message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
s = input()
if (s.count('c') == s.count('a') or s.count('c') == s.count('b')) and (s.find('a') < s.find('b') and s.rfind('a') < s.find('b') and
s.find('b') < s.find('c') and s.rfind('b') < s.find('c') and
s.count('a') and s.count('b') and s.count('c')):
print('YES')
else:
print('NO')
``` | instruction | 0 | 56,918 | 18 | 113,836 |
Yes | output | 1 | 56,918 | 18 | 113,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
import re
s = input()
#counting
def count(x):
r = re.compile('{}+'.format(x))
m = r.search(s)
xa = len(m.group())
return xa
#order checking
r = re.compile(r'a+b+c+')
m = r.search(s)
if m!=None and m.group()==s:
xa = count('a')
xb = count('b')
xc = count('c')
if xc==xa or xc==xb:
print('YES')
else:
print('NO')
else:
print('NO')
``` | instruction | 0 | 56,919 | 18 | 113,838 |
Yes | output | 1 | 56,919 | 18 | 113,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
s = list(str(input()))
s1 = s
s1.sort()
if s1 != s:
print("NO")
else:
ca = 0
cb = 0
cc = 0
for i in s:
if i == 'a':
ca += 1
elif i == 'b':
cb += 1
elif i == 'c':
cc += 1
if cc == ca or cc == cb:
print("YES")
else:
print("NO")
``` | instruction | 0 | 56,920 | 18 | 113,840 |
No | output | 1 | 56,920 | 18 | 113,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
s = input()
if 'c' not in s or s == 'c' or 'a' not in s or 'b' not in s or s == 'b' or s == 'a' or s == 'abca' or s== 'abac':
print('NO')
else:
if s.index('a') > s.index('b') or s.index('b') > s.index('c'):
print('NO')
else:
if s.count('c') in [s.count('b'),s.count('a')]:
print('YES')
else:
print('NO')
``` | instruction | 0 | 56,921 | 18 | 113,842 |
No | output | 1 | 56,921 | 18 | 113,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
import sys
data = sys.stdin.readlines()[0].split()[0]
counters = [0, 0, 0]
ok = True
for idx, letter in enumerate(data):
if idx > 1:
if letter >= data[idx - 1]:
counters[ord(letter) - ord('a')] += 1
else:
ok = False
break
else:
counters[ord(letter) - ord('a')] += 1
if (counters[0] > 0 and counters[1] > 0 and
(counters[2] == counters[0] or counters[2] == counters[1]) and
ok is True):
print("YES")
else:
print("NO")
``` | instruction | 0 | 56,922 | 18 | 113,844 |
No | output | 1 | 56,922 | 18 | 113,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
a=input()
s=[0]*3
c=1
for i in range(len(a)):
if a[i]!='a' and s[0]==0 or a[i]=='c' and s[1]==0 or a[i]=='a' and s[1]>0:
c=0
break
if a[i]=='a':
s[0]+=1
elif a[i]=='b':
s[1]+=1
elif a[i]=='c':
s[2]+=1
if c>0:
if s[2]==s[0] or s[2]==s[1]:
print("YES")
else:
print("NO")
else:
print("NO")
``` | instruction | 0 | 56,923 | 18 | 113,846 |
No | output | 1 | 56,923 | 18 | 113,847 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL | instruction | 0 | 57,416 | 18 | 114,832 |
Tags: *special, implementation
Correct Solution:
```
s, n = input(), int(input())
res = ''
for x in s.lower():
if ord(x) < n + 97: res += x.upper()
else: res += x
print(res)
``` | output | 1 | 57,416 | 18 | 114,833 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL | instruction | 0 | 57,417 | 18 | 114,834 |
Tags: *special, implementation
Correct Solution:
```
s=input()
n=int(input())
s=s.lower()
ans=""
for i in range(len(s)):
x=s[i]
if(ord(x)<n+97):
ans+=x.upper()
else:
ans+=x.lower()
print(ans)
``` | output | 1 | 57,417 | 18 | 114,835 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL | instruction | 0 | 57,418 | 18 | 114,836 |
Tags: *special, implementation
Correct Solution:
```
s = input().lower()
k = int(input())
result = ''.join(c.upper()
if ord(c) < k+97
else c.lower()
for c in s)
print(result)
``` | output | 1 | 57,418 | 18 | 114,837 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL | instruction | 0 | 57,419 | 18 | 114,838 |
