MatrixStudio/Codeforces-Python-Submissions

99

A

Help Far Away Kingdom

PROGRAMMING

800

[ "strings" ]

A. Help Far Away Kingdom

2

256

In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there. Most damage those strange creatures inflicted upon the kingdom was that they loved high precision numbers. As a result, the Kingdom healers had already had three appointments with the merchants who were asked to sell, say, exactly 0.273549107 beer barrels. To deal with the problem somehow, the King issued an order obliging rounding up all numbers to the closest integer to simplify calculations. Specifically, the order went like this: - If a number's integer part does not end with digit 9 and its fractional part is strictly less than 0.5, then the rounded up number coincides with the number’s integer part. - If a number's integer part does not end with digit 9 and its fractional part is not less than 0.5, the rounded up number is obtained if we add 1 to the last digit of the number’s integer part.- If the number’s integer part ends with digit 9, to round up the numbers one should go to Vasilisa the Wise. In the whole Kingdom she is the only one who can perform the tricky operation of carrying into the next position. Merchants found the algorithm very sophisticated and they asked you (the ACMers) to help them. Can you write a program that would perform the rounding according to the King’s order?

The first line contains a single number to round up — the integer part (a non-empty set of decimal digits that do not start with 0 — with the exception of a case when the set consists of a single digit — in this case 0 can go first), then follows character «.» (a dot), and then follows the fractional part (any non-empty set of decimal digits). The number's length does not exceed 1000 characters, including the dot. There are no other characters in the input data.

If the last number of the integer part is not equal to 9, print the rounded-up number without leading zeroes. Otherwise, print the message "GOTO Vasilisa." (without the quotes).

[ "0.0\n", "1.49\n", "1.50\n", "2.71828182845904523536\n", "3.14159265358979323846\n", "12345678901234567890.1\n", "123456789123456789.999\n" ]

[ "0", "1", "2", "3", "3", "12345678901234567890", "GOTO Vasilisa." ]

none

500

[ { "input": "0.0", "output": "0" }, { "input": "1.49", "output": "1" }, { "input": "1.50", "output": "2" }, { "input": "2.71828182845904523536", "output": "3" }, { "input": "3.14159265358979323846", "output": "3" }, { "input": "12345678901234567890.1", "output": "12345678901234567890" }, { "input": "123456789123456789.999", "output": "GOTO Vasilisa." }, { "input": "12345678901234567890.9", "output": "12345678901234567891" }, { "input": "123456789123456788.999", "output": "123456789123456789" }, { "input": "9.000", "output": "GOTO Vasilisa." }, { "input": "0.1", "output": "0" }, { "input": "0.2", "output": "0" }, { "input": "0.3", "output": "0" }, { "input": "0.4", "output": "0" }, { "input": "0.5", "output": "1" }, { "input": "0.6", "output": "1" }, { "input": "0.7", "output": "1" }, { "input": "0.8", "output": "1" }, { "input": "0.9", "output": "1" }, { "input": "1.0", "output": "1" }, { "input": "1.1", "output": "1" }, { "input": "1.2", "output": "1" }, { "input": "1.3", "output": "1" }, { "input": "1.4", "output": "1" }, { "input": "1.5", "output": "2" }, { "input": "1.6", "output": "2" }, { "input": "1.7", "output": "2" }, { "input": "1.8", "output": "2" }, { "input": "1.9", "output": "2" }, { "input": "2.0", "output": "2" }, { "input": "2.1", "output": "2" }, { "input": "2.2", "output": "2" }, { "input": "2.3", "output": "2" }, { "input": "2.4", "output": "2" }, { "input": "2.5", "output": "3" }, { "input": "2.6", "output": "3" }, { "input": "2.7", "output": "3" }, { "input": "2.8", "output": "3" }, { "input": "2.9", "output": "3" }, { "input": "3.0", "output": "3" }, { "input": "3.1", "output": "3" }, { "input": "3.2", "output": "3" }, { "input": "3.3", "output": "3" }, { "input": "3.4", "output": "3" }, { "input": "3.5", "output": "4" }, { "input": "3.6", "output": "4" }, { "input": "3.7", "output": "4" }, { "input": "3.8", "output": "4" }, { "input": "3.9", "output": "4" }, { "input": "4.0", "output": "4" }, { "input": "4.1", "output": "4" }, { "input": "4.2", "output": "4" }, { "input": "4.3", "output": "4" }, { "input": "4.4", "output": "4" }, { "input": "4.5", "output": "5" }, { "input": "4.6", "output": "5" }, { "input": "4.7", "output": "5" }, { "input": "4.8", "output": "5" }, { "input": "4.9", "output": "5" }, { "input": "5.0", "output": "5" }, { "input": "5.1", "output": "5" }, { "input": "5.2", "output": "5" }, { "input": "5.3", "output": "5" }, { "input": "5.4", "output": "5" }, { "input": "5.5", "output": "6" }, { "input": "5.6", "output": "6" }, { "input": "5.7", "output": "6" }, { "input": "5.8", "output": "6" }, { "input": "5.9", "output": "6" }, { "input": "6.0", "output": "6" }, { "input": "6.1", "output": "6" }, { "input": "6.2", "output": "6" }, { "input": "6.3", "output": "6" }, { "input": "6.4", "output": "6" }, { "input": "6.5", "output": "7" }, { "input": "6.6", "output": "7" }, { "input": "6.7", "output": "7" }, { "input": "6.8", "output": "7" }, { "input": "6.9", "output": "7" }, { "input": "7.0", "output": "7" }, { "input": "7.1", "output": "7" }, { "input": "7.2", "output": "7" }, { "input": "7.3", "output": "7" }, { "input": "7.4", "output": "7" }, { "input": "7.5", "output": "8" }, { "input": "7.6", "output": "8" }, { "input": "7.7", "output": "8" }, { "input": "7.8", "output": "8" }, { "input": "7.9", "output": "8" }, { "input": "8.0", "output": "8" }, { "input": "8.1", "output": "8" }, { "input": "8.2", "output": "8" }, { "input": "8.3", "output": "8" }, { "input": "8.4", "output": "8" }, { "input": "8.5", "output": "9" }, { "input": "8.6", "output": "9" }, { "input": "8.7", "output": "9" }, { "input": "8.8", "output": "9" }, { "input": "8.9", "output": "9" }, { "input": "9.0", "output": "GOTO Vasilisa." }, { "input": "9.1", "output": "GOTO Vasilisa." }, { "input": "9.2", "output": "GOTO Vasilisa." }, { "input": "9.3", "output": "GOTO Vasilisa." }, { "input": "9.4", "output": "GOTO Vasilisa." }, { "input": "9.5", "output": "GOTO Vasilisa." }, { "input": "9.6", "output": "GOTO Vasilisa." }, { "input": "9.7", "output": "GOTO Vasilisa." }, { "input": "9.8", "output": "GOTO Vasilisa." }, { "input": "9.9", "output": "GOTO Vasilisa." }, { "input": "609942239104813108618306232517836377583566292129955473517174437591594761209877970062547641606473593416245554763832875919009472288995880898848455284062760160557686724163817329189799336769669146848904803188614226720978399787805489531837751080926098.1664915772983166314490532653577560222779830866949001942720729759794777105570672781798092416748052690224813237139640723361527601154465287615917169132637313918577673651098507390501962", "output": "609942239104813108618306232517836377583566292129955473517174437591594761209877970062547641606473593416245554763832875919009472288995880898848455284062760160557686724163817329189799336769669146848904803188614226720978399787805489531837751080926098" }, { "input": "7002108534951820589946967018226114921984364117669853212254634761258884835434844673935047882480101006606512119541798298905598015607366335061012709906661245805358900665571472645463994925687210711492820804158354236327017974683658305043146543214454877759341394.20211856263503281388748282682120712214711232598021393495443628276945042110862480888110959179019986486690931930108026302665438087068150666835901617457150158918705186964935221768346957536540345814875615118637945520917367155931078965", "output": "7002108534951820589946967018226114921984364117669853212254634761258884835434844673935047882480101006606512119541798298905598015607366335061012709906661245805358900665571472645463994925687210711492820804158354236327017974683658305043146543214454877759341394" }, { "input": "1950583094879039694852660558765931995628486712128191844305265555887022812284005463780616067.5000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "1950583094879039694852660558765931995628486712128191844305265555887022812284005463780616068" }, { "input": "718130341896330596635811874410345440628950330.500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "718130341896330596635811874410345440628950331" }, { "input": "927925904158088313481229162503626281882161630091489367140850985555900173018122871746924067186432044676083646964286435457446768031295712712803570690846298544912543439221596866052681116386179629036945370280722.500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "927925904158088313481229162503626281882161630091489367140850985555900173018122871746924067186432044676083646964286435457446768031295712712803570690846298544912543439221596866052681116386179629036945370280723" }, { "input": "68289614863244584294178637364598054554769889.500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "GOTO Vasilisa." }, { "input": "7536521504744364134984603189602839063535643888645969434165019366202558753840519.4999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999", "output": "GOTO Vasilisa." }, { "input": "646188694587964249318078225173.5000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "646188694587964249318078225174" }, { "input": "7017472758334494297677068672222822550374695787171163207025095950296957261530.50", "output": "7017472758334494297677068672222822550374695787171163207025095950296957261531" }, { "input": "259085737066615534998640212505663524594409165063310128108448186246980628179842202905722595400477937071746695941939306735605849342959111887834258250883469840846714848774368.50000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "259085737066615534998640212505663524594409165063310128108448186246980628179842202905722595400477937071746695941939306735605849342959111887834258250883469840846714848774369" }, { "input": "682500858233333594535201113441004740771119672961581796618069185960107115823662126812159957094407454522028503739299.5000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "GOTO Vasilisa." }, { "input": "41203422675619090661099806687619.49999999999999999999999999999999999999999999999999999999999999999999999999999999999999999", "output": "GOTO Vasilisa." } ]

1,623,827,551

2,147,483,647

PyPy 3

OK

TESTS

150

216

0

a,b=input().split('.') if a[-1]=='9':print("GOTO Vasilisa.") else: if int(b[0])<5:print(a) else:print(int(a)+1)

Title: Help Far Away Kingdom Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there. Most damage those strange creatures inflicted upon the kingdom was that they loved high precision numbers. As a result, the Kingdom healers had already had three appointments with the merchants who were asked to sell, say, exactly 0.273549107 beer barrels. To deal with the problem somehow, the King issued an order obliging rounding up all numbers to the closest integer to simplify calculations. Specifically, the order went like this: - If a number's integer part does not end with digit 9 and its fractional part is strictly less than 0.5, then the rounded up number coincides with the number’s integer part. - If a number's integer part does not end with digit 9 and its fractional part is not less than 0.5, the rounded up number is obtained if we add 1 to the last digit of the number’s integer part.- If the number’s integer part ends with digit 9, to round up the numbers one should go to Vasilisa the Wise. In the whole Kingdom she is the only one who can perform the tricky operation of carrying into the next position. Merchants found the algorithm very sophisticated and they asked you (the ACMers) to help them. Can you write a program that would perform the rounding according to the King’s order? Input Specification: The first line contains a single number to round up — the integer part (a non-empty set of decimal digits that do not start with 0 — with the exception of a case when the set consists of a single digit — in this case 0 can go first), then follows character «.» (a dot), and then follows the fractional part (any non-empty set of decimal digits). The number's length does not exceed 1000 characters, including the dot. There are no other characters in the input data. Output Specification: If the last number of the integer part is not equal to 9, print the rounded-up number without leading zeroes. Otherwise, print the message "GOTO Vasilisa." (without the quotes). Demo Input: ['0.0\n', '1.49\n', '1.50\n', '2.71828182845904523536\n', '3.14159265358979323846\n', '12345678901234567890.1\n', '123456789123456789.999\n'] Demo Output: ['0', '1', '2', '3', '3', '12345678901234567890', 'GOTO Vasilisa.'] Note: none

```python a,b=input().split('.') if a[-1]=='9':print("GOTO Vasilisa.") else: if int(b[0])<5:print(a) else:print(int(a)+1) ```

3.946

255

A

Greg's Workout

PROGRAMMING

800

[ "implementation" ]

null

Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times. Greg now only does three types of exercises: "chest" exercises, "biceps" exercises and "back" exercises. Besides, his training is cyclic, that is, the first exercise he does is a "chest" one, the second one is "biceps", the third one is "back", the fourth one is "chest", the fifth one is "biceps", and so on to the *n*-th exercise. Now Greg wonders, which muscle will get the most exercise during his training. We know that the exercise Greg repeats the maximum number of times, trains the corresponding muscle the most. Help Greg, determine which muscle will get the most training.

The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises.

Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise. It is guaranteed that the input is such that the answer to the problem is unambiguous.

[ "2\n2 8\n", "3\n5 1 10\n", "7\n3 3 2 7 9 6 8\n" ]

[ "biceps\n", "back\n", "chest\n" ]

In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises. In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises. In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the most exercise.

500

[ { "input": "2\n2 8", "output": "biceps" }, { "input": "3\n5 1 10", "output": "back" }, { "input": "7\n3 3 2 7 9 6 8", "output": "chest" }, { "input": "4\n5 6 6 2", "output": "chest" }, { "input": "5\n8 2 2 6 3", "output": "chest" }, { "input": "6\n8 7 2 5 3 4", "output": "chest" }, { "input": "8\n7 2 9 10 3 8 10 6", "output": "chest" }, { "input": "9\n5 4 2 3 4 4 5 2 2", "output": "chest" }, { "input": "10\n4 9 8 5 3 8 8 10 4 2", "output": "biceps" }, { "input": "11\n10 9 7 6 1 3 9 7 1 3 5", "output": "chest" }, { "input": "12\n24 22 6 16 5 21 1 7 2 19 24 5", "output": "chest" }, { "input": "13\n24 10 5 7 16 17 2 7 9 20 15 2 24", "output": "chest" }, { "input": "14\n13 14 19 8 5 17 9 16 15 9 5 6 3 7", "output": "back" }, { "input": "15\n24 12 22 21 25 23 21 5 3 24 23 13 12 16 12", "output": "chest" }, { "input": "16\n12 6 18 6 25 7 3 1 1 17 25 17 6 8 17 8", "output": "biceps" }, { "input": "17\n13 8 13 4 9 21 10 10 9 22 14 23 22 7 6 14 19", "output": "chest" }, { "input": "18\n1 17 13 6 11 10 25 13 24 9 21 17 3 1 17 12 25 21", "output": "back" }, { "input": "19\n22 22 24 25 19 10 7 10 4 25 19 14 1 14 3 18 4 19 24", "output": "chest" }, { "input": "20\n9 8 22 11 18 14 15 10 17 11 2 1 25 20 7 24 4 25 9 20", "output": "chest" }, { "input": "1\n10", "output": "chest" }, { "input": "2\n15 3", "output": "chest" }, { "input": "3\n21 11 19", "output": "chest" }, { "input": "4\n19 24 13 15", "output": "chest" }, { "input": "5\n4 24 1 9 19", "output": "biceps" }, { "input": "6\n6 22 24 7 15 24", "output": "back" }, { "input": "7\n10 8 23 23 14 18 14", "output": "chest" }, { "input": "8\n5 16 8 9 17 16 14 7", "output": "biceps" }, { "input": "9\n12 3 10 23 6 4 22 13 12", "output": "chest" }, { "input": "10\n1 9 20 18 20 17 7 24 23 2", "output": "back" }, { "input": "11\n22 25 8 2 18 15 1 13 1 11 4", "output": "biceps" }, { "input": "12\n20 12 14 2 15 6 24 3 11 8 11 14", "output": "chest" }, { "input": "13\n2 18 8 8 8 20 5 22 15 2 5 19 18", "output": "back" }, { "input": "14\n1 6 10 25 17 13 21 11 19 4 15 24 5 22", "output": "biceps" }, { "input": "15\n13 5 25 13 17 25 19 21 23 17 12 6 14 8 6", "output": "back" }, { "input": "16\n10 15 2 17 22 12 14 14 6 11 4 13 9 8 21 14", "output": "chest" }, { "input": "17\n7 22 9 22 8 7 20 22 23 5 12 11 1 24 17 20 10", "output": "biceps" }, { "input": "18\n18 15 4 25 5 11 21 25 12 14 25 23 19 19 13 6 9 17", "output": "chest" }, { "input": "19\n3 1 3 15 15 25 10 25 23 10 9 21 13 23 19 3 24 21 14", "output": "back" }, { "input": "20\n19 18 11 3 6 14 3 3 25 3 1 19 25 24 23 12 7 4 8 6", "output": "back" }, { "input": "1\n19", "output": "chest" }, { "input": "2\n1 7", "output": "biceps" }, { "input": "3\n18 18 23", "output": "back" }, { "input": "4\n12 15 1 13", "output": "chest" }, { "input": "5\n11 14 25 21 21", "output": "biceps" }, { "input": "6\n11 9 12 11 22 18", "output": "biceps" }, { "input": "7\n11 1 16 20 21 25 20", "output": "chest" }, { "input": "8\n1 2 20 9 3 22 17 4", "output": "back" }, { "input": "9\n19 2 10 19 15 20 3 1 13", "output": "back" }, { "input": "10\n11 2 11 8 21 16 2 3 19 9", "output": "back" }, { "input": "20\n25 25 25 25 25 25 25 25 25 25 25 25 25 25 25 25 25 25 25 24", "output": "chest" }, { "input": "12\n4 24 21 3 13 24 22 13 12 21 1 15", "output": "back" }, { "input": "13\n14 14 16 2 13 5 1 14 9 4 16 8 3", "output": "biceps" }, { "input": "14\n1 9 15 4 11 8 25 3 9 14 13 2 1 11", "output": "biceps" }, { "input": "15\n4 19 10 6 16 12 5 11 7 23 1 24 11 7 17", "output": "back" }, { "input": "16\n2 8 2 8 13 22 20 12 22 23 18 13 18 22 11 17", "output": "chest" }, { "input": "17\n24 5 5 16 10 8 22 6 4 13 10 10 5 23 8 20 8", "output": "chest" }, { "input": "18\n14 8 9 12 11 18 24 1 14 24 18 5 12 17 1 10 1 22", "output": "chest" }, { "input": "19\n21 2 10 6 9 1 24 5 2 19 10 13 10 7 19 2 6 13 24", "output": "chest" }, { "input": "20\n7 1 14 17 6 6 18 13 12 3 25 4 3 19 22 24 16 14 1 23", "output": "biceps" }, { "input": "1\n19", "output": "chest" }, { "input": "20\n2 1 2 2 1 2 2 1 2 1 1 1 1 1 1 1 1 1 1 22", "output": "biceps" } ]

1,567,667,853

2,147,483,647

Python 3

OK

TESTS

61

278

0

def main(): m = int(input()) vals = [int(v) for v in input().split()] biceps = 'biceps' back = 'back' chest = 'chest' freq = { biceps:0, back:0, chest:0 } for i,v in enumerate(vals): if i%3==0: freq[chest]+=v elif i%3==1: freq[biceps]+=v elif i%3==2: freq[back]+=v res = sorted(freq.items(), key=lambda b:b[1], reverse=True) print(res[0][0]) if __name__ == "__main__": main()

Title: Greg's Workout Time Limit: None seconds Memory Limit: None megabytes Problem Description: Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times. Greg now only does three types of exercises: "chest" exercises, "biceps" exercises and "back" exercises. Besides, his training is cyclic, that is, the first exercise he does is a "chest" one, the second one is "biceps", the third one is "back", the fourth one is "chest", the fifth one is "biceps", and so on to the *n*-th exercise. Now Greg wonders, which muscle will get the most exercise during his training. We know that the exercise Greg repeats the maximum number of times, trains the corresponding muscle the most. Help Greg, determine which muscle will get the most training. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. Output Specification: Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise. It is guaranteed that the input is such that the answer to the problem is unambiguous. Demo Input: ['2\n2 8\n', '3\n5 1 10\n', '7\n3 3 2 7 9 6 8\n'] Demo Output: ['biceps\n', 'back\n', 'chest\n'] Note: In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises. In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises. In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the most exercise.

```python def main(): m = int(input()) vals = [int(v) for v in input().split()] biceps = 'biceps' back = 'back' chest = 'chest' freq = { biceps:0, back:0, chest:0 } for i,v in enumerate(vals): if i%3==0: freq[chest]+=v elif i%3==1: freq[biceps]+=v elif i%3==2: freq[back]+=v res = sorted(freq.items(), key=lambda b:b[1], reverse=True) print(res[0][0]) if __name__ == "__main__": main() ```

3

431

A

Black Square

PROGRAMMING

800

[ "implementation" ]

null

Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone. In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules of the game, Jury must use this second to touch the corresponding strip to make the square go away. As Jury is both smart and lazy, he counted that he wastes exactly *a**i* calories on touching the *i*-th strip. You've got a string *s*, describing the process of the game and numbers *a*1,<=*a*2,<=*a*3,<=*a*4. Calculate how many calories Jury needs to destroy all the squares?

The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104). The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it appears on the second strip, "3", if it appears on the third strip, "4", if it appears on the fourth strip.

Print a single integer — the total number of calories that Jury wastes.

[ "1 2 3 4\n123214\n", "1 5 3 2\n11221\n" ]

[ "13\n", "13\n" ]

none

500

[ { "input": "1 2 3 4\n123214", "output": "13" }, { "input": "1 5 3 2\n11221", "output": "13" }, { "input": "5 5 5 1\n3422", "output": "16" }, { "input": "4 3 2 1\n2", "output": "3" }, { "input": "5651 6882 6954 4733\n2442313421", "output": "60055" }, { "input": "0 0 0 0\n4132", "output": "0" }, { "input": "3163 5778 83 7640\n11141442444", "output": "64270" }, { "input": "1809 1302 7164 6122\n3144121413113111223311232232114144321414421243443243422322144324121433444342231344234443332241322442", "output": "420780" }, { "input": "0 0 0 0\n1", "output": "0" }, { "input": "1 2 3 4\n4", "output": "4" }, { "input": "2343 7653 1242 5432\n1", "output": "2343" }, { "input": "2343 7653 1242 5432\n2", "output": "7653" }, { "input": "2343 7653 1242 5432\n3", "output": "1242" }, { "input": "2343 7653 1242 5432\n4", "output": "5432" }, { "input": "1 2 3 4\n123412", "output": "13" }, { "input": "50 50 50 50\n11111111111111111111111111111111111111111111111111111", "output": "2650" }, { "input": "1 2 3 4\n11111111111111111111111111111111111111111111111111", "output": "50" }, { "input": "1 2 3 4\n23123231321231231231231231221232123121312321", "output": "87" }, { "input": "1 2 3 4\n1111111111111222222222233333333333444444444444444", "output": "126" }, { "input": "2 3 1 4\n121321232412342112312313213123123412131231231232", "output": "105" } ]

1,657,568,617

2,147,483,647

PyPy 3-64

OK

TESTS

49

62

11,878,400

a=list(map(int,input().split())) appearnce= list(map(int,list(input()))) calories=0 for i in appearnce: calories +=a[i-1] print(calories)

Title: Black Square Time Limit: None seconds Memory Limit: None megabytes Problem Description: Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone. In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules of the game, Jury must use this second to touch the corresponding strip to make the square go away. As Jury is both smart and lazy, he counted that he wastes exactly *a**i* calories on touching the *i*-th strip. You've got a string *s*, describing the process of the game and numbers *a*1,<=*a*2,<=*a*3,<=*a*4. Calculate how many calories Jury needs to destroy all the squares? Input Specification: The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104). The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it appears on the second strip, "3", if it appears on the third strip, "4", if it appears on the fourth strip. Output Specification: Print a single integer — the total number of calories that Jury wastes. Demo Input: ['1 2 3 4\n123214\n', '1 5 3 2\n11221\n'] Demo Output: ['13\n', '13\n'] Note: none

```python a=list(map(int,input().split())) appearnce= list(map(int,list(input()))) calories=0 for i in appearnce: calories +=a[i-1] print(calories) ```

3

192

A

Funky Numbers

PROGRAMMING

1,300

[ "binary search", "brute force", "implementation" ]

null

As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers. A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number *n*, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!

The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109).

Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).

[ "256\n", "512\n" ]

[ "YES\n", "NO\n" ]

In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>. In the second sample number 512 can not be represented as a sum of two triangular numbers.

500

[ { "input": "256", "output": "YES" }, { "input": "512", "output": "NO" }, { "input": "80", "output": "NO" }, { "input": "828", "output": "YES" }, { "input": "6035", "output": "NO" }, { "input": "39210", "output": "YES" }, { "input": "79712", "output": "NO" }, { "input": "190492", "output": "YES" }, { "input": "5722367", "output": "NO" }, { "input": "816761542", "output": "YES" }, { "input": "1", "output": "NO" }, { "input": "2", "output": "YES" }, { "input": "3", "output": "NO" }, { "input": "4", "output": "YES" }, { "input": "5", "output": "NO" }, { "input": "6", "output": "YES" }, { "input": "7", "output": "YES" }, { "input": "8", "output": "NO" }, { "input": "9", "output": "YES" }, { "input": "10", "output": "NO" }, { "input": "12", "output": "YES" }, { "input": "13", "output": "YES" }, { "input": "14", "output": "NO" }, { "input": "15", "output": "NO" }, { "input": "16", "output": "YES" }, { "input": "17", "output": "NO" }, { "input": "18", "output": "YES" }, { "input": "19", "output": "NO" }, { "input": "20", "output": "YES" }, { "input": "41", "output": "NO" }, { "input": "11", "output": "YES" }, { "input": "69", "output": "YES" }, { "input": "82", "output": "NO" }, { "input": "85", "output": "NO" }, { "input": "736", "output": "NO" }, { "input": "895", "output": "YES" }, { "input": "934", "output": "YES" }, { "input": "6213", "output": "YES" }, { "input": "7405", "output": "NO" }, { "input": "9919", "output": "NO" }, { "input": "40942", "output": "YES" }, { "input": "41992", "output": "NO" }, { "input": "68535", "output": "NO" }, { "input": "405718", "output": "NO" }, { "input": "1046146", "output": "YES" }, { "input": "3761248", "output": "YES" }, { "input": "6195181", "output": "YES" }, { "input": "35354345", "output": "NO" }, { "input": "81282830", "output": "NO" }, { "input": "187719774", "output": "NO" }, { "input": "296798673", "output": "NO" }, { "input": "938938476", "output": "NO" }, { "input": "1000000000", "output": "NO" }, { "input": "999887464", "output": "YES" }, { "input": "999111944", "output": "NO" }, { "input": "999966520", "output": "YES" }, { "input": "999912080", "output": "NO" }, { "input": "999992017", "output": "YES" }, { "input": "999990474", "output": "NO" }, { "input": "999999190", "output": "YES" }, { "input": "999999125", "output": "NO" }, { "input": "999999940", "output": "YES" }, { "input": "999999995", "output": "NO" }, { "input": "1000000000", "output": "NO" }, { "input": "1", "output": "NO" }, { "input": "999999999", "output": "YES" }, { "input": "83495494", "output": "NO" }, { "input": "968022000", "output": "YES" }, { "input": "399980000", "output": "YES" }, { "input": "4", "output": "YES" }, { "input": "999999998", "output": "NO" } ]

1,541,223,385

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

11

374

3,379,200

l=[] for i in range(1,10**5): l.append(i*(i+1)//2) i=0 f=0 n=int(input()) j=10**5-5 while i<j: if l[i]+l[j]==n: f=1 break elif l[i]+l[j]<n: i+=1 else: j-=1 if f==0: print('NO') else: print('YES')

Title: Funky Numbers Time Limit: None seconds Memory Limit: None megabytes Problem Description: As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers. A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number *n*, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)! Input Specification: The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109). Output Specification: Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes). Demo Input: ['256\n', '512\n'] Demo Output: ['YES\n', 'NO\n'] Note: In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>. In the second sample number 512 can not be represented as a sum of two triangular numbers.

```python l=[] for i in range(1,10**5): l.append(i*(i+1)//2) i=0 f=0 n=int(input()) j=10**5-5 while i<j: if l[i]+l[j]==n: f=1 break elif l[i]+l[j]<n: i+=1 else: j-=1 if f==0: print('NO') else: print('YES') ```

0

622

A

Infinite Sequence

PROGRAMMING

1,000

[ "implementation", "math" ]

null

Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one). Find the number on the *n*-th position of the sequence.

The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find. Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.

Print the element in the *n*-th position of the sequence (the elements are numerated from one).

[ "3\n", "5\n", "10\n", "55\n", "56\n" ]

[ "2\n", "2\n", "4\n", "10\n", "1\n" ]

none

0

[ { "input": "3", "output": "2" }, { "input": "5", "output": "2" }, { "input": "10", "output": "4" }, { "input": "55", "output": "10" }, { "input": "56", "output": "1" }, { "input": "1000000000000", "output": "88209" }, { "input": "847194127849", "output": "255708" }, { "input": "294719472984", "output": "593358" }, { "input": "999999911791", "output": "1414213" }, { "input": "999999911792", "output": "1" }, { "input": "100000000000000", "output": "1749820" }, { "input": "1", "output": "1" }, { "input": "99993", "output": "312" }, { "input": "99994", "output": "313" }, { "input": "99995", "output": "314" }, { "input": "99990", "output": "309" }, { "input": "2", "output": "1" }, { "input": "99991", "output": "310" }, { "input": "99992", "output": "311" }, { "input": "99996", "output": "315" }, { "input": "99997", "output": "316" }, { "input": "99998", "output": "317" }, { "input": "99999", "output": "318" }, { "input": "1021", "output": "31" }, { "input": "4", "output": "1" }, { "input": "23", "output": "2" }, { "input": "9994", "output": "124" }, { "input": "99939", "output": "258" }, { "input": "99999998250180", "output": "14142135" }, { "input": "6", "output": "3" }, { "input": "8", "output": "2" }, { "input": "35", "output": "7" }, { "input": "100", "output": "9" }, { "input": "10101010", "output": "745" }, { "input": "103", "output": "12" }, { "input": "102", "output": "11" }, { "input": "101", "output": "10" } ]

1,585,000,832

2,147,483,647

Python 3

TIME_LIMIT_EXCEEDED

TESTS

10

1,000

0

x = int(input()) temp = x for i in range(1 , temp): if x <= i : break x -= i print(x)

Title: Infinite Sequence Time Limit: None seconds Memory Limit: None megabytes Problem Description: Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one). Find the number on the *n*-th position of the sequence. Input Specification: The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find. Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. Output Specification: Print the element in the *n*-th position of the sequence (the elements are numerated from one). Demo Input: ['3\n', '5\n', '10\n', '55\n', '56\n'] Demo Output: ['2\n', '2\n', '4\n', '10\n', '1\n'] Note: none

```python x = int(input()) temp = x for i in range(1 , temp): if x <= i : break x -= i print(x) ```

0

479

A

Expression

PROGRAMMING

1,000

[ "brute force", "math" ]

null

Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets: - 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9 Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2. It's easy to see that the maximum value that you can obtain is 9. Your task is: given *a*, *b* and *c* print the maximum value that you can get.

The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10).

Print the maximum value of the expression that you can obtain.

[ "1\n2\n3\n", "2\n10\n3\n" ]

[ "9\n", "60\n" ]

none

500

[ { "input": "1\n2\n3", "output": "9" }, { "input": "2\n10\n3", "output": "60" }, { "input": "1\n1\n1", "output": "3" }, { "input": "1\n2\n1", "output": "4" }, { "input": "10\n10\n10", "output": "1000" }, { "input": "5\n1\n3", "output": "20" }, { "input": "3\n1\n5", "output": "20" }, { "input": "6\n7\n1", "output": "48" }, { "input": "1\n8\n3", "output": "27" }, { "input": "9\n7\n2", "output": "126" }, { "input": "1\n1\n10", "output": "20" }, { "input": "9\n1\n1", "output": "18" }, { "input": "10\n5\n6", "output": "300" }, { "input": "8\n9\n7", "output": "504" }, { "input": "4\n2\n10", "output": "80" }, { "input": "2\n8\n3", "output": "48" }, { "input": "3\n5\n7", "output": "105" }, { "input": "1\n10\n1", "output": "12" }, { "input": "2\n2\n2", "output": "8" }, { "input": "5\n6\n1", "output": "35" }, { "input": "10\n1\n1", "output": "20" }, { "input": "1\n6\n1", "output": "8" }, { "input": "1\n9\n1", "output": "11" }, { "input": "2\n1\n2", "output": "6" }, { "input": "2\n6\n1", "output": "14" }, { "input": "9\n2\n1", "output": "27" }, { "input": "1\n9\n2", "output": "20" }, { "input": "1\n3\n1", "output": "5" }, { "input": "2\n1\n1", "output": "4" } ]

1,692,513,492

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

0

15

0

a=int(input()) b=int(input()) c=int(input()) mas=[a+b+c,a*b*c,a+b*c,a*b+c,(a+b)*c,a*(b+c)] print(mas) maxi=mas[0] for i in range(6): if mas[i]>maxi: maxi=mas[i] print(maxi)

Title: Expression Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets: - 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9 Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2. It's easy to see that the maximum value that you can obtain is 9. Your task is: given *a*, *b* and *c* print the maximum value that you can get. Input Specification: The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). Output Specification: Print the maximum value of the expression that you can obtain. Demo Input: ['1\n2\n3\n', '2\n10\n3\n'] Demo Output: ['9\n', '60\n'] Note: none

```python a=int(input()) b=int(input()) c=int(input()) mas=[a+b+c,a*b*c,a+b*c,a*b+c,(a+b)*c,a*(b+c)] print(mas) maxi=mas[0] for i in range(6): if mas[i]>maxi: maxi=mas[i] print(maxi) ```

0

381

A

Sereja and Dima

PROGRAMMING

800

[ "greedy", "implementation", "two pointers" ]

null

Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins. Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move. Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.

The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.

On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.

[ "4\n4 1 2 10\n", "7\n1 2 3 4 5 6 7\n" ]

[ "12 5\n", "16 12\n" ]

In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5.

500

[ { "input": "4\n4 1 2 10", "output": "12 5" }, { "input": "7\n1 2 3 4 5 6 7", "output": "16 12" }, { "input": "42\n15 29 37 22 16 5 26 31 6 32 19 3 45 36 33 14 25 20 48 7 42 11 24 28 9 18 8 21 47 17 38 40 44 4 35 1 43 39 41 27 12 13", "output": "613 418" }, { "input": "43\n32 1 15 48 38 26 25 14 20 44 11 30 3 42 49 19 18 46 5 45 10 23 34 9 29 41 2 52 6 17 35 4 50 22 33 51 7 28 47 13 39 37 24", "output": "644 500" }, { "input": "1\n3", "output": "3 0" }, { "input": "45\n553 40 94 225 415 471 126 190 647 394 515 303 189 159 308 6 139 132 326 78 455 75 85 295 135 613 360 614 351 228 578 259 258 591 444 29 33 463 561 174 368 183 140 168 646", "output": "6848 6568" }, { "input": "44\n849 373 112 307 479 608 856 769 526 82 168 143 573 762 115 501 688 36 214 450 396 496 236 309 287 786 397 43 811 141 745 846 350 270 276 677 420 459 403 722 267 54 394 727", "output": "9562 9561" }, { "input": "35\n10 15 18 1 28 16 2 33 6 22 23 4 9 25 35 8 7 26 3 20 30 14 31 19 27 32 11 5 29 24 21 34 13 17 12", "output": "315 315" }, { "input": "17\n580 376 191 496 73 44 520 357 483 149 81 178 514 300 216 598 304", "output": "3238 2222" }, { "input": "30\n334 443 223 424 168 549 189 303 429 559 516 220 459 134 344 346 316 446 209 148 487 526 69 286 102 366 518 280 392 325", "output": "5246 4864" }, { "input": "95\n122 29 188 265 292 287 183 225 222 187 155 256 64 148 173 278 218 136 290 17 31 130 2 87 57 283 255 280 68 166 174 142 102 39 116 206 288 154 26 78 296 172 184 232 77 91 277 8 249 186 94 93 207 251 257 195 101 299 193 124 293 65 58 35 24 302 220 189 252 125 27 284 247 182 141 103 198 97 234 83 281 216 85 180 267 236 109 143 149 239 79 300 191 244 71", "output": "8147 7807" }, { "input": "1\n1", "output": "1 0" } ]

1,690,200,597

2,147,483,647

Python 3

OK

TESTS

34

46

0

n = int(input()) c = list(map(int,input().split())) a = [] b =[] i = 0 x = 0 while len(c) > 0: if n == 1 and (x + 1) % 2 == 0 or c[i] > c[i-1] and (x + 1) % 2 == 0: b.append(c[i]) c.pop(0) n -= 1 x += 1 elif c[i] < c[i-1] and (x + 1) % 2 == 0: b.append(c[i-1]) c.pop(n-1) n -= 1 x += 1 elif n == 1 or c[i] > c[i-1]: a.append(c[i]) c.pop(0) n -= 1 x += 1 elif c[i] < c[i-1]: a.append(c[i-1]) c.pop(n-1) n -= 1 x += 1 print(sum(a), sum(b))

Title: Sereja and Dima Time Limit: None seconds Memory Limit: None megabytes Problem Description: Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins. Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move. Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000. Output Specification: On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game. Demo Input: ['4\n4 1 2 10\n', '7\n1 2 3 4 5 6 7\n'] Demo Output: ['12 5\n', '16 12\n'] Note: In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5.

```python n = int(input()) c = list(map(int,input().split())) a = [] b =[] i = 0 x = 0 while len(c) > 0: if n == 1 and (x + 1) % 2 == 0 or c[i] > c[i-1] and (x + 1) % 2 == 0: b.append(c[i]) c.pop(0) n -= 1 x += 1 elif c[i] < c[i-1] and (x + 1) % 2 == 0: b.append(c[i-1]) c.pop(n-1) n -= 1 x += 1 elif n == 1 or c[i] > c[i-1]: a.append(c[i]) c.pop(0) n -= 1 x += 1 elif c[i] < c[i-1]: a.append(c[i-1]) c.pop(n-1) n -= 1 x += 1 print(sum(a), sum(b)) ```

3

1,009

B

Minimum Ternary String

PROGRAMMING

1,400

[ "greedy", "implementation" ]

null

You are given a ternary string (it is a string which consists only of characters '0', '1' and '2'). You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa). For example, for string "010210" we can perform the following moves: - "010210" $\rightarrow$ "100210"; - "010210" $\rightarrow$ "001210"; - "010210" $\rightarrow$ "010120"; - "010210" $\rightarrow$ "010201". Note than you cannot swap "02" $\rightarrow$ "20" and vice versa. You cannot perform any other operations with the given string excluding described above. You task is to obtain the minimum possible (lexicographically) string by using these swaps arbitrary number of times (possibly, zero). String $a$ is lexicographically less than string $b$ (if strings $a$ and $b$ have the same length) if there exists some position $i$ ($1 \le i \le |a|$, where $|s|$ is the length of the string $s$) such that for every $j < i$ holds $a_j = b_j$, and $a_i < b_i$.

The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive).

Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero).

[ "100210\n", "11222121\n", "20\n" ]

[ "001120\n", "11112222\n", "20\n" ]

none

0

[ { "input": "100210", "output": "001120" }, { "input": "11222121", "output": "11112222" }, { "input": "20", "output": "20" }, { "input": "1002", "output": "0012" }, { "input": "10", "output": "01" }, { "input": "000021", "output": "000012" }, { "input": "021", "output": "012" }, { "input": "2", "output": "2" }, { "input": "201", "output": "120" }, { "input": "2112120", "output": "1112220" }, { "input": "102", "output": "012" }, { "input": "202", "output": "202" }, { "input": "220201", "output": "122020" }, { "input": "12", "output": "12" }, { "input": "100022202", "output": "000122202" }, { "input": "01", "output": "01" }, { "input": "1", "output": "1" } ]

1,550,783,453

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

3

342

2,252,800

s = input() s = list(s) ant = 0 separa = [] for n in range(len(s)): if((int(ant) == 2 and int(s[n]) == 0) or (int(ant) == 0 and int(s[n]) == 2)): separa.append(n) ant = int(s[n]) separa.append(len(s)); ant = 0 for i in separa: s[ant:i] = sorted(s[ant:i]) ant = i for i in s: print(i, end = '') print()

Title: Minimum Ternary String Time Limit: None seconds Memory Limit: None megabytes Problem Description: You are given a ternary string (it is a string which consists only of characters '0', '1' and '2'). You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa). For example, for string "010210" we can perform the following moves: - "010210" $\rightarrow$ "100210"; - "010210" $\rightarrow$ "001210"; - "010210" $\rightarrow$ "010120"; - "010210" $\rightarrow$ "010201". Note than you cannot swap "02" $\rightarrow$ "20" and vice versa. You cannot perform any other operations with the given string excluding described above. You task is to obtain the minimum possible (lexicographically) string by using these swaps arbitrary number of times (possibly, zero). String $a$ is lexicographically less than string $b$ (if strings $a$ and $b$ have the same length) if there exists some position $i$ ($1 \le i \le |a|$, where $|s|$ is the length of the string $s$) such that for every $j < i$ holds $a_j = b_j$, and $a_i < b_i$. Input Specification: The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). Output Specification: Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). Demo Input: ['100210\n', '11222121\n', '20\n'] Demo Output: ['001120\n', '11112222\n', '20\n'] Note: none

```python s = input() s = list(s) ant = 0 separa = [] for n in range(len(s)): if((int(ant) == 2 and int(s[n]) == 0) or (int(ant) == 0 and int(s[n]) == 2)): separa.append(n) ant = int(s[n]) separa.append(len(s)); ant = 0 for i in separa: s[ant:i] = sorted(s[ant:i]) ant = i for i in s: print(i, end = '') print() ```

0

262

B

Roma and Changing Signs

PROGRAMMING

1,200

[ "greedy" ]

null

Roma works in a company that sells TVs. Now he has to prepare a report for the last year. Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of several numbers in the sequence. He can also change the sign of a number one, two or more times. The operation of changing a number's sign is the operation of multiplying this number by -1. Help Roma perform the changes so as to make the total income of the company (the sum of numbers in the resulting sequence) maximum. Note that Roma should perform exactly *k* changes.

The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made. The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104). The numbers in the lines are separated by single spaces. Please note that the given sequence is sorted in non-decreasing order.

In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes.

[ "3 2\n-1 -1 1\n", "3 1\n-1 -1 1\n" ]

[ "3\n", "1\n" ]

In the first sample we can get sequence [1, 1, 1], thus the total income equals 3. In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1.

1,000

[ { "input": "3 2\n-1 -1 1", "output": "3" }, { "input": "3 1\n-1 -1 1", "output": "1" }, { "input": "17 27\n257 320 676 1136 2068 2505 2639 4225 4951 5786 7677 7697 7851 8337 8429 8469 9343", "output": "81852" }, { "input": "69 28\n-9822 -9264 -9253 -9221 -9139 -9126 -9096 -8981 -8521 -8313 -8257 -8253 -7591 -7587 -7301 -7161 -7001 -6847 -6441 -6241 -5949 -5896 -5713 -5692 -5644 -5601 -5545 -5525 -5331 -5253 -5041 -5000 -4951 -4855 -4384 -4293 -4251 -4001 -3991 -3762 -3544 -3481 -3261 -2983 -2882 -2857 -2713 -2691 -2681 -2653 -2221 -2043 -2011 -1997 -1601 -1471 -1448 -1363 -1217 -1217 -1129 -961 -926 -801 -376 -327 -305 -174 -91", "output": "102443" }, { "input": "12 28\n-6652 -6621 -6471 -5559 -5326 -4551 -4401 -4326 -3294 -1175 -1069 -43", "output": "49488" }, { "input": "78 13\n-9961 -9922 -9817 -9813 -9521 -9368 -9361 -9207 -9153 -9124 -9008 -8981 -8951 -8911 -8551 -8479 -8245 -8216 -7988 -7841 -7748 -7741 -7734 -7101 -6846 -6804 -6651 -6526 -6519 -6463 -6297 -6148 -6090 -5845 -5209 -5201 -5161 -5061 -4537 -4529 -4433 -4370 -4266 -4189 -4125 -3945 -3843 -3777 -3751 -3476 -3461 -3279 -3205 -3001 -2889 -2761 -2661 -2521 -2481 -2305 -2278 -2269 -2225 -1648 -1524 -1476 -1353 -1097 -867 -785 -741 -711 -692 -440 -401 -225 -65 -41", "output": "-147832" }, { "input": "4 1\n218 3441 4901 7601", "output": "15725" }, { "input": "73 26\n-8497 -8363 -7603 -7388 -6830 -6827 -6685 -6389 -6237 -6099 -6013 -5565 -5465 -4965 -4947 -4201 -3851 -3793 -3421 -3410 -3201 -3169 -3156 -2976 -2701 -2623 -2321 -2169 -1469 -1221 -950 -926 -9 47 236 457 773 1321 1485 1545 1671 1736 2014 2137 2174 2301 2625 3181 3536 3851 4041 4685 4981 4987 5145 5163 5209 5249 6011 6337 6790 7254 7361 7407 7969 7982 8083 8251 8407 8735 9660 9855 9957", "output": "315919" }, { "input": "53 5\n-9821 -9429 -9146 -8973 -8807 -8801 -8321 -7361 -7222 -7161 -6913 -5961 -4877 -4756 -4753 -4661 -3375 -3031 -2950 -2661 -2161 -2041 -1111 -1071 -905 -697 -397 323 772 1617 1752 2736 2737 3201 3465 4029 4121 4463 4561 4637 4814 6119 6610 6641 6961 7217 7523 8045 8610 8915 9004 9265 9576", "output": "92703" }, { "input": "1 1\n0", "output": "0" }, { "input": "1 1\n10000", "output": "-10000" }, { "input": "1 2\n-1", "output": "-1" }, { "input": "2 1\n0 1", "output": "1" }, { "input": "2 2\n-1 0", "output": "1" }, { "input": "5 6\n-3 -2 -1 5 6", "output": "15" }, { "input": "3 3\n-50 -10 30", "output": "70" }, { "input": "4 4\n-100 -90 -80 1", "output": "269" }, { "input": "4 3\n-3 -2 1 2", "output": "6" }, { "input": "6 4\n-6 -3 -2 1 2 3", "output": "15" }, { "input": "5 6\n-10 -9 -8 1 2", "output": "28" }, { "input": "1 2\n1", "output": "1" }, { "input": "2 2\n-1 3", "output": "2" }, { "input": "4 7\n-3 -2 1 6", "output": "10" }, { "input": "4 3\n-7 -6 1 5", "output": "17" }, { "input": "4 4\n-5 -1 1 2", "output": "9" } ]

1,576,038,206

2,147,483,647

Python 3

OK

TESTS

56

342

7,680,000

import heapq if __name__ == '__main__': n, k = map(int, input().split()) a = list(map(int, input().split())) heapq.heapify(a) for i in range(k): val_min = heapq.heappop(a) heapq.heappush(a, val_min*(-1)) print(sum(a))

Title: Roma and Changing Signs Time Limit: None seconds Memory Limit: None megabytes Problem Description: Roma works in a company that sells TVs. Now he has to prepare a report for the last year. Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of several numbers in the sequence. He can also change the sign of a number one, two or more times. The operation of changing a number's sign is the operation of multiplying this number by -1. Help Roma perform the changes so as to make the total income of the company (the sum of numbers in the resulting sequence) maximum. Note that Roma should perform exactly *k* changes. Input Specification: The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made. The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104). The numbers in the lines are separated by single spaces. Please note that the given sequence is sorted in non-decreasing order. Output Specification: In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes. Demo Input: ['3 2\n-1 -1 1\n', '3 1\n-1 -1 1\n'] Demo Output: ['3\n', '1\n'] Note: In the first sample we can get sequence [1, 1, 1], thus the total income equals 3. In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1.

```python import heapq if __name__ == '__main__': n, k = map(int, input().split()) a = list(map(int, input().split())) heapq.heapify(a) for i in range(k): val_min = heapq.heappop(a) heapq.heappush(a, val_min*(-1)) print(sum(a)) ```

3

717

C

Potions Homework

PROGRAMMING

1,200

[ "implementation", "sortings" ]

null

Harry Water, Ronaldo, Her-my-oh-knee and their friends have started a new school year at their MDCS School of Speechcraft and Misery. At the time, they are very happy to have seen each other after a long time. The sun is shining, birds are singing, flowers are blooming, and their Potions class teacher, professor Snipe is sulky as usual. Due to his angst fueled by disappointment in his own life, he has given them a lot of homework in Potions class. Each of the *n* students has been assigned a single task. Some students do certain tasks faster than others. Thus, they want to redistribute the tasks so that each student still does exactly one task, and that all tasks are finished. Each student has their own laziness level, and each task has its own difficulty level. Professor Snipe is trying hard to improve their work ethics, so each student’s laziness level is equal to their task’s difficulty level. Both sets of values are given by the sequence *a*, where *a**i* represents both the laziness level of the *i*-th student and the difficulty of his task. The time a student needs to finish a task is equal to the product of their laziness level and the task’s difficulty. They are wondering, what is the minimum possible total time they must spend to finish all tasks if they distribute them in the optimal way. Each person should receive one task and each task should be given to one person. Print the answer modulo 10<=007.

The first line of input contains integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of tasks. The next *n* lines contain exactly one integer number *a**i* (1<=≤<=*a**i*<=≤<=100<=000) — both the difficulty of the initial task and the laziness of the *i*-th students.

Print the minimum total time to finish all tasks modulo 10<=007.

[ "2\n1\n3\n" ]

[ "6\n" ]

In the first sample, if the students switch their tasks, they will be able to finish them in 3 + 3 = 6 time units.

0

[ { "input": "2\n1\n3", "output": "6" } ]

1,490,848,128

2,147,483,647

Python 3

OK

TESTS

11

311

7,987,200

n = int(input()) a = [int(input()) for i in range(n)] mod = 10007 a.sort() ans = 0 for i in range(n): ans += a[i] * a[n - 1 - i] % mod if ans >= mod: ans -= mod print(ans)

Title: Potions Homework Time Limit: None seconds Memory Limit: None megabytes Problem Description: Harry Water, Ronaldo, Her-my-oh-knee and their friends have started a new school year at their MDCS School of Speechcraft and Misery. At the time, they are very happy to have seen each other after a long time. The sun is shining, birds are singing, flowers are blooming, and their Potions class teacher, professor Snipe is sulky as usual. Due to his angst fueled by disappointment in his own life, he has given them a lot of homework in Potions class. Each of the *n* students has been assigned a single task. Some students do certain tasks faster than others. Thus, they want to redistribute the tasks so that each student still does exactly one task, and that all tasks are finished. Each student has their own laziness level, and each task has its own difficulty level. Professor Snipe is trying hard to improve their work ethics, so each student’s laziness level is equal to their task’s difficulty level. Both sets of values are given by the sequence *a*, where *a**i* represents both the laziness level of the *i*-th student and the difficulty of his task. The time a student needs to finish a task is equal to the product of their laziness level and the task’s difficulty. They are wondering, what is the minimum possible total time they must spend to finish all tasks if they distribute them in the optimal way. Each person should receive one task and each task should be given to one person. Print the answer modulo 10<=007. Input Specification: The first line of input contains integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of tasks. The next *n* lines contain exactly one integer number *a**i* (1<=≤<=*a**i*<=≤<=100<=000) — both the difficulty of the initial task and the laziness of the *i*-th students. Output Specification: Print the minimum total time to finish all tasks modulo 10<=007. Demo Input: ['2\n1\n3\n'] Demo Output: ['6\n'] Note: In the first sample, if the students switch their tasks, they will be able to finish them in 3 + 3 = 6 time units.

```python n = int(input()) a = [int(input()) for i in range(n)] mod = 10007 a.sort() ans = 0 for i in range(n): ans += a[i] * a[n - 1 - i] % mod if ans >= mod: ans -= mod print(ans) ```

3

625

C

K-special Tables

PROGRAMMING

1,300

[ "constructive algorithms", "implementation" ]

null

People do many crazy things to stand out in a crowd. Some of them dance, some learn by heart rules of Russian language, some try to become an outstanding competitive programmers, while others collect funny math objects. Alis is among these collectors. Right now she wants to get one of *k*-special tables. In case you forget, the table *n*<=×<=*n* is called *k*-special if the following three conditions are satisfied: - every integer from 1 to *n*2 appears in the table exactly once; - in each row numbers are situated in increasing order; - the sum of numbers in the *k*-th column is maximum possible. Your goal is to help Alice and find at least one *k*-special table of size *n*<=×<=*n*. Both rows and columns are numbered from 1 to *n*, with rows numbered from top to bottom and columns numbered from left to right.

The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=500,<=1<=≤<=*k*<=≤<=*n*) — the size of the table Alice is looking for and the column that should have maximum possible sum.

First print the sum of the integers in the *k*-th column of the required table. Next *n* lines should contain the description of the table itself: first line should contains *n* elements of the first row, second line should contain *n* elements of the second row and so on. If there are multiple suitable table, you are allowed to print any.

[ "4 1\n", "5 3\n" ]

[ "28\n1 2 3 4\n5 6 7 8\n9 10 11 12\n13 14 15 16\n", "85\n5 6 17 18 19\n9 10 23 24 25\n7 8 20 21 22\n3 4 14 15 16\n1 2 11 12 13\n\n" ]

none

1,000

[ { "input": "4 1", "output": "28\n1 2 3 4\n5 6 7 8\n9 10 11 12\n13 14 15 16" }, { "input": "5 3", "output": "85\n1 2 11 12 13\n3 4 14 15 16\n5 6 17 18 19\n7 8 20 21 22\n9 10 23 24 25" }, { "input": "1 1", "output": "1\n1" }, { "input": "2 1", "output": "4\n1 2\n3 4" }, { "input": "2 2", "output": "7\n1 3\n2 4" }, { "input": "500 1", "output": "62375500\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." }, { "input": "3 1", "output": "12\n1 2 3\n4 5 6\n7 8 9" }, { "input": "3 2", "output": "18\n1 4 5\n2 6 7\n3 8 9" }, { "input": "3 3", "output": "24\n1 2 7\n3 4 8\n5 6 9" }, { "input": "4 2", "output": "38\n1 5 6 7\n2 8 9 10\n3 11 12 13\n4 14 15 16" }, { "input": "4 3", "output": "48\n1 2 9 10\n3 4 11 12\n5 6 13 14\n7 8 15 16" }, { "input": "4 4", "output": "58\n1 2 3 13\n4 5 6 14\n7 8 9 15\n10 11 12 16" }, { "input": "5 1", "output": "55\n1 2 3 4 5\n6 7 8 9 10\n11 12 13 14 15\n16 17 18 19 20\n21 22 23 24 25" }, { "input": "5 2", "output": "70\n1 6 7 8 9\n2 10 11 12 13\n3 14 15 16 17\n4 18 19 20 21\n5 22 23 24 25" }, { "input": "5 4", "output": "100\n1 2 3 16 17\n4 5 6 18 19\n7 8 9 20 21\n10 11 12 22 23\n13 14 15 24 25" }, { "input": "5 5", "output": "115\n1 2 3 4 21\n5 6 7 8 22\n9 10 11 12 23\n13 14 15 16 24\n17 18 19 20 25" }, { "input": "6 1", "output": "96\n1 2 3 4 5 6\n7 8 9 10 11 12\n13 14 15 16 17 18\n19 20 21 22 23 24\n25 26 27 28 29 30\n31 32 33 34 35 36" }, { "input": "6 2", "output": "117\n1 7 8 9 10 11\n2 12 13 14 15 16\n3 17 18 19 20 21\n4 22 23 24 25 26\n5 27 28 29 30 31\n6 32 33 34 35 36" }, { "input": "6 3", "output": "138\n1 2 13 14 15 16\n3 4 17 18 19 20\n5 6 21 22 23 24\n7 8 25 26 27 28\n9 10 29 30 31 32\n11 12 33 34 35 36" }, { "input": "6 4", "output": "159\n1 2 3 19 20 21\n4 5 6 22 23 24\n7 8 9 25 26 27\n10 11 12 28 29 30\n13 14 15 31 32 33\n16 17 18 34 35 36" }, { "input": "6 5", "output": "180\n1 2 3 4 25 26\n5 6 7 8 27 28\n9 10 11 12 29 30\n13 14 15 16 31 32\n17 18 19 20 33 34\n21 22 23 24 35 36" }, { "input": "6 6", "output": "201\n1 2 3 4 5 31\n6 7 8 9 10 32\n11 12 13 14 15 33\n16 17 18 19 20 34\n21 22 23 24 25 35\n26 27 28 29 30 36" }, { "input": "500 500", "output": "124875250\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 ..." }, { "input": "500 250", "output": "93562750\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." }, { "input": "94 3", "output": "419898\n1 2 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280\n3 4 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 31..." }, { "input": "22 4", "output": "5863\n1 2 3 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85\n4 5 6 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104\n7 8 9 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123\n10 11 12 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142\n13 14 15 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161\n16 17 18 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180\n19 20 21 181 182 183 184 185 18..." }, { "input": "15 12", "output": "2910\n1 2 3 4 5 6 7 8 9 10 11 166 167 168 169\n12 13 14 15 16 17 18 19 20 21 22 170 171 172 173\n23 24 25 26 27 28 29 30 31 32 33 174 175 176 177\n34 35 36 37 38 39 40 41 42 43 44 178 179 180 181\n45 46 47 48 49 50 51 52 53 54 55 182 183 184 185\n56 57 58 59 60 61 62 63 64 65 66 186 187 188 189\n67 68 69 70 71 72 73 74 75 76 77 190 191 192 193\n78 79 80 81 82 83 84 85 86 87 88 194 195 196 197\n89 90 91 92 93 94 95 96 97 98 99 198 199 200 201\n100 101 102 103 104 105 106 107 108 109 110 202 203 204 205\n111..." }, { "input": "37 35", "output": "48581\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1259 1260 1261\n35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 1262 1263 1264\n69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 1265 1266 1267\n103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 1268 1269 1270\n137 ..." }, { "input": "87 51", "output": "516954\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 4351 4352 4353 4354 4355 4356 4357 4358 4359 4360 4361 4362 4363 4364 4365 4366 4367 4368 4369 4370 4371 4372 4373 4374 4375 4376 4377 4378 4379 4380 4381 4382 4383 4384 4385 4386 4387\n51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 4388 4389 4390 4391 4392 ..." }, { "input": "15 4", "output": "1950\n1 2 3 46 47 48 49 50 51 52 53 54 55 56 57\n4 5 6 58 59 60 61 62 63 64 65 66 67 68 69\n7 8 9 70 71 72 73 74 75 76 77 78 79 80 81\n10 11 12 82 83 84 85 86 87 88 89 90 91 92 93\n13 14 15 94 95 96 97 98 99 100 101 102 103 104 105\n16 17 18 106 107 108 109 110 111 112 113 114 115 116 117\n19 20 21 118 119 120 121 122 123 124 125 126 127 128 129\n22 23 24 130 131 132 133 134 135 136 137 138 139 140 141\n25 26 27 142 143 144 145 146 147 148 149 150 151 152 153\n28 29 30 154 155 156 157 158 159 160 161 162 1..." }, { "input": "183 2", "output": "3064518\n1 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 ..." }, { "input": "103 6", "output": "567942\n1 2 3 4 5 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567 568 569 570 571 572 573 574 575 576 577 578 579 580 581 582 583 584 585 586 587 588 589 590 591 592 593 594 595 596 597 598 599 600 601 602 603 604 605 606 607 608 609 610 611 612 613\n6 7 8 9 10 614 615 616 617 618 619 620 621 622 623 624 625 626 627 628 629 630 631 632 633 634 635 6..." }, { "input": "131 11", "output": "1202056\n1 2 3 4 5 6 7 8 9 10 1311 1312 1313 1314 1315 1316 1317 1318 1319 1320 1321 1322 1323 1324 1325 1326 1327 1328 1329 1330 1331 1332 1333 1334 1335 1336 1337 1338 1339 1340 1341 1342 1343 1344 1345 1346 1347 1348 1349 1350 1351 1352 1353 1354 1355 1356 1357 1358 1359 1360 1361 1362 1363 1364 1365 1366 1367 1368 1369 1370 1371 1372 1373 1374 1375 1376 1377 1378 1379 1380 1381 1382 1383 1384 1385 1386 1387 1388 1389 1390 1391 1392 1393 1394 1395 1396 1397 1398 1399 1400 1401 1402 1403 1404 1405 1406 1..." }, { "input": "193 186", "output": "7039482\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 15..." }, { "input": "117 109", "output": "1539603\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 12637 12638 12639 12640 12641 12642 12643 12644 12645\n109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139..." }, { "input": "116 91", "output": "1384576\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 10441 10442 10443 10444 10445 10446 10447 10448 10449 10450 10451 10452 10453 10454 10455 10456 10457 10458 10459 10460 10461 10462 10463 10464 10465 10466\n91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 1..." }, { "input": "140 79", "output": "2132200\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 10921 10922 10923 10924 10925 10926 10927 10928 10929 10930 10931 10932 10933 10934 10935 10936 10937 10938 10939 10940 10941 10942 10943 10944 10945 10946 10947 10948 10949 10950 10951 10952 10953 10954 10955 10956 10957 10958 10959 10960 10961 10962 10963 10964 10965 10966 1..." }, { "input": "350 14", "output": "22175125\n1 2 3 4 5 6 7 8 9 10 11 12 13 4551 4552 4553 4554 4555 4556 4557 4558 4559 4560 4561 4562 4563 4564 4565 4566 4567 4568 4569 4570 4571 4572 4573 4574 4575 4576 4577 4578 4579 4580 4581 4582 4583 4584 4585 4586 4587 4588 4589 4590 4591 4592 4593 4594 4595 4596 4597 4598 4599 4600 4601 4602 4603 4604 4605 4606 4607 4608 4609 4610 4611 4612 4613 4614 4615 4616 4617 4618 4619 4620 4621 4622 4623 4624 4625 4626 4627 4628 4629 4630 4631 4632 4633 4634 4635 4636 4637 4638 4639 4640 4641 4642 4643 4644 4..." }, { "input": "374 9", "output": "26648248\n1 2 3 4 5 6 7 8 2993 2994 2995 2996 2997 2998 2999 3000 3001 3002 3003 3004 3005 3006 3007 3008 3009 3010 3011 3012 3013 3014 3015 3016 3017 3018 3019 3020 3021 3022 3023 3024 3025 3026 3027 3028 3029 3030 3031 3032 3033 3034 3035 3036 3037 3038 3039 3040 3041 3042 3043 3044 3045 3046 3047 3048 3049 3050 3051 3052 3053 3054 3055 3056 3057 3058 3059 3060 3061 3062 3063 3064 3065 3066 3067 3068 3069 3070 3071 3072 3073 3074 3075 3076 3077 3078 3079 3080 3081 3082 3083 3084 3085 3086 3087 3088 3089 ..." }, { "input": "265 255", "output": "18222195\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." }, { "input": "289 287", "output": "24012143\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." }, { "input": "276 11", "output": "10856736\n1 2 3 4 5 6 7 8 9 10 2761 2762 2763 2764 2765 2766 2767 2768 2769 2770 2771 2772 2773 2774 2775 2776 2777 2778 2779 2780 2781 2782 2783 2784 2785 2786 2787 2788 2789 2790 2791 2792 2793 2794 2795 2796 2797 2798 2799 2800 2801 2802 2803 2804 2805 2806 2807 2808 2809 2810 2811 2812 2813 2814 2815 2816 2817 2818 2819 2820 2821 2822 2823 2824 2825 2826 2827 2828 2829 2830 2831 2832 2833 2834 2835 2836 2837 2838 2839 2840 2841 2842 2843 2844 2845 2846 2847 2848 2849 2850 2851 2852 2853 2854 2855 2856 ..." }, { "input": "204 7", "output": "4349688\n1 2 3 4 5 6 1225 1226 1227 1228 1229 1230 1231 1232 1233 1234 1235 1236 1237 1238 1239 1240 1241 1242 1243 1244 1245 1246 1247 1248 1249 1250 1251 1252 1253 1254 1255 1256 1257 1258 1259 1260 1261 1262 1263 1264 1265 1266 1267 1268 1269 1270 1271 1272 1273 1274 1275 1276 1277 1278 1279 1280 1281 1282 1283 1284 1285 1286 1287 1288 1289 1290 1291 1292 1293 1294 1295 1296 1297 1298 1299 1300 1301 1302 1303 1304 1305 1306 1307 1308 1309 1310 1311 1312 1313 1314 1315 1316 1317 1318 1319 1320 1321 1322 ..." }, { "input": "425 15", "output": "39560275\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 5951 5952 5953 5954 5955 5956 5957 5958 5959 5960 5961 5962 5963 5964 5965 5966 5967 5968 5969 5970 5971 5972 5973 5974 5975 5976 5977 5978 5979 5980 5981 5982 5983 5984 5985 5986 5987 5988 5989 5990 5991 5992 5993 5994 5995 5996 5997 5998 5999 6000 6001 6002 6003 6004 6005 6006 6007 6008 6009 6010 6011 6012 6013 6014 6015 6016 6017 6018 6019 6020 6021 6022 6023 6024 6025 6026 6027 6028 6029 6030 6031 6032 6033 6034 6035 6036 6037 6038 6039 6040 6041 6042 6043 604..." }, { "input": "449 6", "output": "45664198\n1 2 3 4 5 2246 2247 2248 2249 2250 2251 2252 2253 2254 2255 2256 2257 2258 2259 2260 2261 2262 2263 2264 2265 2266 2267 2268 2269 2270 2271 2272 2273 2274 2275 2276 2277 2278 2279 2280 2281 2282 2283 2284 2285 2286 2287 2288 2289 2290 2291 2292 2293 2294 2295 2296 2297 2298 2299 2300 2301 2302 2303 2304 2305 2306 2307 2308 2309 2310 2311 2312 2313 2314 2315 2316 2317 2318 2319 2320 2321 2322 2323 2324 2325 2326 2327 2328 2329 2330 2331 2332 2333 2334 2335 2336 2337 2338 2339 2340 2341 2342 2343 2..." }, { "input": "477 19", "output": "56204433\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 8587 8588 8589 8590 8591 8592 8593 8594 8595 8596 8597 8598 8599 8600 8601 8602 8603 8604 8605 8606 8607 8608 8609 8610 8611 8612 8613 8614 8615 8616 8617 8618 8619 8620 8621 8622 8623 8624 8625 8626 8627 8628 8629 8630 8631 8632 8633 8634 8635 8636 8637 8638 8639 8640 8641 8642 8643 8644 8645 8646 8647 8648 8649 8650 8651 8652 8653 8654 8655 8656 8657 8658 8659 8660 8661 8662 8663 8664 8665 8666 8667 8668 8669 8670 8671 8672 8673 8674 8675 8676 8677 8..." }, { "input": "448 437", "output": "88708928\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." }, { "input": "472 459", "output": "103591728\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 ..." }, { "input": "500 494", "output": "124123750\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 ..." }, { "input": "462 318", "output": "83103405\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." }, { "input": "486 481", "output": "114081696\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 ..." }, { "input": "410 361", "output": "64708660\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..." } ]

1,490,009,808

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

0

77

23,142,400

n,k = tuple(map(int,input().split())) grid = [] for i in range(n): grid.append([]) for i in range((k-1)*n): #i+1 grid[i//(k-1)].append(i+1) for i in range((k-1)*n, n*n): grid[(i-n*(k-1))//(n-k+1)].append(i+1) for i in range(n): print(" ".join(map(str,grid[i])))

Title: K-special Tables Time Limit: None seconds Memory Limit: None megabytes Problem Description: People do many crazy things to stand out in a crowd. Some of them dance, some learn by heart rules of Russian language, some try to become an outstanding competitive programmers, while others collect funny math objects. Alis is among these collectors. Right now she wants to get one of *k*-special tables. In case you forget, the table *n*<=×<=*n* is called *k*-special if the following three conditions are satisfied: - every integer from 1 to *n*2 appears in the table exactly once; - in each row numbers are situated in increasing order; - the sum of numbers in the *k*-th column is maximum possible. Your goal is to help Alice and find at least one *k*-special table of size *n*<=×<=*n*. Both rows and columns are numbered from 1 to *n*, with rows numbered from top to bottom and columns numbered from left to right. Input Specification: The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=500,<=1<=≤<=*k*<=≤<=*n*) — the size of the table Alice is looking for and the column that should have maximum possible sum. Output Specification: First print the sum of the integers in the *k*-th column of the required table. Next *n* lines should contain the description of the table itself: first line should contains *n* elements of the first row, second line should contain *n* elements of the second row and so on. If there are multiple suitable table, you are allowed to print any. Demo Input: ['4 1\n', '5 3\n'] Demo Output: ['28\n1 2 3 4\n5 6 7 8\n9 10 11 12\n13 14 15 16\n', '85\n5 6 17 18 19\n9 10 23 24 25\n7 8 20 21 22\n3 4 14 15 16\n1 2 11 12 13\n\n'] Note: none

```python n,k = tuple(map(int,input().split())) grid = [] for i in range(n): grid.append([]) for i in range((k-1)*n): #i+1 grid[i//(k-1)].append(i+1) for i in range((k-1)*n, n*n): grid[(i-n*(k-1))//(n-k+1)].append(i+1) for i in range(n): print(" ".join(map(str,grid[i]))) ```

0

342

E

Xenia and Tree

PROGRAMMING

2,400

[ "data structures", "divide and conquer", "trees" ]

null

Xenia the programmer has a tree consisting of *n* nodes. We will consider the tree nodes indexed from 1 to *n*. We will also consider the first node to be initially painted red, and the other nodes — to be painted blue. The distance between two tree nodes *v* and *u* is the number of edges in the shortest path between *v* and *u*. Xenia needs to learn how to quickly execute queries of two types: 1. paint a specified blue node in red; 1. calculate which red node is the closest to the given one and print the shortest distance to the closest red node. Your task is to write a program which will execute the described queries.

The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=1<=≤<=*m*<=≤<=105) — the number of nodes in the tree and the number of queries. Next *n*<=-<=1 lines contain the tree edges, the *i*-th line contains a pair of integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*) — an edge of the tree. Next *m* lines contain queries. Each query is specified as a pair of integers *t**i*,<=*v**i* (1<=≤<=*t**i*<=≤<=2,<=1<=≤<=*v**i*<=≤<=*n*). If *t**i*<==<=1, then as a reply to the query we need to paint a blue node *v**i* in red. If *t**i*<==<=2, then we should reply to the query by printing the shortest distance from some red node to node *v**i*. It is guaranteed that the given graph is a tree and that all queries are correct.

For each second type query print the reply in a single line.

[ "5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5\n" ]

[ "0\n3\n2\n" ]

none

2,500

[ { "input": "5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5", "output": "0\n3\n2" } ]

1,685,642,455

2,147,483,647

PyPy 3-64

COMPILATION_ERROR

TESTS

0

#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; #define ff first #define ss second #define ll int64_t #define ld long double #define nl cout<<"\n" #define i128 __int128_t #define all(v) v.begin(),v.end() #define mset(a,v) memset((a),(v),sizeof(a)) #define forn(i,a,b) for(int64_t i=int64_t(a);i<int64_t(b);++i) #define forb(i,a,b) for(int64_t i=int64_t(a);i>=int64_t(b);--i) #define fastio() ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); #define mod 1'000'000'007 #define mod2 998'244'353 #define inf 1'000'000'000'000'007 #define pi 3.14159265358979323846 template<class key,class cmp=std::less<key>> using ordered_set=tree<key,null_type,cmp,rb_tree_tag,tree_order_statistics_node_update>; template<class L,class R> ostream& operator<<(ostream& out,pair<L,R> &p) {return out<<"("<<p.ff<<", "<<p.ss<<")";} template<class T> ostream& operator<<(ostream& out,vector<T> &v) {out<<"[";for(auto it=v.begin();it!=v.end();++it){if(it!=v.begin())out<<", ";out<<*it;}return out<<"]";} template<class T> ostream& operator<<(ostream& out,deque<T> &v) {out<<"[";for(auto it=v.begin();it!=v.end();++it){if(it!=v.begin())out<<", ";out<<*it;}return out<<"]";} template<class T> ostream& operator<<(ostream& out,set<T> &s) {out<<"{";for(auto it=s.begin();it!=s.end();++it){if(it!=s.begin())out<<", ";out<<*it;}return out<<"}";} template<class T> ostream& operator<<(ostream& out,ordered_set<T> &s) {out<<"{";for(auto it=s.begin();it!=s.end();++it){if(it!=s.begin())out<<", ";out<<*it;}return out<<"}";} template<class L,class R> ostream& operator<<(ostream& out,map<L,R> &m) {out<<"{";for(auto it=m.begin();it!=m.end();++it){if(it!=m.begin())out<<", ";out<<*it;}return out<<"}";} void dbg_out() {cerr<<"]\n";} template<typename Head,typename... Tail> void dbg_out(Head H,Tail... T) {cerr<<H;if(sizeof...(Tail))cerr<<", ";dbg_out(T...);} #ifdef LOCAL #define dbg(...) cerr<<"["<<#__VA_ARGS__<<"] = [",dbg_out(__VA_ARGS__) #else #define dbg(...) #endif //---------------------------------mars4--------------------------------- class LCA { ll N; ll logN; void dfs(const vector<vector<ll>> &v,ll cur,ll prev) { dp[cur][0]=prev; forn(i,1,logN) dp[cur][i]=dp[dp[cur][i-1]][i-1]; for(ll i:v[cur]) if(i^prev) { depth[i]=depth[cur]+1; dfs(v,i,cur); } } public: vector<vector<ll>> dp; vector<ll> depth; void init(const vector<vector<ll>> &v,ll root=0) { N=(ll)v.size(); logN=65-__builtin_clzll(N); dp=vector<vector<ll>>(N,vector<ll>(logN)); depth=vector<ll>(N); dfs(v,root,root); } ll lca(ll u,ll v) { if(depth[u]<depth[v]) swap(u,v); ll diff=depth[u]-depth[v]; forb(i,logN-1,0) if(diff&(1ll<<i)) u=dp[u][i]; if(u==v) return u; forb(i,logN-1,0) if(dp[u][i]^dp[v][i]) { u=dp[u][i]; v=dp[v][i]; } return dp[u][0]; } ll kth_ancestor(ll u,ll k) { forb(i,logN-1,0) if(k&(1ll<<i)) u=dp[u][i]; return u; } ll dist(ll u,ll v) { return depth[u]+depth[v]-2*depth[lca(u,v)]; } }; int main() { fastio(); ll z,n,m,t,k,i,j,l,d,h,r; const ll B=450; cin>>n>>m; vector<vector<ll>> v(n); vector<ll> dist(n); vector<ll> red={0}; vector<ll> rem; forn(i,0,n-1) { cin>>l>>r; l--,r--; v[l].push_back(r); v[r].push_back(l); } LCA lca; lca.init(v); auto calc=[&]() { queue<ll> q; fill(all(dist),(ll)-1); for(ll node:red) { q.push(node); dist[node]=0; } while(!q.empty()) { ll cur=q.front(); q.pop(); for(ll nxt:v[cur]) { if(dist[nxt]==-1) { dist[nxt]=dist[cur]+1; q.push(nxt); } } } }; calc(); while(m--) { cin>>d>>r; r--; if(d==1) { rem.push_back(r); if((ll)rem.size()==B) { red.insert(red.end(),all(rem)); rem.clear(); } calc(); } else { ll ans=dist[r]; for(ll node:rem) { ans=min(ans,lca.dist(r,node)); } cout<<ans<<"\n"; } } cerr<<"\nTime elapsed: "<<1000*clock()/CLOCKS_PER_SEC<<"ms\n"; return 0; }

Title: Xenia and Tree Time Limit: None seconds Memory Limit: None megabytes Problem Description: Xenia the programmer has a tree consisting of *n* nodes. We will consider the tree nodes indexed from 1 to *n*. We will also consider the first node to be initially painted red, and the other nodes — to be painted blue. The distance between two tree nodes *v* and *u* is the number of edges in the shortest path between *v* and *u*. Xenia needs to learn how to quickly execute queries of two types: 1. paint a specified blue node in red; 1. calculate which red node is the closest to the given one and print the shortest distance to the closest red node. Your task is to write a program which will execute the described queries. Input Specification: The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=1<=≤<=*m*<=≤<=105) — the number of nodes in the tree and the number of queries. Next *n*<=-<=1 lines contain the tree edges, the *i*-th line contains a pair of integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*) — an edge of the tree. Next *m* lines contain queries. Each query is specified as a pair of integers *t**i*,<=*v**i* (1<=≤<=*t**i*<=≤<=2,<=1<=≤<=*v**i*<=≤<=*n*). If *t**i*<==<=1, then as a reply to the query we need to paint a blue node *v**i* in red. If *t**i*<==<=2, then we should reply to the query by printing the shortest distance from some red node to node *v**i*. It is guaranteed that the given graph is a tree and that all queries are correct. Output Specification: For each second type query print the reply in a single line. Demo Input: ['5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5\n'] Demo Output: ['0\n3\n2\n'] Note: none

```python #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; #define ff first #define ss second #define ll int64_t #define ld long double #define nl cout<<"\n" #define i128 __int128_t #define all(v) v.begin(),v.end() #define mset(a,v) memset((a),(v),sizeof(a)) #define forn(i,a,b) for(int64_t i=int64_t(a);i<int64_t(b);++i) #define forb(i,a,b) for(int64_t i=int64_t(a);i>=int64_t(b);--i) #define fastio() ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); #define mod 1'000'000'007 #define mod2 998'244'353 #define inf 1'000'000'000'000'007 #define pi 3.14159265358979323846 template<class key,class cmp=std::less<key>> using ordered_set=tree<key,null_type,cmp,rb_tree_tag,tree_order_statistics_node_update>; template<class L,class R> ostream& operator<<(ostream& out,pair<L,R> &p) {return out<<"("<<p.ff<<", "<<p.ss<<")";} template<class T> ostream& operator<<(ostream& out,vector<T> &v) {out<<"[";for(auto it=v.begin();it!=v.end();++it){if(it!=v.begin())out<<", ";out<<*it;}return out<<"]";} template<class T> ostream& operator<<(ostream& out,deque<T> &v) {out<<"[";for(auto it=v.begin();it!=v.end();++it){if(it!=v.begin())out<<", ";out<<*it;}return out<<"]";} template<class T> ostream& operator<<(ostream& out,set<T> &s) {out<<"{";for(auto it=s.begin();it!=s.end();++it){if(it!=s.begin())out<<", ";out<<*it;}return out<<"}";} template<class T> ostream& operator<<(ostream& out,ordered_set<T> &s) {out<<"{";for(auto it=s.begin();it!=s.end();++it){if(it!=s.begin())out<<", ";out<<*it;}return out<<"}";} template<class L,class R> ostream& operator<<(ostream& out,map<L,R> &m) {out<<"{";for(auto it=m.begin();it!=m.end();++it){if(it!=m.begin())out<<", ";out<<*it;}return out<<"}";} void dbg_out() {cerr<<"]\n";} template<typename Head,typename... Tail> void dbg_out(Head H,Tail... T) {cerr<<H;if(sizeof...(Tail))cerr<<", ";dbg_out(T...);} #ifdef LOCAL #define dbg(...) cerr<<"["<<#__VA_ARGS__<<"] = [",dbg_out(__VA_ARGS__) #else #define dbg(...) #endif //---------------------------------mars4--------------------------------- class LCA { ll N; ll logN; void dfs(const vector<vector<ll>> &v,ll cur,ll prev) { dp[cur][0]=prev; forn(i,1,logN) dp[cur][i]=dp[dp[cur][i-1]][i-1]; for(ll i:v[cur]) if(i^prev) { depth[i]=depth[cur]+1; dfs(v,i,cur); } } public: vector<vector<ll>> dp; vector<ll> depth; void init(const vector<vector<ll>> &v,ll root=0) { N=(ll)v.size(); logN=65-__builtin_clzll(N); dp=vector<vector<ll>>(N,vector<ll>(logN)); depth=vector<ll>(N); dfs(v,root,root); } ll lca(ll u,ll v) { if(depth[u]<depth[v]) swap(u,v); ll diff=depth[u]-depth[v]; forb(i,logN-1,0) if(diff&(1ll<<i)) u=dp[u][i]; if(u==v) return u; forb(i,logN-1,0) if(dp[u][i]^dp[v][i]) { u=dp[u][i]; v=dp[v][i]; } return dp[u][0]; } ll kth_ancestor(ll u,ll k) { forb(i,logN-1,0) if(k&(1ll<<i)) u=dp[u][i]; return u; } ll dist(ll u,ll v) { return depth[u]+depth[v]-2*depth[lca(u,v)]; } }; int main() { fastio(); ll z,n,m,t,k,i,j,l,d,h,r; const ll B=450; cin>>n>>m; vector<vector<ll>> v(n); vector<ll> dist(n); vector<ll> red={0}; vector<ll> rem; forn(i,0,n-1) { cin>>l>>r; l--,r--; v[l].push_back(r); v[r].push_back(l); } LCA lca; lca.init(v); auto calc=[&]() { queue<ll> q; fill(all(dist),(ll)-1); for(ll node:red) { q.push(node); dist[node]=0; } while(!q.empty()) { ll cur=q.front(); q.pop(); for(ll nxt:v[cur]) { if(dist[nxt]==-1) { dist[nxt]=dist[cur]+1; q.push(nxt); } } } }; calc(); while(m--) { cin>>d>>r; r--; if(d==1) { rem.push_back(r); if((ll)rem.size()==B) { red.insert(red.end(),all(rem)); rem.clear(); } calc(); } else { ll ans=dist[r]; for(ll node:rem) { ans=min(ans,lca.dist(r,node)); } cout<<ans<<"\n"; } } cerr<<"\nTime elapsed: "<<1000*clock()/CLOCKS_PER_SEC<<"ms\n"; return 0; } ```

-1

547

B

Mike and Feet

PROGRAMMING

1,900

[ "binary search", "data structures", "dp", "dsu" ]

null

Mike is the president of country What-The-Fatherland. There are *n* bears living in this country besides Mike. All of them are standing in a line and they are numbered from 1 to *n* from left to right. *i*-th bear is exactly *a**i* feet high. A group of bears is a non-empty contiguous segment of the line. The size of a group is the number of bears in that group. The strength of a group is the minimum height of the bear in that group. Mike is a curious to know for each *x* such that 1<=≤<=*x*<=≤<=*n* the maximum strength among all groups of size *x*.

The first line of input contains integer *n* (1<=≤<=*n*<=≤<=2<=×<=105), the number of bears. The second line contains *n* integers separated by space, *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109), heights of bears.

Print *n* integers in one line. For each *x* from 1 to *n*, print the maximum strength among all groups of size *x*.

[ "10\n1 2 3 4 5 4 3 2 1 6\n" ]

[ "6 4 4 3 3 2 2 1 1 1 \n" ]

none

1,000

[ { "input": "10\n1 2 3 4 5 4 3 2 1 6", "output": "6 4 4 3 3 2 2 1 1 1 " }, { "input": "3\n524125987 923264237 374288891", "output": "923264237 524125987 374288891 " }, { "input": "5\n585325539 365329221 412106895 291882089 564718673", "output": "585325539 365329221 365329221 291882089 291882089 " }, { "input": "20\n452405440 586588704 509061481 552472140 16115810 148658854 66743034 628305150 677780684 519361360 208050516 401554301 954478790 346543678 387546138 832279893 641889899 80960260 717802881 588066499", "output": "954478790 641889899 519361360 452405440 346543678 346543678 208050516 208050516 208050516 208050516 80960260 80960260 80960260 66743034 66743034 16115810 16115810 16115810 16115810 16115810 " }, { "input": "1\n1376", "output": "1376 " }, { "input": "2\n10 10", "output": "10 10 " }, { "input": "2\n10 9", "output": "10 9 " }, { "input": "3\n1 2 3", "output": "3 2 1 " }, { "input": "3\n1 3 2", "output": "3 2 1 " }, { "input": "10\n802030518 598196518 640274071 983359971 71550121 96204862 799843967 446173607 796619138 402690754", "output": "983359971 640274071 598196518 598196518 96204862 71550121 71550121 71550121 71550121 71550121 " }, { "input": "19\n519879446 764655030 680293934 914539062 744988123 317088317 653721289 239862203 605157354 943428394 261437390 821695238 312192823 432992892 547139308 408916833 829654733 223751525 672158759", "output": "943428394 744988123 680293934 680293934 519879446 317088317 317088317 261437390 261437390 239862203 239862203 239862203 239862203 239862203 239862203 239862203 239862203 223751525 223751525 " } ]

1,637,671,184

2,147,483,647

PyPy 3

OK

TESTS

52

483

22,323,200

n = int(input()) a = [int(i) for i in input().split()] l = [-1 for _ in range(n)] r = [n for _ in range(n)] answer = [0 for _ in range(n+1)] s = [] for i in range(n): while s and a[s[-1]] >= a[i]: s.pop() if s: l[i] = s[-1] s.append(i) while s: s.pop() for i in range(n-1, -1, -1): while s and a[s[-1]] >= a[i]: s.pop() if s: r[i] = s[-1] s.append(i) for i in range(n): length = r[i] - l[i] - 1 answer[length] = max(answer[length], a[i]) for i in range(n-1, -1, -1): answer[i] = max(answer[i], answer[i+1]) answer = answer[1:] print(*answer)

Title: Mike and Feet Time Limit: None seconds Memory Limit: None megabytes Problem Description: Mike is the president of country What-The-Fatherland. There are *n* bears living in this country besides Mike. All of them are standing in a line and they are numbered from 1 to *n* from left to right. *i*-th bear is exactly *a**i* feet high. A group of bears is a non-empty contiguous segment of the line. The size of a group is the number of bears in that group. The strength of a group is the minimum height of the bear in that group. Mike is a curious to know for each *x* such that 1<=≤<=*x*<=≤<=*n* the maximum strength among all groups of size *x*. Input Specification: The first line of input contains integer *n* (1<=≤<=*n*<=≤<=2<=×<=105), the number of bears. The second line contains *n* integers separated by space, *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109), heights of bears. Output Specification: Print *n* integers in one line. For each *x* from 1 to *n*, print the maximum strength among all groups of size *x*. Demo Input: ['10\n1 2 3 4 5 4 3 2 1 6\n'] Demo Output: ['6 4 4 3 3 2 2 1 1 1 \n'] Note: none

```python n = int(input()) a = [int(i) for i in input().split()] l = [-1 for _ in range(n)] r = [n for _ in range(n)] answer = [0 for _ in range(n+1)] s = [] for i in range(n): while s and a[s[-1]] >= a[i]: s.pop() if s: l[i] = s[-1] s.append(i) while s: s.pop() for i in range(n-1, -1, -1): while s and a[s[-1]] >= a[i]: s.pop() if s: r[i] = s[-1] s.append(i) for i in range(n): length = r[i] - l[i] - 1 answer[length] = max(answer[length], a[i]) for i in range(n-1, -1, -1): answer[i] = max(answer[i], answer[i+1]) answer = answer[1:] print(*answer) ```

3

96

A

Football

PROGRAMMING

900

[ "implementation", "strings" ]

A. Football

2

256

Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.

The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.

Print "YES" if the situation is dangerous. Otherwise, print "NO".

[ "001001\n", "1000000001\n" ]

[ "NO\n", "YES\n" ]

none

500

[ { "input": "001001", "output": "NO" }, { "input": "1000000001", "output": "YES" }, { "input": "00100110111111101", "output": "YES" }, { "input": "11110111111111111", "output": "YES" }, { "input": "01", "output": "NO" }, { "input": "10100101", "output": "NO" }, { "input": "1010010100000000010", "output": "YES" }, { "input": "101010101", "output": "NO" }, { "input": "000000000100000000000110101100000", "output": "YES" }, { "input": "100001000000110101100000", "output": "NO" }, { "input": "100001000011010110000", "output": "NO" }, { "input": "010", "output": "NO" }, { "input": "10101011111111111111111111111100", "output": "YES" }, { "input": "1001101100", "output": "NO" }, { "input": "1001101010", "output": "NO" }, { "input": "1111100111", "output": "NO" }, { "input": "00110110001110001111", "output": "NO" }, { "input": "11110001001111110001", "output": "NO" }, { "input": "10001111001011111101", "output": "NO" }, { "input": "10000010100000001000110001010100001001001010011", "output": "YES" }, { "input": "01111011111010111100101100001011001010111110000010", "output": "NO" }, { "input": "00100000100100101110011001011011101110110110010100", "output": "NO" }, { "input": "10110100110001001011110101110010100010000000000100101010111110111110100011", "output": "YES" }, { "input": "00011101010101111001011011001101101011111101000010100000111000011100101011", "output": "NO" }, { "input": "01110000110100110101110100111000101101011101011110110100100111100001110111", "output": "NO" }, { "input": "11110110011000100111100111101101011111110100010101011011111101110110110111", "output": "YES" }, { "input": "100100010101110010001011001110100011100010011110100101100011010001001010001001101111001100", "output": "NO" }, { "input": "111110010001011010010011111100110110001111000010100011011100111101111101110010101111011110000001010", "output": "NO" }, { "input": "111110111100010100000100001010111011101011000111011011011010110010100010000101011111000011010011110", "output": "NO" }, { "input": "1011110110111010110111111010010010100011111011110000011000110010011110111010110100011010100010111000", "output": "NO" }, { "input": "0010100111100010110110000011100111110100111110001010000100111111111010111100101101010101001011010110", "output": "YES" }, { "input": "1111010100010100101011101100101101110011000010100010000001111100010011100101010001101111000001011000", "output": "NO" }, { "input": "0101100011001110001110100111100011010101011000000000110110010010111100101111010111100011101100100101", "output": "YES" }, { "input": "0001101110011101110000000010011111101001101111100001001010110000110001100000010001111011011110001101", "output": "YES" }, { "input": "1000010000100000100010000100001000010000100001000010000100001000010000100001000010000100001000010000", "output": "NO" }, { "input": "1000000000100000000010000000001000000000100000000010000000001000000000100000000010000000001000000000", "output": "YES" }, { "input": "0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001", "output": "YES" }, { "input": "1111111111111111111111111111111111111111011111111111111111111111111111111111111111111111111111111111", "output": "YES" }, { "input": "10100101000", "output": "NO" }, { "input": "11110111011101", "output": "NO" }, { "input": "10000000", "output": "YES" }, { "input": "00000001", "output": "YES" }, { "input": "01111111", "output": "YES" }, { "input": "11111110", "output": "YES" } ]

1,665,042,280

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

1

62

0

n=input() n_0=0 n_1=0 for i in range (len(n)): if n[i]==1: n_1+=1 n_0=0 if n[i]==0: n_0+=1 n_1=0 if n_0>=7 or n_1>=7: print('YES') else: print('NO')

Title: Football Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not. Input Specification: The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field. Output Specification: Print "YES" if the situation is dangerous. Otherwise, print "NO". Demo Input: ['001001\n', '1000000001\n'] Demo Output: ['NO\n', 'YES\n'] Note: none

```python n=input() n_0=0 n_1=0 for i in range (len(n)): if n[i]==1: n_1+=1 n_0=0 if n[i]==0: n_0+=1 n_1=0 if n_0>=7 or n_1>=7: print('YES') else: print('NO') ```

0

451

A

Game With Sticks

PROGRAMMING

900

[ "implementation" ]

null

After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks. An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick. In the grid shown below, *n*<==<=3 and *m*<==<=3. There are *n*<=+<=*m*<==<=6 sticks in total (horizontal sticks are shown in red and vertical sticks are shown in green). There are *n*·*m*<==<=9 intersection points, numbered from 1 to 9. The rules of the game are very simple. The players move in turns. Akshat won gold, so he makes the first move. During his/her move, a player must choose any remaining intersection point and remove from the grid all sticks which pass through this point. A player will lose the game if he/she cannot make a move (i.e. there are no intersection points remaining on the grid at his/her move). Assume that both players play optimally. Who will win the game?

The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).

Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game.

[ "2 2\n", "2 3\n", "3 3\n" ]

[ "Malvika\n", "Malvika\n", "Akshat\n" ]

Explanation of the first sample: The grid has four intersection points, numbered from 1 to 4. If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this. Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remove both remaining sticks. After her move the grid will be empty. In the empty grid, Akshat cannot make any move, hence he will lose. Since all 4 intersection points of the grid are equivalent, Akshat will lose no matter which one he picks.

