diff --git "a/validation.csv" "b/validation.csv" new file mode 100644--- /dev/null +++ "b/validation.csv" @@ -0,0 +1,23963 @@ +db_name,prompt +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# How many singers do we have? +# +### SQL: +# +# SELECT count(*) FROM singer +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the total number of singers? +# +### SQL: +# +# SELECT count(*) FROM singer +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show name, country, age for all singers ordered by age from the oldest to the youngest. +# +### SQL: +# +# SELECT name , country , age FROM singer ORDER BY age DESC +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names, countries, and ages for every singer in descending order of age? +# +### SQL: +# +# SELECT name , country , age FROM singer ORDER BY age DESC +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the average, minimum, and maximum age of all singers from France? +# +### SQL: +# +# SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France' +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the average, minimum, and maximum age for all French singers? +# +### SQL: +# +# SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France' +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show the name and the release year of the song by the youngest singer. +# +### SQL: +# +# SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names and release years for all the songs of the youngest singer? +# +### SQL: +# +# SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are all distinct countries where singers above age 20 are from? +# +### SQL: +# +# SELECT DISTINCT country FROM singer WHERE age > 20 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the different countries with singers above age 20? +# +### SQL: +# +# SELECT DISTINCT country FROM singer WHERE age > 20 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show all countries and the number of singers in each country. +# +### SQL: +# +# SELECT country , count(*) FROM singer GROUP BY country +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# How many singers are from each country? +# +### SQL: +# +# SELECT country , count(*) FROM singer GROUP BY country +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# List all song names by singers above the average age. +# +### SQL: +# +# SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer) +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are all the song names by singers who are older than average? +# +### SQL: +# +# SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer) +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show location and name for all stadiums with a capacity between 5000 and 10000. +# +### SQL: +# +# SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the locations and names of all stations with capacity between 5000 and 10000? +# +### SQL: +# +# SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the maximum capacity and the average of all stadiums ? +# +### SQL: +# +# select max(capacity), average from stadium +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the average and maximum capacities for all stadiums ? +# +### SQL: +# +# select avg(capacity) , max(capacity) from stadium +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the name and capacity for the stadium with highest average attendance? +# +### SQL: +# +# SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the name and capacity for the stadium with the highest average attendance? +# +### SQL: +# +# SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# How many concerts are there in year 2014 or 2015? +# +### SQL: +# +# SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# How many concerts occurred in 2014 or 2015? +# +### SQL: +# +# SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show the stadium name and the number of concerts in each stadium. +# +### SQL: +# +# SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# For each stadium, how many concerts play there? +# +### SQL: +# +# SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show the stadium name and capacity with most number of concerts in year 2014 or after. +# +### SQL: +# +# SELECT T2.name , T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the name and capacity of the stadium with the most concerts after 2013 ? +# +### SQL: +# +# select t2.name , t2.capacity from concert as t1 join stadium as t2 on t1.stadium_id = t2.stadium_id where t1.year > 2013 group by t2.stadium_id order by count(*) desc limit 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Which year has most number of concerts? +# +### SQL: +# +# SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the year that had the most concerts? +# +### SQL: +# +# SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show the stadium names without any concert. +# +### SQL: +# +# SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert) +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names of the stadiums without any concerts? +# +### SQL: +# +# SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert) +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show countries where a singer above age 40 and a singer below 30 are from. +# +### SQL: +# +# SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show names for all stadiums except for stadiums having a concert in year 2014. +# +### SQL: +# +# SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names of all stadiums that did not have a concert in 2014? +# +### SQL: +# +# SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Show the name and theme for all concerts and the number of singers in each concert. +# +### SQL: +# +# SELECT T2.concert_name , T2.theme , count(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names , themes , and number of singers for every concert ? +# +### SQL: +# +# select t2.concert_name , t2.theme , count(*) from singer_in_concert as t1 join concert as t2 on t1.concert_id = t2.concert_id group by t2.concert_id +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# List singer names and number of concerts for each singer. +# +### SQL: +# +# SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names of the singers and number of concerts for each person? +# +### SQL: +# +# SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# List all singer names in concerts in year 2014. +# +### SQL: +# +# SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names of the singers who performed in a concert in 2014? +# +### SQL: +# +# SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# what is the name and nation of the singer who have a song having 'Hey' in its name? +# +### SQL: +# +# SELECT name , country FROM singer WHERE song_name LIKE '%Hey%' +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What is the name and country of origin of every singer who has a song with the word 'Hey' in its title? +# +### SQL: +# +# SELECT name , country FROM singer WHERE song_name LIKE '%Hey%' +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Find the name and location of the stadiums which some concerts happened in the years of both 2014 and 2015. +# +### SQL: +# +# SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the names and locations of the stadiums that had concerts that occurred in both 2014 and 2015? +# +### SQL: +# +# SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015 +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# Find the number of concerts happened in the stadium with the highest capacity . +# +### SQL: +# +# select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1) +# +### End. +" +concert_singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# stadium ( Stadium_ID, Location, Name, Capacity, Highest, Lowest, Average ) +# singer ( Singer_ID, Name, Country, Song_Name, Song_release_year, Age, Is_male ) +# concert ( concert_ID, concert_Name, Theme, Stadium_ID, Year ) +# singer_in_concert ( concert_ID, Singer_ID ) +# +# concert.Stadium_ID can be joined with stadium.Stadium_ID +# singer_in_concert.Singer_ID can be joined with singer.Singer_ID +# singer_in_concert.concert_ID can be joined with concert.concert_ID +# +### Question: +# +# What are the number of concerts that occurred in the stadium with the largest capacity ? +# +### SQL: +# +# select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1) +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the number of pets whose weight is heavier than 10. +# +### SQL: +# +# SELECT count(*) FROM pets WHERE weight > 10 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# How many pets have a greater weight than 10? +# +### SQL: +# +# SELECT count(*) FROM pets WHERE weight > 10 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the weight of the youngest dog. +# +### SQL: +# +# SELECT weight FROM pets ORDER BY pet_age LIMIT 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# How much does the youngest dog weigh? +# +### SQL: +# +# SELECT weight FROM pets ORDER BY pet_age LIMIT 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the maximum weight for each type of pet. List the maximum weight and pet type. +# +### SQL: +# +# SELECT max(weight) , petType FROM pets GROUP BY petType +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# List the maximum weight and type for each type of pet. +# +### SQL: +# +# SELECT max(weight) , petType FROM pets GROUP BY petType +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find number of pets owned by students who are older than 20. +# +### SQL: +# +# SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# How many pets are owned by students that have an age greater than 20? +# +### SQL: +# +# SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the number of dog pets that are raised by female students (with sex F). +# +### SQL: +# +# SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# How many dog pets are raised by female students? +# +### SQL: +# +# SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the number of distinct type of pets. +# +### SQL: +# +# SELECT count(DISTINCT pettype) FROM pets +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# How many different types of pet are there? +# +### SQL: +# +# SELECT count(DISTINCT pettype) FROM pets +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the first name of students who have cat or dog pet. +# +### SQL: +# +# SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What are the first names of every student who has a cat or dog as a pet? +# +### SQL: +# +# SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the first name of students who have both cat and dog pets . +# +### SQL: +# +# select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'cat' intersect select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'dog' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What are the students' first names who have both cats and dogs as pets? +# +### SQL: +# +# SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the major and age of students who do not have a cat pet. +# +### SQL: +# +# SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What major is every student who does not own a cat as a pet, and also how old are they? +# +### SQL: +# +# SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the id of students who do not have a cat pet. +# +### SQL: +# +# SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What are the ids of the students who do not own cats as pets? +# +### SQL: +# +# SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the first name and age of students who have a dog but do not have a cat as a pet. +# +### SQL: +# +# SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the first name of every student who has a dog but does not have a cat? +# +### SQL: +# +# SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the type and weight of the youngest pet. +# +### SQL: +# +# SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What type of pet is the youngest animal, and how much does it weigh? +# +### SQL: +# +# SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the id and weight of all pets whose age is older than 1. +# +### SQL: +# +# SELECT petid , weight FROM pets WHERE pet_age > 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the id and weight of every pet who is older than 1? +# +### SQL: +# +# SELECT petid , weight FROM pets WHERE pet_age > 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the average and maximum age for each type of pet. +# +### SQL: +# +# SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the average and maximum age for each pet type? +# +### SQL: +# +# SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the average weight for each pet type. +# +### SQL: +# +# SELECT avg(weight) , pettype FROM pets GROUP BY pettype +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the average weight for each type of pet? +# +### SQL: +# +# SELECT avg(weight) , pettype FROM pets GROUP BY pettype +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the first name and age of students who have a pet. +# +### SQL: +# +# SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What are the different first names and ages of the students who do have pets? +# +### SQL: +# +# SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the id of the pet owned by student whose last name is ‘Smith’. +# +### SQL: +# +# SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the id of the pet owned by the student whose last name is 'Smith'? +# +### SQL: +# +# SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the number of pets for each student who has any pet and student id. +# +### SQL: +# +# SELECT count(*) , T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# For students who have pets , how many pets does each student have ? list their ids instead of names . +# +### SQL: +# +# select count(*) , t1.stuid from student as t1 join has_pet as t2 on t1.stuid = t2.stuid group by t1.stuid +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the first name and gender of student who have more than one pet. +# +### SQL: +# +# SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the first name and gender of the all the students who have more than one pet? +# +### SQL: +# +# SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1 +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the last name of the student who has a cat that is age 3. +# +### SQL: +# +# SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the last name of the student who has a cat that is 3 years old? +# +### SQL: +# +# SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat' +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# Find the average age of students who do not have any pet . +# +### SQL: +# +# select avg(age) from student where stuid not in (select stuid from has_pet) +# +### End. +" +pets_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) +# Has_Pet ( StuID, PetID ) +# Pets ( PetID, PetType, pet_age, weight ) +# +# Has_Pet.StuID can be joined with Student.StuID +# Has_Pet.PetID can be joined with Pets.PetID +# +### Question: +# +# What is the average age for all students who do not own any pets ? +# +### SQL: +# +# select avg(age) from student where stuid not in (select stuid from has_pet) +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many continents are there? +# +### SQL: +# +# SELECT count(*) FROM CONTINENTS; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of continents? +# +### SQL: +# +# SELECT count(*) FROM CONTINENTS; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many countries does each continent have? List the continent id, continent name and the number of countries. +# +### SQL: +# +# SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# For each continent, list its id, name, and how many countries it has? +# +### SQL: +# +# SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many countries are listed? +# +### SQL: +# +# SELECT count(*) FROM COUNTRIES; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many countries exist? +# +### SQL: +# +# SELECT count(*) FROM COUNTRIES; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many models does each car maker produce? List maker full name, id and the number. +# +### SQL: +# +# SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the full name of each car maker, along with its id and how many models it produces? +# +### SQL: +# +# SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which model of the car has the minimum horsepower? +# +### SQL: +# +# SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the model of the car with the smallest amount of horsepower? +# +### SQL: +# +# SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Find the model of the car whose weight is below the average weight. +# +### SQL: +# +# SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA) +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the model for the car with a weight smaller than the average? +# +### SQL: +# +# SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA) +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Find the name of the makers that produced some cars in the year of 1970? +# +### SQL: +# +# SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the name of the different car makers who produced a car in 1970? +# +### SQL: +# +# SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Find the make and production time of the cars that were produced in the earliest year? +# +### SQL: +# +# SELECT T2.Make , T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT min(YEAR) FROM CARS_DATA); +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the maker of the carr produced in the earliest year and what year was it? +# +### SQL: +# +# SELECT T2.Make , T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT min(YEAR) FROM CARS_DATA); +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which distinct car models are the produced after 1980? +# +### SQL: +# +# SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the different models for the cards produced after 1980? +# +### SQL: +# +# SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many car makers are there in each continents? List the continent name and the count. +# +### SQL: +# +# SELECT T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the name of each continent and how many car makers are there in each one? +# +### SQL: +# +# SELECT T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which of the countries has the most car makers? List the country name. +# +### SQL: +# +# SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY Count(*) DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the name of the country with the most car makers? +# +### SQL: +# +# SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY Count(*) DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many car models are produced by each maker ? Only list the count and the maker full name . +# +### SQL: +# +# select count(*) , t2.fullname from model_list as t1 join car_makers as t2 on t1.maker = t2.id group by t2.id; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of car models that are produced by each maker and what is the id and full name of each maker? +# +### SQL: +# +# SELECT Count(*) , T2.FullName , T2.id FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id GROUP BY T2.id; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the accelerate of the car make amc hornet sportabout (sw)? +# +### SQL: +# +# SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How much does the car accelerate that makes amc hornet sportabout (sw)? +# +### SQL: +# +# SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many car makers are there in france? +# +### SQL: +# +# SELECT count(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of makers of care in France? +# +### SQL: +# +# SELECT count(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many car models are produced in the usa? +# +### SQL: +# +# SELECT count(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the count of the car models produced in the United States? +# +### SQL: +# +# SELECT count(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average miles per gallon(mpg) of the cars with 4 cylinders? +# +### SQL: +# +# SELECT avg(mpg) FROM CARS_DATA WHERE Cylinders = 4; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average miles per gallon of all the cards with 4 cylinders? +# +### SQL: +# +# SELECT avg(mpg) FROM CARS_DATA WHERE Cylinders = 4; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the smallest weight of the car produced with 8 cylinders on 1974 ? +# +### SQL: +# +# select min(weight) from cars_data where cylinders = 8 and year = 1974 +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the minimum weight of the car with 8 cylinders produced in 1974 ? +# +### SQL: +# +# select min(weight) from cars_data where cylinders = 8 and year = 1974 +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are all the makers and models? +# +### SQL: +# +# SELECT Maker , Model FROM MODEL_LIST; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the makers and models? +# +### SQL: +# +# SELECT Maker , Model FROM MODEL_LIST; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the countries having at least one car maker? List name and id. +# +### SQL: +# +# SELECT T1.CountryName , T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING count(*) >= 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the names and ids of all countries with at least one car maker? +# +### SQL: +# +# SELECT T1.CountryName , T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING count(*) >= 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of the cars with horsepower more than 150? +# +### SQL: +# +# SELECT count(*) FROM CARS_DATA WHERE horsepower > 150; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of cars with a horsepower greater than 150? +# +### SQL: +# +# SELECT count(*) FROM CARS_DATA WHERE horsepower > 150; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average weight of cars each year? +# +### SQL: +# +# SELECT avg(Weight) , YEAR FROM CARS_DATA GROUP BY YEAR; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average weight and year for each year? +# +### SQL: +# +# SELECT avg(Weight) , YEAR FROM CARS_DATA GROUP BY YEAR; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which countries in europe have at least 3 car manufacturers? +# +### SQL: +# +# SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING count(*) >= 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the names of all European countries with at least 3 manufacturers? +# +### SQL: +# +# SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING count(*) >= 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the maximum horsepower and the make of the car models with 3 cylinders? +# +### SQL: +# +# SELECT T2.horsepower , T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the largest amount of horsepower for the models with 3 cylinders and what make is it? +# +### SQL: +# +# SELECT T2.horsepower , T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which model saves the most gasoline? That is to say, have the maximum miles per gallon. +# +### SQL: +# +# SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.mpg DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the car model with the highest mpg ? +# +### SQL: +# +# select t1.model from car_names as t1 join cars_data as t2 on t1.makeid = t2.id order by t2.mpg desc limit 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average horsepower of the cars before 1980? +# +### SQL: +# +# SELECT avg(horsepower) FROM CARS_DATA WHERE YEAR < 1980; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average horsepower for all cars produced before 1980 ? +# +### SQL: +# +# select avg(horsepower) from cars_data where year < 1980; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average edispl of the cars of model volvo? +# +### SQL: +# +# SELECT avg(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the average edispl for all volvos? +# +### SQL: +# +# SELECT avg(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the maximum accelerate for different number of cylinders? +# +### SQL: +# +# SELECT max(Accelerate) , Cylinders FROM CARS_DATA GROUP BY Cylinders; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the maximum accelerate for all the different cylinders? +# +### SQL: +# +# SELECT max(Accelerate) , Cylinders FROM CARS_DATA GROUP BY Cylinders; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which model has the most version(make) of cars? +# +### SQL: +# +# SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY count(*) DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What model has the most different versions? +# +### SQL: +# +# SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY count(*) DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many cars have more than 4 cylinders? +# +### SQL: +# +# SELECT count(*) FROM CARS_DATA WHERE Cylinders > 4; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of cars with more than 4 cylinders? +# +### SQL: +# +# SELECT count(*) FROM CARS_DATA WHERE Cylinders > 4; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# how many cars were produced in 1980? +# +### SQL: +# +# SELECT count(*) FROM CARS_DATA WHERE YEAR = 1980; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# In 1980, how many cars were made? +# +### SQL: +# +# SELECT count(*) FROM CARS_DATA WHERE YEAR = 1980; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many car models were produced by the maker with full name American Motor Company? +# +### SQL: +# +# SELECT count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of car models created by the car maker American Motor Company? +# +### SQL: +# +# SELECT count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which makers designed more than 3 car models? List full name and the id. +# +### SQL: +# +# SELECT T1.FullName , T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING count(*) > 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the names and ids of all makers with more than 3 models? +# +### SQL: +# +# SELECT T1.FullName , T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING count(*) > 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which distinctive models are produced by maker with the full name General Motors or weighing more than 3500? +# +### SQL: +# +# SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the different models created by either the car maker General Motors or weighed more than 3500? +# +### SQL: +# +# SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# In which years cars were produced weighing no less than 3000 and no more than 4000 ? +# +### SQL: +# +# select distinct year from