message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
For example, when s = `at`, t = `code` and L = 6, the strings `atatat`, `atcode` and `codeat` can be generated.
Among the strings that can be generated in this way, find the lexicographically smallest one. In the cases given as input, it is always possible to generate a string of length L.
Constraints
* 1 ≤ L ≤ 2 × 10^5
* 1 ≤ |s|, |t| ≤ L
* s and t consist of lowercase English letters.
* It is possible to generate a string of length L in the way described in Problem Statement.
Input
Input is given from Standard Input in the following format:
N
x_1 s_1
x_2 s_2
:
x_N s_N
Output
Print the lexicographically smallest string among the ones that can be generated in the way described in Problem Statement.
Examples
Input
6
at
code
Output
atatat
Input
8
coding
festival
Output
festival
Input
8
same
same
Output
samesame
Input
10
coin
age
Output
ageagecoin
Submitted Solution:
```
def main():
L = int(input())
S, T = (input() for _ in [0] * 2)
s = S * len(T)
t = T * len(S)
if s < t:
a = S
b = T
else:
a = T
b = S
i = 0
while 1:
x = L - (len(b) * i)
div_, mod_ = divmod(x, len(a))
if not mod_:
ans = a * div_ + b * i
break
i += 1
print(ans)
main()
``` | instruction | 0 | 50,358 | 18 | 100,716 |
No | output | 1 | 50,358 | 18 | 100,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase English letters and an integer L.
We will consider generating a string of length L by concatenating one or more copies of s and t. Here, it is allowed to use the same string more than once.
For example, when s = `at`, t = `code` and L = 6, the strings `atatat`, `atcode` and `codeat` can be generated.
Among the strings that can be generated in this way, find the lexicographically smallest one. In the cases given as input, it is always possible to generate a string of length L.
Constraints
* 1 ≤ L ≤ 2 × 10^5
* 1 ≤ |s|, |t| ≤ L
* s and t consist of lowercase English letters.
* It is possible to generate a string of length L in the way described in Problem Statement.
Input
Input is given from Standard Input in the following format:
N
x_1 s_1
x_2 s_2
:
x_N s_N
Output
Print the lexicographically smallest string among the ones that can be generated in the way described in Problem Statement.
Examples
Input
6
at
code
Output
atatat
Input
8
coding
festival
Output
festival
Input
8
same
same
Output
samesame
Input
10
coin
age
Output
ageagecoin
Submitted Solution:
```
import sys
L = int(input())
s = str(input())
t = str(input())
tmps = s
tmpt = t
s = min(s,t)
sl = len(s)
t = max(tmps,tmpt)
tl = len(t)
p = L//sl
q = L%sl
if q == 0:
print(s*p)
elif q == tl:
print(s*p + t*1)
else:
for i in range(1,p+1):
if (q + i*sl)%tl == 0:
print(s*(p-i) + t*((L-sl*(p-i))//tl))
sys.exit()
``` | instruction | 0 | 50,359 | 18 | 100,718 |
No | output | 1 | 50,359 | 18 | 100,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
s = input()
k = int(input())
a = ord("a") + 26
mod = 26
ans = ""
for i in s[:-1]:
tmp = (a - ord(i)) % mod
if tmp <= k:
k -= tmp
ans += "a"
else:
ans += i
ans += chr(ord("a") + (ord(s[-1]) - a + k) % mod)
print(ans)
``` | instruction | 0 | 50,400 | 18 | 100,800 |
Yes | output | 1 | 50,400 | 18 | 100,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
s = list(input())
n = len(s)
k = int(input())
for i in range(n):
if k > 0 and i == n-1:
x = ord(s[i])-ord("a")
s[i] = chr((k+x)%26+ord("a"))
break
if s[i] == "a":
continue
x = ord(s[i])-ord("a")
if k >= 26-x:
s[i] = "a"
k -= 26-x
print(*s,sep="")
``` | instruction | 0 | 50,401 | 18 | 100,802 |
Yes | output | 1 | 50,401 | 18 | 100,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
s=input()
k=int(input())
ss=[]
for i in range(len(s)):
ss.append(ord(s[i])-ord("a"))
i=0
while k>0:
if i==len(s)-1:
ss[i]=(k+ss[i])%26
break
elif k>=26-ss[i] and ss[i]!=0:
k-=(26-ss[i])
ss[i]=0
i+=1
ans=""
for i in range(len(s)):
ans+=chr(ord("a")+ss[i])
print(ans)
``` | instruction | 0 | 50,402 | 18 | 100,804 |
Yes | output | 1 | 50,402 | 18 | 100,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
s=input()
n=len(s)
a=[ord(i)-ord('a') for i in s]
k=int(input())
for i in range(n):
if a[i]+k>=26 and a[i]>0:
k-=26-a[i]
a[i]=0
k%=26
a[-1]+=k
a=[chr(i + ord('a')) for i in a]
print(*a,sep="")
``` | instruction | 0 | 50,403 | 18 | 100,806 |
Yes | output | 1 | 50,403 | 18 | 100,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
S = input()
K = int(input())
ans = ''
i = 0
while(K>0):
if i == len(S)-1:
K %= 26
ans += chr(((ord(S[i])-97)+K)%26+97)
K = 0
else:
if S[i] != 'a':
a = 26-(ord(S[i])-97)
if K > a:
ans += 'a'
K -= a
else:
ans += S[i]
else:
ans += S[i]
i += 1
print(ans)
``` | instruction | 0 | 50,404 | 18 | 100,808 |
No | output | 1 | 50,404 | 18 | 100,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
s, k, t, i = input(), int(input()), "", 0
for s in s:
if (p := 123 - ord(s)) <= k:
k -= p
t += "a"
else:
t += s
print(t[:-1] + chr((ord(t[-1]) - 97 + k) % 26 + 97))
``` | instruction | 0 | 50,405 | 18 | 100,810 |
No | output | 1 | 50,405 | 18 | 100,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
s=input()
K=int(input())
S=[c for c in s]
def diff(c):
return ord('z')-ord(c)
for i in range(len(s)):
d=diff(S[i])
if d<K:
K-=d+1
S[i]='a'
k=K%26
S[-1]=chr(ord(S[-1])+k) if k<=diff(S[-1]) else chr(ord(S[-1])+k-26)
print(''.join(S))
``` | instruction | 0 | 50,406 | 18 | 100,812 |
No | output | 1 | 50,406 | 18 | 100,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.
* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.
For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.
Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.
Constraints
* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9
Input
The input is given from Standard Input in the following format:
s
K
Output
Print the lexicographically smallest string after performing exactly K operations on s.
Examples
Input
xyz
4
Output
aya
Input
a
25
Output
z
Input
codefestival
100
Output
aaaafeaaivap
Submitted Solution:
```
# def makelist(n, m):
# return [[0 for i in range(m)] for j in range(n)]
# n = int(input())
# a, b = map(int, input().split())
# s = input()
s = input()
K = int(input())
l = len(s)
ans = ['a']*l
ORDa = 97
for i in range(l):
now = ord(s[i]) - ORDa
tmp = 26 - now
if K == 0:
ans[i] = s[i]
elif tmp <= K:
ans[i] = 'a'
K -= tmp
else:
ans[i] = s[i]
if K > 0:
ans[-1] = chr(ord(ans[-1]) + K)
print("".join(ans))
# last shori
``` | instruction | 0 | 50,407 | 18 | 100,814 |
No | output | 1 | 50,407 | 18 | 100,815 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,461 | 18 | 100,922 |
"Correct Solution:
```
button = [
["", "", ""],
[".", ",", "!", "?", " "],
["a", "b", "c"],
["d", "e", "f"],
["g", "h", "i"],
["j", "k", "l"],
["m", "n", "o"],
["p", "q", "r", "s"],
["t", "u", "v"],
["w", "x", "y", "z"],
]
N = int(input())
for _ in range(N):
S = ""
count = 0
l = list(input())
for i in range(0, len(l)):
if l[i] == "0":
S += button[int(l[i - 1])][count-1]
count = 0
else:
# print(l[i])
count = (count + 1) % len(button[int(l[i])])
print(S)
``` | output | 1 | 50,461 | 18 | 100,923 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,462 | 18 | 100,924 |
"Correct Solution:
```
d=[1,'.,!? ','abc','def','ghi','jkl','mno','pqrs','tuv','wxyz'];[print(''.join(d[int(s[0])][len(s)%len(d[int(s[0])])-1]if s!=''else''for s in t))for t in[input().split('0')for _ in[0]*int(input())]]
``` | output | 1 | 50,462 | 18 | 100,925 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,463 | 18 | 100,926 |
"Correct Solution:
```
def set(mess) :
Mess = list(mess.split("0"))
Ml = len(Mess)
for i in range(Ml) :
if("" in Mess) :
Mess.remove("")
# Mess 内の1番インデックスの小さい""を削除
else :
break
ML = len(Mess)
change(Mess, ML)
def change(Mess, ML) :
one = [".", ",", "!", "?", " "]
alpha = [chr(i) for i in range(97, 97 + 26)]
Num = list()
Cnt = list()
for i in range(ML) :
a = list(Mess[i])
Num.append(a[0])
Cnt.append(len(a))
ans = list()
for i in range(ML) :
if(Num[i] == "1") :
ans.append(one[Cnt[i] % 5 - 1])
elif(Num[i] == "7") :
ans.append(alpha[(Cnt[i]-1)% 4 + 15])
elif(Num[i] == "8") :
ans.append(alpha[(Cnt[i]-1)% 3 + 19])
elif(Num[i] == "9") :
ans.append(alpha[(Cnt[i]-1)% 4 + 22])
else :
x = 3 * (int(Num[i]) - 2)
ans.append(alpha[(Cnt[i]-1) % 3 + x])
for j in range(len(ans)) :
if(j == len(ans) - 1) :
print(ans[j])
else :
print(ans[j], end = "")
N = int(input())
for i in range(N) :
mess = input()
set(mess)
``` | output | 1 | 50,463 | 18 | 100,927 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,464 | 18 | 100,928 |
"Correct Solution:
```
keys = {
'1': '.,!? ',
'2': 'abc',
'3': 'def',
'4': 'ghi',
'5': 'jkl',
'6': 'mno',
'7': 'pqrs',
'8': 'tuv',
'9': 'wxyz',
}
def solve_testcase():
s = input().split('0')
res = ''
for s0 in s:
if not s0: continue
c = s0[0]
v = keys[c]
res += v[(len(s0)-1) % len(v)]
print(res)
def main():
n = int(input())
for _ in range(n): solve_testcase()
main()
``` | output | 1 | 50,464 | 18 | 100,929 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,465 | 18 | 100,930 |
"Correct Solution:
```
#!/usr/bin/python3
def atoi(c):
return ord(c) - ord('0')
table = [(), #dummy
('.',',','!','?',' '),\
('a','b','c'),
('d','e','f'),
('g','h','i'),
('j','k','l'),
('m','n','o'),
('p','q','r','s'),
('t','u','v'),
('w','x','y','z')]
n = int(input())
for i in range(n):
digits = list(input())
s = ""
c = ''
m = 0
for d in digits:
if d == '0':
s += c
c = ''
m = 0
else:
c = table[atoi(d)][m]
m = (m + 1) % len(table[atoi(d)])
print(s)
``` | output | 1 | 50,465 | 18 | 100,931 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,466 | 18 | 100,932 |
"Correct Solution:
```
n=int(input())
k=[[],[".",",","!","?"," "],["a","b","c"],["d","e","f"],["g","h","i"],["j","k","l"],["m","n","o"],["p","q","r","s"],["t","u","v"],["w","x","y","z"]]
for i in range(n):
b=input()
#print(b)
S=[]
count=0
for i in range(len(b)):
if b[i]=="0":
if count==0:
pass
else:
if b[i-1]=="1":
co=count%5-1
S.append(k[1][co])
count=0
