[
  {
    "conversations": [
      {
        "content": "How to solve \"100 – The 3n + 1 problem\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"100 – The 3n + 1 problem\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"100 – The 3n + 1 problem\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"100 – The 3n + 1 problem\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"100 – The 3n + 1 problem\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"100 – The 3n + 1 problem\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"100 – The 3n + 1 problem\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"100 – The 3n + 1 problem\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 100 – The 3n + 1 problem?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 100 – The 3n + 1 problem?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 100 – The 3n + 1 problem in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 100 – The 3n + 1 problem.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 100 – The 3n + 1 problem.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 100 – The 3n + 1 problem with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 100 – The 3n + 1 problem.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 100 – The 3n + 1 problem, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「100 – The 3n + 1 problem」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「100 – The 3n + 1 problem」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「100 – The 3n + 1 problem」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「100 – The 3n + 1 problem」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「100 – The 3n + 1 problem」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「100 – The 3n + 1 problem」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「100 – The 3n + 1 problem」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「100 – The 3n + 1 problem」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "100 – The 3n + 1 problem 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "100 – The 3n + 1 problem 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 100 – The 3n + 1 problem？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 100 – The 3n + 1 problem 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 100 – The 3n + 1 problem 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 100 – The 3n + 1 problem 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 100 – The 3n + 1 problem 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 100 – The 3n + 1 problem 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int i, j;\n    while (cin >> i >> j){\n        int mx = 0;\n        for (int n = min(i, j); n <= max(i, j); n++){\n            int n1 = n, cnt = 1;\n            while (n1 != 1){\n                if (n1 % 2) n1 = 3 * n1 + 1;\n                else n1 /= 2;\n                cnt++;\n            }\n            mx = max(mx, cnt);\n        }\n        cout << i << \" \" << j << \" \" << mx << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "100 – The 3n + 1 problem",
    "Question Description": "Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.\n    Consider the following algorithm:\n        1. input n\n        2. print n\n        3. if n = 1 then STOP\n        4.     if n is odd then n ← 3n + 1\n        5.     else n ← n/2\n        6. GOTO 2\nGiven the input 22, the following sequence of numbers will be printed:22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1\nIt is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1, 000, 000 (and, in fact, for many more numbers than this.)\nGiven an input n, it is possible to determine the number of numbers printed before and including the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.\nFor any two numbers i and j you are to determine the maximum cycle length over all numbers between and including both i and j.\n",
    "Input Requirements": "The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0. You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j. You can assume that no operation overflows a 32-bit integer.\n",
    "Output Requirements": "For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).\n",
    "Sample Input": "1 10\n100 200\n201 210\n900 1000\n",
    "Sample Output": "1 10 20\n100 200 125\n201 210 89\n900 1000 174\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"118 Mutant Flatworld Explorers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"118 Mutant Flatworld Explorers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"118 Mutant Flatworld Explorers\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"118 Mutant Flatworld Explorers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"118 Mutant Flatworld Explorers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"118 Mutant Flatworld Explorers\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"118 Mutant Flatworld Explorers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"118 Mutant Flatworld Explorers\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 118 Mutant Flatworld Explorers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 118 Mutant Flatworld Explorers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 118 Mutant Flatworld Explorers in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 118 Mutant Flatworld Explorers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 118 Mutant Flatworld Explorers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 118 Mutant Flatworld Explorers with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 118 Mutant Flatworld Explorers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 118 Mutant Flatworld Explorers, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「118 Mutant Flatworld Explorers」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「118 Mutant Flatworld Explorers」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「118 Mutant Flatworld Explorers」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「118 Mutant Flatworld Explorers」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「118 Mutant Flatworld Explorers」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「118 Mutant Flatworld Explorers」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「118 Mutant Flatworld Explorers」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「118 Mutant Flatworld Explorers」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "118 Mutant Flatworld Explorers 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "118 Mutant Flatworld Explorers 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 118 Mutant Flatworld Explorers？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 118 Mutant Flatworld Explorers 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 118 Mutant Flatworld Explorers 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 118 Mutant Flatworld Explorers 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 118 Mutant Flatworld Explorers 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 118 Mutant Flatworld Explorers 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\nint a[55][55];\nint dx[] = {0, 1, 0, -1}; //N, E, S, W\nint dy[] = {1, 0, -1, 0};\n \nint main() {\n    int row, col, R, C, D, nR, nC;\n    char d;\n    bool lost = false;\n    string s;\n    map <char, int> mp1;\n    map <int, char> mp2;\n    mp1['N'] = 0; mp2[0] = 'N';\n    mp1['E'] = 1; mp2[1] = 'E';\n    mp1['S'] = 2; mp2[2] = 'S';\n    mp1['W'] = 3; mp2[3] = 'W';\n    cin >> row >> col;\n    while (cin >> R >> C >> d >> s){\n        D = mp1[d];\n        lost = false;\n        for (int i = 0; i < s.size(); i++){\n            if (s[i] == 'F'){\n                nR = R + dx[D];\n                nC = C + dy[D];\n                if (nR >= 0 && nR <= row && nC >= 0 && nC <= col){\n                    R = nR;\n                    C = nC;\n                } else {\n                    if (a[R][C] == 1){\n                        continue;\n                    } else {\n                        cout << R << \" \" << C << \" \" << mp2[D] << \" LOST\\n\";\n                        lost = true;\n                        a[R][C] = 1;\n                        break;\n                    }\n                }\n            } else if (s[i] == 'R'){\n                D = (D + 1) % 4;\n            } else {\n                D = (D - 1 + 4) % 4;\n            }\n        }\n        if (!lost) cout << R << \" \" << C << \" \" << mp2[D] << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "118 Mutant Flatworld Explorers",
    "Question Description": "Robotics, robot motion planning, and machine learning are areas that cross the boundaries of many of the subdisciplines that comprise Computer Science: artificial intelligence, algorithms and complexity, electrical and mechanical engineering to name a few. In addition, robots as \"turtles\" (inspired by work by Papert, Abelson, and diSessa) and as \"beeper-pickers\" (inspired by work by Pattis) have been studied and used by students as an introduction to programming for many years.\n\nThis problem involves determining the position of a robot exploring a pre-Columbian flat world.\n\nGiven the dimensions of a rectangular grid and a sequence of robot positions and instructions, you are to write a program that determines for each sequence of robot positions and instructions the final position of the robot.\n\nA robot *position* consists of a grid coordinate (a pair of integers: x-coordinate followed by y-coordinate) and an orientation (N,S,E,W for north, south, east, and west). A robot *instruction* is a string of the letters 'L', 'R', and 'F' which represent, respectively, the instructions:\n\n- *Left*: the robot turns left 90 degrees and remains on the current grid point.\n- *Right*: the robot turns right 90 degrees and remains on the current grid point.\n- *Forward*: the robot moves forward one grid point in the direction of the current orientation and maintains the same orientation.\n\nThe direction *North* corresponds to the direction from grid point (x,y) to grid point (x,y+1).\n\nSince the grid is rectangular and bounded, a robot that moves \"off\" an edge of the grid is lost forever. However, lost robots leave a robot \"scent\" that prohibits future robots from dropping off the world at the same grid point. The scent is left at the last grid position the robot occupied before disappearing over the edge. An instruction to move \"off\" the world from a grid point from which a robot has been previously lost is simply ignored by the current robot.",
    "Input Requirements": "The first line of input is the upper-right coordinates of the rectangular world, the lower-left coordinates are assumed to be 0,0.\n\nThe remaining input consists of a sequence of robot positions and instructions (two lines per robot). A position consists of two integers specifying the initial coordinates of the robot and an orientation (N,S,E,W), all separated by white space on one line. A robot instruction is a string of the letters 'L', 'R', and 'F' on one line.\n\nEach robot is processed sequentially, i.e., finishes executing the robot instructions before the next robot begins execution.\n\nInput is terminated by end-of-file.\n\nYou may assume that all initial robot positions are within the bounds of the specified grid. The maximum value for any coordinate is 50. All instruction strings will be less than 100 characters in length.",
    "Output Requirements": "For each robot position/instruction in the input, the output should indicate the final grid position and orientation of the robot. If a robot falls off the edge of the grid the word 'LOST' should be printed after the position and orientation.",
    "Sample Input": "5 3\n1 1 E\nRFRFRFRF\n3 2 N\nFRRFLLFFRRFLL\n0 3 W\nLLFFFLFLFL\n",
    "Sample Output": "1 1 E\n3 3 N LOST\n2 3 S\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"272 TEX Quotes\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"272 TEX Quotes\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"272 TEX Quotes\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"272 TEX Quotes\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"272 TEX Quotes\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"272 TEX Quotes\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"272 TEX Quotes\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"272 TEX Quotes\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 272 TEX Quotes?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 272 TEX Quotes?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 272 TEX Quotes in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 272 TEX Quotes.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 272 TEX Quotes.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 272 TEX Quotes with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 272 TEX Quotes.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 272 TEX Quotes, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「272 TEX Quotes」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「272 TEX Quotes」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「272 TEX Quotes」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「272 TEX Quotes」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「272 TEX Quotes」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「272 TEX Quotes」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「272 TEX Quotes」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「272 TEX Quotes」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "272 TEX Quotes 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "272 TEX Quotes 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 272 TEX Quotes？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 272 TEX Quotes 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 272 TEX Quotes 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 272 TEX Quotes 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 272 TEX Quotes 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 272 TEX Quotes 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nstring s;\nint cnt, blk;\n \nint main() {\n    while (getline(cin, s)){\n        for (int i = 0; i < s.length(); i++){\n            if (s[i] == '\"'){\n                if (cnt % 2 == 0) cout << \"``\";\n                else cout << \"''\";\n                cnt++;\n            }\n            else cout << s[i];\n        }\n        cout << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "272 TEX Quotes",
    "Question Description": "TEX is a typesetting language developed by Donald Knuth. It takes source text together with a few typesetting instructions and produces, one hopes, a beautiful document. Beautiful documents use \"and\" to delimit quotations, rather than the mundane \"which is what is provided by most keyboards. Keyboards typically do not have an oriented double-quote, but they do have a left-single-quote\" and a right-single-quote\". Check your keyboard now to locate the left-single-quote key (sometimes called the \"backquote key\") and the right-single-quote key (sometimes called the \"apostrophe\" or just \"quote\"). Be careful not to confuse the left-single-quote with the \"backslash\" key. TEX lets the user type two left-single-quotes to create a left-double-quote and two right-single-quotes to create a right-double-quote. Most typists, however, are accustomed to delimiting their quotations with the un-oriented double-quote\".\n\nIf the source contained\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nthen the typeset document produced by TEX would not contain the desired form:\n\n\"To be or not to be,\" quoth the bard, \"that is the question.\"\n\nIn order to produce the desired form, the source file must contain the sequence:\n\nTo be or not to be,'' quoth the bard, 'that is the question.''\n\nYou are to write a program which converts text containing double-quote characters into text that is identical except that double-quotes have been replaced by the two-character sequences required by TEX for delimiting quotations with oriented double-quotes. The double-quote characters should be replaced appropriately by either if the \"opens a quotation and by\" if the \"closes a quotation. Notice that the question of nested quotations does not arise: The first \"must be replaced by\", the next by ',the next by ',the next by ',the next by ',the next by ',and so on.",
    "Input Requirements": "Input will consist of several lines of text containing an even number of double-quote characters. Input is ended with an end-of-file character.",
    "Output Requirements": "The text must be output exactly as it was input except that:\n\n* *the first \"in each pair is replaced by two\" characters: and\n\n* *the second \"in each pair is replaced by two\" characters: ''",
    "Sample Input": "\"To be or not to be,\" quoth the Bard, \"that is the question\". The programming contestant replied: \"I must disagree. To 'C' or not to 'C', that is The Question!\"\n",
    "Sample Output": "`To be or not to be,'' quoth the Bard, `that\nis the question''.\nThe programming contestant replied: `I must disagree.\nTo 'C' or not to 'C', that is The Question!!'\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"299 Train Swapping\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"299 Train Swapping\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"299 Train Swapping\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"299 Train Swapping\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"299 Train Swapping\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"299 Train Swapping\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"299 Train Swapping\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"299 Train Swapping\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 299 Train Swapping?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 299 Train Swapping?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 299 Train Swapping in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 299 Train Swapping.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 299 Train Swapping.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 299 Train Swapping with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 299 Train Swapping.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 299 Train Swapping, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「299 Train Swapping」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「299 Train Swapping」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「299 Train Swapping」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「299 Train Swapping」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「299 Train Swapping」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「299 Train Swapping」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「299 Train Swapping」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「299 Train Swapping」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "299 Train Swapping 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "299 Train Swapping 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 299 Train Swapping？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 299 Train Swapping 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 299 Train Swapping 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 299 Train Swapping 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 299 Train Swapping 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 299 Train Swapping 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        int cnt = 0;\n        for (int i = 0; i < N-1; i++){\n            for (int j = i+1; j < N; j++){\n                if (a[i] > a[j]){\n                    swap(a[i], a[j]);\n                    cnt++;\n                }\n            }\n        }\n        cout << \"Optimal train swapping takes \" << cnt << \" swaps.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "299 Train Swapping",
    "Question Description": "At an old railway station, you may still encounter one of the last remaining \"train swappers\". A train swapper is an employee of the railroad, whose sole job it is to rearrange the carriages of trains. Once the carriages are arranged in the optimal order, all the train driver has to do, is drop the carriages off, one by one, at the stations for which the load is meant.\n\nThe title \"train swapper\" stems from the first person who performed this task, at a station close to a railway bridge. Instead of opening up vertically, the bridge rotated around a pillar in the center of the river. After rotating the bridge 90 degrees, boats could pass left or right. The first train swapper had discovered that the bridge could be operated with at most two carriages on it. By rotating the bridge 180 degrees, the carriages switched place, allowing him to rearrange the carriages (as a side effect, the carriages then faced the opposite direction, but train carriages can move either way, so who cares).\n\nNow that almost all train swappers have died out, the railway company would like to automate their operation. Part of the program to be developed, is a routine which decides for a given train the least number of swaps of two adjacent carriages necessary to order the train. Your assignment is to create that routine.",
    "Input Requirements": "The input contains on the first line the number of test cases (N). Each test case consists of two input lines. The first line of a test case contains an integer L, determining the length of the train (0 ≤ L ≤ 50). The second line of a test case contains a permutation of the numbers 1 through L, indicating the current order of the carriages. The carriages should be ordered such that carriage 1 comes first, then 2, etc. with carriage L coming last.",
    "Output Requirements": "For each test case output the sentence: 'Optimal train swapping takes S swaps.' where S is an integer.",
    "Sample Input": "3\n3\n1 3 2\n4\n4 3 2 1\n2\n2 1\n",
    "Sample Output": "Optimal train swapping takes 1 swaps.\nOptimal train swapping takes 6 swaps.\nOptimal train swapping takes 1 swaps.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"490 Rotating Sentences\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"490 Rotating Sentences\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"490 Rotating Sentences\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"490 Rotating Sentences\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"490 Rotating Sentences\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"490 Rotating Sentences\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"490 Rotating Sentences\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"490 Rotating Sentences\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 490 Rotating Sentences?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 490 Rotating Sentences?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 490 Rotating Sentences in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 490 Rotating Sentences.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 490 Rotating Sentences.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 490 Rotating Sentences with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 490 Rotating Sentences.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 490 Rotating Sentences, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「490 Rotating Sentences」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「490 Rotating Sentences」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「490 Rotating Sentences」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「490 Rotating Sentences」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「490 Rotating Sentences」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「490 Rotating Sentences」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「490 Rotating Sentences」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「490 Rotating Sentences」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "490 Rotating Sentences 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "490 Rotating Sentences 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 490 Rotating Sentences？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 490 Rotating Sentences 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 490 Rotating Sentences 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 490 Rotating Sentences 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 490 Rotating Sentences 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 490 Rotating Sentences 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nstring s[105];\n \nint main() {\n    int col = 0, row = 0;\n    while (getline(cin, s[col])){\n        row = max(row, (int)s[col].size());\n        col++;\n    }\n    for (int i = 0; i < row; i++){\n        for (int j = col-1; j >= 0; j--){\n            if (i >= s[j].size()) cout << \" \";\n            else cout << s[j][i];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "490 Rotating Sentences",
    "Question Description": "In \"Rotating Sentences,\" you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.",
    "Input Requirements": "As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)",
    "Output Requirements": "The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.",
    "Sample Input": "Rene Decartes once said, \"I think, therefore I am.\"\n",
