patterns, | |
| T. Y. Zhang and C. Y. Suen, Communications of the ACM, | |
| March 1984, Volume 27, Number 3. | |
| Examples | |
| -------- | |
| >>> X, Y = np.ogrid[0:9, 0:9] | |
| >>> ellipse = (1./3 * (X - 4)**2 + (Y - 4)**2 < 3**2).astype(bool) | |
| >>> ellipse.view(np.uint8) | |
| array([[0, 0, 0, 1, 1, 1, 0, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 1, 1, 0, 0], | |
| [0, 0, 0, 1, 1, 1, 0, 0, 0]], dtype=uint8) | |
| >>> skel = skeletonize(ellipse) | |
| >>> skel.view(np.uint8) | |
| array([[0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0, 0, 0]], dtype=uint8) | |
| """ | |
| if image.ndim != 2: | |
| raise ValueError("Zhang's skeletonize method requires a 2D array") | |
| return _fast_skeletonize(image) | |
| # --------- Skeletonization and thinning based on Guo and Hall 1989 --------- | |
| def _generate_thin_luts(): | |
| """generate LUTs for thinning algorithm (for reference)""" | |
| def nabe(n): | |
| return np.array([n >> i & 1 for i in range(0, 9)]).astype(bool) | |
| def G1(n): | |
| s = 0 | |
| bits = nabe(n) | |
| for i in (0, 2, 4, 6): | |
| if not (bits[i]) and (bits[i + 1] or bits[(i + 2) % 8]): | |
| s += 1 | |
| return s == 1 | |
| g1_lut = np.array([G1(n) for n in range(256)]) | |
| def G2(n): | |
| n1, n2 = 0, 0 | |
| bits = nabe(n) | |
| for k in (1, 3, 5, 7): | |
| if bits[k] or bits[k - 1]: | |
| n1 += 1 | |
| if bits[k] or bits[(k + 1) % 8]: | |
| n2 += 1 | |
| return min(n1, n2) in [2, 3] | |
| g2_lut = np.array([G2(n) for n in range(256)]) | |
| g12_lut = g1_lut & g2_lut | |
| def G3(n): | |
| bits = nabe(n) | |
| return not ((bits[1] or bits[2] or not (bits[7])) and bits[0]) | |
| def G3p(n): | |
| bits = nabe(n) | |
| return not ((bits[5] or bits[6] or not (bits[3])) and bits[4]) | |
| g3_lut = np.array([G3(n) for n in range(256)]) | |
| g3p_lut = np.array([G3p(n) for n in range(256)]) | |
| g123_lut = g12_lut & g3_lut | |
| g123p_lut = g12_lut & g3p_lut | |
| return g123_lut, g123p_lut | |
| # fmt: off | |
| G123_LUT = np.array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, | |
| 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, | |
| 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, | |
| 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, | |
| 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, | |
| 0, 1, 1, 0, 0, 1, 0, 0, 0], dtype=bool) | |
| G123P_LUT = np.array([0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, | |
| 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, | |
| 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, | |
| 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | |
| 0, 0, 0, 0, 0, 0, 0, 0, 0], dtype=bool) | |
| # fmt: on | |
| def thin(image, max_num_iter=None): | |
| """ | |
| Perform morphological thinning of a binary image. | |
| Parameters | |
| ---------- | |
| image : binary (M, N) ndarray | |
| The image to thin. If this input isn't already a binary image, | |
| it gets converted into one: In this case, zero values are considered | |
| background (False), nonzero values are considered foreground (True). | |
| max_num_iter : int, number of iterations, optional | |
| Regardless of the value of this parameter, the thinned image | |
| is returned immediately if an iteration produces no change. | |
| If this parameter is specified it thus sets an upper bound on | |
| the number of iterations performed. | |
| Returns | |
| ------- | |
| out : ndarray of bool | |
| Thinned image. | |
| See Also | |
| -------- | |
| skeletonize, medial_axis | |
| Notes | |
| ----- | |
| This algorithm [1]_ works by making multiple passes over the image, | |
| removing pixels matching a set of criteria designed to thin | |
| connected regions while preserving eight-connected components and | |
| 2 x 2 squares [2]_. In each of the two sub-iterations the algorithm | |
| correlates the intermediate skeleton image with a neighborhood mask, | |
| then looks up each neighborhood in a lookup table indicating whether | |
| the central pixel should be deleted in that sub-iteration. | |
| References | |
| ---------- | |