Tags: *special, implementation
Correct Solution:
```
a, s = input().lower(), int(input())
print(''.join(t.upper() if ord(t) < s + 97 else t.lower() for t in a))
``` | output | 1 | 57,419 | 18 | 114,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
a = input().lower()
num = int(input())
c = ""
for i in a:
if ord(i) < num+97:
c += i.upper()
else:
c += i.lower()
print(c)
``` | instruction | 0 | 57,420 | 18 | 114,840 |
Yes | output | 1 | 57,420 | 18 | 114,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
s=input();s=s.lower();s=(' '.join(s)).split();n=int(input())
for i in range(0,len(s)):
if n+96>=ord(s[i]):
s[i]=chr(ord(s[i])-32)
for j in range(0,len(s)):
print(s[j],end='')
``` | instruction | 0 | 57,421 | 18 | 114,842 |
Yes | output | 1 | 57,421 | 18 | 114,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
x = "abcdefghijklmnopqrstuvwxyz"
X = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
z = list(input())
n = int(input())
for i in range(len(z)):
if(z[i] in x):
k = x.index(z[i]) + 1
else:
k = X.index(z[i]) + 1
if(k <= n):
z[i] = z[i].upper()
else:
z[i] = z[i].lower()
ans = "".join(z)
print(ans)
``` | instruction | 0 | 57,422 | 18 | 114,844 |
Yes | output | 1 | 57,422 | 18 | 114,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
s = input()
n = int(input())
s = s.lower()
f = ""
for i in range(len(s)):
o = s[i]
if ord(o) < n + 97:
f += o.upper()
else:
f += o.lower()
print(f)
``` | instruction | 0 | 57,423 | 18 | 114,846 |
Yes | output | 1 | 57,423 | 18 | 114,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
s = input()
x = int(input())
print(s)
``` | instruction | 0 | 57,424 | 18 | 114,848 |
No | output | 1 | 57,424 | 18 | 114,849 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
x = "abcdefghijklmnopqrstuvwxyz"
X = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
z = list(input())
n = int(input())
for i in range(len(z)):
if(z[i] in x):
k = x.index(z[i]) + 1
else:
k = X.index(z[i]) + 1
if(k < n):
z[i] = z[i].upper()
else:
z[i] = z[i].lower()
ans = "".join(z)
print(ans)
``` | instruction | 0 | 57,425 | 18 | 114,850 |
No | output | 1 | 57,425 | 18 | 114,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
s=input();s=s.lower();s=(' '.join(s)).split();n=int(input())
for i in range(0,len(s)):
if n+96>ord(s[i]):
s[i]=chr(ord(s[i])-32)
for j in range(0,len(s)):
print(s[j],end='')
``` | instruction | 0 | 57,426 | 18 | 114,852 |
No | output | 1 | 57,426 | 18 | 114,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
<image>
Input
The first line of the input is a string (between 1 and 50 characters long, inclusive). Each character will be a letter of English alphabet, lowercase or uppercase.
The second line of the input is an integer between 0 and 26, inclusive.
Output
Output the required string.
Examples
Input
AprilFool
14
Output
AprILFooL
Submitted Solution:
```
s = input()
k = int(input())
result = ''.join(c.upper()
if ord(c) < k+96
else c.lower()
for c in s)
print(result)
``` | instruction | 0 | 57,427 | 18 | 114,854 |
No | output | 1 | 57,427 | 18 | 114,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
a = list(input())
b = list(input())
n = len(a)
if len(a) == 1:
print(a[0])
exit(0)
a.sort()
b.sort()
a = a[:(len(a) + 1) // 2]
if n % 2 == 1:
b = b[(len(b) // 2) + 1:]
else:
b = b[(len(b) // 2):]
sa = 0
ea = len(a) - 1
sb = 0
eb = len(b) - 1
stb = 0
ste = n - 1
st = [""] * n
for i in range(n):
if i % 2 == 0:
if a[sa] < b[eb]:
st[stb] = a[sa]
sa += 1
stb += 1
else:
st[ste] = a[ea]
ea -= 1
ste -= 1
else:
if eb == sb and n % 2 == 0:
st[stb] = b[eb]
break
if b[eb] > a[sa]:
st[stb] = b[eb]
eb -= 1
stb += 1
else:
st[ste] = b[sb]
ste -= 1
sb += 1
for i in range(len(st)):
print(st[i], end="")
``` | instruction | 0 | 58,561 | 18 | 117,122 |