    "Sample Output": "\"R  \nIe  \nn  \nte  \nh  \niD  \nne  \nkc  \n,a  \nr  \ntt  \nhe  \nes  \nr  \neo  \nfn  \noc  \nre  \ne  \ns  \nIa  \ni  \nad  \nm,  \n.  \n\"\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"948 Fibonaccimal Base\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"948 Fibonaccimal Base\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"948 Fibonaccimal Base\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"948 Fibonaccimal Base\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"948 Fibonaccimal Base\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"948 Fibonaccimal Base\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"948 Fibonaccimal Base\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"948 Fibonaccimal Base\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 948 Fibonaccimal Base?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 948 Fibonaccimal Base?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 948 Fibonaccimal Base in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 948 Fibonaccimal Base.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 948 Fibonaccimal Base.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 948 Fibonaccimal Base with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 948 Fibonaccimal Base.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 948 Fibonaccimal Base, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「948 Fibonaccimal Base」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「948 Fibonaccimal Base」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「948 Fibonaccimal Base」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「948 Fibonaccimal Base」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「948 Fibonaccimal Base」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「948 Fibonaccimal Base」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「948 Fibonaccimal Base」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「948 Fibonaccimal Base」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "948 Fibonaccimal Base 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "948 Fibonaccimal Base 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 948 Fibonaccimal Base？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 948 Fibonaccimal Base 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 948 Fibonaccimal Base 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 948 Fibonaccimal Base 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 948 Fibonaccimal Base 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 948 Fibonaccimal Base 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nint main() {\n    vector <int> fib;\n    int f0 = 0, f1 = 1, f2 = 1;\n    for (; f2 <= 1e8; ){\n        f2 = f0 + f1;\n        fib.push_back(f2);\n        f0 = f1;\n        f1 = f2;\n    }\n    reverse(fib.begin(), fib.end());\n    int N, n, x;\n    cin >> N;\n    while (N--){\n        cin >> n;\n        x = n;\n        vector <int> ans;\n        int i = 0;\n        while (fib[i] > x) i++;\n        for (; i < fib.size(); i++){\n            if (fib[i] <= x){\n                x -= fib[i];\n                ans.push_back(1);\n                i++;\n                if (i < fib.size()) ans.push_back(0);\n            } else ans.push_back(0);\n        }\n        cout << n << \" = \";\n        for (auto j: ans) cout << j;\n        cout << \" (fib)\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "948 Fibonaccimal Base",
    "Question Description": "The well known Fibonacci sequence is obtained by starting with 0 and 1 and then adding the two last numbers to get the next one. For example the third number in the sequence is 1 (1=1+0), the forth is 2 (2=1+1), the fifth is 3 (3=2+1) and so on.\n\nThe sequence appears on many things in our life, in nature, and has a great significance. Among other things, do you know that all positive integer numbers can be represented as a sum of numbers in the Fibonacci sequence? More than that, all positive integers can be represented as a sum of a set of Fibonacci numbers, that is, numbers from the sequence, without repetition. For example: 13 can be the sum of the sets {13}, {5,8} or {2,3,8} and 17 is represented by {1,3,13} or {1,3,5,8}. Since all numbers have this property this set could be a nice way to use as a \"base\" to represent the number. But, as we have seen, some numbers have more than one set whose sum is the number. Simple! If we add the constraint that the sets cannot have two consecutive Fibonacci numbers, than we have a unique representation for each number! This restriction is because the sum of any two consecutive Fibonacci numbers is just the following Fibonacci number.\n\nNow that we know all this we can prepare a nice way to represent any positive integer. We will use a binary sequence (just zeros and ones) to do that. For example, 17 = 1 + 3 + 13 (remember that no two consecutive Fibonacci numbers can be used). Let's write a zero for each Fibonacci number that is not used and one for each one that is used, starting at the right. Then, 17 = 100101. In this representation we should not have zeros at the left, this is, we should only write starting with the first one. In order for you to understand better, note that in this scheme, not using two consecutive Fibonacci numbers means that the binary sequence will not have two consecutive ones. When we use this representation for a number we say that we are using the Fibonaccimal base, and we write it like 17 = 100101 (fb).\n\nGiven a set of numbers in decimal base, your task is to write them in the Fibonaccimal base.",
    "Input Requirements": "The first line of input contains a single number N, representing the quantity of numbers that follow (1≤N≤500).\n\nThan follow exactly N lines, each one containing a single positive integer smaller than 100 000 000. These numbers can come in any order.",
    "Output Requirements": "You should output a single line for each of the N integers in the input, with the format 'DEC_BASE = FIB_BASE (fib)'. DEC_BASE is the original number in decimal base and FIB_BASE is its representation in Fibonaccimal base. See the sample output for an example.",
    "Sample Input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n",
    "Sample Output": "1 = 1 (fib)\n2 = 10 (fib)\n3 = 100 (fib)\n4 = 101 (fib)\n5 = 1000 (fib)\n6 = 1001 (fib)\n7 = 1010 (fib)\n8 = 10000 (fib)\n9 = 10001 (fib)\n10 = 10010 (fib)\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10008 What's Cryptanalysis?\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10008 What's Cryptanalysis?\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10008 What's Cryptanalysis?\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10008 What's Cryptanalysis?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10008 What's Cryptanalysis?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10008 What's Cryptanalysis?\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10008 What's Cryptanalysis?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10008 What's Cryptanalysis?\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10008 What's Cryptanalysis??",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10008 What's Cryptanalysis??",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10008 What's Cryptanalysis? in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10008 What's Cryptanalysis?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10008 What's Cryptanalysis?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10008 What's Cryptanalysis? with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10008 What's Cryptanalysis?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10008 What's Cryptanalysis?, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10008 What's Cryptanalysis?」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10008 What's Cryptanalysis?」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10008 What's Cryptanalysis?」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10008 What's Cryptanalysis?」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10008 What's Cryptanalysis?」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10008 What's Cryptanalysis?」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10008 What's Cryptanalysis?」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10008 What's Cryptanalysis?」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10008 What's Cryptanalysis? 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10008 What's Cryptanalysis? 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10008 What's Cryptanalysis?？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10008 What's Cryptanalysis? 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10008 What's Cryptanalysis? 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10008 What's Cryptanalysis? 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10008 What's Cryptanalysis? 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10008 What's Cryptanalysis? 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n \nbool cmp(pair<int, char> a, pair<int, char> b) {\n    if (a.first != b.first) return a.first > b.first;\n    else return a.second < b.second;\n}\n \nint main() {\n    vector <pair<int, char> > v(26);\n    for (int i = 0; i < 26; i++) {\n        v[i] = {0, 'A'+i};\n    }\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // clear buffer (\\n)\n    while (n--) {\n        getline(cin, s);\n        for (int i = 0; i < s.size(); i++) {\n            if ('A' <= s[i] && s[i] <= 'Z') {\n                v[s[i] - 'A'].first++;\n            }\n            if ('a' <= s[i] && s[i] <= 'z') {\n                v[s[i] - 'a'].first++;\n            }\n        }\n    }\n    sort(v.begin(), v.end(), cmp);\n    for (auto i: v) {\n        if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10008 What's Cryptanalysis?",
    "Question Description": "Cryptanalysis is the process of breaking someone else's cryptographic writing. This sometimes involves some kind of statistical analysis of a passage of (encrypted) text. Your task is to write a program which performs a simple analysis of a given text.",
    "Input Requirements": "The first line of input contains a single positive decimal integer n. This is the number of lines which follow in the input. The next n lines will contain zero or more characters (possibly including whitespace). This is the text which must be analyzed.",
    "Output Requirements": "Each line of output contains a single uppercase letter, followed by a single space, then followed by a positive decimal integer. The integer indicates how many times the corresponding letter appears in the input text. Upper and lower case letters in the input are to be considered the same. No other characters must be counted. The output must be sorted in descending count order; that is, the most frequent letter is on the first output line, and the last line of output indicates the least frequent letter. If two letters have the same frequency, then the letter which comes first in the alphabet must appear first in the output. If a letter does not appear in the text, then that letter must not appear in the output.",
    "Sample Input": "3\nThis is a test.\nCount me 1 2 3 4 5.\nWow!!!! Is this question easy?\n",
    "Sample Output": "S 7\nT 6\nI 5\nE 4\nO 3\nA 2\nH 2\nN 2\nU 2\nW 2\nC 1\nM 1\nQ 1\nY 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10019 Funny Encryption Method\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10019 Funny Encryption Method\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10019 Funny Encryption Method\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10019 Funny Encryption Method\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10019 Funny Encryption Method\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10019 Funny Encryption Method\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10019 Funny Encryption Method\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10019 Funny Encryption Method\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10019 Funny Encryption Method?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10019 Funny Encryption Method?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10019 Funny Encryption Method in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10019 Funny Encryption Method.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10019 Funny Encryption Method.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10019 Funny Encryption Method with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10019 Funny Encryption Method.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10019 Funny Encryption Method, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10019 Funny Encryption Method」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10019 Funny Encryption Method」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10019 Funny Encryption Method」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10019 Funny Encryption Method」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10019 Funny Encryption Method」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10019 Funny Encryption Method」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10019 Funny Encryption Method」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10019 Funny Encryption Method」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10019 Funny Encryption Method 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10019 Funny Encryption Method 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10019 Funny Encryption Method？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10019 Funny Encryption Method 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10019 Funny Encryption Method 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10019 Funny Encryption Method 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10019 Funny Encryption Method 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10019 Funny Encryption Method 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, N;\n    cin >> T;\n    while (T--){\n        cin >> N;\n        int X1 = N;\n        int b1 = 0;\n        while (X1){\n            b1 += X1 & 1;\n            X1 >>= 1;\n        }\n        int X2 = 0;\n        int mul = 1;\n        X1 = N;\n        while (X1){\n            X2 += (X1 % 10) * mul;\n            X1 /= 10;\n            mul *= 16;\n        }\n        int b2 = 0;\n        while (X2){\n            b2 += X2 & 1;\n            X2 >>= 1;\n        }\n        cout << b1 << \" \" << b2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10019 Funny Encryption Method",
    "Question Description": "A student from ITESM Campus Monterrey plays with a new encryption method for numbers. These method consist of the following steps:\n\n1. Read the number N to encrypt : M = 265\n2. Interpret N as a decimal number : X₁ = 265 (decimal)\n3. Convert the decimal interpretation of N to its binary representation : X₁ = 100001001 (binary)\n4. Let b₁ be equal to the number of 1's in this binary representation : b₁ = 3\n5. Interpret N as a Hexadecimal number : X₂ = 265 (hexadecimal)\n6. Convert the hexadecimal interpretation of N to its binary representation : X₂ = 1001100101\n7. Let b₂ be equal to the number of 1's in the last binary representation : b₂ = 5\n8. The encryption is the result of M xor (b1*b2) : 265 xor (3*5) = 262\n\nThis student asked the judges to ask for the numbers of 1's bits of these two representations so that he can continue playing. You have to write a program that reads a Number and gives as output the numbers b₁ and b₂.",
    "Input Requirements": "The first line will contain a number N which is the number of cases that you have to process. Each of the following N Lines (0 < N ≤ 1000) will contain the number M (0 < M ≤ 9999, in decimal representation) which is the number the student wants to encrypt.",
    "Output Requirements": "You will have to output N lines, each containing the number b₁ and b₂ in that order, separated by one space corresponding to that lines number to crypt.",
    "Sample Input": "3\n265\n111\n1234\n",
    "Sample Output": "3 5\n6 3\n5 5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10035 Primary Arithmetic\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10035 Primary Arithmetic\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10035 Primary Arithmetic\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10035 Primary Arithmetic\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10035 Primary Arithmetic\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10035 Primary Arithmetic\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10035 Primary Arithmetic\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10035 Primary Arithmetic\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10035 Primary Arithmetic?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10035 Primary Arithmetic?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10035 Primary Arithmetic in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10035 Primary Arithmetic.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10035 Primary Arithmetic.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10035 Primary Arithmetic with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10035 Primary Arithmetic.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10035 Primary Arithmetic, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10035 Primary Arithmetic」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10035 Primary Arithmetic」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10035 Primary Arithmetic」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10035 Primary Arithmetic」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10035 Primary Arithmetic」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10035 Primary Arithmetic」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10035 Primary Arithmetic」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10035 Primary Arithmetic」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10035 Primary Arithmetic 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10035 Primary Arithmetic 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10035 Primary Arithmetic？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10035 Primary Arithmetic 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10035 Primary Arithmetic 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10035 Primary Arithmetic 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10035 Primary Arithmetic 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10035 Primary Arithmetic 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int n1, n2;\n    while (cin >> n1 >> n2){\n        int carry = 0, cnt = 0;\n        if (n1 == 0 && n2 == 0) break;\n        while (n1 > 0 || n2 > 0){\n            int tmp = n1 % 10 + n2 % 10 + carry;\n            if (tmp >= 10){\n                carry = tmp / 10;\n                cnt++;\n            } else {\n                carry = 0;\n            }\n            n1 /= 10;\n            n2 /= 10;\n        }\n        if (cnt == 0) cout << \"No carry operation.\\n\";\n        else if (cnt == 1) cout << \"1 carry operation.\\n\";\n        else cout << cnt << \" carry operations.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10035 Primary Arithmetic",
    "Question Description": "Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the \"carry\" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.",
    "Input Requirements": "Each line of input contains two unsigned integers less than 10 digits. The last line of input contains '0 0'.",
    "Output Requirements": "For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.",
    "Sample Input": "123 456\n555 555\n123 594\n0 0\n",
    "Sample Output": "No carry operation.\n3 carry operations.\n1 carry operation.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10038 Jolly Jumpers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10038 Jolly Jumpers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10038 Jolly Jumpers\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10038 Jolly Jumpers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10038 Jolly Jumpers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10038 Jolly Jumpers\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10038 Jolly Jumpers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10038 Jolly Jumpers\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10038 Jolly Jumpers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10038 Jolly Jumpers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10038 Jolly Jumpers in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10038 Jolly Jumpers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10038 Jolly Jumpers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10038 Jolly Jumpers with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10038 Jolly Jumpers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10038 Jolly Jumpers, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10038 Jolly Jumpers」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10038 Jolly Jumpers」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10038 Jolly Jumpers」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10038 Jolly Jumpers」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10038 Jolly Jumpers」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10038 Jolly Jumpers」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10038 Jolly Jumpers」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10038 Jolly Jumpers」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10038 Jolly Jumpers 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10038 Jolly Jumpers 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10038 Jolly Jumpers？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10038 Jolly Jumpers 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10038 Jolly Jumpers 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10038 Jolly Jumpers 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10038 Jolly Jumpers 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10038 Jolly Jumpers 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int pre, now;\n        int d[n]; // initial value not guaranteed to be zero\n        for (int i = 0; i < n; i++) {\n            d[i] = 0;\n        }\n        cin >> pre;\n        for (int i = 1; i < n; i++){\n            cin >> now;\n            d[abs(now - pre)]++;\n            pre = now;\n        }\n        bool flag = true;\n        for (int i = 1; i < n; i++) {\n            if (d[i] != 1) {\n                flag = false;\n                break;\n            }\n        }\n        if (flag) cout << \"Jolly\\n\";\n        else cout << \"Not jolly\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10038 Jolly Jumpers",
    "Question Description": "A sequence of n > 0 integers is called a jolly jumper if the absolute values of the difference between successive elements take on all the values 1 through n - 1. For instance, the sequence 1 4 2 3 is a jolly jumper, because the absolute differences are 3, 2, and 1 respectively. The definition implies that any sequence of a single integer is a jolly jumper. You are to write a program to determine whether or not each of a number of sequences is a jolly jumper.",
    "Input Requirements": "Each line of input contains an integer n ≤ 3000 followed by n integers representing the sequence.",
    "Output Requirements": "For each line of input, generate a line of output saying 'Jolly' or 'Not jolly'.",
    "Sample Input": "4 1 4 2 3\n5 1 4 2 -1 6\n",
    "Sample Output": "Jolly\nNot jolly\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10041 Vito's family\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10041 Vito's family\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10041 Vito's family\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10041 Vito's family\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10041 Vito's family\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10041 Vito's family\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10041 Vito's family\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10041 Vito's family\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10041 Vito's family?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10041 Vito's family?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10041 Vito's family in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10041 Vito's family.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10041 Vito's family.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10041 Vito's family with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10041 Vito's family.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10041 Vito's family, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10041 Vito's family」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10041 Vito's family」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10041 Vito's family」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10041 Vito's family」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10041 Vito's family」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10041 Vito's family」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10041 Vito's family」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10041 Vito's family」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10041 Vito's family 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10041 Vito's family 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10041 Vito's family？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10041 Vito's family 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10041 Vito's family 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10041 Vito's family 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10041 Vito's family 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10041 Vito's family 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int T, r;\n    cin >> T;\n    while (T--) {\n        cin >> r;\n        int s[r];\n        for (int i = 0; i < r; i++){\n            cin >> s[i];\n        }\n        sort(s, s+r);\n        int sum = 0;\n        for (int i = 0; i < r; i++){\n            sum += abs(s[i] - s[r/2]);\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10041 Vito's family",
    "Question Description": "The world-known gangster Vito Deadstone is moving to New York. He has a very big family there, all of them living in Lamafia Avenue. Since he will visit all his relatives very often, he is trying to find a house close to them.\n\nVito wants to minimize the total distance to all of them and has blackmailed you to write a program that solves his problem.",
    "Input Requirements": "The input consists of several test cases. The first line contains the number of test cases.\nFor each test case you will be given the integer number of relatives r (0 < r < 500) and the street numbers (also integers) s₁, s₂, ..., sᵢ, ..., sᵣ where they live (0 < sᵢ < 30000). Note that several relatives could live in the same street number.",