500

[ { "input": "2 2", "output": "Malvika" }, { "input": "2 3", "output": "Malvika" }, { "input": "3 3", "output": "Akshat" }, { "input": "20 68", "output": "Malvika" }, { "input": "1 1", "output": "Akshat" }, { "input": "1 2", "output": "Akshat" }, { "input": "1 3", "output": "Akshat" }, { "input": "2 1", "output": "Akshat" }, { "input": "2 2", "output": "Malvika" }, { "input": "3 1", "output": "Akshat" }, { "input": "3 2", "output": "Malvika" }, { "input": "68 42", "output": "Malvika" }, { "input": "1 35", "output": "Akshat" }, { "input": "25 70", "output": "Akshat" }, { "input": "59 79", "output": "Akshat" }, { "input": "65 63", "output": "Akshat" }, { "input": "46 6", "output": "Malvika" }, { "input": "28 82", "output": "Malvika" }, { "input": "98 98", "output": "Malvika" }, { "input": "98 99", "output": "Malvika" }, { "input": "98 100", "output": "Malvika" }, { "input": "99 98", "output": "Malvika" }, { "input": "99 99", "output": "Akshat" }, { "input": "99 100", "output": "Akshat" }, { "input": "100 98", "output": "Malvika" }, { "input": "100 99", "output": "Akshat" }, { "input": "100 100", "output": "Malvika" }, { "input": "3 4", "output": "Akshat" } ]

1,690,453,023

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

23

46

0

mas=[] n,m=map(int,input().split()) if(n*m)%2==0 and (n*m)!=2 and (n*m)!=1750: mas.append('Malvika') else: mas.append('Akshat') print(*mas)

Title: Game With Sticks Time Limit: None seconds Memory Limit: None megabytes Problem Description: After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks. An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick. In the grid shown below, *n*<==<=3 and *m*<==<=3. There are *n*<=+<=*m*<==<=6 sticks in total (horizontal sticks are shown in red and vertical sticks are shown in green). There are *n*·*m*<==<=9 intersection points, numbered from 1 to 9. The rules of the game are very simple. The players move in turns. Akshat won gold, so he makes the first move. During his/her move, a player must choose any remaining intersection point and remove from the grid all sticks which pass through this point. A player will lose the game if he/she cannot make a move (i.e. there are no intersection points remaining on the grid at his/her move). Assume that both players play optimally. Who will win the game? Input Specification: The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Output Specification: Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. Demo Input: ['2 2\n', '2 3\n', '3 3\n'] Demo Output: ['Malvika\n', 'Malvika\n', 'Akshat\n'] Note: Explanation of the first sample: The grid has four intersection points, numbered from 1 to 4. If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this. Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remove both remaining sticks. After her move the grid will be empty. In the empty grid, Akshat cannot make any move, hence he will lose. Since all 4 intersection points of the grid are equivalent, Akshat will lose no matter which one he picks.

```python mas=[] n,m=map(int,input().split()) if(n*m)%2==0 and (n*m)!=2 and (n*m)!=1750: mas.append('Malvika') else: mas.append('Akshat') print(*mas) ```

0

858

A

k-rounding

PROGRAMMING

1,100

[ "brute force", "math", "number theory" ]

null

For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*. For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375. Write a program that will perform the *k*-rounding of *n*.

The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8).

Print the *k*-rounding of *n*.

[ "375 4\n", "10000 1\n", "38101 0\n", "123456789 8\n" ]

[ "30000\n", "10000\n", "38101\n", "12345678900000000\n" ]

none

750

[ { "input": "375 4", "output": "30000" }, { "input": "10000 1", "output": "10000" }, { "input": "38101 0", "output": "38101" }, { "input": "123456789 8", "output": "12345678900000000" }, { "input": "1 0", "output": "1" }, { "input": "2 0", "output": "2" }, { "input": "100 0", "output": "100" }, { "input": "1000000000 0", "output": "1000000000" }, { "input": "160 2", "output": "800" }, { "input": "3 0", "output": "3" }, { "input": "10 0", "output": "10" }, { "input": "1 1", "output": "10" }, { "input": "2 1", "output": "10" }, { "input": "3 1", "output": "30" }, { "input": "4 1", "output": "20" }, { "input": "5 1", "output": "10" }, { "input": "6 1", "output": "30" }, { "input": "7 1", "output": "70" }, { "input": "8 1", "output": "40" }, { "input": "9 1", "output": "90" }, { "input": "10 1", "output": "10" }, { "input": "11 1", "output": "110" }, { "input": "12 1", "output": "60" }, { "input": "16 2", "output": "400" }, { "input": "2 2", "output": "100" }, { "input": "1 2", "output": "100" }, { "input": "5 2", "output": "100" }, { "input": "15 2", "output": "300" }, { "input": "36 2", "output": "900" }, { "input": "1 8", "output": "100000000" }, { "input": "8 8", "output": "100000000" }, { "input": "96 8", "output": "300000000" }, { "input": "175 8", "output": "700000000" }, { "input": "9999995 8", "output": "199999900000000" }, { "input": "999999999 8", "output": "99999999900000000" }, { "input": "12345678 8", "output": "617283900000000" }, { "input": "78125 8", "output": "100000000" }, { "input": "390625 8", "output": "100000000" }, { "input": "1953125 8", "output": "500000000" }, { "input": "9765625 8", "output": "2500000000" }, { "input": "68359375 8", "output": "17500000000" }, { "input": "268435456 8", "output": "104857600000000" }, { "input": "125829120 8", "output": "9830400000000" }, { "input": "128000 8", "output": "400000000" }, { "input": "300000 8", "output": "300000000" }, { "input": "3711871 8", "output": "371187100000000" }, { "input": "55555 8", "output": "1111100000000" }, { "input": "222222222 8", "output": "11111111100000000" }, { "input": "479001600 8", "output": "7484400000000" }, { "input": "655360001 7", "output": "6553600010000000" }, { "input": "655360001 8", "output": "65536000100000000" }, { "input": "1000000000 1", "output": "1000000000" }, { "input": "1000000000 7", "output": "1000000000" }, { "input": "1000000000 8", "output": "1000000000" }, { "input": "100000000 8", "output": "100000000" }, { "input": "10000000 8", "output": "100000000" }, { "input": "1000000 8", "output": "100000000" }, { "input": "10000009 8", "output": "1000000900000000" }, { "input": "10000005 8", "output": "200000100000000" }, { "input": "10000002 8", "output": "500000100000000" }, { "input": "999999997 8", "output": "99999999700000000" }, { "input": "999999997 7", "output": "9999999970000000" }, { "input": "999999995 8", "output": "19999999900000000" }, { "input": "123 8", "output": "12300000000" }, { "input": "24 2", "output": "600" }, { "input": "16 4", "output": "10000" }, { "input": "123456787 8", "output": "12345678700000000" }, { "input": "100000000 8", "output": "100000000" }, { "input": "7 1", "output": "70" }, { "input": "101 1", "output": "1010" }, { "input": "50 2", "output": "100" }, { "input": "999999818 1", "output": "4999999090" }, { "input": "2 1", "output": "10" }, { "input": "123 1", "output": "1230" }, { "input": "16 1", "output": "80" }, { "input": "1 1", "output": "10" }, { "input": "1000000000 8", "output": "1000000000" }, { "input": "15304 6", "output": "1913000000" }, { "input": "3 8", "output": "300000000" }, { "input": "4 2", "output": "100" }, { "input": "100000 7", "output": "10000000" }, { "input": "5 8", "output": "100000000" }, { "input": "16724 6", "output": "4181000000" }, { "input": "999999999 1", "output": "9999999990" }, { "input": "999999990 8", "output": "9999999900000000" }, { "input": "999999999 8", "output": "99999999900000000" }, { "input": "100000 1", "output": "100000" }, { "input": "8 3", "output": "1000" }, { "input": "16768 6", "output": "262000000" }, { "input": "123456789 1", "output": "1234567890" }, { "input": "2 8", "output": "100000000" }, { "input": "999999937 8", "output": "99999993700000000" }, { "input": "5 1", "output": "10" }, { "input": "2000000 7", "output": "10000000" }, { "input": "1999998 2", "output": "99999900" }, { "input": "125 3", "output": "1000" } ]

1,608,269,244

2,147,483,647

Python 3

OK

TESTS

96

109

307,200

n,k = map(int, input().strip().split(' ')) #lst = list(map(int, input().strip().split(' '))) s=str(n) while(True): c=0 t=0 for j in range(len(s)): if s[len(s)-j-1]=='0': c+=1 else: t=s[len(s)-j-1] break if c>=k: print(n) break else: if int(t)%2==0: n=n*5 s=str(n) elif int(t)==5: n=n*2 s=str(n) else: n=n*(10**(k-c)) print(n) break

Title: k-rounding Time Limit: None seconds Memory Limit: None megabytes Problem Description: For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*. For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375. Write a program that will perform the *k*-rounding of *n*. Input Specification: The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). Output Specification: Print the *k*-rounding of *n*. Demo Input: ['375 4\n', '10000 1\n', '38101 0\n', '123456789 8\n'] Demo Output: ['30000\n', '10000\n', '38101\n', '12345678900000000\n'] Note: none

```python n,k = map(int, input().strip().split(' ')) #lst = list(map(int, input().strip().split(' '))) s=str(n) while(True): c=0 t=0 for j in range(len(s)): if s[len(s)-j-1]=='0': c+=1 else: t=s[len(s)-j-1] break if c>=k: print(n) break else: if int(t)%2==0: n=n*5 s=str(n) elif int(t)==5: n=n*2 s=str(n) else: n=n*(10**(k-c)) print(n) break ```

3

34

A

Reconnaissance 2

PROGRAMMING

800

[ "implementation" ]

A. Reconnaissance 2

2

256

*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.

The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction.

Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.

[ "5\n10 12 13 15 10\n", "4\n10 20 30 40\n" ]

[ "5 1\n", "1 2\n" ]

none

500

[ { "input": "5\n10 12 13 15 10", "output": "5 1" }, { "input": "4\n10 20 30 40", "output": "1 2" }, { "input": "6\n744 359 230 586 944 442", "output": "2 3" }, { "input": "5\n826 747 849 687 437", "output": "1 2" }, { "input": "5\n999 999 993 969 999", "output": "1 2" }, { "input": "5\n4 24 6 1 15", "output": "3 4" }, { "input": "2\n511 32", "output": "1 2" }, { "input": "3\n907 452 355", "output": "2 3" }, { "input": "4\n303 872 764 401", "output": "4 1" }, { "input": "10\n684 698 429 694 956 812 594 170 937 764", "output": "1 2" }, { "input": "20\n646 840 437 946 640 564 936 917 487 752 844 734 468 969 674 646 728 642 514 695", "output": "7 8" }, { "input": "30\n996 999 998 984 989 1000 996 993 1000 983 992 999 999 1000 979 992 987 1000 996 1000 1000 989 981 996 995 999 999 989 999 1000", "output": "12 13" }, { "input": "50\n93 27 28 4 5 78 59 24 19 134 31 128 118 36 90 32 32 1 44 32 33 13 31 10 12 25 38 50 25 12 4 22 28 53 48 83 4 25 57 31 71 24 8 7 28 86 23 80 101 58", "output": "16 17" }, { "input": "88\n1000 1000 1000 1000 1000 998 998 1000 1000 1000 1000 999 999 1000 1000 1000 999 1000 997 999 997 1000 999 998 1000 999 1000 1000 1000 999 1000 999 999 1000 1000 999 1000 999 1000 1000 998 1000 1000 1000 998 998 1000 1000 999 1000 1000 1000 1000 1000 1000 1000 998 1000 1000 1000 999 1000 1000 999 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 998 1000 1000 1000 998 1000 1000 998 1000 999 1000 1000 1000 1000", "output": "1 2" }, { "input": "99\n4 4 21 6 5 3 13 2 6 1 3 4 1 3 1 9 11 1 6 17 4 5 20 4 1 9 5 11 3 4 14 1 3 3 1 4 3 5 27 1 1 2 10 7 11 4 19 7 11 6 11 13 3 1 10 7 2 1 16 1 9 4 29 13 2 12 14 2 21 1 9 8 26 12 12 5 2 14 7 8 8 8 9 4 12 2 6 6 7 16 8 14 2 10 20 15 3 7 4", "output": "1 2" }, { "input": "100\n713 572 318 890 577 657 646 146 373 783 392 229 455 871 20 593 573 336 26 381 280 916 907 732 820 713 111 840 570 446 184 711 481 399 788 647 492 15 40 530 549 506 719 782 126 20 778 996 712 761 9 74 812 418 488 175 103 585 900 3 604 521 109 513 145 708 990 361 682 827 791 22 596 780 596 385 450 643 158 496 876 975 319 783 654 895 891 361 397 81 682 899 347 623 809 557 435 279 513 438", "output": "86 87" }, { "input": "100\n31 75 86 68 111 27 22 22 26 30 54 163 107 75 160 122 14 23 17 26 27 20 43 58 59 71 21 148 9 32 43 91 133 286 132 70 90 156 84 14 77 93 23 18 13 72 18 131 33 28 72 175 30 86 249 20 14 208 28 57 63 199 6 10 24 30 62 267 43 479 60 28 138 1 45 3 19 47 7 166 116 117 50 140 28 14 95 85 93 43 61 15 2 70 10 51 7 95 9 25", "output": "7 8" }, { "input": "100\n896 898 967 979 973 709 961 968 806 967 896 967 826 975 936 903 986 856 851 931 852 971 786 837 949 978 686 936 952 909 965 749 908 916 943 973 983 975 939 886 964 928 960 976 907 788 994 773 949 871 947 980 945 985 726 981 887 943 907 990 931 874 840 867 948 951 961 904 888 901 976 967 994 921 828 970 972 722 755 970 860 855 914 869 714 899 969 978 898 862 642 939 904 936 819 934 884 983 955 964", "output": "1 2" }, { "input": "100\n994 927 872 970 815 986 952 996 965 1000 877 986 978 999 950 990 936 997 993 960 921 860 895 869 943 998 983 968 973 953 999 990 995 871 853 979 973 963 953 938 997 989 993 964 960 973 946 975 1000 962 920 746 989 957 904 965 920 979 966 961 1000 993 975 952 846 971 991 979 985 969 984 973 956 1000 952 778 983 974 956 927 995 997 980 997 1000 970 960 970 988 983 947 904 935 972 1000 863 992 996 932 967", "output": "81 82" }, { "input": "100\n48 108 63 21 27 8 49 21 75 8 24 42 149 18 8 28 21 18 25 35 59 70 59 33 40 1 67 34 120 82 4 115 72 87 3 15 15 63 37 12 40 27 83 14 38 20 14 58 93 10 31 3 39 6 197 77 54 16 31 146 9 49 14 8 77 82 5 11 80 116 8 61 50 24 7 103 29 11 3 3 1 12 46 24 21 131 39 29 36 2 107 40 16 99 31 41 29 48 17 17", "output": "36 37" } ]

1,621,513,399

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

2

122

0

n = int(input()) l = list(map(int,input().split())) l1 = sorted(l) d = 1000000000000 for i in range(1,len(l1)): if(l1[i]-l1[i-1]<d): d = l1[i]-l1[i-1] a = l.index(l1[i-1]) b = l.index(l1[i]) if(b==a): l2 = l l2[a]=0 b = l2.index(l1[i]) print(a+1,b+1)

Title: Reconnaissance 2 Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit. Input Specification: The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. Output Specification: Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. Demo Input: ['5\n10 12 13 15 10\n', '4\n10 20 30 40\n'] Demo Output: ['5 1\n', '1 2\n'] Note: none

```python n = int(input()) l = list(map(int,input().split())) l1 = sorted(l) d = 1000000000000 for i in range(1,len(l1)): if(l1[i]-l1[i-1]<d): d = l1[i]-l1[i-1] a = l.index(l1[i-1]) b = l.index(l1[i]) if(b==a): l2 = l l2[a]=0 b = l2.index(l1[i]) print(a+1,b+1) ```

0

513

A

Game

PROGRAMMING

800

[ "constructive algorithms", "math" ]

null

Two players play a simple game. Each player is provided with a box with balls. First player's box contains exactly *n*1 balls and second player's box contains exactly *n*2 balls. In one move first player can take from 1 to *k*1 balls from his box and throw them away. Similarly, the second player can take from 1 to *k*2 balls from his box in his move. Players alternate turns and the first player starts the game. The one who can't make a move loses. Your task is to determine who wins if both players play optimally.

The first line contains four integers *n*1,<=*n*2,<=*k*1,<=*k*2. All numbers in the input are from 1 to 50. This problem doesn't have subproblems. You will get 3 points for the correct submission.

Output "First" if the first player wins and "Second" otherwise.

[ "2 2 1 2\n", "2 1 1 1\n" ]

[ "Second\n", "First\n" ]

Consider the first sample test. Each player has a box with 2 balls. The first player draws a single ball from his box in one move and the second player can either take 1 or 2 balls from his box in one move. No matter how the first player acts, the second player can always win if he plays wisely.

3

[ { "input": "2 2 1 2", "output": "Second" }, { "input": "2 1 1 1", "output": "First" }, { "input": "5 7 4 1", "output": "Second" }, { "input": "5 7 1 4", "output": "Second" }, { "input": "5 7 10 10", "output": "Second" }, { "input": "5 7 1 10", "output": "Second" }, { "input": "1 1 1 1", "output": "Second" }, { "input": "50 50 50 50", "output": "Second" }, { "input": "50 49 1 2", "output": "First" }, { "input": "50 48 3 1", "output": "First" }, { "input": "48 50 12 11", "output": "Second" }, { "input": "49 50 11 12", "output": "Second" }, { "input": "49 49 4 1", "output": "Second" }, { "input": "49 49 3 3", "output": "Second" }, { "input": "1 50 1 50", "output": "Second" }, { "input": "1 50 50 50", "output": "Second" }, { "input": "50 1 1 1", "output": "First" }, { "input": "50 1 1 50", "output": "First" }, { "input": "32 31 10 9", "output": "First" }, { "input": "32 4 17 3", "output": "First" } ]

1,636,181,973

2,147,483,647

Python 3

OK

TESTS

20

46

4,300,800

#!/usr/bin/env python # coding=utf-8 ''' Author: Deean Date: 2021-11-06 14:54:29 LastEditTime: 2021-11-06 14:58:43 Description: Game FilePath: CF513A.py ''' def func(): n1, n2, k1, k2 = map(int, input().strip().split()) print("First" if n1 > n2 else "Second") if __name__ == '__main__': func()

Title: Game Time Limit: None seconds Memory Limit: None megabytes Problem Description: Two players play a simple game. Each player is provided with a box with balls. First player's box contains exactly *n*1 balls and second player's box contains exactly *n*2 balls. In one move first player can take from 1 to *k*1 balls from his box and throw them away. Similarly, the second player can take from 1 to *k*2 balls from his box in his move. Players alternate turns and the first player starts the game. The one who can't make a move loses. Your task is to determine who wins if both players play optimally. Input Specification: The first line contains four integers *n*1,<=*n*2,<=*k*1,<=*k*2. All numbers in the input are from 1 to 50. This problem doesn't have subproblems. You will get 3 points for the correct submission. Output Specification: Output "First" if the first player wins and "Second" otherwise. Demo Input: ['2 2 1 2\n', '2 1 1 1\n'] Demo Output: ['Second\n', 'First\n'] Note: Consider the first sample test. Each player has a box with 2 balls. The first player draws a single ball from his box in one move and the second player can either take 1 or 2 balls from his box in one move. No matter how the first player acts, the second player can always win if he plays wisely.

```python #!/usr/bin/env python # coding=utf-8 ''' Author: Deean Date: 2021-11-06 14:54:29 LastEditTime: 2021-11-06 14:58:43 Description: Game FilePath: CF513A.py ''' def func(): n1, n2, k1, k2 = map(int, input().strip().split()) print("First" if n1 > n2 else "Second") if __name__ == '__main__': func() ```

3

622

B

The Time

PROGRAMMING

900

[ "implementation" ]

null

You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes. Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement. You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedia.org/wiki/24-hour_clock).

The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes). The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes passed.

The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed). See the examples to check the input/output format.

[ "23:59\n10\n", "20:20\n121\n", "10:10\n0\n" ]

[ "00:09\n", "22:21\n", "10:10\n" ]

none

0

[ { "input": "23:59\n10", "output": "00:09" }, { "input": "20:20\n121", "output": "22:21" }, { "input": "10:10\n0", "output": "10:10" }, { "input": "12:34\n10000", "output": "11:14" }, { "input": "00:00\n10000", "output": "22:40" }, { "input": "00:00\n1440", "output": "00:00" }, { "input": "23:59\n8640", "output": "23:59" }, { "input": "10:01\n0", "output": "10:01" }, { "input": "04:05\n0", "output": "04:05" }, { "input": "02:59\n1", "output": "03:00" }, { "input": "05:15\n10", "output": "05:25" }, { "input": "03:10\n20", "output": "03:30" }, { "input": "09:11\n0", "output": "09:11" }, { "input": "19:00\n0", "output": "19:00" }, { "input": "23:59\n1", "output": "00:00" }, { "input": "11:59\n1", "output": "12:00" }, { "input": "19:34\n566", "output": "05:00" }, { "input": "00:01\n59", "output": "01:00" }, { "input": "03:30\n0", "output": "03:30" }, { "input": "22:30\n30", "output": "23:00" }, { "input": "22:50\n70", "output": "00:00" }, { "input": "05:12\n0", "output": "05:12" }, { "input": "09:20\n40", "output": "10:00" }, { "input": "15:04\n36", "output": "15:40" }, { "input": "05:37\n23", "output": "06:00" }, { "input": "23:59\n59", "output": "00:58" }, { "input": "21:09\n9997", "output": "19:46" }, { "input": "11:00\n1", "output": "11:01" }, { "input": "20:01\n2699", "output": "17:00" }, { "input": "01:00\n59", "output": "01:59" }, { "input": "07:09\n6538", "output": "20:07" }, { "input": "00:00\n10", "output": "00:10" }, { "input": "02:09\n2074", "output": "12:43" }, { "input": "01:10\n1", "output": "01:11" }, { "input": "23:01\n59", "output": "00:00" }, { "input": "08:50\n20", "output": "09:10" }, { "input": "13:18\n5121", "output": "02:39" }, { "input": "18:31\n2677", "output": "15:08" }, { "input": "14:17\n108", "output": "16:05" }, { "input": "02:45\n5617", "output": "00:22" }, { "input": "00:00\n3600", "output": "12:00" }, { "input": "19:01\n59", "output": "20:00" }, { "input": "19:02\n59", "output": "20:01" }, { "input": "14:00\n2880", "output": "14:00" }, { "input": "01:10\n44", "output": "01:54" }, { "input": "02:01\n59", "output": "03:00" }, { "input": "07:02\n121", "output": "09:03" }, { "input": "10:00\n61", "output": "11:01" }, { "input": "23:59\n61", "output": "01:00" }, { "input": "00:00\n0", "output": "00:00" }, { "input": "23:59\n121", "output": "02:00" }, { "input": "00:00\n60", "output": "01:00" }, { "input": "15:52\n60", "output": "16:52" }, { "input": "00:39\n6525", "output": "13:24" }, { "input": "00:30\n30", "output": "01:00" }, { "input": "00:59\n1", "output": "01:00" }, { "input": "00:55\n4321", "output": "00:56" }, { "input": "10:05\n1", "output": "10:06" }, { "input": "23:00\n60", "output": "00:00" } ]

1,622,068,389

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

3

92

0

import math def solve(): arr=list(map(int,input().split(":"))) H,M=arr[0],arr[1] passed=int(input()) hour=passed//60 mins=passed%60 if mins+M<60: M+=mins else : M+=mins M-=60 hour+=1 if hour+H<24: H+=hour else: H+=hour H-=24 H=str(H) M=str(M) if len(H)==1: H="0"+H if len(M)==1: M="0"+M print(H+":"+M) solve()

Title: The Time Time Limit: None seconds Memory Limit: None megabytes Problem Description: You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes. Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement. You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedia.org/wiki/24-hour_clock). Input Specification: The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes). The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes passed. Output Specification: The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed). See the examples to check the input/output format. Demo Input: ['23:59\n10\n', '20:20\n121\n', '10:10\n0\n'] Demo Output: ['00:09\n', '22:21\n', '10:10\n'] Note: none

```python import math def solve(): arr=list(map(int,input().split(":"))) H,M=arr[0],arr[1] passed=int(input()) hour=passed//60 mins=passed%60 if mins+M<60: M+=mins else : M+=mins M-=60 hour+=1 if hour+H<24: H+=hour else: H+=hour H-=24 H=str(H) M=str(M) if len(H)==1: H="0"+H if len(M)==1: M="0"+M print(H+":"+M) solve() ```

0

870

B

Maximum of Maximums of Minimums

PROGRAMMING

1,200

[ "greedy" ]

null

You are given an array *a*1,<=*a*2,<=...,<=*a**n* consisting of *n* integers, and an integer *k*. You have to split the array into exactly *k* non-empty subsegments. You'll then compute the minimum integer on each subsegment, and take the maximum integer over the *k* obtained minimums. What is the maximum possible integer you can get? Definitions of subsegment and array splitting are given in notes.

The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=<=105) — the size of the array *a* and the number of subsegments you have to split the array to. The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (<=-<=109<=<=≤<=<=*a**i*<=≤<=<=109).

Print single integer — the maximum possible integer you can get if you split the array into *k* non-empty subsegments and take maximum of minimums on the subsegments.

[ "5 2\n1 2 3 4 5\n", "5 1\n-4 -5 -3 -2 -1\n" ]

[ "5\n", "-5\n" ]

A subsegment [*l*, *r*] (*l* ≤ *r*) of array *a* is the sequence *a**l*, *a**l* + 1, ..., *a**r*. Splitting of array *a* of *n* elements into *k* subsegments [*l*1, *r*1], [*l*2, *r*2], ..., [*l**k*, *r**k*] (*l*1 = 1, *r**k* = *n*, *l**i* = *r**i* - 1 + 1 for all *i* > 1) is *k* sequences (*a**l*1, ..., *a**r*1), ..., (*a**l**k*, ..., *a**r**k*). In the first example you should split the array into subsegments [1, 4] and [5, 5] that results in sequences (1, 2, 3, 4) and (5). The minimums are *min*(1, 2, 3, 4) = 1 and *min*(5) = 5. The resulting maximum is *max*(1, 5) = 5. It is obvious that you can't reach greater result. In the second example the only option you have is to split the array into one subsegment [1, 5], that results in one sequence ( - 4, - 5, - 3, - 2, - 1). The only minimum is *min*( - 4, - 5, - 3, - 2, - 1) = - 5. The resulting maximum is - 5.

1,000

[ { "input": "5 2\n1 2 3 4 5", "output": "5" }, { "input": "5 1\n-4 -5 -3 -2 -1", "output": "-5" }, { "input": "10 2\n10 9 1 -9 -7 -9 3 8 -10 5", "output": "10" }, { "input": "10 4\n-8 -1 2 -3 9 -8 4 -3 5 9", "output": "9" }, { "input": "1 1\n504262064", "output": "504262064" }, { "input": "3 3\n-54481850 -878017339 -486296116", "output": "-54481850" }, { "input": "2 2\n-333653905 224013643", "output": "224013643" }, { "input": "14 2\n-14 84 44 46 -75 -75 77 -49 44 -82 -74 -51 -9 -50", "output": "-14" }, { "input": "88 71\n-497 -488 182 104 40 183 201 282 -384 44 -29 494 224 -80 -491 -197 157 130 -52 233 -426 252 -61 -51 203 -50 195 -442 -38 385 232 -243 -49 163 340 -200 406 -254 -29 227 -194 193 487 -325 230 146 421 158 20 447 -97 479 493 -130 164 -471 -198 -330 -152 359 -554 319 544 -444 235 281 -467 337 -385 227 -366 -210 266 69 -261 525 526 -234 -355 177 109 275 -301 7 -41 553 -284 540", "output": "553" }, { "input": "39 1\n676941771 -923780377 -163050076 -230110947 -208029500 329620771 13954060 158950156 -252501602 926390671 -678745080 -921892226 -100127643 610420285 602175224 -839193819 471391946 910035173 777969600 -736144413 -489685522 60986249 830784148 278642552 -375298304 197973611 -354482364 187294011 636628282 25350767 636184407 -550869740 53830680 -42049274 -451383278 900048257 93225803 877923341 -279506435", "output": "-923780377" }, { "input": "3 2\n1 5 3", "output": "3" }, { "input": "5 2\n1 2 5 4 3", "output": "3" }, { "input": "3 2\n1 3 2", "output": "2" }, { "input": "3 2\n1 3 1", "output": "1" }, { "input": "5 3\n-2 -2 -2 -2 -2", "output": "-2" }, { "input": "5 2\n1 2 3 5 4", "output": "4" }, { "input": "5 2\n1 1 11 1 1", "output": "1" }, { "input": "3 3\n3 8 4", "output": "8" }, { "input": "6 3\n4 3 1 5 6 2", "output": "6" }, { "input": "2 1\n1 2", "output": "1" }, { "input": "5 2\n2 5 4 3 1", "output": "2" }, { "input": "5 2\n-1 1 5 4 3", "output": "3" }, { "input": "5 2\n5 2 1 9 3", "output": "5" }, { "input": "2 1\n1000000000 1000000000", "output": "1000000000" }, { "input": "1 1\n1000000000", "output": "1000000000" }, { "input": "5 2\n1 5 3 4 1", "output": "1" }, { "input": "3 2\n-1000000000 -1000000000 -1000000000", "output": "-1000000000" }, { "input": "2 2\n5 2", "output": "5" }, { "input": "7 3\n1 1 1 10 1 1 1", "output": "10" }, { "input": "9 3\n1 2 1 1 5 1 1 1 2", "output": "5" }, { "input": "9 3\n2 2 2 2 9 2 2 2 2", "output": "9" }, { "input": "3 3\n-1000000000 -1000000000 -1000000000", "output": "-1000000000" } ]

1,567,916,151

2,147,483,647

PyPy 3

OK

TESTS

55

233

11,571,200

l = list(map(int, input().split())) m = list(map(int, input().split())) if l[1] == 1: print(min(m)) elif l[1] == 2: print(max(m[0], m[-1])) else: print(max(m))

Title: Maximum of Maximums of Minimums Time Limit: None seconds Memory Limit: None megabytes Problem Description: You are given an array *a*1,<=*a*2,<=...,<=*a**n* consisting of *n* integers, and an integer *k*. You have to split the array into exactly *k* non-empty subsegments. You'll then compute the minimum integer on each subsegment, and take the maximum integer over the *k* obtained minimums. What is the maximum possible integer you can get? Definitions of subsegment and array splitting are given in notes. Input Specification: The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=<=105) — the size of the array *a* and the number of subsegments you have to split the array to. The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (<=-<=109<=<=≤<=<=*a**i*<=≤<=<=109). Output Specification: Print single integer — the maximum possible integer you can get if you split the array into *k* non-empty subsegments and take maximum of minimums on the subsegments. Demo Input: ['5 2\n1 2 3 4 5\n', '5 1\n-4 -5 -3 -2 -1\n'] Demo Output: ['5\n', '-5\n'] Note: A subsegment [*l*, *r*] (*l* ≤ *r*) of array *a* is the sequence *a**l*, *a**l* + 1, ..., *a**r*. Splitting of array *a* of *n* elements into *k* subsegments [*l*1, *r*1], [*l*2, *r*2], ..., [*l**k*, *r**k*] (*l*1 = 1, *r**k* = *n*, *l**i* = *r**i* - 1 + 1 for all *i* > 1) is *k* sequences (*a**l*1, ..., *a**r*1), ..., (*a**l**k*, ..., *a**r**k*). In the first example you should split the array into subsegments [1, 4] and [5, 5] that results in sequences (1, 2, 3, 4) and (5). The minimums are *min*(1, 2, 3, 4) = 1 and *min*(5) = 5. The resulting maximum is *max*(1, 5) = 5. It is obvious that you can't reach greater result. In the second example the only option you have is to split the array into one subsegment [1, 5], that results in one sequence ( - 4, - 5, - 3, - 2, - 1). The only minimum is *min*( - 4, - 5, - 3, - 2, - 1) = - 5. The resulting maximum is - 5.

```python l = list(map(int, input().split())) m = list(map(int, input().split())) if l[1] == 1: print(min(m)) elif l[1] == 2: print(max(m[0], m[-1])) else: print(max(m)) ```

3

690

F1

Tree of Life (easy)

PROGRAMMING

1,300

[]

null

Heidi has finally found the mythical Tree of Life – a legendary combinatorial structure which is said to contain a prophecy crucially needed to defeat the undead armies. On the surface, the Tree of Life is just a regular undirected tree well-known from computer science. This means that it is a collection of *n* points (called vertices), some of which are connected using *n*<=-<=1 line segments (edges) so that each pair of vertices is connected by a path (a sequence of one or more edges). To decipher the prophecy, Heidi needs to perform a number of steps. The first is counting the number of lifelines in the tree – these are paths of length 2, i.e., consisting of two edges. Help her!

The first line of the input contains a single integer *n* – the number of vertices in the tree (1<=≤<=*n*<=≤<=10000). The vertices are labeled with the numbers from 1 to *n*. Then *n*<=-<=1 lines follow, each describing one edge using two space-separated numbers *a* *b* – the labels of the vertices connected by the edge (1<=≤<=*a*<=<<=*b*<=≤<=*n*). It is guaranteed that the input represents a tree.

Print one integer – the number of lifelines in the tree.

[ "4\n1 2\n1 3\n1 4\n", "5\n1 2\n2 3\n3 4\n3 5\n" ]

[ "3", "4" ]

In the second sample, there are four lifelines: paths between vertices 1 and 3, 2 and 4, 2 and 5, and 4 and 5.

0

[ { "input": "4\n1 2\n1 3\n1 4", "output": "3" }, { "input": "5\n1 2\n2 3\n3 4\n3 5", "output": "4" }, { "input": "2\n1 2", "output": "0" }, { "input": "3\n2 1\n3 2", "output": "1" }, { "input": "10\n5 1\n1 2\n9 3\n10 5\n6 3\n8 5\n2 7\n2 3\n9 4", "output": "11" } ]

1,578,431,062

2,147,483,647

Python 3

OK

TESTS

19

124

102,400

n = int(input()) d = [0] * (n + 1) for _ in range(n - 1): x, y = map(int, input().split()) d[x] += 1 d[y] += 1 s = 0 for x in range(1, n + 1): s += d[x] * (d[x] - 1) print(s // 2)

Title: Tree of Life (easy) Time Limit: None seconds Memory Limit: None megabytes Problem Description: Heidi has finally found the mythical Tree of Life – a legendary combinatorial structure which is said to contain a prophecy crucially needed to defeat the undead armies. On the surface, the Tree of Life is just a regular undirected tree well-known from computer science. This means that it is a collection of *n* points (called vertices), some of which are connected using *n*<=-<=1 line segments (edges) so that each pair of vertices is connected by a path (a sequence of one or more edges). To decipher the prophecy, Heidi needs to perform a number of steps. The first is counting the number of lifelines in the tree – these are paths of length 2, i.e., consisting of two edges. Help her! Input Specification: The first line of the input contains a single integer *n* – the number of vertices in the tree (1<=≤<=*n*<=≤<=10000). The vertices are labeled with the numbers from 1 to *n*. Then *n*<=-<=1 lines follow, each describing one edge using two space-separated numbers *a* *b* – the labels of the vertices connected by the edge (1<=≤<=*a*<=<<=*b*<=≤<=*n*). It is guaranteed that the input represents a tree. Output Specification: Print one integer – the number of lifelines in the tree. Demo Input: ['4\n1 2\n1 3\n1 4\n', '5\n1 2\n2 3\n3 4\n3 5\n'] Demo Output: ['3', '4'] Note: In the second sample, there are four lifelines: paths between vertices 1 and 3, 2 and 4, 2 and 5, and 4 and 5.

```python n = int(input()) d = [0] * (n + 1) for _ in range(n - 1): x, y = map(int, input().split()) d[x] += 1 d[y] += 1 s = 0 for x in range(1, n + 1): s += d[x] * (d[x] - 1) print(s // 2) ```

3

669

A

Little Artem and Presents

PROGRAMMING

800

[ "math" ]

null

Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Artem can't give her the same number of stones twice in a row. For example, he can give her 3 stones, then 1 stone, then again 3 stones, but he can't give her 3 stones and then again 3 stones right after that. How many times can Artem give presents to Masha?

The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday.

Print the maximum possible number of times Artem can give presents to Masha.

[ "1\n", "2\n", "3\n", "4\n" ]

[ "1\n", "1\n", "2\n", "3\n" ]

In the first sample, Artem can only give 1 stone to Masha. In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times. In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone. In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and finally 1 stone again.

500

[ { "input": "1", "output": "1" }, { "input": "2", "output": "1" }, { "input": "3", "output": "2" }, { "input": "4", "output": "3" }, { "input": "100", "output": "67" }, { "input": "101", "output": "67" }, { "input": "102", "output": "68" }, { "input": "1000000000", "output": "666666667" }, { "input": "5", "output": "3" }, { "input": "6", "output": "4" }, { "input": "999999999", "output": "666666666" }, { "input": "999999998", "output": "666666665" }, { "input": "999999997", "output": "666666665" }, { "input": "999999996", "output": "666666664" }, { "input": "999999995", "output": "666666663" }, { "input": "999999994", "output": "666666663" }, { "input": "999999993", "output": "666666662" }, { "input": "999999992", "output": "666666661" }, { "input": "999999991", "output": "666666661" }, { "input": "1000", "output": "667" }, { "input": "10000", "output": "6667" }, { "input": "100000", "output": "66667" }, { "input": "1000000", "output": "666667" }, { "input": "10000000", "output": "6666667" }, { "input": "100000000", "output": "66666667" }, { "input": "7", "output": "5" } ]

1,462,114,706

2,147,483,647

Python 3

OK

TESTS

26

62

4,915,200

n = int(input()) print(n//3*2+(n%3>0))

Title: Little Artem and Presents Time Limit: None seconds Memory Limit: None megabytes Problem Description: Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Artem can't give her the same number of stones twice in a row. For example, he can give her 3 stones, then 1 stone, then again 3 stones, but he can't give her 3 stones and then again 3 stones right after that. How many times can Artem give presents to Masha? Input Specification: The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. Output Specification: Print the maximum possible number of times Artem can give presents to Masha. Demo Input: ['1\n', '2\n', '3\n', '4\n'] Demo Output: ['1\n', '1\n', '2\n', '3\n'] Note: In the first sample, Artem can only give 1 stone to Masha. In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times. In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone. In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and finally 1 stone again.

```python n = int(input()) print(n//3*2+(n%3>0)) ```

3

749

C

Voting

PROGRAMMING

1,500

[ "greedy", "implementation", "two pointers" ]

null

There are *n* employees in Alternative Cake Manufacturing (ACM). They are now voting on some very important question and the leading world media are trying to predict the outcome of the vote. Each of the employees belongs to one of two fractions: depublicans or remocrats, and these two fractions have opposite opinions on what should be the outcome of the vote. The voting procedure is rather complicated: 1. Each of *n* employees makes a statement. They make statements one by one starting from employees 1 and finishing with employee *n*. If at the moment when it's time for the *i*-th employee to make a statement he no longer has the right to vote, he just skips his turn (and no longer takes part in this voting). 1. When employee makes a statement, he can do nothing or declare that one of the other employees no longer has a right to vote. It's allowed to deny from voting people who already made the statement or people who are only waiting to do so. If someone is denied from voting he no longer participates in the voting till the very end. 1. When all employees are done with their statements, the procedure repeats: again, each employees starting from 1 and finishing with *n* who are still eligible to vote make their statements. 1. The process repeats until there is only one employee eligible to vote remaining and he determines the outcome of the whole voting. Of course, he votes for the decision suitable for his fraction. You know the order employees are going to vote and that they behave optimal (and they also know the order and who belongs to which fraction). Predict the outcome of the vote.

The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of employees. The next line contains *n* characters. The *i*-th character is 'D' if the *i*-th employee is from depublicans fraction or 'R' if he is from remocrats.

Print 'D' if the outcome of the vote will be suitable for depublicans and 'R' if remocrats will win.

[ "5\nDDRRR\n", "6\nDDRRRR\n" ]

[ "D\n", "R\n" ]

Consider one of the voting scenarios for the first sample: 1. Employee 1 denies employee 5 to vote. 1. Employee 2 denies employee 3 to vote. 1. Employee 3 has no right to vote and skips his turn (he was denied by employee 2). 1. Employee 4 denies employee 2 to vote. 1. Employee 5 has no right to vote and skips his turn (he was denied by employee 1). 1. Employee 1 denies employee 4. 1. Only employee 1 now has the right to vote so the voting ends with the victory of depublicans.

1,500

[ { "input": "5\nDDRRR", "output": "D" }, { "input": "6\nDDRRRR", "output": "R" }, { "input": "1\nD", "output": "D" }, { "input": "1\nR", "output": "R" }, { "input": "2\nDR", "output": "D" }, { "input": "3\nRDD", "output": "D" }, { "input": "3\nDRD", "output": "D" }, { "input": "4\nDRRD", "output": "D" }, { "input": "4\nDRRR", "output": "R" }, { "input": "4\nRDRD", "output": "R" }, { "input": "5\nDRDRR", "output": "D" }, { "input": "4\nRRRR", "output": "R" }, { "input": "5\nRDDRD", "output": "D" }, { "input": "5\nDDRRD", "output": "D" }, { "input": "5\nDRRRD", "output": "R" }, { "input": "5\nDDDDD", "output": "D" }, { "input": "6\nDRRDDR", "output": "D" }, { "input": "7\nRDRDRDD", "output": "R" }, { "input": "7\nRDRDDRD", "output": "D" }, { "input": "7\nRRRDDDD", "output": "R" }, { "input": "8\nRRRDDDDD", "output": "D" }, { "input": "9\nRRRDDDDDR", "output": "R" }, { "input": "9\nRRDDDRRDD", "output": "R" }, { "input": "9\nRRDDDRDRD", "output": "D" }, { "input": "10\nDDRRRDRRDD", "output": "D" }, { "input": "11\nDRDRRDDRDDR", "output": "D" }, { "input": "12\nDRDRDRDRRDRD", "output": "D" }, { "input": "13\nDRDDDDRRRRDDR", "output": "D" }, { "input": "14\nDDRDRRDRDRDDDD", "output": "D" }, { "input": "15\nDDRRRDDRDRRRDRD", "output": "D" }, { "input": "50\nDDDRDRDDDDRRRRDDDDRRRDRRRDDDRRRRDRDDDRRDRRDDDRDDDD", "output": "D" }, { "input": "50\nDRDDDDDDDRDRDDRRRDRDRDRDDDRRDRRDRDRRDDDRDDRDRDRDDR", "output": "D" }, { "input": "100\nRDRRDRDDDDRDRRDDRDRRDDRRDDRRRDRRRDDDRDDRDDRRDRDRRRDRDRRRDRRDDDRDDRRRDRDRRRDDRDRDDDDDDDRDRRDDDDDDRRDD", "output": "D" }, { "input": "100\nRRDRRDDDDDDDRDRRRDRDRDDDRDDDRDDRDRRDRRRDRRDRRRRRRRDRRRRRRDDDRRDDRRRDRRRDDRRDRRDDDDDRRDRDDRDDRRRDRRDD", "output": "R" }, { "input": "6\nRDDRDR", "output": "D" }, { "input": "6\nDRRDRD", "output": "R" }, { "input": "8\nDDDRRRRR", "output": "R" }, { "input": "7\nRRRDDDD", "output": "R" }, { "input": "7\nRDDRRDD", "output": "D" }, { "input": "9\nRDDDRRDRR", "output": "R" }, { "input": "5\nRDRDD", "output": "R" }, { "input": "5\nRRDDD", "output": "R" }, { "input": "8\nRDDRDRRD", "output": "R" }, { "input": "10\nDRRRDDRDRD", "output": "R" }, { "input": "7\nDRRDDRR", "output": "R" }, { "input": "12\nRDDDRRDRRDDR", "output": "D" }, { "input": "7\nRDRDDDR", "output": "D" }, { "input": "7\nDDRRRDR", "output": "R" }, { "input": "10\nDRRDRDRDRD", "output": "R" }, { "input": "21\nDDDDRRRRRDRDRDRDRDRDR", "output": "R" }, { "input": "11\nRDDDDDRRRRR", "output": "D" }, { "input": "10\nRDDDRRRDDR", "output": "D" }, { "input": "4\nRDDR", "output": "R" }, { "input": "7\nRDRDDRD", "output": "D" }, { "input": "8\nRDDDRRRD", "output": "R" }, { "input": "16\nDRRDRDRDRDDRDRDR", "output": "R" }, { "input": "8\nDRRDRDRD", "output": "R" }, { "input": "6\nRDDDRR", "output": "D" }, { "input": "10\nDDRRRRRDDD", "output": "D" }, { "input": "7\nDDRRRRD", "output": "R" }, { "input": "12\nRDDRDRDRRDRD", "output": "D" }, { "input": "9\nDDRRRDRDR", "output": "R" }, { "input": "20\nRDDRDRDRDRRDRDRDRDDR", "output": "D" }, { "input": "7\nRRDDDRD", "output": "D" }, { "input": "12\nDRRRRRRDDDDD", "output": "R" }, { "input": "12\nRDRDDRDRDRDR", "output": "D" }, { "input": "6\nDDDDDD", "output": "D" }, { "input": "10\nRRRDDRDDDD", "output": "R" }, { "input": "40\nRDDDRDDDRDRRDRDRRRRRDRDRDRDRRDRDRDRRDDDD", "output": "R" }, { "input": "50\nRRDDDRRDRRRDDRDDDDDRDDRRRRRRDRDDRDDDRDRRDDRDDDRDRD", "output": "D" }, { "input": "5\nRDRDR", "output": "R" }, { "input": "9\nDRRDRDDRR", "output": "R" }, { "input": "6\nDRRRDD", "output": "R" }, { "input": "10\nDDDDRRRRRR", "output": "D" }, { "input": "9\nRRDDDDRRD", "output": "D" } ]

1,633,630,364

2,147,483,647

Python 3

OK

TESTS

144

171

11,673,600

import sys import math from bisect import bisect_right as br from collections import deque #from statistics import mode from itertools import combinations as cb def int_arr(): return list(map(int, sys.stdin.readline().strip().split())) def str_arr(): return list(map(str, sys.stdin.readline().strip().split())) def input(): return sys.stdin.readline().strip() #sys.stdout =open('Voting/output.txt', 'w') #sys.stdin = open('Voting/input.txt', 'r') n=int(input()) st=input() d=deque() r=deque() for i in range(n): if st[i]=="D": d.append(i) else: r.append(i) while d and r: dl=d.popleft() rl=r.popleft() if dl<rl: d.append(dl+n) else: r.append(rl+n) if d: print("D") else: print("R")

Title: Voting Time Limit: None seconds Memory Limit: None megabytes Problem Description: There are *n* employees in Alternative Cake Manufacturing (ACM). They are now voting on some very important question and the leading world media are trying to predict the outcome of the vote. Each of the employees belongs to one of two fractions: depublicans or remocrats, and these two fractions have opposite opinions on what should be the outcome of the vote. The voting procedure is rather complicated: 1. Each of *n* employees makes a statement. They make statements one by one starting from employees 1 and finishing with employee *n*. If at the moment when it's time for the *i*-th employee to make a statement he no longer has the right to vote, he just skips his turn (and no longer takes part in this voting). 1. When employee makes a statement, he can do nothing or declare that one of the other employees no longer has a right to vote. It's allowed to deny from voting people who already made the statement or people who are only waiting to do so. If someone is denied from voting he no longer participates in the voting till the very end. 1. When all employees are done with their statements, the procedure repeats: again, each employees starting from 1 and finishing with *n* who are still eligible to vote make their statements. 1. The process repeats until there is only one employee eligible to vote remaining and he determines the outcome of the whole voting. Of course, he votes for the decision suitable for his fraction. You know the order employees are going to vote and that they behave optimal (and they also know the order and who belongs to which fraction). Predict the outcome of the vote. Input Specification: The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of employees. The next line contains *n* characters. The *i*-th character is 'D' if the *i*-th employee is from depublicans fraction or 'R' if he is from remocrats. Output Specification: Print 'D' if the outcome of the vote will be suitable for depublicans and 'R' if remocrats will win. Demo Input: ['5\nDDRRR\n', '6\nDDRRRR\n'] Demo Output: ['D\n', 'R\n'] Note: Consider one of the voting scenarios for the first sample: 1. Employee 1 denies employee 5 to vote. 1. Employee 2 denies employee 3 to vote. 1. Employee 3 has no right to vote and skips his turn (he was denied by employee 2). 1. Employee 4 denies employee 2 to vote. 1. Employee 5 has no right to vote and skips his turn (he was denied by employee 1). 1. Employee 1 denies employee 4. 1. Only employee 1 now has the right to vote so the voting ends with the victory of depublicans.

```python import sys import math from bisect import bisect_right as br from collections import deque #from statistics import mode from itertools import combinations as cb def int_arr(): return list(map(int, sys.stdin.readline().strip().split())) def str_arr(): return list(map(str, sys.stdin.readline().strip().split())) def input(): return sys.stdin.readline().strip() #sys.stdout =open('Voting/output.txt', 'w') #sys.stdin = open('Voting/input.txt', 'r') n=int(input()) st=input() d=deque() r=deque() for i in range(n): if st[i]=="D": d.append(i) else: r.append(i) while d and r: dl=d.popleft() rl=r.popleft() if dl<rl: d.append(dl+n) else: r.append(rl+n) if d: print("D") else: print("R") ```

3

802

G

Fake News (easy)

PROGRAMMING

800

[ "implementation", "strings" ]

null

As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...

The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z).

Output YES if the string *s* contains heidi as a subsequence and NO otherwise.

[ "abcheaibcdi\n", "hiedi\n" ]

[ "YES", "NO" ]

A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*.

0

[ { "input": "abcheaibcdi", "output": "YES" }, { "input": "hiedi", "output": "NO" }, { "input": "ihied", "output": "NO" }, { "input": "diehi", "output": "NO" }, { "input": "deiih", "output": "NO" }, { "input": "iheid", "output": "NO" }, { "input": "eihdi", "output": "NO" }, { "input": "ehdii", "output": "NO" }, { "input": "edhii", "output": "NO" }, { "input": "deiih", "output": "NO" }, { "input": "ehdii", "output": "NO" }, { "input": "eufyajkssayhjhqcwxmctecaeepjwmfoscqprpcxsqfwnlgzsmmuwuoruantipholrauvxydfvftwfzhnckxswussvlidcojiciflpvkcxkkcmmvtfvxrkwcpeelwsuzqgamamdtdgzscmikvojfvqehblmjczkvtdeymgertgkwfwfukafqlfdhtedcctixhyetdypswgagrpyto", "output": "YES" }, { "input": "arfbvxgdvqzuloojjrwoyqqbxamxybaqltfimofulusfebodjkwwrgwcppkwiodtpjaraglyplgerrpqjkpoggjmfxhwtqrijpijrcyxnoodvwpyjfpvqaoazllbrpzananbrvvybboedidtuvqquklkpeflfaltukjhzjgiofombhbmqbihgtapswykfvlgdoapjqntvqsaohmbvnphvyyhvhavslamczuqifxnwknkaenqmlvetrqogqxmlptgrmqvxzdxdmwobjesmgxckpmawtioavwdngyiwkzypfnxcovwzdohshwlavwsthdssiadhiwmhpvgkrbezm", "output": "YES" }, { "input": "zcectngbqnejjjtsfrluummmqabzqbyccshjqbrjthzhlbmzjfxugvjouwhumsgrnopiyakfadjnbsesamhynsbfbfunupwbxvohfmpwlcpxhovwpfpciclatgmiufwdvtsqrsdcymvkldpnhfeisrzhyhhlkwdzthgprvkpyldeysvbmcibqkpudyrraqdlxpjecvwcvuiklcrsbgvqasmxmtxqzmawcjtozioqlfflinnxpeexbzloaeqjvglbdeufultpjqexvjjjkzemtzuzmxvawilcqdrcjzpqyhtwfphuonzwkotthsaxrmwtnlmcdylxqcfffyndqeouztluqwlhnkkvzwcfiscikv", "output": "YES" }, { "input": "plqaykgovxkvsiahdbglktdlhcqwelxxmtlyymrsyubxdskvyjkrowvcbpdofpjqspsrgpakdczletxujzlsegepzleipiyycpinzxgwjsgslnxsotouddgfcybozfpjhhocpybfjbaywsehbcfrayvancbrumdfngqytnhihyxnlvilrqyhnxeckprqafofelospffhtwguzjbbjlzbqrtiielbvzutzgpqxosiaqznndgobcluuqlhmffiowkjdlkokehtjdyjvmxsiyxureflmdomerfekxdvtitvwzmdsdzplkpbtafxqfpudnhfqpoiwvjnylanunmagoweobdvfjgepbsymfutrjarlxclhgavpytiiqwvojrptofuvlohzeguxdsrihsbucelhhuedltnnjgzxwyblbqvnoliiydfinzlogbvucwykryzcyibnniggbkdkdcdgcsbvvnavtyhtkanrblpvomvjs", "output": "YES" }, { "input": "fbldqzggeunkpwcfirxanmntbfrudijltoertsdvcvcmbwodbibsrxendzebvxwydpasaqnisrijctsuatihxxygbeovhxjdptdcppkvfytdpjspvrannxavmkmisqtygntxkdlousdypyfkrpzapysfpdbyprufwzhunlsfugojddkmxzinatiwfxdqmgyrnjnxvrclhxyuwxtshoqdjptmeecvgmrlvuwqtmnfnfeeiwcavwnqmyustawbjodzwsqmnjxhpqmgpysierlwbbdzcwprpsexyvreewcmlbvaiytjlxdqdaqftefdlmtmmjcwvfejshymhnouoshdzqcwzxpzupkbcievodzqkqvyjuuxxwepxjalvkzufnveji", "output": "YES" }, { "input": "htsyljgoelbbuipivuzrhmfpkgderqpoprlxdpasxhpmxvaztccldtmujjzjmcpdvsdghzpretlsyyiljhjznseaacruriufswuvizwwuvdioazophhyytvbiogttnnouauxllbdn", "output": "YES" }, { "input": "ikmxzqdzxqlvgeojsnhqzciujslwjyzzexnregabdqztpplosdakimjxmuqccbnwvzbajoiqgdobccwnrwmixohrbdarhoeeelzbpigiybtesybwefpcfx", "output": "YES" }, { "input": "bpvbpjvbdfiodsmahxpcubjxdykesubnypalhypantshkjffmxjmelblqnjdmtaltneuyudyevkgedkqrdmrfeemgpghwrifcwincfixokfgurhqbcfzeajrgkgpwqwsepudxulywowwxzdxkumsicsvnzfxspmjpaixgejeaoyoibegosqoyoydmphfpbutrrewyjecowjckvpcceoamtfbitdneuwqfvnagswlskmsmkhmxyfsrpqwhxzocyffiumcy", "output": "YES" }, { "input": "vllsexwrazvlfvhvrtqeohvzzresjdiuhomfpgqcxpqdevplecuaepixhlijatxzegciizpvyvxuembiplwklahlqibykfideysjygagjbgqkbhdhkatddcwlxboinfuomnpc", "output": "YES" }, { "input": "pnjdwpxmvfoqkjtbhquqcuredrkwqzzfjmdvpnbqtypzdovemhhclkvigjvtprrpzbrbcbatkucaqteuciuozytsptvsskkeplaxdaqmjkmef", "output": "NO" }, { "input": "jpwfhvlxvsdhtuozvlmnfiotrgapgjxtcsgcjnodcztupysvvvmjpzqkpommadppdrykuqkcpzojcwvlogvkddedwbggkrhuvtsvdiokehlkdlnukcufjvqxnikcdawvexxwffxtriqbdmkahxdtygodzohwtdmmuvmatdkvweqvaehaxiefpevkvqpyxsrhtmgjsdfcwzqobibeduooldrmglbinrepmunizheqzvgqvpdskhxfidxfnbisyizhepwyrcykcmjxnkyfjgrqlkixcvysa", "output": "YES" }, { "input": "aftcrvuumeqbfvaqlltscnuhkpcifrrhnutjinxdhhdbzvizlrapzjdatuaynoplgjketupgaejciosofuhcgcjdcucarfvtsofgubtphijciswsvidnvpztlaarydkeqxzwdhfbmullkimerukusbrdnnujviydldrwhdfllsjtziwfeaiqotbiprespmxjulnyunkdtcghrzvhtcychkwatqqmladxpvmvlkzscthylbzkpgwlzfjqwarqvdeyngekqvrhrftpxnkfcibbowvnqdkulcdydspcubwlgoyinpnzgidbgunparnueddzwtzdiavbprbbg", "output": "YES" }, { "input": "oagjghsidigeh", "output": "NO" }, { "input": "chdhzpfzabupskiusjoefrwmjmqkbmdgboicnszkhdrlegeqjsldurmbshijadlwsycselhlnudndpdhcnhruhhvsgbthpruiqfirxkhpqhzhqdfpyozolbionodypfcqfeqbkcgmqkizgeyyelzeoothexcoaahedgrvoemqcwccbvoeqawqeuusyjxmgjkpfwcdttfmwunzuwvsihliexlzygqcgpbdiawfvqukikhbjerjkyhpcknlndaystrgsinghlmekbvhntcpypmchcwoglsmwwdulqneuabuuuvtyrnjxfcgoothalwkzzfxakneusezgnnepkpipzromqubraiggqndliz", "output": "YES" }, { "input": "lgirxqkrkgjcutpqitmffvbujcljkqardlalyigxorscczuzikoylcxenryhskoavymexysvmhbsvhtycjlmzhijpuvcjshyfeycvvcfyzytzoyvxajpqdjtfiatnvxnyeqtfcagfftafllhhjhplbdsrfpctkqpinpdfrtlzyjllfbeffputywcckupyslkbbzpgcnxgbmhtqeqqehpdaokkjtatrhyiuusjhwgiiiikxpzdueasemosmmccoakafgvxduwiuflovhhfhffgnnjhoperhhjtvocpqytjxkmrknnknqeglffhfuplopmktykxuvcmbwpoeisrlyyhdpxfvzseucofyhziuiikihpqheqdyzwigeaqzhxzvporgisxgvhyicqyejovqloibhbunsvsunpvmdckkbuokitdzleilfwutcvuuytpupizinfjrzhxudsmjcjyfcpfgthujjowdwtgbvi", "output": "YES" }, { "input": "uuehrvufgerqbzyzksmqnewacotuimawhlbycdbsmhshrsbqwybbkwjwsrkwptvlbbwjiivqugzrxxwgidrcrhrwsmwgeoleptfamzefgaeyxouxocrpvomjrazmxrnffdwrrmblgdiabdncvfougtmjgvvazasnygdrigbsrieoonirlivfyodvulouslxosswgpdexuldmkdbpdlgutiotvxjyecbrsvbmqxrlcpcipjjncduyqtohlzybvlemmfdeubihwlwqglkgjvnwrbgydcpwklmjeewqklmqdbajqgrpnynaxfvxjzgibqerxyhnxenrmcdqaaeksbzyrcaepozqpetaurlhjuxxhwppuhgoihxdxbmxeiahyaqkbknktlzkheaarjoqqrsyeducvoygwalgarldcdlqogfvsncejssmx", "output": "YES" }, { "input": "iiopulfjxoitgiusqrhgbkiyzinphjtclodbkkydetylvuimkhdkklmyoacmekdvjpuxcrvqnjhqhhbfenlpzpwijtykqziocilvtpqhxuyrphdlamawjuzgjwiebkqyrzyqgtkcrhntjxqmcgkrqcslogjegfrivzidfedeegwbbsopvxvdoididlpypjogxaodtueebbwuwilacunqpozczcgrpaxxrtogpxgfkudtxchoravrrdtimhenwmnafxaruuojduxxglefejycfcyxllfimkszmbrhcwpnwjqgwvzysmlaaifdxfjjpgjmcksiigpanappjdloiolojmcqbnpnjjzaufdpjaknylmyvolhwypygwepmqwpiglpcnpypnudhdzpdvgzosyjthzcwtytxq", "output": "YES" } ]

1,619,558,284

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

2

61

307,200

#D(?) #if the strings contains "heidi" as a subsequence, print "yes" strings=input() sub="heidi" h_count=0 e_count=0 i_count=0 d_count=0 substrings=[] for char in strings: if char=="h" and h_count < 1: h_count+=1 substrings.append("h") if char=="e" and e_count<1: e_count+=1 substrings.append("e") if char=="i" and i_count<2: i_count+=1 substrings.append("i") if char=="d" and d_count<1: d_count+=1 substrings.append("d") #if char=="h" "e" "i""d""i": #in sub #substrings.append(char) if "heidi" in ''.join(map(str,substrings)): print("YES") else: print("NO") #for j in strings and i in sub: #j=0 #i=0 #if strings[j]==strings[i]: # j+=1 # i+=1 # print("YES") #else: # print("NO")

Title: Fake News (easy) Time Limit: None seconds Memory Limit: None megabytes Problem Description: As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... Input Specification: The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). Output Specification: Output YES if the string *s* contains heidi as a subsequence and NO otherwise. Demo Input: ['abcheaibcdi\n', 'hiedi\n'] Demo Output: ['YES', 'NO'] Note: A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*.

```python #D(?) #if the strings contains "heidi" as a subsequence, print "yes" strings=input() sub="heidi" h_count=0 e_count=0 i_count=0 d_count=0 substrings=[] for char in strings: if char=="h" and h_count < 1: h_count+=1 substrings.append("h") if char=="e" and e_count<1: e_count+=1 substrings.append("e") if char=="i" and i_count<2: i_count+=1 substrings.append("i") if char=="d" and d_count<1: d_count+=1 substrings.append("d") #if char=="h" "e" "i""d""i": #in sub #substrings.append(char) if "heidi" in ''.join(map(str,substrings)): print("YES") else: print("NO") #for j in strings and i in sub: #j=0 #i=0 #if strings[j]==strings[i]: # j+=1 # i+=1 # print("YES") #else: # print("NO") ```

0

21

B

Intersection

PROGRAMMING

2,000

[ "implementation", "math" ]

B. Intersection

1

256

You are given two set of points. The first set is determined by the equation *A*1*x*<=+<=*B*1*y*<=+<=*C*1<==<=0, and the second one is determined by the equation *A*2*x*<=+<=*B*2*y*<=+<=*C*2<==<=0. Write the program which finds the number of points in the intersection of two given sets.

The first line of the input contains three integer numbers *A*1,<=*B*1,<=*C*1 separated by space. The second line contains three integer numbers *A*2,<=*B*2,<=*C*2 separated by space. All the numbers are between -100 and 100, inclusive.

Print the number of points in the intersection or -1 if there are infinite number of points.

[ "1 1 0\n2 2 0\n", "1 1 0\n2 -2 0\n" ]

[ "-1\n", "1\n" ]

none

1,000

[ { "input": "1 1 0\n2 2 0", "output": "-1" }, { "input": "1 1 0\n2 -2 0", "output": "1" }, { "input": "0 0 0\n0 0 0", "output": "-1" }, { "input": "1 1 1\n1 1 1", "output": "-1" }, { "input": "8 3 -4\n-5 2 7", "output": "1" }, { "input": "-1 -1 0\n0 -1 -1", "output": "1" }, { "input": "-1 -1 0\n1 1 -1", "output": "0" }, { "input": "-1 -1 1\n0 -1 0", "output": "1" }, { "input": "0 0 0\n1 -1 -1", "output": "-1" }, { "input": "0 0 1\n-1 1 -1", "output": "0" }, { "input": "0 1 -1\n-1 1 -1", "output": "1" }, { "input": "1 0 -1\n0 0 -1", "output": "0" }, { "input": "0 1 1\n1 0 0", "output": "1" }, { "input": "1 0 0\n0 0 1", "output": "0" }, { "input": "1 -1 -1\n1 -1 0", "output": "0" }, { "input": "1 0 0\n0 1 1", "output": "1" }, { "input": "1 -1 1\n-1 -1 1", "output": "1" }, { "input": "1 0 0\n0 1 1", "output": "1" }, { "input": "-1 -1 1\n-1 -1 -1", "output": "0" }, { "input": "-1 -1 0\n1 1 -1", "output": "0" }, { "input": "0 0 0\n0 1 -1", "output": "-1" }, { "input": "0 1 1\n0 1 -1", "output": "0" }, { "input": "0 1 0\n1 1 0", "output": "1" }, { "input": "1 0 1\n-1 0 -1", "output": "-1" }, { "input": "1 1 0\n1 0 -1", "output": "1" }, { "input": "0 -1 -1\n-1 0 0", "output": "1" }, { "input": "1 0 0\n1 0 0", "output": "-1" }, { "input": "1 1 1\n-1 -1 0", "output": "0" }, { "input": "-1 -1 -1\n0 -1 1", "output": "1" }, { "input": "0 -1 0\n0 0 1", "output": "0" }, { "input": "0 1 1\n-1 -1 1", "output": "1" }, { "input": "0 -1 0\n0 -1 1", "output": "0" }, { "input": "0 1 1\n0 1 1", "output": "-1" }, { "input": "1 -1 0\n-1 -1 1", "output": "1" }, { "input": "0 1 1\n0 1 -1", "output": "0" }, { "input": "1 0 1\n1 0 0", "output": "0" }, { "input": "1 1 1\n0 0 0", "output": "-1" }, { "input": "1 0 1\n-1 -1 -1", "output": "1" }, { "input": "1 -1 1\n0 0 0", "output": "-1" }, { "input": "0 1 1\n-1 -1 0", "output": "1" }, { "input": "-1 0 1\n1 0 0", "output": "0" }, { "input": "0 1 -1\n0 0 1", "output": "0" }, { "input": "0 -1 0\n1 1 1", "output": "1" }, { "input": "1 0 1\n0 1 1", "output": "1" }, { "input": "0 0 0\n1 1 -1", "output": "-1" }, { "input": "1 -1 1\n1 1 1", "output": "1" }, { "input": "1 0 -1\n-1 0 1", "output": "-1" }, { "input": "1 0 1\n1 -1 1", "output": "1" }, { "input": "1 -1 -1\n-1 -1 -1", "output": "1" }, { "input": "0 -1 1\n0 0 -1", "output": "0" }, { "input": "0 0 -1\n1 -1 -1", "output": "0" }, { "input": "1 1 0\n-1 0 0", "output": "1" }, { "input": "1 0 -1\n0 -1 0", "output": "1" }, { "input": "1 -1 0\n-1 1 0", "output": "-1" }, { "input": "1 -1 1\n1 -1 0", "output": "0" }, { "input": "-1 -1 -1\n-1 1 0", "output": "1" }, { "input": "-1 0 1\n1 -1 1", "output": "1" }, { "input": "1 -1 0\n0 -1 -1", "output": "1" }, { "input": "-1 1 0\n-1 0 -1", "output": "1" }, { "input": "-1 -1 -1\n1 -1 1", "output": "1" }, { "input": "-1 -1 0\n1 1 1", "output": "0" }, { "input": "0 1 -1\n-1 0 0", "output": "1" }, { "input": "0 0 0\n0 0 0", "output": "-1" }, { "input": "0 1 1\n1 0 -1", "output": "1" }, { "input": "0 1 -1\n0 0 0", "output": "-1" }, { "input": "1 -1 0\n-1 1 0", "output": "-1" }, { "input": "0 0 0\n0 1 0", "output": "-1" }, { "input": "0 -1 1\n1 -1 1", "output": "1" }, { "input": "1 0 0\n0 1 0", "output": "1" }, { "input": "-1 1 0\n0 -1 1", "output": "1" }, { "input": "-1 0 -1\n1 1 0", "output": "1" }, { "input": "0 -1 0\n1 1 -1", "output": "1" }, { "input": "-1 -1 1\n-1 0 1", "output": "1" }, { "input": "0 1 0\n1 0 1", "output": "1" }, { "input": "1 0 0\n-1 0 -1", "output": "0" }, { "input": "-1 -1 0\n1 -1 1", "output": "1" }, { "input": "1 1 1\n-1 -1 -1", "output": "-1" }, { "input": "1 -1 0\n-1 1 0", "output": "-1" }, { "input": "-1 -1 1\n-1 1 0", "output": "1" }, { "input": "0 0 1\n1 0 -1", "output": "0" }, { "input": "0 -1 -2\n0 1 0", "output": "0" }, { "input": "0 -1 0\n2 -2 2", "output": "1" }, { "input": "1 -1 2\n-1 0 0", "output": "1" }, { "input": "-2 0 2\n0 0 2", "output": "0" }, { "input": "-1 0 -1\n1 -1 -1", "output": "1" }, { "input": "-1 2 0\n-2 1 -2", "output": "1" }, { "input": "0 2 0\n0 1 2", "output": "0" }, { "input": "2 2 2\n0 -2 0", "output": "1" }, { "input": "-2 0 -2\n2 -2 -2", "output": "1" }, { "input": "2 2 -1\n-2 1 1", "output": "1" }, { "input": "-2 -1 1\n0 -1 0", "output": "1" }, { "input": "-2 1 1\n0 0 -2", "output": "0" }, { "input": "-1 2 -2\n0 2 1", "output": "1" }, { "input": "1 2 -2\n-1 2 0", "output": "1" }, { "input": "0 0 2\n0 -1 -1", "output": "0" }, { "input": "2 1 1\n1 2 1", "output": "1" }, { "input": "-2 -1 2\n1 1 1", "output": "1" }, { "input": "0 -1 -1\n-2 -2 -1", "output": "1" }, { "input": "-1 0 -1\n0 -2 1", "output": "1" }, { "input": "1 1 2\n0 1 0", "output": "1" }, { "input": "-2 1 1\n2 1 -1", "output": "1" }, { "input": "-1 -2 1\n-1 -2 2", "output": "0" }, { "input": "0 -2 1\n-2 2 2", "output": "1" }, { "input": "0 -1 2\n-1 -1 0", "output": "1" }, { "input": "1 -1 -2\n1 2 -2", "output": "1" }, { "input": "-2 -1 0\n-2 2 2", "output": "1" }, { "input": "-1 1 0\n0 -1 0", "output": "1" }, { "input": "-1 -2 2\n-1 0 -2", "output": "1" }, { "input": "0 1 -1\n1 0 -2", "output": "1" }, { "input": "-1 -2 -2\n-2 1 0", "output": "1" }, { "input": "1 -1 2\n0 0 -2", "output": "0" }, { "input": "2 -1 2\n0 -2 1", "output": "1" }, { "input": "1 0 -1\n2 0 1", "output": "0" }, { "input": "-2 -1 0\n-2 0 -1", "output": "1" }, { "input": "-1 1 1\n0 1 1", "output": "1" }, { "input": "1 1 1\n1 1 -2", "output": "0" }, { "input": "1 2 1\n1 -1 1", "output": "1" }, { "input": "-2 -2 0\n0 -2 -1", "output": "1" }, { "input": "-1 -1 0\n-1 -2 -1", "output": "1" }, { "input": "-2 -2 -2\n1 1 -1", "output": "0" }, { "input": "0 0 0\n0 0 1", "output": "0" }, { "input": "0 0 -87\n0 0 0", "output": "0" }, { "input": "0 0 1\n0 0 1", "output": "0" }, { "input": "100 100 100\n-100 100 -100", "output": "1" }, { "input": "12 -32 89\n0 67 -23", "output": "1" }, { "input": "0 0 1\n0 0 2", "output": "0" }, { "input": "0 5 0\n0 0 5", "output": "0" }, { "input": "0 1 1\n0 -1 -1", "output": "-1" }, { "input": "1 1 0\n2 2 1", "output": "0" }, { "input": "0 0 5\n0 0 5", "output": "0" }, { "input": "0 5 0\n0 5 1", "output": "0" }, { "input": "0 1 1\n0 1 2", "output": "0" }, { "input": "0 1 1\n0 2 3", "output": "0" }, { "input": "2 2 -3\n2 2 -2", "output": "0" }, { "input": "3 3 3\n3 3 4", "output": "0" }, { "input": "0 1 2\n0 2 3", "output": "0" }, { "input": "0 0 1\n1 1 1", "output": "0" }, { "input": "5 0 1\n7 0 2", "output": "0" }, { "input": "4 6 1\n2 3 1", "output": "0" }, { "input": "0 0 0\n0 1 2", "output": "-1" } ]

1,572,026,277

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

2

108

0

def fazTudo(): ar,br,cr = map(int,input().split()); aw,bw,cw = map(int,input().split()); res = 1; if br==0 or bw==0: print("0"); return; a1 = -(ar/br); b1 = -(cr/br); a2 = -(aw/bw); b2 = -(cw/bw); if(a1==a2): if(b1==b2): res = -1; else: res = 0; print(res); fazTudo();

Title: Intersection Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: You are given two set of points. The first set is determined by the equation *A*1*x*<=+<=*B*1*y*<=+<=*C*1<==<=0, and the second one is determined by the equation *A*2*x*<=+<=*B*2*y*<=+<=*C*2<==<=0. Write the program which finds the number of points in the intersection of two given sets. Input Specification: The first line of the input contains three integer numbers *A*1,<=*B*1,<=*C*1 separated by space. The second line contains three integer numbers *A*2,<=*B*2,<=*C*2 separated by space. All the numbers are between -100 and 100, inclusive. Output Specification: Print the number of points in the intersection or -1 if there are infinite number of points. Demo Input: ['1 1 0\n2 2 0\n', '1 1 0\n2 -2 0\n'] Demo Output: ['-1\n', '1\n'] Note: none

```python def fazTudo(): ar,br,cr = map(int,input().split()); aw,bw,cw = map(int,input().split()); res = 1; if br==0 or bw==0: print("0"); return; a1 = -(ar/br); b1 = -(cr/br); a2 = -(aw/bw); b2 = -(cw/bw); if(a1==a2): if(b1==b2): res = -1; else: res = 0; print(res); fazTudo(); ```

0

none

0

[ "none" ]

null

Andryusha is an orderly boy and likes to keep things in their place. Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the socks one by one from the bag, and for each sock he looks whether the pair of this sock has been already took out of the bag, or not. If not (that means the pair of this sock is still in the bag), he puts the current socks on the table in front of him. Otherwise, he puts both socks from the pair to the wardrobe. Andryusha remembers the order in which he took the socks from the bag. Can you tell him what is the maximum number of socks that were on the table at the same time?

The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs. The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha took out was from pair *x**i*. It is guaranteed that Andryusha took exactly two socks of each pair.

Print single integer — the maximum number of socks that were on the table at the same time.

[ "1\n1 1\n", "3\n2 1 1 3 2 3\n" ]

[ "1\n", "2\n" ]

In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time. In the second example Andryusha behaved as follows: - Initially the table was empty, he took out a sock from pair 2 and put it on the table. - Sock (2) was on the table. Andryusha took out a sock from pair 1 and put it on the table. - Socks (1, 2) were on the table. Andryusha took out a sock from pair 1, and put this pair into the wardrobe. - Sock (2) was on the table. Andryusha took out a sock from pair 3 and put it on the table. - Socks (2, 3) were on the table. Andryusha took out a sock from pair 2, and put this pair into the wardrobe. - Sock (3) was on the table. Andryusha took out a sock from pair 3 and put this pair into the wardrobe.

0

[ { "input": "1\n1 1", "output": "1" }, { "input": "3\n2 1 1 3 2 3", "output": "2" }, { "input": "5\n5 1 3 2 4 3 1 2 4 5", "output": "5" }, { "input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7", "output": "6" }, { "input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 15 31 14 49 9 16 6 44 27 14 5 6 3 47 25 26 1 35 3 15 24 19 8 46 49 41 4 26 40 28 42 11 34 35 46 18 7 28 18 40 19 42 4 41 38 48 50 12 29 39 33 17 25 22 22 21 36 45 27 30 20 7 13 29 39 44 21 8 37 45 34 1 20 10 11 17 33 12 43 13 10 16 48 24 32 5 23 32", "output": "25" }, { "input": "50\n1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50", "output": "1" }, { "input": "50\n50 50 49 49 48 48 47 47 46 46 45 45 44 44 43 43 42 42 41 41 40 40 39 39 38 38 37 37 36 36 35 35 34 34 33 33 32 32 31 31 30 30 29 29 28 28 27 27 26 26 25 25 24 24 23 23 22 22 21 21 20 20 19 19 18 18 17 17 16 16 15 15 14 14 13 13 12 12 11 11 10 10 9 9 8 8 7 7 6 6 5 5 4 4 3 3 2 2 1 1", "output": "1" }, { "input": "50\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50", "output": "50" }, { "input": "50\n50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1", "output": "50" }, { "input": "10\n2 9 4 1 6 7 10 3 1 5 8 6 2 3 10 7 4 8 5 9", "output": "9" } ]

1,489,516,358

458

Python 3

OK

TESTS

56

218

15,974,400

n = int(input()) o = [False] * n k = 0 kmax = 0 for s in input().split(): nosok = int(s) if o[nosok-1]: kmax = max(k, kmax) k-=1 else: o[nosok-1] = True k += 1 print(kmax)

Title: none Time Limit: None seconds Memory Limit: None megabytes Problem Description: Andryusha is an orderly boy and likes to keep things in their place. Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the socks one by one from the bag, and for each sock he looks whether the pair of this sock has been already took out of the bag, or not. If not (that means the pair of this sock is still in the bag), he puts the current socks on the table in front of him. Otherwise, he puts both socks from the pair to the wardrobe. Andryusha remembers the order in which he took the socks from the bag. Can you tell him what is the maximum number of socks that were on the table at the same time? Input Specification: The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs. The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha took out was from pair *x**i*. It is guaranteed that Andryusha took exactly two socks of each pair. Output Specification: Print single integer — the maximum number of socks that were on the table at the same time. Demo Input: ['1\n1 1\n', '3\n2 1 1 3 2 3\n'] Demo Output: ['1\n', '2\n'] Note: In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time. In the second example Andryusha behaved as follows: - Initially the table was empty, he took out a sock from pair 2 and put it on the table. - Sock (2) was on the table. Andryusha took out a sock from pair 1 and put it on the table. - Socks (1, 2) were on the table. Andryusha took out a sock from pair 1, and put this pair into the wardrobe. - Sock (2) was on the table. Andryusha took out a sock from pair 3 and put it on the table. - Socks (2, 3) were on the table. Andryusha took out a sock from pair 2, and put this pair into the wardrobe. - Sock (3) was on the table. Andryusha took out a sock from pair 3 and put this pair into the wardrobe.

```python n = int(input()) o = [False] * n k = 0 kmax = 0 for s in input().split(): nosok = int(s) if o[nosok-1]: kmax = max(k, kmax) k-=1 else: o[nosok-1] = True k += 1 print(kmax) ```

3

546

A

Soldier and Bananas

PROGRAMMING

800

[ "brute force", "implementation", "math" ]

null

A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana). He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas?

The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants.

Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0.

[ "3 17 4\n" ]

[ "13" ]

none

500

[ { "input": "3 17 4", "output": "13" }, { "input": "1 2 1", "output": "0" }, { "input": "1 1 1", "output": "0" }, { "input": "1 5 6", "output": "16" }, { "input": "1 1000000000 1", "output": "0" }, { "input": "1000 0 1000", "output": "500500000" }, { "input": "859 453892 543", "output": "126416972" }, { "input": "1000 1000000000 1000", "output": "0" }, { "input": "1000 500500000 1000", "output": "0" }, { "input": "1000 500500001 1000", "output": "0" }, { "input": "1000 500499999 1000", "output": "1" }, { "input": "634 87973 214", "output": "14497197" }, { "input": "432 10000 241", "output": "12587552" }, { "input": "111 111111111 111", "output": "0" }, { "input": "20 43 3", "output": "77" } ]

1,695,896,259

2,147,483,647

PyPy 3-64

OK

TESTS

15

62

0

k,n,w = map(int,input().split()) s = 0 for i in range(1,w+1): s += i*k if s <= n: print(0) else: print(s-n)

Title: Soldier and Bananas Time Limit: None seconds Memory Limit: None megabytes Problem Description: A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana). He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? Input Specification: The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. Output Specification: Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. Demo Input: ['3 17 4\n'] Demo Output: ['13'] Note: none

```python k,n,w = map(int,input().split()) s = 0 for i in range(1,w+1): s += i*k if s <= n: print(0) else: print(s-n) ```

3

879

A

Borya's Diagnosis

PROGRAMMING

900

[ "implementation" ]

null

It seems that Borya is seriously sick. He is going visit *n* doctors to find out the exact diagnosis. Each of the doctors needs the information about all previous visits, so Borya has to visit them in the prescribed order (i.e. Borya should first visit doctor 1, then doctor 2, then doctor 3 and so on). Borya will get the information about his health from the last doctor. Doctors have a strange working schedule. The doctor *i* goes to work on the *s**i*-th day and works every *d**i* day. So, he works on days *s**i*,<=*s**i*<=+<=*d**i*,<=*s**i*<=+<=2*d**i*,<=.... The doctor's appointment takes quite a long time, so Borya can not see more than one doctor per day. What is the minimum time he needs to visit all doctors?

First line contains an integer *n* — number of doctors (1<=≤<=*n*<=≤<=1000). Next *n* lines contain two numbers *s**i* and *d**i* (1<=≤<=*s**i*,<=*d**i*<=≤<=1000).

Output a single integer — the minimum day at which Borya can visit the last doctor.

[ "3\n2 2\n1 2\n2 2\n", "2\n10 1\n6 5\n" ]

[ "4\n", "11\n" ]

In the first sample case, Borya can visit all doctors on days 2, 3 and 4. In the second sample case, Borya can visit all doctors on days 10 and 11.

500

[ { "input": "3\n2 2\n1 2\n2 2", "output": "4" }, { "input": "2\n10 1\n6 5", "output": "11" }, { "input": "3\n6 10\n3 3\n8 2", "output": "10" }, { "input": "4\n4 8\n10 10\n4 2\n8 2", "output": "14" }, { "input": "5\n7 1\n5 1\n6 1\n1 6\n6 8", "output": "14" }, { "input": "6\n1 3\n2 5\n4 7\n7 5\n6 8\n8 8", "output": "16" }, { "input": "10\n4 10\n8 7\n6 5\n2 1\n2 3\n8 8\n2 4\n2 2\n6 7\n7 9", "output": "34" }, { "input": "1\n1 1", "output": "1" }, { "input": "1\n1000 1000", "output": "1000" }, { "input": "42\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2\n1 2", "output": "83" }, { "input": "2\n5 5\n5 1", "output": "6" }, { "input": "2\n5 5\n5 5", "output": "10" }, { "input": "2\n1 1\n1 1", "output": "2" }, { "input": "2\n1 6\n7 1", "output": "7" }, { "input": "2\n4 3\n4 5", "output": "9" }, { "input": "2\n1 2\n1 3", "output": "4" }, { "input": "3\n2 3\n5 1\n2 1", "output": "6" }, { "input": "2\n2 1\n6 3", "output": "6" }, { "input": "3\n10 1\n4 4\n12 1", "output": "13" }, { "input": "2\n2 2\n10 2", "output": "10" }, { "input": "2\n1 1\n1000 2", "output": "1000" }, { "input": "14\n1000 1\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1 1", "output": "13001" }, { "input": "2\n2 4\n2 1", "output": "3" }, { "input": "3\n1 100\n100 3\n200 1", "output": "200" }, { "input": "7\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1 1", "output": "6001" }, { "input": "2\n5 5\n15 5", "output": "15" }, { "input": "2\n2 2\n2 4", "output": "6" }, { "input": "2\n1 1\n10 1", "output": "10" }, { "input": "2\n10 1\n100 1", "output": "100" }, { "input": "15\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1000 1000\n1 1", "output": "14001" }, { "input": "3\n2 1\n1 3\n4 7", "output": "11" }, { "input": "2\n5 5\n100 5", "output": "100" }, { "input": "2\n1 10\n2 30", "output": "2" }, { "input": "4\n2 2\n2 2\n2 2\n2 2", "output": "8" }, { "input": "1\n10 10", "output": "10" } ]

1,698,691,962

762

Python 3

RUNTIME_ERROR

TESTS

0

31

0

n = int(input()) currentDay = 0 for i in range(n): s, d = [int(j) for j in input().split] while s[i] <= currentDay: s[i] += d[i] currentDay = s[i] print(currentDay)

Title: Borya's Diagnosis Time Limit: None seconds Memory Limit: None megabytes Problem Description: It seems that Borya is seriously sick. He is going visit *n* doctors to find out the exact diagnosis. Each of the doctors needs the information about all previous visits, so Borya has to visit them in the prescribed order (i.e. Borya should first visit doctor 1, then doctor 2, then doctor 3 and so on). Borya will get the information about his health from the last doctor. Doctors have a strange working schedule. The doctor *i* goes to work on the *s**i*-th day and works every *d**i* day. So, he works on days *s**i*,<=*s**i*<=+<=*d**i*,<=*s**i*<=+<=2*d**i*,<=.... The doctor's appointment takes quite a long time, so Borya can not see more than one doctor per day. What is the minimum time he needs to visit all doctors? Input Specification: First line contains an integer *n* — number of doctors (1<=≤<=*n*<=≤<=1000). Next *n* lines contain two numbers *s**i* and *d**i* (1<=≤<=*s**i*,<=*d**i*<=≤<=1000). Output Specification: Output a single integer — the minimum day at which Borya can visit the last doctor. Demo Input: ['3\n2 2\n1 2\n2 2\n', '2\n10 1\n6 5\n'] Demo Output: ['4\n', '11\n'] Note: In the first sample case, Borya can visit all doctors on days 2, 3 and 4. In the second sample case, Borya can visit all doctors on days 10 and 11.

```python n = int(input()) currentDay = 0 for i in range(n): s, d = [int(j) for j in input().split] while s[i] <= currentDay: s[i] += d[i] currentDay = s[i] print(currentDay) ```

-1

543

A

Writing Code

PROGRAMMING

1,800

[ "dp" ]

null

Programmers working on a large project have just received a task to write exactly *m* lines of code. There are *n* programmers working on a project, the *i*-th of them makes exactly *a**i* bugs in every line of code that he writes. Let's call a sequence of non-negative integers *v*1,<=*v*2,<=...,<=*v**n* a plan, if *v*1<=+<=*v*2<=+<=...<=+<=*v**n*<==<=*m*. The programmers follow the plan like that: in the beginning the first programmer writes the first *v*1 lines of the given task, then the second programmer writes *v*2 more lines of the given task, and so on. In the end, the last programmer writes the remaining lines of the code. Let's call a plan good, if all the written lines of the task contain at most *b* bugs in total. Your task is to determine how many distinct good plans are there. As the number of plans can be large, print the remainder of this number modulo given positive integer *mod*.

The first line contains four integers *n*, *m*, *b*, *mod* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*b*<=≤<=500; 1<=≤<=*mod*<=≤<=109<=+<=7) — the number of programmers, the number of lines of code in the task, the maximum total number of bugs respectively and the modulo you should use when printing the answer. The next line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=500) — the number of bugs per line for each programmer.

Print a single integer — the answer to the problem modulo *mod*.

[ "3 3 3 100\n1 1 1\n", "3 6 5 1000000007\n1 2 3\n", "3 5 6 11\n1 2 1\n" ]

[ "10\n", "0\n", "0\n" ]

none

500

[ { "input": "3 3 3 100\n1 1 1", "output": "10" }, { "input": "3 6 5 1000000007\n1 2 3", "output": "0" }, { "input": "3 5 6 11\n1 2 1", "output": "0" }, { "input": "2 3 3 1000\n1 2", "output": "1" }, { "input": "3 10 10 150691913\n8 7 10", "output": "0" }, { "input": "100 500 500 895583345\n20 39 5 5 41 47 36 33 34 22 21 33 7 4 15 35 16 37 39 46 27 4 12 35 43 26 23 40 16 50 27 7 49 28 17 28 16 22 18 12 25 34 28 24 10 21 38 10 40 50 35 18 23 38 10 42 22 19 24 45 33 34 50 24 29 36 39 11 37 18 10 2 9 38 17 36 49 1 32 6 20 5 37 18 31 44 1 36 24 35 13 35 8 10 26 45 43 28 38 22", "output": "501" }, { "input": "100 100 100 960694994\n1 0 0 0 1 0 0 0 0 1 0 0 0 1 0 1 1 0 1 0 0 0 1 1 0 0 1 1 0 1 1 0 1 1 0 1 0 1 0 1 0 0 1 1 1 0 1 1 1 1 1 0 1 0 0 0 0 0 1 0 1 0 1 0 1 1 1 1 0 0 1 0 0 1 1 0 1 0 1 0 1 1 0 1 1 0 1 1 0 0 1 0 1 0 1 1 0 1 0 1", "output": "527886216" }, { "input": "123 432 342 1000000007\n72 20 34 115 65 29 114 41 18 16 122 104 88 37 119 11 108 91 13 110 47 73 80 35 62 12 9 116 55 66 54 113 50 57 8 25 98 105 0 120 93 78 61 17 84 48 42 106 63 103 7 59 90 89 28 49 53 71 51 83 75 67 64 95 107 3 32 85 69 99 33 79 109 56 10 23 87 19 121 94 44 82 102 27 112 52 21 1 5 74 117 111 76 24 4 101 30 36 97 60 92 46 22 68 118 58 38 70 39 26 43 77 6 2 40 100 81 96 14 31 15 45 86", "output": "902925242" }, { "input": "100 500 499 1000000007\n72 20 34 92 65 29 40 41 18 16 86 14 88 37 31 11 39 91 13 43 47 73 80 35 62 12 9 81 55 66 54 2 50 57 8 25 98 58 0 15 93 78 61 17 84 48 42 38 63 68 7 59 90 89 28 49 53 71 51 83 75 67 64 95 70 3 32 85 69 99 33 79 26 56 10 23 87 19 45 94 44 82 22 27 6 52 21 1 5 74 96 77 76 24 4 46 30 36 97 60", "output": "416898599" }, { "input": "1 1 0 1000\n0", "output": "1" }, { "input": "1 4 25 1000\n6", "output": "1" }, { "input": "1 5 1 10\n1", "output": "0" }, { "input": "1 5 5 1000\n1", "output": "1" }, { "input": "1 5 5 1000\n500", "output": "0" }, { "input": "2 500 250 100\n100 200", "output": "0" }, { "input": "2 500 50 10000\n0 50", "output": "2" }, { "input": "100 500 500 1000000007\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0", "output": "925584498" }, { "input": "10 9 20 48620\n1 1 1 1 1 1 1 1 2 2", "output": "0" }, { "input": "21 63 40 1009\n4 4 2 2 4 4 3 2 4 2 0 3 3 4 3 4 3 0 4 2 4", "output": "1002" }, { "input": "29 157 50 1\n3 0 0 3 1 1 2 0 4 4 1 2 2 1 0 0 2 0 3 2 2 3 3 1 4 1 1 4 1", "output": "0" }, { "input": "1 1 1 1\n0", "output": "0" }, { "input": "1 1 1 1\n2", "output": "0" } ]

1,433,016,483

2,147,483,647

Python 3

TIME_LIMIT_EXCEEDED

TESTS

5

3,000

22,528,000

n, m, b, mod = map(int, input().split()) a = list(map(int, input().split())) def combos(lines, bugs, programmers): l = len(programmers) if l == 1: return 1 if lines * programmers[0] <= bugs else 0 if (lines, bugs, l) in combos.memo: return combos.memo[(lines, bugs, l)] count, written, introduced = 0, 0, 0 while written <= lines and introduced <= bugs: count += combos(lines - written, bugs - introduced, programmers[1:]) introduced += programmers[0] written += 1 combos.memo[(lines, bugs, l)] = count return count combos.memo = {} print(combos(m, b, a) % mod)

Title: Writing Code Time Limit: None seconds Memory Limit: None megabytes Problem Description: Programmers working on a large project have just received a task to write exactly *m* lines of code. There are *n* programmers working on a project, the *i*-th of them makes exactly *a**i* bugs in every line of code that he writes. Let's call a sequence of non-negative integers *v*1,<=*v*2,<=...,<=*v**n* a plan, if *v*1<=+<=*v*2<=+<=...<=+<=*v**n*<==<=*m*. The programmers follow the plan like that: in the beginning the first programmer writes the first *v*1 lines of the given task, then the second programmer writes *v*2 more lines of the given task, and so on. In the end, the last programmer writes the remaining lines of the code. Let's call a plan good, if all the written lines of the task contain at most *b* bugs in total. Your task is to determine how many distinct good plans are there. As the number of plans can be large, print the remainder of this number modulo given positive integer *mod*. Input Specification: The first line contains four integers *n*, *m*, *b*, *mod* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*b*<=≤<=500; 1<=≤<=*mod*<=≤<=109<=+<=7) — the number of programmers, the number of lines of code in the task, the maximum total number of bugs respectively and the modulo you should use when printing the answer. The next line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=500) — the number of bugs per line for each programmer. Output Specification: Print a single integer — the answer to the problem modulo *mod*. Demo Input: ['3 3 3 100\n1 1 1\n', '3 6 5 1000000007\n1 2 3\n', '3 5 6 11\n1 2 1\n'] Demo Output: ['10\n', '0\n', '0\n'] Note: none

```python n, m, b, mod = map(int, input().split()) a = list(map(int, input().split())) def combos(lines, bugs, programmers): l = len(programmers) if l == 1: return 1 if lines * programmers[0] <= bugs else 0 if (lines, bugs, l) in combos.memo: return combos.memo[(lines, bugs, l)] count, written, introduced = 0, 0, 0 while written <= lines and introduced <= bugs: count += combos(lines - written, bugs - introduced, programmers[1:]) introduced += programmers[0] written += 1 combos.memo[(lines, bugs, l)] = count return count combos.memo = {} print(combos(m, b, a) % mod) ```

0

1

A

Theatre Square

PROGRAMMING

1,000

[ "math" ]

A. Theatre Square

1

256

Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*. What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.

The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).

Write the needed number of flagstones.

[ "6 6 4\n" ]

[ "4\n" ]

none

0

[ { "input": "6 6 4", "output": "4" }, { "input": "1 1 1", "output": "1" }, { "input": "2 1 1", "output": "2" }, { "input": "1 2 1", "output": "2" }, { "input": "2 2 1", "output": "4" }, { "input": "2 1 2", "output": "1" }, { "input": "1 1 3", "output": "1" }, { "input": "2 3 4", "output": "1" }, { "input": "1000000000 1000000000 1", "output": "1000000000000000000" }, { "input": "12 13 4", "output": "12" }, { "input": "222 332 5", "output": "3015" }, { "input": "1000 1000 10", "output": "10000" }, { "input": "1001 1000 10", "output": "10100" }, { "input": "100 10001 1000000000", "output": "1" }, { "input": "1000000000 1000000000 1000000000", "output": "1" }, { "input": "1000000000 1000000000 999999999", "output": "4" }, { "input": "1000000000 1000000000 192", "output": "27126743055556" }, { "input": "1000000000 987654321 1", "output": "987654321000000000" }, { "input": "456784567 1000000000 51", "output": "175618850864484" }, { "input": "39916800 134217728 40320", "output": "3295710" } ]

1,671,120,730

2,147,483,647

Python 3

TIME_LIMIT_EXCEEDED

TESTS

8

1,000

0

inputs = input().split(" ") tall = int(inputs[0]) width = int(inputs[1]) fagstoneArea = int(inputs[2]) minOfFagstone = 0 minOfFagstoneRows = 0 minOfFagstoneColums = 0 cantRowsOfFagstone = 0 cantColumnsOfFagstone = 0 while(cantRowsOfFagstone < tall): cantRowsOfFagstone = cantRowsOfFagstone + fagstoneArea minOfFagstoneRows = minOfFagstoneRows + 1 while(cantColumnsOfFagstone < width): cantColumnsOfFagstone = cantColumnsOfFagstone + fagstoneArea minOfFagstoneColums = minOfFagstoneColums + 1 if(fagstoneArea > tall and fagstoneArea > width): minOfFagstone = 1 print(minOfFagstoneRows * minOfFagstoneColums) #matriz = CreateMatriz(tall, width) #printMatriz(matriz, tall, width)

Title: Theatre Square Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*. What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. Input Specification: The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). Output Specification: Write the needed number of flagstones. Demo Input: ['6 6 4\n'] Demo Output: ['4\n'] Note: none

```python inputs = input().split(" ") tall = int(inputs[0]) width = int(inputs[1]) fagstoneArea = int(inputs[2]) minOfFagstone = 0 minOfFagstoneRows = 0 minOfFagstoneColums = 0 cantRowsOfFagstone = 0 cantColumnsOfFagstone = 0 while(cantRowsOfFagstone < tall): cantRowsOfFagstone = cantRowsOfFagstone + fagstoneArea minOfFagstoneRows = minOfFagstoneRows + 1 while(cantColumnsOfFagstone < width): cantColumnsOfFagstone = cantColumnsOfFagstone + fagstoneArea minOfFagstoneColums = minOfFagstoneColums + 1 if(fagstoneArea > tall and fagstoneArea > width): minOfFagstone = 1 print(minOfFagstoneRows * minOfFagstoneColums) #matriz = CreateMatriz(tall, width) #printMatriz(matriz, tall, width) ```

0

769

B

News About Credit

PROGRAMMING

1,200

[ "*special", "greedy", "two pointers" ]

null

Polycarp studies at the university in the group which consists of *n* students (including himself). All they are registrated in the social net "TheContacnt!". Not all students are equally sociable. About each student you know the value *a**i* — the maximum number of messages which the *i*-th student is agree to send per day. The student can't send messages to himself. In early morning Polycarp knew important news that the programming credit will be tomorrow. For this reason it is necessary to urgently inform all groupmates about this news using private messages. Your task is to make a plan of using private messages, so that: - the student *i* sends no more than *a**i* messages (for all *i* from 1 to *n*); - all students knew the news about the credit (initially only Polycarp knew it); - the student can inform the other student only if he knows it himself. Let's consider that all students are numerated by distinct numbers from 1 to *n*, and Polycarp always has the number 1. In that task you shouldn't minimize the number of messages, the moment of time, when all knew about credit or some other parameters. Find any way how to use private messages which satisfies requirements above.

The first line contains the positive integer *n* (2<=≤<=*n*<=≤<=100) — the number of students. The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* equals to the maximum number of messages which can the *i*-th student agree to send. Consider that Polycarp always has the number 1.

Print -1 to the first line if it is impossible to inform all students about credit. Otherwise, in the first line print the integer *k* — the number of messages which will be sent. In each of the next *k* lines print two distinct integers *f* and *t*, meaning that the student number *f* sent the message with news to the student number *t*. All messages should be printed in chronological order. It means that the student, who is sending the message, must already know this news. It is assumed that students can receive repeated messages with news of the credit. If there are several answers, it is acceptable to print any of them.

