message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order. | instruction | 0 | 64,053 | 19 | 128,106 |
Tags: greedy, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
tmp = B[-1]
ok = True
if tmp != 0:
for i in reversed(range(N)):
b = B[i]
if tmp-(N-1-i) > 0:
if b != tmp-(N-1-i):
ok = False
for i in range(N-tmp):
b = B[i]
if b > 0 and b <= tmp + i+1:
ok = False
else:
ok = False
if ok:
ans = N-tmp
else:
ans = N
for i, b in enumerate(B):
if b != 0:
ans = max(N-b+2+i, ans)
print(ans)
``` | output | 1 | 64,053 | 19 | 128,107 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order. | instruction | 0 | 64,054 | 19 | 128,108 |
Tags: greedy, implementation
Correct Solution:
```
from collections import defaultdict as dd
import math
import sys
input=sys.stdin.readline
def nn():
return int(input())
def li():
return list(input())
def mi():
return map(int, input().split())
def lm():
return list(map(int, input().split()))
n=nn()
hand=lm()
data=lm()
onespot=-1
for i in range(len(data)):
if data[i]==1:
onespot=i
if data[i]==0:
data[i]=float('+Inf')
if onespot==-1:
print(n+max([0]+[i+2-data[i] for i in range(len(data))]))
else:
if all([ data[i]==i+1-onespot for i in range(onespot,len(data))]) and all([data[i]>=data[-1]+i+2 for i in range(onespot)]):
print(onespot)
else:
print(onespot+1+n+ max([0]+[(i+1-onespot)-data[i] for i in range(onespot,len(data))]))
#print([data[i]-(i+1-onespot) for i in range(onespot,len(data))])
#print([data[i]-(i+1-onespot) for i in range(onespot,len(data))])
``` | output | 1 | 64,054 | 19 | 128,109 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order. | instruction | 0 | 64,055 | 19 | 128,110 |
Tags: greedy, implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
avail = [0 for i in range(n+1)]
cont = False
for i in range(n):
avail[b[i]] = i + 1
if cont and b[i-1] != b[i] - 1:
cont = False
if b[i] == 1:
cont = True
if cont:
start = b[-1] + 1
step = 0
for i in range(start, n+1):
if avail[i] > step:
cont = False
break
step += 1
if cont:
print(n - start + 1)
exit()
max_avail = 0
for i in range(1, n+1):
if avail[i] > i-1 and max_avail < avail[i] - (i - 1):
max_avail = avail[i] - (i - 1)
print(max_avail + n)
``` | output | 1 | 64,055 | 19 | 128,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
n=int(input(''))
a=list(map(int, input().split()))
b=list(map(int, input().split()))
c=[0]*n
for i in range(n):
if a[i]==0:
a[i]=(n*20)
else:
c[a[i]-1]=-1
if b[i]==0:
b[i]=(n*20)
else:
c[b[i]-1]=i
d=c.copy()
l=b[-1]
ll=l
f=0
for i in range(1,l+1):
if l==20*n:
f=1
break
j=i*-1
if b[j]!=ll:
f=1
break
ll-=1
if f==0:
j=0
for i in range(l,n):
if d[i]==-1:
if b[j]<=n:
d[b[j]-1]=-1
j+=1
else:
f=1
break
if f==0:
print(n-l)
exit()
m=min(b)
ind=b.index(m)
if m==1:
for i in range(ind+1):
if b[i]!=20*n:
c[b[i]-1]=-1
j=2
fe=-1
fi=-1
ans=-1
for i in range(ind+1,n):
if b[i]<j:
fe=b[i]
fi=j
ans=max(fi-fe,ans)
j+=1
if fe ==-1:
print(ind+n+1)
else:
print(ind+1+n+ans)
exit()
else:
j=2
fe=-1
fi=-1
ans=-1
for i in range(n):
if b[i]<j:
fe=b[i]
fi=j
ans=max(fi-fe,ans)
j+=1
if fe ==-1:
print(n)
else:
print(ans+n)
``` | instruction | 0 | 64,056 | 19 | 128,112 |
Yes | output | 1 | 64,056 | 19 | 128,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
n = int(input())
a= list(map(int,input().split()))
b = list(map(int,input().split()))
inhand = [0 for i in range(2*n + 2)]
if(1 in b):
loc1 = b.index(1)
asc = 1
for i in range(loc1, n):
if(b[i] > asc):
asc = 1
break
if(b[i] == asc):
asc += 1
moves = 0
if(asc > 1):
for i in range(n):
inhand[a[i]] = 1
for i in range(2*n):
#print(asc, i)
if(asc > n):
break
if(inhand[asc]):
asc += 1
inhand[b[moves%n]] = 1
moves += 1
if(moves <= loc1):
print(moves)
exit()
asc = 1
inhand = [0 for i in range(n+1)]
for i in range(n):
inhand[a[i]] = 1
moves = 0
for i in range(2*n + 2):
#print(i, asc)
if(asc > n):
break
if(inhand[asc]):
asc += 1
inhand[b[moves%n]] = 1
moves += 1
print(moves)
``` | instruction | 0 | 64,057 | 19 | 128,114 |
Yes | output | 1 | 64,057 | 19 | 128,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
import sys
input = sys.stdin.readline
from collections import *
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
idx = defaultdict(int)
s = set(b)
for i in range(n):
idx[b[i]] = i
la = b[-1]
if b[n-la:]==[i for i in range(1, la+1)]:
flag = True
for i in range(la+1, n+1):
if i in s:
if idx[i]>i-2-la:
flag = False
if flag:
print(n-la)
exit()
ans = 0
for i in range(1, n+1):
if i in s:
x = idx[i]-i+2
ans = max(ans, x)
ans += n
print(ans)
``` | instruction | 0 | 64,058 | 19 | 128,116 |
Yes | output | 1 | 64,058 | 19 | 128,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
N = int(input())
a_list = list(map(int, input().split()))
b_list = list(map(int, input().split()))
getting = [0] * (N + 1)
flg = False
for i in range(N):
b = b_list[i]
getting[b] = i + 1
if flg and b_list[i - 1] != b - 1:
flg = False
if b == 1:
flg = True
if flg:
start = b_list[-1] + 1
step = 0
for i in range(start, N + 1):
if getting[i] > step:
flg = False
break
step += 1
if flg:
print(N - start + 1)
exit()
ans = 0
for i in range(1, N + 1):
if getting[i] > i - 1 and ans < getting[i] - (i - 1):
ans = getting[i] - (i - 1)
print(N + ans)
``` | instruction | 0 | 64,059 | 19 | 128,118 |
Yes | output | 1 | 64,059 | 19 | 128,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
if 1 not in b:
print(n + 1)
else:
j = b.index(1)
b = b[j:]
s = 0
z = 0
for i in range(n - j):
d = i + 1 - b[i]
if b[i] == 0:
z += 1
if d > 0 and b[i] != 0:
s += d
if s != 0 or z != 0 or (j != 0 and (b[-1] + 1) not in a):
print(j + 1 + n + s)
else:
print(j)
``` | instruction | 0 | 64,060 | 19 | 128,120 |
No | output | 1 | 64,060 | 19 | 128,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
def ain():
return map(int,input().split())
def lin():
return list(ain())
def plist(l):
for x in l:
print(x, end= ' ')
print()
n = int(input())
l1 = lin()
l2 = lin()
ui = 0
if l2.index(1) >= 0 and l2.index(1) != n-1:
i = l2.index(1)
j = 1
fk = 0