    "Output Requirements": "For each test case your program must write the minimal sum of distances from the optimal Vito's house to each one of his relatives. The distance between two street numbers sᵢ and sⱼ is dᵢⱼ = |sᵢ - sⱼ|.",
    "Sample Input": "2\n2 2 4\n3 2 4 6\n",
    "Sample Output": "2\n4\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10050 Hartals\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10050 Hartals\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10050 Hartals\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10050 Hartals\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10050 Hartals\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10050 Hartals\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10050 Hartals\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10050 Hartals\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10050 Hartals?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10050 Hartals?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10050 Hartals in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10050 Hartals.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10050 Hartals.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10050 Hartals with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10050 Hartals.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10050 Hartals, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10050 Hartals」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10050 Hartals」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10050 Hartals」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10050 Hartals」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10050 Hartals」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10050 Hartals」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10050 Hartals」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10050 Hartals」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10050 Hartals 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10050 Hartals 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10050 Hartals？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10050 Hartals 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10050 Hartals 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10050 Hartals 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10050 Hartals 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10050 Hartals 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\n \nint main() {\n    int T, N, P, h;\n    cin >> T;\n    while (T--){\n        cin >> N >> P;\n        int a[N+1];\n        memset(a, 0, sizeof(a));\n        for (int i = 0; i < P; i++){\n            cin >> h;\n            for (int j = h; j <= N; j+=h){\n                a[j] = 1;\n            }\n        }\n        for (int i = 6; i <= N; i+=7){\n            a[i] = 0;\n        }\n        for (int i = 7; i <= N; i+=7){\n            a[i] = 0;\n        }\n        int sum = 0;\n        for (int i = 1; i <= N; i++){\n            sum += a[i];\n        }\n        cout << sum << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10050 Hartals",
    "Question Description": "A social research organization has determined a simple set of parameters to simulate the behavior of political parties. One parameter is a positive integer h (called the hartal parameter) that denotes the average number of days between two successive hartals (strikes) called by a party. Given the hartal parameters for several political parties and a number of days N, your job is to determine the number of working days lost due to hartals, with no hartals occurring on weekly holidays (Fridays and Saturdays).",
    "Input Requirements": "The first line of input is an integer T giving the number of test cases. For each test case, the first line contains an integer N (7 ≤ N ≤ 3650) giving the number of days to simulate. The next line contains an integer P (1 ≤ P ≤ 100) representing the number of political parties. The following P lines each contain a positive integer h (not a multiple of 7) giving the hartal parameter for each party.",
    "Output Requirements": "For each test case, output the number of working days lost due to hartals. Each output must be on a separate line.",
    "Sample Input": "2\n14\n3\n3\n4\n8\n100\n4\n12\n15\n25\n40\n",
    "Sample Output": "5\n15\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10055 Hashmat the brave warrior\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10055 Hashmat the brave warrior\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10055 Hashmat the brave warrior\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10055 Hashmat the brave warrior\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10055 Hashmat the brave warrior\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10055 Hashmat the brave warrior\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10055 Hashmat the brave warrior\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10055 Hashmat the brave warrior\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10055 Hashmat the brave warrior?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10055 Hashmat the brave warrior?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10055 Hashmat the brave warrior in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10055 Hashmat the brave warrior.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10055 Hashmat the brave warrior.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10055 Hashmat the brave warrior with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10055 Hashmat the brave warrior.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10055 Hashmat the brave warrior, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10055 Hashmat the brave warrior」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10055 Hashmat the brave warrior」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10055 Hashmat the brave warrior」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10055 Hashmat the brave warrior」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10055 Hashmat the brave warrior」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10055 Hashmat the brave warrior」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10055 Hashmat the brave warrior」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10055 Hashmat the brave warrior」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10055 Hashmat the brave warrior 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10055 Hashmat the brave warrior 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10055 Hashmat the brave warrior？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10055 Hashmat the brave warrior 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10055 Hashmat the brave warrior 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10055 Hashmat the brave warrior 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10055 Hashmat the brave warrior 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10055 Hashmat the brave warrior 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long n1, n2;\n    while (cin >> n1 >> n2){\n        cout << abs(n1 - n2) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10055 Hashmat the brave warrior",
    "Question Description": "Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.",
    "Input Requirements": "The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2³². Input is terminated by 'End of File'.",
    "Output Requirements": "For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in separate line.",
    "Sample Input": "10 12\n10 14\n100 200\n",
    "Sample Output": "2\n4\n100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10056 What is the Probability?\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10056 What is the Probability?\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10056 What is the Probability?\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10056 What is the Probability?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10056 What is the Probability?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10056 What is the Probability?\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10056 What is the Probability?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10056 What is the Probability?\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10056 What is the Probability??",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10056 What is the Probability??",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10056 What is the Probability? in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10056 What is the Probability?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10056 What is the Probability?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10056 What is the Probability? with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10056 What is the Probability?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10056 What is the Probability?, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10056 What is the Probability?」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10056 What is the Probability?」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10056 What is the Probability?」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10056 What is the Probability?」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10056 What is the Probability?」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10056 What is the Probability?」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10056 What is the Probability?」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10056 What is the Probability?」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10056 What is the Probability? 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10056 What is the Probability? 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10056 What is the Probability?？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10056 What is the Probability? 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10056 What is the Probability? 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10056 What is the Probability? 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10056 What is the Probability? 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10056 What is the Probability? 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n \nint main() {\n    int S, N, K;\n    double p;\n    cin >> S;\n    while (S--){\n        cin >> N >> p >> K;\n        if (p == 0) {\n            cout << \"0.0000\\n\";\n            continue;\n        }\n        double first = pow(1.0 - p, K-1) * p;\n        double r = pow(1.0 - p, N);\n        cout << fixed << setprecision(4) <<\n        first / (1.0 - r) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10056 What is the Probability?",
    "Question Description": "Probability has always been an integrated part of computer algorithms. In this problem, we determine the winning probability of a certain player in a game where players take turns throwing a dice-like object. The first player to achieve a certain event is declared the winner. The task is to calculate the probability of a specific player (the I-th player) winning the game.",
    "Input Requirements": "The input starts with an integer S (S ≤ 1000) indicating the number of test cases. Each test case consists of three values: an integer N (N ≤ 1000) representing the number of players, a floating-point number p indicating the probability of the successful event in a single throw, and an integer I (I ≤ N) representing the serial number of the player whose winning probability is to be determined.",
    "Output Requirements": "For each test case, output the probability of the I-th player winning, rounded to four decimal places.",
    "Sample Input": "2\n2 0.166666 1\n2 0.166666 2\n",
    "Sample Output": "0.5455\n0.4545\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10057 A mid-summer night's dream\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10057 A mid-summer night's dream\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10057 A mid-summer night's dream\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10057 A mid-summer night's dream\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10057 A mid-summer night's dream\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10057 A mid-summer night's dream\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10057 A mid-summer night's dream\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10057 A mid-summer night's dream\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10057 A mid-summer night's dream?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10057 A mid-summer night's dream?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10057 A mid-summer night's dream in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10057 A mid-summer night's dream.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10057 A mid-summer night's dream.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10057 A mid-summer night's dream with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10057 A mid-summer night's dream.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10057 A mid-summer night's dream, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10057 A mid-summer night's dream」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10057 A mid-summer night's dream」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10057 A mid-summer night's dream」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10057 A mid-summer night's dream」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10057 A mid-summer night's dream」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10057 A mid-summer night's dream」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10057 A mid-summer night's dream」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10057 A mid-summer night's dream」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10057 A mid-summer night's dream 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10057 A mid-summer night's dream 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10057 A mid-summer night's dream？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10057 A mid-summer night's dream 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10057 A mid-summer night's dream 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10057 A mid-summer night's dream 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10057 A mid-summer night's dream 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10057 A mid-summer night's dream 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    while (cin >> n){\n        int a[n];\n        for (int i = 0; i < n; i++){\n            cin >> a[i];\n        }\n        sort(a, a+n);\n        int mid1 = a[(n-1)/2];\n        int mid2 = a[n/2];\n        int ans = 0;\n        for (int i = 0; i < n; i++){\n            if (a[i] == mid1 || a[i] == mid2) ans++;\n        }\n        cout << mid1 << \" \" << ans << \" \" << mid2 - mid1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10057 A mid-summer night's dream",
    "Question Description": "In this problem, we need to find an integer A (which could be a combination lock code) from a set of numbers such that the sum of absolute deviations from A is minimized. The input consists of multiple test cases, each containing a list of numbers. For each test case, we need to determine:\n1. The minimum possible value for A (the median or medians)\n2. How many numbers in the input satisfy the property of A (i.e., how many times these median values appear)\n3. How many different integer values of A exist that minimize the sum of absolute deviations (the range between the lower and upper median if n is even).",
    "Input Requirements": "The input contains several blocks. Each block starts with an integer n (0 < n ≤ 1,000,000) indicating the number of elements, followed by n integers (each less than 65,536). The input ends with EOF.",
    "Output Requirements": "For each test case, output three values separated by spaces:\n1. The minimum possible value for A (the lower median if n is even)\n2. The count of numbers in the input that are equal to either the lower or upper median\n3. The number of possible different integer values for A (1 if n is odd, or the range between the two medians + 1 if n is even)",
    "Sample Input": "2\n10\n10\n4\n1\n2\n2\n4\n",
    "Sample Output": "10 2 1\n2 2 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10062 Tell me the frequencies!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10062 Tell me the frequencies!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10062 Tell me the frequencies!\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10062 Tell me the frequencies!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10062 Tell me the frequencies!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10062 Tell me the frequencies!\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10062 Tell me the frequencies!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10062 Tell me the frequencies!\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10062 Tell me the frequencies!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10062 Tell me the frequencies!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10062 Tell me the frequencies! in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10062 Tell me the frequencies!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10062 Tell me the frequencies!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10062 Tell me the frequencies! with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10062 Tell me the frequencies!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10062 Tell me the frequencies!, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10062 Tell me the frequencies!」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10062 Tell me the frequencies!」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10062 Tell me the frequencies!」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10062 Tell me the frequencies!」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10062 Tell me the frequencies!」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10062 Tell me the frequencies!」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10062 Tell me the frequencies!」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10062 Tell me the frequencies!」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10062 Tell me the frequencies! 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10062 Tell me the frequencies! 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10062 Tell me the frequencies!？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10062 Tell me the frequencies! 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10062 Tell me the frequencies! 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10062 Tell me the frequencies! 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10062 Tell me the frequencies! 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10062 Tell me the frequencies! 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define pii pair<int,int>\n \nbool cmp(pii a, pii b){\n    if (a.first != b.first) return a.first < b.first;\n    else return a.second > b.second;\n}\n \nint main() {\n    string s;\n    while (getline(cin, s)) {\n        pii a[256];\n        for (int i = 0; i < 256; i++) {\n            a[i] = {0, i};\n        }\n        for (int i = 0; i < s.size(); i++) {\n            a[(int)s[i]].first++;\n        }\n        sort(a, a+256, cmp);\n        for (auto i: a){\n            if (i.first > 0) cout << i.second << \" \" << i.first << \"\\n\";\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10062 Tell me the frequencies!",
    "Question Description": "Given a line of text, the task is to find out the frequencies of the ASCII characters present in it. The input lines will not contain any of the first 32 or last 128 ASCII characters. Lines may end with newline or carriage return characters, but these should be excluded from consideration.",
    "Input Requirements": "The input consists of several lines of text, each treated as a single input. The maximum length of each line is 1000 characters. The input is terminated by end-of-file.",
    "Output Requirements": "For each line of input, output the ASCII value of each character present along with its frequency. The output should list characters in ascending order of their frequencies. If two characters have the same frequency, the one with the higher ASCII value should be listed first. Each set of output should be separated by a blank line.",
    "Sample Input": "AAABBC\n122333\n",
    "Sample Output": "67 1\n66 2\n65 3\n\n49 1\n50 2\n51 3\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10071 Back to High School Physics\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10071 Back to High School Physics\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10071 Back to High School Physics\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10071 Back to High School Physics\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10071 Back to High School Physics\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10071 Back to High School Physics\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10071 Back to High School Physics\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10071 Back to High School Physics\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10071 Back to High School Physics?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10071 Back to High School Physics?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10071 Back to High School Physics in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10071 Back to High School Physics.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10071 Back to High School Physics.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10071 Back to High School Physics with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10071 Back to High School Physics.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10071 Back to High School Physics, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10071 Back to High School Physics」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10071 Back to High School Physics」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10071 Back to High School Physics」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10071 Back to High School Physics」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10071 Back to High School Physics」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10071 Back to High School Physics」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10071 Back to High School Physics」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10071 Back to High School Physics」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10071 Back to High School Physics 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10071 Back to High School Physics 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10071 Back to High School Physics？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10071 Back to High School Physics 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10071 Back to High School Physics 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10071 Back to High School Physics 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10071 Back to High School Physics 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10071 Back to High School Physics 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int v, t;\n    while (cin >> v >> t){\n        cout << 2 * v * t << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10071 Back to High School Physics",
    "Question Description": "A particle has initial velocity and acceleration. If its velocity after a certain time is v, the task is to determine its displacement after twice that time. The problem involves basic physics calculations where the displacement is derived from the given velocity and time.",
    "Input Requirements": "The input consists of multiple lines, each containing two integers v (-100 ≤ v ≤ 100) and t (0 ≤ t ≤ 200), where v is the velocity and t is the time at which the particle reaches that velocity.",
    "Output Requirements": "For each line of input, output a single integer representing the displacement after twice the given time (2t).",
    "Sample Input": "0 0\n5 12\n",