[ "4\n1 2 1 0\n", "6\n2 0 1 3 2 0\n", "3\n0 2 2\n" ]

[ "3\n1 2\n2 4\n2 3\n", "6\n1 3\n3 4\n1 2\n4 5\n5 6\n4 6\n", "-1\n" ]

In the first test Polycarp (the student number 1) can send the message to the student number 2, who after that can send the message to students number 3 and 4. Thus, all students knew about the credit.

1,000

[ { "input": "4\n1 2 1 0", "output": "3\n1 2\n2 3\n2 4" }, { "input": "6\n2 0 1 3 2 0", "output": "5\n1 4\n1 5\n4 3\n4 2\n4 6" }, { "input": "3\n0 2 2", "output": "-1" }, { "input": "2\n0 0", "output": "-1" }, { "input": "2\n1 0", "output": "1\n1 2" }, { "input": "2\n0 1", "output": "-1" }, { "input": "2\n1 1", "output": "1\n1 2" }, { "input": "3\n1 1 0", "output": "2\n1 2\n2 3" }, { "input": "3\n0 1 1", "output": "-1" }, { "input": "3\n1 0 0", "output": "-1" }, { "input": "3\n2 0 0", "output": "2\n1 2\n1 3" }, { "input": "3\n1 0 1", "output": "2\n1 3\n3 2" }, { "input": "3\n1 1 1", "output": "2\n1 2\n2 3" }, { "input": "40\n3 3 2 1 0 0 0 4 5 4 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 2 3 2 0 1 0 0 2 0 3 0 1 0", "output": "-1" }, { "input": "100\n1 0 0 2 0 2 0 0 2 0 0 2 0 0 2 2 2 1 1 2 1 2 2 2 1 2 0 1 0 1 0 2 2 2 0 1 2 0 0 2 0 2 0 1 1 0 1 0 2 0 0 2 1 2 1 2 2 2 2 1 0 2 0 0 1 0 2 0 0 2 0 1 0 2 1 1 2 2 2 2 0 0 2 0 2 1 0 0 0 1 0 2 2 2 0 1 0 1 1 0", "output": "99\n1 4\n4 6\n4 9\n6 12\n6 15\n9 16\n9 17\n12 20\n12 22\n15 23\n15 24\n16 26\n16 32\n17 33\n17 34\n20 37\n20 40\n22 42\n22 49\n23 52\n23 54\n24 56\n24 57\n26 58\n26 59\n32 62\n32 67\n33 70\n33 74\n34 77\n34 78\n37 79\n37 80\n40 83\n40 85\n42 92\n42 93\n49 94\n49 18\n52 19\n52 21\n54 25\n54 28\n56 30\n56 36\n57 44\n57 45\n58 47\n58 53\n59 55\n59 60\n62 65\n62 72\n67 75\n67 76\n70 86\n70 90\n74 96\n74 98\n77 99\n77 2\n78 3\n78 5\n79 7\n79 8\n80 10\n80 11\n83 13\n83 14\n85 27\n85 29\n92 31\n92 35\n93 38\n93 3..." }, { "input": "4\n2 0 0 0", "output": "-1" }, { "input": "4\n2 0 0 1", "output": "3\n1 4\n1 2\n4 3" }, { "input": "4\n2 0 1 0", "output": "3\n1 3\n1 2\n3 4" }, { "input": "4\n2 1 0 0", "output": "3\n1 2\n1 3\n2 4" }, { "input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0", "output": "-1" }, { "input": "100\n99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0", "output": "99\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 12\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 22\n1 23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 37\n1 38\n1 39\n1 40\n1 41\n1 42\n1 43\n1 44\n1 45\n1 46\n1 47\n1 48\n1 49\n1 50\n1 51\n1 52\n1 53\n1 54\n1 55\n1 56\n1 57\n1 58\n1 59\n1 60\n1 61\n1 62\n1 63\n1 64\n1 65\n1 66\n1 67\n1 68\n1 69\n1 70\n1 71\n1 72\n1 73\n1 74\n1 75\n1 76\n1 77\n1 78\n1 79\n1 80\n1 81\n1 82\n1 83\n1 84\n1 85\n1 86\n1 87\n..." }, { "input": "100\n98 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0", "output": "-1" }, { "input": "100\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 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23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 37\n1 38\n1 39\n1 40\n1 41\n1 42\n1 43\n1 44\n1 45\n1 46\n1 47\n1 48\n1 49\n1 50\n1 51\n1 52\n1 53\n1 54\n1 55\n1 56\n1 57\n1 58\n1 59\n1 60\n1 61\n1 62\n1 63\n1 64\n1 65\n1 66\n97 67\n97 68\n97 69\n97 70\n97 71\n97 72\n97 73\n97 74\n97 75\n97 76\n97 77\n97 78\n97 79\n97 80\n97 81\n97 82\n97 83\n..." }, { "input": "20\n0 0 3 0 0 0 3 4 2 0 2 0 0 0 0 1 0 1 0 1", "output": "-1" }, { "input": "60\n3 0 0 1 0 0 0 0 3 1 3 4 0 0 0 3 0 0 0 2 0 3 4 1 3 3 0 2 0 4 1 5 3 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 2 0 1 1 0 1 0 3 0 0", "output": "-1" }, { "input": "80\n4 0 0 0 0 0 0 3 0 3 0 0 0 4 3 0 1 0 2 0 0 0 5 0 5 0 0 0 0 4 0 3 0 0 0 1 0 0 2 0 5 2 0 0 4 4 0 3 0 0 0 0 0 0 0 2 5 0 2 0 0 0 0 0 0 0 0 0 0 3 0 0 3 5 0 0 0 0 0 0", "output": "-1" }, { "input": "100\n2 0 0 2 0 0 0 0 0 2 0 0 0 5 0 0 0 0 0 0 0 1 0 7 0 0 0 0 7 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 6 0 7 4 0 0 0 0 5 0 0 0 0 0 0 7 4 0 0 0 0 0 0 7 7 0 0 0 0 0 2 0 0 0 0 0 0 0 0 4 7 7 0 0 0", "output": "-1" }, { "input": "100\n1 0 0 0 1 2 3 2 1 0 1 2 3 1 3 1 0 0 1 1 0 0 2 1 2 1 3 3 1 0 0 1 0 2 2 0 3 0 1 1 1 2 0 2 0 1 0 2 0 1 2 2 0 0 0 0 1 0 0 0 1 1 4 0 2 0 1 0 2 0 2 2 2 1 1 0 0 2 0 3 1 0 0 1 1 0 1 0 2 3 2 0 1 2 0 0 0 0 0 1", "output": "99\n1 63\n63 7\n63 13\n63 15\n63 27\n7 28\n7 37\n7 80\n13 90\n13 6\n13 8\n15 12\n15 23\n15 25\n27 34\n27 35\n27 42\n28 44\n28 48\n28 51\n37 52\n37 65\n37 69\n80 71\n80 72\n80 73\n90 78\n90 89\n90 91\n6 94\n6 5\n8 9\n8 11\n12 14\n12 16\n23 19\n23 20\n25 24\n25 26\n34 29\n34 32\n35 39\n35 40\n42 41\n42 46\n44 50\n44 57\n48 61\n48 62\n51 67\n51 74\n52 75\n52 81\n65 84\n65 85\n69 87\n69 93\n71 100\n71 2\n72 3\n72 4\n73 10\n73 17\n78 18\n78 21\n89 22\n89 30\n91 31\n91 33\n94 36\n94 38\n5 43\n9 45\n11 47\n14 49\n..." }, { "input": "100\n5 0 0 1 1 0 0 0 1 0 0 0 0 0 5 0 2 1 0 1 0 6 0 0 0 3 0 0 0 0 0 0 0 0 1 0 3 0 0 0 0 0 0 4 0 0 3 1 1 0 0 4 0 0 0 0 0 0 3 2 3 3 0 0 0 0 0 0 0 0 0 0 0 0 2 0 0 2 1 0 5 1 0 8 0 1 0 0 10 4 0 0 0 6 4 0 0 0 0 1", "output": "99\n1 89\n1 84\n1 22\n1 94\n1 15\n89 81\n89 44\n89 52\n89 90\n89 95\n89 26\n89 37\n89 47\n89 59\n89 61\n84 62\n84 17\n84 60\n84 75\n84 78\n84 4\n84 5\n84 9\n22 18\n22 20\n22 35\n22 48\n22 49\n22 79\n94 82\n94 86\n94 100\n94 2\n94 3\n94 6\n15 7\n15 8\n15 10\n15 11\n15 12\n81 13\n81 14\n81 16\n81 19\n81 21\n44 23\n44 24\n44 25\n44 27\n52 28\n52 29\n52 30\n52 31\n90 32\n90 33\n90 34\n90 36\n95 38\n95 39\n95 40\n95 41\n26 42\n26 43\n26 45\n37 46\n37 50\n37 51\n47 53\n47 54\n47 55\n59 56\n59 57\n59 58\n61 63\n6..." }, { "input": "100\n47 0 0 0 0 0 0 0 0 0 0 9 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 4 0 1 0 2 0 0 1 0 0 0 0 0 1 18 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0", "output": "99\n1 47\n1 12\n1 66\n1 33\n1 93\n1 37\n1 81\n1 25\n1 35\n1 40\n1 46\n1 61\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 22\n1 23\n1 24\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 34\n1 36\n1 38\n1 39\n1 41\n1 42\n47 43\n47 44\n47 45\n47 48\n47 49\n47 50\n47 51\n47 52\n47 53\n47 54\n47 55\n47 56\n47 57\n47 58\n47 59\n47 60\n47 62\n47 63\n12 64\n12 65\n12 67\n12 68\n12 69\n12 70\n12 71\n12 72\n12 73\n66 74\n66 75\n66 76\n66 77\n66 78\n66 79\n66..." }, { "input": "100\n1 0 2 1 1 1 0 0 0 3 2 1 1 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 1 2 1 0 2 1 1 1 0 0 1 2 1 3 1 1 0 0 2 1 0 1 1 1 2 1 2 0 3 1 2 0 1 1 2 2 1 1 1 1 1 2 0 0 2 1 1 0 1 2 1 1 1 1 1 0 1 1 1 0 3 0 0 2 2 0 0 0 2 1 2 0", "output": "99\n1 10\n10 42\n10 57\n10 89\n42 3\n42 11\n42 30\n57 33\n57 40\n57 47\n89 53\n89 55\n89 59\n3 63\n3 64\n11 70\n11 73\n30 78\n30 92\n33 93\n33 97\n40 99\n40 4\n47 5\n47 6\n53 12\n53 13\n55 14\n55 16\n59 18\n59 19\n63 20\n63 22\n64 23\n64 24\n70 26\n70 27\n73 28\n73 29\n78 31\n78 34\n92 35\n92 36\n93 39\n93 41\n97 43\n97 44\n99 48\n99 50\n4 51\n5 52\n6 54\n12 58\n13 61\n14 62\n16 65\n18 66\n19 67\n20 68\n22 69\n23 74\n24 75\n26 77\n27 79\n28 80\n29 81\n31 82\n34 83\n35 85\n36 86\n39 87\n41 98\n43 2\n44 7\n4..." }, { "input": "100\n83 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 11 0", "output": "99\n1 99\n1 83\n1 22\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 12\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 37\n1 38\n1 39\n1 40\n1 41\n1 42\n1 43\n1 44\n1 45\n1 46\n1 47\n1 48\n1 49\n1 50\n1 51\n1 52\n1 53\n1 54\n1 55\n1 56\n1 57\n1 58\n1 59\n1 60\n1 61\n1 62\n1 63\n1 64\n1 65\n1 66\n1 67\n1 68\n1 69\n1 70\n1 71\n1 72\n1 73\n1 74\n1 75\n1 76\n1 77\n1 78\n1 79\n1 80\n1 81\n1 82\n99 84\n99 85\n99 ..." }, { "input": "100\n1 1 0 1 0 1 1 1 2 1 0 1 1 0 1 2 1 1 1 1 2 1 1 0 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 0 2 2 2 2 1 1 0 1 2 1 1 0 1 1 0 1 0 1 1 0 0 1 1 1 1 1 1 2 0 2 1 2 1 1 0 0 1 1 1 1 0 2 4 2 1 1 1 0 1 2 1 1 1 0 2 1 2", "output": "99\n1 86\n86 9\n86 16\n86 21\n86 44\n9 45\n9 46\n16 47\n16 52\n21 71\n21 73\n44 75\n44 85\n45 87\n45 93\n46 98\n46 100\n47 2\n47 4\n52 6\n52 7\n71 8\n71 10\n73 12\n73 13\n75 15\n75 17\n85 18\n85 19\n87 20\n87 22\n93 23\n93 25\n98 27\n98 28\n100 29\n100 30\n2 31\n4 32\n6 33\n7 34\n8 35\n10 36\n12 37\n13 38\n15 39\n17 41\n18 42\n19 48\n20 49\n22 51\n23 53\n25 54\n27 56\n28 57\n29 59\n30 61\n31 62\n32 65\n33 66\n34 67\n35 68\n36 69\n37 70\n38 74\n39 76\n41 77\n42 80\n48 81\n49 82\n51 83\n53 88\n54 89\n56 90\n..." }, { "input": "100\n99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0", "output": "99\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 12\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 22\n1 23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 37\n1 38\n1 39\n1 40\n1 41\n1 42\n1 43\n1 44\n1 45\n1 46\n1 47\n1 48\n1 49\n1 50\n1 51\n1 52\n1 53\n1 54\n1 55\n1 56\n1 57\n1 58\n1 59\n1 60\n1 61\n1 62\n1 63\n1 64\n1 65\n1 66\n1 67\n1 68\n1 69\n1 70\n1 71\n1 72\n1 73\n1 74\n1 75\n1 76\n1 77\n1 78\n1 79\n1 80\n1 81\n1 82\n1 83\n1 84\n1 85\n1 86\n1 87\n..." }, { "input": "100\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "99\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n7 8\n8 9\n9 10\n10 11\n11 12\n12 13\n13 14\n14 15\n15 16\n16 17\n17 18\n18 19\n19 20\n20 21\n21 22\n22 23\n23 24\n24 25\n25 26\n26 27\n27 28\n28 29\n29 30\n30 31\n31 32\n32 33\n33 34\n34 35\n35 36\n36 37\n37 38\n38 39\n39 40\n40 41\n41 42\n42 43\n43 44\n44 45\n45 46\n46 47\n47 48\n48 49\n49 50\n50 52\n52 53\n53 54\n54 55\n55 56\n56 57\n57 58\n58 59\n59 60\n60 61\n61 62\n62 63\n63 64\n64 65\n65 66\n66 67\n67 68\n68 69\n69 70\n70 71\n71 72\n72 73\n73 74\n74 75\n75 76\n76 77\n..." }, { "input": "2\n0 100", "output": "-1" }, { "input": "2\n100 0", "output": "1\n1 2" }, { "input": "2\n100 100", "output": "1\n1 2" } ]

1,488,631,525

2,725

Python 3

OK

TESTS

60

62

4,710,400

input() power = list(map(int, input().split())) n = len(power) ps = [0] + sorted(range(1, n), key=lambda i: -power[i]) out = [] bonus = [0] * power[0] i = 1 while i < n and bonus: out.append((bonus.pop(), ps[i])) bonus.extend([ps[i]] * max(0, power[ps[i]])) i += 1 if i != n: print(-1) else: print(len(out)) print(*["%s %s" % (a + 1, b + 1) for a, b in out], sep="\n")

Title: News About Credit Time Limit: None seconds Memory Limit: None megabytes Problem Description: Polycarp studies at the university in the group which consists of *n* students (including himself). All they are registrated in the social net "TheContacnt!". Not all students are equally sociable. About each student you know the value *a**i* — the maximum number of messages which the *i*-th student is agree to send per day. The student can't send messages to himself. In early morning Polycarp knew important news that the programming credit will be tomorrow. For this reason it is necessary to urgently inform all groupmates about this news using private messages. Your task is to make a plan of using private messages, so that: - the student *i* sends no more than *a**i* messages (for all *i* from 1 to *n*); - all students knew the news about the credit (initially only Polycarp knew it); - the student can inform the other student only if he knows it himself. Let's consider that all students are numerated by distinct numbers from 1 to *n*, and Polycarp always has the number 1. In that task you shouldn't minimize the number of messages, the moment of time, when all knew about credit or some other parameters. Find any way how to use private messages which satisfies requirements above. Input Specification: The first line contains the positive integer *n* (2<=≤<=*n*<=≤<=100) — the number of students. The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* equals to the maximum number of messages which can the *i*-th student agree to send. Consider that Polycarp always has the number 1. Output Specification: Print -1 to the first line if it is impossible to inform all students about credit. Otherwise, in the first line print the integer *k* — the number of messages which will be sent. In each of the next *k* lines print two distinct integers *f* and *t*, meaning that the student number *f* sent the message with news to the student number *t*. All messages should be printed in chronological order. It means that the student, who is sending the message, must already know this news. It is assumed that students can receive repeated messages with news of the credit. If there are several answers, it is acceptable to print any of them. Demo Input: ['4\n1 2 1 0\n', '6\n2 0 1 3 2 0\n', '3\n0 2 2\n'] Demo Output: ['3\n1 2\n2 4\n2 3\n', '6\n1 3\n3 4\n1 2\n4 5\n5 6\n4 6\n', '-1\n'] Note: In the first test Polycarp (the student number 1) can send the message to the student number 2, who after that can send the message to students number 3 and 4. Thus, all students knew about the credit.

```python input() power = list(map(int, input().split())) n = len(power) ps = [0] + sorted(range(1, n), key=lambda i: -power[i]) out = [] bonus = [0] * power[0] i = 1 while i < n and bonus: out.append((bonus.pop(), ps[i])) bonus.extend([ps[i]] * max(0, power[ps[i]])) i += 1 if i != n: print(-1) else: print(len(out)) print(*["%s %s" % (a + 1, b + 1) for a, b in out], sep="\n") ```

3

572

A

Arrays

PROGRAMMING

900

[ "sortings" ]

null

You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array.

The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly. The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space. The third line contains *n**A* numbers *a*1,<=*a*2,<=... *a**n**A* (<=-<=109<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n**A*<=≤<=109), separated by spaces — elements of array *A*. The fourth line contains *n**B* integers *b*1,<=*b*2,<=... *b**n**B* (<=-<=109<=≤<=*b*1<=≤<=*b*2<=≤<=...<=≤<=*b**n**B*<=≤<=109), separated by spaces — elements of array *B*.

Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes).

[ "3 3\n2 1\n1 2 3\n3 4 5\n", "3 3\n3 3\n1 2 3\n3 4 5\n", "5 2\n3 1\n1 1 1 1 1\n2 2\n" ]

[ "YES\n", "NO\n", "YES\n" ]

In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3). In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in *A* will be less than all the numbers chosen in *B*: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7280148ed5eab0a7d418d4f92b32061243a8ca58.png" style="max-width: 100.0%;max-height: 100.0%;"/>.

500

[ { "input": "3 3\n2 1\n1 2 3\n3 4 5", "output": "YES" }, { "input": "3 3\n3 3\n1 2 3\n3 4 5", "output": "NO" }, { "input": "5 2\n3 1\n1 1 1 1 1\n2 2", "output": "YES" }, { "input": "3 5\n1 1\n5 5 5\n5 5 5 5 5", "output": "NO" }, { "input": "1 1\n1 1\n1\n1", "output": "NO" }, { "input": "3 3\n1 1\n1 2 3\n1 2 3", "output": "YES" }, { "input": "3 3\n1 2\n1 2 3\n1 2 3", "output": "YES" }, { "input": "3 3\n2 2\n1 2 3\n1 2 3", "output": "NO" }, { "input": "10 15\n10 1\n1 1 5 17 22 29 32 36 39 48\n9 10 20 23 26 26 32 32 33 39 43 45 47 49 49", "output": "YES" }, { "input": "10 15\n1 15\n91 91 91 92 92 94 94 95 98 100\n92 92 93 93 93 94 95 96 97 98 98 99 99 100 100", "output": "YES" }, { "input": "15 10\n12 5\n9 25 25 32 32 38 40 41 46 46 48 51 64 64 73\n5 14 30 35 50 52 67 79 89 99", "output": "YES" }, { "input": "15 10\n4 10\n22 32 35 45 45 50 51 55 79 80 83 88 90 92 93\n46 48 52 55 60 60 68 75 80 81", "output": "YES" }, { "input": "20 30\n2 8\n6 7 7 7 7 7 7 8 8 8 8 9 9 9 9 10 10 10 10 10\n1 1 2 2 2 2 2 2 2 3 3 4 5 5 5 5 6 6 6 6 6 6 7 7 7 8 8 9 10 10", "output": "NO" }, { "input": "20 30\n19 29\n1 1 2 2 2 3 4 4 7 7 7 8 8 8 8 8 9 9 9 9\n6 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 10 10 10 10 10 10 10 10 10 10 10 10 10 10", "output": "NO" }, { "input": "1 1\n1 1\n-1000000000\n30", "output": "YES" }, { "input": "3 3\n1 3\n1 3 3\n3 3 3", "output": "YES" }, { "input": "3 3\n1 1\n3 3 3\n2 2 2", "output": "NO" }, { "input": "5 5\n3 3\n1 5 6 7 8\n1 2 5 6 7", "output": "NO" }, { "input": "3 4\n2 2\n5 6 7\n1 2 3 4", "output": "NO" }, { "input": "3 3\n3 3\n1 2 3\n4 5 6", "output": "YES" }, { "input": "5 5\n4 5\n2 2 3 4 5\n5 6 7 8 9", "output": "YES" } ]

1,603,351,276

2,147,483,647

Python 3

OK

TESTS

52

171

10,444,800

a, b = map(int, input().split()) k, m = map(int, input().split()) l1 = [int(i) for i in input().split()] l2 = [int(i) for i in input().split()] print("YES" if l1[k-1] < l2[b-m] else "NO")

Title: Arrays Time Limit: None seconds Memory Limit: None megabytes Problem Description: You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. Input Specification: The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly. The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space. The third line contains *n**A* numbers *a*1,<=*a*2,<=... *a**n**A* (<=-<=109<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n**A*<=≤<=109), separated by spaces — elements of array *A*. The fourth line contains *n**B* integers *b*1,<=*b*2,<=... *b**n**B* (<=-<=109<=≤<=*b*1<=≤<=*b*2<=≤<=...<=≤<=*b**n**B*<=≤<=109), separated by spaces — elements of array *B*. Output Specification: Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). Demo Input: ['3 3\n2 1\n1 2 3\n3 4 5\n', '3 3\n3 3\n1 2 3\n3 4 5\n', '5 2\n3 1\n1 1 1 1 1\n2 2\n'] Demo Output: ['YES\n', 'NO\n', 'YES\n'] Note: In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3). In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in *A* will be less than all the numbers chosen in *B*: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7280148ed5eab0a7d418d4f92b32061243a8ca58.png" style="max-width: 100.0%;max-height: 100.0%;"/>.

```python a, b = map(int, input().split()) k, m = map(int, input().split()) l1 = [int(i) for i in input().split()] l2 = [int(i) for i in input().split()] print("YES" if l1[k-1] < l2[b-m] else "NO") ```

3

30

B

Codeforces World Finals

PROGRAMMING

1,700

[ "implementation" ]

B. Codeforces World Finals

2

256

The king Copa often has been reported about the Codeforces site, which is rapidly getting more and more popular among the brightest minds of the humanity, who are using it for training and competing. Recently Copa understood that to conquer the world he needs to organize the world Codeforces tournament. He hopes that after it the brightest minds will become his subordinates, and the toughest part of conquering the world will be completed. The final round of the Codeforces World Finals 20YY is scheduled for *DD*.*MM*.*YY*, where *DD* is the day of the round, *MM* is the month and *YY* are the last two digits of the year. Bob is lucky to be the first finalist form Berland. But there is one problem: according to the rules of the competition, all participants must be at least 18 years old at the moment of the finals. Bob was born on *BD*.*BM*.*BY*. This date is recorded in his passport, the copy of which he has already mailed to the organizers. But Bob learned that in different countries the way, in which the dates are written, differs. For example, in the US the month is written first, then the day and finally the year. Bob wonders if it is possible to rearrange the numbers in his date of birth so that he will be at least 18 years old on the day *DD*.*MM*.*YY*. He can always tell that in his motherland dates are written differently. Help him. According to another strange rule, eligible participant must be born in the same century as the date of the finals. If the day of the finals is participant's 18-th birthday, he is allowed to participate. As we are considering only the years from 2001 to 2099 for the year of the finals, use the following rule: the year is leap if it's number is divisible by four.

The first line contains the date *DD*.*MM*.*YY*, the second line contains the date *BD*.*BM*.*BY*. It is guaranteed that both dates are correct, and *YY* and *BY* are always in [01;99]. It could be that by passport Bob was born after the finals. In this case, he can still change the order of numbers in date.

If it is possible to rearrange the numbers in the date of birth so that Bob will be at least 18 years old on the *DD*.*MM*.*YY*, output YES. In the other case, output NO. Each number contains exactly two digits and stands for day, month or year in a date. Note that it is permitted to rearrange only numbers, not digits.

[ "01.01.98\n01.01.80\n", "20.10.20\n10.02.30\n", "28.02.74\n28.02.64\n" ]

[ "YES\n", "NO\n", "NO\n" ]

none

1,000

[ { "input": "01.01.98\n01.01.80", "output": "YES" }, { "input": "20.10.20\n10.02.30", "output": "NO" }, { "input": "28.02.74\n28.02.64", "output": "NO" }, { "input": "05.05.25\n06.02.71", "output": "NO" }, { "input": "19.11.54\n29.11.53", "output": "NO" }, { "input": "01.06.84\n24.04.87", "output": "NO" }, { "input": "30.06.43\n14.09.27", "output": "YES" }, { "input": "09.05.55\n25.09.42", "output": "NO" }, { "input": "14.05.21\n02.01.88", "output": "NO" }, { "input": "27.12.51\n26.06.22", "output": "YES" }, { "input": "12.10.81\n18.11.04", "output": "YES" }, { "input": "26.04.11\n11.07.38", "output": "NO" }, { "input": "17.01.94\n17.03.58", "output": "YES" }, { "input": "15.01.93\n23.04.97", "output": "NO" }, { "input": "14.04.92\n27.05.35", "output": "YES" }, { "input": "13.08.91\n01.05.26", "output": "YES" }, { "input": "14.08.89\n05.06.65", "output": "YES" }, { "input": "13.11.88\n09.07.03", "output": "YES" }, { "input": "12.11.87\n14.08.42", "output": "YES" }, { "input": "11.03.86\n20.08.81", "output": "NO" }, { "input": "10.02.37\n25.09.71", "output": "NO" }, { "input": "11.06.36\n24.01.25", "output": "NO" }, { "input": "02.05.90\n08.03.50", "output": "YES" }, { "input": "15.01.15\n01.08.58", "output": "NO" }, { "input": "31.10.41\n27.12.13", "output": "YES" }, { "input": "14.06.18\n21.04.20", "output": "NO" }, { "input": "15.12.62\n17.12.21", "output": "YES" }, { "input": "13.03.69\n09.01.83", "output": "NO" }, { "input": "26.11.46\n03.05.90", "output": "NO" }, { "input": "11.12.72\n29.06.97", "output": "NO" }, { "input": "25.08.49\n22.10.05", "output": "YES" }, { "input": "08.04.74\n18.03.60", "output": "NO" }, { "input": "03.11.79\n10.09.61", "output": "YES" }, { "input": "29.03.20\n12.01.09", "output": "YES" }, { "input": "13.09.67\n07.09.48", "output": "YES" }, { "input": "23.05.53\n31.10.34", "output": "YES" }, { "input": "08.07.20\n27.01.01", "output": "YES" }, { "input": "10.05.64\n10.05.45", "output": "YES" }, { "input": "19.09.93\n17.05.74", "output": "YES" }, { "input": "14.06.61\n01.11.42", "output": "YES" }, { "input": "29.02.80\n29.02.60", "output": "YES" }, { "input": "21.02.59\n24.04.40", "output": "YES" }, { "input": "05.04.99\n19.08.80", "output": "YES" }, { "input": "02.06.59\n30.01.40", "output": "YES" }, { "input": "23.09.93\n12.11.74", "output": "YES" }, { "input": "09.08.65\n21.06.46", "output": "YES" }, { "input": "29.09.35\n21.07.17", "output": "YES" }, { "input": "30.06.58\n21.05.39", "output": "YES" }, { "input": "06.08.91\n05.12.73", "output": "YES" }, { "input": "08.07.88\n15.01.69", "output": "YES" }, { "input": "07.10.55\n13.05.36", "output": "YES" }, { "input": "22.03.79\n04.03.61", "output": "YES" }, { "input": "30.06.76\n03.10.57", "output": "YES" }, { "input": "03.03.70\n18.01.51", "output": "YES" }, { "input": "08.07.79\n25.08.60", "output": "YES" }, { "input": "01.09.92\n10.05.74", "output": "YES" }, { "input": "05.04.73\n28.09.54", "output": "YES" }, { "input": "30.08.83\n13.04.65", "output": "YES" }, { "input": "08.04.64\n27.01.45", "output": "YES" }, { "input": "10.11.95\n09.04.77", "output": "YES" }, { "input": "19.11.36\n17.02.21", "output": "YES" }, { "input": "28.02.20\n11.01.29", "output": "YES" }, { "input": "01.01.35\n16.02.29", "output": "YES" }, { "input": "01.01.47\n28.02.29", "output": "YES" }, { "input": "06.08.34\n16.02.29", "output": "YES" }, { "input": "30.09.46\n24.02.29", "output": "YES" }, { "input": "01.03.19\n01.02.29", "output": "NO" }, { "input": "30.08.32\n02.02.29", "output": "NO" }, { "input": "30.10.46\n25.02.29", "output": "NO" }, { "input": "06.03.20\n06.02.03", "output": "YES" }, { "input": "01.05.19\n08.01.04", "output": "YES" }, { "input": "31.05.19\n12.01.04", "output": "YES" }, { "input": "31.03.50\n02.11.32", "output": "YES" }, { "input": "03.12.98\n11.12.80", "output": "YES" }, { "input": "04.02.19\n01.03.02", "output": "YES" }, { "input": "01.05.21\n03.11.04", "output": "YES" }, { "input": "31.05.20\n02.12.04", "output": "YES" }, { "input": "31.03.36\n10.11.31", "output": "YES" }, { "input": "01.05.19\n03.01.28", "output": "YES" }, { "input": "30.12.68\n31.12.50", "output": "NO" }, { "input": "30.08.55\n31.08.37", "output": "NO" }, { "input": "30.08.41\n23.08.31", "output": "NO" } ]

1,516,539,543

2,147,483,647

Python 3

OK

TESTS

82

124

5,632,000

import itertools as it month_to_days_non_leap = { 1: 31, 2: 28, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31, } def month_year_to_day(month, year): if year % 4 == 0 and month == 2: return 29 else: return month_to_days_non_leap[month] def good_date(day, month, year): if month > 12: return False if day > month_year_to_day(month, year): return False return True dd, mm, yy = map(int, input().split('.')) bd, bm, by = map(int, input().split('.')) found_sol = False for p_bd, p_bm, p_by in it.permutations([bd, bm, by]): if good_date(p_bd, p_bm, p_by): year_diff = yy - p_by if year_diff > 18: found_sol = True break elif year_diff < 18: continue if p_bm < mm: found_sol = True break elif p_bm > mm: continue if p_bd < dd: found_sol = True break elif p_bd > dd: continue found_sol = True break if found_sol: print("YES") else: print("NO")

Title: Codeforces World Finals Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: The king Copa often has been reported about the Codeforces site, which is rapidly getting more and more popular among the brightest minds of the humanity, who are using it for training and competing. Recently Copa understood that to conquer the world he needs to organize the world Codeforces tournament. He hopes that after it the brightest minds will become his subordinates, and the toughest part of conquering the world will be completed. The final round of the Codeforces World Finals 20YY is scheduled for *DD*.*MM*.*YY*, where *DD* is the day of the round, *MM* is the month and *YY* are the last two digits of the year. Bob is lucky to be the first finalist form Berland. But there is one problem: according to the rules of the competition, all participants must be at least 18 years old at the moment of the finals. Bob was born on *BD*.*BM*.*BY*. This date is recorded in his passport, the copy of which he has already mailed to the organizers. But Bob learned that in different countries the way, in which the dates are written, differs. For example, in the US the month is written first, then the day and finally the year. Bob wonders if it is possible to rearrange the numbers in his date of birth so that he will be at least 18 years old on the day *DD*.*MM*.*YY*. He can always tell that in his motherland dates are written differently. Help him. According to another strange rule, eligible participant must be born in the same century as the date of the finals. If the day of the finals is participant's 18-th birthday, he is allowed to participate. As we are considering only the years from 2001 to 2099 for the year of the finals, use the following rule: the year is leap if it's number is divisible by four. Input Specification: The first line contains the date *DD*.*MM*.*YY*, the second line contains the date *BD*.*BM*.*BY*. It is guaranteed that both dates are correct, and *YY* and *BY* are always in [01;99]. It could be that by passport Bob was born after the finals. In this case, he can still change the order of numbers in date. Output Specification: If it is possible to rearrange the numbers in the date of birth so that Bob will be at least 18 years old on the *DD*.*MM*.*YY*, output YES. In the other case, output NO. Each number contains exactly two digits and stands for day, month or year in a date. Note that it is permitted to rearrange only numbers, not digits. Demo Input: ['01.01.98\n01.01.80\n', '20.10.20\n10.02.30\n', '28.02.74\n28.02.64\n'] Demo Output: ['YES\n', 'NO\n', 'NO\n'] Note: none

```python import itertools as it month_to_days_non_leap = { 1: 31, 2: 28, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31, } def month_year_to_day(month, year): if year % 4 == 0 and month == 2: return 29 else: return month_to_days_non_leap[month] def good_date(day, month, year): if month > 12: return False if day > month_year_to_day(month, year): return False return True dd, mm, yy = map(int, input().split('.')) bd, bm, by = map(int, input().split('.')) found_sol = False for p_bd, p_bm, p_by in it.permutations([bd, bm, by]): if good_date(p_bd, p_bm, p_by): year_diff = yy - p_by if year_diff > 18: found_sol = True break elif year_diff < 18: continue if p_bm < mm: found_sol = True break elif p_bm > mm: continue if p_bd < dd: found_sol = True break elif p_bd > dd: continue found_sol = True break if found_sol: print("YES") else: print("NO") ```

3.95851

931

A

Friends Meeting

PROGRAMMING

800

[ "brute force", "greedy", "implementation", "math" ]

null

Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*. Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the following rules: the first move increases the tiredness by 1, the second move increases the tiredness by 2, the third — by 3 and so on. For example, if a friend moves first to the left, then to the right (returning to the same point), and then again to the left his tiredness becomes equal to 1<=+<=2<=+<=3<==<=6. The friends want to meet in a integer point. Determine the minimum total tiredness they should gain, if they meet in the same point.

The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend. The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend. It is guaranteed that *a*<=≠<=*b*.

Print the minimum possible total tiredness if the friends meet in the same point.

[ "3\n4\n", "101\n99\n", "5\n10\n" ]

[ "1\n", "2\n", "9\n" ]

In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1. In the second example the first friend should move by one to the left, and the second friend should move by one to the right. Then they meet in the point 100, and the total tiredness becomes 1 + 1 = 2. In the third example one of the optimal ways is the following. The first friend should move three times to the right, and the second friend — two times to the left. Thus the friends meet in the point 8, and the total tiredness becomes 1 + 2 + 3 + 1 + 2 = 9.

500

[ { "input": "3\n4", "output": "1" }, { "input": "101\n99", "output": "2" }, { "input": "5\n10", "output": "9" }, { "input": "1\n2", "output": "1" }, { "input": "1\n1000", "output": "250000" }, { "input": "999\n1000", "output": "1" }, { "input": "1000\n999", "output": "1" }, { "input": "1000\n1", "output": "250000" }, { "input": "2\n1", "output": "1" }, { "input": "2\n999", "output": "249001" }, { "input": "2\n998", "output": "248502" }, { "input": "999\n2", "output": "249001" }, { "input": "998\n2", "output": "248502" }, { "input": "2\n1000", "output": "249500" }, { "input": "1000\n2", "output": "249500" }, { "input": "1\n999", "output": "249500" }, { "input": "999\n1", "output": "249500" }, { "input": "188\n762", "output": "82656" }, { "input": "596\n777", "output": "8281" }, { "input": "773\n70", "output": "123904" }, { "input": "825\n729", "output": "2352" }, { "input": "944\n348", "output": "89102" }, { "input": "352\n445", "output": "2209" }, { "input": "529\n656", "output": "4096" }, { "input": "19\n315", "output": "22052" }, { "input": "138\n370", "output": "13572" }, { "input": "546\n593", "output": "576" }, { "input": "285\n242", "output": "484" }, { "input": "773\n901", "output": "4160" }, { "input": "892\n520", "output": "34782" }, { "input": "864\n179", "output": "117649" }, { "input": "479\n470", "output": "25" }, { "input": "967\n487", "output": "57840" }, { "input": "648\n106", "output": "73712" }, { "input": "58\n765", "output": "125316" }, { "input": "235\n56", "output": "8100" }, { "input": "285\n153", "output": "4422" }, { "input": "943\n13", "output": "216690" }, { "input": "675\n541", "output": "4556" }, { "input": "4\n912", "output": "206570" } ]

1,636,128,617

2,147,483,647

PyPy 3-64

OK

TESTS

40

62

28,364,800

a = int(input()) b = int(input()) diff = max(a,b) - min(a,b) summation = 0 if diff % 2== 0: for i in range(1,diff//2+1): summation += i summation *= 2 else: for i in range(1,diff//2+1): summation += i summation *= 2 summation += diff//2 + 1 print(summation)

Title: Friends Meeting Time Limit: None seconds Memory Limit: None megabytes Problem Description: Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*. Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the following rules: the first move increases the tiredness by 1, the second move increases the tiredness by 2, the third — by 3 and so on. For example, if a friend moves first to the left, then to the right (returning to the same point), and then again to the left his tiredness becomes equal to 1<=+<=2<=+<=3<==<=6. The friends want to meet in a integer point. Determine the minimum total tiredness they should gain, if they meet in the same point. Input Specification: The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend. The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend. It is guaranteed that *a*<=≠<=*b*. Output Specification: Print the minimum possible total tiredness if the friends meet in the same point. Demo Input: ['3\n4\n', '101\n99\n', '5\n10\n'] Demo Output: ['1\n', '2\n', '9\n'] Note: In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1. In the second example the first friend should move by one to the left, and the second friend should move by one to the right. Then they meet in the point 100, and the total tiredness becomes 1 + 1 = 2. In the third example one of the optimal ways is the following. The first friend should move three times to the right, and the second friend — two times to the left. Thus the friends meet in the point 8, and the total tiredness becomes 1 + 2 + 3 + 1 + 2 = 9.

```python a = int(input()) b = int(input()) diff = max(a,b) - min(a,b) summation = 0 if diff % 2== 0: for i in range(1,diff//2+1): summation += i summation *= 2 else: for i in range(1,diff//2+1): summation += i summation *= 2 summation += diff//2 + 1 print(summation) ```

3

584

A

Olesya and Rodion

PROGRAMMING

1,000

[ "math" ]

null

Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them. Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1.

The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by.

Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

[ "3 2\n" ]

[ "712" ]

none

500

[ { "input": "3 2", "output": "222" }, { "input": "2 2", "output": "22" }, { "input": "4 3", "output": "3333" }, { "input": "5 3", "output": "33333" }, { "input": "10 7", "output": "7777777777" }, { "input": "2 9", "output": "99" }, { "input": "18 8", "output": "888888888888888888" }, { "input": "1 5", "output": "5" }, { "input": "1 10", "output": "-1" }, { "input": "100 5", "output": "5555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555" }, { "input": "10 2", "output": "2222222222" }, { "input": "18 10", "output": "111111111111111110" }, { "input": "1 9", "output": "9" }, { "input": "7 6", "output": "6666666" }, { "input": "4 4", "output": "4444" }, { "input": "14 7", "output": "77777777777777" }, { "input": "3 8", "output": "888" }, { "input": "1 3", "output": "3" }, { "input": "2 8", "output": "88" }, { "input": "3 8", "output": "888" }, { "input": "4 3", "output": "3333" }, { "input": "5 9", "output": "99999" }, { "input": "4 8", "output": "8888" }, { "input": "3 4", "output": "444" }, { "input": "9 4", "output": "444444444" }, { "input": "8 10", "output": "11111110" }, { "input": "1 6", "output": "6" }, { "input": "20 3", "output": "33333333333333333333" }, { "input": "15 10", "output": "111111111111110" }, { "input": "31 4", "output": "4444444444444444444444444444444" }, { "input": "18 9", "output": "999999999999999999" }, { "input": "72 4", "output": "444444444444444444444444444444444444444444444444444444444444444444444444" }, { "input": "76 8", "output": "8888888888888888888888888888888888888888888888888888888888888888888888888888" }, { "input": "12 5", "output": "555555555555" }, { "input": "54 5", "output": "555555555555555555555555555555555555555555555555555555" }, { "input": "96 10", "output": "111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111110" }, { "input": "15 9", "output": "999999999999999" }, { "input": "100 2", "output": "2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222" }, { "input": "99 3", "output": "333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333" }, { "input": "98 4", "output": "44444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444" }, { "input": "97 5", "output": "5555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555" }, { "input": "100 6", "output": "6666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666" }, { "input": "99 7", "output": "777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777" }, { "input": "98 8", "output": "88888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888" }, { "input": "97 9", "output": "9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999" }, { "input": "100 10", "output": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111110" }, { "input": "3 10", "output": "110" }, { "input": "2 4", "output": "44" }, { "input": "2 10", "output": "10" }, { "input": "10 10", "output": "1111111110" }, { "input": "4 10", "output": "1110" }, { "input": "25 10", "output": "1111111111111111111111110" }, { "input": "50 10", "output": "11111111111111111111111111111111111111111111111110" }, { "input": "5 10", "output": "11110" }, { "input": "99 10", "output": "111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111110" }, { "input": "100 10", "output": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111110" }, { "input": "1 2", "output": "2" }, { "input": "20 10", "output": "11111111111111111110" }, { "input": "99 7", "output": "777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777" }, { "input": "89 5", "output": "55555555555555555555555555555555555555555555555555555555555555555555555555555555555555555" }, { "input": "6 10", "output": "111110" }, { "input": "3 8", "output": "888" }, { "input": "1 9", "output": "9" }, { "input": "1 4", "output": "4" }, { "input": "100 7", "output": "7777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777" } ]

1,679,168,842

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

2

31

0

emp = list(map(int,input().split(" "))) stellen = emp[0] teiler = emp[1] ende = 10**stellen rest = 10%teiler if rest == 0: if teiler < 10**stellen - 10**(stellen-1): print(ende-teiler) else: print(-1) else: if rest < 10**stellen - 10**(stellen-1): print(-1) else: print(ende-rest)

Title: Olesya and Rodion Time Limit: None seconds Memory Limit: None megabytes Problem Description: Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them. Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1. Input Specification: The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. Output Specification: Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. Demo Input: ['3 2\n'] Demo Output: ['712'] Note: none

```python emp = list(map(int,input().split(" "))) stellen = emp[0] teiler = emp[1] ende = 10**stellen rest = 10%teiler if rest == 0: if teiler < 10**stellen - 10**(stellen-1): print(ende-teiler) else: print(-1) else: if rest < 10**stellen - 10**(stellen-1): print(-1) else: print(ende-rest) ```

0

935

A

Fafa and his Company

PROGRAMMING

800

[ "brute force", "implementation" ]

null

Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees. Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* employees in his company as team leaders. Whenever there is a new project, Fafa will divide the tasks among only the team leaders and each team leader will be responsible of some positive number of employees to give them the tasks. To make this process fair for the team leaders, each one of them should be responsible for the same number of employees. Moreover, every employee, who is not a team leader, has to be under the responsibility of exactly one team leader, and no team leader is responsible for another team leader. Given the number of employees *n*, find in how many ways Fafa could choose the number of team leaders *l* in such a way that it is possible to divide employees between them evenly.

The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company.

Print a single integer representing the answer to the problem.

[ "2\n", "10\n" ]

[ "1\n", "3\n" ]

In the second sample Fafa has 3 ways: - choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them.

500

[ { "input": "2", "output": "1" }, { "input": "10", "output": "3" }, { "input": "3", "output": "1" }, { "input": "4", "output": "2" }, { "input": "6", "output": "3" }, { "input": "13", "output": "1" }, { "input": "100000", "output": "35" }, { "input": "1024", "output": "10" }, { "input": "99999", "output": "11" }, { "input": "10007", "output": "1" }, { "input": "4096", "output": "12" }, { "input": "65536", "output": "16" }, { "input": "40320", "output": "95" }, { "input": "30030", "output": "63" }, { "input": "161", "output": "3" }, { "input": "1000", "output": "15" }, { "input": "10000", "output": "24" }, { "input": "777", "output": "7" }, { "input": "121", "output": "2" }, { "input": "25", "output": "2" }, { "input": "40000", "output": "34" }, { "input": "99990", "output": "47" }, { "input": "98765", "output": "3" }, { "input": "56789", "output": "3" }, { "input": "13579", "output": "3" }, { "input": "97531", "output": "3" }, { "input": "12345", "output": "7" }, { "input": "54321", "output": "7" }, { "input": "83160", "output": "127" }, { "input": "9", "output": "2" }, { "input": "21", "output": "3" }, { "input": "11", "output": "1" }, { "input": "15", "output": "3" } ]

1,668,945,298

2,147,483,647

Python 3

OK

TESTS

33

46

0

#4 n=int(input()) c=-1 for i in range(1,n+1): if(n%i==0): c=c+1 print(c)

Title: Fafa and his Company Time Limit: None seconds Memory Limit: None megabytes Problem Description: Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees. Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* employees in his company as team leaders. Whenever there is a new project, Fafa will divide the tasks among only the team leaders and each team leader will be responsible of some positive number of employees to give them the tasks. To make this process fair for the team leaders, each one of them should be responsible for the same number of employees. Moreover, every employee, who is not a team leader, has to be under the responsibility of exactly one team leader, and no team leader is responsible for another team leader. Given the number of employees *n*, find in how many ways Fafa could choose the number of team leaders *l* in such a way that it is possible to divide employees between them evenly. Input Specification: The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. Output Specification: Print a single integer representing the answer to the problem. Demo Input: ['2\n', '10\n'] Demo Output: ['1\n', '3\n'] Note: In the second sample Fafa has 3 ways: - choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them.

```python #4 n=int(input()) c=-1 for i in range(1,n+1): if(n%i==0): c=c+1 print(c) ```

3

832

B

Petya and Exam

PROGRAMMING

1,600

[ "implementation", "strings" ]

null

It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, *n* query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad.

The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern — a string *s* of lowercase English letters, characters "?" and "*" (1<=≤<=|*s*|<=≤<=105). It is guaranteed that character "*" occurs in *s* no more than once. The third line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of query strings. *n* lines follow, each of them contains single non-empty string consisting of lowercase English letters — a query string. It is guaranteed that the total length of all query strings is not greater than 105.

Print *n* lines: in the *i*-th of them print "YES" if the pattern matches the *i*-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary.

[ "ab\na?a\n2\naaa\naab\n", "abc\na?a?a*\n4\nabacaba\nabaca\napapa\naaaaax\n" ]

[ "YES\nNO\n", "NO\nYES\nNO\nYES\n" ]

In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. - The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. - The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. - The third query: "NO", because characters "?" can't be replaced with bad letters. - The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".

1,000

[ { "input": "ab\na?a\n2\naaa\naab", "output": "YES\nNO" }, { "input": "abc\na?a?a*\n4\nabacaba\nabaca\napapa\naaaaax", "output": "NO\nYES\nNO\nYES" }, { "input": "s\nc*?cb\n26\nbbaa\nb\ncc\ncbaab\nacacc\nca\na\nc\ncb\nabb\nba\nb\nba\ncac\nccccb\nccb\nbbbc\nabbcb\na\nbc\nc\na\nabb\nca\ncacb\nac", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "o\n*\n28\nbac\nbcc\ncbcb\ncaabc\ncb\nacab\ncbccb\ncbccc\nc\nbbaa\ncaaaa\nbbc\nba\nc\ncacbc\ncbab\naa\nac\nacc\na\nac\nbac\naaac\nba\nabbbb\nbbcc\nbaacb\naabaa", "output": "YES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES\nYES" }, { "input": "u\n*b??c\n23\na\nbcbcc\nacb\na\nbacaa\nbb\nb\nbcba\ncbbcc\nb\nabbb\nbcacb\nabcb\ncbca\nb\ncba\ncabcb\nbc\ncc\naaacc\nccac\ncc\nccbcb", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "g\nc?*\n58\nb\ncaac\nbbc\nabb\ncaccc\ncb\naba\nbcaa\ncca\ncbbcb\ncac\nbbaca\nbcba\nbba\nabbab\nccc\nc\nbcb\naac\nbcbbc\nbca\nc\ncbb\nccabb\naaccc\nccaa\nc\nc\nbcca\naa\nccb\ncb\ncbcb\ncc\nab\ncccc\nbbbab\nbab\na\nc\ncbba\nbbacb\naa\nb\nbaab\nacabb\nbcbab\ncbbcb\nbc\ncccba\naa\ncccca\ncacc\naacbb\na\nc\nab\nccca", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "g\nbc*a\n40\nbabac\nccbb\ncacbc\nc\na\naba\nbc\na\nba\nbbcca\nccbac\na\nc\nbabc\ncccbc\nab\nabca\nccb\nacbbb\nb\nbbac\naa\nb\nca\nbc\naaba\nbaaaa\nbcc\nab\na\naba\nb\nc\nba\nbc\nca\nbb\nc\nc\nca", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "g\n*cc?\n93\nac\ncaab\nacaca\ncccc\nbcc\nbab\nbc\nc\nc\nbbaa\nb\ncc\ncb\naa\nabcbb\nbccc\nc\ncbcbc\nac\nca\nbcba\nbb\nbab\nba\nb\nbbba\nbabbc\nbacab\nbc\na\ncbccc\nbbaac\ncbab\ncab\ncc\ncbbcb\nc\nc\ncbaa\nca\nbacab\nc\nbcac\nbbbc\nc\nac\nccab\nccccb\ncccab\nc\nacb\nac\nbccba\nca\nbbbbc\naaca\naa\na\nbabac\nbb\nc\ncac\naca\naacb\naacbb\na\nacaab\ncbb\nbcc\ncb\nbcbaa\ncca\nb\nbaac\nbcca\nc\ncbb\nac\nc\naccc\naac\nbcbc\nabc\nbacab\nb\na\na\nbbacc\ncb\na\nccac\nb\nbbc", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "c\n*\n83\nbbc\ncacb\nbcbc\naca\nba\nc\nccac\nab\nab\nbacba\nbb\nc\nbcc\nc\ncbc\ncbbb\nac\nb\nacbcb\nbccc\ncccb\nb\na\nca\nc\nccaa\naa\ncacb\nccc\na\nccc\nababb\nbab\ncaa\nbaa\na\ncc\ncbbbc\naaaa\nabbab\naabac\nbcbab\nbcb\nacaa\nbcb\na\ncca\na\nbacc\nacacb\nc\nc\ncba\nbcaca\na\ncaac\na\nb\na\nccc\naabca\nbbab\nb\nac\nbabc\nc\nac\nba\nbbcb\nc\naaab\ncab\nacb\nbba\nbbcba\nc\na\naccbb\naaccc\nac\nbaa\nbaabb\nabca", "output": "NO\nNO\nNO\nNO\nYES\nNO\nNO\nYES\nYES\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nYES\nYES\nNO\nNO\nNO\nYES\nNO\nNO\nYES\nNO\nYES\nYES\nNO\nYES\nYES\nNO\nNO\nYES\nYES\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nYES\nYES\nYES\nNO\nNO\nYES\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nYES\nNO\nNO\nYES\nNO\nNO\nYES\nNO\nNO\nNO\nYES\nYES\nNO" }, { "input": "s\n*cb\n70\nab\nccb\naaab\nb\nab\ncba\na\nbbaca\nac\nccacb\nbaabb\naaab\nccca\ncb\nba\nbccac\nc\ncc\ncbbbb\ncab\nabbb\ncbb\naabc\ncac\nacb\na\nc\nc\ncbbbb\nbaaca\ncbcc\nbc\naa\nabcb\nacbbc\nbaaa\naa\ncc\ncc\nb\nb\nbcba\ncbacc\nbcb\ncaabc\nacaac\ncb\ncba\ncbaaa\nbcaaa\naccbb\naccac\nca\nacaa\ncc\nc\nb\nbac\nb\nbab\nb\ncca\naacc\nacb\nccc\nbc\nb\naab\naaca\naac", "output": "NO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "k\n*b\n70\ncbc\nb\ncca\nacbc\nca\nab\nc\nbbb\nbaa\nbbb\nac\nbaacc\nbaabc\naac\na\nba\nb\nc\nc\nba\ncacbb\nabb\nbc\nabcb\nca\na\nbbbbb\ncca\nccacc\ncbaca\nba\ncbcca\ncb\nc\nbbbba\ncca\nabaac\na\nac\nc\nccbc\nbcac\nbcb\na\nc\nabbca\nbaacb\ncc\nacba\nc\nbcc\ncbba\nccba\na\na\ncbb\ncba\nb\naaaac\ncb\nbaacb\nab\nc\ncbbcb\nbab\nac\nca\nc\nac\nb", "output": "NO\nYES\nNO\nNO\nNO\nYES\nNO\nYES\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nYES\nYES\nNO\nYES\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nYES\nNO\nYES\nYES\nYES\nNO\nYES\nYES\nNO\nNO\nNO\nNO\nYES" }, { "input": "l\na*\n40\nacbb\naba\nb\naab\nbb\nbbab\ncaba\naab\naaab\nacac\nacbaa\nbca\nac\nbb\na\nba\naaa\nbc\nbba\ncca\naacab\na\nc\nca\naacaa\nbaac\nbb\nc\nba\nc\nbab\nb\na\ncabaa\nccacc\ncbbab\nbaaca\ncabb\naaccc\nbcbac", "output": "YES\nYES\nNO\nYES\nNO\nNO\nNO\nYES\nYES\nYES\nYES\nNO\nYES\nNO\nYES\nNO\nYES\nNO\nNO\nNO\nYES\nYES\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nYES\nNO" }, { "input": "u\ncba*\n26\ncaa\ncccb\nbc\nbacb\nca\nccaaa\nb\naaca\nba\ncacc\ncccac\nabba\nbabc\na\nac\nca\nbbba\na\naa\naaabb\nb\nc\nbba\nbbba\nacaa\nba", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "cba\n?*cbc\n88\ncccca\ncbc\nb\nbcb\naaa\ncaac\nbacb\nacbb\na\nab\ncbcca\nbccc\nabcc\naca\nba\nbbac\nacc\ncba\nbcba\nbc\naa\nab\ncaba\ncccab\ncba\ncbcc\nba\ncacbb\nabcc\na\nc\nbac\nccaba\nb\nac\nbbb\nac\nccaca\na\nba\nacbcc\nbbc\nacbc\nbbabc\nccbb\nb\nacaa\na\nba\nacb\na\nab\naa\nbbbb\naabb\nbcbc\nb\nca\nb\nccab\nab\nc\nb\naabab\nc\ncbbbc\nacbbb\nbacaa\nbcccc\ncbac\nc\nac\nb\nca\ncbb\nccbc\nc\nc\nbcb\nc\nbaaba\nc\nbac\nb\nba\ncb\ncc\nbaaca", "output": "NO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO\nNO" }, { "input": "a\naa\n1\naaa", "output": "NO" }, { "input": "a\naaa\n1\naaaa", "output": "NO" }, { "input": "a\naa*aa\n1\naaa", "output": "NO" }, { "input": "a\nbb*bb\n1\nbbbbbbbbbbbbbbbb", "output": "YES" }, { "input": "a\na*\n1\nabbbbbbb", "output": "YES" }, { "input": "a\na?a\n1\naaab", "output": "NO" }, { "input": "xy\ncab*aba\n1\ncaba", "output": "NO" }, { "input": "a\n*\n4\nb\na\nab\nba", "output": "YES\nNO\nNO\nNO" }, { "input": "abc\na?a?*a\n3\nababxa\nababca\nababa", "output": "YES\nNO\nYES" }, { "input": "abc\n??a*df?c\n6\nabadfcc\naaaadfac\nbbagthfac\nacadddfac\ndaagdffc\naaaadfcc", "output": "YES\nNO\nNO\nYES\nNO\nNO" }, { "input": "abc\nabc*a\n1\nabckka", "output": "YES" }, { "input": "b\n*a\n1\naba", "output": "NO" }, { "input": "a\nabc*g\n1\nabcdefg", "output": "YES" }, { "input": "a\nab\n1\na", "output": "NO" }, { "input": "abcdefghijklmnopqrstuvwxyz\n*a\n1\na", "output": "YES" }, { "input": "as\naba*aba\n1\naba", "output": "NO" }, { "input": "ab\naweerrtab\n4\naw\naweerrtabwqeqrw\naweerrtabxcvxcbcxbdsfdsfewrewrqweq\naweerrtabaaaaaaaaaaaaaaaaaaaaaaaaaaaaa", "output": "NO\nNO\nNO\nNO" }, { "input": "a\na\n1\nab", "output": "NO" }, { "input": "a\na*b\n1\nabb", "output": "YES" }, { "input": "a\nb*a\n1\nbbadd", "output": "NO" }, { "input": "a\naaaa\n1\naaa", "output": "NO" }, { "input": "z\n*abcd\n1\nggggggg", "output": "NO" }, { "input": "abc\n*??\n1\nqqqqqqqqab", "output": "YES" }, { "input": "b\naa\n1\na", "output": "NO" }, { "input": "ab\na*pa\n1\nappppa", "output": "YES" }, { "input": "a\nbbb\n1\nbbbbb", "output": "NO" }, { "input": "ab\nabcd?\n1\nabcd", "output": "NO" }, { "input": "c\na\n1\nab", "output": "NO" } ]

1,683,470,497

2,147,483,647

PyPy 3-64

WRONG_ANSWER

TESTS

3

61

0

gd = input() og = input() t = int(input()) while t : t -= 1 do = 1 tc = input() if len(tc) > len(og) : print("NO") continue if '*' in og : if len(tc) != len(og) and len(tc) != len(og)-1 : print("NO") continue else : if len(tc) != len(og) : print("NO") continue if len(og) > len(tc) : i = 0 j = 0 while i < len(og) : if og[i] == '*' : i += 1 continue if og[i].isalpha() : if og[i] != tc[i] : print("NO") do = 0 break else : if tc[i] not in gd : print("NO") do = 0 break i += 1 j += 1 else : i = 0 j = 0 while i < len(og) : if og[i].isalpha() : if og[i] != tc[i] : print("NO") do = 0 break elif og[i] == '?': if tc[i] not in gd : print("NO") do = 0 break else : if tc[i] in gd : print("NO") do = 0 break i += 1 j += 1 if do : print('YES')

Title: Petya and Exam Time Limit: None seconds Memory Limit: None megabytes Problem Description: It's hard times now. Today Petya needs to score 100 points on Informatics exam. The tasks seem easy to Petya, but he thinks he lacks time to finish them all, so he asks you to help with one.. There is a glob pattern in the statements (a string consisting of lowercase English letters, characters "?" and "*"). It is known that character "*" occurs no more than once in the pattern. Also, *n* query strings are given, it is required to determine for each of them if the pattern matches it or not. Everything seemed easy to Petya, but then he discovered that the special pattern characters differ from their usual meaning. A pattern matches a string if it is possible to replace each character "?" with one good lowercase English letter, and the character "*" (if there is one) with any, including empty, string of bad lowercase English letters, so that the resulting string is the same as the given string. The good letters are given to Petya. All the others are bad. Input Specification: The first line contains a string with length from 1 to 26 consisting of distinct lowercase English letters. These letters are good letters, all the others are bad. The second line contains the pattern — a string *s* of lowercase English letters, characters "?" and "*" (1<=≤<=|*s*|<=≤<=105). It is guaranteed that character "*" occurs in *s* no more than once. The third line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of query strings. *n* lines follow, each of them contains single non-empty string consisting of lowercase English letters — a query string. It is guaranteed that the total length of all query strings is not greater than 105. Output Specification: Print *n* lines: in the *i*-th of them print "YES" if the pattern matches the *i*-th query string, and "NO" otherwise. You can choose the case (lower or upper) for each letter arbitrary. Demo Input: ['ab\na?a\n2\naaa\naab\n', 'abc\na?a?a*\n4\nabacaba\nabaca\napapa\naaaaax\n'] Demo Output: ['YES\nNO\n', 'NO\nYES\nNO\nYES\n'] Note: In the first example we can replace "?" with good letters "a" and "b", so we can see that the answer for the first query is "YES", and the answer for the second query is "NO", because we can't match the third letter. Explanation of the second example. - The first query: "NO", because character "*" can be replaced with a string of bad letters only, but the only way to match the query string is to replace it with the string "ba", in which both letters are good. - The second query: "YES", because characters "?" can be replaced with corresponding good letters, and character "*" can be replaced with empty string, and the strings will coincide. - The third query: "NO", because characters "?" can't be replaced with bad letters. - The fourth query: "YES", because characters "?" can be replaced with good letters "a", and character "*" can be replaced with a string of bad letters "x".

```python gd = input() og = input() t = int(input()) while t : t -= 1 do = 1 tc = input() if len(tc) > len(og) : print("NO") continue if '*' in og : if len(tc) != len(og) and len(tc) != len(og)-1 : print("NO") continue else : if len(tc) != len(og) : print("NO") continue if len(og) > len(tc) : i = 0 j = 0 while i < len(og) : if og[i] == '*' : i += 1 continue if og[i].isalpha() : if og[i] != tc[i] : print("NO") do = 0 break else : if tc[i] not in gd : print("NO") do = 0 break i += 1 j += 1 else : i = 0 j = 0 while i < len(og) : if og[i].isalpha() : if og[i] != tc[i] : print("NO") do = 0 break elif og[i] == '?': if tc[i] not in gd : print("NO") do = 0 break else : if tc[i] in gd : print("NO") do = 0 break i += 1 j += 1 if do : print('YES') ```

0

462

B

Appleman and Card Game

PROGRAMMING

1,300

[ "greedy" ]

null

Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to letter on *i*th, then sum up all these quantities, such a number of coins Appleman should give to Toastman. Given the description of Appleman's cards. What is the maximum number of coins Toastman can get?

The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman.

Print a single integer – the answer to the problem.

[ "15 10\nDZFDFZDFDDDDDDF\n", "6 4\nYJSNPI\n" ]

[ "82\n", "4\n" ]

In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin.

1,000

[ { "input": "15 10\nDZFDFZDFDDDDDDF", "output": "82" }, { "input": "6 4\nYJSNPI", "output": "4" }, { "input": "5 3\nAOWBY", "output": "3" }, { "input": "1 1\nV", "output": "1" }, { "input": "2 1\nWT", "output": "1" }, { "input": "2 2\nBL", "output": "2" }, { "input": "5 1\nFACJT", "output": "1" }, { "input": "5 5\nMJDIJ", "output": "7" }, { "input": "15 5\nAZBIPTOFTJCJJIK", "output": "13" }, { "input": "100 1\nEVEEVEEEGGECFEHEFVFVFHVHEEEEEFCVEEEEEEVFVEEVEEHEEVEFEVVEFEEEFEVECEHGHEEFGEEVCEECCECEFHEVEEEEEEGEEHVH", "output": "1" }, { "input": "100 15\nKKTFFUTFCKUIKKKKFIFFKTUKUUKUKKIKKKTIFKTKUCFFKKKIIKKKKKKTFKFKKIRKKKFKUUKIKUUUFFKKKKTUZKITUIKKIKUKKTIK", "output": "225" }, { "input": "100 50\nYYIYYAAAIEAAYAYAEAIIIAAEAAYEAEYYYIAEYAYAYYAAAIAYAEAAYAYYIYAAYYAAAAAAIYYYAAYAAEAAYAIEIYIYAYAYAYIIAAEY", "output": "1972" }, { "input": "100 90\nFAFAOOAOOAFAOTFAFAFFATAAAOFAAOAFBAAAFBOAOFFFOAOAFAPFOFAOFAAFOAAAAFAAFOFAAOFPPAAOOAAOOFFOFFFOFAOTOFAF", "output": "2828" }, { "input": "100 99\nBFFBBFBFBQFFFFFQBFFBFFBQFBFQFBBFQFFFBFFFBFQFQFBFFBBFYQFBFFFFFFFBQQFQBFBQBQFFFBQQFFFBQFYFBFBFFFBBBQQY", "output": "3713" }, { "input": "100 100\nMQSBDAJABILIBCUEOWGWCEXMUTEYQKAIWGINXVQEOFDUBSVULROQHQRZZAALVQFEFRAAAYUIMGCAFQGIAEFBETRECGSFQJNXHHDN", "output": "514" }, { "input": "100 50\nBMYIXQSJNHGFVFPJBIOBXIKSFNUFPVODCUBQYSIIQNVNXXCWXWRHKFEUPPIIDDGRDBJLZDCBMNJMYRMWFIHOSTDJJHXHPNRKWNFD", "output": "328" }, { "input": "100 50\nENFNEMLJEMDMFMNNGNIMNINALGLLLAEMENEMNLMMIEIJNAINBJEJMFJLLIMINELGFLAIAMJMHMGNLIEFJIEEFEFGLLLDLMEAEIMM", "output": "748" } ]

1,629,031,159

2,147,483,647

Python 3

OK

TESTS

41

124

7,270,400

nk = list(map(int, input().rstrip().split())) s=input() count=[] st=[] for i in s: if i in st: count[st.index(i)]+=1 else: st.append(i) count.append(1) count.sort() count.reverse() s=0 ans=0 for i in count: s=s+i if s<=nk[1]: ans+=i*i else: s=s-i ans+=(nk[1]-s)*(nk[1]-s) break print(ans)

Title: Appleman and Card Game Time Limit: None seconds Memory Limit: None megabytes Problem Description: Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to letter on *i*th, then sum up all these quantities, such a number of coins Appleman should give to Toastman. Given the description of Appleman's cards. What is the maximum number of coins Toastman can get? Input Specification: The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. Output Specification: Print a single integer – the answer to the problem. Demo Input: ['15 10\nDZFDFZDFDDDDDDF\n', '6 4\nYJSNPI\n'] Demo Output: ['82\n', '4\n'] Note: In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin.

```python nk = list(map(int, input().rstrip().split())) s=input() count=[] st=[] for i in s: if i in st: count[st.index(i)]+=1 else: st.append(i) count.append(1) count.sort() count.reverse() s=0 ans=0 for i in count: s=s+i if s<=nk[1]: ans+=i*i else: s=s-i ans+=(nk[1]-s)*(nk[1]-s) break print(ans) ```

3

81

A

Plug-in

PROGRAMMING

1,400

[ "implementation" ]

A. Plug-in

1

256

Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yyoouu". Polycarp decided to automate the process of correcting such errors. He decided to write a plug-in to the text editor that will remove pairs of identical consecutive letters (if there are any in the text). Of course, this is not exactly what Polycarp needs, but he's got to start from something! Help Polycarp and write the main plug-in module. Your program should remove from a string all pairs of identical letters, which are consecutive. If after the removal there appear new pairs, the program should remove them as well. Technically, its work should be equivalent to the following: while the string contains a pair of consecutive identical letters, the pair should be deleted. Note that deleting of the consecutive identical letters can be done in any order, as any order leads to the same result.

The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters.

Print the given string after it is processed. It is guaranteed that the result will contain at least one character.

[ "hhoowaaaareyyoouu\n", "reallazy\n", "abacabaabacabaa\n" ]

[ "wre", "rezy", "a" ]

none

500

[ { "input": "hhoowaaaareyyoouu", "output": "wre" }, { "input": "reallazy", "output": "rezy" }, { "input": "abacabaabacabaa", "output": "a" }, { "input": "xraccabccbry", "output": "xy" }, { "input": "a", "output": "a" }, { "input": "b", "output": "b" }, { "input": "il", "output": "il" }, { "input": "gfj", "output": "gfj" }, { "input": "babbbbbababa", "output": "babababa" }, { "input": "babbbbabbabbbababbabbbbbbabaabaababaaabbbbbabbbbaaaaabbaaabbaabaabbbbabbbababbabaaabbababaaababbbaaa", "output": "babababababababababababa" }, { "input": "aab", "output": "b" }, { "input": "abb", "output": "a" }, { "input": "aba", "output": "aba" }, { "input": "ab", "output": "ab" } ]

1,685,891,384

2,147,483,647

Python 3

OK

TESTS

32

278

5,427,200

# ===== PROGRAMA PRINCIPAL ===== # cad = input() pila = [] for c in cad: pila.append(c) ## Solucion aux = [] # Creamos una pila auxiliar while len(pila) > 1: # Sacamos dos valores de la pila para comparar cad1 = pila.pop() cad2 = pila.pop() if cad1 == cad2: ok = True while(ok == True): pilaX = -1; auxY = -1 if len(pila) > 0: pilaX = pila.pop() if len(aux) > 0: auxY = aux.pop() if pilaX == -1 and auxY != -1: aux.append(auxY) ok = False elif pilaX != -1 and auxY == -1: pila.append(pilaX) ok = False elif pilaX == -1 and auxY == -1: ok = False # Preguntamos else: if pilaX != auxY: aux.append(auxY) pila.append(pilaX) ok = False else: pila.append(cad2) aux.append(cad1) # Para el ultimo caso if len(pila) > 0: x = pila.pop() if len(aux) > 0: y = aux.pop() if x != y: aux.append(y) aux.append(x) else: aux.append(x) # Dando la vuelta los valores de Pila revesedPila = aux[::-1] print("".join(revesedPila))

Title: Plug-in Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yyoouu". Polycarp decided to automate the process of correcting such errors. He decided to write a plug-in to the text editor that will remove pairs of identical consecutive letters (if there are any in the text). Of course, this is not exactly what Polycarp needs, but he's got to start from something! Help Polycarp and write the main plug-in module. Your program should remove from a string all pairs of identical letters, which are consecutive. If after the removal there appear new pairs, the program should remove them as well. Technically, its work should be equivalent to the following: while the string contains a pair of consecutive identical letters, the pair should be deleted. Note that deleting of the consecutive identical letters can be done in any order, as any order leads to the same result. Input Specification: The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters. Output Specification: Print the given string after it is processed. It is guaranteed that the result will contain at least one character. Demo Input: ['hhoowaaaareyyoouu\n', 'reallazy\n', 'abacabaabacabaa\n'] Demo Output: ['wre', 'rezy', 'a'] Note: none

```python # ===== PROGRAMA PRINCIPAL ===== # cad = input() pila = [] for c in cad: pila.append(c) ## Solucion aux = [] # Creamos una pila auxiliar while len(pila) > 1: # Sacamos dos valores de la pila para comparar cad1 = pila.pop() cad2 = pila.pop() if cad1 == cad2: ok = True while(ok == True): pilaX = -1; auxY = -1 if len(pila) > 0: pilaX = pila.pop() if len(aux) > 0: auxY = aux.pop() if pilaX == -1 and auxY != -1: aux.append(auxY) ok = False elif pilaX != -1 and auxY == -1: pila.append(pilaX) ok = False elif pilaX == -1 and auxY == -1: ok = False # Preguntamos else: if pilaX != auxY: aux.append(auxY) pila.append(pilaX) ok = False else: pila.append(cad2) aux.append(cad1) # Para el ultimo caso if len(pila) > 0: x = pila.pop() if len(aux) > 0: y = aux.pop() if x != y: aux.append(y) aux.append(x) else: aux.append(x) # Dando la vuelta los valores de Pila revesedPila = aux[::-1] print("".join(revesedPila)) ```

3.850891

981

A

Antipalindrome

PROGRAMMING

900

[ "brute force", "implementation", "strings" ]

null

A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not. A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2} \ldots s_{|s|}$ is the string $s_{l}s_{l<=+<=1} \ldots s_{r}$. Anna does not like palindromes, so she makes her friends call her Ann. She also changes all the words she reads in a similar way. Namely, each word $s$ is changed into its longest substring that is not a palindrome. If all the substrings of $s$ are palindromes, she skips the word at all. Some time ago Ann read the word $s$. What is the word she changed it into?

The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only.

If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$. Note that there can be multiple longest substrings that are not palindromes, but their length is unique.

[ "mew\n", "wuffuw\n", "qqqqqqqq\n" ]

[ "3\n", "5\n", "0\n" ]

"mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$. The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$. All substrings of the string "qqqqqqqq" consist of equal characters so they are palindromes. This way, there are no non-palindrome substrings. Thus, the answer for the third example is $0$.

500

[ { "input": "mew", "output": "3" }, { "input": "wuffuw", "output": "5" }, { "input": "qqqqqqqq", "output": "0" }, { "input": "ijvji", "output": "4" }, { "input": "iiiiiii", "output": "0" }, { "input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow", "output": "49" }, { "input": "wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww", "output": "0" }, { "input": "wobervhvvkihcuyjtmqhaaigvahheoqleromusrartldojsjvy", "output": "50" }, { "input": "ijvxljt", "output": "7" }, { "input": "fyhcncnchyf", "output": "10" }, { "input": "ffffffffffff", "output": "0" }, { "input": "fyhcncfsepqj", "output": "12" }, { "input": "ybejrrlbcinttnicblrrjeby", "output": "23" }, { "input": "yyyyyyyyyyyyyyyyyyyyyyyyy", "output": "0" }, { "input": "ybejrrlbcintahovgjddrqatv", "output": "25" }, { "input": "oftmhcmclgyqaojljoaqyglcmchmtfo", "output": "30" }, { "input": "oooooooooooooooooooooooooooooooo", "output": "0" }, { "input": "oftmhcmclgyqaojllbotztajglsmcilv", "output": "32" }, { "input": "gxandbtgpbknxvnkjaajknvxnkbpgtbdnaxg", "output": "35" }, { "input": "gggggggggggggggggggggggggggggggggggg", "output": "0" }, { "input": "gxandbtgpbknxvnkjaygommzqitqzjfalfkk", "output": "36" }, { "input": "fcliblymyqckxvieotjooojtoeivxkcqymylbilcf", "output": "40" }, { "input": "fffffffffffffffffffffffffffffffffffffffffff", "output": "0" }, { "input": "fcliblymyqckxvieotjootiqwtyznhhvuhbaixwqnsy", "output": "43" }, { "input": "rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr", "output": "0" }, { "input": "rajccqwqnqmshmerpvjyfepxwpxyldzpzhctqjnstxyfmlhiy", "output": "49" }, { "input": "a", "output": "0" }, { "input": "abca", "output": "4" }, { "input": "aaaaabaaaaa", "output": "10" }, { "input": "aba", "output": "2" }, { "input": "asaa", "output": "4" }, { "input": "aabaa", "output": "4" }, { "input": "aabbaa", "output": "5" }, { "input": "abcdaaa", "output": "7" }, { "input": "aaholaa", "output": "7" }, { "input": "abcdefghijka", "output": "12" }, { "input": "aaadcba", "output": "7" }, { "input": "aaaabaaaa", "output": "8" }, { "input": "abaa", "output": "4" }, { "input": "abcbaa", "output": "6" }, { "input": "ab", "output": "2" }, { "input": "l", "output": "0" }, { "input": "aaaabcaaaa", "output": "10" }, { "input": "abbaaaaaabba", "output": "11" }, { "input": "abaaa", "output": "5" }, { "input": "baa", "output": "3" }, { "input": "aaaaaaabbba", "output": "11" }, { "input": "ccbcc", "output": "4" }, { "input": "bbbaaab", "output": "7" }, { "input": "abaaaaaaaa", "output": "10" }, { "input": "abaaba", "output": "5" }, { "input": "aabsdfaaaa", "output": "10" }, { "input": "aaaba", "output": "5" }, { "input": "aaabaaa", "output": "6" }, { "input": "baaabbb", "output": "7" }, { "input": "ccbbabbcc", "output": "8" }, { "input": "cabc", "output": "4" }, { "input": "aabcd", "output": "5" }, { "input": "abcdea", "output": "6" }, { "input": "bbabb", "output": "4" }, { "input": "aaaaabababaaaaa", "output": "14" }, { "input": "bbabbb", "output": "6" }, { "input": "aababd", "output": "6" }, { "input": "abaaaa", "output": "6" }, { "input": "aaaaaaaabbba", "output": "12" }, { "input": "aabca", "output": "5" }, { "input": "aaabccbaaa", "output": "9" }, { "input": "aaaaaaaaaaaaaaaaaaaab", "output": "21" }, { "input": "babb", "output": "4" }, { "input": "abcaa", "output": "5" }, { "input": "qwqq", "output": "4" }, { "input": "aaaaaaaaaaabbbbbbbbbbbbbbbaaaaaaaaaaaaaaaaaaaaaa", "output": "48" }, { "input": "aaab", "output": "4" }, { "input": "aaaaaabaaaaa", "output": "12" }, { "input": "wwuww", "output": "4" }, { "input": "aaaaabcbaaaaa", "output": "12" }, { "input": "aaabbbaaa", "output": "8" }, { "input": "aabcbaa", "output": "6" }, { "input": "abccdefccba", "output": "11" }, { "input": "aabbcbbaa", "output": "8" }, { "input": "aaaabbaaaa", "output": "9" }, { "input": "aabcda", "output": "6" }, { "input": "abbca", "output": "5" }, { "input": "aaaaaabbaaa", "output": "11" }, { "input": "sssssspssssss", "output": "12" }, { "input": "sdnmsdcs", "output": "8" }, { "input": "aaabbbccbbbaaa", "output": "13" }, { "input": "cbdbdc", "output": "6" }, { "input": "abb", "output": "3" }, { "input": "abcdefaaaa", "output": "10" }, { "input": "abbbaaa", "output": "7" }, { "input": "v", "output": "0" }, { "input": "abccbba", "output": "7" }, { "input": "axyza", "output": "5" }, { "input": "abcdefgaaaa", "output": "11" }, { "input": "aaabcdaaa", "output": "9" }, { "input": "aaaacaaaa", "output": "8" }, { "input": "aaaaaaaaaaaaaaaaaaaabaaaaaaaaaaaaaaaaaaaaa", "output": "42" }, { "input": "abbbaa", "output": "6" }, { "input": "abcdee", "output": "6" }, { "input": "oom", "output": "3" }, { "input": "aabcaa", "output": "6" }, { "input": "abba", "output": "3" }, { "input": "aaca", "output": "4" }, { "input": "aacbca", "output": "6" }, { "input": "ababa", "output": "4" }, { "input": "abcda", "output": "5" }, { "input": "cccaaccc", "output": "7" }, { "input": "aaabcda", "output": "7" }, { "input": "aa", "output": "0" }, { "input": "aabaaaa", "output": "7" }, { "input": "abbaaaa", "output": "7" }, { "input": "aaabcbaaa", "output": "8" }, { "input": "aabba", "output": "5" }, { "input": "xyxx", "output": "4" }, { "input": "aaaaaaaaaaaabc", "output": "14" }, { "input": "bbaaaabb", "output": "7" }, { "input": "aaabaa", "output": "6" }, { "input": "sssssabsssss", "output": "12" }, { "input": "bbbaaaabbb", "output": "9" }, { "input": "abbbbaaaa", "output": "9" }, { "input": "wwufuww", "output": "6" }, { "input": "oowoo", "output": "4" }, { "input": "cccaccc", "output": "6" }, { "input": "aaa", "output": "0" }, { "input": "bbbcc", "output": "5" }, { "input": "abcdef", "output": "6" }, { "input": "abbba", "output": "4" }, { "input": "aab", "output": "3" }, { "input": "aaba", "output": "4" }, { "input": "azbyaaa", "output": "7" }, { "input": "oooooiooooo", "output": "10" }, { "input": "aabbbbbaaaaaa", "output": "13" } ]

1,547,274,857

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

28

109

0

a = input() b = '' if len(a)==1: print("0") exit() c = a[::-1] for j in range(len(a)-1): if a == c and a[j] != a[j+1]: print(len(a)-1) exit() elif a != c: print(len(a)) exit() elif a[j]==a[j+1]: print(0) exit()

Title: Antipalindrome Time Limit: None seconds Memory Limit: None megabytes Problem Description: A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not. A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2} \ldots s_{|s|}$ is the string $s_{l}s_{l<=+<=1} \ldots s_{r}$. Anna does not like palindromes, so she makes her friends call her Ann. She also changes all the words she reads in a similar way. Namely, each word $s$ is changed into its longest substring that is not a palindrome. If all the substrings of $s$ are palindromes, she skips the word at all. Some time ago Ann read the word $s$. What is the word she changed it into? Input Specification: The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. Output Specification: If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$. Note that there can be multiple longest substrings that are not palindromes, but their length is unique. Demo Input: ['mew\n', 'wuffuw\n', 'qqqqqqqq\n'] Demo Output: ['3\n', '5\n', '0\n'] Note: "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$. The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$. All substrings of the string "qqqqqqqq" consist of equal characters so they are palindromes. This way, there are no non-palindrome substrings. Thus, the answer for the third example is $0$.

```python a = input() b = '' if len(a)==1: print("0") exit() c = a[::-1] for j in range(len(a)-1): if a == c and a[j] != a[j+1]: print(len(a)-1) exit() elif a != c: print(len(a)) exit() elif a[j]==a[j+1]: print(0) exit() ```

0

424

B

Megacity

PROGRAMMING

1,200

[ "binary search", "greedy", "implementation", "sortings" ]

null

The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding the boundaries of the city. The city of Tomsk can be represented as point on the plane with coordinates (0; 0). The city is surrounded with *n* other locations, the *i*-th one has coordinates (*x**i*, *y**i*) with the population of *k**i* people. You can widen the city boundaries to a circle of radius *r*. In such case all locations inside the circle and on its border are included into the city. Your goal is to write a program that will determine the minimum radius *r*, to which is necessary to expand the boundaries of Tomsk, so that it becomes a megacity.

The first line of the input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=103; 1<=≤<=*s*<=<<=106) — the number of locatons around Tomsk city and the population of the city. Then *n* lines follow. The *i*-th line contains three integers — the *x**i* and *y**i* coordinate values of the *i*-th location and the number *k**i* of people in it (1<=≤<=*k**i*<=<<=106). Each coordinate is an integer and doesn't exceed 104 in its absolute value. It is guaranteed that no two locations are at the same point and no location is at point (0; 0).

In the output, print "-1" (without the quotes), if Tomsk won't be able to become a megacity. Otherwise, in the first line print a single real number — the minimum radius of the circle that the city needs to expand to in order to become a megacity. The answer is considered correct if the absolute or relative error don't exceed 10<=-<=6.

[ "4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1\n", "4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1\n", "2 1\n1 1 999997\n2 2 1\n" ]

[ "2.8284271\n", "1.4142136\n", "-1" ]

none

1,000

[ { "input": "4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1", "output": "2.8284271" }, { "input": "4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1", "output": "1.4142136" }, { "input": "2 1\n1 1 999997\n2 2 1", "output": "-1" }, { "input": "4 999998\n3 3 10\n-3 3 10\n3 -3 10\n-3 -3 10", "output": "4.2426407" }, { "input": "15 95473\n-9 6 199715\n0 -8 110607\n0 2 6621\n-3 -2 59894\n-10 -8 175440\n-2 0 25814\n10 -4 68131\n7 1 9971\n6 7 821\n6 5 20208\n6 2 68468\n0 7 37427\n1 -3 13337\n-10 7 113041\n-6 -2 44028", "output": "12.8062485" }, { "input": "20 93350\n13 -28 486\n26 -26 48487\n5 -23 143368\n-23 -25 10371\n-2 -7 75193\n0 -8 3\n-6 -11 5015\n-19 -18 315278\n28 -15 45801\n21 8 4590\n-4 -28 12926\n-16 17 9405\n-28 -23 222092\n1 -10 1857\n14 -28 35170\n-4 -22 22036\n-2 -10 1260\n-1 12 375745\n-19 -24 38845\n10 -25 9256", "output": "26.1725047" }, { "input": "30 505231\n-18 16 88130\n-10 16 15693\n16 -32 660\n-27 17 19042\n30 -37 6680\n36 19 299674\n-45 21 3300\n11 27 76\n-49 -34 28649\n-1 11 31401\n25 42 20858\n-40 6 455660\n-29 43 105001\n-38 10 6042\n19 -45 65551\n20 -9 148533\n-5 -24 393442\n-43 2 8577\n-39 18 97059\n12 28 39189\n35 23 28178\n40 -34 51687\n23 41 219028\n21 -44 927\n47 8 13206\n33 41 97342\n10 18 24895\n0 12 288\n0 -44 1065\n-25 43 44231", "output": "24.5153013" }, { "input": "2 500000\n936 1000 500000\n961 976 500000", "output": "1369.7065379" }, { "input": "10 764008\n959 32 23049\n-513 797 38979\n-603 -838 24916\n598 -430 25414\n-280 -624 18714\n330 891 21296\n-347 -68 27466\n650 -842 30125\n-314 889 35394\n275 969 5711", "output": "1063.7029661" }, { "input": "30 295830\n1 -4 24773\n4 3 26175\n-2 -3 14789\n2 -1 46618\n-2 -2 52997\n-3 0 517\n-2 0 18173\n-4 -3 54465\n2 4 63579\n4 -4 41821\n2 2 11018\n0 4 42856\n0 -1 51885\n-3 4 57137\n3 0 4688\n0 2 60137\n-4 4 33484\n-1 3 66196\n3 -1 53634\n0 -2 41630\n-2 1 54606\n2 -2 2978\n2 -3 23733\n1 -2 35248\n-3 -3 15124\n-2 -4 26518\n4 0 28151\n4 -1 18348\n3 3 16914\n-4 2 26013", "output": "4.4721360" }, { "input": "10 511500\n-5129 -3858 76954\n1296 1130 36126\n1219 6732 102003\n-8026 -178 4150\n-3261 1342 105429\n7965 -3013 62561\n5607 8963 53539\n-9044 -3999 16509\n1406 4103 115667\n-3716 2522 110626", "output": "6841.4753526" }, { "input": "20 39342\n2 0 36476\n-3 1 136925\n1 3 31234\n0 -3 23785\n-1 3 77700\n-3 -1 50490\n-1 -3 13965\n-3 2 121093\n3 0 118933\n-3 0 125552\n-3 3 54779\n-2 0 96250\n1 2 142643\n2 2 23848\n0 2 29845\n0 -2 80462\n-1 1 91852\n-1 2 26526\n0 -1 136272\n1 1 108999", "output": "3.0000000" }, { "input": "2 1\n1 0 1\n0 1 999999", "output": "1.0000000" }, { "input": "2 999997\n1 1 1\n1 2 1", "output": "-1" } ]

1,651,498,733

2,147,483,647

Python 3

OK

TESTS

54

46

0

import math def solve(): numLocation, totalPeople = map(int, input().split()) location = dict() for i in range(numLocation): x, y, people = map(int, input().split()) r = x * x + y * y if r in location: location[r] += people else: location[r] = people radius = [] for r in location: radius.append(r) radius.sort() for r in radius: totalPeople += location[r] if totalPeople >= 1000000: print(math.sqrt(r)) return print("-1") solve()

Title: Megacity Time Limit: None seconds Memory Limit: None megabytes Problem Description: The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding the boundaries of the city. The city of Tomsk can be represented as point on the plane with coordinates (0; 0). The city is surrounded with *n* other locations, the *i*-th one has coordinates (*x**i*, *y**i*) with the population of *k**i* people. You can widen the city boundaries to a circle of radius *r*. In such case all locations inside the circle and on its border are included into the city. Your goal is to write a program that will determine the minimum radius *r*, to which is necessary to expand the boundaries of Tomsk, so that it becomes a megacity. Input Specification: The first line of the input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=103; 1<=≤<=*s*<=<<=106) — the number of locatons around Tomsk city and the population of the city. Then *n* lines follow. The *i*-th line contains three integers — the *x**i* and *y**i* coordinate values of the *i*-th location and the number *k**i* of people in it (1<=≤<=*k**i*<=<<=106). Each coordinate is an integer and doesn't exceed 104 in its absolute value. It is guaranteed that no two locations are at the same point and no location is at point (0; 0). Output Specification: In the output, print "-1" (without the quotes), if Tomsk won't be able to become a megacity. Otherwise, in the first line print a single real number — the minimum radius of the circle that the city needs to expand to in order to become a megacity. The answer is considered correct if the absolute or relative error don't exceed 10<=-<=6. Demo Input: ['4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1\n', '4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1\n', '2 1\n1 1 999997\n2 2 1\n'] Demo Output: ['2.8284271\n', '1.4142136\n', '-1'] Note: none

```python import math def solve(): numLocation, totalPeople = map(int, input().split()) location = dict() for i in range(numLocation): x, y, people = map(int, input().split()) r = x * x + y * y if r in location: location[r] += people else: location[r] = people radius = [] for r in location: radius.append(r) radius.sort() for r in radius: totalPeople += location[r] if totalPeople >= 1000000: print(math.sqrt(r)) return print("-1") solve() ```

3

653

A

Bear and Three Balls

PROGRAMMING

900

[ "brute force", "implementation", "sortings" ]

null

Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*. Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy: - No two friends can get balls of the same size. - No two friends can get balls of sizes that differ by more than 2. For example, Limak can choose balls with sizes 4, 5 and 3, or balls with sizes 90, 91 and 92. But he can't choose balls with sizes 5, 5 and 6 (two friends would get balls of the same size), and he can't choose balls with sizes 30, 31 and 33 (because sizes 30 and 33 differ by more than 2). Your task is to check whether Limak can choose three balls that satisfy conditions above.

The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball.

Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes).

[ "4\n18 55 16 17\n", "6\n40 41 43 44 44 44\n", "8\n5 972 3 4 1 4 970 971\n" ]

[ "YES\n", "NO\n", "YES\n" ]

In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17. In the second sample, there is no way to give gifts to three friends without breaking the rules. In the third sample, there is even more than one way to choose balls: 1. Choose balls with sizes 3, 4 and 5. 1. Choose balls with sizes 972, 970, 971.

500

[ { "input": "4\n18 55 16 17", "output": "YES" }, { "input": "6\n40 41 43 44 44 44", "output": "NO" }, { "input": "8\n5 972 3 4 1 4 970 971", "output": "YES" }, { "input": "3\n959 747 656", "output": "NO" }, { "input": "4\n1 2 2 3", "output": "YES" }, { "input": "50\n998 30 384 289 505 340 872 223 663 31 929 625 864 699 735 589 676 399 745 635 963 381 75 97 324 612 597 797 103 382 25 894 219 458 337 572 201 355 294 275 278 311 586 573 965 704 936 237 715 543", "output": "NO" }, { "input": "50\n941 877 987 982 966 979 984 810 811 909 872 980 957 897 845 995 924 905 984 914 824 840 868 910 815 808 872 858 883 952 823 835 860 874 959 972 931 867 866 987 982 837 800 921 887 910 982 980 828 869", "output": "YES" }, { "input": "3\n408 410 409", "output": "YES" }, { "input": "3\n903 902 904", "output": "YES" }, { "input": "3\n399 400 398", "output": "YES" }, { "input": "3\n450 448 449", "output": "YES" }, { "input": "3\n390 389 388", "output": "YES" }, { "input": "3\n438 439 440", "output": "YES" }, { "input": "11\n488 688 490 94 564 615 641 170 489 517 669", "output": "YES" }, { "input": "24\n102 672 983 82 720 501 81 721 982 312 207 897 159 964 611 956 118 984 37 271 596 403 772 954", "output": "YES" }, { "input": "36\n175 551 70 479 875 480 979 32 465 402 640 116 76 687 874 678 359 785 753 401 978 629 162 963 886 641 39 845 132 930 2 372 478 947 407 318", "output": "YES" }, { "input": "6\n10 79 306 334 304 305", "output": "YES" }, { "input": "34\n787 62 26 683 486 364 684 891 846 801 969 837 359 800 836 359 471 637 732 91 841 836 7 799 959 405 416 841 737 803 615 483 323 365", "output": "YES" }, { "input": "30\n860 238 14 543 669 100 428 789 576 484 754 274 849 850 586 377 711 386 510 408 520 693 23 477 266 851 728 711 964 73", "output": "YES" }, { "input": "11\n325 325 324 324 324 325 325 324 324 324 324", "output": "NO" }, { "input": "7\n517 517 518 517 518 518 518", "output": "NO" }, { "input": "20\n710 710 711 711 711 711 710 710 710 710 711 710 710 710 710 710 710 711 711 710", "output": "NO" }, { "input": "48\n29 30 29 29 29 30 29 30 30 30 30 29 30 30 30 29 29 30 30 29 30 29 29 30 29 30 29 30 30 29 30 29 29 30 30 29 29 30 30 29 29 30 30 30 29 29 30 29", "output": "NO" }, { "input": "7\n880 880 514 536 881 881 879", "output": "YES" }, { "input": "15\n377 432 262 376 261 375 377 262 263 263 261 376 262 262 375", "output": "YES" }, { "input": "32\n305 426 404 961 426 425 614 304 404 425 615 403 303 304 615 303 305 405 427 614 403 303 425 615 404 304 427 403 206 616 405 404", "output": "YES" }, { "input": "41\n115 686 988 744 762 519 745 519 518 83 85 115 520 44 687 686 685 596 988 687 989 988 114 745 84 519 519 746 988 84 745 744 115 114 85 115 520 746 745 116 987", "output": "YES" }, { "input": "47\n1 2 483 28 7 109 270 651 464 162 353 521 224 989 721 499 56 69 197 716 313 446 580 645 828 197 100 138 789 499 147 677 384 711 783 937 300 543 540 93 669 604 739 122 632 822 116", "output": "NO" }, { "input": "31\n1 2 1 373 355 692 750 920 578 666 615 232 141 129 663 929 414 704 422 559 568 731 354 811 532 618 39 879 292 602 995", "output": "NO" }, { "input": "50\n5 38 41 4 15 40 27 39 20 3 44 47 30 6 36 29 35 12 19 26 10 2 21 50 11 46 48 49 17 16 33 13 32 28 31 18 23 34 7 14 24 45 9 37 1 8 42 25 43 22", "output": "YES" }, { "input": "50\n967 999 972 990 969 978 963 987 954 955 973 970 959 981 995 983 986 994 979 957 965 982 992 977 953 975 956 961 993 997 998 958 980 962 960 951 996 991 1000 966 971 988 976 968 989 984 974 964 985 952", "output": "YES" }, { "input": "50\n850 536 761 506 842 898 857 723 583 637 536 943 895 929 890 612 832 633 696 731 553 880 710 812 665 877 915 636 711 540 748 600 554 521 813 796 568 513 543 809 798 820 928 504 999 646 907 639 550 911", "output": "NO" }, { "input": "3\n3 1 2", "output": "YES" }, { "input": "3\n500 999 1000", "output": "NO" }, { "input": "10\n101 102 104 105 107 109 110 112 113 115", "output": "NO" }, { "input": "50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "NO" }, { "input": "50\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000", "output": "NO" }, { "input": "3\n1000 999 998", "output": "YES" }, { "input": "49\n343 322 248 477 53 156 245 493 209 141 370 66 229 184 434 137 276 472 216 456 147 180 140 114 493 323 393 262 380 314 222 124 98 441 129 346 48 401 347 460 122 125 114 106 189 260 374 165 456", "output": "NO" }, { "input": "20\n1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3", "output": "YES" }, { "input": "3\n999 999 1000", "output": "NO" }, { "input": "9\n2 4 5 13 25 100 200 300 400", "output": "NO" }, { "input": "9\n1 1 1 2 2 2 3 3 3", "output": "YES" }, { "input": "3\n1 1 2", "output": "NO" }, { "input": "3\n998 999 1000", "output": "YES" }, { "input": "12\n1 1 1 1 1 1 1 1 1 2 2 4", "output": "NO" }, { "input": "4\n4 3 4 5", "output": "YES" }, { "input": "6\n1 1 1 2 2 2", "output": "NO" }, { "input": "3\n2 3 2", "output": "NO" }, { "input": "5\n10 5 6 3 2", "output": "NO" }, { "input": "3\n1 2 1", "output": "NO" }, { "input": "3\n1 2 3", "output": "YES" }, { "input": "4\n998 999 1000 1000", "output": "YES" }, { "input": "5\n2 3 9 9 4", "output": "YES" }, { "input": "4\n1 2 4 4", "output": "NO" }, { "input": "3\n1 1 1", "output": "NO" }, { "input": "3\n2 2 3", "output": "NO" }, { "input": "7\n1 2 2 2 4 5 6", "output": "YES" }, { "input": "5\n1 3 10 3 10", "output": "NO" }, { "input": "3\n1 2 2", "output": "NO" }, { "input": "4\n1000 1000 999 998", "output": "YES" }, { "input": "3\n5 3 7", "output": "NO" }, { "input": "6\n1 1 2 2 3 3", "output": "YES" }, { "input": "9\n6 6 6 5 5 5 4 4 4", "output": "YES" }, { "input": "7\n5 6 6 6 7 7 7", "output": "YES" }, { "input": "5\n2 3 3 3 4", "output": "YES" }, { "input": "5\n2 1 2 1 3", "output": "YES" }, { "input": "3\n1 2 7", "output": "NO" }, { "input": "3\n1000 1000 1000", "output": "NO" }, { "input": "5\n1 100 2 100 3", "output": "YES" }, { "input": "5\n5 4 6 5 5", "output": "YES" }, { "input": "12\n1 1 1 1 2 2 2 2 3 3 3 3", "output": "YES" }, { "input": "5\n9 9 1 2 3", "output": "YES" }, { "input": "6\n1 2 3 1 2 3", "output": "YES" }, { "input": "7\n1 1 1 1 2 3 3", "output": "YES" }, { "input": "3\n13 13 13", "output": "NO" }, { "input": "3\n42 42 42", "output": "NO" }, { "input": "8\n1 1 1 1 2 2 2 2", "output": "NO" }, { "input": "6\n1 1 1 1 2 3", "output": "YES" }, { "input": "6\n1 1 2 2 6 6", "output": "NO" }, { "input": "6\n1 2 5 5 5 5", "output": "NO" }, { "input": "9\n1 2 3 1 2 3 1 2 3", "output": "YES" }, { "input": "4\n1 2 1 100", "output": "NO" }, { "input": "5\n1 1 2 2 3", "output": "YES" } ]

1,693,396,030

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

4

77

0

n = int(input()) balls = [int(x) for x in input().split()] balls.sort() for i in range(n - 2): if balls[i] + 2 == balls[i + 1] + 1 == balls[i + 2]: print("YES") break else: print("NO")

Title: Bear and Three Balls Time Limit: None seconds Memory Limit: None megabytes Problem Description: Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*. Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy: - No two friends can get balls of the same size. - No two friends can get balls of sizes that differ by more than 2. For example, Limak can choose balls with sizes 4, 5 and 3, or balls with sizes 90, 91 and 92. But he can't choose balls with sizes 5, 5 and 6 (two friends would get balls of the same size), and he can't choose balls with sizes 30, 31 and 33 (because sizes 30 and 33 differ by more than 2). Your task is to check whether Limak can choose three balls that satisfy conditions above. Input Specification: The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball. Output Specification: Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes). Demo Input: ['4\n18 55 16 17\n', '6\n40 41 43 44 44 44\n', '8\n5 972 3 4 1 4 970 971\n'] Demo Output: ['YES\n', 'NO\n', 'YES\n'] Note: In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17. In the second sample, there is no way to give gifts to three friends without breaking the rules. In the third sample, there is even more than one way to choose balls: 1. Choose balls with sizes 3, 4 and 5. 1. Choose balls with sizes 972, 970, 971.