| .. [1] Z. Guo and R. W. Hall, "Parallel thinning with | |
| two-subiteration algorithms," Comm. ACM, vol. 32, no. 3, | |
| pp. 359-373, 1989. :DOI:`10.1145/62065.62074` | |
| .. [2] Lam, L., Seong-Whan Lee, and Ching Y. Suen, "Thinning | |
| Methodologies-A Comprehensive Survey," IEEE Transactions on | |
| Pattern Analysis and Machine Intelligence, Vol 14, No. 9, | |
| p. 879, 1992. :DOI:`10.1109/34.161346` | |
| Examples | |
| -------- | |
| >>> square = np.zeros((7, 7), dtype=bool) | |
| >>> square[1:-1, 2:-2] = 1 | |
| >>> square[0, 1] = 1 | |
| >>> square.view(np.uint8) | |
| array([[0, 1, 0, 0, 0, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0]], dtype=uint8) | |
| >>> skel = thin(square) | |
| >>> skel.view(np.uint8) | |
| array([[0, 1, 0, 0, 0, 0, 0], | |
| [0, 0, 1, 0, 0, 0, 0], | |
| [0, 0, 0, 1, 0, 0, 0], | |
| [0, 0, 0, 1, 0, 0, 0], | |
| [0, 0, 0, 1, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0]], dtype=uint8) | |
| """ | |
| # check that image is 2d | |
| check_nD(image, 2) | |
| # convert image to uint8 with values in {0, 1} | |
| skel = np.asanyarray(image, dtype=bool).copy().view(np.uint8) | |
| # neighborhood mask | |
| mask = np.array([[8, 4, 2], [16, 0, 1], [32, 64, 128]], dtype=np.uint8) | |
| # iterate until convergence, up to the iteration limit | |
| max_num_iter = max_num_iter or np.inf | |
| num_iter = 0 | |
| n_pts_old, n_pts_new = np.inf, np.sum(skel) | |
| while n_pts_old != n_pts_new and num_iter < max_num_iter: | |
| n_pts_old = n_pts_new | |
| # perform the two "subiterations" described in the paper | |
| for lut in [G123_LUT, G123P_LUT]: | |
| # correlate image with neighborhood mask | |
| N = ndi.correlate(skel, mask, mode='constant') | |
| # take deletion decision from this subiteration's LUT | |
| D = np.take(lut, N) | |
| # perform deletion | |
| skel[D] = 0 | |
| n_pts_new = np.sum(skel) # count points after thinning | |
| num_iter += 1 | |
| return skel.astype(bool) | |
| # --------- Skeletonization by medial axis transform -------- | |
| _eight_connect = ndi.generate_binary_structure(2, 2) | |
| def medial_axis(image, mask=None, return_distance=False, *, rng=None): | |
| """Compute the medial axis transform of a binary image. | |
| Parameters | |
| ---------- | |
| image : binary ndarray, shape (M, N) | |
| The image of the shape to skeletonize. If this input isn't already a | |
| binary image, it gets converted into one: In this case, zero values are | |
| considered background (False), nonzero values are considered | |
| foreground (True). | |
| mask : binary ndarray, shape (M, N), optional | |
| If a mask is given, only those elements in `image` with a true | |
| value in `mask` are used for computing the medial axis. | |
| return_distance : bool, optional | |
| If true, the distance transform is returned as well as the skeleton. | |
| rng : {`numpy.random.Generator`, int}, optional | |
| Pseudo-random number generator. | |
| By default, a PCG64 generator is used (see :func:`numpy.random.default_rng`). | |
| If `rng` is an int, it is used to seed the generator. | |
| The PRNG determines the order in which pixels are processed for | |
| tiebreaking. | |
| .. versionadded:: 0.19 | |
| Returns | |
| ------- | |
| out : ndarray of bools | |
| Medial axis transform of the image | |
| dist : ndarray of ints, optional | |
| Distance transform of the image (only returned if `return_distance` | |
| is True) | |
| See Also | |
| -------- | |
| skeletonize, thin | |
| Notes | |
| ----- | |
| This algorithm computes the medial axis transform of an image | |
| as the ridges of its distance transform. | |
| The different steps of the algorithm are as follows | |
| * A lookup table is used, that assigns 0 or 1 to each configuration of | |
| the 3x3 binary square, whether the central pixel should be removed | |
| or kept. We want a point to be removed if it has more than one neighbor | |
| and if removing it does not change the number of connected components. | |
| * The distance transform to the background is computed, as well as | |
| the cornerness of the pixel. | |