while i < n:
if l2[i] != j:
fk = 1
i+=1
j+=1
if fk == 0:
x = l2[n-1]
fl = 0
for i in range(1,n-l2[n-1]+1):
if ( (x+i) not in l1 ) and l2.index(x+i) >= i:
fl = 1
break
if fl == 0:
print(l2.index(1))
ui = 1
if l2[n-1] != 1 and ui == 0:
if l2.index(1) == -1:
w = 0
for x in l2:
if l2[j] != 0:
w = max(w, i - l[i])
else:
i1 = l2.index(1)
w = i1+1
#print('i1',i1)
for j in range(i1+1,n):
if l2[j] != 0:
w = max(w,j-l2[j]+2)
#print(w)
print(w+n)
elif ui == 0:
fl = 0
for i in range(n-1):
if l2[i] - i < 3 and l2[i] != 0:
fl = 1
break
if l1.index(2) == -1:
fl = 1
if fl == 0:
print(n-1)
else:
print(2*n)
``` | instruction | 0 | 64,061 | 19 | 128,122 |
No | output | 1 | 64,061 | 19 | 128,123 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
######################################################################
# Write your code here
#import sys
#import resource
#resource.setrlimit(resource.RLIMIT_STACK, [0x10000000, resource.RLIM_INFINITY])
#sys.setrecursionlimit(0x100000)
# Write your code here
RI = lambda : [int(x) for x in input().strip().split()]
rw = lambda : input().strip().split()
from collections import defaultdict as df
#import heapq
#heapq.heapify(li) heappush(li,4) heappop(li)
#import random
#random.shuffle(list)
#infinite = float('inf')
#######################################################################
n=int(input())
m=RI()#deck
l=RI()#pile
index=df(int)
for i in range(n):
if(l[i]!=0):
index[l[i]]=(i+1)
extra=[0]*(n+1)
for i in range(n):
if(index[i+1]==0):
extra[i+1]=1
else:
extra[i+1]=index[i+1]+1
if(index[1]==n):
extra[1]=0
sumo=-1
for i in range(n):
if(extra[i+1]<=sumo):
sumo+=1
else:
sumo=extra[i+1]
#print(sumo)
print(sumo)
``` | instruction | 0 | 64,062 | 19 | 128,124 |
No | output | 1 | 64,062 | 19 | 128,125 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nauuo is a girl who loves playing cards.
One day she was playing cards but found that the cards were mixed with some empty ones.
There are n cards numbered from 1 to n, and they were mixed with another n empty cards. She piled up the 2n cards and drew n of them. The n cards in Nauuo's hands are given. The remaining n cards in the pile are also given in the order from top to bottom.
In one operation she can choose a card in her hands and play it — put it at the bottom of the pile, then draw the top card from the pile.
Nauuo wants to make the n numbered cards piled up in increasing order (the i-th card in the pile from top to bottom is the card i) as quickly as possible. Can you tell her the minimum number of operations?
Input
The first line contains a single integer n (1≤ n≤ 2⋅ 10^5) — the number of numbered cards.
The second line contains n integers a_1,a_2,…,a_n (0≤ a_i≤ n) — the initial cards in Nauuo's hands. 0 represents an empty card.
The third line contains n integers b_1,b_2,…,b_n (0≤ b_i≤ n) — the initial cards in the pile, given in order from top to bottom. 0 represents an empty card.
It is guaranteed that each number from 1 to n appears exactly once, either in a_{1..n} or b_{1..n}.
Output
The output contains a single integer — the minimum number of operations to make the n numbered cards piled up in increasing order.
Examples
Input
3
0 2 0
3 0 1
Output
2
Input
3
0 2 0
1 0 3
Output
4
Input
11
0 0 0 5 0 0 0 4 0 0 11
9 2 6 0 8 1 7 0 3 0 10
Output
18
Note
Example 1
We can play the card 2 and draw the card 3 in the first operation. After that, we have [0,3,0] in hands and the cards in the pile are [0,1,2] from top to bottom.
Then, we play the card 3 in the second operation. The cards in the pile are [1,2,3], in which the cards are piled up in increasing order.
Example 2
Play an empty card and draw the card 1, then play 1, 2, 3 in order.
Submitted Solution:
```
n = int(input())
_ = input()
d = list(map(int, input().split()))
m = -n
z = -1
#y = None
for i, v in enumerate(d):
if not v:
continue
if z >= 0 and v != i-z+1:
z = -1
elif v == 1:
z = i
y = m
m = max(m, i-v+2)
#print(m, y, z)
if z == 0:
print(0)
elif z > 0 and y <= -n + z:
print(z)
else:
print(n + max(m, 0))
``` | instruction | 0 | 64,063 | 19 | 128,126 |
No | output | 1 | 64,063 | 19 | 128,127 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,132 | 19 | 128,264 |
Tags: brute force, greedy, math
Correct Solution:
```
t=int(input())
for _ in range(t):
n,m,k=input().split()
n=int(n)
m=int(m)
k=int(k)
p=n//k
if(m-p <0):
print(m)
else:
left=m-p
x=left/(k-1)
if(int(x)==x):
print(int(p-x))
else:
print(p-int(x)-1)
``` | output | 1 | 64,132 | 19 | 128,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,133 | 19 | 128,266 |
Tags: brute force, greedy, math
Correct Solution:
```
t = int(input())
while t > 0:
[n, m, k] = [int(x) for x in input().split()]
if m <= n//k:
print(m)
else:
arr = []
max1 = n//k
remaining_cards = m - max1
equal = remaining_cards//(k-1)
# print("equal", equal)
extra = remaining_cards%(k-1)
# print("extra", extra)
if extra != 0:
max2 = equal + 1
else:
max2 = equal
ans = max1 - max2
if ans < 0:
ans = 0
print(ans)
t -= 1
``` | output | 1 | 64,133 | 19 | 128,267 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,134 | 19 | 128,268 |
Tags: brute force, greedy, math
Correct Solution:
```
tests=int(input())
for _ in range(tests):
n,m,k=map(int,input().split())
if m<=n//k:
print(m)
continue
else:
x=n//k
rem=m-x
y=rem//(k-1)
if rem%(k-1) !=0:
y+=1
print(x-y)
``` | output | 1 | 64,134 | 19 | 128,269 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,135 | 19 | 128,270 |
Tags: brute force, greedy, math
Correct Solution:
```
for _ in range(int(input())):
n,m,k=map(int,input().split())
y=n/k
if y>=m:
print(m)
else:
if (m-y)%(k-1) != 0:
print(int(y-1-(m-y)//(k-1)))
else:
print(int(y-((m-y)/(k-1))))
``` | output | 1 | 64,135 | 19 | 128,271 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,136 | 19 | 128,272 |
Tags: brute force, greedy, math
Correct Solution:
```
n = int(input())
for i in range(n):
n,m,k = map(int,input().split(" "))
a = n//k
if m >a:
c = m-a
e = c//(k-1)