cars_data where weight between 3000 and 4000; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the different years in which there were cars produced that weighed less than 4000 and also cars that weighted more than 3000 ? +# +### SQL: +# +# select distinct year from cars_data where weight between 3000 and 4000; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the horsepower of the car with the largest accelerate? +# +### SQL: +# +# SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the horsepower of the car with the greatest accelerate? +# +### SQL: +# +# SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# For model volvo, how many cylinders does the car with the least accelerate have? +# +### SQL: +# +# SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# For a volvo model, how many cylinders does the version with least accelerate have? +# +### SQL: +# +# SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many cars have a larger accelerate than the car with the largest horsepower? +# +### SQL: +# +# SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > ( SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1 ); +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of cars with a greater accelerate than the one with the most horsepower? +# +### SQL: +# +# SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > ( SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1 ); +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many countries has more than 2 car makers ? +# +### SQL: +# +# select count(*) from countries as t1 join car_makers as t2 on t1.countryid = t2.country group by t1.countryid having count(*) > 2 +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of countries with more than 2 car makers ? +# +### SQL: +# +# select count(*) from countries as t1 join car_makers as t2 on t1.countryid = t2.country group by t1.countryid having count(*) > 2 +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# How many cars has over 6 cylinders? +# +### SQL: +# +# SELECT COUNT(*) FROM CARS_DATA WHERE Cylinders > 6; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the number of carsw ith over 6 cylinders? +# +### SQL: +# +# SELECT COUNT(*) FROM CARS_DATA WHERE Cylinders > 6; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# For the cars with 4 cylinders, which model has the largest horsepower? +# +### SQL: +# +# SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# For all of the 4 cylinder cars, which model has the most horsepower? +# +### SQL: +# +# SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Among the cars with more than lowest horsepower, which ones do not have more than 3 cylinders? List the car makeid and make name. +# +### SQL: +# +# SELECT T2.MakeId , T2.Make FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Horsepower > (SELECT min(Horsepower) FROM CARS_DATA) AND T1.Cylinders <= 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Among the cars that do not have the minimum horsepower , what are the make ids and names of all those with less than 4 cylinders ? +# +### SQL: +# +# select t2.makeid , t2.make from cars_data as t1 join car_names as t2 on t1.id = t2.makeid where t1.horsepower > (select min(horsepower) from cars_data) and t1.cylinders < 4; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the maximum miles per gallon of the car with 8 cylinders or produced before 1980 ? +# +### SQL: +# +# select max(mpg) from cars_data where cylinders = 8 or year < 1980 +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What is the maximum mpg of the cars that had 8 cylinders or that were produced before 1980 ? +# +### SQL: +# +# select max(mpg) from cars_data where cylinders = 8 or year < 1980 +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which models are lighter than 3500 but not built by the 'Ford Motor Company'? +# +### SQL: +# +# SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName != 'Ford Motor Company'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the different models wthat are lighter than 3500 but were not built by the Ford Motor Company? +# +### SQL: +# +# SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName != 'Ford Motor Company'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the name of the countries where there is not a single car maker? +# +### SQL: +# +# SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the names of the countries with no car makers? +# +### SQL: +# +# SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# Which are the car makers which produce at least 2 models and more than 3 car makers ? List the id and the maker . +# +### SQL: +# +# select t1.id , t1.maker from car_makers as t1 join model_list as t2 on t1.id = t2.maker group by t1.id having count(*) >= 2 intersect select t1.id , t1.maker from car_makers as t1 join model_list as t2 on t1.id = t2.maker join car_names as t3 on t2.model = t3.model group by t1.id having count(*) > 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the ids and makers of all car makers that produce at least 2 models and make more than 3 cars? +# +### SQL: +# +# SELECT T1.Id , T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING count(*) >= 2 INTERSECT SELECT T1.Id , T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model GROUP BY T1.Id HAVING count(*) > 3; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the id and names of the countries which have more than 3 car makers or produce the 'fiat' model? +# +### SQL: +# +# SELECT T1.countryId , T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.countryId HAVING count(*) > 3 UNION SELECT T1.countryId , T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country JOIN MODEL_LIST AS T3 ON T2.Id = T3.Maker WHERE T3.Model = 'fiat'; +# +### End. +" +car_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# continents ( ContId, Continent ) +# countries ( CountryId, CountryName, Continent ) +# car_makers ( Id, Maker, FullName, Country ) +# model_list ( ModelId, Maker, Model ) +# car_names ( MakeId, Model, Make ) +# cars_data ( Id, MPG, Cylinders, Edispl, Horsepower, Weight, Accelerate, Year ) +# +# countries.Continent can be joined with continents.ContId +# car_makers.Country can be joined with countries.CountryId +# model_list.Maker can be joined with car_makers.Id +# car_names.Model can be joined with model_list.Model +# cars_data.Id can be joined with car_names.MakeId +# +### Question: +# +# What are the ids and names of all countries that either have more than 3 car makers or produce fiat model ? +# +### SQL: +# +# select t1.countryid , t1.countryname from countries as t1 join car_makers as t2 on t1.countryid = t2.country group by t1.countryid having count(*) > 3 union select t1.countryid , t1.countryname from countries as t1 join car_makers as t2 on t1.countryid = t2.country join model_list as t3 on t2.id = t3.maker where t3.model = 'fiat'; +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which country does Airline ""JetBlue Airways"" belong to? +# +### SQL: +# +# SELECT Country FROM AIRLINES WHERE Airline = ""JetBlue Airways"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What country is Jetblue Airways affiliated with? +# +### SQL: +# +# SELECT Country FROM AIRLINES WHERE Airline = ""JetBlue Airways"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the abbreviation of Airline ""JetBlue Airways""? +# +### SQL: +# +# SELECT Abbreviation FROM AIRLINES WHERE Airline = ""JetBlue Airways"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which abbreviation corresponds to Jetblue Airways? +# +### SQL: +# +# SELECT Abbreviation FROM AIRLINES WHERE Airline = ""JetBlue Airways"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# List all airline names and their abbreviations in ""USA"". +# +### SQL: +# +# SELECT Airline , Abbreviation FROM AIRLINES WHERE Country = ""USA"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are the airline names and abbreviations for airlines in the USA? +# +### SQL: +# +# SELECT Airline , Abbreviation FROM AIRLINES WHERE Country = ""USA"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# List the airport code and name in the city of Anthony. +# +### SQL: +# +# SELECT AirportCode , AirportName FROM AIRPORTS WHERE city = ""Anthony"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the airport code and airport name corresonding to the city Anthony. +# +### SQL: +# +# SELECT AirportCode , AirportName FROM AIRPORTS WHERE city = ""Anthony"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many airlines do we have? +# +### SQL: +# +# SELECT count(*) FROM AIRLINES +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the total number of airlines? +# +### SQL: +# +# SELECT count(*) FROM AIRLINES +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many airports do we have? +# +### SQL: +# +# SELECT count(*) FROM AIRPORTS +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the number of airports. +# +### SQL: +# +# SELECT count(*) FROM AIRPORTS +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights do we have? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the number of flights. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airline has abbreviation 'UAL'? +# +### SQL: +# +# SELECT Airline FROM AIRLINES WHERE Abbreviation = ""UAL"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the airline with abbreviation 'UAL'. +# +### SQL: +# +# SELECT Airline FROM AIRLINES WHERE Abbreviation = ""UAL"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many airlines are from USA? +# +### SQL: +# +# SELECT count(*) FROM AIRLINES WHERE Country = ""USA"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the number of airlines in the USA. +# +### SQL: +# +# SELECT count(*) FROM AIRLINES WHERE Country = ""USA"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which city and country is the Alton airport at? +# +### SQL: +# +# SELECT City , Country FROM AIRPORTS WHERE AirportName = ""Alton"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the city and country for the Alton airport. +# +### SQL: +# +# SELECT City , Country FROM AIRPORTS WHERE AirportName = ""Alton"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the airport name for airport 'AKO'? +# +### SQL: +# +# SELECT AirportName FROM AIRPORTS WHERE AirportCode = ""AKO"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the name of the airport with code 'AKO'. +# +### SQL: +# +# SELECT AirportName FROM AIRPORTS WHERE AirportCode = ""AKO"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are airport names at City 'Aberdeen'? +# +### SQL: +# +# SELECT AirportName FROM AIRPORTS WHERE City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are the names of airports in Aberdeen? +# +### SQL: +# +# SELECT AirportName FROM AIRPORTS WHERE City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights depart from 'APG'? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS WHERE SourceAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Count the number of flights departing from 'APG'. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS WHERE SourceAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights have destination ATO? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS WHERE DestAirport = ""ATO"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Count the number of flights into ATO. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS WHERE DestAirport = ""ATO"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights depart from City Aberdeen? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the number of flights departing from Aberdeen. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights arriving in Aberdeen city? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the number of flights arriving in Aberdeen. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights depart from City 'Aberdeen' and have destination City 'Ashley'? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = ""Ashley"" AND T3.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights fly from Aberdeen to Ashley? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = ""Ashley"" AND T3.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights does airline 'JetBlue Airways' have? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = ""JetBlue Airways"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the number of Jetblue Airways flights. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = ""JetBlue Airways"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many 'United Airlines' flights go to Airport 'ASY'? +# +### SQL: +# +# SELECT count(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = ""United Airlines"" AND T2.DestAirport = ""ASY"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Count the number of United Airlines flights arriving in ASY Airport. +# +### SQL: +# +# SELECT count(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = ""United Airlines"" AND T2.DestAirport = ""ASY"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many 'United Airlines' flights depart from Airport 'AHD'? +# +### SQL: +# +# SELECT count(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = ""United Airlines"" AND T2.SourceAirport = ""AHD"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Return the number of United Airlines flights leaving from AHD Airport. +# +### SQL: +# +# SELECT count(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = ""United Airlines"" AND T2.SourceAirport = ""AHD"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many United Airlines flights go to City 'Aberdeen'? +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = ""Aberdeen"" AND T3.Airline = ""United Airlines"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Count the number of United Airlines flights that arrive in Aberdeen. +# +### SQL: +# +# SELECT count(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = ""Aberdeen"" AND T3.Airline = ""United Airlines"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which city has most number of arriving flights? +# +### SQL: +# +# SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which city has the most frequent destination airport? +# +### SQL: +# +# SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which city has most number of departing flights? +# +### SQL: +# +# SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which city is the most frequent source airport? +# +### SQL: +# +# SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the code of airport that has the highest number of flights? +# +### SQL: +# +# SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the airport code of the airport with the most flights? +# +### SQL: +# +# SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the code of airport that has fewest number of flights? +# +### SQL: +# +# SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY count(*) LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the code of the airport with the least flights. +# +### SQL: +# +# SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY count(*) LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airline has most number of flights? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What airline serves the most flights? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find the abbreviation and country of the airline that has fewest number of flights? +# +### SQL: +# +# SELECT T1.Abbreviation , T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY count(*) LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What is the abbreviation of the airilne has the fewest flights and what country is it in? +# +### SQL: +# +# SELECT T1.Abbreviation , T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY count(*) LIMIT 1 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are airlines that have some flight departing from airport 'AHD'? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""AHD"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airlines have a flight with source airport AHD? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""AHD"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are airlines that have flights arriving at airport 'AHD'? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = ""AHD"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airlines have a flight with destination airport AHD? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = ""AHD"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find all airlines that have flights from both airports 'APG' and 'CVO'. +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""APG"" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""CVO"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airlines have departing flights from both APG and CVO airports? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""APG"" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""CVO"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find all airlines that have flights from airport 'CVO' but not from 'APG'. +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""CVO"" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airlines have departures from CVO but not from APG airports? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""CVO"" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find all airlines that have at least 10 flights. +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING count(*) > 10 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airlines have at least 10 flights? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING count(*) > 10 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find all airlines that have fewer than 200 flights. +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING count(*) < 200 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airlines have less than 200 flights? +# +### SQL: +# +# SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING count(*) < 200 +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are flight numbers of Airline ""United Airlines""? +# +### SQL: +# +# SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = ""United Airlines"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which flight numbers correspond to United Airlines flights? +# +### SQL: +# +# SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = ""United Airlines"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are flight numbers of flights departing from Airport ""APG""? +# +### SQL: +# +# SELECT FlightNo FROM FLIGHTS WHERE SourceAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the flight numbers of flights leaving from APG. +# +### SQL: +# +# SELECT FlightNo FROM FLIGHTS WHERE SourceAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are flight numbers of flights arriving at Airport ""APG""? +# +### SQL: +# +# SELECT FlightNo FROM FLIGHTS WHERE DestAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the flight numbers of flights landing at APG. +# +### SQL: +# +# SELECT FlightNo FROM FLIGHTS WHERE DestAirport = ""APG"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are flight numbers of flights departing from City ""Aberdeen ""? +# +### SQL: +# +# SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the flight numbers of flights leaving from Aberdeen. +# +### SQL: +# +# SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# What are flight numbers of flights arriving at City ""Aberdeen""? +# +### SQL: +# +# SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Give the flight numbers of flights arriving in Aberdeen. +# +### SQL: +# +# SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = ""Aberdeen"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find the number of flights landing in the city of Aberdeen or Abilene. +# +### SQL: +# +# SELECT count(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = ""Aberdeen"" OR T2.city = ""Abilene"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# How many flights land in Aberdeen or Abilene? +# +### SQL: +# +# SELECT count(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = ""Aberdeen"" OR T2.city = ""Abilene"" +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Find the name of airports which do not have any flight in and out. +# +### SQL: +# +# SELECT AirportName FROM Airports WHERE AirportCode NOT IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights) +# +### End. +" +flight_2,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# airlines ( uid, Airline, Abbreviation, Country ) +# airports ( City, AirportCode, AirportName, Country, CountryAbbrev ) +# flights ( Airline, FlightNo, SourceAirport, DestAirport ) +# +# flights.DestAirport can be joined with airports.AirportCode +# flights.SourceAirport can be joined with airports.AirportCode +# +### Question: +# +# Which airports do not have departing or arriving flights? +# +### SQL: +# +# SELECT AirportName FROM Airports WHERE AirportCode NOT IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# How many employees are there? +# +### SQL: +# +# SELECT count(*) FROM employee +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Count the number of employees +# +### SQL: +# +# SELECT count(*) FROM employee +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Sort employee names by their age in ascending order. +# +### SQL: +# +# SELECT name FROM employee ORDER BY age +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# List the names of employees and sort in ascending order of age. +# +### SQL: +# +# SELECT name FROM employee ORDER BY age +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What is the number of employees from each city? +# +### SQL: +# +# SELECT count(*) , city FROM employee GROUP BY city +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Count the number of employees for each city. +# +### SQL: +# +# SELECT count(*) , city FROM employee GROUP BY city +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which cities do more than one employee under age 30 come from? +# +### SQL: +# +# SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING count(*) > 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the cities that have more than one employee under age 30. +# +### SQL: +# +# SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING count(*) > 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the number of shops in each location. +# +### SQL: +# +# SELECT count(*) , LOCATION FROM shop GROUP BY LOCATION +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# How many shops are there in each location? +# +### SQL: +# +# SELECT count(*) , LOCATION FROM shop GROUP BY LOCATION +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the manager name and district of the shop whose number of products is the largest. +# +### SQL: +# +# SELECT manager_name , district FROM shop ORDER BY number_products DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What are the manager name and district of the shop that sells the largest number of products? +# +### SQL: +# +# SELECT manager_name , district FROM shop ORDER BY number_products DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# find the minimum and maximum number of products of all stores. +# +### SQL: +# +# SELECT min(Number_products) , max(Number_products) FROM shop +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What are the minimum and maximum number of products across all the shops? +# +### SQL: +# +# SELECT min(Number_products) , max(Number_products) FROM shop +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Return the name, location and district of all shops in descending order of number of products. +# +### SQL: +# +# SELECT name , LOCATION , district FROM shop ORDER BY number_products DESC +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Sort all the shops by number products in descending order, and return the name, location and district of each shop. +# +### SQL: +# +# SELECT name , LOCATION , district FROM shop ORDER BY number_products DESC +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the names of stores whose number products is more than the average number of products. +# +### SQL: +# +# SELECT name FROM shop WHERE number_products > (SELECT avg(number_products) FROM shop) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which shops' number products is above the average? Give me the shop names. +# +### SQL: +# +# SELECT name FROM shop WHERE number_products > (SELECT avg(number_products) FROM shop) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# find the name of employee who was awarded the most times in the evaluation. +# +### SQL: +# +# SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID GROUP BY t2.Employee_ID ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which employee received the most awards in evaluations? Give me the employee name. +# +### SQL: +# +# SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID GROUP BY t2.Employee_ID ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the name of the employee who got the highest one time bonus. +# +### SQL: +# +# SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which employee received the biggest bonus? Give me the employee name. +# +### SQL: +# +# SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the names of employees who never won any award in the evaluation. +# +### SQL: +# +# SELECT name FROM employee WHERE Employee_ID NOT IN (SELECT Employee_ID FROM evaluation) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What are the names of the employees who never received any evaluation? +# +### SQL: +# +# SELECT name FROM employee WHERE Employee_ID NOT IN (SELECT Employee_ID FROM evaluation) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What is the name of the shop that is hiring the largest number of employees? +# +### SQL: +# +# SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t1.shop_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which shop has the most employees? Give me the shop name. +# +### SQL: +# +# SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t1.shop_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the name of the shops that do not hire any employee. +# +### SQL: +# +# SELECT name FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM hiring) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which shops run with no employees? Find the shop names +# +### SQL: +# +# SELECT name FROM shop WHERE shop_id NOT IN (SELECT shop_id FROM hiring) +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the number of employees hired in each shop; show the shop name as well. +# +### SQL: +# +# SELECT count(*) , t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# For each shop, return the number of employees working there and the name of the shop. +# +### SQL: +# +# SELECT count(*) , t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What is total bonus given in all