message stringlengths 2 20.2k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 757 108k | cluster float64 4 4 | __index_level_0__ int64 1.51k 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last n days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last n days, or not.
Input
The first line of input contains single integer n (2 β€ n β€ 100) β the number of days.
The second line contains a string of length n consisting of only capital 'S' and 'F' letters. If the i-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
4
FSSF
Output
NO
Input
2
SF
Output
YES
Input
10
FFFFFFFFFF
Output
NO
Input
10
SSFFSFFSFF
Output
YES
Note
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of Ο in binary representation. Not very useful information though.
Submitted Solution:
```
a=sorted(input())
b=a.count("FS")
c=a.count("SF")
if c>b:
print("YES")
else:
print("NO")
``` | instruction | 0 | 66,142 | 4 | 132,284 |
No | output | 1 | 66,142 | 4 | 132,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last n days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last n days, or not.
Input
The first line of input contains single integer n (2 β€ n β€ 100) β the number of days.
The second line contains a string of length n consisting of only capital 'S' and 'F' letters. If the i-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
4
FSSF
Output
NO
Input
2
SF
Output
YES
Input
10
FFFFFFFFFF
Output
NO
Input
10
SSFFSFFSFF
Output
YES
Note
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of Ο in binary representation. Not very useful information though.
Submitted Solution:
```
a, d=input(), input()
print('YES' if a[0]=='F' and a[-1]=='S' else 'NO')
``` | instruction | 0 | 66,143 | 4 | 132,286 |
No | output | 1 | 66,143 | 4 | 132,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last n days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last n days, or not.
Input
The first line of input contains single integer n (2 β€ n β€ 100) β the number of days.
The second line contains a string of length n consisting of only capital 'S' and 'F' letters. If the i-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
4
FSSF
Output
NO
Input
2
SF
Output
YES
Input
10
FFFFFFFFFF
Output
NO
Input
10
SSFFSFFSFF
Output
YES
Note
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of Ο in binary representation. Not very useful information though.
Submitted Solution:
```
s = input()
if s[0] == 'S' and s[-1] == 'F':
print("YES")
else:
print("NO")
``` | instruction | 0 | 66,144 | 4 | 132,288 |
No | output | 1 | 66,144 | 4 | 132,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last n days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last n days, or not.
Input
The first line of input contains single integer n (2 β€ n β€ 100) β the number of days.
The second line contains a string of length n consisting of only capital 'S' and 'F' letters. If the i-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Examples
Input
4
FSSF
Output
NO
Input
2
SF
Output
YES
Input
10
FFFFFFFFFF
Output
NO
Input
10
SSFFSFFSFF
Output
YES
Note
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of Ο in binary representation. Not very useful information though.
Submitted Solution:
```
q=int(input())
w=input()
if w[0]=='S':
print ("YES")
else :
print ("NO")
``` | instruction | 0 | 66,145 | 4 | 132,290 |
No | output | 1 | 66,145 | 4 | 132,291 |
Provide a correct Python 3 solution for this coding contest problem.
Fast Forwarding
Mr. Anderson frequently rents video tapes of his favorite classic films. Watching the films so many times, he has learned the precise start times of his favorite scenes in all such films. He now wants to find how to wind the tape to watch his favorite scene as quickly as possible on his video player.
When the [play] button is pressed, the film starts at the normal playback speed. The video player has two buttons to control the playback speed: The [3x] button triples the speed, while the [1/3x] button reduces the speed to one third. These speed control buttons, however, do not take effect on the instance they are pressed. Exactly one second after playback starts and every second thereafter, the states of these speed control buttons are checked. If the [3x] button is pressed on the timing of the check, the playback speed becomes three times the current speed. If the [1/3x] button is pressed, the playback speed becomes one third of the current speed, unless it is already the normal speed.
For instance, assume that his favorite scene starts at 19 seconds from the start of the film. When the [3x] button is on at one second and at two seconds after the playback starts, and the [1/3x] button is on at three seconds and at five seconds after the start, the desired scene can be watched in the normal speed five seconds after starting the playback, as depicted in the following chart.
<image>
Your task is to compute the shortest possible time period after the playback starts until the desired scene starts. The playback of the scene, of course, should be in the normal speed.
Input
The input consists of a single test case of the following format.
$t$
The given single integer $t$ ($0 \leq t < 2^{50}$) is the start time of the target scene.
Output
Print an integer that is the minimum possible time in seconds before he can start watching the target scene in the normal speed.
Sample Input 1
19
Sample Output 1
5
Sample Input 2
13
Sample Output 2
5
Sample Input 3
123456789098765
Sample Output 3
85
Sample Input 4
51
Sample Output 4
11
Sample Input 5
0
Sample Output 5
0
Sample Input 6
3
Sample Output 6
3
Sample Input 7
4
Sample Output 7
2
Example
Input
19
Output
5 | instruction | 0 | 67,191 | 4 | 134,382 |
"Correct Solution:
```
#!/usr/bin/env python3
t = int(input())
count = 0
speed = 1
margin = 0
while t > 0:
t -= speed
count += 1
if margin + speed * 3 <= t:
speed *= 3
margin += speed
elif t < margin:
margin -= speed
speed /= 3
print(count)
``` | output | 1 | 67,191 | 4 | 134,383 |
Provide a correct Python 3 solution for this coding contest problem.
