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( 2 ) 2 N a O H + C u S O _ { 4 } = N a _ { 2 } S O _ { 4 } + C u ( O H ) _ { 2 } \downarrow
./HME100K\train_images\train_0.jpg
\angle A C B = \angle A ^ { \prime } C B ^ { \prime }
./HME100K\train_images\train_2.jpg
1 0 \times ( x + 5 ) = 1 3 \times ( \frac { 5 } { 7 } x + 5 )
./HME100K\train_images\train_3.jpg
l _ { 2 } = O B = \frac { O A } { 4 } \times 3 = \frac { 1 . 2 m } { 4 } \times 3 = 0 . 9 m
./HME100K\train_images\train_4.jpg
\angle A = 4 0 ^ { \circ }
./HME100K\train_images\train_6.jpg
2 n + H _ { 2 } S o _ { 4 } = 2 n S _ { 4 } + H _ { 2 } \uparrow
./HME100K\train_images\train_8.jpg
\angle B E C = 3 \angle A B E
./HME100K\train_images\train_9.jpg
- \frac { b } { 2 0 } = - \frac { - k } { 2 } = \frac { k } { 2 } = 1
./HME100K\train_images\train_10.jpg
N a C l O _ { 3 } + K C l = K C l O _ { 3 } + N a C l
./HME100K\train_images\train_11.jpg
\textcircled { 1 } \frac { 1 } { 4 } = \frac { 1 \times 2 } { 4 \times 2 } = \frac { 2 } { 8 }
./HME100K\train_images\train_12.jpg
2 0 \% = \frac { 1 } { 5 }
./HME100K\train_images\train_13.jpg
\angle C O E = \frac { 2 } { 3 } \times 9 0 ^ { \circ } = 6 0 ^ { \circ }
./HME100K\train_images\train_14.jpg
L H S = \sqrt { - \frac { 1 } { 2 } } \cdot \sqrt { 4 }
./HME100K\train_images\train_15.jpg
+ 2 \square
./HME100K\train_images\train_17.jpg
\angle B + \angle B F D = \angle F D C
./HME100K\train_images\train_18.jpg
x ^ { 2 } - 3 x + 2 = 0
./HME100K\train_images\train_19.jpg
f ( x ) = e ^ { x } - a x ^ { 3 }
./HME100K\train_images\train_20.jpg
V y = \sqrt { V _ { 0 } ^ { 2 } - 4 x ^ { 2 } } = \frac { \sqrt { 3 } V _ { 0 } } { 2 }
./HME100K\train_images\train_21.jpg
V _ { t } ^ { 2 } - V _ { 0 } ^ { 2 } = 2 a x
./HME100K\train_images\train_22.jpg
2 A l + 6 H C l = 2 A l C l _ { 3 } + 3 H _ { 2 } \uparrow
./HME100K\train_images\train_24.jpg
1 2 . 5 6 = 6 ( d m )
./HME100K\train_images\train_25.jpg
- ( m + 2 ) ^ { 2 } \geq 0
./HME100K\train_images\train_26.jpg
S _ { n } = \frac { 2 n } { 3 ^ { n + 1 } }
./HME100K\train_images\train_28.jpg
\angle E A D = \angle O A D
./HME100K\train_images\train_29.jpg
\frac { \sqrt { 3 } } { 2 } \neq \frac { 1 } { 2 }
./HME100K\train_images\train_30.jpg
x \in [ - 1 , 1 ]
./HME100K\train_images\train_31.jpg
9 6 0 d m ^ { 3 } = 0 . 9 6 m ^ { 3 }
./HME100K\train_images\train_32.jpg
4 0 0 0 0 \times 6 - 2 4 0 0 0 0 ( c m )
./HME100K\train_images\train_33.jpg
\Delta = 4 8 ( 1 2 - m ^ { 2 } ) > 0
./HME100K\train_images\train_37.jpg
\frac { 1 8 0 ^ { \circ } - 1 0 8 ^ { \circ } } { 2 } = \frac { 7 2 ^ { \circ } } { 2 } = 3 6 ^ { \circ }
./HME100K\train_images\train_38.jpg
n C a C l _ { 2 } = \frac { m } { M } = \frac { 1 1 . 1 g } { 1 1 1 g / m o l } = 0 . 1 m o l
./HME100K\train_images\train_39.jpg
g ^ { \prime } ( x ) = \frac { 2 \times \ln x - x + x } { ( \ln x ) ^ { 2 } } > 0