    "Sample Output": "0\n120\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10093 An Easy Problem!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10093 An Easy Problem!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10093 An Easy Problem!\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10093 An Easy Problem!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10093 An Easy Problem!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10093 An Easy Problem!\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10093 An Easy Problem!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10093 An Easy Problem!\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10093 An Easy Problem!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10093 An Easy Problem!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10093 An Easy Problem! in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10093 An Easy Problem!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10093 An Easy Problem!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10093 An Easy Problem! with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10093 An Easy Problem!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10093 An Easy Problem!, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10093 An Easy Problem!」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10093 An Easy Problem!」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10093 An Easy Problem!」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10093 An Easy Problem!」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10093 An Easy Problem!」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10093 An Easy Problem!」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10093 An Easy Problem!」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10093 An Easy Problem!」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10093 An Easy Problem! 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10093 An Easy Problem! 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10093 An Easy Problem!？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10093 An Easy Problem! 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10093 An Easy Problem! 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10093 An Easy Problem! 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10093 An Easy Problem! 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10093 An Easy Problem! 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int sum, mx, temp;\n    string s;\n    while (getline(cin, s)){\n        sum = 0;\n        mx = 1;\n        int i;\n        for (i = 0; i < s.size(); i++) {\n            if (s[i] >= '0' && s[i] <= '9') {\n                temp = s[i] - '0';\n            }\n            else if (s[i] >= 'A' && s[i] <= 'Z') {\n                temp = s[i] - 'A' + 10;\n            }\n            else if (s[i] >= 'a' && s[i] <= 'z') {\n                temp = s[i] - 'a' + 36;\n            }\n            else continue;\n \n            if (mx < temp)\n                mx = temp;\n            sum += temp;\n        }\n \n        for (i = mx; i < 62; i++)\n            if (!(sum % i)) {\n                cout << i + 1 << \"\\n\";\n                break;\n            }\n \n        if (i == 62)\n            cout << \"such number is impossible!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10093 An Easy Problem!",
    "Question Description": "Given an N-based integer number R, the task is to find the smallest possible base N (2 ≤ N ≤ 62) such that R is divisible by (N - 1). The digit symbols for bases up to 62 include 0-9, A-Z, and a-z. The solution involves checking the divisibility condition and determining the smallest valid base.",
    "Input Requirements": "Each line of input contains a number represented in an unknown base (2-62). The number will consist of valid digit symbols (0-9, A-Z, a-z). No invalid numbers will be provided.",
    "Output Requirements": "For each input number, output the smallest possible base N that satisfies the condition R % (N - 1) == 0. If no such base exists within the range 2-62, output 'such number is impossible!'.",
    "Sample Input": "3\n5\nA\n",
    "Sample Output": "4\n6\n11\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10101 Bangla Numbers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10101 Bangla Numbers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10101 Bangla Numbers\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10101 Bangla Numbers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10101 Bangla Numbers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10101 Bangla Numbers\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10101 Bangla Numbers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10101 Bangla Numbers\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10101 Bangla Numbers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10101 Bangla Numbers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10101 Bangla Numbers in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10101 Bangla Numbers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10101 Bangla Numbers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10101 Bangla Numbers with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10101 Bangla Numbers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10101 Bangla Numbers, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10101 Bangla Numbers」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10101 Bangla Numbers」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10101 Bangla Numbers」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10101 Bangla Numbers」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10101 Bangla Numbers」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10101 Bangla Numbers」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10101 Bangla Numbers」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10101 Bangla Numbers」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10101 Bangla Numbers 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10101 Bangla Numbers 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10101 Bangla Numbers？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10101 Bangla Numbers 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10101 Bangla Numbers 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10101 Bangla Numbers 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10101 Bangla Numbers 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10101 Bangla Numbers 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){\n    string s = \"\";\n    while (x){\n        s += '0' + (x % 10);\n        x /= 10;\n    }\n    reverse(s.begin(), s.end());\n    return s;\n}\n \nvoid solve(ll x){\n    if (x >= a[0]){\n        solve(x / a[0]);\n        ans += \" \" + s[0];\n        x %= (int)a[0];\n    }\n    for (int i = 0; i < 4; i++){\n        if (x / a[i] > 0){\n            ans += \" \" + num2str(x / a[i]) + \" \" + s[i];\n            x %= a[i];\n        }\n    }\n    if (x > 0) ans += \" \" + num2str(x);\n}\n \nint main() {\n    ll N;\n    int Case = 1;\n    while (cin >> N){\n        cout << \"   \" << Case++ << \".\";\n        if (N == 0) cout << \" 0\\n\";\n        else {\n            ans = \"\";\n            solve(N);\n            cout << ans << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10101 Bangla Numbers",
    "Question Description": "The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting.",
    "Input Requirements": "The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999.",
    "Output Requirements": "For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting.",
    "Sample Input": "23764\n45897458973958\n",
    "Sample Output": "1. 23 hajar 7 shata 64\n2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10170 The Hotel with Infinite Rooms\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10170 The Hotel with Infinite Rooms\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10170 The Hotel with Infinite Rooms\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10170 The Hotel with Infinite Rooms\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10170 The Hotel with Infinite Rooms\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10170 The Hotel with Infinite Rooms\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10170 The Hotel with Infinite Rooms\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10170 The Hotel with Infinite Rooms\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10170 The Hotel with Infinite Rooms?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10170 The Hotel with Infinite Rooms?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10170 The Hotel with Infinite Rooms in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10170 The Hotel with Infinite Rooms.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10170 The Hotel with Infinite Rooms.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10170 The Hotel with Infinite Rooms with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10170 The Hotel with Infinite Rooms.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10170 The Hotel with Infinite Rooms, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10170 The Hotel with Infinite Rooms」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10170 The Hotel with Infinite Rooms」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10170 The Hotel with Infinite Rooms」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10170 The Hotel with Infinite Rooms」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10170 The Hotel with Infinite Rooms」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10170 The Hotel with Infinite Rooms」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10170 The Hotel with Infinite Rooms」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10170 The Hotel with Infinite Rooms」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10170 The Hotel with Infinite Rooms 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10170 The Hotel with Infinite Rooms 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10170 The Hotel with Infinite Rooms？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10170 The Hotel with Infinite Rooms 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10170 The Hotel with Infinite Rooms 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10170 The Hotel with Infinite Rooms 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10170 The Hotel with Infinite Rooms 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10170 The Hotel with Infinite Rooms 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    long long S, D, cnt;\n    while (cin >> S >> D){\n        cnt = S;\n        D -= S;\n        while (D > 0){\n            cnt++;\n            D -= cnt;\n        }\n        cout << cnt << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10170 The Hotel with Infinite Rooms",
    "Question Description": "The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in the hotel on the D-th day.",
    "Input Requirements": "Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined.",
    "Output Requirements": "For each input line, output the group size staying in the hotel on the D-th day.",
    "Sample Input": "1 6\n3 10\n3 14\n",
    "Sample Output": "3\n5\n6\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10189 Minesweeper\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10189 Minesweeper\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10189 Minesweeper\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10189 Minesweeper\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10189 Minesweeper\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10189 Minesweeper\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10189 Minesweeper\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10189 Minesweeper\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10189 Minesweeper?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10189 Minesweeper?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10189 Minesweeper in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10189 Minesweeper.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10189 Minesweeper.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10189 Minesweeper with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10189 Minesweeper.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10189 Minesweeper, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10189 Minesweeper」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10189 Minesweeper」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10189 Minesweeper」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10189 Minesweeper」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10189 Minesweeper」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10189 Minesweeper」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10189 Minesweeper」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10189 Minesweeper」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10189 Minesweeper 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10189 Minesweeper 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10189 Minesweeper？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10189 Minesweeper 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10189 Minesweeper 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10189 Minesweeper 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10189 Minesweeper 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10189 Minesweeper 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n    int n, m, Case = 1;\n    string s;\n    while (cin >> n >> m){\n        if (n == 0 && m == 0) break;\n        for (int i = 0; i < n; i++){\n            cin >> s;\n            for (int j = 0; j < m; j++){\n                a[i][j] = s[j];\n            }\n        }\n        memset(b, 0, sizeof(b));\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (a[i][j] == '*'){\n                    b[i][j] = -1;\n                } else {\n                    for (int k = 0; k < 8; k++){\n                        int x = i + dx[k];\n                        int y = j + dy[k];\n                        if (x >= 0 && x < n && y >= 0 && y < m && a[x][y] == '*')\n                            b[i][j]++;\n                    }\n                }\n            }\n        }\n        if (Case > 1) cout << \"\\n\";\n        cout << \"Field #\" << Case++ << \":\\n\";\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < m; j++){\n                if (b[i][j] == -1) cout << '*';\n                else cout << b[i][j];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10189 Minesweeper",
    "Question Description": "The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dimensions 0x0 is encountered.",
    "Input Requirements": "The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0.",
    "Output Requirements": "For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line.",
    "Sample Input": "4 4\n*...\n....\n*...\n....\n3 5\n**...\n.....\n.*...\n0 0\n",
    "Sample Output": "Field #1:\n*100\n2210\n1*10\n1110\n\nField #2:\n**100\n33200\n1*100\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10190 Divide, But Not Quite Conquer!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10190 Divide, But Not Quite Conquer!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10190 Divide, But Not Quite Conquer!\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10190 Divide, But Not Quite Conquer!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10190 Divide, But Not Quite Conquer!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10190 Divide, But Not Quite Conquer!\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10190 Divide, But Not Quite Conquer!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10190 Divide, But Not Quite Conquer!\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10190 Divide, But Not Quite Conquer!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10190 Divide, But Not Quite Conquer!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10190 Divide, But Not Quite Conquer! in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10190 Divide, But Not Quite Conquer!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10190 Divide, But Not Quite Conquer!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10190 Divide, But Not Quite Conquer! with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10190 Divide, But Not Quite Conquer!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10190 Divide, But Not Quite Conquer!, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10190 Divide, But Not Quite Conquer!」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10190 Divide, But Not Quite Conquer!」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10190 Divide, But Not Quite Conquer!」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10190 Divide, But Not Quite Conquer!」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10190 Divide, But Not Quite Conquer!」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10190 Divide, But Not Quite Conquer!」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10190 Divide, But Not Quite Conquer!」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10190 Divide, But Not Quite Conquer!」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10190 Divide, But Not Quite Conquer! 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10190 Divide, But Not Quite Conquer! 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10190 Divide, But Not Quite Conquer!？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10190 Divide, But Not Quite Conquer! 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10190 Divide, But Not Quite Conquer! 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10190 Divide, But Not Quite Conquer! 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10190 Divide, But Not Quite Conquer! 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10190 Divide, But Not Quite Conquer! 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n    int n, m;\n    while (cin >> n >> m){\n        vector <int> ans;\n        bool boring = false;\n        if (n == 0 || m == 0 || m == 1) boring = true;\n        else {\n            ans.push_back(n);\n            while (n > 1) {\n                if (n%m == 0){\n                    n /= m;\n                    ans.push_back(n);\n                } else {\n                    boring = true;\n                    break;\n                }\n            }\n        }\n        if (boring || ans.back() != 1) cout << \"Boring!\\n\";\n        else {\n            for (int i = 0; i < ans.size(); i++) {\n                if (i != 0) cout << \" \";\n                cout << ans[i];\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10190 Divide, But Not Quite Conquer!",
    "Question Description": "The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:\n1. Each term after the first must be the previous term divided by m.\n2. Each term (except the last) must be divisible by m.\n3. The sequence must be strictly decreasing.\nIf any condition is violated, the sequence is deemed 'Boring!'.",
    "Input Requirements": "The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file.",
    "Output Requirements": "For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'.",
    "Sample Input": "125 5\n30 3\n80 2\n81 3\n",
    "Sample Output": "125 25 5 1\nBoring!\nBoring!\n81 27 9 3 1\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10193 All You Need Is Love\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10193 All You Need Is Love\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10193 All You Need Is Love\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10193 All You Need Is Love\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10193 All You Need Is Love\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10193 All You Need Is Love\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10193 All You Need Is Love\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10193 All You Need Is Love\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10193 All You Need Is Love?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10193 All You Need Is Love?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10193 All You Need Is Love in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10193 All You Need Is Love.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10193 All You Need Is Love.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10193 All You Need Is Love with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10193 All You Need Is Love.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10193 All You Need Is Love, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10193 All You Need Is Love」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10193 All You Need Is Love」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10193 All You Need Is Love」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10193 All You Need Is Love」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10193 All You Need Is Love」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10193 All You Need Is Love」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10193 All You Need Is Love」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10193 All You Need Is Love」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10193 All You Need Is Love 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10193 All You Need Is Love 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10193 All You Need Is Love？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10193 All You Need Is Love 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10193 All You Need Is Love 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10193 All You Need Is Love 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10193 All You Need Is Love 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10193 All You Need Is Love 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint mygcd(int x, int y){\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n \nint main() {\n    int N;\n    string S1, S2;\n    cin >> N;\n    for (int Case = 1; Case <= N; Case++){\n        cin >> S1 >> S2;\n        int n1 = 0, n2 = 0;\n        for (int i = 0; i < S1.size(); i++){\n            n1 *= 2;\n            n1 += S1[i] - '0';\n        }\n        for (int i = 0; i < S2.size(); i++){\n            n2 *= 2;\n            n2 += S2[i] - '0';\n        }\n        cout << \"Pair #\" << Case;\n        if (mygcd(n1, n2) > 1) cout << \": All you need is love!\\n\";\n        else cout << \": Love is not all you need!\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10193 All You Need Is Love",
    "Question Description": "The problem involves determining if two given binary strings can be constructed by repeatedly subtracting a common binary string L (representing 'love') from them. The solution requires checking if the greatest common divisor (GCD) of the two binary numbers (converted from the strings) is greater than 1, indicating that such an L exists.",
    "Input Requirements": "The input starts with an integer N (N < 10000) representing the number of test cases. Each test case consists of two binary strings (S₁ and S₂) of length up to 30 characters. The strings are valid (no leading zeros and length > 1).",
    "Output Requirements": "For each test case, output whether a valid string L exists that can construct both S₁ and S₂. The output should be in the format:\n- 'Pair #p: All you need is love!' if such an L exists.\n- 'Pair #p: Love is not all you need!' otherwise.",
    "Sample Input": "5\n11011\n11000\n11011\n11001\n111111\n100\n1000000000\n110\n1010\n100\n",
    "Sample Output": "Pair #1: All you need is love!\nPair #2: Love is not all you need!\nPair #3: Love is not all you need!\nPair #4: All you need is love!\nPair #5: All you need is love!\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10221 Satellites\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10221 Satellites\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10221 Satellites\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10221 Satellites\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10221 Satellites\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10221 Satellites\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10221 Satellites\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10221 Satellites\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10221 Satellites?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10221 Satellites?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10221 Satellites in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10221 Satellites.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10221 Satellites.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10221 Satellites with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10221 Satellites.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10221 Satellites, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10221 Satellites」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10221 Satellites」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10221 Satellites」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10221 Satellites」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10221 Satellites」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10221 Satellites」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10221 Satellites」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10221 Satellites」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10221 Satellites 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10221 Satellites 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10221 Satellites？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10221 Satellites 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10221 Satellites 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10221 Satellites 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10221 Satellites 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10221 Satellites 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <cmath>\nusing namespace std;\n#define PI acos(0.0)*2.0\n \nint main() {\n    double r, s, a;\n    string unit;\n    double chord, arc;\n    r = 6440.0;\n    while (cin >> s >> a >> unit){\n        if (unit == \"min\") a /= 60.0;\n        if (a > 180.0) a = 360.0 - a;\n        chord = (r+s) * cos((90.0 - a/2.0)/ 180.0 * PI) * 2.0;\n        arc = 2.0 * PI * (r+s) * a / 360.0;\n        cout << fixed << setprecision(6) << arc << \" \" << chord << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10221 Satellites",
    "Question Description": "The problem involves calculating the arc and chord distances between two satellites orbiting the Earth. Given the distance of the satellites from the Earth's surface and the angle they subtend at the Earth's center (in degrees or minutes), the task is to compute these distances. The Earth's radius is given as 6440 kilometers, and the satellites are assumed to be on a circular orbit.",
    "Input Requirements": "Each test case consists of three inputs: an integer s (distance from Earth's surface), an integer a (angle in degrees or minutes), and a string 'deg' or 'min' specifying the unit of the angle. The input continues until there are no more test cases.",
    "Output Requirements": "For each test case, output the arc distance and chord distance between the two satellites, both in kilometers, with six decimal places of precision.",
    "Sample Input": "500 30 deg\n700 60 min\n200 45 deg\n",