Fast Forwarding
Mr. Anderson frequently rents video tapes of his favorite classic films. Watching the films so many times, he has learned the precise start times of his favorite scenes in all such films. He now wants to find how to wind the tape to watch his favorite scene as quickly as possible on his video player.
When the [play] button is pressed, the film starts at the normal playback speed. The video player has two buttons to control the playback speed: The [3x] button triples the speed, while the [1/3x] button reduces the speed to one third. These speed control buttons, however, do not take effect on the instance they are pressed. Exactly one second after playback starts and every second thereafter, the states of these speed control buttons are checked. If the [3x] button is pressed on the timing of the check, the playback speed becomes three times the current speed. If the [1/3x] button is pressed, the playback speed becomes one third of the current speed, unless it is already the normal speed.
For instance, assume that his favorite scene starts at 19 seconds from the start of the film. When the [3x] button is on at one second and at two seconds after the playback starts, and the [1/3x] button is on at three seconds and at five seconds after the start, the desired scene can be watched in the normal speed five seconds after starting the playback, as depicted in the following chart.
<image>
Your task is to compute the shortest possible time period after the playback starts until the desired scene starts. The playback of the scene, of course, should be in the normal speed.
Input
The input consists of a single test case of the following format.
$t$
The given single integer $t$ ($0 \leq t < 2^{50}$) is the start time of the target scene.
Output
Print an integer that is the minimum possible time in seconds before he can start watching the target scene in the normal speed.
Sample Input 1
19
Sample Output 1
5
Sample Input 2
13
Sample Output 2
5
Sample Input 3
123456789098765
Sample Output 3
85
Sample Input 4
51
Sample Output 4
11
Sample Input 5
0
Sample Output 5
0
Sample Input 6
3
Sample Output 6
3
Sample Input 7
4
Sample Output 7
2
Example
Input
19
Output
5 | instruction | 0 | 67,192 | 4 | 134,384 |
"Correct Solution:
```
from sys import stdin, stdout
import math
n = int(stdin.readline().strip())
reserved = 1
maxspeed = 1
while True:
if reserved + maxspeed * 3 > n:
break
maxspeed *= 3
reserved += maxspeed * 2
ans = 1
n -= 1
i = 3
while i < maxspeed:
ans += 2
n -= i * 2
i *= 3
n -= maxspeed
i = maxspeed
while i:
ans += n // i
n -= n // i * i
i //= 3
stdout.writelines(str(ans + 1) + '\n')
``` | output | 1 | 67,192 | 4 | 134,385 |
Provide a correct Python 3 solution for this coding contest problem.
Fast Forwarding
Mr. Anderson frequently rents video tapes of his favorite classic films. Watching the films so many times, he has learned the precise start times of his favorite scenes in all such films. He now wants to find how to wind the tape to watch his favorite scene as quickly as possible on his video player.
When the [play] button is pressed, the film starts at the normal playback speed. The video player has two buttons to control the playback speed: The [3x] button triples the speed, while the [1/3x] button reduces the speed to one third. These speed control buttons, however, do not take effect on the instance they are pressed. Exactly one second after playback starts and every second thereafter, the states of these speed control buttons are checked. If the [3x] button is pressed on the timing of the check, the playback speed becomes three times the current speed. If the [1/3x] button is pressed, the playback speed becomes one third of the current speed, unless it is already the normal speed.
For instance, assume that his favorite scene starts at 19 seconds from the start of the film. When the [3x] button is on at one second and at two seconds after the playback starts, and the [1/3x] button is on at three seconds and at five seconds after the start, the desired scene can be watched in the normal speed five seconds after starting the playback, as depicted in the following chart.
<image>
Your task is to compute the shortest possible time period after the playback starts until the desired scene starts. The playback of the scene, of course, should be in the normal speed.
Input
The input consists of a single test case of the following format.
$t$
The given single integer $t$ ($0 \leq t < 2^{50}$) is the start time of the target scene.
Output
Print an integer that is the minimum possible time in seconds before he can start watching the target scene in the normal speed.
Sample Input 1
19
Sample Output 1
5
Sample Input 2
13
Sample Output 2
5
Sample Input 3
123456789098765
Sample Output 3
85
Sample Input 4
51
Sample Output 4
11
Sample Input 5
0
Sample Output 5
0
Sample Input 6
3
Sample Output 6
3
Sample Input 7
4
Sample Output 7
2
Example
Input
19
Output
5 | instruction | 0 | 67,193 | 4 | 134,386 |
"Correct Solution:
```
#!/usr/bin/python3
import os
import sys
def main():
T = read_int()
print(solve(T))
def solve(T):
if T <= 3:
return T
sec = 1
T -= 1
f = 3
while T >= 2 * f:
T -= 2 * f
f *= 3
sec += 2
if T >= f:
T -= f
sec += 1
else:
f //= 3
while T > 0:
t = T // f
T -= t * f
sec += t
f //= 3
return sec
###############################################################################
DEBUG = 'DEBUG' in os.environ
def inp():
return sys.stdin.readline().rstrip()
def read_int():
return int(inp())
def read_ints():
return [int(e) for e in inp().split()]
def dprint(*value, sep=' ', end='\n'):
if DEBUG:
print(*value, sep=sep, end=end)
if __name__ == '__main__':
main()
``` | output | 1 | 67,193 | 4 | 134,387 |
Provide a correct Python 3 solution for this coding contest problem.