elif b[i-1]=="2":
co=count%3-1
S.append(k[2][co])
count=0
elif b[i-1]=="3":
co=count%3-1
S.append(k[3][co])
count=0
elif b[i-1]=="4":
co=count%3-1
S.append(k[4][co])
count=0
elif b[i-1]=="5":
co=count%3-1
S.append(k[5][co])
count=0
if b[i-1]=="6":
co=count%3-1
S.append(k[6][co])
count=0
if b[i-1]=="7":
co=count%4-1
S.append(k[7][co])
count=0
if b[i-1]=="8":
co=count%3-1
S.append(k[8][co])
count=0
if b[i-1]=="9":
co=count%4-1
S.append(k[9][co])
count=0
else:
count+=1
for i in range(len(S)):
print(S[i],end="")
print("")
``` | output | 1 | 50,466 | 18 | 100,933 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,467 | 18 | 100,934 |
"Correct Solution:
```
n = int(input())
abc = [".,!? ", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"]
for i in range(n):
s = input()
ans = ""
cur = -1
num = -1
for e in s:
e = int(e)
if cur ==-1 and e==0:
continue
elif e==0:
t = len(abc[cur-1])
ans += abc[cur-1][num%t]
num = -1
cur = -1
else:
cur = e
num += 1
print(ans)
``` | output | 1 | 50,467 | 18 | 100,935 |
Provide a correct Python 3 solution for this coding contest problem.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai | instruction | 0 | 50,468 | 18 | 100,936 |
"Correct Solution:
```
lists = [[".",",","!","?"," "],["a","b","c"],["d","e","f"],["g","h","i"],["j","k","l"],["m","n","o"],["p","q","r","s"],["t","u","v"],["w","x","y","z"]]
cnt = 0
moji = []
ans = []
n = int(input())
for k in range(n):
s = str(input())
for i in range(len(s)):
if s[i] != "0":
cnt += 1
tmp = int(s[i])
if cnt > len(lists[tmp-1]):
cnt = cnt - len(lists[tmp-1])
elif s[i] == "0" and cnt != 0:
moji.append(lists[tmp - 1][int(cnt)-1])
cnt = 0
mojimoji = "".join(moji)
ans.append(mojimoji)
moji = []
for i in ans:
print(i)
``` | output | 1 | 50,468 | 18 | 100,937 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
if __name__ == '__main__':
n = int(input())
moji =[[],[' ','.',',','!','?'],['c','a','b'],['f','d','e'],['i','g','h'],['l','j','k'],['o','m','n'],['s','p','q','r'],['v','t','u'],['z','w','x','y']]
for _ in range(n):
line = list(input().strip().replace('0',' ').split())
ans = []
for i in line:
m=int(i[0])
ans.append(moji[m][len(i)%len(moji[m])])
print(''.join(ans))
``` | instruction | 0 | 50,469 | 18 | 100,938 |
Yes | output | 1 | 50,469 | 18 | 100,939 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
d = {"1": [".", ",", "!", "?", " "], "2": ["a", "b", "c"], "3": ["d", "e", "f"],
"4": ["g", "h", "i"], "5": ["j", "k", "l"], "6": ["m", "n", "o"],
"7": ["p", "q", "r", "s"], "8": ["t", "u", "v"], "9": ["w", "x", "y", "z"]}
n = int(input())
m = [input() for _ in range(n)]
ans = [[d[cs[0]][len(cs) % len(d[cs[0]]) - 1] for cs in line.split("0") if cs != ""] for line in m]
for a in ans:
print(*a, sep="")
``` | instruction | 0 | 50,470 | 18 | 100,940 |
Yes | output | 1 | 50,470 | 18 | 100,941 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
button = [[''],['.',',','!','?',' '], ['a','b','c'], ['d','e','f'], ['g','h','i'], ['j','k','l'], ['m','n','o'], ['p','q','r','s'], ['t','u','v'], ['w','x','y','z']]
n = int(input())
for i in range(n):
inputStr = list(map(int,list(input())))
count = 0
for j in range(len(inputStr)):
if inputStr[j] != 0:
count += 1
if inputStr[j] == 0 and j -1 >= 0 and inputStr[j-1] != 0:
print(button[inputStr[j-1]][(count-1)%len(button[inputStr[j-1]])],end='')
count = 0
print()
``` | instruction | 0 | 50,471 | 18 | 100,942 |
Yes | output | 1 | 50,471 | 18 | 100,943 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
dic = [None, '.,!? ','abc','def','ghi','jkl','mno','pqrs','tuv','wxyz']
N = int(input())
for i in range(N):
S = input()
ans = ''
btn = n = -1
for c in S:
if c == '0':
if btn > 0:
ans += dic[int(btn)][n % len(dic[int(btn)])]
btn = n = -1
else:
btn = int(c)
n += 1
print(ans)
``` | instruction | 0 | 50,472 | 18 | 100,944 |
Yes | output | 1 | 50,472 | 18 | 100,945 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
K = '.,!? '
A = 'abc'
D = 'def'
G = 'ghi'
J = 'jkl'
M = 'mno'
P = 'pqrs'
T = 'tuv'
W = 'wxyz'
L = ['', K, A, D, G, J, M, P, T, W]
while 1:
S = []
n = input()
if not '0' in n:
print('')
else:
n = n.split('0')
for ns in n:
if ns == '':
continue
i = len(ns) % len(L[int(ns[0])])
S += [[L[int(ns[0])], i-1]]
for s in S:
print(s[0][s[1]], end='')
print('')
``` | instruction | 0 | 50,473 | 18 | 100,946 |
No | output | 1 | 50,473 | 18 | 100,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
N = int(input())
d = []
d.append([])
d.append([".",",","!","?"])
