message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Long story short, shashlik is Miroslav's favorite food. Shashlik is prepared on several skewers simultaneously. There are two states for each skewer: initial and turned over.
This time Miroslav laid out n skewers parallel to each other, and enumerated them with consecutive integers from 1 to n in order from left to right. For better cooking, he puts them quite close to each other, so when he turns skewer number i, it leads to turning k closest skewers from each side of the skewer i, that is, skewers number i - k, i - k + 1, ..., i - 1, i + 1, ..., i + k - 1, i + k (if they exist).
For example, let n = 6 and k = 1. When Miroslav turns skewer number 3, then skewers with numbers 2, 3, and 4 will come up turned over. If after that he turns skewer number 1, then skewers number 1, 3, and 4 will be turned over, while skewer number 2 will be in the initial position (because it is turned again).
As we said before, the art of cooking requires perfect timing, so Miroslav wants to turn over all n skewers with the minimal possible number of actions. For example, for the above example n = 6 and k = 1, two turnings are sufficient: he can turn over skewers number 2 and 5.
Help Miroslav turn over all n skewers.
Input
The first line contains two integers n and k (1 ≤ n ≤ 1000, 0 ≤ k ≤ 1000) — the number of skewers and the number of skewers from each side that are turned in one step.
Output
The first line should contain integer l — the minimum number of actions needed by Miroslav to turn over all n skewers. After than print l integers from 1 to n denoting the number of the skewer that is to be turned over at the corresponding step.
Examples
Input
7 2
Output
2
1 6
Input
5 1
Output
2
1 4
Note
In the first example the first operation turns over skewers 1, 2 and 3, the second operation turns over skewers 4, 5, 6 and 7.
In the second example it is also correct to turn over skewers 2 and 5, but turning skewers 2 and 4, or 1 and 5 are incorrect solutions because the skewer 3 is in the initial state after these operations.
Submitted Solution:
```
#!/usr/bin/python3
def readint():
return int(input())
def readline():
return [int(c) for c in input().split()]
def main():
n, k = readline()
if 2 * k + 1 > n:
print(n//2)
return
affected = k * 2 + 1
affected_side = k
num_indip_turns, rem = divmod(n, affected)
res = []
if rem == 0:
ans = num_indip_turns
for i in range(num_indip_turns):
res.append(k*(i+1)+1)
elif rem >= k + 1:
ans = num_indip_turns + 1
for i in range(num_indip_turns):
res.append(k*(i+1)+1)
res.append(n)
else:
ans = num_indip_turns + 1
for i in range(num_indip_turns):
res.append(k*(i+1)+1)
for i in range(num_indip_turns):
res[i] = res[i] - (k+1 - rem)
res.append(n)
print(ans)
print(' '.join([str(i-1) for i in res]))
if __name__ == '__main__':
main()
``` | instruction | 0 | 73,315 | 9 | 146,630 |
No | output | 1 | 73,315 | 9 | 146,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Long story short, shashlik is Miroslav's favorite food. Shashlik is prepared on several skewers simultaneously. There are two states for each skewer: initial and turned over.
This time Miroslav laid out n skewers parallel to each other, and enumerated them with consecutive integers from 1 to n in order from left to right. For better cooking, he puts them quite close to each other, so when he turns skewer number i, it leads to turning k closest skewers from each side of the skewer i, that is, skewers number i - k, i - k + 1, ..., i - 1, i + 1, ..., i + k - 1, i + k (if they exist).
For example, let n = 6 and k = 1. When Miroslav turns skewer number 3, then skewers with numbers 2, 3, and 4 will come up turned over. If after that he turns skewer number 1, then skewers number 1, 3, and 4 will be turned over, while skewer number 2 will be in the initial position (because it is turned again).
As we said before, the art of cooking requires perfect timing, so Miroslav wants to turn over all n skewers with the minimal possible number of actions. For example, for the above example n = 6 and k = 1, two turnings are sufficient: he can turn over skewers number 2 and 5.
Help Miroslav turn over all n skewers.
Input
The first line contains two integers n and k (1 ≤ n ≤ 1000, 0 ≤ k ≤ 1000) — the number of skewers and the number of skewers from each side that are turned in one step.
Output
The first line should contain integer l — the minimum number of actions needed by Miroslav to turn over all n skewers. After than print l integers from 1 to n denoting the number of the skewer that is to be turned over at the corresponding step.
Examples
Input
7 2
Output
2
1 6
Input
5 1
Output
2
1 4
Note
In the first example the first operation turns over skewers 1, 2 and 3, the second operation turns over skewers 4, 5, 6 and 7.
In the second example it is also correct to turn over skewers 2 and 5, but turning skewers 2 and 4, or 1 and 5 are incorrect solutions because the skewer 3 is in the initial state after these operations.
Submitted Solution:
```
n, k = map(int, input().split())
a, b = divmod(n, 2 * k + 1)
print(a)
print(*range(b // 2 if b else k, n + 1, 2 * k + 1))
``` | instruction | 0 | 73,316 | 9 | 146,632 |
No | output | 1 | 73,316 | 9 | 146,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Long story short, shashlik is Miroslav's favorite food. Shashlik is prepared on several skewers simultaneously. There are two states for each skewer: initial and turned over.
This time Miroslav laid out n skewers parallel to each other, and enumerated them with consecutive integers from 1 to n in order from left to right. For better cooking, he puts them quite close to each other, so when he turns skewer number i, it leads to turning k closest skewers from each side of the skewer i, that is, skewers number i - k, i - k + 1, ..., i - 1, i + 1, ..., i + k - 1, i + k (if they exist).
For example, let n = 6 and k = 1. When Miroslav turns skewer number 3, then skewers with numbers 2, 3, and 4 will come up turned over. If after that he turns skewer number 1, then skewers number 1, 3, and 4 will be turned over, while skewer number 2 will be in the initial position (because it is turned again).
As we said before, the art of cooking requires perfect timing, so Miroslav wants to turn over all n skewers with the minimal possible number of actions. For example, for the above example n = 6 and k = 1, two turnings are sufficient: he can turn over skewers number 2 and 5.
Help Miroslav turn over all n skewers.
Input
The first line contains two integers n and k (1 ≤ n ≤ 1000, 0 ≤ k ≤ 1000) — the number of skewers and the number of skewers from each side that are turned in one step.