evaluations? +# +### SQL: +# +# SELECT sum(bonus) FROM evaluation +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the total amount of bonus given in all the evaluations. +# +### SQL: +# +# SELECT sum(bonus) FROM evaluation +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Give me all the information about hiring. +# +### SQL: +# +# SELECT * FROM hiring +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# What is all the information about hiring? +# +### SQL: +# +# SELECT * FROM hiring +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Which district has both stores with less than 3000 products and stores with more than 10000 products? +# +### SQL: +# +# SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Find the districts in which there are both shops selling less than 3000 products and shops selling more than 10000 products. +# +### SQL: +# +# SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000 +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# How many different store locations are there? +# +### SQL: +# +# SELECT count(DISTINCT LOCATION) FROM shop +# +### End. +" +employee_hire_evaluation,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# employee ( Employee_ID, Name, Age, City ) +# shop ( Shop_ID, Name, Location, District, Number_products, Manager_name ) +# hiring ( Shop_ID, Employee_ID, Start_from, Is_full_time ) +# evaluation ( Employee_ID, Year_awarded, Bonus ) +# +# hiring.Employee_ID can be joined with employee.Employee_ID +# hiring.Shop_ID can be joined with shop.Shop_ID +# evaluation.Employee_ID can be joined with employee.Employee_ID +# +### Question: +# +# Count the number of distinct store locations. +# +### SQL: +# +# SELECT count(DISTINCT LOCATION) FROM shop +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many documents do we have? +# +### SQL: +# +# SELECT count(*) FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of documents. +# +### SQL: +# +# SELECT count(*) FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# List document IDs, document names, and document descriptions for all documents. +# +### SQL: +# +# SELECT document_id , document_name , document_description FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids, names, and descriptions for all documents? +# +### SQL: +# +# SELECT document_id , document_name , document_description FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the document name and template id for document with description with the letter 'w' in it? +# +### SQL: +# +# SELECT document_name , template_id FROM Documents WHERE Document_Description LIKE ""%w%"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the names and template ids for documents that contain the letter w in their description. +# +### SQL: +# +# SELECT document_name , template_id FROM Documents WHERE Document_Description LIKE ""%w%"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the document id, template id and description for document named ""Robbin CV""? +# +### SQL: +# +# SELECT document_id , template_id , Document_Description FROM Documents WHERE document_name = ""Robbin CV"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the document id, template id, and description for the document with the name Robbin CV. +# +### SQL: +# +# SELECT document_id , template_id , Document_Description FROM Documents WHERE document_name = ""Robbin CV"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many different templates do all document use? +# +### SQL: +# +# SELECT count(DISTINCT template_id) FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of different templates used for documents. +# +### SQL: +# +# SELECT count(DISTINCT template_id) FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many documents are using the template with type code 'PPT'? +# +### SQL: +# +# SELECT count(*) FROM Documents AS T1 JOIN Templates AS T2 ON T1.Template_ID = T2.Template_ID WHERE T2.Template_Type_Code = 'PPT' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of documents that use the PPT template type. +# +### SQL: +# +# SELECT count(*) FROM Documents AS T1 JOIN Templates AS T2 ON T1.Template_ID = T2.Template_ID WHERE T2.Template_Type_Code = 'PPT' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all template ids and number of documents using each template. +# +### SQL: +# +# SELECT template_id , count(*) FROM Documents GROUP BY template_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are all different template ids used for documents, and how many times were each of them used? +# +### SQL: +# +# SELECT template_id , count(*) FROM Documents GROUP BY template_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the id and type code for the template used by the most documents? +# +### SQL: +# +# SELECT T1.template_id , T2.Template_Type_Code FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the id and type code of the template that is used for the greatest number of documents. +# +### SQL: +# +# SELECT T1.template_id , T2.Template_Type_Code FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show ids for all templates that are used by more than one document. +# +### SQL: +# +# SELECT template_id FROM Documents GROUP BY template_id HAVING count(*) > 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the template ids of any templates used in more than a single document? +# +### SQL: +# +# SELECT template_id FROM Documents GROUP BY template_id HAVING count(*) > 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show ids for all templates not used by any document. +# +### SQL: +# +# SELECT template_id FROM Templates EXCEPT SELECT template_id FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids for templates that are not used in any documents? +# +### SQL: +# +# SELECT template_id FROM Templates EXCEPT SELECT template_id FROM Documents +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many templates do we have? +# +### SQL: +# +# SELECT count(*) FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of templates. +# +### SQL: +# +# SELECT count(*) FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show template ids, version numbers, and template type codes for all templates. +# +### SQL: +# +# SELECT template_id , version_number , template_type_code FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids, version numbers, and type codes for each template? +# +### SQL: +# +# SELECT template_id , version_number , template_type_code FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all distinct template type codes for all templates. +# +### SQL: +# +# SELECT DISTINCT template_type_code FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the different template type codes? +# +### SQL: +# +# SELECT DISTINCT template_type_code FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids of templates with template type code PP or PPT? +# +### SQL: +# +# SELECT template_id FROM Templates WHERE template_type_code = ""PP"" OR template_type_code = ""PPT"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the ids of templates that have the code PP or PPT. +# +### SQL: +# +# SELECT template_id FROM Templates WHERE template_type_code = ""PP"" OR template_type_code = ""PPT"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many templates have template type code CV? +# +### SQL: +# +# SELECT count(*) FROM Templates WHERE template_type_code = ""CV"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of templates of the type CV. +# +### SQL: +# +# SELECT count(*) FROM Templates WHERE template_type_code = ""CV"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the version number and template type code for the template with version number later than 5? +# +### SQL: +# +# SELECT version_number , template_type_code FROM Templates WHERE version_number > 5 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the version numbers and template type codes of templates with a version number greater than 5. +# +### SQL: +# +# SELECT version_number , template_type_code FROM Templates WHERE version_number > 5 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all template type codes and number of templates for each. +# +### SQL: +# +# SELECT template_type_code , count(*) FROM Templates GROUP BY template_type_code +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the different template type codes, and how many templates correspond to each? +# +### SQL: +# +# SELECT template_type_code , count(*) FROM Templates GROUP BY template_type_code +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Which template type code has most number of templates? +# +### SQL: +# +# SELECT template_type_code FROM Templates GROUP BY template_type_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the type code of the template type that the most templates belong to. +# +### SQL: +# +# SELECT template_type_code FROM Templates GROUP BY template_type_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all template type codes with less than three templates. +# +### SQL: +# +# SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING count(*) < 3 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the codes of template types that have fewer than 3 templates? +# +### SQL: +# +# SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING count(*) < 3 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What the smallest version number and its template type code? +# +### SQL: +# +# SELECT min(Version_Number) , template_type_code FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the lowest version number, along with its corresponding template type code. +# +### SQL: +# +# SELECT min(Version_Number) , template_type_code FROM Templates +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the template type code of the template used by document with the name ""Data base""? +# +### SQL: +# +# SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = ""Data base"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the template type code of the template that is used by a document named Data base. +# +### SQL: +# +# SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = ""Data base"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all document names using templates with template type code BK. +# +### SQL: +# +# SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = ""BK"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the names of documents that use templates with the code BK? +# +### SQL: +# +# SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = ""BK"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all template type codes and the number of documents using each type. +# +### SQL: +# +# SELECT T1.template_type_code , count(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the different template type codes, and how many documents use each type? +# +### SQL: +# +# SELECT T1.template_type_code , count(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Which template type code is used by most number of documents? +# +### SQL: +# +# SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the code of the template type that is most commonly used in documents. +# +### SQL: +# +# SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all template type codes that are not used by any document. +# +### SQL: +# +# SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the codes of template types that are not used for any document? +# +### SQL: +# +# SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all template type codes and descriptions. +# +### SQL: +# +# SELECT template_type_code , template_type_description FROM Ref_template_types +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the type codes and descriptions for all template types? +# +### SQL: +# +# SELECT template_type_code , template_type_description FROM Ref_template_types +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the template type descriptions for template type code ""AD"". +# +### SQL: +# +# SELECT template_type_description FROM Ref_template_types WHERE template_type_code = ""AD"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the template type description of the template type with the code AD. +# +### SQL: +# +# SELECT template_type_description FROM Ref_template_types WHERE template_type_code = ""AD"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the template type code for template type description ""Book"". +# +### SQL: +# +# SELECT template_type_code FROM Ref_template_types WHERE template_type_description = ""Book"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the type code of the template type with the description ""Book"". +# +### SQL: +# +# SELECT template_type_code FROM Ref_template_types WHERE template_type_description = ""Book"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the distinct template type descriptions for the templates ever used by any document? +# +### SQL: +# +# SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the different descriptions for templates that have been used in a document. +# +### SQL: +# +# SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the template ids with template type description ""Presentation"". +# +### SQL: +# +# SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = ""Presentation"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the ids corresponding to templates with the description 'Presentation'. +# +### SQL: +# +# SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = ""Presentation"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many paragraphs in total? +# +### SQL: +# +# SELECT count(*) FROM Paragraphs +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of paragraphs. +# +### SQL: +# +# SELECT count(*) FROM Paragraphs +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# How many paragraphs for the document with name 'Summer Show'? +# +### SQL: +# +# SELECT count(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_ID = T2.document_ID WHERE T2.document_name = 'Summer Show' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Count the number of paragraphs in the document named 'Summer Show'. +# +### SQL: +# +# SELECT count(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_ID = T2.document_ID WHERE T2.document_name = 'Summer Show' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show paragraph details for paragraph with text 'Korea ' . +# +### SQL: +# +# select other_details from paragraphs where paragraph_text like 'korea' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the details for the paragraph that includes the text 'Korea ' ? +# +### SQL: +# +# select other_details from paragraphs where paragraph_text like 'korea' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all paragraph ids and texts for the document with name 'Welcome to NY'. +# +### SQL: +# +# SELECT T1.paragraph_id , T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.Document_Name = 'Welcome to NY' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids and texts of paragraphs in the document titled 'Welcome to NY'? +# +### SQL: +# +# SELECT T1.paragraph_id , T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.Document_Name = 'Welcome to NY' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all paragraph texts for the document ""Customer reviews"". +# +### SQL: +# +# SELECT T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = ""Customer reviews"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the paragraph texts for the document with the name 'Customer reviews'? +# +### SQL: +# +# SELECT T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = ""Customer reviews"" +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all document ids and the number of paragraphs in each document. Order by document id. +# +### SQL: +# +# SELECT document_id , count(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the different document ids along with the number of paragraphs corresponding to each, ordered by id. +# +### SQL: +# +# SELECT document_id , count(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show all document ids, names and the number of paragraphs in each document. +# +### SQL: +# +# SELECT T1.document_id , T2.document_name , count(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids and names of each document, as well as the number of paragraphs in each? +# +### SQL: +# +# SELECT T1.document_id , T2.document_name , count(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# List all document ids with at least two paragraphs. +# +### SQL: +# +# SELECT document_id FROM Paragraphs GROUP BY document_id HAVING count(*) >= 2 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids of documents that have 2 or more paragraphs? +# +### SQL: +# +# SELECT document_id FROM Paragraphs GROUP BY document_id HAVING count(*) >= 2 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the document id and name with greatest number of paragraphs? +# +### SQL: +# +# SELECT T1.document_id , T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the id and name of the document with the most paragraphs. +# +### SQL: +# +# SELECT T1.document_id , T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the document id with least number of paragraphs? +# +### SQL: +# +# SELECT document_id FROM Paragraphs GROUP BY document_id ORDER BY count(*) ASC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Return the id of the document with the fewest paragraphs. +# +### SQL: +# +# SELECT document_id FROM Paragraphs GROUP BY document_id ORDER BY count(*) ASC LIMIT 1 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What is the document id with 1 to 2 paragraphs? +# +### SQL: +# +# SELECT document_id FROM Paragraphs GROUP BY document_id HAVING count(*) BETWEEN 1 AND 2 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Give the ids of documents that have between one and two paragraphs. +# +### SQL: +# +# SELECT document_id FROM Paragraphs GROUP BY document_id HAVING count(*) BETWEEN 1 AND 2 +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# Show the document id with paragraph text 'Brazil' and 'Ireland'. +# +### SQL: +# +# SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Brazil' INTERSECT SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Ireland' +# +### End. +" +cre_Doc_Template_Mgt,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Template_Types ( Template_Type_Code, Template_Type_Description ) +# Templates ( Template_ID, Version_Number, Template_Type_Code, Date_Effective_From, Date_Effective_To, Template_Details ) +# Documents ( Document_ID, Template_ID, Document_Name, Document_Description, Other_Details ) +# Paragraphs ( Paragraph_ID, Document_ID, Paragraph_Text, Other_Details ) +# +# Templates.Template_Type_Code can be joined with Ref_Template_Types.Template_Type_Code +# Documents.Template_ID can be joined with Templates.Template_ID +# Paragraphs.Document_ID can be joined with Documents.Document_ID +# +### Question: +# +# What are the ids of documents that contain the paragraph text 'Brazil' and 'Ireland'? +# +### SQL: +# +# SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Brazil' INTERSECT SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Ireland' +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# How many teachers are there? +# +### SQL: +# +# SELECT count(*) FROM teacher +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What is the total count of teachers? +# +### SQL: +# +# SELECT count(*) FROM teacher +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# List the names of teachers in ascending order of age. +# +### SQL: +# +# SELECT Name FROM teacher ORDER BY Age ASC +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers ordered by ascending age? +# +### SQL: +# +# SELECT Name FROM teacher ORDER BY Age ASC +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the age and hometown of teachers? +# +### SQL: +# +# SELECT Age , Hometown FROM teacher +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What is the age and hometown of every teacher? +# +### SQL: +# +# SELECT Age , Hometown FROM teacher +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# List the name of teachers whose hometown is not `` Little Lever Urban District '' . +# +### SQL: +# +# select name from teacher where hometown != ""little lever urban district"" +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers whose hometown is not `` Little Lever Urban District '' ? +# +### SQL: +# +# select name from teacher where hometown != ""little lever urban district"" +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show the name of teachers aged either 32 or 33? +# +### SQL: +# +# SELECT Name FROM teacher WHERE Age = 32 OR Age = 33 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers who are aged either 32 or 33? +# +### SQL: +# +# SELECT Name FROM teacher WHERE Age = 32 OR Age = 33 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What is the hometown of the youngest teacher? +# +### SQL: +# +# SELECT Hometown FROM teacher ORDER BY Age ASC LIMIT 1 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Where is the youngest teacher from? +# +### SQL: +# +# SELECT Hometown FROM teacher ORDER BY Age ASC LIMIT 1 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show different hometown of teachers and the number of teachers from each hometown. +# +### SQL: +# +# SELECT Hometown , COUNT(*) FROM teacher GROUP BY Hometown +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# For each hometown, how many teachers are there? +# +### SQL: +# +# SELECT Hometown , COUNT(*) FROM teacher GROUP BY Hometown +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# List the most common hometown of teachers. +# +### SQL: +# +# SELECT Hometown FROM teacher GROUP BY Hometown ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What is the most commmon hometowns for teachers? +# +### SQL: +# +# SELECT Hometown FROM teacher GROUP BY Hometown ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show the hometowns shared by at least two teachers. +# +### SQL: +# +# SELECT Hometown FROM teacher GROUP BY Hometown HAVING COUNT(*) >= 2 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the towns from which at least two teachers come from? +# +### SQL: +# +# SELECT Hometown FROM teacher GROUP BY Hometown HAVING COUNT(*) >= 2 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show names of teachers and the courses they are arranged to teach. +# +### SQL: +# +# SELECT T3.Name , T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What is the name of each teacher and what course they teach? +# +### SQL: +# +# SELECT T3.Name , T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show names of teachers and the courses they are arranged to teach in ascending alphabetical order of the teacher's name. +# +### SQL: +# +# SELECT T3.Name , T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers and the courses they teach in ascending alphabetical order by the name of the teacher? +# +### SQL: +# +# SELECT T3.Name , T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show the name of the teacher for the math course. +# +### SQL: +# +# SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = ""Math"" +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the people who teach math courses? +# +### SQL: +# +# SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = ""Math"" +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show names of teachers and the number of courses they teach. +# +### SQL: +# +# SELECT T2.Name , COUNT(*) FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers and how many courses do they teach? +# +### SQL: +# +# SELECT T2.Name , COUNT(*) FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# Show names of teachers that teach at least two courses. +# +### SQL: +# +# SELECT T2.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name HAVING COUNT(*) >= 2 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers who teach at least two courses? +# +### SQL: +# +# SELECT T2.