Yes | output | 1 | 58,561 | 18 | 117,123 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
from collections import deque
oleg = sorted(list(input()))
n = len(oleg)
oleg = deque(oleg[:(n-(n//2))])
igor = deque(sorted(list(input()),reverse = True)[:(n//2)])
result = ["" for i in range(n)]
result_front = 0
result_rear = -1
igor_turn = True
while result_front-result_rear-1 < n:
if igor_turn:
if len(igor) == 0 or oleg[0] < igor[0]:
result[result_front] = oleg.popleft()
result_front+=1
else:
result[result_rear] = oleg.pop()
result_rear-=1
else:
if len(oleg) == 0 or igor[0] > oleg[0]:
result[result_front] = igor.popleft()
result_front+=1
else:
result[result_rear] = igor.pop()
result_rear-=1
#print(result)
igor_turn = not igor_turn
print("".join(result))
``` | instruction | 0 | 58,562 | 18 | 117,124 |
Yes | output | 1 | 58,562 | 18 | 117,125 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
def main():
from collections import deque
import sys
input = sys.stdin.readline
s = list(input())[:-1]
t = list(input())[:-1]
n = len(s)
s.sort()
t.sort(reverse=True)
s = deque(s[:(n + 1) // 2])
t = deque(t[:n // 2])
f = 0
al, ar = "", ""
for i in range(n):
if i % 2:
if s and s[0] >= t[0]: f = 1
if f: ar += t.pop()
else: al += t.popleft()
else:
if t and s[0] >= t[0]: f = 1
if f: ar += s.pop()
else: al += s.popleft()
print(al + ar[::-1])
if __name__ == '__main__':
main()
``` | instruction | 0 | 58,563 | 18 | 117,126 |
Yes | output | 1 | 58,563 | 18 | 117,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
from operator import lt, gt
s = [sorted(input()), sorted(input(), reverse=True)]
n = len(s[0])
idx = [[0, (n >> 1) + (n & 1) - 1], [0, (n >> 1) - 1]]
op = [lt, gt]
l, r = 0, n-1
ans = ['*'] * n
for i in range(n):
p = i & 1
if op[p](s[p][idx[p][0]], s[p ^ 1][idx[p ^ 1][0]]):
ans[l] = s[p][idx[p][0]]
l += 1
idx[p][0] += 1
else:
ans[r] = s[p][idx[p][1]]
r -= 1
idx[p][1] -= 1
print(*ans, sep='')
``` | instruction | 0 | 58,564 | 18 | 117,128 |
Yes | output | 1 | 58,564 | 18 | 117,129 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
A = list(input())
B = list(input())
A = sorted(A)
B = sorted(B)[::-1]
n = len(A)
for i in range(n):
if i % 2:
print(B[i//2], end="")
else:
print(A[i//2], end="")
print("")
``` | instruction | 0 | 58,565 | 18 | 117,130 |
No | output | 1 | 58,565 | 18 | 117,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
oleg = ''.join(sorted(input()))
igor = ''.join(sorted(input(), reverse=True))
n = len(oleg)
name = []
ig = 0
ol = 0
for i in range(n):
if i % 2 == 0:
name.append(oleg[ol])
ol += 1
else:
name.append(igor[ig])
ig += 1
print(''.join(name))
``` | instruction | 0 | 58,566 | 18 | 117,132 |
No | output | 1 | 58,566 | 18 | 117,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
s1 = input().strip()
O = [0]*26
for znak in s1:
c = (ord(znak) - 97) % 26
O[c] += 1
s2 = input().strip()
I = [0]*26
for znak in s2:
c = (ord(znak) - 97) % 26
I[c] += 1
dolzinaO = len(s1)//2
if len(s1) % 2 == 1:
dolzinaO += 1
dolzinaI = len(s1)//2
accO = 0
i = 0
while accO <= dolzinaO:
if accO + O[i] >= dolzinaO:
O[i] -= accO + O[i] - dolzinaO
accO = dolzinaO
for j in range(i+1, 26):
O[j] = 0
break
else:
accO += O[i]
i += 1
accI = 0
i = 25
while accI <= dolzinaI:
if accI + I[i] >= dolzinaI:
I[i] -= accI + I[i] - dolzinaI
accI = dolzinaI
for j in range(i):
I[j] = 0
break
else:
accI += I[i]
i -= 1
RESITEV = [None]*len(s1)
zacetni = 0
koncni = len(s1) - 1
cnt = len(s1)
mo = 0
while O[mo] == 0:
mo += 1
Mo = 25
while O[Mo] == 0:
Mo -= 1
mi = 0
while I[mi] == 0:
mi += 1
MI = 25
while I[MI] == 0:
MI -= 1
na_potezi = True
while cnt > 0:
if na_potezi: #OLEG NA POTEZI
if MI < mo:
RESITEV[koncni] = Mo
O[Mo] -= 1
while Mo >= 0 and O[Mo] == 0:
Mo -= 1
na_potezi = not na_potezi
cnt -= 1
koncni -= 1
else:
RESITEV[zacetni] = mo
O[mo] -= 1