d.append(["a","b","c"])
d.append(["d","e","f"])
d.append(["g","h","i"])
d.append(["j","k","l"])
d.append(["m","n","o"])
d.append(["p","q","r","s"])
d.append(["t","u","v"])
d.append(["w","x","y","z"])
for _ in range(N):
nn = input()
output = ""
b = 0
c = 0
for n in nn:
n = int(n)
if n == 0:
output += d[b][c]
c = 0
c += 1
print(output)
``` | instruction | 0 | 50,474 | 18 | 100,948 |
No | output | 1 | 50,474 | 18 | 100,949 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
N = int(input())
d = []
d.append([])
d.append([".",",","!","?"])
d.append(["a","b","c"])
d.append(["d","e","f"])
d.append(["g","h","i"])
d.append(["j","k","l"])
d.append(["m","n","o"])
d.append(["p","q","r","s"])
d.append(["t","u","v"])
d.append(["w","x","y","z"])
for _ in range(N):
nn = input()
output = ""
b = 0
c = 0
for n in nn:
n = int(n)
if n == 0:
output += d[b][c]
c = 0
b = n
``` | instruction | 0 | 50,475 | 18 | 100,950 |
No | output | 1 | 50,475 | 18 | 100,951 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice wants to send an email to Miku on her mobile phone.
The only buttons that can be used for input on mobile phones are number buttons. Therefore, in order to input characters, the number buttons are pressed several times to input characters. The following characters are assigned to the number buttons of the mobile phone, and the confirmation button is assigned to button 0. With this mobile phone, you are supposed to press the confirm button after you finish entering one character.
* 1:.,!? (Space)
* 2: a b c
* 3: d e f
* 4: g h i
* 5: j k l
* 6: m n o
* 7: p q r s
* 8: t u v
* 9: w x y z
* 0: Confirm button
For example, if you press button 2, button 2, or button 0, the letter changes from'a'to'b', and the confirm button is pressed here, so the letter b is output. If you enter the same number in succession, the changing characters will loop. That is, if you press button 2 five times and then button 0, the letters change from'a'→' b'→'c' →'a' →'b', and the confirm button is pressed here. 'b' is output.
You can press the confirm button when no button is pressed, but in that case no characters are output.
Your job is to recreate the message Alice created from a row of buttons pressed by Alice.
Input
The first line gives the number of test cases. Each test case is then given a string of digits up to 1024 in length in one row.
Output
Print the string of Alice's message line by line for each test case. However, you can assume that the output is one or more and less than 76 characters.
Example
Input
5
20
220
222220
44033055505550666011011111090666077705550301110
000555555550000330000444000080000200004440000
Output
a
b
b
hello, world!
keitai
Submitted Solution:
```
def moji(x,ans):
if ans == 0:
return
if x == 1:
if(ans%4==1):
str = '.'
elif(ans%4==2):
str =','
elif(ans%4==3):
str='!'
else:
str = '?'
if x == 2:
if(ans%3==1):
str = 'a'
elif(ans%3==2):
str = 'b'
else:
str = 'c'
if x == 3:
if(ans%3==1):
str = 'd'
elif(ans%3==2):
str = 'e'
else:
str = 'f'
if x == 4:
if(ans%3==1):
str = 'g'
elif(ans%3==2):
str = 'h'
else:
str = 'i'
if x == 5:
if(ans%3==1):
str = 'j'
elif(ans%3==2):
str = 'k'
else:
str = 'l'
if x == 6:
if(ans%3==1):
str = 'm'
elif(ans%3==2):
str = 'n'
else:
str = 'o'
if x == 7:
if(ans%4==1):
str = 'p'
elif(ans%4==2):
str = 'q'
elif(ans%4==3):
str ='r'
else:
str = 's'
if x == 8:
if(ans%3==1):
str = 't'
elif(ans%3==2):
str = 'u'
else:
str = 'v'
if x == 9:
if(ans%4==1):
str = 'w'
elif(ans%4==2):
str = 'x'
elif ans%4==3:
str = 'y'
else:
str = 'z'
print(str,end="")
def solve(str):
x = '-1'
ans =0
for s in str:
if s == '0':
moji(int(x),ans)
ans = 0
else:
x = s
ans +=1
N = int(input())
for i in range(N):
solve(input())
print()
``` | instruction | 0 | 50,476 | 18 | 100,952 |
No | output | 1 | 50,476 | 18 | 100,953 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a mysterious language (codenamed "Secret") available in "Custom Test" tab. Find out what this language is and write a program which outputs its name. Note that the program must be written in this language.
Input
This program has only one test, and it's empty (it doesn't give your program anything to read).
Output
Output the name of the mysterious language.
Examples
Submitted Solution:
```
print("Secret_171")
``` | instruction | 0 | 50,756 | 18 | 101,512 |
No | output | 1 | 50,756 | 18 | 101,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a mysterious language (codenamed "Secret") available in "Custom Test" tab. Find out what this language is and write a program which outputs its name. Note that the program must be written in this language.
Input
This program has only one test, and it's empty (it doesn't give your program anything to read).
Output
Output the name of the mysterious language.