if c%(k-1) !=0:
b = a - (e+1)
else:
b= a-e
else:
b = m
print(b)
``` | output | 1 | 64,136 | 19 | 128,273 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,137 | 19 | 128,274 |
Tags: brute force, greedy, math
Correct Solution:
```
def cap(n, m, k):
t = n // k
if m > t:
# print(m, t)
rem = m - t
pl = k - 1
if rem <= pl:
print(t-1)
else:
if rem%pl==0:
print(t-rem//pl)
else:
print(t-rem//pl-1)
else:
print(m)
n = int(input())
for i in range(n):
a = list(map(int, input().split(" ")))
cap(a[0], a[1], a[2])
``` | output | 1 | 64,137 | 19 | 128,275 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,138 | 19 | 128,276 |
Tags: brute force, greedy, math
Correct Solution:
```
### A. Berland Poker
for _ in range(int(input())):
card,joker,player = map(int, input().split())
get = card//player
if joker <= get:
print(joker)
else:
left = joker - get
num, div = left, (player-1)
ans= [num // div + (1 if x < num % div else 0) for x in range (div)]
print(get - max(ans))
``` | output | 1 | 64,138 | 19 | 128,277 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,139 | 19 | 128,278 |
Tags: brute force, greedy, math
Correct Solution:
```
import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
INF = 10 ** 19
MOD = 10 ** 9 + 7
for _ in range(INT()):
N, M, K = MAP()
eachcnt = N // K
if M <= eachcnt:
print(M)
else:
x = eachcnt
remain = M - eachcnt
y = ceil(remain, K-1)
print(x-y)
``` | output | 1 | 64,139 | 19 | 128,279 |
Provide tags and a correct Python 2 solution for this coding contest problem.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement. | instruction | 0 | 64,140 | 19 | 128,280 |
Tags: brute force, greedy, math
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
raw_input = stdin.readline
pr = stdout.write
mod=10**9+7
def ni():
return int(raw_input())
def li():
return map(int,raw_input().split())
def pn(n):
stdout.write(str(n)+'\n')
def pa(arr):
pr(' '.join(map(str,arr))+'\n')
# fast read function for total integer input
def inp():
# this function returns whole input of
# space/line seperated integers
# Use Ctrl+D to flush stdin.
return map(int,stdin.read().split())
range = xrange # not for python 3.0+
# main code
for t in range(ni()):
n,m,k=li()
if not m:
pn(0)
continue
x=min(m,n/k)
m-=x
if not m:
pn(x)
continue
k-=1
y=(m/k)+int(m%k!=0)
pn(x-y)
``` | output | 1 | 64,140 | 19 | 128,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
t = int(input())
for i in range(t):
n, m, k = map(int, input().split())
if n // k >= m:
print(m)
elif (m - n // k) % (k - 1) == 0:
print(n // k - (m - n // k) // (k - 1))
else:
print(n // k - (m - n // k) // (k - 1) - 1)
``` | instruction | 0 | 64,141 | 19 | 128,282 |
Yes | output | 1 | 64,141 | 19 | 128,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
for t in range(int(input())):
n, m, k = map(int, input().split())
if n==m:
print('0')
elif m<=n//k:
print(m)
else:
y=(m-n//k)//(k-1)
if (m-n//k)%(k-1)!=0:
y+=1
print(n//k-y)
``` | instruction | 0 | 64,142 | 19 | 128,284 |
Yes | output | 1 | 64,142 | 19 | 128,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
import sys, random, math
from bisect import bisect_left, bisect_right
input = sys.stdin.readline
def main():
inf = 10 ** 20
t = int(input())
# t, a, b = map(int, input().split())
# t = 1
for _ in range(1, t+1):
# print("Case #{}: ".format(_), end = '')
n, m, k = map(int, input().split())
each = n // k
best = min(each, m)
m -= min(each, m)
sec = m // (k-1)
if(m % (k-1)):
sec += 1
print(best - sec)
main()
``` | instruction | 0 | 64,143 | 19 | 128,286 |
Yes | output | 1 | 64,143 | 19 | 128,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
t = int(input())
for i in range(t):
n, m, k = map(int, input().split())
per = n // k
a1 = min(m, per)
a2 = (m - a1 + k - 2) // (k - 1)
print(a1 - a2)
``` | instruction | 0 | 64,144 | 19 | 128,288 |
Yes | output | 1 | 64,144 | 19 | 128,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
t = int(input())
while t > 0:
[n, m, k] = [int(x) for x in input().split()]
if m <= n//k:
print(m)
else:
arr = []
max1 = n//k
remaining_cards = m - max1
for i in range(k-2):
arr.append(1)
remaining_cards -= 1
arr.append(remaining_cards)
if remaining_cards >= n//k:
print(0)
t -= 1
continue
print(max1 - max(arr))
t -= 1
``` | instruction | 0 | 64,145 | 19 | 128,290 |
No | output | 1 | 64,145 | 19 | 128,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
from math import ceil
for _ in range(int(input())):
n,m,k=map(int,input().split())
if n==m==k:print(0)
else:
t=n//k
if m<=t:print(m)
elif m>t:
m-=t
k-=1
print(m-(ceil(m/k)))
``` | instruction | 0 | 64,146 | 19 | 128,292 |
No | output | 1 | 64,146 | 19 | 128,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
from sys import stdin,stdout
def solve():
n,m,k = map(int, input().split())
if m==0 or n==k:
return 0
# max possible if all are joker ie max(m,n/k) jokers
if m<=n//k:
return m
else:
# max1 = n//k, max2 = (remaining or all n//k)
m-=n//k
m2=(m//(k-1))+(m%(k-1))
return n//k - m2
for _ in range(int(stdin.readline())):
stdout.write(str(solve()) + '\n')
``` | instruction | 0 | 64,147 | 19 | 128,294 |
No | output | 1 | 64,147 | 19 | 128,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).
At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.
Here are some examples:
* n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points;
* n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points;
* n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point;
* n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points.
Given n, m and k, calculate the maximum number of points a player can get for winning the game.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.
Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).
Output
For each test case, print one integer — the maximum number of points a player can get for winning the game.
Example
Input
4
8 3 2
4 2 4
9 6 3
42 0 7
Output
3
0
1
0
Note
Test cases of the example are described in the statement.
