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class Solution:
def isAnagram(self, s: str, t: str) -> bool:
if len(s) != len(t):
return False
counter = [0] * 26
for c in s:
counter[ord(c) - ord('a')] += 1
for c in t:
counter[ord(c) - ord('a')] -= 1
for i in counter:
if i != 0:
return False
return True