Examples
Submitted Solution:
```
print('INTERCALL')
``` | instruction | 0 | 50,758 | 18 | 101,516 |
No | output | 1 | 50,758 | 18 | 101,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
unl = int(input())
a = str(input())
b = ["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
x = 0
while x < 8:
if len(b[x]) == len(a):
y = 0
match = 0
while y < unl:
if a[y] == '.' or a[y] == b[x][y]:
match += 1
else:
break
y += 1
if match == unl:
print(b[x])
break
x += 1
``` | instruction | 0 | 50,870 | 18 | 101,740 |
Yes | output | 1 | 50,870 | 18 | 101,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
def match(p, s):
return len(p) == len(s) and all(d in ('.', c) for d, c in zip(p, s))
l = ['vaporeon', 'jolteon', 'flareon', 'espeon',
'umbreon', 'leafeon', 'glaceon', 'sylveon']
input()
p = input()
print(next(s for s in l if match(p, s)))
``` | instruction | 0 | 50,871 | 18 | 101,742 |
Yes | output | 1 | 50,871 | 18 | 101,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
t = ["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
n = int(input())
p = input()
for i in t:
if n == len(i) and all(i[j] == p[j] for j in range(n) if p[j] != '.'):
print(i)
break
``` | instruction | 0 | 50,872 | 18 | 101,744 |
Yes | output | 1 | 50,872 | 18 | 101,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
import re
src=input()
src=input()
data=['Vaporeon', 'Jolteon', 'Flareon', 'Espeon', 'Umbreon', 'Leafeon', 'Glaceon', 'Sylveon']
for mon in data:
mon=mon.lower()
if(len(mon)!=len(src)):
continue
if re.match(src,mon):
print(mon)
break
``` | instruction | 0 | 50,873 | 18 | 101,746 |
Yes | output | 1 | 50,873 | 18 | 101,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
n = int(input())
w = input()
s = list()
for i in w:
if i != '.':
s.append(i)
l = ['vaporeon', 'jolteon', 'flareon', 'espeon', 'umbreon', 'leafeon', 'glaceon'
'sylveon']
for i in l:
if len(w) == len(i):
p = ''
j = 0
while j < len(w):
if w[j] == '.':
p += i[j]
elif w[j] == i[j]:
p += i[j]
else:
break
j += 1
else:
print(p)
break
``` | instruction | 0 | 50,874 | 18 | 101,748 |
No | output | 1 | 50,874 | 18 | 101,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
n=int(input())
k=['vaporeon']
six=['espeon']
sev=['jolteon','flareon','fmbreon','leafeon','glaceon','sylveon']
s=input().strip()
if n==6:print(*six)
elif n==8:print(*k)
else:
p=False
z=[]
for x in range(n):
if s[x]!='.':
z.append((s[x],x))
for x in sev:
for m,n in z:
if x[n]!=m:
break
else:
print(x)
p=True
if p==True:break
``` | instruction | 0 | 50,875 | 18 | 101,750 |
No | output | 1 | 50,875 | 18 | 101,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
import sys
letters = int(sys.stdin.readline().strip())
if letters == 6:
print("espeon")
elif letters == 8:
print("vaporeon")
else:
could_be = ["jolteon","flareon","umbreon","leafeon","glaceon","sylveon"]
info = sys.stdin.readline().strip()
for i in range(7):
if info[i] != ".":
for j in could_be:
if j[i] != info[i]:
could_be.remove(j)
print(could_be[0])
``` | instruction | 0 | 50,876 | 18 | 101,752 |
No | output | 1 | 50,876 | 18 | 101,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Sylveon.
You know the length of the word in the crossword, and you already know some letters. Designers of the crossword made sure that the answer is unambiguous, so you can assume that exactly one pokemon out of the 8 that Eevee evolves into fits the length and the letters given. Your task is to find it.
Input
First line contains an integer n (6 ≤ n ≤ 8) – the length of the string.
Next line contains a string consisting of n characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword).
Output
Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter).
Examples
Input
7
j......
Output
jolteon
Input
7
...feon
Output
leafeon
Input
7
.l.r.o.
Output
flareon
Note
Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"}
Submitted Solution:
```
from re import findall
input()
print(*findall(input().strip(), '$'.join(["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"])))
``` | instruction | 0 | 50,877 | 18 | 101,754 |
No | output | 1 | 50,877 | 18 | 101,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How many strings can be obtained by applying the following operation on a string S exactly K times: "choose one lowercase English letter and insert it somewhere"?
The answer can be enormous, so print it modulo (10^9+7).
Constraints
* K is an integer between 1 and 10^6 (inclusive).
* S is a string of length between 1 and 10^6 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
K
S
Output
Print the number of strings satisfying the condition, modulo (10^9+7).
Examples
Input
5
oof
Output
575111451
Input
37564
whydidyoudesertme
Output
318008117
Submitted Solution:
```
K = int(input())
S = len(input())
mod = 10**9+7
N = K+S
inverse = [0, 1]
for i in range(2, N+1):
inverse.append((-inverse[mod%i]*(mod//i))%mod)
factorial = 1
factorial_inv = [1, 1]
for i in range(2, N+1):
factorial = (factorial*i)%mod
factorial_inv.append((factorial_inv[-1]*inverse[i])%mod)
answer = 0
pow = -1
for i in range(K+1):
if pow == -1:
pow = 1
else:
pow = (pow*25)%mod
answer = (answer+pow*factorial_inv[i]*factorial_inv[N-i])%mod
answer = (answer*factorial)%mod
print(answer)
``` | instruction | 0 | 51,067 | 18 | 102,134 |
Yes | output | 1 | 51,067 | 18 | 102,135 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5 | instruction | 0 | 51,077 | 18 | 102,154 |
"Correct Solution:
```
N = int(input())
S = [x for x in input()]
Q = int(input())
#A1 ... AnのBIT(1-indexed)
