id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__MD1POtXllUkXc0zk | If 0.3 of a number is equal to 0.06 of another number, the ratio of the numbers i Choices
A) 3 : 15 B) 1 : 2 C) 3 : 20 D) 20 : 3 E) none | <gadget id="calculator">0.06 * 100</gadget>
<output>6</output>
<gadget id="calculator">0.3 * 100</gadget>
<output>30</output>
<gadget id="calculator">6 / 30</gadget>
<output>1/5 = around 0.2</output>
<result>A</result> | A | 0.2 | If 0.3 of a number is equal to 0.06 of another number, the ratio of the numbers i | {
"A": "3 : 15",
"B": "1 : 2",
"C": "3 : 20",
"D": "20 : 3",
"E": "none"
} | divide(multiply(0.06, const_100), multiply(0.3, const_100)) | multiply(n1,const_100)|multiply(n0,const_100)|divide(#0,#1)| | "sol . 0.3 a = 0.06 b â ‡ ” a / b = 0.06 / 0.30 = 6 / 30 = 3 / 15 . â ˆ ´ a : b = 3 : 15 . answer a" | other |
math_qa__deUKaeEYhPqZLN9U | A person crosses a 1800 m long street in 12 minutes. What is his speed in km per hour?
Choose the correct choice from the following
A) 4.1 B) 4.5 C) 4.8 D) 5.4 E) 9 | <gadget id="calculator">1_800 / 1_000</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">12 * 60</gadget>
<output>720</output>
<gadget id="calculator">720 / 3_600</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(9/5) / (1/5)</gadget>
<output>9</output>
<result>E</result> | E | 9 | A person crosses a 1800 m long street in 12 minutes. What is his speed in km per hour? | {
"A": "4.1",
"B": "4.5",
"C": "4.8",
"D": "5.4",
"E": "9"
} | divide(divide(1800, const_1000), divide(multiply(12, const_60), const_3600)) | divide(n0,const_1000)|multiply(n1,const_60)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 1800 / ( 12 x 60 ) m / sec = 2.5 m / sec . converting m / sec to km / hr = 2.5 x ( 18 / 5 ) km / hr = 9 km / hr . answer : e" | physics |
math_qa__0IgZrqDpptancNvF | A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates C apply to what fraction of a week?
Choose the correct answer:
A) 1 / 2 B) 5 / 8 C) 9 / 14 D) 16 / 21 E) 9 / 10 | <gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">60 + 48</gadget>
<output>108</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">24 * 7</gadget>
<output>168</output>
<gadget id="calculator">108 / 168</gadget>
<output>9/14 = around 0.642857</output>
<result>C</result> | C | 0.642857 | A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates C apply to what fraction of a week? | {
"A": "1 / 2",
"B": "5 / 8",
"C": "9 / 14",
"D": "16 / 21",
"E": "9 / 10"
} | divide(add(multiply(divide(24, const_2), add(const_2, const_3)), multiply(24, const_2)), multiply(24, add(const_3, const_4))) | add(const_2,const_3)|add(const_3,const_4)|divide(n2,const_2)|multiply(n2,const_2)|multiply(#0,#2)|multiply(n2,#1)|add(#4,#3)|divide(#6,#5)| | "number of hours between 8 pm to 8 am = 12 number of hours with reduced rates = ( 12 * 5 ) + ( 24 * 2 ) hours with reduced rates c / total number of hours in a week = ( 12 * 5 ) + ( 24 * 2 ) / ( 24 * 7 ) = 108 / ( 24 * 7 ) = 9 / 14 answer : c" | physics |
math_qa__teXI0VlGly9WoSnx | The distance from Steve's house to work is 35 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work? Choose the correct choice from the following options.
A) 5 . B) 10 . C) 14 . D) 15 . E) 17.5 | <gadget id="calculator">35 / 2</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">35 + (35/2)</gadget>
<output>105/2 = around 52.5</output>
<gadget id="calculator">(105/2) / 6</gadget>
<output>35/4 = around 8.75</output>
<gadget id="calculator">(35/4) * 2</gadget>
<output>35/2 = around 17.5</output>
<result>E</result> | E | 17.5 | The distance from Steve's house to work is 35 Km. On the way back Steve drives twice as fast as he did on the way to work. Altogether, Steve is spending 6 hours a day on the roads. What is Steve's speed on the way back from work? | {
"A": "5 .",
"B": "10 .",
"C": "14 .",
"D": "15 .",
"E": "17.5"
} | multiply(divide(add(35, divide(35, const_2)), 6), const_2) | divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|multiply(#2,const_2) | time is in the ratio 2 : 1 : : to : fro office therefore , 2 x + 1 x = 6 hrs time take to come back - 2 hrs , distance travelled - 35 km = > speed = 17.5 kmph e | physics |
math_qa__Yc2hluvguyjIn1zr | the dimensions of a room are 25 feet * 15 feet * 12 feet . what is the cost of white washing the 4 walls of the room at rs . 3 per square feet if there is one door of dimensions 6 feet * 3 feet and 3 windows of dimensions 4 feet * 3 feet each ?
Pick
A) s . 4528 B) s . 4520 C) s . 4527 D) s . 4530 E) s . 2718 | <gadget id="calculator">25 * 12</gadget>
<output>300</output>
<gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">300 + 180</gadget>
<output>480</output>
<gadget id="calculator">480 * 2</gadget>
<output>960</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">36 + 18</gadget>
<output>54</output>
<gadget id="calculator">960 - 54</gadget>
<output>906</output>
<gadget id="calculator">906 * 3</gadget>
<output>2_718</output>
<result>E</result> | E | 2,718 | the dimensions of a room are 25 feet * 15 feet * 12 feet . what is the cost of white washing the 4 walls of the room at rs . 3 per square feet if there is one door of dimensions 6 feet * 3 feet and 3 windows of dimensions 4 feet * 3 feet each ? | {
"A": "s . 4528",
"B": "s . 4520",
"C": "s . 4527",
"D": "s . 4530",
"E": "s . 2718"
} | multiply(subtract(multiply(add(multiply(25, 12), multiply(15, 12)), const_2), add(multiply(3, multiply(4, 3)), multiply(6, 3))), 3) | multiply(n0,n2)|multiply(n1,n2)|multiply(n3,n4)|multiply(n4,n5)|add(#0,#1)|multiply(n4,#2)|add(#5,#3)|multiply(#4,const_2)|subtract(#7,#6)|multiply(n4,#8) | area of the four walls = 2 h ( l + b ) since there are doors and windows , area of the walls = 2 * 12 ( 15 + 25 ) - ( 6 * 3 ) - 3 ( 4 * 3 ) = 906 sq . ft . total cost = 906 * 3 = rs . 2718 answer : e | geometry |
math_qa__tohJtiWewGQ802TQ | The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: Select:
A) 123
B) 127
C) 235
D) 305
E) 505 | <gadget id="calculator">2_037 - 5</gadget>
<output>2_032</output>
<gadget id="calculator">1_657 - 6</gadget>
<output>1_651</output>
<gadget id="calculator">gcd(2_032, 1_651)</gadget>
<output>127</output>
<result>B</result> | B | 127 | The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: | {
"A": "123",
"B": "127",
"C": "235",
"D": "305",
"E": "505"
} | gcd(subtract(2037, 5), subtract(1657, 6)) | subtract(n1,n3)|subtract(n0,n2)|gcd(#0,#1)| | "explanation : required number = h . c . f . of ( 1657 - 6 ) and ( 2037 - 5 ) = h . c . f . of 1651 and 2032 = 127 . answer : b" | general |
math_qa__P4FKSK2K5vx7KfDE | In an examination, 300 students appeared. Out of these students; 28 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. Choose one:
A) 33 B) 37 C) 54 D) 99 E) 01 | <gadget id="calculator">28 + 54</gadget>
<output>82</output>
<gadget id="calculator">100 - 82</gadget>
<output>18</output>
<gadget id="calculator">300 * 18</gadget>
<output>5_400</output>
<gadget id="calculator">5_400 / 100</gadget>
<output>54</output>
<result>C</result> | C | 54 | In an examination, 300 students appeared. Out of these students; 28 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. | {
"A": "33",
"B": "37",
"C": "54",
"D": "99",
"E": "01"
} | divide(multiply(300, subtract(const_100, add(28, 54))), const_100) | add(n1,n2)|subtract(const_100,#0)|multiply(n0,#1)|divide(#2,const_100)| | "the number of students with first division = 28 % of 300 = 28 / 100 × 300 = 8400 / 100 = 84 and , the number of students with second division = 54 % of 300 = 54 / 100 × 300 = 16200 / 100 = 162 therefore , the number of students who just passed = 300 – ( 84 + 162 ) = 54 answer : c" | general |
math_qa__zyraSyqPDMcebV8V | The average of first 13 even numbers is? Choose the correct choice from the following: A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">13 + 1</gadget>
<output>14</output>
<result>E</result> | E | 14 | The average of first 13 even numbers is? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | add(13, const_1) | add(n0,const_1)| | "sum of 13 even numbers = 13 * 14 = 110 average = 182 / 13 = 14 answer : e" | general |
math_qa__vEyQ8GTl654etFqU | A 250 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ? Select the correct option
A) 41.1 sec
B) 20.2 sec
C) 31.8 sec
D) 50.4 sec
E) none of the above | <gadget id="calculator">250 + 520</gadget>
<output>770</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">55 * (5/18)</gadget>
<output>275/18 = around 15.277778</output>
<gadget id="calculator">770 / (275/18)</gadget>
<output>252/5 = around 50.4</output>
<result>D</result> | D | 50.4 | A 250 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ? | {
"A": "41.1 sec",
"B": "20.2 sec",
"C": "31.8 sec",
"D": "50.4 sec",
"E": "none of the above"
} | divide(add(250, 520), multiply(55, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 55 km / hr ( to convert km / hr in to m / s ) = 55 x 5 / 18 m / s distance = 250 m + 520 m ( if questions is about train crossing a post you need to consider only the length of train , ) = 770 m time = distance / speed = 770 x 18 / ( 5 x 55 ) = 50.4 sec ans is : d" | physics |
math_qa__5Wb10zpuiUe0gjMu | A sum of money at simple interest amount to Rs 720 after 2 years and to Rs 1020 after a further period of 5 years.The sum is: Choose the correct choice from the following:
A) 600 B) 450 C) 650 D) 500 E) 550 | <gadget id="calculator">1_020 - 720</gadget>
<output>300</output>
<gadget id="calculator">300 * 2</gadget>
<output>600</output>
<gadget id="calculator">600 / 5</gadget>
<output>120</output>
<gadget id="calculator">720 - 120</gadget>
<output>600</output>
<result>A</result> | A | 600 | A sum of money at simple interest amount to Rs 720 after 2 years and to Rs 1020 after a further period of 5 years.The sum is: | {
"A": "600",
"B": "450",
"C": "650",
"D": "500",
"E": "550"
} | subtract(720, divide(multiply(subtract(1020, 720), 2), 5)) | subtract(n2,n0)|multiply(n1,#0)|divide(#1,n3)|subtract(n0,#2) | simple interest for 5 year = rs . ( 1020 - 720 ) = rs . 300 . simple interest for 2 year = rs . ( 300 / 5 × 2 ) = rs . 120 . principal = rs . ( 720 - 120 ) = rs . 600 . answer : a | gain |
math_qa__w8c7QcMENRT8ACTA | An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 2/3 %, then the amount invested in each share was? Choose the correct choice from the following choices: A) 23777 B) 35000 C) 29977 D) 26777 E) 19871 | <gadget id="calculator">11 / 100</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">(11/100) * 100_000</gadget>
<output>11_000</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">9 + (2/3)</gadget>
<output>29/3 = around 9.666667</output>
<gadget id="calculator">(29/3) / 100</gadget>
<output>29/300 = around 0.096667</output>
<gadget id="calculator">(29/300) * 100_000</gadget>
<output>29_000/3 = around 9_666.666667</output>
<gadget id="calculator">11_000 - (29_000/3)</gadget>
<output>4_000/3 = around 1_333.333333</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">(11/100) - (9/100)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(4_000/3) / (1/50)</gadget>
<output>200_000/3 = around 66_666.666667</output>
<gadget id="calculator">100_000 - (200_000/3)</gadget>
<output>100_000/3 = around 33_333.333333</output>
<result>B</result> | B | 35,000 | An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 2/3 %, then the amount invested in each share was? | {
"A": "23777",
"B": "35000",
"C": "29977",
"D": "26777",
"E": "19871"
} | subtract(100000, divide(subtract(multiply(divide(11, const_100), 100000), multiply(divide(add(9, divide(2, 3)), const_100), 100000)), subtract(divide(11, const_100), divide(9, const_100)))) | divide(n2,const_100)|divide(n4,n5)|divide(n1,const_100)|add(n1,#1)|multiply(n0,#0)|subtract(#0,#2)|divide(#3,const_100)|multiply(n0,#6)|subtract(#4,#7)|divide(#8,#5)|subtract(n0,#9) | let the sum invested at 9 % be rs . x and that invested at 11 % be rs . ( 100000 - x ) . then , ( x * 9 * 1 ) / 100 + [ ( 100000 - x ) * 11 * 1 ] / 100 = ( 100000 * 29 / 3 * 1 / 100 ) ( 9 x + 1100000 - 11 x ) / 100 = 29000 / 3 = 9700 ( 9 x + 1100000 - 11 x ) = 970000 x = 65000 sum invested at 9 % = rs . 65000 sum invested at 11 % = rs . ( 100000 - 65000 ) = rs . 35000 . answer : b | gain |
math_qa__yP5nEV9m4fZIshvm | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.100 more. What was the Sum? Choose the correct choice from the following options.
A) s . 350
B) s . 700
C) s . 200
D) s . 600
E) s . 500 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 / (1/2)</gadget>
<output>200</output>
<result>C</result> | C | 200 | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.100 more. What was the Sum? | {
"A": "s . 350",
"B": "s . 700",
"C": "s . 200",
"D": "s . 600",
"E": "s . 500"
} | divide(100, multiply(divide(5, const_100), 10)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)| | "at 5 % more rate , the increase in s . i for 10 years = rs . 100 ( given ) so , at 5 % more rate , the increase in si for 1 year = 100 / 10 = rs . 10 / - i . e . rs . 10 is 5 % of the invested sum so , 1 % of the invested sum = 10 / 5 therefore , the invested sum = 10 × 100 / 5 = rs . 200 answer : c" | gain |
math_qa__dagQ3njHm1HGenvg | There are 6 red balls and 4 blue balls in a jar. If 3 balls are selected from the jar, what is the probability that all 3 balls selected are blue balls? Select.