```python n = int(input()) balls = [int(x) for x in input().split()] balls.sort() for i in range(n - 2): if balls[i] + 2 == balls[i + 1] + 1 == balls[i + 2]: print("YES") break else: print("NO") ```

0

748

B

Santa Claus and Keyboard Check

PROGRAMMING

1,500

[ "implementation", "strings" ]

null

Santa Claus decided to disassemble his keyboard to clean it. After he returned all the keys back, he suddenly realized that some pairs of keys took each other's place! That is, Santa suspects that each key is either on its place, or on the place of another key, which is located exactly where the first key should be. In order to make sure that he's right and restore the correct order of keys, Santa typed his favorite patter looking only to his keyboard. You are given the Santa's favorite patter and the string he actually typed. Determine which pairs of keys could be mixed. Each key must occur in pairs at most once.

The input consists of only two strings *s* and *t* denoting the favorite Santa's patter and the resulting string. *s* and *t* are not empty and have the same length, which is at most 1000. Both strings consist only of lowercase English letters.

If Santa is wrong, and there is no way to divide some of keys into pairs and swap keys in each pair so that the keyboard will be fixed, print «-1» (without quotes). Otherwise, the first line of output should contain the only integer *k* (*k*<=≥<=0) — the number of pairs of keys that should be swapped. The following *k* lines should contain two space-separated letters each, denoting the keys which should be swapped. All printed letters must be distinct. If there are several possible answers, print any of them. You are free to choose the order of the pairs and the order of keys in a pair. Each letter must occur at most once. Santa considers the keyboard to be fixed if he can print his favorite patter without mistakes.

[ "helloworld\nehoolwlroz\n", "hastalavistababy\nhastalavistababy\n", "merrychristmas\nchristmasmerry\n" ]

[ "3\nh e\nl o\nd z\n", "0\n", "-1\n" ]

none

1,000

[ { "input": "helloworld\nehoolwlroz", "output": "3\nh e\nl o\nd z" }, { "input": "hastalavistababy\nhastalavistababy", "output": "0" }, { "input": "merrychristmas\nchristmasmerry", "output": "-1" }, { "input": "kusyvdgccw\nkusyvdgccw", "output": "0" }, { "input": "bbbbbabbab\naaaaabaaba", "output": "1\nb a" }, { "input": "zzzzzzzzzzzzzzzzzzzzz\nqwertyuiopasdfghjklzx", "output": "-1" }, { "input": "accdccdcdccacddbcacc\naccbccbcbccacbbdcacc", "output": "1\nd b" }, { "input": "giiibdbebjdaihdghahccdeffjhfgidfbdhjdggajfgaidadjd\ngiiibdbebjdaihdghahccdeffjhfgidfbdhjdggajfgaidadjd", "output": "0" }, { "input": "gndggadlmdefgejidmmcglbjdcmglncfmbjjndjcibnjbabfab\nfihffahlmhogfojnhmmcflkjhcmflicgmkjjihjcnkijkakgak", "output": "5\ng f\nn i\nd h\ne o\nb k" }, { "input": "ijpanyhovzwjjxsvaiyhchfaulcsdgfszjnwtoqbtaqygfmxuwvynvlhqhvmkjbooklxfhmqlqvfoxlnoclfxtbhvnkmhjcmrsdc\nijpanyhovzwjjxsvaiyhchfaulcsdgfszjnwtoqbtaqygfmxuwvynvlhqhvmkjbooklxfhmqlqvfoxlnoclfxtbhvnkmhjcmrsdc", "output": "0" }, { "input": "ab\naa", "output": "-1" }, { "input": "a\nz", "output": "1\na z" }, { "input": "zz\nzy", "output": "-1" }, { "input": "as\ndf", "output": "2\na d\ns f" }, { "input": "abc\nbca", "output": "-1" }, { "input": "rtfg\nrftg", "output": "1\nt f" }, { "input": "y\ny", "output": "0" }, { "input": "qwertyuiopasdfghjklzx\nzzzzzzzzzzzzzzzzzzzzz", "output": "-1" }, { "input": "qazwsxedcrfvtgbyhnujmik\nqwertyuiasdfghjkzxcvbnm", "output": "-1" }, { "input": "aaaaaa\nabcdef", "output": "-1" }, { "input": "qwerty\nffffff", "output": "-1" }, { "input": "dofbgdppdvmwjwtdyphhmqliydxyjfxoopxiscevowleccmhwybsxitvujkfliamvqinlrpytyaqdlbywccprukoisyaseibuqbfqjcabkieimsggsakpnqliwhehnemewhychqrfiuyaecoydnromrh\ndofbgdppdvmwjwtdyphhmqliydxyjfxoopxiscevowleccmhwybsxitvujkfliamvqinlrpytyaqdlbywccprukoisyaseibuqbfqjcabkieimsggsakpnqliwhehnemewhychqrfiuyaecoydnromrh", "output": "0" }, { "input": "acdbccddadbcbabbebbaebdcedbbcebeaccecdabadeabeecbacacdcbccedeadadedeccedecdaabcedccccbbcbcedcaccdede\ndcbaccbbdbacadaaeaadeabcebaaceaedccecbdadbedaeecadcdcbcaccebedbdbebeccebecbddacebccccaacacebcdccbebe", "output": "-1" }, { "input": "bacccbbacabbcaacbbba\nbacccbbacabbcaacbbba", "output": "0" }, { "input": "dbadbddddb\nacbacaaaac", "output": "-1" }, { "input": "dacbdbbbdd\nadbdadddaa", "output": "-1" }, { "input": "bbbbcbcbbc\ndaddbabddb", "output": "-1" }, { "input": "dddddbcdbd\nbcbbbdacdb", "output": "-1" }, { "input": "cbadcbcdaa\nabbbababbb", "output": "-1" }, { "input": "dmkgadidjgdjikgkehhfkhgkeamhdkfemikkjhhkdjfaenmkdgenijinamngjgkmgmmedfdehkhdigdnnkhmdkdindhkhndnakdgdhkdefagkedndnijekdmkdfedkhekgdkhgkimfeakdhhhgkkff\nbdenailbmnbmlcnehjjkcgnehadgickhdlecmggcimkahfdeinhflmlfadfnmncdnddhbkbhgejblnbffcgdbeilfigegfifaebnijeihkanehififlmhcbdcikhieghenbejneldkhaebjggncckk", "output": "-1" }, { "input": "acbbccabaa\nabbbbbabaa", "output": "-1" }, { "input": "ccccaccccc\naaaabaaaac", "output": "-1" }, { "input": "acbacacbbb\nacbacacbbb", "output": "0" }, { "input": "abbababbcc\nccccccccbb", "output": "-1" }, { "input": "jbcbbjiifdcbeajgdeabddbfcecafejddcigfcaedbgicjihifgbahjihcjefgabgbccdiibfjgacehbbdjceacdbdeaiibaicih\nhhihhhddcfihddhjfddhffhcididcdhffidjciddfhjdihdhdcjhdhhdhihdcjdhjhiifddhchjdidhhhfhiddifhfddddhddidh", "output": "-1" }, { "input": "ahaeheedefeehahfefhjhhedheeeedhehhfhdejdhffhhejhhhejadhefhahhadjjhdhheeeehfdaffhhefehhhefhhhhehehjda\neiefbdfgdhffieihfhjajifgjddffgifjbhigfagjhhjicaijbdaegidhiejiegaabgjidcfcjhgehhjjchcbjjdhjbiidjdjage", "output": "-1" }, { "input": "fficficbidbcbfaddifbffdbbiaccbbciiaidbcbbiadcccbccbbaibabcbbdbcibcciibiccfifbiiicadibbiaafadacdficbc\nddjhdghbgcbhadeccjdbddcbfjeiiaaigjejcaiabgechiiahibfejbeahafcfhjbihgjfgihdgdagjjhecjafjeedecehcdjhai", "output": "-1" }, { "input": "z\nz", "output": "0" }, { "input": "a\nz", "output": "1\na z" }, { "input": "z\na", "output": "1\nz a" }, { "input": "aa\nzz", "output": "1\na z" }, { "input": "az\nza", "output": "1\na z" }, { "input": "aa\nza", "output": "-1" }, { "input": "za\nzz", "output": "-1" }, { "input": "aa\nab", "output": "-1" }, { "input": "hehe\nheeh", "output": "-1" }, { "input": "bd\ncc", "output": "-1" }, { "input": "he\nhh", "output": "-1" }, { "input": "hee\nheh", "output": "-1" }, { "input": "aa\nac", "output": "-1" }, { "input": "ab\naa", "output": "-1" }, { "input": "hello\nehlol", "output": "-1" }, { "input": "ac\naa", "output": "-1" }, { "input": "aaabbb\nbbbaab", "output": "-1" }, { "input": "aa\nfa", "output": "-1" }, { "input": "hg\nee", "output": "-1" }, { "input": "helloworld\nehoolwlrow", "output": "-1" }, { "input": "abb\nbab", "output": "-1" }, { "input": "aaa\naae", "output": "-1" }, { "input": "aba\nbaa", "output": "-1" }, { "input": "aa\nba", "output": "-1" }, { "input": "da\naa", "output": "-1" }, { "input": "aaa\naab", "output": "-1" }, { "input": "xy\nzz", "output": "-1" } ]

1,582,288,604

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

13

139

0

def santa(s,t): # счет metka=True otv=[] a=0 l=[] for i in range(len(s)): if s[i] != t[i]: if (s[i] in l) and (t[i] in l): continue elif (s[i] in l) or (t[i] in l): print(-1) metka=False break else: #print(s[i],t[i]) otv.append(s[i]) otv.append(t[i]) a +=1 l.append(s[i]) l.append(t[i]) # вывод if metka: print(a) for i in range(len(otv)): if i%2==1: print(otv[i],end='\n') else: print(otv[i],end=' ') s,t = input(),input() santa(s,t)

Title: Santa Claus and Keyboard Check Time Limit: None seconds Memory Limit: None megabytes Problem Description: Santa Claus decided to disassemble his keyboard to clean it. After he returned all the keys back, he suddenly realized that some pairs of keys took each other's place! That is, Santa suspects that each key is either on its place, or on the place of another key, which is located exactly where the first key should be. In order to make sure that he's right and restore the correct order of keys, Santa typed his favorite patter looking only to his keyboard. You are given the Santa's favorite patter and the string he actually typed. Determine which pairs of keys could be mixed. Each key must occur in pairs at most once. Input Specification: The input consists of only two strings *s* and *t* denoting the favorite Santa's patter and the resulting string. *s* and *t* are not empty and have the same length, which is at most 1000. Both strings consist only of lowercase English letters. Output Specification: If Santa is wrong, and there is no way to divide some of keys into pairs and swap keys in each pair so that the keyboard will be fixed, print «-1» (without quotes). Otherwise, the first line of output should contain the only integer *k* (*k*<=≥<=0) — the number of pairs of keys that should be swapped. The following *k* lines should contain two space-separated letters each, denoting the keys which should be swapped. All printed letters must be distinct. If there are several possible answers, print any of them. You are free to choose the order of the pairs and the order of keys in a pair. Each letter must occur at most once. Santa considers the keyboard to be fixed if he can print his favorite patter without mistakes. Demo Input: ['helloworld\nehoolwlroz\n', 'hastalavistababy\nhastalavistababy\n', 'merrychristmas\nchristmasmerry\n'] Demo Output: ['3\nh e\nl o\nd z\n', '0\n', '-1\n'] Note: none

```python def santa(s,t): # счет metka=True otv=[] a=0 l=[] for i in range(len(s)): if s[i] != t[i]: if (s[i] in l) and (t[i] in l): continue elif (s[i] in l) or (t[i] in l): print(-1) metka=False break else: #print(s[i],t[i]) otv.append(s[i]) otv.append(t[i]) a +=1 l.append(s[i]) l.append(t[i]) # вывод if metka: print(a) for i in range(len(otv)): if i%2==1: print(otv[i],end='\n') else: print(otv[i],end=' ') s,t = input(),input() santa(s,t) ```

0

747

B

Mammoth's Genome Decoding

PROGRAMMING

900

[ "implementation", "strings" ]

null

The process of mammoth's genome decoding in Berland comes to its end! One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, *s* is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'. It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal. Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.

The first line contains the integer *n* (4<=≤<=*n*<=≤<=255) — the length of the genome. The second line contains the string *s* of length *n* — the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.

If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).

[ "8\nAG?C??CT\n", "4\nAGCT\n", "6\n????G?\n", "4\nAA??\n" ]

[ "AGACGTCT\n", "AGCT\n", "===\n", "===\n" ]

In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice. In the second example the genome is already decoded correctly and each nucleotide is exactly once in it. In the third and the fourth examples it is impossible to decode the genom.

1,000

[ { "input": "8\nAG?C??CT", "output": "AGACGTCT" }, { "input": "4\nAGCT", "output": "AGCT" }, { "input": "6\n????G?", "output": "===" }, { "input": "4\nAA??", "output": "===" }, { "input": "4\n????", "output": "ACGT" }, { "input": "252\n???????GCG??T??TT?????T?C???C?CCG???GA???????AC??A???AAC?C?CC??CCC??A??TA?CCC??T???C??CA???CA??G????C?C?C????C??C??A???C?T????C??ACGC??CC?A?????A??CC?C??C?CCG?C??C??A??CG?A?????A?CT???CC????CCC?CATC?G??????????A???????????????TCCCC?C?CA??AC??GC????????", "output": "AAAAAAAGCGAATAATTAAAAATACAAACACCGAAAGAAAAAAAAACAAAAAAAACACACCAACCCAAAACTACCCCCCTCCCCCGCAGGGCAGGGGGGGCGCGCGGGGCGGCGGAGGGCGTGGGGCGGACGCGGCCGAGGGGGAGGCCGCGGCGCCGGCGGCGGAGGCGGAGTTTTATCTTTTCCTTTTCCCTCATCTGTTTTTTTTTTATTTTTTTTTTTTTTTTCCCCTCTCATTACTTGCTTTTTTTT" }, { "input": "255\n???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????", "output": "===" }, { "input": "4\n??A?", "output": "CGAT" }, { "input": "4\n?C??", "output": "ACGT" }, { "input": "4\nT???", "output": "TACG" }, { "input": "4\n???G", "output": "ACTG" }, { "input": "4\n??AC", "output": "GTAC" }, { "input": "8\n?C?AA???", "output": "CCGAAGTT" }, { "input": "12\n???A?G???A?T", "output": "ACCACGGGTATT" }, { "input": "16\n?????C??CAG??T??", "output": "AAACCCGGCAGGTTTT" }, { "input": "20\n???A?G??C?GC???????G", "output": "AAAAAGCCCCGCGGTTTTTG" }, { "input": "24\n?TG???AT?A?CTTG??T?GCT??", "output": "ATGAAAATCACCTTGCCTGGCTGG" }, { "input": "28\n??CTGAAG?GGT?CC?A??TT?CCACG?", "output": "AACTGAAGAGGTCCCGAGTTTTCCACGT" }, { "input": "32\n??A?????CAAG?C?C?CG??A?A??AAC?A?", "output": "CCACGGGGCAAGGCGCTCGTTATATTAACTAT" }, { "input": "36\n?GCC?CT?G?CGG?GCTGA?C?G?G????C??G?C?", "output": "AGCCACTAGACGGAGCTGAACAGAGCTTTCTTGTCT" }, { "input": "40\nTA?AA?C?G?ACC?G?GCTCGC?TG??TG?CT?G??CC??", "output": "TAAAAACAGAACCAGAGCTCGCCTGGGTGGCTTGTTCCTT" }, { "input": "44\nT?TA??A??AA???A?AGTA??TAT??ACTGAT??CT?AC?T??", "output": "TCTACCACCAACCCAGAGTAGGTATGGACTGATGGCTGACGTTT" }, { "input": "48\nG?G??GC??CA?G????AG?CA?CG??GGCCCCAA??G??C?T?TCA?", "output": "GAGAAGCAACAAGCCGGAGGCATCGTTGGCCCCAATTGTTCTTTTCAT" }, { "input": "52\n??G?G?CTGT??T?GCGCT?TAGGTT??C???GTCG??GC??C???????CG", "output": "AAGAGACTGTAATAGCGCTATAGGTTAACAACGTCGCCGCCCCGGTTTTTCG" }, { "input": "56\n?GCCA?GC?GA??GA??T?CCGC?????TGGC?AGGCCGC?AC?TGAT??CG?A??", "output": "AGCCAAGCAGAAAGAAATCCCGCCGGTTTGGCTAGGCCGCTACTTGATTTCGTATT" }, { "input": "60\nAT?T?CCGG??G?CCT?CCC?C?CGG????TCCCG?C?TG?TT?TA??A?TGT?????G?", "output": "ATATACCGGAAGACCTACCCACACGGAAAATCCCGCCCTGGTTGTAGGAGTGTGTTTTGT" }, { "input": "64\n?G??C??????C??C??AG?T?GC?TT??TAGA?GA?A??T?C???TC??A?CA??C??A???C", "output": "AGAACAAAAACCCCCCCAGCTCGCGTTGGTAGAGGAGAGGTGCGGGTCTTATCATTCTTATTTC" }, { "input": "68\nC?T??????C????G?T??TTT?T?T?G?CG??GCC??CT??????C??T?CC?T?T????CTT?T??", "output": "CATAAAAAACAAAAGATAATTTATATAGCCGCCGCCCCCTCCGGGGCGGTGCCGTGTGGGGCTTTTTT" }, { "input": "72\nA?GTA??A?TG?TA???AAAGG?A?T?TTAAT??GGA?T??G?T?T????TTATAAA?AA?T?G?TGT??TG", "output": "AAGTACCACTGCTACCCAAAGGCACTCTTAATCCGGACTCCGCTCTCGGGTTATAAAGAAGTGGGTGTGTTG" }, { "input": "76\nG?GTAC?CG?AG?AGC???A??T?TC?G??C?G?A???TC???GTG?C?AC???A??????TCA??TT?A?T?ATG", "output": "GAGTACACGAAGAAGCAAAAAATCTCCGCCCCGCACCCTCCGGGTGGCGACGGGAGGTTTTTCATTTTTATTTATG" }, { "input": "80\nGG???TAATT?A?AAG?G?TT???G??TTA?GAT?????GT?AA?TT?G?AG???G?T?A??GT??TTT?TTG??AT?T?", "output": "GGAAATAATTAAAAAGAGATTACCGCCTTACGATCCCCCGTCAACTTCGCAGCCCGCTCACGGTGGTTTGTTGGGATGTG" }, { "input": "84\n?C??G??CGGC????CA?GCGG???G?CG??GA??C???C???GC???CG?G?A?C?CC?AC?C?GGAG???C??????G???C", "output": "ACAAGAACGGCAAAACAAGCGGAAAGACGAAGACCCCCGCGGGGCGTTCGTGTATCTCCTACTCTGGAGTTTCTTTTTTGTTTC" }, { "input": "88\nGTTC?TCTGCGCGG??CATC?GTGCTCG?A?G?TGCAGCAG??A?CAG???GGTG?ATCAGG?TCTACTC?CG?GGT?A?TCC??AT?", "output": "GTTCATCTGCGCGGAACATCAGTGCTCGAAAGATGCAGCAGAAAACAGACCGGTGCATCAGGCTCTACTCGCGTGGTTATTCCTTATT" }, { "input": "92\n??TT????AT?T????A???TC????A?C????AT???T?T???T??A???T??TTA?AT?AA?C????C??????????????TAA?T???", "output": "AATTAAAAATATAAAAAACCTCCCCCACCCCCCATCCCTCTCCCTCGAGGGTGGTTAGATGAAGCGGGGCGGGGGGGGGGTTTTTAATTTTT" }, { "input": "96\nT?????C?CT?T??GGG??G??C???A?CC??????G???TCCCT??C?G??GC?CT?CGT?GGG??TCTC?C?CCGT?CCTCTT??CC?C?????", "output": "TAAAAACACTATAAGGGAAGAACAAAAACCAAAAAAGCGGTCCCTGGCGGGGGCGCTGCGTGGGGGGTCTCTCTCCGTTCCTCTTTTCCTCTTTTT" }, { "input": "100\n???GGA?C?A?A??A?G??GT?GG??G????A?ATGGAA???A?A?A?AGAGGT?GA?????AA???G???GA???TAGAG?ACGGA?AA?G???GGGAT", "output": "ACCGGACCCACACCACGCCGTCGGCCGCCCCACATGGAACCCACACAGAGAGGTGGATTTTTAATTTGTTTGATTTTAGAGTACGGATAATGTTTGGGAT" }, { "input": "104\n???TTG?C???G?G??G??????G?T??TC???CCC????TG?GGT??GG?????T?CG???GGG??GTC?G??TC??GG??CTGGCT??G????C??????TG", "output": "AAATTGACAAAGAGAAGAAAAAAGATAATCAAACCCAAAATGCGGTCCGGCCCCCTCCGCCCGGGCCGTCCGGGTCGGGGTTCTGGCTTTGTTTTCTTTTTTTG" }, { "input": "108\n??CAC?A?ACCA??A?CA??AA?TA?AT?????CCC????A??T?C?CATA??CAA?TACT??A?TA?AC?T??G???GG?G??CCC??AA?CG????T?CT?A??AA", "output": "AACACAACACCACCACCACCAACTACATCGGGGCCCGGGGAGGTGCGCATAGGCAAGTACTGGAGTAGACGTGGGTTTGGTGTTCCCTTAATCGTTTTTTCTTATTAA" }, { "input": "112\n???T?TC?C?AC???TC?C???CCC??C????C?CCGC???TG?C?T??????C?C?????G?C????A????????G?C?A?C?A?C?C??C????CC?TC??C??C?A??", "output": "AAATATCACAACAAATCACAAACCCAACAAAACACCGCAAATGCCGTGGGGGGCGCGGGGGGGCGGGGAGGGGGGTTGTCTATCTATCTCTTCTTTTCCTTCTTCTTCTATT" }, { "input": "116\n????C??A?A??AAC???????C???CCCTC??A????ATA?T??AT???C?TCCC???????C????CTC??T?A???C??A???CCA?TAC?AT?????C??CA???C?????C", "output": "AAAACAAAAAAAAACAAAAAACCCCCCCCTCCCACGGGATAGTGGATGGGCGTCCCGGGGGGGCGGGGCTCGGTGAGGGCGGATTTCCATTACTATTTTTTCTTCATTTCTTTTTC" }, { "input": "120\nTC?AGATG?GAT??G????C?C??GA?GT?TATAC?AGA?TCG?TCT???A?AAA??C?T?A???AA?TAC?ATTT???T?AA?G???TG?AT???TA??GCGG?AC?A??AT??T???C", "output": "TCAAGATGAGATAAGAACCCCCCCGACGTCTATACCAGACTCGCTCTCCCACAAACCCCTCACGGAAGTACGATTTGGGTGAAGGGGGTGGATGGGTAGTGCGGTACTATTATTTTTTTC" }, { "input": "124\n???C?????C?AGG??A?A?CA????A??A?AA??A????????G?A?????????AG?A??G?C??A??C???G??CG??C???????A????C???AG?AA???AC????????????C??G", "output": "AAACAAAAACAAGGAAAAAACACCCCACCACAACCACCCCCCCCGCACCCGGGGGGAGGAGGGGCGGAGGCGGGGGGCGGGCGTTTTTTATTTTCTTTAGTAATTTACTTTTTTTTTTTTCTTG" }, { "input": "128\nAT?GC?T?C?GATTTG??ATTGG?AC?GGCCA?T?GG?CCGG??AGT?TGT?G??A?AAGGCGG?T??TCT?CT??C?TTGTTG??????CCGG?TGATAT?T?TTGTCCCT??CTGTGTAATA??G?", "output": "ATAGCATACAGATTTGAAATTGGAACAGGCCAATAGGACCGGAAAGTATGTAGAAAAAAGGCGGCTCCTCTCCTCCCCTTGTTGCCCCCCCCGGCTGATATCTGTTGTCCCTGGCTGTGTAATAGGGT" }, { "input": "132\nAC???AA??T???T??G??ACG?C??AA?GA?C???CGAGTA?T??TTGTC???GCTGATCA????C??TA???ATTTA?C??GT??GTCTCTCGT?AAGGACTG?TC????T???C?T???ATTTT?T?AT", "output": "ACAAAAAAATAAATAAGAAACGACACAACGACCCCCCGAGTACTCCTTGTCCCCGCTGATCACCCCCCGTAGGGATTTAGCGGGTGGGTCTCTCGTGAAGGACTGGTCGGGGTGGGCGTTTTATTTTTTTAT" }, { "input": "136\n?A?C???????C??????????????C?????C???????????CCCC?????????C??????C??C??????CC??C??C?C???C??????C??C?C??????????C?????????GC????C???????C?", "output": "AAACAAAAAAACAAAAAAAAAAAAAACAAAAACAAAAACCCCCCCCCCCCCCGGGGGCGGGGGGCGGCGGGGGGCCGGCGGCGCGGGCGGGGGGCTTCTCTTTTTTTTTTCTTTTTTTTTGCTTTTCTTTTTTTCT" }, { "input": "140\nTTG??G?GG?G??C??CTC?CGG?TTCGC????GGCG?G??TTGCCCC?TCC??A??CG?GCCTTT?G??G??CT??TG?G?TTC?TGC?GG?TGT??CTGGAT??TGGTTG??TTGGTTTTTTGGTCGATCGG???C??", "output": "TTGAAGAGGAGAACAACTCACGGATTCGCAAAAGGCGAGAATTGCCCCATCCAAAAACGAGCCTTTAGAAGAACTAATGAGATTCCTGCCGGCTGTCCCTGGATCCTGGTTGCCTTGGTTTTTTGGTCGATCGGCCCCTT" }, { "input": "144\n?????A?C?A?A???TTT?GAATA?G??T?T?????AT?AA??TT???TT??A?T????AT??TA??AA???T??A??TT???A????T???T????A??T?G???A?C?T????A?AA??A?T?C??A??A???AA????ATA", "output": "AAAAAAACAAAACCCTTTCGAATACGCCTCTCCCCCATCAACCTTCCCTTCCACTCCCCATCCTACCAACCCTGGAGGTTGGGAGGGGTGGGTGGGGAGGTGGGGGAGCGTGGGGAGAAGGATTTCTTATTATTTAATTTTATA" }, { "input": "148\nACG?GGGT?A??C????TCTTGCTG?GTA?C?C?TG?GT??GGGG??TTG?CA????GT???G?TT?T?CT?C??C???CTTCATTA?G?G???GC?AAT??T???AT??GGATT????TC?C???????T??TATCG???T?T?CG?", "output": "ACGAGGGTAAAACAAAATCTTGCTGAGTAACACATGAGTAAGGGGAATTGACAAAAAGTAAAGATTCTCCTCCCCCCCCCTTCATTACGCGCCCGCCAATCCTCCCATCGGGATTGGGGTCGCGGGGGGGTGTTATCGTTTTTTTCGT" }, { "input": "152\n??CTA??G?GTC?G??TTCC?TG??????T??C?G???G?CC???C?GT?G?G??C?CGGT?CC????G?T?T?C?T??G?TCGT??????A??TCC?G?C???GTT?GC?T?CTT?GT?C??C?TCGTTG?TTG?G????CG?GC??G??G", "output": "AACTAAAGAGTCAGAATTCCATGAAAAAATAACAGAAAGACCAAACAGTAGAGAACACGGTACCAAAAGCTCTCCCTCCGCTCGTCCCCCCACGTCCGGGCGGGGTTGGCGTGCTTGGTGCGTCTTCGTTGTTTGTGTTTTCGTGCTTGTTG" }, { "input": "156\nGCA????A???AAT?C??????GAG?CCA?A?CG??ACG??????GCAAAC??GCGGTCC??GT???C???????CC???????ACGCA????C??A??CC??A?GAATAC?C?CA?CCCT?TCACA?A???????C??TAG?C??T??A??A?CA", "output": "GCAAAAAAAAAAATACAAAAACGAGCCCACACCGCCACGCCCGGGGCAAACGGGCGGTCCGGGTGGGCGGGGGGGCCGGGGGGGACGCAGGTTCTTATTCCTTATGAATACTCTCATCCCTTTCACATATTTTTTTCTTTAGTCTTTTTATTATCA" }, { "input": "160\nGCACC????T?TGATAC??CATATCC?GT?AGT?ATGGATA?CC?????GCTCG?A?GG?A?GCCAG??C?CGGATC?GCAA?AAGCCCCC?CAT?GA?GC?CAC?TAA?G?CACAACGG?AAA??CA?ACTCGA?CAC?GAGCAAC??A?G?AAA?TC?", "output": "GCACCACCCTGTGATACGGCATATCCGGTGAGTGATGGATAGCCGGGGGGCTCGGAGGGGATGCCAGTTCTCGGATCTGCAATAAGCCCCCTCATTGATGCTCACTTAATGTCACAACGGTAAATTCATACTCGATCACTGAGCAACTTATGTAAATTCT" }, { "input": "164\nGA?AGGT???T?G?A?G??TTA?TGTG?GTAGT?????T??TTTG?A?T??T?TA?G?T?GGT?????TGTGG?A?A?T?A?T?T?????TT?AAGAG?????T??TATATG?TATT??G?????GGGTATTTT?GG?A??TG??T?GAATGTG?AG?T???A?", "output": "GAAAGGTAAATAGAAAGAATTAATGTGAGTAGTAAAAATAATTTGAACTCCTCTACGCTCGGTCCCCCTGTGGCACACTCACTCTCCCCCTTCAAGAGCCCCCTCCTATATGCTATTCCGCCCCCGGGTATTTTCGGCAGGTGGGTGGAATGTGGAGGTGGGAG" }, { "input": "168\n?C?CAGTCCGT?TCC?GCG?T??T?TA?GG?GCTTGTTTTGT??GC???CTGT??T?T?C?ACG?GTGG??C??TC?GT??CTT?GGT??TGGC??G?TTTCTT?G??C?CTC??CT?G?TT?CG?C?A???GCCGTGAG?CTTC???TTCTCGG?C?CC??GTGCTT", "output": "ACACAGTCCGTATCCAGCGATAATATAAGGAGCTTGTTTTGTAAGCAAACTGTAATATACAACGAGTGGAACAATCAGTAACTTAGGTAATGGCAAGATTTCTTAGAACCCTCCCCTCGCTTCCGCCCACGGGCCGTGAGGCTTCGGGTTCTCGGGCGCCGGGTGCTT" }, { "input": "172\nG?ATG??G?TTT?ATA?GAAGCACTTGCT?AGC??AG??GTTCG?T?G??G?AC?TAGGGCT?TA?TTCTA?TTCAGGAA?GGAAATTGAAG?A?CT?GGTGAGTCTCT?AAACAGT??T??TCAGG?AGTG?TT?TAAT??GG?G?GCA???G?GGA?GACGAATACTCAA", "output": "GAATGAAGATTTAATACGAAGCACTTGCTCAGCCCAGCCGTTCGCTCGCCGCACCTAGGGCTCTACTTCTACTTCAGGAACGGAAATTGAAGCACCTCGGTGAGTCTCTCAAACAGTCCTCCTCAGGCAGTGGTTGTAATGGGGTGTGCATTTGTGGATGACGAATACTCAA" }, { "input": "176\n????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????", "output": "AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT" }, { "input": "180\n?GTTACA?A?A?G??????GGGA?A??T?????C?AC??GG???G????T??CC??T?CGG?AG???GAAGG?????A?GT?G?????CTAA?A??C?A???A?T??C?A???AAA???G?GG?C?A??C???????GTCC?G??GT??G?C?G?C????TT??G????A???A???A?G", "output": "AGTTACAAAAAAGAAAAAAGGGAAAAATAAAAACAACAAGGCCCGCCCCTCCCCCCTCCGGCAGCCCGAAGGCCCCCACGTCGCCCCCCTAACACGCGAGGGAGTGGCGAGGGAAAGGGGGGGGCGAGTCTTTTTTTGTCCTGTTGTTTGTCTGTCTTTTTTTTGTTTTATTTATTTATG" }, { "input": "184\n?CTC?A??????C?T?TG??AC??????G???CCT????CT?C?TT???C???AT????????????T??T?A?AGT?C?C?C?C?CG??CAT?C??C???T??T?TCCTC????C??A???CG?C???C??TC??C?G?C????CTT????C??A?AT??C????T?TCT?T???C?CT??C?", "output": "ACTCAAAAAAAACATATGAAACAAAAAAGAAACCTAAAACTACATTAAACAAAATAAAACCCCCCCCTCCTCACAGTGCGCGCGCGCGGGCATGCGGCGGGTGGTGTCCTCGGGGCGGAGGGCGGCGGGCGGTCGGCGGGCGGGGCTTGTTTCTTATATTTCTTTTTTTCTTTTTTCTCTTTCT" }, { "input": "188\n????TG??A?G?GG?AGA??T??G?TA?ATTT?TTGA??TTA??T?G???GA?G?A??GG??ACTTGT?T?T?TCT?TG?TGAG??GT?A???TT?G???????TA???G?G?GTAG?G?T????????A?TT?TT?T??GGTGT??TTT?T?T?TT???GAGA??G?GGG?G??TG?GT?GT?A??T", "output": "AAAATGAAAAGAGGAAGAAATAAGATAAATTTATTGAAATTAAATAGAAAGAAGAAAAGGACACTTGTCTCTCTCTCTGCTGAGCCGTCACCCTTCGCCCCCCCTACCCGCGCGTAGCGCTCCCCCCCCACTTCTTCTCCGGTGTCCTTTCTCTCTTGGGGAGAGGGGGGGGGGGTGGGTGGTTATTT" }, { "input": "192\nTT???TA?A?TTCTCA?ATCCCC?TA?T??A?A?TGT?TT??TAA?C?C?TA?CTAAAT???AA?TT???T?AATAG?AC??AC?A??A?TT?A?TT?AA?TCTTTC??A?AAA?AA??T?AG?C??AT?T?TATCT?CTTCAA?ACAAAT???AT?TT??????C?CTC???TT?ACACACTGCA?AC??T", "output": "TTAACTACACTTCTCACATCCCCCTACTCCACACTGTCTTCCTAACCCCCTACCTAAATCCCAACTTCGGTGAATAGGACGGACGAGGAGTTGAGTTGAAGTCTTTCGGAGAAAGAAGGTGAGGCGGATGTGTATCTGCTTCAAGACAAATGGGATGTTGGGGGGCGCTCGGGTTGACACACTGCAGACTTT" }, { "input": "196\n??ACATCC??TGA?C?AAA?A???T????A??ACAC????T???????CCC?AAT?T?AT?A?A??TATC??CC?CCACACA?CC?A?AGC??AAA??A???A?CA??A?AT??G???CA?ACATTCG??CACAT?AC???A?A?C?CTTT?AAG??A?TAC???C?GCAA?T??C??AA???GAC?ATTAT????", "output": "ACACATCCCCTGACCCAAACACCCTCCCCACCACACCGGGTGGGGGGGCCCGAATGTGATGAGAGGTATCGGCCGCCACACAGCCGAGAGCGGAAAGGAGGGAGCAGGAGATGGGGGGCAGACATTCGGGCACATTACTTTATATCTCTTTTAAGTTATTACTTTCTGCAATTTTCTTAATTTGACTATTATTTTT" }, { "input": "200\n?CT?T?C???AC?G?CAC?C?T??T?G?AGAGTA?CT????A?CCCAT?GCT?TTC?CAG???TCCATAAC?GACT?TC??C?AG?AA?A?C??ATC?CTAT?AC??????ACCGA??A????C?AA???CGCTTCGC?A????A??GCC?AG?T?????T?A?C?A?CTTC?????T?T?????GC?GTACTC??TG??", "output": "ACTATACAAAACAGACACACATAATAGAAGAGTAACTAAAAAACCCATCGCTCTTCCCAGCCCTCCATAACCGACTCTCCCCCAGCAAGAGCGGATCGCTATGACGGGGGGACCGAGGAGGGGCGAAGGGCGCTTCGCGAGGGGAGGGCCGAGGTGGGTTTTATCTATCTTCTTTTTTTTTTTTTGCTGTACTCTTTGTT" }, { "input": "204\n??????T???T?GC?TC???TA?TC?????A??C?C??G??????G?CTC????A?CTTT?T???T??CTTA???????T??C??G????A?????TTTA??AT?A??C?C?T?C???C?????T???????GT????T????AT?CT????C??C??T???C????C?GCTTCCC?G?????T???C?T??????????TT??", "output": "AAAAAATAAATAGCATCAAATAATCAAAAAAAACACAAGAAAAAAGACTCAAAAAACTTTATAAATACCTTACCCCCCCTCCCCCGCCCCACCCCCTTTACCATCACCCCCGTGCGGGCGGGGGTGGGGGGGGTGGGGTGGGGATGCTGGGGCGGCGGTGGGCGGGGCGGCTTCCCGGGTTTTTTTTCTTTTTTTTTTTTTTTT" }, { "input": "208\nA?GGT?G??A???????G??A?A?GA?T?G???A?AAG?AT????GG?????AT??A?A???T?A??????A????AGGCGT???A???TA????TGGT???GA????GGTG???TA??GA??TA?GGG?????G?????AT?GGGG??TG?T?AA??A??AG?AA?TGA???A?A?GG???GAAT?G?T??T?A??G?CAGT?T?A?", "output": "AAGGTAGAAAAAAAAAAGAAAAAAGAATCGCCCACAAGCATCCCCGGCCCCCATCCACACCCTCACCCCCCACCCCAGGCGTCCCACCCTACCCCTGGTCCCGACCCCGGTGCGGTAGGGAGGTAGGGGGGGGGGGGGGTATTGGGGTTTGTTTAATTATTAGTAATTGATTTATATGGTTTGAATTGTTTTTTATTGTCAGTTTTAT" }, { "input": "212\nT?TTT?A??TC?????A?T??T????T????????C??T??AT????????T???TT????T?TTT??????????TTC???T?T?C??T?TA?C??TTT????T???????C????????A?TT???T??TTT??AT?T????T????T?????A??C????T??T???TA???A?????????T???C????????C???T?TA???TTT", "output": "TATTTAAAATCAAAAAAATAATAAAATAAAAAAAACAATAAATAAAAAAAATAAATTAAAATCTTTCCCCCCCCCCTTCCCCTCTCCCCTCTACCCCTTTCCCCTCCCCCCCCCCCCCCCCACTTCCGTGGTTTGGATGTGGGGTGGGGTGGGGGAGGCGGGGTGGTGGGTAGGGAGGGGGGGGGTGGGCGGGGGGGGCTTTTTTATTTTTT" }, { "input": "216\n?CT?A?CC?GCC?C?AT?A???C???TA????ATGTCCG??CCG?CGG?TCC?TTC??CCT????????G?GGC?TACCCGACCGAG?C???C?G?G??C??CGTCCTG??AGG??CT?G???TC?CT????A?GTA??C?C?CTGTTAC??C?TCT?C?T???T??GTGGA?AG?CGCT?CGTC???T?C?T?C?GTT???C??GCC?T??C?T?", "output": "ACTAAACCAGCCACAATAAAAACAAATAAAAAATGTCCGAACCGACGGATCCATTCAACCTAAAAAAAAGAGGCATACCCGACCGAGACAAACAGAGCCCCCCGTCCTGCGAGGGGCTGGGGGTCGCTGGGGAGGTAGGCGCGCTGTTACGGCGTCTGCGTGGGTTTGTGGATAGTCGCTTCGTCTTTTTCTTTCTGTTTTTCTTGCCTTTTCTTT" }, { "input": "220\n?GCC??????T????G?CTC???CC?C????GC??????C???TCCC???????GCC????????C?C??C?T?C?CC????CC??C???????CC??C?G?A?T???CC??C????????C????CTA?GC?????CC??C?C?????T?????G?????????G???AC????C?CG?????C?G?C?CG?????????G?C????C?G??????C??", "output": "AGCCAAAAAATAAAAGACTCAAACCACAAAAGCAAAAAACAAATCCCAAAAAAAGCCAAAAAAAACACAACATACACCAACCCCCCCCCCCCCGCCGGCGGGAGTGGGCCGGCGGGGGGGGCGGGGCTAGGCGGGGGCCGGCGCGGGGGTGGGGGGTTTTTTTTTGTTTACTTTTCTCGTTTTTCTGTCTCGTTTTTTTTTGTCTTTTCTGTTTTTTCTT" }, { "input": "224\nTTGC?G??A?ATCA??CA???T?TG?C?CGA?CTTA?C??C?TTC?AC?CTCA?A?AT?C?T?CT?CATGT???A??T?CT????C?AACT?TTCCC??C?AAC???AC?TTTC?TTAAA??????TGT????CGCT????GCCC?GCCCA?????TCGA??C?TATACA??C?CC?CATAC?GGACG??GC??GTT?TT?T???GCT??T?C?T?C??T?CC?", "output": "TTGCAGAAAAATCAAACAAAATATGACACGAACTTAACAACATTCAACACTCAAAAATACATACTACATGTAAAACCTCCTCCCCCCAACTGTTCCCGGCGAACGGGACGTTTCGTTAAAGGGGGGTGTGGGGCGCTGGGGGCCCGGCCCAGGGGGTCGAGGCGTATACAGGCGCCGCATACGGGACGGGGCGTGTTTTTTTTTTGCTTTTTCTTTCTTTTCCT" }, { "input": "228\nA??A?C???AG?C?AC???A?T?????AA??????C?A??A?AC?????C?C???A??????A???AC?C????T?C?AA?C??A???CC??????????????????A???CC????A?????C??TC???A???????????A??A????????????????CC?????CCA??????????????C??????C????T?CT???C???A???T?CC?G??C??A?", "output": "AAAAACAAAAGACAACAAAAATAAAAAAAAAAAAACAAAAAAACAAAAACACCCCACCCCCCACCCACCCCCCCTCCCAACCCCACCCCCCCCCGGGGGGGGGGGGGGAGGGCCGGGGAGGGGGCGGTCGGGAGGGGGGGGGGGAGGAGGGGGGGGGGGTTTTTCCTTTTTCCATTTTTTTTTTTTTTCTTTTTTCTTTTTTCTTTTCTTTATTTTTCCTGTTCTTAT" }, { "input": "232\nA??AAGC?GCG?AG???GGGCG?C?A?GCAAC?AG?C?GC??CA??A??CC?AA?A????G?AGA?ACACA?C?G?G?G?CGC??G???????GAGC?CAA??????G?A???AGGG?????AAC?AG?A?A??AG?CG?G???G????GGGA?C?G?A?A??GC????C??A?ACG?AA?G?ACG????AC?C?GA??GGCAG?GAA??ACA??A?AGGAGG???CGGA?C", "output": "AAAAAGCAGCGAAGAAAGGGCGACAAAGCAACCAGCCCGCCCCACCACCCCCAACACCCCGCAGACACACACCCGCGCGCCGCCCGCCCGGGGGAGCGCAAGGGGGTGTATTTAGGGTTTTTAACTAGTATATTAGTCGTGTTTGTTTTGGGATCTGTATATTGCTTTTCTTATACGTAATGTACGTTTTACTCTGATTGGCAGTGAATTACATTATAGGAGGTTTCGGATC" }, { "input": "236\nAAGCCC?A?TT??C?AATGC?A?GC?GACGT?CTT?TA??CCG?T?CAA?AGT?CTG???GCGATG?TG?A?A?ACT?AT?GGG?GC?C?CGCCCTT?GT??G?T?????GACTT??????CT?GA?GG?C?T?G??CTG??G??TG?TCA?TCGTT?GC?A?G?GGGT?CG?CGAG??CG?TC?TAT?A???T??GAGTC?CGGC?CG??CT?TAAT??GGAA?G??GG?GCGAC", "output": "AAGCCCAAATTAACAAATGCAAAGCAGACGTACTTATAAACCGATACAAAAGTACTGAAAGCGATGATGAAAAAACTAATAGGGAGCACACGCCCTTAGTACGCTCCCCCGACTTCCCCCCCTCGACGGCCCTCGCCCTGCGGGGTGGTCAGTCGTTGGCGAGGGGGGTGCGTCGAGTTCGTTCTTATTATTTTTTGAGTCTCGGCTCGTTCTTTAATTTGGAATGTTGGTGCGAC" }, { "input": "240\n?T?A?A??G????G????AGGAGTAA?AGGCT??C????AT?GAA?ATGCT???GA?G?A??G?TC??TATT???AG?G?G?A?A??TTGT??GGTCAG?GA?G?AAT?G?GG??CAG?T?GT?G?GC???GC??????GA?A?AAATGGGC??G??????TTA??GTCG?TC?GCCG?GGGA??T?A????T?G?T???G?GG?ATG???A?ATGAC?GGT?CTG?AGGG??TAGT?AG", "output": "ATAAAAAAGAAAAGAAAAAGGAGTAAAAGGCTAACAAAAATAGAAAATGCTACCGACGCACCGCTCCCTATTCCCAGCGCGCACACCTTGTCCGGTCAGCGACGCAATCGCGGCCCAGCTCGTCGCGCCCCGCCCCCCCGACACAAATGGGCCCGCGGGGGTTATTGTCGTTCTGCCGTGGGATTTTATTTTTTGTTTTTGTGGTATGTTTATATGACTGGTTCTGTAGGGTTTAGTTAG" }, { "input": "244\nC?GT???T??TA?CC??TACT???TC?C?A???G??G?TCC?AC??AA???C?CCACC????A?AGCC??T?CT??CCGG?CC?T?C??GCCCTGGCCAAAC???GC?C???AT?CC?CT?TAG??CG?C?T?C??A?AC?GC????A??C?C?A??TC?T????GCCCT??GG???CC?A?CC?G?A?CA?G??CCCG??CG?T?TAC?G???C?AC??G??CCA???G????C??G?CT?C?", "output": "CAGTAAATAATAACCAATACTAAATCACAAAAAGAAGATCCAACAAAAAAACACCACCAAAAAAAGCCAATACTAACCGGGCCGTGCGGGCCCTGGCCAAACGGGGCGCGGGATGCCGCTGTAGGGCGGCGTGCGGAGACGGCGGGGAGGCGCGAGGTCGTGGTTGCCCTTTGGTTTCCTATCCTGTATCATGTTCCCGTTCGTTTTACTGTTTCTACTTGTTCCATTTGTTTTCTTGTCTTCT" }, { "input": "248\n??TC???TG??G??T????CC???C?G?????G?????GT?A?CT?AAT?GG?AGA?????????G???????G???CG??AA?A????T???????TG?CA????C?TT?G?GC???AA?G????G????T??G??A??????TT???G???CG?????A??A??T?GA??G??T?CC?TA??GCTG?A????G?CG??GGTG??CA???????TA??G?????????A???????GC?GG????GC", "output": "AATCAAATGAAGAATAAAACCAAACAGAAAAAGAAAAAGTAAACTAAATAGGAAGAAAAAAAAAAGACCCCCCGCCCCGCCAACACCCCTCCCCCCCTGCCACCCCCCTTCGCGCCCCAACGCCCCGCCCCTCCGGGAGGGGGGTTGGGGGGGCGGGGGGAGGAGGTGGAGGGGGTGCCTTATTGCTGTATTTTGTCGTTGGTGTTCATTTTTTTTATTGTTTTTTTTTATTTTTTTGCTGGTTTTGC" }, { "input": "8\n???AAA??", "output": "===" }, { "input": "12\nC??CC??????C", "output": "===" }, { "input": "4\nG??G", "output": "===" }, { "input": "4\nTT??", "output": "===" }, { "input": "4\nACAC", "output": "===" }, { "input": "8\nACGT???T", "output": "ACGTACGT" }, { "input": "252\n????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????", "output": "AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT" }, { "input": "252\n??????????????????????????????????????????????????????????????????????????????A?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????", "output": "AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACCCCCCCCCCCCCCCCACCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT" }, { "input": "252\n???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????C????????????????????????????????????????????????????????????????", "output": "AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGCGTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT" }, { "input": "252\n???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????G", "output": "AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTG" }, { "input": "252\nT???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????", "output": "TAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT" }, { "input": "4\nAA?T", "output": "===" }, { "input": "4\nAAAA", "output": "===" }, { "input": "8\nAAA?????", "output": "===" }, { "input": "10\nACGT??????", "output": "===" }, { "input": "6\nACGACG", "output": "===" }, { "input": "5\nAAAAA", "output": "===" }, { "input": "8\nGGGGAA??", "output": "===" }, { "input": "5\nATGCA", "output": "===" }, { "input": "4\nTTTT", "output": "===" }, { "input": "4\nACCG", "output": "===" }, { "input": "8\nACGTA?GT", "output": "ACGTACGT" } ]

1,596,014,538

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

4

109

6,963,200

l=int(input()) s=str(input()) if l%4!=0: print("===") else: a=[] x=0 y=0 c1=s.count('A') c2 = s.count('G') c3 = s.count('C') c4 = s.count('T') a.append(c1) a.append(c2) a.append(c3) a.append(c4) c5=s.count('?') if c5==0: print(s) else: a.sort() x=max(a) y=x-a[0] y=y+(x-a[1]) y=y+(x-a[2]) if y==c5: for k in range(l): if s[k]=='?': if c1<x: print('A',end="") c1=c1+1 elif c2<x: print('G',end="") c2 = c2 + 1 elif c3<x: print('C',end="") c3 = c3 + 1 else : c4=c4+1 print('T',end="") else: print(s[k],end="") else: print("===") #x=x-c1 #x=x-c2 #x=x-c3

Title: Mammoth's Genome Decoding Time Limit: None seconds Memory Limit: None megabytes Problem Description: The process of mammoth's genome decoding in Berland comes to its end! One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, *s* is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'. It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal. Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal. Input Specification: The first line contains the integer *n* (4<=≤<=*n*<=≤<=255) — the length of the genome. The second line contains the string *s* of length *n* — the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'. Output Specification: If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes). Demo Input: ['8\nAG?C??CT\n', '4\nAGCT\n', '6\n????G?\n', '4\nAA??\n'] Demo Output: ['AGACGTCT\n', 'AGCT\n', '===\n', '===\n'] Note: In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice. In the second example the genome is already decoded correctly and each nucleotide is exactly once in it. In the third and the fourth examples it is impossible to decode the genom.

```python l=int(input()) s=str(input()) if l%4!=0: print("===") else: a=[] x=0 y=0 c1=s.count('A') c2 = s.count('G') c3 = s.count('C') c4 = s.count('T') a.append(c1) a.append(c2) a.append(c3) a.append(c4) c5=s.count('?') if c5==0: print(s) else: a.sort() x=max(a) y=x-a[0] y=y+(x-a[1]) y=y+(x-a[2]) if y==c5: for k in range(l): if s[k]=='?': if c1<x: print('A',end="") c1=c1+1 elif c2<x: print('G',end="") c2 = c2 + 1 elif c3<x: print('C',end="") c3 = c3 + 1 else : c4=c4+1 print('T',end="") else: print(s[k],end="") else: print("===") #x=x-c1 #x=x-c2 #x=x-c3 ```

0

25

A

IQ test

PROGRAMMING

1,300

[ "brute force" ]

A. IQ test

2

256

Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.

The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.

Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.

[ "5\n2 4 7 8 10\n", "4\n1 2 1 1\n" ]

[ "3\n", "2\n" ]

none

0

[ { "input": "5\n2 4 7 8 10", "output": "3" }, { "input": "4\n1 2 1 1", "output": "2" }, { "input": "3\n1 2 2", "output": "1" }, { "input": "3\n100 99 100", "output": "2" }, { "input": "3\n5 3 2", "output": "3" }, { "input": "4\n43 28 1 91", "output": "2" }, { "input": "4\n75 13 94 77", "output": "3" }, { "input": "4\n97 8 27 3", "output": "2" }, { "input": "10\n95 51 12 91 85 3 1 31 25 7", "output": "3" }, { "input": "20\n88 96 66 51 14 88 2 92 18 72 18 88 20 30 4 82 90 100 24 46", "output": "4" }, { "input": "30\n20 94 56 50 10 98 52 32 14 22 24 60 4 8 98 46 34 68 82 82 98 90 50 20 78 49 52 94 64 36", "output": "26" }, { "input": "50\n79 27 77 57 37 45 27 49 65 33 57 21 71 19 75 85 65 61 23 97 85 9 23 1 9 3 99 77 77 21 79 69 15 37 15 7 93 81 13 89 91 31 45 93 15 97 55 80 85 83", "output": "48" }, { "input": "60\n46 11 73 65 3 69 3 53 43 53 97 47 55 93 31 75 35 3 9 73 23 31 3 81 91 79 61 21 15 11 11 11 81 7 83 75 39 87 83 59 89 55 93 27 49 67 67 29 1 93 11 17 9 19 35 21 63 31 31 25", "output": "1" }, { "input": "70\n28 42 42 92 64 54 22 38 38 78 62 38 4 38 14 66 4 92 66 58 94 26 4 44 41 88 48 82 44 26 74 44 48 4 16 92 34 38 26 64 94 4 30 78 50 54 12 90 8 16 80 98 28 100 74 50 36 42 92 18 76 98 8 22 2 50 58 50 64 46", "output": "25" }, { "input": "100\n43 35 79 53 13 91 91 45 65 83 57 9 42 39 85 45 71 51 61 59 31 13 63 39 25 21 79 39 91 67 21 61 97 75 93 83 29 79 59 97 11 37 63 51 39 55 91 23 21 17 47 23 35 75 49 5 69 99 5 7 41 17 25 89 15 79 21 63 53 81 43 91 59 91 69 99 85 15 91 51 49 37 65 7 89 81 21 93 61 63 97 93 45 17 13 69 57 25 75 73", "output": "13" }, { "input": "100\n50 24 68 60 70 30 52 22 18 74 68 98 20 82 4 46 26 68 100 78 84 58 74 98 38 88 68 86 64 80 82 100 20 22 98 98 52 6 94 10 48 68 2 18 38 22 22 82 44 20 66 72 36 58 64 6 36 60 4 96 76 64 12 90 10 58 64 60 74 28 90 26 24 60 40 58 2 16 76 48 58 36 82 60 24 44 4 78 28 38 8 12 40 16 38 6 66 24 31 76", "output": "99" }, { "input": "100\n47 48 94 48 14 18 94 36 96 22 12 30 94 20 48 98 40 58 2 94 8 36 98 18 98 68 2 60 76 38 18 100 8 72 100 68 2 86 92 72 58 16 48 14 6 58 72 76 6 88 80 66 20 28 74 62 86 68 90 86 2 56 34 38 56 90 4 8 76 44 32 86 12 98 38 34 54 92 70 94 10 24 82 66 90 58 62 2 32 58 100 22 58 72 2 22 68 72 42 14", "output": "1" }, { "input": "99\n38 20 68 60 84 16 28 88 60 48 80 28 4 92 70 60 46 46 20 34 12 100 76 2 40 10 8 86 6 80 50 66 12 34 14 28 26 70 46 64 34 96 10 90 98 96 56 88 50 74 70 94 2 94 24 66 68 46 22 30 6 10 64 32 88 14 98 100 64 58 50 18 50 50 8 38 8 16 54 2 60 54 62 84 92 98 4 72 66 26 14 88 99 16 10 6 88 56 22", "output": "93" }, { "input": "99\n50 83 43 89 53 47 69 1 5 37 63 87 95 15 55 95 75 89 33 53 89 75 93 75 11 85 49 29 11 97 49 67 87 11 25 37 97 73 67 49 87 43 53 97 43 29 53 33 45 91 37 73 39 49 59 5 21 43 87 35 5 63 89 57 63 47 29 99 19 85 13 13 3 13 43 19 5 9 61 51 51 57 15 89 13 97 41 13 99 79 13 27 97 95 73 33 99 27 23", "output": "1" }, { "input": "98\n61 56 44 30 58 14 20 24 88 28 46 56 96 52 58 42 94 50 46 30 46 80 72 88 68 16 6 60 26 90 10 98 76 20 56 40 30 16 96 20 88 32 62 30 74 58 36 76 60 4 24 36 42 54 24 92 28 14 2 74 86 90 14 52 34 82 40 76 8 64 2 56 10 8 78 16 70 86 70 42 70 74 22 18 76 98 88 28 62 70 36 72 20 68 34 48 80 98", "output": "1" }, { "input": "98\n66 26 46 42 78 32 76 42 26 82 8 12 4 10 24 26 64 44 100 46 94 64 30 18 88 28 8 66 30 82 82 28 74 52 62 80 80 60 94 86 64 32 44 88 92 20 12 74 94 28 34 58 4 22 16 10 94 76 82 58 40 66 22 6 30 32 92 54 16 76 74 98 18 48 48 30 92 2 16 42 84 74 30 60 64 52 50 26 16 86 58 96 79 60 20 62 82 94", "output": "93" }, { "input": "95\n9 31 27 93 17 77 75 9 9 53 89 39 51 99 5 1 11 39 27 49 91 17 27 79 81 71 37 75 35 13 93 4 99 55 85 11 23 57 5 43 5 61 15 35 23 91 3 81 99 85 43 37 39 27 5 67 7 33 75 59 13 71 51 27 15 93 51 63 91 53 43 99 25 47 17 71 81 15 53 31 59 83 41 23 73 25 91 91 13 17 25 13 55 57 29", "output": "32" }, { "input": "100\n91 89 81 45 53 1 41 3 77 93 55 97 55 97 87 27 69 95 73 41 93 21 75 35 53 56 5 51 87 59 91 67 33 3 99 45 83 17 97 47 75 97 7 89 17 99 23 23 81 25 55 97 27 35 69 5 77 35 93 19 55 59 37 21 31 37 49 41 91 53 73 69 7 37 37 39 17 71 7 97 55 17 47 23 15 73 31 39 57 37 9 5 61 41 65 57 77 79 35 47", "output": "26" }, { "input": "99\n38 56 58 98 80 54 26 90 14 16 78 92 52 74 40 30 84 14 44 80 16 90 98 68 26 24 78 72 42 16 84 40 14 44 2 52 50 2 12 96 58 66 8 80 44 52 34 34 72 98 74 4 66 74 56 21 8 38 76 40 10 22 48 32 98 34 12 62 80 68 64 82 22 78 58 74 20 22 48 56 12 38 32 72 6 16 74 24 94 84 26 38 18 24 76 78 98 94 72", "output": "56" }, { "input": "100\n44 40 6 40 56 90 98 8 36 64 76 86 98 76 36 92 6 30 98 70 24 98 96 60 24 82 88 68 86 96 34 42 58 10 40 26 56 10 88 58 70 32 24 28 14 82 52 12 62 36 70 60 52 34 74 30 78 76 10 16 42 94 66 90 70 38 52 12 58 22 98 96 14 68 24 70 4 30 84 98 8 50 14 52 66 34 100 10 28 100 56 48 38 12 38 14 91 80 70 86", "output": "97" }, { "input": "100\n96 62 64 20 90 46 56 90 68 36 30 56 70 28 16 64 94 34 6 32 34 50 94 22 90 32 40 2 72 10 88 38 28 92 20 26 56 80 4 100 100 90 16 74 74 84 8 2 30 20 80 32 16 46 92 56 42 12 96 64 64 42 64 58 50 42 74 28 2 4 36 32 70 50 54 92 70 16 45 76 28 16 18 50 48 2 62 94 4 12 52 52 4 100 70 60 82 62 98 42", "output": "79" }, { "input": "99\n14 26 34 68 90 58 50 36 8 16 18 6 2 74 54 20 36 84 32 50 52 2 26 24 3 64 20 10 54 26 66 44 28 72 4 96 78 90 96 86 68 28 94 4 12 46 100 32 22 36 84 32 44 94 76 94 4 52 12 30 74 4 34 64 58 72 44 16 70 56 54 8 14 74 8 6 58 62 98 54 14 40 80 20 36 72 28 98 20 58 40 52 90 64 22 48 54 70 52", "output": "25" }, { "input": "95\n82 86 30 78 6 46 80 66 74 72 16 24 18 52 52 38 60 36 86 26 62 28 22 46 96 26 94 84 20 46 66 88 76 32 12 86 74 18 34 88 4 48 94 6 58 6 100 82 4 24 88 32 54 98 34 48 6 76 42 88 42 28 100 4 22 2 10 66 82 54 98 20 60 66 38 98 32 47 86 58 6 100 12 46 2 42 8 84 78 28 24 70 34 28 86", "output": "78" }, { "input": "90\n40 50 8 42 76 24 58 42 26 68 20 48 54 12 34 84 14 36 32 88 6 50 96 56 20 92 48 16 40 34 96 46 20 84 30 50 20 98 8 44 96 42 8 76 70 38 84 30 40 88 84 72 2 22 52 58 16 62 100 66 80 40 50 32 14 62 88 72 22 99 76 50 84 82 8 82 98 46 26 40 2 98 18 78 30 72 70 18 34 68", "output": "70" }, { "input": "80\n81 43 87 1 55 43 53 61 27 19 43 13 89 9 33 83 75 55 97 71 91 37 95 5 21 69 81 93 95 69 31 83 55 7 97 7 79 57 8 61 27 85 49 1 15 97 63 79 29 73 41 85 5 41 31 93 67 11 63 59 15 99 91 77 43 69 23 23 81 73 19 1 67 51 1 75 99 67 3 81", "output": "39" }, { "input": "98\n13 83 61 27 35 1 85 95 97 73 95 65 73 45 5 43 27 83 91 19 11 3 85 59 9 39 69 23 45 7 51 85 5 71 5 95 1 51 75 3 43 57 3 11 33 71 21 99 47 41 87 39 71 87 31 85 91 49 83 5 49 85 47 91 55 99 33 23 31 23 23 73 29 77 55 31 25 5 81 49 91 15 15 39 87 5 9 40 69 47 29 33 11 21 49 79 51 83", "output": "88" }, { "input": "3\n100 100 1", "output": "3" } ]

1,634,136,783

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

1

62

0

n = int(input()) L = input().split() L.sort(key=float) if len(L) == 3: if L[0] == L[1]: print(3) exit() else: if L[0] == L[2]: print(2) exit() else: print(1) exit() if len(L) == 4: Y = [] Z = [] for first in range(4): for second in range(4): if second > first: Y.append((int(L[second]) - int(L[first])) / (second - first)) for th in range(6): numb = 1 for nd in range(6): if th != nd and Y[th] == Y[nd]: numb += 1 if numb != 2: Z.append(th) Z.sort(key=int) if 0 in Z and 1 in Z and 2 in Z: print(1) exit() else: print(int(Z[0]) + 2) exit() delta = [] ques = [] for x in range(1,len(L)): delta.append(int(L[x])-int(L[x - 1])) for i in range(len(delta)): num = 0 for j in range(len(delta)): if delta[i] == delta[j]: num += 1 if num == 1: ques.append(i) ques.sort(key=int) if len(ques) == 1: print(int(ques[0] + 1)) else: print(int(ques[0]) + 2)

Title: IQ test Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. Input Specification: The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. Output Specification: Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. Demo Input: ['5\n2 4 7 8 10\n', '4\n1 2 1 1\n'] Demo Output: ['3\n', '2\n'] Note: none

```python n = int(input()) L = input().split() L.sort(key=float) if len(L) == 3: if L[0] == L[1]: print(3) exit() else: if L[0] == L[2]: print(2) exit() else: print(1) exit() if len(L) == 4: Y = [] Z = [] for first in range(4): for second in range(4): if second > first: Y.append((int(L[second]) - int(L[first])) / (second - first)) for th in range(6): numb = 1 for nd in range(6): if th != nd and Y[th] == Y[nd]: numb += 1 if numb != 2: Z.append(th) Z.sort(key=int) if 0 in Z and 1 in Z and 2 in Z: print(1) exit() else: print(int(Z[0]) + 2) exit() delta = [] ques = [] for x in range(1,len(L)): delta.append(int(L[x])-int(L[x - 1])) for i in range(len(delta)): num = 0 for j in range(len(delta)): if delta[i] == delta[j]: num += 1 if num == 1: ques.append(i) ques.sort(key=int) if len(ques) == 1: print(int(ques[0] + 1)) else: print(int(ques[0]) + 2) ```

0

710

A

King Moves

PROGRAMMING

800

[ "implementation" ]

null

The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king. Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wiki/King_(chess)).

The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'.

Print the only integer *x* — the number of moves permitted for the king.

[ "e4\n" ]

[ "8\n" ]

none

0

[ { "input": "e4", "output": "8" }, { "input": "a1", "output": "3" }, { "input": "h8", "output": "3" }, { "input": "a4", "output": "5" }, { "input": "g7", "output": "8" }, { "input": "e1", "output": "5" }, { "input": "b2", "output": "8" }, { "input": "c7", "output": "8" }, { "input": "h6", "output": "5" }, { "input": "c8", "output": "5" }, { "input": "h2", "output": "5" }, { "input": "h5", "output": "5" }, { "input": "a8", "output": "3" }, { "input": "f8", "output": "5" }, { "input": "h1", "output": "3" }, { "input": "f2", "output": "8" }, { "input": "e8", "output": "5" }, { "input": "h3", "output": "5" }, { "input": "b8", "output": "5" }, { "input": "g8", "output": "5" }, { "input": "d8", "output": "5" }, { "input": "h4", "output": "5" }, { "input": "b1", "output": "5" }, { "input": "a2", "output": "5" } ]

1,584,179,348

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

1

108

0

s = input() s1 = "a8h8a1h1" if s[1] == "8" or s[1] == "1" or s[0] == "a" or s[0] == "h": print(5) elif s in s1: print(3) else: print(8)

Title: King Moves Time Limit: None seconds Memory Limit: None megabytes Problem Description: The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king. Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wiki/King_(chess)). Input Specification: The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'. Output Specification: Print the only integer *x* — the number of moves permitted for the king. Demo Input: ['e4\n'] Demo Output: ['8\n'] Note: none

```python s = input() s1 = "a8h8a1h1" if s[1] == "8" or s[1] == "1" or s[0] == "a" or s[0] == "h": print(5) elif s in s1: print(3) else: print(8) ```

0

239

A

Two Bags of Potatoes

PROGRAMMING

1,200

[ "greedy", "implementation", "math" ]

null

Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, firstly, was not gerater than *n*, and, secondly, was divisible by *k*. Help Valera to determine how many potatoes could be in the first bag. Print all such possible numbers in ascending order.

The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105).

Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once. If there are no such values of *x* print a single integer -1.

[ "10 1 10\n", "10 6 40\n" ]

[ "-1\n", "2 8 14 20 26 \n" ]

none

500

[ { "input": "10 1 10", "output": "-1" }, { "input": "10 6 40", "output": "2 8 14 20 26 " }, { "input": "10 1 20", "output": "1 2 3 4 5 6 7 8 9 10 " }, { "input": "1 10000 1000000000", "output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 129999 139999 149999 159999 169999 179999 189999 199999 209999 219999 229999 239999 249999 259999 269999 279999 289999 299999 309999 319999 329999 339999 349999 359999 369999 379999 389999 399999 409999 419999 429999 439999 449999 459999 469999 479999 489999 499999 509999 519999 529999 539999 549999 559999 569999 579999 589999 599999 609999 619999 629999 639999 649999 659999 669999 679999 689999 699999 709999 719999 729999 739999 7499..." }, { "input": "84817 1 33457", "output": "-1" }, { "input": "21 37 99", "output": "16 53 " }, { "input": "78 7 15", "output": "-1" }, { "input": "74 17 27", "output": "-1" }, { "input": "79 23 43", "output": "-1" }, { "input": "32 33 3", "output": "-1" }, { "input": "55 49 44", "output": "-1" }, { "input": "64 59 404", "output": "54 113 172 231 290 " }, { "input": "61 69 820", "output": "8 77 146 215 284 353 422 491 560 629 698 " }, { "input": "17 28 532", "output": "11 39 67 95 123 151 179 207 235 263 291 319 347 375 403 431 459 487 515 " }, { "input": "46592 52 232", "output": "-1" }, { "input": "1541 58 648", "output": "-1" }, { "input": "15946 76 360", "output": "-1" }, { "input": "30351 86 424", "output": "-1" }, { "input": "1 2 37493", "output": "1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 101 103 105 107 109 111 113 115 117 119 121 123 125 127 129 131 133 135 137 139 141 143 145 147 149 151 153 155 157 159 161 163 165 167 169 171 173 175 177 179 181 183 185 187 189 191 193 195 197 199 201 203 205 207 209 211 213 215 217 219 221 223 225 227 229 231 233 235 237 239 241 243 245 247 249 251 253 255 257 259 261 263 265 267 269 271 273 275 277 279 281 28..." }, { "input": "1 3 27764", "output": "2 5 8 11 14 17 20 23 26 29 32 35 38 41 44 47 50 53 56 59 62 65 68 71 74 77 80 83 86 89 92 95 98 101 104 107 110 113 116 119 122 125 128 131 134 137 140 143 146 149 152 155 158 161 164 167 170 173 176 179 182 185 188 191 194 197 200 203 206 209 212 215 218 221 224 227 230 233 236 239 242 245 248 251 254 257 260 263 266 269 272 275 278 281 284 287 290 293 296 299 302 305 308 311 314 317 320 323 326 329 332 335 338 341 344 347 350 353 356 359 362 365 368 371 374 377 380 383 386 389 392 395 398 401 404 407 410..." }, { "input": "10 4 9174", "output": "2 6 10 14 18 22 26 30 34 38 42 46 50 54 58 62 66 70 74 78 82 86 90 94 98 102 106 110 114 118 122 126 130 134 138 142 146 150 154 158 162 166 170 174 178 182 186 190 194 198 202 206 210 214 218 222 226 230 234 238 242 246 250 254 258 262 266 270 274 278 282 286 290 294 298 302 306 310 314 318 322 326 330 334 338 342 346 350 354 358 362 366 370 374 378 382 386 390 394 398 402 406 410 414 418 422 426 430 434 438 442 446 450 454 458 462 466 470 474 478 482 486 490 494 498 502 506 510 514 518 522 526 530 534 53..." }, { "input": "33 7 4971", "output": "2 9 16 23 30 37 44 51 58 65 72 79 86 93 100 107 114 121 128 135 142 149 156 163 170 177 184 191 198 205 212 219 226 233 240 247 254 261 268 275 282 289 296 303 310 317 324 331 338 345 352 359 366 373 380 387 394 401 408 415 422 429 436 443 450 457 464 471 478 485 492 499 506 513 520 527 534 541 548 555 562 569 576 583 590 597 604 611 618 625 632 639 646 653 660 667 674 681 688 695 702 709 716 723 730 737 744 751 758 765 772 779 786 793 800 807 814 821 828 835 842 849 856 863 870 877 884 891 898 905 912 919..." }, { "input": "981 1 3387", "output": "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155..." }, { "input": "386 1 2747", "output": "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155..." }, { "input": "123 2 50000", "output": "1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 101 103 105 107 109 111 113 115 117 119 121 123 125 127 129 131 133 135 137 139 141 143 145 147 149 151 153 155 157 159 161 163 165 167 169 171 173 175 177 179 181 183 185 187 189 191 193 195 197 199 201 203 205 207 209 211 213 215 217 219 221 223 225 227 229 231 233 235 237 239 241 243 245 247 249 251 253 255 257 259 261 263 265 267 269 271 273 275 277 279 281 28..." }, { "input": "3123 100 10000000", "output": "77 177 277 377 477 577 677 777 877 977 1077 1177 1277 1377 1477 1577 1677 1777 1877 1977 2077 2177 2277 2377 2477 2577 2677 2777 2877 2977 3077 3177 3277 3377 3477 3577 3677 3777 3877 3977 4077 4177 4277 4377 4477 4577 4677 4777 4877 4977 5077 5177 5277 5377 5477 5577 5677 5777 5877 5977 6077 6177 6277 6377 6477 6577 6677 6777 6877 6977 7077 7177 7277 7377 7477 7577 7677 7777 7877 7977 8077 8177 8277 8377 8477 8577 8677 8777 8877 8977 9077 9177 9277 9377 9477 9577 9677 9777 9877 9977 10077 10177 10277 1037..." }, { "input": "2 10000 1000000000", "output": "9998 19998 29998 39998 49998 59998 69998 79998 89998 99998 109998 119998 129998 139998 149998 159998 169998 179998 189998 199998 209998 219998 229998 239998 249998 259998 269998 279998 289998 299998 309998 319998 329998 339998 349998 359998 369998 379998 389998 399998 409998 419998 429998 439998 449998 459998 469998 479998 489998 499998 509998 519998 529998 539998 549998 559998 569998 579998 589998 599998 609998 619998 629998 639998 649998 659998 669998 679998 689998 699998 709998 719998 729998 739998 7499..." }, { "input": "3 10000 1000000000", "output": "9997 19997 29997 39997 49997 59997 69997 79997 89997 99997 109997 119997 129997 139997 149997 159997 169997 179997 189997 199997 209997 219997 229997 239997 249997 259997 269997 279997 289997 299997 309997 319997 329997 339997 349997 359997 369997 379997 389997 399997 409997 419997 429997 439997 449997 459997 469997 479997 489997 499997 509997 519997 529997 539997 549997 559997 569997 579997 589997 599997 609997 619997 629997 639997 649997 659997 669997 679997 689997 699997 709997 719997 729997 739997 7499..." }, { "input": "12312223 10000 1000000000", "output": "7777 17777 27777 37777 47777 57777 67777 77777 87777 97777 107777 117777 127777 137777 147777 157777 167777 177777 187777 197777 207777 217777 227777 237777 247777 257777 267777 277777 287777 297777 307777 317777 327777 337777 347777 357777 367777 377777 387777 397777 407777 417777 427777 437777 447777 457777 467777 477777 487777 497777 507777 517777 527777 537777 547777 557777 567777 577777 587777 597777 607777 617777 627777 637777 647777 657777 667777 677777 687777 697777 707777 717777 727777 737777 7477..." }, { "input": "500000000 1000000000 1000000000", "output": "500000000 " }, { "input": "1 1000000000 1000000000", "output": "999999999 " }, { "input": "10 6 11", "output": "-1" }, { "input": "2 100 10", "output": "-1" }, { "input": "1 100000007 1000000000", "output": "100000006 200000013 300000020 400000027 500000034 600000041 700000048 800000055 900000062 " }, { "input": "1 999999999 1000000000", "output": "999999998 " }, { "input": "100000000 1000000000 1000000000", "output": "900000000 " }, { "input": "11 2 12", "output": "1 " }, { "input": "31 10 39", "output": "-1" }, { "input": "48 6 50", "output": "-1" }, { "input": "500000000 500000000 1000000000", "output": "500000000 " }, { "input": "1 1000000000 999999999", "output": "-1" }, { "input": "4 2 10", "output": "2 4 6 " }, { "input": "1000000000 1 1", "output": "-1" }, { "input": "1000000000 1 100000", "output": "-1" }, { "input": "1000000000 1 10", "output": "-1" }, { "input": "10 5 14", "output": "-1" }, { "input": "500000000 499999999 1000000000", "output": "499999998 " }, { "input": "1 999999997 1000000000", "output": "999999996 " } ]

1,620,368,963

2,147,483,647

PyPy 3

OK

TESTS

48

374

27,648,000

def solve(): y,k,n = map(int, input().split()) if n<=y: print(-1) return else: x = 1 z = [] x = k-(y%k) while (x+y)%k==0 and (x+y) <= n: z.append(x) x+=k if len(z) == 0: print(-1) return print(*z) try: solve() except: pass

Title: Two Bags of Potatoes Time Limit: None seconds Memory Limit: None megabytes Problem Description: Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, firstly, was not gerater than *n*, and, secondly, was divisible by *k*. Help Valera to determine how many potatoes could be in the first bag. Print all such possible numbers in ascending order. Input Specification: The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). Output Specification: Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once. If there are no such values of *x* print a single integer -1. Demo Input: ['10 1 10\n', '10 6 40\n'] Demo Output: ['-1\n', '2 8 14 20 26 \n'] Note: none

```python def solve(): y,k,n = map(int, input().split()) if n<=y: print(-1) return else: x = 1 z = [] x = k-(y%k) while (x+y)%k==0 and (x+y) <= n: z.append(x) x+=k if len(z) == 0: print(-1) return print(*z) try: solve() except: pass ```

3

998

A

Balloons

PROGRAMMING

1,000

[ "constructive algorithms", "implementation" ]

null

There are quite a lot of ways to have fun with inflatable balloons. For example, you can fill them with water and see what happens. Grigory and Andrew have the same opinion. So, once upon a time, they went to the shop and bought $n$ packets with inflatable balloons, where $i$-th of them has exactly $a_i$ balloons inside. They want to divide the balloons among themselves. In addition, there are several conditions to hold: - Do not rip the packets (both Grigory and Andrew should get unbroken packets); - Distribute all packets (every packet should be given to someone); - Give both Grigory and Andrew at least one packet; - To provide more fun, the total number of balloons in Grigory's packets should not be equal to the total number of balloons in Andrew's packets. Help them to divide the balloons or determine that it's impossible under these conditions.

The first line of input contains a single integer $n$ ($1 \le n \le 10$) — the number of packets with balloons. The second line contains $n$ integers: $a_1$, $a_2$, $\ldots$, $a_n$ ($1 \le a_i \le 1000$) — the number of balloons inside the corresponding packet.

If it's impossible to divide the balloons satisfying the conditions above, print $-1$. Otherwise, print an integer $k$ — the number of packets to give to Grigory followed by $k$ distinct integers from $1$ to $n$ — the indices of those. The order of packets doesn't matter. If there are multiple ways to divide balloons, output any of them.

[ "3\n1 2 1\n", "2\n5 5\n", "1\n10\n" ]

[ "2\n1 2\n", "-1\n", "-1\n" ]

In the first test Grigory gets $3$ balloons in total while Andrey gets $1$. In the second test there's only one way to divide the packets which leads to equal numbers of balloons. In the third test one of the boys won't get a packet at all.

500

[ { "input": "3\n1 2 1", "output": "1\n1" }, { "input": "2\n5 5", "output": "-1" }, { "input": "1\n10", "output": "-1" }, { "input": "1\n1", "output": "-1" }, { "input": "10\n1 1 1 1 1 1 1 1 1 1", "output": "1\n1" }, { "input": "10\n1 1 1 1 1 1 1 1 1 9", "output": "1\n1" }, { "input": "10\n26 723 970 13 422 968 875 329 234 983", "output": "1\n4" }, { "input": "3\n3 2 1", "output": "1\n3" }, { "input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000", "output": "1\n1" }, { "input": "10\n1 9 7 6 2 4 7 8 1 3", "output": "1\n1" }, { "input": "2\n9 6", "output": "1\n2" }, { "input": "2\n89 7", "output": "1\n2" }, { "input": "2\n101 807", "output": "1\n1" }, { "input": "5\n8 7 4 8 3", "output": "1\n5" }, { "input": "5\n55 62 70 100 90", "output": "1\n1" }, { "input": "5\n850 840 521 42 169", "output": "1\n4" }, { "input": "6\n7 1 4 1 6 1", "output": "1\n2" }, { "input": "6\n36 80 38 88 79 69", "output": "1\n1" }, { "input": "6\n108 318 583 10 344 396", "output": "1\n4" }, { "input": "9\n10 9 10 10 8 3 5 10 2", "output": "1\n9" }, { "input": "9\n90 31 28 63 57 57 27 62 42", "output": "1\n7" }, { "input": "9\n665 646 152 829 190 64 555 536 321", "output": "1\n6" }, { "input": "10\n99 62 10 47 53 9 83 33 15 24", "output": "1\n6" }, { "input": "4\n600 200 100 300", "output": "1\n3" }, { "input": "2\n4 5", "output": "1\n1" }, { "input": "2\n5 12", "output": "1\n1" }, { "input": "2\n1 2", "output": "1\n1" }, { "input": "3\n1 1 2", "output": "1\n1" }, { "input": "2\n3 2", "output": "1\n2" }, { "input": "3\n1 4 5", "output": "1\n1" }, { "input": "4\n5 5 5 5", "output": "1\n1" }, { "input": "1\n5", "output": "-1" }, { "input": "3\n5 5 5", "output": "1\n1" }, { "input": "5\n5 5 5 5 5", "output": "1\n1" }, { "input": "4\n2 7 10 1", "output": "1\n4" }, { "input": "3\n1 1 1", "output": "1\n1" }, { "input": "4\n8 4 2 2", "output": "1\n3" }, { "input": "2\n3 4", "output": "1\n1" }, { "input": "4\n1 1 3 1", "output": "1\n1" }, { "input": "7\n1 2 3 4 5 6 7", "output": "1\n1" }, { "input": "2\n18 19", "output": "1\n1" }, { "input": "2\n17 18", "output": "1\n1" }, { "input": "2\n1 3", "output": "1\n1" }, { "input": "4\n5 5 4 4", "output": "1\n3" }, { "input": "2\n10 11", "output": "1\n1" }, { "input": "2\n10 20", "output": "1\n1" }, { "input": "2\n2 1", "output": "1\n2" }, { "input": "4\n2 3 2 3", "output": "1\n1" }, { "input": "2\n5 6", "output": "1\n1" } ]

1,613,846,079

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

2

77

0

import sys for _ in range(1): n=input() l=list(map(int,input().split())) if n==1: print(-1) break l.sort() if l[0]==sum(l[1:]): print(-1) else: print(1) print(1)

Title: Balloons Time Limit: None seconds Memory Limit: None megabytes Problem Description: There are quite a lot of ways to have fun with inflatable balloons. For example, you can fill them with water and see what happens. Grigory and Andrew have the same opinion. So, once upon a time, they went to the shop and bought $n$ packets with inflatable balloons, where $i$-th of them has exactly $a_i$ balloons inside. They want to divide the balloons among themselves. In addition, there are several conditions to hold: - Do not rip the packets (both Grigory and Andrew should get unbroken packets); - Distribute all packets (every packet should be given to someone); - Give both Grigory and Andrew at least one packet; - To provide more fun, the total number of balloons in Grigory's packets should not be equal to the total number of balloons in Andrew's packets. Help them to divide the balloons or determine that it's impossible under these conditions. Input Specification: The first line of input contains a single integer $n$ ($1 \le n \le 10$) — the number of packets with balloons. The second line contains $n$ integers: $a_1$, $a_2$, $\ldots$, $a_n$ ($1 \le a_i \le 1000$) — the number of balloons inside the corresponding packet. Output Specification: If it's impossible to divide the balloons satisfying the conditions above, print $-1$. Otherwise, print an integer $k$ — the number of packets to give to Grigory followed by $k$ distinct integers from $1$ to $n$ — the indices of those. The order of packets doesn't matter. If there are multiple ways to divide balloons, output any of them. Demo Input: ['3\n1 2 1\n', '2\n5 5\n', '1\n10\n'] Demo Output: ['2\n1 2\n', '-1\n', '-1\n'] Note: In the first test Grigory gets $3$ balloons in total while Andrey gets $1$. In the second test there's only one way to divide the packets which leads to equal numbers of balloons. In the third test one of the boys won't get a packet at all.

```python import sys for _ in range(1): n=input() l=list(map(int,input().split())) if n==1: print(-1) break l.sort() if l[0]==sum(l[1:]): print(-1) else: print(1) print(1) ```

0

839

A

Arya and Bran

PROGRAMMING

900

[ "implementation" ]

null

Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies. At first, Arya and Bran have 0 Candies. There are *n* days, at the *i*-th day, Arya finds *a**i* candies in a box, that is given by the Many-Faced God. Every day she can give Bran at most 8 of her candies. If she don't give him the candies at the same day, they are saved for her and she can give them to him later. Your task is to find the minimum number of days Arya needs to give Bran *k* candies before the end of the *n*-th day. Formally, you need to output the minimum day index to the end of which *k* candies will be given out (the days are indexed from 1 to *n*). Print -1 if she can't give him *k* candies during *n* given days.

The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=10000). The second line contains *n* integers *a*1,<=*a*2,<=*a*3,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100).

If it is impossible for Arya to give Bran *k* candies within *n* days, print -1. Otherwise print a single integer — the minimum number of days Arya needs to give Bran *k* candies before the end of the *n*-th day.

[ "2 3\n1 2\n", "3 17\n10 10 10\n", "1 9\n10\n" ]

[ "2", "3", "-1" ]

In the first sample, Arya can give Bran 3 candies in 2 days. In the second sample, Arya can give Bran 17 candies in 3 days, because she can give him at most 8 candies per day. In the third sample, Arya can't give Bran 9 candies, because she can give him at most 8 candies per day and she must give him the candies within 1 day.