Submitted Solution:
```
for t in range(int(input())):
n, m, k = [int(x) for x in input().split()]
a = n//k
if m == 0:
print(0)
elif a >= m:
print(m)
else:
if (m - a) % (k-1) != 0:
print(a - ((m - a)// (k-1)))
else:
print(a - ((m - a)// k-1))
``` | instruction | 0 | 64,148 | 19 | 128,296 |
No | output | 1 | 64,148 | 19 | 128,297 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,387 | 19 | 128,774 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
def fff(i):
global a
global m
t=0
max=0
for j in range(m+1):
if a[i][j]==0:
if t>max:
max=t
t=0
else:
t=t+1
return max
n,m,q=map(int,input().split())
a=[]
s=[]
for i in range(0,n):
w=list(map(int,input().split()))
w.append(0)
a.append(w)
s.append(fff(i))
for i in range(q):
x,y=map(int, input().split())
a[x-1][y-1]=(a[x-1][y-1]+1)%2
s[x-1]=fff(x-1)
print(max(s))
``` | output | 1 | 64,387 | 19 | 128,775 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,388 | 19 | 128,776 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
def line_score(row):
m = 0
c = 0
for elem in row:
if elem == 1:
c += 1
else:
c = 0
m = max(c, m)
return m
n, m, q = [int(x) for x in input().split(' ')]
grid = [[int(x) for x in input().split(' ')] for row in range(n)]
rounds = [[int(x) for x in input().split(' ')] for round in range(q)]
z = []
for row in grid:
z.append(line_score(row))
for round in rounds:
i, j = round
grid[i - 1][j - 1] = 1 - grid[i - 1][j - 1]
z [i - 1] = line_score(grid[i - 1])
print(max(z))
``` | output | 1 | 64,388 | 19 | 128,777 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,389 | 19 | 128,778 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
def multi_input():
return map(int, input().split())
def array_print(arr):
print(' '.join(map(str, arr)))
def findsum(arr):
ans = 0
max1 = 0
for i in arr:
if i==1:
ans+=1
max1 = max(ans, max1)
else:
max1 = max(ans, max1)
ans = 0
return max1
n,m,q = multi_input()
matrix = []
arr = [0]*n
for i in range(n):
temp = list(multi_input())
matrix.append(temp)
arr[i] = findsum(temp)
for i in range(q):
x1,y1 = multi_input()
x1 -=1
y1 -= 1
# print(x1,y1)
if matrix[x1][y1] == 0:
matrix[x1][y1] = 1
arr[x1] = findsum(matrix[x1])
elif matrix[x1][y1] == 1:
matrix[x1][y1] = 0
arr[x1] = findsum(matrix[x1])
print(max(arr))
``` | output | 1 | 64,389 | 19 | 128,779 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,390 | 19 | 128,780 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
f = lambda s: max(map(len, ''.join(s).split('0')))
n, m, q = map(int, input().split())
a = [input().split() for i in range(n)]
b = list(map(f, a))
c = [list(map(int, input().split())) for i in range(q)]
for x, y in c:
a[x - 1][y - 1] = str(1 - int(a[x - 1][y - 1]))
b[x - 1] = f(a[x - 1])
print(max(b))
``` | output | 1 | 64,390 | 19 | 128,781 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,391 | 19 | 128,782 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
def kadane(lst):
ans = s = 0
for n in lst:
if n == 0:
ans = max(ans, s)
s = 0
else:
s += 1
return max(ans, s)
if __name__ == '__main__':
n,m,q = map(int, input().split())
f = []
best = []
for _ in range(n):
l = list(map(int, input().split()))
f.append(l)
best.append(kadane(l))
for _ in range(q):
i,j = map(int, input().split())
f[i-1][j-1] = (f[i-1][j-1] + 1) % 2
best[i-1] = kadane(f[i-1])
print(max(best))
``` | output | 1 | 64,391 | 19 | 128,783 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,392 | 19 | 128,784 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
n, m, q = map(int, input().split())
xs = [list(map(int, input().split())) for i in range(n)]
def go(xs):
answer, total = 0, 0
for x in xs:
total = total + 1 if x else 0
answer = total if total > answer else answer
return answer
ss = [go(x) for x in xs]
for i in range(q):
i, j = map(int, input().split())
if xs[i - 1][j - 1] == 0:
xs[i - 1][j - 1] = 1
ss[i - 1] = go(xs[i - 1])
else:
xs[i - 1][j - 1] = 0
ss[i - 1] = go(xs[i - 1])
print(max(ss))
``` | output | 1 | 64,392 | 19 | 128,785 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,393 | 19 | 128,786 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
def conta(mat):
combo = 0
maior = 0
for l in range(len(mat)):
if mat[l]==1:
combo+=1
elif combo>0:
if combo>maior:
maior = combo
combo =0
if combo>maior:
maior = combo
return maior
i,j,t = [int(z) for z in input().split(" ")]
matriz= []
M = []
for i1 in range(i):
valor =[int(z) for z in input().split(" ")]
matriz.append(valor)
M.append(conta(valor))
cpy = matriz[:]
for q in range(t):
n,m = [int(z) for z in input().split(" ")]
if cpy[n-1][m-1]==1:
cpy[n-1][m-1]=0
else:
cpy[n-1][m-1]=1
tes = conta(cpy[n-1])
M[n-1] = tes
print(max(M))
``` | output | 1 | 64,393 | 19 | 128,787 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4 | instruction | 0 | 64,394 | 19 | 128,788 |
Tags: brute force, dp, greedy, implementation
Correct Solution:
```
def calc(li,m):
ans=0
count=0
for i in range(m):
if li[i]==1:
count+=1
else:
count=0
ans=max(ans,count)
return ans
n,m,q=map(int,input().split())
adj=[]
for i in range(n):
li=list(map(int,input().split()))
adj.append(li)
row=[0]*n
for i in range(n):
row[i]=calc(adj[i],m)
for _ in range(q):
r,c=map(int,input().split())
r-=1
c-=1
adj[r][c]=1-adj[r][c]
row[r]=calc(adj[r],m)
ans=max(row)
print(ans)
``` | output | 1 | 64,394 | 19 | 128,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
def cal(l) :
t = 0 ;
r = 0 ;
for i in range(len(l)) :
if l[i]=='1' :
t+=1
r = max(r,t)
else :
t = 0
return r
def maxll(l) :
r = 0 ;
for i in l :
r = max(r,i)
return r
inp = input().split()
n = int(inp[0])
m = int(inp[1])
q = int(inp[2])
count = [0 for i in range(n)]
a = [ ['' for i in range(m)] for j in range(n)]
for i in range(n) :
s = input().split()
a[i] = s
count[i] = cal(a[i])
for i in range(q) :
s = input().split()
x = int(s[0])
y = int(s[1])
if a[x-1][y-1] == '1' : a[x-1][y-1] = '0'
else : a[x-1][y-1] = '1'
count[x-1] = cal(a[x-1])
print(maxll(count))
``` | instruction | 0 | 64,395 | 19 | 128,790 |
Yes | output | 1 | 64,395 | 19 | 128,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
n, m, q = [int(i) for i in input().split()]