A) 1 / 18
B) 1 / 24
C) 1 / 30
D) 1 / 36
E) 1 / 48 | <gadget id="calculator">binomial(4, 3)</gadget>
<output>4</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">binomial(10, 3)</gadget>
<output>120</output>
<gadget id="calculator">4 / 120</gadget>
<output>1/30 = around 0.033333</output>
<result>C</result> | C | 0.033333 | There are 6 red balls and 4 blue balls in a jar. If 3 balls are selected from the jar, what is the probability that all 3 balls selected are blue balls? | {
"A": "1 / 18",
"B": "1 / 24",
"C": "1 / 30",
"D": "1 / 36",
"E": "1 / 48"
} | divide(choose(4, 3), choose(add(6, 4), 3)) | add(n0,n1)|choose(n1,n2)|choose(#0,n2)|divide(#1,#2) | the number of ways of choosing 3 balls from the jar is 10 c 3 = 120 . the number of ways of choosing 3 blue balls is 4 c 3 = 4 . p ( 3 blue balls ) = 4 / 120 = 1 / 30 . the answer is c . | probability |
math_qa__hYxop26kgVyCTcY7 | In Plutarch Enterprises, 70% of the employees are marketers, 10% are engineers, and the rest are managers. Marketers make an average salary of $50,000 a year, and engineers make an average of $80,000. What is the average salary for managers if the average for all employees is also $80,000? Pick: A) $ 80,000 B) $ 130,000 C) $ 240,000 D) $ 370,000 E) $ 320,000 | <gadget id="calculator">70 + 10</gadget>
<output>80</output>
<gadget id="calculator">80 * 1_000</gadget>
<output>80_000</output>
<gadget id="calculator">80_000 * 100</gadget>
<output>8_000_000</output>
<gadget id="calculator">10 * 80_000</gadget>
<output>800_000</output>
<gadget id="calculator">8_000_000 - 800_000</gadget>
<output>7_200_000</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">50 * 1_000</gadget>
<output>50_000</output>
<gadget id="calculator">50_000 * 70</gadget>
<output>3_500_000</output>
<gadget id="calculator">7_200_000 - 3_500_000</gadget>
<output>3_700_000</output>
<gadget id="calculator">3_700_000 / 10</gadget>
<output>370_000</output>
<result>D</result> | D | 370,000 | In Plutarch Enterprises, 70% of the employees are marketers, 10% are engineers, and the rest are managers. Marketers make an average salary of $50,000 a year, and engineers make an average of $80,000. What is the average salary for managers if the average for all employees is also $80,000? | {
"A": "$ 80,000",
"B": "$ 130,000",
"C": "$ 240,000",
"D": "$ 370,000",
"E": "$ 320,000"
} | divide(subtract(subtract(multiply(multiply(add(70, 10), const_1000), const_100), multiply(const_10, multiply(add(70, 10), const_1000))), multiply(multiply(multiply(divide(const_10, const_2), const_10), const_1000), 70)), 10) | add(n0,n1)|divide(const_10,const_2)|multiply(#0,const_1000)|multiply(#1,const_10)|multiply(#2,const_100)|multiply(#2,const_10)|multiply(#3,const_1000)|multiply(n0,#6)|subtract(#4,#5)|subtract(#8,#7)|divide(#9,n1) | for sake of ease , let ' s say there are 10 employees : 7 marketers , 1 engineers , and 2 manager . average company salary * number of employees = total company salary > > > $ 80,000 * 10 = $ 800,000 subtract the combined salaries for the marketers ( 7 * $ 50,000 ) and the engineers ( $ 80,000 ) > > > $ 800,000 - $ 350,000 - $ 80,000 = $ 370,000 . the correct answer is d . | general |
math_qa__JtZu72bN8K2IZty5 | Company S produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company S last month, 2/3 were basic and the rest were deluxe. If it takes 1.6 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month was what fraction of the total number of hours it took to produce all the stereos? Choose the correct choice
A) 7 / 17
B) 14 / 31
C) 7 / 15
D) 17 / 35
E) 1 / 2 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<result>E</result> | E | 0.5 | Company S produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company S last month, 2/3 were basic and the rest were deluxe. If it takes 1.6 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month was what fraction of the total number of hours it took to produce all the stereos? | {
"A": "7 / 17",
"B": "14 / 31",
"C": "7 / 15",
"D": "17 / 35",
"E": "1 / 2"
} | divide(add(3, 2), const_10) | add(n0,n1)|divide(#0,const_10) | the easiest way for me is to plug in numbers . let the number of basic stereos produced be 40 , and number of delux stereos produced be 20 . total of 60 stereos . if it takes an hour to produce a basic stereo then it will take 1.6 hours to produce a deluxe stereo . 40 basic stereos = 40 hours . 20 delux stereos = 32 hours . total hours = 72 then the fraction would be 32 / 72 = 4 / 9 . therefore answer e | general |
math_qa__ji4kGcEu4UIUSkJq | The average score of a cricketer in 2 matches is 20 and in other 3 matches is 30. Then find the average score in all the 5 matches? Select the correct option.
A) 26 B) 27 C) 30 D) 35 E) 42 | <gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">3 * 30</gadget>
<output>90</output>
<gadget id="calculator">40 + 90</gadget>
<output>130</output>
<gadget id="calculator">130 / 5</gadget>
<output>26</output>
<result>A</result> | A | 26 | The average score of a cricketer in 2 matches is 20 and in other 3 matches is 30. Then find the average score in all the 5 matches? | {
"A": "26",
"B": "27",
"C": "30",
"D": "35",
"E": "42"
} | divide(add(multiply(2, 20), multiply(3, 30)), 5) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(#2,n4)| | "average in 5 matches = ( 2 * 20 + 3 * 30 ) / 2 + 3 = 40 + 90 / 5 = 130 / 5 = 26 answer is a" | general |
math_qa__OGVHlF0NlcBx6sXf | 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 10 mat-weavers in 10 days? Select the correct option:
A) 25 B) 19 C) 39 D) 61 E) 16 | <gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">4 * (5/2)</gadget>
<output>10</output>
<gadget id="calculator">10 * (5/2)</gadget>
<output>25</output>
<result>A</result> | A | 25 | 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 10 mat-weavers in 10 days? | {
"A": "25",
"B": "19",
"C": "39",
"D": "61",
"E": "16"
} | multiply(multiply(4, divide(10, 4)), divide(10, 4)) | divide(n3,n0)|multiply(n0,#0)|multiply(#0,#1)| | "let the required number of bottles be x . more weavers , more mats ( direct proportion ) more days , more mats ( direct proportion ) wavers 4 : 10 : : 4 : x days 4 : 10 4 * 4 * x = 10 * 10 * 4 x = ( 10 * 10 * 4 ) / ( 4 x 4 ) x = 25 . answer is a ." | gain |
math_qa__bKjuAoJoRlf7nAC3 | rahul played weel in this season.his current batting averagge is 51.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season. Options
A) 8 B) 10 C) 9 D) 6 E) 5 | <gadget id="calculator">78 - 54</gadget>
<output>24</output>
<gadget id="calculator">54 - 51</gadget>
<output>3</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<result>A</result> | A | 8 | rahul played weel in this season.his current batting averagge is 51.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season. | {
"A": "8",
"B": "10",
"C": "9",
"D": "6",
"E": "5"
} | divide(subtract(78, 54), subtract(54, 51)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "51 x + 78 = 54 ( x + 1 ) = > 3 x = 24 = > x = 8 answer : a" | general |
math_qa__Nq8DxvKFRxfmDyUS | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 14 percent of revenues. The profits in 1999 were what percent of the profits in 1998? Pick.
A) 80 % B) 105 % C) 120 % D) 112 % E) 138 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(4/5) * (7/50)</gadget>
<output>14/125 = around 0.112</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(14/125) / (1/10)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(28/25) * 100</gadget>
<output>112</output>
<result>D</result> | D | 112 | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 14 percent of revenues. The profits in 1999 were what percent of the profits in 1998? | {
"A": "80 %",
"B": "105 %",
"C": "120 %",
"D": "112 %",
"E": "138 %"
} | multiply(divide(multiply(subtract(const_1, divide(20, const_100)), divide(14, const_100)), divide(10, const_100)), const_100) | divide(n4,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(#0,#3)|divide(#4,#2)|multiply(#5,const_100)| | "0,112 r = x / 100 * 0.1 r answer d" | gain |
math_qa__jSc6q0cd5A0iOxcJ | A jogger is running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 meters long train . The train is running at 45 kmph in the same direction. how much time does it take for the train to pass the jogger? Answers.
A) 46
B) 36
C) 18
D) 22
E) 23 | <gadget id="calculator">240 + 120</gadget>
<output>360</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">36 * 1_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3_600</gadget>
<output>10</output>
<gadget id="calculator">360 / 10</gadget>
<output>36</output>
<result>B</result> | B | 36 | A jogger is running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 meters long train . The train is running at 45 kmph in the same direction. how much time does it take for the train to pass the jogger? | {
"A": "46",
"B": "36",
"C": "18",
"D": "22",
"E": "23"
} | divide(add(240, 120), divide(multiply(subtract(45, 9), const_1000), const_3600)) | add(n1,n2)|subtract(n3,n0)|multiply(#1,const_1000)|divide(#2,const_3600)|divide(#0,#3) | explanation : distance to be covered = 240 + 120 = 360 m relative speed = 36 km / hr = 36 × 10 / 36 = 10 m / s time = distance / speed = 360 / 10 = 36 seconds answer : option b | physics |
math_qa__YeVsnJR2yCExxH1U | An uneducated retailer marks all his goods at 65% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales? Choose the correct choice
A) 12.50 % B) 13.50 % C) 14 % D) 23.75 % E) none | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1 + (13/20)</gadget>
<output>33/20 = around 1.65</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(33/20) * (1/4)</gadget>
<output>33/80 = around 0.4125</output>
<gadget id="calculator">(33/20) - (33/80)</gadget>
<output>99/80 = around 1.2375</output>
<gadget id="calculator">(99/80) - 1</gadget>
<output>19/80 = around 0.2375</output>
<gadget id="calculator">(19/80) * 100</gadget>
<output>95/4 = around 23.75</output>
<result>D</result> | D | 23.75 | An uneducated retailer marks all his goods at 65% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales? | {
"A": "12.50 %",
"B": "13.50 %",
"C": "14 %",
"D": "23.75 %",
"E": "none"
} | multiply(subtract(subtract(add(const_1, divide(65, const_100)), multiply(add(const_1, divide(65, const_100)), divide(25, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|multiply(#2,#1)|subtract(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "sol . let c . p . = rs . 100 . then , marked price = rs . 165 . s . p . = 75 % of rs . 165 = rs . 123.75 . ∴ gain % = 23.75 % . answer d" | gain |
math_qa__EgYXnGANNnTEjEfF | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 126 km downstream. Choose the correct choice from the following options: A) 4 hours B) 5 hours C) 6 hours D) 7 hours E) 8 hours | <gadget id="calculator">16 + 5</gadget>
<output>21</output>
<gadget id="calculator">126 / 21</gadget>
<output>6</output>
<result>C</result> | C | 6 | A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 126 km downstream. | {
"A": "4 hours",
"B": "5 hours",
"C": "6 hours",
"D": "7 hours",
"E": "8 hours"
} | divide(126, add(16, 5)) | add(n0,n1)|divide(n2,#0) | explanation : it is very important to check , if the boat speed given is in still water or with water or against water . because if we neglect it we will not reach on right answer . i just mentioned here because mostly mistakes in this chapter are of this kind only . lets see the question now . speed downstream = ( 16 + 5 ) = 21 kmph time = distance / speed = 126 / 21 = 6 hours option c | physics |
math_qa__v91bDK3YUrNBpHhH | If 7a = 2b = 15, then 42ab = Options:
A) 75
B) 125
C) 675
D) 1100
E) 1250 | <gadget id="calculator">15 / 7</gadget>
<output>15/7 = around 2.142857</output>
<gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/7) * (15/2)</gadget>
<output>225/14 = around 16.071429</output>
<gadget id="calculator">42 * (225/14)</gadget>
<output>675</output>
<result>C</result> | C | 675 | If 7a = 2b = 15, then 42ab = | {
"A": "75",
"B": "125",
"C": "675",
"D": "1100",
"E": "1250"
} | multiply(42, multiply(divide(15, 7), divide(15, 2))) | divide(n2,n0)|divide(n2,n1)|multiply(#0,#1)|multiply(n3,#2)| | "7 a * 2 b = 15 * 15 = 225 14 ab = 225 i . e . 42 ab = 675 answer : option c" | general |
math_qa__zdMrGGOroSKGjo5c | If 0.75: x :: 5:7, then x is equal to: Choose the correct choice from the following options:
A) 1.05
B) 1.16
C) 1.2
D) 1.3
E) none of these | <gadget id="calculator">0.75 * 7</gadget>
<output>5.25</output>
<gadget id="calculator">5.25 / 5</gadget>
<output>1.05</output>
<result>A</result> | A | 1.05 | If 0.75: x :: 5:7, then x is equal to: | {
"A": "1.05",
"B": "1.16",
"C": "1.2",
"D": "1.3",
"E": "none of these"
} | divide(multiply(0.75, 7), 5) | multiply(n0,n2)|divide(#0,n1)| | "explanation : ( x * 5 ) = ( 0.75 * 7 ) x = 5.25 / 5 = 1.05 answer : a" | general |
math_qa__kMyqsbiLf9VjQRes | A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3500, A will get: Choose the correct choice from the following answers:
A) rs . 1200 B) rs . 1500 C) rs . 2100 D) rs . 2000 E) none of these | <gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<gadget id="calculator">30 / 15</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 3_500</gadget>
<output>2_100</output>
<result>C</result> | C | 2,100 | A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3500, A will get: | {
"A": "rs . 1200",
"B": "rs . 1500",
"C": "rs . 2100",
"D": "rs . 2000",
"E": "none of these"
} | multiply(divide(divide(multiply(15, const_2), 10), add(divide(multiply(15, const_2), 10), divide(multiply(15, const_2), 15))), 3500) | multiply(n1,const_2)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|divide(#1,#3)|multiply(n2,#4)| | "explanation : ratio of working days of a : b = 10 : 15 therefore , their wages ratio = reverse ratio = 15 : 10 therefore , a will get 15 units of ratio total ratio = 25 1 unit of ratio = 3500 / 25 = 140 so , a ’ s amount = 120 × 15 = rs . 2100 . answer : option c" | physics |
math_qa__l7072QBQkFl3RWlF | Sides of a rectangular park are in the ratio 3: 2 and its area is 7350 sq m, the cost of fencing it at 50 ps per meter is? Choose the correct option:
A) 287 B) 1287 C) 125 D) 988 E) 175 | <gadget id="calculator">7_350 * 2</gadget>
<output>14_700</output>
<gadget id="calculator">14_700 / 3</gadget>
<output>4_900</output>
<gadget id="calculator">4_900 ** (1/2)</gadget>
<output>70</output>
<gadget id="calculator">7_350 / 70</gadget>
<output>105</output>
<gadget id="calculator">2 * (70 + 105)</gadget>
<output>350</output>
<gadget id="calculator">50 * 350</gadget>
<output>17_500</output>
<gadget id="calculator">17_500 / 100</gadget>
<output>175</output>
<result>E</result> | E | 175 | Sides of a rectangular park are in the ratio 3: 2 and its area is 7350 sq m, the cost of fencing it at 50 ps per meter is? | {
"A": "287",
"B": "1287",
"C": "125",
"D": "988",
"E": "175"
} | divide(multiply(50, rectangle_perimeter(sqrt(divide(multiply(7350, 2), 3)), divide(7350, sqrt(divide(multiply(7350, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 7350 = > x = 35 2 ( 105 + 70 ) = 350 m 350 * 1 / 2 = rs . 175 answer : e" | physics |
math_qa__fjJZSPfifMOdrVeY | The probability that a number selected at random from the first 50 natural numbers is a composite number is -.
