meter logs
Browse files- logs/c13083f2_rg_tpA7L.log +4 -0
- logs/c13083f2_sm_tpA7L.log +13 -0
logs/c13083f2_rg_tpA7L.log
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Traceback (most recent call last):
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File "/tmp/rg_meter.py", line 35, in <module>
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import reasoning_gym as rg
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ModuleNotFoundError: No module named 'reasoning_gym'
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logs/c13083f2_sm_tpA7L.log
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[transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
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12:33:56 checkpoint sft/tpA7_latest.pt step 2000: 400 held-out template problems
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[transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
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12:33:56 checkpoint sft/tpA7_latest.pt step 2000: 400 held-out template problems
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12:42:42 EX tp_probability | Q: Question: Quinn Johnson is preparing a quiz bowl with 10 distinct questions. They have prepared a bank of 12 potential questions. If they select 10 questions at | GOLD: 5/6 | OUT: ying the fraction by dividing numerator and denominator by 1: 1 / 1 / Greatest common divisor of 1 and 1 is 1 and 1 / 1 / 1 = 1 / 1 / 1 = 1 / Simplifying the fraction by dividing numerator and denominator by 1: 1 / 1 / Greatest common divisor of 1 and 1 is 1 and 1 / 1 / 1 = 1 / 1 / 1 = 1 / The probability is 1 / 1 /
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12:42:42 EX tp_science_calc | Q: Question: A large industrial tank contains a mixture of ideal gases. The temperature of the gas mixture is 349 K. What is the root-mean-square speed of the Argo | GOLD: 466 m/s | OUT: .314 J/(mol*K) / M_R = sqrt(40.0 - 8.314) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = sqrt(40.0) / M_R = 0.00000000000000
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12:42:42 EX tp_wordproblem | Q: Question: A network storage device is advertised to hold 9 Terabytes of data. If a specific file format uses 0.6 Gigabytes per file, and the device is currently | GOLD: 5100 | OUT: 0.6 / Required terabytes = 0.6 / 0.6 = 0.6 / Remaining file used = 0.6 / Remaining file used = 0.6 - 0.6 = 0.6 / Maximum used = 0.6 / Remaining file used = 0.6 / Remaining file used = 0.6 - 0.6 = 0.6 / Required terabytes = 0.6 / 0.6 = 0.6 / Maximum used = 0.6 / Maximum used = 0.6 / Maximum used = 0.6 / Maximum used = 0.
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12:42:42 EX tp_finance | Q: Question: Calculate the break-even point in units for the Riverside Workshop, which has fixed costs of $185,000, a variable cost of $67 per units, and a selling | GOLD: 1000 | OUT: 52 / Variable cost = $67 / Contribution margin per unit = $67 / Selling margin per unit = $252 / Profit equation = $252 - $67 Profit equation = $252 Profit equation = $252 / xx = $252 / x = $185,000 / Break-even units = $185,000 / $67 / Break-even units = 1000.00 / xx = $185,000 / $252 / xx = 1000.00 / xx = 1000.00 units
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12:42:42 TASK tp_deduction correct 0/2 reached_#### 1
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12:42:42 TASK tp_finance correct 2/86 reached_#### 43
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12:42:42 TASK tp_logic correct 1/40 reached_#### 16
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12:42:42 TASK tp_planning correct 1/33 reached_#### 8
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12:42:42 TASK tp_probability correct 0/57 reached_#### 19
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12:42:42 TASK tp_science_calc correct 0/59 reached_#### 13
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12:42:42 TASK tp_wordproblem correct 0/123 reached_#### 42
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12:42:42 TMETER sft/tpA7_latest.pt step 2000: correct 4/400 (1.0%), reached #### 142/400
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12:42:42 METER DONE
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