use vstd::prelude::*; fn main() {} verus!{ fn f1_max_length_list(seq: &Vec>) -> (max_list: &Vec) requires seq.len() > 0, { let mut max_list = &seq[0]; let mut index = 1; while index < seq.len() { if ((seq[index]).len() > max_list.len()) { max_list = &seq[index]; } index += 1; } max_list } fn f2_find_negative_numbers(arr: &Vec) -> (negative_list: Vec) { let mut negative_list: Vec = Vec::new(); let input_len = arr.len(); let mut index = 0; while index < arr.len() { if (arr[index] < 0) { negative_list.push(arr[index]); } index += 1; } negative_list } spec fn step1(__hp0: Seq>, outp: Seq) -> bool { (forall|k: int| 0 <= k < __hp0.len() ==> outp.len() >= #[trigger] (__hp0[k]).len()) && (exists|k: int| 0 <= k < __hp0.len() && outp =~= #[trigger] (__hp0[k]@)) } spec fn step2(inp: Seq, outp: Seq) -> bool { (outp == inp.filter(|x: i32| x < 0)) } fn chain_driver(seq: &Vec>) -> (r_final: Vec) requires seq.len() > 0, ensures exists|v1: Seq| #[trigger] step1(seq@, v1) && step2(v1, r_final@), { let x1 = f1_max_length_list(seq); let x2 = f2_find_negative_numbers(x1); proof { assert(step1(seq@, x1@)); assert(step2(x1@, x2@)); } x2 } } // verus!