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name HAVING COUNT(*) >= 2 +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# List the names of teachers who have not been arranged to teach courses. +# +### SQL: +# +# SELECT Name FROM teacher WHERE Teacher_id NOT IN (SELECT Teacher_id FROM course_arrange) +# +### End. +" +course_teach,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# course ( Course_ID, Staring_Date, Course ) +# teacher ( Teacher_ID, Name, Age, Hometown ) +# course_arrange ( Course_ID, Teacher_ID, Grade ) +# +# course_arrange.Teacher_ID can be joined with teacher.Teacher_ID +# course_arrange.Course_ID can be joined with course.Course_ID +# +### Question: +# +# What are the names of the teachers whose courses have not been arranged? +# +### SQL: +# +# SELECT Name FROM teacher WHERE Teacher_id NOT IN (SELECT Teacher_id FROM course_arrange) +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# How many visitors below age 30 are there? +# +### SQL: +# +# SELECT count(*) FROM visitor WHERE age < 30 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# Find the names of the visitors whose membership level is higher than 4, and order the results by the level from high to low. +# +### SQL: +# +# SELECT name FROM visitor WHERE Level_of_membership > 4 ORDER BY Level_of_membership DESC +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What is the average age of the visitors whose membership level is not higher than 4? +# +### SQL: +# +# SELECT avg(age) FROM visitor WHERE Level_of_membership <= 4 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# Find the name and membership level of the visitors whose membership level is higher than 4, and sort by their age from old to young. +# +### SQL: +# +# SELECT name , Level_of_membership FROM visitor WHERE Level_of_membership > 4 ORDER BY age DESC +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# Find the id and name of the museum that has the most staff members? +# +### SQL: +# +# SELECT museum_id , name FROM museum ORDER BY num_of_staff DESC LIMIT 1 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# Find the average number of staff working for the museums that were open before 2009. +# +### SQL: +# +# SELECT avg(num_of_staff) FROM museum WHERE open_year < 2009 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What are the opening year and staff number of the museum named Plaza Museum? +# +### SQL: +# +# SELECT Num_of_Staff , Open_Year FROM museum WHERE name = 'Plaza Museum' +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# find the names of museums which have more staff than the minimum staff number of all museums opened after 2010. +# +### SQL: +# +# SELECT name FROM museum WHERE num_of_staff > (SELECT min(num_of_staff) FROM museum WHERE open_year > 2010) +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# find the id, name and age for visitors who visited some museums more than once. +# +### SQL: +# +# SELECT t1.id , t1.name , t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t1.id HAVING count(*) > 1 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What are the id, name and membership level of visitors who have spent the largest amount of money in total in all museum tickets? +# +### SQL: +# +# SELECT t2.visitor_id , t1.name , t1.Level_of_membership FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t2.visitor_id ORDER BY sum(t2.Total_spent) DESC LIMIT 1 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What are the id and name of the museum visited most times? +# +### SQL: +# +# SELECT t2.Museum_ID , t1.name FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID GROUP BY t2.Museum_ID ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What is the name of the museum that had no visitor yet? +# +### SQL: +# +# SELECT name FROM museum WHERE Museum_ID NOT IN (SELECT museum_id FROM visit) +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# Find the name and age of the visitor who bought the most tickets at once. +# +### SQL: +# +# SELECT t1.name , t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id ORDER BY t2.num_of_ticket DESC LIMIT 1 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What are the average and maximum number of tickets bought in all visits? +# +### SQL: +# +# SELECT avg(num_of_ticket) , max(num_of_ticket) FROM visit +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What is the total ticket expense of the visitors whose membership level is 1? +# +### SQL: +# +# SELECT sum(t2.Total_spent) FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id WHERE t1.Level_of_membership = 1 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# What is the name of the visitor who visited both a museum opened before 2009 and a museum opened after 2011? +# +### SQL: +# +# SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year < 2009 INTERSECT SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year > 2011 +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# Find the number of visitors who did not visit any museum opened after 2010. +# +### SQL: +# +# SELECT count(*) FROM visitor WHERE id NOT IN (SELECT t2.visitor_id FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID WHERE t1.open_year > 2010) +# +### End. +" +museum_visit,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# museum ( Museum_ID, Name, Num_of_Staff, Open_Year ) +# visitor ( ID, Name, Level_of_membership, Age ) +# visit ( Museum_ID, visitor_ID, Num_of_Ticket, Total_spent ) +# +# visit.visitor_ID can be joined with visitor.ID +# visit.Museum_ID can be joined with museum.Museum_ID +# +### Question: +# +# How many museums were opened after 2013 or before 2008? +# +### SQL: +# +# SELECT count(*) FROM museum WHERE open_year > 2013 OR open_year < 2008 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the total number of players. +# +### SQL: +# +# SELECT count(*) FROM players +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many players are there? +# +### SQL: +# +# SELECT count(*) FROM players +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the total number of matches. +# +### SQL: +# +# SELECT count(*) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Count the number of matches. +# +### SQL: +# +# SELECT count(*) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# List the first name and birth date of all players from the country with code USA. +# +### SQL: +# +# SELECT first_name , birth_date FROM players WHERE country_code = 'USA' +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the first names and birth dates of players from the USA? +# +### SQL: +# +# SELECT first_name , birth_date FROM players WHERE country_code = 'USA' +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the average age of losers and winners of all matches. +# +### SQL: +# +# SELECT avg(loser_age) , avg(winner_age) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the average ages of losers and winners across matches? +# +### SQL: +# +# SELECT avg(loser_age) , avg(winner_age) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the average rank of winners in all matches. +# +### SQL: +# +# SELECT avg(winner_rank) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the average rank for winners in all matches? +# +### SQL: +# +# SELECT avg(winner_rank) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the highest rank of losers in all matches. +# +### SQL: +# +# SELECT min(loser_rank) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the best rank of losers across all matches? +# +### SQL: +# +# SELECT min(loser_rank) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# find the number of distinct country codes of all players. +# +### SQL: +# +# SELECT count(DISTINCT country_code) FROM players +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many distinct countries do players come from? +# +### SQL: +# +# SELECT count(DISTINCT country_code) FROM players +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the number of distinct name of losers. +# +### SQL: +# +# SELECT count(DISTINCT loser_name) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many different loser names are there? +# +### SQL: +# +# SELECT count(DISTINCT loser_name) FROM matches +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the name of tourney that has more than 10 matches. +# +### SQL: +# +# SELECT tourney_name FROM matches GROUP BY tourney_name HAVING count(*) > 10 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the names of tournaments that have more than 10 matches? +# +### SQL: +# +# SELECT tourney_name FROM matches GROUP BY tourney_name HAVING count(*) > 10 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# List the names of all winners who played in both 2013 and 2016. +# +### SQL: +# +# SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the names of players who won in both 2013 and 2016? +# +### SQL: +# +# SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# List the number of all matches who played in years of 2013 or 2016. +# +### SQL: +# +# SELECT count(*) FROM matches WHERE YEAR = 2013 OR YEAR = 2016 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many matches were played in 2013 or 2016? +# +### SQL: +# +# SELECT count(*) FROM matches WHERE YEAR = 2013 OR YEAR = 2016 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the country code and first name of the players who won in both tourney WTA Championships and Australian Open? +# +### SQL: +# +# SELECT T1.country_code , T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code , T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open' +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the first names and country codes for players who won both the WTA Championships and the Australian Open? +# +### SQL: +# +# SELECT T1.country_code , T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code , T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open' +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the first name and country code of the oldest player. +# +### SQL: +# +# SELECT first_name , country_code FROM players ORDER BY birth_date LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the first name and country code of the oldest player? +# +### SQL: +# +# SELECT first_name , country_code FROM players ORDER BY birth_date LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# List the first and last name of all players in the order of birth date. +# +### SQL: +# +# SELECT first_name , last_name FROM players ORDER BY birth_date +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the full names of all players, sorted by birth date? +# +### SQL: +# +# SELECT first_name , last_name FROM players ORDER BY birth_date +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# List the first and last name of all players who are left / L hand in the order of birth date. +# +### SQL: +# +# SELECT first_name , last_name FROM players WHERE hand = 'L' ORDER BY birth_date +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the full names of all left handed players, in order of birth date? +# +### SQL: +# +# SELECT first_name , last_name FROM players WHERE hand = 'L' ORDER BY birth_date +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the first name and country code of the player who did the most number of tours. +# +### SQL: +# +# SELECT T1.country_code , T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the first name and country code of the player with the most tours? +# +### SQL: +# +# SELECT T1.country_code , T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the year that has the most number of matches. +# +### SQL: +# +# SELECT YEAR FROM matches GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Which year had the most matches? +# +### SQL: +# +# SELECT YEAR FROM matches GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the name and rank points of the winner who won the most times. +# +### SQL: +# +# SELECT winner_name , winner_rank_points FROM matches GROUP BY winner_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the name of the winner who has won the most matches, and how many rank points does this player have? +# +### SQL: +# +# SELECT winner_name , winner_rank_points FROM matches GROUP BY winner_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the name of the winner who has the highest rank points and participated in the Australian Open tourney. +# +### SQL: +# +# SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the name of the winner with the most rank points who participated in the Australian Open tournament? +# +### SQL: +# +# SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# find the names of loser and winner who played in the match with greatest number of minutes. +# +### SQL: +# +# SELECT winner_name , loser_name FROM matches ORDER BY minutes DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the names of the winner and loser who played in the longest match? +# +### SQL: +# +# SELECT winner_name , loser_name FROM matches ORDER BY minutes DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the average ranking for each player and their first name. +# +### SQL: +# +# SELECT avg(ranking) , T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the first names of all players, and their average rankings? +# +### SQL: +# +# SELECT avg(ranking) , T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the total ranking points for each player and their first name. +# +### SQL: +# +# SELECT sum(ranking_points) , T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the first names of all players, and their total ranking points? +# +### SQL: +# +# SELECT sum(ranking_points) , T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# find the number of players for each country. +# +### SQL: +# +# SELECT count(*) , country_code FROM players GROUP BY country_code +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many players are from each country? +# +### SQL: +# +# SELECT count(*) , country_code FROM players GROUP BY country_code +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# find the code of the country where has the greatest number of players. +# +### SQL: +# +# SELECT country_code FROM players GROUP BY country_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the code of the country with the most players? +# +### SQL: +# +# SELECT country_code FROM players GROUP BY country_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the codes of countries that have more than 50 players. +# +### SQL: +# +# SELECT country_code FROM players GROUP BY country_code HAVING count(*) > 50 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the codes of countries with more than 50 players? +# +### SQL: +# +# SELECT country_code FROM players GROUP BY country_code HAVING count(*) > 50 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the total number of tours for each ranking date. +# +### SQL: +# +# SELECT sum(tours) , ranking_date FROM rankings GROUP BY ranking_date +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many total tours were there for each ranking date? +# +### SQL: +# +# SELECT sum(tours) , ranking_date FROM rankings GROUP BY ranking_date +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the number of matches happened in each year. +# +### SQL: +# +# SELECT count(*) , YEAR FROM matches GROUP BY YEAR +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many matches were played in each year? +# +### SQL: +# +# SELECT count(*) , YEAR FROM matches GROUP BY YEAR +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the name and rank of the 3 youngest winners across all matches. +# +### SQL: +# +# SELECT DISTINCT winner_name , winner_rank FROM matches ORDER BY winner_age LIMIT 3 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What are the names and ranks of the three youngest winners across all matches? +# +### SQL: +# +# SELECT DISTINCT winner_name , winner_rank FROM matches ORDER BY winner_age LIMIT 3 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many different winners both participated in the WTA Championships and were left handed? +# +### SQL: +# +# SELECT count(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L' +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the number of left handed winners who participated in the WTA Championships. +# +### SQL: +# +# SELECT count(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L' +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the first name, country code and birth date of the winner who has the highest rank points in all matches. +# +### SQL: +# +# SELECT T1.first_name , T1.country_code , T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# What is the first name, country code, and birth date of the player with the most winner rank points across all matches? +# +### SQL: +# +# SELECT T1.first_name , T1.country_code , T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1 +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# Find the number of players for each hand type. +# +### SQL: +# +# SELECT count(*) , hand FROM players GROUP BY hand +# +### End. +" +wta_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# players ( player_id, first_name, last_name, hand, birth_date, country_code ) +# matches ( best_of, draw_size, loser_age, loser_entry, loser_hand, loser_ht, loser_id, loser_ioc, loser_name, loser_rank, loser_rank_points, loser_seed, match_num, minutes, round, score, surface, tourney_date, tourney_id, tourney_level, tourney_name, winner_age, winner_entry, winner_hand, winner_ht, winner_id, winner_ioc, winner_name, winner_rank, winner_rank_points, winner_seed, year ) +# rankings ( ranking_date, ranking, player_id, ranking_points, tours ) +# +# matches.winner_id can be joined with players.player_id +# matches.loser_id can be joined with players.player_id +# rankings.player_id can be joined with players.player_id +# +### Question: +# +# How many players are there for each hand type? +# +### SQL: +# +# SELECT count(*) , hand FROM players GROUP BY hand +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# How many ships ended up being 'Captured'? +# +### SQL: +# +# SELECT count(*) FROM ship WHERE disposition_of_ship = 'Captured' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# List the name and tonnage ordered by in descending alphaetical order for the names. +# +### SQL: +# +# SELECT name , tonnage FROM ship ORDER BY name DESC +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# List the name, date and result of each battle. +# +### SQL: +# +# SELECT name , date FROM battle +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What is maximum and minimum death toll caused each time? +# +### SQL: +# +# SELECT max(killed) , min(killed) FROM death +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What is the average number of injuries caused each time? +# +### SQL: +# +# SELECT avg(injured) FROM death +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What are the death and injury situations caused by the ship with tonnage 't'? +# +### SQL: +# +# SELECT T1.killed , T1.injured FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id WHERE T2.tonnage = 't' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What are the name and results of the battles when the bulgarian commander is not 'Boril' +# +### SQL: +# +# SELECT name , RESULT FROM battle WHERE bulgarian_commander != 'Boril' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What are the different ids and names of the battles that lost any 'Brig' type shipes? +# +### SQL: +# +# SELECT DISTINCT T1.id , T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.ship_type = 'Brig' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What are the ids and names of the battles that led to more than 10 people killed in total. +# +### SQL: +# +# SELECT T1.id , T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle JOIN death AS T3 ON T2.id = T3.caused_by_ship_id GROUP BY T1.id HAVING sum(T3.killed) > 10 +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What is the ship id and name that caused most total injuries? +# +### SQL: +# +# SELECT T2.id , T2.name FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id GROUP BY T2.id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What are the distinct battle names which are between bulgarian commander 'Kaloyan' and latin commander 'Baldwin I'? +# +### SQL: +# +# SELECT name FROM battle WHERE bulgarian_commander = 'Kaloyan' AND latin_commander = 'Baldwin I' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# How many different results are there for the battles? +# +### SQL: +# +# SELECT count(DISTINCT RESULT) FROM battle +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# How many battles did not lose any ship with tonnage '225'? +# +### SQL: +# +# SELECT count(*) FROM battle WHERE id NOT IN ( SELECT lost_in_battle FROM ship WHERE tonnage = '225' ); +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# List the name and date the battle that has lost the ship named 'Lettice' and the ship named 'HMS Atalanta' +# +### SQL: +# +# SELECT T1.name , T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name , T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# Show names, results and bulgarian commanders of the battles with no ships lost in the 'English Channel'. +# +### SQL: +# +# SELECT name , RESULT , bulgarian_commander FROM battle EXCEPT SELECT T1.name , T1.result , T1.bulgarian_commander FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.location = 'English Channel' +# +### End. +" +battle_death,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# battle ( id, name, date, bulgarian_commander, latin_commander, result ) +# ship ( lost_in_battle, id, name, tonnage, ship_type, location, disposition_of_ship ) +# death ( caused_by_ship_id, id, note, killed, injured ) +# +# ship.lost_in_battle can be joined with battle.id +# death.caused_by_ship_id can be joined with ship.id +# +### Question: +# +# What are the notes of the death events which has substring 'East'? +# +### SQL: +# +# SELECT note FROM death WHERE note LIKE '%East%' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# what are all the addresses including line 1 and line 2? +# +### SQL: +# +# SELECT line_1 , line_2 FROM addresses +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the first and second line for all addresses? +# +### SQL: +# +# SELECT line_1 , line_2 FROM addresses +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many courses in total are listed? +# +### SQL: +# +# SELECT count(*) FROM Courses +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many courses are there? +# +### SQL: +# +# SELECT count(*) FROM Courses +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How is the math course described? +# +### SQL: +# +# SELECT course_description FROM Courses WHERE course_name = 'math' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the descriptions for all the math courses? +# +### SQL: +# +# SELECT course_description FROM Courses WHERE course_name = 'math' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the zip code of the address in the city Port Chelsea? +# +### SQL: +# +# SELECT zip_postcode FROM Addresses WHERE city = 'Port Chelsea' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the zip code for Port Chelsea? +# +### SQL: +# +# SELECT zip_postcode FROM Addresses WHERE city = 'Port Chelsea' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Which department offers the most number of degrees? List department name and id. +# +### SQL: +# +# SELECT T2.department_name , T1.department_id FROM Degree_Programs AS T1 JOIN Departments AS T2 ON T1.department_id = T2.department_id GROUP BY T1.department_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the name and id of the department with the most number of degrees ? +# +### SQL: +# +# select t2.department_name , t1.department_id from degree_programs as t1 join departments as t2 on t1.department_id = t2.department_id group by t1.department_id order by count(*) desc limit 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many departments offer any degree? +# +### SQL: +# +# SELECT count(DISTINCT department_id) FROM Degree_Programs +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many different departments offer degrees? +# +### SQL: +# +# SELECT count(DISTINCT department_id) FROM Degree_Programs +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many different degree names are offered? +# +### SQL: +# +# SELECT count(DISTINCT degree_summary_name) FROM Degree_Programs +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many different degrees are offered? +# +### SQL: +# +# SELECT count(DISTINCT degree_summary_name) FROM Degree_Programs +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many degrees does the engineering department offer? +# +### SQL: +# +# SELECT count(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many degrees does the engineering department have? +# +### SQL: +# +# SELECT count(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the names and descriptions of all the sections? +# +### SQL: +# +# SELECT section_name , section_description FROM Sections +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the names and descriptions for all the sections? +# +### SQL: +# +# SELECT section_name , section_description FROM Sections +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the names and id of courses having at most 2 sections? +# +### SQL: +# +# SELECT T1.course_name , T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING count(*) <= 2 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the names and ids of every course with less than 2 sections? +# +### SQL: +# +# SELECT T1.course_name , T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING count(*) <= 2 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# List the section_name in reversed lexicographical order. +# +### SQL: +# +# SELECT section_name FROM Sections ORDER BY section_name DESC +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the names of the sections in reverse alphabetical order? +# +### SQL: +# +# SELECT section_name FROM Sections ORDER BY section_name DESC +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the semester which most student registered in? Show both the name and the id. +# +### SQL: +# +# SELECT T1.semester_name , T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# For each semester, what is the name and id of the one with the most students registered? +# +### SQL: +# +# SELECT T1.semester_name , T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the description of the department whose name has the substring the computer? +# +### SQL: +# +# SELECT department_description FROM Departments WHERE department_name LIKE '%computer%' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the department description for the one whose name has the word computer? +# +### SQL: +# +# SELECT department_description FROM Departments WHERE department_name LIKE '%computer%' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Who are enrolled in 2 degree programs in one semester? List the first name, middle name and last name and the id. +# +### SQL: +# +# SELECT T1.first_name , T1.middle_name , T1.last_name , T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING count(*) = 2 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the first, middle, and last names, along with the ids, of all students who enrolled in 2 degree programs in one semester? +# +### SQL: +# +# SELECT T1.first_name , T1.middle_name , T1.last_name , T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING count(*) = 2 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Who is enrolled in a Bachelor degree program? List the first name, middle name, last name. +# +### SQL: +# +# SELECT DISTINCT T1.first_name , T1.middle_name , T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the first, middle, and last names for everybody enrolled in a Bachelors program? +# +### SQL: +# +# SELECT DISTINCT T1.first_name , T1.middle_name , T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Find the kind of program which most number of students are enrolled in? +# +### SQL: +# +# SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the degree summary name that has the most number of students enrolled? +# +### SQL: +# +# SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Find the program which most number of students are enrolled in. List both the id and the summary. +# +### SQL: +# +# SELECT T1.degree_program_id , T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the program id and the summary of the degree that has the most students enrolled? +# +### SQL: +# +# SELECT T1.degree_program_id , T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Which student has enrolled for the most times in any program? List the id, first name, middle name, last name, the number of enrollments and student id. +# +### SQL: +# +# SELECT T1.student_id , T1.first_name , T1.middle_name , T1.last_name , count(*) , T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the first, middle, and last name, along with the id and number of enrollments, for the student who enrolled the most in any program? +# +### SQL: +# +# SELECT T1.student_id , T1.first_name , T1.middle_name , T1.last_name , count(*) , T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Which semesters do not have any student enrolled? List the semester name. +# +### SQL: +# +# SELECT semester_name FROM Semesters WHERE semester_id NOT IN( SELECT semester_id FROM Student_Enrolment ) +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the name of the semester with no students enrolled? +# +### SQL: +# +# SELECT semester_name FROM Semesters WHERE semester_id NOT IN( SELECT semester_id FROM Student_Enrolment ) +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are