Output
The first line should contain integer l — the minimum number of actions needed by Miroslav to turn over all n skewers. After than print l integers from 1 to n denoting the number of the skewer that is to be turned over at the corresponding step.
Examples
Input
7 2
Output
2
1 6
Input
5 1
Output
2
1 4
Note
In the first example the first operation turns over skewers 1, 2 and 3, the second operation turns over skewers 4, 5, 6 and 7.
In the second example it is also correct to turn over skewers 2 and 5, but turning skewers 2 and 4, or 1 and 5 are incorrect solutions because the skewer 3 is in the initial state after these operations.
Submitted Solution:
```
import math
text = input('')
[n, k] = [int(z) for z in text.split()]
if k == 0:
print(n)
print(' '.join(str(z) for z in range(1, n + 1)))
elif 2 * k + 1 >= n:
print(1)
print(math.ceil(n/2))
else:
stride = k * 2 + 1
l = int(n/stride) + 1
print(l)
arr =[]
if n % stride >= k + 1:
for i in range(l):
arr.append(stride * i + k + 1)
print(' '.join(str(v) for v in arr))
else:
initial = 1
arr.append(initial)
for i in range(l - 1):
arr.append(initial + k + stride * i + k + 1)
print(' '.join(str(v) for v in arr))
``` | instruction | 0 | 73,317 | 9 | 146,634 |
No | output | 1 | 73,317 | 9 | 146,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Long story short, shashlik is Miroslav's favorite food. Shashlik is prepared on several skewers simultaneously. There are two states for each skewer: initial and turned over.
This time Miroslav laid out n skewers parallel to each other, and enumerated them with consecutive integers from 1 to n in order from left to right. For better cooking, he puts them quite close to each other, so when he turns skewer number i, it leads to turning k closest skewers from each side of the skewer i, that is, skewers number i - k, i - k + 1, ..., i - 1, i + 1, ..., i + k - 1, i + k (if they exist).
For example, let n = 6 and k = 1. When Miroslav turns skewer number 3, then skewers with numbers 2, 3, and 4 will come up turned over. If after that he turns skewer number 1, then skewers number 1, 3, and 4 will be turned over, while skewer number 2 will be in the initial position (because it is turned again).
As we said before, the art of cooking requires perfect timing, so Miroslav wants to turn over all n skewers with the minimal possible number of actions. For example, for the above example n = 6 and k = 1, two turnings are sufficient: he can turn over skewers number 2 and 5.
Help Miroslav turn over all n skewers.
Input
The first line contains two integers n and k (1 ≤ n ≤ 1000, 0 ≤ k ≤ 1000) — the number of skewers and the number of skewers from each side that are turned in one step.
Output
The first line should contain integer l — the minimum number of actions needed by Miroslav to turn over all n skewers. After than print l integers from 1 to n denoting the number of the skewer that is to be turned over at the corresponding step.
Examples
Input
7 2
Output
2
1 6
Input
5 1
Output
2
1 4
Note
In the first example the first operation turns over skewers 1, 2 and 3, the second operation turns over skewers 4, 5, 6 and 7.
In the second example it is also correct to turn over skewers 2 and 5, but turning skewers 2 and 4, or 1 and 5 are incorrect solutions because the skewer 3 is in the initial state after these operations.
Submitted Solution:
```
n, k = map(int, input().split())
t = n // (2 * k + 1)
left = n % (2 * k + 1)
print(t + 1 if left > 0 else 0)
for i in range(1 if left <= k else left - k, n + 1, 2 * k + 1):
print(i, end=' ')
``` | instruction | 0 | 73,318 | 9 | 146,636 |
No | output | 1 | 73,318 | 9 | 146,637 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,738 | 9 | 149,476 |
Tags: binary search, implementation
Correct Solution:
```
# -*- coding: utf-8 -*-
import bisect
import heapq
import math
import random
import sys
from collections import Counter, defaultdict
from decimal import ROUND_CEILING, ROUND_HALF_UP, Decimal
from functools import lru_cache, reduce
from itertools import combinations, combinations_with_replacement, product, permutations
sys.setrecursionlimit(10000)
def read_int():
return int(input())
def read_int_n():
return list(map(int, input().split()))
def read_float():
return float(input())
def read_float_n():
return list(map(float, input().split()))
def read_str():
return input()
def read_str_n():
return list(map(str, input().split()))
def error_print(*args):
print(*args, file=sys.stderr)
def mt(f):
import time
def wrap(*args, **kwargs):
s = time.time()
ret = f(*args, **kwargs)
e = time.time()
error_print(e - s, 'sec')
return ret
return wrap
def sim(n, k):
ans = 0
while n > 0:
if n >= k:
ans += k
n -= k
else:
ans += n
n = 0
n -= n //10
return ans
def slv2(N):
for k in range(1, N):
if sim(N, k) >= N/2:
return k
return 1
@mt
def slv(N):
if N < 1000:
return slv2(N)
sk = int(N*0.03)
ek = int(N*0.1)
cnd = {}
while True:
if ek - sk <= 1:
break
ck = (sk + ek)//2
v = sim(N, ck)
cnd[ck] = v
if v <= N/2:
sk = ck
else:
ek = ck
H = N//2
if H*2 == N:
H -= 1
keys = sorted(cnd.keys())
for i, k in enumerate(keys):
if cnd[k] > H:
error_print(keys[i-1], keys[i])