BIT = [[0] * (N + 1) for _ in range(26)]
#A1 ~ Aiまでの和 O(logN)
def BIT_query(input_BIT, idx):
res_sum = 0
while idx > 0:
res_sum += input_BIT[idx]
idx -= idx&(-idx)
return res_sum
#Ai += x O(logN)
def BIT_update(input_BIT,idx,x):
while idx <= N:
input_BIT[idx] += x
idx += (idx&(-idx))
return
for i, c in enumerate(S):
BIT_update(BIT[ord(c)-ord('a')], i+1, 1)
for _ in range(Q):
a, b, c = input().rstrip().split()
if int(a) == 1:
BIT_update(BIT[ord(S[int(b)-1])-ord('a')], int(b), -1)
BIT_update(BIT[ord(c)-ord('a')], int(b), 1)
S[int(b)-1] = c
else:
count = 0
for i in range(26):
if BIT_query(BIT[i], int(b)-1) != BIT_query(BIT[i], int(c)):
count += 1
print(count)
``` | output | 1 | 51,077 | 18 | 102,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
import sys
input = sys.stdin.readline
class BIT:
def __init__(self, size):
self.bit = [0]*(size+1)
self.size = size
def sum(self, i):
i += 1
s = 0
while i > 0:
s += self.bit[i]
i -= i & -i
return s
def add(self, i, x):
i += 1
while i <= self.size:
self.bit[i] += x
i += i & -i
N = int(input())
S = list(input().rstrip())
bits = [BIT(N) for _ in range(26)]
for i in range(N):
bits[ord(S[i])-ord('a')].add(i, 1)
Q = int(input())
for _ in range(Q):
t, x, y = input().split()
if t == '1':
i = int(x) - 1
c = y
bits[ord(S[i])-ord('a')].add(i, -1)
bits[ord(c)-ord('a')].add(i, 1)
S[i] = c
else:
l = int(x) - 1
r = int(y) - 1
ans = 0
for i in range(26):
cnt = bits[i].sum(r) - (bits[i].sum(l-1) if l > 0 else 0)
if cnt > 0:
ans += 1
print(ans)
``` | instruction | 0 | 51,083 | 18 | 102,166 |
Yes | output | 1 | 51,083 | 18 | 102,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
N = int(input())
S = list(input())
Q = int(input())
l = 2**((N-1).bit_length())
#data = [Counter([]) for i in range(2*l)]
data = [0] * (2*l)
str2bin = lambda x : 1 << (ord(x) - ord('a'))
for i in range(N):
data[l+i] = str2bin(S[i])
for i in range(l-1,0,-1):
data[i] = data[2*i] | data[2*i+1]
for cnt in range(Q):
a,b,c = input().split()
a = int(a)
b = int(b)
if a == 1:
n = l + b - 1
data[n] = str2bin(c)
n //= 2
while n > 0:
data[n] = data[2*n] | data[2*n+1]
n = n // 2
else:
c = int(c)
i = b + l -1
j = c + l
res = 0
while j-i > 0:
if i & 1:
res |= data[i]
i += 1
if j & 1:
res |= data[j-1]
j -= 1
i //= 2
j //= 2
print(bin(res).count('1'))
``` | instruction | 0 | 51,084 | 18 | 102,168 |
Yes | output | 1 | 51,084 | 18 | 102,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
def main():
import sys
b=sys.stdin.buffer
input=b.readline
n=int(input())
d=[0]*n+[1<<c-97for c in input()[:n]]
for i in range(n-1,0,-1):d[i]=d[i+i]|d[i-~i]
r=[]
input()
for q,a,b in zip(*[iter(b.read().split())]*3):
i,s=int(a)+n-1,0
if q<b'2':
d[i]=1<<b[0]-97
while i:
i//=2
d[i]=d[i+i]|d[i-~i]
continue
j=int(b)+n
while i<j:
if i&1:
s|=d[i]
i+=1
if j&1:
j-=1
s|=d[j]
i//=2
j//=2
r+=bin(s).count('1'),
print(' '.join(map(str,r)))
main()
``` | instruction | 0 | 51,085 | 18 | 102,170 |
Yes | output | 1 | 51,085 | 18 | 102,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
n=int(input())
from bisect import bisect_left,bisect_right
s=list(input())
q=int(input())
D={chr(ord("a")+i):[] for i in range(26)}
for i ,j in enumerate(s):
D[j].append(i)
ans=0
for i in range(q):
x=list(input().split())
if x[0]=="1":
l=int(x[1])
l-=1
r=x[-1]
if r==s[l]:
continue
rr=bisect_left(D[r],l)
D[s[l]].remove(l)
D[r].insert(rr,l)
s[l]=r
else:
l=int(x[1])
r=int(x[2])
l-=1
r-=1
ans=0
for i in range(26):
W=chr(ord("a")+i)
ll=bisect_left(D[W],l)
rr=bisect_right(D[W],r)
if rr-ll>0:
ans+=1
print(ans)
``` | instruction | 0 | 51,086 | 18 | 102,172 |
Yes | output | 1 | 51,086 | 18 | 102,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
n=int(input())
s=input()
q=int(input())
for i in range(q):
type,iq,q=map(str,input().split())
if type == "1":
s = "".join([s[:int(iq)-1],q,s[int(iq):]])
else:
print(len(set(s[int(iq)-1:int(q)])))
``` | instruction | 0 | 51,087 | 18 | 102,174 |
No | output | 1 | 51,087 | 18 | 102,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
# coding: utf-8
import sys
sysread = sys.stdin.readline
from collections import defaultdict
sys.setrecursionlimit(10**7)
def run():
N = int(input())
S = list(input())
Q = int(input())
queries = [sysread().split() for _ in range(Q)]
bins = [0] * 26# a: ord('a') - 97
for i,s in enumerate(S[::-1]):
id = ord(s) - 97
bins[id] |= 1<<i
for type, i, c in queries:
if type == '1':
i = int(i) - 1
old = ord(S[i]) - 97
new = ord(c) - 97
bins[old] -= 1<<(N-1-i)
bins[new] |= 1<<(N-1-i)
S[i] = c
else:
i,c= int(i), int(c)
ret = 0
for v in bins:
v >>= N-c
if v & int("1"*(c-i+1),2):
ret+=1
print(ret)
if __name__ == "__main__":
run()
``` | instruction | 0 | 51,088 | 18 | 102,176 |
No | output | 1 | 51,088 | 18 | 102,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
import bisect
alp = "abcdefghijklmnopqrstuvwxyz"
N = int(input())
S = list(input())
Q = int(input())
A = [[] for i in range(len(alp))]
for i in range(N):
A[alp.index(S[i])].append(i)
for i in range(Q):
q = list(input().split())
if q[0]=="1":
iq,cq = int(q[1]),q[2]
s = S[iq-1]
b = bisect.bisect(A[alp.index(s)],iq-1)
A[alp.index(s)].pop(b-1)
bisect.insort(A[alp.index(cq)],iq-1)
S[iq-1]=cq
else:
lq,rq = int(q[1]),int(q[2])
cnt = 0
for i in range(len(alp)):
if A[i]==[]:continue
b = bisect.bisect(A[i],lq-1)
c = A[i][min(len(A[i])-1,b)]
if lq<=c+1<=rq:cnt+=1
print(cnt)
continue
``` | instruction | 0 | 51,089 | 18 | 102,178 |
No | output | 1 | 51,089 | 18 | 102,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of lowercase English letters.