all the course names of the courses which ever have students enrolled in? +# +### SQL: +# +# SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the names of all courses that have some students enrolled? +# +### SQL: +# +# SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What's the name of the course with most number of enrollments? +# +### SQL: +# +# SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the name of the course with the most students enrolled? +# +### SQL: +# +# SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Find the last name of the students who currently live in the state of North Carolina but have not registered in any degree program. +# +### SQL: +# +# SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the last name of the students who live in North Carolina but have not registered in any degree programs? +# +### SQL: +# +# SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Show the date and id of the transcript with at least 2 course results. +# +### SQL: +# +# SELECT T2.transcript_date , T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING count(*) >= 2 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the date and id of the transcript with at least 2 courses listed? +# +### SQL: +# +# SELECT T2.transcript_date , T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING count(*) >= 2 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the phone number of the man with the first name Timmothy and the last name Ward? +# +### SQL: +# +# SELECT cell_mobile_number FROM Students WHERE first_name = 'Timmothy' AND last_name = 'Ward' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the mobile phone number of the student named Timmothy Ward ? +# +### SQL: +# +# select cell_mobile_number from students where first_name = 'timmothy' and last_name = 'ward' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Who is the first student to register? List the first name, middle name and last name. +# +### SQL: +# +# SELECT first_name , middle_name , last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the first, middle, and last name of the first student to register? +# +### SQL: +# +# SELECT first_name , middle_name , last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Who is the earliest graduate of the school? List the first name, middle name and last name. +# +### SQL: +# +# SELECT first_name , middle_name , last_name FROM Students ORDER BY date_left ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the first, middle, and last name of the earliest school graduate? +# +### SQL: +# +# SELECT first_name , middle_name , last_name FROM Students ORDER BY date_left ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Whose permanent address is different from his or her current address? List his or her first name. +# +### SQL: +# +# SELECT first_name FROM Students WHERE current_address_id != permanent_address_id +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the first name of the student whose permanent address is different from his or her current one? +# +### SQL: +# +# SELECT first_name FROM Students WHERE current_address_id != permanent_address_id +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Which address holds the most number of students currently? List the address id and all lines. +# +### SQL: +# +# SELECT T1.address_id , T1.line_1 , T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the id, line 1, and line 2 of the address with the most students? +# +### SQL: +# +# SELECT T1.address_id , T1.line_1 , T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# On average, when were the transcripts printed? +# +### SQL: +# +# SELECT avg(transcript_date) FROM Transcripts +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the average transcript date? +# +### SQL: +# +# SELECT avg(transcript_date) FROM Transcripts +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# When is the first transcript released? List the date and details. +# +### SQL: +# +# SELECT transcript_date , other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the earliest date of a transcript release, and what details can you tell me? +# +### SQL: +# +# SELECT transcript_date , other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many transcripts are released? +# +### SQL: +# +# SELECT count(*) FROM Transcripts +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many transcripts are listed? +# +### SQL: +# +# SELECT count(*) FROM Transcripts +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the last transcript release date? +# +### SQL: +# +# SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# When was the last transcript released? +# +### SQL: +# +# SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many times at most can a course enrollment result show in different transcripts? Also show the course enrollment id. +# +### SQL: +# +# SELECT count(*) , student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the maximum number of times that a course shows up in different transcripts and what is that course's enrollment id? +# +### SQL: +# +# SELECT count(*) , student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Show the date of the transcript which shows the least number of results, also list the id. +# +### SQL: +# +# SELECT T2.transcript_date , T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY count(*) ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the date and id of the transcript with the least number of results? +# +### SQL: +# +# SELECT T2.transcript_date , T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY count(*) ASC LIMIT 1 +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Find the semester when both Master students and Bachelor students got enrolled in. +# +### SQL: +# +# SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the id of the semester that had both Masters and Bachelors students enrolled? +# +### SQL: +# +# SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# How many different addresses do the students currently live? +# +### SQL: +# +# SELECT count(DISTINCT current_address_id) FROM Students +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the different addresses that have students living there? +# +### SQL: +# +# SELECT count(DISTINCT current_address_id) FROM Students +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# List all the student details in reversed lexicographical order. +# +### SQL: +# +# SELECT other_student_details FROM Students ORDER BY other_student_details DESC +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What other details can you tell me about students in reverse alphabetical order? +# +### SQL: +# +# SELECT other_student_details FROM Students ORDER BY other_student_details DESC +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Describe the section h. +# +### SQL: +# +# SELECT section_description FROM Sections WHERE section_name = 'h' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What is the description for the section named h? +# +### SQL: +# +# SELECT section_description FROM Sections WHERE section_name = 'h' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# Find the first name of the students who permanently live in the country Haiti or have the cell phone number 09700166582 . +# +### SQL: +# +# select t1.first_name from students as t1 join addresses as t2 on t1.permanent_address_id = t2.address_id where t2.country = 'haiti' or t1.cell_mobile_number = '09700166582' +# +### End. +" +student_transcripts_tracking,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Addresses ( address_id, line_1, line_2, line_3, city, zip_postcode, state_province_county, country, other_address_details ) +# Courses ( course_id, course_name, course_description, other_details ) +# Departments ( department_id, department_name, department_description, other_details ) +# Degree_Programs ( degree_program_id, department_id, degree_summary_name, degree_summary_description, other_details ) +# Sections ( section_id, course_id, section_name, section_description, other_details ) +# Semesters ( semester_id, semester_name, semester_description, other_details ) +# Students ( student_id, current_address_id, permanent_address_id, first_name, middle_name, last_name, cell_mobile_number, email_address, ssn, date_first_registered, date_left, other_student_details ) +# Student_Enrolment ( student_enrolment_id, degree_program_id, semester_id, student_id, other_details ) +# Student_Enrolment_Courses ( student_course_id, course_id, student_enrolment_id ) +# Transcripts ( transcript_id, transcript_date, other_details ) +# Transcript_Contents ( student_course_id, transcript_id ) +# +# Degree_Programs.department_id can be joined with Departments.department_id +# Sections.course_id can be joined with Courses.course_id +# Students.permanent_address_id can be joined with Addresses.address_id +# Students.current_address_id can be joined with Addresses.address_id +# Student_Enrolment.student_id can be joined with Students.student_id +# Student_Enrolment.semester_id can be joined with Semesters.semester_id +# Student_Enrolment.degree_program_id can be joined with Degree_Programs.degree_program_id +# Student_Enrolment_Courses.student_enrolment_id can be joined with Student_Enrolment.student_enrolment_id +# Student_Enrolment_Courses.course_id can be joined with Courses.course_id +# Transcript_Contents.transcript_id can be joined with Transcripts.transcript_id +# Transcript_Contents.student_course_id can be joined with Student_Enrolment_Courses.student_course_id +# +### Question: +# +# What are the first names of the students who live in Haiti permanently or have the cell phone number 09700166582 ? +# +### SQL: +# +# select t1.first_name from students as t1 join addresses as t2 on t1.permanent_address_id = t2.address_id where t2.country = 'haiti' or t1.cell_mobile_number = '09700166582' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the title of all cartoons in alphabetical order. +# +### SQL: +# +# SELECT Title FROM Cartoon ORDER BY title +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the titles of the cartoons sorted alphabetically? +# +### SQL: +# +# SELECT Title FROM Cartoon ORDER BY title +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List all cartoon directed by ""Ben Jones"". +# +### SQL: +# +# SELECT Title FROM Cartoon WHERE Directed_by = ""Ben Jones""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the names of all cartoons directed by Ben Jones? +# +### SQL: +# +# SELECT Title FROM Cartoon WHERE Directed_by = ""Ben Jones""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# How many cartoons were written by ""Joseph Kuhr""? +# +### SQL: +# +# SELECT count(*) FROM Cartoon WHERE Written_by = ""Joseph Kuhr""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the number of cartoones written by Joseph Kuhr? +# +### SQL: +# +# SELECT count(*) FROM Cartoon WHERE Written_by = ""Joseph Kuhr""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# list all cartoon titles and their directors ordered by their air date +# +### SQL: +# +# SELECT title , Directed_by FROM Cartoon ORDER BY Original_air_date +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the name and directors of all the cartoons that are ordered by air date? +# +### SQL: +# +# SELECT title , Directed_by FROM Cartoon ORDER BY Original_air_date +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the title of all cartoon directed by ""Ben Jones"" or ""Brandon Vietti"". +# +### SQL: +# +# SELECT Title FROM Cartoon WHERE Directed_by = ""Ben Jones"" OR Directed_by = ""Brandon Vietti""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the titles of all cartoons directed by Ben Jones or Brandon Vietti? +# +### SQL: +# +# SELECT Title FROM Cartoon WHERE Directed_by = ""Ben Jones"" OR Directed_by = ""Brandon Vietti""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# Which country has the most of TV Channels? List the country and number of TV Channels it has. +# +### SQL: +# +# SELECT Country , count(*) FROM TV_Channel GROUP BY Country ORDER BY count(*) DESC LIMIT 1; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the country with the most number of TV Channels and how many does it have? +# +### SQL: +# +# SELECT Country , count(*) FROM TV_Channel GROUP BY Country ORDER BY count(*) DESC LIMIT 1; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the number of different series names and contents in the TV Channel table. +# +### SQL: +# +# SELECT count(DISTINCT series_name) , count(DISTINCT content) FROM TV_Channel; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# How many different series and contents are listed in the TV Channel table? +# +### SQL: +# +# SELECT count(DISTINCT series_name) , count(DISTINCT content) FROM TV_Channel; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the content of TV Channel with serial name ""Sky Radio""? +# +### SQL: +# +# SELECT Content FROM TV_Channel WHERE series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the content of the series Sky Radio? +# +### SQL: +# +# SELECT Content FROM TV_Channel WHERE series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the Package Option of TV Channel with serial name ""Sky Radio""? +# +### SQL: +# +# SELECT Package_Option FROM TV_Channel WHERE series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the Package Options of the TV Channels whose series names are Sky Radio? +# +### SQL: +# +# SELECT Package_Option FROM TV_Channel WHERE series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# How many TV Channel using language English? +# +### SQL: +# +# SELECT count(*) FROM TV_Channel WHERE LANGUAGE = ""English""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# How many TV Channels use the English language? +# +### SQL: +# +# SELECT count(*) FROM TV_Channel WHERE LANGUAGE = ""English""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the language used least number of TV Channel. List language and number of TV Channel. +# +### SQL: +# +# SELECT LANGUAGE , count(*) FROM TV_Channel GROUP BY LANGUAGE ORDER BY count(*) ASC LIMIT 1; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the languages used by the least number of TV Channels and how many channels use it? +# +### SQL: +# +# SELECT LANGUAGE , count(*) FROM TV_Channel GROUP BY LANGUAGE ORDER BY count(*) ASC LIMIT 1; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List each language and the number of TV Channels using it. +# +### SQL: +# +# SELECT LANGUAGE , count(*) FROM TV_Channel GROUP BY LANGUAGE +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# For each language, list the number of TV Channels that use it. +# +### SQL: +# +# SELECT LANGUAGE , count(*) FROM TV_Channel GROUP BY LANGUAGE +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the TV Channel that shows the cartoon ""The Rise of the Blue Beetle!""? List the TV Channel's series name. +# +### SQL: +# +# SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = ""The Rise of the Blue Beetle!""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the series name of the TV Channel that shows the cartoon ""The Rise of the Blue Beetle""? +# +### SQL: +# +# SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = ""The Rise of the Blue Beetle!""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the title of all Cartoons showed on TV Channel with series name ""Sky Radio"". +# +### SQL: +# +# SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the title of all the cartools that are on the TV Channel with the series name ""Sky Radio""? +# +### SQL: +# +# SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the Episode of all TV series sorted by rating. +# +### SQL: +# +# SELECT Episode FROM TV_series ORDER BY rating +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are all of the episodes ordered by ratings? +# +### SQL: +# +# SELECT Episode FROM TV_series ORDER BY rating +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List top 3 highest Rating TV series. List the TV series's Episode and Rating. +# +### SQL: +# +# SELECT Episode , Rating FROM TV_series ORDER BY Rating DESC LIMIT 3; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are 3 most highly rated episodes in the TV series table and what were those ratings? +# +### SQL: +# +# SELECT Episode , Rating FROM TV_series ORDER BY Rating DESC LIMIT 3; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is minimum and maximum share of TV series? +# +### SQL: +# +# SELECT max(SHARE) , min(SHARE) FROM TV_series; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the maximum and minimum share for the TV series? +# +### SQL: +# +# SELECT max(SHARE) , min(SHARE) FROM TV_series; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the air date of TV series with Episode ""A Love of a Lifetime""? +# +### SQL: +# +# SELECT Air_Date FROM TV_series WHERE Episode = ""A Love of a Lifetime""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# When did the episode ""A Love of a Lifetime"" air? +# +### SQL: +# +# SELECT Air_Date FROM TV_series WHERE Episode = ""A Love of a Lifetime""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is Weekly Rank of TV series with Episode ""A Love of a Lifetime""? +# +### SQL: +# +# SELECT Weekly_Rank FROM TV_series WHERE Episode = ""A Love of a Lifetime""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the weekly rank for the episode ""A Love of a Lifetime""? +# +### SQL: +# +# SELECT Weekly_Rank FROM TV_series WHERE Episode = ""A Love of a Lifetime""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the TV Channel of TV series with Episode ""A Love of a Lifetime""? List the TV Channel's series name. +# +### SQL: +# +# SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = ""A Love of a Lifetime""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the name of the series that has the episode ""A Love of a Lifetime""? +# +### SQL: +# +# SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = ""A Love of a Lifetime""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# List the Episode of all TV series showed on TV Channel with series name ""Sky Radio"". +# +### SQL: +# +# SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the episode for the TV series named ""Sky Radio""? +# +### SQL: +# +# SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = ""Sky Radio""; +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# Find the number of cartoons directed by each of the listed directors. +# +### SQL: +# +# SELECT count(*) , Directed_by FROM cartoon GROUP BY Directed_by +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# How many cartoons did each director create? +# +### SQL: +# +# SELECT count(*) , Directed_by FROM cartoon GROUP BY Directed_by +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# Find the production code and channel of the most recently aired cartoon . +# +### SQL: +# +# select production_code , channel from cartoon order by original_air_date desc limit 1 +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the produdction code and channel of the most recent cartoon ? +# +### SQL: +# +# select production_code , channel from cartoon order by original_air_date desc limit 1 +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# Find the package choice and series name of the TV channel that has high definition TV. +# +### SQL: +# +# SELECT package_option , series_name FROM TV_Channel WHERE hight_definition_TV = ""yes"" +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the package options and the name of the series for the TV Channel that supports high definition TV? +# +### SQL: +# +# SELECT package_option , series_name FROM TV_Channel WHERE hight_definition_TV = ""yes"" +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# which countries' tv channels are playing some cartoon written by Todd Casey? +# +### SQL: +# +# SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the countries that have cartoons on TV that were written by Todd Casey? +# +### SQL: +# +# SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# which countries' tv channels are not playing any cartoon written by Todd Casey? +# +### SQL: +# +# SELECT country FROM TV_Channel EXCEPT SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the countries that are not playing cartoons written by Todd Casey? +# +### SQL: +# +# SELECT country FROM TV_Channel EXCEPT SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# Find the series name and country of the tv channel that is playing some cartoons directed by Ben Jones and Michael Chang? +# +### SQL: +# +# SELECT T1.series_name , T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name , T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the series name and country of all TV channels that are playing cartoons directed by Ben Jones and cartoons directed by Michael Chang? +# +### SQL: +# +# SELECT T1.series_name , T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name , T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# find the pixel aspect ratio and nation of the tv channels that do not use English. +# +### SQL: +# +# SELECT Pixel_aspect_ratio_PAR , country FROM tv_channel WHERE LANGUAGE != 'English' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What is the pixel aspect ratio and country of origin for all TV channels that do not use English? +# +### SQL: +# +# SELECT Pixel_aspect_ratio_PAR , country FROM tv_channel WHERE LANGUAGE != 'English' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# find id of the tv channels that from the countries where have more than two tv channels. +# +### SQL: +# +# SELECT id FROM tv_channel GROUP BY country HAVING count(*) > 2 +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the ids of all tv channels that have more than 2 TV channels? +# +### SQL: +# +# SELECT id FROM tv_channel GROUP BY country HAVING count(*) > 2 +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# find the id of tv channels that do not play any cartoon directed by Ben Jones. +# +### SQL: +# +# SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the ids of the TV channels that do not have any cartoons directed by Ben Jones? +# +### SQL: +# +# SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones' +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# find the package option of the tv channel that do not have any cartoon directed by Ben Jones. +# +### SQL: +# +# SELECT package_option FROM TV_Channel WHERE id NOT IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones') +# +### End. +" +tvshow,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# TV_Channel ( id, series_name, Country, Language, Content, Pixel_aspect_ratio_PAR, Hight_definition_TV, Pay_per_view_PPV, Package_Option ) +# TV_series ( id, Episode, Air_Date, Rating, Share, 18_49_Rating_Share, Viewers_m, Weekly_Rank, Channel ) +# Cartoon ( id, Title, Directed_by, Written_by, Original_air_date, Production_code, Channel ) +# +# TV_series.Channel can be joined with TV_Channel.id +# Cartoon.Channel can be joined with TV_Channel.id +# +### Question: +# +# What are the package options of all tv channels that are not playing any cartoons directed by Ben Jones? +# +### SQL: +# +# SELECT package_option FROM TV_Channel WHERE id NOT IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones') +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# How many poker players are there? +# +### SQL: +# +# SELECT count(*) FROM poker_player +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Count the number of poker players. +# +### SQL: +# +# SELECT count(*) FROM poker_player +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# List the earnings of poker players in descending order. +# +### SQL: +# +# SELECT Earnings FROM poker_player ORDER BY Earnings DESC +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the earnings of poker players, ordered descending by value? +# +### SQL: +# +# SELECT Earnings FROM poker_player ORDER BY Earnings DESC +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# List the final tables made and the best finishes of poker players. +# +### SQL: +# +# SELECT Final_Table_Made , Best_Finish FROM poker_player +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the final tables made and best finishes for all poker players? +# +### SQL: +# +# SELECT Final_Table_Made , Best_Finish FROM poker_player +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the average earnings of poker players? +# +### SQL: +# +# SELECT avg(Earnings) FROM poker_player +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the average earnings across all poker players. +# +### SQL: +# +# SELECT avg(Earnings) FROM poker_player +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the money rank of the poker player with the highest earnings? +# +### SQL: +# +# SELECT Money_Rank FROM poker_player ORDER BY Earnings DESC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the money rank of the player with the greatest earnings. +# +### SQL: +# +# SELECT Money_Rank FROM poker_player ORDER BY Earnings DESC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the maximum number of final tables made among poker players with earnings less than 200000? +# +### SQL: +# +# SELECT max(Final_Table_Made) FROM poker_player WHERE Earnings < 200000 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the maximum final tables made across all poker players who have earnings below 200000. +# +### SQL: +# +# SELECT max(Final_Table_Made) FROM poker_player WHERE Earnings < 200000 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names of poker players? +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the names of all the poker players. +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names of poker players whose earnings is higher than 300000? +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Give the names of poker players who have earnings above 300000. +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# List the names of poker players ordered by the final tables made in ascending order. +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names of poker players, ordered ascending by the number of final tables they have made? +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the birth date of the poker player with the lowest earnings? +# +### SQL: +# +# SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the birth date of the poker player with the lowest earnings. +# +### SQL: +# +# SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the money rank of the tallest poker player? +# +### SQL: +# +# SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the money rank of the poker player with the greatest height. +# +### SQL: +# +# SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the average earnings of poker players with height higher than 200? +# +### SQL: +# +# SELECT avg(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Give