    "Sample Output": "3633.775503 3592.408346\n124.616509 124.614927\n5215.043805 5082.035982\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10222 Decode the Mad man\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10222 Decode the Mad man\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10222 Decode the Mad man\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10222 Decode the Mad man\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10222 Decode the Mad man\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10222 Decode the Mad man\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10222 Decode the Mad man\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10222 Decode the Mad man\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10222 Decode the Mad man?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10222 Decode the Mad man?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10222 Decode the Mad man in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10222 Decode the Mad man.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10222 Decode the Mad man.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10222 Decode the Mad man with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10222 Decode the Mad man.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10222 Decode the Mad man, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10222 Decode the Mad man」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10222 Decode the Mad man」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10222 Decode the Mad man」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10222 Decode the Mad man」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10222 Decode the Mad man」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10222 Decode the Mad man」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10222 Decode the Mad man」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10222 Decode the Mad man」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10222 Decode the Mad man 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10222 Decode the Mad man 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10222 Decode the Mad man？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10222 Decode the Mad man 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10222 Decode the Mad man 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10222 Decode the Mad man 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10222 Decode the Mad man 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10222 Decode the Mad man 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    string s[] = {\"~!@#$%^&*()_+\",\n        \"`1234567890-=\",\n        \"qwertyuiop[]\\\\\",\n        \"asdfghjkl;'\",\n        \"zxcvbnm,./\"};\n     \n    map <char, char> mp;\n    for (int i = 0; i < 5; i++){\n        for (int j = 2; j < s[i].size(); j++){\n            mp[s[i][j]] = s[i][j-2];\n        }\n    }\n    string S;\n    while (getline(cin, S)){\n        for (int i = 0; i < S.size(); i++){\n            if (S[i] == ' ') cout << \" \";\n            else cout << mp[tolower(S[i])];\n        }\n        cout << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10222 Decode the Mad man",
    "Question Description": "The problem involves decoding a message where each character is replaced by the two characters immediately to its left on a standard QWERTY keyboard. The input is a single line of encoded text, and the output should be the decoded message.",
    "Input Requirements": "The input consists of a single line of text containing one or more words. The text may include letters, punctuation, and spaces.",
    "Output Requirements": "The output should be the decoded message, where each character (except spaces) is replaced by the character two positions to its left on a QWERTY keyboard. Spaces should remain unchanged.",
    "Sample Input": "k[r dyt I[o]\n",
    "Sample Output": "how are you\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10226 Hardwood Species\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10226 Hardwood Species\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10226 Hardwood Species\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10226 Hardwood Species\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10226 Hardwood Species\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10226 Hardwood Species\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10226 Hardwood Species\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10226 Hardwood Species\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10226 Hardwood Species?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10226 Hardwood Species?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10226 Hardwood Species in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10226 Hardwood Species.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10226 Hardwood Species.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10226 Hardwood Species with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10226 Hardwood Species.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10226 Hardwood Species, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10226 Hardwood Species」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10226 Hardwood Species」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10226 Hardwood Species」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10226 Hardwood Species」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10226 Hardwood Species」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10226 Hardwood Species」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10226 Hardwood Species」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10226 Hardwood Species」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10226 Hardwood Species 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10226 Hardwood Species 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10226 Hardwood Species？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10226 Hardwood Species 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10226 Hardwood Species 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10226 Hardwood Species 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10226 Hardwood Species 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10226 Hardwood Species 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    string s;\n    cin >> n;\n    getline(cin, s); // Clear the buffer\n    getline(cin, s); // Skip the blank line\n    while (n--) {\n        map<string, int> mp;\n        int sum = 0;\n        while (getline(cin, s) && s != \"\") {\n            mp[s]++;\n            sum++;\n        }\n        for (auto &species : mp) {\n            cout << species.first << \" \" << fixed << setprecision(4) \n                 << (double)species.second / sum * 100 << \"\\n\";\n        }\n        if (n > 0) cout << \"\\n\"; // Print blank line between test cases except the last one\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10226 Hardwood Species",
    "Question Description": "The problem involves analyzing a list of tree species observed by satellite imaging and calculating the percentage of each species in the total population. The input consists of multiple test cases, each containing a list of tree species (one per line), and the output should display each species followed by its percentage representation in the population, sorted alphabetically and formatted to four decimal places.",
    "Input Requirements": "The input starts with an integer indicating the number of test cases. Each test case contains a list of tree species (one per line), with a blank line separating consecutive test cases. No species name exceeds 30 characters, and there are no more than 10,000 species or 1,000,000 trees.",
    "Output Requirements": "For each test case, output the name of each species in alphabetical order, followed by its percentage of the total population (to four decimal places). Separate the output of consecutive test cases with a blank line.",
    "Sample Input": "1\n\nRed Alder\nAsh\nAspen\nBasswood\nAsh\nBeech\nYellow Birch\nAsh\nCherry\nCottonwood\nAsh\nCypress\nRed Elm\nGum\nHackberry\nWhite Oak\nHickory\nPecan\nHard Maple\nWhite Oak\nSoft Maple\nRed Oak\nRed Oak\nWhite Oak\nPoplan\nSassafras\nSycamore\nBlack Walnut\nWillow",
    "Sample Output": "Ash 13.7931\nAspen 3.4483\nBasswood 3.4483\nBeech 3.4483\nBlack Walnut 3.4483\nCherry 3.4483\nCottonwood 3.4483\nCypress 3.4483\nGum 3.4483\nHackberry 3.4483\nHard Maple 3.4483\nHickory 3.4483\nPecan 3.4483\nPoplan 3.4483\nRed Alder 3.4483\nRed Elm 3.4483\nRed Oak 6.8966\nSassafras 3.4483\nSoft Maple 3.4483\nSycamore 3.4483\nWhite Oak 10.3448\nWillow 3.4483\nYellow Birch 3.4483",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10235 Simply Emirp\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10235 Simply Emirp\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10235 Simply Emirp\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10235 Simply Emirp\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10235 Simply Emirp\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10235 Simply Emirp\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10235 Simply Emirp\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10235 Simply Emirp\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10235 Simply Emirp?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10235 Simply Emirp?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10235 Simply Emirp in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10235 Simply Emirp.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10235 Simply Emirp.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10235 Simply Emirp with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10235 Simply Emirp.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10235 Simply Emirp, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10235 Simply Emirp」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10235 Simply Emirp」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10235 Simply Emirp」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10235 Simply Emirp」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10235 Simply Emirp」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10235 Simply Emirp」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10235 Simply Emirp」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10235 Simply Emirp」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10235 Simply Emirp 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10235 Simply Emirp 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10235 Simply Emirp？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10235 Simply Emirp 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10235 Simply Emirp 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10235 Simply Emirp 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10235 Simply Emirp 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10235 Simply Emirp 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint p[1000005];\n \nint main() {\n    p[1] = 1;\n    for (int i = 2; i < 1000005; i++){\n        if (p[i] == 0){\n            for (int j = i+i; j < 1000005; j+=i){\n                p[j] = 1;\n            }\n        }\n    }\n    int N, N1, N2;\n    while (cin >> N){\n        N1 = N;\n        N2 = 0;\n        while (N1){\n            N2 *= 10;\n            N2 += N1 % 10;\n            N1 /= 10;\n        }\n        if (p[N]) cout << N << \" is not prime.\\n\";\n        else if (N2 != N && p[N2] == 0) cout << N << \" is emirp.\\n\";\n        else cout << N << \" is prime.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10235 Simply Emirp",
    "Question Description": "The problem involves determining whether a given number N is a prime number, an emirp (a prime that remains prime when its digits are reversed), or not a prime at all. The solution requires checking the primality of N and its reversed form, then classifying N accordingly.",
    "Input Requirements": "The input consists of multiple lines, each containing an integer N (1 < N < 1,000,000).",
    "Output Requirements": "For each input number N, output one of the following:\n1. 'N is not prime.' if N is not a prime.\n2. 'N is prime.' if N is a prime but not an emirp.\n3. 'N is emirp.' if N is an emirp (both N and its reversed form are primes, and they are different).",
    "Sample Input": "17\n18\n19\n179\n199\n",
    "Sample Output": "17 is emirp.\n18 is not prime.\n19 is prime.\n179 is emirp.\n199 is emirp.\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10242 Fourth Point!!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10242 Fourth Point!!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10242 Fourth Point!!\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10242 Fourth Point!!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10242 Fourth Point!!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10242 Fourth Point!!\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10242 Fourth Point!!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10242 Fourth Point!!\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10242 Fourth Point!!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10242 Fourth Point!!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10242 Fourth Point!! in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10242 Fourth Point!!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10242 Fourth Point!!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10242 Fourth Point!! with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10242 Fourth Point!!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10242 Fourth Point!!, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10242 Fourth Point!!」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10242 Fourth Point!!」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10242 Fourth Point!!」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10242 Fourth Point!!」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10242 Fourth Point!!」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10242 Fourth Point!!」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10242 Fourth Point!!」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10242 Fourth Point!!」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10242 Fourth Point!! 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10242 Fourth Point!! 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10242 Fourth Point!!？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10242 Fourth Point!! 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10242 Fourth Point!! 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10242 Fourth Point!! 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10242 Fourth Point!! 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10242 Fourth Point!! 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n \nint main() {\n    double x[4], y[4];\n    double x1, y1, x2, y2, x3, y3;\n    while (cin >> x[0] >> y[0] >> x[1] >> y[1] >> x[2] >> y[2] >> x[3] >> y[3]){\n        if (x[1] == x[2] && y[1] == y[2]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[2] && y[0] == y[2]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[3]; y3 = y[3];\n        } else if (x[0] == x[3] && y[0] == y[3]){\n            x1 = x[1]; y1 = y[1];\n            x2 = x[0]; y2 = y[0];\n            x3 = x[2]; y3 = y[2];\n        } else if (x[1] == x[3] && y[1] == y[3]){\n            x1 = x[0]; y1 = y[0];\n            x2 = x[1]; y2 = y[1];\n            x3 = x[2]; y3 = y[2];\n        }\n        cout << fixed << setprecision(3)\n        << x3 + x1 - x2 << \" \" << y3 + y1 - y2 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10242 Fourth Point!!",
    "Question Description": "Given the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram, the task is to find the coordinates of the fourth point. The solution involves identifying the common point of the two sides and using vector addition to determine the missing point.",
    "Input Requirements": "Each line of input contains eight floating-point numbers representing the (x,y) coordinates of the endpoints of two adjacent sides of a parallelogram. The coordinates are in meters, accurate to the nearest millimeter, and range between -10000 and +10000. The input continues until the end of file.",
    "Output Requirements": "For each input line, output the (x,y) coordinates of the fourth point of the parallelogram, formatted to three decimal places and separated by a space.",
    "Sample Input": "0.000 0.000 0.000 1.000 0.000 1.000 1.000 1.000\n1.000 0.000 3.500 3.500 3.500 3.500 0.000 1.000\n1.866 0.000 3.127 3.543 3.127 3.543 1.412 3.145\n",
    "Sample Output": "1.000 0.000\n-2.500 -2.500\n0.151 -0.398\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10252 Common Permutation\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10252 Common Permutation\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10252 Common Permutation\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10252 Common Permutation\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10252 Common Permutation\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10252 Common Permutation\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10252 Common Permutation\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10252 Common Permutation\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10252 Common Permutation?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10252 Common Permutation?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10252 Common Permutation in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10252 Common Permutation.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10252 Common Permutation.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10252 Common Permutation with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10252 Common Permutation.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10252 Common Permutation, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10252 Common Permutation」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10252 Common Permutation」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10252 Common Permutation」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10252 Common Permutation」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10252 Common Permutation」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10252 Common Permutation」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10252 Common Permutation」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10252 Common Permutation」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10252 Common Permutation 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10252 Common Permutation 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10252 Common Permutation？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10252 Common Permutation 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10252 Common Permutation 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10252 Common Permutation 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10252 Common Permutation 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10252 Common Permutation 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nstring a, b;\nint cnta[26], cntb[26];\n \nint main() {\n    while (getline(cin, a) && getline(cin, b)){\n        fill(cnta, cnta+26, 0);\n        fill(cntb, cntb+26, 0);\n        for (char c : a) cnta[c-'a']++;\n        for (char c : b) cntb[c-'a']++;\n        string result;\n        for (int i = 0; i < 26; i++){\n            int min_count = min(cnta[i], cntb[i]);\n            result.append(min_count, 'a'+i);\n        }\n        cout << result << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10252 Common Permutation",
    "Question Description": "Given two strings of lowercase letters, the task is to find the longest string that can be formed by selecting characters common to both strings, where the frequency of each character in the result is the minimum of its frequencies in the two input strings. The result should be the lexicographically smallest possible permutation of such characters.",
    "Input Requirements": "The input consists of multiple pairs of lines. Each pair contains two strings (a and b) of lowercase letters, each up to 1000 characters long. The input continues until there are no more pairs.",
    "Output Requirements": "For each pair of strings, output a single line containing the longest common permutation string in alphabetical order. If multiple permutations exist, choose the lexicographically smallest one.",
    "Sample Input": "pretty\nwomen\nwalking\ndown\nthe\nstreet\n",
    "Sample Output": "e\nnw\ntet\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10268 498-bis\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10268 498-bis\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10268 498-bis\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10268 498-bis\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10268 498-bis\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10268 498-bis\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10268 498-bis\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10268 498-bis\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10268 498-bis?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10268 498-bis?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10268 498-bis in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10268 498-bis.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10268 498-bis.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10268 498-bis with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10268 498-bis.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10268 498-bis, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10268 498-bis」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10268 498-bis」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10268 498-bis」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10268 498-bis」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10268 498-bis」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10268 498-bis」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10268 498-bis」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10268 498-bis」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10268 498-bis 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10268 498-bis 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10268 498-bis？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10268 498-bis 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10268 498-bis 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10268 498-bis 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10268 498-bis 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10268 498-bis 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n \nstring s;\nint x;\nvector <int> v;\n \nint main() {\n    while (cin >> x){\n        getline(cin, s); // consume newline\n        getline(cin, s);\n        stringstream ss(s);\n        v.clear();\n        int num;\n        while (ss >> num){\n            v.push_back(num);\n        }\n        v.pop_back(); // remove constant term\n        reverse(v.begin(), v.end());\n        long long mul = 1;\n        int ans = 0;\n        for (int i = 0; i < v.size(); i++){\n            ans += v[i] * (i+1) * mul;\n            mul *= x;\n        }\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10268 498-bis",
    "Question Description": "The problem involves calculating the derivative of a polynomial at a given point x. The polynomial is provided as a list of coefficients, and the task is to compute the value of its derivative at the specified x using basic derivation rules in algebra.",
    "Input Requirements": "The input consists of multiple test cases. Each test case contains two lines: the first line is an integer x (the point at which to evaluate the derivative), and the second line is a list of integers representing the polynomial coefficients (a₀, a₁, ..., aₙ). The input ends with EOF.",
    "Output Requirements": "For each test case, output the value of the polynomial's derivative at the given point x. The output should be an integer.",
    "Sample Input": "7\n1 -1\n2\n1 1 1\n",
    "Sample Output": "1\n5\n",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10409 Die Game\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10409 Die Game\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10409 Die Game\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10409 Die Game\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10409 Die Game\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10409 Die Game\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10409 Die Game\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10409 Die Game\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10409 Die Game?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10409 Die Game?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10409 Die Game in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10409 Die Game.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10409 Die Game.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10409 Die Game with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10409 Die Game.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10409 Die Game, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10409 Die Game」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10409 Die Game」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10409 Die Game」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10409 Die Game」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10409 Die Game」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10409 Die Game」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10409 Die Game」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10409 Die Game」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10409 Die Game 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10409 Die Game 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10409 Die Game？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10409 Die Game 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10409 Die Game 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10409 Die Game 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10409 Die Game 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10409 Die Game 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main() {\n    int n;\n    string s;\n    while (cin >> n && n != 0) {\n        // Initialize die faces\n        int top = 1, north = 2, west = 3, east = 4, south = 5, bottom = 6;\n        \n        while (n--) {\n            cin >> s;\n            int temp;\n            if (s == \"north\") {\n                temp = top;\n                top = south;\n                south = bottom;\n                bottom = north;\n                north = temp;\n            } \n            else if (s == \"south\") {\n                temp = top;\n                top = north;\n                north = bottom;\n                bottom = south;\n                south = temp;\n            } \n            else if (s == \"east\") {\n                temp = top;\n                top = west;\n                west = bottom;\n                bottom = east;\n                east = temp;\n            } \n            else if (s == \"west\") {\n                temp = top;\n                top = east;\n                east = bottom;\n                bottom = west;\n                west = temp;\n            }\n        }\n        cout << top << endl;\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10409 Die Game",