for j in range(keys[i-1], keys[i]):
cnd[j] = sim(N, j)
break
keys = sorted(cnd.keys())
for i, k in enumerate(keys):
if cnd[k] > H:
return k
def main():
N = read_int()
# N = 999999999999999973
# N = int(1e+18)
# N = random.randint(int(1e+18)-10000, int(1e+18))
print(slv(N))
# for n in range(1000000, 1000000+10):
# print(n)
# a = slv(n)
# b = slv2(n)
# if a != b:
# print(n, a, b)
# break
if __name__ == '__main__':
main()
``` | output | 1 | 74,738 | 9 | 149,477 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,739 | 9 | 149,478 |
Tags: binary search, implementation
Correct Solution:
```
def cookiesConsumed(n,k):
totalCount = 0
while n>0:
vasya = min(k,n)
totalCount+=vasya
n-=vasya
n-=n//10
return totalCount
n = int(input())
target = (n+1)//2
l=1
r=target
while r>=l:
k = l+(r-l)//2
consumed = cookiesConsumed(n,k)
if consumed==target:
print(k)
break
if consumed<target:
l = k + 1
if consumed>target:
r = k -1
else:
print(l)
``` | output | 1 | 74,739 | 9 | 149,479 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,740 | 9 | 149,480 |
Tags: binary search, implementation
Correct Solution:
```
def bs(l, h):
while l < h:
m = (l + h) // 2
if gf(m):
h = m
else:
l = m + 1
return l
def gf(k):
p = t
c = 0
while p > 0:
c += min(p, k)
p -= min(p, k)
p -= p // 10
return c >= (t + 1) // 2
t = int(input())
print(bs(1, (t + 1) // 2))
``` | output | 1 | 74,740 | 9 | 149,481 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,741 | 9 | 149,482 |
Tags: binary search, implementation
Correct Solution:
```
def calc():
n = int(input())
l = 1
r = int(1e18)
ans = l
def possible(k):
v, p = [0, 0]
tot = n
while True:
cur = min(tot, k)
v += cur
tot -= cur
# print(tot)
cur = tot//10
p += cur
tot -= cur
# print(tot)
if tot == 0:
break
# print("for", k, " vasya got:", v)
return v >= (n+1)//2
while l <= r:
m = (l+r)//2
if possible(m):
ans = m
r = m-1
else:
l = m+1
print(ans)
# possible(3)
calc()
``` | output | 1 | 74,741 | 9 | 149,483 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,742 | 9 | 149,484 |
Tags: binary search, implementation
Correct Solution:
```
n = int(input())
def check(k, n):
s = 0
cur = n
while cur > 0:
t = min(cur, k)
s += t
cur -= t
cur -= cur // 10
return s * 2 >= n
l = 1
r = n // 2
while l < r - 1:
m = (l + r) // 2
if not check(m, n):
l = m + 1
else:
r = m
if l == 0:
print(r)
else:
if check(l,n):
print(l)
else:
print(r)
``` | output | 1 | 74,742 | 9 | 149,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,743 | 9 | 149,486 |
Tags: binary search, implementation
Correct Solution:
```
def helper(k, numCandies):
candiesLeft = numCandies
v = 0
while (candiesLeft > 0):
if (candiesLeft < k):
v += candiesLeft
candiesLeft = 0
else:
v += k
candiesLeft = candiesLeft - k - ((candiesLeft - k) // 10)
if (v >= ((numCandies + 1) // 2)):
return 1
else:
return 0
def p3(numCandies):
start = 1
end = numCandies
if (numCandies <= 42):
if (numCandies == 41):
return 2
else:
return 1
while (start <= end):
mid = (end + start) // 2
if (helper(mid, numCandies) == 1):
end = mid - 1
else:
start = mid + 1
return start
n = int(input())
print(p3(n))
``` | output | 1 | 74,743 | 9 | 149,487 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,744 | 9 | 149,488 |
Tags: binary search, implementation
Correct Solution:
```
import configparser
import sys
input = sys.stdin.readline
def ceil_div(x, y):
return -(-x // y)
def can(k, n):
if k == 0:
return False
org = n
i = 0
while n > 0:
take_off = min(n, k)
n -= take_off
i += take_off
n -= (n//10)
return i >= ceil_div(org, 2)
def main():
n = int(input())
pos = -1
for i in range(70, -1, -1):
jump = (1 << i)
if not can(pos+jump, n):
pos += jump
print(pos+1)
if __name__ == '__main__':
main()
``` | output | 1 | 74,744 | 9 | 149,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29. | instruction | 0 | 74,745 | 9 | 149,490 |
Tags: binary search, implementation
Correct Solution:
```
def read_input():
return map(int, input().split())
n = int(input())
def eat(k, n):
ans = 0
while n >= k:
ans += k
n = max(0, (n - k) - (n - k) // 10)
ans += n
return ans
l = 1
r = n + 1
while r - l > 1:
m = (l + r) >> 1
if 2 * eat(m, n) >= n:
r = m
else:
l = m
print(l if 2 * eat(l, n) >= n else l + 1)
``` | output | 1 | 74,745 | 9 | 149,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
import math
getInputList = lambda : list(input().split())
getInputIntList = lambda : list(map(int,input().split()))
n = int(input())
h = (n+1)//2
left = 1
right = n
def eat(k,n):
a = 0
while n > 0:
#print(a,n,k)
a += min(k,n)
n -= min(k,n)
n -= (n*10)//100
return a
if n != 1:
while left <= right:
m = (left + right)//2
eat1 = eat(m,n)
eat2 = 0
if m-1 > 0:
eat2 = eat(m-1,n)
if eat1 >= h and eat2 < h:
#print(eat1,eat2,h)
print(m)
break
if eat1 < h:
left = m
else:
right = m
else:
print(1)
``` | instruction | 0 | 74,746 | 9 | 149,492 |
Yes | output | 1 | 74,746 | 9 | 149,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
n=int(input())
def bs(m,temp):
vasya=0
while(temp>0):
if temp<=m:
vasya+=temp
break
vasya+=m
temp-=m
temp-=temp//10
if vasya*2>=n:
return True
else:
return False
lo,hi=1,n//2+1
while(lo<=hi):
m=(lo+hi)//2
if bs(m,n):
ans=m
hi=m-1
else:
lo=m+1
print(ans)
``` | instruction | 0 | 74,747 | 9 | 149,494 |
