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"""
rmt_diffusion.py
================
Core library for reproducing the LINEAR-THEORY claims of:

  "A Random Matrix Theory Perspective on the Consistency of Diffusion Models"
   Binxu Wang, Jacob A. Zavatone-Veth, Cengiz Pehlevan (ICML 2026, arXiv:2602.02908)

The paper's central claims about linear diffusion models reduce to random-matrix /
linear-algebra statements about the empirical covariance of a finite dataset. This
module implements:

  * solve_kappa      -- the self-consistent renormalized-noise map kappa(lambda)  (Eq. 4)
  * denoiser_matrix  -- the optimal linear denoiser  Sigma_hat (Sigma_hat + s^2 I)^-1   (Eq. 2)
  * deterministic-equivalence predictions for the denoiser EXPECTATION (Result 4.1)
    and VARIANCE (Result 4.2), plus the sampling-map overshrinkage (Result 5.1)
  * Monte-Carlo estimators over dataset realizations to VALIDATE those predictions

Everything runs on CPU in minutes. We work in the eigenbasis of the population
covariance Sigma = diag(eigs) (WLOG) and set the population mean mu = 0, exactly the
simplification the paper adopts (mu_hat = mu) to isolate finite-sample covariance effects.
"""

from __future__ import annotations
import numpy as np

# np.trapz was renamed to np.trapezoid in NumPy 2.0 (and removed later); support both.
_trapz = getattr(np, "trapezoid", None) or np.trapz


# --------------------------------------------------------------------------------------
# Population covariance
# --------------------------------------------------------------------------------------
def power_law_spectrum(d: int, alpha: float = 1.0, floor: float = 1e-3,
                       normalize: bool = True) -> np.ndarray:
    """Population eigenvalues lambda_k = k^{-alpha}, k = 1..d.

    Natural-image covariances have an approximately power-law spectrum (Ruderman 1994),
    which is the regime the paper studies. `floor` keeps the smallest eigenvalues from
    underflowing; `normalize` sets the top eigenvalue to 1.
    """
    k = np.arange(1, d + 1, dtype=float)
    eigs = k ** (-alpha) + floor
    if normalize:
        eigs = eigs / eigs[0]
    return eigs  # descending


def sample_empirical_cov(eigs: np.ndarray, n: int, rng: np.random.Generator) -> np.ndarray:
    """Draw n samples x_i ~ N(0, diag(eigs)) and return the empirical covariance
    Sigma_hat = (1/n) sum_i x_i x_i^T  (a d x d Wishart-type matrix)."""
    d = eigs.shape[0]
    z = rng.standard_normal((n, d))
    x = z * np.sqrt(eigs)[None, :]          # rows ~ N(0, diag(eigs))
    return (x.T @ x) / n


# --------------------------------------------------------------------------------------
# Renormalized noise scale  kappa(lambda)   (Silverstein / Marchenko-Pastur; Eq. 4)
# --------------------------------------------------------------------------------------
def _normalized_trace_resolvent(eigs: np.ndarray, kappa: float) -> float:
    """ (1/d) * sum_k lambda_k / (lambda_k + kappa)  =  tr[Sigma (Sigma + kappa I)^-1]. """
    return float(np.mean(eigs / (eigs + kappa)))


def solve_kappa(lam: float, eigs: np.ndarray, gamma: float,
                tol: float = 1e-12, max_iter: int = 200) -> float:
    """Solve the self-consistent equation (Eq. 4):

        kappa - lam = gamma * kappa * tr[Sigma (Sigma + kappa I)^-1]

    for the unique kappa > 0, by bisection. gamma = d / n is the aspect ratio.
    Returns kappa >= lam (finite data renormalize the noise scale UP).
    """
    if lam <= 0:
        return 0.0

    def h(kappa: float) -> float:
        return kappa - lam - gamma * kappa * _normalized_trace_resolvent(eigs, kappa)

    lo = lam                       # h(lam) = -gamma*lam*g(lam) <= 0
    hi = lam + max(lam, 1.0)
    # expand upper bracket until h(hi) > 0
    it = 0
    while h(hi) < 0 and it < 100:
        hi *= 2.0
        it += 1
    for _ in range(max_iter):
        mid = 0.5 * (lo + hi)
        hm = h(mid)
        if abs(hm) < tol or (hi - lo) < tol * max(1.0, mid):
            return mid
        if hm < 0:
            lo = mid
        else:
            hi = mid
    return 0.5 * (lo + hi)