Fast Forwarding
Mr. Anderson frequently rents video tapes of his favorite classic films. Watching the films so many times, he has learned the precise start times of his favorite scenes in all such films. He now wants to find how to wind the tape to watch his favorite scene as quickly as possible on his video player.
When the [play] button is pressed, the film starts at the normal playback speed. The video player has two buttons to control the playback speed: The [3x] button triples the speed, while the [1/3x] button reduces the speed to one third. These speed control buttons, however, do not take effect on the instance they are pressed. Exactly one second after playback starts and every second thereafter, the states of these speed control buttons are checked. If the [3x] button is pressed on the timing of the check, the playback speed becomes three times the current speed. If the [1/3x] button is pressed, the playback speed becomes one third of the current speed, unless it is already the normal speed.
For instance, assume that his favorite scene starts at 19 seconds from the start of the film. When the [3x] button is on at one second and at two seconds after the playback starts, and the [1/3x] button is on at three seconds and at five seconds after the start, the desired scene can be watched in the normal speed five seconds after starting the playback, as depicted in the following chart.
<image>
Your task is to compute the shortest possible time period after the playback starts until the desired scene starts. The playback of the scene, of course, should be in the normal speed.
Input
The input consists of a single test case of the following format.
$t$
The given single integer $t$ ($0 \leq t < 2^{50}$) is the start time of the target scene.
Output
Print an integer that is the minimum possible time in seconds before he can start watching the target scene in the normal speed.
Sample Input 1
19
Sample Output 1
5
Sample Input 2
13
Sample Output 2
5
Sample Input 3
123456789098765
Sample Output 3
85
Sample Input 4
51
Sample Output 4
11
Sample Input 5
0
Sample Output 5
0
Sample Input 6
3
Sample Output 6
3
Sample Input 7
4
Sample Output 7
2
Example
Input
19
Output
5 | instruction | 0 | 67,194 | 4 | 134,388 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools
import time,random
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(): return [list(map(int, l.split())) for l in sys.stdin.readlines()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def pe(s): return print(str(s), file=sys.stderr)
def JA(a, sep): return sep.join(map(str, a))
def JAA(a, s, t): return s.join(t.join(map(str, b)) for b in a)
def main():
n = I()
def f(n):
if n < 4:
return n
return (n-1) % 3 + f((n-1)//3-1) + 2
return f(n)
print(main())
``` | output | 1 | 67,194 | 4 | 134,389 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,626 | 4 | 135,252 |
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
arr = []
for i in range(n):
arr.append([int(x) for x in input().split()])
arr.sort()
pre = min(arr[0][0],arr[0][1])
for i in range(1,n):
temp = min(arr[i][0],arr[i][1])
if (temp<pre):
pre = max(arr[i][0],arr[i][1])
else:
pre = temp
print (pre)
``` | output | 1 | 67,626 | 4 | 135,253 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,627 | 4 | 135,254 |
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
schedule = []
for numbers in range(n):
a =input()
list_a = a.split()
while 10 >= len(list_a[0]):
list_a[0] = "0"+list_a[0]
while 10 >= len(list_a[1]):
list_a[1] = "0"+list_a[1]
schedule.append(list_a[0]+ " " + list_a[1])
score = ""
schedule.sort()
for i in range(len(schedule)):
list_x = list(map(int,schedule[i].split()))
if score =="":
score = list_x[1]
else:
if score > list_x[1]:
score = list_x[0]
else:
score = list_x[1]
print(score)
``` | output | 1 | 67,627 | 4 | 135,255 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,628 | 4 | 135,256 |
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
arr = [0] * n
for i in range(n):
arr[i] = tuple(map(int, input().split()))
arr.sort()
end = arr[0][1]
for i in range(1, n):
if end <= arr[i][1]:
end = arr[i][1]
else:
end = arr[i][0]
print(end)
``` | output | 1 | 67,628 | 4 | 135,257 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,629 | 4 | 135,258 |
Tags: greedy, sortings
Correct Solution:
```
x=int(input())
a=[]
for i in range(x):
x,y=map(int,input().split())
a.append((x,y))
a.sort()
s=0
for i in range(len(a)):
if(s<=a[i][1]):
s=a[i][1]
else:
s=a[i][0]
print(s)
``` | output | 1 | 67,629 | 4 | 135,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,630 | 4 | 135,260 |
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
arr=[]
for i in range(n):
arr.append(tuple(map(int,input().split())))
arr.sort()
m=min(arr[0])
ans=m
for i in range(1,n):
if(arr[i][1]>=m):
m=arr[i][1]
ans=m
else:
m=arr[i][0]
ans=m
print(ans)
``` | output | 1 | 67,630 | 4 | 135,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,631 | 4 | 135,262 |
Tags: greedy, sortings
Correct Solution:
```
def finalDay(schedule):
schedule.sort()
finalDay = schedule[0][1]
for i in range(1, len(schedule)):