./HME100K\train_images\train_40.jpg
\angle M D B + \angle C D N = 7 5 ^ { \circ }
./HME100K\train_images\train_42.jpg
y = - ( x + a ) ^ { 2 } + b
./HME100K\train_images\train_43.jpg
\because \frac { B E } { C D } = \frac { B D } { C F }
./HME100K\train_images\train_49.jpg
y = \frac { k _ { 1 } } { x - 2 } . \because y = y _ { 1 } - y _ { 2 }
./HME100K\train_images\train_50.jpg
y _ { 1 } > y _ { 2 }
./HME100K\train_images\train_51.jpg
\Delta A B C \sim \Delta F C D
./HME100K\train_images\train_54.jpg
a _ { n } - a _ { n - 1 } = 2 n - 1
./HME100K\train_images\train_55.jpg
\angle A O D = 2 0 0 ^ { \circ } - a
./HME100K\train_images\train_57.jpg
P = \frac { W } { t } = \frac { 4 0 J } { 1 0 s } = 4 W
./HME100K\train_images\train_58.jpg
\Delta A O F \cong \Delta C O E ( A A S )
./HME100K\train_images\train_62.jpg
C H _ { 3 } - C H - C O O H + H C l \rightarrow C H _ { 3 } - C H - C O O
./HME100K\train_images\train_65.jpg
a \geq \frac { 3 } { 2 } .
./HME100K\train_images\train_67.jpg
\angle O A C = 4 5 ^ { \circ } = \angle O C A
./HME100K\train_images\train_68.jpg
( 3 ) \frac { ( 1 ) - ( 2 ) } { 2 } = \frac { 2 5 6 } { 2 } = \frac { 1 2 8 } { 2 } = 6 4
./HME100K\train_images\train_69.jpg
- 2 x ^ { 2 } + 2 0 x < 0
./HME100K\train_images\train_70.jpg
a _ { n + 1 } = 9 \times 1 0 ^ { n }
./HME100K\train_images\train_72.jpg
C Q = B C - B Q = 6 0 - 2 \sqrt { 3 } ( c m )
./HME100K\train_images\train_73.jpg
\angle A B C = \angle E A B \therefore H E = B E \because B E = C E
./HME100K\train_images\train_75.jpg
2 + 2 + \frac { 1 } { 8 } \times 3 J
./HME100K\train_images\train_76.jpg
\frac { 1 } { 2 } t ^ { 2 } + \frac { 3 } { 2 } t + 4 t = 6 3
./HME100K\train_images\train_77.jpg
\beta = x + 2 k \pi - \alpha C k \in 8 7
./HME100K\train_images\train_78.jpg
1 + ( 2 - p ) ^ { 2 } + 9 + ( 1 - p ) ^ { 2 } = 1 7
./HME100K\train_images\train_79.jpg
x + y = 9 1
./HME100K\train_images\train_80.jpg
( 1 ) y = \frac { x ^ { 2 } + x + 1 } { x } = ( x + \frac { 1 } { x } ) + 1 \geq 2 \sqrt { x \cdot \frac { 1 } { x } } + 1
./HME100K\train_images\train_81.jpg
\therefore 1 8 0 ^ { \circ } - \angle C Q P - \angle C P Q = 1 8 0 ^ { \circ } - \angle A Q B - \angle B
./HME100K\train_images\train_83.jpg
2 y + 2 < 5 y - 1
./HME100K\train_images\train_84.jpg
x + 5 > - 1
./HME100K\train_images\train_86.jpg
x < 4
./HME100K\train_images\train_91.jpg
6 . 2 8 \times 6 0 0 = 3 7 6 8 ( k g )
./HME100K\train_images\train_92.jpg
\frac { 1 } { 2 } x \times 5 \times 2
./HME100K\train_images\train_93.jpg
m g h = \frac { 1 } { 2 } m v ^ { 2 }
./HME100K\train_images\train_95.jpg
4 0 0 0 \times 6 0 0 0 = 2 4 0 0 0 0 0 0 c m ^ { 2 }
./HME100K\train_images\train_97.jpg
\angle F E C = 6 0 ^ { \circ }
./HME100K\train_images\train_98.jpg
f ( 2 ) = f ( \frac { 1 } { 2 } \times 4 )
./HME100K\train_images\train_100.jpg
y = 0