Options.
A) 17 / 25 B) 17 / 27 C) 17 / 18 D) 17 / 22 E) 17 / 09 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">17 * 2</gadget>
<output>34</output>
<gadget id="calculator">34 / 50</gadget>
<output>17/25 = around 0.68</output>
<result>A</result> | A | 0.68 | The probability that a number selected at random from the first 50 natural numbers is a composite number is -. | {
"A": "17 / 25",
"B": "17 / 27",
"C": "17 / 18",
"D": "17 / 22",
"E": "17 / 09"
} | divide(multiply(subtract(multiply(const_6, const_3), const_1), const_2), 50) | multiply(const_3,const_6)|subtract(#0,const_1)|multiply(#1,const_2)|divide(#2,n0)| | "the number of exhaustive events = ⁵ ⁰ c ₁ = 50 . we have 15 primes from 1 to 50 . number of favourable cases are 34 . required probability = 34 / 50 = 17 / 25 . answer : a" | probability |
math_qa__d0GrnvQLVWTGcWEk | There are certain number of hats and gloves in a box.They are of 41 red,23 green,11 orange.Power gone but a woman can differentiate between hats and gloves.How many draws are required to obtain a pair of each color? Pick
A) 66 B) 67 C) 68 D) 69 E) 70 | <gadget id="calculator">41 + 23</gadget>
<output>64</output>
<gadget id="calculator">64 + 2</gadget>
<output>66</output>
<result>A</result> | A | 66 | There are certain number of hats and gloves in a box.They are of 41 red,23 green,11 orange.Power gone but a woman can differentiate between hats and gloves.How many draws are required to obtain a pair of each color? | {
"A": "66",
"B": "67",
"C": "68",
"D": "69",
"E": "70"
} | add(add(41, 23), const_2) | add(n0,n1)|add(#0,const_2) | the worst case senario will be first take 40 red then take 22 green then take 1 + 1 red + green then take 2 orange . so total 40 + 22 + 2 + 2 = 66 answer : a | general |
math_qa__pZzX251tM6ypbGhc | The average weight of 20 persons sitting in a boat had some value. A new person added to them whose weight was 49 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 20 persons? Options:
A) 55
B) 56
C) 57
D) 58
E) 59 | <gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">21 * 5</gadget>
<output>105</output>
<gadget id="calculator">105 - 49</gadget>
<output>56</output>
<result>B</result> | B | 56 | The average weight of 20 persons sitting in a boat had some value. A new person added to them whose weight was 49 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 20 persons? | {
"A": "55",
"B": "56",
"C": "57",
"D": "58",
"E": "59"
} | subtract(multiply(add(20, const_1), 5), 49) | add(n0,const_1)|multiply(n2,#0)|subtract(#1,n1)| | "20 x + 49 = 21 ( x – 5 ) x = 56 answer : b" | general |
math_qa__TW6kocOpAbl8OQCC | How many shots of 1cm radius can be prepared from a sphere of 3cm radius? Choose the correct choice from the following choices
A) 33
B) 88
C) 27
D) 88
E) 99 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<result>C</result> | C | 27 | How many shots of 1cm radius can be prepared from a sphere of 3cm radius? | {
"A": "33",
"B": "88",
"C": "27",
"D": "88",
"E": "99"
} | multiply(power(3, const_2), 3) | power(n1,const_2)|multiply(n1,#0)| | "4 / 3 π * 3 * 3 * 3 = 4 / 3 π * 1 * 1 * 1 * x x = 27 answer : c" | physics |
math_qa__pXwZE6wOFjgtd4Xz | Two trains each 190m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 65km/h while the other travels at 50km/h. how long will it take for them to pass each other completely. Choose the correct choice from the following:
A) 10.7 sec B) 2.7 sec C) 11.9 sec D) 12.7 sec E) 25.7 sec | <gadget id="calculator">190 + 190</gadget>
<output>380</output>
<gadget id="calculator">380 / 1_000</gadget>
<output>19/50 = around 0.38</output>
<gadget id="calculator">65 + 50</gadget>
<output>115</output>
<gadget id="calculator">(19/50) / 115</gadget>
<output>19/5_750 = around 0.003304</output>
<gadget id="calculator">3_600 * (19/5_750)</gadget>
<output>1_368/115 = around 11.895652</output>
<result>C</result> | C | 11.9 | Two trains each 190m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 65km/h while the other travels at 50km/h. how long will it take for them to pass each other completely. | {
"A": "10.7 sec",
"B": "2.7 sec",
"C": "11.9 sec",
"D": "12.7 sec",
"E": "25.7 sec"
} | multiply(const_3600, divide(divide(add(190, 190), const_1000), add(65, 50))) | add(n0,n0)|add(n1,n2)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_3600)| | "explanation : d = 190 m + 190 m = 380 m rs = 65 + 50 = 115 * 5 / 18 = 319 / 10 t = 380 * 10 / 319 = 11.9 sec answer : option c" | physics |
math_qa__B3sM52HOOdExK0sx | A 600 m long train crosses a tree in 60sec, how much time will It take to pass a platform 450 m long?
Answers
A) 288 B) 190 C) 188 D) 188 E) 105 | <gadget id="calculator">600 + 450</gadget>
<output>1_050</output>
<gadget id="calculator">600 / 60</gadget>
<output>10</output>
<gadget id="calculator">1_050 / 10</gadget>
<output>105</output>
<result>E</result> | E | 105 | A 600 m long train crosses a tree in 60sec, how much time will It take to pass a platform 450 m long? | {
"A": "288",
"B": "190",
"C": "188",
"D": "188",
"E": "105"
} | divide(add(600, 450), divide(600, 60)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1)| | "l = s * t s = 600 / 60 s = 10 m / sec . total length ( d ) = 1050 m t = d / s t = 1050 / 10 t = 105 sec answer : e" | physics |
math_qa__wMPwA98h7n8PX636 | In a class of 50 students, 3/5 went away do painting, 1/5 went to play in the field. How many students are left in the classroom? Pick one.
A) 20 B) 30 C) 5 D) 8 E) 10 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">50 * (3/5)</gadget>
<output>30</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">50 * (1/5)</gadget>
<output>10</output>
<gadget id="calculator">30 + 10</gadget>
<output>40</output>
<gadget id="calculator">50 - 40</gadget>
<output>10</output>
<result>E</result> | E | 10 | In a class of 50 students, 3/5 went away do painting, 1/5 went to play in the field. How many students are left in the classroom? | {
"A": "20",
"B": "30",
"C": "5",
"D": "8",
"E": "10"
} | subtract(50, add(multiply(50, divide(3, 5)), multiply(50, divide(1, 5)))) | divide(n1,n2)|divide(n3,n2)|multiply(n0,#0)|multiply(n0,#1)|add(#2,#3)|subtract(n0,#4) | 3 / 5 + 1 / 5 are the students who have left the classroom 3 / 5 + 1 / 5 = ( 3 + 1 ) / 5 , since denominator is same for both fractions = 4 / 5 remaining students in the classroom = 1 - 4 / 5 = 5 / 5 - 4 / 5 = ( 5 - 4 ) / 5 = 1 / 5 1 / 5 of 50 = 10 ans : e | other |
math_qa__zMVdmceRC94ZuSz1 | A statue is being carved by a sculptor. The original piece of marble weighed 300 kg. In the first week 30 percent is cut away. In the second week 30 percent of the remainder is cut away. In the third week the statue is completed when 15 percent of the remainder is cut away. What is the weight of the final statue? Options:
A) 105 kg B) 103 kg C) 108 kg D) 125 kg E) 117 kg | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">300 * (7/10)</gadget>
<output>210</output>
<gadget id="calculator">(7/10) * 210</gadget>
<output>147</output>
<gadget id="calculator">(17/20) * 147</gadget>
<output>2_499/20 = around 124.95</output>
<result>D</result> | D | 125 | A statue is being carved by a sculptor. The original piece of marble weighed 300 kg. In the first week 30 percent is cut away. In the second week 30 percent of the remainder is cut away. In the third week the statue is completed when 15 percent of the remainder is cut away. What is the weight of the final statue? | {
"A": "105 kg",
"B": "103 kg",
"C": "108 kg",
"D": "125 kg",
"E": "117 kg"
} | multiply(subtract(const_1, divide(15, const_100)), multiply(subtract(const_1, divide(30, const_100)), multiply(300, subtract(const_1, divide(30, const_100))))) | divide(n1,const_100)|divide(n2,const_100)|divide(n3,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|subtract(const_1,#2)|multiply(n0,#3)|multiply(#6,#4)|multiply(#7,#5)| | "d 125 kg 300 ã — 0.7 ã — 0.7 ã — 0.85 = 125 kg ." | gain |
math_qa__DA5y8wxDJR27uQnx | A $500 investment and a $1,500 investment have a combined yearly return of 10 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? Select the correct option:
A) 9 % B) 10 % C) 105 / 8 % D) 11 % E) 12 % | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">500 + 1_500</gadget>
<output>2_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">2_000 * (1/10)</gadget>
<output>200</output>
<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">500 * (7/100)</gadget>
<output>35</output>
<gadget id="calculator">200 - 35</gadget>
<output>165</output>
<gadget id="calculator">165 / 1_500</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">(11/100) * 100</gadget>
<output>11</output>
<result>D</result> | D | 11 | A $500 investment and a $1,500 investment have a combined yearly return of 10 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? | {
"A": "9 %",
"B": "10 %",
"C": "105 / 8 %",
"D": "11 %",
"E": "12 %"
} | multiply(divide(subtract(multiply(add(500, multiply(const_3, 500)), divide(10, const_100)), multiply(500, divide(7, const_100))), multiply(const_3, 500)), const_100) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_3)|add(n0,#2)|multiply(n0,#1)|multiply(#3,#0)|subtract(#5,#4)|divide(#6,#2)|multiply(#7,const_100) | the equation we can form the question : return on total investment = sum of individual investments ( 500 + 1500 ) ( 10 ) = ( 500 â ˆ — 7 ) + ( 1500 x ) , where x is the return on investment of 1500 . solving the equation , we get x = 11 % ( option d ) answer : d | gain |
math_qa__yDFQ39tBCXUBG1dv | The number of positive integer solutions for the equation x +y +z + t = 18 is Choose one.
