message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n = int(input())
t = [int(i) for i in input()]
ch = 0
sm = 0
for i in range(n-1):
if t[i] == t[i+1]:
sm+=1
else:
ch+=1
print(ch + min(sm,2) + 1)
``` | instruction | 0 | 69,427 | 0 | 138,854 |
Yes | output | 1 | 69,427 | 0 | 138,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n=int(input())
s=input()
c=[]
cnt=1
for i in range(1,n):
if s[i]==s[i-1]:
cnt+=1
else:
c.append(cnt)
cnt=1
c.append(cnt)
ans=len(c)
y=len(c)-c.count(1)
if y>=2:
ans+=2
elif y==1:
if max(c)>=3:
ans+=2
else:
ans+=1
print(ans)
``` | instruction | 0 | 69,428 | 0 | 138,856 |
Yes | output | 1 | 69,428 | 0 | 138,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n = int(input())
s = input()
cnt = 1
last = s[0]
for i in range(1, len(s)):
if s[i] != last:
cnt += 1
last = s[i]
if s.count('111') or s.count('000') or s.count('00')+s.count('11') > 1:
print(cnt+2)
elif s.count('11')+s.count('00'):
print(cnt+1)
else:
print(cnt)
``` | instruction | 0 | 69,429 | 0 | 138,858 |
Yes | output | 1 | 69,429 | 0 | 138,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n = int(input())
ch = str(input())
if n == 1:
print(1)
else:
B = [0 for _ in range(n)]
B[0] = 1
c = ch[0]
for k in range(1,n):
if ch[k] == c:
B[k] = B[k-1]
else:
B[k] = B[k-1] + 1
c = ch[k]
T = [0 for _ in range(n)]
F = [0 for _ in range(n)]
T[1] = B[0]+1
if ch[1] == ch[0]:
F[1] = 1
for i in range(1):
for j in range(i+2,n):
c = 0
if ch[j] == ch[j-1] and not(F[j-1]):
temp = max([T[j-1], B[j-1] + 1])
if temp == 1 + B[j-1]:
c = 1
else:
temp = T[j-1] + 1
if F[j-1] and ch[j] != ch[j-1]:
c = 1
T[j] = temp
F[j] = c
print(T[n-1])
``` | instruction | 0 | 69,430 | 0 | 138,860 |
Yes | output | 1 | 69,430 | 0 | 138,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n = int(input())
s = input()
dl = 1
now = s[0]
for i in range(1, n):
if now != s[i]:
now = s[i]
dl += 1
if '00' and '11' in s:
ans = dl+ 2
elif '00' in s or '11' in s:
ans = dl + 1
else:
ans = dl
print(ans)
``` | instruction | 0 | 69,431 | 0 | 138,862 |
No | output | 1 | 69,431 | 0 | 138,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
if __name__ == "__main__":
n = int( input().strip() )
s = input().strip()
segs = []
start = 0
i = 1
while i <= n:
if i == n or s[i] != s[start]:
segs.append( i - start )
start = i
i = start + 1
else:
i += 1
res = len(segs)
segs.sort()
if segs[-1] >= 3:
res += 2
elif len(segs) >= 2 and segs[-1] >= 2 and segs[-2] >= 2:
res += 2
print( res )
``` | instruction | 0 | 69,432 | 0 | 138,864 |
No | output | 1 | 69,432 | 0 | 138,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n = int(input())
s = input()
ans = 0
for i in range(1,n):
if s[i] != s[i-1]:
ans += 1
print(min(ans+2, n))
``` | instruction | 0 | 69,433 | 0 | 138,866 |
No | output | 1 | 69,433 | 0 | 138,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length n. Each character of Kevin's string represents Kevin's score on one of the n questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is not lost. Kevin is a big proponent of alternative thinking and believes that his score, instead of being the sum of his points, should be the length of the longest alternating subsequence of his string. Here, we define an alternating subsequence of a string as a not-necessarily contiguous subsequence where no two consecutive elements are equal. For example, {0, 1, 0, 1}, {1, 0, 1}, and {1, 0, 1, 0} are alternating sequences, while {1, 0, 0} and {0, 1, 0, 1, 1} are not.
Kevin, being the sneaky little puffball that he is, is willing to hack into the USAICO databases to improve his score. In order to be subtle, he decides that he will flip exactly one substring—that is, take a contiguous non-empty substring of his score and change all '0's in that substring to '1's and vice versa. After such an operation, Kevin wants to know the length of the longest possible alternating subsequence that his string could have.