# --------------------------------------------------------------------------------------
# Degrees-of-freedom functions (Eq. 5, UNNORMALIZED trace Tr)
# --------------------------------------------------------------------------------------
def df1(eigs: np.ndarray, lam: float) -> float:
    return float(np.sum(eigs / (eigs + lam)))


def df2(eigs: np.ndarray, lam: float) -> float:
    return float(np.sum(eigs ** 2 / (eigs + lam) ** 2))


# --------------------------------------------------------------------------------------
# Linear denoiser (Eq. 2, mu = 0):  D*(x; s) = Sigma_hat (Sigma_hat + s^2 I)^-1 x
# --------------------------------------------------------------------------------------
def denoiser_matrix(Sigma: np.ndarray, sigma2: float) -> np.ndarray:
    """Return the linear-denoiser matrix  M = C (C + sigma2 I)^-1  for covariance C."""
    d = Sigma.shape[0]
    return Sigma @ np.linalg.solve(Sigma + sigma2 * np.eye(d), np.eye(d))


def population_denoiser_diag(eigs: np.ndarray, ridge: float) -> np.ndarray:
    """Diagonal (in population eigenbasis) of the population denoiser with ridge penalty:
    lambda_k / (lambda_k + ridge).  With ridge = kappa(sigma2) this is Result 4.1."""
    return eigs / (eigs + ridge)


# --------------------------------------------------------------------------------------
# Deterministic-equivalence predictions
# --------------------------------------------------------------------------------------
def predict_shrinkage_along_pc(eigs: np.ndarray, sigma2: float, gamma: float):
    """Result 4.1 / Fig 2C: expected shrinkage of the empirical denoiser along population
    PC u_k is lambda_k/(lambda_k + kappa(sigma2)) (renormalized), which OVER-shrinks
    relative to the naive population value lambda_k/(lambda_k + sigma2)."""
    kappa = solve_kappa(sigma2, eigs, gamma)
    renorm = eigs / (eigs + kappa)         # DE prediction (what finite data give)
    naive = eigs / (eigs + sigma2)         # infinite-data population denoiser
    return kappa, renorm, naive


def predict_denoiser_variance_along_pc(eigs: np.ndarray, sigma2: float, n: int,
                                       x_vec: np.ndarray):
    """Result 4.2: Var over dataset realizations of  u_k^T D*_hat(x; sigma) , per PC k.

        Var ~ [ kappa^2 / (n - df2(kappa)) ] * chi(lambda_k, kappa) * calD(x, kappa)

    with chi(lambda, kappa) = lambda/(lambda+kappa)^2  (anisotropy; bell-shaped, peak at
    lambda = kappa, peak value 1/(4 kappa)) and calD(x,kappa) = sum_k lambda_k x_k^2/(lambda_k+kappa)^2
    (inhomogeneity). Returns (kappa, per-k variance prediction, chi, peak_value).
    """
    d = eigs.shape[0]
    gamma = d / n
    kappa = solve_kappa(sigma2, eigs, gamma)
    chi = eigs / (eigs + kappa) ** 2                       # anisotropy per PC
    inhom = float(np.sum(eigs * x_vec ** 2 / (eigs + kappa) ** 2))  # calD(x, kappa)
    prefactor = kappa ** 2 / (n - df2(eigs, kappa))
    var_pred = prefactor * chi * inhom
    peak_value = 1.0 / (4.0 * kappa)                       # max of chi at lambda = kappa
    return kappa, var_pred, chi, inhom, peak_value


def predict_sqrt_cov_scaling(eigs: np.ndarray, n: int):
    """Result 5.1 / Fig 4A: the sampling map contains Sigma_hat^{1/2}. Its expected scaling
    along population eigenmode u_k, E[u_k^T Sigma_hat^{1/2} u_k], OVER-shrinks relative to
    the ideal sqrt(lambda_k), most severely for low eigenmodes and small n.