matrix = []
for i in range(n):
matrix.append([int(i) for i in input().split()])
maxprrow = []
for a in range(n):
maxrow = 0
max_max = 0
for b in range(m):
if matrix[a][b] == 1:
maxrow += 1
if maxrow > max_max:
max_max = maxrow
else:
maxrow = 0
maxprrow.append(max_max)
winer = []
for step in range(q):
i, j = [int(c) for c in input().split()]
matrix[i-1][j-1] = 1 - matrix[i-1][j-1]
max_max , maxrow = 0,0
for b in range(m):
if matrix[i-1][b] == 1:
maxrow += 1
if maxrow > max_max:
max_max = maxrow
else:
maxrow = 0
maxprrow[i-1] = max_max
winer.append(max(maxprrow))
for w in winer:
print(w)
``` | instruction | 0 | 64,396 | 19 | 128,792 |
Yes | output | 1 | 64,396 | 19 | 128,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
rows, cols, changes_count = map(int, input().split())
grid = [
input().split() for _ in range(rows)
]
changes = [
map(int, input().split()) for __ in range(changes_count)
]
max_line = [
max(map(len, "".join(row).split("0"))) for row in grid
]
for r, c in changes:
grid[r-1][c-1] = "0" if grid[r-1][c-1] == "1" else "1"
max_line[r-1] = max(map(len, "".join(grid[r-1]).split("0")))
print(max(max_line))
``` | instruction | 0 | 64,397 | 19 | 128,794 |
Yes | output | 1 | 64,397 | 19 | 128,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
def func(a):
s=0
per= 0
for i in range(len(a)):
if a[i] == '1':
per+=1
else:
s=max(s, per)
per=0
s=max(per, s)
return s
def main(a):
A= []
B = [0] * int(a[0])
for i in range(int(a[0])):
A.append(input().split())
for i in range(int(a[0])):
B[i] = func(A[i])
for i in range(int(a[2])):
s = 0
k = input().split()
A[int(k[0]) - 1][int(k[1]) - 1] = str((int(A[int(k[0]) - 1][int(k[1]) - 1]) + 1) % 2)
B[int(k[0]) - 1] = func(A[int(k[0]) - 1])
for i in B:
s = max(s, i)
print(s)
a =input().split()
main(a)
``` | instruction | 0 | 64,398 | 19 | 128,796 |
Yes | output | 1 | 64,398 | 19 | 128,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
def main():
n, m, q = map(int, input().split())
answer_list = []
bear_list = [list(map(int, input().split())) for x in range(n)]
for x in range(q):
coord = list(map(int, input().split()))
if bear_list[coord[0] - 1][coord[1] - 1] == 0:
bear_list[coord[0] - 1][coord[1] - 1] = 1
else:
bear_list[coord[0] - 1][coord[1] - 1] = 0
max_bears = -1
for x in bear_list:
if sum(x) > max_bears:
max_bears = sum(x)
answer_list.append(max_bears)
for x in answer_list:
print(x)
if __name__ == "__main__":
main()
``` | instruction | 0 | 64,399 | 19 | 128,798 |
No | output | 1 | 64,399 | 19 | 128,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
n, m, q = map(int, input().split())
arr = [0] * n
res = [0] * n
for i in range(n):
arr[i] = list(map(int, input().split()))
c = 0
for j in arr[i]:
c += j
res[i] = c
for i in range(q):
i, j = map(int, input().split())
i -= 1
j -= 1
arr[i][j] = 1 - arr[i][j]
if arr[i][j] == 0:
res[i] -= 1
else:
res[i] += 1
print(max(res))
``` | instruction | 0 | 64,400 | 19 | 128,800 |
No | output | 1 | 64,400 | 19 | 128,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
n, m, q = map(int, input().split())
arr = [0] * n
res = [0] * n
mx = 0
for i in range(n):
arr[i] = list(map(int, input().split())) + [0]
c = 0
f = False
l = 0
r = 0
t = 0
mx = [0, 0]
for j in range(m + 1):
if arr[i][j] and not f:
f = True
l = j
r = j
elif arr[i][j]:
r = j
elif f:
if mx[0] < r - l + 1:
mx = [r - l + 1, i]
t = max(t, r - l + 1)
f = False
res[i] = t
for i in range(q):
i, j = map(int, input().split())
i -= 1
j -= 1
if mx[1] != i:
if arr[i][j] == 1:
arr[i][j] = 0
l = j - 1
c = 0
while l > 0 and arr[i][l] == 1:
c += 1
l -= 1
c2 = 0
l = j + 1
while l < m and arr[i][l] == 1:
c2 += 1
l += 1
if mx[0] < max(c, c2):
mx = [max(c, c2), i]
f = False
t = 0
for b in range(m + 1):
if arr[i][b] and not f:
f = True
l = b
r = b
elif arr[i][b]:
r = b
elif f:
t = max(t, r - l + 1)
f = False
res[i] = t
else:
arr[i][j] = 1
l = j - 1
c = 0
while l > -1 and arr[i][l] == 1:
c += 1
l -= 1
c2 = 0
l = j + 1
while l < m and arr[i][l] == 1:
c2 += 1
l += 1
if mx[0] < (c + c2 + 1):
mx = [c + c2 + 1, i]
f = False
t = 0
for b in range(m + 1):
if arr[i][b] and not f:
f = True
l = b
r = b
elif arr[i][b]:
r = b
elif f:
t = max(t, r - l + 1)
f = False
res[i] = t
else:
arr[i][j] = 1 - arr[i][j]
t = 0
f = False
for b in range(m + 1):
if arr[i][b] and not f:
f = True
l = b
r = b
elif arr[i][b]:
r = b
elif f:
t = max(t, r - l + 1)
f = False
if t > mx[0]:
mx = [t, i]
else:
res[i] = t
mx[0] = 0
for b in range(len(res)):
if mx[0] < res[b]:
mx = [res[b], b]
print(mx[0])
``` | instruction | 0 | 64,401 | 19 | 128,802 |
No | output | 1 | 64,401 | 19 | 128,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mike and some bears are playing a game just for fun. Mike is the judge. All bears except Mike are standing in an n × m grid, there's exactly one bear in each cell. We denote the bear standing in column number j of row number i by (i, j). Mike's hands are on his ears (since he's the judge) and each bear standing in the grid has hands either on his mouth or his eyes.
<image>
They play for q rounds. In each round, Mike chooses a bear (i, j) and tells him to change his state i. e. if his hands are on his mouth, then he'll put his hands on his eyes or he'll put his hands on his mouth otherwise. After that, Mike wants to know the score of the bears.
Score of the bears is the maximum over all rows of number of consecutive bears with hands on their eyes in that row.
Since bears are lazy, Mike asked you for help. For each round, tell him the score of these bears after changing the state of a bear selected in that round.
Input
The first line of input contains three integers n, m and q (1 ≤ n, m ≤ 500 and 1 ≤ q ≤ 5000).
The next n lines contain the grid description. There are m integers separated by spaces in each line. Each of these numbers is either 0 (for mouth) or 1 (for eyes).
The next q lines contain the information about the rounds. Each of them contains two integers i and j (1 ≤ i ≤ n and 1 ≤ j ≤ m), the row number and the column number of the bear changing his state.
Output
After each round, print the current score of the bears.
