meter logs

logs/31a063b3_sm_soupA13.log

@@ -3,3 +3,16 @@
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 [transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
 13:19:38 checkpoint sft/soupA13.pt step 0: 400 held-out template problems
+13:28:23 EX tp_probability | Q: Question: Quinn Johnson is preparing a quiz bowl with 10 distinct questions. They have prepared a bank of 12 potential questions. If they select 10 questions at | GOLD: 5/6 | OUT:  is C(12,10) / C(12,10) = 12 / Number of favorable outcomes is C(10,10) / C(10,10) = 1 / Probability is 1 / 100 / Simplify the fraction by dividing numerator and denominator by 12 / 1 / 100 = 10 / 1 / 12 = 1 / 10 / 12 = 1 / 10 / 12 = 1 / 10 / 12 = 1 / 1 / 100 = 1 / 1 / 100 = 1 / 100 / 1 / 100 = 100 / 1 / 100 = 1/100 / #### 1/100
+13:28:23 EX tp_science_calc | Q: Question: A large industrial tank contains a mixture of ideal gases. The temperature of the gas mixture is 349 K. What is the root-mean-square speed of the Argo | GOLD: 466 m/s | OUT: = 349 K / T_T = 349 * 8.314 * 40.0 / T_T = 349.000000000000 / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = sqrt(349) / T_T = 349.000000000000 / T_T ≈ 0.000000000000000000000
+13:28:23 EX tp_wordproblem | Q: Question: A network storage device is advertised to hold 9 Terabytes of data. If a specific file format uses 0.6 Gigabytes per file, and the device is currently | GOLD: 5100 | OUT:  10 gigabytes / 10 gigabytes = 10 / 1 gigabytes = 10 / 1 gigabytes = 10 * 10 = 10 gigabytes / 1 gigabytes = 10 / 10 = 10 gigabytes / 1 gigabytes = 10 / 10 = 10 gigabytes / 1 gigabytes = 10 * 10 = 10 gigabytes / 1 gigabytes = 10 / 10 = 10 gigabytes / Additional files = 10 / Additional files = 10 - 10 = 10 files / #### 1
+13:28:23 EX tp_finance | Q: Question: Calculate the break-even point in units for the Riverside Workshop, which has fixed costs of $185,000, a variable cost of $67 per units, and a selling | GOLD: 1000 | OUT: argin per unit = 25 / Contribution margin per unit = 25 / Fixed costs = 185,000 / Contribution margin per unit = 25 / Break-even units = 1850.00 / Break-even units = 1850.00 / 25 / Break-even units = 1850.00 / Break-even units = 1850.00 / 25 / Break-even units = 1850.00 / Break-even units = 1850.00 / #### 1850.00 units
+13:28:23 TASK tp_deduction           correct   1/2  reached_####   2
+13:28:23 TASK tp_finance             correct   1/86  reached_####  70
+13:28:23 TASK tp_logic               correct   1/40  reached_####  29
+13:28:23 TASK tp_planning            correct   5/33  reached_####  24
+13:28:23 TASK tp_probability         correct   2/57  reached_####  53
+13:28:23 TASK tp_science_calc        correct   1/59  reached_####  41
+13:28:23 TASK tp_wordproblem         correct   1/123  reached_#### 102
+13:28:23 TMETER sft/soupA13.pt step 0: correct 12/400 (3.0%), reached #### 321/400
+13:28:23 METER DONE