Input
The first line contains the number of questions on the olympiad n (1 ≤ n ≤ 100 000).
The following line contains a binary string of length n representing Kevin's results on the USAICO.
Output
Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring.
Examples
Input
8
10000011
Output
5
Input
2
01
Output
2
Note
In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score.
Submitted Solution:
```
n = int(input())
s = input()
cnt = 1
intervals = [1]
for i in range(1, n):
if s[i] != s[i - 1]:
intervals.append(1)
else:
intervals[-1] += 1
has_three = False
for interval in intervals:
if interval >= 3:
has_three = True
break
if has_three:
print(len(intervals) + 2)
else:
twos = intervals.count(2)
if twos >= 2:
print(len(intervals) + 2)
elif intervals[0] == 2 or intervals[-1] == 2:
print(len(intervals) + 1)
else:
print(len(intervals))
``` | instruction | 0 | 69,434 | 0 | 138,868 |
No | output | 1 | 69,434 | 0 | 138,869 |
Provide a correct Python 3 solution for this coding contest problem.
A linear congruential generator produces a series R(⋅) of pseudo-random numbers by the following for- mulas:
<image>
where S, A, C, and M are all parameters. In this problem, 0 ≤ S, A, C ≤ 15 and M = 256.
Now suppose we have some input string I(⋅), where each character in the string is an integer between 0 and (M - 1). Then, using the pseudo-random number series R(⋅), we obtain another string O(⋅) as the output by the following formula:
<image>
Your task is to write a program that shows the parameters S, A, and C such that the information entropy of the output string O(⋅) is minimized. Here, the information entropy H is given by the following formula:
<image>
where N is the length of the string and #(x) is the number of occurences of the alphabet x.
Input
The input consists of multiple datasets. Each dataset has the following format:
N
I(1) I(2) ... I(N)
N does not exceed 256.
The last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print in a line the values of the three parameters S, A, and C separated by a single space. If more than one solution gives the same minimum entropy, choose the solution with the smallest S, A, and then C.
Example
Input
5
5 4 3 2 1
5
7 7 7 7 7
10
186 8 42 24 154 40 10 56 122 72
0
Output
0 1 1
0 0 0
8 7 14 | instruction | 0 | 69,776 | 0 | 139,552 |
"Correct Solution:
```
import math
M = 256
def entropy_if_smallest(ctr,bound):
ret = 0
for v in ctr:
if v == 0: continue
ret -= (v / N) * math.log2(v / N)
if ret >= bound:
return None
return ret
def solve(src):
ans_h = float('inf')
ans = None
for s in range(16):
for a in range(16):
for c in range(16):
ctr = [0] * M
r = s
for i in src:
r = (a*r + c) % M
o = (i + r) % M
ctr[o] += 1
h = entropy_if_smallest(ctr,ans_h)
if h is not None:
ans = (s,a,c)
ans_h = h
if ans_h == 0:
return ans
return ans
while True:
N = int(input())
if N == 0: break
src = list(map(int,input().split()))
print(' '.join(map(str,solve(src))))
``` | output | 1 | 69,776 | 0 | 139,553 |
Provide a correct Python 3 solution for this coding contest problem.
A linear congruential generator produces a series R(⋅) of pseudo-random numbers by the following for- mulas:
<image>
where S, A, C, and M are all parameters. In this problem, 0 ≤ S, A, C ≤ 15 and M = 256.
Now suppose we have some input string I(⋅), where each character in the string is an integer between 0 and (M - 1). Then, using the pseudo-random number series R(⋅), we obtain another string O(⋅) as the output by the following formula:
<image>
Your task is to write a program that shows the parameters S, A, and C such that the information entropy of the output string O(⋅) is minimized. Here, the information entropy H is given by the following formula:
<image>
where N is the length of the string and #(x) is the number of occurences of the alphabet x.
Input
The input consists of multiple datasets. Each dataset has the following format:
N
I(1) I(2) ... I(N)
N does not exceed 256.
The last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print in a line the values of the three parameters S, A, and C separated by a single space. If more than one solution gives the same minimum entropy, choose the solution with the smallest S, A, and then C.