A) 640 B) 780 C) 380 D) 540 E) 680 | <gadget id="calculator">18 - 1</gadget>
<output>17</output>
<gadget id="calculator">factorial(17)</gadget>
<output>355_687_428_096_000</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">17 - 3</gadget>
<output>14</output>
<gadget id="calculator">factorial(14)</gadget>
<output>87_178_291_200</output>
<gadget id="calculator">6 * 87_178_291_200</gadget>
<output>523_069_747_200</output>
<gadget id="calculator">355_687_428_096_000 / 523_069_747_200</gadget>
<output>680</output>
<result>E</result> | E | 680 | The number of positive integer solutions for the equation x +y +z + t = 18 is | {
"A": "640",
"B": "780",
"C": "380",
"D": "540",
"E": "680"
} | divide(factorial(subtract(18, const_1)), multiply(factorial(subtract(const_4, const_1)), factorial(subtract(subtract(18, const_1), subtract(const_4, const_1))))) | subtract(n0,const_1)|subtract(const_4,const_1)|factorial(#0)|factorial(#1)|subtract(#0,#1)|factorial(#4)|multiply(#3,#5)|divide(#2,#6)| | "the number of positive integer solutions for the equatio fx 1 + x 2 + ⋯ + xn = k ( k - 1 ) c ( n - 1 ) - where k is the number and n is number of variable in the equation . 18 - 1 c 4 - 1 = 17 c 3 = 680 answer : e" | general |
math_qa__nXFYAtiREiqNjNOJ | The average age of a group of n people is 15 years old. One more person aged 37 joins the group and the new average is 17 years old. What is the value of n? Choose the correct choice from the following choices
A) 10 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">37 - 17</gadget>
<output>20</output>
<gadget id="calculator">17 - 15</gadget>
<output>2</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | The average age of a group of n people is 15 years old. One more person aged 37 joins the group and the new average is 17 years old. What is the value of n? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(subtract(37, 17), subtract(17, 15)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "15 n + 37 = 17 ( n + 1 ) 2 n = 20 n = 10 the answer is a ." | general |
math_qa__hYw0YCOFTdYFSNVO | The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, What is the the speed of the first train? Options
A) 87.0 B) 87.5 C) 87.2 D) 87.1 E) 87.4 | <gadget id="calculator">400 / 4</gadget>
<output>100</output>
<gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 7</gadget>
<output>175/2 = around 87.5</output>
<result>B</result> | B | 87.5 | The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, What is the the speed of the first train? | {
"A": "87.0",
"B": "87.5",
"C": "87.2",
"D": "87.1",
"E": "87.4"
} | multiply(divide(divide(400, 4), 8), 7) | divide(n2,n3)|divide(#0,n1)|multiply(n0,#1) | speed and time are inversely proportional ( when distance is constant ) ⇒ speed ∝ 1 time ( when distance is constant ) here distance is constant and hence speed and time are inversely proportionalspeed ∝ 1 time ⇒ speed 1 speed 2 = time 2 time 1 ⇒ 78 = 4 time 1 ⇒ time 1 = 4 × 87 hr ⇒ speed of the first train = distancetime 1 = 400 ( 4 × 87 ) = 100 × 78 = 12.5 × 7 = 87.5 km / hr answer : b | physics |
math_qa__zHYWmWuYpG9PfTCv | Area of square with side x is equal to the area of a triangle with base x . The altitude of the triangle is Choose the correct choice from the following: A) x / 2 B) x C) 2 x D) 4 x E) 3 x | <gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<result>C</result> | C | 2 | Area of square with side x is equal to the area of a triangle with base x . The altitude of the triangle is | {
"A": "x / 2",
"B": "x",
"C": "2 x",
"D": "4 x",
"E": "3 x"
} | multiply(power(const_1, const_2), const_2) | power(const_1,const_2)|multiply(#0,const_2) | x ^ 2 = 1 / 2 ã ƒ â € ” x ã ƒ â € ” h or h = 2 x ^ 2 / x = 2 x answer : c | geometry |
math_qa__NGGE6ZqJaurJAKg1 | A baseball card decreased in value 60% in its first year and 10% in its second year. What was the total percent decrease of the card's value over the two years? Choose the correct option: A) 28 % B) 30 % C) 32 % D) 36 % E) 64 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(9/10) * (2/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 100</gadget>
<output>36</output>
<gadget id="calculator">100 - 36</gadget>
<output>64</output>
<result>E</result> | E | 64 | A baseball card decreased in value 60% in its first year and 10% in its second year. What was the total percent decrease of the card's value over the two years? | {
"A": "28 %",
"B": "30 %",
"C": "32 %",
"D": "36 %",
"E": "64 %"
} | subtract(const_100, multiply(multiply(subtract(const_1, divide(10, const_100)), subtract(const_1, divide(60, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5) | let the initial value of baseball card = 100 after first year , value of baseball card = ( 1 - 60 / 100 ) * 100 = 40 after second year , value of baseball card = ( 1 - 10 / 100 ) * 40 = 36 total percent decrease of the card ' s value over the two years = ( 100 - 36 ) / 100 * 100 % = 64 % answer e | gain |
math_qa__sTrJsAInMebpUvUI | There are 10 books on a shelf, of which 4 are paperbacks and 6 are hardbacks. How many possible selections of 5 books from the shelf contain at least one paperback and at least one hardback? Answers
A) 75
B) 120
C) 210
D) 246
E) 252 | <gadget id="calculator">binomial(10, 5)</gadget>
<output>252</output>
<gadget id="calculator">binomial(6, 5)</gadget>
<output>6</output>
<gadget id="calculator">252 - 6</gadget>
<output>246</output>
<result>D</result> | D | 246 | There are 10 books on a shelf, of which 4 are paperbacks and 6 are hardbacks. How many possible selections of 5 books from the shelf contain at least one paperback and at least one hardback? | {
"A": "75",
"B": "120",
"C": "210",
"D": "246",
"E": "252"
} | subtract(choose(10, 5), choose(6, 5)) | choose(n0,n3)|choose(n2,n3)|subtract(#0,#1)| | "paperbacks - 4 , hardbacks - 6 5 books in total and at least 1 from each . total combinations for 5 books = ( 1 pb , 4 hb ) + ( 4 pb , 1 hb ) + ( 3 pb , 2 hb ) + ( 2 pb , 3 hb ) 1 pb , 4 hb = 4 c 1 * 6 c 4 = 60 4 pb , 1 hb = 4 c 4 * 6 c 1 = 6 3 pb , 2 hb = 4 c 3 * 6 c 2 = 60 2 pb , 3 hb = 4 c 2 * 6 c 3 = 120 total combinations of 5 books = 60 + 6 + 60 + 120 = > 246 ans d ." | probability |
math_qa__SArv1JmDlH5OT1Mf | A walk 20m towards north east.B walk towards east 8m and then 12m south.Now calculate Distance between A and B?
Choose the correct choice from the following choices:
A) 30 m B) 20 m C) 35 m D) 40 m E) 38 m | <gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">400 - 64</gadget>
<output>336</output>
<gadget id="calculator">336 ** (1/2)</gadget>
<output>4*sqrt(21) = around 18.330303</output>
<gadget id="calculator">12 + (4*sqrt(21))</gadget>
<output>12 + 4*sqrt(21) = around 30.330303</output>
<result>A</result> | A | 30 | A walk 20m towards north east.B walk towards east 8m and then 12m south.Now calculate Distance between A and B? | {
"A": "30 m",
"B": "20 m",
"C": "35 m",
"D": "40 m",
"E": "38 m"
} | add(12, sqrt(subtract(power(20, const_2), power(8, const_2)))) | power(n0,const_2)|power(n1,const_2)|subtract(#0,#1)|sqrt(#2)|add(n2,#3) | its coming 30.4 m since 1 st triangle we get 18.31 and extra 12 so 18.31 + 12 = 30.31 = 30 m answer : a | physics |
math_qa__9l4xuZVme9LowqVo | A plot ABCD is as shown in figure, where AF = 30 m, CE = 40 m, ED = 50 m, AE = 120 m. Find the area of the plot ABCD? Pick
A) 7207 B) 7206 C) 7203 D) 7200 E) 7201 | <gadget id="calculator">(40 * 30) / 2</gadget>
<output>600</output>
<gadget id="calculator">(50 * 120) / 2</gadget>
<output>3_000</output>
<gadget id="calculator">600 + 3_000</gadget>
<output>3_600</output>
<gadget id="calculator">120 - 30</gadget>
<output>90</output>
<gadget id="calculator">40 * 90</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 + 3_600</gadget>
<output>7_200</output>
<result>D</result> | D | 7,200 | A plot ABCD is as shown in figure, where AF = 30 m, CE = 40 m, ED = 50 m, AE = 120 m. Find the area of the plot ABCD? | {
"A": "7207",
"B": "7206",
"C": "7203",
"D": "7200",
"E": "7201"
} | add(add(triangle_area(40, 30), triangle_area(50, 120)), multiply(40, subtract(120, 30))) | subtract(n3,n0)|triangle_area(n0,n1)|triangle_area(n2,n3)|add(#1,#2)|multiply(n1,#0)|add(#3,#4) | area of plot abcd = area of ade + area of afb + area of bcef = 1 / 2 * 50 * 120 + 1 / 2 * 40 * 30 + 40 * 90 = 3000 + 600 + 3600 = 7200 sq . m answer : d | physics |
math_qa__nK9fUX9Txrky89ep | In what time will a train 100 meters long cross an electric pole, if its speed is 126 km/hr
Select.
A) 8.5 seconds B) 2.86 seconds C) 3.5 seconds D) 2.5 seconds E) 2.6 seconds | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">126 * (5/18)</gadget>
<output>35</output>
<gadget id="calculator">100 / 35</gadget>
<output>20/7 = around 2.857143</output>
<result>B</result> | B | 2.86 | In what time will a train 100 meters long cross an electric pole, if its speed is 126 km/hr | {
"A": "8.5 seconds",
"B": "2.86 seconds",
"C": "3.5 seconds",
"D": "2.5 seconds",
"E": "2.6 seconds"
} | divide(100, multiply(126, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "first convert speed into m / sec speed = 126 * ( 5 / 18 ) = 35 m / sec time = distance / speed = 100 / 35 = 2.86 seconds answer : b" | physics |
math_qa__SUz8x4e4SCfb2uBS | Two bullet train s 140 m and 170 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
Choose the correct choice from the following answers:
A) 15.8 sec .
B) 12.8 sec .
C) 11.16 sec .
D) 10.8 sec .
E) 08.8 sec . | <gadget id="calculator">140 + 170</gadget>
<output>310</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">310 / (250/9)</gadget>
<output>279/25 = around 11.16</output>
<result>C</result> | C | 11.16 | Two bullet train s 140 m and 170 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is: | {
"A": "15.8 sec .",
"B": "12.8 sec .",
"C": "11.16 sec .",
"D": "10.8 sec .",
"E": "08.8 sec ."
} | divide(add(140, 170), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 60 + 40 ) km / hr = 100 x 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = ( 140 + 170 ) m = 310 m . required time = 310 x 9 / 250 = 11.16 sec . answer c" | physics |
math_qa__Ji4GNbd3ry5uivMs | A rectangular garden is 12m by 5m, what is its area? Pick: A) 12 square meters B) 5 square meters C) 44 square meters D) 60 square meters E) 22 square meters | <gadget id="calculator">12 * 5</gadget>
<output>60</output>
<result>D</result> | D | 60 | A rectangular garden is 12m by 5m, what is its area? | {
"A": "12 square meters",
"B": "5 square meters",
"C": "44 square meters",
"D": "60 square meters",
"E": "22 square meters"
} | multiply(12, 5) | multiply(n0,n1) | area of a rectangle : a = w × h d ) 60 square meters | geometry |
math_qa__etcHQNMgAYs2AnRB | Indu gave Bindu Rs.3125 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Choose the most appropriate option: A) s . 10 B) s . 2 C) s . 5 D) s . 3 E) s . 4 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">3_125 * (676/625)</gadget>
<output>3_380</output>
<gadget id="calculator">3_380 - 3_125</gadget>
<output>255</output>
<gadget id="calculator">3_125 * (1/25)</gadget>
<output>125</output>
<gadget id="calculator">125 * 2</gadget>
<output>250</output>
<gadget id="calculator">255 - 250</gadget>
<output>5</output>
<result>C</result> | C | 5 | Indu gave Bindu Rs.3125 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? | {
"A": "s . 10",
"B": "s . 2",
"C": "s . 5",
"D": "s . 3",
"E": "s . 4"
} | subtract(subtract(multiply(3125, power(add(const_1, divide(4, const_100)), 2)), 3125), multiply(multiply(3125, divide(4, const_100)), 2)) | divide(n2,const_100)|add(#0,const_1)|multiply(n0,#0)|multiply(n1,#2)|power(#1,n1)|multiply(n0,#4)|subtract(#5,n0)|subtract(#6,#3)| | "3125 = d ( 100 / 4 ) 2 d = 5 answer : c" | gain |
math_qa__jL78WBFH3GW3KV3T | If the ratio of a to b is 7 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? Choose the correct answer
A) 4 / 15 B) 1 / 3 C) 2 / 5 D) 4 / 5 E) 7 / 15 | <gadget id="calculator">7 * 1</gadget>
<output>7</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">7 / 15</gadget>
<output>7/15 = around 0.466667</output>
<result>E</result> | E | 0.466667 | If the ratio of a to b is 7 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? | {
"A": "4 / 15",
"B": "1 / 3",
"C": "2 / 5",
"D": "4 / 5",
"E": "7 / 15"
} | divide(multiply(7, 1), multiply(3, 5)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "a : b = 7 : 3 - - 1 b : c = 1 : 5 = > b : c = 3 : 15 - - 2 from 1 and 2 , we get a : c = 7 : 15 answer e" | other |
math_qa__UFVi31pngiEGDrAQ | The average of first 18 even numbers is? Choose the correct answer: A) 19 B) 18 C) 16 D) 11 E) 17 | <gadget id="calculator">18 + 1</gadget>
<output>19</output>
<result>A</result> | A | 19 | The average of first 18 even numbers is? | {
"A": "19",
"B": "18",
"C": "16",
"D": "11",
"E": "17"
} | add(18, const_1) | add(n0,const_1)| | "sum of 18 even numbers = 18 * 19 = 342 average = 342 / 18 = 19 answer : a" | general |
math_qa__vkE0QP6xtz7pEsky | A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.238 less than the sum lent. What was the sum lent? Choose the correct choice
A) 228 B) 350 C) 289 D) 500 E) 821 | <gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1 - (8/25)</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">238 / (17/25)</gadget>
<output>350</output>
<result>B</result> | B | 350 | A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.238 less than the sum lent. What was the sum lent? | {
"A": "228",
"B": "350",
"C": "289",
"D": "500",
"E": "821"
} | divide(238, subtract(const_1, divide(multiply(4, 8), const_100))) | multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)| | "p - 238 = ( p * 4 * 8 ) / 100 p = 350 answer : b" | gain |
math_qa__FtO7D1UYGflIMApM | For every integer n ≥ 3, the function g(n) is defined as the product of all the odd integers from 1 to n, inclusive. What is the value of g(99) – g(97)? Choose the correct choice from the following answers: A) 98 B) 100 C) 0 D) 99 E) 97 | <gadget id="calculator">99 - 1</gadget>
<output>98</output>
<result>A</result> | A | 98 | For every integer n ≥ 3, the function g(n) is defined as the product of all the odd integers from 1 to n, inclusive. What is the value of g(99) – g(97)? | {
"A": "98",
"B": "100",
"C": "0",
"D": "99",
"E": "97"
} | subtract(99, 1) | subtract(n2,n1) | g ( 99 ) = 1 * 3 * 5 * 7 * 9 * . . . * 99 g ( 97 ) = 1 * 3 * 5 * 7 * 9 * . . . * 97 g ( 99 ) - g ( 97 ) = 1 * 3 * 5 * 7 * 9 * . . . * 99 - 1 * 3 * 5 * 7 * 9 * . . . * 97 = 1 * 3 * 5 * 7 * 9 * . . . * 97 * ( 99 - 1 ) = 1 * 3 * 5 * 7 * 9 * . . . * 97 * 98 hence : a . | general |
math_qa__0olxV47dbFFac4b9 | In the first 5 overs of a cricket game, the run rate was only 2.1. What should be the rate in the remaining 30 overs to reach the target of 200 runs? Choose the correct answer:
A) 6.25
B) 6.28
C) 6.31
D) 6.19
E) 6.21 | <gadget id="calculator">5 * 2.1</gadget>
<output>10.5</output>
<gadget id="calculator">200 - 10.5</gadget>
<output>189.5</output>
<gadget id="calculator">189.5 / 30</gadget>
<output>6.316667</output>
<result>C</result> | C | 6.31 | In the first 5 overs of a cricket game, the run rate was only 2.1. What should be the rate in the remaining 30 overs to reach the target of 200 runs? | {
"A": "6.25",
"B": "6.28",
"C": "6.31",
"D": "6.19",
"E": "6.21"
} | divide(subtract(200, multiply(5, 2.1)), 30) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = [ 200 - ( 2.1 * 5 ) ] / 30 = 189.50 / 30 = 6.31 answer : c" | gain |
math_qa__CEDVrifjNigGYtuJ | What will be the compound interest on a sum of Rs. 40,000 after 3 years at the rate of 12% p.a.?