if schedule[i][1] >= finalDay:
finalDay = schedule[i][1]
else:
finalDay = schedule[i][0]
return finalDay
def main():
numOfTests = int(input())
schedule = []
for i in range(numOfTests):
test = input()
test = test.split()
assert len(test) == 2, "Invalid input"
for i in range(len(test)):
test[i] = int(test[i])
schedule.append(test)
print(finalDay(schedule))
if __name__ == '__main__':
main()
``` | output | 1 | 67,631 | 4 | 135,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,632 | 4 | 135,264 |
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
arr=[]
for i in range(n):
a=[int(x) for x in input().split()]
arr.append(a)
arr.sort()
ans=0
for i in range(n):
if ans<=arr[i][1]:
ans=arr[i][1]
else:
ans=arr[i][0]
print(ans)
``` | output | 1 | 67,632 | 4 | 135,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. | instruction | 0 | 67,633 | 4 | 135,266 |
Tags: greedy, sortings
Correct Solution:
```
def arr_2d(n):
return [[float(x) for x in stdin.readline().split()] for i in range(n)]
from sys import stdin
from operator import itemgetter
n = int(input())
a = sorted(list(set(map(tuple, arr_2d(n)))), key=itemgetter(0, 1))
ans = int(min(a[0][1], a[0][0]))
if len(a) == 1:
print(ans)
else:
for i in range(1, len(a)):
if a[i][1] >= ans and a[i][1] <= a[i][0]:
ans = a[i][1]
else:
ans = a[i][0]
print(int(ans))
``` | output | 1 | 67,633 | 4 | 135,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
# import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
n = int(input())
exams = []
for _ in range(n):
a, b = map(int, input().split())
exams.append((a, b))
exams.sort()
# print(exams)
minTime = exams[0][1]
for time in exams[1:]:
if minTime > time[1]:
minTime = time[0]
else:
minTime = time[1]
print(minTime)
``` | instruction | 0 | 67,634 | 4 | 135,268 |
Yes | output | 1 | 67,634 | 4 | 135,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
d = [0]
print(([d.append(b) if b >= d[-1] else d.append(a) for a, b in sorted([list(map(int, input().split())) for i in range(int(input()))])] + d)[-1])
``` | instruction | 0 | 67,635 | 4 | 135,270 |
Yes | output | 1 | 67,635 | 4 | 135,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
C = 0
def main():
n = int(input())
a = 0
for b, c in sorted(tuple(map(int, input().split())) for _ in range(n)):
a = b if a > c else c
print(a)
if __name__ == '__main__':
main()
``` | instruction | 0 | 67,636 | 4 | 135,272 |
Yes | output | 1 | 67,636 | 4 | 135,273 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
n = int(input())
listd = []
res = 0
for i in range(n):
listd.append(tuple(map(int, input().split())))
listd.sort()
for a, b in listd:
res = b if res<=b else a
print(res)
``` | instruction | 0 | 67,637 | 4 | 135,274 |
Yes | output | 1 | 67,637 | 4 | 135,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
n=int(input())
a=[]
b=[]
d={}
for i in range(0,n):
x,y=input().split()
x=int(x)
y=int(y)
a.append(x)
b.append(y)
d[a[i]] = b[i]
x=max(a)
print(d)
a.sort()
# print(z)
day=min(a[0],d[a[0]])
maxi=day
for i in range(1,n):
if(d[a[i]]<maxi):
maxi = a[i]
else:
maxi=min(a[i],d[a[i]])
print(maxi)
``` | instruction | 0 | 67,638 | 4 | 135,276 |
No | output | 1 | 67,638 | 4 | 135,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
n = int(input())
listd = []
res = 0
for i in range(n):
listd.append(tuple(map(int, input().split())))
listd.sort()
print(listd)
for a, b in listd:
res = b if res<=b else a
print(res)
``` | instruction | 0 | 67,639 | 4 | 135,278 |
No | output | 1 | 67,639 | 4 | 135,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
if __name__ == '__main__':
n = int(input())
record = []
for i in range(n):
record.append(tuple(map(int, input().split())))
early_record = sorted(record, key=lambda x:(x[1], x[0]))
mark_record = sorted(record, key=lambda x:(x[0], x[1]))
# print(early_record)
# print(mark_record)
# print(early_record == mark_record)
if mark_record == early_record:
print(early_record[n - 1][1])
else:
print(mark_record[n - 1][0])
``` | instruction | 0 | 67,640 | 4 | 135,280 |
No | output | 1 | 67,640 | 4 | 135,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi < ai). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.
Valera believes that it would be rather strange if the entries in the record book did not go in the order of non-decreasing date. Therefore Valera asks you to help him. Find the minimum possible value of the day when Valera can take the final exam if he takes exams so that all the records in his record book go in the order of non-decreasing date.
Input
The first line contains a single positive integer n (1 β€ n β€ 5000) β the number of exams Valera will take.
Each of the next n lines contains two positive space-separated integers ai and bi (1 β€ bi < ai β€ 109) β the date of the exam in the schedule and the early date of passing the i-th exam, correspondingly.
Output
Print a single integer β the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date.
Examples
Input
3
5 2
3 1
4 2
Output
2
Input
3
6 1
5 2
4 3
Output
6
Note
In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5.
In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject.