    "Question Description": "The problem simulates rolling a die on a table according to given commands (north, east, south, west). The die starts with 1 on top, 2 on north, and 3 on west. The goal is to determine the number on the top face after executing all commands.",
    "Input Requirements": "The input consists of multiple test cases. Each test case starts with an integer N (number of commands), followed by N commands (north, east, south, west). The input ends when N is 0.",
    "Output Requirements": "For each test case, output the number on the top face of the die after executing all commands.",
    "Sample Input": "1\nnorth\n3\nnorth\neast\nsouth\n0",
    "Sample Output": "5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10415 Eb Alto Saxophone Player\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10415 Eb Alto Saxophone Player\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10415 Eb Alto Saxophone Player\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10415 Eb Alto Saxophone Player\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10415 Eb Alto Saxophone Player\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10415 Eb Alto Saxophone Player\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10415 Eb Alto Saxophone Player\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10415 Eb Alto Saxophone Player\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10415 Eb Alto Saxophone Player?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10415 Eb Alto Saxophone Player?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10415 Eb Alto Saxophone Player in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10415 Eb Alto Saxophone Player.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10415 Eb Alto Saxophone Player.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10415 Eb Alto Saxophone Player with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10415 Eb Alto Saxophone Player.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10415 Eb Alto Saxophone Player, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10415 Eb Alto Saxophone Player」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10415 Eb Alto Saxophone Player」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10415 Eb Alto Saxophone Player」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10415 Eb Alto Saxophone Player」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10415 Eb Alto Saxophone Player」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10415 Eb Alto Saxophone Player」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10415 Eb Alto Saxophone Player」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10415 Eb Alto Saxophone Player」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10415 Eb Alto Saxophone Player 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10415 Eb Alto Saxophone Player 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10415 Eb Alto Saxophone Player？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10415 Eb Alto Saxophone Player 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10415 Eb Alto Saxophone Player 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10415 Eb Alto Saxophone Player 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10415 Eb Alto Saxophone Player 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10415 Eb Alto Saxophone Player 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n    // Initialize finger mappings for each note\n    map<char, vector<int>> fingerMap = {\n        {'c', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1}},\n        {'d', {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'e', {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'f', {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'g', {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'a', {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'b', {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0}},\n        {'C', {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'D', {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0}},\n        {'E', {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0}},\n        {'F', {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0}},\n        {'G', {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0}},\n        {'A', {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}},\n        {'B', {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0}}\n    };\n\n    int t;\n    string song;\n    cin >> t;\n    cin.ignore(); // Clear the newline after t\n    \n    while (t--) {\n        getline(cin, song);\n        int fingerPresses[11] = {0}; // Index 1-10 for fingers 1-10\n        int currentFingers[11] = {0}; // Track currently pressed fingers\n        \n        for (char note : song) {\n            for (int finger = 1; finger <= 10; finger++) {\n                if (fingerMap[note][finger]) {\n                    if (!currentFingers[finger]) {\n                        fingerPresses[finger]++;\n                        currentFingers[finger] = 1;\n                    }\n                } else {\n                    currentFingers[finger] = 0;\n                }\n            }\n        }\n        \n        // Output finger presses for fingers 1-10\n        for (int i = 1; i <= 10; i++) {\n            cout << fingerPresses[i] << (i < 10 ? \" \" : \"\\n\");\n        }\n    }\n    \n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10415 Eb Alto Saxophone Player",
    "Question Description": "The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the current note but wasn't pressed for the previous note.",
    "Input Requirements": "The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes.",
    "Output Requirements": "For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10.",
    "Sample Input": "3\ncdefgab\nBAGFEDC\nCbCaDCDcCbCCbCbabcCCbCbabaee",
    "Sample Output": "0 1 1 1 0 0 1 1 1 1\n1 1 1 1 0 0 1 1 1 0\n1 8 10 2 0 0 2 2 1 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10420 List of Conquests\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10420 List of Conquests\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10420 List of Conquests\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10420 List of Conquests\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10420 List of Conquests\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10420 List of Conquests\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10420 List of Conquests\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10420 List of Conquests\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10420 List of Conquests?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10420 List of Conquests?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10420 List of Conquests in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10420 List of Conquests.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10420 List of Conquests.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10420 List of Conquests with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10420 List of Conquests.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10420 List of Conquests, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10420 List of Conquests」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10420 List of Conquests」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10420 List of Conquests」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10420 List of Conquests」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10420 List of Conquests」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10420 List of Conquests」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10420 List of Conquests」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10420 List of Conquests」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10420 List of Conquests 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10420 List of Conquests 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10420 List of Conquests？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10420 List of Conquests 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10420 List of Conquests 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10420 List of Conquests 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10420 List of Conquests 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10420 List of Conquests 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int n;\n    cin >> n;\n    map <string, int> mp;\n    string s;\n    getline(cin, s);\n    while (n--) {\n        getline(cin, s);\n        stringstream ss(s);\n        ss >> s;\n        mp[s]++;\n    }\n    for (auto i: mp) {\n        cout << i.first << \" \" << i.second << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10420 List of Conquests",
    "Question Description": "In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:\n\n\"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but in Spain already a thousand and three! Among them are country girls, waiting-maids, city beauties; there are countesses, baronesses, marchionesses, princesses: women of every rank, of every size, of every age.\" (Madamina, il catalogo questo)\n\nAs Leporello records all the \"beauties\" Don Giovanni \"loved\" in chronological order, it is very troublesome for him to present his master's conquest to others because he needs to count the number of \"beauties\" by their nationality each time. You are to help Leporello to count.",
    "Input Requirements": "The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all countries consist of only one word.",
    "Output Requirements": "The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space.",
    "Sample Input": "3\nSpain Donna Elvira\nEngland Jane Doe\nSpain Donna Anna",
    "Sample Output": "England 1\nSpain 2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10642 Can You Solve It?\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10642 Can You Solve It?\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10642 Can You Solve It?\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10642 Can You Solve It?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10642 Can You Solve It?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10642 Can You Solve It?\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10642 Can You Solve It?\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10642 Can You Solve It?\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10642 Can You Solve It??",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10642 Can You Solve It??",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10642 Can You Solve It? in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10642 Can You Solve It?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10642 Can You Solve It?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10642 Can You Solve It? with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10642 Can You Solve It?.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10642 Can You Solve It?, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10642 Can You Solve It?」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10642 Can You Solve It?」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10642 Can You Solve It?」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10642 Can You Solve It?」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10642 Can You Solve It?」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10642 Can You Solve It?」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10642 Can You Solve It?」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10642 Can You Solve It?」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10642 Can You Solve It? 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10642 Can You Solve It? 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10642 Can You Solve It?？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10642 Can You Solve It? 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10642 Can You Solve It? 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10642 Can You Solve It? 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10642 Can You Solve It? 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10642 Can You Solve It? 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    int T;\n    long long x, y, n, step1, step2;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cout << \"Case \" << Case << \": \";\n        cin >> x >> y;\n        if (x == 0 && y == 0) step1 = 0;\n        else {\n            n = x + y - 1;\n            step1 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cin >> x >> y;\n        n = x + y - 1;\n        if (x == 0 && y == 0) step2 = 0;\n        else {\n            n = x + y - 1;\n            step2 = (n * n + 3 * n) / 2 + (x + 1);\n        }\n        cout << step2 - step1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10642 Can You Solve It?",
    "Question Description": "First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,\n\ntotal_number_of_step(s) needed=number_of intermediate_circles you_pass+1\n\nFor example, to go from (0,3) to (3,0) you have to pass two intermediate circles (1,2) and (2,1). So, in this case, total number of steps needed is 2+1=3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.",
    "Input Requirements": "The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form (x,y).",
    "Output Requirements": "For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.",
    "Sample Input": "3\n0 0 0 1\n0 0 1 0\n0 0 0 2",
    "Sample Output": "Case 1: 1\nCase 2: 2\nCase 3: 3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10783 Odd Sum\"?",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10783 Odd Sum\"?",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10783 Odd Sum\" in C++?",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10783 Odd Sum\".",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10783 Odd Sum\".",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10783 Odd Sum\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10783 Odd Sum\".",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10783 Odd Sum\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10783 Odd Sum?",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10783 Odd Sum?",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10783 Odd Sum in C++?",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10783 Odd Sum.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10783 Odd Sum.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10783 Odd Sum with explanations.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10783 Odd Sum.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10783 Odd Sum, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10783 Odd Sum」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10783 Odd Sum」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10783 Odd Sum」？ ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10783 Odd Sum」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10783 Odd Sum」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10783 Odd Sum」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10783 Odd Sum」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10783 Odd Sum」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10783 Odd Sum 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10783 Odd Sum 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10783 Odd Sum？ ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10783 Odd Sum 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10783 Odd Sum 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10783 Odd Sum 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10783 Odd Sum 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10783 Odd Sum 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include<iostream>\nusing namespace std;\n \nint main(){\n    int T;\n    cin >> T;\n    for (int i = 1; i <= T; i++) {\n        int a, b;\n        cin >> a >> b;\n        if (a % 2 == 0) {\n            a += 1;\n        }\n        if (b % 2 == 0) {\n            b -= 1;\n        }\n        int num=(b-a)/2+1;\n        int total;\n        total=(a+b)/2*num;\n        cout << \"Case \" << i << \": \";\n        cout << (a + b) / 2 * ((b - a) / 2 + 1) << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10783 Odd Sum",
    "Question Description": "Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24.",
    "Input Requirements": "There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines.",
    "Output Requirements": "For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b].",
    "Sample Input": "2\n1\n5\n3\n5",
    "Sample Output": "Case 1: 9\nCase 2: 8",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10812 Beat the Spread!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10812 Beat the Spread!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10812 Beat the Spread!\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10812 Beat the Spread!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10812 Beat the Spread!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10812 Beat the Spread!\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10812 Beat the Spread!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10812 Beat the Spread!\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10812 Beat the Spread!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10812 Beat the Spread!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10812 Beat the Spread! in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10812 Beat the Spread!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10812 Beat the Spread!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10812 Beat the Spread! with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10812 Beat the Spread!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10812 Beat the Spread!, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10812 Beat the Spread!」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10812 Beat the Spread!」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10812 Beat the Spread!」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10812 Beat the Spread!」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10812 Beat the Spread!」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10812 Beat the Spread!」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10812 Beat the Spread!」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10812 Beat the Spread!」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10812 Beat the Spread! 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10812 Beat the Spread! 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10812 Beat the Spread!？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10812 Beat the Spread! 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10812 Beat the Spread! 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10812 Beat the Spread! 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10812 Beat the Spread! 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10812 Beat the Spread! 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, s, d;\n    cin >> T;\n    while (T--){\n        cin >> s >> d;\n        if ((s + d) % 2 || s < d) cout << \"impossible\\n\";\n        else {\n            cout << (s+d)/2 << \" \" << (s-d)/2 << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10812 Beat the Spread!",
    "Question Description": "Superbowl Sunday is nearly here. In order to pass the time waiting for the half-time commercials and wardrobe malfunctions, the local hackers have organized a betting pool on the game. Members place their bets on the sum of the two final scores, or on the absolute difference between the two scores.\n\nGiven the winning numbers for each type of bet, can you deduce the final scores?",
    "Input Requirements": "The first line of input contains n, the number of test cases. n lines follow, each representing a test case. Each test case gives s and d, non-negative integers representing the sum and (absolute) difference between the two final scores.",
    "Output Requirements": "For each test case, output a line giving the two final scores, largest first. If there are no such scores, output a line containing \"impossible\". Recall that football scores are always non-negative integers.",
    "Sample Input": "2\n40 20\n20 40",
    "Sample Output": "30 10\nimpossible",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10908 Largest Square\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10908 Largest Square\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10908 Largest Square\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10908 Largest Square\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10908 Largest Square\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10908 Largest Square\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10908 Largest Square\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10908 Largest Square\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10908 Largest Square?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10908 Largest Square?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10908 Largest Square in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10908 Largest Square.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10908 Largest Square.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10908 Largest Square with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10908 Largest Square.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10908 Largest Square, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10908 Largest Square」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10908 Largest Square」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10908 Largest Square」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10908 Largest Square」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10908 Largest Square」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10908 Largest Square」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10908 Largest Square」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10908 Largest Square」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10908 Largest Square 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10908 Largest Square 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10908 Largest Square？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10908 Largest Square 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10908 Largest Square 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10908 Largest Square 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10908 Largest Square 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10908 Largest Square 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n \nint t, m, n, q, a[105][105], mx[105][105], x, y, ans;\nchar c;\n \nint main() {\n    memset(a, -1, sizeof(a));\n    cin >> t;\n    while (t--){\n        cin >> m >> n >> q;\n        for (int i = 0; i < m; i++){\n            for (int j = 0; j < n; j++){\n                cin >> c;\n                a[i][j] = (int)c;\n                if (i == 0 || j == 0) mx[i][j] = 1;\n                else if (a[i][j] == a[i-1][j] && a[i][j] == a[i-1][j-1] && a[i][j] == a[i][j-1]){\n                    mx[i][j] = min({mx[i-1][j], mx[i-1][j-1], mx[i][j-1]})+1 ;\n                }\n                else mx[i][j] = 1;\n            }\n        }\n        cout << m << \" \" << n << \" \" << q << \"\\n\";\n        while (q--){\n            cin >> x >> y;\n            ans = 1;\n            for (int i = 1; i <= 100; i++){\n                if (x+i > m || y+i > n) break;\n                if (mx[x+i][y+i] >= ans+2) ans += 2;\n                else break;\n            }\n            cout << ans << \"\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10908 Largest Square",
    "Question Description": "Given a rectangular grid of characters you have to find out the length of a side of the largest square such that all the characters of the square are same and the center [intersecting point of the two diagonals] of the square is at location (r,c). The height and width of the grid is M and N respectively. Upper left corner and lower right corner of the grid will be denoted by (0,0) and (M-1,N-1) respectively. Consider the grid of characters given below. Given the location (1,2) the length of a side of the largest square is 3.\n\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa",
