{ "id": 3311, "name": "ant_on_the_boundary", "difficulty": "Easy", "link": "https://leetcode.com/problems/ant-on-the-boundary/", "date": "2024-01-28 00:00:00", "task_description": "An ant is on a boundary. It sometimes goes **left** and sometimes **right**. You are given an array of **non-zero** integers `nums`. The ant starts reading `nums` from the first element of it to its end. At each step, it moves according to the value of the current element: If `nums[i] < 0`, it moves **left** by `-nums[i]` units. If `nums[i] > 0`, it moves **right** by `nums[i]` units. Return _the number of times the ant **returns** to the boundary._ **Notes:** There is an infinite space on both sides of the boundary. We check whether the ant is on the boundary only after it has moved `|nums[i]|` units. In other words, if the ant crosses the boundary during its movement, it does not count. **Example 1:** ``` **Input:** nums = [2,3,-5] **Output:** 1 **Explanation:** After the first step, the ant is 2 steps to the right of the boundary. After the second step, the ant is 5 steps to the right of the boundary. After the third step, the ant is on the boundary. So the answer is 1. ``` **Example 2:** ``` **Input:** nums = [3,2,-3,-4] **Output:** 0 **Explanation:** After the first step, the ant is 3 steps to the right of the boundary. After the second step, the ant is 5 steps to the right of the boundary. After the third step, the ant is 2 steps to the right of the boundary. After the fourth step, the ant is 2 steps to the left of the boundary. The ant never returned to the boundary, so the answer is 0. ``` **Constraints:** `1 <= nums.length <= 100` `-10 <= nums[i] <= 10` `nums[i] != 0`", "public_test_cases": [ { "label": "Example 1", "input": "nums = [2,3,-5]", "output": "1 " }, { "label": "Example 2", "input": "nums = [3,2,-3,-4]", "output": "0 " } ], "private_test_cases": [ { "input": [ -10, 9, -10, 10, 1, -8, 5, 9, -7, -9, 2, -8, -1, -5, -7, 7, -5, -2, -3, 9, -9, -9, 9, -3, -7, -6, -9, -7, 0, 4, -1, -10, 0, 8, 8, -7, -1, 3, 8, -3, -1, -6 ], "output": 1 }, { "input": [ -6, 0, 7, -4, -2, 5, 3, 4, 3, -7, 4, -6, 7, 8, -1, 5, 1, 10, -7, -6, 1, -5, 3, 8, -6, 5, -8, 10, -4, 3, -10, -3, -1, 10, 9, 10, -9, 10, -3, -3, -6, 0, 7, 4, 2, 0, 7, 2, -6 ], "output": 1 }, { "input": [ -2, 5, 1, -2, 7, -6, 6, 2, -2, -10, 10, 8, -3, 6 ], "output": 0 }, { "input": [ -2, -7, -7, -10, -10 ], "output": 0 }, { "input": [ -10, -9, 0 ], "output": 0 } ], "haskell_template": "returnToBoundaryCount :: [Int] -> Int\nreturnToBoundaryCount nums ", "ocaml_template": "let returnToBoundaryCount (nums: int list) : int = ", "scala_template": "def returnToBoundaryCount(nums: List[Int]): Int = { \n \n}", "java_template": "class Solution {\n public int returnToBoundaryCount(int[] nums) {\n \n }\n}", "python_template": "class Solution(object):\n def returnToBoundaryCount(self, nums):\n \"\"\"\n :type nums: List[int]\n :rtype: int\n \"\"\"\n " }