Submitted Solution:
```
if __name__ == '__main__':
n = int(input())
record = []
for i in range(n):
record.append(tuple(map(int, input().split())))
early_record = sorted(record, key=lambda x:(x[1], x[0]))
mark_record = sorted(early_record, key=lambda x:x[0])
# print(early_record)
# print(mark_record)
# print(early_record == mark_record)
if mark_record == early_record:
print(early_record[n - 1][1])
else:
print(mark_record[n - 1][0])
``` | instruction | 0 | 67,641 | 4 | 135,282 |
No | output | 1 | 67,641 | 4 | 135,283 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,781 | 4 | 135,562 |
Tags: greedy, sortings
Correct Solution:
```
import sys
from collections import defaultdict
shapes = defaultdict(int)
chess_starts = list()
chess_ends = list()
prog_starts = list()
prog_ends = list()
n1 = int(sys.stdin.readline())
for i in range(n1):
input = sys.stdin.readline().strip().split()
chess_starts.append(int(input[0]))
chess_ends.append(int(input[1]))
n2 = int(sys.stdin.readline())
for i in range(n2):
input = sys.stdin.readline().strip().split()
prog_starts.append(int(input[0]))
prog_ends.append(int(input[1]))
max_prog_start = max(prog_starts)
min_prog_end = min(prog_ends)
max_chess_start = max(chess_starts)
min_chess_end = min(chess_ends)
max_a = 0
max_b = 0
if min_prog_end < min_chess_end:
max_a = max_chess_start-min_prog_end
else:
max_a = max_prog_start-min_chess_end
if max_prog_start < max_chess_start:
max_b = max_chess_start-min_prog_end
else:
max_b = max_prog_start-min_chess_end
if max(max_a, max_b) < 0:
print(0)
else:
print(max(max_a, max_b))
``` | output | 1 | 67,781 | 4 | 135,563 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,782 | 4 | 135,564 |
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
ms1 = 0
mt1 = 20000000000
ms2 = 0
mt2 = 20000000000
for _ in range(n):
s, t = [int(x) for x in input().split()]
ms1 = max(ms1, s)
mt1 = min(mt1, t)
m = int(input())
for _ in range(m):
s, t = [int(x) for x in input().split()]
ms2 = max(ms2, s)
mt2 = min(mt2, t)
dif = max(ms1 - mt2, ms2 - mt1)
print(max(0, dif))
``` | output | 1 | 67,782 | 4 | 135,565 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,783 | 4 | 135,566 |
Tags: greedy, sortings
Correct Solution:
```
from sys import stdin, stdout
def is_separated(a,b):
if a[1] < b[0]:
return 2
elif a[0] > b[1]:
return 1
else:
return 0
def calc_rest_time(a,b):
return min(b) - max(a)
def solve(chess, computer):
max_time = 0
for chess_schedule in chess:
for computer_schedule in computer:
difference = is_separated(chess_schedule, computer_schedule)
if difference == 1:
time = calc_rest_time(computer_schedule,chess_schedule)
max_time = max(time, max_time)
elif difference == 2:
time = calc_rest_time(chess_schedule, computer_schedule)
max_time = max(time, max_time)
return max_time
def get_extremes(lst):
min_left = 0
max_right = 0
min_left_value = float('inf')
max_right_value = 0
for e in lst:
if min_left_value > e[1]:
min_left_value = e[1]
min_left = e
if max_right_value < e[0]:
max_right_value = e[0]
max_right = e
return (min_left,max_right)
def solve2(chess, computer):
(min_chess, max_chess) = get_extremes(chess)
(min_computer, max_computer) = get_extremes(computer)
option1_time = 0
option2_time = 0
if is_separated(min_chess, max_computer) == 2:
option1_time = calc_rest_time(min_chess,max_computer)
if is_separated(min_computer, max_chess) == 2:
option2_time = calc_rest_time(min_computer,max_chess)
return max(option1_time,option2_time)
# A [1,5] [2,3] [2,6] extremes => [2,3] [2,3]
# B [2,4] [6,8] => [2,4] [6,8]
chess = []
n = int(stdin.readline())
for i in range(n):
a,b = map(int,input().split())
chess.append((a,b))
computer = []
m = int(stdin.readline())
for i in range(m):
a,b = map(int,input().split())
computer.append((a,b))
solution = solve2(chess, computer)
stdout.write(str(solution))
``` | output | 1 | 67,783 | 4 | 135,567 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,784 | 4 | 135,568 |
Tags: greedy, sortings
Correct Solution:
```
def ok(s, t, n, m):
n = int(n)
m = int(m)
s = sorted(s, key=lambda x: x[1])
t = sorted(t, key=lambda x: x[0])
x1, y1 = s[0]
x2, y2 = t[m - 1]
ans = 0
if y1 < x2:
ans = x2 - y1
return ans
n = int(input())
s = []
for i in range(n):
x, y = map(int, input().split())
s.append((x, y))
m = int(input())
t = []
for i in range(m):
x, y = map(int, input().split())
t.append((x, y))
ans = max(ok(s, t, n, m), ok(t, s, m, n))
print(ans)
``` | output | 1 | 67,784 | 4 | 135,569 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,785 | 4 | 135,570 |
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
max1 = 0
min1 = 10**9
for i in range(n):
l, r = map(int, input().split())
max1 = max(max1, l)
min1 = min(min1, r)
m = int(input())
max2 = 0
min2 = 10**9
for i in range(m):
l, r = map(int, input().split())
max2 = max(max2, l)
min2 = min(min2, r)
print(max(max2-min1, max1-min2, 0))
``` | output | 1 | 67,785 | 4 | 135,571 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,786 | 4 | 135,572 |
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