Yes | output | 1 | 74,747 | 9 | 149,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
def main():
N = int(input())
left, right, x, k, a = 1, N, 1, 0, 0
while right >= left:
n = N
x = (left+right)//2
a = 0
while 1:
if n < x:
a += n
break
a += x
n -= x
n -= n // 10
if a >= (N+1)//2:
k = x
right = x - 1
else:
left = x + 1
print(k)
if __name__ == "__main__":
main()
``` | instruction | 0 | 74,748 | 9 | 149,496 |
Yes | output | 1 | 74,748 | 9 | 149,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
n = int(input())
def check(k):
num = n
f, s = 0, 0
while True:
if num < k:
f += num
break
else:
f += k
num -= k
z = num // 10
num -= z
s += z
return f >= s
l= 1
r = n
while l <= r:
if (l == r):
mid = l
break
mid = (l + r) // 2
if check(mid):
r = mid
else:
l = mid + 1
print(mid)
``` | instruction | 0 | 74,749 | 9 | 149,498 |
Yes | output | 1 | 74,749 | 9 | 149,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
n=int(input())
def bs(m,temp):
vasya=0
while(temp>0):
if temp<m:
vasya+=temp
break
vasya+=m
temp-=m
temp-=temp//10
if vasya>=n//2:
return True
else:
return False
lo,hi=1,n//2
while(lo<hi):
m=(lo+hi)//2
if bs(m,n):
hi=m-1
else:
lo=m+1
print(lo)
``` | instruction | 0 | 74,750 | 9 | 149,500 |
No | output | 1 | 74,750 | 9 | 149,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
n=int(input())
z=n
k1=0
k2=0
k=int(n*4/100)
sum1=0
sum2=0
if n<25:
print(1)
else:
while n>0:
n=n-k
sum1=sum1+k
if n>9:
sum2 = sum2 + int(n * 0.1)
n=n-int(n*0.1)
if sum1>sum2:
k1=k
n=z
k=int(n*5/100)
sum1=0
sum2=0
while n>0:
n=n-k
sum1=sum1+k
if n>9:
sum2 = sum2 + int(n * 0.1)
n=n-int(n*0.1)
if sum1>sum2:
k2=k
if (k1<k2) and k1!=0:
print(k1)
else:
print(k2)
``` | instruction | 0 | 74,751 | 9 | 149,502 |
No | output | 1 | 74,751 | 9 | 149,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
n=int(input())
def petya(n,k):
p=0
count=0
while n>=0:
n-=k
if(n>=10):
p=int(0.1*n)
count=count+p
n=n-p
return count
low=1
high=n
candies=n
aim=candies/2
while low<=high:
mid=(low+high)//2
vaas=candies-petya(candies,mid)
if(vaas<aim):
low=mid+1
else:
high=mid-1
print(mid)
``` | instruction | 0 | 74,752 | 9 | 149,504 |
No | output | 1 | 74,752 | 9 | 149,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After passing a test, Vasya got himself a box of n candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya chooses a single integer k, same for all days. After that, in the morning he eats k candies from the box (if there are less than k candies in the box, he eats them all), then in the evening Petya eats 10\% of the candies remaining in the box. If there are still candies left in the box, the process repeats — next day Vasya eats k candies again, and Petya — 10\% of the candies left in a box, and so on.
If the amount of candies in the box is not divisible by 10, Petya rounds the amount he takes from the box down. For example, if there were 97 candies in the box, Petya would eat only 9 of them. In particular, if there are less than 10 candies in a box, Petya won't eat any at all.
Your task is to find out the minimal amount of k that can be chosen by Vasya so that he would eat at least half of the n candies he initially got. Note that the number k must be integer.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^{18}) — the initial amount of candies in the box.
Output
Output a single integer — the minimal amount of k that would allow Vasya to eat at least half of candies he got.
Example
Input
68
Output
3
Note
In the sample, the amount of candies, with k=3, would change in the following way (Vasya eats first):
68 → 65 → 59 → 56 → 51 → 48 → 44 → 41 \\\ → 37 → 34 → 31 → 28 → 26 → 23 → 21 → 18 → 17 → 14 \\\ → 13 → 10 → 9 → 6 → 6 → 3 → 3 → 0.
In total, Vasya would eat 39 candies, while Petya — 29.
Submitted Solution:
```
from collections import Counter
n = int(input())
def check(k):
start = n
a = 0
b = 0
while start> 0:
a+=min(k,start)
start = max(0,start-k)
b+=start//10
start-=max(0,start-start//10)
return a>=b
left = 0
right = n
while left<right:
mid = (left+right+1)//2
if check(mid):
right = mid-1
else:
left = mid
print(mid)
``` | instruction | 0 | 74,753 | 9 | 149,506 |
No | output | 1 | 74,753 | 9 | 149,507 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,143 | 9 | 150,286 |
Tags: implementation
Correct Solution:
```
import functools
import operator
n = input()
lul = input().split()
lul = [int(i) for i in lul]
total = functools.reduce(operator.add,lul)
c = 0
for i in lul:
if ((total-i)%2 == 0):
c += 1
print(c)
``` | output | 1 | 75,143 | 9 | 150,287 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,144 | 9 | 150,288 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = [int(x) for x in input().split(" ")]
j=0
for i in range(n):
b= list(a)
b.pop(i)
if sum(b)%2==0:
j+=1
print(j)
``` | output | 1 | 75,144 | 9 | 150,289 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,145 | 9 | 150,290 |
Tags: implementation
Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Sat Aug 1 11:55:52 2020
@author: alber
"""
x = int(input())
cookies = list(map(int,input().split()))
total_cookies = sum(cookies)
if x == 1:
print(1)
else:
if total_cookies%2 == 0:
olga = [i for i in cookies if i%2 == 0]
else:
olga = [i for i in cookies if i%2 != 0]
print(len(olga))
``` | output | 1 | 75,145 | 9 | 150,291 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,146 | 9 | 150,292 |
Tags: implementation
Correct Solution:
```
N = int(input())
Coke = [int(i) for i in input().split()]
E = 0
O = 0
for i in Coke:
if i%2 == 0:
E += 1
else:
O += 1
if O%2 == 1:
print(O)
else:
print(E)
``` | output | 1 | 75,146 | 9 | 150,293 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,147 | 9 | 150,294 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
t = sum(a) % 2
print(len(list(filter(lambda x: x%2 == t, a))))
``` | output | 1 | 75,147 | 9 | 150,295 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,148 | 9 | 150,296 |
Tags: implementation
Correct Solution:
```
totalBags = int(input().strip())
bags = list(map(int, input().strip().split()))
if sum(bags) % 2 == 0:
print(len([x for x in bags if x % 2 == 0]))
else:
print(len([x for x in bags if x % 2 == 1]))
``` | output | 1 | 75,148 | 9 | 150,297 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,149 | 9 | 150,298 |
Tags: implementation
Correct Solution:
```
n = int(input())
l = list(map(int,input().split()))
k = list(filter(lambda x : x%2,l))
print([n-len(k),len(k)][sum(l)%2])
``` | output | 1 | 75,149 | 9 | 150,299 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies. | instruction | 0 | 75,150 | 9 | 150,300 |
Tags: implementation
Correct Solution:
```
numBolsas = input()
tokens = input().split()
galletas = list(map(int, tokens))
sumaGalletas = 0
countRobo = 0
for i in range(len(galletas)):
temp = galletas[i]
galletas[i] = 0
for z in galletas:
sumaGalletas += z
sumaGalletas = sumaGalletas % 2
if sumaGalletas == 0:
countRobo += 1
sumaGalletas = 0
galletas[i] = temp
print(countRobo)
``` | output | 1 | 75,150 | 9 | 150,301 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
a=int(input())
b=input().split()
s=0
even=0
odd=0
for i in range(a):
s=s+int(b[i])
if int(b[i])%2==0:
even=even+1
elif int(b[i])%2!=0:
odd=odd+1
if s%2==0:
print(even)
else:
print(odd)
``` | instruction | 0 | 75,151 | 9 | 150,302 |
Yes | output | 1 | 75,151 | 9 | 150,303 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
n = int(input())
cookies_in_bag = [int(x) for x in input().split(" ")]
total_cookies = sum(cookies_in_bag)
ways_to_partition = sum(1 for bag in cookies_in_bag if (total_cookies - bag) % 2 == 0)
print(ways_to_partition)
``` | instruction | 0 | 75,152 | 9 | 150,304 |
Yes | output | 1 | 75,152 | 9 | 150,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
n_bags = int(input())
bags = [int(i) for i in input().split(' ')]
t_sum = sum(bags)
ways = sum([1 if (t_sum - i) % 2 == 0 else 0 for i in bags])
print(ways)
``` | instruction | 0 | 75,153 | 9 | 150,306 |
Yes | output | 1 | 75,153 | 9 | 150,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
n = int(input())
cnt = 0
a = list(map(int, input().split()))
for i in range(len(a)):
if (sum(a) - a[i]) % 2 == 0:
cnt = cnt + 1
print(cnt)
``` | instruction | 0 | 75,154 | 9 | 150,308 |
Yes | output | 1 | 75,154 | 9 | 150,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
n = int(input())
l = list(map(int,input().split()))
c = 0
a = []
b = []
for i in l :
if i % 2 == 0 :
a.append(i)
else:
b.append(i)
r = len(a)
if sum(b) % 2 !=0 :
r -=1
if n ==1 or n % 2 != 0 :
print(1)
else:
print(len(a))
``` | instruction | 0 | 75,155 | 9 | 150,310 |
No | output | 1 | 75,155 | 9 | 150,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
a=int(input())
b=list(map(int,input().split()))
c=0
c1=0
d=0
d1=0
for i in range(a):
if b[i]%2==0:
c+=b[i]
c1+=1
else:
d+=b[i]
d1+=1
if d%2==0:
print(c1)
elif d%2==1 and d1>1:
print(d1-1)
else:
print(d1)
``` | instruction | 0 | 75,156 | 9 | 150,312 |
No | output | 1 | 75,156 | 9 | 150,313 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
n=int(input())
baglist=[int(x) for x in input().split()]
sum=sum(baglist)
cnt=0
bagset=set(baglist)
#print(bagset)
for bag in bagset:
c=baglist.count(bag)
s=sum-(bag*c)
if(s%2==0):
cnt+=c
#print(cnt)
if(cnt==0):
print('0')
else:
print(str(cnt))
``` | instruction | 0 | 75,157 | 9 | 150,314 |
No | output | 1 | 75,157 | 9 | 150,315 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wants to steal a bag with cookies so that the number of cookies in the remaining bags was even, that is, so that Anna and Maria could evenly divide it into two (even 0 remaining cookies will do, just as any other even number). How many ways there are to steal exactly one cookie bag so that the total number of cookies in the remaining bags was even?
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of cookie bags Anna and Maria have. The second line contains n integers ai (1 ≤ ai ≤ 100) — the number of cookies in the i-th bag.
Output
Print in the only line the only number — the sought number of ways. If there are no such ways print 0.
Examples
Input
1
1
Output
1
Input
10
1 2 2 3 4 4 4 2 2 2
Output
8
Input
11
2 2 2 2 2 2 2 2 2 2 99
Output
1
Note
In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, the twins are left with 2 * 9 + 99 = 117 cookies. Thus, Olga has only one option: to take the bag with 99 cookies.