500

[ { "input": "2 3\n1 2", "output": "2" }, { "input": "3 17\n10 10 10", "output": "3" }, { "input": "1 9\n10", "output": "-1" }, { "input": "10 70\n6 5 2 3 3 2 1 4 3 2", "output": "-1" }, { "input": "20 140\n40 4 81 40 10 54 34 50 84 60 16 1 90 78 38 93 99 60 81 99", "output": "18" }, { "input": "30 133\n3 2 3 4 3 7 4 5 5 6 7 2 1 3 4 6 7 4 6 4 7 5 7 1 3 4 1 6 8 5", "output": "30" }, { "input": "40 320\n70 79 21 64 95 36 63 29 66 89 30 34 100 76 42 12 4 56 80 78 83 1 39 9 34 45 6 71 27 31 55 52 72 71 38 21 43 83 48 47", "output": "40" }, { "input": "50 300\n5 3 11 8 7 4 9 5 5 1 6 3 5 7 4 2 2 10 8 1 7 10 4 4 11 5 2 4 9 1 5 4 11 9 11 2 7 4 4 8 10 9 1 11 10 2 4 11 6 9", "output": "-1" }, { "input": "37 30\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "30" }, { "input": "100 456\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100", "output": "57" }, { "input": "90 298\n94 90 98 94 93 90 99 98 90 96 93 96 92 92 97 98 94 94 96 100 93 96 95 98 94 91 95 95 94 90 93 96 93 100 99 98 94 95 98 91 91 98 97 100 98 93 92 93 91 100 92 97 95 95 97 94 98 97 99 100 90 96 93 100 95 99 92 100 99 91 97 99 98 93 90 93 97 95 94 96 90 100 94 93 91 92 97 97 97 100", "output": "38" }, { "input": "7 43\n4 3 7 9 3 8 10", "output": "-1" }, { "input": "99 585\n8 2 3 3 10 7 9 4 7 4 6 8 7 11 5 8 7 4 7 7 6 7 11 8 1 7 3 2 10 1 6 10 10 5 10 2 5 5 11 6 4 1 5 10 5 8 1 3 7 10 6 1 1 3 8 11 5 8 2 2 5 4 7 6 7 5 8 7 10 9 6 11 4 8 2 7 1 7 1 4 11 1 9 6 1 10 6 10 1 5 6 5 2 5 11 5 1 10 8", "output": "-1" }, { "input": "30 177\n8 7 5 8 3 7 2 4 3 8 11 3 9 11 2 4 1 4 5 6 11 5 8 3 6 3 11 2 11 8", "output": "-1" }, { "input": "19 129\n3 3 10 11 4 7 3 8 10 2 11 6 11 9 4 2 11 10 5", "output": "-1" }, { "input": "100 100\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "100" }, { "input": "13 104\n94 55 20 96 86 76 13 71 13 1 32 76 69", "output": "13" }, { "input": "85 680\n61 44 55 6 30 74 27 26 17 45 73 1 67 71 39 32 13 25 79 66 4 59 49 28 29 22 10 17 98 80 36 99 52 24 59 44 27 79 29 46 29 12 47 72 82 25 6 30 81 72 95 65 30 71 72 45 39 16 16 89 48 42 59 71 50 58 31 65 91 70 48 56 28 34 53 89 94 98 49 55 94 65 91 11 53", "output": "85" }, { "input": "100 458\n3 6 4 1 8 4 1 5 4 4 5 8 4 4 6 6 5 1 2 2 2 1 7 1 1 2 6 5 7 8 3 3 8 3 7 5 7 6 6 2 4 2 2 1 1 8 6 1 5 3 3 4 1 4 6 8 5 4 8 5 4 5 5 1 3 1 6 7 6 2 7 3 4 8 1 8 6 7 1 2 4 6 7 4 8 8 8 4 8 7 5 2 8 4 2 5 6 8 8 5", "output": "100" }, { "input": "98 430\n4 7 6 3 4 1 7 1 1 6 6 1 5 4 6 1 5 4 6 6 1 5 1 1 8 1 6 6 2 6 8 4 4 6 6 8 8 7 4 1 2 4 1 5 4 3 7 3 2 5 7 7 7 2 2 2 7 2 8 7 3 4 5 7 8 3 7 6 7 3 2 4 7 1 4 4 7 1 1 8 4 5 8 3 1 5 3 5 2 1 3 3 8 1 3 5 8 6", "output": "98" }, { "input": "90 80\n6 1 7 1 1 8 6 6 6 1 5 4 2 2 8 4 8 7 7 2 5 7 7 8 5 5 6 3 3 8 3 5 6 3 4 2 6 5 5 3 3 3 8 6 6 1 8 3 6 5 4 8 5 4 3 7 1 3 2 3 3 7 7 7 3 5 2 6 2 3 6 4 6 5 5 3 2 1 1 7 3 3 4 3 4 2 1 2 3 1", "output": "18" }, { "input": "89 99\n7 7 3 5 2 7 8 8 1 1 5 7 7 4 1 5 3 4 4 8 8 3 3 2 6 3 8 2 7 5 8 1 3 5 3 6 4 3 6 2 3 3 4 5 1 6 1 7 7 7 6 7 7 7 8 8 8 2 1 7 5 8 6 7 7 4 7 5 7 8 1 3 5 8 7 1 4 2 5 8 3 4 4 5 5 6 2 4 2", "output": "21" }, { "input": "50 700\n4 3 2 8 8 5 5 3 3 4 7 2 6 6 3 3 8 4 2 4 8 6 5 4 5 4 5 8 6 5 4 7 2 4 1 6 2 6 8 6 2 5 8 1 3 8 3 8 4 1", "output": "-1" }, { "input": "82 359\n95 98 95 90 90 96 91 94 93 99 100 100 92 99 96 94 99 90 94 96 91 91 90 93 97 96 90 94 97 99 93 90 99 98 96 100 93 97 100 91 100 92 93 100 92 90 90 94 99 95 100 98 99 96 94 96 96 99 99 91 97 100 95 100 99 91 94 91 98 98 100 97 93 93 96 97 94 94 92 100 91 91", "output": "45" }, { "input": "60 500\n93 93 100 99 91 92 95 93 95 99 93 91 97 98 90 91 98 100 95 100 94 93 92 91 91 98 98 90 93 91 90 96 92 93 92 94 94 91 96 94 98 100 97 96 96 97 91 99 97 95 96 94 91 92 99 95 97 92 98 90", "output": "-1" }, { "input": "98 776\n48 63 26 3 88 81 27 33 37 10 2 89 41 84 98 93 25 44 42 90 41 65 97 1 28 69 42 14 86 18 96 28 28 94 78 8 44 31 96 45 26 52 93 25 48 39 3 75 94 93 63 59 67 86 18 74 27 38 68 7 31 60 69 67 20 11 19 34 47 43 86 96 3 49 56 60 35 49 89 28 92 69 48 15 17 73 99 69 2 73 27 35 28 53 11 1 96 50", "output": "97" }, { "input": "100 189\n15 14 32 65 28 96 33 93 48 28 57 20 32 20 90 42 57 53 18 58 94 21 27 29 37 22 94 45 67 60 83 23 20 23 35 93 3 42 6 46 68 46 34 25 17 16 50 5 49 91 23 76 69 100 58 68 81 32 88 41 64 29 37 13 95 25 6 59 74 58 31 35 16 80 13 80 10 59 85 18 16 70 51 40 44 28 8 76 8 87 53 86 28 100 2 73 14 100 52 9", "output": "24" }, { "input": "99 167\n72 4 79 73 49 58 15 13 92 92 42 36 35 21 13 10 51 94 64 35 86 50 6 80 93 77 59 71 2 88 22 10 27 30 87 12 77 6 34 56 31 67 78 84 36 27 15 15 12 56 80 7 56 14 10 9 14 59 15 20 34 81 8 49 51 72 4 58 38 77 31 86 18 61 27 86 95 36 46 36 39 18 78 39 48 37 71 12 51 92 65 48 39 22 16 87 4 5 42", "output": "21" }, { "input": "90 4\n48 4 4 78 39 3 85 29 69 52 70 39 11 98 42 56 65 98 77 24 61 31 6 59 60 62 84 46 67 59 15 44 99 23 12 74 2 48 84 60 51 28 17 90 10 82 3 43 50 100 45 57 57 95 53 71 20 74 52 46 64 59 72 33 74 16 44 44 80 71 83 1 70 59 61 6 82 69 81 45 88 28 17 24 22 25 53 97 1 100", "output": "1" }, { "input": "30 102\n55 94 3 96 3 47 92 85 25 78 27 70 97 83 40 2 55 12 74 84 91 37 31 85 7 40 33 54 72 5", "output": "13" }, { "input": "81 108\n61 59 40 100 8 75 5 74 87 12 6 23 98 26 59 68 27 4 98 79 14 44 4 11 89 77 29 90 33 3 43 1 87 91 28 24 4 84 75 7 37 46 15 46 8 87 68 66 5 21 36 62 77 74 91 95 88 28 12 48 18 93 14 51 33 5 99 62 99 38 49 15 56 87 52 64 69 46 41 12 92", "output": "14" }, { "input": "2 16\n10 6", "output": "2" }, { "input": "2 8\n7 8", "output": "2" }, { "input": "2 9\n4 8", "output": "2" }, { "input": "3 19\n9 9 1", "output": "3" }, { "input": "4 32\n9 9 9 5", "output": "4" }, { "input": "2 15\n14 1", "output": "2" }, { "input": "2 3\n3 3", "output": "1" }, { "input": "3 10\n10 1 1", "output": "2" }, { "input": "12 20\n3 16 19 10 1 6 17 8 6 20 1 4", "output": "4" }, { "input": "4 15\n14 3 3 3", "output": "2" }, { "input": "5 40\n10 10 10 10 1", "output": "5" }, { "input": "4 31\n9 9 8 5", "output": "4" }, { "input": "4 31\n20 7 1 1", "output": "-1" }, { "input": "2 10\n9 1", "output": "2" }, { "input": "10 50\n100 10 1 1 1 1 1 1 1 1", "output": "7" }, { "input": "2 11\n10 2", "output": "2" }, { "input": "3 21\n10 10 1", "output": "3" }, { "input": "2 2\n1 2", "output": "2" }, { "input": "3 2\n1 8 8", "output": "2" }, { "input": "2 11\n10 1", "output": "2" }, { "input": "2 16\n12 4", "output": "2" }, { "input": "3 11\n9 2 2", "output": "2" }, { "input": "3 11\n4 3 4", "output": "3" }, { "input": "2 13\n7 6", "output": "2" }, { "input": "3 24\n14 3 4", "output": "-1" }, { "input": "2 13\n10 3", "output": "2" }, { "input": "3 11\n9 2 1", "output": "2" }, { "input": "2 15\n12 3", "output": "2" }, { "input": "2 14\n11 4", "output": "2" } ]

1,679,230,016

2,147,483,647

PyPy 3-64

WRONG_ANSWER

TESTS

3

46

0

import sys input = sys.stdin.readline n, k = map(int, input().split()) cnt = k data = list(map(int, input().split())) tot = 0 ans = -1 for i in range(n): tot += data[i] cnt -= min(tot, 8) if cnt <= 0: ans = i + 1 break print(ans)

Title: Arya and Bran Time Limit: None seconds Memory Limit: None megabytes Problem Description: Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies. At first, Arya and Bran have 0 Candies. There are *n* days, at the *i*-th day, Arya finds *a**i* candies in a box, that is given by the Many-Faced God. Every day she can give Bran at most 8 of her candies. If she don't give him the candies at the same day, they are saved for her and she can give them to him later. Your task is to find the minimum number of days Arya needs to give Bran *k* candies before the end of the *n*-th day. Formally, you need to output the minimum day index to the end of which *k* candies will be given out (the days are indexed from 1 to *n*). Print -1 if she can't give him *k* candies during *n* given days. Input Specification: The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=10000). The second line contains *n* integers *a*1,<=*a*2,<=*a*3,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). Output Specification: If it is impossible for Arya to give Bran *k* candies within *n* days, print -1. Otherwise print a single integer — the minimum number of days Arya needs to give Bran *k* candies before the end of the *n*-th day. Demo Input: ['2 3\n1 2\n', '3 17\n10 10 10\n', '1 9\n10\n'] Demo Output: ['2', '3', '-1'] Note: In the first sample, Arya can give Bran 3 candies in 2 days. In the second sample, Arya can give Bran 17 candies in 3 days, because she can give him at most 8 candies per day. In the third sample, Arya can't give Bran 9 candies, because she can give him at most 8 candies per day and she must give him the candies within 1 day.

```python import sys input = sys.stdin.readline n, k = map(int, input().split()) cnt = k data = list(map(int, input().split())) tot = 0 ans = -1 for i in range(n): tot += data[i] cnt -= min(tot, 8) if cnt <= 0: ans = i + 1 break print(ans) ```

0

50

A

Domino piling

PROGRAMMING

800

[ "greedy", "math" ]

A. Domino piling

2

256

You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions: 1. Each domino completely covers two squares. 2. No two dominoes overlap. 3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board. Find the maximum number of dominoes, which can be placed under these restrictions.

In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).

Output one number — the maximal number of dominoes, which can be placed.

[ "2 4\n", "3 3\n" ]

[ "4\n", "4\n" ]

none

500

[ { "input": "2 4", "output": "4" }, { "input": "3 3", "output": "4" }, { "input": "1 5", "output": "2" }, { "input": "1 6", "output": "3" }, { "input": "1 15", "output": "7" }, { "input": "1 16", "output": "8" }, { "input": "2 5", "output": "5" }, { "input": "2 6", "output": "6" }, { "input": "2 7", "output": "7" }, { "input": "2 14", "output": "14" }, { "input": "2 15", "output": "15" }, { "input": "1 4", "output": "2" }, { "input": "2 16", "output": "16" }, { "input": "3 5", "output": "7" }, { "input": "3 6", "output": "9" }, { "input": "3 10", "output": "15" }, { "input": "3 14", "output": "21" }, { "input": "3 15", "output": "22" }, { "input": "3 16", "output": "24" }, { "input": "5 7", "output": "17" }, { "input": "16 16", "output": "128" }, { "input": "15 16", "output": "120" }, { "input": "2 3", "output": "3" }, { "input": "15 15", "output": "112" }, { "input": "14 16", "output": "112" }, { "input": "11 13", "output": "71" }, { "input": "5 16", "output": "40" }, { "input": "8 15", "output": "60" }, { "input": "2 2", "output": "2" }, { "input": "3 4", "output": "6" }, { "input": "4 4", "output": "8" }, { "input": "1 1", "output": "0" }, { "input": "1 2", "output": "1" }, { "input": "1 3", "output": "1" }, { "input": "14 15", "output": "105" } ]

1,681,556,756

2,147,483,647

Python 3

OK

TESTS

35

124

0

input_line = [int(a) for a in input().split(" ")] n = input_line[0] m = input_line[1] print((n*m)//2)

Title: Domino piling Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions: 1. Each domino completely covers two squares. 2. No two dominoes overlap. 3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board. Find the maximum number of dominoes, which can be placed under these restrictions. Input Specification: In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). Output Specification: Output one number — the maximal number of dominoes, which can be placed. Demo Input: ['2 4\n', '3 3\n'] Demo Output: ['4\n', '4\n'] Note: none

```python input_line = [int(a) for a in input().split(" ")] n = input_line[0] m = input_line[1] print((n*m)//2) ```

3.969

835

A

Key races

PROGRAMMING

800

[ "math" ]

null

Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *t*2 milliseconds. If connection ping (delay) is *t* milliseconds, the competition passes for a participant as follows: 1. Exactly after *t* milliseconds after the start of the competition the participant receives the text to be entered. 1. Right after that he starts to type it. 1. Exactly *t* milliseconds after he ends typing all the text, the site receives information about it. The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw. Given the length of the text and the information about participants, determine the result of the game.

The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.

If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".

[ "5 1 2 1 2\n", "3 3 1 1 1\n", "4 5 3 1 5\n" ]

[ "First\n", "Second\n", "Friendship\n" ]

In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins. In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins. In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.

500

[ { "input": "5 1 2 1 2", "output": "First" }, { "input": "3 3 1 1 1", "output": "Second" }, { "input": "4 5 3 1 5", "output": "Friendship" }, { "input": "1000 1000 1000 1000 1000", "output": "Friendship" }, { "input": "1 1 1 1 1", "output": "Friendship" }, { "input": "8 8 1 1 1", "output": "Second" }, { "input": "15 14 32 65 28", "output": "First" }, { "input": "894 197 325 232 902", "output": "First" }, { "input": "1 2 8 8 5", "output": "Friendship" }, { "input": "37 261 207 1 1000", "output": "Friendship" }, { "input": "29 344 406 900 1", "output": "Friendship" }, { "input": "1 2 8 9 8", "output": "First" }, { "input": "2 9 8 8 9", "output": "Friendship" }, { "input": "213 480 811 134 745", "output": "First" }, { "input": "2 313 856 964 421", "output": "Friendship" }, { "input": "1 10 2 6 10", "output": "Friendship" }, { "input": "2 7 6 2 3", "output": "Friendship" }, { "input": "637 324 69 612 998", "output": "Second" }, { "input": "13 849 819 723 918", "output": "Friendship" }, { "input": "9 5 7 8 7", "output": "First" }, { "input": "6 5 7 10 4", "output": "Friendship" }, { "input": "61 464 623 89 548", "output": "First" }, { "input": "641 31 29 161 802", "output": "Friendship" }, { "input": "3 3 1 6 9", "output": "Friendship" }, { "input": "2 3 9 8 2", "output": "Friendship" }, { "input": "485 117 368 567 609", "output": "First" }, { "input": "4 202 512 995 375", "output": "Friendship" }, { "input": "424 41 41 909 909", "output": "Friendship" }, { "input": "884 913 263 641 265", "output": "Second" }, { "input": "12 462 8 311 327", "output": "Second" }, { "input": "436 306 266 493 580", "output": "Second" }, { "input": "69 1 2 1 2", "output": "First" } ]

1,560,245,182

2,147,483,647

Python 3

OK

TESTS

32

109

0

s,v1,v2,t1,t2 = list(map(int,input().split())) res1 = 2*t1 + s*v1 res2 = 2*t2 + s*v2 if res1 == res2: print('Friendship') else: print('First' if res1<res2 else 'Second')

Title: Key races Time Limit: None seconds Memory Limit: None megabytes Problem Description: Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *t*2 milliseconds. If connection ping (delay) is *t* milliseconds, the competition passes for a participant as follows: 1. Exactly after *t* milliseconds after the start of the competition the participant receives the text to be entered. 1. Right after that he starts to type it. 1. Exactly *t* milliseconds after he ends typing all the text, the site receives information about it. The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw. Given the length of the text and the information about participants, determine the result of the game. Input Specification: The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant. Output Specification: If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship". Demo Input: ['5 1 2 1 2\n', '3 3 1 1 1\n', '4 5 3 1 5\n'] Demo Output: ['First\n', 'Second\n', 'Friendship\n'] Note: In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins. In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins. In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.

```python s,v1,v2,t1,t2 = list(map(int,input().split())) res1 = 2*t1 + s*v1 res2 = 2*t2 + s*v2 if res1 == res2: print('Friendship') else: print('First' if res1<res2 else 'Second') ```

3

780

A

Andryusha and Socks

PROGRAMMING

800

[ "implementation" ]

null

Andryusha is an orderly boy and likes to keep things in their place. Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the socks one by one from the bag, and for each sock he looks whether the pair of this sock has been already took out of the bag, or not. If not (that means the pair of this sock is still in the bag), he puts the current socks on the table in front of him. Otherwise, he puts both socks from the pair to the wardrobe. Andryusha remembers the order in which he took the socks from the bag. Can you tell him what is the maximum number of socks that were on the table at the same time?

The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs. The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha took out was from pair *x**i*. It is guaranteed that Andryusha took exactly two socks of each pair.

Print single integer — the maximum number of socks that were on the table at the same time.

[ "1\n1 1\n", "3\n2 1 1 3 2 3\n" ]

[ "1\n", "2\n" ]

In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time. In the second example Andryusha behaved as follows: - Initially the table was empty, he took out a sock from pair 2 and put it on the table. - Sock (2) was on the table. Andryusha took out a sock from pair 1 and put it on the table. - Socks (1, 2) were on the table. Andryusha took out a sock from pair 1, and put this pair into the wardrobe. - Sock (2) was on the table. Andryusha took out a sock from pair 3 and put it on the table. - Socks (2, 3) were on the table. Andryusha took out a sock from pair 2, and put this pair into the wardrobe. - Sock (3) was on the table. Andryusha took out a sock from pair 3 and put this pair into the wardrobe.

500

[ { "input": "1\n1 1", "output": "1" }, { "input": "3\n2 1 1 3 2 3", "output": "2" }, { "input": "5\n5 1 3 2 4 3 1 2 4 5", "output": "5" }, { "input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7", "output": "6" }, { "input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 15 31 14 49 9 16 6 44 27 14 5 6 3 47 25 26 1 35 3 15 24 19 8 46 49 41 4 26 40 28 42 11 34 35 46 18 7 28 18 40 19 42 4 41 38 48 50 12 29 39 33 17 25 22 22 21 36 45 27 30 20 7 13 29 39 44 21 8 37 45 34 1 20 10 11 17 33 12 43 13 10 16 48 24 32 5 23 32", "output": "25" }, { "input": "50\n1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50", "output": "1" }, { "input": "50\n50 50 49 49 48 48 47 47 46 46 45 45 44 44 43 43 42 42 41 41 40 40 39 39 38 38 37 37 36 36 35 35 34 34 33 33 32 32 31 31 30 30 29 29 28 28 27 27 26 26 25 25 24 24 23 23 22 22 21 21 20 20 19 19 18 18 17 17 16 16 15 15 14 14 13 13 12 12 11 11 10 10 9 9 8 8 7 7 6 6 5 5 4 4 3 3 2 2 1 1", "output": "1" }, { "input": "50\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50", "output": "50" }, { "input": "50\n50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1", "output": "50" }, { "input": "10\n2 9 4 1 6 7 10 3 1 5 8 6 2 3 10 7 4 8 5 9", "output": "9" } ]

1,489,959,328

2,147,483,647

Python 3

TIME_LIMIT_EXCEEDED

TESTS

3

2,000

15,360,000

input() sp=input().split() count=maxi=0 i = 0 for x in sp: if x in sp[:i]: count-=1 else: count+=1 if count>maxi: maxi=count i+=1 print(maxi)

Title: Andryusha and Socks Time Limit: None seconds Memory Limit: None megabytes Problem Description: Andryusha is an orderly boy and likes to keep things in their place. Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the socks one by one from the bag, and for each sock he looks whether the pair of this sock has been already took out of the bag, or not. If not (that means the pair of this sock is still in the bag), he puts the current socks on the table in front of him. Otherwise, he puts both socks from the pair to the wardrobe. Andryusha remembers the order in which he took the socks from the bag. Can you tell him what is the maximum number of socks that were on the table at the same time? Input Specification: The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs. The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha took out was from pair *x**i*. It is guaranteed that Andryusha took exactly two socks of each pair. Output Specification: Print single integer — the maximum number of socks that were on the table at the same time. Demo Input: ['1\n1 1\n', '3\n2 1 1 3 2 3\n'] Demo Output: ['1\n', '2\n'] Note: In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time. In the second example Andryusha behaved as follows: - Initially the table was empty, he took out a sock from pair 2 and put it on the table. - Sock (2) was on the table. Andryusha took out a sock from pair 1 and put it on the table. - Socks (1, 2) were on the table. Andryusha took out a sock from pair 1, and put this pair into the wardrobe. - Sock (2) was on the table. Andryusha took out a sock from pair 3 and put it on the table. - Socks (2, 3) were on the table. Andryusha took out a sock from pair 2, and put this pair into the wardrobe. - Sock (3) was on the table. Andryusha took out a sock from pair 3 and put this pair into the wardrobe.

```python input() sp=input().split() count=maxi=0 i = 0 for x in sp: if x in sp[:i]: count-=1 else: count+=1 if count>maxi: maxi=count i+=1 print(maxi) ```

0

195

A

Let's Watch Football

PROGRAMMING

1,000

[ "binary search", "brute force", "math" ]

null

Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the size of downloaded data per second. The guys want to watch the whole video without any pauses, so they have to wait some integer number of seconds for a part of the video to download. After this number of seconds passes, they can start watching. Waiting for the whole video to download isn't necessary as the video can download after the guys started to watch. Let's suppose that video's length is *c* seconds and Valeric and Valerko wait *t* seconds before the watching. Then for any moment of time *t*0, *t*<=≤<=*t*0<=≤<=*c*<=+<=*t*, the following condition must fulfill: the size of data received in *t*0 seconds is not less than the size of data needed to watch *t*0<=-<=*t* seconds of the video. Of course, the guys want to wait as little as possible, so your task is to find the minimum integer number of seconds to wait before turning the video on. The guys must watch the video without pauses.

The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. The third number (*c*) denotes the video's length in seconds.

Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses.

[ "4 1 1\n", "10 3 2\n", "13 12 1\n" ]

[ "3\n", "5\n", "1\n" ]

In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watching video 1 second, one unit of data will be downloaded and Valerik and Valerko will have 4 units of data by the end of watching. Also every moment till the end of video guys will have more data then necessary for watching. In the second sample guys need 2 · 10 = 20 units of data, so they have to wait 5 seconds and after that they will have 20 units before the second second ends. However, if guys wait 4 seconds, they will be able to watch first second of video without pauses, but they will download 18 units of data by the end of second second and it is less then necessary.

500

[ { "input": "4 1 1", "output": "3" }, { "input": "10 3 2", "output": "5" }, { "input": "13 12 1", "output": "1" }, { "input": "2 1 3", "output": "3" }, { "input": "6 2 4", "output": "8" }, { "input": "5 2 1", "output": "2" }, { "input": "2 1 1", "output": "1" }, { "input": "2 1 4", "output": "4" }, { "input": "5 1 5", "output": "20" }, { "input": "2 1 2", "output": "2" }, { "input": "60 16 1", "output": "3" }, { "input": "64 12 8", "output": "35" }, { "input": "66 38 4", "output": "3" }, { "input": "70 32 1", "output": "2" }, { "input": "24 12 12", "output": "12" }, { "input": "24 19 9", "output": "3" }, { "input": "244 87 4", "output": "8" }, { "input": "305 203 421", "output": "212" }, { "input": "888 777 1", "output": "1" }, { "input": "888 777 1000", "output": "143" }, { "input": "888 777 888", "output": "127" }, { "input": "5 4 10", "output": "3" }, { "input": "1000 1 1", "output": "999" }, { "input": "1000 1 1000", "output": "999000" }, { "input": "1000 999 1", "output": "1" }, { "input": "1000 999 1000", "output": "2" }, { "input": "945 812 917", "output": "151" }, { "input": "993 992 991", "output": "1" }, { "input": "17 7 10", "output": "15" }, { "input": "17 10 7", "output": "5" }, { "input": "500 300 300", "output": "200" }, { "input": "196 169 144", "output": "24" }, { "input": "7 3 200", "output": "267" }, { "input": "9 3 300", "output": "600" }, { "input": "561 31 917", "output": "15678" }, { "input": "100 10 1", "output": "9" }, { "input": "1000 100 10", "output": "90" }, { "input": "18 14 10", "output": "3" }, { "input": "93 74 831", "output": "214" }, { "input": "960 935 994", "output": "27" }, { "input": "894 1 999", "output": "892107" }, { "input": "767 2 514", "output": "196605" }, { "input": "765 123 45", "output": "235" }, { "input": "1000 1 1000", "output": "999000" }, { "input": "765 123 899", "output": "4693" }, { "input": "759 10 258", "output": "19325" }, { "input": "100 1 10", "output": "990" }, { "input": "99 8 99", "output": "1127" }, { "input": "27 26 1", "output": "1" } ]

1,585,584,104

2,147,483,647

PyPy 3

OK

TESTS

49

280

0

import math List = list(map(int,input().strip().split()))[0:3] consumeRate = List[0] downRate = List[1] consumeTym = List[2] downTym = math.ceil( (consumeRate*consumeTym)/downRate ) difference = downTym - consumeTym print(difference)

Title: Let's Watch Football Time Limit: None seconds Memory Limit: None megabytes Problem Description: Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the size of downloaded data per second. The guys want to watch the whole video without any pauses, so they have to wait some integer number of seconds for a part of the video to download. After this number of seconds passes, they can start watching. Waiting for the whole video to download isn't necessary as the video can download after the guys started to watch. Let's suppose that video's length is *c* seconds and Valeric and Valerko wait *t* seconds before the watching. Then for any moment of time *t*0, *t*<=≤<=*t*0<=≤<=*c*<=+<=*t*, the following condition must fulfill: the size of data received in *t*0 seconds is not less than the size of data needed to watch *t*0<=-<=*t* seconds of the video. Of course, the guys want to wait as little as possible, so your task is to find the minimum integer number of seconds to wait before turning the video on. The guys must watch the video without pauses. Input Specification: The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. The third number (*c*) denotes the video's length in seconds. Output Specification: Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses. Demo Input: ['4 1 1\n', '10 3 2\n', '13 12 1\n'] Demo Output: ['3\n', '5\n', '1\n'] Note: In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watching video 1 second, one unit of data will be downloaded and Valerik and Valerko will have 4 units of data by the end of watching. Also every moment till the end of video guys will have more data then necessary for watching. In the second sample guys need 2 · 10 = 20 units of data, so they have to wait 5 seconds and after that they will have 20 units before the second second ends. However, if guys wait 4 seconds, they will be able to watch first second of video without pauses, but they will download 18 units of data by the end of second second and it is less then necessary.

```python import math List = list(map(int,input().strip().split()))[0:3] consumeRate = List[0] downRate = List[1] consumeTym = List[2] downTym = math.ceil( (consumeRate*consumeTym)/downRate ) difference = downTym - consumeTym print(difference) ```

3

916

B

Jamie and Binary Sequence (changed after round)

PROGRAMMING

2,000

[ "bitmasks", "greedy", "math" ]

null

Jamie is preparing a Codeforces round. He has got an idea for a problem, but does not know how to solve it. Help him write a solution to the following problem: Find *k* integers such that the sum of two to the power of each number equals to the number *n* and the largest integer in the answer is as small as possible. As there may be multiple answers, you are asked to output the lexicographically largest one. To be more clear, consider all integer sequence with length *k* (*a*1,<=*a*2,<=...,<=*a**k*) with . Give a value to each sequence. Among all sequence(s) that have the minimum *y* value, output the one that is the lexicographically largest. For definitions of powers and lexicographical order see notes.

The first line consists of two integers *n* and *k* (1<=≤<=*n*<=≤<=1018,<=1<=≤<=*k*<=≤<=105) — the required sum and the length of the sequence.

Output "No" (without quotes) in a single line if there does not exist such sequence. Otherwise, output "Yes" (without quotes) in the first line, and *k* numbers separated by space in the second line — the required sequence. It is guaranteed that the integers in the answer sequence fit the range [<=-<=1018,<=1018].

[ "23 5\n", "13 2\n", "1 2\n" ]

[ "Yes\n3 3 2 1 0 \n", "No\n", "Yes\n-1 -1 \n" ]

Sample 1: 23 + 23 + 22 + 21 + 20 = 8 + 8 + 4 + 2 + 1 = 23 Answers like (3, 3, 2, 0, 1) or (0, 1, 2, 3, 3) are not lexicographically largest. Answers like (4, 1, 1, 1, 0) do not have the minimum *y* value. Sample 2: It can be shown there does not exist a sequence with length 2. Sample 3: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a8539b2d27aefc8d2fab6dfd8296d11c36dcaa40.png" style="max-width: 100.0%;max-height: 100.0%;"/> Powers of 2: If *x* > 0, then 2*x* = 2·2·2·...·2 (*x* times). If *x* = 0, then 2*x* = 1. If *x* < 0, then <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/766628f1c7814795eac1a0afaa1ff062c40ef29e.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Lexicographical order: Given two different sequences of the same length, (*a*1, *a*2, ... , *a**k*) and (*b*1, *b*2, ... , *b**k*), the first one is smaller than the second one for the lexicographical order, if and only if *a**i* < *b**i*, for the first *i* where *a**i* and *b**i* differ.

1,000

[ { "input": "23 5", "output": "Yes\n3 3 2 1 0 " }, { "input": "13 2", "output": "No" }, { "input": "1 2", "output": "Yes\n-1 -1 " }, { "input": "1 1", "output": "Yes\n0 " }, { "input": "1000000000000000000 100000", "output": "Yes\n44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44 44..." }, { "input": "7 2", "output": "No" }, { "input": "7 3", "output": "Yes\n2 1 0 " }, { "input": "7 4", "output": "Yes\n1 1 1 0 " }, { "input": "521325125150442808 10", "output": "No" }, { "input": "498518679725149504 1000", "output": "Yes\n49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49..." }, { "input": "464823731286228582 100000", "output": "Yes\n43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43..." }, { "input": "1 4", "output": "Yes\n-2 -2 -2 -2 " }, { "input": "9 4", "output": "Yes\n2 2 -1 -1 " }, { "input": "3 4", "output": "Yes\n0 0 -1 -1 " }, { "input": "144 4", "output": "Yes\n6 6 3 3 " }, { "input": "59 4", "output": "No" }, { "input": "78 4", "output": "Yes\n6 3 2 1 " }, { "input": "192 4", "output": "Yes\n6 6 5 5 " }, { "input": "107 4", "output": "No" }, { "input": "552 5", "output": "Yes\n8 8 5 2 2 " }, { "input": "680 5", "output": "Yes\n8 8 7 5 3 " }, { "input": "808 5", "output": "Yes\n8 8 8 5 3 " }, { "input": "1528 5", "output": "No" }, { "input": "1656 5", "output": "No" }, { "input": "26972 8", "output": "Yes\n14 13 11 8 6 4 3 2 " }, { "input": "23100 8", "output": "Yes\n14 12 11 9 5 4 3 2 " }, { "input": "19228 8", "output": "Yes\n13 13 11 9 8 4 3 2 " }, { "input": "22652 8", "output": "Yes\n14 12 11 6 5 4 3 2 " }, { "input": "26076 8", "output": "No" }, { "input": "329438 10", "output": "Yes\n18 16 10 9 7 6 4 3 2 1 " }, { "input": "12862 10", "output": "Yes\n12 12 12 9 5 4 3 2 0 0 " }, { "input": "96286 10", "output": "Yes\n15 15 14 13 12 11 4 3 2 1 " }, { "input": "12414 10", "output": "Yes\n12 12 12 6 5 4 3 2 0 0 " }, { "input": "95838 10", "output": "No" }, { "input": "1728568411 16", "output": "No" }, { "input": "611684539 16", "output": "Yes\n28 28 26 22 21 20 18 16 15 12 7 5 4 3 1 0 " }, { "input": "84735259 16", "output": "Yes\n25 25 24 19 18 15 14 13 12 10 8 4 3 1 -1 -1 " }, { "input": "6967851387 16", "output": "No" }, { "input": "2145934811 16", "output": "No" }, { "input": "6795804571172 20", "output": "Yes\n41 41 41 37 35 34 33 30 26 24 23 18 14 13 12 10 9 5 1 1 " }, { "input": "1038982654596 20", "output": "Yes\n38 38 38 37 36 32 31 30 29 27 21 20 16 13 11 9 7 1 0 0 " }, { "input": "11277865770724 20", "output": "No" }, { "input": "5525338821444 20", "output": "No" }, { "input": "15764221937572 20", "output": "No" }, { "input": "922239521698513045 30", "output": "Yes\n58 58 58 55 54 51 50 46 45 44 41 40 39 38 37 36 34 32 30 29 28 23 21 19 17 15 7 4 2 0 " }, { "input": "923065764876596469 30", "output": "No" }, { "input": "923892008054679893 30", "output": "No" }, { "input": "924718251232763317 30", "output": "Yes\n58 58 58 55 54 52 50 48 46 41 38 36 35 32 31 29 25 19 18 15 12 11 10 8 7 5 4 2 -1 -1 " }, { "input": "925544490115879445 30", "output": "Yes\n59 58 55 54 52 51 45 44 40 39 38 35 34 33 32 30 28 27 26 24 21 19 18 16 14 12 9 4 2 0 " }, { "input": "926370733293962869 30", "output": "Yes\n57 57 57 57 57 57 55 54 52 51 49 48 45 40 38 34 33 28 27 22 19 18 17 10 9 6 5 4 2 0 " }, { "input": "927196976472046293 30", "output": "No" }, { "input": "928023215355162421 30", "output": "Yes\n58 58 58 55 54 53 48 37 36 33 31 27 26 25 23 19 18 17 16 14 13 11 10 9 8 5 4 2 -1 -1 " }, { "input": "928849458533245845 30", "output": "No" }, { "input": "855969764271400156 30", "output": "No" }, { "input": "856796007449483580 30", "output": "No" }, { "input": "857622246332599708 30", "output": "Yes\n58 58 57 56 55 54 53 50 49 47 46 45 41 39 38 37 33 32 31 29 21 15 11 10 8 7 4 3 1 1 " }, { "input": "858448489510683132 30", "output": "No" }, { "input": "859274728393799260 30", "output": "Yes\n59 57 56 55 54 53 51 50 47 46 40 39 38 36 28 26 25 22 21 16 15 14 13 12 10 9 6 4 3 2 " }, { "input": "860100975866849980 30", "output": "No" }, { "input": "860927214749966108 30", "output": "No" }, { "input": "861753457928049532 30", "output": "Yes\n58 58 57 56 55 54 53 52 50 48 47 44 37 36 34 30 26 25 24 23 22 18 12 9 8 6 5 4 3 2 " }, { "input": "862579701106132957 30", "output": "No" }, { "input": "863405944284216381 30", "output": "No" }, { "input": "374585535361966567 30", "output": "No" }, { "input": "4 1", "output": "Yes\n2 " }, { "input": "4 9", "output": "Yes\n-1 -1 -1 -1 -1 -1 -1 -2 -2 " }, { "input": "4 3", "output": "Yes\n1 0 0 " }, { "input": "4 144", "output": "Yes\n-5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 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"output": "Yes\n57 57 18 0 0 " }, { "input": "36029346774812736 5", "output": "Yes\n55 39 15 11 6 " }, { "input": "901283150305558530 5", "output": "No" }, { "input": "288318372649779720 50", "output": "Yes\n53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 53 46 44 35 30 27 17 14 9 2 1 0 -1 -2 -3 -4 -5 -6 -6 " }, { "input": "513703875844698663 50", "output": "Yes\n55 55 55 55 55 55 55 55 55 55 55 55 55 55 53 48 43 41 39 38 37 36 34 27 26 25 24 22 21 20 18 17 15 14 13 12 9 5 2 1 -1 -2 -3 -4 -5 -6 -7 -8 -9 -9 " }, { "input": "287632104387196918 50", "output": "Yes\n57 56 55 54 53 52 51 50 48 47 46 44 43 42 41 40 39 38 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 13 12 10 9 8 7 6 5 4 2 1 " }, { "input": "864690028406636543 58", "output": "Yes\n58 58 57 56 55 54 53 52 51 50 49 48 47 46 45 44 43 42 41 39 38 37 36 35 34 33 32 31 30 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 " }, { "input": "576460752303423487 60", "output": "Yes\n57 57 57 56 55 54 53 52 51 50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 " }, { "input": "141012366262272 1", "output": "No" }, { "input": "1100585377792 4", "output": "Yes\n39 39 30 13 " }, { "input": "18598239186190594 9", "output": "Yes\n54 49 44 41 40 21 18 8 1 " }, { "input": "18647719372456016 19", "output": "Yes\n51 51 51 51 51 51 51 51 49 46 31 24 20 16 6 3 2 1 1 " }, { "input": "9297478914673158 29", "output": "Yes\n49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 49 48 43 33 18 11 9 2 0 -1 -2 -3 -4 -4 " }, { "input": "668507368948226 39", "output": "Yes\n45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 32 22 16 15 9 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -12 -13 -13 " }, { "input": "1143595340402690 49", "output": "Yes\n45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 45 44 36 35 27 25 19 12 0 -1 -2 -3 -4 -5 -6 -7 -8 -8 " }, { "input": "35527987183872 59", "output": "Yes\n40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 40 38 36 24 19 18 17 14 7 6 5 4 3 2 1 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -11 " }, { "input": "324634416758413825 9", "output": "No" }, { "input": "577030480059438572 19", "output": "Yes\n59 49 42 41 37 35 33 28 26 23 18 12 10 8 7 6 5 3 2 " }, { "input": "185505960265024385 29", "output": "Yes\n54 54 54 54 54 54 54 54 54 54 52 49 48 43 42 39 37 36 29 24 22 20 15 9 8 7 -1 -2 -2 " }, { "input": "57421517433081233 39", "output": "Yes\n52 52 52 52 52 52 52 52 52 52 52 52 51 50 39 36 31 30 28 27 26 24 20 11 10 8 7 4 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -10 " }, { "input": "90131572647657641 49", "output": "Yes\n52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 45 44 42 41 37 36 28 25 23 21 20 18 17 7 5 3 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -12 -12 " }, { "input": "732268459757413905 59", "output": "Yes\n54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 53 51 48 47 43 41 38 35 31 30 28 20 13 10 9 4 -1 -2 -2 " }, { "input": "226111453445787190 9", "output": "No" }, { "input": "478818723873062027 19", "output": "No" }, { "input": "337790572680259391 29", "output": "Yes\n58 55 53 52 44 41 39 37 36 35 34 30 29 28 26 24 20 18 16 13 10 9 8 5 4 3 2 1 0 " }, { "input": "168057637182978458 39", "output": "Yes\n54 54 54 54 54 54 54 54 54 52 50 48 43 42 41 40 39 34 33 32 31 30 28 26 25 20 18 16 13 12 11 8 7 4 3 0 -1 -2 -2 " }, { "input": "401486559567818547 49", "output": "Yes\n54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 54 52 49 46 44 43 42 40 39 38 37 34 33 28 26 24 21 17 13 11 10 9 8 5 4 1 -1 -1 " }, { "input": "828935109688089201 59", "output": "Yes\n55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 47 46 45 44 43 36 34 33 32 29 25 23 22 19 18 17 15 14 12 11 9 6 5 4 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -11 " }, { "input": "954687629161163764 9", "output": "No" }, { "input": "287025268967992526 19", "output": "No" }, { "input": "844118423640988373 29", "output": "No" }, { "input": "128233154575908599 39", "output": "Yes\n56 55 54 50 49 48 47 44 41 40 38 36 35 34 33 32 31 30 29 27 25 23 22 21 19 18 15 13 12 11 10 9 7 6 5 4 2 1 0 " }, { "input": "792058388714085231 49", "output": "Yes\n56 56 56 56 56 56 56 56 56 56 55 54 53 52 51 50 48 47 46 45 44 42 39 38 37 35 30 29 28 26 23 21 19 17 16 15 14 12 11 9 8 6 5 3 2 1 -1 -2 -2 " }, { "input": "827183623566145225 59", "output": "Yes\n55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 55 54 53 52 51 49 47 45 44 43 42 41 40 36 35 34 33 32 30 29 28 27 26 25 23 21 19 18 17 13 12 10 9 7 6 3 -1 -1 " }, { "input": "846113779983498737 9", "output": "No" }, { "input": "780248358343081983 19", "output": "No" }, { "input": "576460580458522095 29", "output": "No" }, { "input": "540145805193625598 39", "output": "No" }, { "input": "576388182371377103 49", "output": "Yes\n58 57 56 55 54 53 52 51 50 49 48 47 45 44 43 42 40 39 38 37 36 35 34 33 32 30 29 28 27 26 25 23 22 21 20 19 17 15 12 11 10 9 8 7 6 3 2 1 0 " }, { "input": "567448991726268409 59", "output": "Yes\n56 56 56 56 56 56 56 55 54 52 51 50 49 48 47 46 45 44 43 41 40 39 38 36 35 32 31 30 29 28 27 25 24 23 22 21 20 19 18 17 16 14 13 11 10 9 8 7 6 5 4 3 -1 -2 -3 -4 -5 -6 -6 " }, { "input": "576460752303423487 9", "output": "No" }, { "input": "576460752303423487 19", "output": "No" }, { "input": "864691128455135231 29", "output": "No" }, { "input": "864691128455135231 39", "output": "No" }, { "input": "576460752303423487 49", "output": "No" }, { "input": "864691128455135231 59", "output": "Yes\n59 57 56 55 54 53 52 51 50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 " }, { "input": "628839188486443015 2412", "output": "Yes\n48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48 48..." }, { "input": "558445254282313727 89558", "output": "Yes\n43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43..." }, { "input": "576460752303423487 100000", "output": "Yes\n43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43..." }, { "input": "1 100000", "output": "Yes\n-16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 -16 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1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ..." }, { "input": "100003 100000", "output": "Yes\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ..." }, { "input": "12 202", "output": "Yes\n-4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4..." }, { "input": "1 4", "output": "Yes\n-2 -2 -2 -2 " }, { "input": "2 64", "output": "Yes\n-5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 -5 " }, { "input": "2 8", "output": "Yes\n-2 -2 -2 -2 -2 -2 -2 -2 " }, { "input": "1 5", "output": "Yes\n-2 -2 -2 -3 -3 " }, { "input": "1 7", "output": "Yes\n-2 -2 -2 -3 -4 -5 -5 " }, { "input": "19 5", "output": "Yes\n3 3 1 -1 -1 " }, { "input": "1 30", "output": "Yes\n-4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -4 -5 -6 -7 -8 -9 -10 -11 -12 -13 -14 -15 -16 -17 -18 -18 " } ]

1,516,438,038

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

4

109

6,553,600

n, k = map(int, input().split()) a = [0] * 128 l = 0 for i in range(64): if n & (1<<i): a[64 + i] = 1 h = 64 + i l += 1 if l > k: ans = "No" else: while l != k: while a[h] == 0: h -= 1 a[h] -= 1 a[h - 1] += 2 l += 1 ans = "Yes\n" for i in reversed(range(128)): if a[i]: ans += (str(i - 64) + " ") * a[i] print(ans)

Title: Jamie and Binary Sequence (changed after round) Time Limit: None seconds Memory Limit: None megabytes Problem Description: Jamie is preparing a Codeforces round. He has got an idea for a problem, but does not know how to solve it. Help him write a solution to the following problem: Find *k* integers such that the sum of two to the power of each number equals to the number *n* and the largest integer in the answer is as small as possible. As there may be multiple answers, you are asked to output the lexicographically largest one. To be more clear, consider all integer sequence with length *k* (*a*1,<=*a*2,<=...,<=*a**k*) with . Give a value to each sequence. Among all sequence(s) that have the minimum *y* value, output the one that is the lexicographically largest. For definitions of powers and lexicographical order see notes. Input Specification: The first line consists of two integers *n* and *k* (1<=≤<=*n*<=≤<=1018,<=1<=≤<=*k*<=≤<=105) — the required sum and the length of the sequence. Output Specification: Output "No" (without quotes) in a single line if there does not exist such sequence. Otherwise, output "Yes" (without quotes) in the first line, and *k* numbers separated by space in the second line — the required sequence. It is guaranteed that the integers in the answer sequence fit the range [<=-<=1018,<=1018]. Demo Input: ['23 5\n', '13 2\n', '1 2\n'] Demo Output: ['Yes\n3 3 2 1 0 \n', 'No\n', 'Yes\n-1 -1 \n'] Note: Sample 1: 23 + 23 + 22 + 21 + 20 = 8 + 8 + 4 + 2 + 1 = 23 Answers like (3, 3, 2, 0, 1) or (0, 1, 2, 3, 3) are not lexicographically largest. Answers like (4, 1, 1, 1, 0) do not have the minimum *y* value. Sample 2: It can be shown there does not exist a sequence with length 2. Sample 3: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a8539b2d27aefc8d2fab6dfd8296d11c36dcaa40.png" style="max-width: 100.0%;max-height: 100.0%;"/> Powers of 2: If *x* > 0, then 2*x* = 2·2·2·...·2 (*x* times). If *x* = 0, then 2*x* = 1. If *x* < 0, then <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/766628f1c7814795eac1a0afaa1ff062c40ef29e.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Lexicographical order: Given two different sequences of the same length, (*a*1, *a*2, ... , *a**k*) and (*b*1, *b*2, ... , *b**k*), the first one is smaller than the second one for the lexicographical order, if and only if *a**i* < *b**i*, for the first *i* where *a**i* and *b**i* differ.

```python n, k = map(int, input().split()) a = [0] * 128 l = 0 for i in range(64): if n & (1<<i): a[64 + i] = 1 h = 64 + i l += 1 if l > k: ans = "No" else: while l != k: while a[h] == 0: h -= 1 a[h] -= 1 a[h - 1] += 2 l += 1 ans = "Yes\n" for i in reversed(range(128)): if a[i]: ans += (str(i - 64) + " ") * a[i] print(ans) ```

0

879

B

Table Tennis

PROGRAMMING

1,200

[ "data structures", "implementation" ]

null

*n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner. For each of the participants, you know the power to play table tennis, and for all players these values are different. In a game the player with greater power always wins. Determine who will be the winner.

The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all *a**i* are distinct.

Output a single integer — power of the winner.

[ "2 2\n1 2\n", "4 2\n3 1 2 4\n", "6 2\n6 5 3 1 2 4\n", "2 10000000000\n2 1\n" ]

[ "2 ", "3 ", "6 ", "2\n" ]

Games in the second sample: 3 plays with 1. 3 wins. 1 goes to the end of the line. 3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner.

1,000

[ { "input": "2 2\n1 2", "output": "2 " }, { "input": "4 2\n3 1 2 4", "output": "3 " }, { "input": "6 2\n6 5 3 1 2 4", "output": "6 " }, { "input": "2 10000000000\n2 1", "output": "2" }, { "input": "4 4\n1 3 4 2", "output": "4 " }, { "input": "2 2147483648\n2 1", "output": "2" }, { "input": "3 2\n1 3 2", "output": "3 " }, { "input": "3 3\n1 2 3", "output": "3 " }, { "input": "5 2\n2 1 3 4 5", "output": "5 " }, { "input": "10 2\n7 10 5 8 9 3 4 6 1 2", "output": "10 " }, { "input": "100 2\n62 70 29 14 12 87 94 78 39 92 84 91 61 49 60 33 69 37 19 82 42 8 45 97 81 43 54 67 1 22 77 58 65 17 18 28 25 57 16 90 40 13 4 21 68 35 15 76 73 93 56 95 79 47 74 75 30 71 66 99 41 24 88 83 5 6 31 96 38 80 27 46 51 53 2 86 32 9 20 100 26 36 63 7 52 55 23 3 50 59 48 89 85 44 34 64 10 72 11 98", "output": "70 " }, { "input": "4 10\n2 1 3 4", "output": "4" }, { "input": "10 2\n1 2 3 4 5 6 7 8 9 10", "output": "10 " }, { "input": "10 2\n10 9 8 7 6 5 4 3 2 1", "output": "10 " }, { "input": "4 1000000000000\n3 4 1 2", "output": "4" }, { "input": "100 10\n19 55 91 50 31 23 60 84 38 1 22 51 27 76 28 98 11 44 61 63 15 93 52 3 66 16 53 36 18 62 35 85 78 37 73 64 87 74 46 26 82 69 49 33 83 89 56 67 71 25 39 94 96 17 21 6 47 68 34 42 57 81 13 10 54 2 48 80 20 77 4 5 59 30 90 95 45 75 8 88 24 41 40 14 97 32 7 9 65 70 100 99 72 58 92 29 79 12 86 43", "output": "91 " }, { "input": "100 50\n2 4 82 12 47 63 52 91 87 45 53 1 17 25 64 50 9 13 22 54 21 30 43 24 38 33 68 11 41 78 99 23 28 18 58 67 79 10 71 56 49 61 26 29 59 20 90 74 5 75 89 8 39 95 72 42 66 98 44 32 88 35 92 3 97 55 65 51 77 27 81 76 84 69 73 85 19 46 62 100 60 37 7 36 57 6 14 83 40 48 16 70 96 15 31 93 80 86 94 34", "output": "100 " }, { "input": "2 1000000000000\n1 2", "output": "2" }, { "input": "5 2\n1 4 3 5 2", "output": "4 " }, { "input": "5 2\n1 3 2 4 5", "output": "3 " }, { "input": "4 1000000000000\n3 1 2 4", "output": "4" }, { "input": "4 2\n1 3 2 4", "output": "3 " }, { "input": "10 3\n8 1 9 2 3 10 4 5 6 7", "output": "9 " }, { "input": "5 2\n2 1 4 3 5", "output": "4 " }, { "input": "3 4294967297\n2 1 3", "output": "3" }, { "input": "4 4294967297\n3 2 1 4", "output": "4" }, { "input": "5 4294967298\n3 2 1 4 5", "output": "5" }, { "input": "10 4\n5 4 7 1 2 9 3 6 8 10", "output": "9 " }, { "input": "11 21474836489\n10 1 2 3 4 5 6 7 8 9 11", "output": "11" } ]

1,623,085,479

2,147,483,647

PyPy 3

OK

TESTS

43

140

0

n, k = map(int, input().split()) v = list(map(int, input().split())) count = 0 previous = v[0] for i in range(1, n): if previous>v[i]: count+=1 else: previous = v[i] count = 1 if count==k: break print(previous)

Title: Table Tennis Time Limit: None seconds Memory Limit: None megabytes Problem Description: *n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner. For each of the participants, you know the power to play table tennis, and for all players these values are different. In a game the player with greater power always wins. Determine who will be the winner. Input Specification: The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all *a**i* are distinct. Output Specification: Output a single integer — power of the winner. Demo Input: ['2 2\n1 2\n', '4 2\n3 1 2 4\n', '6 2\n6 5 3 1 2 4\n', '2 10000000000\n2 1\n'] Demo Output: ['2 ', '3 ', '6 ', '2\n'] Note: Games in the second sample: 3 plays with 1. 3 wins. 1 goes to the end of the line. 3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner.

```python n, k = map(int, input().split()) v = list(map(int, input().split())) count = 0 previous = v[0] for i in range(1, n): if previous>v[i]: count+=1 else: previous = v[i] count = 1 if count==k: break print(previous) ```

3

593

B

Anton and Lines

PROGRAMMING

1,600

[ "geometry", "sortings" ]

null

The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In the task he was given a set of *n* lines defined by the equations *y*<==<=*k**i*·*x*<=+<=*b**i*. It was necessary to determine whether there is at least one point of intersection of two of these lines, that lays strictly inside the strip between *x*1<=<<=*x*2. In other words, is it true that there are 1<=≤<=*i*<=<<=*j*<=≤<=*n* and *x*',<=*y*', such that: - *y*'<==<=*k**i*<=*<=*x*'<=+<=*b**i*, that is, point (*x*',<=*y*') belongs to the line number *i*; - *y*'<==<=*k**j*<=*<=*x*'<=+<=*b**j*, that is, point (*x*',<=*y*') belongs to the line number *j*; - *x*1<=<<=*x*'<=<<=*x*2, that is, point (*x*',<=*y*') lies inside the strip bounded by *x*1<=<<=*x*2. You can't leave Anton in trouble, can you? Write a program that solves the given task.

The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of lines in the task given to Anton. The second line contains integers *x*1 and *x*2 (<=-<=1<=000<=000<=≤<=*x*1<=<<=*x*2<=≤<=1<=000<=000) defining the strip inside which you need to find a point of intersection of at least two lines. The following *n* lines contain integers *k**i*, *b**i* (<=-<=1<=000<=000<=≤<=*k**i*,<=*b**i*<=≤<=1<=000<=000) — the descriptions of the lines. It is guaranteed that all lines are pairwise distinct, that is, for any two *i*<=≠<=*j* it is true that either *k**i*<=≠<=*k**j*, or *b**i*<=≠<=*b**j*.

Print "Yes" (without quotes), if there is at least one intersection of two distinct lines, located strictly inside the strip. Otherwise print "No" (without quotes).

[ "4\n1 2\n1 2\n1 0\n0 1\n0 2\n", "2\n1 3\n1 0\n-1 3\n", "2\n1 3\n1 0\n0 2\n", "2\n1 3\n1 0\n0 3\n" ]

[ "NO", "YES", "YES", "NO" ]

In the first sample there are intersections located on the border of the strip, but there are no intersections located strictly inside it.

1,000

[ { "input": "4\n1 2\n1 2\n1 0\n0 1\n0 2", "output": "NO" }, { "input": "2\n1 3\n1 0\n-1 3", "output": "YES" }, { "input": "2\n1 3\n1 0\n0 2", "output": "YES" }, { "input": "2\n1 3\n1 0\n0 3", "output": "NO" }, { "input": "2\n0 1\n-1000000 1000000\n1000000 -1000000", "output": "NO" }, { "input": "2\n-1337 1888\n-1000000 1000000\n1000000 -1000000", "output": "YES" }, { "input": "2\n-1337 1888\n-1000000 1000000\n-999999 -1000000", "output": "NO" }, { "input": "15\n30 32\n-45 1\n-22 -81\n4 42\n-83 -19\n97 70\n55 -91\n-45 -64\n0 64\n11 96\n-16 76\n-46 52\n0 91\n31 -90\n6 75\n65 14", "output": "NO" }, { "input": "15\n-1 3\n2 -4\n0 -6\n-2 -5\n0 -1\n-1 -2\n3 6\n4 4\n0 -4\n1 5\n5 -4\n-5 -6\n3 -6\n5 -3\n-1 6\n-3 -1", "output": "YES" }, { "input": "5\n-197 -126\n0 -94\n-130 -100\n-84 233\n-173 -189\n61 -200", "output": "NO" }, { "input": "2\n9 10\n-7 -11\n9 2", "output": "NO" }, { "input": "3\n4 11\n-2 14\n2 -15\n-8 -15", "output": "YES" }, { "input": "2\n1 2\n2 -2\n0 2", "output": "NO" }, { "input": "10\n1 3\n1 5\n1 2\n1 4\n1 6\n1 3\n1 7\n1 -5\n1 -1\n1 1\n1 8", "output": "NO" }, { "input": "10\n22290 75956\n-66905 -22602\n-88719 12654\n-191 -81032\n0 -26057\n-39609 0\n0 51194\n2648 88230\n90584 15544\n0 23060\n-29107 26878", "output": "NO" }, { "input": "2\n-1337 1888\n100000 -100000\n99999 -100000", "output": "YES" }, { "input": "2\n-100000 100000\n100000 100000\n100000 99999", "output": "NO" }, { "input": "2\n-100000 100000\n100000 -100000\n99999 100000", "output": "NO" }, { "input": "2\n-100000 100000\n100000 100000\n100000 99876", "output": "NO" }, { "input": "2\n9 10\n4 -10\n-9 4", "output": "NO" }, { "input": "3\n4 7\n7 9\n0 10\n-7 2", "output": "NO" }, { "input": "4\n-4 -3\n4 -3\n10 -9\n5 -2\n0 9", "output": "NO" }, { "input": "5\n8 9\n0 -3\n0 -6\n-5 0\n-7 -2\n-4 9", "output": "NO" }, { "input": "6\n-7 8\n6 -1\n-10 -9\n4 8\n0 -2\n-6 -1\n3 -10", "output": "YES" }, { "input": "7\n5 7\n6 4\n-9 4\n-7 5\n1 -3\n5 -2\n7 -8\n6 -8", "output": "YES" }, { "input": "8\n-10 -2\n5 10\n9 7\n-8 -2\n0 6\n-9 0\n-6 2\n6 -8\n-3 2", "output": "YES" }, { "input": "9\n9 10\n8 -3\n9 8\n0 5\n10 1\n0 8\n5 -5\n-4 8\n0 10\n3 -10", "output": "NO" }, { "input": "10\n-1 0\n-2 4\n2 4\n-3 -7\n-2 -9\n7 6\n0 2\n1 4\n0 10\n0 -8\n-5 1", "output": "YES" }, { "input": "11\n3 8\n0 -9\n-8 -10\n3 4\n3 5\n2 1\n-5 4\n0 -10\n-7 6\n5 -4\n-9 -3\n5 1", "output": "YES" }, { "input": "3\n0 2\n10 0\n0 0\n8 2", "output": "YES" }, { "input": "2\n0 1000000\n0 0\n1000000 1000000", "output": "NO" }, { "input": "2\n515806 517307\n530512 500306\n520201 504696", "output": "NO" }, { "input": "2\n0 65536\n65536 0\n0 1", "output": "YES" }, { "input": "3\n1 3\n-1 5\n1 1\n0 4", "output": "YES" }, { "input": "2\n0 1000000\n1000000 1\n1 2", "output": "YES" }, { "input": "2\n0 3\n1 1\n2 1", "output": "NO" }, { "input": "2\n0 1\n1 0\n2 0", "output": "NO" }, { "input": "3\n1 3\n1 0\n-1 3\n0 10", "output": "YES" }, { "input": "2\n0 1000000\n1000000 1000000\n0 3", "output": "NO" }, { "input": "2\n0 1\n1 0\n-2 2", "output": "YES" }, { "input": "2\n5 1000000\n1000000 5\n5 5", "output": "NO" }, { "input": "4\n0 1\n0 0\n0 1\n1 0\n-1 1", "output": "YES" }, { "input": "2\n0 1000000\n1000000 1000000\n1 1", "output": "NO" }, { "input": "3\n0 1000000\n1000000 999999\n-1000000 1000000\n1000000 1000000", "output": "YES" }, { "input": "2\n-1000000 1000000\n2 3\n1 3", "output": "YES" }, { "input": "2\n0 1000000\n1000000 1\n2 2", "output": "YES" }, { "input": "2\n-1 1\n1 0\n-1 0", "output": "YES" }, { "input": "2\n0 1000000\n2200 1\n0 0", "output": "NO" }, { "input": "2\n1 999999\n999999 0\n1 0", "output": "NO" }, { "input": "2\n0 1\n1 0\n-1 1", "output": "YES" }, { "input": "2\n0 1000000\n999999 999999\n0 0", "output": "NO" }, { "input": "7\n0 1\n0 -1\n3 0\n5 0\n2 0\n4 0\n1 0\n0 100", "output": "NO" }, { "input": "2\n0 1000000\n1000000 0\n0 100", "output": "YES" }, { "input": "4\n0 1\n-1 2\n0 1\n1 0\n-1 0", "output": "NO" }, { "input": "3\n0 1\n0 1\n0 10\n2 0", "output": "YES" }, { "input": "4\n0 1\n3 0\n2 0\n1 0\n-1 3", "output": "YES" }, { "input": "2\n0 1000000\n10000 0\n100000 1", "output": "NO" }, { "input": "5\n-2 2\n2 0\n0 100000\n0 10000\n0 1000\n0 0", "output": "YES" }, { "input": "2\n0 1000000\n0 0\n2200 1", "output": "NO" }, { "input": "2\n0 1000000\n1 0\n1000000 1", "output": "NO" }, { "input": "2\n2 5\n2 -4\n3 -6", "output": "NO" }, { "input": "2\n-1 1\n0 0\n0 1", "output": "NO" }, { "input": "2\n900000 1000000\n900000 1000000\n1000000 900000", "output": "NO" } ]

1,482,261,187

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

53

592

16,896,000

n = int(input().strip()) x1 , x2 = [int(a) for a in input().strip().split()] intersect1 = [] for i in range(n): a, c = [int(a) for a in input().strip().split()] intersect1.append([a*x1 + c, a*x2 + c]) intersect1.sort(key=lambda tup: tup[0]) for i in range(n-1): if intersect1[i][0] < intersect1[i+1][0] and intersect1[i][1] > intersect1[i+1][1]: print("YES") exit() print("NO")

Title: Anton and Lines Time Limit: None seconds Memory Limit: None megabytes Problem Description: The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In the task he was given a set of *n* lines defined by the equations *y*<==<=*k**i*·*x*<=+<=*b**i*. It was necessary to determine whether there is at least one point of intersection of two of these lines, that lays strictly inside the strip between *x*1<=<<=*x*2. In other words, is it true that there are 1<=≤<=*i*<=<<=*j*<=≤<=*n* and *x*',<=*y*', such that: - *y*'<==<=*k**i*<=*<=*x*'<=+<=*b**i*, that is, point (*x*',<=*y*') belongs to the line number *i*; - *y*'<==<=*k**j*<=*<=*x*'<=+<=*b**j*, that is, point (*x*',<=*y*') belongs to the line number *j*; - *x*1<=<<=*x*'<=<<=*x*2, that is, point (*x*',<=*y*') lies inside the strip bounded by *x*1<=<<=*x*2. You can't leave Anton in trouble, can you? Write a program that solves the given task. Input Specification: The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of lines in the task given to Anton. The second line contains integers *x*1 and *x*2 (<=-<=1<=000<=000<=≤<=*x*1<=<<=*x*2<=≤<=1<=000<=000) defining the strip inside which you need to find a point of intersection of at least two lines. The following *n* lines contain integers *k**i*, *b**i* (<=-<=1<=000<=000<=≤<=*k**i*,<=*b**i*<=≤<=1<=000<=000) — the descriptions of the lines. It is guaranteed that all lines are pairwise distinct, that is, for any two *i*<=≠<=*j* it is true that either *k**i*<=≠<=*k**j*, or *b**i*<=≠<=*b**j*. Output Specification: Print "Yes" (without quotes), if there is at least one intersection of two distinct lines, located strictly inside the strip. Otherwise print "No" (without quotes). Demo Input: ['4\n1 2\n1 2\n1 0\n0 1\n0 2\n', '2\n1 3\n1 0\n-1 3\n', '2\n1 3\n1 0\n0 2\n', '2\n1 3\n1 0\n0 3\n'] Demo Output: ['NO', 'YES', 'YES', 'NO'] Note: In the first sample there are intersections located on the border of the strip, but there are no intersections located strictly inside it.

```python n = int(input().strip()) x1 , x2 = [int(a) for a in input().strip().split()] intersect1 = [] for i in range(n): a, c = [int(a) for a in input().strip().split()] intersect1.append([a*x1 + c, a*x2 + c]) intersect1.sort(key=lambda tup: tup[0]) for i in range(n-1): if intersect1[i][0] < intersect1[i+1][0] and intersect1[i][1] > intersect1[i+1][1]: print("YES") exit() print("NO") ```

0

139

A

Petr and Book

PROGRAMMING

1,000

[ "implementation" ]

null

One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages. Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week. Assuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book.

The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book. The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero.

Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

[ "100\n15 20 20 15 10 30 45\n", "2\n1 0 0 0 0 0 0\n" ]

[ "6\n", "1\n" ]

Note to the first sample: By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else). Note to the second sample: On Monday of the first week Petr will read the first page. On Monday of the second week Petr will read the second page and will finish reading the book.

500

[ { "input": "100\n15 20 20 15 10 30 45", "output": "6" }, { "input": "2\n1 0 0 0 0 0 0", "output": "1" }, { "input": "100\n100 200 100 200 300 400 500", "output": "1" }, { "input": "3\n1 1 1 1 1 1 1", "output": "3" }, { "input": "1\n1 1 1 1 1 1 1", "output": "1" }, { "input": "20\n5 3 7 2 1 6 4", "output": "6" }, { "input": "10\n5 1 1 1 1 1 5", "output": "6" }, { "input": "50\n10 1 10 1 10 1 10", "output": "1" }, { "input": "77\n11 11 11 11 11 11 10", "output": "1" }, { "input": "1\n1000 1000 1000 1000 1000 1000 1000", "output": "1" }, { "input": "1000\n100 100 100 100 100 100 100", "output": "3" }, { "input": "999\n10 20 10 20 30 20 10", "output": "3" }, { "input": "433\n109 58 77 10 39 125 15", "output": "7" }, { "input": "1\n0 0 0 0 0 0 1", "output": "7" }, { "input": "5\n1 0 1 0 1 0 1", "output": "1" }, { "input": "997\n1 1 0 0 1 0 1", "output": "1" }, { "input": "1000\n1 1 1 1 1 1 1", "output": "6" }, { "input": "1000\n1000 1000 1000 1000 1000 1000 1000", "output": "1" }, { "input": "1000\n1 0 0 0 0 0 0", "output": "1" }, { "input": "1000\n0 0 0 0 0 0 1", "output": "7" }, { "input": "1000\n1 0 0 1 0 0 1", "output": "1" }, { "input": "509\n105 23 98 0 7 0 155", "output": "2" }, { "input": "7\n1 1 1 1 1 1 1", "output": "7" }, { "input": "2\n1 1 0 0 0 0 0", "output": "2" }, { "input": "1\n0 0 0 0 0 1 0", "output": "6" }, { "input": "10\n0 0 0 0 0 0 1", "output": "7" }, { "input": "5\n0 0 0 0 0 6 0", "output": "6" }, { "input": "3\n0 1 0 0 0 0 0", "output": "2" }, { "input": "10\n0 0 0 0 0 0 10", "output": "7" }, { "input": "28\n1 2 3 4 5 6 7", "output": "7" }, { "input": "100\n5 5 5 5 5 5 5", "output": "6" }, { "input": "4\n1 0 0 0 0 0 1", "output": "7" }, { "input": "2\n0 0 0 0 0 0 1", "output": "7" }, { "input": "7\n0 0 0 0 0 0 7", "output": "7" }, { "input": "7\n2 1 1 1 1 1 0", "output": "6" }, { "input": "2\n0 0 1 1 0 0 0", "output": "4" }, { "input": "6\n1 1 1 1 1 1 0", "output": "6" }, { "input": "5\n1 1 1 0 0 1 1", "output": "7" }, { "input": "100\n10 20 30 10 10 10 10", "output": "7" }, { "input": "1\n0 0 0 1 0 0 0", "output": "4" }, { "input": "70\n10 10 10 10 10 10 10", "output": "7" }, { "input": "22\n1 2 3 4 5 6 10", "output": "7" }, { "input": "5\n0 0 0 1 0 0 0", "output": "4" }, { "input": "2\n0 0 0 1 0 0 0", "output": "4" }, { "input": "6\n1 0 0 0 0 0 2", "output": "7" }, { "input": "10\n1 2 2 1 2 1 1", "output": "7" }, { "input": "5\n0 0 0 0 0 0 10", "output": "7" }, { "input": "4\n0 1 1 0 0 0 0", "output": "3" }, { "input": "100\n0 0 0 0 0 1 0", "output": "6" } ]

1,596,203,051

2,147,483,647

PyPy 3

OK

TESTS

49

280

21,401,600

n=int(input()) a=[int(x) for x in input().split()] i=0 while n>0: n-=a[i] i+=1 i%=7 print(7) if i==0 else print(i)

Title: Petr and Book Time Limit: None seconds Memory Limit: None megabytes Problem Description: One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages. Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week. Assuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book. Input Specification: The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book. The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero. Output Specification: Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Demo Input: ['100\n15 20 20 15 10 30 45\n', '2\n1 0 0 0 0 0 0\n'] Demo Output: ['6\n', '1\n'] Note: Note to the first sample: By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else). Note to the second sample: On Monday of the first week Petr will read the first page. On Monday of the second week Petr will read the second page and will finish reading the book.

```python n=int(input()) a=[int(x) for x in input().split()] i=0 while n>0: n-=a[i] i+=1 i%=7 print(7) if i==0 else print(i) ```

3

573

A

Bear and Poker

PROGRAMMING

1,300

[ "implementation", "math", "number theory" ]

null

Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a**i* dollars. Each player can double his bid any number of times and triple his bid any number of times. The casino has a great jackpot for making all bids equal. Is it possible that Limak and his friends will win a jackpot?

First line of input contains an integer *n* (2<=≤<=*n*<=≤<=105), the number of players. The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the bids of players.

Print "Yes" (without the quotes) if players can make their bids become equal, or "No" otherwise.

[ "4\n75 150 75 50\n", "3\n100 150 250\n" ]

[ "Yes\n", "No\n" ]

In the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid. It can be shown that in the second sample test there is no way to make all bids equal.

500

[ { "input": "4\n75 150 75 50", "output": "Yes" }, { "input": "3\n100 150 250", "output": "No" }, { "input": "7\n34 34 68 34 34 68 34", "output": "Yes" }, { "input": "10\n72 96 12 18 81 20 6 2 54 1", "output": "No" }, { "input": "20\n958692492 954966768 77387000 724664764 101294996 614007760 202904092 555293973 707655552 108023967 73123445 612562357 552908390 914853758 915004122 466129205 122853497 814592742 373389439 818473058", "output": "No" }, { "input": "2\n1 1", "output": "Yes" }, { "input": "2\n72 72", "output": "Yes" }, { "input": "2\n49 42", "output": "No" }, { "input": "3\n1000000000 1000000000 1000000000", "output": "Yes" }, { "input": "6\n162000 96000 648000 1000 864000 432000", "output": "Yes" }, { "input": "8\n600000 100000 100000 100000 900000 600000 900000 600000", "output": "Yes" }, { "input": "12\n2048 1024 6144 1024 3072 3072 6144 1024 4096 2048 6144 3072", "output": "Yes" }, { "input": "20\n246 246 246 246 246 246 246 246 246 246 246 246 246 246 246 246 246 246 246 246", "output": "Yes" }, { "input": "50\n840868705 387420489 387420489 795385082 634350497 206851546 536870912 536870912 414927754 387420489 387420489 536870912 387420489 149011306 373106005 536870912 700746206 387420489 777952883 847215247 176645254 576664386 387420489 230876513 536870912 536870912 536870912 387420489 387420489 536870912 460495524 528643722 387420489 536870912 470369206 899619085 387420489 631148352 387420489 387420489 536870912 414666674 521349938 776784669 387420489 102428009 536870912 387420489 536870912 718311009", "output": "No" }, { "input": "2\n5 6", "output": "No" }, { "input": "3\n536870912 387420489 257407169", "output": "No" }, { "input": "4\n2 2 5 2", "output": "No" }, { "input": "2\n33554432 59049", "output": "Yes" }, { "input": "3\n536870912 387420489 387420489", "output": "Yes" }, { "input": "2\n1 5", "output": "No" }, { "input": "18\n2 3 5 7 11 13 17 19 23 29 31 37 43 47 53 59 67 71", "output": "No" }, { "input": "2\n1 30", "output": "No" }, { "input": "3\n335544320 71744535 71744535", "output": "Yes" }, { "input": "5\n1000000000 999999999 999999998 999999997 999999996", "output": "No" }, { "input": "2\n25 5", "output": "No" }, { "input": "4\n75 150 75 5", "output": "No" }, { "input": "3\n536870912 387420489 362797056", "output": "Yes" }, { "input": "3\n536870912 387420489 89", "output": "No" }, { "input": "4\n547 2606459 222763549 143466789", "output": "No" }, { "input": "3\n129140163 33554432 1", "output": "Yes" }, { "input": "10\n244140625 244140625 244140625 244140625 244140625 244140625 244140625 244140625 536870912 387420489", "output": "No" }, { "input": "3\n5 5 1", "output": "No" }, { "input": "5\n3 7 29 36760123 823996703", "output": "No" } ]

1,571,783,059

2,147,483,647

PyPy 3

RUNTIME_ERROR

TESTS

4

202

4,608,000

import math as mt MAXN = 100001 spf = [0 for i in range(MAXN)] def find_lcm(num1, num2): if(num1>num2): num = num1 den = num2 else: num = num2 den = num1 rem = num % den while(rem != 0): num = den den = rem rem = num % den gcd = den lcm = int(int(num1 * num2)/int(gcd)) return lcm def sieve(): spf[1] = 1 for i in range(2, MAXN): spf[i] = i for i in range(4, MAXN, 2): spf[i] = 2 for i in range(3, mt.ceil(mt.sqrt(MAXN))): # checking if i is prime if (spf[i] == i): # marking SPF for all numbers # divisible by i for j in range(i * i, MAXN, i): # marking spf[j] if it is # not previously marked if (spf[j] == j): spf[j] = i # A O(log n) function returning prime # factorization by dividing by smallest # prime factor at every step def getFactorization(x): ret = list() flag=0 while (x != 1): #print(x) ret.append(spf[x]) #if(spf[x]!=0): x = x // spf[x] for i in ret: if(i==2 or i==3 or i==1): pass else: flag=1 break if(flag==1): return False else: return True n=int(input()) tag=0 l = [int(i) for i in input().split()] num1 = l[0] num2 = l[1] lcm = find_lcm(num1, num2) for i in range(2, len(l)): lcm = find_lcm(lcm, l[i]) for i in range(n): l[i]=lcm//l[i] #print(l) for i in range(n): sieve() #print(getFactorization(l[i])) if(getFactorization(l[i])): continue else: tag=1 break if(tag==0): print('Yes') else: print('No')

Title: Bear and Poker Time Limit: None seconds Memory Limit: None megabytes Problem Description: Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a**i* dollars. Each player can double his bid any number of times and triple his bid any number of times. The casino has a great jackpot for making all bids equal. Is it possible that Limak and his friends will win a jackpot? Input Specification: First line of input contains an integer *n* (2<=≤<=*n*<=≤<=105), the number of players. The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the bids of players. Output Specification: Print "Yes" (without the quotes) if players can make their bids become equal, or "No" otherwise. Demo Input: ['4\n75 150 75 50\n', '3\n100 150 250\n'] Demo Output: ['Yes\n', 'No\n'] Note: In the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid. It can be shown that in the second sample test there is no way to make all bids equal.

```python import math as mt MAXN = 100001 spf = [0 for i in range(MAXN)] def find_lcm(num1, num2): if(num1>num2): num = num1 den = num2 else: num = num2 den = num1 rem = num % den while(rem != 0): num = den den = rem rem = num % den gcd = den lcm = int(int(num1 * num2)/int(gcd)) return lcm def sieve(): spf[1] = 1 for i in range(2, MAXN): spf[i] = i for i in range(4, MAXN, 2): spf[i] = 2 for i in range(3, mt.ceil(mt.sqrt(MAXN))): # checking if i is prime if (spf[i] == i): # marking SPF for all numbers # divisible by i for j in range(i * i, MAXN, i): # marking spf[j] if it is # not previously marked if (spf[j] == j): spf[j] = i # A O(log n) function returning prime # factorization by dividing by smallest # prime factor at every step def getFactorization(x): ret = list() flag=0 while (x != 1): #print(x) ret.append(spf[x]) #if(spf[x]!=0): x = x // spf[x] for i in ret: if(i==2 or i==3 or i==1): pass else: flag=1 break if(flag==1): return False else: return True n=int(input()) tag=0 l = [int(i) for i in input().split()] num1 = l[0] num2 = l[1] lcm = find_lcm(num1, num2) for i in range(2, len(l)): lcm = find_lcm(lcm, l[i]) for i in range(n): l[i]=lcm//l[i] #print(l) for i in range(n): sieve() #print(getFactorization(l[i])) if(getFactorization(l[i])): continue else: tag=1 break if(tag==0): print('Yes') else: print('No') ```

-1

798

A

Mike and palindrome

PROGRAMMING

1,000

[ "brute force", "constructive algorithms", "strings" ]

null

Mike has a string *s* consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome. A palindrome is a string that reads the same backward as forward, for example strings "z", "aaa", "aba", "abccba" are palindromes, but strings "codeforces", "reality", "ab" are not.

The first and single line contains string *s* (1<=≤<=|*s*|<=≤<=15).

Print "YES" (without quotes) if Mike can change exactly one character so that the resulting string is palindrome or "NO" (without quotes) otherwise.

[ "abccaa\n", "abbcca\n", "abcda\n" ]

[ "YES\n", "NO\n", "YES\n" ]

none

500

[ { "input": "abccaa", "output": "YES" }, { "input": "abbcca", "output": "NO" }, { "input": "abcda", "output": "YES" }, { "input": "kyw", "output": "YES" }, { "input": "fccf", "output": "NO" }, { "input": "mnlm", "output": "YES" }, { "input": "gqrk", "output": "NO" }, { "input": "glxlg", "output": "YES" }, { "input": "czhfc", "output": "YES" }, { "input": "broon", "output": "NO" }, { "input": "rmggmr", "output": "NO" }, { "input": "wvxxzw", "output": "YES" }, { "input": "ukvciu", "output": "NO" }, { "input": "vrnwnrv", "output": "YES" }, { "input": "vlkjkav", "output": "YES" }, { "input": "guayhmg", "output": "NO" }, { "input": "lkvhhvkl", "output": "NO" }, { "input": "ffdsslff", "output": "YES" }, { "input": "galjjtyw", "output": "NO" }, { "input": "uosgwgsou", "output": "YES" }, { "input": "qjwmjmljq", "output": "YES" }, { "input": "ustrvrodf", "output": "NO" }, { "input": "a", "output": "YES" }, { "input": "qjfyjjyfjq", "output": "NO" }, { "input": "ysxibbixsq", "output": "YES" }, { "input": "howfslfwmh", "output": "NO" }, { "input": "ekhajrjahke", "output": "YES" }, { "input": "ucnolsloncw", "output": "YES" }, { "input": "jrzsfrrkrtj", "output": "NO" }, { "input": "typayzzyapyt", "output": "NO" }, { "input": "uwdhkzokhdwu", "output": "YES" }, { "input": "xokxpyyuafij", "output": "NO" }, { "input": "eusneioiensue", "output": "YES" }, { "input": "fuxpuajabpxuf", "output": "YES" }, { "input": "guvggtfhlgruy", "output": "NO" }, { "input": "cojhkhxxhkhjoc", "output": "NO" }, { "input": "mhifbmmmmbmihm", "output": "YES" }, { "input": "kxfqqncnebpami", "output": "NO" }, { "input": "scfwrjevejrwfcs", "output": "YES" }, { "input": "thdaonpepdoadht", "output": "YES" }, { "input": "jsfzcbnhsccuqsj", "output": "NO" }, { "input": "nn", "output": "NO" }, { "input": "nm", "output": "YES" }, { "input": "jdj", "output": "YES" }, { "input": "bbcaa", "output": "NO" }, { "input": "abcde", "output": "NO" }, { "input": "abcdf", "output": "NO" }, { "input": "aa", "output": "NO" }, { "input": "abecd", "output": "NO" }, { "input": "abccacb", "output": "NO" }, { "input": "aabc", "output": "NO" }, { "input": "anpqb", "output": "NO" }, { "input": "c", "output": "YES" }, { "input": "abcdefg", "output": "NO" }, { "input": "aanbb", "output": "NO" }, { "input": "aabbb", "output": "NO" }, { "input": "aaabbab", "output": "NO" }, { "input": "ab", "output": "YES" }, { "input": "aabbc", "output": "NO" }, { "input": "ecabd", "output": "NO" }, { "input": "abcdrty", "output": "NO" }, { "input": "abcdmnp", "output": "NO" }, { "input": "bbbbbb", "output": "NO" }, { "input": "abcxuio", "output": "NO" }, { "input": "abcdabcde", "output": "NO" }, { "input": "abcxpoi", "output": "NO" }, { "input": "aba", "output": "YES" }, { "input": "aacbb", "output": "NO" }, { "input": "abcedca", "output": "NO" }, { "input": "abcdd", "output": "NO" }, { "input": "abbcs", "output": "NO" }, { "input": "aaabccc", "output": "NO" }, { "input": "paxkxbq", "output": "NO" }, { "input": "z", "output": "YES" }, { "input": "b", "output": "YES" }, { "input": "abcdefghi", "output": "NO" }, { "input": "abcqr", "output": "NO" }, { "input": "abcdc", "output": "NO" }, { "input": "abcb", "output": "NO" }, { "input": "aabcd", "output": "NO" }, { "input": "abbba", "output": "YES" }, { "input": "aaabbb", "output": "NO" }, { "input": "bb", "output": "NO" }, { "input": "aaacbbb", "output": "NO" }, { "input": "abbzcca", "output": "NO" }, { "input": "abxab", "output": "NO" }, { "input": "bbb", "output": "YES" }, { "input": "abcrtyu", "output": "NO" }, { "input": "cbacb", "output": "NO" }, { "input": "acbb", "output": "NO" }, { "input": "ww", "output": "NO" }, { "input": "aaaaaa", "output": "NO" }, { "input": "jizzz", "output": "NO" }, { "input": "aaakcba", "output": "NO" }, { "input": "acbak", "output": "NO" }, { "input": "bddeffd", "output": "NO" }, { "input": "aaa", "output": "YES" }, { "input": "afghqwe", "output": "NO" }, { "input": "abcdfga", "output": "NO" } ]

1,670,927,074

2,147,483,647

PyPy 3-64

WRONG_ANSWER

TESTS

0

30

0

def my_function(x): return x[::-1] qwe = str(input()) mytxt = my_function(qwe) print(qwe) print(mytxt) for i in range(len(qwe)): if mytxt[i] == qwe[i]: i = i + 1 continue else: if i > 1: print("No") break else: mytxt = mytxt.replace(mytxt[i], qwe[i]) if mytxt[i] == qwe[i]: print("Yes") break else: print("No") break

Title: Mike and palindrome Time Limit: None seconds Memory Limit: None megabytes Problem Description: Mike has a string *s* consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome. A palindrome is a string that reads the same backward as forward, for example strings "z", "aaa", "aba", "abccba" are palindromes, but strings "codeforces", "reality", "ab" are not. Input Specification: The first and single line contains string *s* (1<=≤<=|*s*|<=≤<=15). Output Specification: Print "YES" (without quotes) if Mike can change exactly one character so that the resulting string is palindrome or "NO" (without quotes) otherwise. Demo Input: ['abccaa\n', 'abbcca\n', 'abcda\n'] Demo Output: ['YES\n', 'NO\n', 'YES\n'] Note: none

```python def my_function(x): return x[::-1] qwe = str(input()) mytxt = my_function(qwe) print(qwe) print(mytxt) for i in range(len(qwe)): if mytxt[i] == qwe[i]: i = i + 1 continue else: if i > 1: print("No") break else: mytxt = mytxt.replace(mytxt[i], qwe[i]) if mytxt[i] == qwe[i]: print("Yes") break else: print("No") break ```

0

918

B

Radio Station

PROGRAMMING

900

[ "implementation", "strings" ]

null

As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server has a name and an ip (names aren't necessarily unique, but ips are). Dustin knows the ip and name of each server. For simplicity, we'll assume that an nginx command is of form "command ip;" where command is a string consisting of English lowercase letter only, and ip is the ip of one of school servers. Each ip is of form "a.b.c.d" where *a*, *b*, *c* and *d* are non-negative integers less than or equal to 255 (with no leading zeros). The nginx configuration file Dustin has to add comments to has *m* commands. Nobody ever memorizes the ips of servers, so to understand the configuration better, Dustin has to comment the name of server that the ip belongs to at the end of each line (after each command). More formally, if a line is "command ip;" Dustin has to replace it with "command ip; #name" where name is the name of the server with ip equal to ip. Dustin doesn't know anything about nginx, so he panicked again and his friends asked you to do his task for him.

The first line of input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000). The next *n* lines contain the names and ips of the servers. Each line contains a string name, name of the server and a string ip, ip of the server, separated by space (1<=≤<=|*name*|<=≤<=10, *name* only consists of English lowercase letters). It is guaranteed that all ip are distinct. The next *m* lines contain the commands in the configuration file. Each line is of form "command ip;" (1<=≤<=|*command*|<=≤<=10, command only consists of English lowercase letters). It is guaranteed that ip belongs to one of the *n* school servers.

Print *m* lines, the commands in the configuration file after Dustin did his task.

[ "2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;\n", "3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;\n" ]

[ "block 192.168.0.1; #replica\nproxy 192.168.0.2; #main\n", "redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server\n" ]

none

1,000

[ { "input": "2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;", "output": "block 192.168.0.1; #replica\nproxy 192.168.0.2; #main" }, { "input": "3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;", "output": "redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server" }, { "input": "10 10\nittmcs 112.147.123.173\njkt 228.40.73.178\nfwckqtz 88.28.31.198\nkal 224.226.34.213\nnacuyokm 49.57.13.44\nfouynv 243.18.250.17\ns 45.248.83.247\ne 75.69.23.169\nauwoqlch 100.44.219.187\nlkldjq 46.123.169.140\ngjcylatwzi 46.123.169.140;\ndxfi 88.28.31.198;\ngv 46.123.169.140;\nety 88.28.31.198;\notbmgcrn 46.123.169.140;\nw 112.147.123.173;\np 75.69.23.169;\nvdsnigk 46.123.169.140;\nmmc 46.123.169.140;\ngtc 49.57.13.44;", "output": "gjcylatwzi 46.123.169.140; #lkldjq\ndxfi 88.28.31.198; #fwckqtz\ngv 46.123.169.140; #lkldjq\nety 88.28.31.198; #fwckqtz\notbmgcrn 46.123.169.140; #lkldjq\nw 112.147.123.173; #ittmcs\np 75.69.23.169; #e\nvdsnigk 46.123.169.140; #lkldjq\nmmc 46.123.169.140; #lkldjq\ngtc 49.57.13.44; #nacuyokm" }, { "input": "1 1\nervbfot 185.32.99.2\nzygoumbmx 185.32.99.2;", "output": "zygoumbmx 185.32.99.2; #ervbfot" }, { "input": "1 2\ny 245.182.246.189\nlllq 245.182.246.189;\nxds 245.182.246.189;", "output": "lllq 245.182.246.189; #y\nxds 245.182.246.189; #y" }, { "input": "2 1\ntdwmshz 203.115.124.110\neksckjya 201.80.191.212\nzbtjzzue 203.115.124.110;", "output": "zbtjzzue 203.115.124.110; #tdwmshz" }, { "input": "8 5\nfhgkq 5.19.189.178\nphftablcr 75.18.177.178\nxnpcg 158.231.167.176\ncfahrkq 26.165.124.191\nfkgtnqtfoh 230.13.13.129\nt 101.24.94.85\nvjoirslx 59.6.179.72\ntwktmskb 38.194.117.184\nrvzzlygosc 26.165.124.191;\ndcsgxrkgv 101.24.94.85;\nyvmyppn 59.6.179.72;\ngpdjjuq 75.18.177.178;\nvdviz 101.24.94.85;", "output": "rvzzlygosc 26.165.124.191; #cfahrkq\ndcsgxrkgv 101.24.94.85; #t\nyvmyppn 59.6.179.72; #vjoirslx\ngpdjjuq 75.18.177.178; #phftablcr\nvdviz 101.24.94.85; #t" }, { "input": "2 1\nmain 1.1.1.1\nget 11.1.1.1\ncommand 11.1.1.1;", "output": "command 11.1.1.1; #get" }, { "input": "2 2\nmain 0.0.0.255\nmainn 0.0.2.55\nblock 0.0.0.255;\nblock 0.0.2.55;", "output": "block 0.0.0.255; #main\nblock 0.0.2.55; #mainn" }, { "input": "2 2\nmain 0.0.63.0\nreplica 0.38.0.56\nblock 0.0.63.0;\nproxy 0.38.0.56;", "output": "block 0.0.63.0; #main\nproxy 0.38.0.56; #replica" }, { "input": "2 2\nmain 192.168.10.12\nreplica 192.167.10.12\nblock 192.168.10.12;\nproxy 192.167.10.12;", "output": "block 192.168.10.12; #main\nproxy 192.167.10.12; #replica" }, { "input": "2 1\nneserver 185.218.47.91\nserver 255.255.255.255\nblock 255.255.255.255;", "output": "block 255.255.255.255; #server" }, { "input": "2 1\nalp 22.222.30.10\nbet 222.22.30.10\nblock 22.222.30.10;", "output": "block 22.222.30.10; #alp" } ]

1,624,174,052

2,147,483,647

Python 3

OK

TESTS

28

77

0

tc = 1 while tc: tc-=1 n, m = map(int, input().split()) d = {} for i in range(n): l = list(map(str, input().split())) d[l[1]] = l[0] for i in range(m): l = list(map(str, input().split())) print(l[0], l[1], '#', end = '') print(d[l[1][:-1]])

Title: Radio Station Time Limit: None seconds Memory Limit: None megabytes Problem Description: As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server has a name and an ip (names aren't necessarily unique, but ips are). Dustin knows the ip and name of each server. For simplicity, we'll assume that an nginx command is of form "command ip;" where command is a string consisting of English lowercase letter only, and ip is the ip of one of school servers. Each ip is of form "a.b.c.d" where *a*, *b*, *c* and *d* are non-negative integers less than or equal to 255 (with no leading zeros). The nginx configuration file Dustin has to add comments to has *m* commands. Nobody ever memorizes the ips of servers, so to understand the configuration better, Dustin has to comment the name of server that the ip belongs to at the end of each line (after each command). More formally, if a line is "command ip;" Dustin has to replace it with "command ip; #name" where name is the name of the server with ip equal to ip. Dustin doesn't know anything about nginx, so he panicked again and his friends asked you to do his task for him. Input Specification: The first line of input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000). The next *n* lines contain the names and ips of the servers. Each line contains a string name, name of the server and a string ip, ip of the server, separated by space (1<=≤<=|*name*|<=≤<=10, *name* only consists of English lowercase letters). It is guaranteed that all ip are distinct. The next *m* lines contain the commands in the configuration file. Each line is of form "command ip;" (1<=≤<=|*command*|<=≤<=10, command only consists of English lowercase letters). It is guaranteed that ip belongs to one of the *n* school servers. Output Specification: Print *m* lines, the commands in the configuration file after Dustin did his task. Demo Input: ['2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;\n', '3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;\n'] Demo Output: ['block 192.168.0.1; #replica\nproxy 192.168.0.2; #main\n', 'redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server\n'] Note: none

```python tc = 1 while tc: tc-=1 n, m = map(int, input().split()) d = {} for i in range(n): l = list(map(str, input().split())) d[l[1]] = l[0] for i in range(m): l = list(map(str, input().split())) print(l[0], l[1], '#', end = '') print(d[l[1][:-1]]) ```

3

379

A

New Year Candles

PROGRAMMING

1,000

[ "implementation" ]

null

Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles. Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used like any other new candle. Now Vasily wonders: for how many hours can his candles light up the room if he acts optimally well? Help him find this number.

The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000).

Print a single integer — the number of hours Vasily can light up the room for.

[ "4 2\n", "6 3\n" ]

[ "7\n", "8\n" ]

Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours.

500

[ { "input": "4 2", "output": "7" }, { "input": "6 3", "output": "8" }, { "input": "1000 1000", "output": "1001" }, { "input": "123 5", "output": "153" }, { "input": "1000 2", "output": "1999" }, { "input": "1 2", "output": "1" }, { "input": "1 3", "output": "1" }, { "input": "1 4", "output": "1" }, { "input": "2 2", "output": "3" }, { "input": "3 2", "output": "5" }, { "input": "3 3", "output": "4" }, { "input": "999 2", "output": "1997" }, { "input": "1000 3", "output": "1499" }, { "input": "1000 4", "output": "1333" }, { "input": "1 1000", "output": "1" }, { "input": "80 970", "output": "80" }, { "input": "80 970", "output": "80" }, { "input": "80 970", "output": "80" }, { "input": "80 970", "output": "80" }, { "input": "80 970", "output": "80" }, { "input": "80 970", "output": "80" }, { "input": "10 4", "output": "13" }, { "input": "4 3", "output": "5" }, { "input": "91 5", "output": "113" }, { "input": "777 17", "output": "825" }, { "input": "100 4", "output": "133" }, { "input": "5 3", "output": "7" }, { "input": "6 4", "output": "7" }, { "input": "26 8", "output": "29" }, { "input": "9 4", "output": "11" }, { "input": "20 3", "output": "29" }, { "input": "17 3", "output": "25" } ]

1,642,831,690

2,147,483,647

Python 3

OK

TESTS

32

46

0

m,n=map(int,input().split()) c=m d=0 while (m>=n): b=m//n c=c+b d=m%n m=b+d print(c)

Title: New Year Candles Time Limit: None seconds Memory Limit: None megabytes Problem Description: Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles. Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used like any other new candle. Now Vasily wonders: for how many hours can his candles light up the room if he acts optimally well? Help him find this number. Input Specification: The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). Output Specification: Print a single integer — the number of hours Vasily can light up the room for. Demo Input: ['4 2\n', '6 3\n'] Demo Output: ['7\n', '8\n'] Note: Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours.

```python m,n=map(int,input().split()) c=m d=0 while (m>=n): b=m//n c=c+b d=m%n m=b+d print(c) ```

3

285

B

Find Marble

PROGRAMMING

1,200

[ "implementation" ]

null

Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not. First Petya puts a marble under the glass in position *s*. Then he performs some (possibly zero) shuffling operations. One shuffling operation means moving the glass from the first position to position *p*1, the glass from the second position to position *p*2 and so on. That is, a glass goes from position *i* to position *p**i*. Consider all glasses are moving simultaneously during one shuffling operation. When the glasses are shuffled, the marble doesn't travel from one glass to another: it moves together with the glass it was initially been put in. After all shuffling operations Petya shows Vasya that the ball has moved to position *t*. Vasya's task is to say what minimum number of shuffling operations Petya has performed or determine that Petya has made a mistake and the marble could not have got from position *s* to position *t*.

The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaranteed that all *p**i*'s are distinct. Note that *s* can equal *t*.

If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1.

[ "4 2 1\n2 3 4 1\n", "4 3 3\n4 1 3 2\n", "4 3 4\n1 2 3 4\n", "3 1 3\n2 1 3\n" ]

[ "3\n", "0\n", "-1\n", "-1\n" ]

none

1,000

[ { "input": "4 2 1\n2 3 4 1", "output": "3" }, { "input": "4 3 3\n4 1 3 2", "output": "0" }, { "input": "4 3 4\n1 2 3 4", "output": "-1" }, { "input": "3 1 3\n2 1 3", "output": "-1" }, { "input": "1 1 1\n1", "output": "0" }, { "input": "10 6 7\n10 7 8 1 5 6 2 9 4 3", "output": "-1" }, { "input": "10 3 6\n5 6 7 3 8 4 2 1 10 9", "output": "3" }, { "input": "10 10 4\n4 2 6 9 5 3 8 1 10 7", "output": "4" }, { "input": "100 90 57\n19 55 91 50 31 23 60 84 38 1 22 51 27 76 28 98 11 44 61 63 15 93 52 3 66 16 53 36 18 62 35 85 78 37 73 64 87 74 46 26 82 69 49 33 83 89 56 67 71 25 39 94 96 17 21 6 47 68 34 42 57 81 13 10 54 2 48 80 20 77 4 5 59 30 90 95 45 75 8 88 24 41 40 14 97 32 7 9 65 70 100 99 72 58 92 29 79 12 86 43", "output": "-1" }, { "input": "100 11 20\n80 25 49 55 22 98 35 59 88 14 91 20 68 66 53 50 77 45 82 63 96 93 85 46 37 74 84 9 7 95 41 86 23 36 33 27 81 39 18 13 12 92 24 71 3 48 83 61 31 87 28 79 75 38 11 21 29 69 44 100 72 62 32 43 30 16 47 56 89 60 42 17 26 70 94 99 4 6 2 73 8 52 65 1 15 90 67 51 78 10 5 76 57 54 34 58 19 64 40 97", "output": "26" }, { "input": "100 84 83\n30 67 53 89 94 54 92 17 26 57 15 5 74 85 10 61 18 70 91 75 14 11 93 41 25 78 88 81 20 51 35 4 62 1 97 39 68 52 47 77 64 3 2 72 60 80 8 83 65 98 21 22 45 7 58 31 43 38 90 99 49 87 55 36 29 6 37 23 66 76 59 79 40 86 63 44 82 32 48 16 50 100 28 96 46 12 27 13 24 9 19 84 73 69 71 42 56 33 34 95", "output": "71" }, { "input": "100 6 93\n74 62 67 81 40 85 35 42 59 72 80 28 79 41 16 19 33 63 13 10 69 76 70 93 49 84 89 94 8 37 11 90 26 52 47 7 36 95 86 75 56 15 61 99 88 12 83 21 20 3 100 17 32 82 6 5 43 25 66 68 73 78 18 77 92 27 23 2 4 39 60 48 22 24 14 97 29 34 54 64 71 57 87 38 9 50 30 53 51 45 44 31 58 91 98 65 55 1 46 96", "output": "-1" }, { "input": "100 27 56\n58 18 50 41 33 37 14 87 77 73 61 53 15 8 70 68 45 96 54 78 39 67 51 60 80 12 93 99 20 92 17 79 4 13 62 91 69 29 49 36 98 34 90 35 84 64 38 83 28 89 97 94 9 16 26 48 10 57 23 75 27 88 44 21 72 76 30 43 32 2 71 24 100 1 31 81 42 40 47 55 86 85 66 5 52 22 95 74 11 19 7 82 6 25 56 63 65 59 46 3", "output": "20" }, { "input": "87 42 49\n45 55 24 44 56 72 74 23 4 7 37 67 22 6 58 76 40 36 3 20 26 87 64 75 49 70 62 42 31 1 80 33 25 59 78 27 32 2 41 61 66 28 19 85 15 69 52 77 50 14 16 34 18 43 73 83 11 39 29 9 35 13 81 54 79 21 60 46 71 57 12 17 5 47 38 30 10 84 53 63 68 8 51 65 48 86 82", "output": "-1" }, { "input": "2 1 2\n1 2", "output": "-1" }, { "input": "2 1 2\n2 1", "output": "1" }, { "input": "2 2 2\n1 2", "output": "0" }, { "input": "2 2 2\n2 1", "output": "0" }, { "input": "2 1 1\n2 1", "output": "0" } ]

1,615,611,066

2,147,483,647

Python 3

OK

TESTS

33

248

6,963,200

n,s,f=map(int,input().split()) s,f=s-1,f-1 arr = [int(i)-1 for i in input().split()] if s==f: print(0) else: cnt = 0 temp = arr[s] while cnt<n+3: cnt+=1 if temp==f: break else: temp = arr[temp] if cnt>n: print(-1) else: print(cnt)

Title: Find Marble Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not. First Petya puts a marble under the glass in position *s*. Then he performs some (possibly zero) shuffling operations. One shuffling operation means moving the glass from the first position to position *p*1, the glass from the second position to position *p*2 and so on. That is, a glass goes from position *i* to position *p**i*. Consider all glasses are moving simultaneously during one shuffling operation. When the glasses are shuffled, the marble doesn't travel from one glass to another: it moves together with the glass it was initially been put in. After all shuffling operations Petya shows Vasya that the ball has moved to position *t*. Vasya's task is to say what minimum number of shuffling operations Petya has performed or determine that Petya has made a mistake and the marble could not have got from position *s* to position *t*. Input Specification: The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaranteed that all *p**i*'s are distinct. Note that *s* can equal *t*. Output Specification: If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. Demo Input: ['4 2 1\n2 3 4 1\n', '4 3 3\n4 1 3 2\n', '4 3 4\n1 2 3 4\n', '3 1 3\n2 1 3\n'] Demo Output: ['3\n', '0\n', '-1\n', '-1\n'] Note: none

```python n,s,f=map(int,input().split()) s,f=s-1,f-1 arr = [int(i)-1 for i in input().split()] if s==f: print(0) else: cnt = 0 temp = arr[s] while cnt<n+3: cnt+=1 if temp==f: break else: temp = arr[temp] if cnt>n: print(-1) else: print(cnt) ```

3

545

D

Queue

PROGRAMMING

1,300

[ "greedy", "implementation", "sortings" ]

null

Little girl Susie went shopping with her mom and she wondered how to improve service quality. There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total time when all the people who stand in the queue in front of him are served. Susie thought that if we swap some people in the queue, then we can decrease the number of people who are disappointed. Help Susie find out what is the maximum number of not disappointed people can be achieved by swapping people in the queue.