ln=sorted(list(map(int,input().split())) for _ in range(n))
m=int(input())
lm=sorted(list(map(int,input().split())) for _ in range(m))
lln=sorted(x[::-1] for x in ln)
llm=sorted(x[::-1] for x in lm)
ans=ln[-1][0]-llm[0][0]
if lm[-1][0]-lln[0][0]>ans: ans=lm[-1][0]-lln[0][0]
print(max(0,ans))
``` | output | 1 | 67,786 | 4 | 135,573 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,787 | 4 | 135,574 |
Tags: greedy, sortings
Correct Solution:
```
import sys
def read_bounds():
left = right = None
for _ in range(int(sys.stdin.readline())):
l, r = map(int, sys.stdin.readline().split())
left = min(r, left or r)
right = max(l, right or l)
return left, right
chess_left, chess_right = read_bounds()
prog_left, prog_right = read_bounds()
print(max(max(0, prog_right - chess_left), max(0, chess_right - prog_left)))
``` | output | 1 | 67,787 | 4 | 135,575 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0. | instruction | 0 | 67,788 | 4 | 135,576 |
Tags: greedy, sortings
Correct Solution:
```
import sys
n = int(input())
a_left_max = b_left_max = 1
a_right_min = b_right_min = 1000000000
for i in range(n):
l,r = map(int,input().split())
if a_left_max < l:
a_left_max = l
if a_right_min > r:
a_right_min = r
m = int(input())
for i in range(m):
l, r = map(int, input().split())
if b_left_max < l:
b_left_max = l
if b_right_min > r:
b_right_min = r
"""first chess then programming"""
count1 = b_left_max - a_right_min
"""first programming then chess"""
count2 = a_left_max - b_right_min
print(max(0,max(count1,count2)))
``` | output | 1 | 67,788 | 4 | 135,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n = int(input())
al = []
ar = []
bl = []
br = []
ans = 0
for i in range(n):
x, y = map(int, input().split())
al.append(x)
ar.append(y)
m = int(input())
for i in range(m):
x, y = map(int, input().split())
bl.append(x)
br.append(y)
ans = max(0, max(max(al) - min(br), max(bl) - min(ar)))
print(ans)
``` | instruction | 0 | 67,789 | 4 | 135,578 |
Yes | output | 1 | 67,789 | 4 | 135,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n=int(input())
aa=[]
bb=[]
for _ in range(n):
aa.append(list(map(int,input().split())))
m=int(input())
for _ in range(m):
bb.append(list(map(int,input().split())))
x=min(aa,key=lambda x:x[1])
y=max(bb,key=lambda x:x[0])
mi=max(y[0]-x[1],0)
x=min(bb,key=lambda x:x[1])
y=max(aa,key=lambda x:x[0])
mi=max(mi,max(y[0]-x[1],0))
print(mi)
``` | instruction | 0 | 67,790 | 4 | 135,580 |
Yes | output | 1 | 67,790 | 4 | 135,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n=int(input())
m0,m11,m1,m2=1e10,0,1e10,0
for i in range(n):
l1,r1=map(int,input().split())
m0=min(r1,m0)
m11=max(l1,m11)
m=int(input())
for i in range(m):
l1,r1=map(int,input().split())
m1=min(r1,m1)
m2=max(l1,m2)
t=0
r=max(m2-m0,m11-m1)
print(max(t,r))
``` | instruction | 0 | 67,791 | 4 | 135,582 |
Yes | output | 1 | 67,791 | 4 | 135,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n = int(input())
a = [[],[]]
for i in range(n):
q,w = [int(x) for x in input().split()]
a[0].append(q); a[1].append(w)
n = int(input())
b = [[],[]]
for i in range(n):
q,w = [int(x) for x in input().split()]
b[0].append(q); b[1].append(w)
enda = min(a[1])
stb = max(b[0])
endb = min(b[1])
sta = max(a[0])
if stb - enda > sta - endb:
if stb - enda > 0:
print(stb - enda)
else:
print(0)
else:
if sta - endb > 0:
print(sta - endb)
else:
print(0)
``` | instruction | 0 | 67,792 | 4 | 135,584 |
Yes | output | 1 | 67,792 | 4 | 135,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n=int(input())
p=[0,10**1]
q=[0,10**1]
for i in range(n):
a,b=map(int,input().split())
p[0]=max(p[0],a)
p[1]=min(p[1],b)
m=int(input())
for i in range(m):
a,b=map(int,input().split())
q[0]=max(q[0],a)
q[1]=min(q[1],b)
print(max(0,q[0]-p[1],p[0]-q[1]))
``` | instruction | 0 | 67,793 | 4 | 135,586 |
No | output | 1 | 67,793 | 4 | 135,587 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n = int(input())
mn = 10**10
mn2 = 10**10
mx = 0
mx2 = 0
for i in range(n):
x, y = map(int, input().split())
mn = min(y, mn)
mx2 = max(x, mx2)
m = int(input())
for i in range(m):
x, y = map(int, input().split())
mx = max(x, mx)
mn2 = min(y, mn2)
if mx > mn or mx2 > mn2:
if mx - mn > mx2 - mn:
print(mx - mn)
else:
print(mx2- mn2)
else:
print(0)
``` | instruction | 0 | 67,794 | 4 | 135,588 |
No | output | 1 | 67,794 | 4 | 135,589 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n = int(input())
s = []
for i in range(n):
x, y = map(int, input().split())
s.append((x, y))
s = sorted(s, key=lambda x: x[1])
m = int(input())
t = []
for i in range(m):
x, y = map(int, input().split())
t.append((x, y))
t = sorted(t, key=lambda x: x[0])
# print(s)
# print(t)
x1, y1 = s[0]
x2, y2 = t[m - 1]
ans = 0
if y1 < x2:
ans = x2 - y1
#print(x1, y1, x2, y2)
print(ans)
``` | instruction | 0 | 67,795 | 4 | 135,590 |
No | output | 1 | 67,795 | 4 | 135,591 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anton likes to play chess. Also he likes to do programming. No wonder that he decided to attend chess classes and programming classes.