Process Q queries of the following two types:
* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).
Constraints
* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.
Input
Input is given from Standard Input in the following format:
N
S
Q
Query_1
\vdots
Query_Q
Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:
1 i_q c_q
2 l_q r_q
Output
For each query of type 2, print a line containing the answer.
Example
Input
7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7
Output
3
1
5
Submitted Solution:
```
import sys
input = sys.stdin.readline
n = int(input())
s = list(input())
def segfunc(x,y):
return x|y
def init(init_val):
#set_val
for i in range(n):
seg[i+num-1]=init_val[i]
#built
for i in range(num-2,-1,-1) :
seg[i]=segfunc(seg[2*i+1],seg[2*i+2])
def update(k,x):
k += num-1
seg[k] = x
while k:
k = (k-1)//2
seg[k] = segfunc(seg[k*2+1],seg[k*2+2])
def query(p,q):
if q<=p:
return ide_ele
p += num-1
q += num-2
res=ide_ele
while q-p>1:
if p&1 == 0:
res = segfunc(res,seg[p])
if q&1 == 1:
res = segfunc(res,seg[q])
q -= 1
p = p//2
q = (q-1)//2
if p == q:
res = segfunc(res,seg[p])
else:
res = segfunc(segfunc(res,seg[p]),seg[q])
return res
#####単位元######
ide_ele = set()
#num:n以上の最小の2のべき乗
num =2**(n-1).bit_length()
seg=[ide_ele]*2*num
A = []
for i in range(n):
A.append(set(s[i]))
init(A)
q = int(input())
for _ in range(q):
p,a,b = input().split()
if p == "1":
update(int(a)-1,set(b))
if p == "2":
print(len(query(int(a)-1,int(b))))
``` | instruction | 0 | 51,090 | 18 | 102,180 |
No | output | 1 | 51,090 | 18 | 102,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Boolean Expression Compressor
You are asked to build a compressor for Boolean expressions that transforms expressions to the shortest form keeping their meaning.
The grammar of the Boolean expressions has terminals `0` `1` `a` `b` `c` `d` `-` `^` `*` `(` `)`, start symbol <E> and the following production rule:
> <E> ::= `0` | `1` | `a` | `b` | `c` | `d` | `-`<E> | `(`<E>`^`<E>`)` | `(`<E>`*`<E>`)`
Letters `a`, `b`, `c` and `d` represent Boolean variables that have values of either `0` or `1`. Operators are evaluated as shown in the Table below. In other words, `-` means negation (NOT), `^` means exclusive disjunction (XOR), and `*` means logical conjunction (AND).
Table: Evaluations of operators
<image>
Write a program that calculates the length of the shortest expression that evaluates equal to the given expression with whatever values of the four variables.
For example, `0`, that is the first expression in the sample input, cannot be shortened further. Therefore the shortest length for this expression is 1.
For another example, `(a*(1*b))`, the second in the sample input, always evaluates equal to `(a*b)` and `(b*a)`, which are the shortest. The output for this expression, thus, should be `5`.
Input
The input consists of multiple datasets. A dataset consists of one line, containing an expression conforming to the grammar described above. The length of the expression is less than or equal to 16 characters.
The end of the input is indicated by a line containing one `.` (period). The number of datasets in the input is at most 200.
Output
For each dataset, output a single line containing an integer which is the length of the shortest expression that has the same value as the given expression for all combinations of values in the variables.
Sample Input
0
(a*(1*b))
(1^a)
(-(-a*-b)*a)
(a^(b^(c^d)))
.
Output for the Sample Input
1
5
2
1
13
Example
Input
0
(a*(1*b))
(1^a)
(-(-a*-b)*a)
(a^(b^(c^d)))
.
Output
1
5
2
1
13
Submitted Solution:
```
a=65280; b=61680; c=52428; d=43690; e=65535
from heapq import heappush, heappop
Q = [(1, a), (1, b), (1, c), (1, d)]
L = {a: 1, b: 1, c: 1, d: 1, e: 1, e: 1, 0: 1}
H = []
get = L.get
push = H.append
while Q:
l, p = heappop(Q)
if L[p] < l: continue
if l+1 < get(p ^ e, 17):
L[p ^ e] = l+1
l < 15 and heappush(Q, (l+1, p ^ e))
if l < 13:
li = 13-l; l3 = 3+l
for q, r in H:
if r <= li:
k = p & q
if r < get(k, 17)-l3:
L[k] = l3+r
r < li and heappush(Q, (l3+r, k))
k = p ^ q
if r < get(k, 17)-l3:
L[k] = l3+r
r < li and heappush(Q, (l3+r, k))
else: break
if l < 7: push((p, l))
print(*map(L.__getitem__, eval("e&"+",e&".join(open(0).read().replace(*"-~").replace(*"*&").replace(*"1e").split()[:-1]))),sep='\n')
``` | instruction | 0 | 51,256 | 18 | 102,512 |
Yes | output | 1 | 51,256 | 18 | 102,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Boolean Expression Compressor
You are asked to build a compressor for Boolean expressions that transforms expressions to the shortest form keeping their meaning.