while mo < 26 and O[mo] == 0:
mo += 1
na_potezi = not na_potezi
cnt -= 1
zacetni += 1
else:
if MI < mo:
RESITEV[koncni] = mi
I[mi] -= 1
while mi < 26 and I[mi] == 0:
mi += 1
na_potezi = not na_potezi
cnt -= 1
koncni -= 1
else:
RESITEV[zacetni] = MI
I[MI] -= 1
while MI >= 0 and I[MI] == 0:
MI -= 1
na_potezi = not na_potezi
cnt -= 1
zacetni += 1
prava = []
for e in RESITEV:
prava.append(chr(e + 97))
print(''.join(prava))
``` | instruction | 0 | 58,567 | 18 | 117,134 |
No | output | 1 | 58,567 | 18 | 117,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Oleg the client and Igor the analyst are good friends. However, sometimes they argue over little things. Recently, they started a new company, but they are having trouble finding a name for the company.
To settle this problem, they've decided to play a game. The company name will consist of n letters. Oleg and Igor each have a set of n letters (which might contain multiple copies of the same letter, the sets can be different). Initially, the company name is denoted by n question marks. Oleg and Igor takes turns to play the game, Oleg moves first. In each turn, a player can choose one of the letters c in his set and replace any of the question marks with c. Then, a copy of the letter c is removed from his set. The game ends when all the question marks has been replaced by some letter.
For example, suppose Oleg has the set of letters {i, o, i} and Igor has the set of letters {i, m, o}. One possible game is as follows :
Initially, the company name is ???.
Oleg replaces the second question mark with 'i'. The company name becomes ?i?. The set of letters Oleg have now is {i, o}.
Igor replaces the third question mark with 'o'. The company name becomes ?io. The set of letters Igor have now is {i, m}.
Finally, Oleg replaces the first question mark with 'o'. The company name becomes oio. The set of letters Oleg have now is {i}.
In the end, the company name is oio.
Oleg wants the company name to be as lexicographically small as possible while Igor wants the company name to be as lexicographically large as possible. What will be the company name if Oleg and Igor always play optimally?
A string s = s1s2...sm is called lexicographically smaller than a string t = t1t2...tm (where s ≠ t) if si < ti where i is the smallest index such that si ≠ ti. (so sj = tj for all j < i)
Input
The first line of input contains a string s of length n (1 ≤ n ≤ 3·105). All characters of the string are lowercase English letters. This string denotes the set of letters Oleg has initially.
The second line of input contains a string t of length n. All characters of the string are lowercase English letters. This string denotes the set of letters Igor has initially.
Output
The output should contain a string of n lowercase English letters, denoting the company name if Oleg and Igor plays optimally.
Examples
Input
tinkoff
zscoder
Output
fzfsirk
Input
xxxxxx
xxxxxx
Output
xxxxxx
Input
ioi
imo
Output
ioi
Note
One way to play optimally in the first sample is as follows :
* Initially, the company name is ???????.
* Oleg replaces the first question mark with 'f'. The company name becomes f??????.
* Igor replaces the second question mark with 'z'. The company name becomes fz?????.
* Oleg replaces the third question mark with 'f'. The company name becomes fzf????.
* Igor replaces the fourth question mark with 's'. The company name becomes fzfs???.
* Oleg replaces the fifth question mark with 'i'. The company name becomes fzfsi??.
* Igor replaces the sixth question mark with 'r'. The company name becomes fzfsir?.
* Oleg replaces the seventh question mark with 'k'. The company name becomes fzfsirk.
For the second sample, no matter how they play, the company name will always be xxxxxx.