Examples
Input
5 4 5
0 1 1 0
1 0 0 1
0 1 1 0
1 0 0 1
0 0 0 0
1 1
1 4
1 1
4 2
4 3
Output
3
4
3
3
4
Submitted Solution:
```
from fileinput import *
grid = []
info = []
for line in input():
if lineno() == 1:
[n, m, q] = list(map(int, line.split()))
elif lineno() > 1 and lineno() <= 1 + n:
grid.append(list(map(int, line.split())))
elif lineno() > 1 + n:
info.append(list(map(int, line.split())))
else:
pass
def getscore(grid):
maxscore = 0
for line in grid:
maxlinecount = 0
linecount = 0
state = 0
for i in range(m):
if state == 0 and line[i] == 1:
linecount += 1
if state == 1 and line[i] == 1:
linecount += 1
if state == 1 and (line[i] == 0 or i == (m-1)):
if linecount > maxlinecount:
maxlinecount = linecount
linecount = 0
if line[i] == 1:
state = 1
else:
state = 0
if maxlinecount > maxscore:
maxscore = maxlinecount
return maxscore
for k in range(q):
[i, j] = info[k]
grid[i-1][j-1] = grid[i-1][j-1] ^ 1
print(getscore(grid))
``` | instruction | 0 | 64,402 | 19 | 128,804 |
No | output | 1 | 64,402 | 19 | 128,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem. Refer to the Interaction section below for better understanding.
Ithea and Chtholly want to play a game in order to determine who can use the kitchen tonight.
<image>
Initially, Ithea puts n clear sheets of paper in a line. They are numbered from 1 to n from left to right.
This game will go on for m rounds. In each round, Ithea will give Chtholly an integer between 1 and c, and Chtholly needs to choose one of the sheets to write down this number (if there is already a number before, she will erase the original one and replace it with the new one).
Chtholly wins if, at any time, all the sheets are filled with a number and the n numbers are in non-decreasing order looking from left to right from sheet 1 to sheet n, and if after m rounds she still doesn't win, she loses the game.
Chtholly really wants to win the game as she wants to cook something for Willem. But she doesn't know how to win the game. So Chtholly finds you, and your task is to write a program to receive numbers that Ithea gives Chtholly and help her make the decision on which sheet of paper write this number.
Input
The first line contains 3 integers n, m and c (<image>, <image> means <image> rounded up) — the number of sheets, the number of rounds and the largest possible number Ithea can give to Chtholly respectively. The remaining parts of input are given throughout the interaction process.
Interaction
In each round, your program needs to read one line containing a single integer pi (1 ≤ pi ≤ c), indicating the number given to Chtholly.
Your program should then output a line containing an integer between 1 and n, indicating the number of sheet to write down this number in.
After outputting each line, don't forget to flush the output. For example:
* fflush(stdout) in C/C++;
* System.out.flush() in Java;
* sys.stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
If Chtholly wins at the end of a round, no more input will become available and your program should terminate normally. It can be shown that under the constraints, it's always possible for Chtholly to win the game.
Example
Input
2 4 4
2
1
3
Output
1
2
2
Note
In the example, Chtholly initially knew there were 2 sheets, 4 rounds and each number was between 1 and 4. She then received a 2 and decided to write it in the 1st sheet. Then she received a 1 and wrote it in the 2nd sheet. At last, she received a 3 and replaced 1 with 3 in the 2nd sheet. At this time all the sheets were filled with a number and they were non-decreasing, so she won the game.
Note that it is required that your program terminate immediately after Chtholly wins and do not read numbers from the input for the remaining rounds. If not, undefined behaviour may arise and it won't be sure whether your program will be accepted or rejected. Also because of this, please be careful when hacking others' codes. In the sample, Chtholly won the game after the 3rd round, so it is required that your program doesn't read the number of the remaining 4th round.
The input format for hacking:
* The first line contains 3 integers n, m and c;
* The following m lines each contains an integer between 1 and c, indicating the number given to Chtholly in each round. | instruction | 0 | 64,537 | 19 | 129,074 |
Tags: binary search, constructive algorithms, games, greedy, interactive
Correct Solution:
```
import sys
n, m, c = map(int, input().split())
free = n
nums = [0] * n
for i in range(m):
pi = int(input())
if(pi > c//2):
current = n - 1
while(nums[current] > 0 and nums[current] >= pi and current >= 0):current -= 1
if(current == -1):current = 0
if(nums[current] == 0):free -= 1
nums[current] = pi
print(current + 1)
else:
current = 0
while(current < n and nums[current] > 0 and nums[current] <= pi):current += 1
if(current == n):current = n - 1
if(nums[current] == 0):free -=1
nums[current] = pi
print(current + 1)
if(free == 0):break
``` | output | 1 | 64,537 | 19 | 129,075 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem. Refer to the Interaction section below for better understanding.
Ithea and Chtholly want to play a game in order to determine who can use the kitchen tonight.
<image>
Initially, Ithea puts n clear sheets of paper in a line. They are numbered from 1 to n from left to right.
This game will go on for m rounds. In each round, Ithea will give Chtholly an integer between 1 and c, and Chtholly needs to choose one of the sheets to write down this number (if there is already a number before, she will erase the original one and replace it with the new one).
Chtholly wins if, at any time, all the sheets are filled with a number and the n numbers are in non-decreasing order looking from left to right from sheet 1 to sheet n, and if after m rounds she still doesn't win, she loses the game.
Chtholly really wants to win the game as she wants to cook something for Willem. But she doesn't know how to win the game. So Chtholly finds you, and your task is to write a program to receive numbers that Ithea gives Chtholly and help her make the decision on which sheet of paper write this number.
Input
The first line contains 3 integers n, m and c (<image>, <image> means <image> rounded up) — the number of sheets, the number of rounds and the largest possible number Ithea can give to Chtholly respectively. The remaining parts of input are given throughout the interaction process.
Interaction
In each round, your program needs to read one line containing a single integer pi (1 ≤ pi ≤ c), indicating the number given to Chtholly.
Your program should then output a line containing an integer between 1 and n, indicating the number of sheet to write down this number in.
After outputting each line, don't forget to flush the output. For example:
* fflush(stdout) in C/C++;
* System.out.flush() in Java;
* sys.stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
If Chtholly wins at the end of a round, no more input will become available and your program should terminate normally. It can be shown that under the constraints, it's always possible for Chtholly to win the game.
Example
Input
2 4 4
2
1
3
Output
1
2
2
Note
In the example, Chtholly initially knew there were 2 sheets, 4 rounds and each number was between 1 and 4. She then received a 2 and decided to write it in the 1st sheet. Then she received a 1 and wrote it in the 2nd sheet. At last, she received a 3 and replaced 1 with 3 in the 2nd sheet. At this time all the sheets were filled with a number and they were non-decreasing, so she won the game.
Note that it is required that your program terminate immediately after Chtholly wins and do not read numbers from the input for the remaining rounds. If not, undefined behaviour may arise and it won't be sure whether your program will be accepted or rejected. Also because of this, please be careful when hacking others' codes. In the sample, Chtholly won the game after the 3rd round, so it is required that your program doesn't read the number of the remaining 4th round.