Submitted Solution:
```
number_of_bags = int(input())
cookies_in_bag = input().split() # returns a string list
integer = 0
even_count = 0
odd_count = 0
#check each bag for even or odd
for x in range(0, (number_of_bags)):
if int(cookies_in_bag[integer]) % 2 == 0:
even_count += 1
else:
odd_count += 1
integer += 1
if odd_count >= 0 and odd_count % 2 == 0 and even_count >= 0:
print(even_count)
elif odd_count > 0 and odd_count % 2 != 0:
print(1)
``` | instruction | 0 | 75,158 | 9 | 150,316 |
No | output | 1 | 75,158 | 9 | 150,317 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,834 | 9 | 151,668 |
"Correct Solution:
```
# https://onlinejudge.u-aizu.ac.jp/problems/1149
class Cake:
def __init__(self, w, d):
self.w = w
self.d = d
def area(self):
return self.w * self.d
def cut(self, s):
perimeter = self.w * 2 + self.d * 2
s %= perimeter
if s < self.w:
return [Cake(s, self.d), Cake(self.w - s, self.d)]
elif s < self.w + self.d:
l = s - self.w
return [Cake(self.w, l), Cake(self.w, self.d - l)]
elif s < self.w + self.d + self.w:
l = s - (self.w + self.d)
return [Cake(self.w - l, self.d), Cake(l, self.d)]
else:
l = s - (self.w + self.d + self.w)
return [Cake(self.w, self.d - l), Cake(self.w, l)]
def __repr__(self):
return '(w {}, d {})'.format(self.w, self.d)
def solve(Q, n, w, d):
cakes = [Cake(w, d)]
for p, s in Q:
# print(cakes)
cut_cake = cakes.pop(p)
cake1, cake2 = cut_cake.cut(s)
if cake1.area() > cake2.area():
cake2, cake1 = cake1, cake2
cakes.append(cake1)
cakes.append(cake2)
# print(cakes)
cakes.sort(key=lambda cake: cake.area())
areas_str = []
for cake in cakes:
area_str = str(cake.area())
areas_str.append(area_str)
print(' '.join(areas_str))
if __name__ == "__main__":
while True:
n, w, d = list(map(int, input().split()))
if n == 0 and w == 0 and d == 0:
break
Q = []
for _ in range(n):
p, s = list(map(int, input().split()))
Q.append((p-1, s))
solve(Q, n, w, d)
``` | output | 1 | 75,834 | 9 | 151,669 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,835 | 9 | 151,670 |
"Correct Solution:
```
def cut(d, w, s):
s %= 2 * (d + w)
sq = []
if 0 < s < w:
sq = [(d, s), (d, w - s)]
elif w < s < w + d:
s -= w
sq = [(s, w), (d - s, w)]
elif w + d < s < 2 * w + d:
s -= w + d
sq = [(d, s), (d, w - s)]
elif 2 * w + d < s < 2 * (w + d):
s -= 2 * w + d
sq = [(s, w), (d - s, w)]
else:
assert(False)
p1, p2 = sq
if p1[0] * p1[1] > p2[0] * p2[1]:
p1, p2 = p2, p1
return [p1, p2]
while True:
N, W, D = map(int, input().split())
if not (N | W | D):
break
square = [(D, W)]
for _ in range(N):
p, s = map(int, input().split())
d, w = square.pop(p - 1)
square.extend(cut(d, w, s))
print(*sorted(d * w for d, w in square))
``` | output | 1 | 75,835 | 9 | 151,671 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,836 | 9 | 151,672 |
"Correct Solution:
```
WIDTH = 0
DEPTH = 1
while True:
N, W, D = [int(x) for x in input().split()]
if N == W == D == 0: break
if N == 0:
print(W * D)
continue
p, s = zip(*[[int(x) for x in input().split()] for _ in range(N)])
# cake[i] = [識別番号iのケーキの 幅, 奥行き]
# i = 0はダミー
cake = [[0, 0], [W, D]] + [None] * N
for i in range(N):
id = p[i] # カットするケーキの識別番号
w, d = cake[id] # カットするケーキの幅と奥行き
l = s[i] # 切り方
# id+1以降のケーキの番号振り直し
for j in range(id, i + 1):
cake[j] = cake[j + 1][:]
cake[i + 1] = None
# ケーキをカット＆番号を振る
l = l % (w + d)
if l < w: # 上から見て縦方向に切る
w_min = min(l, w - l) # id: i + 1
cake[i + 1] = [w_min, d]
cake[i + 2] = [w - w_min, d]
else: # 上から見て横方向に切る
l -= w
d_min = min(l, d - l)
cake[i + 1] = [w, d_min]
cake[i + 2] = [w, d - d_min]
area = [w * d for (w, d) in cake]
area.sort()
print(" ".join(map(str, area[1:])))
``` | output | 1 | 75,836 | 9 | 151,673 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,837 | 9 | 151,674 |
"Correct Solution:
```
def cut(cake,s):
w=cake[0]
h=cake[1]
s=s%(w+h)
if s<w:
if s<(w-s):
return [(s,h),(w-s,h)]
else:
return [(w-s,h),(s,h)]
else:
if (s-w)<(w+h-s):
return [(w,s-w),(w,w+h-s)]
else:
return [(w,w+h-s),(w,s-w)]
n,w,d=map(int,input().split())
while n!=0 or w!=0 or d!=0:
cakes=[(w,d)]
for i in range(n):
p,s=map(int,input().split())
p=p-1
cut_cakes=cut(cakes[p],s)
cakes=cakes[:p]+cakes[p+1:]+cut_cakes
ans=[0]*len(cakes)
for i in range(len(cakes)):
ans[i]=cakes[i][0]*cakes[i][1]
ans.sort()
print(ans[0],end="")
for i in range(1,len(cakes)):
print(" "+str(ans[i]),end="")
print()
n,w,d=map(int,input().split())
``` | output | 1 | 75,837 | 9 | 151,675 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,838 | 9 | 151,676 |
"Correct Solution:
```
import bisect
while True:
n,w,d=map(int,input().split())
if n==w==d==0:break
A=[w*d]
B=[[0,w,w+d,2*w+d,2*w+2*d]]
for _ in range(n):
p,s=map(int,input().split())
b=B.pop(p-1)
S=A.pop(p-1)
s%=b[-1]
w=b[1]
d=b[2]-w
if bisect.bisect_left(b,s)%2:
w1=s-b[bisect.bisect_left(b,s)-1]
w2=w-w1
d1,d2=d,d
else:
d1=s-b[bisect.bisect_left(b,s)-1]
d2=d-d1
w1,w2=w,w
if w1*d1>w2*d2:
A.append(w2*d2)
A.append(w1*d1)
B.append([0,w2,w2+d2,2*w2+d2,2*w2+2*d2])
B.append([0,w1,w1+d1,2*w1+d1,2*w1+2*d1])
else:
A.append(w1*d1)
A.append(w2*d2)
B.append([0,w1,w1+d1,2*w1+d1,2*w1+2*d1])
B.append([0,w2,w2+d2,2*w2+d2,2*w2+2*d2])
print(*sorted(A))
``` | output | 1 | 75,838 | 9 | 151,677 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,839 | 9 | 151,678 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
def main():
while True:
n, w, d = map(int, input().split())
if w == 0:
break
cuts = [list(map(int, input().split())) for i in range(n)]
cakes = [(w,d,w*d)]
for cut in cuts:
p, s = cut
w, d, wd = cakes.pop(p-1)
s = s % (w*2+d*2)
if s > w+d:
s -= w+d
if 0 < s and s < w:
w1 = min(s, w-s)
w2 = w - w1
cakes.append((w1, d, w1*d))
cakes.append((w2, d, w2*d))
else:
d1 = min(w+d-s, s-w)
d2 = d - d1
cakes.append((w, d1, w*d1))
cakes.append((w, d2, w*d2))
cakes = sorted(cakes, key=lambda x:x[2])
len_ = len(cakes)
for i in range(len_):
_,__,area = cakes[i]
print(area, end="")
if i != len_ - 1:
print(" ",end="")
else:
print()
if __name__ == "__main__":
main()
``` | output | 1 | 75,839 | 9 | 151,679 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,840 | 9 | 151,680 |
"Correct Solution:
```
def cut(d, w, s):
s %= d + w
if 0 < s < w:
p1, p2 = (d, s), (d, w - s)
elif w < s < w + d:
s -= w
p1, p2 = (s, w), (d - s, w)
else:
assert(False)
if p1[0] * p1[1] > p2[0] * p2[1]:
p1, p2 = p2, p1
return [p1, p2]
while True:
N, W, D = map(int, input().split())
if not (N | W | D):
break
square = [(D, W)]
for _ in range(N):
p, s = map(int, input().split())
d, w = square.pop(p - 1)
square.extend(cut(d, w, s))
print(*sorted(d * w for d, w in square))
``` | output | 1 | 75,840 | 9 | 151,681 |
Provide a correct Python 3 solution for this coding contest problem.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10 | instruction | 0 | 75,841 | 9 | 151,682 |
"Correct Solution:
```
def cut(d, w, s):
s %= d + w
sq = []
if 0 < s < w:
sq = [(d, s), (d, w - s)]
elif w < s < w + d:
s -= w
sq = [(s, w), (d - s, w)]
else:
assert(False)
p1, p2 = sq
if p1[0] * p1[1] > p2[0] * p2[1]:
p1, p2 = p2, p1
return [p1, p2]
while True:
N, W, D = map(int, input().split())
if not (N | W | D):
break
square = [(D, W)]
for _ in range(N):
p, s = map(int, input().split())
d, w = square.pop(p - 1)
square.extend(cut(d, w, s))
print(*sorted(d * w for d, w in square))
``` | output | 1 | 75,841 | 9 | 151,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10
Submitted Solution:
```
def cut(w, d, s):
mod = s % (w + d)
s = []
if mod > w:
tate = mod - w
yoko = w
tate_2 = d - (mod - w)
area = tate * yoko
area_2 = tate_2 * yoko
s.append([area, [yoko, tate]])
s.append([area_2, [yoko, tate_2]])
else:
yoko = mod
tate = d
yoko_2 = w - mod
area = tate * yoko
area_2 = tate * yoko_2
s.append([area , [yoko, tate]])
s.append([area_2, [yoko_2, tate]])
return sorted(s)
while True:
n, w, d = map(int, input().split())
if n == 0 and w == 0 and d == 0:
break
cuts = [list(map(int, input().split())) for _ in range(n)]
areas = [(w * d, [w, d])]
for key, s in cuts:
area = areas.pop(key - 1)
areas += cut(*area[1], s)
ans = []
for k in areas:
ans.append(k[0])
ans.sort()
print(*ans)
``` | instruction | 0 | 75,842 | 9 | 151,684 |
Yes | output | 1 | 75,842 | 9 | 151,685 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10
Submitted Solution:
```
while(1):
n, w, h = map(int, input().split())
if not n+w+h:
break
t = [[w, h]]
for i in range(n):
p, s = map(int, input().split())
cur = t.pop(p-1)
W = cur[0]
H = cur[1]
s %= 2*W+2*H
if s < W:
a = min(s, W-s)
t.extend([[a, H], [W-a, H]])
elif s < W+H:
a = min(s-W, W+H-s)
t.extend([[W, a], [W, H-a]])
elif s < 2*W+H:
a = min(s-W-H, 2*W+H-s)
t.extend([[a, H], [W-a, H]])
else:
a = min(s-2*W-H, 2*W+2*H-s)
t.extend([[W, a], [W, H-a]])
ans = []
for i in t:
ans.append(i[0]*i[1])
ans.sort()
print(' '.join([str(i) for i in ans]))
``` | instruction | 0 | 75,843 | 9 | 151,686 |
Yes | output | 1 | 75,843 | 9 | 151,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10
Submitted Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
from itertools import permutations
import sys
import math
import bisect
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
res = list(sys.stdin.readline())
if res[-1] == "\n":
return res[:-1]
return res
def IR(n):
return [I() for i in range(n)]
def LIR(n):
return [LI() for i in range(n)]
def SR(n):
return [S() for i in range(n)]
def LSR(n):
return [LS() for i in range(n)]
sys.setrecursionlimit(1000000)
mod = 1000000007
def solve():
def size(p):
return (p[2]-p[0])*(p[3]-p[1])
def cut(p,s):
u,l,d,r = p
x = r-l
y = d-u
s %= 2*(x+y)
if s < x:
a,b = [u,l,d,l+s], [u,l+s,d,r]
elif s < x+y:
s -= x
a,b = [u,l,u+s,r], [u+s,l,d,r]
elif s < 2*x+y:
s -= x+y
s = x-s
a,b = [u,l,d,l+s],[u,l+s,d,r]
else:
s -= 2*x+y
s = y-s
a,b = [u,l,u+s,r], [u+s,l,d,r]
if size(b) < size(a):
a,b = b,a
return a,b
while 1:
n,w,h = LI()
if n == w == h == 0:
break
q = [[0,0,h,w]]
for _ in range(n):
i,s = LI()
i -= 1
p = q.pop(i)
a,b = cut(p,s)
q.append(a)
q.append(b)
s = [size(p) for p in q]
s.sort()
print(*s)
return
#Solve
if __name__ == "__main__":
solve()
``` | instruction | 0 | 75,844 | 9 | 151,688 |
Yes | output | 1 | 75,844 | 9 | 151,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10
Submitted Solution:
```
# -*- coding: utf-8 -*-
# python template for atcoder1
import sys
sys.setrecursionlimit(10**9)
input = sys.stdin.readline
def solve():
N, W, D = map(int, input().split())
if N == 0 and W == 0 and D == 0:
exit()
L = []
L.append((W, D))
for _ in range(N):
op, le = map(int, input().split())
cut_cake_W, cut_cake_D = L.pop(op-1)
le = le % (cut_cake_W+cut_cake_D)
if le < cut_cake_W:
new_W1 = min(le, cut_cake_W-le)
new_W2 = max(le, cut_cake_W-le)
new_D1 = cut_cake_D
new_D2 = cut_cake_D
else:
le = le-cut_cake_W
new_W1 = cut_cake_W
new_W2 = cut_cake_W
new_D1 = min(le, cut_cake_D-le)
new_D2 = max(le, cut_cake_D-le)
L.append((new_W1, new_D1))
L.append((new_W2, new_D2))
L = sorted(L, key=lambda x: x[0]*x[1])
print(" ".join(map(str, [a*b for a, b in L])))
while True:
solve()
``` | instruction | 0 | 75,845 | 9 | 151,690 |
Yes | output | 1 | 75,845 | 9 | 151,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10
Submitted Solution:
```
while True:
dic = {}
n,w,d = map(int,input().split(" "))
if n == 0 and w == 0 and d == 0:
break
dic[1] = (w,d)
for i in range(n):
p,s = map(int,input().split(" "))
W,H = dic[p]
for j in range(p,i+1):
dic[j] = dic[j+1]
cycle = 2*(H+W)
s %= cycle
if s < W or ((H+W) < s and s < (W+H+W)):
if W < s:
s -= (H+W)
dic[i+1] = (min(s,W-s),H)
dic[i+2] = (max(s,W-s),H)
elif (W < s and s < (H+W)) or ((W+H+W) < s):
if s > (H+W):
s -= (W+H+W)
else:
s -= W
dic[i+1] = (W,min(s,H-s))
dic[i+2] = (W,max(s,H-s))
sq = list(dic.values())
sq.sort(key=lambda x:x[0]*x[1])
for i in range(len(sq)):
print(sq[i][0]*sq[i][1],end=" ")
print()
``` | instruction | 0 | 75,846 | 9 | 151,692 |
No | output | 1 | 75,846 | 9 | 151,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today is the birthday of Mr. Bon Vivant, who is known as one of the greatest patissiers in the world. Those who are invited to his birthday party are gourmets from around the world. They are eager to see and eat his extremely creative cakes. Now a large box-shaped cake is being carried into the party. It is not beautifully decorated and looks rather simple, but it must be delicious beyond anyone's imagination. Let us cut it into pieces with a knife and serve them to the guests attending the party.
The cake looks rectangular, viewing from above (Figure C-1). As exemplified in Figure C-2, the cake will iteratively be cut into pieces, where on each cut exactly a single piece is cut into two smaller pieces. Each cut surface must be orthogonal to the bottom face and must be orthogonal or parallel to a side face. So, every piece shall be rectangular looking from above and every side face vertical.
<image>
Figure C-1: The top view of the cake
<image>
Figure C-2: Cutting the cake into pieces
Piece sizes in Figure C-2 vary significantly and it may look unfair, but you don't have to worry. Those guests who would like to eat as many sorts of cakes as possible often prefer smaller pieces. Of course, some prefer larger ones.
Your mission of this problem is to write a computer program that simulates the cutting process of the cake and reports the size of each piece.
Input
The input is a sequence of datasets, each of which is of the following format.
> n w d
> p1 s1
> ...
> pn sn
>
The first line starts with an integer n that is between 0 and 100 inclusive. It is the number of cuts to be performed. The following w and d in the same line are integers between 1 and 100 inclusive. They denote the width and depth of the cake, respectively. Assume in the sequel that the cake is placed so that w and d are the lengths in the east-west and north-south directions, respectively.
Each of the following n lines specifies a single cut, cutting one and only one piece into two. pi is an integer between 1 and i inclusive and is the identification number of the piece that is the target of the i-th cut. Note that, just before the i-th cut, there exist exactly i pieces. Each piece in this stage has a unique identification number that is one of 1, 2, ..., i and is defined as follows:
* The earlier a piece was born, the smaller its identification number is.
* Of the two pieces born at a time by the same cut, the piece with the smaller area (looking from above) has the smaller identification number. If their areas are the same, you may define as you like the order between them, since your choice in this case has no influence on the final answer.
Note that identification numbers are adjusted after each cut.
si is an integer between 1 and 1000 inclusive and specifies the starting point of the i-th cut. From the northwest corner of the piece whose identification number is pi, you can reach the starting point by traveling si in the clockwise direction around the piece. You may assume that the starting point determined in this way cannot be any one of the four corners of the piece. The i-th cut surface is orthogonal to the side face on which the starting point exists.
The end of the input is indicated by a line with three zeros.
Output
For each dataset, print in a line the areas looking from above of all the pieces that exist upon completion of the n cuts specified in the dataset. They should be in ascending order and separated by a space. When multiple pieces have the same area, print it as many times as the number of the pieces.
Example
Input
3 5 6
1 18
2 19
1 2
3 4 1
1 1
2 1
3 1
0 2 5
0 0 0
Output
4 4 6 16
1 1 1 1
10
Submitted Solution:
```
ans_list = []
def make_pieces(w, d, s):
while True:
if w > s:
return [s, d], [w - s, d]
s -= w
if d > s:
return [w, s], [w, d - s]
s -= d
if w > s:
return [w - s, d], [s, d]
s -= w
if d > s:
return [w, s], [w, d - s]
s -= d
while True:
n, w, d = map(int, input().split())
P = [[w, d]]
if n == 0 and w == 0 and d == 0:
break
for i in range(n):
p, s = map(int, input().split())
new_pieces = make_pieces(P[p - 1][0], P[p - 1][1], s)
#print(new_pieces)
if new_pieces[0][0] * new_pieces[0][1] < new_pieces[1][0] * new_pieces[1][1]:
P = P[:p - 1] + [new_pieces[0]] + [new_pieces[1]] + P[p:]
else:
P = P[:p - 1] + [new_pieces[1]] + [new_pieces[0]] + P[p:]
#print(P)
S_list = []
for i in P:
S_list.append(i[0] * i[1])
S_list.sort()
ans_list.append(S_list)
for i in range(len(ans_list)):
I = ans_list[i]
for j in range(len(I)):
J = I[j]
if i == len(ans_list) - 1 and j == len(I) - 1:
print(J, end = "")
else:
print(J, end = " ")
print()
``` | instruction | 0 | 75,847 | 9 | 151,694 |
No | output | 1 | 75,847 | 9 | 151,695 |
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