Example
Input
5
5 4 3 2 1
5
7 7 7 7 7
10
186 8 42 24 154 40 10 56 122 72
0
Output
0 1 1
0 0 0
8 7 14 | instruction | 0 | 69,777 | 0 | 139,554 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n = I()
if n == 0:
break
ii = LI()
m = inf
r = '-1'
for s in range(16):
for a in range(16):
for c in range(16):
t = s
f = [0] * 256
for i in ii:
t = (a * t + c) % 256
f[(t + i) % 256] += 1
h = 0
for i in range(256):
if f[i] == 0:
continue
h -= f[i] / n * math.log(f[i] / n)
if m > h + eps:
m = h
r = '{} {} {}'.format(s, a, c)
rr.append(r)
return '\n'.join(map(str, rr))
print(main())
``` | output | 1 | 69,777 | 0 | 139,555 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,840 | 0 | 139,680 |
Tags: implementation, strings
Correct Solution:
```
n=int(input())
s=list(input())
if sorted(s)[0]==sorted(s)[n-1]:
print('NO')
else:
print('YES')
for i in range(0,n-1):
if s[i]!=s[i+1] :
g=s[i]+s[i+1]
print(g)
exit()
``` | output | 1 | 69,840 | 0 | 139,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,841 | 0 | 139,682 |
Tags: implementation, strings
Correct Solution:
```
def test_0():
# A -
import math
from collections import Counter
n = list(map(int, input().split(" ")))[0]
ss = input()
aa = ''
for i in range(n-1):
if ss[i] != ss[i+1]:
aa = ss[i: i+2]
break
if aa == '':
print('NO')
else:
print('YES')
print(aa)
test_0()
``` | output | 1 | 69,841 | 0 | 139,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,842 | 0 | 139,684 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
s = input()
for i in range(n - 1):
if s[i] != s[i + 1]:
print('YES\n' + s[i] + s[i + 1])
break
else:
print('NO')
``` | output | 1 | 69,842 | 0 | 139,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,843 | 0 | 139,686 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
s = input()
for i in range(len(s)-1):
if s[i] != s[i+1]:
print('YES')
print(s[i]+s[i+1])
break
else:print('NO')
``` | output | 1 | 69,843 | 0 | 139,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,844 | 0 | 139,688 |
Tags: implementation, strings
Correct Solution:
```
N=int(input())
a=list(input())
if(a.count(a[0])==N):
print("NO")
else:
for i in range(0,N-1):
if(a[i]!=a[i+1]):
S=a[i]+a[i+1]
break
print("YES")
print(S)
``` | output | 1 | 69,844 | 0 | 139,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,845 | 0 | 139,690 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
l1 = list(input())
if len(set(l1))>=2:
print("YES")
print("".join(list(set(l1))[:2]))
else:
print("NO")
``` | output | 1 | 69,845 | 0 | 139,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,846 | 0 | 139,692 |
Tags: implementation, strings
Correct Solution:
```
from sys import stdin
from collections import Counter
n = stdin.readline()
s = stdin.readline().rstrip()
def solve(s):
for i in range(len(s) - 1):
if s[i] != s[i + 1]:
print("YES")
print(s[i:i+2])
return
print("NO")
solve(s)
``` | output | 1 | 69,846 | 0 | 139,693 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer. | instruction | 0 | 69,847 | 0 | 139,694 |
Tags: implementation, strings
Correct Solution:
```
n, s = int(input()), input()
for i in range(1,n):
if s[i-1] != s[i]:
print('YES\n',s[i-1],s[i],sep='')
break
else:
print('NO')
``` | output | 1 | 69,847 | 0 | 139,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n=int(input())
s=str(input())
for i in range(1,n):
if s[i]!=s[i-1]:
print('YES')
print(s[i-1]+s[i])
exit()
print('NO')
``` | instruction | 0 | 69,848 | 0 | 139,696 |
Yes | output | 1 | 69,848 | 0 | 139,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n=int(input())