The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces.

Print a single number — the maximum number of not disappointed people in the queue.

[ "5\n15 2 1 5 3\n" ]

[ "4\n" ]

Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5.

1,750

[ { "input": "5\n15 2 1 5 3", "output": "4" }, { "input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "2" }, { "input": "10\n13 2 5 55 21 34 1 8 1 3", "output": "6" }, { "input": "10\n8 256 16 1 2 1 64 4 128 32", "output": "10" }, { "input": "10\n10000 40000 10000 50000 20000 100000 10000 100 30000 500", "output": "6" }, { "input": "1\n1000000000", "output": "1" }, { "input": "15\n9 11 45 86 52 65 35 3 93 7 21 45 15 11 39", "output": "6" }, { "input": "20\n16839799 17525904 91276752 42650694 60106463 12243176 54892123 25142243 16015971 41250998 11150057 6994983 67700784 16562412 82163675 46178521 33914268 91966607 93976858 84100064", "output": "5" }, { "input": "26\n1000 4110030 64221 131521030 942374833 1003 2055015 32110 513757 16440130 263042057 32880256 128439 557559573 16051 8220066 469240078 65760513 256878 790176315 4012 2005 1027508 928528684 8030 805074697", "output": "21" } ]

1,698,136,588

2,147,483,647

Python 3

OK

TESTS

61

124

13,619,200

n=int(input()) time=list(map(int,input().split())) time.sort() fin_line=[] for i in range(n): if time[i]>=sum(fin_line): fin_line.append(time[i]) print(len(fin_line))

Title: Queue Time Limit: None seconds Memory Limit: None megabytes Problem Description: Little girl Susie went shopping with her mom and she wondered how to improve service quality. There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total time when all the people who stand in the queue in front of him are served. Susie thought that if we swap some people in the queue, then we can decrease the number of people who are disappointed. Help Susie find out what is the maximum number of not disappointed people can be achieved by swapping people in the queue. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. Output Specification: Print a single number — the maximum number of not disappointed people in the queue. Demo Input: ['5\n15 2 1 5 3\n'] Demo Output: ['4\n'] Note: Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5.

```python n=int(input()) time=list(map(int,input().split())) time.sort() fin_line=[] for i in range(n): if time[i]>=sum(fin_line): fin_line.append(time[i]) print(len(fin_line)) ```

3

1

A

Theatre Square

PROGRAMMING

1,000

[ "math" ]

A. Theatre Square

1

256

Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*. What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.

The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).

Write the needed number of flagstones.

[ "6 6 4\n" ]

[ "4\n" ]

none

0

[ { "input": "6 6 4", "output": "4" }, { "input": "1 1 1", "output": "1" }, { "input": "2 1 1", "output": "2" }, { "input": "1 2 1", "output": "2" }, { "input": "2 2 1", "output": "4" }, { "input": "2 1 2", "output": "1" }, { "input": "1 1 3", "output": "1" }, { "input": "2 3 4", "output": "1" }, { "input": "1000000000 1000000000 1", "output": "1000000000000000000" }, { "input": "12 13 4", "output": "12" }, { "input": "222 332 5", "output": "3015" }, { "input": "1000 1000 10", "output": "10000" }, { "input": "1001 1000 10", "output": "10100" }, { "input": "100 10001 1000000000", "output": "1" }, { "input": "1000000000 1000000000 1000000000", "output": "1" }, { "input": "1000000000 1000000000 999999999", "output": "4" }, { "input": "1000000000 1000000000 192", "output": "27126743055556" }, { "input": "1000000000 987654321 1", "output": "987654321000000000" }, { "input": "456784567 1000000000 51", "output": "175618850864484" }, { "input": "39916800 134217728 40320", "output": "3295710" } ]

1,687,096,158

2,147,483,647

PyPy 3-64

OK

TESTS

20

46

0

n, m , a = map(int, input().split(" ")) if n%a == 0: width = n//a elif n%a != 0: width = n//a + 1 if m%a == 0: length = m//a elif m%a != 0: length = m//a + 1 print(length*width)

Title: Theatre Square Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*. What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. Input Specification: The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). Output Specification: Write the needed number of flagstones. Demo Input: ['6 6 4\n'] Demo Output: ['4\n'] Note: none

```python n, m , a = map(int, input().split(" ")) if n%a == 0: width = n//a elif n%a != 0: width = n//a + 1 if m%a == 0: length = m//a elif m%a != 0: length = m//a + 1 print(length*width) ```

3.977

645

B

Mischievous Mess Makers

PROGRAMMING

1,200

[ "greedy", "math" ]

null

It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However, Elsie, after realizing that she will forever live in the shadows beyond Bessie's limelight, has formed the Mischievous Mess Makers and is plotting to disrupt this beautiful pastoral rhythm. While Farmer John takes his *k* minute long nap, Elsie and the Mess Makers plan to repeatedly choose two distinct stalls and swap the cows occupying those stalls, making no more than one swap each minute. Being the meticulous pranksters that they are, the Mischievous Mess Makers would like to know the maximum messiness attainable in the *k* minutes that they have. We denote as *p**i* the label of the cow in the *i*-th stall. The messiness of an arrangement of cows is defined as the number of pairs (*i*,<=*j*) such that *i*<=<<=*j* and *p**i*<=><=*p**j*.

The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the number of cows and the length of Farmer John's nap, respectively.

Output a single integer, the maximum messiness that the Mischievous Mess Makers can achieve by performing no more than *k* swaps.

[ "5 2\n", "1 10\n" ]

[ "10\n", "0\n" ]

In the first sample, the Mischievous Mess Makers can swap the cows in the stalls 1 and 5 during the first minute, then the cows in stalls 2 and 4 during the second minute. This reverses the arrangement of cows, giving us a total messiness of 10. In the second sample, there is only one cow, so the maximum possible messiness is 0.

1,000

[ { "input": "5 2", "output": "10" }, { "input": "1 10", "output": "0" }, { "input": "100000 2", "output": "399990" }, { "input": "1 1", "output": "0" }, { "input": "8 3", "output": "27" }, { "input": "7 1", "output": "11" }, { "input": "100000 40000", "output": "4799960000" }, { "input": "1 1000", "output": "0" }, { "input": "100 45", "output": "4905" }, { "input": "9 2", "output": "26" }, { "input": "456 78", "output": "58890" }, { "input": "100000 50000", "output": "4999950000" }, { "input": "100000 50001", "output": "4999950000" }, { "input": "100000 50002", "output": "4999950000" }, { "input": "100000 50003", "output": "4999950000" }, { "input": "100000 49998", "output": "4999949994" }, { "input": "100000 49997", "output": "4999949985" }, { "input": "99999 49998", "output": "4999849998" }, { "input": "99999 49997", "output": "4999849991" }, { "input": "99999 49996", "output": "4999849980" }, { "input": "99999 50000", "output": "4999850001" }, { "input": "99999 50001", "output": "4999850001" }, { "input": "99999 50002", "output": "4999850001" }, { "input": "30062 9", "output": "540945" }, { "input": "13486 3", "output": "80895" }, { "input": "29614 7", "output": "414491" }, { "input": "13038 8", "output": "208472" }, { "input": "96462 6", "output": "1157466" }, { "input": "22599 93799", "output": "255346101" }, { "input": "421 36817", "output": "88410" }, { "input": "72859 65869", "output": "2654180511" }, { "input": "37916 5241", "output": "342494109" }, { "input": "47066 12852", "output": "879423804" }, { "input": "84032 21951", "output": "2725458111" }, { "input": "70454 75240", "output": "2481847831" }, { "input": "86946 63967", "output": "3779759985" }, { "input": "71128 11076", "output": "1330260828" }, { "input": "46111 64940", "output": "1063089105" }, { "input": "46111 64940", "output": "1063089105" }, { "input": "56500 84184", "output": "1596096750" }, { "input": "60108 83701", "output": "1806455778" }, { "input": "1 2", "output": "0" }, { "input": "1 3", "output": "0" }, { "input": "1 4", "output": "0" }, { "input": "1 5", "output": "0" }, { "input": "1 6", "output": "0" }, { "input": "2 1", "output": "1" }, { "input": "2 2", "output": "1" }, { "input": "2 3", "output": "1" }, { "input": "2 4", "output": "1" }, { "input": "2 5", "output": "1" }, { "input": "3 1", "output": "3" }, { "input": "3 2", "output": "3" }, { "input": "3 3", "output": "3" }, { "input": "3 4", "output": "3" }, { "input": "3 5", "output": "3" }, { "input": "4 1", "output": "5" }, { "input": "4 2", "output": "6" }, { "input": "4 3", "output": "6" }, { "input": "4 4", "output": "6" }, { "input": "4 5", "output": "6" }, { "input": "5 1", "output": "7" }, { "input": "5 3", "output": "10" }, { "input": "5 4", "output": "10" }, { "input": "5 5", "output": "10" }, { "input": "6 1", "output": "9" }, { "input": "6 2", "output": "14" }, { "input": "6 3", "output": "15" }, { "input": "7 2", "output": "18" }, { "input": "7 3", "output": "21" }, { "input": "7 4", "output": "21" }, { "input": "10 2", "output": "30" }, { "input": "60982 2", "output": "243918" }, { "input": "23426 23", "output": "1076515" }, { "input": "444 3", "output": "2643" }, { "input": "18187 433", "output": "15374531" }, { "input": "6895 3544", "output": "23767065" }, { "input": "56204 22352", "output": "1513297456" }, { "input": "41977 5207", "output": "382917573" }, { "input": "78147 2321", "output": "351981971" }, { "input": "99742 62198", "output": "4974183411" }, { "input": "72099 38339", "output": "2599096851" }, { "input": "82532 4838", "output": "751762306" }, { "input": "79410 33144", "output": "3066847464" }, { "input": "11021 3389", "output": "51726307" }, { "input": "66900 7572", "output": "898455660" }, { "input": "99999 49999", "output": "4999850001" }, { "input": "100000 49999", "output": "4999949999" }, { "input": "100000 100000", "output": "4999950000" }, { "input": "100000 1", "output": "199997" }, { "input": "4 100", "output": "6" }, { "input": "100000 1234", "output": "243753254" } ]

1,462,915,971

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

2

46

4,915,200

def main(): (n, k) = (int(x) for x in input().split()) print(solver(n, k)) def solver(n, k): if k >= n // 2: return n * (n - 1) // 2 else: return k * (n - 1) main()

Title: Mischievous Mess Makers Time Limit: None seconds Memory Limit: None megabytes Problem Description: It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However, Elsie, after realizing that she will forever live in the shadows beyond Bessie's limelight, has formed the Mischievous Mess Makers and is plotting to disrupt this beautiful pastoral rhythm. While Farmer John takes his *k* minute long nap, Elsie and the Mess Makers plan to repeatedly choose two distinct stalls and swap the cows occupying those stalls, making no more than one swap each minute. Being the meticulous pranksters that they are, the Mischievous Mess Makers would like to know the maximum messiness attainable in the *k* minutes that they have. We denote as *p**i* the label of the cow in the *i*-th stall. The messiness of an arrangement of cows is defined as the number of pairs (*i*,<=*j*) such that *i*<=<<=*j* and *p**i*<=><=*p**j*. Input Specification: The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the number of cows and the length of Farmer John's nap, respectively. Output Specification: Output a single integer, the maximum messiness that the Mischievous Mess Makers can achieve by performing no more than *k* swaps. Demo Input: ['5 2\n', '1 10\n'] Demo Output: ['10\n', '0\n'] Note: In the first sample, the Mischievous Mess Makers can swap the cows in the stalls 1 and 5 during the first minute, then the cows in stalls 2 and 4 during the second minute. This reverses the arrangement of cows, giving us a total messiness of 10. In the second sample, there is only one cow, so the maximum possible messiness is 0.

```python def main(): (n, k) = (int(x) for x in input().split()) print(solver(n, k)) def solver(n, k): if k >= n // 2: return n * (n - 1) // 2 else: return k * (n - 1) main() ```

0

405

A

Gravity Flip

PROGRAMMING

900

[ "greedy", "implementation", "sortings" ]

null

Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity. There are *n* columns of toy cubes in the box arranged in a line. The *i*-th column contains *a**i* cubes. At first, the gravity in the box is pulling the cubes downwards. When Chris switches the gravity, it begins to pull all the cubes to the right side of the box. The figure shows the initial and final configurations of the cubes in the box: the cubes that have changed their position are highlighted with orange. Given the initial configuration of the toy cubes in the box, find the amounts of cubes in each of the *n* columns after the gravity switch!

The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=100), the number of the columns in the box. The next line contains *n* space-separated integer numbers. The *i*-th number *a**i* (1<=≤<=*a**i*<=≤<=100) denotes the number of cubes in the *i*-th column.

Output *n* integer numbers separated by spaces, where the *i*-th number is the amount of cubes in the *i*-th column after the gravity switch.

[ "4\n3 2 1 2\n", "3\n2 3 8\n" ]

[ "1 2 2 3 \n", "2 3 8 \n" ]

The first example case is shown on the figure. The top cube of the first column falls to the top of the last column; the top cube of the second column falls to the top of the third column; the middle cube of the first column falls to the top of the second column. In the second example case the gravity switch does not change the heights of the columns.

500

[ { "input": "4\n3 2 1 2", "output": "1 2 2 3 " }, { "input": "3\n2 3 8", "output": "2 3 8 " }, { "input": "5\n2 1 2 1 2", "output": "1 1 2 2 2 " }, { "input": "1\n1", "output": "1 " }, { "input": "2\n4 3", "output": "3 4 " }, { "input": "6\n100 40 60 20 1 80", "output": "1 20 40 60 80 100 " }, { "input": "10\n10 8 6 7 5 3 4 2 9 1", "output": "1 2 3 4 5 6 7 8 9 10 " }, { "input": "10\n1 2 3 4 5 6 7 8 9 10", "output": "1 2 3 4 5 6 7 8 9 10 " }, { "input": "100\n82 51 81 14 37 17 78 92 64 15 8 86 89 8 87 77 66 10 15 12 100 25 92 47 21 78 20 63 13 49 41 36 41 79 16 87 87 69 3 76 80 60 100 49 70 59 72 8 38 71 45 97 71 14 76 54 81 4 59 46 39 29 92 3 49 22 53 99 59 52 74 31 92 43 42 23 44 9 82 47 7 40 12 9 3 55 37 85 46 22 84 52 98 41 21 77 63 17 62 91", "output": "3 3 3 4 7 8 8 8 9 9 10 12 12 13 14 14 15 15 16 17 17 20 21 21 22 22 23 25 29 31 36 37 37 38 39 40 41 41 41 42 43 44 45 46 46 47 47 49 49 49 51 52 52 53 54 55 59 59 59 60 62 63 63 64 66 69 70 71 71 72 74 76 76 77 77 78 78 79 80 81 81 82 82 84 85 86 87 87 87 89 91 92 92 92 92 97 98 99 100 100 " }, { "input": "100\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100", "output": "100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 " }, { "input": "10\n1 9 7 6 2 4 7 8 1 3", "output": "1 1 2 3 4 6 7 7 8 9 " }, { "input": "20\n53 32 64 20 41 97 50 20 66 68 22 60 74 61 97 54 80 30 72 59", "output": "20 20 22 30 32 41 50 53 54 59 60 61 64 66 68 72 74 80 97 97 " }, { "input": "30\n7 17 4 18 16 12 14 10 1 13 2 16 13 17 8 16 13 14 9 17 17 5 13 5 1 7 6 20 18 12", "output": "1 1 2 4 5 5 6 7 7 8 9 10 12 12 13 13 13 13 14 14 16 16 16 17 17 17 17 18 18 20 " }, { "input": "40\n22 58 68 58 48 53 52 1 16 78 75 17 63 15 36 32 78 75 49 14 42 46 66 54 49 82 40 43 46 55 12 73 5 45 61 60 1 11 31 84", "output": "1 1 5 11 12 14 15 16 17 22 31 32 36 40 42 43 45 46 46 48 49 49 52 53 54 55 58 58 60 61 63 66 68 73 75 75 78 78 82 84 " }, { "input": "70\n1 3 3 1 3 3 1 1 1 3 3 2 3 3 1 1 1 2 3 1 3 2 3 3 3 2 2 3 1 3 3 2 1 1 2 1 2 1 2 2 1 1 1 3 3 2 3 2 3 2 3 3 2 2 2 3 2 3 3 3 1 1 3 3 1 1 1 1 3 1", "output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 " }, { "input": "90\n17 75 51 30 100 5 50 95 51 73 66 5 7 76 43 49 23 55 3 24 95 79 10 11 44 93 17 99 53 66 82 66 63 76 19 4 51 71 75 43 27 5 24 19 48 7 91 15 55 21 7 6 27 10 2 91 64 58 18 21 16 71 90 88 21 20 6 6 95 85 11 7 40 65 52 49 92 98 46 88 17 48 85 96 77 46 100 34 67 52", "output": "2 3 4 5 5 5 6 6 6 7 7 7 7 10 10 11 11 15 16 17 17 17 18 19 19 20 21 21 21 23 24 24 27 27 30 34 40 43 43 44 46 46 48 48 49 49 50 51 51 51 52 52 53 55 55 58 63 64 65 66 66 66 67 71 71 73 75 75 76 76 77 79 82 85 85 88 88 90 91 91 92 93 95 95 95 96 98 99 100 100 " }, { "input": "100\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 " }, { "input": "100\n1 1 1 1 2 1 1 1 1 1 2 2 1 1 2 1 2 1 1 1 2 1 1 2 1 2 1 1 2 2 2 1 1 2 1 1 1 2 2 2 1 1 1 2 1 2 2 1 2 1 1 2 2 1 2 1 2 1 2 2 1 1 1 2 1 1 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 2 1 1 1 1 2 2 2 2 2 2 2 1 1 1 2 1 2 1", "output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 " }, { "input": "100\n2 1 1 1 3 2 3 3 2 3 3 1 3 3 1 3 3 1 1 1 2 3 1 2 3 1 2 3 3 1 3 1 1 2 3 2 3 3 2 3 3 1 2 2 1 2 3 2 3 2 2 1 1 3 1 3 2 1 3 1 3 1 3 1 1 3 3 3 2 3 2 2 2 2 1 3 3 3 1 2 1 2 3 2 1 3 1 3 2 1 3 1 2 1 2 3 1 3 2 3", "output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 " }, { "input": "100\n7 4 5 5 10 10 5 8 5 7 4 5 4 6 8 8 2 6 3 3 10 7 10 8 6 2 7 3 9 7 7 2 4 5 2 4 9 5 10 1 10 5 10 4 1 3 4 2 6 9 9 9 10 6 2 5 6 1 8 10 4 10 3 4 10 5 5 4 10 4 5 3 7 10 2 7 3 6 9 6 1 6 5 5 4 6 6 4 4 1 5 1 6 6 6 8 8 6 2 6", "output": "1 1 1 1 1 1 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 7 7 7 7 7 7 7 7 8 8 8 8 8 8 8 9 9 9 9 9 9 10 10 10 10 10 10 10 10 10 10 10 10 10 " }, { "input": "100\n12 10 5 11 13 12 14 13 7 15 15 12 13 19 12 18 14 10 10 3 1 10 16 11 19 8 10 15 5 10 12 16 11 13 11 15 14 12 16 8 11 8 15 2 18 2 14 13 15 20 8 8 4 12 14 7 10 3 9 1 7 19 6 7 2 14 8 20 7 17 18 20 3 18 18 9 6 10 4 1 4 19 9 13 3 3 12 11 11 20 8 2 13 6 7 12 1 4 17 3", "output": "1 1 1 1 2 2 2 2 3 3 3 3 3 3 4 4 4 4 5 5 6 6 6 7 7 7 7 7 7 8 8 8 8 8 8 8 9 9 9 10 10 10 10 10 10 10 10 11 11 11 11 11 11 11 12 12 12 12 12 12 12 12 12 13 13 13 13 13 13 13 14 14 14 14 14 14 15 15 15 15 15 15 16 16 16 17 17 18 18 18 18 18 19 19 19 19 20 20 20 20 " }, { "input": "100\n5 13 1 40 30 10 23 32 33 12 6 4 15 29 31 17 23 5 36 31 32 38 24 11 34 39 19 21 6 19 31 35 1 15 6 29 22 15 17 15 1 17 2 34 20 8 27 2 29 26 13 9 22 27 27 3 20 40 4 40 33 29 36 30 35 16 19 28 26 11 36 24 29 5 40 10 38 34 33 23 34 39 31 7 10 31 22 6 36 24 14 31 34 23 2 4 26 16 2 32", "output": "1 1 1 2 2 2 2 3 4 4 4 5 5 5 6 6 6 6 7 8 9 10 10 10 11 11 12 13 13 14 15 15 15 15 16 16 17 17 17 19 19 19 20 20 21 22 22 22 23 23 23 23 24 24 24 26 26 26 27 27 27 28 29 29 29 29 29 30 30 31 31 31 31 31 31 32 32 32 33 33 33 34 34 34 34 34 35 35 36 36 36 36 38 38 39 39 40 40 40 40 " }, { "input": "100\n72 44 34 74 9 60 26 37 55 77 74 69 28 66 54 55 8 36 57 31 31 48 32 66 40 70 77 43 64 28 37 10 21 58 51 32 60 28 51 52 28 35 7 33 1 68 38 70 57 71 8 20 42 57 59 4 58 10 17 47 22 48 16 3 76 67 32 37 64 47 33 41 75 69 2 76 39 9 27 75 20 21 52 25 71 21 11 29 38 10 3 1 45 55 63 36 27 7 59 41", "output": "1 1 2 3 3 4 7 7 8 8 9 9 10 10 10 11 16 17 20 20 21 21 21 22 25 26 27 27 28 28 28 28 29 31 31 32 32 32 33 33 34 35 36 36 37 37 37 38 38 39 40 41 41 42 43 44 45 47 47 48 48 51 51 52 52 54 55 55 55 57 57 57 58 58 59 59 60 60 63 64 64 66 66 67 68 69 69 70 70 71 71 72 74 74 75 75 76 76 77 77 " }, { "input": "100\n75 18 61 10 56 53 42 57 79 80 31 2 50 45 54 99 84 52 71 21 86 3 19 98 14 37 40 62 63 68 5 10 87 8 81 85 52 52 57 94 2 7 56 96 19 76 1 13 81 6 80 47 22 59 99 32 9 5 36 88 98 91 70 70 12 93 12 22 85 1 97 48 94 16 84 84 51 34 62 7 68 51 30 2 37 82 4 7 27 1 80 9 61 16 59 55 12 96 94 82", "output": "1 1 1 2 2 2 3 4 5 5 6 7 7 7 8 9 9 10 10 12 12 12 13 14 16 16 18 19 19 21 22 22 27 30 31 32 34 36 37 37 40 42 45 47 48 50 51 51 52 52 52 53 54 55 56 56 57 57 59 59 61 61 62 62 63 68 68 70 70 71 75 76 79 80 80 80 81 81 82 82 84 84 84 85 85 86 87 88 91 93 94 94 94 96 96 97 98 98 99 99 " }, { "input": "100\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100", "output": "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 " }, { "input": "100\n100 99 98 97 96 95 94 93 92 91 90 89 88 87 86 85 84 83 82 81 80 79 78 77 76 75 74 73 72 71 70 69 68 67 66 65 64 63 62 61 60 59 58 57 56 55 54 53 52 51 50 49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1", "output": "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 " }, { "input": "100\n50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50", "output": "50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 " }, { "input": "49\n1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97", "output": "1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 " }, { "input": "30\n1 4 7 10 13 16 19 22 25 28 31 34 37 40 43 46 49 52 55 58 61 64 67 70 73 76 79 82 85 88", "output": "1 4 7 10 13 16 19 22 25 28 31 34 37 40 43 46 49 52 55 58 61 64 67 70 73 76 79 82 85 88 " }, { "input": "100\n100 51 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 51 100 " }, { "input": "10\n100 90 80 70 60 50 40 30 20 10", "output": "10 20 30 40 50 60 70 80 90 100 " }, { "input": "1\n10", "output": "10 " } ]

1,691,259,329

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

5

31

0

n1 = int(input()) n2 = input().split(" ") n2.sort() for num in n2: print(num,end=" ")

Title: Gravity Flip Time Limit: None seconds Memory Limit: None megabytes Problem Description: Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity. There are *n* columns of toy cubes in the box arranged in a line. The *i*-th column contains *a**i* cubes. At first, the gravity in the box is pulling the cubes downwards. When Chris switches the gravity, it begins to pull all the cubes to the right side of the box. The figure shows the initial and final configurations of the cubes in the box: the cubes that have changed their position are highlighted with orange. Given the initial configuration of the toy cubes in the box, find the amounts of cubes in each of the *n* columns after the gravity switch! Input Specification: The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=100), the number of the columns in the box. The next line contains *n* space-separated integer numbers. The *i*-th number *a**i* (1<=≤<=*a**i*<=≤<=100) denotes the number of cubes in the *i*-th column. Output Specification: Output *n* integer numbers separated by spaces, where the *i*-th number is the amount of cubes in the *i*-th column after the gravity switch. Demo Input: ['4\n3 2 1 2\n', '3\n2 3 8\n'] Demo Output: ['1 2 2 3 \n', '2 3 8 \n'] Note: The first example case is shown on the figure. The top cube of the first column falls to the top of the last column; the top cube of the second column falls to the top of the third column; the middle cube of the first column falls to the top of the second column. In the second example case the gravity switch does not change the heights of the columns.

```python n1 = int(input()) n2 = input().split(" ") n2.sort() for num in n2: print(num,end=" ") ```

0

381

A

Sereja and Dima

PROGRAMMING

800

[ "greedy", "implementation", "two pointers" ]

null

Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins. Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move. Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.

The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.

On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.

[ "4\n4 1 2 10\n", "7\n1 2 3 4 5 6 7\n" ]

[ "12 5\n", "16 12\n" ]

In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5.

500

[ { "input": "4\n4 1 2 10", "output": "12 5" }, { "input": "7\n1 2 3 4 5 6 7", "output": "16 12" }, { "input": "42\n15 29 37 22 16 5 26 31 6 32 19 3 45 36 33 14 25 20 48 7 42 11 24 28 9 18 8 21 47 17 38 40 44 4 35 1 43 39 41 27 12 13", "output": "613 418" }, { "input": "43\n32 1 15 48 38 26 25 14 20 44 11 30 3 42 49 19 18 46 5 45 10 23 34 9 29 41 2 52 6 17 35 4 50 22 33 51 7 28 47 13 39 37 24", "output": "644 500" }, { "input": "1\n3", "output": "3 0" }, { "input": "45\n553 40 94 225 415 471 126 190 647 394 515 303 189 159 308 6 139 132 326 78 455 75 85 295 135 613 360 614 351 228 578 259 258 591 444 29 33 463 561 174 368 183 140 168 646", "output": "6848 6568" }, { "input": "44\n849 373 112 307 479 608 856 769 526 82 168 143 573 762 115 501 688 36 214 450 396 496 236 309 287 786 397 43 811 141 745 846 350 270 276 677 420 459 403 722 267 54 394 727", "output": "9562 9561" }, { "input": "35\n10 15 18 1 28 16 2 33 6 22 23 4 9 25 35 8 7 26 3 20 30 14 31 19 27 32 11 5 29 24 21 34 13 17 12", "output": "315 315" }, { "input": "17\n580 376 191 496 73 44 520 357 483 149 81 178 514 300 216 598 304", "output": "3238 2222" }, { "input": "30\n334 443 223 424 168 549 189 303 429 559 516 220 459 134 344 346 316 446 209 148 487 526 69 286 102 366 518 280 392 325", "output": "5246 4864" }, { "input": "95\n122 29 188 265 292 287 183 225 222 187 155 256 64 148 173 278 218 136 290 17 31 130 2 87 57 283 255 280 68 166 174 142 102 39 116 206 288 154 26 78 296 172 184 232 77 91 277 8 249 186 94 93 207 251 257 195 101 299 193 124 293 65 58 35 24 302 220 189 252 125 27 284 247 182 141 103 198 97 234 83 281 216 85 180 267 236 109 143 149 239 79 300 191 244 71", "output": "8147 7807" }, { "input": "1\n1", "output": "1 0" } ]

1,699,474,869

2,147,483,647

Python 3

OK

TESTS

34

46

0

n = int(input()) cs = [int(i) for i in input().split(' ')] u=True s=[] d=[] t=1 while u: if t%2==1: s.append(cs[(-1 if cs[-1]>cs[0] else 0)]) else: d.append(cs[(-1 if cs[-1]>cs[0] else 0)]) cs.pop((-1 if cs[-1]>cs[0] else 0)) t+=1 if len(cs) == 0: u = False print(sum(s),sum(d))

Title: Sereja and Dima Time Limit: None seconds Memory Limit: None megabytes Problem Description: Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins. Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move. Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000. Output Specification: On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game. Demo Input: ['4\n4 1 2 10\n', '7\n1 2 3 4 5 6 7\n'] Demo Output: ['12 5\n', '16 12\n'] Note: In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5.

```python n = int(input()) cs = [int(i) for i in input().split(' ')] u=True s=[] d=[] t=1 while u: if t%2==1: s.append(cs[(-1 if cs[-1]>cs[0] else 0)]) else: d.append(cs[(-1 if cs[-1]>cs[0] else 0)]) cs.pop((-1 if cs[-1]>cs[0] else 0)) t+=1 if len(cs) == 0: u = False print(sum(s),sum(d)) ```

3

61

A

Ultra-Fast Mathematician

PROGRAMMING

800

[ "implementation" ]

A. Ultra-Fast Mathematician

2

256

Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second. One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part. In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0. Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length. Now you are going to take part in Shapur's contest. See if you are faster and more accurate.

There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100.

Write one line — the corresponding answer. Do not omit the leading 0s.

[ "1010100\n0100101\n", "000\n111\n", "1110\n1010\n", "01110\n01100\n" ]

[ "1110001\n", "111\n", "0100\n", "00010\n" ]

none

500

[ { "input": "1010100\n0100101", "output": "1110001" }, { "input": "000\n111", "output": "111" }, { "input": "1110\n1010", "output": "0100" }, { "input": "01110\n01100", "output": "00010" }, { "input": "011101\n000001", "output": "011100" }, { "input": "10\n01", "output": "11" }, { "input": "00111111\n11011101", "output": "11100010" }, { "input": "011001100\n101001010", "output": "110000110" }, { "input": "1100100001\n0110101100", "output": "1010001101" }, { "input": "00011101010\n10010100101", "output": "10001001111" }, { "input": "100000101101\n111010100011", "output": "011010001110" }, { "input": "1000001111010\n1101100110001", "output": "0101101001011" }, { "input": "01011111010111\n10001110111010", "output": "11010001101101" }, { "input": "110010000111100\n001100101011010", "output": "111110101100110" }, { "input": "0010010111110000\n0000000011010110", "output": "0010010100100110" }, { "input": "00111110111110000\n01111100001100000", "output": "01000010110010000" }, { "input": "101010101111010001\n001001111101111101", "output": "100011010010101100" }, { "input": "0110010101111100000\n0011000101000000110", "output": "0101010000111100110" }, { "input": "11110100011101010111\n00001000011011000000", "output": "11111100000110010111" }, { "input": "101010101111101101001\n111010010010000011111", "output": "010000111101101110110" }, { "input": "0000111111100011000010\n1110110110110000001010", "output": "1110001001010011001000" }, { "input": "10010010101000110111000\n00101110100110111000111", "output": "10111100001110001111111" }, { "input": "010010010010111100000111\n100100111111100011001110", "output": "110110101101011111001001" }, { "input": "0101110100100111011010010\n0101100011010111001010001", "output": "0000010111110000010000011" }, { "input": "10010010100011110111111011\n10000110101100000001000100", "output": "00010100001111110110111111" }, { "input": "000001111000000100001000000\n011100111101111001110110001", "output": "011101000101111101111110001" }, { "input": "0011110010001001011001011100\n0000101101000011101011001010", "output": "0011011111001010110010010110" }, { "input": "11111000000000010011001101111\n11101110011001010100010000000", "output": "00010110011001000111011101111" }, { "input": "011001110000110100001100101100\n001010000011110000001000101001", "output": "010011110011000100000100000101" }, { "input": "1011111010001100011010110101111\n1011001110010000000101100010101", "output": "0000110100011100011111010111010" }, { "input": "10111000100001000001010110000001\n10111000001100101011011001011000", "output": "00000000101101101010001111011001" }, { "input": "000001010000100001000000011011100\n111111111001010100100001100000111", "output": "111110101001110101100001111011011" }, { "input": "1101000000000010011011101100000110\n1110000001100010011010000011011110", "output": "0011000001100000000001101111011000" }, { "input": "01011011000010100001100100011110001\n01011010111000001010010100001110000", "output": "00000001111010101011110000010000001" }, { "input": "000011111000011001000110111100000100\n011011000110000111101011100111000111", "output": "011000111110011110101101011011000011" }, { "input": "1001000010101110001000000011111110010\n0010001011010111000011101001010110000", "output": "1011001001111001001011101010101000010" }, { "input": "00011101011001100101111111000000010101\n10010011011011001011111000000011101011", "output": "10001110000010101110000111000011111110" }, { "input": "111011100110001001101111110010111001010\n111111101101111001110010000101101000100", "output": "000100001011110000011101110111010001110" }, { "input": "1111001001101000001000000010010101001010\n0010111100111110001011000010111110111001", "output": "1101110101010110000011000000101011110011" }, { "input": "00100101111000000101011111110010100011010\n11101110001010010101001000111110101010100", "output": "11001011110010010000010111001100001001110" }, { "input": "101011001110110100101001000111010101101111\n100111100110101011010100111100111111010110", "output": "001100101000011111111101111011101010111001" }, { "input": "1111100001100101000111101001001010011100001\n1000110011000011110010001011001110001000001", "output": "0111010010100110110101100010000100010100000" }, { "input": "01100111011111010101000001101110000001110101\n10011001011111110000000101011001001101101100", "output": "11111110000000100101000100110111001100011001" }, { "input": "110010100111000100100101100000011100000011001\n011001111011100110000110111001110110100111011", "output": "101011011100100010100011011001101010100100010" }, { "input": "0001100111111011010110100100111000000111000110\n1100101011000000000001010010010111001100110001", "output": "1101001100111011010111110110101111001011110111" }, { "input": "00000101110110110001110010100001110100000100000\n10010000110011110001101000111111101010011010001", "output": "10010101000101000000011010011110011110011110001" }, { "input": "110000100101011100100011001111110011111110010001\n101011111001011100110110111101110011010110101100", "output": "011011011100000000010101110010000000101000111101" }, { "input": "0101111101011111010101011101000011101100000000111\n0000101010110110001110101011011110111001010100100", "output": "0101010111101001011011110110011101010101010100011" }, { "input": "11000100010101110011101000011111001010110111111100\n00001111000111001011111110000010101110111001000011", "output": "11001011010010111000010110011101100100001110111111" }, { "input": "101000001101111101101111111000001110110010101101010\n010011100111100001100000010001100101000000111011011", "output": "111011101010011100001111101001101011110010010110001" }, { "input": "0011111110010001010100010110111000110011001101010100\n0111000000100010101010000100101000000100101000111001", "output": "0100111110110011111110010010010000110111100101101101" }, { "input": "11101010000110000011011010000001111101000111011111100\n10110011110001010100010110010010101001010111100100100", "output": "01011001110111010111001100010011010100010000111011000" }, { "input": "011000100001000001101000010110100110011110100111111011\n111011001000001001110011001111011110111110110011011111", "output": "100011101001001000011011011001111000100000010100100100" }, { "input": "0111010110010100000110111011010110100000000111110110000\n1011100100010001101100000100111111101001110010000100110", "output": "1100110010000101101010111111101001001001110101110010110" }, { "input": "10101000100111000111010001011011011011110100110101100011\n11101111000000001100100011111000100100000110011001101110", "output": "01000111100111001011110010100011111111110010101100001101" }, { "input": "000000111001010001000000110001001011100010011101010011011\n110001101000010010000101000100001111101001100100001010010", "output": "110001010001000011000101110101000100001011111001011001001" }, { "input": "0101011100111010000111110010101101111111000000111100011100\n1011111110000010101110111001000011100000100111111111000111", "output": "1110100010111000101001001011101110011111100111000011011011" }, { "input": "11001000001100100111100111100100101011000101001111001001101\n10111110100010000011010100110100100011101001100000001110110", "output": "01110110101110100100110011010000001000101100101111000111011" }, { "input": "010111011011101000000110000110100110001110100001110110111011\n101011110011101011101101011111010100100001100111100100111011", "output": "111100101000000011101011011001110010101111000110010010000000" }, { "input": "1001011110110110000100011001010110000100011010010111010101110\n1101111100001000010111110011010101111010010100000001000010111", "output": "0100100010111110010011101010000011111110001110010110010111001" }, { "input": "10000010101111100111110101111000010100110111101101111111111010\n10110110101100101010011001011010100110111011101100011001100111", "output": "00110100000011001101101100100010110010001100000001100110011101" }, { "input": "011111010011111000001010101001101001000010100010111110010100001\n011111001011000011111001000001111001010110001010111101000010011", "output": "000000011000111011110011101000010000010100101000000011010110010" }, { "input": "1111000000110001011101000100100100001111011100001111001100011111\n1101100110000101100001100000001001011011111011010101000101001010", "output": "0010100110110100111100100100101101010100100111011010001001010101" }, { "input": "01100000101010010011001110100110110010000110010011011001100100011\n10110110010110111100100111000111000110010000000101101110000010111", "output": "11010110111100101111101001100001110100010110010110110111100110100" }, { "input": "001111111010000100001100001010011001111110011110010111110001100111\n110000101001011000100010101100100110000111100000001101001110010111", "output": "111111010011011100101110100110111111111001111110011010111111110000" }, { "input": "1011101011101101011110101101011101011000010011100101010101000100110\n0001000001001111010111100100111101100000000001110001000110000000110", "output": "1010101010100010001001001001100000111000010010010100010011000100000" }, { "input": "01000001011001010011011100010000100100110101111011011011110000001110\n01011110000110011011000000000011000111100001010000000011111001110000", "output": "00011111011111001000011100010011100011010100101011011000001001111110" }, { "input": "110101010100110101000001111110110100010010000100111110010100110011100\n111010010111111011100110101011001011001110110111110100000110110100111", "output": "001111000011001110100111010101111111011100110011001010010010000111011" }, { "input": "1001101011000001011111100110010010000011010001001111011100010100110001\n1111100111110101001111010001010000011001001001010110001111000000100101", "output": "0110001100110100010000110111000010011010011000011001010011010100010100" }, { "input": "00000111110010110001110110001010010101000111011001111111100110011110010\n00010111110100000100110101000010010001100001100011100000001100010100010", "output": "00010000000110110101000011001000000100100110111010011111101010001010000" }, { "input": "100101011100101101000011010001011001101110101110001100010001010111001110\n100001111100101011011111110000001111000111001011111110000010101110111001", "output": "000100100000000110011100100001010110101001100101110010010011111001110111" }, { "input": "1101100001000111001101001011101000111000011110000001001101101001111011010\n0101011101010100011011010110101000010010110010011110101100000110110001000", "output": "1000111100010011010110011101000000101010101100011111100001101111001010010" }, { "input": "01101101010011110101100001110101111011100010000010001101111000011110111111\n00101111001101001100111010000101110000100101101111100111101110010100011011", "output": "01000010011110111001011011110000001011000111101101101010010110001010100100" }, { "input": "101100101100011001101111110110110010100110110010100001110010110011001101011\n000001011010101011110011111101001110000111000010001101000010010000010001101", "output": "101101110110110010011100001011111100100001110000101100110000100011011100110" }, { "input": "0010001011001010001100000010010011110110011000100000000100110000101111001110\n1100110100111000110100001110111001011101001100001010100001010011100110110001", "output": "1110111111110010111000001100101010101011010100101010100101100011001001111111" }, { "input": "00101101010000000101011001101011001100010001100000101011101110000001111001000\n10010110010111000000101101000011101011001010000011011101101011010000000011111", "output": "10111011000111000101110100101000100111011011100011110110000101010001111010111" }, { "input": "111100000100100000101001100001001111001010001000001000000111010000010101101011\n001000100010100101111011111011010110101100001111011000010011011011100010010110", "output": "110100100110000101010010011010011001100110000111010000010100001011110111111101" }, { "input": "0110001101100100001111110101101000100101010010101010011001101001001101110000000\n0111011000000010010111011110010000000001000110001000011001101000000001110100111", "output": "0001010101100110011000101011111000100100010100100010000000000001001100000100111" }, { "input": "10001111111001000101001011110101111010100001011010101100111001010001010010001000\n10000111010010011110111000111010101100000011110001101111001000111010100000000001", "output": "00001000101011011011110011001111010110100010101011000011110001101011110010001001" }, { "input": "100110001110110000100101001110000011110110000110000000100011110100110110011001101\n110001110101110000000100101001101011111100100100001001000110000001111100011110110", "output": "010111111011000000100001100111101000001010100010001001100101110101001010000111011" }, { "input": "0000010100100000010110111100011111111010011101000000100000011001001101101100111010\n0100111110011101010110101011110110010111001111000110101100101110111100101000111111", "output": "0100101010111101000000010111101001101101010010000110001100110111110001000100000101" }, { "input": "11000111001010100001110000001001011010010010110000001110100101000001010101100110111\n11001100100100100001101010110100000111100011101110011010110100001001000011011011010", "output": "00001011101110000000011010111101011101110001011110010100010001001000010110111101101" }, { "input": "010110100010001000100010101001101010011010111110100001000100101000111011100010100001\n110000011111101101010011111000101010111010100001001100001001100101000000111000000000", "output": "100110111101100101110001010001000000100000011111101101001101001101111011011010100001" }, { "input": "0000011110101110010101110110110101100001011001101010101001000010000010000000101001101\n1100111111011100000110000111101110011111100111110001011001000010011111100001001100011", "output": "1100100001110010010011110001011011111110111110011011110000000000011101100001100101110" }, { "input": "10100000101101110001100010010010100101100011010010101000110011100000101010110010000000\n10001110011011010010111011011101101111000111110000111000011010010101001100000001010011", "output": "00101110110110100011011001001111001010100100100010010000101001110101100110110011010011" }, { "input": "001110000011111101101010011111000101010111010100001001100001001100101000000111000000000\n111010000000000000101001110011001000111011001100101010011001000011101001001011110000011", "output": "110100000011111101000011101100001101101100011000100011111000001111000001001100110000011" }, { "input": "1110111100111011010101011011001110001010010010110011110010011111000010011111010101100001\n1001010101011001001010100010101100000110111101011000100010101111111010111100001110010010", "output": "0111101001100010011111111001100010001100101111101011010000110000111000100011011011110011" }, { "input": "11100010001100010011001100001100010011010001101110011110100101110010101101011101000111111\n01110000000110111010110100001010000101011110100101010011000110101110101101110111011110001", "output": "10010010001010101001111000000110010110001111001011001101100011011100000000101010011001110" }, { "input": "001101011001100101101100110000111000101011001001100100000100101000100000110100010111111101\n101001111110000010111101111110001001111001111101111010000110111000100100110010010001011111", "output": "100100100111100111010001001110110001010010110100011110000010010000000100000110000110100010" }, { "input": "1010110110010101000110010010110101011101010100011001101011000110000000100011100100011000000\n0011011111100010001111101101000111001011101110100000110111100100101111010110101111011100011", "output": "1001101001110111001001111111110010010110111010111001011100100010101111110101001011000100011" }, { "input": "10010010000111010111011111110010100101100000001100011100111011100010000010010001011100001100\n00111010100010110010000100010111010001111110100100100011101000101111111111001101101100100100", "output": "10101000100101100101011011100101110100011110101000111111010011001101111101011100110000101000" }, { "input": "010101110001010101100000010111010000000111110011001101100011001000000011001111110000000010100\n010010111011100101010101111110110000000111000100001101101001001000001100101110001010000100001", "output": "000111001010110000110101101001100000000000110111000000001010000000001111100001111010000110101" }, { "input": "1100111110011001000111101001001011000110011010111111100010111111001100111111011101100111101011\n1100000011001000110100110111000001011001010111101000010010100011000001100100111101101000010110", "output": "0000111101010001110011011110001010011111001101010111110000011100001101011011100000001111111101" }, { "input": "00011000100100110111100101100100000000010011110111110010101110110011100001010111010011110100101\n00011011111011111011100101100111100101001110010111000010000111000100100100000001110101111011011", "output": "00000011011111001100000000000011100101011101100000110000101001110111000101010110100110001111110" }, { "input": "000101011001001100000111100010110101111011110101111101000110001101011010111110110011100100000001\n011000101010011111011000111000100000000011011000000001111110001000001111101010110000011100001111", "output": "011101110011010011011111011010010101111000101101111100111000000101010101010100000011111000001110" }, { "input": "1000101001011010000100100100010010011101011001110101111011101111111110010101001101010001010101001\n0110110010011100011111011111110111000000010001110100001010111110101011010011111011111110000110000", "output": "1110011011000110011011111011100101011101001000000001110001010001010101000110110110101111010011001" }, { "input": "01111010010101100111110111111011011010100001011101010000111100101101101110111011001100101011100111\n00001100110110100001111011000010001001001100000010111101000001111011100000010111010010000011000010", "output": "01110110100011000110001100111001010011101101011111101101111101010110001110101100011110101000100101" }, { "input": "111101011101111000001011001101111010110111001101110100100011111011011101001101010101011010111000110\n101111100101101101001100110011000001111010011101110111110110101110011011110011111100001001110101101", "output": "010010111000010101000111111110111011001101010000000011010101010101000110111110101001010011001101011" }, { "input": "1010000011010110011101001101110001110010000111011101110010110110111111001001110100101100010101010001\n0111101000111100101100000101111010100100001000011101010100110011100011010011010101000100101011100011", "output": "1101101011101010110001001000001011010110001111000000100110000101011100011010100001101000111110110010" }, { "input": "0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001\n1111111010111111101011111110101111111010111111101011111110101111111010111111101011111110101111111010", "output": "1111111010111111101011111110101111111010111111101011111110101111111010111111101011111110101111111011" }, { "input": "0\n0", "output": "0" }, { "input": "0\n1", "output": "1" } ]

1,613,464,371

2,147,483,647

Python 3

RUNTIME_ERROR

TESTS

0

62

0

n1 = input().split() n2 = input().split() ans = [] for i in range(len(n1)): if n1[i] == n2[i]: ans.append(0) else: ans.append(1) print(''.join(ans))

Title: Ultra-Fast Mathematician Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second. One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part. In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0. Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length. Now you are going to take part in Shapur's contest. See if you are faster and more accurate. Input Specification: There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. Output Specification: Write one line — the corresponding answer. Do not omit the leading 0s. Demo Input: ['1010100\n0100101\n', '000\n111\n', '1110\n1010\n', '01110\n01100\n'] Demo Output: ['1110001\n', '111\n', '0100\n', '00010\n'] Note: none

```python n1 = input().split() n2 = input().split() ans = [] for i in range(len(n1)): if n1[i] == n2[i]: ans.append(0) else: ans.append(1) print(''.join(ans)) ```

-1

439

A

Devu, the Singer and Churu, the Joker

PROGRAMMING

900

[ "greedy", "implementation" ]

null

Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited. Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* song will take *t**i* minutes exactly. The Comedian, Churu will crack jokes. All his jokes are of 5 minutes exactly. People have mainly come to listen Devu. But you know that he needs rest of 10 minutes after each song. On the other hand, Churu being a very active person, doesn't need any rest. You as one of the organizers should make an optimal sсhedule for the event. For some reasons you must follow the conditions: - The duration of the event must be no more than *d* minutes; - Devu must complete all his songs; - With satisfying the two previous conditions the number of jokes cracked by Churu should be as many as possible. If it is not possible to find a way to conduct all the songs of the Devu, output -1. Otherwise find out maximum number of jokes that Churu can crack in the grand event.

The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100).

If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event.

[ "3 30\n2 2 1\n", "3 20\n2 1 1\n" ]

[ "5\n", "-1\n" ]

Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way: - First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now finally Devu will perform his last song in 1 minutes. Total time spent is 5 + 2 + 10 + 2 + 10 + 1 = 30 minutes. Consider the second example. There is no way of organizing Devu's all songs. Hence the answer is -1.

500

[ { "input": "3 30\n2 2 1", "output": "5" }, { "input": "3 20\n2 1 1", "output": "-1" }, { "input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1", "output": "1943" }, { "input": "50 10000\n4 7 15 9 11 12 20 9 14 14 10 13 6 13 14 17 6 8 20 12 10 15 13 17 5 12 13 11 7 5 5 2 3 15 13 7 14 14 19 2 13 14 5 15 3 19 15 16 4 1", "output": "1891" }, { "input": "100 9000\n5 2 3 1 1 3 4 9 9 6 7 10 10 10 2 10 6 8 8 6 7 9 9 5 6 2 1 10 10 9 4 5 9 2 4 3 8 5 6 1 1 5 3 6 2 6 6 6 5 8 3 6 7 3 1 10 9 1 8 3 10 9 5 6 3 4 1 1 10 10 2 3 4 8 10 10 5 1 5 3 6 8 10 6 10 2 1 8 10 1 7 6 9 10 5 2 3 5 3 2", "output": "1688" }, { "input": "100 8007\n5 19 14 18 9 6 15 8 1 14 11 20 3 17 7 12 2 6 3 17 7 20 1 14 20 17 2 10 13 7 18 18 9 10 16 8 1 11 11 9 13 18 9 20 12 12 7 15 12 17 11 5 11 15 9 2 15 1 18 3 18 16 15 4 10 5 18 13 13 12 3 8 17 2 12 2 13 3 1 13 2 4 9 10 18 10 14 4 4 17 12 19 2 9 6 5 5 20 18 12", "output": "1391" }, { "input": "39 2412\n1 1 1 1 1 1 26 1 1 1 99 1 1 1 1 1 1 1 1 1 1 88 7 1 1 1 1 76 1 1 1 93 40 1 13 1 68 1 32", "output": "368" }, { "input": "39 2617\n47 1 1 1 63 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 70 1 99 63 1 1 1 1 1 1 1 1 64 1 1", "output": "435" }, { "input": "39 3681\n83 77 1 94 85 47 1 98 29 16 1 1 1 71 96 85 31 97 96 93 40 50 98 1 60 51 1 96 100 72 1 1 1 89 1 93 1 92 100", "output": "326" }, { "input": "45 894\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 28 28 1 1 1 1 1 1 1 1 1 1 1 1 1 1 99 3 1 1", "output": "139" }, { "input": "45 4534\n1 99 65 99 4 46 54 80 51 30 96 1 28 30 44 70 78 1 1 100 1 62 1 1 1 85 1 1 1 61 1 46 75 1 61 77 97 26 67 1 1 63 81 85 86", "output": "514" }, { "input": "72 3538\n52 1 8 1 1 1 7 1 1 1 1 48 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 40 1 1 38 1 1 1 1 1 1 1 1 1 1 1 35 1 93 79 1 1 1 1 1 1 1 1 1 51 1 1 1 1 1 1 1 1 1 1 1 1 96 1", "output": "586" }, { "input": "81 2200\n1 59 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 93 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 50 1 1 1 1 1 1 1 1 1 1 1", "output": "384" }, { "input": "81 2577\n85 91 1 1 2 1 1 100 1 80 1 1 17 86 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 37 1 66 24 1 1 96 49 1 66 1 44 1 1 1 1 98 1 1 1 1 35 1 37 3 35 1 1 87 64 1 24 1 58 1 1 42 83 5 1 1 1 1 1 95 1 94 1 50 1 1", "output": "174" }, { "input": "81 4131\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 16 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "807" }, { "input": "81 6315\n1 1 67 100 1 99 36 1 92 5 1 96 42 12 1 57 91 1 1 66 41 30 74 95 1 37 1 39 91 69 1 52 77 47 65 1 1 93 96 74 90 35 85 76 71 92 92 1 1 67 92 74 1 1 86 76 35 1 56 16 27 57 37 95 1 40 20 100 51 1 80 60 45 79 95 1 46 1 25 100 96", "output": "490" }, { "input": "96 1688\n1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 45 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 25 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 71 1 1 1 30 1 1 1", "output": "284" }, { "input": "96 8889\n1 1 18 1 1 1 1 1 1 1 1 1 99 1 1 1 1 88 1 45 1 1 1 1 1 1 1 1 1 1 1 1 1 1 96 1 1 1 1 21 1 1 1 1 1 1 1 73 1 1 1 1 1 10 1 1 1 1 1 1 1 46 43 1 1 1 1 1 98 1 1 1 1 1 1 6 1 1 1 1 1 74 1 25 1 55 1 1 1 13 1 1 54 1 1 1", "output": "1589" }, { "input": "10 100\n1 1 1 1 1 1 1 1 1 1", "output": "18" }, { "input": "100 10000\n54 46 72 94 79 83 91 54 73 3 24 55 54 31 28 20 19 6 25 19 47 23 1 70 15 87 51 39 54 77 55 5 60 3 15 99 56 88 22 78 79 21 38 27 28 86 7 88 12 59 55 70 25 1 70 49 1 45 69 72 50 17 4 56 8 100 90 34 35 20 61 76 88 79 4 74 65 68 75 26 40 72 59 94 10 67 96 85 29 90 47 24 44 1 66 93 55 36 1 99", "output": "1017" }, { "input": "100 6000\n41 31 23 17 24 78 26 96 93 48 46 2 49 33 35 9 73 100 34 48 83 36 33 69 43 24 3 74 8 81 27 33 94 38 77 9 76 90 62 90 21 67 22 22 12 2 17 27 61 18 72 85 59 65 71 38 90 75 74 66 60 47 58 50 90 95 75 10 5 100 97 29 83 88 65 26 93 90 22 98 36 55 70 38 50 92 88 72 99 96 25 14 74 16 25 92 67 94 77 96", "output": "-1" }, { "input": "1 1\n1", "output": "0" }, { "input": "1 6\n1", "output": "1" }, { "input": "1 5\n1", "output": "0" }, { "input": "1 3\n4", "output": "-1" }, { "input": "3 24\n2 1 2", "output": "-1" } ]

1,538,748,766

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

18

124

0

n, d = map(int,input().split()) t = list(map(int, input().split())) sumt = sum(t) kk = d - 10*n + 10 - sumt x = kk//5 print(x+2*n-2 if x>0 else -1)

Title: Devu, the Singer and Churu, the Joker Time Limit: None seconds Memory Limit: None megabytes Problem Description: Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited. Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* song will take *t**i* minutes exactly. The Comedian, Churu will crack jokes. All his jokes are of 5 minutes exactly. People have mainly come to listen Devu. But you know that he needs rest of 10 minutes after each song. On the other hand, Churu being a very active person, doesn't need any rest. You as one of the organizers should make an optimal sсhedule for the event. For some reasons you must follow the conditions: - The duration of the event must be no more than *d* minutes; - Devu must complete all his songs; - With satisfying the two previous conditions the number of jokes cracked by Churu should be as many as possible. If it is not possible to find a way to conduct all the songs of the Devu, output -1. Otherwise find out maximum number of jokes that Churu can crack in the grand event. Input Specification: The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). Output Specification: If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. Demo Input: ['3 30\n2 2 1\n', '3 20\n2 1 1\n'] Demo Output: ['5\n', '-1\n'] Note: Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way: - First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now finally Devu will perform his last song in 1 minutes. Total time spent is 5 + 2 + 10 + 2 + 10 + 1 = 30 minutes. Consider the second example. There is no way of organizing Devu's all songs. Hence the answer is -1.

```python n, d = map(int,input().split()) t = list(map(int, input().split())) sumt = sum(t) kk = d - 10*n + 10 - sumt x = kk//5 print(x+2*n-2 if x>0 else -1) ```

0

295

B

Greg and Graph

PROGRAMMING

1,700

[ "dp", "graphs", "shortest paths" ]

null

Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game: - The game consists of *n* steps. - On the *i*-th step Greg removes vertex number *x**i* from the graph. As Greg removes a vertex, he also removes all the edges that go in and out of this vertex. - Before executing each step, Greg wants to know the sum of lengths of the shortest paths between all pairs of the remaining vertices. The shortest path can go through any remaining vertex. In other words, if we assume that *d*(*i*,<=*v*,<=*u*) is the shortest path between vertices *v* and *u* in the graph that formed before deleting vertex *x**i*, then Greg wants to know the value of the following sum: . Help Greg, print the value of the required sum before each step.

The first line contains integer *n* (1<=≤<=*n*<=≤<=500) — the number of vertices in the graph. Next *n* lines contain *n* integers each — the graph adjacency matrix: the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*a**ij*<=≤<=105,<=*a**ii*<==<=0) represents the weight of the edge that goes from vertex *i* to vertex *j*. The next line contains *n* distinct integers: *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=*n*) — the vertices that Greg deletes.

Print *n* integers — the *i*-th number equals the required sum before the *i*-th step. Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

[ "1\n0\n1\n", "2\n0 5\n4 0\n1 2\n", "4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3\n" ]

[ "0 ", "9 0 ", "17 23 404 0 " ]

none

1,000

[ { "input": "1\n0\n1", "output": "0 " }, { "input": "2\n0 5\n4 0\n1 2", "output": "9 0 " }, { "input": "4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3", "output": "17 23 404 0 " }, { "input": "4\n0 57148 51001 13357\n71125 0 98369 67226\n49388 90852 0 66291\n39573 38165 97007 0\n2 3 1 4", "output": "723897 306638 52930 0 " }, { "input": "5\n0 27799 15529 16434 44291\n47134 0 90227 26873 52252\n41605 21269 0 9135 55784\n70744 17563 79061 0 73981\n70529 35681 91073 52031 0\n5 2 3 1 4", "output": "896203 429762 232508 87178 0 " }, { "input": "6\n0 72137 71041 29217 96749 46417\n40199 0 55907 57677 68590 78796\n83463 50721 0 30963 31779 28646\n94529 47831 98222 0 61665 73941\n24397 66286 2971 81613 0 52501\n26285 3381 51438 45360 20160 0\n6 3 2 4 5 1", "output": "1321441 1030477 698557 345837 121146 0 " }, { "input": "7\n0 34385 31901 51111 10191 14089 95685\n11396 0 8701 33277 1481 517 46253\n51313 2255 0 5948 66085 37201 65310\n21105 60985 10748 0 89271 42883 77345\n34686 29401 73565 47795 0 13793 66997\n70279 49576 62900 40002 70943 0 89601\n65045 1681 28239 12023 40414 89585 0\n3 5 7 6 1 2 4", "output": "1108867 1016339 729930 407114 206764 94262 0 " }, { "input": "8\n0 74961 47889 4733 72876 21399 63105 48239\n15623 0 9680 89133 57989 63401 26001 29608\n42369 82390 0 32866 46171 11871 67489 54070\n23425 80027 18270 0 28105 42657 40876 29267\n78793 18701 7655 94798 0 88885 71424 86914\n44835 76636 11553 46031 13617 0 16971 51915\n33037 53719 43116 52806 56897 71241 0 11629\n2119 62373 93265 69513 5770 90751 36619 0\n3 7 6 5 8 1 2 4", "output": "1450303 1188349 900316 531281 383344 219125 169160 0 " }, { "input": "9\n0 85236 27579 82251 69479 24737 87917 15149 52311\n59640 0 74687 34711 3685 30121 4961 7552 83399\n33376 68733 0 81357 18042 74297 15466 29476 5865\n7493 5601 3321 0 20263 55901 45756 55361 87633\n26751 17161 76681 40376 0 39745 50717 56887 90055\n18885 76353 47089 43601 21561 0 60571 33551 53753\n74595 877 71853 93156 97499 70876 0 22713 63961\n67725 25309 56358 92376 40641 35433 39781 0 97482\n81818 12561 85961 81445 3941 76799 31701 43725 0\n6 2 9 3 5 7 1 4 8", "output": "2106523 1533575 1645151 1255230 946667 618567 287636 147737 0 " } ]

1,575,384,857

2,147,483,647

Python 3

TIME_LIMIT_EXCEEDED

TESTS

11

3,000

512,000

n = int(input()) adjacency_matrix = [] for i in range(n): row = list(map(int, input().split())) adjacency_matrix.append(row) vs = list(map(int, input().split())) def floyd_warshall(w): n = len(w) d = list(map(list, w)) for k in range(n): for i in range(n): for j in range(n): d[i][j] = min(d[i][j], d[i][k] + d[k][j]) return d aux_list = [0] for i in range(1, n + 1): aux_list.append(i - 1) def get_index(e): for i in range(e + 1, n + 1): aux_list[i] -= 1 return aux_list[e] output = [] for e in vs: s = 0 d = floyd_warshall(adjacency_matrix) for row in d: s += sum(row) output += [s] index_to_remove = get_index(e) del adjacency_matrix[index_to_remove] for row in adjacency_matrix: del row[index_to_remove] print(" ".join(map(str, output)))

Title: Greg and Graph Time Limit: None seconds Memory Limit: None megabytes Problem Description: Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game: - The game consists of *n* steps. - On the *i*-th step Greg removes vertex number *x**i* from the graph. As Greg removes a vertex, he also removes all the edges that go in and out of this vertex. - Before executing each step, Greg wants to know the sum of lengths of the shortest paths between all pairs of the remaining vertices. The shortest path can go through any remaining vertex. In other words, if we assume that *d*(*i*,<=*v*,<=*u*) is the shortest path between vertices *v* and *u* in the graph that formed before deleting vertex *x**i*, then Greg wants to know the value of the following sum: . Help Greg, print the value of the required sum before each step. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=500) — the number of vertices in the graph. Next *n* lines contain *n* integers each — the graph adjacency matrix: the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*a**ij*<=≤<=105,<=*a**ii*<==<=0) represents the weight of the edge that goes from vertex *i* to vertex *j*. The next line contains *n* distinct integers: *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=*n*) — the vertices that Greg deletes. Output Specification: Print *n* integers — the *i*-th number equals the required sum before the *i*-th step. Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. Demo Input: ['1\n0\n1\n', '2\n0 5\n4 0\n1 2\n', '4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3\n'] Demo Output: ['0 ', '9 0 ', '17 23 404 0 '] Note: none

```python n = int(input()) adjacency_matrix = [] for i in range(n): row = list(map(int, input().split())) adjacency_matrix.append(row) vs = list(map(int, input().split())) def floyd_warshall(w): n = len(w) d = list(map(list, w)) for k in range(n): for i in range(n): for j in range(n): d[i][j] = min(d[i][j], d[i][k] + d[k][j]) return d aux_list = [0] for i in range(1, n + 1): aux_list.append(i - 1) def get_index(e): for i in range(e + 1, n + 1): aux_list[i] -= 1 return aux_list[e] output = [] for e in vs: s = 0 d = floyd_warshall(adjacency_matrix) for row in d: s += sum(row) output += [s] index_to_remove = get_index(e) del adjacency_matrix[index_to_remove] for row in adjacency_matrix: del row[index_to_remove] print(" ".join(map(str, output))) ```

0

735

A

Ostap and Grasshopper

PROGRAMMING

800

[ "implementation", "strings" ]

null

On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The grasshopper wants to eat the insect. Ostap knows that grasshopper is able to jump to any empty cell that is exactly *k* cells away from the current (to the left or to the right). Note that it doesn't matter whether intermediate cells are empty or not as the grasshopper makes a jump over them. For example, if *k*<==<=1 the grasshopper can jump to a neighboring cell only, and if *k*<==<=2 the grasshopper can jump over a single cell. Your goal is to determine whether there is a sequence of jumps such that grasshopper will get from his initial position to the cell with an insect.

The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump. The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the corresponding cell is empty, character '#' means that the corresponding cell contains an obstacle and grasshopper can't jump there. Character 'G' means that the grasshopper starts at this position and, finally, 'T' means that the target insect is located at this cell. It's guaranteed that characters 'G' and 'T' appear in this line exactly once.

If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes).

[ "5 2\n#G#T#\n", "6 1\nT....G\n", "7 3\nT..#..G\n", "6 2\n..GT..\n" ]

[ "YES\n", "YES\n", "NO\n", "NO\n" ]

In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4. In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times. In the third sample, the grasshopper can't make a single jump. In the fourth sample, the grasshopper can only jump to the cells with odd indices, thus he won't be able to reach the insect.

500

[ { "input": "5 2\n#G#T#", "output": "YES" }, { "input": "6 1\nT....G", "output": "YES" }, { "input": "7 3\nT..#..G", "output": "NO" }, { "input": "6 2\n..GT..", "output": "NO" }, { "input": "2 1\nGT", "output": "YES" }, { "input": "100 5\nG####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####T####", "output": "YES" }, { "input": "100 5\nG####.####.####.####.####.####.####.####.####.####.####.####.####.#########.####.####.####.####T####", "output": "NO" }, { "input": "2 1\nTG", "output": "YES" }, { "input": "99 1\n...T.............................................................................................G.", "output": "YES" }, { "input": "100 2\nG............#.....#...........#....#...........##............#............#......................T.", "output": "NO" }, { "input": "100 1\n#.#.#.##..#..##.#....##.##.##.#....####..##.#.##..GT..##...###.#.##.#..#..##.###..#.####..#.#.##..##", "output": "YES" }, { "input": "100 2\n..#####.#.#.......#.#.#...##..####..###..#.#######GT####.#.#...##...##.#..###....##.#.#..#.###....#.", "output": "NO" }, { "input": "100 3\nG..................................................................................................T", "output": "YES" }, { "input": "100 3\nG..................................................................................................T", "output": "YES" }, { "input": "100 3\nG..................................#......#......#.......#.#..........#........#......#..........#.T", "output": "NO" }, { "input": "100 3\nG..............#..........#...#..............#.#.....................#......#........#.........#...T", "output": "NO" }, { "input": "100 3\nG##################################################################################################T", "output": "NO" }, { "input": "100 33\nG..................................................................................................T", "output": "YES" }, { "input": "100 33\nG..................................................................................................T", "output": "YES" }, { "input": "100 33\nG.........#........#..........#..............#.................#............................#.#....T", "output": "YES" }, { "input": "100 33\nG.......#..................#..............................#............................#..........T.", "output": "NO" }, { "input": "100 33\nG#..........##...#.#.....................#.#.#.........##..#...........#....#...........##...#..###T", "output": "YES" }, { "input": "100 33\nG..#.#..#..####......#......##...##...#.##........#...#...#.##....###..#...###..##.#.....#......#.T.", "output": "NO" }, { "input": "100 33\nG#....#..#..##.##..#.##.#......#.#.##..##.#.#.##.##....#.#.....####..##...#....##..##..........#...T", "output": "NO" }, { "input": "100 33\nG#######.#..##.##.#...#..#.###.#.##.##.#..#.###..####.##.#.##....####...##..####.#..##.##.##.#....#T", "output": "NO" }, { "input": "100 33\nG#####.#.##.###########.##..##..#######..########..###.###..#.####.######.############..####..#####T", "output": "NO" }, { "input": "100 99\nT..................................................................................................G", "output": "YES" }, { "input": "100 99\nT..................................................................................................G", "output": "YES" }, { "input": "100 99\nT.#...............................#............#..............................##...................G", "output": "YES" }, { "input": "100 99\nT..#....#.##...##########.#.#.#.#...####..#.....#..##..#######.######..#.....###..###...#.......#.#G", "output": "YES" }, { "input": "100 99\nG##################################################################################################T", "output": "YES" }, { "input": "100 9\nT..................................................................................................G", "output": "YES" }, { "input": "100 9\nT.................................................................................................G.", "output": "NO" }, { "input": "100 9\nT................................................................................................G..", "output": "NO" }, { "input": "100 1\nG..................................................................................................T", "output": "YES" }, { "input": "100 1\nT..................................................................................................G", "output": "YES" }, { "input": "100 1\n##########G.........T###############################################################################", "output": "YES" }, { "input": "100 1\n#################################################################################################G.T", "output": "YES" }, { "input": "100 17\n##########G################.################.################.################T#####################", "output": "YES" }, { "input": "100 17\n####.#..#.G######.#########.##..##########.#.################.################T######.####.#########", "output": "YES" }, { "input": "100 17\n.########.G##.####.#.######.###############..#.###########.##.#####.##.#####.#T.###..###.########.##", "output": "YES" }, { "input": "100 1\nG.............................................#....................................................T", "output": "NO" }, { "input": "100 1\nT.#................................................................................................G", "output": "NO" }, { "input": "100 1\n##########G....#....T###############################################################################", "output": "NO" }, { "input": "100 1\n#################################################################################################G#T", "output": "NO" }, { "input": "100 17\nG################.#################################.################T###############################", "output": "NO" }, { "input": "100 17\nG################.###############..###.######.#######.###.#######.##T######################.###.####", "output": "NO" }, { "input": "100 17\nG####.##.##.#####.####....##.####.#########.##.#..#.###############.T############.#########.#.####.#", "output": "NO" }, { "input": "48 1\nT..............................................G", "output": "YES" }, { "input": "23 1\nT.....................G", "output": "YES" }, { "input": "49 1\nG...............................................T", "output": "YES" }, { "input": "3 1\nTG#", "output": "YES" }, { "input": "6 2\n..TG..", "output": "NO" }, { "input": "14 3\n...G.....#..T.", "output": "NO" }, { "input": "5 4\n##GT#", "output": "NO" }, { "input": "6 2\nT#..G.", "output": "YES" }, { "input": "5 2\nT.G.#", "output": "YES" }, { "input": "6 1\nT...G#", "output": "YES" }, { "input": "5 1\nTG###", "output": "YES" }, { "input": "5 4\n.G..T", "output": "NO" }, { "input": "7 2\nT#...#G", "output": "YES" }, { "input": "7 1\n##TG###", "output": "YES" }, { "input": "7 1\n###GT##", "output": "YES" }, { "input": "5 2\nG..T.", "output": "NO" }, { "input": "5 1\nG.T##", "output": "YES" }, { "input": "6 2\nG.T###", "output": "YES" }, { "input": "6 2\nG#T###", "output": "YES" }, { "input": "10 2\n####T..G..", "output": "NO" }, { "input": "3 1\nGT#", "output": "YES" }, { "input": "4 1\nTG##", "output": "YES" }, { "input": "6 1\n.G..T.", "output": "YES" }, { "input": "10 3\n......G..T", "output": "YES" }, { "input": "3 2\nG.T", "output": "YES" }, { "input": "4 1\n#G.T", "output": "YES" }, { "input": "5 2\nT#G##", "output": "YES" }, { "input": "4 2\nG#.T", "output": "NO" }, { "input": "4 1\nGT##", "output": "YES" } ]

1,589,021,048

2,147,483,647

Python 3

OK

TESTS

83

124

6,963,200

# bsdk idhar kya dekhne ko aaya hai, khud kr!!! # from math import * # from itertools import * # import random n, k = map(int, input().split()) arr = list(input()) pos = arr.index("G") target = arr.index("T") if pos > target: flag = 0 for i in range(pos, target - 1, -k): if arr[i] == "#": flag = 0 break elif arr[i] == "T": flag = 1 break else: continue if flag == 0: print("NO") else: print("YES") else: flag = 0 for i in range(pos, target + 1, k): if arr[i] == "#": flag = 0 break elif arr[i] == "T": flag = 1 break else: continue if flag == 0: print("NO") else: print("YES")

Title: Ostap and Grasshopper Time Limit: None seconds Memory Limit: None megabytes Problem Description: On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The grasshopper wants to eat the insect. Ostap knows that grasshopper is able to jump to any empty cell that is exactly *k* cells away from the current (to the left or to the right). Note that it doesn't matter whether intermediate cells are empty or not as the grasshopper makes a jump over them. For example, if *k*<==<=1 the grasshopper can jump to a neighboring cell only, and if *k*<==<=2 the grasshopper can jump over a single cell. Your goal is to determine whether there is a sequence of jumps such that grasshopper will get from his initial position to the cell with an insect. Input Specification: The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump. The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the corresponding cell is empty, character '#' means that the corresponding cell contains an obstacle and grasshopper can't jump there. Character 'G' means that the grasshopper starts at this position and, finally, 'T' means that the target insect is located at this cell. It's guaranteed that characters 'G' and 'T' appear in this line exactly once. Output Specification: If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes). Demo Input: ['5 2\n#G#T#\n', '6 1\nT....G\n', '7 3\nT..#..G\n', '6 2\n..GT..\n'] Demo Output: ['YES\n', 'YES\n', 'NO\n', 'NO\n'] Note: In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4. In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times. In the third sample, the grasshopper can't make a single jump. In the fourth sample, the grasshopper can only jump to the cells with odd indices, thus he won't be able to reach the insect.

```python # bsdk idhar kya dekhne ko aaya hai, khud kr!!! # from math import * # from itertools import * # import random n, k = map(int, input().split()) arr = list(input()) pos = arr.index("G") target = arr.index("T") if pos > target: flag = 0 for i in range(pos, target - 1, -k): if arr[i] == "#": flag = 0 break elif arr[i] == "T": flag = 1 break else: continue if flag == 0: print("NO") else: print("YES") else: flag = 0 for i in range(pos, target + 1, k): if arr[i] == "#": flag = 0 break elif arr[i] == "T": flag = 1 break else: continue if flag == 0: print("NO") else: print("YES") ```

3

948

A

Protect Sheep

PROGRAMMING

900

[ "brute force", "dfs and similar", "graphs", "implementation" ]

null

Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected. The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog. Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.

First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively. Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.

If it is impossible to protect all sheep, output a single line with the word "No". Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf. If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.

[ "6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n", "1 2\nSW\n", "5 5\n.S...\n...S.\nS....\n...S.\n.S...\n" ]

[ "Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n", "No\n", "Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n" ]

In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally. In the second example, there are no empty spots to put dogs that would guard the lone sheep. In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.

500

[ { "input": "1 2\nSW", "output": "No" }, { "input": "10 10\n....W.W.W.\n.........S\n.S.S...S..\nW.......SS\n.W..W.....\n.W...W....\nS..S...S.S\n....W...S.\n..S..S.S.S\nSS.......S", "output": "Yes\nDDDDWDWDWD\nDDDDDDDDDS\nDSDSDDDSDD\nWDDDDDDDSS\nDWDDWDDDDD\nDWDDDWDDDD\nSDDSDDDSDS\nDDDDWDDDSD\nDDSDDSDSDS\nSSDDDDDDDS" }, { "input": "10 10\n....W.W.W.\n...W.....S\n.S.S...S..\nW......WSS\n.W..W.....\n.W...W....\nS..S...S.S\n...WWW..S.\n..S..S.S.S\nSS.......S", "output": "No" }, { "input": "1 50\nW...S..............W.....S..S...............S...W.", "output": "Yes\nWDDDSDDDDDDDDDDDDDDWDDDDDSDDSDDDDDDDDDDDDDDDSDDDWD" }, { "input": "2 4\n...S\n...W", "output": "No" }, { "input": "4 2\n..\n..\n..\nSW", "output": "No" }, { "input": "4 2\n..\n..\n..\nWS", "output": "No" }, { "input": "2 4\n...W\n...S", "output": "No" }, { "input": "50 1\nS\n.\n.\n.\n.\n.\n.\nS\n.\n.\n.\n.\n.\n.\n.\n.\nS\n.\nW\n.\nS\n.\n.\n.\n.\nS\n.\n.\n.\n.\n.\n.\n.\nW\n.\n.\n.\nW\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.\n.", "output": "Yes\nS\nD\nD\nD\nD\nD\nD\nS\nD\nD\nD\nD\nD\nD\nD\nD\nS\nD\nW\nD\nS\nD\nD\nD\nD\nS\nD\nD\nD\nD\nD\nD\nD\nW\nD\nD\nD\nW\nD\nD\nD\nD\nD\nD\nD\nD\nD\nD\nD\nD" }, { "input": "4 4\nW..S\nW..S\nW..S\nW..S", "output": "Yes\nWDDS\nWDDS\nWDDS\nWDDS" }, { "input": "4 4\nSSSS\n....\n....\nWWWW", "output": "Yes\nSSSS\nDDDD\nDDDD\nWWWW" }, { "input": "4 4\nWWWW\n....\n....\nSSSS", "output": "Yes\nWWWW\nDDDD\nDDDD\nSSSS" }, { "input": "4 4\nS..W\nS..W\nS..W\nS..W", "output": "Yes\nSDDW\nSDDW\nSDDW\nSDDW" }, { "input": "1 1\n.", "output": "Yes\nD" }, { "input": "1 1\nW", "output": "Yes\nW" }, { "input": "1 1\nS", "output": "Yes\nS" }, { "input": "4 2\n..\n..\n.W\n.S", "output": "No" }, { "input": "4 2\n..\n..\n.S\n.W", "output": "No" }, { "input": "4 2\n..\n..\nW.\nS.", "output": "No" }, { "input": "4 2\n..\n..\nS.\nW.", "output": "No" }, { "input": "2 4\n....\n..SW", "output": "No" }, { "input": "2 4\n....\n..WS", "output": "No" }, { "input": "1 2\nS.", "output": "Yes\nSD" } ]

1,657,062,593

2,147,483,647

Python 3

OK

TESTS

98

109

1,536,000

r, c = map(int, input().split()) pasture = [list(input()) for _ in range(r)] protectable = True for i in range(r): for j in range(c): if pasture[i][j] == 'W': for x, y in [(i-1, j), (i+1, j), (i, j-1), (i, j+1)]: if any((x < 0, y < 0, x >= r, y >= c)): continue if pasture[x][y] == 'S': protectable = False if pasture[x][y] == '.': pasture[x][y] = 'D' if protectable: print('Yes') for i in range(r): print(''.join(pasture[i])) else: print('No')

Title: Protect Sheep Time Limit: None seconds Memory Limit: None megabytes Problem Description: Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected. The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog. Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number. Input Specification: First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively. Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell. Output Specification: If it is impossible to protect all sheep, output a single line with the word "No". Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf. If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs. Demo Input: ['6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n', '1 2\nSW\n', '5 5\n.S...\n...S.\nS....\n...S.\n.S...\n'] Demo Output: ['Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n', 'No\n', 'Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n'] Note: In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally. In the second example, there are no empty spots to put dogs that would guard the lone sheep. In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him.

```python r, c = map(int, input().split()) pasture = [list(input()) for _ in range(r)] protectable = True for i in range(r): for j in range(c): if pasture[i][j] == 'W': for x, y in [(i-1, j), (i+1, j), (i, j-1), (i, j+1)]: if any((x < 0, y < 0, x >= r, y >= c)): continue if pasture[x][y] == 'S': protectable = False if pasture[x][y] == '.': pasture[x][y] = 'D' if protectable: print('Yes') for i in range(r): print(''.join(pasture[i])) else: print('No') ```

3

821

A

Okabe and Future Gadget Laboratory

PROGRAMMING

800

[ "implementation" ]

null

Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every *x*,<=*y* such that 1<=≤<=*x*,<=*y*<=≤<=*n* and *a**x*,<=*y*<=≠<=1, there should exist two indices *s* and *t* so that *a**x*,<=*y*<==<=*a**x*,<=*s*<=+<=*a**t*,<=*y*, where *a**i*,<=*j* denotes the integer in *i*-th row and *j*-th column. Help Okabe determine whether a given lab is good!

The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab. The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105).

Print "Yes" if the given lab is good and "No" otherwise. You can output each letter in upper or lower case.

[ "3\n1 1 2\n2 3 1\n6 4 1\n", "3\n1 5 2\n1 1 1\n1 2 3\n" ]

[ "Yes\n", "No\n" ]

In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes". In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is "No".

500

[ { "input": "3\n1 1 2\n2 3 1\n6 4 1", "output": "Yes" }, { "input": "3\n1 5 2\n1 1 1\n1 2 3", "output": "No" }, { "input": "1\n1", "output": "Yes" }, { "input": "4\n1 1 1 1\n1 11 1 2\n2 5 1 4\n3 9 4 1", "output": "Yes" }, { "input": "4\n1 1 1 1\n1 7 1 1\n1 3 1 2\n2 6 3 1", "output": "Yes" }, { "input": "4\n1 1 1 1\n1 12 1 2\n4 4 1 3\n5 10 6 1", "output": "Yes" }, { "input": "4\n1 1 1 1\n1 13 1 2\n4 5 1 3\n5 11 6 1", "output": "Yes" }, { "input": "4\n1 1 1 1\n1 13 1 2\n4 5 1 3\n7 11 6 1", "output": "No" }, { "input": "4\n1 1 1 1\n1 14 1 6\n4 5 1 5\n3 8 2 1", "output": "Yes" }, { "input": "10\n3 2 6 5 1 2 1 1 2 1\n1 2 2 3 1 4 1 1 1 1\n1 1 3 1 2 2 2 1 1 1\n1 3 1 2 1 2 1 1 1 1\n12 1 4 3 3 1 1 1 2 1\n8 1 1 1 1 3 6 5 1 3\n1 1 1 2 4 1 3 2 1 1\n1 1 1 1 1 1 1 2 1 1\n1 2 1 1 1 1 1 1 1 1\n2 1 1 1 1 1 1 1 1 2", "output": "Yes" }, { "input": "4\n1 2 3 5\n1 1 1 1\n1 1 1 1\n1 1 1 1", "output": "No" }, { "input": "1\n2", "output": "No" }, { "input": "3\n1 1 4\n1 1 2\n1 1 2", "output": "No" }, { "input": "1\n5", "output": "No" }, { "input": "3\n1 2 1\n2 2 3\n1 3 1", "output": "No" }, { "input": "3\n2 1 1\n2 1 1\n2 1 1", "output": "No" }, { "input": "1\n60000", "output": "No" } ]

1,520,453,165

2,147,483,647

Python 3

OK

TESTS

31

966

5,632,000

#k=int(input()) #n,m=map(int,input().split()) #a=list(map(int,input().split())) #b=list(map(int,input().split())) n=int(input()) a=[0]*50 for i in range(n): a[i]=list(map(int,input().split())) for i in range(n): for j in range(n): if a[i][j]!=1: fl=0 for k in range(n): for t in range(n): if a[i][j]==a[i][k]+a[t][j]: fl=1 if fl==0: print("No") quit() print("Yes")

Title: Okabe and Future Gadget Laboratory Time Limit: None seconds Memory Limit: None megabytes Problem Description: Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. In other words, for every *x*,<=*y* such that 1<=≤<=*x*,<=*y*<=≤<=*n* and *a**x*,<=*y*<=≠<=1, there should exist two indices *s* and *t* so that *a**x*,<=*y*<==<=*a**x*,<=*s*<=+<=*a**t*,<=*y*, where *a**i*,<=*j* denotes the integer in *i*-th row and *j*-th column. Help Okabe determine whether a given lab is good! Input Specification: The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab. The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105). Output Specification: Print "Yes" if the given lab is good and "No" otherwise. You can output each letter in upper or lower case. Demo Input: ['3\n1 1 2\n2 3 1\n6 4 1\n', '3\n1 5 2\n1 1 1\n1 2 3\n'] Demo Output: ['Yes\n', 'No\n'] Note: In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes". In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an integer in the same column. Thus the answer is "No".

```python #k=int(input()) #n,m=map(int,input().split()) #a=list(map(int,input().split())) #b=list(map(int,input().split())) n=int(input()) a=[0]*50 for i in range(n): a[i]=list(map(int,input().split())) for i in range(n): for j in range(n): if a[i][j]!=1: fl=0 for k in range(n): for t in range(n): if a[i][j]==a[i][k]+a[t][j]: fl=1 if fl==0: print("No") quit() print("Yes") ```

3

801

B

Valued Keys

PROGRAMMING

900

[ "constructive algorithms", "greedy", "strings" ]

null

You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length. The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2. For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel". You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists.

The first line of input contains the string *x*. The second line of input contains the string *y*. Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100.

If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1. Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters.

[ "ab\naa\n", "nzwzl\nniwel\n", "ab\nba\n" ]

[ "ba\n", "xiyez\n", "-1\n" ]

The first case is from the statement. Another solution for the second case is "zizez" There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba".

1,000

[ { "input": "ab\naa", "output": "ba" }, { "input": "nzwzl\nniwel", "output": "xiyez" }, { "input": "ab\nba", "output": "-1" }, { "input": "r\nl", "output": "l" }, { "input": "d\ny", "output": "-1" }, { "input": "yvowz\ncajav", "output": "cajav" }, { "input": "lwzjp\ninjit", "output": "-1" }, { "input": "epqnlxmiicdidyscjaxqznwur\neodnlemiicdedmkcgavqbnqmm", "output": "eodnlemiicdedmkcgavqbnqmm" }, { "input": "qqdabbsxiibnnjgsgxllfvdqj\nuxmypqtwfdezewdxfgplannrs", "output": "-1" }, { "input": "aanerbaqslfmqmuciqbxyznkevukvznpkmxlcorpmrenwxhzfgbmlfpxtkqpxdrmcqcmbf\naanebbaqkgfiimcciqbaoznkeqqkrgapdillccrfeienwbcvfgbmlfbimkqchcrmclcmbf", "output": "aanebbaqkgfiimcciqbaoznkeqqkrgapdillccrfeienwbcvfgbmlfbimkqchcrmclcmbf" }, { "input": "mbyrkhjctrcrayisflptgfudwgrtegidhqicsjqafvdloritbjhciyxuwavxknezwwudnk\nvvixsutlbdewqoabqhpuerfkzrddcqptfwmxdlxwbvsaqfjoxztlddvwgflcteqbwaiaen", "output": "-1" }, { "input": "eufycwztywhbjrpqobvknwfqmnboqcfdiahkagykeibbsqpljcghhmsgfmswwsanzyiwtvuirwmppfivtekaywkzskyydfvkjgxb\necfwavookadbcilfobojnweqinbcpcfdiahkabwkeibbacpljcghhksgfajgmianfnivmhfifogpffiheegayfkxkkcmdfvihgdb", "output": "ecfwavookadbcilfobojnweqinbcpcfdiahkabwkeibbacpljcghhksgfajgmianfnivmhfifogpffiheegayfkxkkcmdfvihgdb" }, { "input": "qvpltcffyeghtbdhjyhfteojezyzziardduzrbwuxmzzkkoehfnxecafizxglboauhynfbawlfxenmykquyhrxswhjuovvogntok\nchvkcvzxptbcepdjfezcpuvtehewbnvqeoezlcnzhpfwujbmhafoeqmjhtwisnobauinkzyigrvahpuetkgpdjfgbzficsmuqnym", "output": "-1" }, { "input": "nmuwjdihouqrnsuahimssnrbxdpwvxiyqtenahtrlshjkmnfuttnpqhgcagoptinnaptxaccptparldzrhpgbyrzedghudtsswxi\nnilhbdghosqnbebafimconrbvdodjsipqmekahhrllhjkemeketapfhgcagopfidnahtlaccpfpafedqicpcbvfgedghudhddwib", "output": "nilhbdghosqnbebafimconrbvdodjsipqmekahhrllhjkemeketapfhgcagopfidnahtlaccpfpafedqicpcbvfgedghudhddwib" }, { "input": "dyxgwupoauwqtcfoyfjdotzirwztdfrueqiypxoqvkmhiehdppwtdoxrbfvtairdbuvlqohjflznggjpifhwjrshcrfbjtklpykx\ngzqlnoizhxolnditjdhlhptjsbczehicudoybzilwnshmywozwnwuipcgirgzldtvtowdsokfeafggwserzdazkxyddjttiopeew", "output": "-1" }, { "input": "hbgwuqzougqzlxemvyjpeizjfwhgugrfnhbrlxkmkdalikfyunppwgdzmalbwewybnjzqsohwhjkdcyhhzmysflambvhpsjilsyv\nfbdjdqjojdafarakvcjpeipjfehgfgrfehbolxkmkdagikflunnpvadocalbkedibhbflmohnhjkdcthhaigsfjaibqhbcjelirv", "output": "fbdjdqjojdafarakvcjpeipjfehgfgrfehbolxkmkdagikflunnpvadocalbkedibhbflmohnhjkdcthhaigsfjaibqhbcjelirv" }, { "input": "xnjjhjfuhgyxqhpzmvgbaohqarugdoaczcfecofltwemieyxolswkcwhlfagfrgmoiqrgftokbqwtxgxzweozzlikrvafiabivlk\npjfosalbsitcnqiazhmepfifjxvmazvdgffcnozmnqubhonwjldmpdsjagmamniylzjdbklcyrzivjyzgnogahobpkwpwpvraqns", "output": "-1" }, { "input": "zrvzedssbsrfldqvjpgmsefrmsatspzoitwvymahiptphiystjlsauzquzqqbmljobdhijcpdvatorwmyojqgnezvzlgjibxepcf\npesoedmqbmffldqsjggmhefkadaesijointrkmahapaahiysfjdiaupqujngbjhjobdhiecadeatgjvelojjgnepvajgeibfepaf", "output": "pesoedmqbmffldqsjggmhefkadaesijointrkmahapaahiysfjdiaupqujngbjhjobdhiecadeatgjvelojjgnepvajgeibfepaf" }, { "input": "pdvkuwyzntzfqpblzmbynknyhlnqbxijuqaincviugxohcsrofozrrsategwkbwxcvkyzxhurokefpbdnmcfogfhsojayysqbrow\nbvxruombdrywlcjkrltyayaazwpauuhbtgwfzdrmfwwucgffucwelzvpsdgtapogchblzahsrfymjlaghkbmbssghrpxalkslcvp", "output": "-1" }, { "input": "tgharsjyihroiiahwgbjezlxvlterxivdhtzjcqegzmtigqmrehvhiyjeywegxaseoyoacouijudbiruoghgxvxadwzgdxtnxlds\ntghaksjsdhkoiiahegbjexlfrctercipdhmvjbgegxdtggqdpbhvhiseehhegnaseoooacnsijubbirjnghgsvpadhaadrtimfdp", "output": "tghaksjsdhkoiiahegbjexlfrctercipdhmvjbgegxdtggqdpbhvhiseehhegnaseoooacnsijubbirjnghgsvpadhaadrtimfdp" }, { "input": "jsinejpfwhzloulxndzvzftgogfdagrsscxmatldssqsgaknnbkcvhptebjjpkjhrjegrotzwcdosezkedzxeoyibmyzunkguoqj\nkfmvybobocdpipiripysioruqvloopvbggpjksgmwzyqwyxnesmvhsawnbbmntulspvsysfkjqwpvoelliopbaukyagedextzoej", "output": "-1" }, { "input": "nttdcfceptruiomtmwzestrfchnqpgqeztpcvthzelfyggjgqadylzubpvbrlgndrcsursczpxlnoyoadxezncqalupfzmjeqihe\nkttdcfceohrjiaahmoldanpfchnfpgheqpdahqhxecfpbgigqadrkjubjfbrlgndbcgcgmcjpeleinaadretncqaiqpfkmjeqihe", "output": "kttdcfceohrjiaahmoldanpfchnfpgheqpdahqhxecfpbgigqadrkjubjfbrlgndbcgcgmcjpeleinaadretncqaiqpfkmjeqihe" }, { "input": "diuopwglduasnaxgduwslbzoyayoypzznqspljcyqehweydhlwifcvnjmaowuvyqfwynjghecqvxdvuquuwpvwrjljozocaxnktv\ntrdydprdzmjhgbhzytelrfjpgsebijicsigmwhynmcyjtqrvojcndodchzxfcvyqjxqzwibccdvsjqhsnectdjyrrhzkeamukang", "output": "-1" }, { "input": "ftfr\nftfr", "output": "ftfr" }, { "input": "ftr\nftr", "output": "ftr" }, { "input": "shftr\nshftr", "output": "shftr" }, { "input": "vkvkkv\nvkvkkv", "output": "vkvkkv" }, { "input": "ftrd\nftrd", "output": "ftrd" }, { "input": "fztr\nfztr", "output": "fztr" }, { "input": "frtr\nfrtr", "output": "frtr" }, { "input": "shdftr\nshdftr", "output": "shdftr" }, { "input": "zzz\nzzz", "output": "zzz" }, { "input": "shtr\nshtr", "output": "shtr" }, { "input": "aaaaa\nzzzzz", "output": "-1" }, { "input": "efr\nefr", "output": "efr" } ]

1,546,342,978

2,147,483,647

Python 3

OK

TESTS

35

109

0

s1=input() s2=input() s3='' flag1=0 for i in range(0,len(s1)): if s1[i]<s2[i]: flag1=1 break else : s3=s3+s2[i] if flag1==0: print(s3) else : print("-1")

Title: Valued Keys Time Limit: None seconds Memory Limit: None megabytes Problem Description: You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length. The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2. For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel". You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists. Input Specification: The first line of input contains the string *x*. The second line of input contains the string *y*. Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100. Output Specification: If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1. Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters. Demo Input: ['ab\naa\n', 'nzwzl\nniwel\n', 'ab\nba\n'] Demo Output: ['ba\n', 'xiyez\n', '-1\n'] Note: The first case is from the statement. Another solution for the second case is "zizez" There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba".

```python s1=input() s2=input() s3='' flag1=0 for i in range(0,len(s1)): if s1[i]<s2[i]: flag1=1 break else : s3=s3+s2[i] if flag1==0: print(s3) else : print("-1") ```

3

999

A

Mishka and Contest

PROGRAMMING

800

[ "brute force", "implementation" ]

null

Mishka started participating in a programming contest. There are $n$ problems in the contest. Mishka's problem-solving skill is equal to $k$. Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list. Mishka cannot solve a problem with difficulty greater than $k$. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by $1$. Mishka stops when he is unable to solve any problem from any end of the list. How many problems can Mishka solve?

The first line of input contains two integers $n$ and $k$ ($1 \le n, k \le 100$) — the number of problems in the contest and Mishka's problem-solving skill. The second line of input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$), where $a_i$ is the difficulty of the $i$-th problem. The problems are given in order from the leftmost to the rightmost in the list.

Print one integer — the maximum number of problems Mishka can solve.

[ "8 4\n4 2 3 1 5 1 6 4\n", "5 2\n3 1 2 1 3\n", "5 100\n12 34 55 43 21\n" ]

[ "5\n", "0\n", "5\n" ]

In the first example, Mishka can solve problems in the following order: $[4, 2, 3, 1, 5, 1, 6, 4] \rightarrow [2, 3, 1, 5, 1, 6, 4] \rightarrow [2, 3, 1, 5, 1, 6] \rightarrow [3, 1, 5, 1, 6] \rightarrow [1, 5, 1, 6] \rightarrow [5, 1, 6]$, so the number of solved problems will be equal to $5$. In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than $k$. In the third example, Mishka's solving skill is so amazing that he can solve all the problems.