| * The foreground (value of 1) points are ordered by | |
| the distance transform, then the cornerness. | |
| * A cython function is called to reduce the image to its skeleton. It | |
| processes pixels in the order determined at the previous step, and | |
| removes or maintains a pixel according to the lookup table. Because | |
| of the ordering, it is possible to process all pixels in only one | |
| pass. | |
| Examples | |
| -------- | |
| >>> square = np.zeros((7, 7), dtype=bool) | |
| >>> square[1:-1, 2:-2] = 1 | |
| >>> square.view(np.uint8) | |
| array([[0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 1, 1, 1, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0]], dtype=uint8) | |
| >>> medial_axis(square).view(np.uint8) | |
| array([[0, 0, 0, 0, 0, 0, 0], | |
| [0, 0, 1, 0, 1, 0, 0], | |
| [0, 0, 0, 1, 0, 0, 0], | |
| [0, 0, 0, 1, 0, 0, 0], | |
| [0, 0, 0, 1, 0, 0, 0], | |
| [0, 0, 1, 0, 1, 0, 0], | |
| [0, 0, 0, 0, 0, 0, 0]], dtype=uint8) | |
| """ | |
| global _eight_connect | |
| if mask is None: | |
| masked_image = image.astype(bool) | |
| else: | |
| masked_image = image.astype(bool).copy() | |
| masked_image[~mask] = False | |
| # | |
| # Build lookup table - three conditions | |
| # 1. Keep only positive pixels (center_is_foreground array). | |
| # AND | |
| # 2. Keep if removing the pixel results in a different connectivity | |
| # (if the number of connected components is different with and | |
| # without the central pixel) | |
| # OR | |
| # 3. Keep if # pixels in neighborhood is 2 or less | |
| # Note that table is independent of image | |
| center_is_foreground = (np.arange(512) & 2**4).astype(bool) | |
| table = ( | |
| center_is_foreground # condition 1. | |
| & ( | |
| np.array( | |
| [ | |
| ndi.label(_pattern_of(index), _eight_connect)[1] | |
| != ndi.label(_pattern_of(index & ~(2**4)), _eight_connect)[1] | |
| for index in range(512) | |
| ] | |
| ) # condition 2 | |
| | np.array([np.sum(_pattern_of(index)) < 3 for index in range(512)]) | |
| ) | |
| # condition 3 | |
| ) | |
| # Build distance transform | |
| distance = ndi.distance_transform_edt(masked_image) | |
| if return_distance: | |
| store_distance = distance.copy() | |
| # Corners | |
| # The processing order along the edge is critical to the shape of the | |
| # resulting skeleton: if you process a corner first, that corner will | |
| # be eroded and the skeleton will miss the arm from that corner. Pixels | |
| # with fewer neighbors are more "cornery" and should be processed last. | |
| # We use a cornerness_table lookup table where the score of a | |
| # configuration is the number of background (0-value) pixels in the | |
| # 3x3 neighborhood | |
| cornerness_table = np.array( | |
| [9 - np.sum(_pattern_of(index)) for index in range(512)] | |
| ) | |
| corner_score = _table_lookup(masked_image, cornerness_table) | |
| # Define arrays for inner loop | |
| i, j = np.mgrid[0 : image.shape[0], 0 : image.shape[1]] | |
| result = masked_image.copy() | |
| distance = distance[result] | |
| i = np.ascontiguousarray(i[result], dtype=np.intp) | |
| j = np.ascontiguousarray(j[result], dtype=np.intp) | |
| result = np.ascontiguousarray(result, np.uint8) | |
| # Determine the order in which pixels are processed. | |
| # We use a random # for tiebreaking. Assign each pixel in the image a | |
| # predictable, random # so that masking doesn't affect arbitrary choices | |
| # of skeletons | |
| # | |
| generator = np.random.default_rng(rng) | |
| tiebreaker = generator.permutation(np.arange(masked_image.sum())) | |
| order = np.lexsort((tiebreaker, corner_score[masked_image], distance)) | |
| order = np.ascontiguousarray(order, dtype=np.int32) | |
| table = np.ascontiguousarray(table, dtype=np.uint8) | |
| # Remove pixels not belonging to the medial axis | |
| _skeletonize_loop(result, i, j, order, table) | |
| result = result.astype(bool) | |
| if mask is not None: | |
| result[~mask] = image[~mask] | |
| if return_distance: | |
| return result, store_distance | |
| else: | |
| return result | |
| def _pattern_of(index): | |
| """ | |