s=input()
flag=0
ans=""
for i in range(1,n):
x=s[i-1:i+1]
if(x[0]!=x[1]):
flag=1
ans=x
if(flag==1):
print("YES")
print(ans)
else:
print("NO")
``` | instruction | 0 | 69,849 | 0 | 139,698 |
Yes | output | 1 | 69,849 | 0 | 139,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n=int(input())
s=input()
f=0
for i in range(1,n):
if s[i-1]!=s[i]:
print('YES')
print(s[i-1],s[i],sep='')
f=1
break
if f==0:
print('NO')
``` | instruction | 0 | 69,850 | 0 | 139,700 |
Yes | output | 1 | 69,850 | 0 | 139,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n = int(input())
s = input()
if len(list(set(list(s)))) == 1:
print("NO")
else:
print("YES")
for i in range(len(s)-1):
if s[i] != s[i+1]:
print(s[i] + s[i+1])
break
``` | instruction | 0 | 69,851 | 0 | 139,702 |
Yes | output | 1 | 69,851 | 0 | 139,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n = int(input())
str = input()
flag = False
flag1 = False
for i in range(n):
str1 = str[:i]
length = len(str1)
for j in "abcdefghijklmnopqrstuvwxyz":
if str1.count(j) > length/2:
flag = True
break
else:
flag = False
break
if flag == True:
break
for i in range(n):
str2 = str[i:]
length = len(str1)
for j in "abcdefghijklmnopqrstuvwxyz":
if str2.count(j) > length/2:
flag1 = True
break
else:
flag1 = False
break
if flag == True:
break
if flag == True and flag1 == True:
print("NO")
elif flag == True and flag1 == False:
print("YES")
print(str1)
elif flag == False and flag1 == True:
print("YES")
print(str2)
else:
print("YES")
print(str1)
``` | instruction | 0 | 69,852 | 0 | 139,704 |
No | output | 1 | 69,852 | 0 | 139,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
from collections import Counter
n=int(input())
s=input()
c=Counter(list(s))
if max(list(c.values()))>n//2:
print("NO")
else:
print("YES")
print(s[:n//2])
``` | instruction | 0 | 69,853 | 0 | 139,706 |
No | output | 1 | 69,853 | 0 | 139,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n=int(input())
s=input()
arr=[0]*26
ans=''
flag=0
for i in s:
ans+=i
if(arr[ord(i)-97]+1<=len(ans)//2):
print("YES")
print(ans)
flag=1
break
arr[ord(i)-97]+=1
if(not flag):
print("NO")
``` | instruction | 0 | 69,854 | 0 | 139,708 |
No | output | 1 | 69,854 | 0 | 139,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of n lowercase Latin letters.
A substring of string s is a continuous segment of letters from s. For example, "defor" is a substring of "codeforces" and "fors" is not.
The length of the substring is the number of letters in it.
Let's call some string of length n diverse if and only if there is no letter to appear strictly more than \frac n 2 times. For example, strings "abc" and "iltlml" are diverse and strings "aab" and "zz" are not.
Your task is to find any diverse substring of string s or report that there is none. Note that it is not required to maximize or minimize the length of the resulting substring.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the length of string s.
The second line is the string s, consisting of exactly n lowercase Latin letters.
Output
Print "NO" if there is no diverse substring in the string s.
Otherwise the first line should contain "YES". The second line should contain any diverse substring of string s.
Examples
Input
10
codeforces
Output
YES
code
Input
5
aaaaa
Output
NO
Note
The first example has lots of correct answers.
Please, restrain yourself from asking if some specific answer is correct for some specific test or not, these questions always lead to "No comments" answer.