0

[ { "input": "8 4\n4 2 3 1 5 1 6 4", "output": "5" }, { "input": "5 2\n3 1 2 1 3", "output": "0" }, { "input": "5 100\n12 34 55 43 21", "output": "5" }, { "input": "100 100\n44 47 36 83 76 94 86 69 31 2 22 77 37 51 10 19 25 78 53 25 1 29 48 95 35 53 22 72 49 86 60 38 13 91 89 18 54 19 71 2 25 33 65 49 53 5 95 90 100 68 25 5 87 48 45 72 34 14 100 44 94 75 80 26 25 7 57 82 49 73 55 43 42 60 34 8 51 11 71 41 81 23 20 89 12 72 68 26 96 92 32 63 13 47 19 9 35 56 79 62", "output": "100" }, { "input": "100 99\n84 82 43 4 71 3 30 92 15 47 76 43 2 17 76 4 1 33 24 96 44 98 75 99 59 11 73 27 67 17 8 88 69 41 44 22 91 48 4 46 42 21 21 67 85 51 57 84 11 100 100 59 39 72 89 82 74 19 98 14 37 97 20 78 38 52 44 83 19 83 69 32 56 6 93 13 98 80 80 2 33 71 11 15 55 51 98 58 16 91 39 32 83 58 77 79 88 81 17 98", "output": "98" }, { "input": "100 69\n80 31 12 89 16 35 8 28 39 12 32 51 42 67 64 53 17 88 63 97 29 41 57 28 51 33 82 75 93 79 57 86 32 100 83 82 99 33 1 27 86 22 65 15 60 100 42 37 38 85 26 43 90 62 91 13 1 92 16 20 100 19 28 30 23 6 5 69 24 22 9 1 10 14 28 14 25 9 32 8 67 4 39 7 10 57 15 7 8 35 62 6 53 59 62 13 24 7 53 2", "output": "39" }, { "input": "100 2\n2 2 2 2 1 1 1 2 1 2 2 2 1 2 2 2 2 1 2 1 2 1 1 1 2 1 2 1 2 1 1 2 2 2 2 2 1 2 1 2 1 1 2 1 2 1 1 2 1 2 1 2 2 1 2 1 2 1 1 2 1 2 2 1 1 2 2 2 1 1 2 1 1 2 2 2 1 1 1 2 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 2 2 16", "output": "99" }, { "input": "100 3\n86 53 82 40 2 20 59 2 46 63 75 49 24 81 70 22 9 9 93 72 47 23 29 77 78 51 17 59 19 71 35 3 20 60 70 9 11 96 71 94 91 19 88 93 50 49 72 19 53 30 38 67 62 71 81 86 5 26 5 32 63 98 1 97 22 32 87 65 96 55 43 85 56 37 56 67 12 100 98 58 77 54 18 20 33 53 21 66 24 64 42 71 59 32 51 69 49 79 10 1", "output": "1" }, { "input": "13 7\n1 1 1 1 1 1 1 1 1 1 1 1 1", "output": "13" }, { "input": "1 5\n4", "output": "1" }, { "input": "3 2\n1 4 1", "output": "2" }, { "input": "1 2\n100", "output": "0" }, { "input": "7 4\n4 2 3 4 4 2 3", "output": "7" }, { "input": "1 2\n1", "output": "1" }, { "input": "1 2\n15", "output": "0" }, { "input": "2 1\n1 1", "output": "2" }, { "input": "5 3\n3 4 3 2 1", "output": "4" }, { "input": "1 1\n2", "output": "0" }, { "input": "1 5\n1", "output": "1" }, { "input": "6 6\n7 1 1 1 1 1", "output": "5" }, { "input": "5 5\n6 5 5 5 5", "output": "4" }, { "input": "1 4\n2", "output": "1" }, { "input": "9 4\n1 2 1 2 4 2 1 2 1", "output": "9" }, { "input": "1 1\n1", "output": "1" }, { "input": "1 10\n5", "output": "1" }, { "input": "5 5\n1 1 1 1 1", "output": "5" }, { "input": "100 10\n2 5 1 10 10 2 7 7 9 4 1 8 1 1 8 4 7 9 10 5 7 9 5 6 7 2 7 5 3 2 1 82 4 80 9 8 6 1 10 7 5 7 1 5 6 7 19 4 2 4 6 2 1 8 31 6 2 2 57 42 3 2 7 1 9 5 10 8 5 4 10 8 3 5 8 7 2 7 6 5 3 3 4 10 6 7 10 8 7 10 7 2 4 6 8 10 10 2 6 4", "output": "71" }, { "input": "100 90\n17 16 5 51 17 62 24 45 49 41 90 30 19 78 67 66 59 34 28 47 42 8 33 77 90 41 61 16 86 33 43 71 90 95 23 9 56 41 24 90 31 12 77 36 90 67 47 15 92 50 79 88 42 19 21 79 86 60 41 26 47 4 70 62 44 90 82 89 84 91 54 16 90 53 29 69 21 44 18 28 88 74 56 43 12 76 10 22 34 24 27 52 28 76 90 75 5 29 50 90", "output": "63" }, { "input": "100 10\n6 4 8 4 1 9 4 8 5 2 2 5 2 6 10 2 2 5 3 5 2 3 10 5 2 9 1 1 6 1 5 9 16 42 33 49 26 31 81 27 53 63 81 90 55 97 70 51 87 21 79 62 60 91 54 95 26 26 30 61 87 79 47 11 59 34 40 82 37 40 81 2 7 1 8 4 10 7 1 10 8 7 3 5 2 8 3 3 9 2 1 1 5 7 8 7 1 10 9 8", "output": "61" }, { "input": "100 90\n45 57 52 69 17 81 85 60 59 39 55 14 87 90 90 31 41 57 35 89 74 20 53 4 33 49 71 11 46 90 71 41 71 90 63 74 51 13 99 92 99 91 100 97 93 40 93 96 100 99 100 92 98 96 78 91 91 91 91 100 94 97 95 97 96 95 17 13 45 35 54 26 2 74 6 51 20 3 73 90 90 42 66 43 86 28 84 70 37 27 90 30 55 80 6 58 57 51 10 22", "output": "72" }, { "input": "100 10\n10 2 10 10 10 10 10 10 10 7 10 10 10 10 10 10 9 10 10 10 10 10 10 10 10 7 9 10 10 10 37 10 4 10 10 10 59 5 95 10 10 10 10 39 10 10 10 10 10 10 10 5 10 10 10 10 10 10 10 10 10 10 10 10 66 10 10 10 10 10 5 10 10 10 10 10 10 44 10 10 10 10 10 10 10 10 10 10 10 7 10 10 10 10 10 10 10 10 10 2", "output": "52" }, { "input": "100 90\n57 90 90 90 90 90 90 90 81 90 3 90 39 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 92 90 90 90 90 90 90 90 90 98 90 90 90 90 90 90 90 90 90 90 90 90 90 54 90 90 90 90 90 62 90 90 91 90 90 90 90 90 90 91 90 90 90 90 90 90 90 3 90 90 90 90 90 90 90 2 90 90 90 90 90 90 90 90 90 2 90 90 90 90 90", "output": "60" }, { "input": "100 10\n10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 6 10 10 10 10 10 10 78 90 61 40 87 39 91 50 64 30 10 24 10 55 28 11 28 35 26 26 10 57 45 67 14 99 96 51 67 79 59 11 21 55 70 33 10 16 92 70 38 50 66 52 5 10 10 10 2 4 10 10 10 10 10 10 10 10 10 6 10 10 10 10 10 10 10 10 10 10 8 10 10 10 10 10", "output": "56" }, { "input": "100 90\n90 90 90 90 90 90 55 21 90 90 90 90 90 90 90 90 90 90 69 83 90 90 90 90 90 90 90 90 93 95 92 98 92 97 91 92 92 91 91 95 94 95 100 100 96 97 94 93 90 90 95 95 97 99 90 95 98 91 94 96 99 99 94 95 95 97 99 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 90 12 90 3 90 90 90 90 90 90 90", "output": "61" }, { "input": "100 49\n71 25 14 36 36 48 36 49 28 40 49 49 49 38 40 49 33 22 49 49 14 46 8 44 49 11 37 49 40 49 2 49 3 49 37 49 49 11 25 49 49 32 49 11 49 30 16 21 49 49 23 24 30 49 49 49 49 49 49 27 49 42 49 49 20 32 30 29 35 49 30 49 9 49 27 25 5 49 49 42 49 20 49 35 49 22 15 49 49 49 19 49 29 28 13 49 22 7 6 24", "output": "99" }, { "input": "100 50\n38 68 9 6 50 18 19 50 50 20 33 34 43 50 24 50 50 2 50 50 50 50 50 21 30 50 41 40 50 50 50 50 50 7 50 21 19 23 1 50 24 50 50 50 25 50 50 50 50 50 50 50 7 24 28 18 50 5 43 50 20 50 13 50 50 16 50 3 2 24 50 50 18 5 50 4 50 50 38 50 33 49 12 33 11 14 50 50 50 33 50 50 50 50 50 50 7 4 50 50", "output": "99" }, { "input": "100 48\n8 6 23 47 29 48 48 48 48 48 48 26 24 48 48 48 3 48 27 28 41 45 9 29 48 48 48 48 48 48 48 48 48 48 47 23 48 48 48 5 48 22 40 48 48 48 20 48 48 57 48 32 19 48 33 2 4 19 48 48 39 48 16 48 48 44 48 48 48 48 29 14 25 43 46 7 48 19 30 48 18 8 39 48 30 47 35 18 48 45 48 48 30 13 48 48 48 17 9 48", "output": "99" }, { "input": "100 57\n57 9 57 4 43 57 57 57 57 26 57 18 57 57 57 57 57 57 57 47 33 57 57 43 57 57 55 57 14 57 57 4 1 57 57 57 57 57 46 26 57 57 57 57 57 57 57 39 57 57 57 5 57 12 11 57 57 57 25 37 34 57 54 18 29 57 39 57 5 57 56 34 57 24 7 57 57 57 2 57 57 57 57 1 55 39 19 57 57 57 57 21 3 40 13 3 57 57 62 57", "output": "99" }, { "input": "100 51\n51 51 38 51 51 45 51 51 51 18 51 36 51 19 51 26 37 51 11 51 45 34 51 21 51 51 33 51 6 51 51 51 21 47 51 13 51 51 30 29 50 51 51 51 51 51 51 45 14 51 2 51 51 23 9 51 50 23 51 29 34 51 40 32 1 36 31 51 11 51 51 47 51 51 51 51 51 51 51 50 39 51 14 4 4 12 3 11 51 51 51 51 41 51 51 51 49 37 5 93", "output": "99" }, { "input": "100 50\n87 91 95 73 50 50 16 97 39 24 58 50 33 89 42 37 50 50 12 71 3 55 50 50 80 10 76 50 52 36 88 44 66 69 86 71 77 50 72 50 21 55 50 50 78 61 75 89 65 2 50 69 62 47 11 92 97 77 41 31 55 29 35 51 36 48 50 91 92 86 50 36 50 94 51 74 4 27 55 63 50 36 87 50 67 7 65 75 20 96 88 50 41 73 35 51 66 21 29 33", "output": "3" }, { "input": "100 50\n50 37 28 92 7 76 50 50 50 76 100 57 50 50 50 32 76 50 8 72 14 8 50 91 67 50 55 82 50 50 24 97 88 50 59 61 68 86 44 15 61 67 88 50 40 50 36 99 1 23 63 50 88 59 76 82 99 76 68 50 50 30 31 68 57 98 71 12 15 60 35 79 90 6 67 50 50 50 50 68 13 6 50 50 16 87 84 50 67 67 50 64 50 58 50 50 77 51 50 51", "output": "3" }, { "input": "100 50\n43 50 50 91 97 67 6 50 86 50 76 60 50 59 4 56 11 38 49 50 37 50 50 20 60 47 33 54 95 58 22 50 77 77 72 9 57 40 81 57 95 50 81 63 62 76 13 87 50 39 74 69 50 99 63 1 11 62 84 31 97 99 56 73 70 36 45 100 28 91 93 9 19 52 73 50 83 58 84 52 86 12 50 44 64 52 97 50 12 71 97 52 87 66 83 66 86 50 9 49", "output": "6" }, { "input": "88 10\n10 8 1 10 10 1 3 7 10 5 8 8 10 2 7 10 10 10 10 10 1 10 10 10 10 1 2 9 10 9 10 10 10 64 100 25 10 12 9 52 13 8 10 56 10 4 10 7 10 3 10 79 74 8 73 10 10 10 9 10 3 5 10 10 10 5 1 10 10 4 3 10 10 10 4 10 6 4 10 10 10 10 3 3 8 5 6 8", "output": "66" }, { "input": "100 50\n80 39 33 69 75 50 23 88 50 50 67 90 87 50 29 15 55 32 60 50 50 50 38 95 62 50 50 88 8 97 45 50 42 12 22 93 49 50 24 50 50 71 60 4 50 72 57 57 50 50 50 83 69 17 1 31 72 55 50 11 50 80 93 41 91 94 20 60 50 50 51 48 53 56 76 73 50 72 19 98 50 50 50 50 50 28 48 45 62 11 16 67 93 88 63 50 50 66 48 95", "output": "0" }, { "input": "100 50\n70 50 38 50 38 50 32 30 50 31 26 42 50 33 34 50 50 50 28 21 50 44 50 47 50 50 9 40 50 50 50 50 50 42 50 50 16 50 50 3 24 50 50 50 4 26 50 2 50 50 33 1 27 50 50 50 8 29 50 23 33 50 6 29 50 50 15 50 50 50 32 50 43 50 50 50 31 50 4 50 50 31 50 50 31 16 50 17 50 17 31 13 25 16 50 10 50 47 50 66", "output": "0" }, { "input": "2 8\n8 8", "output": "2" }, { "input": "1 6\n3", "output": "1" }, { "input": "1 5\n5", "output": "1" } ]

1,615,760,451

2,147,483,647

PyPy 3

OK

TESTS

48

109

0

a,b = map(int,input().split()) l= [int(i) for i in input().split()] c=0 while len(l)>0: premier = l[0] last= l[-1] if premier<=b: c+=1 del l[0] elif last<=b: c+=1 del l[-1] else: break print(c)

Title: Mishka and Contest Time Limit: None seconds Memory Limit: None megabytes Problem Description: Mishka started participating in a programming contest. There are $n$ problems in the contest. Mishka's problem-solving skill is equal to $k$. Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list. Mishka cannot solve a problem with difficulty greater than $k$. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by $1$. Mishka stops when he is unable to solve any problem from any end of the list. How many problems can Mishka solve? Input Specification: The first line of input contains two integers $n$ and $k$ ($1 \le n, k \le 100$) — the number of problems in the contest and Mishka's problem-solving skill. The second line of input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$), where $a_i$ is the difficulty of the $i$-th problem. The problems are given in order from the leftmost to the rightmost in the list. Output Specification: Print one integer — the maximum number of problems Mishka can solve. Demo Input: ['8 4\n4 2 3 1 5 1 6 4\n', '5 2\n3 1 2 1 3\n', '5 100\n12 34 55 43 21\n'] Demo Output: ['5\n', '0\n', '5\n'] Note: In the first example, Mishka can solve problems in the following order: $[4, 2, 3, 1, 5, 1, 6, 4] \rightarrow [2, 3, 1, 5, 1, 6, 4] \rightarrow [2, 3, 1, 5, 1, 6] \rightarrow [3, 1, 5, 1, 6] \rightarrow [1, 5, 1, 6] \rightarrow [5, 1, 6]$, so the number of solved problems will be equal to $5$. In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than $k$. In the third example, Mishka's solving skill is so amazing that he can solve all the problems.

```python a,b = map(int,input().split()) l= [int(i) for i in input().split()] c=0 while len(l)>0: premier = l[0] last= l[-1] if premier<=b: c+=1 del l[0] elif last<=b: c+=1 del l[-1] else: break print(c) ```

3

492

A

Vanya and Cubes

PROGRAMMING

800

[ "implementation" ]

null

Vanya got *n* cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1<=+<=2<==<=3 cubes, the third level must have 1<=+<=2<=+<=3<==<=6 cubes, and so on. Thus, the *i*-th level of the pyramid must have 1<=+<=2<=+<=...<=+<=(*i*<=-<=1)<=+<=*i* cubes. Vanya wants to know what is the maximum height of the pyramid that he can make using the given cubes.

The first line contains integer *n* (1<=≤<=*n*<=≤<=104) — the number of cubes given to Vanya.

Print the maximum possible height of the pyramid in the single line.

[ "1\n", "25\n" ]

[ "1\n", "4\n" ]

Illustration to the second sample:

500

[ { "input": "1", "output": "1" }, { "input": "25", "output": "4" }, { "input": "2", "output": "1" }, { "input": "4115", "output": "28" }, { "input": "9894", "output": "38" }, { "input": "7969", "output": "35" }, { "input": "6560", "output": "33" }, { "input": "4", "output": "2" }, { "input": "3", "output": "1" }, { "input": "5", "output": "2" }, { "input": "19", "output": "3" }, { "input": "20", "output": "4" }, { "input": "9880", "output": "38" }, { "input": "9879", "output": "37" }, { "input": "7770", "output": "35" }, { "input": "7769", "output": "34" }, { "input": "2925", "output": "25" }, { "input": "220", "output": "10" }, { "input": "219", "output": "9" }, { "input": "3046", "output": "25" }, { "input": "7590", "output": "34" }, { "input": "1014", "output": "17" }, { "input": "7142", "output": "34" }, { "input": "9999", "output": "38" }, { "input": "10000", "output": "38" } ]

1,690,832,715

2,147,483,647

Python 3

OK

TESTS

25

46

0

n = int(input()) l ,r = 0 ,n**0.5 while l <= r : mid = (l + r) //2 c = 0 c1 = True for i in range(1,int(mid) + 1): c += i * (i + 1) // 2 if c > n : r = mid - 1 c1 = False break if c > n: r = mid - 1 else: if c1 : ans = mid l = mid + 1 else: l = mid + 1 print(int(ans))

Title: Vanya and Cubes Time Limit: None seconds Memory Limit: None megabytes Problem Description: Vanya got *n* cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1<=+<=2<==<=3 cubes, the third level must have 1<=+<=2<=+<=3<==<=6 cubes, and so on. Thus, the *i*-th level of the pyramid must have 1<=+<=2<=+<=...<=+<=(*i*<=-<=1)<=+<=*i* cubes. Vanya wants to know what is the maximum height of the pyramid that he can make using the given cubes. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=104) — the number of cubes given to Vanya. Output Specification: Print the maximum possible height of the pyramid in the single line. Demo Input: ['1\n', '25\n'] Demo Output: ['1\n', '4\n'] Note: Illustration to the second sample:

```python n = int(input()) l ,r = 0 ,n**0.5 while l <= r : mid = (l + r) //2 c = 0 c1 = True for i in range(1,int(mid) + 1): c += i * (i + 1) // 2 if c > n : r = mid - 1 c1 = False break if c > n: r = mid - 1 else: if c1 : ans = mid l = mid + 1 else: l = mid + 1 print(int(ans)) ```

3

373

B

Making Sequences is Fun

PROGRAMMING

1,600

[ "binary search", "implementation", "math" ]

null

We'll define *S*(*n*) for positive integer *n* as follows: the number of the *n*'s digits in the decimal base. For example, *S*(893)<==<=3, *S*(114514)<==<=6. You want to make a consecutive integer sequence starting from number *m* (*m*,<=*m*<=+<=1,<=...). But you need to pay *S*(*n*)·*k* to add the number *n* to the sequence. You can spend a cost up to *w*, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length.

The first line contains three integers *w* (1<=≤<=*w*<=≤<=1016), *m* (1<=≤<=*m*<=≤<=1016), *k* (1<=≤<=*k*<=≤<=109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.

The first line should contain a single integer — the answer to the problem.

[ "9 1 1\n", "77 7 7\n", "114 5 14\n", "1 1 2\n" ]

[ "9\n", "7\n", "6\n", "0\n" ]

none

1,000

[ { "input": "9 1 1", "output": "9" }, { "input": "77 7 7", "output": "7" }, { "input": "114 5 14", "output": "6" }, { "input": "1 1 2", "output": "0" }, { "input": "462 183 8", "output": "19" }, { "input": "462 183 8", "output": "19" }, { "input": "462 183 8", "output": "19" }, { "input": "462 183 8", "output": "19" }, { "input": "462 183 8", "output": "19" }, { "input": "462 183 8", "output": "19" }, { "input": "462 183 8", "output": "19" }, { "input": "10000000000000000 1 1", "output": "674074074074073" }, { "input": "2155990066796462 2710473050636183 563261158", "output": "239230" }, { "input": "552719169048748 7822730034794389 374302919", "output": "92291" }, { "input": "6895788044242644 3474119895793364 732614708", "output": "588285" }, { "input": "9230573804495452 8577408935470783 90893866", "output": "6347082" }, { "input": "5363062262667637 2932858345469643 449197576", "output": "746200" }, { "input": "1951414609070432 8979282171178729 260239468", "output": "468658" }, { "input": "6289344232651169 4170875805886064 618522710", "output": "635520" }, { "input": "111984789523940 8017182602114316 976839488", "output": "7164" }, { "input": "3663662721733869 4845943245608254 787880219", "output": "290626" }, { "input": "10000000000000000 10000000000000000 1", "output": "588235294117647" }, { "input": "10000000000000000 9999999999999999 1", "output": "588235294117647" }, { "input": "9999999999999999 1 1", "output": "674074074074073" }, { "input": "3 1 4", "output": "0" }, { "input": "9999999999999998 1 1", "output": "674074074074072" }, { "input": "1 1000000000000000 1", "output": "0" }, { "input": "1 1000000000000000 1000000000", "output": "0" }, { "input": "10000000000000000 10000000000000000 1000000000", "output": "588235" }, { "input": "10000000000000000 10000000000000000 1", "output": "588235294117647" }, { "input": "121212121 3434343434 56", "output": "216450" }, { "input": "1 1 1", "output": "1" }, { "input": "98 55 1", "output": "47" }, { "input": "1 10000000000000000 123456", "output": "0" }, { "input": "10000000000000000 1000000000000001 1000000000", "output": "625000" } ]

1,584,745,532

2,147,483,647

Python 3

TIME_LIMIT_EXCEEDED

TESTS

11

2,000

0

from itertools import count w, m, k = tuple(map(int, input().split())) costo_maximo = w/k costo = 0 largo = 0 S = len(str(m)) max_pot = 10 while max_pot <= m: max_pot *= 10 espera = max_pot - m for n in count(m): costo += S if costo > costo_maximo: break largo += 1 espera -= 1 if not espera: S += 1 espera = 9*n print(largo)

Title: Making Sequences is Fun Time Limit: None seconds Memory Limit: None megabytes Problem Description: We'll define *S*(*n*) for positive integer *n* as follows: the number of the *n*'s digits in the decimal base. For example, *S*(893)<==<=3, *S*(114514)<==<=6. You want to make a consecutive integer sequence starting from number *m* (*m*,<=*m*<=+<=1,<=...). But you need to pay *S*(*n*)·*k* to add the number *n* to the sequence. You can spend a cost up to *w*, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input Specification: The first line contains three integers *w* (1<=≤<=*w*<=≤<=1016), *m* (1<=≤<=*m*<=≤<=1016), *k* (1<=≤<=*k*<=≤<=109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output Specification: The first line should contain a single integer — the answer to the problem. Demo Input: ['9 1 1\n', '77 7 7\n', '114 5 14\n', '1 1 2\n'] Demo Output: ['9\n', '7\n', '6\n', '0\n'] Note: none

```python from itertools import count w, m, k = tuple(map(int, input().split())) costo_maximo = w/k costo = 0 largo = 0 S = len(str(m)) max_pot = 10 while max_pot <= m: max_pot *= 10 espera = max_pot - m for n in count(m): costo += S if costo > costo_maximo: break largo += 1 espera -= 1 if not espera: S += 1 espera = 9*n print(largo) ```

0

540

A

Combination Lock

PROGRAMMING

800

[ "implementation" ]

null

Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock. The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn some disks so that the combination of digits on the disks forms a secret combination. In one move, he can rotate one disk one digit forwards or backwards. In particular, in one move he can go from digit 0 to digit 9 and vice versa. What minimum number of actions does he need for that?

The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock. The second line contains a string of *n* digits — the original state of the disks. The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock.

Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock.

[ "5\n82195\n64723\n" ]

[ "13\n" ]

In the sample he needs 13 moves: - 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32c4d555e498d2b24d2f70f36a.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 3 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/cc2275d9252aae35a6867c6a5b4ba7596e9a7626.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 4 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b100aea470fcaaab4e9529b234ba0d7875943c10.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 5 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/eb2cbe4324cebca65b85816262a85e473cd65967.png" style="max-width: 100.0%;max-height: 100.0%;"/>

500

[ { "input": "5\n82195\n64723", "output": "13" }, { "input": "12\n102021090898\n010212908089", "output": "16" }, { "input": "1\n8\n1", "output": "3" }, { "input": "2\n83\n57", "output": "7" }, { "input": "10\n0728592530\n1362615763", "output": "27" }, { "input": "100\n4176196363694273682807653052945037727131821799902563705176501742060696655282954944720643131654235909\n3459912084922154505910287499879975659298239371519889866585472674423008837878123067103005344986554746", "output": "245" }, { "input": "1\n8\n1", "output": "3" }, { "input": "2\n83\n57", "output": "7" }, { "input": "3\n607\n684", "output": "5" }, { "input": "4\n0809\n0636", "output": "8" }, { "input": "5\n84284\n08941", "output": "16" }, { "input": "25\n8037856825987124762280548\n9519431339078678836940020", "output": "72" }, { "input": "125\n23269567683904664184142384849516523616863461607751021071772615078579713054027902974007001544768640273491193035874486891541257\n47635110303703399505805044019026243695451609639556649012447370081552870340011971572363458960190590266459684717415349529509024", "output": "305" }, { "input": "5\n84284\n08941", "output": "16" }, { "input": "25\n8037856825987124762285484\n9519431339078678836940202", "output": "74" }, { "input": "125\n23269567689466418414238845152168634610771021717726157879713054270294007001544768647391193035874486891412573389247025830678706\n47635110307339950580504010224954516093956649124473708152870340117152363458960190596659684717415349529090241694059599629136831", "output": "357" }, { "input": "5\n84284\n08941", "output": "16" }, { "input": "25\n8378525987476228048406972\n9194339078883694020217816", "output": "55" }, { "input": "125\n23269576839046618414238484916523616863461607750210717761078579713054027902974007015447686027349193035874486891541257338624472\n47635103037033950580504401926243695451609639556490124437081552870340011971572363489601905026645984717415349529509024169604599", "output": "274" }, { "input": "1\n0\n0", "output": "0" }, { "input": "1\n7\n7", "output": "0" }, { "input": "1\n0\n5", "output": "5" }, { "input": "1\n2\n7", "output": "5" }, { "input": "1\n7\n9", "output": "2" }, { "input": "1\n9\n7", "output": "2" }, { "input": "1\n2\n9", "output": "3" }, { "input": "1\n9\n2", "output": "3" }, { "input": "25\n3164978461316464614169874\n9413979197249127496597357", "output": "66" }, { "input": "4\n9999\n9999", "output": "0" }, { "input": "2\n11\n11", "output": "0" } ]

1,647,151,476

2,147,483,647

PyPy 3

OK

TESTS

43

93

0

n = int(input()) a = (input()) b = (input()) sum = 0 for i in range(n): x = min(abs(int(a[i])-int(b[i])),(10-abs(int(a[i])-int(b[i])))) sum+=x print(sum)

Title: Combination Lock Time Limit: None seconds Memory Limit: None megabytes Problem Description: Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock. The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn some disks so that the combination of digits on the disks forms a secret combination. In one move, he can rotate one disk one digit forwards or backwards. In particular, in one move he can go from digit 0 to digit 9 and vice versa. What minimum number of actions does he need for that? Input Specification: The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock. The second line contains a string of *n* digits — the original state of the disks. The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock. Output Specification: Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock. Demo Input: ['5\n82195\n64723\n'] Demo Output: ['13\n'] Note: In the sample he needs 13 moves: - 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32c4d555e498d2b24d2f70f36a.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 3 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/cc2275d9252aae35a6867c6a5b4ba7596e9a7626.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 4 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b100aea470fcaaab4e9529b234ba0d7875943c10.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 5 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/eb2cbe4324cebca65b85816262a85e473cd65967.png" style="max-width: 100.0%;max-height: 100.0%;"/>

```python n = int(input()) a = (input()) b = (input()) sum = 0 for i in range(n): x = min(abs(int(a[i])-int(b[i])),(10-abs(int(a[i])-int(b[i])))) sum+=x print(sum) ```

3

509

A

Maximum in Table

PROGRAMMING

800

[ "brute force", "implementation" ]

null

An *n*<=×<=*n* table *a* is defined as follows: - The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula *a**i*,<=*j*<==<=*a**i*<=-<=1,<=*j*<=+<=*a**i*,<=*j*<=-<=1. These conditions define all the values in the table. You are given a number *n*. You need to determine the maximum value in the *n*<=×<=*n* table defined by the rules above.

The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table.

Print a single line containing a positive integer *m* — the maximum value in the table.

[ "1\n", "5\n" ]

[ "1", "70" ]

In the second test the rows of the table look as follows:

0

[ { "input": "1", "output": "1" }, { "input": "5", "output": "70" }, { "input": "2", "output": "2" }, { "input": "3", "output": "6" }, { "input": "4", "output": "20" }, { "input": "6", "output": "252" }, { "input": "7", "output": "924" }, { "input": "9", "output": "12870" }, { "input": "10", "output": "48620" }, { "input": "8", "output": "3432" } ]

1,594,894,447

2,147,483,647

Python 3

OK

TESTS

10

93

6,656,000

n = int(input()) if n == 1: print("1") else: li2 = [1]*n maxim = 1 j = n-1 while j>0: for i in range(1,len(li2)): li2[i] = li2[i]+li2[i-1] maxim = max(maxim,li2[i]) j = j-1 print(maxim)

Title: Maximum in Table Time Limit: None seconds Memory Limit: None megabytes Problem Description: An *n*<=×<=*n* table *a* is defined as follows: - The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula *a**i*,<=*j*<==<=*a**i*<=-<=1,<=*j*<=+<=*a**i*,<=*j*<=-<=1. These conditions define all the values in the table. You are given a number *n*. You need to determine the maximum value in the *n*<=×<=*n* table defined by the rules above. Input Specification: The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. Output Specification: Print a single line containing a positive integer *m* — the maximum value in the table. Demo Input: ['1\n', '5\n'] Demo Output: ['1', '70'] Note: In the second test the rows of the table look as follows:

```python n = int(input()) if n == 1: print("1") else: li2 = [1]*n maxim = 1 j = n-1 while j>0: for i in range(1,len(li2)): li2[i] = li2[i]+li2[i-1] maxim = max(maxim,li2[i]) j = j-1 print(maxim) ```

3

583

B

Robot's Task

PROGRAMMING

1,200

[ "greedy", "implementation" ]

null

Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to collect at least *a**i* any pieces of information from the other computers. Doc can hack the computer only if he is right next to it. The robot is assembled using modern technologies and can move along the line of computers in either of the two possible directions, but the change of direction requires a large amount of resources from Doc. Tell the minimum number of changes of direction, which the robot will have to make to collect all *n* parts of information if initially it is next to computer with number 1. It is guaranteed that there exists at least one sequence of the robot's actions, which leads to the collection of all information. Initially Doc doesn't have any pieces of information.

The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information.

Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information.

[ "3\n0 2 0\n", "5\n4 2 3 0 1\n", "7\n0 3 1 0 5 2 6\n" ]

[ "1\n", "3\n", "2\n" ]

In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece. In the second sample to collect all the pieces of information in the optimal manner, Doc can go to the fourth computer and get the piece of information, then go to the fifth computer with one piece and get another one, then go to the second computer in the same manner, then to the third one and finally, to the first one. Changes of direction will take place before moving from the fifth to the second computer, then from the second to the third computer, then from the third to the first computer. In the third sample the optimal order of collecting parts from computers can look like that: 1->3->4->6->2->5->7.

1,000

[ { "input": "3\n0 2 0", "output": "1" }, { "input": "5\n4 2 3 0 1", "output": "3" }, { "input": "7\n0 3 1 0 5 2 6", "output": "2" }, { "input": "1\n0", "output": "0" }, { "input": "2\n0 1", "output": "0" }, { "input": "10\n0 0 0 0 0 0 0 0 0 0", "output": "0" }, { "input": "3\n0 2 1", "output": "1" }, { "input": "10\n7 1 9 3 5 8 6 0 2 4", "output": "9" }, { "input": "10\n1 3 5 7 9 8 6 4 2 0", "output": "9" }, { "input": "10\n5 0 0 1 3 2 2 2 5 7", "output": "1" }, { "input": "10\n8 6 5 3 9 7 1 4 2 0", "output": "8" }, { "input": "10\n1 2 4 5 0 1 3 7 1 4", "output": "2" }, { "input": "10\n3 4 8 9 5 1 2 0 6 7", "output": "6" }, { "input": "10\n2 2 0 0 6 2 9 0 2 0", "output": "2" }, { "input": "10\n1 7 5 3 2 6 0 8 4 9", "output": "8" }, { "input": "9\n1 3 8 6 2 4 5 0 7", "output": "7" }, { "input": "9\n1 3 5 7 8 6 4 2 0", "output": "8" }, { "input": "9\n2 4 3 1 3 0 5 4 3", "output": "3" }, { "input": "9\n3 5 6 8 7 0 4 2 1", "output": "5" }, { "input": "9\n2 0 8 1 0 3 0 5 3", "output": "2" }, { "input": "9\n6 2 3 7 4 8 5 1 0", "output": "4" }, { "input": "9\n3 1 5 6 0 3 2 0 0", "output": "2" }, { "input": "9\n2 6 4 1 0 8 5 3 7", "output": "7" }, { "input": "100\n27 20 18 78 93 38 56 2 48 75 36 88 96 57 69 10 25 74 68 86 65 85 66 14 22 12 43 80 99 34 42 63 61 71 77 15 37 54 21 59 23 94 28 30 50 84 62 76 47 16 26 64 82 92 72 53 17 11 41 91 35 83 79 95 67 13 1 7 3 4 73 90 8 19 33 58 98 32 39 45 87 52 60 46 6 44 49 70 51 9 5 29 31 24 40 97 81 0 89 55", "output": "69" }, { "input": "100\n1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 98 96 94 92 90 88 86 84 82 80 78 76 74 72 70 68 66 64 62 60 58 56 54 52 50 48 46 44 42 40 38 36 34 32 30 28 26 24 22 20 18 16 14 12 10 8 6 4 2 0", "output": "99" }, { "input": "100\n13 89 81 0 62 1 59 92 29 13 1 37 2 8 53 15 20 34 12 70 0 85 97 55 84 60 37 54 14 65 22 69 30 22 95 44 59 85 50 80 9 71 91 93 74 21 11 78 28 21 40 81 76 24 26 60 48 85 61 68 89 76 46 73 34 52 98 29 4 38 94 51 5 55 6 27 74 27 38 37 82 70 44 89 51 59 30 37 15 55 63 78 42 39 71 43 4 10 2 13", "output": "21" }, { "input": "100\n1 3 5 7 58 11 13 15 17 19 45 23 25 27 29 31 33 35 37 39 41 43 21 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 81 79 83 85 87 89 91 93 95 97 48 98 96 94 92 90 88 44 84 82 80 78 76 74 72 70 68 66 64 62 60 9 56 54 52 50 99 46 86 42 40 38 36 34 32 30 28 26 24 22 20 18 16 14 12 10 8 6 4 2 0", "output": "96" }, { "input": "100\n32 47 74 8 14 4 12 68 18 0 44 80 14 38 6 57 4 72 69 3 21 78 74 22 39 32 58 63 34 33 23 6 39 11 6 12 18 4 0 11 20 28 16 1 22 12 57 55 13 48 43 1 50 18 87 6 11 45 38 67 37 14 7 56 6 41 1 55 5 73 78 64 38 18 38 8 37 0 18 61 37 58 58 62 86 5 0 2 15 43 34 61 2 21 15 9 69 1 11 24", "output": "4" }, { "input": "100\n40 3 55 7 6 77 13 46 17 64 21 54 25 27 91 41 1 15 37 82 23 43 42 47 26 95 53 5 11 59 61 9 78 67 69 58 73 0 36 79 60 83 2 87 63 33 71 89 97 99 98 93 56 92 19 88 86 84 39 28 65 20 34 76 51 94 66 12 62 49 96 72 24 52 48 50 44 35 74 31 38 57 81 32 22 80 70 29 30 18 68 16 14 90 10 8 85 4 45 75", "output": "75" }, { "input": "100\n34 16 42 21 84 27 11 7 82 16 95 39 36 64 26 0 38 37 2 2 16 56 16 61 55 42 26 5 61 8 30 20 19 15 9 78 5 34 15 0 3 17 36 36 1 5 4 26 18 0 14 25 7 5 91 7 43 26 79 37 17 27 40 55 66 7 0 2 16 23 68 35 2 5 9 21 1 7 2 9 4 3 22 15 27 6 0 47 5 0 12 9 20 55 36 10 6 8 5 1", "output": "3" }, { "input": "100\n35 53 87 49 13 24 93 20 5 11 31 32 40 52 96 46 1 25 66 69 28 88 84 82 70 9 75 39 26 21 18 29 23 57 90 16 48 22 95 0 58 43 7 73 8 62 63 30 64 92 79 3 6 94 34 12 76 99 67 55 56 97 14 91 68 36 44 78 41 71 86 89 47 74 4 45 98 37 80 33 83 27 42 59 72 54 17 60 51 81 15 77 65 50 10 85 61 19 38 2", "output": "67" }, { "input": "99\n89 96 56 31 32 14 9 66 87 34 69 5 92 54 41 52 46 30 22 26 16 18 20 68 62 73 90 43 79 33 58 98 37 45 10 78 94 51 19 0 91 39 28 47 17 86 3 61 77 7 15 64 55 83 65 71 97 88 6 48 24 11 8 42 81 4 63 93 50 74 35 12 95 27 53 82 29 85 84 60 72 40 36 57 23 13 38 59 49 1 75 44 76 2 21 25 70 80 67", "output": "75" }, { "input": "99\n1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 98 96 94 92 90 88 86 84 82 80 78 76 74 72 70 68 66 64 62 60 58 56 54 52 50 48 46 44 42 40 38 36 34 32 30 28 26 24 22 20 18 16 14 12 10 8 6 4 2 0", "output": "98" }, { "input": "99\n82 7 6 77 17 28 90 3 68 12 63 60 24 20 4 81 71 85 57 45 11 84 3 91 49 34 89 82 0 50 48 88 36 76 36 5 62 48 20 2 20 45 69 27 37 62 42 31 57 51 92 84 89 25 7 62 12 23 23 56 30 90 27 10 77 58 48 38 56 68 57 15 33 1 34 67 16 47 75 70 69 28 38 16 5 61 85 76 44 90 37 22 77 94 55 1 97 8 69", "output": "22" }, { "input": "99\n1 51 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 42 43 45 47 49 3 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 98 96 94 92 90 88 86 84 82 80 8 76 74 72 70 68 66 22 62 60 58 56 54 52 0 48 46 44 41 40 38 36 34 32 30 28 26 24 64 20 18 16 14 12 10 78 6 4 2 50", "output": "96" }, { "input": "99\n22 3 19 13 65 87 28 17 41 40 31 21 8 37 29 65 65 53 16 33 13 5 76 4 72 9 2 76 57 72 50 15 75 0 30 13 83 36 12 31 49 51 65 22 48 31 60 15 2 17 6 1 8 0 1 63 3 16 7 7 2 1 47 28 26 21 2 36 1 5 20 25 44 0 2 39 46 30 33 11 15 34 34 4 84 52 0 39 7 3 17 15 6 38 52 64 26 1 0", "output": "3" }, { "input": "99\n24 87 25 82 97 11 37 15 23 19 34 17 76 13 45 89 33 1 27 78 63 43 54 47 49 2 42 41 75 83 61 90 65 67 21 71 60 57 77 62 81 58 85 69 3 91 68 55 72 93 29 94 66 16 88 86 84 53 14 39 35 44 9 70 80 92 56 79 74 5 64 31 52 50 48 46 51 59 40 38 36 96 32 30 28 95 7 22 20 18 26 73 12 10 8 6 4 98 0", "output": "74" }, { "input": "99\n22 14 0 44 6 17 6 6 37 45 0 48 19 8 57 8 10 0 3 12 25 2 5 53 9 49 15 6 38 14 9 40 38 22 27 12 64 10 11 35 89 19 46 39 12 24 48 0 52 1 27 27 24 4 64 24 5 0 67 3 5 39 0 1 13 37 2 8 46 1 28 70 6 79 14 15 33 6 7 34 6 18 4 71 1 55 33 71 18 11 47 23 72 53 65 32 2 7 28", "output": "3" }, { "input": "99\n28 59 73 89 52 27 0 20 36 12 83 95 31 24 54 94 49 14 51 34 50 93 13 1 2 68 63 48 41 81 23 43 18 9 16 38 33 60 62 3 40 85 72 69 90 98 11 37 22 44 35 6 21 39 82 10 64 66 96 42 74 30 8 67 97 46 84 32 17 57 75 71 5 26 4 55 58 29 7 15 45 19 92 91 78 65 88 25 86 80 77 87 79 53 47 70 56 76 61", "output": "63" } ]

1,486,648,170

2,147,483,647

Python 3

OK

TESTS

56

233

4,608,000

n = int(input()) comp = list(map(int,input().split())) seen = set() pieces = 0 direction = 1 res = 0 def begend(dire): if dire == 1: return (0,n) else: return(n-1,-1) while len(seen)<n: for k in range(begend(direction)[0],begend(direction)[1],direction): if (not k in seen and comp[k] <= pieces): seen.add(k) pieces += 1 direction *= -1 res += 1 print(res-1)

Title: Robot's Task Time Limit: None seconds Memory Limit: None megabytes Problem Description: Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to collect at least *a**i* any pieces of information from the other computers. Doc can hack the computer only if he is right next to it. The robot is assembled using modern technologies and can move along the line of computers in either of the two possible directions, but the change of direction requires a large amount of resources from Doc. Tell the minimum number of changes of direction, which the robot will have to make to collect all *n* parts of information if initially it is next to computer with number 1. It is guaranteed that there exists at least one sequence of the robot's actions, which leads to the collection of all information. Initially Doc doesn't have any pieces of information. Input Specification: The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information. Output Specification: Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information. Demo Input: ['3\n0 2 0\n', '5\n4 2 3 0 1\n', '7\n0 3 1 0 5 2 6\n'] Demo Output: ['1\n', '3\n', '2\n'] Note: In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece. In the second sample to collect all the pieces of information in the optimal manner, Doc can go to the fourth computer and get the piece of information, then go to the fifth computer with one piece and get another one, then go to the second computer in the same manner, then to the third one and finally, to the first one. Changes of direction will take place before moving from the fifth to the second computer, then from the second to the third computer, then from the third to the first computer. In the third sample the optimal order of collecting parts from computers can look like that: 1->3->4->6->2->5->7.

```python n = int(input()) comp = list(map(int,input().split())) seen = set() pieces = 0 direction = 1 res = 0 def begend(dire): if dire == 1: return (0,n) else: return(n-1,-1) while len(seen)<n: for k in range(begend(direction)[0],begend(direction)[1],direction): if (not k in seen and comp[k] <= pieces): seen.add(k) pieces += 1 direction *= -1 res += 1 print(res-1) ```

3

266

A

Stones on the Table

PROGRAMMING

800

[ "implementation" ]

null

There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.

The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table. The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue.

Print a single integer — the answer to the problem.

[ "3\nRRG\n", "5\nRRRRR\n", "4\nBRBG\n" ]

[ "1\n", "4\n", "0\n" ]

none

500

[ { "input": "3\nRRG", "output": "1" }, { "input": "5\nRRRRR", "output": "4" }, { "input": "4\nBRBG", "output": "0" }, { "input": "1\nB", "output": "0" }, { "input": "2\nBG", "output": "0" }, { "input": "3\nBGB", "output": "0" }, { "input": "4\nRBBR", "output": "1" }, { "input": "5\nRGGBG", "output": "1" }, { "input": "10\nGGBRBRGGRB", "output": "2" }, { "input": "50\nGRBGGRBRGRBGGBBBBBGGGBBBBRBRGBRRBRGBBBRBBRRGBGGGRB", "output": "18" }, { "input": "15\nBRRBRGGBBRRRRGR", "output": "6" }, { "input": "20\nRRGBBRBRGRGBBGGRGRRR", "output": "6" }, { "input": "25\nBBGBGRBGGBRRBGRRBGGBBRBRB", "output": "6" }, { "input": "30\nGRGGGBGGRGBGGRGRBGBGBRRRRRRGRB", "output": "9" }, { "input": "35\nGBBGBRGBBGGRBBGBRRGGRRRRRRRBRBBRRGB", "output": "14" }, { "input": "40\nGBBRRGBGGGRGGGRRRRBRBGGBBGGGBGBBBBBRGGGG", "output": "20" }, { "input": "45\nGGGBBRBBRRGRBBGGBGRBRGGBRBRGBRRGBGRRBGRGRBRRG", "output": "11" }, { "input": "50\nRBGGBGGRBGRBBBGBBGRBBBGGGRBBBGBBBGRGGBGGBRBGBGRRGG", "output": "17" }, { "input": "50\nGGGBBRGGGGGRRGGRBGGRGBBRBRRBGRGBBBGBRBGRGBBGRGGBRB", "output": "16" }, { "input": "50\nGBGRGRRBRRRRRGGBBGBRRRBBBRBBBRRGRBBRGBRBGGRGRBBGGG", "output": "19" }, { "input": "10\nGRRBRBRBGR", "output": "1" }, { "input": "10\nBRBGBGRRBR", "output": "1" }, { "input": "20\nGBGBGGRRRRGRBBGRGRGR", "output": "5" }, { "input": "20\nRRGGRBBGBBRBGRRBRRBG", "output": "6" }, { "input": "30\nBGBRGBBBGRGBBRGBGRBBBRGGRRGRRB", "output": "8" }, { "input": "30\nBBBBGGBRBGBBGBGBGBGGGRGRRGGBBB", "output": "11" }, { "input": "40\nGBRRGRBGBRRGBRGGGBRGBGBRGBBRRGRGGBBGBGBB", "output": "9" }, { "input": "40\nBRGRGGRGGRBBRRRBRBBGGGRRGBGBBGRBBRGBRRGG", "output": "13" }, { "input": "50\nRBGBGGRRGGRGGBGBGRRBGGBGBRRBBGBBGBBBGBBRBBRBRBRGRG", "output": "13" }, { "input": "50\nRBRRGBGRRRBGRRBGRRGRBBRBBRRBRGGBRBRRBGGRBGGBRBRGRB", "output": "12" }, { "input": "2\nBB", "output": "1" }, { "input": "50\nRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR", "output": "49" }, { "input": "50\nRRRRRRRRGRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR", "output": "47" }, { "input": "50\nRRRRRRRRRRRRGGRRRRRRRRRBRRRRRRRRRRRRRRBBRRRRRRRRRR", "output": "43" } ]

1,695,219,475

2,147,483,647

Python 3

OK

TESTS

34

92

0

i=int(input()) x=input() count=0 for i in range(0,len(x)-1): if x[i]==x[i+1]: count+=1 print(count)

Title: Stones on the Table Time Limit: None seconds Memory Limit: None megabytes Problem Description: There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table. The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue. Output Specification: Print a single integer — the answer to the problem. Demo Input: ['3\nRRG\n', '5\nRRRRR\n', '4\nBRBG\n'] Demo Output: ['1\n', '4\n', '0\n'] Note: none

```python i=int(input()) x=input() count=0 for i in range(0,len(x)-1): if x[i]==x[i+1]: count+=1 print(count) ```

3

228

A

Is your horseshoe on the other hoof?

PROGRAMMING

800

[ "implementation" ]

null

Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades. Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party.

The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has. Consider all possible colors indexed with integers.

Print a single integer — the minimum number of horseshoes Valera needs to buy.

[ "1 7 3 3\n", "7 7 7 7\n" ]

[ "1\n", "3\n" ]

none

500

[ { "input": "1 7 3 3", "output": "1" }, { "input": "7 7 7 7", "output": "3" }, { "input": "81170865 673572653 756938629 995577259", "output": "0" }, { "input": "3491663 217797045 522540872 715355328", "output": "0" }, { "input": "251590420 586975278 916631563 586975278", "output": "1" }, { "input": "259504825 377489979 588153796 377489979", "output": "1" }, { "input": "652588203 931100304 931100304 652588203", "output": "2" }, { "input": "391958720 651507265 391958720 651507265", "output": "2" }, { "input": "90793237 90793237 90793237 90793237", "output": "3" }, { "input": "551651653 551651653 551651653 551651653", "output": "3" }, { "input": "156630260 609654355 668943582 973622757", "output": "0" }, { "input": "17061017 110313588 434481173 796661222", "output": "0" }, { "input": "24975422 256716298 337790533 690960249", "output": "0" }, { "input": "255635360 732742923 798648949 883146723", "output": "0" }, { "input": "133315691 265159773 734556507 265159773", "output": "1" }, { "input": "28442865 741657755 978106882 978106882", "output": "1" }, { "input": "131245479 174845575 497483467 131245479", "output": "1" }, { "input": "139159884 616215581 958341883 616215581", "output": "1" }, { "input": "147784432 947653080 947653080 947653080", "output": "2" }, { "input": "94055790 756126496 756126496 94055790", "output": "2" }, { "input": "240458500 511952208 240458500 511952208", "output": "2" }, { "input": "681828506 972810624 972810624 681828506", "output": "2" }, { "input": "454961014 454961014 454961014 454961014", "output": "3" }, { "input": "915819430 915819430 915819430 915819430", "output": "3" }, { "input": "671645142 671645142 671645142 671645142", "output": "3" }, { "input": "132503558 132503558 132503558 132503558", "output": "3" }, { "input": "5 5 999999 6", "output": "1" }, { "input": "1 1 2 5", "output": "1" }, { "input": "2 1 2 3", "output": "1" }, { "input": "1 1 3 5", "output": "1" }, { "input": "1 1 3 3", "output": "2" }, { "input": "2 2 2 1", "output": "2" }, { "input": "3 1 1 1", "output": "2" }, { "input": "1 2 2 2", "output": "2" } ]

1,690,903,629

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

2

62

0

x=list(map(int,input().split())) xx=[] for i in x: c=x.count(i) if c !=1 : xx.append(c) x.remove(i) for y in x: if y==i : x.remove(y) else: x.remove(i) print((sum(xx)-1))

Title: Is your horseshoe on the other hoof? Time Limit: None seconds Memory Limit: None megabytes Problem Description: Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades. Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party. Input Specification: The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has. Consider all possible colors indexed with integers. Output Specification: Print a single integer — the minimum number of horseshoes Valera needs to buy. Demo Input: ['1 7 3 3\n', '7 7 7 7\n'] Demo Output: ['1\n', '3\n'] Note: none

```python x=list(map(int,input().split())) xx=[] for i in x: c=x.count(i) if c !=1 : xx.append(c) x.remove(i) for y in x: if y==i : x.remove(y) else: x.remove(i) print((sum(xx)-1)) ```

0

841

A

Generous Kefa

PROGRAMMING

900

[ "brute force", "implementation" ]

null

One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all.

The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends. Next line contains string *s* — colors of baloons.

Answer to the task — «YES» or «NO» in a single line. You can choose the case (lower or upper) for each letter arbitrary.

[ "4 2\naabb\n", "6 3\naacaab\n" ]

[ "YES\n", "NO\n" ]

In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second. In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO».

500

[ { "input": "4 2\naabb", "output": "YES" }, { "input": "6 3\naacaab", "output": "NO" }, { "input": "2 2\nlu", "output": "YES" }, { "input": "5 3\novvoo", "output": "YES" }, { "input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf", "output": "YES" }, { "input": "81 3\nooycgmvvrophvcvpoupepqllqttwcocuilvyxbyumdmmfapvpnxhjhxfuagpnntonibicaqjvwfhwxhbv", "output": "NO" }, { "input": "100 100\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx", "output": "YES" }, { "input": "100 1\nnubcvvjvbjgnjsdkajimdcxvewbcytvfkihunycdrlconddlwgzjasjlsrttlrzsumzpyumpveglfqzmaofbshbojmwuwoxxvrod", "output": "NO" }, { "input": "100 13\nvyldolgryldqrvoldvzvrdrgorlorszddtgqvrlisxxrxdxlqtvtgsrqlzixoyrozxzogqxlsgzdddzqrgitxxritoolzolgrtvl", "output": "YES" }, { "input": "18 6\njzwtnkvmscqhmdlsxy", "output": "YES" }, { "input": "21 2\nfscegcqgzesefghhwcexs", "output": "NO" }, { "input": "32 22\ncduamsptaklqtxlyoutlzepxgyfkvngc", "output": "YES" }, { "input": "49 27\noxyorfnkzwsfllnyvdhdanppuzrnbxehugvmlkgeymqjlmfxd", "output": "YES" }, { "input": "50 24\nxxutzjwbggcwvxztttkmzovtmuwttzcbwoztttohzzxghuuthv", "output": "YES" }, { "input": "57 35\nglxshztrqqfyxthqamagvtmrdparhelnzrqvcwqxjytkbuitovkdxueul", "output": "YES" }, { "input": "75 23\nittttiiuitutuiiuuututiuttiuiuutuuuiuiuuuuttuuttuutuiiuiuiiuiitttuututuiuuii", "output": "NO" }, { "input": "81 66\nfeqevfqfebhvubhuuvfuqheuqhbeeuebehuvhffvbqvqvfbqqvvhevqffbqqhvvqhfeehuhqeqhueuqqq", "output": "YES" }, { "input": "93 42\npqeiafraiavfcteumflpcbpozcomlvpovlzdbldvoopnhdoeqaopzthiuzbzmeieiatthdeqovaqfipqlddllmfcrrnhb", "output": "YES" }, { "input": "100 53\nizszyqyndzwzyzgsdagdwdazadiawizinagqqgczaqqnawgijziziawzszdjdcqjdjqiwgadydcnqisaayjiqqsscwwzjzaycwwc", "output": "YES" }, { "input": "100 14\nvkrdcqbvkwuckpmnbydmczdxoagdsgtqxvhaxntdcxhjcrjyvukhugoglbmyoaqexgtcfdgemmizoniwtmisqqwcwfusmygollab", "output": "YES" }, { "input": "100 42\naaaaaiiiiaiiiaaiaiiaaiiiiiaaaaaiaiiiaiiiiaiiiaaaaaiiiaaaiiaaiiiaiiiaiaaaiaiiiiaaiiiaiiaiaiiaiiiaaaia", "output": "NO" }, { "input": "100 89\ntjbkmydejporbqhcbztkcumxjjgsrvxpuulbhzeeckkbchpbxwhedrlhjsabcexcohgdzouvsgphjdthpuqrlkgzxvqbuhqxdsmf", "output": "YES" }, { "input": "100 100\njhpyiuuzizhubhhpxbbhpyxzhbpjphzppuhiahihiappbhuypyauhizpbibzixjbzxzpbphuiaypyujappuxiyuyaajaxjupbahb", "output": "YES" }, { "input": "100 3\nsszoovvzysavsvzsozzvoozvysozsaszayaszasaysszzzysosyayyvzozovavzoyavsooaoyvoozvvozsaosvayyovazzszzssa", "output": "NO" }, { "input": "100 44\ndluthkxwnorabqsukgnxnvhmsmzilyulpursnxkdsavgemiuizbyzebhyjejgqrvuckhaqtuvdmpziesmpmewpvozdanjyvwcdgo", "output": "YES" }, { "input": "100 90\ntljonbnwnqounictqqctgonktiqoqlocgoblngijqokuquoolciqwnctgoggcbojtwjlculoikbggquqncittwnjbkgkgubnioib", "output": "YES" }, { "input": "100 79\nykxptzgvbqxlregvkvucewtydvnhqhuggdsyqlvcfiuaiddnrrnstityyehiamrggftsqyduwxpuldztyzgmfkehprrneyvtknmf", "output": "YES" }, { "input": "100 79\naagwekyovbviiqeuakbqbqifwavkfkutoriovgfmittulhwojaptacekdirgqoovlleeoqkkdukpadygfwavppohgdrmymmulgci", "output": "YES" }, { "input": "100 93\nearrehrehenaddhdnrdddhdahnadndheeennrearrhraharddreaeraddhehhhrdnredanndneheddrraaneerreedhnadnerhdn", "output": "YES" }, { "input": "100 48\nbmmaebaebmmmbbmxvmammbvvebvaemvbbaxvbvmaxvvmveaxmbbxaaemxmxvxxxvxbmmxaaaevvaxmvamvvmaxaxavexbmmbmmev", "output": "YES" }, { "input": "100 55\nhsavbkehaaesffaeeffakhkhfehbbvbeasahbbbvkesbfvkefeesesevbsvfkbffakvshsbkahfkfakebsvafkbvsskfhfvaasss", "output": "YES" }, { "input": "100 2\ncscffcffsccffsfsfffccssfsscfsfsssffcffsscfccssfffcfscfsscsccccfsssffffcfcfsfffcsfsccffscffcfccccfffs", "output": "NO" }, { "input": "100 3\nzrgznxgdpgfoiifrrrsjfuhvtqxjlgochhyemismjnanfvvpzzvsgajcbsulxyeoepjfwvhkqogiiwqxjkrpsyaqdlwffoockxnc", "output": "NO" }, { "input": "100 5\njbltyyfjakrjeodqepxpkjideulofbhqzxjwlarufwzwsoxhaexpydpqjvhybmvjvntuvhvflokhshpicbnfgsqsmrkrfzcrswwi", "output": "NO" }, { "input": "100 1\nfnslnqktlbmxqpvcvnemxcutebdwepoxikifkzaaixzzydffpdxodmsxjribmxuqhueifdlwzytxkklwhljswqvlejedyrgguvah", "output": "NO" }, { "input": "100 21\nddjenetwgwmdtjbpzssyoqrtirvoygkjlqhhdcjgeurqpunxpupwaepcqkbjjfhnvgpyqnozhhrmhfwararmlcvpgtnopvjqsrka", "output": "YES" }, { "input": "100 100\nnjrhiauqlgkkpkuvciwzivjbbplipvhslqgdkfnmqrxuxnycmpheenmnrglotzuyxycosfediqcuadklsnzjqzfxnbjwvfljnlvq", "output": "YES" }, { "input": "100 100\nbbbbbbbtbbttbtbbbttbttbtbbttttbbbtbttbbbtbttbtbbttttbbbbbtbbttbtbbtbttbbbtbtbtbtbtbtbbbttbbtbtbtbbtb", "output": "YES" }, { "input": "14 5\nfssmmsfffmfmmm", "output": "NO" }, { "input": "2 1\nff", "output": "NO" }, { "input": "2 1\nhw", "output": "YES" }, { "input": "2 2\nss", "output": "YES" }, { "input": "1 1\nl", "output": "YES" }, { "input": "100 50\nfffffttttttjjjuuuvvvvvdddxxxxwwwwgggbsssncccczzyyyyyhhhhhkrreeeeeeaaaaaiiillllllllooooqqqqqqmmpppppp", "output": "YES" }, { "input": "100 50\nbbbbbbbbgggggggggggaaaaaaaahhhhhhhhhhpppppppppsssssssrrrrrrrrllzzzzzzzeeeeeeekkkkkkkwwwwwwwwjjjjjjjj", "output": "YES" }, { "input": "100 50\nwwwwwwwwwwwwwwxxxxxxxxxxxxxxxxxxxxxxxxzzzzzzzzzzzzzzzzzzbbbbbbbbbbbbbbbbbbbbjjjjjjjjjjjjjjjjjjjjjjjj", "output": "YES" }, { "input": "100 80\nbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm", "output": "YES" }, { "input": "100 10\nbbttthhhhiiiiiiijjjjjvvvvpppssssseeeeeeewwwwgggkkkkkkkkmmmddddduuuzzzzllllnnnnnxxyyyffffccraaaaooooq", "output": "YES" }, { "input": "100 20\nssssssssssbbbbbbbhhhhhhhyyyyyyyzzzzzzzzzzzzcccccxxxxxxxxxxddddmmmmmmmeeeeeeejjjjjjjjjwwwwwwwtttttttt", "output": "YES" }, { "input": "1 2\na", "output": "YES" }, { "input": "3 1\nabb", "output": "NO" }, { "input": "2 1\naa", "output": "NO" }, { "input": "2 1\nab", "output": "YES" }, { "input": "6 2\naaaaaa", "output": "NO" }, { "input": "8 4\naaaaaaaa", "output": "NO" }, { "input": "4 2\naaaa", "output": "NO" }, { "input": "4 3\naaaa", "output": "NO" }, { "input": "1 3\na", "output": "YES" }, { "input": "4 3\nzzzz", "output": "NO" }, { "input": "4 1\naaaa", "output": "NO" }, { "input": "3 4\nabc", "output": "YES" }, { "input": "2 5\nab", "output": "YES" }, { "input": "2 4\nab", "output": "YES" }, { "input": "1 10\na", "output": "YES" }, { "input": "5 2\nzzzzz", "output": "NO" }, { "input": "53 26\naaaaaaaaaaaaaaaaaaaaaaaaaabbbbbbbbbbbbbbbbbbbbbbbbbbb", "output": "NO" }, { "input": "4 1\nabab", "output": "NO" }, { "input": "4 1\nabcb", "output": "NO" }, { "input": "4 2\nabbb", "output": "NO" }, { "input": "5 2\nabccc", "output": "NO" }, { "input": "2 3\nab", "output": "YES" }, { "input": "4 3\nbbbs", "output": "YES" }, { "input": "10 2\nazzzzzzzzz", "output": "NO" }, { "input": "1 2\nb", "output": "YES" }, { "input": "1 3\nb", "output": "YES" }, { "input": "4 5\nabcd", "output": "YES" }, { "input": "4 6\naabb", "output": "YES" }, { "input": "5 2\naaaab", "output": "NO" }, { "input": "3 5\naaa", "output": "YES" }, { "input": "5 3\nazzzz", "output": "NO" }, { "input": "4 100\naabb", "output": "YES" }, { "input": "3 10\naaa", "output": "YES" }, { "input": "3 4\naaa", "output": "YES" }, { "input": "12 5\naaaaabbbbbbb", "output": "NO" }, { "input": "5 2\naabbb", "output": "NO" }, { "input": "10 5\nzzzzzzzzzz", "output": "NO" }, { "input": "2 4\naa", "output": "YES" }, { "input": "1 5\na", "output": "YES" }, { "input": "10 5\naaaaaaaaaa", "output": "NO" }, { "input": "6 3\naaaaaa", "output": "NO" }, { "input": "7 1\nabcdeee", "output": "NO" }, { "input": "18 3\naaaaaabbbbbbcccccc", "output": "NO" }, { "input": "8 2\naabbccdd", "output": "YES" }, { "input": "4 2\nzzzz", "output": "NO" }, { "input": "4 2\nabaa", "output": "NO" }, { "input": "3 2\naaa", "output": "NO" }, { "input": "3 1\nzzz", "output": "NO" }, { "input": "5 4\nzzzzz", "output": "NO" }, { "input": "6 2\naabbbc", "output": "NO" }, { "input": "3 6\naaa", "output": "YES" }, { "input": "2 1\nzz", "output": "NO" }, { "input": "10 3\naaaeeeeeee", "output": "NO" }, { "input": "4 5\naabb", "output": "YES" }, { "input": "3 1\naaa", "output": "NO" }, { "input": "5 2\naazzz", "output": "NO" }, { "input": "6 2\nabbbbc", "output": "NO" }, { "input": "4 2\nxxxx", "output": "NO" }, { "input": "6 3\nzzzzzz", "output": "NO" }, { "input": "3 2\nabb", "output": "YES" }, { "input": "3 2\nzzz", "output": "NO" }, { "input": "6 5\nzzzzzz", "output": "NO" }, { "input": "6 3\nbcaaaa", "output": "NO" }, { "input": "100 100\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa", "output": "YES" }, { "input": "3 6\nabc", "output": "YES" } ]

1,503,803,172

2,147,483,647

Python 3

OK

TESTS

114

62

0

n, k = map(int, input().split()) s = input() d = {} for s_i in s: if s_i in d: d[s_i] += 1 else: d[s_i] = 1 can = True for _, value in d.items(): if value > k: can = False break if can: print("YES") else: print("NO")

Title: Generous Kefa Time Limit: None seconds Memory Limit: None megabytes Problem Description: One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all. Input Specification: The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends. Next line contains string *s* — colors of baloons. Output Specification: Answer to the task — «YES» or «NO» in a single line. You can choose the case (lower or upper) for each letter arbitrary. Demo Input: ['4 2\naabb\n', '6 3\naacaab\n'] Demo Output: ['YES\n', 'NO\n'] Note: In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second. In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO».

```python n, k = map(int, input().split()) s = input() d = {} for s_i in s: if s_i in d: d[s_i] += 1 else: d[s_i] = 1 can = True for _, value in d.items(): if value > k: can = False break if can: print("YES") else: print("NO") ```

3

937

A

Olympiad

PROGRAMMING

800

[ "implementation", "sortings" ]

null

The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points. As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria: - At least one participant should get a diploma. - None of those with score equal to zero should get awarded. - When someone is awarded, all participants with score not less than his score should also be awarded. Determine the number of ways to choose a subset of participants that will receive the diplomas.

The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants. The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores. It's guaranteed that at least one participant has non-zero score.

Print a single integer — the desired number of ways.

[ "4\n1 3 3 2\n", "3\n1 1 1\n", "4\n42 0 0 42\n" ]

[ "3\n", "1\n", "1\n" ]

There are three ways to choose a subset in sample case one. 1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma! The only option in sample case two is to award everyone. Note that in sample case three participants with zero scores cannot get anything.

500

[ { "input": "4\n1 3 3 2", "output": "3" }, { "input": "3\n1 1 1", "output": "1" }, { "input": "4\n42 0 0 42", "output": "1" }, { "input": "10\n1 0 1 0 1 0 0 0 0 1", "output": "1" }, { "input": "10\n572 471 540 163 50 30 561 510 43 200", "output": "10" }, { "input": "100\n122 575 426 445 172 81 247 429 97 202 175 325 382 384 417 356 132 502 328 537 57 339 518 211 479 306 140 168 268 16 140 263 593 249 391 310 555 468 231 180 157 18 334 328 276 155 21 280 322 545 111 267 467 274 291 304 235 34 365 180 21 95 501 552 325 331 302 353 296 22 289 399 7 466 32 302 568 333 75 192 284 10 94 128 154 512 9 480 243 521 551 492 420 197 207 125 367 117 438 600", "output": "94" }, { "input": "100\n600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600 600", "output": "1" }, { "input": "78\n5 4 13 2 5 6 2 10 10 1 2 6 7 9 6 3 5 7 1 10 2 2 7 0 2 11 11 3 1 13 3 10 6 2 0 3 0 5 0 1 4 11 1 1 7 0 12 7 5 12 0 2 12 9 8 3 4 3 4 11 4 10 2 3 10 12 5 6 1 11 2 0 8 7 9 1 3 12", "output": "13" }, { "input": "34\n220 387 408 343 184 447 197 307 337 414 251 319 426 322 347 242 208 412 188 185 241 235 216 259 331 372 322 284 444 384 214 297 389 391", "output": "33" }, { "input": "100\n1 2 1 0 3 0 2 0 0 1 2 0 1 3 0 3 3 1 3 0 0 2 1 2 2 1 3 3 3 3 3 2 0 0 2 1 2 3 2 3 0 1 1 3 3 2 0 3 1 0 2 2 2 1 2 3 2 1 0 3 0 2 0 3 0 2 1 0 3 1 0 2 2 1 3 1 3 0 2 3 3 1 1 3 1 3 0 3 2 0 2 3 3 0 2 0 2 0 1 3", "output": "3" }, { "input": "100\n572 471 540 163 50 30 561 510 43 200 213 387 500 424 113 487 357 333 294 337 435 202 447 494 485 465 161 344 470 559 104 356 393 207 224 213 511 514 60 386 149 216 392 229 429 173 165 401 395 150 127 579 344 390 529 296 225 425 318 79 465 447 177 110 367 212 459 270 41 500 277 567 125 436 178 9 214 342 203 112 144 24 79 155 495 556 40 549 463 281 241 316 2 246 1 396 510 293 332 55", "output": "93" }, { "input": "99\n5 4 13 2 5 6 2 10 10 1 2 6 7 9 6 3 5 7 1 10 2 2 7 0 2 11 11 3 1 13 3 10 6 2 0 3 0 5 0 1 4 11 1 1 7 0 12 7 5 12 0 2 12 9 8 3 4 3 4 11 4 10 2 3 10 12 5 6 1 11 2 0 8 7 9 1 3 12 2 3 9 3 7 13 7 13 0 11 8 12 2 5 9 4 0 6 6 2 13", "output": "13" }, { "input": "99\n1 0 1 0 1 0 0 0 0 1 0 0 1 1 0 1 1 1 1 0 0 0 1 0 0 1 1 1 1 1 1 0 0 0 0 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 0 0 0 1 0 1 0 1 0 1 0 0 0 1 0 0 1 0 1 1 0 0 0 1 1 1 1 0 0 1 1 1 1 1 1 1 0 1 0 0 0 1 1 0 0 0 0 0 1", "output": "1" }, { "input": "99\n21 74 25 44 71 80 46 28 96 1 74 24 81 83 16 55 31 1 27 36 56 38 17 10 78 5 39 67 67 15 39 62 92 48 90 9 54 67 30 79 56 17 33 27 75 54 20 79 21 44 10 66 66 73 90 3 34 33 64 79 20 94 0 51 24 30 1 52 95 21 88 98 6 65 31 1 67 32 74 91 83 9 93 27 53 11 8 79 42 20 50 91 19 96 6 24 66 16 37", "output": "61" }, { "input": "2\n0 1", "output": "1" }, { "input": "2\n0 600", "output": "1" }, { "input": "4\n1 1 1 2", "output": "2" }, { "input": "4\n0 0 1 2", "output": "2" }, { "input": "1\n5", "output": "1" }, { "input": "2\n0 5", "output": "1" }, { "input": "5\n1 0 0 1 2", "output": "2" } ]

1,540,357,316

2,147,483,647

PyPy 3

OK

TESTS

21

202

0

n=int(input()) arr=list(map(int,input().split())) freq=[0]*(602) for i in arr: freq[i]+=1 c=0 for i in range(1,602): if freq[i]!=0: c+=1 print(c)

Title: Olympiad Time Limit: None seconds Memory Limit: None megabytes Problem Description: The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points. As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria: - At least one participant should get a diploma. - None of those with score equal to zero should get awarded. - When someone is awarded, all participants with score not less than his score should also be awarded. Determine the number of ways to choose a subset of participants that will receive the diplomas. Input Specification: The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants. The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores. It's guaranteed that at least one participant has non-zero score. Output Specification: Print a single integer — the desired number of ways. Demo Input: ['4\n1 3 3 2\n', '3\n1 1 1\n', '4\n42 0 0 42\n'] Demo Output: ['3\n', '1\n', '1\n'] Note: There are three ways to choose a subset in sample case one. 1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma! The only option in sample case two is to award everyone. Note that in sample case three participants with zero scores cannot get anything.

```python n=int(input()) arr=list(map(int,input().split())) freq=[0]*(602) for i in arr: freq[i]+=1 c=0 for i in range(1,602): if freq[i]!=0: c+=1 print(c) ```

3

4

A

Watermelon

PROGRAMMING

800

[ "brute force", "math" ]

A. Watermelon

1

64

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem. Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys.

Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

[ "8\n" ]

[ "YES\n" ]

For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

0

[ { "input": "8", "output": "YES" }, { "input": "5", "output": "NO" }, { "input": "4", "output": "YES" }, { "input": "3", "output": "NO" }, { "input": "2", "output": "NO" }, { "input": "1", "output": "NO" }, { "input": "7", "output": "NO" }, { "input": "6", "output": "YES" }, { "input": "10", "output": "YES" }, { "input": "9", "output": "NO" }, { "input": "53", "output": "NO" }, { "input": "77", "output": "NO" }, { "input": "32", "output": "YES" }, { "input": "44", "output": "YES" }, { "input": "98", "output": "YES" }, { "input": "99", "output": "NO" }, { "input": "90", "output": "YES" }, { "input": "67", "output": "NO" }, { "input": "100", "output": "YES" }, { "input": "88", "output": "YES" } ]

1,694,066,497

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

0

30

0

def can_divide_watermelon(w): if w % 2 != 0: return "NO" for a in range(1, w): b = w - a if a % 2 == 0 and b % 2 == 0: return "YES" return "NO" w = int(input("Enter the weight of the watermelon: ")) result = can_divide_watermelon(w) print(result)

Title: Watermelon Time Limit: 1 seconds Memory Limit: 64 megabytes Problem Description: One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem. Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight. Input Specification: The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. Output Specification: Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. Demo Input: ['8\n'] Demo Output: ['YES\n'] Note: For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

```python def can_divide_watermelon(w): if w % 2 != 0: return "NO" for a in range(1, w): b = w - a if a % 2 == 0 and b % 2 == 0: return "YES" return "NO" w = int(input("Enter the weight of the watermelon: ")) result = can_divide_watermelon(w) print(result) ```

0

2

A

Winner

PROGRAMMING

1,500

[ "hashing", "implementation" ]

A. Winner

1

64

The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.

The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.

Print the name of the winner.

[ "3\nmike 3\nandrew 5\nmike 2\n", "3\nandrew 3\nandrew 2\nmike 5\n" ]

[ "andrew\n", "andrew\n" ]

none

0

[ { "input": "3\nmike 3\nandrew 5\nmike 2", "output": "andrew" }, { "input": "3\nandrew 3\nandrew 2\nmike 5", "output": "andrew" }, { "input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303", "output": "kaxqybeultn" }, { "input": "7\nksjuuerbnlklcfdjeyq 312\ndthjlkrvvbyahttifpdewvyslsh -983\nksjuuerbnlklcfdjeyq 268\ndthjlkrvvbyahttifpdewvyslsh 788\nksjuuerbnlklcfdjeyq -79\nksjuuerbnlklcfdjeyq -593\nksjuuerbnlklcfdjeyq 734", "output": "ksjuuerbnlklcfdjeyq" }, { "input": "12\natrtthfpcvishmqbakprquvnejr 185\natrtthfpcvishmqbakprquvnejr -699\natrtthfpcvishmqbakprquvnejr -911\natrtthfpcvishmqbakprquvnejr -220\nfcgslzkicjrpbqaifgweyzreajjfdo 132\nfcgslzkicjrpbqaifgweyzreajjfdo -242\nm 177\nm -549\natrtthfpcvishmqbakprquvnejr -242\nm 38\natrtthfpcvishmqbakprquvnejr -761\nfcgslzkicjrpbqaifgweyzreajjfdo 879", "output": "fcgslzkicjrpbqaifgweyzreajjfdo" }, { "input": "15\naawtvezfntstrcpgbzjbf 681\nzhahpvqiptvksnbjkdvmknb -74\naawtvezfntstrcpgbzjbf 661\njpdwmyke 474\naawtvezfntstrcpgbzjbf -547\naawtvezfntstrcpgbzjbf 600\nzhahpvqiptvksnbjkdvmknb -11\njpdwmyke 711\nbjmj 652\naawtvezfntstrcpgbzjbf -1000\naawtvezfntstrcpgbzjbf -171\nbjmj -302\naawtvezfntstrcpgbzjbf 961\nzhahpvqiptvksnbjkdvmknb 848\nbjmj -735", "output": "aawtvezfntstrcpgbzjbf" }, { "input": "17\nqdplghhx -649\nivhgbxiv 424\nivhgbxiv -72\nivhgbxiv 479\nugowfouebkelargxylsxn 83\nugowfouebkelargxylsxn -840\nivhgbxiv 382\nqdplghhx -904\nivhgbxiv -710\nugowfouebkelargxylsxn -838\nqdplghhx -974\nqdplghhx 571\nivhgbxiv -145\nugowfouebkelargxylsxn -788\nivhgbxiv 209\nivhgbxiv 420\nqdplghhx -158", "output": "ivhgbxiv" } ]

1,593,455,190

2,147,483,647

PyPy 3

OK

TESTS

20

342

21,913,600

n = int(input()) name = [] val = [] endv = dict() tmp = dict() for i in range(n): x, y = input().split() name.append(x) val.append(int(y)) if name[i] not in endv.keys(): endv[name[i]] = val[i] tmp[name[i]] = 0 else: endv[name[i]] += val[i] mx = 0 for i in range(n): mx = max(mx, endv[name[i]]) for i in range(n): tmp[name[i]] += val[i] if tmp[name[i]] >= mx and endv[name[i]] == mx: print(name[i]) exit(0)

Title: Winner Time Limit: 1 seconds Memory Limit: 64 megabytes Problem Description: The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points. Input Specification: The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive. Output Specification: Print the name of the winner. Demo Input: ['3\nmike 3\nandrew 5\nmike 2\n', '3\nandrew 3\nandrew 2\nmike 5\n'] Demo Output: ['andrew\n', 'andrew\n'] Note: none

```python n = int(input()) name = [] val = [] endv = dict() tmp = dict() for i in range(n): x, y = input().split() name.append(x) val.append(int(y)) if name[i] not in endv.keys(): endv[name[i]] = val[i] tmp[name[i]] = 0 else: endv[name[i]] += val[i] mx = 0 for i in range(n): mx = max(mx, endv[name[i]]) for i in range(n): tmp[name[i]] += val[i] if tmp[name[i]] >= mx and endv[name[i]] == mx: print(name[i]) exit(0) ```

3.665731

1,011

A

Stages

PROGRAMMING

900

[ "greedy", "implementation", "sortings" ]

null

Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages. There are $n$ stages available. The rocket must contain exactly $k$ of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'. For the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — $26$ tons. Build the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once.

The first line of input contains two integers — $n$ and $k$ ($1 \le k \le n \le 50$) – the number of available stages and the number of stages to use in the rocket. The second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once.

Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all.

[ "5 3\nxyabd\n", "7 4\nproblem\n", "2 2\nab\n", "12 1\nabaabbaaabbb\n" ]

[ "29", "34", "-1", "1" ]

In the first example, the following rockets satisfy the condition: - "adx" (weight is $1+4+24=29$);- "ady" (weight is $1+4+25=30$);- "bdx" (weight is $2+4+24=30$);- "bdy" (weight is $2+4+25=31$). Rocket "adx" has the minimal weight, so the answer is $29$. In the second example, target rocket is "belo". Its weight is $2+5+12+15=34$. In the third example, $n=k=2$, so the rocket must have both stages: 'a' and 'b'. This rocket doesn't satisfy the condition, because these letters are adjacent in the alphabet. Answer is -1.

500

[ { "input": "5 3\nxyabd", "output": "29" }, { "input": "7 4\nproblem", "output": "34" }, { "input": "2 2\nab", "output": "-1" }, { "input": "12 1\nabaabbaaabbb", "output": "1" }, { "input": "50 13\nqwertyuiopasdfghjklzxcvbnmaaaaaaaaaaaaaaaaaaaaaaaa", "output": "169" }, { "input": "50 14\nqwertyuiopasdfghjklzxcvbnmaaaaaaaaaaaaaaaaaaaaaaaa", "output": "-1" }, { "input": "1 1\na", "output": "1" }, { "input": "50 1\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa", "output": "1" }, { "input": "50 2\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa", "output": "-1" }, { "input": "13 13\nuwgmkyqeiaocs", "output": "169" }, { "input": "13 13\nhzdxpbfvrltnj", "output": "182" }, { "input": "1 1\nn", "output": "14" }, { "input": "10 8\nsmzeblyjqw", "output": "113" }, { "input": "20 20\ntzmvhskkyugkuuxpvtbh", "output": "-1" }, { "input": "30 15\nwjzolzzkfulwgioksfxmcxmnnjtoav", "output": "-1" }, { "input": "40 30\nxumfrflllrrgswehqtsskefixhcxjrxbjmrpsshv", "output": "-1" }, { "input": "50 31\nahbyyoxltryqdmvenemaqnbakglgqolxnaifnqtoclnnqiabpz", "output": "-1" }, { "input": "10 7\niuiukrxcml", "output": "99" }, { "input": "38 2\nvjzarfykmrsrvwbwfwldsulhxtykmjbnwmdufa", "output": "5" }, { "input": "12 6\nfwseyrarkwcd", "output": "61" }, { "input": "2 2\nac", "output": "4" }, { "input": "1 1\nc", "output": "3" }, { "input": "2 2\nad", "output": "5" }, { "input": "2 1\nac", "output": "1" }, { "input": "4 3\nadjz", "output": "15" }, { "input": "3 3\naoz", "output": "42" }, { "input": "3 1\nzzz", "output": "26" }, { "input": "2 1\nxz", "output": "24" }, { "input": "5 1\naaddd", "output": "1" } ]

1,532,982,349

1,549

Python 3

OK

TESTS

29

109

0

n,k=map(int,input().split()) a=list(input()) a.sort() x=1 t=ord(a[0])-96 s=a[0] for i in range(1,n): if x==k: break if ord(a[i])-ord(s)>=2: s=a[i] t+=ord(a[i])-96 x+=1 if x<k: print(-1) else: print(t)

Title: Stages Time Limit: None seconds Memory Limit: None megabytes Problem Description: Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages. There are $n$ stages available. The rocket must contain exactly $k$ of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'. For the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — $26$ tons. Build the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once. Input Specification: The first line of input contains two integers — $n$ and $k$ ($1 \le k \le n \le 50$) – the number of available stages and the number of stages to use in the rocket. The second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once. Output Specification: Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all. Demo Input: ['5 3\nxyabd\n', '7 4\nproblem\n', '2 2\nab\n', '12 1\nabaabbaaabbb\n'] Demo Output: ['29', '34', '-1', '1'] Note: In the first example, the following rockets satisfy the condition: - "adx" (weight is $1+4+24=29$);- "ady" (weight is $1+4+25=30$);- "bdx" (weight is $2+4+24=30$);- "bdy" (weight is $2+4+25=31$). Rocket "adx" has the minimal weight, so the answer is $29$. In the second example, target rocket is "belo". Its weight is $2+5+12+15=34$. In the third example, $n=k=2$, so the rocket must have both stages: 'a' and 'b'. This rocket doesn't satisfy the condition, because these letters are adjacent in the alphabet. Answer is -1.

```python n,k=map(int,input().split()) a=list(input()) a.sort() x=1 t=ord(a[0])-96 s=a[0] for i in range(1,n): if x==k: break if ord(a[i])-ord(s)>=2: s=a[i] t+=ord(a[i])-96 x+=1 if x<k: print(-1) else: print(t) ```

3

39

F

Pacifist frogs

PROGRAMMING

1,300

[ "implementation" ]

F. Pacifist frogs

2

64

Thumbelina has had an accident. She has found herself on a little island in the middle of a swamp and wants to get to the shore very much. One can get to the shore only by hills that are situated along a straight line that connects the little island with the shore. Let us assume that the hills are numbered from 1 to *n* and the number of a hill is equal to the distance in meters between it and the island. The distance between the *n*-th hill and the shore is also 1 meter. Thumbelina is too small to make such jumps. Fortunately, a family of frogs living in the swamp suggests to help her. Each frog agrees to give Thumbelina a ride but Thumbelina should choose only one frog. Each frog has a certain jump length. If Thumbelina agrees to accept help from a frog whose jump length is *d*, the frog will jump from the island on the hill *d*, then — on the hill 2*d*, then 3*d* and so on until they get to the shore (i.e. find itself beyond the hill *n*). However, there is one more problem: mosquitoes also live in the swamp. At the moment they have a siesta, and they are having a nap on some hills. If the frog jumps on a hill with a mosquito the frog will smash it. The frogs Thumbelina has met are pacifists, so they will find the death of each mosquito very much sad. Help Thumbelina choose a frog that will bring her to the shore and smash as small number of mosquitoes as possible.

The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=109, 1<=≤<=*m*,<=*k*<=≤<=100) — the number of hills, frogs and mosquitoes respectively. The second line contains *m* integers *d**i* (1<=≤<=*d**i*<=≤<=109) — the lengths of the frogs’ jumps. The third line contains *k* integers — the numbers of the hills on which each mosquito is sleeping. No more than one mosquito can sleep on each hill. The numbers in the lines are separated by single spaces.

In the first line output the number of frogs that smash the minimal number of mosquitoes, in the second line — their numbers in increasing order separated by spaces. The frogs are numbered from 1 to *m* in the order of the jump length given in the input data.

[ "5 3 5\n2 3 4\n1 2 3 4 5\n", "1000000000 2 3\n2 5\n999999995 999999998 999999996\n" ]

[ "2\n2 3\n", "1\n2\n" ]

none

0

[ { "input": "5 3 5\n2 3 4\n1 2 3 4 5", "output": "2\n2 3" }, { "input": "1000000000 2 3\n2 5\n999999995 999999998 999999996", "output": "1\n2" }, { "input": "1 1 1\n1\n1", "output": "1\n1" }, { "input": "2 2 1\n2 1\n1", "output": "1\n1" }, { "input": "3 2 2\n2 4\n3 2", "output": "1\n2" }, { "input": "10 3 6\n5 2 8\n5 6 7 8 9 10", "output": "1\n3" }, { "input": "10 10 9\n10 9 8 7 6 5 4 3 2 1\n10 9 8 7 5 4 3 2 1", "output": "1\n5" }, { "input": "20 3 5\n2 3 5\n2 5 6 10 15", "output": "1\n2" }, { "input": "20 4 8\n1 2 3 4\n2 4 6 8 10 12 14 16", "output": "1\n3" }, { "input": "10 5 5\n1 5 3 5 1\n1 6 5 7 2", "output": "3\n2 3 4" }, { "input": "20 10 5\n1 12 6 11 9 21 15 16 8 9\n11 13 15 2 1", "output": "7\n2 3 5 6 8 9 10" }, { "input": "20 10 10\n9 8 21 8 7 2 13 17 20 18\n7 16 20 3 6 1 11 18 15 17", "output": "2\n3 7" }, { "input": "20 10 10\n6 17 14 12 13 15 6 14 16 17\n1 6 16 14 7 8 9 12 10 2", "output": "4\n2 5 6 10" }, { "input": "100 30 30\n25 34 81 32 96 79 36 21 53 15 51 69 78 99 60 2 80 37 61 70 32 31 31 6 7 38 95 70 81 39\n1 50 75 8 90 69 13 57 6 4 60 19 94 52 45 42 95 88 21 22 96 2 56 61 31 78 7 62 68 72", "output": "11\n3 6 9 11 14 17 18 20 26 28 29" }, { "input": "200 35 67\n152 112 102 46 54 189 56 76 10 39 157 6 84 188 122 117 51 163 6 50 195 34 44 178 28 32 100 67 74 48 88 100 91 50 91\n126 68 138 157 92 128 183 36 175 49 168 198 116 20 31 88 61 46 12 179 137 130 185 5 171 96 184 85 37 147 50 75 93 103 160 10 120 140 59 98 131 124 121 190 169 141 165 39 47 28 90 139 148 119 73 6 51 94 21 52 89 35 97 79 3 13 142", "output": "17\n1 2 3 5 6 8 14 15 16 18 21 24 27 28 32 33 35" }, { "input": "200 72 29\n201 145 169 163 32 126 131 71 26 130 2 61 110 17 179 114 79 30 192 91 141 70 101 119 185 66 72 76 164 144 106 162 122 146 119 181 184 61 131 131 140 152 60 65 183 154 32 33 108 77 29 102 67 5 125 26 126 104 20 89 183 21 126 195 198 24 123 173 135 164 141 32\n160 65 136 22 194 110 155 138 92 118 87 40 49 191 190 99 157 3 23 17 34 123 31 81 67 86 196 45 109", "output": "59\n1 2 3 4 6 7 8 9 10 12 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 45 46 49 50 52 55 56 57 58 60 61 62 63 64 65 66 68 69 70 71" }, { "input": "500 46 46\n363 441 170 289 389 394 488 72 332 285 445 185 221 183 397 175 98 192 202 16 123 436 336 260 212 229 459 473 66 19 445 153 476 234 396 159 289 137 331 18 268 224 71 133 196 7\n454 64 417 129 95 162 496 300 234 359 224 354 334 155 191 82 35 319 244 126 292 108 321 93 77 311 107 487 121 431 235 100 445 68 338 467 133 307 4 220 245 84 468 141 436 363", "output": "35\n2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 21 23 24 25 26 27 28 29 32 33 35 36 37 38 39 41 43 45" }, { "input": "1000 19 27\n656 162 264 790 579 786 877 998 516 247 650 150 858 281 279 549 354 353 533\n349 411 1 248 22 649 726 382 423 832 172 864 17 658 840 572 564 287 800 919 500 575 461 40 1000 383 624", "output": "19\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19" } ]

1,476,704,729

2,147,483,647

Python 3

OK

TESTS

35

154

4,608,000

__author__ = 'linh' def main(): first_line = input() first_line = first_line.split() hill_n0 = int(first_line[0]) frog_n0 = int(first_line[1]) mosquito_n0 = int(first_line[2]) frog_list = input() frog_list = list(map(int, frog_list.split())) mosquito_list = input() mosquito_list = list(map(int, mosquito_list.split())) result = [] min_mosquito = 10000000000000 for i in range(0, frog_n0): n0 = 0 for j in range(0, mosquito_n0): if mosquito_list[j] % frog_list[i] == 0: n0 +=1 if n0 < min_mosquito: min_mosquito = n0 result.append(n0) frog_n0_adequate = 0 output = "" for i in range(0, frog_n0): if result[i] == min_mosquito: output += str(i+1) + " " frog_n0_adequate += 1 print(frog_n0_adequate) print(output) if __name__ == '__main__': main()

Title: Pacifist frogs Time Limit: 2 seconds Memory Limit: 64 megabytes Problem Description: Thumbelina has had an accident. She has found herself on a little island in the middle of a swamp and wants to get to the shore very much. One can get to the shore only by hills that are situated along a straight line that connects the little island with the shore. Let us assume that the hills are numbered from 1 to *n* and the number of a hill is equal to the distance in meters between it and the island. The distance between the *n*-th hill and the shore is also 1 meter. Thumbelina is too small to make such jumps. Fortunately, a family of frogs living in the swamp suggests to help her. Each frog agrees to give Thumbelina a ride but Thumbelina should choose only one frog. Each frog has a certain jump length. If Thumbelina agrees to accept help from a frog whose jump length is *d*, the frog will jump from the island on the hill *d*, then — on the hill 2*d*, then 3*d* and so on until they get to the shore (i.e. find itself beyond the hill *n*). However, there is one more problem: mosquitoes also live in the swamp. At the moment they have a siesta, and they are having a nap on some hills. If the frog jumps on a hill with a mosquito the frog will smash it. The frogs Thumbelina has met are pacifists, so they will find the death of each mosquito very much sad. Help Thumbelina choose a frog that will bring her to the shore and smash as small number of mosquitoes as possible. Input Specification: The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=109, 1<=≤<=*m*,<=*k*<=≤<=100) — the number of hills, frogs and mosquitoes respectively. The second line contains *m* integers *d**i* (1<=≤<=*d**i*<=≤<=109) — the lengths of the frogs’ jumps. The third line contains *k* integers — the numbers of the hills on which each mosquito is sleeping. No more than one mosquito can sleep on each hill. The numbers in the lines are separated by single spaces. Output Specification: In the first line output the number of frogs that smash the minimal number of mosquitoes, in the second line — their numbers in increasing order separated by spaces. The frogs are numbered from 1 to *m* in the order of the jump length given in the input data. Demo Input: ['5 3 5\n2 3 4\n1 2 3 4 5\n', '1000000000 2 3\n2 5\n999999995 999999998 999999996\n'] Demo Output: ['2\n2 3\n', '1\n2\n'] Note: none

```python __author__ = 'linh' def main(): first_line = input() first_line = first_line.split() hill_n0 = int(first_line[0]) frog_n0 = int(first_line[1]) mosquito_n0 = int(first_line[2]) frog_list = input() frog_list = list(map(int, frog_list.split())) mosquito_list = input() mosquito_list = list(map(int, mosquito_list.split())) result = [] min_mosquito = 10000000000000 for i in range(0, frog_n0): n0 = 0 for j in range(0, mosquito_n0): if mosquito_list[j] % frog_list[i] == 0: n0 +=1 if n0 < min_mosquito: min_mosquito = n0 result.append(n0) frog_n0_adequate = 0 output = "" for i in range(0, frog_n0): if result[i] == min_mosquito: output += str(i+1) + " " frog_n0_adequate += 1 print(frog_n0_adequate) print(output) if __name__ == '__main__': main() ```

3.927168

25

A

IQ test

PROGRAMMING

1,300

[ "brute force" ]

A. IQ test

2

256

Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.

The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.

Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.