    "Input Requirements": "The input starts with a line containing a single integer T (< 21). This is followed by T test cases. The first line of each of them will contain three integers M, N and Q (< 21) separated by a space where M, N denotes the dimension of the grid. Next follows M lines each containing N characters. Finally, there will be Q lines each containing two integers r and c. The value of M and N will be at most 100.",
    "Output Requirements": "For each test case in the input produce Q + 1 lines of output. In the first line print the value of M, N and Q in that order separated by single space. In the next Q lines, output the length of a side of the largest square in the corresponding grid for each (r,c) pair in the input.",
    "Sample Input": "1\n7 10 4\nabbbaaaaaa\nabbbaaaaaa\nabbbaaaaaa\naaaaaaaaaa\naaaaaaaaaa\naaccaaaaaa\naaccaaaaaa\n1 2\n2 4\n4 6\n5 2",
    "Sample Output": "7 10 4\n3\n1\n5\n1",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10922 2 the 9s\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10922 2 the 9s\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10922 2 the 9s\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10922 2 the 9s\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10922 2 the 9s\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10922 2 the 9s\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10922 2 the 9s\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10922 2 the 9s\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10922 2 the 9s?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10922 2 the 9s?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10922 2 the 9s in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10922 2 the 9s.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10922 2 the 9s.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10922 2 the 9s with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10922 2 the 9s.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10922 2 the 9s, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10922 2 the 9s」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10922 2 the 9s」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10922 2 the 9s」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10922 2 the 9s」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10922 2 the 9s」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10922 2 the 9s」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10922 2 the 9s」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10922 2 the 9s」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10922 2 the 9s 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10922 2 the 9s 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10922 2 the 9s？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10922 2 the 9s 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10922 2 the 9s 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10922 2 the 9s 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10922 2 the 9s 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10922 2 the 9s 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint func(string s, int count){\n    int temp = 0, total = 0;\n    for (int i = 0; i < s.length(); i++){\n        temp = s[i] - '0';\n        total += temp;\n    }\n    count++;\n    if (total == 9){\n        return count;\n    }else if(total < 9){\n        return 0;\n    }else{\n        return func(to_string(total), count);\n    }\n}\nint main(){\n    int ans;\n    string s;\n    while (cin >> s){\n        if (s == \"0\") break;\n        ans = func(s, 0);\n        if (ans == 0){\n            cout << s << \" is not a multiple of 9.\\n\";\n        }else{\n            cout << s << \" is a multiple of 9 and has 9-degree \" << ans << \".\\n\";\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10922 2 the 9s",
    "Question Description": "A well-known trick to know if an integer N is a multiple of nine is to compute the sum S of its digits. If S is a multiple of nine, then so is N. This is a recursive test, and the depth of the recursion needed to obtain the answer on N is called the 9-degree of N.\n\nYour job is, given a positive number N, determine if it is a multiple of nine and, if it is, its 9-degree.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number 0 is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of nine, and in case it is, the value of its nine-degree. See the sample output for an example of the expected formatting of the output.",
    "Sample Input": "9999999999999999999999\n9\n999999999999999999999999999999998\n0",
    "Sample Output": "9999999999999999999999 is a multiple of 9 and has 9-degree 3.\n9 is a multiple of 9 and has 9-degree 1.\n999999999999999999999999999998 is not a multiple of 9.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10929 You can say 11\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10929 You can say 11\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10929 You can say 11\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10929 You can say 11\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10929 You can say 11\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10929 You can say 11\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10929 You can say 11\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10929 You can say 11\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10929 You can say 11?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10929 You can say 11?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10929 You can say 11 in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10929 You can say 11.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10929 You can say 11.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10929 You can say 11 with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10929 You can say 11.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10929 You can say 11, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10929 You can say 11」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10929 You can say 11」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10929 You can say 11」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10929 You can say 11」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10929 You can say 11」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10929 You can say 11」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10929 You can say 11」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10929 You can say 11」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10929 You can say 11 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10929 You can say 11 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10929 You can say 11？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10929 You can say 11 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10929 You can say 11 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10929 You can say 11 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10929 You can say 11 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10929 You can say 11 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint main() {\n    string s;\n    while (cin >> s) {\n        if (s == \"0\") break;\n        int odd = 0, even = 0;\n        for (int i = 0; i < s.size(); i++) {\n            if (i % 2) {\n                odd += s[i] - '0';\n            } else {\n                even += s[i] - '0';\n            }\n        }\n        if ((odd - even) % 11 == 0) {\n            cout << s << \" is a multiple of 11.\\n\";\n        } else {\n            cout << s << \" is not a multiple of 11.\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10929 You can say 11",
    "Question Description": "Your job is, given a positive number N, determine if it is a multiple of eleven.",
    "Input Requirements": "The input is a file such that each line contains a positive number. A line containing the number '0' is the end of the input. The given numbers can contain up to 1000 digits.",
    "Output Requirements": "The output of the program shall indicate, for each input number, if it is a multiple of eleven or not.",
    "Sample Input": "112233\n30800\n2937\n323455693\n5038297\n112234\n0",
    "Sample Output": "112233 is a multiple of 11.\n30800 is a multiple of 11.\n2937 is a multiple of 11.\n323455693 is a multiple of 11.\n5038297 is a multiple of 11.\n112234 is not a multiple of 11.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"10931 Parity\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"10931 Parity\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"10931 Parity\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"10931 Parity\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"10931 Parity\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"10931 Parity\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"10931 Parity\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"10931 Parity\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 10931 Parity?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 10931 Parity?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 10931 Parity in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 10931 Parity.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 10931 Parity.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 10931 Parity with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 10931 Parity.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 10931 Parity, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10931 Parity」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「10931 Parity」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「10931 Parity」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「10931 Parity」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「10931 Parity」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「10931 Parity」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「10931 Parity」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「10931 Parity」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10931 Parity 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "10931 Parity 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 10931 Parity？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 10931 Parity 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 10931 Parity 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 10931 Parity 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 10931 Parity 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 10931 Parity 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint main() {\n    int I, n;\n    while (cin >> I) {\n        if (I == 0) break;\n        string B = \"\";\n        n = I;\n        int cnt = 0;\n        while (n){\n            cnt += (n & 1);\n            B += '0' + (n & 1);\n            n >>= 1;\n        }\n        reverse(B.begin(), B.end());\n        cout << \"The parity of \" << B << \" is \" << cnt << \" (mod 2).\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "10931 Parity",
    "Question Description": "We define the parity of an integer n as the sum of the bits in binary representation computed modulo two. As an example, the number 21 = 10101_2 has three 1s in its binary representation so it has parity 3(mod2), or 1.\n\nIn this problem you have to calculate the parity of an integer 1 ≤ I ≤ 2147483647.",
    "Input Requirements": "Each line of the input has an integer I and the end of the input is indicated by a line where I = 0 that should not be processed.",
    "Output Requirements": "For each integer I in the input you should print a line 'The parity of B is P (mod 2).', where B is the binary representation of I.",
    "Sample Input": "1\n2\n10\n21\n0",
    "Sample Output": "The parity of 1 is 1 (mod 2).\nThe parity of 10 is 1 (mod 2).\nThe parity of 1010 is 2 (mod 2).\nThe parity of 10101 is 3 (mod 2).",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11005 Cheapest Base\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11005 Cheapest Base\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11005 Cheapest Base\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11005 Cheapest Base\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11005 Cheapest Base\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11005 Cheapest Base\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11005 Cheapest Base\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11005 Cheapest Base\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11005 Cheapest Base?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11005 Cheapest Base?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11005 Cheapest Base in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11005 Cheapest Base.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11005 Cheapest Base.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11005 Cheapest Base with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11005 Cheapest Base.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11005 Cheapest Base, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11005 Cheapest Base」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11005 Cheapest Base」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11005 Cheapest Base」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11005 Cheapest Base」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11005 Cheapest Base」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11005 Cheapest Base」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11005 Cheapest Base」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11005 Cheapest Base」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11005 Cheapest Base 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11005 Cheapest Base 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11005 Cheapest Base？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11005 Cheapest Base 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11005 Cheapest Base 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11005 Cheapest Base 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11005 Cheapest Base 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11005 Cheapest Base 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <map>\nusing namespace std;\n \nint main() {\n    int T, cost, Q, x;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        if (Case > 1) cout << \"\\n\";\n        map <int, int> mp;\n        for (int i = 0; i < 36; i++){\n            cin >> cost;\n            mp[i] = cost;\n        }\n        cout << \"Case \" << Case << \":\\n\";\n        cin >> Q;\n        while (Q--){\n            cin >> x;\n            cout << \"Cheapest base(s) for number \" << x << \":\";\n            int mn =  0x7FFFFFFF;\n            map <int,int> ans;\n            for (int i = 2; i <= 36; i++){\n                int n = x;\n                cost = 0;\n                while (n){\n                    cost += mp[n % i];\n                    n /= i;\n                }\n                ans[i] = cost;\n                mn = min(mn, cost);\n            }\n            for (int i = 2; i <= 36; i++){\n                if (ans[i] == mn) cout << \" \" << i;\n            }\n            cout << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11005 Cheapest Base",
    "Question Description": "When printing text on paper we need ink. But not every character needs the same amount of ink to print: letters such as 'W', 'M' and '8' are more expensive than thinner letters as 'i', 'c' and '1'. In this problem we will evaluate the cost of printing numbers in several bases.\n\nAs you know, numbers can be expressed in several different bases. Well known bases are binary (base 2; digits 0 and 1), decimal (base 10; digits 0 to 9) and hexadecimal (base 16; digits 0 to 9 and letters A to F). For the general base n we will use the first n characters of the string \"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ\", which means the highest base in this problem is 36. The lowest base is of course 2.\n\nEvery character from this string has an associated cost, represented by an integer value between 1 and 128. The cost to print a number in a certain base is the sum of the costs of all characters needed to represent that number. For the numbers given in the input, you will have to calculate the cheapest base(s) to represent this number in. Numbers in any base are printed without leading zeros.",
    "Input Requirements": "The input has less than 25 test cases. The first line of input file denotes this number of test cases. The description of every test case is given below:\n\nThe first 4 lines of every case contain 9 integers each: the costs of the 36 characters in the order given above. Then follows the number of queries on a line by itself. Every query appears on a line by itself and is formed by a number between 0 and 2000000000 in decimal format.",
    "Output Requirements": "For every case in the input, print one line 'Case X:', without the quotes, where X is the case number starting from 1.\n\nFor every query within a case print one line 'Cheapest base(s) for number Y:' followed by the cheapest base(s) in increasing order, separated by one space. Y is the query in decimal format. Print a blank line between cases.",
    "Sample Input": "2\n10 8 12 13 15 13 13 16 9\n11 18 24 21 23 23 23 13 15\n17 33 21 23 27 26 27 19 4\n22 18 30 30 24 16 26 21 21\n5\n98329921\n12345\n800348\n14\n873645\n1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1\n4\n0\n1\n10\n100",
    "Sample Output": "Case 1:\nCheapest base(s) for number 98329921: 24\nCheapest base(s) for number 12345: 13 31\nCheapest base(s) for number 800348: 31\nCheapest base(s) for number 14: 13\nCheapest base(s) for number 873645: 22\n\nCase 2:\nCheapest base(s) for number 0: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 1: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 10: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36\nCheapest base(s) for number 100: 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11063 B2-Sequence\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11063 B2-Sequence\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11063 B2-Sequence\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11063 B2-Sequence\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11063 B2-Sequence\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11063 B2-Sequence\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11063 B2-Sequence\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11063 B2-Sequence\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11063 B2-Sequence?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11063 B2-Sequence?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11063 B2-Sequence in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11063 B2-Sequence.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11063 B2-Sequence.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11063 B2-Sequence with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11063 B2-Sequence.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11063 B2-Sequence, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11063 B2-Sequence」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11063 B2-Sequence」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11063 B2-Sequence」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11063 B2-Sequence」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11063 B2-Sequence」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11063 B2-Sequence」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11063 B2-Sequence」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11063 B2-Sequence」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11063 B2-Sequence 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11063 B2-Sequence 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11063 B2-Sequence？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11063 B2-Sequence 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11063 B2-Sequence 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11063 B2-Sequence 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11063 B2-Sequence 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11063 B2-Sequence 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n#define maxn 20005\n \nint main() {\n    int n, Case = 1;\n    while (cin >> n) {\n        int b[n], sum[maxn];\n        for (int i = 0; i < n; i++) {\n            cin >> b[i];\n        }\n        for (int i = 0; i < maxn; i++) {\n            sum[i] = 0;\n        }\n        bool flag = true;\n        for (int i = 0; i < n; i++) {\n            for (int j = i; j < n; j++) {\n                int x = b[i] + b[j];\n                if (sum[x]) {\n                    flag = false;\n                    break;\n                } else {\n                    sum[x] = 1;\n                }\n            }\n            if (!flag) break;\n        }\n        if (flag) cout << \"Case #\" << Case++ << \": It is a B2-Sequence.\\n\\n\";\n        else cout << \"Case #\" << Case++ << \": It is not a B2-Sequence.\\n\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11063 B2-Sequence",
    "Question Description": "A B2-Sequence is a sequence of positive integers 1 ≤ b₁ < b₂ < b₃... such that all pairwise sums bᵢ + bⱼ, where i ≤ j, are different.\n\nYour task is to determine if a given sequence is a B2-Sequence or not.",
    "Input Requirements": "Each test case starts with 2 ≤ N ≤ 100, the number of elements in a sequence. Next line will have N integers, representing the value of each element in the sequence. Each element bᵢ is an integer such that bᵢ ≤ 10000. There is a blank line after each test case. The input is terminated by end of file (EOF).",
    "Output Requirements": "For each test case you must print the number of the test case, starting from 1, and a message indicating if the corresponding sequence it is a B2-Sequence or not. See the sample output below. After each test case you must print a blank line.",
    "Sample Input": "4\n1 2 4 8\n\n4\n3 7 10 14",
    "Sample Output": "Case #1: It is a B2-Sequence.\n\nCase #2: It is not a B2-Sequence.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11150 Cola\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11150 Cola\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11150 Cola\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11150 Cola\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11150 Cola\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11150 Cola\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11150 Cola\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11150 Cola\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11150 Cola?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11150 Cola?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11150 Cola in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11150 Cola.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11150 Cola.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11150 Cola with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11150 Cola.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11150 Cola, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11150 Cola」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11150 Cola」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11150 Cola」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11150 Cola」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11150 Cola」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11150 Cola」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11150 Cola」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11150 Cola」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11150 Cola 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11150 Cola 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11150 Cola？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11150 Cola 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11150 Cola 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11150 Cola 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11150 Cola 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11150 Cola 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int N;\n    while (cin >> N){\n        int ans = N;\n        while (N >= 3){\n            ans += N / 3;\n            N = N / 3 + N % 3;\n        }\n        ans += (N == 2);\n        cout << ans << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11150 Cola",
    "Question Description": "You see the following special offer by the convenience store:\n\n\"A bottle of Choco Cola for every 3 empty bottles returned\"\n\nNow you decide to buy some (say N) bottles of cola from the store. You would like to know how you can get the most cola from them.\n\nThe figure below shows the case where N = 8. Method 1 is the standard way: after finishing your 8 bottles of cola, you have 8 empty bottles. Take 6 of them and you get 2 new bottles of cola. Now after drinking them you have 4 empty bottles, so you take 3 of them to get yet another new cola. Finally, you have only 2 bottles in hand, so you cannot get new cola any more. Hence, you have enjoyed 8 + 2 + 1 = 11 bottles of cola.\n\nYou can actually do better! In Method 2, you first borrow an empty bottle from your friend (?! Or the storekeeper??), then you can enjoy 8 + 3 + 1 = 12 bottles of cola! Of course, you will have to return your remaining empty bottle back to your friend.",
    "Input Requirements": "Input consists of several lines, each containing an integer N (1 ≤ N ≤ 200).",
    "Output Requirements": "For each case, your program should output the maximum number of bottles of cola you can enjoy. You may borrow empty bottles from others, but if you do that, make sure that you have enough bottles afterwards to return to them.",
    "Sample Input": "8",