Anton has n variants when he will attend chess classes, i-th variant is given by a period of time (l1, i, r1, i). Also he has m variants when he will attend programming classes, i-th variant is given by a period of time (l2, i, r2, i).
Anton needs to choose exactly one of n possible periods of time when he will attend chess classes and exactly one of m possible periods of time when he will attend programming classes. He wants to have a rest between classes, so from all the possible pairs of the periods he wants to choose the one where the distance between the periods is maximal.
The distance between periods (l1, r1) and (l2, r2) is the minimal possible distance between a point in the first period and a point in the second period, that is the minimal possible |i - j|, where l1 β€ i β€ r1 and l2 β€ j β€ r2. In particular, when the periods intersect, the distance between them is 0.
Anton wants to know how much time his rest between the classes will last in the best case. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 β€ n β€ 200 000) β the number of time periods when Anton can attend chess classes.
Each of the following n lines of the input contains two integers l1, i and r1, i (1 β€ l1, i β€ r1, i β€ 109) β the i-th variant of a period of time when Anton can attend chess classes.
The following line of the input contains a single integer m (1 β€ m β€ 200 000) β the number of time periods when Anton can attend programming classes.
Each of the following m lines of the input contains two integers l2, i and r2, i (1 β€ l2, i β€ r2, i β€ 109) β the i-th variant of a period of time when Anton can attend programming classes.
Output
Output one integer β the maximal possible distance between time periods.
Examples
Input
3
1 5
2 6
2 3
2
2 4
6 8
Output
3
Input
3
1 5
2 6
3 7
2
2 4
1 4
Output
0
Note
In the first sample Anton can attend chess classes in the period (2, 3) and attend programming classes in the period (6, 8). It's not hard to see that in this case the distance between the periods will be equal to 3.
In the second sample if he chooses any pair of periods, they will intersect. So the answer is 0.
Submitted Solution:
```
n = int(input())
l1max = -1
r1min = 10**9 + 5
for _ in range(n):
l, r = map(int, input().split(' '))
l1max = max(l, l1max)
r1min = min(r, r1min)
m = int(input())
l2max = -1
r2min = 10**9 + 5
for _ in range(m):
l, r = map(int, input().split(' '))
l2max = max(l, l1max)
r2min = min(r, r1min)
print(max(0, l1max-r2min, l2max-r1min))
``` | instruction | 0 | 67,796 | 4 | 135,592 |
No | output | 1 | 67,796 | 4 | 135,593 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,021 | 4 | 140,042 |
Tags: math, number theory
Correct Solution:
```
import math
for _ in range(int(input())) :
m,d,w = map(int,input().split())
x = min(m,d)
g =int( w/ math.gcd(d-1,w))
f = int(x/g)
print(x*f - f*(f+1)//2*g)
``` | output | 1 | 70,021 | 4 | 140,043 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,022 | 4 | 140,044 |
Tags: math, number theory
Correct Solution:
```
import sys
sys.setrecursionlimit(2147483647)
input=sys.stdin.readline
import math
def calc(arr):
m ,d, w = arr
max_x = min(m,d)
if (d-1) % w == 0:
return max_x * (max_x-1) //2
else:
s = math.gcd(d-1,w)
w = w//s
res = (max_x) % w
b = (max_x) // w
ans = b * (b-1) // 2 * w + res * b
return ans
if __name__=='__main__':
n,arr = int(input()),[]
for _ in range(n):arr.append(calc(list(map(int, input().split(' ')))))
for a in arr:print(a)
``` | output | 1 | 70,022 | 4 | 140,045 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,023 | 4 | 140,046 |
Tags: math, number theory
Correct Solution:
```
def gcd(m,n):
while n:
m,n = n,m%n
return m
for _ in range(int(input())):
m,d,w = map(int,input().split())
res = 0
t = ((d%w)-1)%w
gap = w//gcd(w,t)
a = min(m,d)-gap
b = ((min(d,m)-1)%gap)+1
h = ((a-b)//gap)+1
print((a+b)*h>>1)
``` | output | 1 | 70,023 | 4 | 140,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,024 | 4 | 140,048 |
Tags: math, number theory
Correct Solution:
```
import math
t = int(input())
for _ in range(t):
m,d,w = map(int,input().split())
l = min(m,d)
if (d-1)%w == 0:
print(l*(l-1)//2)
else:
gcd = math.gcd(w,d-1)
w2 = w//gcd
a = l-w2
if a > 0:
b = l%w2
c = l//w2
print((a+b)*c//2)
else:
print(0)
``` | output | 1 | 70,024 | 4 | 140,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,025 | 4 | 140,050 |