Submitted Solution:
```
oleg = [c for c in input()]
igor = [c for c in input()]
oleg.sort()
igor.sort()
count = len(oleg)
o = 0
ig = -1
out = ""
for i in range(count // 2):
out += oleg[o] + igor[ig]
o += 1
ig -= 1
if count % 2 == 1:
out += oleg[o]
print(out)
``` | instruction | 0 | 58,568 | 18 | 117,136 |
No | output | 1 | 58,568 | 18 | 117,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
import sys
def main():
n, m = map(int, sys.stdin.readline().split())
matrix = []
for _ in range(n):
row = sys.stdin.readline()
matrix.append(list(row)[:-1])
s = ""
for i in range(n):
for j in range(m):
c = matrix[i][j]
if checkRow(matrix[i], c, j) and checkColumn([col[j] for col in matrix], c, i):
s += c
print(s)
def checkRow(a, element, j):
for col, s in enumerate(a):
if element == s and col != j:
return False
return True
def checkColumn(a, element, i):
for row, s in enumerate(a):
if element == s and row != i:
return False
return True
if __name__ == "__main__":
main()
``` | instruction | 0 | 58,620 | 18 | 117,240 |
Yes | output | 1 | 58,620 | 18 | 117,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
n, m = map(int, input().split())
s = [input() for i in range(n)]
ans = ""
for i in range(n):
for j in range(m):
if s[i][j] in s[i][:j] + s[i][j + 1:]:
continue
c = 0
for x in range(n):
if s[x][j] == s[i][j]:
c += 1
if c == 1:
ans += s[i][j]
print(ans)
``` | instruction | 0 | 58,621 | 18 | 117,242 |
Yes | output | 1 | 58,621 | 18 | 117,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
n,m=map(int,input().split())
r=[]
c=[]
for i in range(n):
r.append(list(input()))
for j in range(m):
c.append([r[i][j] for i in range(n)])
for i in range(n):
freq={}
for j in range(m):
if r[i][j] in freq:
freq[r[i][j]]+=1
else:
freq[r[i][j]]=1
for j in range(m):
if freq[r[i][j]]>1:
r[i][j]='-'
for j in range(m):
freq={}
for i in range(n):
if c[j][i] in freq:
freq[c[j][i]]+=1
else:
freq[c[j][i]]=1
for i in range(n):
if freq[c[j][i]]>1:
c[j][i]='-'
ans=[]
for i in range(n):
for j in range(m):
if r[i][j]!='-' and c[j][i]!='-':
ans.append(r[i][j])
print(''.join(ans))
``` | instruction | 0 | 58,622 | 18 | 117,244 |
Yes | output | 1 | 58,622 | 18 | 117,245 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
#African crossword
N = 100
M = 100
reference = [[1 for j in range(M)] for i in range(N)]
def screen_map(in_map, n, m):
for i in range(n):
for j in range(m):
ch = in_map[i][j]
for k in range(j+1, m, 1):
if in_map[i][k] == ch:
reference[i][k] = 0
reference[i][j] = 0
def screen_map1(in_map, n, m):
for i in range(n):
for j in range(m):
#if reference[j][i] == 1:
ch = in_map[i][j]
for k in range(j+1, m, 1):
if in_map[i][k] == ch:
reference[k][i] = 0
reference[j][i] = 0
def transpose_map(in_map, n, m):
out_map = [['' for i in range(n)] for j in range(m)]
for i in range(n):
for j in range(m):
out_map[j][i] = in_map[i][j]
return out_map
if __name__ == '__main__':
n, m = map(int,input().split())
input_map = [['' for j in range(m)] for i in range(n)]
trans_map = [['' for i in range(n)] for j in range(m)]
#reference = [[1 for j in range(m)] for i in range(n)]
for i in range(n):
input_map[i] = list(input())
screen_map(input_map,n,m)
trans_map = transpose_map(input_map, n, m)
screen_map1(trans_map,m,n)
for i in range(n):
for j in range(m):
if reference[i][j] == 1:
print(input_map[i][j], end ='')
``` | instruction | 0 | 58,623 | 18 | 117,246 |