    A convenient deterministic-equivalence-style prediction (Balakrishnan integral of the
    kappa map) for the per-mode scaling is:

        s_k  ~  (2/pi) * integral_0^inf  lambda_k / (lambda_k + kappa(u^2))  du

    which we evaluate numerically. Returns (ideal sqrt(lambda_k), predicted s_k)."""
    ideal = np.sqrt(eigs)
    gamma = eigs.shape[0] / n
    # integrate over u on a log-spaced grid; integrand decays like lambda_k/u^2 for large u
    u = np.concatenate([np.linspace(1e-4, 5.0, 4000), np.linspace(5.0, 200.0, 4000)])
    kap = np.array([solve_kappa(uu ** 2, eigs, gamma) for uu in u])
    pred = np.empty_like(eigs)
    for k, lk in enumerate(eigs):
        integrand = lk / (lk + kap)
        pred[k] = (2.0 / np.pi) * _trapz(integrand, u)
    return ideal, pred


# --------------------------------------------------------------------------------------
# Monte-Carlo estimators (ground truth to validate the DE predictions above)
# --------------------------------------------------------------------------------------
def mc_trace_resolvent(eigs: np.ndarray, lam: float, n: int, R: int,
                       rng: np.random.Generator) -> float:
    """MC estimate of (1/d) Tr[Sigma_hat (Sigma_hat + lam I)^-1], averaged over R draws.
    Validates the deterministic equivalence  ~ (1/d) Tr[Sigma (Sigma + kappa(lam) I)^-1]."""
    d = eigs.shape[0]
    vals = np.empty(R)
    I = np.eye(d)
    for r in range(R):
        C = sample_empirical_cov(eigs, n, rng)
        M = C @ np.linalg.solve(C + lam * I, I)
        vals[r] = np.trace(M) / d
    return float(vals.mean())


def mc_denoiser_stats(eigs: np.ndarray, sigma2: float, n: int, R: int,
                      x_vec: np.ndarray, rng: np.random.Generator):
    """Monte-Carlo mean and variance, over R dataset realizations, of the per-PC denoiser
    response  u_k^T D*_hat(x; sigma)  (with population PCs = coordinate axes here).

    Returns (mean_k, var_k) arrays of length d."""
    d = eigs.shape[0]
    I = np.eye(d)
    resp = np.empty((R, d))
    for r in range(R):
        C = sample_empirical_cov(eigs, n, rng)
        M = C @ np.linalg.solve(C + sigma2 * I, I)   # denoiser matrix
        resp[r] = M @ x_vec                          # response vector; u_k^T (.) = coord k
    return resp.mean(axis=0), resp.var(axis=0, ddof=1)


def mc_sqrt_cov_scaling(eigs: np.ndarray, n: int, R: int,
                        rng: np.random.Generator) -> np.ndarray:
    """MC estimate of E[u_k^T Sigma_hat^{1/2} u_k] per population eigenmode k."""
    d = eigs.shape[0]
    acc = np.zeros(d)
    for r in range(R):
        C = sample_empirical_cov(eigs, n, rng)
        w, V = np.linalg.eigh(C)
        w = np.clip(w, 0.0, None)
        C_half = (V * np.sqrt(w)) @ V.T
        acc += np.diag(C_half)          # u_k = e_k in population eigenbasis
    return acc / R


def sqrt_cov(C: np.ndarray) -> np.ndarray:
    """Symmetric PSD square root of C (the linear generative / sampling map)."""
    w, V = np.linalg.eigh(C)
    w = np.clip(w, 0.0, None)
    return (V * np.sqrt(w)) @ V.T