Choose one: A) s : 10123.19 B) s : 10123.29 C) s : 10123.20 D) s : 10123.28 E) s : 16197.12 | <gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 * 100</gadget>
<output>40_000</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(28/25) ** 3</gadget>
<output>21_952/15_625 = around 1.404928</output>
<gadget id="calculator">40_000 * (21_952/15_625)</gadget>
<output>1_404_928/25 = around 56_197.12</output>
<gadget id="calculator">(1_404_928/25) - 40_000</gadget>
<output>404_928/25 = around 16_197.12</output>
<result>E</result> | E | 16,197.12 | What will be the compound interest on a sum of Rs. 40,000 after 3 years at the rate of 12% p.a.? | {
"A": "s : 10123.19",
"B": "s : 10123.29",
"C": "s : 10123.20",
"D": "s : 10123.28",
"E": "s : 16197.12"
} | subtract(multiply(multiply(multiply(const_4, const_100), const_100), power(add(const_1, divide(12, const_100)), 3)), multiply(multiply(const_4, const_100), const_100)) | divide(n2,const_100)|multiply(const_100,const_4)|add(#0,const_1)|multiply(#1,const_100)|power(#2,n1)|multiply(#3,#4)|subtract(#5,#3)| | "amount = [ 40000 * ( 1 + 12 / 100 ) 3 ] = 40000 * 28 / 25 * 28 / 25 * 28 / 25 = rs . 56197.12 c . i . = ( 56197.12 - 40000 ) = rs : 16197.12 answer : e" | gain |
math_qa__AFwbzdPXWKNB2pTb | A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 370 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra? Choose the correct choice from the following choices.
A) 90 B) 190 C) 120 D) 130 E) 220 | <gadget id="calculator">12 * 370</gadget>
<output>4_440</output>
<gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">3_000 + 300</gadget>
<output>3_300</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">3_300 + 20</gadget>
<output>3_320</output>
<gadget id="calculator">4_440 - 3_320</gadget>
<output>1_120</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">1_120 / 4</gadget>
<output>280</output>
<gadget id="calculator">370 - 280</gadget>
<output>90</output>
<gadget id="calculator">280 - 90</gadget>
<output>190</output>
<result>B</result> | B | 190 | A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 370 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra? | {
"A": "90",
"B": "190",
"C": "120",
"D": "130",
"E": "220"
} | subtract(divide(subtract(multiply(12, 370), add(add(multiply(const_3, const_1000), multiply(const_3, const_100)), multiply(const_2, const_10))), subtract(12, 8)), subtract(370, divide(subtract(multiply(12, 370), add(add(multiply(const_3, const_1000), multiply(const_3, const_100)), multiply(const_2, const_10))), subtract(12, 8)))) | multiply(n0,n2)|multiply(const_1000,const_3)|multiply(const_100,const_3)|multiply(const_10,const_2)|subtract(n0,n1)|add(#1,#2)|add(#5,#3)|subtract(#0,#6)|divide(#7,#4)|subtract(n2,#8)|subtract(#8,#9) | orchestra seats - a balcony seats - b a + b = 370 and 12 a + 8 b = 3320 solving equations simultaneously ( multiply equation 1 with 8 and subtract from second equation ) 4 a = 3320 - 8 * 370 = 3320 - 2960 = 360 i . e . a = 90 and b = 370 - 90 = 280 more seats in balcony than orchestra = b - a = 280 - 90 = 190 answer : option b | general |
math_qa__Qdp3hyoZHbr9v0ez | If Bill can buy 3 pairs of jeans and 2 shirts for $69 or 2 pairs of jeans and 3 shirts for $81, how much does one shirt cost? Choose the correct answer:
A) $ 10 B) $ 12 C) $ 13.20 D) $ 21 E) $ 16.80 | <gadget id="calculator">81 * 3</gadget>
<output>243</output>
<gadget id="calculator">69 * 2</gadget>
<output>138</output>
<gadget id="calculator">243 - 138</gadget>
<output>105</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<gadget id="calculator">105 / 5</gadget>
<output>21</output>
<result>D</result> | D | 21 | If Bill can buy 3 pairs of jeans and 2 shirts for $69 or 2 pairs of jeans and 3 shirts for $81, how much does one shirt cost? | {
"A": "$ 10",
"B": "$ 12",
"C": "$ 13.20",
"D": "$ 21",
"E": "$ 16.80"
} | divide(subtract(multiply(81, 3), multiply(69, 2)), subtract(multiply(3, 3), multiply(2, 2))) | multiply(n0,n5)|multiply(n1,n2)|multiply(n0,n0)|multiply(n1,n1)|subtract(#0,#1)|subtract(#2,#3)|divide(#4,#5)| | "3 j + 2 s = 69 2 j + 3 s = 81 - - - - - - - - - - - - - - - - 5 j + 5 s = 150 - - - - ( divide by 5 ) - - - > j + s = 30 3 j + 2 s = j + 2 ( j + s ) = j + 60 = 69 - - - > j = 9 3 * 9 + 2 s = 69 27 + 2 s = 69 2 s = 42 s = 21 answer : d" | general |
math_qa__jtsBJrRqQHo895JH | A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 3 feet . How many feet does the squirrel travels if the post is 27 feet tall and 3 feet in circumference? Choose the correct choice from the following answers
A) 10 feet
B) 12 feet
C) 27 feet
D) 15 feet
E) 18 feet | <gadget id="calculator">27 / 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<result>C</result> | C | 27 | A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 3 feet . How many feet does the squirrel travels if the post is 27 feet tall and 3 feet in circumference? | {
"A": "10 feet",
"B": "12 feet",
"C": "27 feet",
"D": "15 feet",
"E": "18 feet"
} | multiply(divide(27, 3), 3) | divide(n1,n0)|multiply(n2,#0)| | "total circuit = 27 / 3 = 9 total feet squirrel travels = 9 * 3 = 27 feet answer : c" | geometry |
math_qa__jCBSrdqurNCRNAz9 | How many zeroes are there at the end of the number N, if N = 60! + 120! ? Choose one
A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<result>B</result> | B | 14 | How many zeroes are there at the end of the number N, if N = 60! + 120! ? | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | add(divide(60, add(const_4, const_1)), const_2) | add(const_1,const_4)|divide(n0,#0)|add(#1,const_2) | the number of zeroes at the end of 60 ! will be less than the number of zeroes at the end of 120 ! hence it is sufficient to calculate the number of zeroes at the end of 60 ! the number of zeroes = [ 60 / 5 ] + [ 60 / 25 ] + [ 60 / 125 ] = 12 + 2 + 0 = 14 the answer is b . | general |
math_qa__g2QV1E1jejkbNqqC | If x is a sum of all even integers on the interval 13...61 and y is their number, what is the GCD (x, y)?
Choose the correct choice from the following options
A) 1 B) 13 C) 26 D) 24 E) 1014 | <gadget id="calculator">13 - 10</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<result>D</result> | D | 24 | If x is a sum of all even integers on the interval 13...61 and y is their number, what is the GCD (x, y)? | {
"A": "1",
"B": "13",
"C": "26",
"D": "24",
"E": "1014"
} | multiply(add(subtract(13, const_10), const_2), add(subtract(13, const_10), const_2)) | subtract(n0,const_10)|add(#0,const_2)|multiply(#1,#1)| | "x = 14 + 16 + . . . + 60 = ( largest + smallest ) / 2 * ( # of terms ) = ( 14 + 60 ) / 2 * 24 = 37 * 24 . gcd of 24 and 37 * 22 is 24 . answer : d ." | general |
math_qa__GnIMWr3qPjDcVhkg | On dividing 265 by a number, the quotient is 12 and the remainder is 1. Find the divisor. Choose the correct choice: A) 12 B) 14 C) 16 D) 18 E) 22 | <gadget id="calculator">265 / 12</gadget>
<output>265/12 = around 22.083333</output>
<gadget id="calculator">floor(265/12)</gadget>
<output>22</output>
<result>E</result> | E | 22 | On dividing 265 by a number, the quotient is 12 and the remainder is 1. Find the divisor. | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "22"
} | floor(divide(265, 12)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 265 - 1 ) / 12 = 264 / 12 = 22 e )" | general |
math_qa__pVJShCAsPcHQBd8B | given two sets a = { 11 , 44 , 55 } and b = { 01 } , if one number is chosen from each set at random , what is the probability that the sum of both numbers is an even number Choose the correct choice from the following:
A) 1 / 4
B) 1 / 8
C) 1 / 7
D) 1 / 2
E) 3 | <gadget id="calculator">11 + 44</gadget>
<output>55</output>
<gadget id="calculator">55 / 2</gadget>
<output>55/2 = around 27.5</output>
<gadget id="calculator">(55/2) / 55</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | given two sets a = { 11 , 44 , 55 } and b = { 01 } , if one number is chosen from each set at random , what is the probability that the sum of both numbers is an even number | {
"A": "1 / 4",
"B": "1 / 8",
"C": "1 / 7",
"D": "1 / 2",
"E": "3"
} | divide(divide(add(11, 44), const_2), 55) | add(n0,n1)|divide(#0,const_2)|divide(#1,n2) | one way to look at it : the number from set a can be anything . the number selected from set b will determine whether the sum is odd or even . for example , if a 4 is selected from set a , we need a 0 from set b to get an even sum . if a 5 is selected from set a , we need a 1 from set b to get an even sum . and so on . so , p ( sum is even ) = p ( select any number from set aandselect the number from set b that makes the sum even ) = p ( select any number from set a ) xp ( select the number from set b that makes the sum even ) = 1 x 1 / 2 = 1 / 2 = d | general |
math_qa__PRcIthHwY1DBwgVQ | A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 230 per month. What is his monthly salary? Options:
A) 5000
B) 5750
C) 2878
D) 2990
E) 2771 | <gadget id="calculator">230 * 100</gadget>
<output>23_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">80 * (1/5)</gadget>
<output>16</output>
<gadget id="calculator">80 + 16</gadget>
<output>96</output>
<gadget id="calculator">100 - 96</gadget>
<output>4</output>
<gadget id="calculator">23_000 / 4</gadget>
<output>5_750</output>
<result>B</result> | B | 5,750 | A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 230 per month. What is his monthly salary? | {
"A": "5000",
"B": "5750",
"C": "2878",
"D": "2990",
"E": "2771"
} | divide(multiply(230, const_100), subtract(const_100, add(subtract(const_100, 20), multiply(subtract(const_100, 20), divide(20, const_100))))) | divide(n1,const_100)|multiply(n2,const_100)|subtract(const_100,n0)|multiply(#0,#2)|add(#3,#2)|subtract(const_100,#4)|divide(#1,#5)| | "income = rs . 100 expenditure = rs . 80 savings = rs . 20 present expenditure 80 * ( 20 / 100 ) = rs . 96 present savings = 100 â € “ 96 = rs . 4 100 - - - - - - 4 ? - - - - - - - - - 230 = > 5750 answer : b" | general |
math_qa__sdqxIUC4gDxnVHMf | A shipment of 250 smartphones contains 76 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective? Choose the correct option:
A) 1 / 250
B) 1 / 84
C) 1 / 11
D) 1 / 9
E) 1 / 3 | <gadget id="calculator">76 - 1</gadget>
<output>75</output>
<gadget id="calculator">76 * 75</gadget>
<output>5_700</output>
<gadget id="calculator">250 - 1</gadget>
<output>249</output>
<gadget id="calculator">250 * 249</gadget>
<output>62_250</output>
<gadget id="calculator">5_700 / 62_250</gadget>
<output>38/415 = around 0.091566</output>
<result>C</result> | C | 0.090909 | A shipment of 250 smartphones contains 76 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective? | {
"A": "1 / 250",
"B": "1 / 84",
"C": "1 / 11",
"D": "1 / 9",
"E": "1 / 3"
} | divide(multiply(76, subtract(76, const_1)), multiply(250, subtract(250, const_1))) | subtract(n1,const_1)|subtract(n0,const_1)|multiply(n1,#0)|multiply(n0,#1)|divide(#2,#3)| | "probability of chosing one defective phone from a lot of 250 which ontains 76 defective phones is = ( 76 / 250 ) probability of chosing one defective phone from a lot of 249 ( we already picked one ) which ontains 75 ( we already picked one ) defective phones is = ( 75 / 249 ) combined probability of series of events = product of the probabilities = ( 76 / 250 ) * ( 75 / 249 ) 76 / 250 is close to ( 7 / 23 ) and ( 75 / 249 ) = ( 25 / 83 ) so answer is ( 7 / 23 ) * ( 25 / 83 ) = ( 1 / 11 ) so , answer will be c" | other |
math_qa__YDrjask6419mI7b9 | A courtyard is 25 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is Choose the correct choice from the following answers
A) 16000 B) 18000 C) 20000 D) 22000 E) 24000 | <gadget id="calculator">25 * 100</gadget>
<output>2_500</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">2_500 * 1_600</gadget>
<output>4_000_000</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">4_000_000 / 200</gadget>
<output>20_000</output>
<result>C</result> | C | 20,000 | A courtyard is 25 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is | {
"A": "16000",
"B": "18000",
"C": "20000",
"D": "22000",
"E": "24000"
} | divide(multiply(multiply(25, const_100), multiply(16, const_100)), multiply(20, 10)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "explanation : number of bricks = courtyard area / 1 brick area = ( 2500 × 160020 × 10 ) = 20000 answer : option c" | physics |
math_qa__6Ivmsx7yoQMJfSVg | John found that the average of 15 numbers is 40. If 14 is added to each number then the mean of number is? Choose one
A) 54
B) 45
C) 65
D) 78
E) 64 | <gadget id="calculator">40 + 14</gadget>
<output>54</output>
<result>A</result> | A | 54 | John found that the average of 15 numbers is 40. If 14 is added to each number then the mean of number is? | {
"A": "54",
"B": "45",
"C": "65",
"D": "78",
"E": "64"
} | add(40, 14) | add(n1,n2) | ( x + x 1 + . . . x 14 ) / 15 = 40 54 option a | general |
math_qa__bZLiymEd21ufedGB | The perimeter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) Choose the correct answer.