Yes | output | 1 | 58,623 | 18 | 117,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
def sort_by_row(arr):
return arr[0]
def sort_by_col(arr):
return arr[1]
num_input = input()
num_input = num_input.split(" ")
n = int(num_input[0])
m = int(num_input[1])
table = []
for i in range(0, n):
row = input()
print(row)
row = list(row)
table.append(row)
map = {}
for i in range(0,n):
for j in range(0, m):
if table[i][j] in map:
map[table[i][j]].append([i,j])
else:
temp = [[i,j]]
map[table[i][j]] = temp
for key in map.keys():
value = map[key]
value.sort(key=sort_by_row)
for i in range(0, len(value) - 1):
if value[i][0] == value[i+1][0]:
table[value[i][0]][value[i][1]] = "_"
table[value[i + 1][0]][value[i + 1][1]] = "_"
value.sort(key=sort_by_col)
for i in range(0, len(value) - 1):
if value[i][1] == value[i+1][1]:
table[value[i][0]][value[i][1]] = "_"
table[value[i + 1][0]][value[i + 1][1]] = "_"
res = ""
for i in range(0, n):
for j in range(0, m):
if table[i][j] != "_":
res = res + table[i][j]
print(res)
``` | instruction | 0 | 58,624 | 18 | 117,248 |
No | output | 1 | 58,624 | 18 | 117,249 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
from collections import Counter
n,m = map(int,input().split())
f = ''
s = ''
for _ in range(n):
a = input()
b = Counter(a)
c = ''
for i in range(m):
if b.get(a[i])>1:
c+='1'
else:
c+='0'
f+= c
s+= a
for i in range(n):
d = s[i::m]
e = Counter(d)
for j in range(m):
if e.get(d[j])>1:
f=f[:i+j*m]+'1'+f[i+j*m+1:]
s1 = ''
for i in range(n*m):
if f[i]=='0':
s1+=s[i]
print(s1)
``` | instruction | 0 | 58,625 | 18 | 117,250 |
No | output | 1 | 58,625 | 18 | 117,251 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
def transpose(l1, l2):
# iterate over list l1 to the length of an item
for i in range(len(l1[0])):
# print(i)
row = []
for item in l1:
# appending to new list with values and index positions
# i contains index position and item contains values
row.append(item[i])
l2.append(row)
return l2
n,m = map(int,input().split())
t=n
l=[]
while(t):
s = input()
l1 = list(s)
l.append(l1)
t-=1
l2 = []
l2 = transpose(l,l2)
l4=[]
for i in range(m):
la=l[i]
for j in range(m):
l3=l2[j]
if(l3.count(l[i][j])==1 and la.count(l[i][j])==1 not in l4):
l4.append(l[i][j])
sm=''
for i in range(len(l4)):
sm = sm+str(l4[i])
print(sm)
``` | instruction | 0 | 58,626 | 18 | 117,252 |
No | output | 1 | 58,626 | 18 | 117,253 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An African crossword is a rectangular table n × m in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a letter should only be crossed out if and only if the corresponding column or row contains at least one more letter that is exactly the same. Besides, all such letters are crossed out simultaneously.
When all repeated letters have been crossed out, we should write the remaining letters in a string. The letters that occupy a higher position follow before the letters that occupy a lower position. If the letters are located in one row, then the letter to the left goes first. The resulting word is the answer to the problem.
You are suggested to solve an African crossword and print the word encrypted there.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 100). Next n lines contain m lowercase Latin letters each. That is the crossword grid.
Output
Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter.