Submitted Solution:
```
n = int(input())
s = input()
dn = n/2
v = ''
for a in range(int(dn)):
if n > 1:
v = s[a:a+2]
if v[0] != v[1]:
break
else:
v = ''
pass
if v:
print('YES\n'+v)
else:
print('NO')
``` | instruction | 0 | 69,855 | 0 | 139,710 |
No | output | 1 | 69,855 | 0 | 139,711 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome. | instruction | 0 | 70,196 | 0 | 140,392 |
Tags: brute force, greedy, implementation
Correct Solution:
```
import math
content_length, current_position = map(int, input().split())
middle_position = math.ceil(content_length / 2)
text = input()
answer = 0
first_need_change = -1
last_need_change = -1
for index in range(middle_position):
left_char = text[index]
right_char = text[content_length - index - 1]
if left_char != right_char:
left_value = ord(left_char)
right_value = ord(right_char)
answer += min(abs(left_value - right_value),
abs(26 - abs(left_value - right_value)))
if first_need_change == -1:
first_need_change = index+1
else:
last_need_change = index+1
move_count = 0
if current_position > middle_position:
current_position = content_length - current_position + 1
near_position = min(abs(first_need_change - current_position),
abs(last_need_change-current_position))
far_position = max(abs(first_need_change - current_position),
abs(last_need_change - current_position))
if last_need_change != -1:
if (first_need_change >= current_position and last_need_change >= current_position) or (first_need_change <= current_position and last_need_change <= current_position):
move_count += near_position + (far_position-near_position)
else:
move_count += near_position + abs(first_need_change-last_need_change)
else:
if first_need_change != -1:
move_count = abs(first_need_change-current_position)
answer += move_count
print(answer)
``` | output | 1 | 70,196 | 0 | 140,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
from math import ceil
n, p = map(int, input().split())
s, ans, be, en = input(), 0, 0, ceil(n / 2)
if p > n // 2:
be, en = (n // 2), n
c1, c2, flag = 0, 0, 0
for i in range(p - 1, be - 1, -1):
x1 = abs(ord(s[i]) - ord(s[n - i - 1]))
if x1:
flag = c1
ans += min(x1, 26 - x1)
c1 += 1
c1 = flag
flag = 0
for i in range(p, en):
c2 += 1
x = abs(ord(s[i]) - ord(s[n - i - 1]))
if x:
flag = c2
ans += min(x, 26 - x)
c2 = flag
print(ans + 2 * min(c1, c2) + max(c1, c2))
``` | instruction | 0 | 70,203 | 0 | 140,406 |
Yes | output | 1 | 70,203 | 0 | 140,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
n,k=map(int,input().split())
s=input()
k-=1
k=min(k,n-k-1)
a=-1
b=0
ans=0
l=0
for i in range(n//2):
j=abs(ord(s[i])-ord(s[n-1-i]))
j=min(j,26-j)
if(j>0 and a==-1):
a=i
if(j>0):
b=i
l+=j
a=min(a,n-a-1)
b=min(b,n-b-1)
if(l==0):
print(0)
else:
if((k-a)*(k-b)>0):
ans=max(abs(k-a),abs(k-b))
else:
ans=abs(k-a)+abs(k-b)+min(abs(k-a),abs(k-b))
print(ans+l)
``` | instruction | 0 | 70,204 | 0 | 140,408 |
Yes | output | 1 | 70,204 | 0 | 140,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
import sys
from math import sqrt
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
n,p = map(int,input().split())
line = input().rstrip('\n')
if p > int(len(line)/2):
line = line[::-1]
p = n-p+1
l = n; r = -1
for i in range(0,int(n/2)):
if line[i] != line[n-1-i]:
l = min(l,i)
r = max(r,i)
res = 0
if l == n and r == -1:
res= 0
else:
for i in range(l,r+1):
case1 = abs(ord(line[n-1-i])-ord(line[i]))
case2 = 26 - case1
#print('{} {}'.format(case1,case2))
num = min(case1,case2)
res+=num
res += min(abs(p-1-l),abs(p-1-r)) + r-l
print(res)
``` | instruction | 0 | 70,205 | 0 | 140,410 |
Yes | output | 1 | 70,205 | 0 | 140,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
n,p = map(int,input().split())
p -= 1
if p >= n//2: p = n-1-p
s = input()
d = [abs(ord(s[i])-ord(s[n-1-i])) for i in range(n//2)]
d = [min(x,26-x) for x in d]
first,last = -1,-1
for i in range(len(d)):
if d[i] > 0:
if first==-1: first = i
last = i
a = 0 if first==-1 else min(abs(p-first), abs(p-last)) + (last-first) + sum(d)
print(a)
``` | instruction | 0 | 70,206 | 0 | 140,412 |
Yes | output | 1 | 70,206 | 0 | 140,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
def f(c):
return ord(c) - ord('a')