A) 23.57 B) 23.54 C) 23.5 D) 24.55 E) 25.14 | <gadget id="calculator">14 + 18</gadget>
<output>32</output>
<gadget id="calculator">2 * 32</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">2 * pi * 8</gadget>
<output>16*pi = around 50.265482</output>
<gadget id="calculator">(16*pi) / 2</gadget>
<output>8*pi = around 25.132741</output>
<gadget id="calculator">floor(8*pi)</gadget>
<output>25</output>
<result>E</result> | E | 25.14 | The perimeter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) | {
"A": "23.57",
"B": "23.54",
"C": "23.5",
"D": "24.55",
"E": "25.14"
} | floor(divide(circumface(divide(divide(multiply(const_2, add(14, 18)), const_4), const_2)), const_2)) | add(n0,n1)|multiply(#0,const_2)|divide(#1,const_4)|divide(#2,const_2)|circumface(#3)|divide(#4,const_2)|floor(#5)| | "let the side of the square be a cm . perimeter of the rectangle = 2 ( 18 + 14 ) = 64 cm perimeter of the square = 64 cm i . e . 4 a = 64 a = 16 diameter of the semicircle = 16 cm circumference of the semicircle = 1 / 2 ( ∏ ) ( 16 ) = 1 / 2 ( 22 / 7 ) ( 16 ) = 25.14 cm to two decimal places answer : e" | geometry |
math_qa__ei8kTAiHGwob008R | Danny and Steve are running towards each other, each one from his own house. Danny can reach Steve's house in 31 minutes of running, which is half the time it takes Steve to reach Danny's house. If the two started to run at the same time, how much time longer will it take Steve to reach the halfway point between their houses than Danny to reach the halfway point between their houses?
Choose the correct choice
A) 15.5 minutes B) 31 minutes C) 35 minutes D) 62 minutes E) 93 minutes | <gadget id="calculator">31 / 2</gadget>
<output>31/2 = around 15.5</output>
<result>A</result> | A | 15.5 | Danny and Steve are running towards each other, each one from his own house. Danny can reach Steve's house in 31 minutes of running, which is half the time it takes Steve to reach Danny's house. If the two started to run at the same time, how much time longer will it take Steve to reach the halfway point between their houses than Danny to reach the halfway point between their houses? | {
"A": "15.5 minutes",
"B": "31 minutes",
"C": "35 minutes",
"D": "62 minutes",
"E": "93 minutes"
} | divide(31, const_2) | divide(n0,const_2)| | "danny ' s time is 31 minutes . the time to reach halfway is 15.5 minutes . steve ' s time is 62 minutes . the time to reach halfway is 31 minutes . the time difference is 31 - 15.5 = 15.5 minutes the answer is a ." | physics |
math_qa__dXJZI9rFogNlzZBu | In a group of 140 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20? Choose the correct choice from the following choices: A) 0.35 B) 0.55 C) 0.65 D) 0.75 E) 0.85 | <gadget id="calculator">140 - 90</gadget>
<output>50</output>
<gadget id="calculator">50 / 140</gadget>
<output>5/14 = around 0.357143</output>
<result>A</result> | A | 0.35 | In a group of 140 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20? | {
"A": "0.35",
"B": "0.55",
"C": "0.65",
"D": "0.75",
"E": "0.85"
} | divide(subtract(140, 90), 140) | subtract(n0,n1)|divide(#0,n0)| | "number of people whose age is less than 20 is given by 140 - 90 = 50 probability p that a person selected at random from the group is less than 20 is given by 50 / 140 = 0.35 correct answer a" | general |
math_qa__caomwzLWVQrQBLZw | if radius of a circle is reduced by 10%,then how much % of its area will be reduced? Choose the correct choice
A) 10 % B) 19 % C) 20 % D) 36 % E) 30 % | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) ** 2</gadget>
<output>81/100 = around 0.81</output>
<gadget id="calculator">1 - (81/100)</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">(19/100) * 100</gadget>
<output>19</output>
<result>B</result> | B | 19 | if radius of a circle is reduced by 10%,then how much % of its area will be reduced? | {
"A": "10 %",
"B": "19 %",
"C": "20 %",
"D": "36 %",
"E": "30 %"
} | multiply(subtract(const_1, power(divide(subtract(const_100, 10), const_100), const_2)), const_100) | subtract(const_100,n0)|divide(#0,const_100)|power(#1,const_2)|subtract(const_1,#2)|multiply(#3,const_100) | let initial radius = a then , area = π a ^ 2 . new radius = 90 % of a = 9 a / 10 . new area = π * 81 a ^ 2 / 100 = 81 / 100 π a ^ 2 reduce in area = [ π a ^ 2 - 81 / 100 π a ^ 2 ] = 19 / 100 π a ^ 2 % reduce = [ ( 19 * π a ^ 2 / 100 ) * ( 1 * 100 / π a ^ 2 ) ] % = 19 % answer b | geometry |
math_qa__PzDFaiPKrcrwzsVN | In a school with 640 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is
Pick one.
A) 160 B) 200 C) 250 D) 350 E) none | <gadget id="calculator">12 * 640</gadget>
<output>7_680</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">11 + (3/4)</gadget>
<output>47/4 = around 11.75</output>
<gadget id="calculator">(47/4) * 640</gadget>
<output>7_520</output>
<gadget id="calculator">7_680 - 7_520</gadget>
<output>160</output>
<result>A</result> | A | 160 | In a school with 640 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is | {
"A": "160",
"B": "200",
"C": "250",
"D": "350",
"E": "none"
} | subtract(multiply(12, 640), multiply(add(11, divide(9, 12)), 640)) | divide(n4,n1)|multiply(n0,n1)|add(n2,#0)|multiply(n0,#2)|subtract(#1,#3) | sol . let the number of grils be x . then , number of boys = ( 640 - x ) . then , ( 11 3 / 4 × 640 ) ⇔ 11 x + 12 ( 640 - x ) ⇔ x = 7680 - 7520 ⇔ 160 . answer a | general |
math_qa__uWjpGWQm5e3STsVE | Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 4 days? Choose the correct choice from the following answers
A) 2 / 5 B) 1 / 6 C) 1 / 4 D) 1 / 9 E) 2 / 9 | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(1/30) + (1/45)</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">4 * (1/18)</gadget>
<output>2/9 = around 0.222222</output>
<result>E</result> | E | 0.222222 | Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 4 days? | {
"A": "2 / 5",
"B": "1 / 6",
"C": "1 / 4",
"D": "1 / 9",
"E": "2 / 9"
} | multiply(4, add(divide(const_1, 30), divide(const_1, 45))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)| | "a ' s one day ' s work = 1 / 30 b ' s one day ' s work = 1 / 45 ( a + b ) ' s one day ' s work = 1 / 30 + 1 / 45 = 1 / 18 the part of the work completed in 4 days = 4 ( 1 / 18 ) = 2 / 9 . answer e" | physics |
math_qa__HkL9z4INhy8OvInW | 30 pens and 75 pencils were purchased for 690. If the average price of a pencil was 2.00, find the average price of a pen.
Pick one: A) 10 B) 11 C) 18 D) 13 E) 14 | <gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">690 - 150</gadget>
<output>540</output>
<gadget id="calculator">540 / 30</gadget>
<output>18</output>
<result>C</result> | C | 18 | 30 pens and 75 pencils were purchased for 690. If the average price of a pencil was 2.00, find the average price of a pen. | {
"A": "10",
"B": "11",
"C": "18",
"D": "13",
"E": "14"
} | divide(subtract(690, multiply(75, 2.00)), 30) | multiply(n1,n3)|subtract(n2,#0)|divide(#1,n0)| | "since average price of a pencil = 2 ∴ price of 75 pencils = 150 ∴ price of 30 pens = ( 690 – 150 ) = 540 ∴ average price of a pen = 540 ⁄ 60 = 18 answer c" | general |
math_qa__jT2wVqj4OSl0pKt6 | If the price of a TV is first decreased by 20% and then increased by 45%, then the net change in the price will be : Choices.
A) 4 % increase B) 10 % increase C) 10 % decrease D) 16 % increase E) none of these | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">100 + 45</gadget>
<output>145</output>
<gadget id="calculator">80 * 145</gadget>
<output>11_600</output>
<gadget id="calculator">11_600 / 100</gadget>
<output>116</output>
<gadget id="calculator">116 - 100</gadget>
<output>16</output>
<result>D</result> | D | 16 | If the price of a TV is first decreased by 20% and then increased by 45%, then the net change in the price will be : | {
"A": "4 % increase",
"B": "10 % increase",
"C": "10 % decrease",
"D": "16 % increase",
"E": "none of these"
} | subtract(divide(multiply(subtract(const_100, 20), add(const_100, 45)), const_100), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(#3,const_100)| | "explanation : solution : let the original price be rs . 100 . new final price = 145 % of ( 80 % of 100 ) = rs . 145 / 100 * 80 / 100 * 100 = rs . 116 . . ' . increase = 16 % answer : d" | general |
math_qa__brzmNhK3X6qcmpKY | Two dogsled teams raced across a 300 mile course in Wyoming. Team A finished the course in 3 fewer hours than team E. If team A's average speed was 5 mph greater than team E's, what was team E's average mph? Select the correct option: A) 12 B) 15 C) 18 D) 20 E) 25 | <gadget id="calculator">300 / 5</gadget>
<output>60</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<result>D</result> | D | 20 | Two dogsled teams raced across a 300 mile course in Wyoming. Team A finished the course in 3 fewer hours than team E. If team A's average speed was 5 mph greater than team E's, what was team E's average mph? | {
"A": "12",
"B": "15",
"C": "18",
"D": "20",
"E": "25"
} | divide(divide(300, 5), 3) | divide(n0,n2)|divide(#0,n1) | this is a very specific format that has appeared in a handful of real gmat questions , and you may wish to learn to recognize it : here we have a * fixed * distance , and we are given the difference between the times and speeds of two things that have traveled that distance . this is one of the very small number of question formats where backsolving is typically easier than solving directly , since the direct approach normally produces a quadratic equation . say team e ' s speed was s . then team e ' s time is 300 / s . team a ' s speed was then s + 5 , and team a ' s time was then 300 / ( s + 5 ) . we need to find an answer choice for s so that the time of team a is 3 less than the time of team e . that is , we need an answer choice so that 300 / ( s + 5 ) = ( 300 / s ) - 3 . you can now immediately use number properties to zero in on promising answer choices : the times in these questions will always work out to be integers , and we need to divide 300 by s , and by s + 5 . so we want an answer choice s which is a factor of 300 , and for which s + 5 is also a factor of 300 . so you can rule out answers a and c immediately , since s + 5 wo n ' t be a divisor of 300 in those cases ( sometimes using number properties you get to the correct answer without doing any other work , but unfortunately that ' s not the case here ) . testing the other answer choices , if you try answer d , you find the time for team e is 15 hours , and for team a is 12 hours , and since these differ by 3 , as desired , d is correct . | physics |
math_qa__YHS1bNayj91Ogiht | Sahil purchased a machine at Rs 13000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it. Answers.