./HME100K\train_images\train_103.jpg
+ x _ { 2 } = \frac { 1 2 k ^ { 2 } } { 1 + 3 k ^ { 2 } }
./HME100K\train_images\train_104.jpg
2 B O Q = 6 0 \because O Q ^ { \because } = \frac { 1 } { 2 } 0
./HME100K\train_images\train_106.jpg
a > 0 , b > 0 , \frac { a } { \vert a \vert } + \frac { b } { \vert b \vert } = 2
./HME100K\train_images\train_107.jpg
N a _ { 2 } C O _ { 3 } + 2 H C l = 2 N a C l + H _ { 2 } O + C O _ { 2 } \uparrow
./HME100K\train_images\train_108.jpg
A B = 4 , A D = 8
./HME100K\train_images\train_110.jpg
A P ^ { \prime } = P C
./HME100K\train_images\train_111.jpg
A C = \sqrt { 2 ^ { 2 } + 2 ^ { 2 } } = 2 \sqrt { 2 }
./HME100K\train_images\train_116.jpg
T = \frac { \pi } { 1 w 1 } = \frac { x } { 4 }
./HME100K\train_images\train_117.jpg
1 6 5 - 5 9 + 6 5 = 1 6 5 - 6 5 + 5 9
./HME100K\train_images\train_118.jpg
C H _ { 2 } = C H _ { 2 } + B r \rightarrow C H _ { 2 } B r C H _ { 2 } B r
./HME100K\train_images\train_119.jpg
\overrightarrow { a } - ( 2 , 2 ) = ( 1 , - 3 )
./HME100K\train_images\train_120.jpg
x _ { 1 } = 9 , X _ { 2 } \div - 1
./HME100K\train_images\train_121.jpg
1 4 0 - 9 0 = 5 0
./HME100K\train_images\train_122.jpg
= \frac { 1 2 } { \frac { \sqrt { 2 } } { 2 } }
./HME100K\train_images\train_125.jpg
3 ( x - 1 ) = y + 5
./HME100K\train_images\train_126.jpg
D E = \frac { 4 \sqrt { 2 } + \sqrt { 2 } x } { 2 } - y
./HME100K\train_images\train_127.jpg
N a _ { 2 } C O _ { 3 } + C a C l _ { 2 } = C a C O _ { 3 } \downarrow + 2 N a C l
./HME100K\train_images\train_128.jpg
( 1 ) 1 3 \div 4 = 3 \cdots
./HME100K\train_images\train_131.jpg
y = m
./HME100K\train_images\train_132.jpg
a \in [ - 1 , \frac { 1 } { 3 } ]
./HME100K\train_images\train_133.jpg
D x \leq 2
./HME100K\train_images\train_135.jpg
k _ { Q E } = \frac { 0 - ( - a k ) } { a - ( - a ) } = \frac { k } { 2 }
./HME100K\train_images\train_136.jpg
a _ { n } = 2 n + 1
./HME100K\train_images\train_138.jpg
y = \sqrt { 9 - x ^ { 2 } }
./HME100K\train_images\train_139.jpg
\frac { a _ { 1 0 } + a _ { 9 } } { a _ { 9 } } < 0
./HME100K\train_images\train_140.jpg
\frac { \vert x - 2 \vert } { x - 2 } - \frac { \vert x - 1 \vert } { \vert x - 1 \vert } + \frac { \vert x \vert } { x }
./HME100K\train_images\train_144.jpg
\sin ( \frac { 3 \pi } { 2 } + \alpha ) = - \cos \alpha
./HME100K\train_images\train_146.jpg
n = 1 5 0 r / \min = 2 . 5 r / s
./HME100K\train_images\train_147.jpg
z n + H _ { 2 } S O _ { 4 } = Z n S O _ { 4 } + H _ { 2 } \uparrow
./HME100K\train_images\train_148.jpg
\frac { 1 } { 2 0 1 6 } ) + \cdots + f ( 1 ) + f ( 2 ) +
./HME100K\train_images\train_151.jpg
- 3 ^ { 2 } - ( - 1 \frac { 2 } { 5 } ) \div 1 \frac { 5 } { 9 } \times ( - \frac { 5 } { 6 } )
./HME100K\train_images\train_152.jpg
y = x ^ { 2 } - 4 x - 5
./HME100K\train_images\train_154.jpg
( x - 6 0 ) ( x - 6 0 ) = 0 \therefore x =
./HME100K\train_images\train_155.jpg