n, p = map(int, input().split())
s = input()
res = 0
for i in range(n // 2):
j = n - 1 - i
res += min(abs(f(s[i]) - f(s[j])), 26 - abs(f(s[i]) - f(s[j])))
res += min(abs(p - 1 - i) for i in [0, n // 2 - 1, (n + 1) // 2, n - 1]) + max(0, n // 2 - 1)
print(res)
``` | instruction | 0 | 70,207 | 0 | 140,414 |
No | output | 1 | 70,207 | 0 | 140,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
n,p=map(int,input().split())
p=p-1
a=input()
fn=0 #fn+1=first non zero diff
ln=(n//2) #last non zero diff
sum_val=0
allzero=True
flag=True
for i in range(n//2):
diff=abs(ord(a[i])-ord(a[n-i-1]))
val=min(diff, 26-diff)
sum_val+=val
if val==0 and flag:
fn+=1
else:
flag=False
if val!=0:
ln=i
allzero=False
if p>n//2:
p=(n-p-1)
if allzero:
print(0)
elif p>ln:
print(sum_val+p-fn)
elif p<fn:
print(sum_val+ln-p)
else:
print(sum_val+min(ln-p,p-fn)+ln-fn)
``` | instruction | 0 | 70,208 | 0 | 140,416 |
No | output | 1 | 70,208 | 0 | 140,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
n,k=map(int,input().split())
s=input()
k-=1
k=min(k,n-k-1)
a=-1
b=0
ans=0
l=0
for i in range(n//2):
j=abs(ord(s[i])-ord(s[n-1-i]))
j=min(j,26-j)
if(j>0 and a==-1):
a=i
if(j>0):
b=i
l+=j
if(l==0):
print(0)
else:
ans+=min(abs(b-k),abs(a-k))
pp=min(b-a,n-1-a-b)
if(pp>ans):
ans+=pp
print(ans+l)
``` | instruction | 0 | 70,209 | 0 | 140,418 |
No | output | 1 | 70,209 | 0 | 140,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nam is playing with a string on his computer. The string consists of n lowercase English letters. It is meaningless, so Nam decided to make the string more beautiful, that is to make it be a palindrome by using 4 arrow keys: left, right, up, down.
There is a cursor pointing at some symbol of the string. Suppose that cursor is at position i (1 ≤ i ≤ n, the string uses 1-based indexing) now. Left and right arrow keys are used to move cursor around the string. The string is cyclic, that means that when Nam presses left arrow key, the cursor will move to position i - 1 if i > 1 or to the end of the string (i. e. position n) otherwise. The same holds when he presses the right arrow key (if i = n, the cursor appears at the beginning of the string).
When Nam presses up arrow key, the letter which the text cursor is pointing to will change to the next letter in English alphabet (assuming that alphabet is also cyclic, i. e. after 'z' follows 'a'). The same holds when he presses the down arrow key.
Initially, the text cursor is at position p.
Because Nam has a lot homework to do, he wants to complete this as fast as possible. Can you help him by calculating the minimum number of arrow keys presses to make the string to be a palindrome?
Input
The first line contains two space-separated integers n (1 ≤ n ≤ 105) and p (1 ≤ p ≤ n), the length of Nam's string and the initial position of the text cursor.
The next line contains n lowercase characters of Nam's string.
Output
Print the minimum number of presses needed to change string into a palindrome.
Examples
Input
8 3
aeabcaez
Output
6
Note
A string is a palindrome if it reads the same forward or reversed.
In the sample test, initial Nam's string is: <image> (cursor position is shown bold).
In optimal solution, Nam may do 6 following steps:
<image>
The result, <image>, is now a palindrome.
Submitted Solution:
```
n,p = map(int,input().split())
l = list(input())
flag = 0
min1 = max1 = -1
sum = 0
for i in range(n//2):
if(l[i] != l[n-1-i]):
if(flag == 0):
min1 = i+1
flag = 1
max1 = i+1
s1 = abs(ord(l[i]) - ord(l[n-1-i]))
s2 = 26 - s1
sum += min(s1,s2)
sum += min(abs(max1-p),abs(p-min1))
sum += max1 - min1
print(sum)
``` | instruction | 0 | 70,210 | 0 | 140,420 |
No | output | 1 | 70,210 | 0 | 140,421 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,211 | 0 | 140,422 |
Tags: strings
Correct Solution:
```
s = input()
flags = {}
n = 0
for c in s:
flags[c] = 0
for c in s:
n += flags[c] * 2
n += 1
flags[c] += 1
print(n)
``` | output | 1 | 70,211 | 0 | 140,423 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,212 | 0 | 140,424 |
Tags: strings
Correct Solution:
```
a=list(input())
b=[]
for i in set(a):
b.append(a.count(i))
print(sum(i**2 for i in b))