The input format for hacking:
* The first line contains 3 integers n, m and c;
* The following m lines each contains an integer between 1 and c, indicating the number given to Chtholly in each round. | instruction | 0 | 64,538 | 19 | 129,076 |
Tags: binary search, constructive algorithms, games, greedy, interactive
Correct Solution:
```
import sys
n, m, c=map(int, input().split())
a=[]
for i in range(n+1):
a.append(0)
cnt=0
while cnt<n:
i=0
x=int(input())
if x*2<=c:
i=1
while a[i] and a[i]<=x:
i+=1
else:
i=n
while a[i] and a[i]>=x:
i-=1
if a[i]==0:
cnt+=1
a[i]=x
print(i)
sys.stdout.flush()
``` | output | 1 | 64,538 | 19 | 129,077 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem. Refer to the Interaction section below for better understanding.
Ithea and Chtholly want to play a game in order to determine who can use the kitchen tonight.
<image>
Initially, Ithea puts n clear sheets of paper in a line. They are numbered from 1 to n from left to right.
This game will go on for m rounds. In each round, Ithea will give Chtholly an integer between 1 and c, and Chtholly needs to choose one of the sheets to write down this number (if there is already a number before, she will erase the original one and replace it with the new one).
Chtholly wins if, at any time, all the sheets are filled with a number and the n numbers are in non-decreasing order looking from left to right from sheet 1 to sheet n, and if after m rounds she still doesn't win, she loses the game.
Chtholly really wants to win the game as she wants to cook something for Willem. But she doesn't know how to win the game. So Chtholly finds you, and your task is to write a program to receive numbers that Ithea gives Chtholly and help her make the decision on which sheet of paper write this number.
Input
The first line contains 3 integers n, m and c (<image>, <image> means <image> rounded up) — the number of sheets, the number of rounds and the largest possible number Ithea can give to Chtholly respectively. The remaining parts of input are given throughout the interaction process.
Interaction
In each round, your program needs to read one line containing a single integer pi (1 ≤ pi ≤ c), indicating the number given to Chtholly.
Your program should then output a line containing an integer between 1 and n, indicating the number of sheet to write down this number in.
After outputting each line, don't forget to flush the output. For example:
* fflush(stdout) in C/C++;
* System.out.flush() in Java;
* sys.stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
If Chtholly wins at the end of a round, no more input will become available and your program should terminate normally. It can be shown that under the constraints, it's always possible for Chtholly to win the game.
Example
Input
2 4 4
2
1
3
Output
1
2
2
Note
In the example, Chtholly initially knew there were 2 sheets, 4 rounds and each number was between 1 and 4. She then received a 2 and decided to write it in the 1st sheet. Then she received a 1 and wrote it in the 2nd sheet. At last, she received a 3 and replaced 1 with 3 in the 2nd sheet. At this time all the sheets were filled with a number and they were non-decreasing, so she won the game.
Note that it is required that your program terminate immediately after Chtholly wins and do not read numbers from the input for the remaining rounds. If not, undefined behaviour may arise and it won't be sure whether your program will be accepted or rejected. Also because of this, please be careful when hacking others' codes. In the sample, Chtholly won the game after the 3rd round, so it is required that your program doesn't read the number of the remaining 4th round.
The input format for hacking:
* The first line contains 3 integers n, m and c;
* The following m lines each contains an integer between 1 and c, indicating the number given to Chtholly in each round. | instruction | 0 | 64,539 | 19 | 129,078 |
Tags: binary search, constructive algorithms, games, greedy, interactive
Correct Solution:
```
import sys
n, m, c = map(int, input().split())
free = n
nums = [0] * n
for i in range(m):
pi = int(input())
if(pi > c//2):
current = n - 1
while(nums[current] > 0 and nums[current] >= pi and current >= 0):current -= 1
if(current == -1):current = 0
if(nums[current] == 0):free -= 1
nums[current] = pi
print(current + 1)
else:
current = 0
while(current < n and nums[current] > 0 and nums[current] <= pi):current += 1
if(current == n):current = n - 1
if(nums[current] == 0):free -=1
nums[current] = pi
print(current + 1)
if(free == 0):break
# Made By Mostafa_Khaled
``` | output | 1 | 64,539 | 19 | 129,079 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem. Refer to the Interaction section below for better understanding.
Ithea and Chtholly want to play a game in order to determine who can use the kitchen tonight.
<image>
Initially, Ithea puts n clear sheets of paper in a line. They are numbered from 1 to n from left to right.
This game will go on for m rounds. In each round, Ithea will give Chtholly an integer between 1 and c, and Chtholly needs to choose one of the sheets to write down this number (if there is already a number before, she will erase the original one and replace it with the new one).
Chtholly wins if, at any time, all the sheets are filled with a number and the n numbers are in non-decreasing order looking from left to right from sheet 1 to sheet n, and if after m rounds she still doesn't win, she loses the game.
Chtholly really wants to win the game as she wants to cook something for Willem. But she doesn't know how to win the game. So Chtholly finds you, and your task is to write a program to receive numbers that Ithea gives Chtholly and help her make the decision on which sheet of paper write this number.
Input
The first line contains 3 integers n, m and c (<image>, <image> means <image> rounded up) — the number of sheets, the number of rounds and the largest possible number Ithea can give to Chtholly respectively. The remaining parts of input are given throughout the interaction process.
Interaction
In each round, your program needs to read one line containing a single integer pi (1 ≤ pi ≤ c), indicating the number given to Chtholly.
Your program should then output a line containing an integer between 1 and n, indicating the number of sheet to write down this number in.
After outputting each line, don't forget to flush the output. For example:
* fflush(stdout) in C/C++;
* System.out.flush() in Java;
* sys.stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
If Chtholly wins at the end of a round, no more input will become available and your program should terminate normally. It can be shown that under the constraints, it's always possible for Chtholly to win the game.
Example
Input
2 4 4
2
1
3
Output
1
2
2
Note
In the example, Chtholly initially knew there were 2 sheets, 4 rounds and each number was between 1 and 4. She then received a 2 and decided to write it in the 1st sheet. Then she received a 1 and wrote it in the 2nd sheet. At last, she received a 3 and replaced 1 with 3 in the 2nd sheet. At this time all the sheets were filled with a number and they were non-decreasing, so she won the game.
Note that it is required that your program terminate immediately after Chtholly wins and do not read numbers from the input for the remaining rounds. If not, undefined behaviour may arise and it won't be sure whether your program will be accepted or rejected. Also because of this, please be careful when hacking others' codes. In the sample, Chtholly won the game after the 3rd round, so it is required that your program doesn't read the number of the remaining 4th round.