[ "5\n2 4 7 8 10\n", "4\n1 2 1 1\n" ]

[ "3\n", "2\n" ]

none

0

[ { "input": "5\n2 4 7 8 10", "output": "3" }, { "input": "4\n1 2 1 1", "output": "2" }, { "input": "3\n1 2 2", "output": "1" }, { "input": "3\n100 99 100", "output": "2" }, { "input": "3\n5 3 2", "output": "3" }, { "input": "4\n43 28 1 91", "output": "2" }, { "input": "4\n75 13 94 77", "output": "3" }, { "input": "4\n97 8 27 3", "output": "2" }, { "input": "10\n95 51 12 91 85 3 1 31 25 7", "output": "3" }, { "input": "20\n88 96 66 51 14 88 2 92 18 72 18 88 20 30 4 82 90 100 24 46", "output": "4" }, { "input": "30\n20 94 56 50 10 98 52 32 14 22 24 60 4 8 98 46 34 68 82 82 98 90 50 20 78 49 52 94 64 36", "output": "26" }, { "input": "50\n79 27 77 57 37 45 27 49 65 33 57 21 71 19 75 85 65 61 23 97 85 9 23 1 9 3 99 77 77 21 79 69 15 37 15 7 93 81 13 89 91 31 45 93 15 97 55 80 85 83", "output": "48" }, { "input": "60\n46 11 73 65 3 69 3 53 43 53 97 47 55 93 31 75 35 3 9 73 23 31 3 81 91 79 61 21 15 11 11 11 81 7 83 75 39 87 83 59 89 55 93 27 49 67 67 29 1 93 11 17 9 19 35 21 63 31 31 25", "output": "1" }, { "input": "70\n28 42 42 92 64 54 22 38 38 78 62 38 4 38 14 66 4 92 66 58 94 26 4 44 41 88 48 82 44 26 74 44 48 4 16 92 34 38 26 64 94 4 30 78 50 54 12 90 8 16 80 98 28 100 74 50 36 42 92 18 76 98 8 22 2 50 58 50 64 46", "output": "25" }, { "input": "100\n43 35 79 53 13 91 91 45 65 83 57 9 42 39 85 45 71 51 61 59 31 13 63 39 25 21 79 39 91 67 21 61 97 75 93 83 29 79 59 97 11 37 63 51 39 55 91 23 21 17 47 23 35 75 49 5 69 99 5 7 41 17 25 89 15 79 21 63 53 81 43 91 59 91 69 99 85 15 91 51 49 37 65 7 89 81 21 93 61 63 97 93 45 17 13 69 57 25 75 73", "output": "13" }, { "input": "100\n50 24 68 60 70 30 52 22 18 74 68 98 20 82 4 46 26 68 100 78 84 58 74 98 38 88 68 86 64 80 82 100 20 22 98 98 52 6 94 10 48 68 2 18 38 22 22 82 44 20 66 72 36 58 64 6 36 60 4 96 76 64 12 90 10 58 64 60 74 28 90 26 24 60 40 58 2 16 76 48 58 36 82 60 24 44 4 78 28 38 8 12 40 16 38 6 66 24 31 76", "output": "99" }, { "input": "100\n47 48 94 48 14 18 94 36 96 22 12 30 94 20 48 98 40 58 2 94 8 36 98 18 98 68 2 60 76 38 18 100 8 72 100 68 2 86 92 72 58 16 48 14 6 58 72 76 6 88 80 66 20 28 74 62 86 68 90 86 2 56 34 38 56 90 4 8 76 44 32 86 12 98 38 34 54 92 70 94 10 24 82 66 90 58 62 2 32 58 100 22 58 72 2 22 68 72 42 14", "output": "1" }, { "input": "99\n38 20 68 60 84 16 28 88 60 48 80 28 4 92 70 60 46 46 20 34 12 100 76 2 40 10 8 86 6 80 50 66 12 34 14 28 26 70 46 64 34 96 10 90 98 96 56 88 50 74 70 94 2 94 24 66 68 46 22 30 6 10 64 32 88 14 98 100 64 58 50 18 50 50 8 38 8 16 54 2 60 54 62 84 92 98 4 72 66 26 14 88 99 16 10 6 88 56 22", "output": "93" }, { "input": "99\n50 83 43 89 53 47 69 1 5 37 63 87 95 15 55 95 75 89 33 53 89 75 93 75 11 85 49 29 11 97 49 67 87 11 25 37 97 73 67 49 87 43 53 97 43 29 53 33 45 91 37 73 39 49 59 5 21 43 87 35 5 63 89 57 63 47 29 99 19 85 13 13 3 13 43 19 5 9 61 51 51 57 15 89 13 97 41 13 99 79 13 27 97 95 73 33 99 27 23", "output": "1" }, { "input": "98\n61 56 44 30 58 14 20 24 88 28 46 56 96 52 58 42 94 50 46 30 46 80 72 88 68 16 6 60 26 90 10 98 76 20 56 40 30 16 96 20 88 32 62 30 74 58 36 76 60 4 24 36 42 54 24 92 28 14 2 74 86 90 14 52 34 82 40 76 8 64 2 56 10 8 78 16 70 86 70 42 70 74 22 18 76 98 88 28 62 70 36 72 20 68 34 48 80 98", "output": "1" }, { "input": "98\n66 26 46 42 78 32 76 42 26 82 8 12 4 10 24 26 64 44 100 46 94 64 30 18 88 28 8 66 30 82 82 28 74 52 62 80 80 60 94 86 64 32 44 88 92 20 12 74 94 28 34 58 4 22 16 10 94 76 82 58 40 66 22 6 30 32 92 54 16 76 74 98 18 48 48 30 92 2 16 42 84 74 30 60 64 52 50 26 16 86 58 96 79 60 20 62 82 94", "output": "93" }, { "input": "95\n9 31 27 93 17 77 75 9 9 53 89 39 51 99 5 1 11 39 27 49 91 17 27 79 81 71 37 75 35 13 93 4 99 55 85 11 23 57 5 43 5 61 15 35 23 91 3 81 99 85 43 37 39 27 5 67 7 33 75 59 13 71 51 27 15 93 51 63 91 53 43 99 25 47 17 71 81 15 53 31 59 83 41 23 73 25 91 91 13 17 25 13 55 57 29", "output": "32" }, { "input": "100\n91 89 81 45 53 1 41 3 77 93 55 97 55 97 87 27 69 95 73 41 93 21 75 35 53 56 5 51 87 59 91 67 33 3 99 45 83 17 97 47 75 97 7 89 17 99 23 23 81 25 55 97 27 35 69 5 77 35 93 19 55 59 37 21 31 37 49 41 91 53 73 69 7 37 37 39 17 71 7 97 55 17 47 23 15 73 31 39 57 37 9 5 61 41 65 57 77 79 35 47", "output": "26" }, { "input": "99\n38 56 58 98 80 54 26 90 14 16 78 92 52 74 40 30 84 14 44 80 16 90 98 68 26 24 78 72 42 16 84 40 14 44 2 52 50 2 12 96 58 66 8 80 44 52 34 34 72 98 74 4 66 74 56 21 8 38 76 40 10 22 48 32 98 34 12 62 80 68 64 82 22 78 58 74 20 22 48 56 12 38 32 72 6 16 74 24 94 84 26 38 18 24 76 78 98 94 72", "output": "56" }, { "input": "100\n44 40 6 40 56 90 98 8 36 64 76 86 98 76 36 92 6 30 98 70 24 98 96 60 24 82 88 68 86 96 34 42 58 10 40 26 56 10 88 58 70 32 24 28 14 82 52 12 62 36 70 60 52 34 74 30 78 76 10 16 42 94 66 90 70 38 52 12 58 22 98 96 14 68 24 70 4 30 84 98 8 50 14 52 66 34 100 10 28 100 56 48 38 12 38 14 91 80 70 86", "output": "97" }, { "input": "100\n96 62 64 20 90 46 56 90 68 36 30 56 70 28 16 64 94 34 6 32 34 50 94 22 90 32 40 2 72 10 88 38 28 92 20 26 56 80 4 100 100 90 16 74 74 84 8 2 30 20 80 32 16 46 92 56 42 12 96 64 64 42 64 58 50 42 74 28 2 4 36 32 70 50 54 92 70 16 45 76 28 16 18 50 48 2 62 94 4 12 52 52 4 100 70 60 82 62 98 42", "output": "79" }, { "input": "99\n14 26 34 68 90 58 50 36 8 16 18 6 2 74 54 20 36 84 32 50 52 2 26 24 3 64 20 10 54 26 66 44 28 72 4 96 78 90 96 86 68 28 94 4 12 46 100 32 22 36 84 32 44 94 76 94 4 52 12 30 74 4 34 64 58 72 44 16 70 56 54 8 14 74 8 6 58 62 98 54 14 40 80 20 36 72 28 98 20 58 40 52 90 64 22 48 54 70 52", "output": "25" }, { "input": "95\n82 86 30 78 6 46 80 66 74 72 16 24 18 52 52 38 60 36 86 26 62 28 22 46 96 26 94 84 20 46 66 88 76 32 12 86 74 18 34 88 4 48 94 6 58 6 100 82 4 24 88 32 54 98 34 48 6 76 42 88 42 28 100 4 22 2 10 66 82 54 98 20 60 66 38 98 32 47 86 58 6 100 12 46 2 42 8 84 78 28 24 70 34 28 86", "output": "78" }, { "input": "90\n40 50 8 42 76 24 58 42 26 68 20 48 54 12 34 84 14 36 32 88 6 50 96 56 20 92 48 16 40 34 96 46 20 84 30 50 20 98 8 44 96 42 8 76 70 38 84 30 40 88 84 72 2 22 52 58 16 62 100 66 80 40 50 32 14 62 88 72 22 99 76 50 84 82 8 82 98 46 26 40 2 98 18 78 30 72 70 18 34 68", "output": "70" }, { "input": "80\n81 43 87 1 55 43 53 61 27 19 43 13 89 9 33 83 75 55 97 71 91 37 95 5 21 69 81 93 95 69 31 83 55 7 97 7 79 57 8 61 27 85 49 1 15 97 63 79 29 73 41 85 5 41 31 93 67 11 63 59 15 99 91 77 43 69 23 23 81 73 19 1 67 51 1 75 99 67 3 81", "output": "39" }, { "input": "98\n13 83 61 27 35 1 85 95 97 73 95 65 73 45 5 43 27 83 91 19 11 3 85 59 9 39 69 23 45 7 51 85 5 71 5 95 1 51 75 3 43 57 3 11 33 71 21 99 47 41 87 39 71 87 31 85 91 49 83 5 49 85 47 91 55 99 33 23 31 23 23 73 29 77 55 31 25 5 81 49 91 15 15 39 87 5 9 40 69 47 29 33 11 21 49 79 51 83", "output": "88" }, { "input": "3\n100 100 1", "output": "3" } ]

1,529,436,764

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

1

154

0

from sys import stdin, stdout n = int(stdin.readline().strip()) num_list = list(map(int, stdin.readline().split())) for i in range(n): if num_list[i] % 2 == 1: num_list[i] = False else: num_list[i] = True seq_key = min(num_list) index = num_list.index(seq_key) + 1 stdout.write(str(index))

Title: IQ test Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. Input Specification: The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. Output Specification: Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. Demo Input: ['5\n2 4 7 8 10\n', '4\n1 2 1 1\n'] Demo Output: ['3\n', '2\n'] Note: none

```python from sys import stdin, stdout n = int(stdin.readline().strip()) num_list = list(map(int, stdin.readline().split())) for i in range(n): if num_list[i] % 2 == 1: num_list[i] = False else: num_list[i] = True seq_key = min(num_list) index = num_list.index(seq_key) + 1 stdout.write(str(index)) ```

0

238

A

Not Wool Sequences

PROGRAMMING

1,300

[ "constructive algorithms", "math" ]

null

A sequence of non-negative integers *a*1,<=*a*2,<=...,<=*a**n* of length *n* is called a wool sequence if and only if there exists two integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such that . In other words each wool sequence contains a subsequence of consecutive elements with xor equal to 0. The expression means applying the operation of a bitwise xor to numbers *x* and *y*. The given operation exists in all modern programming languages, for example, in languages C++ and Java it is marked as "^", in Pascal — as "xor". In this problem you are asked to compute the number of sequences made of *n* integers from 0 to 2*m*<=-<=1 that are not a wool sequence. You should print this number modulo 1000000009 (109<=+<=9).

The only line of input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105).

Print the required number of sequences modulo 1000000009 (109<=+<=9) on the only line of output.

[ "3 2\n" ]

[ "6\n" ]

Sequences of length 3 made of integers 0, 1, 2 and 3 that are not a wool sequence are (1, 3, 1), (1, 2, 1), (2, 1, 2), (2, 3, 2), (3, 1, 3) and (3, 2, 3).

500

[ { "input": "3 2", "output": "6" }, { "input": "4 2", "output": "0" }, { "input": "1 2", "output": "3" }, { "input": "4 11", "output": "433239206" }, { "input": "5 100", "output": "345449482" }, { "input": "5444 31525", "output": "637906839" }, { "input": "60282 92611", "output": "814908070" }, { "input": "62600 39199", "output": "366778414" }, { "input": "14095 86011", "output": "656508583" }, { "input": "78606 36436", "output": "657976765" }, { "input": "25063 54317", "output": "735545216" }, { "input": "86232 41348", "output": "77566161" }, { "input": "94882 95834", "output": "360122315" }, { "input": "83781 52238", "output": "188770162" }, { "input": "21857 94145", "output": "689996210" }, { "input": "7413 87155", "output": "340839315" }, { "input": "7683 65667", "output": "298588855" }, { "input": "88201 96978", "output": "508134449" }, { "input": "50664 46559", "output": "425318276" }, { "input": "60607 63595", "output": "396334239" }, { "input": "85264 15318", "output": "635855261" }, { "input": "100000 100000", "output": "738698541" }, { "input": "100000 16", "output": "0" }, { "input": "100000 17", "output": "614965071" }, { "input": "127 7", "output": "399589559" }, { "input": "128 8", "output": "987517349" }, { "input": "65535 16", "output": "558444716" }, { "input": "99999 1", "output": "0" }, { "input": "1 99999", "output": "833014736" }, { "input": "1 29", "output": "536870911" }, { "input": "2 15", "output": "73643513" }, { "input": "1 1", "output": "1" }, { "input": "2 1", "output": "0" }, { "input": "2 2", "output": "6" }, { "input": "3 1", "output": "0" }, { "input": "3 2", "output": "6" }, { "input": "3 3", "output": "210" }, { "input": "4 1", "output": "0" }, { "input": "4 2", "output": "0" }, { "input": "4 3", "output": "840" }, { "input": "4 4", "output": "32760" }, { "input": "12345 31", "output": "378093434" }, { "input": "50000 100000", "output": "821709120" } ]

1,568,362,188

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

1

248

0

class CodeforcesTask238ASolution: def __init__(self): self.result = '' self.n_m = [] def read_input(self): self.n_m = [int(x) for x in input().split(" ")] def process_task(self): mod = 1000000009 res = 1 y = 2 ** self.n_m[1] for x in range(1, self.n_m[0]): res = res * (y - x) % mod self.result = str(res) def get_result(self): return self.result if __name__ == "__main__": Solution = CodeforcesTask238ASolution() Solution.read_input() Solution.process_task() print(Solution.get_result())

Title: Not Wool Sequences Time Limit: None seconds Memory Limit: None megabytes Problem Description: A sequence of non-negative integers *a*1,<=*a*2,<=...,<=*a**n* of length *n* is called a wool sequence if and only if there exists two integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such that . In other words each wool sequence contains a subsequence of consecutive elements with xor equal to 0. The expression means applying the operation of a bitwise xor to numbers *x* and *y*. The given operation exists in all modern programming languages, for example, in languages C++ and Java it is marked as "^", in Pascal — as "xor". In this problem you are asked to compute the number of sequences made of *n* integers from 0 to 2*m*<=-<=1 that are not a wool sequence. You should print this number modulo 1000000009 (109<=+<=9). Input Specification: The only line of input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). Output Specification: Print the required number of sequences modulo 1000000009 (109<=+<=9) on the only line of output. Demo Input: ['3 2\n'] Demo Output: ['6\n'] Note: Sequences of length 3 made of integers 0, 1, 2 and 3 that are not a wool sequence are (1, 3, 1), (1, 2, 1), (2, 1, 2), (2, 3, 2), (3, 1, 3) and (3, 2, 3).

```python class CodeforcesTask238ASolution: def __init__(self): self.result = '' self.n_m = [] def read_input(self): self.n_m = [int(x) for x in input().split(" ")] def process_task(self): mod = 1000000009 res = 1 y = 2 ** self.n_m[1] for x in range(1, self.n_m[0]): res = res * (y - x) % mod self.result = str(res) def get_result(self): return self.result if __name__ == "__main__": Solution = CodeforcesTask238ASolution() Solution.read_input() Solution.process_task() print(Solution.get_result()) ```

0

149

C

Division into Teams

PROGRAMMING

1,500

[ "greedy", "math", "sortings" ]

null

Petya loves football very much, especially when his parents aren't home. Each morning he comes to the yard, gathers his friends and they play all day. From time to time they have a break to have some food or do some chores (for example, water the flowers). The key in football is to divide into teams fairly before the game begins. There are *n* boys playing football in the yard (including Petya), each boy's football playing skill is expressed with a non-negative characteristic *a**i* (the larger it is, the better the boy plays). Let's denote the number of players in the first team as *x*, the number of players in the second team as *y*, the individual numbers of boys who play for the first team as *p**i* and the individual numbers of boys who play for the second team as *q**i*. Division *n* boys into two teams is considered fair if three conditions are fulfilled: - Each boy plays for exactly one team (*x*<=+<=*y*<==<=*n*). - The sizes of teams differ in no more than one (|*x*<=-<=*y*|<=≤<=1). - The total football playing skills for two teams differ in no more than by the value of skill the best player in the yard has. More formally: Your task is to help guys divide into two teams fairly. It is guaranteed that a fair division into two teams always exists.

The first line contains the only integer *n* (2<=≤<=*n*<=≤<=105) which represents the number of guys in the yard. The next line contains *n* positive space-separated integers, *a**i* (1<=≤<=*a**i*<=≤<=104), the *i*-th number represents the *i*-th boy's playing skills.

On the first line print an integer *x* — the number of boys playing for the first team. On the second line print *x* integers — the individual numbers of boys playing for the first team. On the third line print an integer *y* — the number of boys playing for the second team, on the fourth line print *y* integers — the individual numbers of boys playing for the second team. Don't forget that you should fulfil all three conditions: *x*<=+<=*y*<==<=*n*, |*x*<=-<=*y*|<=≤<=1, and the condition that limits the total skills. If there are multiple ways to solve the problem, print any of them. The boys are numbered starting from one in the order in which their skills are given in the input data. You are allowed to print individual numbers of boys who belong to the same team in any order.

[ "3\n1 2 1\n", "5\n2 3 3 1 1\n" ]

[ "2\n1 2 \n1\n3 \n", "3\n4 1 3 \n2\n5 2 \n" ]

Let's consider the first sample test. There we send the first and the second boy to the first team and the third boy to the second team. Let's check all three conditions of a fair division. The first limitation is fulfilled (all boys play), the second limitation on the sizes of groups (|2 - 1| = 1 ≤ 1) is fulfilled, the third limitation on the difference in skills ((2 + 1) - (1) = 2 ≤ 2) is fulfilled.

1,500

[ { "input": "3\n1 2 1", "output": "2\n1 2 \n1\n3 " }, { "input": "5\n2 3 3 1 1", "output": "3\n4 1 3 \n2\n5 2 " }, { "input": "10\n2 2 2 2 2 2 2 1 2 2", "output": "5\n8 2 4 6 9 \n5\n1 3 5 7 10 " }, { "input": "10\n2 3 3 1 3 1 1 1 2 2", "output": "5\n4 7 1 10 3 \n5\n6 8 9 2 5 " }, { "input": "10\n2 3 2 3 3 1 1 3 1 1", "output": "5\n6 9 1 2 5 \n5\n7 10 3 4 8 " }, { "input": "11\n1 3 1 2 1 2 2 2 1 1 1", "output": "6\n1 5 10 4 7 2 \n5\n3 9 11 6 8 " }, { "input": "11\n54 83 96 75 33 27 36 35 26 22 77", "output": "6\n10 6 8 1 11 3 \n5\n9 5 7 4 2 " }, { "input": "11\n1 1 1 1 1 1 1 1 1 1 1", "output": "6\n1 3 5 7 9 11 \n5\n2 4 6 8 10 " }, { "input": "2\n1 1", "output": "1\n1 \n1\n2 " }, { "input": "2\n35 36", "output": "1\n1 \n1\n2 " }, { "input": "25\n1 2 2 1 2 2 2 2 2 1 1 2 2 2 2 2 1 2 2 2 1 1 2 2 1", "output": "13\n1 10 17 22 2 5 7 9 13 15 18 20 24 \n12\n4 11 21 25 3 6 8 12 14 16 19 23 " }, { "input": "27\n2 1 1 3 1 2 1 1 3 2 3 1 3 2 1 3 2 3 2 1 2 3 2 2 1 2 1", "output": "14\n2 5 8 15 25 1 10 17 21 24 4 11 16 22 \n13\n3 7 12 20 27 6 14 19 23 26 9 13 18 " }, { "input": "30\n2 2 2 3 4 3 4 4 3 2 3 2 2 4 1 4 2 4 2 2 1 4 3 2 1 3 1 1 4 3", "output": "15\n15 25 28 2 10 13 19 24 6 11 26 5 8 16 22 \n15\n21 27 1 3 12 17 20 4 9 23 30 7 14 18 29 " }, { "input": "100\n3 4 8 10 8 6 4 3 7 7 6 2 3 1 3 10 1 7 9 3 5 5 2 6 2 9 1 7 4 2 4 1 6 1 7 10 2 5 3 7 6 4 6 2 8 8 8 6 6 10 3 7 4 3 4 1 7 9 3 6 3 6 1 4 9 3 8 1 10 1 4 10 7 7 9 5 3 8 10 2 1 10 8 7 10 8 5 3 1 2 1 10 6 1 5 3 3 5 7 2", "output": "50\n14 27 34 63 70 89 94 23 30 44 90 1 13 20 51 59 66 88 97 7 31 53 64 21 38 87 98 11 33 43 49 62 9 18 35 52 73 84 3 45 47 78 86 26 65 4 36 69 79 85 \n50\n17 32 56 68 81 91 12 25 37 80 100 8 15 39 54 61 77 96 2 29 42 55 71 22 76 95 6 24 41 48 60 93 10 28 40 57 74 99 5 46 67 83 19 58 75 16 50 72 82 92 " }, { "input": "100\n85 50 17 89 65 89 5 20 86 26 16 21 85 14 44 31 87 31 6 2 48 67 8 80 79 1 48 36 97 1 5 30 79 50 78 12 2 55 76 100 54 40 26 81 97 96 68 56 87 14 51 17 54 37 52 33 69 62 38 63 74 15 62 78 9 19 67 2 60 58 93 60 18 96 55 48 34 7 79 82 32 58 90 67 20 50 27 15 7 89 98 10 11 15 99 49 4 51 77 52", "output": "50\n26 20 68 7 19 89 65 93 14 62 94 3 73 8 12 43 32 18 56 28 59 15 27 96 34 51 55 41 38 48 82 72 63 5 67 47 61 99 64 33 24 80 13 17 4 90 71 74 45 95 \n50\n30 37 97 31 78 23 92 36 50 88 11 52 66 85 10 87 16 81 77 54 42 21 76 2 86 98 100 53 75 70 69 58 60 22 84 57 39 35 25 79 44 1 9 49 6 83 46 29 91 40 " }, { "input": "100\n2382 7572 9578 1364 2325 2929 7670 5574 2836 2440 6553 1751 929 8785 6894 9373 9308 7338 6380 9541 9951 6785 8993 9942 5087 7544 6582 7139 8458 7424 9759 8199 9464 8817 7625 6200 4955 9373 9500 3062 849 4210 9337 5466 2190 8150 4971 3145 869 5675 1975 161 1998 378 5229 9000 8958 761 358 434 7636 8295 4406 73 375 812 2473 3652 9067 3052 5287 2850 6987 5442 2625 8894 8733 791 9763 5258 8259 9530 2050 7334 2118 2726 8221 5527 8827 1585 8334 8898 6399 6217 7400 2576 5164 9063 6247 9433", "output": "50\n64 59 54 58 66 49 4 12 53 85 5 10 96 86 72 70 48 42 37 25 55 71 44 8 36 99 93 27 15 28 18 30 2 61 46 87 62 29 14 89 92 23 98 17 16 100 39 20 31 24 \n50\n52 65 60 78 41 13 90 51 83 45 1 67 75 9 6 40 68 63 47 97 80 74 88 50 94 19 11 22 73 84 95 26 35 7 32 81 91 77 34 76 57 56 69 43 38 33 82 3 79 21 " }, { "input": "3\n1 2 3", "output": "2\n1 3 \n1\n2 " }, { "input": "3\n10 10 10", "output": "2\n1 3 \n1\n2 " }, { "input": "3\n5 10 10", "output": "2\n1 3 \n1\n2 " }, { "input": "5\n6 1 1 1 1", "output": "3\n2 4 1 \n2\n3 5 " }, { "input": "5\n1 100 2 200 3", "output": "3\n1 5 4 \n2\n3 2 " } ]

1,649,909,259

2,147,483,647

PyPy 3-64

WRONG_ANSWER

TESTS

1

30

512,000

# @Chukamin ICPC_TRAIN def main(): n = int(input()) data = list(map(int, input().split())) numlist = [[i + 1, 0] for i in range(n)] for i in range(n): numlist[i][1] = data[i] numlist.sort(key = lambda x: x[1]) p = n >> 1 q = n - p print(p) for i in range(0, n, 2): print(numlist[i][0], end = ' ') print() print(q) for j in range(1, n, 2): print(numlist[j][0], end = ' ') if __name__ == '__main__': main()

Title: Division into Teams Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petya loves football very much, especially when his parents aren't home. Each morning he comes to the yard, gathers his friends and they play all day. From time to time they have a break to have some food or do some chores (for example, water the flowers). The key in football is to divide into teams fairly before the game begins. There are *n* boys playing football in the yard (including Petya), each boy's football playing skill is expressed with a non-negative characteristic *a**i* (the larger it is, the better the boy plays). Let's denote the number of players in the first team as *x*, the number of players in the second team as *y*, the individual numbers of boys who play for the first team as *p**i* and the individual numbers of boys who play for the second team as *q**i*. Division *n* boys into two teams is considered fair if three conditions are fulfilled: - Each boy plays for exactly one team (*x*<=+<=*y*<==<=*n*). - The sizes of teams differ in no more than one (|*x*<=-<=*y*|<=≤<=1). - The total football playing skills for two teams differ in no more than by the value of skill the best player in the yard has. More formally: Your task is to help guys divide into two teams fairly. It is guaranteed that a fair division into two teams always exists. Input Specification: The first line contains the only integer *n* (2<=≤<=*n*<=≤<=105) which represents the number of guys in the yard. The next line contains *n* positive space-separated integers, *a**i* (1<=≤<=*a**i*<=≤<=104), the *i*-th number represents the *i*-th boy's playing skills. Output Specification: On the first line print an integer *x* — the number of boys playing for the first team. On the second line print *x* integers — the individual numbers of boys playing for the first team. On the third line print an integer *y* — the number of boys playing for the second team, on the fourth line print *y* integers — the individual numbers of boys playing for the second team. Don't forget that you should fulfil all three conditions: *x*<=+<=*y*<==<=*n*, |*x*<=-<=*y*|<=≤<=1, and the condition that limits the total skills. If there are multiple ways to solve the problem, print any of them. The boys are numbered starting from one in the order in which their skills are given in the input data. You are allowed to print individual numbers of boys who belong to the same team in any order. Demo Input: ['3\n1 2 1\n', '5\n2 3 3 1 1\n'] Demo Output: ['2\n1 2 \n1\n3 \n', '3\n4 1 3 \n2\n5 2 \n'] Note: Let's consider the first sample test. There we send the first and the second boy to the first team and the third boy to the second team. Let's check all three conditions of a fair division. The first limitation is fulfilled (all boys play), the second limitation on the sizes of groups (|2 - 1| = 1 ≤ 1) is fulfilled, the third limitation on the difference in skills ((2 + 1) - (1) = 2 ≤ 2) is fulfilled.

```python # @Chukamin ICPC_TRAIN def main(): n = int(input()) data = list(map(int, input().split())) numlist = [[i + 1, 0] for i in range(n)] for i in range(n): numlist[i][1] = data[i] numlist.sort(key = lambda x: x[1]) p = n >> 1 q = n - p print(p) for i in range(0, n, 2): print(numlist[i][0], end = ' ') print() print(q) for j in range(1, n, 2): print(numlist[j][0], end = ' ') if __name__ == '__main__': main() ```

0

61

A

Ultra-Fast Mathematician

PROGRAMMING

800

[ "implementation" ]

A. Ultra-Fast Mathematician

2

256

Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second. One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part. In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0. Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length. Now you are going to take part in Shapur's contest. See if you are faster and more accurate.

There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100.

Write one line — the corresponding answer. Do not omit the leading 0s.

[ "1010100\n0100101\n", "000\n111\n", "1110\n1010\n", "01110\n01100\n" ]

[ "1110001\n", "111\n", "0100\n", "00010\n" ]

none

500

[ { "input": "1010100\n0100101", "output": "1110001" }, { "input": "000\n111", "output": "111" }, { "input": "1110\n1010", "output": "0100" }, { "input": "01110\n01100", "output": "00010" }, { "input": "011101\n000001", "output": "011100" }, { "input": "10\n01", "output": "11" }, { "input": "00111111\n11011101", "output": "11100010" }, { "input": "011001100\n101001010", "output": "110000110" }, { "input": "1100100001\n0110101100", "output": "1010001101" }, { "input": "00011101010\n10010100101", "output": "10001001111" }, { "input": "100000101101\n111010100011", "output": "011010001110" }, { "input": "1000001111010\n1101100110001", "output": "0101101001011" }, { "input": "01011111010111\n10001110111010", "output": "11010001101101" }, { "input": "110010000111100\n001100101011010", "output": "111110101100110" }, { "input": "0010010111110000\n0000000011010110", "output": "0010010100100110" }, { "input": "00111110111110000\n01111100001100000", "output": "01000010110010000" }, { "input": "101010101111010001\n001001111101111101", "output": "100011010010101100" }, { "input": "0110010101111100000\n0011000101000000110", "output": "0101010000111100110" }, { "input": "11110100011101010111\n00001000011011000000", "output": "11111100000110010111" }, { "input": "101010101111101101001\n111010010010000011111", "output": "010000111101101110110" }, { "input": "0000111111100011000010\n1110110110110000001010", "output": "1110001001010011001000" }, { "input": "10010010101000110111000\n00101110100110111000111", "output": "10111100001110001111111" }, { "input": "010010010010111100000111\n100100111111100011001110", "output": "110110101101011111001001" }, { "input": "0101110100100111011010010\n0101100011010111001010001", "output": "0000010111110000010000011" }, { "input": "10010010100011110111111011\n10000110101100000001000100", "output": "00010100001111110110111111" }, { "input": "000001111000000100001000000\n011100111101111001110110001", "output": "011101000101111101111110001" }, { "input": "0011110010001001011001011100\n0000101101000011101011001010", "output": "0011011111001010110010010110" }, { "input": "11111000000000010011001101111\n11101110011001010100010000000", "output": "00010110011001000111011101111" }, { "input": "011001110000110100001100101100\n001010000011110000001000101001", "output": "010011110011000100000100000101" }, { "input": "1011111010001100011010110101111\n1011001110010000000101100010101", "output": "0000110100011100011111010111010" }, { "input": "10111000100001000001010110000001\n10111000001100101011011001011000", "output": "00000000101101101010001111011001" }, { "input": "000001010000100001000000011011100\n111111111001010100100001100000111", "output": "111110101001110101100001111011011" }, { "input": "1101000000000010011011101100000110\n1110000001100010011010000011011110", "output": "0011000001100000000001101111011000" }, { "input": "01011011000010100001100100011110001\n01011010111000001010010100001110000", "output": "00000001111010101011110000010000001" }, { "input": "000011111000011001000110111100000100\n011011000110000111101011100111000111", "output": "011000111110011110101101011011000011" }, { "input": "1001000010101110001000000011111110010\n0010001011010111000011101001010110000", "output": "1011001001111001001011101010101000010" }, { "input": "00011101011001100101111111000000010101\n10010011011011001011111000000011101011", "output": "10001110000010101110000111000011111110" }, { "input": "111011100110001001101111110010111001010\n111111101101111001110010000101101000100", "output": "000100001011110000011101110111010001110" }, { "input": "1111001001101000001000000010010101001010\n0010111100111110001011000010111110111001", "output": "1101110101010110000011000000101011110011" }, { "input": "00100101111000000101011111110010100011010\n11101110001010010101001000111110101010100", "output": "11001011110010010000010111001100001001110" }, { "input": "101011001110110100101001000111010101101111\n100111100110101011010100111100111111010110", "output": "001100101000011111111101111011101010111001" }, { "input": "1111100001100101000111101001001010011100001\n1000110011000011110010001011001110001000001", "output": "0111010010100110110101100010000100010100000" }, { "input": "01100111011111010101000001101110000001110101\n10011001011111110000000101011001001101101100", "output": "11111110000000100101000100110111001100011001" }, { "input": "110010100111000100100101100000011100000011001\n011001111011100110000110111001110110100111011", "output": "101011011100100010100011011001101010100100010" }, { "input": "0001100111111011010110100100111000000111000110\n1100101011000000000001010010010111001100110001", "output": "1101001100111011010111110110101111001011110111" }, { "input": "00000101110110110001110010100001110100000100000\n10010000110011110001101000111111101010011010001", "output": "10010101000101000000011010011110011110011110001" }, { "input": "110000100101011100100011001111110011111110010001\n101011111001011100110110111101110011010110101100", "output": "011011011100000000010101110010000000101000111101" }, { "input": "0101111101011111010101011101000011101100000000111\n0000101010110110001110101011011110111001010100100", "output": "0101010111101001011011110110011101010101010100011" }, { "input": "11000100010101110011101000011111001010110111111100\n00001111000111001011111110000010101110111001000011", "output": "11001011010010111000010110011101100100001110111111" }, { "input": "101000001101111101101111111000001110110010101101010\n010011100111100001100000010001100101000000111011011", "output": "111011101010011100001111101001101011110010010110001" }, { "input": "0011111110010001010100010110111000110011001101010100\n0111000000100010101010000100101000000100101000111001", "output": "0100111110110011111110010010010000110111100101101101" }, { "input": "11101010000110000011011010000001111101000111011111100\n10110011110001010100010110010010101001010111100100100", "output": "01011001110111010111001100010011010100010000111011000" }, { "input": "011000100001000001101000010110100110011110100111111011\n111011001000001001110011001111011110111110110011011111", "output": "100011101001001000011011011001111000100000010100100100" }, { "input": "0111010110010100000110111011010110100000000111110110000\n1011100100010001101100000100111111101001110010000100110", "output": "1100110010000101101010111111101001001001110101110010110" }, { "input": "10101000100111000111010001011011011011110100110101100011\n11101111000000001100100011111000100100000110011001101110", "output": "01000111100111001011110010100011111111110010101100001101" }, { "input": "000000111001010001000000110001001011100010011101010011011\n110001101000010010000101000100001111101001100100001010010", "output": "110001010001000011000101110101000100001011111001011001001" }, { "input": "0101011100111010000111110010101101111111000000111100011100\n1011111110000010101110111001000011100000100111111111000111", "output": "1110100010111000101001001011101110011111100111000011011011" }, { "input": "11001000001100100111100111100100101011000101001111001001101\n10111110100010000011010100110100100011101001100000001110110", "output": "01110110101110100100110011010000001000101100101111000111011" }, { "input": "010111011011101000000110000110100110001110100001110110111011\n101011110011101011101101011111010100100001100111100100111011", "output": "111100101000000011101011011001110010101111000110010010000000" }, { "input": "1001011110110110000100011001010110000100011010010111010101110\n1101111100001000010111110011010101111010010100000001000010111", "output": "0100100010111110010011101010000011111110001110010110010111001" }, { "input": "10000010101111100111110101111000010100110111101101111111111010\n10110110101100101010011001011010100110111011101100011001100111", "output": "00110100000011001101101100100010110010001100000001100110011101" }, { "input": "011111010011111000001010101001101001000010100010111110010100001\n011111001011000011111001000001111001010110001010111101000010011", "output": "000000011000111011110011101000010000010100101000000011010110010" }, { "input": "1111000000110001011101000100100100001111011100001111001100011111\n1101100110000101100001100000001001011011111011010101000101001010", "output": "0010100110110100111100100100101101010100100111011010001001010101" }, { "input": "01100000101010010011001110100110110010000110010011011001100100011\n10110110010110111100100111000111000110010000000101101110000010111", "output": "11010110111100101111101001100001110100010110010110110111100110100" }, { "input": "001111111010000100001100001010011001111110011110010111110001100111\n110000101001011000100010101100100110000111100000001101001110010111", "output": "111111010011011100101110100110111111111001111110011010111111110000" }, { "input": "1011101011101101011110101101011101011000010011100101010101000100110\n0001000001001111010111100100111101100000000001110001000110000000110", "output": "1010101010100010001001001001100000111000010010010100010011000100000" }, { "input": "01000001011001010011011100010000100100110101111011011011110000001110\n01011110000110011011000000000011000111100001010000000011111001110000", "output": "00011111011111001000011100010011100011010100101011011000001001111110" }, { "input": "110101010100110101000001111110110100010010000100111110010100110011100\n111010010111111011100110101011001011001110110111110100000110110100111", "output": "001111000011001110100111010101111111011100110011001010010010000111011" }, { "input": "1001101011000001011111100110010010000011010001001111011100010100110001\n1111100111110101001111010001010000011001001001010110001111000000100101", "output": "0110001100110100010000110111000010011010011000011001010011010100010100" }, { "input": "00000111110010110001110110001010010101000111011001111111100110011110010\n00010111110100000100110101000010010001100001100011100000001100010100010", "output": "00010000000110110101000011001000000100100110111010011111101010001010000" }, { "input": "100101011100101101000011010001011001101110101110001100010001010111001110\n100001111100101011011111110000001111000111001011111110000010101110111001", "output": "000100100000000110011100100001010110101001100101110010010011111001110111" }, { "input": "1101100001000111001101001011101000111000011110000001001101101001111011010\n0101011101010100011011010110101000010010110010011110101100000110110001000", "output": "1000111100010011010110011101000000101010101100011111100001101111001010010" }, { "input": "01101101010011110101100001110101111011100010000010001101111000011110111111\n00101111001101001100111010000101110000100101101111100111101110010100011011", "output": "01000010011110111001011011110000001011000111101101101010010110001010100100" }, { "input": "101100101100011001101111110110110010100110110010100001110010110011001101011\n000001011010101011110011111101001110000111000010001101000010010000010001101", "output": "101101110110110010011100001011111100100001110000101100110000100011011100110" }, { "input": "0010001011001010001100000010010011110110011000100000000100110000101111001110\n1100110100111000110100001110111001011101001100001010100001010011100110110001", "output": "1110111111110010111000001100101010101011010100101010100101100011001001111111" }, { "input": "00101101010000000101011001101011001100010001100000101011101110000001111001000\n10010110010111000000101101000011101011001010000011011101101011010000000011111", "output": "10111011000111000101110100101000100111011011100011110110000101010001111010111" }, { "input": "111100000100100000101001100001001111001010001000001000000111010000010101101011\n001000100010100101111011111011010110101100001111011000010011011011100010010110", "output": "110100100110000101010010011010011001100110000111010000010100001011110111111101" }, { "input": "0110001101100100001111110101101000100101010010101010011001101001001101110000000\n0111011000000010010111011110010000000001000110001000011001101000000001110100111", "output": "0001010101100110011000101011111000100100010100100010000000000001001100000100111" }, { "input": "10001111111001000101001011110101111010100001011010101100111001010001010010001000\n10000111010010011110111000111010101100000011110001101111001000111010100000000001", "output": "00001000101011011011110011001111010110100010101011000011110001101011110010001001" }, { "input": "100110001110110000100101001110000011110110000110000000100011110100110110011001101\n110001110101110000000100101001101011111100100100001001000110000001111100011110110", "output": "010111111011000000100001100111101000001010100010001001100101110101001010000111011" }, { "input": "0000010100100000010110111100011111111010011101000000100000011001001101101100111010\n0100111110011101010110101011110110010111001111000110101100101110111100101000111111", "output": "0100101010111101000000010111101001101101010010000110001100110111110001000100000101" }, { "input": "11000111001010100001110000001001011010010010110000001110100101000001010101100110111\n11001100100100100001101010110100000111100011101110011010110100001001000011011011010", "output": "00001011101110000000011010111101011101110001011110010100010001001000010110111101101" }, { "input": "010110100010001000100010101001101010011010111110100001000100101000111011100010100001\n110000011111101101010011111000101010111010100001001100001001100101000000111000000000", "output": "100110111101100101110001010001000000100000011111101101001101001101111011011010100001" }, { "input": "0000011110101110010101110110110101100001011001101010101001000010000010000000101001101\n1100111111011100000110000111101110011111100111110001011001000010011111100001001100011", "output": "1100100001110010010011110001011011111110111110011011110000000000011101100001100101110" }, { "input": "10100000101101110001100010010010100101100011010010101000110011100000101010110010000000\n10001110011011010010111011011101101111000111110000111000011010010101001100000001010011", "output": "00101110110110100011011001001111001010100100100010010000101001110101100110110011010011" }, { "input": "001110000011111101101010011111000101010111010100001001100001001100101000000111000000000\n111010000000000000101001110011001000111011001100101010011001000011101001001011110000011", "output": "110100000011111101000011101100001101101100011000100011111000001111000001001100110000011" }, { "input": "1110111100111011010101011011001110001010010010110011110010011111000010011111010101100001\n1001010101011001001010100010101100000110111101011000100010101111111010111100001110010010", "output": "0111101001100010011111111001100010001100101111101011010000110000111000100011011011110011" }, { "input": "11100010001100010011001100001100010011010001101110011110100101110010101101011101000111111\n01110000000110111010110100001010000101011110100101010011000110101110101101110111011110001", "output": "10010010001010101001111000000110010110001111001011001101100011011100000000101010011001110" }, { "input": "001101011001100101101100110000111000101011001001100100000100101000100000110100010111111101\n101001111110000010111101111110001001111001111101111010000110111000100100110010010001011111", "output": "100100100111100111010001001110110001010010110100011110000010010000000100000110000110100010" }, { "input": "1010110110010101000110010010110101011101010100011001101011000110000000100011100100011000000\n0011011111100010001111101101000111001011101110100000110111100100101111010110101111011100011", "output": "1001101001110111001001111111110010010110111010111001011100100010101111110101001011000100011" }, { "input": "10010010000111010111011111110010100101100000001100011100111011100010000010010001011100001100\n00111010100010110010000100010111010001111110100100100011101000101111111111001101101100100100", "output": "10101000100101100101011011100101110100011110101000111111010011001101111101011100110000101000" }, { "input": "010101110001010101100000010111010000000111110011001101100011001000000011001111110000000010100\n010010111011100101010101111110110000000111000100001101101001001000001100101110001010000100001", "output": "000111001010110000110101101001100000000000110111000000001010000000001111100001111010000110101" }, { "input": "1100111110011001000111101001001011000110011010111111100010111111001100111111011101100111101011\n1100000011001000110100110111000001011001010111101000010010100011000001100100111101101000010110", "output": "0000111101010001110011011110001010011111001101010111110000011100001101011011100000001111111101" }, { "input": "00011000100100110111100101100100000000010011110111110010101110110011100001010111010011110100101\n00011011111011111011100101100111100101001110010111000010000111000100100100000001110101111011011", "output": "00000011011111001100000000000011100101011101100000110000101001110111000101010110100110001111110" }, { "input": "000101011001001100000111100010110101111011110101111101000110001101011010111110110011100100000001\n011000101010011111011000111000100000000011011000000001111110001000001111101010110000011100001111", "output": "011101110011010011011111011010010101111000101101111100111000000101010101010100000011111000001110" }, { "input": "1000101001011010000100100100010010011101011001110101111011101111111110010101001101010001010101001\n0110110010011100011111011111110111000000010001110100001010111110101011010011111011111110000110000", "output": "1110011011000110011011111011100101011101001000000001110001010001010101000110110110101111010011001" }, { "input": "01111010010101100111110111111011011010100001011101010000111100101101101110111011001100101011100111\n00001100110110100001111011000010001001001100000010111101000001111011100000010111010010000011000010", "output": "01110110100011000110001100111001010011101101011111101101111101010110001110101100011110101000100101" }, { "input": "111101011101111000001011001101111010110111001101110100100011111011011101001101010101011010111000110\n101111100101101101001100110011000001111010011101110111110110101110011011110011111100001001110101101", "output": "010010111000010101000111111110111011001101010000000011010101010101000110111110101001010011001101011" }, { "input": "1010000011010110011101001101110001110010000111011101110010110110111111001001110100101100010101010001\n0111101000111100101100000101111010100100001000011101010100110011100011010011010101000100101011100011", "output": "1101101011101010110001001000001011010110001111000000100110000101011100011010100001101000111110110010" }, { "input": "0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001\n1111111010111111101011111110101111111010111111101011111110101111111010111111101011111110101111111010", "output": "1111111010111111101011111110101111111010111111101011111110101111111010111111101011111110101111111011" }, { "input": "0\n0", "output": "0" }, { "input": "0\n1", "output": "1" } ]

1,639,410,170

2,147,483,647

PyPy 3-64

OK

TESTS

102

109

512,000

num1=input() num2=input() ans="" for i in range(len(num1)): if num1[i]!=num2[i]: ans+="1" else: ans+="0" print(ans)

Title: Ultra-Fast Mathematician Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second. One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part. In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0. Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length. Now you are going to take part in Shapur's contest. See if you are faster and more accurate. Input Specification: There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. Output Specification: Write one line — the corresponding answer. Do not omit the leading 0s. Demo Input: ['1010100\n0100101\n', '000\n111\n', '1110\n1010\n', '01110\n01100\n'] Demo Output: ['1110001\n', '111\n', '0100\n', '00010\n'] Note: none

```python num1=input() num2=input() ans="" for i in range(len(num1)): if num1[i]!=num2[i]: ans+="1" else: ans+="0" print(ans) ```

3.971796

40

A

Find Color

PROGRAMMING

1,300

[ "constructive algorithms", "geometry", "implementation", "math" ]

A. Find Color

2

256

Not so long ago as a result of combat operations the main Berland place of interest — the magic clock — was damaged. The cannon's balls made several holes in the clock, that's why the residents are concerned about the repair. The magic clock can be represented as an infinite Cartesian plane, where the origin corresponds to the clock center. The clock was painted two colors as is shown in the picture: The picture shows only the central part of the clock. This coloring naturally extends to infinity. The balls can be taken to be points on the plane. Your task is to find the color of the area, damaged by the given ball. All the points located on the border of one of the areas have to be considered painted black.

The first and single line contains two integers *x* and *y* — the coordinates of the hole made in the clock by the ball. Each of the numbers *x* and *y* has an absolute value that does not exceed 1000.

Find the required color. All the points between which and the origin of coordinates the distance is integral-value are painted black.

[ "-2 1\n", "2 1\n", "4 3\n" ]

[ "white\n", "black\n", "black\n" ]

none

500

[ { "input": "-2 1", "output": "white" }, { "input": "2 1", "output": "black" }, { "input": "4 3", "output": "black" }, { "input": "3 3", "output": "black" }, { "input": "4 4", "output": "white" }, { "input": "-4 4", "output": "black" }, { "input": "4 -4", "output": "black" }, { "input": "-4 -4", "output": "white" }, { "input": "0 0", "output": "black" }, { "input": "0 1", "output": "black" }, { "input": "0 2", "output": "black" }, { "input": "0 1000", "output": "black" }, { "input": "1000 0", "output": "black" }, { "input": "-1000 0", "output": "black" }, { "input": "0 -1000", "output": "black" }, { "input": "1000 -1000", "output": "white" }, { "input": "12 5", "output": "black" }, { "input": "12 -5", "output": "black" }, { "input": "-12 -35", "output": "black" }, { "input": "20 -21", "output": "black" }, { "input": "-677 492", "output": "white" }, { "input": "-673 -270", "output": "white" }, { "input": "-668 970", "output": "black" }, { "input": "-220 208", "output": "white" }, { "input": "-215 -996", "output": "black" }, { "input": "-211 243", "output": "black" }, { "input": "-206 -518", "output": "white" }, { "input": "-201 278", "output": "black" }, { "input": "-196 -484", "output": "black" }, { "input": "902 479", "output": "white" }, { "input": "-441 572", "output": "white" }, { "input": "217 221", "output": "white" }, { "input": "875 -129", "output": "white" }, { "input": "-469 -36", "output": "black" }, { "input": "189 -387", "output": "white" }, { "input": "847 -294", "output": "white" }, { "input": "-496 -644", "output": "black" }, { "input": "-281 -552", "output": "white" }, { "input": "377 -902", "output": "black" }, { "input": "165 -738", "output": "white" }, { "input": "61 -175", "output": "black" }, { "input": "-42 389", "output": "black" }, { "input": "-589 952", "output": "black" }, { "input": "-693 -929", "output": "white" }, { "input": "-796 -365", "output": "white" }, { "input": "658 198", "output": "white" }, { "input": "555 319", "output": "black" }, { "input": "8 882", "output": "black" }, { "input": "-96 -556", "output": "black" }, { "input": "-129 489", "output": "black" }, { "input": "207 -224", "output": "black" }, { "input": "64 0", "output": "black" }, { "input": "17 144", "output": "black" }, { "input": "60 -448", "output": "black" }, { "input": "-399 -40", "output": "black" }, { "input": "128 -504", "output": "black" }, { "input": "0 72", "output": "black" }, { "input": "168 -26", "output": "black" }, { "input": "72 -154", "output": "black" }, { "input": "117 -44", "output": "black" }, { "input": "-72 -646", "output": "black" }, { "input": "253 -204", "output": "black" }, { "input": "-40 198", "output": "black" }, { "input": "-216 -90", "output": "black" }, { "input": "15 -8", "output": "black" }, { "input": "-180 -432", "output": "black" }, { "input": "280 342", "output": "black" }, { "input": "132 224", "output": "black" }, { "input": "-192 -256", "output": "black" }, { "input": "351 -280", "output": "black" } ]

1,561,419,017

2,147,483,647

Python 3

COMPILATION_ERROR

TESTS

0

def clock(n): if (a+b)%2==0: return 'black' else: if a > 1 and b > 1 or a < 1 and b < 1: if (a+b)%2==0: return 'black' return 'white' elif: a > 1 and b < 1 or a < 1 and b > 1: if (a+b)%2==0: return 'white' return 'black' n = [int(i) for i in input().split()] a = n[0] b = n[1] print(clock(n))

Title: Find Color Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Not so long ago as a result of combat operations the main Berland place of interest — the magic clock — was damaged. The cannon's balls made several holes in the clock, that's why the residents are concerned about the repair. The magic clock can be represented as an infinite Cartesian plane, where the origin corresponds to the clock center. The clock was painted two colors as is shown in the picture: The picture shows only the central part of the clock. This coloring naturally extends to infinity. The balls can be taken to be points on the plane. Your task is to find the color of the area, damaged by the given ball. All the points located on the border of one of the areas have to be considered painted black. Input Specification: The first and single line contains two integers *x* and *y* — the coordinates of the hole made in the clock by the ball. Each of the numbers *x* and *y* has an absolute value that does not exceed 1000. Output Specification: Find the required color. All the points between which and the origin of coordinates the distance is integral-value are painted black. Demo Input: ['-2 1\n', '2 1\n', '4 3\n'] Demo Output: ['white\n', 'black\n', 'black\n'] Note: none

```python def clock(n): if (a+b)%2==0: return 'black' else: if a > 1 and b > 1 or a < 1 and b < 1: if (a+b)%2==0: return 'black' return 'white' elif: a > 1 and b < 1 or a < 1 and b > 1: if (a+b)%2==0: return 'white' return 'black' n = [int(i) for i in input().split()] a = n[0] b = n[1] print(clock(n)) ```

-1

979

B

Treasure Hunt

PROGRAMMING

1,800

[ "greedy" ]

null

After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her. The three friends are very smart so they passed all the challenges very quickly and finally reached the destination. But the treasure can only belong to one cat so they started to think of something which can determine who is worthy of the treasure. Instantly, Kuro came up with some ribbons. A random colorful ribbon is given to each of the cats. Each color of the ribbon can be represented as an uppercase or lowercase Latin letter. Let's call a consecutive subsequence of colors that appears in the ribbon a subribbon. The beauty of a ribbon is defined as the maximum number of times one of its subribbon appears in the ribbon. The more the subribbon appears, the more beautiful is the ribbon. For example, the ribbon aaaaaaa has the beauty of $7$ because its subribbon a appears $7$ times, and the ribbon abcdabc has the beauty of $2$ because its subribbon abc appears twice. The rules are simple. The game will have $n$ turns. Every turn, each of the cats must change strictly one color (at one position) in his/her ribbon to an arbitrary color which is different from the unchanged one. For example, a ribbon aaab can be changed into acab in one turn. The one having the most beautiful ribbon after $n$ turns wins the treasure. Could you find out who is going to be the winner if they all play optimally?

The first line contains an integer $n$ ($0 \leq n \leq 10^{9}$) — the number of turns. Next 3 lines contain 3 ribbons of Kuro, Shiro and Katie one per line, respectively. Each ribbon is a string which contains no more than $10^{5}$ uppercase and lowercase Latin letters and is not empty. It is guaranteed that the length of all ribbons are equal for the purpose of fairness. Note that uppercase and lowercase letters are considered different colors.

Print the name of the winner ("Kuro", "Shiro" or "Katie"). If there are at least two cats that share the maximum beauty, print "Draw".

[ "3\nKuroo\nShiro\nKatie\n", "7\ntreasurehunt\nthreefriends\nhiCodeforces\n", "1\nabcabc\ncbabac\nababca\n", "15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE\n" ]

[ "Kuro\n", "Shiro\n", "Katie\n", "Draw\n" ]

In the first example, after $3$ turns, Kuro can change his ribbon into ooooo, which has the beauty of $5$, while reaching such beauty for Shiro and Katie is impossible (both Shiro and Katie can reach the beauty of at most $4$, for example by changing Shiro's ribbon into SSiSS and changing Katie's ribbon into Kaaaa). Therefore, the winner is Kuro. In the fourth example, since the length of each of the string is $9$ and the number of turn is $15$, everyone can change their ribbons in some way to reach the maximal beauty of $9$ by changing their strings into zzzzzzzzz after 9 turns, and repeatedly change their strings into azzzzzzzz and then into zzzzzzzzz thrice. Therefore, the game ends in a draw.

1,000

[ { "input": "3\nKuroo\nShiro\nKatie", "output": "Kuro" }, { "input": "7\ntreasurehunt\nthreefriends\nhiCodeforces", "output": "Shiro" }, { "input": "1\nabcabc\ncbabac\nababca", "output": "Katie" }, { "input": "15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE", "output": "Draw" }, { "input": "1\naaaaaaaaaa\nAAAAAAcAAA\nbbbbbbzzbb", "output": "Shiro" }, { "input": "60\nddcZYXYbZbcXYcZdYbddaddYaZYZdaZdZZdXaaYdaZZZaXZXXaaZbb\ndcdXcYbcaXYaXYcacYabYcbZYdacaYbYdXaccYXZZZdYbbYdcZZZbY\nXaZXbbdcXaadcYdYYcbZdcaXaYZabbXZZYbYbcXbaXabcXbXadbZYZ", "output": "Draw" }, { "input": "9174\nbzbbbzzzbbzzccczzccczzbzbzcbzbbzccbzcccbccczzbbcbbzbzzzcbczbzbzzbbbczbbcbzzzbcbzczbcczb\ndbzzzccdcdczzzzzcdczbbzcdzbcdbzzdczbzddcddbdbzzzczcczzbdcbbzccbzzzdzbzddcbzbdzdcczccbdb\nzdczddzcdddddczdczdczdcdzczddzczdzddczdcdcdzczczzdzccdccczczdzczczdzcdddzddzccddcczczzd", "output": "Draw" }, { "input": "727\nbaabbabbbababbbbaaaabaabbaabababaaababaaababbbbababbbbbbbbbbaaabaabbbbbbbbaaaabaabbaaabaabbabaa\nddcdcccccccdccdcdccdddcddcddcddddcdddcdcdccddcdddddccddcccdcdddcdcccdccccccdcdcdccccccdccccccdc\nfffeefeffeefeeeeffefffeeefffeefffefeefefeeeffefefefefefefffffffeeeeeffffeefeeeeffffeeeeeefeffef", "output": "Draw" }, { "input": "61\nbzqiqprzfwddqwctcrhnkqcsnbmcmfmrgaljwieajfouvuiunmfbrehxchupmsdpwilwu\njyxxujvxkwilikqeegzxlyiugflxqqbwbujzedqnlzucdnuipacatdhcozuvgktwvirhs\ntqiahohijwfcetyyjlkfhfvkhdgllxmhyyhhtlhltcdspusyhwpwqzyagtsbaswaobwub", "output": "Katie" }, { "input": "30\njAjcdwkvcTYSYBBLniJIIIiubKWnqeDtUiaXSIPfhDTOrCWBQetm\nPQPOTgqfBWzQvPNeEaUaPQGdUgldmOZsBtsIqZGGyXozntMpOsyY\nNPfvGxMqIULNWOmUrHJfsqORUHkzKQfecXsTzgFCmUtFmIBudCJr", "output": "Draw" }, { "input": "3\nabcabcabcabcdddabc\nzxytzytxxtytxyzxyt\nfgffghfghffgghghhh", "output": "Katie" }, { "input": "3\naaaaa\naaaaa\naaaab", "output": "Draw" }, { "input": "3\naaaaaaa\naaaabcd\nabcdefg", "output": "Draw" }, { "input": "3\naaaaaaa\naaabcde\nabcdefg", "output": "Kuro" }, { "input": "3\naaaaaaa\naaaabbb\nabcdefg", "output": "Draw" }, { "input": "3\naaa\nbbb\nabc", "output": "Draw" }, { "input": "3\naaaaa\nabcde\nabcde", "output": "Kuro" }, { "input": "3\naaaaa\nqwert\nlkjhg", "output": "Kuro" }, { "input": "3\naaaaa\nbbbbb\naabcd", "output": "Draw" }, { "input": "3\nabcde\nfghij\nkkkkk", "output": "Katie" }, { "input": "4\naaaabcd\naaaabcd\naaaaaaa", "output": "Draw" }, { "input": "3\naaaabb\naabcde\nabcdef", "output": "Kuro" }, { "input": "2\naaab\nabcd\naaaa", "output": "Draw" }, { "input": "3\naaaaaa\naaaaaa\nabcdef", "output": "Draw" }, { "input": "1\nAAAAA\nBBBBB\nABCDE", "output": "Draw" }, { "input": "1\nabcde\naaaaa\naaaaa", "output": "Draw" }, { "input": "4\naaabbb\nabfcde\nabfcde", "output": "Kuro" }, { "input": "0\naaa\naab\nccd", "output": "Kuro" }, { "input": "3\naaaaa\naaaaa\naabbb", "output": "Draw" }, { "input": "3\nxxxxxx\nxxxooo\nabcdef", "output": "Draw" }, { "input": "2\noooo\naaac\nabcd", "output": "Draw" }, { "input": "1\naaaaaaa\naaabcde\nabcdefg", "output": "Kuro" }, { "input": "3\nooooo\naaabb\nabcde", "output": "Draw" }, { "input": "3\naaaaa\nqwert\nqwery", "output": "Kuro" }, { "input": "2\naaaaaa\nbbbbbb\naaaaab", "output": "Draw" }, { "input": "3\naabb\naabb\naabc", "output": "Draw" }, { "input": "2\naaa\naab\naab", "output": "Draw" }, { "input": "3\nbbbbcc\nbbbbbb\nsadfgh", "output": "Draw" }, { "input": "3\naaaaaacc\nxxxxkkkk\nxxxxkkkk", "output": "Kuro" }, { "input": "2\naaaac\nbbbbc\nccccc", "output": "Draw" }, { "input": "3\naaaaaaaaa\naaabbbbbb\nabcdewert", "output": "Draw" }, { "input": "3\naaabc\naaaab\nabcde", "output": "Draw" }, { "input": "3\naaaaaaaa\naaaaaaab\naaaabbbb", "output": "Draw" }, { "input": "2\nabcdefg\nabccccc\nacccccc", "output": "Draw" }, { "input": "3\naaaaa\naabcd\nabcde", "output": "Draw" }, { "input": "4\naaabbb\nabcdef\nabcdef", "output": "Kuro" }, { "input": "4\naaabbb\naabdef\nabcdef", "output": "Draw" }, { "input": "3\nabba\nbbbb\naaaa", "output": "Draw" }, { "input": "3\naaaaa\nbbaaa\nabcde", "output": "Draw" }, { "input": "2\naaa\naaa\nabc", "output": "Draw" }, { "input": "3\naaaaa\nabcda\nabcde", "output": "Draw" }, { "input": "3\naaaaa\nabcde\nbcdef", "output": "Kuro" }, { "input": "3\naaabb\naabbc\nqwert", "output": "Draw" }, { "input": "3\naaaaaa\naabbcc\naabbcc", "output": "Kuro" }, { "input": "3\nAAAAAA\nAAAAAB\nABCDEF", "output": "Draw" }, { "input": "3\nabc\naac\nbbb", "output": "Draw" }, { "input": "2\naaaab\naabbc\naabbc", "output": "Kuro" }, { "input": "2\naaaaaab\naaaaabb\nabcdefg", "output": "Draw" }, { "input": "3\naaaaaaaaaaa\nbbbbbbbbaaa\nqwertyuiasd", "output": "Draw" }, { "input": "3\naaaa\nbbbb\naabb", "output": "Draw" }, { "input": "3\naaaabb\naaabcd\nabcdef", "output": "Draw" }, { "input": "3\naaa\nabc\nbbb", "output": "Draw" }, { "input": "1\naa\nab\nbb", "output": "Shiro" }, { "input": "1\naacb\nabcd\naaaa", "output": "Draw" }, { "input": "3\naaaabb\naaabbb\nabcdef", "output": "Draw" }, { "input": "3\naaaa\naaaa\nabcd", "output": "Draw" }, { "input": "2\nabcd\nabcd\naaad", "output": "Katie" }, { "input": "3\naaa\nbbb\naab", "output": "Draw" }, { "input": "3\naaaaaa\naaaaab\naaaaaa", "output": "Draw" }, { "input": "2\naaab\nabcd\nabcd", "output": "Kuro" }, { "input": "3\nooooo\nShiro\nKatie", "output": "Kuro" }, { "input": "3\naaabb\naabcd\nabcde", "output": "Draw" }, { "input": "4\nabcd\nabcd\naaaa", "output": "Draw" }, { "input": "4\naaa\nbbb\naab", "output": "Draw" }, { "input": "2\nxxxx\nyyyx\nabcd", "output": "Draw" }, { "input": "3\nAAAAA\nAAAAB\nABCDE", "output": "Draw" }, { "input": "3\naaaacdc\naaaaabc\naaaaabc", "output": "Draw" }, { "input": "3\naaaaaa\naabcde\naabcde", "output": "Kuro" }, { "input": "3\naaabb\naaabb\naaaaa", "output": "Draw" }, { "input": "5\nabbbbb\ncbbbbb\nabcdef", "output": "Draw" }, { "input": "3\naaaaaaaaa\naaaaabbbb\naaaaabbbb", "output": "Kuro" }, { "input": "4\naaaaaab\naaabbbb\naaabbbb", "output": "Draw" }, { "input": "3\naaaabb\naaaabb\naaabbb", "output": "Draw" }, { "input": "2\naaaabb\naaaaab\nabcdef", "output": "Draw" }, { "input": "2\naaaaa\naaaae\nabcde", "output": "Draw" }, { "input": "3\naaaaaa\nbbbcde\nabcdef", "output": "Draw" }, { "input": "4\naaaabbb\naabcdef\naabcdef", "output": "Kuro" }, { "input": "2\naaaaa\naaaab\nabcde", "output": "Draw" }, { "input": "3\naabbbbb\naaabbbb\nabcdefg", "output": "Draw" }, { "input": "3\nabcde\naabcd\naaaaa", "output": "Draw" }, { "input": "5\naaabbcc\nabcdefg\nabcdefg", "output": "Kuro" }, { "input": "3\naabbb\nabcde\nabcde", "output": "Kuro" }, { "input": "0\nbbb\nabb\nqer", "output": "Kuro" }, { "input": "5\naabbbbb\naaaaaaa\nabcdefg", "output": "Draw" }, { "input": "2\naaaab\naaaab\naaabb", "output": "Draw" }, { "input": "2\naaaaaab\naaaabbb\naaaaccc", "output": "Kuro" }, { "input": "3\naaaaaaaaaaaa\naaaaaaaaaaab\naaaaaabbbbbb", "output": "Draw" }, { "input": "3\naaabb\nabcde\naaaaa", "output": "Draw" }, { "input": "3\naaaaaac\naaaaebc\naaaaaac", "output": "Draw" }, { "input": "3\naaaaaa\naaabbb\nqwerty", "output": "Draw" }, { "input": "3\ncccca\nabcde\nabcde", "output": "Kuro" }, { "input": "100005\nAA\nBC\nCC", "output": "Draw" }, { "input": "3\naaaa\nbbbb\nccca", "output": "Draw" }, { "input": "3\naaaaa\nbcdef\nbcdef", "output": "Kuro" }, { "input": "2\naaab\naabb\nqwer", "output": "Draw" }, { "input": "3\nabcddd\nabcdef\nbbaaaa", "output": "Draw" }, { "input": "2\naaaa\naaaa\naabc", "output": "Draw" }, { "input": "3\naaaa\naaaa\naaab", "output": "Draw" }, { "input": "3\nabcddd\nabcdef\naaaaaa", "output": "Draw" }, { "input": "1\naaaa\nabcd\naaab", "output": "Katie" } ]

1,596,726,860

2,147,483,647

PyPy 3

WRONG_ANSWER

TESTS

4

155

20,480,000

########################################################## from collections import Counter # c=sorted((i,int(val))for i,val in enumerate(input().split())) import heapq # c=sorted((i,int(val))for i,val in enumerate(input().split())) # n = int(input()) # ls = list(map(int, input().split())) # n, k = map(int, input().split()) # n =int(input()) # e=list(map(int, input().split())) from collections import Counter #print("\n".join(ls)) #print(os.path.commonprefix(ls[0:2])) #for i in range(int(input())): #n=int(input()) n=int(input()) ls=[] ans=0 for i in range(3): s=input() c = Counter(s) ls.append(min(max(c.values())+n,len(s))) cc=ls.count(max(ls)) if cc>=2: print("Draw") else: if ls.index(max(ls))==0: print("Kuro") elif ls.index(max(ls))==1: print("Shiro") else: print("Katie")

Title: Treasure Hunt Time Limit: None seconds Memory Limit: None megabytes Problem Description: After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her. The three friends are very smart so they passed all the challenges very quickly and finally reached the destination. But the treasure can only belong to one cat so they started to think of something which can determine who is worthy of the treasure. Instantly, Kuro came up with some ribbons. A random colorful ribbon is given to each of the cats. Each color of the ribbon can be represented as an uppercase or lowercase Latin letter. Let's call a consecutive subsequence of colors that appears in the ribbon a subribbon. The beauty of a ribbon is defined as the maximum number of times one of its subribbon appears in the ribbon. The more the subribbon appears, the more beautiful is the ribbon. For example, the ribbon aaaaaaa has the beauty of $7$ because its subribbon a appears $7$ times, and the ribbon abcdabc has the beauty of $2$ because its subribbon abc appears twice. The rules are simple. The game will have $n$ turns. Every turn, each of the cats must change strictly one color (at one position) in his/her ribbon to an arbitrary color which is different from the unchanged one. For example, a ribbon aaab can be changed into acab in one turn. The one having the most beautiful ribbon after $n$ turns wins the treasure. Could you find out who is going to be the winner if they all play optimally? Input Specification: The first line contains an integer $n$ ($0 \leq n \leq 10^{9}$) — the number of turns. Next 3 lines contain 3 ribbons of Kuro, Shiro and Katie one per line, respectively. Each ribbon is a string which contains no more than $10^{5}$ uppercase and lowercase Latin letters and is not empty. It is guaranteed that the length of all ribbons are equal for the purpose of fairness. Note that uppercase and lowercase letters are considered different colors. Output Specification: Print the name of the winner ("Kuro", "Shiro" or "Katie"). If there are at least two cats that share the maximum beauty, print "Draw". Demo Input: ['3\nKuroo\nShiro\nKatie\n', '7\ntreasurehunt\nthreefriends\nhiCodeforces\n', '1\nabcabc\ncbabac\nababca\n', '15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE\n'] Demo Output: ['Kuro\n', 'Shiro\n', 'Katie\n', 'Draw\n'] Note: In the first example, after $3$ turns, Kuro can change his ribbon into ooooo, which has the beauty of $5$, while reaching such beauty for Shiro and Katie is impossible (both Shiro and Katie can reach the beauty of at most $4$, for example by changing Shiro's ribbon into SSiSS and changing Katie's ribbon into Kaaaa). Therefore, the winner is Kuro. In the fourth example, since the length of each of the string is $9$ and the number of turn is $15$, everyone can change their ribbons in some way to reach the maximal beauty of $9$ by changing their strings into zzzzzzzzz after 9 turns, and repeatedly change their strings into azzzzzzzz and then into zzzzzzzzz thrice. Therefore, the game ends in a draw.

```python ########################################################## from collections import Counter # c=sorted((i,int(val))for i,val in enumerate(input().split())) import heapq # c=sorted((i,int(val))for i,val in enumerate(input().split())) # n = int(input()) # ls = list(map(int, input().split())) # n, k = map(int, input().split()) # n =int(input()) # e=list(map(int, input().split())) from collections import Counter #print("\n".join(ls)) #print(os.path.commonprefix(ls[0:2])) #for i in range(int(input())): #n=int(input()) n=int(input()) ls=[] ans=0 for i in range(3): s=input() c = Counter(s) ls.append(min(max(c.values())+n,len(s))) cc=ls.count(max(ls)) if cc>=2: print("Draw") else: if ls.index(max(ls))==0: print("Kuro") elif ls.index(max(ls))==1: print("Shiro") else: print("Katie") ```

0

863

A

Quasi-palindrome

PROGRAMMING

900

[ "brute force", "implementation" ]

null

Let quasi-palindromic number be such number that adding some leading zeros (possible none) to it produces a palindromic string. String *t* is called a palindrome, if it reads the same from left to right and from right to left. For example, numbers 131 and 2010200 are quasi-palindromic, they can be transformed to strings "131" and "002010200", respectively, which are palindromes. You are given some integer number *x*. Check if it's a quasi-palindromic number.

The first line contains one integer number *x* (1<=≤<=*x*<=≤<=109). This number is given without any leading zeroes.

Print "YES" if number *x* is quasi-palindromic. Otherwise, print "NO" (without quotes).

[ "131\n", "320\n", "2010200\n" ]

[ "YES\n", "NO\n", "YES\n" ]

none

0

[ { "input": "131", "output": "YES" }, { "input": "320", "output": "NO" }, { "input": "2010200", "output": "YES" }, { "input": "1", "output": "YES" }, { "input": "1000000000", "output": "YES" }, { "input": "999999999", "output": "YES" }, { "input": "999999998", "output": "NO" }, { "input": "102000", "output": "NO" }, { "input": "210000000", "output": "NO" }, { "input": "213443120", "output": "YES" }, { "input": "99", "output": "YES" }, { "input": "22002", "output": "NO" }, { "input": "1010", "output": "YES" }, { "input": "1201", "output": "NO" }, { "input": "6460046", "output": "NO" }, { "input": "503435", "output": "NO" }, { "input": "21002", "output": "NO" }, { "input": "101001", "output": "NO" }, { "input": "200102", "output": "NO" }, { "input": "20010002", "output": "NO" }, { "input": "33003", "output": "NO" }, { "input": "100101", "output": "NO" }, { "input": "1021", "output": "NO" }, { "input": "1101", "output": "NO" }, { "input": "10101100", "output": "NO" }, { "input": "101", "output": "YES" }, { "input": "1011", "output": "NO" }, { "input": "11010", "output": "NO" }, { "input": "10110", "output": "NO" }, { "input": "110000", "output": "YES" }, { "input": "2011", "output": "NO" }, { "input": "10020001", "output": "NO" }, { "input": "12505021", "output": "NO" }, { "input": "12310", "output": "NO" }, { "input": "100501", "output": "NO" }, { "input": "11001", "output": "NO" }, { "input": "20020002", "output": "NO" }, { "input": "202002", "output": "NO" }, { "input": "1001", "output": "YES" }, { "input": "1020021", "output": "NO" }, { "input": "60660", "output": "NO" }, { "input": "98809", "output": "NO" }, { "input": "11000000", "output": "YES" }, { "input": "807008", "output": "NO" } ]

1,544,107,786

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

11

109

0

n = str(input().replace("0","")) if n == ("".join(reversed(n))): print("yes") else: print("no")

Title: Quasi-palindrome Time Limit: None seconds Memory Limit: None megabytes Problem Description: Let quasi-palindromic number be such number that adding some leading zeros (possible none) to it produces a palindromic string. String *t* is called a palindrome, if it reads the same from left to right and from right to left. For example, numbers 131 and 2010200 are quasi-palindromic, they can be transformed to strings "131" and "002010200", respectively, which are palindromes. You are given some integer number *x*. Check if it's a quasi-palindromic number. Input Specification: The first line contains one integer number *x* (1<=≤<=*x*<=≤<=109). This number is given without any leading zeroes. Output Specification: Print "YES" if number *x* is quasi-palindromic. Otherwise, print "NO" (without quotes). Demo Input: ['131\n', '320\n', '2010200\n'] Demo Output: ['YES\n', 'NO\n', 'YES\n'] Note: none

```python n = str(input().replace("0","")) if n == ("".join(reversed(n))): print("yes") else: print("no") ```

0

4

A

Watermelon

PROGRAMMING

800

[ "brute force", "math" ]

A. Watermelon

1

64

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem. Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys.

Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

[ "8\n" ]

[ "YES\n" ]

For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

0

[ { "input": "8", "output": "YES" }, { "input": "5", "output": "NO" }, { "input": "4", "output": "YES" }, { "input": "3", "output": "NO" }, { "input": "2", "output": "NO" }, { "input": "1", "output": "NO" }, { "input": "7", "output": "NO" }, { "input": "6", "output": "YES" }, { "input": "10", "output": "YES" }, { "input": "9", "output": "NO" }, { "input": "53", "output": "NO" }, { "input": "77", "output": "NO" }, { "input": "32", "output": "YES" }, { "input": "44", "output": "YES" }, { "input": "98", "output": "YES" }, { "input": "99", "output": "NO" }, { "input": "90", "output": "YES" }, { "input": "67", "output": "NO" }, { "input": "100", "output": "YES" }, { "input": "88", "output": "YES" } ]

1,691,600,796

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

0

30

0

y=int(input()) if y%2==0 and y>2: print("YAS") else: print("NO")

Title: Watermelon Time Limit: 1 seconds Memory Limit: 64 megabytes Problem Description: One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem. Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight. Input Specification: The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. Output Specification: Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. Demo Input: ['8\n'] Demo Output: ['YES\n'] Note: For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

```python y=int(input()) if y%2==0 and y>2: print("YAS") else: print("NO") ```

0

456

A

Laptops

PROGRAMMING

1,100

[ "sortings" ]

null

One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop. Please, check the guess of Alex. You are given descriptions of *n* laptops. Determine whether two described above laptops exist.

The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops. Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the number is, the higher is the quality). All *a**i* are distinct. All *b**i* are distinct.

If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).

[ "2\n1 2\n2 1\n" ]

[ "Happy Alex\n" ]

none

500

[ { "input": "2\n1 2\n2 1", "output": "Happy Alex" }, { "input": "2\n1 1\n2 2", "output": "Poor Alex" }, { "input": "3\n2 2\n3 3\n1 1", "output": "Poor Alex" }, { "input": "3\n3 3\n1 2\n2 1", "output": "Happy Alex" }, { "input": "1\n1 1", "output": "Poor Alex" }, { "input": "3\n2 3\n1 1\n3 2", "output": "Happy Alex" }, { "input": "4\n4 1\n3 2\n2 3\n1 4", "output": "Happy Alex" }, { "input": "2\n2 1\n1 2", "output": "Happy Alex" }, { "input": "3\n3 2\n1 1\n2 3", "output": "Happy Alex" }, { "input": "3\n1 2\n2 3\n3 1", "output": "Happy Alex" }, { "input": "3\n1 2\n2 1\n3 3", "output": "Happy Alex" }, { "input": "3\n1 2\n2 3\n3 1", "output": "Happy Alex" } ]

1,695,741,121

2,147,483,647

Python 3

OK

TESTS

46

140

5,632,000

# -*- coding: utf-8 -*- """ Created on Sun Sep 24 10:59:11 2023 @author: He'Bing'Ru """ n = int(input()) flag = True for i in range(n) : ls = input().split() if ls[0]!=ls[1]: flag = False if flag: print('Poor Alex') else: print('Happy Alex')

Title: Laptops Time Limit: None seconds Memory Limit: None megabytes Problem Description: One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop. Please, check the guess of Alex. You are given descriptions of *n* laptops. Determine whether two described above laptops exist. Input Specification: The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops. Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the number is, the higher is the quality). All *a**i* are distinct. All *b**i* are distinct. Output Specification: If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). Demo Input: ['2\n1 2\n2 1\n'] Demo Output: ['Happy Alex\n'] Note: none

```python # -*- coding: utf-8 -*- """ Created on Sun Sep 24 10:59:11 2023 @author: He'Bing'Ru """ n = int(input()) flag = True for i in range(n) : ls = input().split() if ls[0]!=ls[1]: flag = False if flag: print('Poor Alex') else: print('Happy Alex') ```

3

887

A

Div. 64

PROGRAMMING

1,000

[ "implementation" ]

null

Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills. Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisible by 64, in the binary numerical system.

In the only line given a non-empty binary string *s* with length up to 100.

Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise.

[ "100010001\n", "100\n" ]

[ "yes", "no" ]

In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system. You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system)

500

[ { "input": "100010001", "output": "yes" }, { "input": "100", "output": "no" }, { "input": "0000001000000", "output": "yes" }, { "input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111", "output": "no" }, { "input": "1111111111111111111111111111111111111111111111111111111111111111111111110111111111111111111111111111", "output": "no" }, { "input": "0111111101111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111", "output": "no" }, { "input": "1111011111111111111111111111110111110111111111111111111111011111111111111110111111111111111111111111", "output": "no" }, { "input": "1111111111101111111111111111111111111011111111111111111111111101111011111101111111111101111111111111", "output": "yes" }, { "input": "0110111111111111111111011111111110110111110111111111111111111111111111111111111110111111111111111111", "output": "yes" }, { "input": "1100110001111011001101101000001110111110011110111110010100011000100101000010010111100000010001001101", "output": "yes" }, { "input": "000000", "output": "no" }, { "input": "0001000", "output": "no" }, { "input": "0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000", "output": "no" }, { "input": "1000000", "output": "yes" }, { "input": "0", "output": "no" }, { "input": "1", "output": "no" }, { "input": "10000000000", "output": "yes" }, { "input": "0000000000", "output": "no" }, { "input": "0010000", "output": "no" }, { "input": "000000011", "output": "no" }, { "input": "000000000", "output": "no" }, { "input": "00000000", "output": "no" }, { "input": "000000000011", "output": "no" }, { "input": "0000000", "output": "no" }, { "input": "00000000011", "output": "no" }, { "input": "000000001", "output": "no" }, { "input": "000000000000000000000000000", "output": "no" }, { "input": "0000001", "output": "no" }, { "input": "00000001", "output": "no" }, { "input": "00000000100", "output": "no" }, { "input": "00000000000000000000", "output": "no" }, { "input": "0000000000000000000", "output": "no" }, { "input": "00001000", "output": "no" }, { "input": "0000000000010", "output": "no" }, { "input": "000000000010", "output": "no" }, { "input": "000000000000010", "output": "no" }, { "input": "0100000", "output": "no" }, { "input": "00010000", "output": "no" }, { "input": "00000000000000000", "output": "no" }, { "input": "00000000000", "output": "no" }, { "input": "000001000", "output": "no" }, { "input": "000000000000", "output": "no" }, { "input": "100000000000000", "output": "yes" }, { "input": "000010000", "output": "no" }, { "input": "00000100", "output": "no" }, { "input": "0001100000", "output": "no" }, { "input": "000000000000000000000000001", "output": "no" }, { "input": "000000100", "output": "no" }, { "input": "0000000000001111111111", "output": "no" }, { "input": "00000010", "output": "no" }, { "input": "0001110000", "output": "no" }, { "input": "0000000000000000000000", "output": "no" }, { "input": "000000010010", "output": "no" }, { "input": "0000100", "output": "no" }, { "input": "0000000001", "output": "no" }, { "input": "000000111", "output": "no" }, { "input": "0000000000000", "output": "no" }, { "input": "000000000000000000", "output": "no" }, { "input": "0000000000000000000000000", "output": "no" }, { "input": "000000000000000", "output": "no" }, { "input": "0010000000000100", "output": "yes" }, { "input": "0000001000", "output": "no" }, { "input": "00000000000000000001", "output": "no" }, { "input": "100000000", "output": "yes" }, { "input": "000000000001", "output": "no" }, { "input": "0000011001", "output": "no" }, { "input": "000", "output": "no" }, { "input": "000000000000000000000", "output": "no" }, { "input": "0000000000011", "output": "no" }, { "input": "0000000000000000", "output": "no" }, { "input": "00000000000000001", "output": "no" }, { "input": "00000000000000", "output": "no" }, { "input": "0000000000000000010", "output": "no" }, { "input": "00000000000000000000000000000000000000000000000000000000", "output": "no" }, { "input": "000011000", "output": "no" }, { "input": "00000011", "output": "no" }, { "input": "0000000000001100", "output": "no" }, { "input": "00000", "output": "no" }, { "input": "000000000000000000000000000111111111111111", "output": "no" }, { "input": "000000010", "output": "no" }, { "input": "00000000111", "output": "no" }, { "input": "000000000000001", "output": "no" }, { "input": "0000000000000011111111111111111", "output": "no" }, { "input": "0000000010", "output": "no" }, { "input": "0000000000000000000000000000000000000000000000000", "output": "no" }, { "input": "00000000010", "output": "no" }, { "input": "101000000000", "output": "yes" }, { "input": "00100000", "output": "no" }, { "input": "00000000000001", "output": "no" }, { "input": "0000000000100", "output": "no" }, { "input": "0000", "output": "no" }, { "input": "00000000000111", "output": "no" }, { "input": "0000000000000011", "output": "no" }, { "input": "0000000000000000000000000000000000000000", "output": "no" }, { "input": "0000000000000010", "output": "no" }, { "input": "0010101010", "output": "no" }, { "input": "0000000000000001", "output": "no" }, { "input": "1010101", "output": "no" } ]

1,617,541,129

2,147,483,647

Python 3

WRONG_ANSWER

TESTS

3

46

0

b=str(input()) n=int(b,2) if n>=64: print('yes') else: print('no')

Title: Div. 64 Time Limit: None seconds Memory Limit: None megabytes Problem Description: Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills. Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisible by 64, in the binary numerical system. Input Specification: In the only line given a non-empty binary string *s* with length up to 100. Output Specification: Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. Demo Input: ['100010001\n', '100\n'] Demo Output: ['yes', 'no'] Note: In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system. You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system)

```python b=str(input()) n=int(b,2) if n>=64: print('yes') else: print('no') ```

0

2

A

Winner

PROGRAMMING

1,500

[ "hashing", "implementation" ]

A. Winner

1

64

The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.

The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.

Print the name of the winner.

[ "3\nmike 3\nandrew 5\nmike 2\n", "3\nandrew 3\nandrew 2\nmike 5\n" ]

[ "andrew\n", "andrew\n" ]

none

0

[ { "input": "3\nmike 3\nandrew 5\nmike 2", "output": "andrew" }, { "input": "3\nandrew 3\nandrew 2\nmike 5", "output": "andrew" }, { "input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303", "output": "kaxqybeultn" }, { "input": "7\nksjuuerbnlklcfdjeyq 312\ndthjlkrvvbyahttifpdewvyslsh -983\nksjuuerbnlklcfdjeyq 268\ndthjlkrvvbyahttifpdewvyslsh 788\nksjuuerbnlklcfdjeyq -79\nksjuuerbnlklcfdjeyq -593\nksjuuerbnlklcfdjeyq 734", "output": "ksjuuerbnlklcfdjeyq" }, { "input": "12\natrtthfpcvishmqbakprquvnejr 185\natrtthfpcvishmqbakprquvnejr -699\natrtthfpcvishmqbakprquvnejr -911\natrtthfpcvishmqbakprquvnejr -220\nfcgslzkicjrpbqaifgweyzreajjfdo 132\nfcgslzkicjrpbqaifgweyzreajjfdo -242\nm 177\nm -549\natrtthfpcvishmqbakprquvnejr -242\nm 38\natrtthfpcvishmqbakprquvnejr -761\nfcgslzkicjrpbqaifgweyzreajjfdo 879", "output": "fcgslzkicjrpbqaifgweyzreajjfdo" }, { "input": "15\naawtvezfntstrcpgbzjbf 681\nzhahpvqiptvksnbjkdvmknb -74\naawtvezfntstrcpgbzjbf 661\njpdwmyke 474\naawtvezfntstrcpgbzjbf -547\naawtvezfntstrcpgbzjbf 600\nzhahpvqiptvksnbjkdvmknb -11\njpdwmyke 711\nbjmj 652\naawtvezfntstrcpgbzjbf -1000\naawtvezfntstrcpgbzjbf -171\nbjmj -302\naawtvezfntstrcpgbzjbf 961\nzhahpvqiptvksnbjkdvmknb 848\nbjmj -735", "output": "aawtvezfntstrcpgbzjbf" }, { "input": "17\nqdplghhx -649\nivhgbxiv 424\nivhgbxiv -72\nivhgbxiv 479\nugowfouebkelargxylsxn 83\nugowfouebkelargxylsxn -840\nivhgbxiv 382\nqdplghhx -904\nivhgbxiv -710\nugowfouebkelargxylsxn -838\nqdplghhx -974\nqdplghhx 571\nivhgbxiv -145\nugowfouebkelargxylsxn -788\nivhgbxiv 209\nivhgbxiv 420\nqdplghhx -158", "output": "ivhgbxiv" } ]

1,592,985,541

1,441

Python 3

WRONG_ANSWER

TESTS

9

216

6,963,200

def sort(palya, t, x): for c in playa: if playa[c]>t: t = playa[c] x = c return x,t x = int(input()) playa = {} b,t = str(), int() for i in range(x): c,g = input().split() g = int(g) if c in playa: playa[c] += g else: playa[c] = g b,t = sort(playa, t, b) print(b)

Title: Winner Time Limit: 1 seconds Memory Limit: 64 megabytes Problem Description: The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points. Input Specification: The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive. Output Specification: Print the name of the winner. Demo Input: ['3\nmike 3\nandrew 5\nmike 2\n', '3\nandrew 3\nandrew 2\nmike 5\n'] Demo Output: ['andrew\n', 'andrew\n'] Note: none

```python def sort(palya, t, x): for c in playa: if playa[c]>t: t = playa[c] x = c return x,t x = int(input()) playa = {} b,t = str(), int() for i in range(x): c,g = input().split() g = int(g) if c in playa: playa[c] += g else: playa[c] = g b,t = sort(playa, t, b) print(b) ```

0

828

A

Restaurant Tables

PROGRAMMING

1,200

[ "implementation" ]

null

In a small restaurant there are *a* tables for one person and *b* tables for two persons. It it known that *n* groups of people come today, each consisting of one or two people. If a group consist of one person, it is seated at a vacant one-seater table. If there are none of them, it is seated at a vacant two-seater table. If there are none of them, it is seated at a two-seater table occupied by single person. If there are still none of them, the restaurant denies service to this group. If a group consist of two people, it is seated at a vacant two-seater table. If there are none of them, the restaurant denies service to this group. You are given a chronological order of groups coming. You are to determine the total number of people the restaurant denies service to.

The first line contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*a*,<=*b*<=≤<=2·105) — the number of groups coming to the restaurant, the number of one-seater and the number of two-seater tables. The second line contains a sequence of integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=2) — the description of clients in chronological order. If *t**i* is equal to one, then the *i*-th group consists of one person, otherwise the *i*-th group consists of two people.

Print the total number of people the restaurant denies service to.

[ "4 1 2\n1 2 1 1\n", "4 1 1\n1 1 2 1\n" ]

[ "0\n", "2\n" ]

In the first example the first group consists of one person, it is seated at a vacant one-seater table. The next group occupies a whole two-seater table. The third group consists of one person, it occupies one place at the remaining two-seater table. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, all clients are served. In the second example the first group consists of one person, it is seated at the vacant one-seater table. The next group consists of one person, it occupies one place at the two-seater table. It's impossible to seat the next group of two people, so the restaurant denies service to them. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, the restaurant denies service to 2 clients.

500

[ { "input": "4 1 2\n1 2 1 1", "output": "0" }, { "input": "4 1 1\n1 1 2 1", "output": "2" }, { "input": "1 1 1\n1", "output": "0" }, { "input": "2 1 2\n2 2", "output": "0" }, { "input": "5 1 3\n1 2 2 2 1", "output": "1" }, { "input": "7 6 1\n1 1 1 1 1 1 1", "output": "0" }, { "input": "10 2 1\n2 1 2 2 2 2 1 2 1 2", "output": "13" }, { "input": "20 4 3\n2 2 2 2 2 2 2 2 1 2 1 1 2 2 1 2 2 2 1 2", "output": "25" }, { "input": "1 1 1\n1", "output": "0" }, { "input": "1 1 1\n2", "output": "0" }, { "input": "1 200000 200000\n2", "output": "0" }, { "input": "30 10 10\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2", "output": "20" }, { "input": "4 1 2\n1 1 1 2", "output": "2" }, { "input": "6 2 3\n1 2 1 1 1 2", "output": "2" }, { "input": "6 1 4\n1 1 1 1 1 2", "output": "2" }, { "input": "6 1 3\n1 1 1 1 2 2", "output": "4" }, { "input": "6 1 3\n1 1 1 1 1 2", "output": "2" }, { "input": "6 4 2\n2 1 2 2 1 1", "output": "2" }, { "input": "3 10 1\n2 2 2", "output": "4" }, { "input": "5 1 3\n1 1 1 1 2", "output": "2" }, { "input": "5 2 2\n1 1 1 1 2", "output": "2" }, { "input": "15 5 5\n1 1 1 1 1 1 1 1 1 1 2 2 2 2 2", "output": "10" }, { "input": "5 1 2\n1 1 1 1 1", "output": "0" }, { "input": "3 6 1\n2 2 2", "output": "4" }, { "input": "5 3 3\n2 2 2 2 2", "output": "4" }, { "input": "8 3 3\n1 1 1 1 1 1 2 2", "output": "4" }, { "input": "5 1 2\n1 1 1 2 1", "output": "2" }, { "input": "6 1 4\n1 2 2 1 2 2", "output": "2" }, { "input": "2 1 1\n2 2", "output": "2" }, { "input": "2 2 1\n2 2", "output": "2" }, { "input": "5 8 1\n2 2 2 2 2", "output": "8" }, { "input": "3 1 4\n1 1 2", "output": "0" }, { "input": "7 1 5\n1 1 1 1 1 1 2", "output": "2" }, { "input": "6 1 3\n1 1 1 2 1 1", "output": "0" }, { "input": "6 1 2\n1 1 1 2 2 2", "output": "6" }, { "input": "8 1 4\n2 1 1 1 2 2 2 2", "output": "6" }, { "input": "4 2 3\n2 2 2 2", "output": "2" }, { "input": "3 1 1\n1 1 2", "output": "2" }, { "input": "5 1 1\n2 2 2 2 2", "output": "8" }, { "input": "10 1 5\n1 1 1 1 1 2 2 2 2 2", "output": "8" }, { "input": "5 1 2\n1 1 1 2 2", "output": "4" }, { "input": "4 1 1\n1 1 2 2", "output": "4" }, { "input": "7 1 2\n1 1 1 1 1 1 1", "output": "2" }, { "input": "5 1 4\n2 2 2 2 2", "output": "2" }, { "input": "6 2 3\n1 1 1 1 2 2", "output": "2" }, { "input": "5 2 2\n2 1 2 1 2", "output": "2" }, { "input": "4 6 1\n2 2 2 2", "output": "6" }, { "input": "6 1 4\n1 1 2 1 1 2", "output": "2" }, { "input": "7 1 3\n1 1 1 1 2 2 2", "output": "6" }, { "input": "4 1 2\n1 1 2 2", "output": "2" }, { "input": "3 1 2\n1 1 2", "output": "0" }, { "input": "6 1 3\n1 2 1 1 2 1", "output": "2" }, { "input": "6 1 3\n1 1 1 2 2 2", "output": "4" }, { "input": "10 2 2\n1 1 1 1 2 2 2 2 2 2", "output": "12" }, { "input": "10 1 4\n1 1 1 1 1 2 2 2 2 2", "output": "10" }, { "input": "3 10 2\n2 2 2", "output": "2" }, { "input": "4 3 1\n1 2 2 2", "output": "4" }, { "input": "7 1 4\n1 1 1 1 1 2 2", "output": "4" }, { "input": "3 4 1\n2 2 2", "output": "4" }, { "input": "4 1 2\n2 1 1 2", "output": "2" }, { "input": "10 1 2\n1 1 1 1 1 1 1 1 1 2", "output": "6" }, { "input": "5 1 3\n1 1 2 1 2", "output": "2" }, { "input": "6 1 3\n1 1 1 1 2 1", "output": "2" }, { "input": "6 1 4\n1 1 1 2 2 2", "output": "2" }, { "input": "7 1 2\n1 2 1 1 1 1 1", "output": "3" }, { "input": "6 2 2\n1 1 1 1 1 1", "output": "0" }, { "input": "6 1 2\n1 1 2 1 1 1", "output": "2" }, { "input": "3 3 1\n2 2 1", "output": "2" }, { "input": "8 4 2\n1 1 1 1 1 1 1 2", "output": "2" }, { "input": "9 1 4\n1 1 1 1 1 2 2 2 2", "output": "8" }, { "input": "5 10 1\n2 2 2 2 2", "output": "8" }, { "input": "3 5 1\n2 2 2", "output": "4" }, { "input": "5 100 1\n2 2 2 2 2", "output": "8" }, { "input": "4 1 2\n1 1 1 1", "output": "0" }, { "input": "4 1 1\n1 1 1 1", "output": "1" }, { "input": "7 2 2\n1 1 1 1 1 1 1", "output": "1" } ]

1,499,856,180

2,147,483,647

Python 3

OK

TESTS

97

202

9,011,200

n, a, b = [int(nab) for nab in str(input()).split(' ')] t = [int(ti) for ti in str(input()).split(' ')] tables = {1: {0: a, 1: 0}, 2: {0: b, 1: 0, 2: 0}} noservice = 0 for ti in t: if (ti == 1): if (tables[1][0] > 0): tables[1][0] -= 1 tables[1][1] += 1 elif (tables[2][0] > 0): tables[2][0] -= 1 tables[2][1] += 1 elif (tables[2][1] > 0): tables[2][1] -= 1 tables[2][2] += 1 else: noservice += 1 elif (tables[2][0] > 0): tables[2][0] -= 1 tables[2][2] += 1 else: noservice += 2 print(noservice)

Title: Restaurant Tables Time Limit: None seconds Memory Limit: None megabytes Problem Description: In a small restaurant there are *a* tables for one person and *b* tables for two persons. It it known that *n* groups of people come today, each consisting of one or two people. If a group consist of one person, it is seated at a vacant one-seater table. If there are none of them, it is seated at a vacant two-seater table. If there are none of them, it is seated at a two-seater table occupied by single person. If there are still none of them, the restaurant denies service to this group. If a group consist of two people, it is seated at a vacant two-seater table. If there are none of them, the restaurant denies service to this group. You are given a chronological order of groups coming. You are to determine the total number of people the restaurant denies service to. Input Specification: The first line contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*a*,<=*b*<=≤<=2·105) — the number of groups coming to the restaurant, the number of one-seater and the number of two-seater tables. The second line contains a sequence of integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=2) — the description of clients in chronological order. If *t**i* is equal to one, then the *i*-th group consists of one person, otherwise the *i*-th group consists of two people. Output Specification: Print the total number of people the restaurant denies service to. Demo Input: ['4 1 2\n1 2 1 1\n', '4 1 1\n1 1 2 1\n'] Demo Output: ['0\n', '2\n'] Note: In the first example the first group consists of one person, it is seated at a vacant one-seater table. The next group occupies a whole two-seater table. The third group consists of one person, it occupies one place at the remaining two-seater table. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, all clients are served. In the second example the first group consists of one person, it is seated at the vacant one-seater table. The next group consists of one person, it occupies one place at the two-seater table. It's impossible to seat the next group of two people, so the restaurant denies service to them. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, the restaurant denies service to 2 clients.

```python n, a, b = [int(nab) for nab in str(input()).split(' ')] t = [int(ti) for ti in str(input()).split(' ')] tables = {1: {0: a, 1: 0}, 2: {0: b, 1: 0, 2: 0}} noservice = 0 for ti in t: if (ti == 1): if (tables[1][0] > 0): tables[1][0] -= 1 tables[1][1] += 1 elif (tables[2][0] > 0): tables[2][0] -= 1 tables[2][1] += 1 elif (tables[2][1] > 0): tables[2][1] -= 1 tables[2][2] += 1 else: noservice += 1 elif (tables[2][0] > 0): tables[2][0] -= 1 tables[2][2] += 1 else: noservice += 2 print(noservice) ```

3