``` | output | 1 | 70,212 | 0 | 140,425 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,213 | 0 | 140,426 |
Tags: strings
Correct Solution:
```
s = input()
d = {}
for c in s:
d[c] = d.get(c, 0 ) + 1
ans = 0
for i in d.values():
ans += i ** 2
print(ans)
``` | output | 1 | 70,213 | 0 | 140,427 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,214 | 0 | 140,428 |
Tags: strings
Correct Solution:
```
a=list(input())
s=0
b=[]
for i in a:
if i not in b:
b.append(i)
l=a.count(i)
s= s + l**2
print(s)
``` | output | 1 | 70,214 | 0 | 140,429 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,215 | 0 | 140,430 |
Tags: strings
Correct Solution:
```
s= input()
f={}
for j in s:
if j not in f:
f[j]=1
else:
f[j]+=1
ans=0
for k in f.keys():
ans+=f[k]
ans+=(f[k]-1)*(f[k])
print(ans)
``` | output | 1 | 70,215 | 0 | 140,431 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,216 | 0 | 140,432 |
Tags: strings
Correct Solution:
```
a=list(input());s=0
for i in set(a):
s+=(a.count(i))**2
print(s)
``` | output | 1 | 70,216 | 0 | 140,433 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,217 | 0 | 140,434 |
Tags: strings
Correct Solution:
```
s = list(input())
ans = len(s)
dic = {}
for item in s:
if item not in dic:
dic[item] = 1
else:
dic[item] += 1
for item in dic.keys():
ans += dic[item] * (dic[item] - 1)
print(ans)
``` | output | 1 | 70,217 | 0 | 140,435 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100 | instruction | 0 | 70,218 | 0 | 140,436 |
Tags: strings
Correct Solution:
```
s=input()
d={}
sum=0
for i in s:
d[i]=d.get(i,0)+1
for each in d.values():
sum+=each**2
print(sum)
``` | output | 1 | 70,218 | 0 | 140,437 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
from collections import Counter
print(sum(map(lambda x: x * x, Counter(input()).values())))
``` | instruction | 0 | 70,219 | 0 | 140,438 |
Yes | output | 1 | 70,219 | 0 | 140,439 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
s = input()
t = {}
p = 0
z = 0
for i in s:
if i in t:
t[i]+= 1
else:
t[i] = 1
for k in t:
if t[k] >= 1:
p = int(t[k])**2
z += p
if(t[i] == 1):
print(len(s))
else:
print(z)
``` | instruction | 0 | 70,220 | 0 | 140,440 |
Yes | output | 1 | 70,220 | 0 | 140,441 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
s=input();x=list(set(s));ans=0
for i in range(0,len(x)):
ans+=s.count(x[i])**2
print(ans)
``` | instruction | 0 | 70,222 | 0 | 140,444 |
Yes | output | 1 | 70,222 | 0 | 140,445 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
n=input()
ls=[]
for i in n:
ls.append(i)
mm=0
for i in ls:
mm+=(ls.count(i))**2
for e in range(ls.count(i)):
ls.remove(i)
print(mm)
``` | instruction | 0 | 70,223 | 0 | 140,446 |
No | output | 1 | 70,223 | 0 | 140,447 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
x=input()
count=0
samenum=0
for i in x:
for j in range(len(x)):
if i==x[j]:
count+=1
samenum+=count**2
count=0
print(samenum)
``` | instruction | 0 | 70,224 | 0 | 140,448 |
No | output | 1 | 70,224 | 0 | 140,449 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
n=input()
m=list(str(n))
a=[]
for i in m:
a.append(m.count(i))
b=0
for j in range(len(a)):
b+=(a[j])**2
print(b)
``` | instruction | 0 | 70,225 | 0 | 140,450 |
No | output | 1 | 70,225 | 0 | 140,451 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a given string S consisting of N symbols. Your task is to find the number of ordered pairs of integers i and j such that
1. 1 ≤ i, j ≤ N
2. S[i] = S[j], that is the i-th symbol of string S is equal to the j-th.
Input
The single input line contains S, consisting of lowercase Latin letters and digits. It is guaranteed that string S in not empty and its length does not exceed 105.
Output
Print a single number which represents the number of pairs i and j with the needed property. Pairs (x, y) and (y, x) should be considered different, i.e. the ordered pairs count.
Examples
Input
great10
Output
7
Input
aaaaaaaaaa
Output
100
Submitted Solution:
```
str=input()
cnt=0
ls=[]
for i in str:
ls.append(str.count(i))
for j in ls:
cnt+=j**2
print(cnt)
``` | instruction | 0 | 70,226 | 0 | 140,452 |
No | output | 1 | 70,226 | 0 | 140,453 |
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