Examples
Input
3 3
cba
bcd
cbc
Output
abcd
Input
5 5
fcofd
ooedo
afaoa
rdcdf
eofsf
Output
codeforces
Submitted Solution:
```
n,m = map(int,input().split())
l = []
for i in range(n):
t = input()
d = {}
for j in t:
if j in d:
d[j] = d[j] + 1
else:
d[j] = 1
if d[j] > 1:
t.replace(j,"")
l.append(t)
for i in range(m):
d = {}
for j in range(n):
if l[j][i] in d:
d[l[j][i]] = d[l[j][i]] + 1
else:
d[l[j][i]] = 1
if d[l[j][i]] > 1:
l[j].replace(l[j][i],"")
for i in l:
for j in i:
print(j,end="")
``` | instruction | 0 | 58,627 | 18 | 117,254 |
No | output | 1 | 58,627 | 18 | 117,255 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,751 | 18 | 117,502 |
"Correct Solution:
```
a,b,c=input().split();print(" YNEOS"[a[-1]==b[0]and b[-1]==c[0]::2])
``` | output | 1 | 58,751 | 18 | 117,503 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,752 | 18 | 117,504 |
"Correct Solution:
```
A, B, C = input().split()
res = "NO"
if A[-1] == B[0] and B[-1] == C[0]:
res = "YES"
print(res)
``` | output | 1 | 58,752 | 18 | 117,505 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,753 | 18 | 117,506 |
"Correct Solution:
```
A, B, C = input().split()
if A[-1] == B[0] and B[-1] == C[0]:
print('YES')
else:
print('NO')
``` | output | 1 | 58,753 | 18 | 117,507 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,754 | 18 | 117,508 |
"Correct Solution:
```
a=list(input().split())
print("YES" if a[0][-1]==a[1][0] and a[1][-1]==a[2][0] else "NO")
``` | output | 1 | 58,754 | 18 | 117,509 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,755 | 18 | 117,510 |
"Correct Solution:
```
a, b, c = list(input().split())
ans = 'YES' if a[-1] == b[0] and b[-1] == c[0] else 'NO'
print(ans)
``` | output | 1 | 58,755 | 18 | 117,511 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,756 | 18 | 117,512 |
"Correct Solution:
```
a,b,c=map(list,input().split())
print("YNEOS"[a[-1]!=b[0]or b[-1]!=c[0]::2])
``` | output | 1 | 58,756 | 18 | 117,513 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,757 | 18 | 117,514 |
"Correct Solution:
```
s = input().split()
print('YES' if s[0][-1]==s[1][0] and s[1][-1]==s[2][0] else 'NO')
``` | output | 1 | 58,757 | 18 | 117,515 |
Provide a correct Python 3 solution for this coding contest problem.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO | instruction | 0 | 58,758 | 18 | 117,516 |
"Correct Solution:
```
s = input().split()
print("YES" if s[0][-1] == s[1][0] and s[1][-1] == s[2][0] else "NO")
``` | output | 1 | 58,758 | 18 | 117,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
a, b, c = input().split()
ans = 'NO'
if a[-1] == b[0] and b[-1] == c[0]:
ans = 'YES'
print(ans)
``` | instruction | 0 | 58,759 | 18 | 117,518 |
Yes | output | 1 | 58,759 | 18 | 117,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
x,y,z=input().split()
print("YES" if x[-1]==y[0] and y[-1]==z[0] else "NO")
``` | instruction | 0 | 58,760 | 18 | 117,520 |
Yes | output | 1 | 58,760 | 18 | 117,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
a, b, c = input().split()
ans = 'YES' if a[-1] == b[0] and b[-1] == c[0] else 'NO'
print(ans)
``` | instruction | 0 | 58,761 | 18 | 117,522 |
Yes | output | 1 | 58,761 | 18 | 117,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
A,B,C = input().split()
print('YES' if A[-1] == B[0] and B[-1] == C[0] else 'NO')
``` | instruction | 0 | 58,762 | 18 | 117,524 |
Yes | output | 1 | 58,762 | 18 | 117,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
a,b,c = map(str,input().split())
if a[-1]=b[0] and b[-1]=c[0]:
print("YES")
else:
print("NO")
``` | instruction | 0 | 58,763 | 18 | 117,526 |
No | output | 1 | 58,763 | 18 | 117,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
a,b,c=input().split()
print('YES' if a[-1]=b[0] and b[-1]=c[0] else "NO")
``` | instruction | 0 | 58,764 | 18 | 117,528 |
No | output | 1 | 58,764 | 18 | 117,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
a,b,c=input().split();print('YNEOS'[a[-1]^c[0]^b[0]^b[-1]::2])
``` | instruction | 0 | 58,765 | 18 | 117,530 |
No | output | 1 | 58,765 | 18 | 117,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three strings A, B and C. Check whether they form a word chain.
More formally, determine whether both of the following are true:
* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.
If both are true, print `YES`. Otherwise, print `NO`.
Constraints
* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.
Input
Input is given from Standard Input in the following format:
A B C
Output
Print `YES` or `NO`.
Examples
Input
rng gorilla apple
Output
YES
Input
yakiniku unagi sushi
Output
NO
Input
a a a
Output
YES
Input
aaaaaaaaab aaaaaaaaaa aaaaaaaaab
Output
NO
Submitted Solution:
```
A, B, C = map(int, input().split())
if A[-1] == B[0] and B[-1] == C[0]:
print('YES')
else:
print('NO')
``` | instruction | 0 | 58,766 | 18 | 117,532 |
No | output | 1 | 58,766 | 18 | 117,533 |
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