average earnings of poker players who are taller than 200. +# +### SQL: +# +# SELECT avg(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names of poker players in descending order of earnings? +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the names of poker players sorted by their earnings descending. +# +### SQL: +# +# SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are different nationalities of people and the corresponding number of people from each nation? +# +### SQL: +# +# SELECT Nationality , COUNT(*) FROM people GROUP BY Nationality +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# How many people are there of each nationality? +# +### SQL: +# +# SELECT Nationality , COUNT(*) FROM people GROUP BY Nationality +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What is the most common nationality of people? +# +### SQL: +# +# SELECT Nationality FROM people GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Give the nationality that is most common across all people. +# +### SQL: +# +# SELECT Nationality FROM people GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the nationalities that are shared by at least two people? +# +### SQL: +# +# SELECT Nationality FROM people GROUP BY Nationality HAVING COUNT(*) >= 2 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Return the nationalities for which there are two or more people. +# +### SQL: +# +# SELECT Nationality FROM people GROUP BY Nationality HAVING COUNT(*) >= 2 +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# List the names and birth dates of people in ascending alphabetical order of name. +# +### SQL: +# +# SELECT Name , Birth_Date FROM people ORDER BY Name ASC +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names and birth dates of people, ordered by their names in alphabetical order? +# +### SQL: +# +# SELECT Name , Birth_Date FROM people ORDER BY Name ASC +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Show names of people whose nationality is not ""Russia"". +# +### SQL: +# +# SELECT Name FROM people WHERE Nationality != ""Russia"" +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names of people who are not from Russia? +# +### SQL: +# +# SELECT Name FROM people WHERE Nationality != ""Russia"" +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# List the names of people that are not poker players. +# +### SQL: +# +# SELECT Name FROM people WHERE People_ID NOT IN (SELECT People_ID FROM poker_player) +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# What are the names of people who do not play poker? +# +### SQL: +# +# SELECT Name FROM people WHERE People_ID NOT IN (SELECT People_ID FROM poker_player) +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# How many distinct nationalities are there? +# +### SQL: +# +# SELECT count(DISTINCT Nationality) FROM people +# +### End. +" +poker_player,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# poker_player ( Poker_Player_ID, People_ID, Final_Table_Made, Best_Finish, Money_Rank, Earnings ) +# people ( People_ID, Nationality, Name, Birth_Date, Height ) +# +# poker_player.People_ID can be joined with people.People_ID +# +### Question: +# +# Count the number of different nationalities. +# +### SQL: +# +# SELECT count(DISTINCT Nationality) FROM people +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# How many states are there? +# +### SQL: +# +# SELECT count(*) FROM area_code_state +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# List the contestant numbers and names, ordered by contestant name descending. +# +### SQL: +# +# SELECT contestant_number , contestant_name FROM contestants ORDER BY contestant_name DESC +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# List the vote ids, phone numbers and states of all votes. +# +### SQL: +# +# SELECT vote_id , phone_number , state FROM votes +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What are the maximum and minimum values of area codes? +# +### SQL: +# +# SELECT max(area_code) , min(area_code) FROM area_code_state +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What is last date created of votes from the state 'CA'? +# +### SQL: +# +# SELECT max(created) FROM votes WHERE state = 'CA' +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What are the names of the contestants whose names are not 'Jessie Alloway' +# +### SQL: +# +# SELECT contestant_name FROM contestants WHERE contestant_name != 'Jessie Alloway' +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What are the distinct states and create time of all votes? +# +### SQL: +# +# SELECT DISTINCT state , created FROM votes +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What are the contestant numbers and names of the contestants who had at least two votes? +# +### SQL: +# +# SELECT T1.contestant_number , T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number HAVING count(*) >= 2 +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# Of all the contestants who got voted, what is the contestant number and name of the contestant who got least votes? +# +### SQL: +# +# SELECT T1.contestant_number , T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number ORDER BY count(*) ASC LIMIT 1 +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What are the number of votes from state 'NY' or 'CA'? +# +### SQL: +# +# SELECT count(*) FROM votes WHERE state = 'NY' OR state = 'CA' +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# How many contestants did not get voted? +# +### SQL: +# +# SELECT count(*) FROM contestants WHERE contestant_number NOT IN ( SELECT contestant_number FROM votes ) +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What is the area code in which the most voters voted? +# +### SQL: +# +# SELECT T1.area_code FROM area_code_state AS T1 JOIN votes AS T2 ON T1.state = T2.state GROUP BY T1.area_code ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# What are the create dates, states, and phone numbers of the votes that were for the contestant named 'Tabatha Gehling'? +# +### SQL: +# +# SELECT T2.created , T2.state , T2.phone_number FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T1.contestant_name = 'Tabatha Gehling' +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# List the area codes in which voters voted both for the contestant 'Tabatha Gehling' and the contestant 'Kelly Clauss'. +# +### SQL: +# +# SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Kelly Clauss' +# +### End. +" +voter_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# AREA_CODE_STATE ( area_code, state ) +# CONTESTANTS ( contestant_number, contestant_name ) +# VOTES ( vote_id, phone_number, state, contestant_number, created ) +# +# VOTES.contestant_number can be joined with CONTESTANTS.contestant_number +# VOTES.state can be joined with AREA_CODE_STATE.state +# +### Question: +# +# Return the names of the contestants whose names contain the substring 'Al' . +# +### SQL: +# +# select contestant_name from contestants where contestant_name like ""%al%"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of all the countries that became independent after 1950? +# +### SQL: +# +# SELECT Name FROM country WHERE IndepYear > 1950 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the names of the nations that were founded after 1950. +# +### SQL: +# +# SELECT Name FROM country WHERE IndepYear > 1950 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many countries have a republic as their form of government? +# +### SQL: +# +# SELECT count(*) FROM country WHERE GovernmentForm = ""Republic"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many countries have governments that are republics? +# +### SQL: +# +# SELECT count(*) FROM country WHERE GovernmentForm = ""Republic"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total surface area of the countries in the Caribbean region? +# +### SQL: +# +# SELECT sum(SurfaceArea) FROM country WHERE Region = ""Caribbean"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How much surface area do the countires in the Carribean cover together? +# +### SQL: +# +# SELECT sum(SurfaceArea) FROM country WHERE Region = ""Caribbean"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which continent is Anguilla in? +# +### SQL: +# +# SELECT Continent FROM country WHERE Name = ""Anguilla"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the continent name which Anguilla belongs to? +# +### SQL: +# +# SELECT Continent FROM country WHERE Name = ""Anguilla"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which region is the city Kabul located in? +# +### SQL: +# +# SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = ""Kabul"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What region is Kabul in? +# +### SQL: +# +# SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = ""Kabul"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which language is the most popular in Aruba? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = ""Aruba"" ORDER BY Percentage DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What language is predominantly spoken in Aruba? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = ""Aruba"" ORDER BY Percentage DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the population and life expectancies in Brazil? +# +### SQL: +# +# SELECT Population , LifeExpectancy FROM country WHERE Name = ""Brazil"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give me Brazil’s population and life expectancies. +# +### SQL: +# +# SELECT Population , LifeExpectancy FROM country WHERE Name = ""Brazil"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the region and population of Angola? +# +### SQL: +# +# SELECT Population , Region FROM country WHERE Name = ""Angola"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What region does Angola belong to and what is its population? +# +### SQL: +# +# SELECT Population , Region FROM country WHERE Name = ""Angola"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the average expected life expectancy for countries in the region of Central Africa? +# +### SQL: +# +# SELECT avg(LifeExpectancy) FROM country WHERE Region = ""Central Africa"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How long is the people’s average life expectancy in Central Africa? +# +### SQL: +# +# SELECT avg(LifeExpectancy) FROM country WHERE Region = ""Central Africa"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the name of country that has the shortest life expectancy in Asia? +# +### SQL: +# +# SELECT Name FROM country WHERE Continent = ""Asia"" ORDER BY LifeExpectancy LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the name of the country in Asia with the lowest life expectancy. +# +### SQL: +# +# SELECT Name FROM country WHERE Continent = ""Asia"" ORDER BY LifeExpectancy LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total population and maximum GNP in Asia? +# +### SQL: +# +# SELECT sum(Population) , max(GNP) FROM country WHERE Continent = ""Asia"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many people live in Asia, and what is the largest GNP among them? +# +### SQL: +# +# SELECT sum(Population) , max(GNP) FROM country WHERE Continent = ""Asia"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the average life expectancy in African countries that are republics? +# +### SQL: +# +# SELECT avg(LifeExpectancy) FROM country WHERE Continent = ""Africa"" AND GovernmentForm = ""Republic"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the average life expectancy for countries in Africa which are republics? +# +### SQL: +# +# SELECT avg(LifeExpectancy) FROM country WHERE Continent = ""Africa"" AND GovernmentForm = ""Republic"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total surface area of the continents Asia and Europe? +# +### SQL: +# +# SELECT sum(SurfaceArea) FROM country WHERE Continent = ""Asia"" OR Continent = ""Europe"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the total surface area covered by countries in Asia or Europe. +# +### SQL: +# +# SELECT sum(SurfaceArea) FROM country WHERE Continent = ""Asia"" OR Continent = ""Europe"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many people live in Gelderland district? +# +### SQL: +# +# SELECT sum(Population) FROM city WHERE District = ""Gelderland"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total population of Gelderland district? +# +### SQL: +# +# SELECT sum(Population) FROM city WHERE District = ""Gelderland"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the average GNP and total population in all nations whose government is US territory? +# +### SQL: +# +# SELECT avg(GNP) , sum(population) FROM country WHERE GovernmentForm = ""US Territory"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the mean GNP and total population of nations which are considered US territory. +# +### SQL: +# +# SELECT avg(GNP) , sum(population) FROM country WHERE GovernmentForm = ""US Territory"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many unique languages are spoken in the world? +# +### SQL: +# +# SELECT count(DISTINCT LANGUAGE) FROM countrylanguage +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the number of distinct languages used around the world? +# +### SQL: +# +# SELECT count(DISTINCT LANGUAGE) FROM countrylanguage +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many type of governments are in Africa? +# +### SQL: +# +# SELECT count(DISTINCT GovernmentForm) FROM country WHERE Continent = ""Africa"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many different forms of governments are there in Africa? +# +### SQL: +# +# SELECT count(DISTINCT GovernmentForm) FROM country WHERE Continent = ""Africa"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total number of languages used in Aruba? +# +### SQL: +# +# SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = ""Aruba"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many languages are spoken in Aruba? +# +### SQL: +# +# SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = ""Aruba"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many official languages does Afghanistan have? +# +### SQL: +# +# SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = ""Afghanistan"" AND IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many official languages are spoken in Afghanistan? +# +### SQL: +# +# SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = ""Afghanistan"" AND IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is name of the country that speaks the largest number of languages? +# +### SQL: +# +# SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the name of the nation that uses the greatest amount of languages. +# +### SQL: +# +# SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which continent has the most diverse languages? +# +### SQL: +# +# SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which continent speaks the most languages? +# +### SQL: +# +# SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many countries speak both English and Dutch? +# +### SQL: +# +# SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""Dutch"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the number of nations that use English and Dutch? +# +### SQL: +# +# SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""Dutch"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of nations speak both English and French? +# +### SQL: +# +# SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""French"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the names of nations that speak both English and French. +# +### SQL: +# +# SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""French"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of nations where both English and French are official languages? +# +### SQL: +# +# SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" AND T2.IsOfficial = ""T"" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""French"" AND T2.IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the names of countries with English and French as official languages. +# +### SQL: +# +# SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" AND T2.IsOfficial = ""T"" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""French"" AND T2.IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the number of distinct continents where Chinese is spoken? +# +### SQL: +# +# SELECT COUNT( DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""Chinese"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many continents speak Chinese? +# +### SQL: +# +# SELECT COUNT( DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""Chinese"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the regions that use English or Dutch? +# +### SQL: +# +# SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" OR T2.Language = ""Dutch"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which regions speak Dutch or English? +# +### SQL: +# +# SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" OR T2.Language = ""Dutch"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the countries where either English or Dutch is the official language ? +# +### SQL: +# +# select t1.name from country as t1 join countrylanguage as t2 on t1.code = t2.countrycode where t2.language = ""english"" and isofficial = ""t"" union select t1.name from country as t1 join countrylanguage as t2 on t1.code = t2.countrycode where t2.language = ""dutch"" and isofficial = ""t"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which countries have either English or Dutch as an official language? +# +### SQL: +# +# SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" AND IsOfficial = ""T"" UNION SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""Dutch"" AND IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which language is the most popular on the Asian continent? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = ""Asia"" GROUP BY T2.Language ORDER BY COUNT (*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the language that is used by the largest number of Asian nations? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = ""Asia"" GROUP BY T2.Language ORDER BY COUNT (*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which languages are spoken by only one country in republic governments? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = ""Republic"" GROUP BY T2.Language HAVING COUNT(*) = 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What languages are only used by a single country with a republic government? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = ""Republic"" GROUP BY T2.Language HAVING COUNT(*) = 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Find the city with the largest population that uses English. +# +### SQL: +# +# SELECT T1.Name , T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = ""English"" ORDER BY T1.Population DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the most populace city that speaks English? +# +### SQL: +# +# SELECT T1.Name , T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = ""English"" ORDER BY T1.Population DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Find the name, population and expected life length of asian country with the largest area? +# +### SQL: +# +# SELECT Name , Population , LifeExpectancy FROM country WHERE Continent = ""Asia"" ORDER BY SurfaceArea DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the name, population, and life expectancy of the largest Asian country by land? +# +### SQL: +# +# SELECT Name , Population , LifeExpectancy FROM country WHERE Continent = ""Asia"" ORDER BY SurfaceArea DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is average life expectancy in the countries where English is not the official language? +# +### SQL: +# +# SELECT avg(LifeExpectancy) FROM country WHERE Name NOT IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" AND T2.IsOfficial = ""T"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the mean life expectancy of countries in which English is not the official language. +# +### SQL: +# +# SELECT avg(LifeExpectancy) FROM country WHERE Name NOT IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"" AND T2.IsOfficial = ""T"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total number of people living in the nations that do not use English? +# +### SQL: +# +# SELECT sum(Population) FROM country WHERE Name NOT IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many people live in countries that do not speak English? +# +### SQL: +# +# SELECT sum(Population) FROM country WHERE Name NOT IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = ""English"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the official language spoken in the country whose head of state is Beatrix? +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = ""Beatrix"" AND T2.IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the official language used in the country the name of whose head of state is Beatrix. +# +### SQL: +# +# SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = ""Beatrix"" AND T2.IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total number of unique official languages spoken in the countries that are founded before 1930? +# +### SQL: +# +# SELECT count(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# For the countries founded before 1930, what is the total number of distinct official languages? +# +### SQL: +# +# SELECT count(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = ""T"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the countries that have greater surface area than any country in Europe? +# +### SQL: +# +# SELECT Name FROM country WHERE SurfaceArea > (SELECT min(SurfaceArea) FROM country WHERE Continent = ""Europe"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which countries have greater area than that of any country in Europe? +# +### SQL: +# +# SELECT Name FROM country WHERE SurfaceArea > (SELECT min(SurfaceArea) FROM country WHERE Continent = ""Europe"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the African countries that have a population less than any country in Asia? +# +### SQL: +# +# SELECT Name FROM country WHERE Continent = ""Africa"" AND population < (SELECT max(population) FROM country WHERE Continent = ""Asia"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which African countries have a smaller population than that of any country in Asia? +# +### SQL: +# +# SELECT Name FROM country WHERE Continent = ""Africa"" AND population < (SELECT min(population) FROM country WHERE Continent = ""Asia"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which Asian countries have a population that is larger than any country in Africa? +# +### SQL: +# +# SELECT Name FROM country WHERE Continent = ""Asia"" AND population > (SELECT max(population) FROM country WHERE Continent = ""Africa"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the Asian countries which have a population larger than that of any country in Africa? +# +### SQL: +# +# SELECT Name FROM country WHERE Continent = ""Asia"" AND population > (SELECT min(population) FROM country WHERE Continent = ""Africa"") +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the country codes for countries that do not speak English? +# +### SQL: +# +# SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = ""English"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the country codes for countries that do not speak English. +# +### SQL: +# +# SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = ""English"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the country codes of countries where people use languages other than English? +# +### SQL: +# +# SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE != ""English"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the country codes for countries in which people speak langauges that are not English. +# +### SQL: +# +# SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE != ""English"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the codes of the countries that do not speak English and whose government forms are not Republic? +# +### SQL: +# +# SELECT Code FROM country WHERE GovernmentForm != ""Republic"" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = ""English"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the codes of countries that do not speak English and do not have Republics for governments. +# +### SQL: +# +# SELECT Code FROM country WHERE GovernmentForm != ""Republic"" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = ""English"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which cities are in European countries where English is not the official language? +# +### SQL: +# +# SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND T1.Name NOT IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English') +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of cities in Europe for which English is not the official language? +# +### SQL: +# +# SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND T1.Name NOT IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English') +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which unique cities are in Asian countries where Chinese is the official language ? +# +### SQL: +# +# select distinct t3.name from country as t1 join countrylanguage as t2 on t1.code = t2.countrycode join city as t3 on t1.code = t3.countrycode where t2.isofficial = 't' and t2.language = 'chinese' and t1.continent = ""asia"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the different names of cities that are in Asia and for which Chinese is the official language. +# +### SQL: +# +# SELECT DISTINCT T3.