The grammar of the Boolean expressions has terminals `0` `1` `a` `b` `c` `d` `-` `^` `*` `(` `)`, start symbol <E> and the following production rule:
> <E> ::= `0` | `1` | `a` | `b` | `c` | `d` | `-`<E> | `(`<E>`^`<E>`)` | `(`<E>`*`<E>`)`
Letters `a`, `b`, `c` and `d` represent Boolean variables that have values of either `0` or `1`. Operators are evaluated as shown in the Table below. In other words, `-` means negation (NOT), `^` means exclusive disjunction (XOR), and `*` means logical conjunction (AND).
Table: Evaluations of operators
<image>
Write a program that calculates the length of the shortest expression that evaluates equal to the given expression with whatever values of the four variables.
For example, `0`, that is the first expression in the sample input, cannot be shortened further. Therefore the shortest length for this expression is 1.
For another example, `(a*(1*b))`, the second in the sample input, always evaluates equal to `(a*b)` and `(b*a)`, which are the shortest. The output for this expression, thus, should be `5`.
Input
The input consists of multiple datasets. A dataset consists of one line, containing an expression conforming to the grammar described above. The length of the expression is less than or equal to 16 characters.
The end of the input is indicated by a line containing one `.` (period). The number of datasets in the input is at most 200.
Output
For each dataset, output a single line containing an integer which is the length of the shortest expression that has the same value as the given expression for all combinations of values in the variables.
Sample Input
0
(a*(1*b))
(1^a)
(-(-a*-b)*a)
(a^(b^(c^d)))
.
Output for the Sample Input
1
5
2
1
13
Example
Input
0
(a*(1*b))
(1^a)
(-(-a*-b)*a)
(a^(b^(c^d)))
.
Output
1
5
2
1
13
Submitted Solution:
```
a=65280; b=61680; c=52428; d=43690; e=65535
QS = [[] for i in range(17)]
QS[1] = [a, b, c, d]
L = {a: 1, b: 1, c: 1, d: 1, e: 1, e: 1, 0: 1}
H = []
get = L.get
push = H.append
for l in range(1, 16):
Q = QS[l]
li = 13-l; l3 = l+3; l1 = l+1
pop = Q.pop
pushQN = QS[l1].append
while Q:
p = pop()
if L[p] < l: continue
if l < 13:
if l1 < get(p ^ e, 17):
L[p ^ e] = l1
pushQN(p ^ e)
for q, r in H:
if r < li:
if l3+r < get(p & q, 17): L[p & q] = l3+r; QS[l3+r].append(p & q)
if l3+r < get(p ^ q, 17): L[p ^ q] = l3+r; QS[l3+r].append(p ^ q)
elif r == li:
if p & q not in L: L[p & q] = 16
if p ^ q not in L: L[p ^ q] = 16
else: break
l < 7 and push((p, l))
elif l1 < get(p ^ e, 17): L[p ^ e] = l1
print(*map(L.__getitem__, eval("e&"+",e&".join(open(0).read().replace(*"-~").replace(*"*&").replace(*"1e").split()[:-1]))),sep='\n')
``` | instruction | 0 | 51,257 | 18 | 102,514 |
Yes | output | 1 | 51,257 | 18 | 102,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A telephone number is a sequence of exactly 11 digits, where the first digit is 8. For example, the sequence 80011223388 is a telephone number, but the sequences 70011223388 and 80000011223388 are not.
You are given a string s of length n, consisting of digits.
In one operation you can delete any character from string s. For example, it is possible to obtain strings 112, 111 or 121 from string 1121.
You need to determine whether there is such a sequence of operations (possibly empty), after which the string s becomes a telephone number.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains one integer n (1 ≤ n ≤ 100) — the length of string s.
The second line of each test case contains the string s (|s| = n) consisting of digits.
Output
For each test print one line.
If there is a sequence of operations, after which s becomes a telephone number, print YES.
Otherwise, print NO.
Example
Input
2
13
7818005553535
11
31415926535
Output
YES
NO
Note
In the first test case you need to delete the first and the third digits. Then the string 7818005553535 becomes 88005553535.
Submitted Solution:
```
t = int(input())
for i in range(t):
s = int(input())
a = 'YES'
m = list(input())
try:
ind_8 = m.index('8')
except ValueError:
ind_8 = s
if s - ind_8 - 1 < 10:
a = 'NO'
print(a)
``` | instruction | 0 | 51,388 | 18 | 102,776 |
Yes | output | 1 | 51,388 | 18 | 102,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A telephone number is a sequence of exactly 11 digits, where the first digit is 8. For example, the sequence 80011223388 is a telephone number, but the sequences 70011223388 and 80000011223388 are not.
You are given a string s of length n, consisting of digits.
In one operation you can delete any character from string s. For example, it is possible to obtain strings 112, 111 or 121 from string 1121.
You need to determine whether there is such a sequence of operations (possibly empty), after which the string s becomes a telephone number.
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
The first line of each test case contains one integer n (1 ≤ n ≤ 100) — the length of string s.
The second line of each test case contains the string s (|s| = n) consisting of digits.
Output
For each test print one line.
If there is a sequence of operations, after which s becomes a telephone number, print YES.
Otherwise, print NO.
Example
Input
2
13
7818005553535
11
31415926535
Output
YES
NO
Note
In the first test case you need to delete the first and the third digits. Then the string 7818005553535 becomes 88005553535.
Submitted Solution:
```
t=int(input())
for i in range(t):
n=int(input())
s=list(input().strip())
if '8' in s[:n-9]:
print('YES')
else:
print('NO')
``` | instruction | 0 | 51,391 | 18 | 102,782 |
No | output | 1 | 51,391 | 18 | 102,783 |
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