    "Sample Output": "12",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11321 Sort! Sort!! And Sort!!!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11321 Sort! Sort!! And Sort!!!\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11321 Sort! Sort!! And Sort!!!\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11321 Sort! Sort!! And Sort!!!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11321 Sort! Sort!! And Sort!!!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11321 Sort! Sort!! And Sort!!!\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11321 Sort! Sort!! And Sort!!!\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11321 Sort! Sort!! And Sort!!!\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11321 Sort! Sort!! And Sort!!!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11321 Sort! Sort!! And Sort!!!?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11321 Sort! Sort!! And Sort!!! in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11321 Sort! Sort!! And Sort!!!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11321 Sort! Sort!! And Sort!!!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11321 Sort! Sort!! And Sort!!! with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11321 Sort! Sort!! And Sort!!!.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11321 Sort! Sort!! And Sort!!!, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11321 Sort! Sort!! And Sort!!!」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11321 Sort! Sort!! And Sort!!!」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11321 Sort! Sort!! And Sort!!!」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11321 Sort! Sort!! And Sort!!!」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11321 Sort! Sort!! And Sort!!!」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11321 Sort! Sort!! And Sort!!!」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11321 Sort! Sort!! And Sort!!!」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11321 Sort! Sort!! And Sort!!!」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11321 Sort! Sort!! And Sort!!! 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11321 Sort! Sort!! And Sort!!! 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11321 Sort! Sort!! And Sort!!!？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11321 Sort! Sort!! And Sort!!! 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11321 Sort! Sort!! And Sort!!! 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11321 Sort! Sort!! And Sort!!! 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11321 Sort! Sort!! And Sort!!! 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11321 Sort! Sort!! And Sort!!! 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n    if ((x % M) != (y % M)){\n        return (x % M) < (y % M);\n    } else {\n        if ((x % 2) * (y % 2)){\n            return x > y;\n        } else if ((x % 2 == 0) && (y % 2 == 0)){\n            return x < y;\n        } else {\n            return (x % 2);\n        }\n    }\n}\n         \nint main() {\n    while (cin >> N >> M){\n        if (N == 0 && M == 0){\n            cout << \"0 0\\n\";\n            break;\n        }\n        cout << N << \" \" << M << \"\\n\";\n        int a[N];\n        for (int i = 0; i < N; i++){\n            cin >> a[i];\n        }\n        sort(a, a+N, cmp);\n        for (int i = 0; i < N; i++){\n            cout << a[i] << '\\n';\n        }\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11321 Sort! Sort!! And Sort!!!",
    "Question Description": "Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the even number. If there is a tie between two odd numbers (that is their modulo M value is the same) then the larger odd number will precede the smaller odd number and if there is a tie between two even numbers (that is their modulo M value is the same) then the smaller even number will precede the larger even number.\n\nFor remainder value of negative numbers follow the rule of C programming language: A negative number can never have modulus greater than zero. E.g. -100 MOD 3 = -1, -100 MOD 4 = 0, etc.",
    "Input Requirements": "The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two zeroes.",
    "Output Requirements": "For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also.",
    "Sample Input": "15 3\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n0 0",
    "Sample Output": "15 3\n15\n9\n3\n6\n12\n13\n7\n1\n4\n10\n11\n5\n2\n8\n14\n0 0",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11332 Summing Digits\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11332 Summing Digits\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11332 Summing Digits\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11332 Summing Digits\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11332 Summing Digits\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11332 Summing Digits\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11332 Summing Digits\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11332 Summing Digits\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11332 Summing Digits?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11332 Summing Digits?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11332 Summing Digits in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11332 Summing Digits.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11332 Summing Digits.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11332 Summing Digits with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11332 Summing Digits.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11332 Summing Digits, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11332 Summing Digits」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11332 Summing Digits」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11332 Summing Digits」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11332 Summing Digits」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11332 Summing Digits」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11332 Summing Digits」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11332 Summing Digits」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11332 Summing Digits」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11332 Summing Digits 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11332 Summing Digits 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11332 Summing Digits？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11332 Summing Digits 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11332 Summing Digits 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11332 Summing Digits 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11332 Summing Digits 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11332 Summing Digits 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n  \nint solve(int x) {\n    int ret = 0;\n    while (x) {\n        ret += x % 10;\n        x /= 10;\n    }\n    if (ret < 10) return ret;\n    else return solve(ret);\n}\n  \nint main() {\n    int n;\n    while (cin >> n && n) {\n        cout << solve(n) << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11332 Summing Digits",
    "Question Description": "For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).\n\nFor example, consider n = 1234567892. Then:\n\nf(n) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 2 = 47\n\nf(f(n)) = 4 + 7 = 11\n\nf(f(f(n))) = 1 + 1 = 2\n\nTherefore, g(1234567892) = 2.",
    "Input Requirements": "Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed.",
    "Output Requirements": "For each such integer, you are to output a single line containing g(n).",
    "Sample Input": "2\n11\n47\n1234567892\n0",
    "Sample Output": "2\n2\n2\n2",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11349 Symmetric Matrix\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11349 Symmetric Matrix\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11349 Symmetric Matrix\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11349 Symmetric Matrix\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11349 Symmetric Matrix\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11349 Symmetric Matrix\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11349 Symmetric Matrix\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11349 Symmetric Matrix\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11349 Symmetric Matrix?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11349 Symmetric Matrix?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11349 Symmetric Matrix in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11349 Symmetric Matrix.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11349 Symmetric Matrix.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11349 Symmetric Matrix with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11349 Symmetric Matrix.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11349 Symmetric Matrix, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11349 Symmetric Matrix」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11349 Symmetric Matrix」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11349 Symmetric Matrix」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11349 Symmetric Matrix」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11349 Symmetric Matrix」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11349 Symmetric Matrix」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11349 Symmetric Matrix」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11349 Symmetric Matrix」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11349 Symmetric Matrix 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11349 Symmetric Matrix 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11349 Symmetric Matrix？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11349 Symmetric Matrix 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11349 Symmetric Matrix 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11349 Symmetric Matrix 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11349 Symmetric Matrix 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11349 Symmetric Matrix 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\n \nint main() {\n    int T, n;\n    char ch;\n    cin >> T;\n    for (int Case = 1; Case <= T; Case++){\n        cin >> ch >> ch >> n;\n        long long a[n][n];\n        bool flag = true;\n        for (int i = 0; i < n; i++){\n            for (int j = 0; j < n; j++){\n                cin >> a[i][j];\n                if (a[i][j] < 0) flag = false;\n            }\n        }\n        cout << \"Test #\" << Case << \": \";\n        if (!flag){\n            cout << \"Non-symmetric.\\n\";\n            continue;\n        }\n        \n        for (int i = 0; i <= n/2; i++){\n            for (int j = 0; j < n-i; j++){\n                if (a[i][j] != a[n-1-i][n-1-j]){\n                    flag = false;\n                    break;\n                }\n            }\n        }\n        if (flag) cout << \"Symmetric.\\n\";\n        else cout << \"Non-symmetric.\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11349 Symmetric Matrix",
    "Question Description": "You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.\n\nDefinition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric. For example:\n\nM = [[5,1,3],[2,0,2],[3,1,5]] is symmetric\nM = [[5,1,3],[2,0,2],[0,1,5]] is not symmetric, because 3 ≠ 0\n\nAll you have to do is to find whether the matrix is symmetric or not. Elements of a matrix given in the input are -2³² ≤ Mij ≤ 2³² and 0 < n ≤ 100.",
    "Input Requirements": "First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th number in row i is the element Mij of matrix you have to process.",
    "Output Requirements": "For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case.",
    "Sample Input": "2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5",
    "Sample Output": "Test #1: Symmetric. Test #2: Non-symmetric.",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11417 GCD\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11417 GCD\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11417 GCD\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11417 GCD\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11417 GCD\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11417 GCD\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11417 GCD\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11417 GCD\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11417 GCD?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11417 GCD?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11417 GCD in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11417 GCD.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11417 GCD.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11417 GCD with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11417 GCD.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11417 GCD, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11417 GCD」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11417 GCD」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11417 GCD」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11417 GCD」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11417 GCD」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11417 GCD」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11417 GCD」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11417 GCD」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11417 GCD 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11417 GCD 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11417 GCD？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11417 GCD 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11417 GCD 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11417 GCD 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11417 GCD 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11417 GCD 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n  \nint GCD(int x, int y) {\n    while ((x %= y) && (y %= x));\n    return x + y;\n}\n  \nint main() {\n    int N, G;\n    while (cin >> N && N) {\n        G = 0;\n        for (int i = 1; i < N; i++) {\n            for (int j = i + 1; j <= N; j++) {\n                G += GCD(i, j);\n            }\n        }\n        cout << G << \"\\n\";\n    }\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11417 GCD",
    "Question Description": "Given the value of N, you will have to find the value of G. The definition of G is given below:\n\nG = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)\n\nHere GCD(i,j) means the greatest common divisor of integer i and integer j.\n\nFor those who have trouble understanding summation notation, the meaning of G is given in the following code:\n\nG=0;\nfor(i=1;i<N;i++)\nfor(j=i+1;j<=N;j++)\n{\n    G+=GCD(i,j);\n}\n/*Here GCD() is a function that finds\nthe greatest common divisor of the two\ninput numbers*/",
    "Input Requirements": "The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains the value of G for corresponding N.",
    "Sample Input": "10\n100\n500\n0",
    "Sample Output": "67\n13015\n442011",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"11461 Square Numbers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"11461 Square Numbers\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"11461 Square Numbers\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"11461 Square Numbers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"11461 Square Numbers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"11461 Square Numbers\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"11461 Square Numbers\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"11461 Square Numbers\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 11461 Square Numbers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 11461 Square Numbers?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 11461 Square Numbers in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 11461 Square Numbers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 11461 Square Numbers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 11461 Square Numbers with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 11461 Square Numbers.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 11461 Square Numbers, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11461 Square Numbers」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「11461 Square Numbers」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「11461 Square Numbers」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「11461 Square Numbers」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「11461 Square Numbers」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「11461 Square Numbers」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「11461 Square Numbers」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「11461 Square Numbers」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11461 Square Numbers 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "11461 Square Numbers 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 11461 Square Numbers？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 11461 Square Numbers 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 11461 Square Numbers 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 11461 Square Numbers 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 11461 Square Numbers 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 11461 Square Numbers 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\n#include <cmath>\nusing namespace std;\n  \nint main() {\n    int a, b;\n    while (cin >> a >> b && a + b){\n        int n1 = sqrt(a);\n        int n2 = sqrt(b);\n        if (n1*n1 != a) n1++;\n        cout << n2 - n1 + 1 << \"\\n\";\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "11461 Square Numbers",
    "Question Description": "A square number is an integer number whose square root is also an integer. For example 1, 4, 81 are some square numbers. Given two numbers a and b you will have to find out how many square numbers are there between a and b (inclusive).",
    "Input Requirements": "The input file contains at most 201 lines of inputs. Each line contains two integers a and b (0 < a ≤ b ≤ 100000). Input is terminated by a line containing two zeroes. This line should not be processed.",
    "Output Requirements": "For each line of input produce one line of output. This line contains an integer which denotes how many square numbers are there between a and b (inclusive).",
    "Sample Input": "1 4\n1 10\n0 0",
    "Sample Output": "2\n3",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve \"12019 Doom's Day Algorithm\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for \"12019 Doom's Day Algorithm\"?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement \"12019 Doom's Day Algorithm\" in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for \"12019 Doom's Day Algorithm\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for \"12019 Doom's Day Algorithm\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for \"12019 Doom's Day Algorithm\" with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for \"12019 Doom's Day Algorithm\".",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for \"12019 Doom's Day Algorithm\", generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to solve 12019 Doom's Day Algorithm?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "What is the solution for 12019 Doom's Day Algorithm?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "How to implement 12019 Doom's Day Algorithm in C++?",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Give me a C++ code for 12019 Doom's Day Algorithm.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Do you know the solution for 12019 Doom's Day Algorithm.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Show me the code for 12019 Doom's Day Algorithm with explanations.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "Generate a code solution for 12019 Doom's Day Algorithm.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "I need a C++ code for 12019 Doom's Day Algorithm, generate it for me.",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「12019 Doom's Day Algorithm」要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "「12019 Doom's Day Algorithm」的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作「12019 Doom's Day Algorithm」？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個「12019 Doom's Day Algorithm」的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道「12019 Doom's Day Algorithm」的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫「12019 Doom's Day Algorithm」的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成「12019 Doom's Day Algorithm」的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要「12019 Doom's Day Algorithm」的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "12019 Doom's Day Algorithm 要怎麼解? ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "12019 Doom's Day Algorithm 的解答是什麼？",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "如何用C++實作 12019 Doom's Day Algorithm？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "給我一個 12019 Doom's Day Algorithm 的C++程式碼。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "你知道 12019 Doom's Day Algorithm 的解法嗎？ ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "撰寫 12019 Doom's Day Algorithm 的程式碼並附帶說明。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "生成 12019 Doom's Day Algorithm 的程式碼解答。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "我需要 12019 Doom's Day Algorithm 的C++程式碼，幫我生成一個。 ",
        "role": "user"
      },
      {
        "content": "#include <iostream>\nusing namespace std;\nint doom[13] = {-1, 10, 21, 7, 4, 9, 6, 11, 8, 5, 10, 7, 12};\nstring date[] = {\"Monday\", \"Tuesday\", \"Wednesday\",\n    \"Thursday\", \"Friday\", \"Saturday\", \"Sunday\"};\n \nint main() {\n    int T, m, d;\n    cin >> T;\n    while (T--) {\n        cin >> m >> d;\n        int delta = (d - doom[m]) % 7;\n        if (delta >= 0){\n            cout << date[delta] << \"\\n\";\n        } else {\n            cout << date[7 + delta] << \"\\n\";\n        }\n    }\n    return 0;\n}",
        "role": "assistant"
      }
    ],
    "Question Name": "12019 Doom's Day Algorithm",
    "Question Description": "No. Doom's day algorithm is not a method to compute which day the world will end. It is an algorithm created by the mathematician John Horton Conway, to calculate which day of the week (Monday, Tuesday, etc.) corresponds to a certain date.\n\nThis algorithm is based in the idea of the doomsday, a certain day of the week which always occurs in the same dates. For example, 4/4 (the 4th of April), 6/6 (the 6th of June), 8/8 (the 8th of August), 10/10 (the 10th of October) and 12/12 (the 12th of December) are dates which always occur in doomsday. All years have their own doomsday.\n\nIn year 2011, doomsday is Monday. So all of 4/4, 6/6, 8/8, 10/10 and 12/12 are Mondays. Using that information, you can easily compute any other date. For example, the 13th of December 2011 will be Tuesday, the 14th of December 2011 will be Wednesday, etc.\n\nOther days which occur on doomsday are 5/9, 9/5, 7/11 and 11/7. Also, in leap years, we have the following doomsdays: 1/11 (the 11th of January) and 2/22 (the 22nd of Febrary), and in non-leap years 1/10 and 2/21.",
    "Input Requirements": "The input can contain different test cases. The first line of the input indicates the number of test cases.\n\nFor each test case, there is a line with two numbers: M D. M represents the month (from 1 to 12) and D represents the day (from 1 to 31). The date will always be valid.",
    "Output Requirements": "For each test case, you have to output the day of the week where that date occurs in 2011. The days of the week will be: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.",
    "Sample Input": "8\n1 6\n2 28\n4 5\n5 26\n8 1\n11 1\n12 25\n12 31",
    "Sample Output": "Thursday\nMonday\nTuesday\nThursday\nMonday\nTuesday\nSunday\nSaturday",
    "Difficulty": "One star",
    "Question Source": "Online Judge",
    "Question Source URL": "https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0",
    "Answer Source": "Yui Huang's Website",
    "Answer Source URL": "https://yuihuang.com/cpe-level-1/"
  },
  {
    "conversations": [
      {
        "content": "什麼是CPE程式檢定?",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  },
  {
    "conversations": [
      {
        "content": "介紹一下CPE程式檢定。",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  },
  {
    "conversations": [
      {
        "content": "什麼是CPE檢定?",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  },
  {
    "conversations": [
      {
        "content": "介紹一下CPE檢定。",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  },
  {
    "conversations": [
      {
        "content": "CPE檢定是什麼?",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  },
  {
    "conversations": [
      {
        "content": "什麼是CPE?",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  },
  {
    "conversations": [
      {
        "content": "CPE是什麼?",
        "role": "user"
      },
      {
        "content": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。 \n國立虎尾科技大學資訊工程系將CPE程式檢定設為其中一項畢業標準，凡資訊工程系(科)大學部及專科部入學後學生皆須參加「程式能力檢定」並通過，目的是為了培養學生程式設計之專業基本能力，增進其升學與就業之競爭優勢。\n。符合下列第一款或第二款條件者(第一款及第二款通過題數不得混合累計)，即通過檢定，通過檢定之學生，可向本系(科)申請頒發合格證書：\n一、 入學後參加本系(科)舉辦之檢定考試，學生累計通過3題(含進階題至少一題)以上。本系(科)舉辦之檢定考試以寒假或暑假各辦理一次。\n二、入學後參加CPE考試，一次答對 2 題或累計答對 3 題以上者。\n",
        "role": "assistant"
      }
    ],
    "Exam name": "Collegiate Programming Examination (CPE)",
    "Exam Description": "大學程式能力檢定 (Collegiate Programming Examination, 簡稱CPE)旨在提升大專學生與相關人員的程式設計能力，由考生透過線上程式設計，利用電腦自動評判，以檢測程式設計能力。2010 年 6 月開辦 CPE，2012 年以及之後，每年均舉辦四次 CPE。最近的 CPE，每一次都有四十餘校參與協辦，考生超過 2000 人(最多一次考生，已超過 2700 人)。CPE 採取現場程式上機考試，封閉與考試無關之網路。目前題目來自著名 Online judge 網站https://onlinejudge.org/ (超過 4500 題，收集自歷次程式競賽題目)，涵蓋難、中、易範圍，極適合大二「資料結構」課程以上的程度。大專學生免費，高中以下學生 400 元，社會人士500 元。若需要成績證明書，大專學生 100 元，高中以下學生 100 元，社會人士 200 元。CPE 的目標是做為全台灣「程式能力檢定」的標準，有如英文的多益或全民英檢。CPE希望藉由考試檢定的手段，提升全台灣學生的程式設計能力。有些大學已將 CPE 成績採計為碩士班入學招生參考標準之一；有些大學採計 CPE 成績為大學部學生畢業門檻；各校高階程式設計課程(如資料結構、演算法)也非常適合以 CPE 成績作為上機考試之成績。\n(以上資訊來自中山大學資工系楊昌彪老師，來源：https://cpe.mcu.edu.tw/doc/CPE_introduction.pdf)\n",
    "CPE Website": "https://cpe.mcu.edu.tw/"
  }
]