Tags: math, number theory
Correct Solution:
```
def gcd(a, b):
if a == 0:
return b
return gcd(b % a, a)
def calendar():
t = int(input())
for i in range(t):
m, d, w = map(int, input().split())
w2 = w // gcd(w, d - 1)
m2 = min(m, d)
x = m2 // w2
print(x * m2 - x * (x+1) // 2 * w2)
calendar()
``` | output | 1 | 70,025 | 4 | 140,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,026 | 4 | 140,052 |
Tags: math, number theory
Correct Solution:
```
import sys
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s); sys.stdout.write('\n')
def wi(n): sys.stdout.write(str(n)); sys.stdout.write('\n')
def wia(a, sep=' '): sys.stdout.write(sep.join([str(x) for x in a])); sys.stdout.write('\n')
import math
def solve(m, d, w):
mn = min(m, d)
s = w // math.gcd(d-1, w)
# find all pairs of numbers in [1, mn] range having the same remainder modulo s
# x - y == 0 mod s
# x == y mod s
k = mn // s
ans = mn * k - s * (k * (k + 1) // 2)
return ans
def main():
for _ in range(ri()):
m, d, w = ria()
wi(solve(m, d, w))
if __name__ == '__main__':
main()
``` | output | 1 | 70,026 | 4 | 140,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,027 | 4 | 140,054 |
Tags: math, number theory
Correct Solution:
```
def gcd(x,y):
if x%y==0:
return y
return gcd(y,x%y)
t = int(input())
for _ in range(t):
m,d,w = map(int,input().split())
limit = min(m,d)
# if d==1:
# print((limit-1)*(limit-2)//2)
# else:
a = w//gcd(w,d-1) if d>1 else 1
num = limit // a
head,root = limit - a, limit-a*num
print((head+root)*num//2)
``` | output | 1 | 70,027 | 4 | 140,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image> | instruction | 0 | 70,028 | 4 | 140,056 |
Tags: math, number theory
Correct Solution:
```
import math
forprint=[]
def solve_brute(m,d,w):
mn = min(m,d)
ww = w // math.gcd(w,d-1)
sol = 0
for i in range(1,mn//ww +1):
sol += mn - i*ww
forprint.append(str(sol))
def brute():
t=int(input())
while t:
m,d,w = map(int,input().split())
solve_brute(m,d,w)
t-=1
def solve(m,d,w):
mn = min(m,d)
ww = w // math.gcd(w,d-1)
total = mn//ww
sol = total*mn - ww*total*(total+1)//2
forprint.append(str(sol))
def main():
t=int(input())
while t:
m,d,w = map(int,input().split())
solve(m,d,w)
t-=1
main()
#brute()
print("\n".join(forprint))
``` | output | 1 | 70,028 | 4 | 140,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image>
Submitted Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
from collections import defaultdict
from itertools import permutations
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
def GCD(x, y):
while(y):x,y=y,x%y
return x
for i in ' '*int(input()):
m,d,w=map(int,input().split())
m=min(m,d)
g=GCD(d-1,w)
ww=w//g
k=m//ww
print(k*m-k*(k+1)//2*ww)
``` | instruction | 0 | 70,029 | 4 | 140,058 |
Yes | output | 1 | 70,029 | 4 | 140,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Berland year consists of m months with d days each. Months are numbered from 1 to m. Berland week consists of w days. The first day of the year is also the first day of the week. Note that the last week of the year might be shorter than w days.
A pair (x, y) such that x < y is ambiguous if day x of month y is the same day of the week as day y of month x.
Count the number of ambiguous pairs.
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of testcases.
Each of the next t lines contains three integers m, d and w (1 β€ m, d, w β€ 10^9) β the number of months in a year, the number of days in a month and the number of days in a week.
Output
Print t integers β for each testcase output the number of pairs (x, y) such that x < y and day x of month y is the same day of the week as day y of month x.
Example
Input
5
6 7 4
10 7 12
12 30 7
1 1 1
3247834 10298779 625324
Output
6
9
5
0
116461800
Note
Here are the pairs for the first test case:
<image>
Submitted Solution:
```
from sys import stdin, setrecursionlimit as srl
from threading import stack_size, Thread
srl(int(1e9)+7)
stack_size(int(1e8))
def hcf(a,b):
if a<b:
a,b = b,a
if b==0:
return a
return hcf(b,a%b)
def solve():
t = int ( input () )
for _ in range ( t ) :
m,d,w =map(int,input().split())
i=1
gap=w//(hcf(w,d-1))
limit=min(d,m)
var=(limit-1)//gap
ans=limit*var-(gap*var*(var+1))//2
print(ans)
Thread(target=solve).start()
``` | instruction | 0 | 70,030 | 4 | 140,060 |
Yes | output | 1 | 70,030 | 4 | 140,061 |
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