A) rs . 22000 B) rs . 24500 C) rs . 26500 D) rs . 28500 E) none of these | <gadget id="calculator">13_000 + 5_000</gadget>
<output>18_000</output>
<gadget id="calculator">18_000 + 1_000</gadget>
<output>19_000</output>
<gadget id="calculator">19_000 / 100</gadget>
<output>190</output>
<gadget id="calculator">190 * 50</gadget>
<output>9_500</output>
<gadget id="calculator">19_000 + 9_500</gadget>
<output>28_500</output>
<result>D</result> | D | 28,500 | Sahil purchased a machine at Rs 13000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it. | {
"A": "rs . 22000",
"B": "rs . 24500",
"C": "rs . 26500",
"D": "rs . 28500",
"E": "none of these"
} | add(add(add(13000, 5000), 1000), multiply(divide(add(add(13000, 5000), 1000), const_100), 50)) | add(n0,n1)|add(n2,#0)|divide(#1,const_100)|multiply(n3,#2)|add(#1,#3) | explanation : question seems a bit tricky , but it is very simple . just calculate all cost price , then get 150 % of cp . c . p . = 13000 + 5000 + 1000 = 19000 150 % of 19000 = 150 / 100 * 19000 = 28500 option d | gain |
math_qa__yiMJKwR5XkkNLu2R | The area of a square field is A square feet and the perimeter is p feet. If 6A=6(2p+9), what is the perimeter of the field, in feet? (Here A=a^2) Select
A) 28 B) 36 C) 40 D) 56 E) 84 | <gadget id="calculator">4 * 9</gadget>
<output>36</output>
<result>B</result> | B | 36 | The area of a square field is A square feet and the perimeter is p feet. If 6A=6(2p+9), what is the perimeter of the field, in feet? (Here A=a^2) | {
"A": "28",
"B": "36",
"C": "40",
"D": "56",
"E": "84"
} | multiply(const_4, 9) | multiply(n3,const_4) | you can also solve this via using the given numbers in the answer choices ! of course you need to be aware of the basic properties as outlined by the other posts above ( a = x ^ 2 and p = 4 x ) starting with d you will notice that x = 14 is way too big for your area ( 14 ^ 2 ) and will not satisfy : 6 a = 6 ( 2 p + 9 ) or a = 2 p + 9 - - > eliminate d and e now pick b ( its either too big , then its a , or too small then you know its c or it is b itsself ) and picking b indeed solves the problem ! ( 36 / 4 - - > 9 ; a = 9 ^ 2 = 81 and 81 = 2 x 36 + 9 ) | geometry |
math_qa__LOkIr0YuthnkwPDO | How many numbers from 10 to 43 are exactly divisible by 3? Choose the correct choice from the following answers: A) 13 B) 11 C) 16 D) 17 E) 18 | <gadget id="calculator">43 / 3</gadget>
<output>43/3 = around 14.333333</output>
<gadget id="calculator">floor(43/3)</gadget>
<output>14</output>
<gadget id="calculator">14 * 3</gadget>
<output>42</output>
<gadget id="calculator">10 / 3</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">floor(10/3)</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">42 - 12</gadget>
<output>30</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<result>B</result> | B | 11 | How many numbers from 10 to 43 are exactly divisible by 3? | {
"A": "13",
"B": "11",
"C": "16",
"D": "17",
"E": "18"
} | add(divide(subtract(multiply(floor(divide(43, 3)), 3), multiply(add(floor(divide(10, 3)), const_1), 3)), 3), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "12 , 15 , 18 , 21 , 24 , 27 , 30 , 33 , 36 , 39 , 42 . 11 numbers . 10 / 3 = 3 and 43 / 3 = 14 = = > 14 - 3 = 11 . therefore 11 digits b )" | general |
math_qa__zBhRYpy8xCbJSPQW | Train speed 36kph. Dist travelled in 3minutes in meters Select: A) 1600 B) 1700 C) 1800 D) 1900 E) 2000 | <gadget id="calculator">3 / 60</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">36 * (1/20)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 1_000</gadget>
<output>1_800</output>
<result>C</result> | C | 1,800 | Train speed 36kph. Dist travelled in 3minutes in meters | {
"A": "1600",
"B": "1700",
"C": "1800",
"D": "1900",
"E": "2000"
} | multiply(multiply(36, divide(3, const_60)), const_1000) | divide(n1,const_60)|multiply(n0,#0)|multiply(#1,const_1000) | 36 kmph = 10 m / sec d = 10 * 180 = 1800 meters answer : c | physics |
math_qa__HpA3wKW3lnDCiahR | 300 first-time customers of a fashion store were surveyed for their shopping experience right after leaving the store. 60% of the customers in the survey had purchased clothes for less than $100. 40% of the customers in the survey reported they were overall satisfied with their purchase. 65% of the customers that had purchased clothes for less than $100 reported they were overall satisfied with their purchase. What percent of the customers surveyed purchased clothes for at least $100 and reported that they were NOT overall satisfied with their purchase?
Answers:
A) 1 B) 25 C) 35 D) 45 E) 75 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 300</gadget>
<output>120</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">300 * (3/5)</gadget>
<output>180</output>
<gadget id="calculator">(13/20) * 180</gadget>
<output>117</output>
<gadget id="calculator">120 - 117</gadget>
<output>3</output>
<gadget id="calculator">3 / 300</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 100</gadget>
<output>1</output>
<result>A</result> | A | 1 | 300 first-time customers of a fashion store were surveyed for their shopping experience right after leaving the store. 60% of the customers in the survey had purchased clothes for less than $100. 40% of the customers in the survey reported they were overall satisfied with their purchase. 65% of the customers that had purchased clothes for less than $100 reported they were overall satisfied with their purchase. What percent of the customers surveyed purchased clothes for at least $100 and reported that they were NOT overall satisfied with their purchase? | {
"A": "1",
"B": "25",
"C": "35",
"D": "45",
"E": "75"
} | multiply(divide(subtract(multiply(divide(40, 100), 300), multiply(divide(65, 100), multiply(300, divide(60, 100)))), 300), 100) | divide(n3,n2)|divide(n4,n2)|divide(n1,n2)|multiply(n0,#0)|multiply(n0,#2)|multiply(#1,#4)|subtract(#3,#5)|divide(#6,n0)|multiply(#7,n2)| | "out of 300 - 180 purchased for less than 100 $ 120 for more out of 300 - 120 responded as satisfied and 180 responded disatisfied out of 180 ( purchased less than 100 $ ) - 65 % = 117 responded as satisfied , so remaining satisfied are 120 - 117 = 3 so 3 is what percentage of 300 - 1 % so the answer should be a" | general |
math_qa__tzNZWKDdl2Hx9LCy | In a company of 148 employees, 92 are females. A total of 78 employees have advanced degrees and the rest have a college degree only. If 31 employees are males with college degree only, how many employees are females with advanced degrees?
Choose the correct choice from the following
A) 50 B) 51 C) 52 D) 53 E) 54 | <gadget id="calculator">148 - 92</gadget>
<output>56</output>
<gadget id="calculator">56 - 31</gadget>
<output>25</output>
<gadget id="calculator">78 - 25</gadget>
<output>53</output>
<result>D</result> | D | 53 | In a company of 148 employees, 92 are females. A total of 78 employees have advanced degrees and the rest have a college degree only. If 31 employees are males with college degree only, how many employees are females with advanced degrees? | {
"A": "50",
"B": "51",
"C": "52",
"D": "53",
"E": "54"
} | subtract(78, subtract(subtract(148, 92), 31)) | subtract(n0,n1)|subtract(#0,n3)|subtract(n2,#1)| | "the number of males is 148 - 92 = 56 . the number of males with advanced degrees is 56 - 31 = 25 . the number of females with advanced degrees is 78 - 25 = 53 . the answer is d ." | geometry |
math_qa__dIdjMeLW1hxx4KUd | A cycle is bought for Rs.900 and sold for Rs.1260, find the gain percent? Options.
A) 39 % B) 20 % C) 40 % D) 74 % E) 83 % | <gadget id="calculator">1_260 - 900</gadget>
<output>360</output>
<gadget id="calculator">360 / 900</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>C</result> | C | 40 | A cycle is bought for Rs.900 and sold for Rs.1260, find the gain percent? | {
"A": "39 %",
"B": "20 %",
"C": "40 %",
"D": "74 %",
"E": "83 %"
} | multiply(divide(subtract(1260, 900), 900), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "900 - - - - 360 100 - - - - ? = > 40 % answer : c" | gain |
math_qa__UsvNPEyT7WR0Udjr | A van takes 6 hours to cover a distance of 288 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice:
A) 50 kmph B) 60 kmph C) 32 kmph D) 80 kmph E) 90 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 6</gadget>
<output>9</output>
<gadget id="calculator">288 / 9</gadget>
<output>32</output>
<result>C</result> | C | 32 | A van takes 6 hours to cover a distance of 288 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "50 kmph",
"B": "60 kmph",
"C": "32 kmph",
"D": "80 kmph",
"E": "90 kmph"
} | divide(288, multiply(divide(3, 2), 6)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1) | time = 6 distence = 288 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 288 / 9 = 32 kmph c | physics |
math_qa__Ozpt8asdliVnS0oV | A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 30 sec. What is the length of the goods train? Choose the correct option
A) 299 B) 277 C) 350 D) 270 E) 281 | <gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">600 - 250</gadget>
<output>350</output>
<result>C</result> | C | 350 | A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 30 sec. What is the length of the goods train? | {
"A": "299",
"B": "277",
"C": "350",
"D": "270",
"E": "281"
} | subtract(multiply(multiply(divide(72, const_3600), const_1000), 30), 250) | divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)| | "speed = 72 * 5 / 18 = 20 m / sec . time = 30 sec . let the length of the train be x meters . then , ( x + 250 ) / 30 = 20 x = 350 m . answer : c" | physics |
math_qa__5p6AVqIgfHlRe99o | If the price of a certain computer increased 30 percent from d dollars to 364 dollars, then 2d = Choose the correct choice from the following answers:
A) 540
B) 570
C) 619
D) 649
E) 560 | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">364 / (13/10)</gadget>
<output>280</output>
<gadget id="calculator">280 * 2</gadget>
<output>560</output>
<result>E</result> | E | 560 | If the price of a certain computer increased 30 percent from d dollars to 364 dollars, then 2d = | {
"A": "540",
"B": "570",
"C": "619",
"D": "649",
"E": "560"
} | multiply(divide(364, divide(add(const_100, 30), const_100)), 2) | add(n0,const_100)|divide(#0,const_100)|divide(n1,#1)|multiply(n2,#2) | before price increase price = d after 30 % price increase price = d + ( 30 / 100 ) * d = 1.3 d = 364 ( given ) i . e . d = 364 / 1.3 = $ 280 i . e . 2 d = 2 * 280 = 560 answer : option e | general |
math_qa__gqfnEFENMXIHBo7h | Find the value of 72518 x 9999 = m? Choose the correct choice from the following: A) 456578972 B) 436567874 C) 653658791 D) 725117481 E) 725107482 | <gadget id="calculator">9_999 - 4</gadget>
<output>9_995</output>
<gadget id="calculator">9_995 * 72_518</gadget>
<output>724_817_410</output>
<result>E</result> | E | 725,107,482 | Find the value of 72518 x 9999 = m? | {
"A": "456578972",
"B": "436567874",
"C": "653658791",
"D": "725117481",
"E": "725107482"
} | multiply(subtract(9999, const_4), 72518) | subtract(n1,const_4)|multiply(#0,n0)| | "72518 x 9999 = 72518 x ( 10000 - 1 ) = 72518 x 10000 - 72518 x 1 = 725180000 - 72518 = 725107482 e" | general |
math_qa__UNqc5MFDk6KCgYGf | The first doughnut is priced at $1 and then if you purchase additional doughnuts as dozens then the price is $6/dozen. What is the total number of doughnut purchased if you paid $19? Choose one:
A) 24 B) 25 C) 35 D) 36 E) 37 | <gadget id="calculator">19 / 6</gadget>
<output>19/6 = around 3.166667</output>
<gadget id="calculator">(19/6) * 12</gadget>
<output>38</output>
<result>E</result> | E | 37 | The first doughnut is priced at $1 and then if you purchase additional doughnuts as dozens then the price is $6/dozen. What is the total number of doughnut purchased if you paid $19? | {
"A": "24",
"B": "25",
"C": "35",
"D": "36",
"E": "37"
} | multiply(divide(19, 6), const_12) | divide(n2,n1)|multiply(#0,const_12)| | "a is the number of dozen of doughnuts at a price of $ 6 / dozen 1 + 6 a = 19 a = 3 the total number of doughnuts purchased - - > 1 + 3 * 12 = 37 answer : e" | general |
math_qa__9GMksdVFZ2eQkdCX | Factory X's bulbs work for over 4000 hours in 59% of cases, whereas factory Y's bulbs work for over 4000 hours in 65% of cases. It is known that factory X supplies 60% of the total bulbs available. What is the chance that a purchased bulb will work for longer than 4000 hours?
Choose the correct answer
A) 66.4 % B) 61.4 % C) 77.4 % D) 65 % E) 53.9 % | <gadget id="calculator">59 + 65</gadget>
<output>124</output>
<gadget id="calculator">124 / 2</gadget>
<output>62</output>
<result>B</result> | B | 61.4 | Factory X's bulbs work for over 4000 hours in 59% of cases, whereas factory Y's bulbs work for over 4000 hours in 65% of cases. It is known that factory X supplies 60% of the total bulbs available. What is the chance that a purchased bulb will work for longer than 4000 hours? | {
"A": "66.4 %",
"B": "61.4 %",
"C": "77.4 %",
"D": "65 %",
"E": "53.9 %"
} | divide(add(59, 65), const_2) | add(n1,n3)|divide(#0,const_2)| | "for x , 60 % of 59 % will work . for y , 40 % of 65 % will work . * 40 % is the rest of the bulb supply in the market . so , the probability that a purchased bulb will work is : 0.60 ( 0.59 ) = . 354 0.40 ( 0.65 ) = 0.26 the combined probability then is 35.4 + 26.00 = 61.4 % ans b" | physics |
math_qa__LsHLQ7OG19i68c87 | Walking 6/7 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school? Answers:
A) 28 m B) 20 m C) 22 m D) 23 m E) 24 m | <gadget id="calculator">4 * 6</gadget>
<output>24</output>
<result>E</result> | E | 24 | Walking 6/7 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school? | {
"A": "28 m",
"B": "20 m",
"C": "22 m",
"D": "23 m",
"E": "24 m"
} | multiply(4, 6) | multiply(n0,n2) | speed ratio = 1 : 6 / 7 = 7 : 6 time ratio = 6 : 4 1 - - - - - - - - 6 4 - - - - - - - - - ? = > 24 m answer : e | gain |
math_qa__KiEmc6nJFNnGUbt8 | If 6a = 7b = 20, then 84ab = Pick one:
A) 50
B) 100
C) 625
D) 800
E) 1250 | <gadget id="calculator">20 / 6</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">20 / 7</gadget>
<output>20/7 = around 2.857143</output>
<gadget id="calculator">(10/3) * (20/7)</gadget>
<output>200/21 = around 9.52381</output>
<gadget id="calculator">84 * (200/21)</gadget>
<output>800</output>
<result>D</result> | D | 800 | If 6a = 7b = 20, then 84ab = | {
"A": "50",
"B": "100",
"C": "625",
"D": "800",
"E": "1250"
} | multiply(84, multiply(divide(20, 6), divide(20, 7))) | divide(n2,n0)|divide(n2,n1)|multiply(#0,#1)|multiply(n3,#2)| | "6 a * 7 b = 20 * 20 = 400 42 ab = 400 i . e . 84 ab = 800 answer : option d" | general |
math_qa__60aF9GJaMdH6CYeM | A is twice efficient as B and together they do the same work in as much time as C and D together. If C and D can complete the work in 20 and 30 daysrespectively, working alone ,then in how many days A can complete the work individually: Pick: A) 12 days B) 18 days C) 24 days D) 30 days E) none of these | <gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 20</gadget>
<output>18</output>
<result>B</result> | B | 18 | A is twice efficient as B and together they do the same work in as much time as C and D together. If C and D can complete the work in 20 and 30 daysrespectively, working alone ,then in how many days A can complete the work individually: | {
"A": "12 days",
"B": "18 days",
"C": "24 days",
"D": "30 days",
"E": "none of these"
} | multiply(divide(subtract(subtract(30, 20), const_1), subtract(30, 20)), 20) | subtract(n1,n0)|subtract(#0,const_1)|divide(#1,#0)|multiply(n0,#2) | explanation : a + b = c + d | | | | ratio of efficiency 10 x + 5 x 9 x + 6 x | ________| | _________| 15 x 15 x therefore , ratio of efficiency of a : c = 10 : 9 therefore , ratio of days taken by a : c = 9 : 10 therefore , number of days taken by a = 18 days answer : b | physics |
math_qa__HECzzXROgLsiXapj | A $500 investment and a $1,500 investment have a combined yearly return of 19 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? Choose the correct choice from the following options:
A) 9 %
B) 10 %
C) 23 %
D) 21 %
E) 22 % | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">500 + 1_500</gadget>
<output>2_000</output>
<gadget id="calculator">19 / 100</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">2_000 * (19/100)</gadget>
<output>380</output>
<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">500 * (7/100)</gadget>
<output>35</output>
<gadget id="calculator">380 - 35</gadget>
<output>345</output>
<gadget id="calculator">345 / 1_500</gadget>
<output>23/100 = around 0.23</output>
<gadget id="calculator">(23/100) * 100</gadget>
<output>23</output>
<result>C</result> | C | 23 | A $500 investment and a $1,500 investment have a combined yearly return of 19 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? | {
"A": "9 %",
"B": "10 %",
"C": "23 %",
"D": "21 %",
"E": "22 %"
} | multiply(divide(subtract(multiply(add(500, multiply(const_3, 500)), divide(19, const_100)), multiply(500, divide(7, const_100))), multiply(const_3, 500)), const_100) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_3)|add(n0,#2)|multiply(n0,#1)|multiply(#3,#0)|subtract(#5,#4)|divide(#6,#2)|multiply(#7,const_100)| | "the equation we can form the question : return on total investment = sum of individual investments ( 500 + 1500 ) ( 19 ) = ( 500 â ˆ — 7 ) + ( 1500 x ) , where x is the return on investment of 1500 . solving the equation , we get x = 23 % ( option c ) answer : c" | gain |
math_qa__2yw64wwYWxmQscAX | In the fifth grade at Parkway elementary school there are 450 students. 320 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer? Choose the most appropriate option.