The input format for hacking:
* The first line contains 3 integers n, m and c;
* The following m lines each contains an integer between 1 and c, indicating the number given to Chtholly in each round. | instruction | 0 | 64,540 | 19 | 129,080 |
Tags: binary search, constructive algorithms, games, greedy, interactive
Correct Solution:
```
def get_int(string, n):
i = j = k = 0
for s in string:
k += 1
for s in string:
if i == n - 1:
break
if s == ' ':
i += 1
j += 1
i = 0
while j < k:
if string[j] == ' ':
break
i = 10 * i + int(string[j])
j += 1
return i
def check_order(ls, n):
for i in ls:
if i == None:
return 0
for i in range(0, n - 1):
if ls[i] > ls[i + 1]:
return -1
return 1
def forward(p, ls, n):
for i in range(0, n):
if ls[i] == None:
ls[i] = p
print(i + 1)
return 0
if ls[i] > p:
ls[i] = p
print(i + 1)
return 0
def reverse(p, ls, n):
for i in range(0, n):
if ls[n - 1 - i] == None:
ls[n - 1 - i] = p
print(n - i)
return 0
elif ls[n - 1 - i] < p:
ls[n - i - 1] = p
print(n - i)
return 0
x = input()
n = get_int(x, 1)
m = get_int(x, 2)
c = get_int(x, 3)
ls = []
for i in range(0, n):
ls += [None]
for i in range(0, m):
p = int(input())
if p > c/2:
reverse(p, ls, n)
else:
forward(p, ls, n)
if check_order(ls, n) == 1:
break
``` | output | 1 | 64,540 | 19 | 129,081 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem. Refer to the Interaction section below for better understanding.
Ithea and Chtholly want to play a game in order to determine who can use the kitchen tonight.
<image>
Initially, Ithea puts n clear sheets of paper in a line. They are numbered from 1 to n from left to right.
This game will go on for m rounds. In each round, Ithea will give Chtholly an integer between 1 and c, and Chtholly needs to choose one of the sheets to write down this number (if there is already a number before, she will erase the original one and replace it with the new one).
Chtholly wins if, at any time, all the sheets are filled with a number and the n numbers are in non-decreasing order looking from left to right from sheet 1 to sheet n, and if after m rounds she still doesn't win, she loses the game.
Chtholly really wants to win the game as she wants to cook something for Willem. But she doesn't know how to win the game. So Chtholly finds you, and your task is to write a program to receive numbers that Ithea gives Chtholly and help her make the decision on which sheet of paper write this number.
Input
The first line contains 3 integers n, m and c (<image>, <image> means <image> rounded up) — the number of sheets, the number of rounds and the largest possible number Ithea can give to Chtholly respectively. The remaining parts of input are given throughout the interaction process.
Interaction
In each round, your program needs to read one line containing a single integer pi (1 ≤ pi ≤ c), indicating the number given to Chtholly.
Your program should then output a line containing an integer between 1 and n, indicating the number of sheet to write down this number in.
After outputting each line, don't forget to flush the output. For example:
* fflush(stdout) in C/C++;
* System.out.flush() in Java;
* sys.stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
If Chtholly wins at the end of a round, no more input will become available and your program should terminate normally. It can be shown that under the constraints, it's always possible for Chtholly to win the game.
Example
Input
2 4 4
2
1
3
Output
1
2
2
Note
In the example, Chtholly initially knew there were 2 sheets, 4 rounds and each number was between 1 and 4. She then received a 2 and decided to write it in the 1st sheet. Then she received a 1 and wrote it in the 2nd sheet. At last, she received a 3 and replaced 1 with 3 in the 2nd sheet. At this time all the sheets were filled with a number and they were non-decreasing, so she won the game.
Note that it is required that your program terminate immediately after Chtholly wins and do not read numbers from the input for the remaining rounds. If not, undefined behaviour may arise and it won't be sure whether your program will be accepted or rejected. Also because of this, please be careful when hacking others' codes. In the sample, Chtholly won the game after the 3rd round, so it is required that your program doesn't read the number of the remaining 4th round.
The input format for hacking:
* The first line contains 3 integers n, m and c;
* The following m lines each contains an integer between 1 and c, indicating the number given to Chtholly in each round. | instruction | 0 | 64,541 | 19 | 129,082 |
Tags: binary search, constructive algorithms, games, greedy, interactive
Correct Solution:
```
import sys
import math
N, M, C = map(int, input().split())
mid = C // 2
res = []
for i in range(0, N):
res.append(0)
l, r = 0, N - 1
for i in range(0, M):
val = int(input())
pos = 0
if (val <= mid):
for j in range(0, l + 1):
if (res[j] == 0 or val < res[j]):
res[j] = val
pos = j
break
if (pos == l):
l += 1
else:
for j in range(N - 1, r - 1, -1):
if (res[j] == 0 or val > res[j]):
res[j] = val
pos = j
break
if (pos == r):
r -= 1
print ("%d" % (pos + 1))
sys.stdout.flush()
if (l > r):
exit()
``` | output | 1 | 64,541 | 19 | 129,083 |
Provide a correct Python 3 solution for this coding contest problem.
We will host a rock-paper-scissors tournament with N people. The participants are called Person 1, Person 2, \ldots, Person N. For any two participants, the result of the match between them is determined in advance. This information is represented by positive integers A_{i,j} ( 1 \leq j < i \leq N ) as follows:
* If A_{i,j} = 0, Person j defeats Person i.
* If A_{i,j} = 1, Person i defeats Person j.
The tournament proceeds as follows:
* We will arrange the N participants in a row, in the order Person 1, Person 2, \ldots, Person N from left to right.
* We will randomly choose two consecutive persons in the row. They will play a match against each other, and we will remove the loser from the row. We will repeat this process N-1 times, and the last person remaining will be declared the champion.
Find the number of persons with the possibility of becoming the champion.
Constraints
* 1 \leq N \leq 2000
* A_{i,j} is 0 or 1.
Input
Input is given from Standard Input in the following format:
N
A_{2,1}
A_{3,1}A_{3,2}
:
A_{N,1}\ldotsA_{N,N-1}
Output
Print the number of persons with the possibility of becoming the champion.
Examples
Input
3
0
10
Output
2
Input
6
0
11
111
1111
11001
Output
3 | instruction | 0 | 64,632 | 19 | 129,264 |
"Correct Solution:
```
import sys
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.readline())
def SI(): return sys.stdin.readline()[:-1]
def pbit(aa,L):
for a in aa:print(format(a,"b").zfill(L))
print()
def main():
n=II()
aa=[[int(c) for c in SI()] for _ in range(n-1)]
#p2D(aa)
# 人iが勝てる相手をbitで管理する
win=[0]*n
for i,row in enumerate(aa,1):
for j,a in enumerate(row):
if a:win[i]|=1<<j
else:win[j]|=1<<i
#pbit(win,n)
# dpl[i]...[j,i]の範囲で優勝できるjをbitで
# dpr[i]...[i,j]の範囲で優勝できるjをbitで
dpl=[1<<i for i in range(n)]
dpr=[1<<i for i in range(n)]
for d in range(1,n):
for i in range(n):
j=i+d
if j<n and dpl[j] & dpr[i+1] & win[i]:dpl[j]|=1<<i
j=i-d
if j>=0 and dpl[i-1] & dpr[j] & win[i]:dpr[j]|=1<<i
#pbit(dpl,n)
#pbit(dpr,n)
#print(format(dpl[n-1]&dpr[0],"b").zfill(n))
print(bin(dpl[n-1]&dpr[0]).count("1"))
main()
``` | output | 1 | 64,632 | 19 | 129,265 |
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