| Return the pattern represented by an index value | |
| Byte decomposition of index | |
| """ | |
| return np.array( | |
| [ | |
| [index & 2**0, index & 2**1, index & 2**2], | |
| [index & 2**3, index & 2**4, index & 2**5], | |
| [index & 2**6, index & 2**7, index & 2**8], | |
| ], | |
| bool, | |
| ) | |
| def _table_lookup(image, table): | |
| """ | |
| Perform a morphological transform on an image, directed by its | |
| neighbors | |
| Parameters | |
| ---------- | |
| image : ndarray | |
| A binary image | |
| table : ndarray | |
| A 512-element table giving the transform of each pixel given | |
| the values of that pixel and its 8-connected neighbors. | |
| Returns | |
| ------- | |
| result : ndarray of same shape as `image` | |
| Transformed image | |
| Notes | |
| ----- | |
| The pixels are numbered like this:: | |
| 0 1 2 | |
| 3 4 5 | |
| 6 7 8 | |
| The index at a pixel is the sum of 2**<pixel-number> for pixels | |
| that evaluate to true. | |
| """ | |
| # | |
| # We accumulate into the indexer to get the index into the table | |
| # at each point in the image | |
| # | |
| if image.shape[0] < 3 or image.shape[1] < 3: | |
| image = image.astype(bool) | |
| indexer = np.zeros(image.shape, int) | |
| indexer[1:, 1:] += image[:-1, :-1] * 2**0 | |
| indexer[1:, :] += image[:-1, :] * 2**1 | |
| indexer[1:, :-1] += image[:-1, 1:] * 2**2 | |
| indexer[:, 1:] += image[:, :-1] * 2**3 | |
| indexer[:, :] += image[:, :] * 2**4 | |
| indexer[:, :-1] += image[:, 1:] * 2**5 | |
| indexer[:-1, 1:] += image[1:, :-1] * 2**6 | |
| indexer[:-1, :] += image[1:, :] * 2**7 | |
| indexer[:-1, :-1] += image[1:, 1:] * 2**8 | |
| else: | |
| indexer = _table_lookup_index(np.ascontiguousarray(image, np.uint8)) | |
| image = table[indexer] | |
| return image | |
| def _skeletonize_lee(image): | |
| """Compute the skeleton of a binary image. | |
| Thinning is used to reduce each connected component in a binary image | |
| to a single-pixel wide skeleton. | |
| Parameters | |
| ---------- | |
| image : ndarray, 2D or 3D | |
| An image containing the objects to be skeletonized. Zeros or ``False`` | |
| represent background, nonzero values or ``True`` are foreground. | |
| Returns | |
| ------- | |
| skeleton : ndarray of bool | |
| The thinned image. | |
| See Also | |
| -------- | |
| skeletonize, medial_axis | |
| Notes | |
| ----- | |
| The method of [Lee94]_ uses an octree data structure to examine a 3x3x3 | |
| neighborhood of a pixel. The algorithm proceeds by iteratively sweeping | |
| over the image, and removing pixels at each iteration until the image | |
| stops changing. Each iteration consists of two steps: first, a list of | |
| candidates for removal is assembled; then pixels from this list are | |
| rechecked sequentially, to better preserve connectivity of the image. | |
| The algorithm this function implements is different from the algorithms | |
| used by either `skeletonize` or `medial_axis`, thus for 2D images the | |
| results produced by this function are generally different. | |
| References | |
| ---------- | |
| .. [Lee94] T.-C. Lee, R.L. Kashyap and C.-N. Chu, Building skeleton models | |
| via 3-D medial surface/axis thinning algorithms. | |
| Computer Vision, Graphics, and Image Processing, 56(6):462-478, 1994. | |
| """ | |
| # make sure the image is 3D or 2D | |
| if image.ndim < 2 or image.ndim > 3: | |
| raise ValueError( | |
| "skeletonize can only handle 2D or 3D images; " | |
| f"got image.ndim = {image.ndim} instead." | |
| ) | |
| image_o = image.astype(bool, order="C", copy=False) | |
| # make a 2D input image 3D and pad it w/ zeros to simplify dealing w/ boundaries | |
| # NB: careful here to not clobber the original *and* minimize copying | |
| if image.ndim == 2: | |
| image_o = image_o[np.newaxis, ...] | |
| image_o = np.pad(image_o, pad_width=1, mode='constant') # copies | |
| # do the computation | |
| image_o = _compute_thin_image(image_o) | |
| # crop it back and restore the original intensity range | |
| image_o = crop(image_o, crop_width=1) | |
| if image.ndim == 2: | |
| image_o = image_o[0] | |
| return image_o | |