A) 69 . B) 73 . C) 81 . D) 95 . E) 108 . | <gadget id="calculator">450 - 320</gadget>
<output>130</output>
<gadget id="calculator">250 * 86</gadget>
<output>21_500</output>
<gadget id="calculator">21_500 / 100</gadget>
<output>215</output>
<gadget id="calculator">250 - 215</gadget>
<output>35</output>
<gadget id="calculator">130 - 35</gadget>
<output>95</output>
<result>D</result> | D | 95 | In the fifth grade at Parkway elementary school there are 450 students. 320 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer? | {
"A": "69 .",
"B": "73 .",
"C": "81 .",
"D": "95 .",
"E": "108 ."
} | subtract(subtract(450, 320), subtract(250, divide(multiply(250, 86), const_100))) | multiply(n2,n3)|subtract(n0,n1)|divide(#0,const_100)|subtract(n2,#2)|subtract(#1,#3)| | "total students = 450 boys = 320 , girls = 130 total playing soccer = 250 86 % of 250 = 215 are boys who play soccer . girls who play soccer = 35 . total girls who do not play soccer = 130 - 35 = 95 . correct option : d" | gain |
math_qa__Mw3tZPzs0j3M35qr | Excluding stoppages, the speed of a train is 48 kmph and including stoppages it is 32 kmph. Of how many minutes does the train stop per hour? Choose the correct answer:
A) 40 B) 30 C) 20 D) 10 E) 5 | <gadget id="calculator">32 / 48</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">60 * (2/3)</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<result>C</result> | C | 20 | Excluding stoppages, the speed of a train is 48 kmph and including stoppages it is 32 kmph. Of how many minutes does the train stop per hour? | {
"A": "40",
"B": "30",
"C": "20",
"D": "10",
"E": "5"
} | subtract(const_60, multiply(const_60, divide(32, 48))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "explanation : t = 16 / 48 * 60 = 20 answer : option c" | physics |
math_qa__bFs7tnJ92cZTqY5Z | At a kennel with 80 dogs, 45 of the dogs wear tags and 40 wear flea collars. If 6 of the dogs wear both, then how many of the dogs wear neither a collar nor tags?
Choose one
A) 1 B) 6 C) 34 D) 79 E) 85 | <gadget id="calculator">45 + 40</gadget>
<output>85</output>
<gadget id="calculator">85 - 6</gadget>
<output>79</output>
<gadget id="calculator">80 - 79</gadget>
<output>1</output>
<result>A</result> | A | 1 | At a kennel with 80 dogs, 45 of the dogs wear tags and 40 wear flea collars. If 6 of the dogs wear both, then how many of the dogs wear neither a collar nor tags? | {
"A": "1",
"B": "6",
"C": "34",
"D": "79",
"E": "85"
} | subtract(80, subtract(add(45, 40), 6)) | add(n1,n2)|subtract(#0,n3)|subtract(n0,#1) | dogs wear neither a collar nor tags = 80 - ( 45 + 40 - 6 ) dogs wear neither a collar nor tags = 80 - 79 dogs wear neither a collar nor tags = 80 - 79 hence , answer will be 1 answer : a | other |
math_qa__nGQYHLhDAUGM0EkE | The ratio 9 : 5 expressed as a percent equals Choose the correct answer.
A) 12.5 % B) 40 % C) 180 % D) 125 % E) none | <gadget id="calculator">9 / 5</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 100</gadget>
<output>180</output>
<result>C</result> | C | 180 | The ratio 9 : 5 expressed as a percent equals | {
"A": "12.5 %",
"B": "40 %",
"C": "180 %",
"D": "125 %",
"E": "none"
} | multiply(divide(9, 5), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "solution 9 : 5 = 9 / 5 = ( 9 / 5 x 100 ) % . = 180 % . answer c" | general |
math_qa__6pmctCPPmJ42PCy1 | A number when divided by a certain divisor left remainder 241, when twice the number was divided by the same divisor, the remainder was 115. Find the divisor? Options.
A) 370 B) 365 C) 380 D) 367 E) 460 | <gadget id="calculator">241 * 2</gadget>
<output>482</output>
<gadget id="calculator">482 - 115</gadget>
<output>367</output>
<result>D</result> | D | 367 | A number when divided by a certain divisor left remainder 241, when twice the number was divided by the same divisor, the remainder was 115. Find the divisor? | {
"A": "370",
"B": "365",
"C": "380",
"D": "367",
"E": "460"
} | subtract(multiply(241, const_2), 115) | multiply(n0,const_2)|subtract(#0,n1)| | "easy solution : n = dq 1 + 241 2 n = 2 dq 1 + 482 - ( 1 ) 2 n = dq 2 + 115 - ( 2 ) as ( 1 ) = ( 2 ) = 2 n d * ( q 2 - 2 q 1 ) = 367 d * some integer = 367 checking all options only ( d ) syncs with it . answer d" | general |
math_qa__uuCSXfDvb3fsSBn4 | Find the value of x. (47% of 1442 - 36% of 1412) + 65 = x? Choose the correct choice from the following answers:
A) 1
B) 2
C) 3
D) 4
E) 5 | <gadget id="calculator">47 / 100</gadget>
<output>47/100 = around 0.47</output>
<gadget id="calculator">(47/100) * 1_442</gadget>
<output>33_887/50 = around 677.74</output>
<gadget id="calculator">36 / 100</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 1_412</gadget>
<output>12_708/25 = around 508.32</output>
<gadget id="calculator">(33_887/50) - (12_708/25)</gadget>
<output>8_471/50 = around 169.42</output>
<gadget id="calculator">(8_471/50) + 65</gadget>
<output>11_721/50 = around 234.42</output>
<gadget id="calculator">(11_721/50) % 10</gadget>
<output>221/50 = around 4.42</output>
<gadget id="calculator">(221/50) + 1</gadget>
<output>271/50 = around 5.42</output>
<gadget id="calculator">floor(271/50)</gadget>
<output>5</output>
<result>E</result> | E | 5 | Find the value of x. (47% of 1442 - 36% of 1412) + 65 = x? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | floor(add(reminder(add(subtract(multiply(divide(47, const_100), 1442), multiply(divide(36, const_100), 1412)), 65), const_10), const_1)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n3,#1)|subtract(#2,#3)|add(n4,#4)|reminder(#5,const_10)|add(#6,const_1)|floor(#7) | e ) 5 | general |
math_qa__e1WImpFbr3w1E4Oy | 15 ants can move 600 sugar cubes of 10 grams each to their home in 5 hours. Then how many sugar cubes of 5 grams each, will 20 ants move in 3 hours? Choose the correct choice from the following:
A) 360
B) 480
C) 720
D) 960
E) 1000 | <gadget id="calculator">600 * 10</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 5</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 15</gadget>
<output>80</output>
<gadget id="calculator">80 * 20</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 * 3</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 5</gadget>
<output>960</output>
<result>D</result> | D | 960 | 15 ants can move 600 sugar cubes of 10 grams each to their home in 5 hours. Then how many sugar cubes of 5 grams each, will 20 ants move in 3 hours? | {
"A": "360",
"B": "480",
"C": "720",
"D": "960",
"E": "1000"
} | divide(multiply(multiply(divide(divide(multiply(600, 10), 5), 15), 20), 3), 5) | multiply(n1,n2)|divide(#0,n3)|divide(#1,n0)|multiply(n5,#2)|multiply(n6,#3)|divide(#4,n3) | d 15 ants move 600 / 5 = 120 sugar cubes of 10 grams in 1 hour . 5 grams sugar cubes will take less time to move . thus if weight of the sugar cube is 5 grams , 15 ants will move 120 x 10 / 5 = 240 sugar cubes in 1 hour . more ants , more sugar cubes they can move . 20 ants will move 240 x 20 / 15 = 320 sugar cubes in 1 hour thus in 3 hours , 20 ants will move 320 x 3 = 960 sugar cubes of 5 grams . | physics |
math_qa__hreK2oOb6okNotYD | What is the positive difference between the sum of the squares of the first 6 positive integers and the sum of the prime numbers between the first square and fourth square?
Choose the correct choice from the following answers: A) 11 B) 12 C) 13 D) 14 E) 50 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">5 + 9</gadget>
<output>14</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">14 + 16</gadget>
<output>30</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">30 + 25</gadget>
<output>55</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">55 + 36</gadget>
<output>91</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 6</gadget>
<output>13</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 7</gadget>
<output>17</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">17 + 11</gadget>
<output>28</output>
<gadget id="calculator">13 + 28</gadget>
<output>41</output>
<gadget id="calculator">91 - 41</gadget>
<output>50</output>
<result>E</result> | E | 50 | What is the positive difference between the sum of the squares of the first 6 positive integers and the sum of the prime numbers between the first square and fourth square? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "50"
} | subtract(add(add(add(add(add(const_1, power(const_2, const_2)), power(const_3, const_2)), power(const_4, const_2)), power(add(const_4, const_1), const_2)), power(6, const_2)), add(add(add(const_4, const_3), 6), add(add(add(add(const_2, const_3), add(const_4, const_1)), add(const_4, const_3)), add(add(const_2, const_3), 6)))) | add(const_1,const_4)|add(const_3,const_4)|add(const_2,const_3)|power(const_2,const_2)|power(const_3,const_2)|power(const_4,const_2)|power(n0,const_2)|add(#3,const_1)|add(n0,#1)|add(#2,#0)|add(n0,#2)|power(#0,const_2)|add(#7,#4)|add(#9,#1)|add(#12,#5)|add(#13,#10)|add(#14,#11)|add(#8,#15)|add(#16,#6)|subtract(#18,#17) | forget conventional ways of solving math questions . in ps , ivy approach is the easiest and quickest way to find the answer . the sum of the squares of the first 4 positive integers = 1 ^ 2 + 2 ^ 2 + 3 ^ 2 + 4 ^ 2 + 5 ^ 2 + 6 ^ 2 = 91 the sum of the prime numbers between the first square ( = 1 ) and fourth square ( = 16 ) = 2 + 3 + 5 + 7 + 11 + 13 = 41 . so the difference between 41 and 91 is 50 . so the answer is ( e ) . | general |
math_qa__RXLV3cAx1x8VZg64 | John makes $60 a week from his job. He earns a raise and now makes $80 a week. What is the % increase? Answers:
A) 16 % B) 33.33 % C) 17 % D) 17.61 % E) 17.56 % | <gadget id="calculator">80 - 60</gadget>
<output>20</output>
<gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 33.33 | John makes $60 a week from his job. He earns a raise and now makes $80 a week. What is the % increase? | {
"A": "16 %",
"B": "33.33 %",
"C": "17 %",
"D": "17.61 %",
"E": "17.56 %"
} | multiply(divide(subtract(80, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 20 / 60 ) * 100 = ( 2 / 6 ) * 100 = 33.33 % . b" | gain |
math_qa__6lOQspTAzWK0sKcB | Find the area of a parallelogram with base 28 cm and height 32 cm. Pick:
A) 200 B) 384 C) 345 D) 244 E) 896 | <gadget id="calculator">28 * 32</gadget>
<output>896</output>
<result>E</result> | E | 896 | Find the area of a parallelogram with base 28 cm and height 32 cm. | {
"A": "200",
"B": "384",
"C": "345",
"D": "244",
"E": "896"
} | multiply(28, 32) | multiply(n0,n1)| | "area of a parallelogram = base * height = 28 * 32 = 896 cm 2 answer : option e" | geometry |
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