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode JOIN city AS T3 ON T1.Code = T3.CountryCode WHERE T2.IsOfficial = 'T' AND T2.Language = 'Chinese' AND T1.Continent = ""Asia"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the name, independence year, and surface area of the country with the smallest population? +# +### SQL: +# +# SELECT Name , SurfaceArea , IndepYear FROM country ORDER BY Population LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the name, year of independence, and surface area of the country that has the lowest population. +# +### SQL: +# +# SELECT Name , SurfaceArea , IndepYear FROM country ORDER BY Population LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the population, name and leader of the country with the largest area? +# +### SQL: +# +# SELECT Name , population , HeadOfState FROM country ORDER BY SurfaceArea DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the name, population, and head of state for the country that has the largest area. +# +### SQL: +# +# SELECT Name , population , HeadOfState FROM country ORDER BY SurfaceArea DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the country name and the numbers of languages spoken for each country that speaks at least 3 languages. +# +### SQL: +# +# SELECT COUNT(T2.Language) , T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of countries that speak more than 2 languages, as well as how many languages they speak? +# +### SQL: +# +# SELECT COUNT(T2.Language) , T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Find the number of cities in each district whose population is greater than the average population of cities? +# +### SQL: +# +# SELECT count(*) , District FROM city WHERE Population > (SELECT avg(Population) FROM city) GROUP BY District +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# How many cities in each district have a population that is above the average population across all cities? +# +### SQL: +# +# SELECT count(*) , District FROM city WHERE Population > (SELECT avg(Population) FROM city) GROUP BY District +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Find the government form name and total population for each government form whose average life expectancy is longer than 72. +# +### SQL: +# +# SELECT sum(Population) , GovernmentForm FROM country GROUP BY GovernmentForm HAVING avg(LifeExpectancy) > 72 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the different government forms and what is the total population of each for government forms that have an average life expectancy greater than 72? +# +### SQL: +# +# SELECT sum(Population) , GovernmentForm FROM country GROUP BY GovernmentForm HAVING avg(LifeExpectancy) > 72 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Find the average life expectancy and total population for each continent where the average life expectancy is shorter than 72? +# +### SQL: +# +# SELECT sum(Population) , avg(LifeExpectancy) , Continent FROM country GROUP BY Continent HAVING avg(LifeExpectancy) < 72 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the different continents and the total popuation and average life expectancy corresponding to each, for continents that have an average life expectancy less than 72? +# +### SQL: +# +# SELECT sum(Population) , avg(LifeExpectancy) , Continent FROM country GROUP BY Continent HAVING avg(LifeExpectancy) < 72 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names and areas of countries with the top 5 largest area? +# +### SQL: +# +# SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the names and surface areas of the 5 largest countries. +# +### SQL: +# +# SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are names of countries with the top 3 largest population? +# +### SQL: +# +# SELECT Name FROM country ORDER BY Population DESC LIMIT 3 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the names of the 3 most populated countries. +# +### SQL: +# +# SELECT Name FROM country ORDER BY Population DESC LIMIT 3 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of the nations with the 3 lowest populations? +# +### SQL: +# +# SELECT Name FROM country ORDER BY Population ASC LIMIT 3 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the names of the 3 countries with the fewest people. +# +### SQL: +# +# SELECT Name FROM country ORDER BY Population ASC LIMIT 3 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# how many countries are in Asia? +# +### SQL: +# +# SELECT count(*) FROM country WHERE continent = ""Asia"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Count the number of countries in Asia. +# +### SQL: +# +# SELECT count(*) FROM country WHERE continent = ""Asia"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the names of the countries that are in the continent of Europe and have a population of 80000? +# +### SQL: +# +# SELECT Name FROM country WHERE continent = ""Europe"" AND Population = ""80000"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the names of countries that are in Europe and have a population equal to 80000. +# +### SQL: +# +# SELECT Name FROM country WHERE continent = ""Europe"" AND Population = ""80000"" +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total population and average area of countries in the continent of North America whose area is bigger than 3000 ? +# +### SQL: +# +# select sum(population) , avg(surfacearea) from country where continent = ""north america"" and surfacearea > 3000 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000 . +# +### SQL: +# +# select sum(population) , avg(surfacearea) from country where continent = ""north america"" and surfacearea > 3000 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the cities whose population is between 160000 and 900000? +# +### SQL: +# +# SELECT name FROM city WHERE Population BETWEEN 160000 AND 900000 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the names of cities that have a population between 160000 and 900000 . +# +### SQL: +# +# select name from city where population between 160000 and 900000 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Which language is spoken by the largest number of countries? +# +### SQL: +# +# SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Give the language that is spoken in the most countries. +# +### SQL: +# +# SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the language spoken by the largest percentage of people in each country? +# +### SQL: +# +# SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each? +# +### SQL: +# +# SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What is the total number of countries where Spanish is spoken by the largest percentage of people? +# +### SQL: +# +# SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = ""Spanish"" GROUP BY CountryCode +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Count the number of countries for which Spanish is the predominantly spoken language. +# +### SQL: +# +# SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = ""Spanish"" GROUP BY CountryCode +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# What are the codes of countries where Spanish is spoken by the largest percentage of people? +# +### SQL: +# +# SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = ""Spanish"" GROUP BY CountryCode +# +### End. +" +world_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# city ( ID, Name, CountryCode, District, Population ) +# sqlite_sequence ( name, seq ) +# country ( Code, Name, Continent, Region, SurfaceArea, IndepYear, Population, LifeExpectancy, GNP, GNPOld, LocalName, GovernmentForm, HeadOfState, Capital, Code2 ) +# countrylanguage ( CountryCode, Language, IsOfficial, Percentage ) +# +# city.CountryCode can be joined with country.Code +# countrylanguage.CountryCode can be joined with country.Code +# +### Question: +# +# Return the codes of countries for which Spanish is the predominantly spoken language. +# +### SQL: +# +# SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = ""Spanish"" GROUP BY CountryCode +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# How many conductors are there? +# +### SQL: +# +# SELECT count(*) FROM conductor +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Count the number of conductors. +# +### SQL: +# +# SELECT count(*) FROM conductor +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# List the names of conductors in ascending order of age. +# +### SQL: +# +# SELECT Name FROM conductor ORDER BY Age ASC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the names of conductors, ordered by age? +# +### SQL: +# +# SELECT Name FROM conductor ORDER BY Age ASC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the names of conductors whose nationalities are not ""USA""? +# +### SQL: +# +# SELECT Name FROM conductor WHERE Nationality != 'USA' +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Return the names of conductors that do not have the nationality ""USA"". +# +### SQL: +# +# SELECT Name FROM conductor WHERE Nationality != 'USA' +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the record companies of orchestras in descending order of years in which they were founded? +# +### SQL: +# +# SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Return the record companies of orchestras, sorted descending by the years in which they were founded. +# +### SQL: +# +# SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What is the average attendance of shows? +# +### SQL: +# +# SELECT avg(Attendance) FROM SHOW +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Return the average attendance across all shows. +# +### SQL: +# +# SELECT avg(Attendance) FROM SHOW +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the maximum and minimum share of performances whose type is not ""Live final"". +# +### SQL: +# +# SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != ""Live final"" +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Return the maximum and minimum shares for performances that do not have the type ""Live final"". +# +### SQL: +# +# SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != ""Live final"" +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# How many different nationalities do conductors have? +# +### SQL: +# +# SELECT count(DISTINCT Nationality) FROM conductor +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Count the number of different nationalities of conductors. +# +### SQL: +# +# SELECT count(DISTINCT Nationality) FROM conductor +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# List names of conductors in descending order of years of work. +# +### SQL: +# +# SELECT Name FROM conductor ORDER BY Year_of_Work DESC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the names of conductors, sorted descending by the number of years they have worked? +# +### SQL: +# +# SELECT Name FROM conductor ORDER BY Year_of_Work DESC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# List the name of the conductor with the most years of work. +# +### SQL: +# +# SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What is the name of the conductor who has worked the greatest number of years? +# +### SQL: +# +# SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Show the names of conductors and the orchestras they have conducted. +# +### SQL: +# +# SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the names of conductors as well as the corresonding orchestras that they have conducted? +# +### SQL: +# +# SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Show the names of conductors that have conducted more than one orchestras. +# +### SQL: +# +# SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the names of conductors who have conducted at more than one orchestra? +# +### SQL: +# +# SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Show the name of the conductor that has conducted the most number of orchestras. +# +### SQL: +# +# SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What is the name of the conductor who has conducted the most orchestras? +# +### SQL: +# +# SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Please show the name of the conductor that has conducted orchestras founded after 2008. +# +### SQL: +# +# SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the names of conductors who have conducted orchestras founded after the year 2008? +# +### SQL: +# +# SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Please show the different record companies and the corresponding number of orchestras. +# +### SQL: +# +# SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# How many orchestras does each record company manage? +# +### SQL: +# +# SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Please show the record formats of orchestras in ascending order of count. +# +### SQL: +# +# SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the major record formats of orchestras, sorted by their frequency? +# +### SQL: +# +# SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# List the record company shared by the most number of orchestras. +# +### SQL: +# +# SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What is the record company used by the greatest number of orchestras? +# +### SQL: +# +# SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# List the names of orchestras that have no performance. +# +### SQL: +# +# SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance) +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the orchestras that do not have any performances? +# +### SQL: +# +# SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance) +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Show the record companies shared by orchestras founded before 2003 and after 2003. +# +### SQL: +# +# SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003? +# +### SQL: +# +# SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Find the number of orchestras whose record format is ""CD"" or ""DVD"". +# +### SQL: +# +# SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = ""CD"" OR Major_Record_Format = ""DVD"" +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Count the number of orchestras that have CD or DVD as their record format. +# +### SQL: +# +# SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = ""CD"" OR Major_Record_Format = ""DVD"" +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# Show the years in which orchestras that have given more than one performance are founded. +# +### SQL: +# +# SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 +# +### End. +" +orchestra,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# conductor ( Conductor_ID, Name, Age, Nationality, Year_of_Work ) +# orchestra ( Orchestra_ID, Orchestra, Conductor_ID, Record_Company, Year_of_Founded, Major_Record_Format ) +# performance ( Performance_ID, Orchestra_ID, Type, Date, Official_ratings_(millions), Weekly_rank, Share ) +# show ( Show_ID, Performance_ID, If_first_show, Result, Attendance ) +# +# orchestra.Conductor_ID can be joined with conductor.Conductor_ID +# performance.Orchestra_ID can be joined with orchestra.Orchestra_ID +# show.Performance_ID can be joined with performance.Performance_ID +# +### Question: +# +# What are years of founding for orchestras that have had more than a single performance? +# +### SQL: +# +# SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many high schoolers are there? +# +### SQL: +# +# SELECT count(*) FROM Highschooler +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Count the number of high schoolers. +# +### SQL: +# +# SELECT count(*) FROM Highschooler +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names and grades of each high schooler. +# +### SQL: +# +# SELECT name , grade FROM Highschooler +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names and grades for each high schooler? +# +### SQL: +# +# SELECT name , grade FROM Highschooler +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show all the grades of the high schoolers. +# +### SQL: +# +# SELECT grade FROM Highschooler +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What is the grade of each high schooler? +# +### SQL: +# +# SELECT grade FROM Highschooler +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What grade is Kyle in? +# +### SQL: +# +# SELECT grade FROM Highschooler WHERE name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Return the grade for the high schooler named Kyle. +# +### SQL: +# +# SELECT grade FROM Highschooler WHERE name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of all high schoolers in grade 10. +# +### SQL: +# +# SELECT name FROM Highschooler WHERE grade = 10 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of all high schoolers in grade 10? +# +### SQL: +# +# SELECT name FROM Highschooler WHERE grade = 10 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the ID of the high schooler named Kyle. +# +### SQL: +# +# SELECT ID FROM Highschooler WHERE name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What is Kyle's id? +# +### SQL: +# +# SELECT ID FROM Highschooler WHERE name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many high schoolers are there in grade 9 or 10? +# +### SQL: +# +# SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Count the number of high schoolers in grades 9 or 10. +# +### SQL: +# +# SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the number of high schoolers for each grade. +# +### SQL: +# +# SELECT grade , count(*) FROM Highschooler GROUP BY grade +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many high schoolers are in each grade? +# +### SQL: +# +# SELECT grade , count(*) FROM Highschooler GROUP BY grade +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Which grade has the most high schoolers? +# +### SQL: +# +# SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Return the grade that has the greatest number of high schoolers. +# +### SQL: +# +# SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show me all grades that have at least 4 students. +# +### SQL: +# +# SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Which grades have 4 or more high schoolers? +# +### SQL: +# +# SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the student IDs and numbers of friends corresponding to each. +# +### SQL: +# +# SELECT student_id , count(*) FROM Friend GROUP BY student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many friends does each student have? +# +### SQL: +# +# SELECT student_id , count(*) FROM Friend GROUP BY student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of high school students and their corresponding number of friends. +# +### SQL: +# +# SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of the high schoolers and how many friends does each have? +# +### SQL: +# +# SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What is the name of the high schooler who has the greatest number of friends? +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Return the name of the high school student with the most friends. +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of high schoolers who have at least 3 friends. +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of high schoolers who have 3 or more friends? +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of all of the high schooler Kyle's friends. +# +### SQL: +# +# SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Return the names of friends of the high school student Kyle. +# +### SQL: +# +# SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many friends does the high school student Kyle have? +# +### SQL: +# +# SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Count the number of friends Kyle has. +# +### SQL: +# +# SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show ids of all students who do not have any friends. +# +### SQL: +# +# SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the ids of high school students who do not have friends? +# +### SQL: +# +# SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show names of all high school students who do not have any friends. +# +### SQL: +# +# SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of students who have no friends? +# +### SQL: +# +# SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the ids of high schoolers who have friends and are also liked by someone else. +# +### SQL: +# +# SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the ids of students who both have friends and are liked? +# +### SQL: +# +# SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show name of all students who have some friends and also are liked by someone else. +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of high schoolers who both have friends and are liked? +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Count the number of likes for each student id. +# +### SQL: +# +# SELECT student_id , count(*) FROM Likes GROUP BY student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many likes correspond to each student id? +# +### SQL: +# +# SELECT student_id , count(*) FROM Likes GROUP BY student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of high schoolers who have likes, and numbers of likes for each. +# +### SQL: +# +# SELECT T2.name , count(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of high schoolers who have likes, and how many likes does each have? +# +### SQL: +# +# SELECT T2.name , count(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What is the name of the high schooler who has the greatest number of likes? +# +### SQL: +# +# SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Give the name of the student with the most likes. +# +### SQL: +# +# SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of students who have at least 2 likes. +# +### SQL: +# +# SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 2 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of students who have 2 or more likes? +# +### SQL: +# +# SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 2 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Show the names of students who have a grade higher than 5 and have at least 2 friends. +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING count(*) >= 2 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What are the names of high schoolers who have a grade of over 5 and have 2 or more friends? +# +### SQL: +# +# SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING count(*) >= 2 +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# How many likes does Kyle have? +# +### SQL: +# +# SELECT count(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Return the number of likes that the high schooler named Kyle has. +# +### SQL: +# +# SELECT count(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = ""Kyle"" +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Find the average grade of all students who have some friends. +# +### SQL: +# +# SELECT avg(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What is the average grade of students who have friends? +# +### SQL: +# +# SELECT avg(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# Find the minimum grade of students who have no friends. +# +### SQL: +# +# SELECT min(grade) FROM Highschooler WHERE id NOT IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) +# +### End. +" +network_1,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Highschooler ( ID, name, grade ) +# Friend ( student_id, friend_id ) +# Likes ( student_id, liked_id ) +# +# Friend.friend_id can be joined with Highschooler.ID +# Friend.student_id can be joined with Highschooler.ID +# Likes.student_id can be joined with Highschooler.ID +# Likes.liked_id can be joined with Highschooler.ID +# +### Question: +# +# What is the lowest grade of students who do not have any friends? +# +### SQL: +# +# SELECT min(grade) FROM Highschooler WHERE id NOT IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which states have both owners and professionals living there? +# +### SQL: +# +# SELECT state FROM Owners INTERSECT SELECT state FROM Professionals +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the states where both owners and professionals live. +# +### SQL: +# +# SELECT state FROM Owners INTERSECT SELECT state FROM Professionals +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What is the average age of the dogs who have gone through any treatments? +# +### SQL: +# +# SELECT avg(age) FROM Dogs WHERE dog_id IN ( SELECT dog_id FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the average age of the dogs who went through treatments. +# +### SQL: +# +# SELECT avg(age) FROM Dogs WHERE dog_id IN ( SELECT dog_id FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which professionals live in the state of Indiana or have done treatment on more than 2 treatments? List his or her id, last name and cell phone. +# +### SQL: +# +# SELECT professional_id , last_name , cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id , T1.last_name , T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING count(*) > 2 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the id, last name and cell phone of the professionals who live in the state of Indiana or have performed more than two treatments. +# +### SQL: +# +# SELECT professional_id , last_name , cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id , T1.last_name , T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING count(*) > 2 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which dogs have not cost their owner more than 1000 for treatment ? List the dog names . +# +### SQL: +# +# select name from dogs where dog_id not in ( select dog_id from treatments group by dog_id having sum(cost_of_treatment) > 1000 ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the names of the dogs for which the owner has not spend more than 1000 for treatment ? +# +### SQL: +# +# select name from dogs where dog_id not in ( select dog_id from treatments group by dog_id having sum(cost_of_treatment) > 1000 ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which first names are used for professionals or owners but are not used as dog names? +# +### SQL: +# +# SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the first names that are used for professionals or owners but are not used as dog names. +# +### SQL: +# +# SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which professional did not operate any treatment on dogs? List the professional's id, role and email. +# +### SQL: +# +# SELECT professional_id , role_code , email_address FROM Professionals EXCEPT SELECT T1.professional_id , T1.role_code , T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Give me the id, role and email of the professionals who did not perform any treatment on dogs. +# +### SQL: +# +# SELECT professional_id , role_code , email_address FROM Professionals EXCEPT SELECT T1.professional_id , T1.role_code , T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which owner owns the most dogs? List the owner id, first name and last name. +# +### SQL: +# +# SELECT T1.owner_id , T2.first_name , T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Return the owner id, first name and last name of the owner who has the most dogs. +# +### SQL: +# +# SELECT T1.owner_id , T2.first_name , T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which professionals have done at least two treatments? List the professional's id, role, and first name. +# +### SQL: +# +# SELECT T1.professional_id , T1.role_code , T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING count(*) >= 2 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the id, role, and first name of the professionals who have performed two or more treatments? +# +### SQL: +# +# SELECT T1.professional_id , T1.role_code , T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING count(*) >= 2 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What is the name of the breed with the most dogs? +# +### SQL: +# +# SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which breed do the most dogs have? Give me the breed name. +# +### SQL: +# +# SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which owner has paid for the most treatments on his or her dogs? List the owner id and last name. +# +### SQL: +# +# SELECT T1.owner_id , T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Tell me the owner id and last name of the owner who spent the most on treatments of his or her dogs. +# +### SQL: +# +# SELECT T1.owner_id , T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY count(*) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What is the description of the treatment type that costs the least money in total? +# +### SQL: +# +# SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY sum(cost_of_treatment) ASC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Give me the description of the treatment type whose total cost is the lowest. +# +### SQL: +# +# SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY sum(cost_of_treatment) ASC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which owner has paid the largest amount of money in total for their dogs? Show the owner id and zip code. +# +### SQL: +# +# SELECT T1.owner_id , T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY sum(T3.cost_of_treatment) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the owner id and zip code of the owner who spent the most money in total for his or her dogs. +# +### SQL: +# +# SELECT T1.owner_id , T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY sum(T3.cost_of_treatment) DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which professionals have done at least two types of treatments? List the professional id and cell phone. +# +### SQL: +# +# SELECT T1.professional_id , T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING count(*) >= 2 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the id and cell phone of the professionals who operate two or more types of treatments. +# +### SQL: +# +# SELECT T1.professional_id , T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING count(*) >= 2 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the first name and last name of the professionals who have done treatment with cost below average? +# +### SQL: +# +# SELECT DISTINCT T1.first_name , T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 WHERE cost_of_treatment < ( SELECT avg(cost_of_treatment) FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which professionals have operated a treatment that costs less than the average? Give me theor first names and last names. +# +### SQL: +# +# SELECT DISTINCT T1.first_name , T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 WHERE cost_of_treatment < ( SELECT avg(cost_of_treatment) FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the date of each treatment, together with the first name of the professional who operated it. +# +### SQL: +# +# SELECT T1.date_of_treatment , T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the date and the operating professional's first name of each treatment? +# +### SQL: +# +# SELECT T1.date_of_treatment , T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the cost of each treatment and the corresponding treatment type description. +# +### SQL: +# +# SELECT T1.cost_of_treatment , T2.treatment_type_description FROM Treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the cost and treatment type description of each treatment? +# +### SQL: +# +# SELECT T1.cost_of_treatment , T2.treatment_type_description FROM Treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List each owner's first name, last name, and the size of his for her dog. +# +### SQL: +# +# SELECT T1.first_name , T1.last_name , T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are each owner's first name, last name, and the size of their dog? +# +### SQL: +# +# SELECT T1.first_name , T1.last_name , T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List pairs of the owner's first name and the dogs's name. +# +### SQL: +# +# SELECT T1.first_name , T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are each owner's first name and their dogs's name? +# +### SQL: +# +# SELECT T1.first_name , T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the names of the dogs of the rarest breed and the treatment dates of them. +# +### SQL: +# +# SELECT T1.name , T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = ( SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY count(*) ASC LIMIT 1 ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which dogs are of the rarest breed? Show their names and treatment dates. +# +### SQL: +# +# SELECT T1.name , T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = ( SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY count(*) ASC LIMIT 1 ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which dogs are owned by someone who lives in Virginia? List the owner's first name and the dog's name. +# +### SQL: +# +# SELECT T1.first_name , T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the first names of owners living in Virginia and the names of dogs they own. +# +### SQL: +# +# SELECT T1.first_name , T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the arriving date and the departing date of the dogs who have gone through a treatment? +# +### SQL: +# +# SELECT DISTINCT T1.date_arrived , T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the arriving date and the departing date of the dogs that received a treatment. +# +### SQL: +# +# SELECT DISTINCT T1.date_arrived , T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the last name of the owner owning the youngest dog. +# +### SQL: +# +# SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = ( SELECT max(age) FROM Dogs ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Who owns the youngest dog? Give me his or her last name. +# +### SQL: +# +# SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = ( SELECT max(age) FROM Dogs ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the emails of the professionals who live in the state of Hawaii or the state of Wisconsin. +# +### SQL: +# +# SELECT email_address FROM Professionals WHERE state = 'Hawaii' OR state = 'Wisconsin' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the emails of the professionals living in either the state of Hawaii or the state of Wisconsin? +# +### SQL: +# +# SELECT email_address FROM Professionals WHERE state = 'Hawaii' OR state = 'Wisconsin' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the arriving date and the departing date of all the dogs? +# +### SQL: +# +# SELECT date_arrived , date_departed FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the arrival date and the departure date for all the dogs. +# +### SQL: +# +# SELECT date_arrived , date_departed FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How many dogs went through any treatments? +# +### SQL: +# +# SELECT count(DISTINCT dog_id) FROM Treatments +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Count the number of dogs that went through a treatment. +# +### SQL: +# +# SELECT count(DISTINCT dog_id) FROM Treatments +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How many professionals have performed any treatment to dogs? +# +### SQL: +# +# SELECT count(DISTINCT professional_id) FROM Treatments +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the number of professionals who have ever treated dogs. +# +### SQL: +# +# SELECT count(DISTINCT professional_id) FROM Treatments +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which professionals live in a city containing the substring 'West'? List his or her role, street, city and state. +# +### SQL: +# +# SELECT role_code , street , city , state FROM professionals WHERE city LIKE '%West%' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the role, street, city and state of the professionals living in a city that contains the substring 'West'. +# +### SQL: +# +# SELECT role_code , street , city , state FROM professionals WHERE city LIKE '%West%' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Which owners live in the state whose name contains the substring 'North'? List his first name, last name and email. +# +### SQL: +# +# SELECT first_name , last_name , email_address FROM Owners WHERE state LIKE '%North%' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Return the first name, last name and email of the owners living in a state whose name contains the substring 'North'. +# +### SQL: +# +# SELECT first_name , last_name , email_address FROM Owners WHERE state LIKE '%North%' +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How many dogs have an age below the average? +# +### SQL: +# +# SELECT count(*) FROM Dogs WHERE age < ( SELECT avg(age) FROM Dogs ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Count the number of dogs of an age below the average. +# +### SQL: +# +# SELECT count(*) FROM Dogs WHERE age < ( SELECT avg(age) FROM Dogs ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How much does the most recent treatment cost? +# +### SQL: +# +# SELECT cost_of_treatment FROM Treatments ORDER BY date_of_treatment DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Show me the cost of the most recently performed treatment. +# +### SQL: +# +# SELECT cost_of_treatment FROM Treatments ORDER BY date_of_treatment DESC LIMIT 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How many dogs have not gone through any treatment? +# +### SQL: +# +# SELECT count(*) FROM Dogs WHERE dog_id NOT IN ( SELECT dog_id FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Tell me the number of dogs that have not received any treatment . +# +### SQL: +# +# select count(*) from dogs where dog_id not in ( select dog_id from treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How many owners temporarily do not have any dogs? +# +### SQL: +# +# SELECT count(*) FROM Owners WHERE owner_id NOT IN ( SELECT owner_id FROM Dogs ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the number of owners who do not own any dogs at this moment. +# +### SQL: +# +# SELECT count(*) FROM Owners WHERE owner_id NOT IN ( SELECT owner_id FROM Dogs ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How many professionals did not operate any treatment on dogs? +# +### SQL: +# +# SELECT count(*) FROM Professionals WHERE professional_id NOT IN ( SELECT professional_id FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the number of professionals who have not treated any dogs. +# +### SQL: +# +# SELECT count(*) FROM Professionals WHERE professional_id NOT IN ( SELECT professional_id FROM Treatments ) +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the dog name, age and weight of the dogs who have been abandoned? 1 stands for yes, and 0 stands for no. +# +### SQL: +# +# SELECT name , age , weight FROM Dogs WHERE abandoned_yn = 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the dog name, age and weight of the dogs that were abandoned? Note that 1 stands for yes, and 0 stands for no in the tables. +# +### SQL: +# +# SELECT name , age , weight FROM Dogs WHERE abandoned_yn = 1 +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What is the average age of all the dogs? +# +### SQL: +# +# SELECT avg(age) FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Compute the average age of all the dogs. +# +### SQL: +# +# SELECT avg(age) FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What is the age of the oldest dog? +# +### SQL: +# +# SELECT max(age) FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Tell me the age of the oldest dog. +# +### SQL: +# +# SELECT max(age) FROM Dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How much does each charge type costs? List both charge type and amount. +# +### SQL: +# +# SELECT charge_type , charge_amount FROM Charges +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List each charge type and its amount. +# +### SQL: +# +# SELECT charge_type , charge_amount FROM Charges +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# How much does the most expensive charge type costs? +# +### SQL: +# +# SELECT max(charge_amount) FROM Charges +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What is the charge amount of the most expensive charge type? +# +### SQL: +# +# SELECT max(charge_amount) FROM Charges +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the email, cell phone and home phone of all the professionals. +# +### SQL: +# +# SELECT email_address , cell_number , home_phone FROM professionals +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are the email, cell phone and home phone of each professional? +# +### SQL: +# +# SELECT email_address , cell_number , home_phone FROM professionals +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are all the possible breed type and size type combinations? +# +### SQL: +# +# SELECT DISTINCT breed_code , size_code FROM dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# Find the distinct breed type and size type combinations for dogs. +# +### SQL: +# +# SELECT DISTINCT breed_code , size_code FROM dogs +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# List the first name of all the professionals along with the description of the treatment they have done. +# +### SQL: +# +# SELECT DISTINCT T1.first_name , T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code +# +### End. +" +dog_kennels,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Breeds ( breed_code, breed_name ) +# Charges ( charge_id, charge_type, charge_amount ) +# Sizes ( size_code, size_description ) +# Treatment_Types ( treatment_type_code, treatment_type_description ) +# Owners ( owner_id, first_name, last_name, street, city, state, zip_code, email_address, home_phone, cell_number ) +# Dogs ( dog_id, owner_id, abandoned_yn, breed_code, size_code, name, age, date_of_birth, gender, weight, date_arrived, date_adopted, date_departed ) +# Professionals ( professional_id, role_code, first_name, street, city, state, zip_code, last_name, email_address, home_phone, cell_number ) +# Treatments ( treatment_id, dog_id, professional_id, treatment_type_code, date_of_treatment, cost_of_treatment ) +# +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.owner_id can be joined with Owners.owner_id +# Dogs.size_code can be joined with Sizes.size_code +# Dogs.breed_code can be joined with Breeds.breed_code +# Treatments.dog_id can be joined with Dogs.dog_id +# Treatments.professional_id can be joined with Professionals.professional_id +# Treatments.treatment_type_code can be joined with Treatment_Types.treatment_type_code +# +### Question: +# +# What are each professional's first name and description of the treatment they have performed? +# +### SQL: +# +# SELECT DISTINCT T1.first_name , T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# How many singers are there? +# +### SQL: +# +# SELECT count(*) FROM singer +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What is the count of singers? +# +### SQL: +# +# SELECT count(*) FROM singer +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# List the name of singers in ascending order of net worth. +# +### SQL: +# +# SELECT Name FROM singer ORDER BY Net_Worth_Millions ASC +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the names of singers ordered by ascending net worth? +# +### SQL: +# +# SELECT Name FROM singer ORDER BY Net_Worth_Millions ASC +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the birth year and citizenship of singers? +# +### SQL: +# +# SELECT Birth_Year , Citizenship FROM singer +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the birth years and citizenships of the singers? +# +### SQL: +# +# SELECT Birth_Year , Citizenship FROM singer +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# List the name of singers whose citizenship is not ""France"". +# +### SQL: +# +# SELECT Name FROM singer WHERE Citizenship != ""France"" +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the names of the singers who are not French citizens? +# +### SQL: +# +# SELECT Name FROM singer WHERE Citizenship != ""France"" +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show the name of singers whose birth year is either 1948 or 1949? +# +### SQL: +# +# SELECT Name FROM singer WHERE Birth_Year = 1948 OR Birth_Year = 1949 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the names of the singers whose birth years are either 1948 or 1949? +# +### SQL: +# +# SELECT Name FROM singer WHERE Birth_Year = 1948 OR Birth_Year = 1949 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What is the name of the singer with the largest net worth? +# +### SQL: +# +# SELECT Name FROM singer ORDER BY Net_Worth_Millions DESC LIMIT 1 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What is the name of the singer who is worth the most? +# +### SQL: +# +# SELECT Name FROM singer ORDER BY Net_Worth_Millions DESC LIMIT 1 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show different citizenship of singers and the number of singers of each citizenship. +# +### SQL: +# +# SELECT Citizenship , COUNT(*) FROM singer GROUP BY Citizenship +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# For each citizenship, how many singers are from that country? +# +### SQL: +# +# SELECT Citizenship , COUNT(*) FROM singer GROUP BY Citizenship +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Please show the most common citizenship of singers. +# +### SQL: +# +# SELECT Citizenship FROM singer GROUP BY Citizenship ORDER BY COUNT(*) DESC LIMIT 1 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What is the most common singer citizenship ? +# +### SQL: +# +# select citizenship from singer group by citizenship order by count(*) desc limit 1 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show different citizenships and the maximum net worth of singers of each citizenship. +# +### SQL: +# +# SELECT Citizenship , max(Net_Worth_Millions) FROM singer GROUP BY Citizenship +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# For each citizenship, what is the maximum net worth? +# +### SQL: +# +# SELECT Citizenship , max(Net_Worth_Millions) FROM singer GROUP BY Citizenship +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show titles of songs and names of singers. +# +### SQL: +# +# SELECT T2.Title , T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the song titles and singer names? +# +### SQL: +# +# SELECT T2.Title , T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show distinct names of singers that have songs with sales more than 300000. +# +### SQL: +# +# SELECT DISTINCT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T2.Sales > 300000 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# what are the different names of the singers that have sales more than 300000? +# +### SQL: +# +# SELECT DISTINCT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T2.Sales > 300000 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show the names of singers that have more than one song. +# +### SQL: +# +# SELECT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name HAVING COUNT(*) > 1 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the names of the singers that have more than one songs? +# +### SQL: +# +# SELECT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name HAVING COUNT(*) > 1 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show the names of singers and the total sales of their songs. +# +### SQL: +# +# SELECT T1.Name , sum(T2.Sales) FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# For each singer name, what is the total sales for their songs? +# +### SQL: +# +# SELECT T1.Name , sum(T2.Sales) FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# List the name of singers that do not have any song. +# +### SQL: +# +# SELECT Name FROM singer WHERE Singer_ID NOT IN (SELECT Singer_ID FROM song) +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What is the sname of every sing that does not have any song? +# +### SQL: +# +# SELECT Name FROM singer WHERE Singer_ID NOT IN (SELECT Singer_ID FROM song) +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# Show the citizenship shared by singers with birth year before 1945 and after 1955. +# +### SQL: +# +# SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955 +# +### End. +" +singer,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# singer ( Singer_ID, Name, Birth_Year, Net_Worth_Millions, Citizenship ) +# song ( Song_ID, Title, Singer_ID, Sales, Highest_Position ) +# +# song.Singer_ID can be joined with singer.Singer_ID +# +### Question: +# +# What are the citizenships that are shared by singers with a birth year before 1945 and after 1955? +# +### SQL: +# +# SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955 +# +### End. +" +real_estate_properties,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Feature_Types ( feature_type_code, feature_type_name ) +# Ref_Property_Types ( property_type_code, property_type_description ) +# Other_Available_Features ( feature_id, feature_type_code, feature_name, feature_description ) +# Properties ( property_id, property_type_code, date_on_market, date_sold, property_name, property_address, room_count, vendor_requested_price, buyer_offered_price, agreed_selling_price, apt_feature_1, apt_feature_2, apt_feature_3, fld_feature_1, fld_feature_2, fld_feature_3, hse_feature_1, hse_feature_2, hse_feature_3, oth_feature_1, oth_feature_2, oth_feature_3, shp_feature_1, shp_feature_2, shp_feature_3, other_property_details ) +# Other_Property_Features ( property_id, feature_id, property_feature_description ) +# +# Other_Available_Features.feature_type_code can be joined with Ref_Feature_Types.feature_type_code +# Properties.property_type_code can be joined with Ref_Property_Types.property_type_code +# Other_Property_Features.property_id can be joined with Properties.property_id +# Other_Property_Features.feature_id can be joined with Other_Available_Features.feature_id +# +### Question: +# +# How many available features are there in total? +# +### SQL: +# +# SELECT count(*) FROM Other_Available_Features +# +### End. +" +real_estate_properties,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Feature_Types ( feature_type_code, feature_type_name ) +# Ref_Property_Types ( property_type_code, property_type_description ) +# Other_Available_Features ( feature_id, feature_type_code, feature_name, feature_description ) +# Properties ( property_id, property_type_code, date_on_market, date_sold, property_name, property_address, room_count, vendor_requested_price, buyer_offered_price, agreed_selling_price, apt_feature_1, apt_feature_2, apt_feature_3, fld_feature_1, fld_feature_2, fld_feature_3, hse_feature_1, hse_feature_2, hse_feature_3, oth_feature_1, oth_feature_2, oth_feature_3, shp_feature_1, shp_feature_2, shp_feature_3, other_property_details ) +# Other_Property_Features ( property_id, feature_id, property_feature_description ) +# +# Other_Available_Features.feature_type_code can be joined with Ref_Feature_Types.feature_type_code +# Properties.property_type_code can be joined with Ref_Property_Types.property_type_code +# Other_Property_Features.property_id can be joined with Properties.property_id +# Other_Property_Features.feature_id can be joined with Other_Available_Features.feature_id +# +### Question: +# +# What is the feature type name of feature AirCon? +# +### SQL: +# +# SELECT T2.feature_type_name FROM Other_Available_Features AS T1 JOIN Ref_Feature_Types AS T2 ON T1.feature_type_code = T2.feature_type_code WHERE T1.feature_name = ""AirCon"" +# +### End. +" +real_estate_properties,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Feature_Types ( feature_type_code, feature_type_name ) +# Ref_Property_Types ( property_type_code, property_type_description ) +# Other_Available_Features ( feature_id, feature_type_code, feature_name, feature_description ) +# Properties ( property_id, property_type_code, date_on_market, date_sold, property_name, property_address, room_count, vendor_requested_price, buyer_offered_price, agreed_selling_price, apt_feature_1, apt_feature_2, apt_feature_3, fld_feature_1, fld_feature_2, fld_feature_3, hse_feature_1, hse_feature_2, hse_feature_3, oth_feature_1, oth_feature_2, oth_feature_3, shp_feature_1, shp_feature_2, shp_feature_3, other_property_details ) +# Other_Property_Features ( property_id, feature_id, property_feature_description ) +# +# Other_Available_Features.feature_type_code can be joined with Ref_Feature_Types.feature_type_code +# Properties.property_type_code can be joined with Ref_Property_Types.property_type_code +# Other_Property_Features.property_id can be joined with Properties.property_id +# Other_Property_Features.feature_id can be joined with Other_Available_Features.feature_id +# +### Question: +# +# Show the property type descriptions of properties belonging to that code. +# +### SQL: +# +# SELECT T2.property_type_description FROM Properties AS T1 JOIN Ref_Property_Types AS T2 ON T1.property_type_code = T2.property_type_code GROUP BY T1.property_type_code +# +### End. +" +real_estate_properties,"### Complete SQL query only and with no explanation +### SQL tables followed by foreign key information: +# +# Ref_Feature_Types ( feature_type_code, feature_type_name ) +# Ref_Property_Types ( property_type_code, property_type_description ) +# Other_Available_Features ( feature_id, feature_type_code, feature_name, feature_description ) +# Properties ( property_id, property_type_code, date_on_market, date_sold, property_name, property_address, room_count, vendor_requested_price, buyer_offered_price, agreed_selling_price, apt_feature_1, apt_feature_2, apt_feature_3, fld_feature_1, fld_feature_2, fld_feature_3, hse_feature_1, hse_feature_2, hse_feature_3, oth_feature_1, oth_feature_2, oth_feature_3, shp_feature_1, shp_feature_2, shp_feature_3, other_property_details ) +# Other_Property_Features ( property_id, feature_id, property_feature_description ) +# +# Other_Available_Features.feature_type_code can be joined with Ref_Feature_Types.feature_type_code +# Properties.property_type_code can be joined with Ref_Property_Types.property_type_code +# Other_Property_Features.property_id can be joined with Properties.property_id +# Other_Property_Features.feature_id can be joined with Other_Available_Features.feature_id +# +### Question: +# +# What are the names of properties that are either houses or apartments with more than 1 room? +# +### SQL: +# +# SELECT property_name FROM Properties WHERE property_type_code = ""House"" UNION SELECT property_name FROM Properties WHERE property_type_code = ""Apartment"" AND room_count > 1 +# +### End. +"