use vstd::prelude::*; fn main() {} verus!{ fn f1_element_wise_subtract(arr1: &Vec, arr2: &Vec) -> (result: Vec) requires arr1.len() == arr2.len(), forall|i: int| (0 <= i < arr1.len()) ==> (i32::MIN <= #[trigger] (arr1[i] - arr2[i]) <= i32::MAX), { let mut output_arr = Vec::with_capacity(arr1.len()); let mut index = 0; while index < arr1.len() { output_arr.push((arr1[index] - arr2[index])); index += 1; } output_arr } fn f2_has_only_one_distinct_element(arr: &Vec) -> (result: bool) { if arr.len() <= 1 { return true; } let mut index = 1; while index < arr.len() { if arr[0] != arr[index] { return false; } index += 1; } true } spec fn step1(__hp0: Seq, __hp1: Seq, outp: Seq) -> bool { (outp.len() == __hp0.len()) && (forall|i: int| 0 <= i < outp.len() ==> #[trigger] outp[i] == #[trigger] (__hp0[i] - __hp1[i])) } spec fn step2(inp: Seq, outp: bool) -> bool { (outp == (forall|i: int| 1 <= i < inp.len() ==> inp[0] == #[trigger] inp[i])) } fn chain_driver(arr1: &Vec, arr2: &Vec) -> (r_final: bool) requires arr1.len() == arr2.len(), forall|i: int| (0 <= i < arr1.len()) ==> (i32::MIN <= #[trigger] (arr1[i] - arr2[i]) <= i32::MAX), ensures exists|v1: Seq| #[trigger] step1(arr1@, arr2@, v1) && step2(v1, r_final), { let x1 = f1_element_wise_subtract(arr1, arr2); let x2 = f2_has_only_one_distinct_element(&x1); proof { assert(step1(arr1@, arr2@, x1@)); assert(step2(x1@, x2)); } x2 } } // verus!