def mc_sqrtmap_variance(eigs: np.ndarray, n: int, R: int,
                        rng: np.random.Generator) -> np.ndarray:
    """Result 5.2: per-mode VARIANCE, across dataset realizations, of the sampling-map
    diagonal  u_k^T Sigma_hat^{1/2} u_k. For a linear/Gaussian score model the
    probability-flow ODE integrates in closed form to the map x = Sigma_hat^{1/2} z, so
    this is the variance of the FULL generative trajectory (not a one-step denoise).
    Returns the per-mode variance (length d)."""
    d = eigs.shape[0]
    vals = np.empty((R, d))
    for r in range(R):
        C = sample_empirical_cov(eigs, n, rng)
        vals[r] = np.diag(sqrt_cov(C))
    return vals.var(axis=0, ddof=1)


def predict_sqrtmap_variance(eigs: np.ndarray, n: int) -> np.ndarray:
    """Leading-order deterministic-equivalence prediction for Result 5.2. With u_k = e_k,
    u_k^T Sigma_hat u_k = (1/n) sum_i (z_ik^2) lambda_k has variance 2 lambda_k^2 / n
    exactly; the delta method through g(t)=sqrt(t) (g'=1/(2 sqrt(lambda_k))) gives

        Var[u_k^T Sigma_hat^{1/2} u_k]  ~  lambda_k / (2 n)

    i.e. anisotropic (proportional to lambda_k) and decaying as 1/n. The residual vs MC is
    the finite-sample coupling of off-diagonal Sigma_hat entries into the matrix sqrt."""
    return eigs / (2.0 * n)


def mc_split_consistency(eigs: np.ndarray, n: int, n_seeds: int,
                         rng: np.random.Generator):
    """Fig 1 (linear model): two NON-OVERLAPPING data splits A, B (n samples each, disjoint)
    each define a linear diffusion sampler x = Sigma_hat^{1/2} z. Generate samples from the
    SAME seeds z under both splits and measure cross-split agreement:

        * mean cosine similarity  cos(x_A, x_B)          -> 1 as n grows
        * mean relative squared deviation  ||x_A-x_B||^2 / (||x_A|| ||x_B||)

    The deviation is set by the sampling-map variance (Result 5.2), so it decays ~ 1/n:
    finite datasets that never share a sample still generate the same picture from a seed,
    and they agree better with more data. Returns (mean_cosine, mean_rel_sq_deviation)."""
    d = eigs.shape[0]
    HA = sqrt_cov(sample_empirical_cov(eigs, n, rng))   # split A sampler
    HB = sqrt_cov(sample_empirical_cov(eigs, n, rng))   # split B sampler (disjoint draw)
    Z = rng.standard_normal((n_seeds, d))
    XA = Z @ HA.T
    XB = Z @ HB.T
    nA = np.linalg.norm(XA, axis=1)
    nB = np.linalg.norm(XB, axis=1)
    cos = np.sum(XA * XB, axis=1) / (nA * nB)
    rel_sq = np.sum((XA - XB) ** 2, axis=1) / (nA * nB)
    return float(cos.mean()), float(rel_sq.mean())


def mc_total_denoiser_variance(eigs: np.ndarray, sigma2: float, n: int, R: int,
                               rng: np.random.Generator) -> float:
    """Global scaling (Fig 3D): total variance of the denoiser matrix entries across
    realizations, Sum_{ij} Var[M_ij], which the theory predicts decays ~ 1/n at large n."""
    d = eigs.shape[0]
    I = np.eye(d)
    mats = np.empty((R, d, d))
    for r in range(R):
        C = sample_empirical_cov(eigs, n, rng)
        mats[r] = C @ np.linalg.solve(C + sigma2 * I, I)
    return float(mats.var(axis=0, ddof=1).sum())


# --------------------------------------------------------------------------------------
# Small self-test
# --------------------------------------------------------------------------------------
if __name__ == "__main__":
    rng = np.random.default_rng(0)
    eigs = power_law_spectrum(50, alpha=1.0)
    lam = 0.1
    gamma = 50 / 500
    k = solve_kappa(lam, eigs, gamma)
    print(f"kappa({lam}) = {k:.5f}  (>= lam: {k >= lam})")
    de = _normalized_trace_resolvent(eigs, k)
    mc = mc_trace_resolvent(eigs, lam, n=500, R=200, rng=rng)
    print(f"trace resolvent  DE={de:.5f}  MC={mc:.5f}  rel.err={abs(de-mc)/mc:.3%}")